help-0

[upbeat eagle]

Same thing?

https://tenor.com/view/cat-fast-pet-kitten-cat-pet-pet-cat-gif-25030970

Hehe-
If you dont mind me asking

How do they get 13.1 cos 67 & 13.1 sin 67

[floral bronze]

IS B A RIGHT ANGLE

[upbeat eagle]

I dont know

no

Probably not

[floral bronze]

EITHER WAY, WE'D BE CORRECT I THINK

[upbeat eagle]

https://tenor.com/view/shake-hand-dab-nice-to-meet-you-shake-good-dog-gif-7173262

OH they got 13.1

because uh cosine rule

OB= 15^2 + 9^2 -2 15 9 cos60

But I dont know why they write since OB = 13.1

OA = 13.1

and AB = 13.1

Weird no?

Ty anyways :>

.close

[lone heart]

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[jovial lark]

Yo can anyone help me solve this : Find the real and imaginary parts of the following complex numbers:((Sqrt[3+i]) (-1+iSqrt[3]))/(1+i)^2
i have no clue why rez=0 and irez= sqrt[3]

[north canopy]

expand and simplify

[jovial lark]

bro how

like

I put this in wolfram

and get thisL

:

[north canopy]

expand denom and use conj

[frail grove]

You can't put i inside sqrt

[jovial lark]

so this is an error in the qstiuon

or what

w8

[frail grove]

Depends on ur country i guess

[upbeat eagle]

lol

[north canopy]

what do u get?

[fickle heath]

The question is probably meant to be (sqrt(3)+i)*... but you can absolutely put i inside sqrt

[jovial lark]

u think?

[frail grove]

But either way, u should multiply top and bottom by -2i to get rid of i in the denom

[fickle heath]

Well the answer would be way neater

[north canopy]

couldnt u j square the whole thing to get rid of that sqrt anyways?

[jovial lark]

and what can i do

nothing

[fickle heath]

Then what? You add the sqrt back at the end?

[frail grove]

When we do sqrt(a) we take in consideration positive square roots of a
What convention are u using for complex numbers?

[fickle heath]

Pretty sure there is no simplification for that sqrt part

[north canopy]

i guess

[frail grove]

sqrt(4)=2 and not -2 cause by convention sqrt is from R+ to R+

[fickle heath]

It's called the principal root https://en.wikipedia.org/wiki/Square_root#Principal_square_root_of_a_complex_number

[jovial lark]

soooooo what can i do?

about this

[fickle heath]

Ask whoever gave you this problem if there may be a typo

[frail grove]

Hmm ok, good to know ty

[frail grove]

You need to solve this equation: a^2 =3+i in order to simplify the sqrt

[jovial lark]

so I put a^2 i instead of 3+i

[fickle heath]

I think you replied to the wrong message?

[frail grove]

No i mean you should find the square roots of 3+i

[fickle heath]

That's going to be pretty difficult

[jovial lark]

yea

but this is 1st task on my list

so i think

[frail grove]

You just need to solve a system of equations

[jovial lark]

this is not to be hard

[jovial lark]

mean to be hard

[fickle heath]

In polar form? With a 4th root and some exp and arctan in the mix?

[frail grove]

No... wait I'll send it here

[jovial lark]

kk

[frail grove]

the square roots of 3+i are the complex numbers x + iy that verify this system of equations

[jovial lark]

okay but why in my answers rez =1 and Irez=sqrt[3]

[frail grove]

$x^2+y^2=|3+i| \ x^2-y^2=Real(3+i) \ 2xy=Im(3+i)$

[ocean seal]

Adam Chebil

[frail grove]

What's rez??

[jovial lark]

Real

[fickle heath]

You said rez=0 earlier

[jovial lark]

sorry thats polish notation

[fickle heath]

I thought you had tried something and that was your solution

You have the actual answers?

[jovial lark]

i mean

[frail grove]

You just need to simplify this right?

Where did z come from?

[jovial lark]

yes

[jovial lark]

what z

[fickle heath]

rez=real part, irez=imaginary part

[jovial lark]

yes

[frail grove]

Oh ok xd

[jovial lark]

XDDD

[frail grove]

So u got 1 + i sqrt(3) ?

[jovial lark]

bro im stuck in this position

and not clue what to do

what can i do from this

[fickle heath]

in my answers rez =1 and Irez=sqrt[3]
Where do they come from?

[jovial lark]

from my teacher pdf xDDDD

[fickle heath]

So you're supposed to have them, right?

[jovial lark]

yes

[fickle heath]

Okay, then it is a typo

It's meant to be sqrt(3) + i

[frail grove]

Multiply top and bottom by conjugate of 2i which is -2i

$\frac{2i\sqrt{3+i} + 2\sqrt{9+3i}}{4}$

[ocean seal]

Adam Chebil

[jovial lark]

this is in the end

i put this in wolfram

and i got this:

so what can i do from this

like

[fickle heath]

I told you already, it's a typo

[frail grove]

Yeah there's no way to simplify this unless u find square roots of 3+i

[jovial lark]

okaaaaaaay

thx guys

i close this

.close

[lone heart]

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[wind pawn]

29h

[wind pawn]

calculate the distance from the diagonal BH and the rib AD

<@&286206848099549185>

[lone heart]

@wind pawn Has your question been resolved?

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[slow saffron]

tried getting help and realised i was doing it wrong, but i still dont understand

[gleaming granite]

if two shapes are similar then the ratios of their sides are equal

do you know how to start the problem?

[slow saffron]

well i'd have guessed id do:

20/4 = 5
4x9 = 45
45x5

and get the answer

225

is that wrong? if so are you aware why im doing it wrong 😭

[gleaming granite]

I don't believe this is right, try being more thorough and I think you'll notice why this is wrong

[slow saffron]

.close

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[placid zinc]

The side lengths of D are 5 times bigger than that of A

But the area is not

[lone heart]

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[regal lake]

Proof the inequality for a, b \in |R for a >b >=0

And for which a and b is the inequality equal?

[lone heart]

@regal lake Has your question been resolved?

[regal lake]

<@&286206848099549185>

[lone heart]

@regal lake Has your question been resolved?

[regal lake]

<@&286206848099549185>

[lone heart]

@regal lake Has your question been resolved?

[lone heart]

@regal lake Has your question been resolved?

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[last dagger]

i need help

[last dagger]

it's pre cal

i don't get it I tried what i know and it still didn't work

[alpine sable]

uh

for 7

[last dagger]

7 and 9

[alpine sable]

try putting 3 into the number of real zeros box

[last dagger]

8*

[alpine sable]

and see if its right

[last dagger]

its wrong

[alpine sable]

fuck

try putting

3,1,0

[last dagger]

still

[alpine sable]

okay 1 sec

[last dagger]

i know you have to get the possible roots and then use synthetic division for it but it didn't work and the teacher never finished the question in class

[alpine sable]

try 4

and then try 5

see if either is right

[last dagger]

there wrong

[alpine sable]

istg

[last dagger]

ik man i hate this shit i don't get it

[alpine sable]

ik how to get the positive and negative roots

[last dagger]

i put it in desmos and there was no roots so i tried to put 0

[alpine sable]

idk what the hell the 3rd part means

try putting 3,1,0,0

[last dagger]

still wrong

[alpine sable]

is the question before this similar

#6

[last dagger]

x is the real zeros

[alpine sable]

try just putting 1

[last dagger]

still wrong

[alpine sable]

yeah im just lost too

you'll have to wait for someone else

[last dagger]

aright man thanks for trying tho

[alpine sable]

alright i got 1 last idea

try putting just 3,1 in

@last dagger

[last dagger]

Still doesn’t work

I’m pretty sure I used that before

[alpine sable]

@last dagger i'd say repost the problem and ping helpers

[last dagger]

ok thanks

@alpine sable actually nvm i got some people to help me figure it out

thank you for the help tho and 3,1 did work i thought it didn't because i could have sworn i put it in before and it came back as wrong

.close

[lone heart]

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[mossy parrot]

hello

[mossy parrot]

give me 1 second im takinga picture of my question

for question 1

i just want to know if my setup

is right

i did cylendrical form so i have the first interrgal from 0 to 2pie , raduis from 1 to 2 and z from 1 to 3

is that right ?

<@&286206848099549185>

[plucky sluice]

Yeah, those bounds sound correct

@mossy parrot

[mossy parrot]

Thank you so much

[lone heart]

@mossy parrot Has your question been resolved?

[lone heart]

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[wide marlin]

can someone confirm my answer?

[lone heart]

@wide marlin Has your question been resolved?

[wide marlin]

<@&286206848099549185>

[alpine sable]

didnt you already do this shit

[wide marlin]

Yea but I’m not sure if it’s what you said

[alpine sable]

i said a because it matches the normal line at x=0

[wide marlin]

Ok can you help me check another one then?

[alpine sable]

sure

[wide marlin]

is d correct?

[alpine sable]

hm lets see

im not great at derivatives but that looks correct to me

if its not d then idk what it would be

[wide marlin]

ok

can someone else confirm on the previous answers

[alpine sable]

^

[wide marlin]

<@&286206848099549185>

[acoustic island]

I'll check this for ya, seems like you just apply the quotient rule to find the derivative, then compare your computed derivative to those choices

[wide marlin]

ok please check both thanks

[acoustic island]

i think D is correct for the second question, here's my work if you want to read it over

[wide marlin]

can you do the first

one

[acoustic island]

i'll check the first

[wide marlin]

ok ty

@acoustic island any update?

[acoustic island]

my bad, took me a little longer than i expected to write up

was trying to be thorough so i could check

haven't done calc by hand in a little while so it was nice to brush up on this

wait hold on i miswrote

[wide marlin]

ok

[acoustic island]

check this

earlier i shifted the wrong term around at the end

[wide marlin]

are you sure this is right

[acoustic island]

where do you disagree

i can also try to clarify a step if you'd like

[wide marlin]

idk

[magic pagoda]

Rino

[wide marlin]

hi

[magic pagoda]

Hi

Can you help me with me math

?

[wide marlin]

no

[wooden wave]

I need help

[magic pagoda]

Bruh

[wooden wave]

I cannot open my own help room. And I have a question that need solving

[wide marlin]

.close

[lone heart]

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[analog nymph]

can someone check to see if my logic is correct?

[analog nymph]

oh and btw this is not from an assignment or quiz/test/exam, it's from:

[lone heart]

@analog nymph Has your question been resolved?

[analog nymph]

<@&286206848099549185>

[analog nymph]

im gonna assume its correct

.close

[lone heart]

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[last hatch]

Can you someone please explain to me how I can manipulate the left side to equal the right side?

I got 1 + cos(2t) = to 2cos^2(2t)
I did get sin(2t) - cos(t) = to 2sin(t)cos(t)-cos(t)
So my equation looks something like this, 2cos^2(2t) / 2sin(t)cos(t)-cos(t)

What further can I do? I am very confused. You do not need to solve the question for me, but give me a direction to go. Thank you guys!

https://cdn.discordapp.com/attachments/1172422952185253929/1172422952344621116/image.png?ex=656042f6&is=654dcdf6&hm=03678153a54f0b714abc549dbcd0211d6858d54648c8fd4131e4646a06e413f0&

[lunar tide]

expanding cos2t and sin2t might help

[last hatch]

i expanded 1 + cos(2t) = to 2cos^2(2t)
and i expanded sin(2t) = 2sin(t)cos(t)

[lunar tide]

mm

factor out cos(t) from the denominator

[last hatch]

so divide it out of 2cos^2(t)?

[lunar tide]

yes

[last hatch]

.close

.close

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[grim pumice]

Honestly, I had to look up the steps to this problem in Symbolab, but since I don't have the paid version, I cant see the jump here. I must be blanking or something, but I have no idea which Log Rule turns one into the other. Can anyone explain how it gets from the first to the second?

[deft sage]

what us log2(4)

[grim pumice]

why does it say you're a likely spammer

[deft sage]

idk, i have to verifiy number probably

[grim pumice]

ah

log2(4) is 2 right

[deft sage]

ye

[grim pumice]

5-2 is 3- 3/3 is 1 though, no?

[deft sage]

yep

[grim pumice]

and if im just simplifying that down, how does it remove the log from the other side

[deft sage]

well log of what makes 1

[grim pumice]

uhh

like u mean like log10(x)=1?

🤔

[deft sage]

log2(x) = 1

[grim pumice]

o

2

[deft sage]

so that means x-1 = 2

[grim pumice]

oh wait

distributing the log2?

or wait no

where did u get log2(x) = 1

[deft sage]

ok wait lets substitute first x-1 = u

now we have log2(u) = 1

u=2

so x-1=2

[grim pumice]

hmm

[deft sage]

this was just an example

[grim pumice]

ohh

ohh i see

it confused the shit out of me when it said "log rule" cause i was expecting it to use some fancy rule instead of like. . . just simplifying it down normally 😭

[deft sage]

hahahhaha, nah its just that simple

[grim pumice]

i was overthinking it!

yeah my brain is just not functioning. im on hour 14 at school rn. got here at 9:30am, and im sitting in an empty campus at bout midnight now trying to get hw done before i go home and get distracted, and my brain is just not wanting to cooperate

[deft sage]

why would you stay so late though?

[grim pumice]

cause i can only get work done at school

as soon as i go home, i have either a comfy bed or my pc to instantly distract me

and i wont ever be able to stay focused, ever

[deft sage]

what do u study btw

[grim pumice]

like major or just level of math rn?

[deft sage]

ye like in what are you majoring or like what direction you are going

[grim pumice]

mechanical engineering atm

im in pre-calc rn

gotta take calc 1, calc 2, calc 3, differential, linear

[deft sage]

ohh thats nice, ususally i hear people go on mechanical engeneering

[grim pumice]

yeah

well im between mechanical and biomedical

we'll see

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[dreamy crow]

Hey y’all. Could anyone please give me a tip on how to do this problem. I have already tried completing the square and some other methods but that got me nowhere. I honestly have no clue what to do. Thanks

[gray isle]

what "other methods"

[dreamy crow]

Honestly not much I tried doing it integration by parts but that didn’t help

[gray isle]

since the denominator isn't factorisable here, you could express the integrand in the form:
$$\frac{m\cdot g'(x)}{g(x)} + \frac{n}{g(x)}$$

[ocean seal]

ℝαμΩℕωⅤ

[dreamy crow]

What’s n and m

[gray isle]

constants

for you to determine

[dreamy crow]

How do I find them

[gray isle]

do the manipulation/decomposition

what's the derivative of the denominator?

[dreamy crow]

Sorry English isn’t my first language is the denominator the bottom one?

[gray isle]

yes

[dreamy crow]

6x-4

[gray isle]

for what constants m,n will
5x + 31 = m(6x-4) + n

[dreamy crow]

m=5/6

n= 34 1/3

Oh wait nvm

I had n wrong

Which functions is g(x)

[gray isle]

g(x) is the denominator

,w m(6x-4) + n when m=5/6 and n = 34 + 1/3

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ramonov

[gray isle]

something off

[dreamy crow]

How so?

[gray isle]

nvm

thought wolfram should've simplfied that

anyway integral of the first term will involve log
and you can complete the square for the second term which will get you something with arctan

[dreamy crow]

When you say integrand does that mean the whole function im integrating?

[gray isle]

yes

[mellow grail]

could writing this as $1 - \frac{3x^2 - x -20}{3x^2 - 4x + 11}$ help?

[solemn juniper]

Editing in a ping doesn't ping them

[mellow grail]

oh 💀

[ocean seal]

ItzKraken

[mellow grail]

@gray isle

[gray isle]

what do you plan on doing after that?

[lone heart]

@dreamy crow Has your question been resolved?

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[rapid canyon]

so how do i calculate if

i take a random number (0 to 9) 32 times and put it together.

then i remove all cobinations where the same number is used more than 4 times in a row

how woud i calculate this?

[narrow garden]

pnc and probability I suppose

[rapid canyon]

pnc?

[narrow garden]

Permutations and combinations

Okay look

Consider that you get the same number 4 times in a row in the first go

Then you have 28 spaces with 10 numbers, 10^28 possible combinations but multiplied by 10 too as any number can repeat

So 10^29

Then these 4 can be 1-4, 2-5 and so on up till 29-32 which is basically 29 numbers

So 10^29*29 is the possible combinations where you might have the same number repeated 4 times

And 10^32 are the total combinations

So probably 10^29(1000-29) = (10^29)(971)

Not sure

I'm in a car going back home so I couldn't give it much thought but this should be the thought process

[rapid canyon]

okay thx

.close

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[icy nymph]

Can someone tell me what they get for part b pls

[zealous lichen]

,rotate

[lone heart]

@icy nymph Has your question been resolved?

[gray isle]

did you do part a)?

the two parts are linked

[lone heart]

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[icy nymph]

Yes

.reopen

[lone heart]

✅

[icy nymph]

I got 8/25 for part a

[gray isle]

jsut 8/25?

where are the x and k

[icy nymph]

.close

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[lone heart]

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[bleak smelt]

Triangle ABC has vertices A(2,1), B(10,4) and C(5,13). Hence find the area of triangle ABC

[bleak smelt]

I already found the exact value of sin angle ABC and cos angle ABC

What are the next steps

[slender gull]

Do you know determinant?

[bleak smelt]

No, what is determinant?

[slender gull]

No, nevermind.
If you did know, it'd have been much easier.

Anyways, you can find the side lengths too using the vertices.

And then use area = 1/2ab * sin(C)

Or something like that.

[bleak smelt]

Okay thank you I'll try that method

[lone heart]

@bleak smelt Has your question been resolved?

[bleak smelt]

Could someone explain the question a bit more

*Explain how to get to the answer of the question a bit more

Because the answer is 87/2 and I am not getting the answer

[bleak smelt]

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[north mulch]

Stupid question but Would it be possible for 0x to be equal to anything other than 0 for example 0x=1

[rich escarp]

no

0x=0!=1

[gray isle]

using != for not equals doesn't read well here

[north mulch]

What about 1x=0 and 2x=to smth

[gray isle]

with
1x = 0
multiplying both sides by 2
2x = 0

[north mulch]

Oh ok

Thanks

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[alpine sable]

I have to show that left-neutral elements are generally ambiguous. But I can't get any further because, for example, e_1 = e_1*e_2=e_2 and therefore they are always unique?

[alpine sable]

xD

[vale crag]

@vivid garnet don't multipost, 1 channel, 1 person

I'll come in yours

[alpine sable]

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[mortal trellis]

well in the first equality you used that e2 is right neutral? what happens if thats not the case

[alpine sable]

.reopen

[lone heart]

✅

[alpine sable]

but both are left neutral but I see ur point. So two left neutral elements aren´t the same?

[mortal trellis]

well you didnt use that e2 is left neutral

[alpine sable]

Yes I see it

[mortal trellis]

if e2 is both then its a proper identity

and you have uniqueness

[alpine sable]

But is it possible to have two different neutral elements

[mortal trellis]

I think so. you just need a less nice operation

[restive igloo]

ho

hi

[alpine sable]

Well to be honest I don´t know how to show it properly

[mortal trellis]

what other properties do you need to satisfy for your operation?

you could just take two elements x,y which are not the same and then define all results of one times another so that they are both left neutral

[alpine sable]

But how does it show that both left neutral elements aren´t unique. Lets assume we have a left neutral element which is e_1 * x = x and the another element e_2y=y . x and y arent the same. But since e_1 and e_2 are left neutral. Doesnt it mean that I can say e_2x = x and e_1*y=y. So e_2=e_1 and they are unique

[mortal trellis]

no

you can for example define xx=x, xy=y, yx=x, yy=y

by definition x and y are both left-neutral

[alpine sable]

So are u saying since e_1 x= x and e_2 y=y and x unequal y --> e_1 is unequal e_2

[mortal trellis]

e_1=x and e_2=y. they both work

since you can verify that e_1 a=a for all a and e_2 a = a for all a (where a can be x or y)

[lone heart]

@alpine sable Has your question been resolved?

[alpine sable]

I dont understand this man.

How does this show that they are not unique

[mortal trellis]

I have the set M={x,y}

I define the operation $\cdot:M\times M\to M$ by $x\cdot x=x, x\cdot y=y, y\cdot x=x, y\cdot y=y$

[ocean seal]

Denascite

[mortal trellis]

and then by definition, x and y are both left neutral for the operation

but by definition of them, they are different

[alpine sable]

Yes

[mortal trellis]

hence, left neutral elements do not need to be the same

[alpine sable]

Anyone here can help me with quadrants🥲

[alpine sable]

Ok so the idea is basically just taking two different elements from the set which have different left neutral elements by definition?

[mortal trellis]

the phrasing is a bit off

elements dont have left-neutral elements

the operation has left-neutral elements

which are x and y in this case

pretty much because of how I defined what the operation does. I defined it to be that way

[alpine sable]

Ok thank you for your time!

.close

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[flint otter]

Can someone help me to solve this

[flint otter]

@compact mirage can you help me ?

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@flint otter Has your question been resolved?

[flint otter]

@obtuse sonnet can you please help me to solve this ?

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@flint otter Has your question been resolved?

[flint otter]

<@&286206848099549185>

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@flint otter Has your question been resolved?

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[leaden aspen]

There is no inverse to this function because the same bit strings can be output from different bit string inputs right ?

[mortal trellis]

can they?

if yes then give an example

[leaden aspen]

(1010101010) and (1111111111) come out with the same output from this function

*I think haha

transitions being (1010101010) -> (1111111111) -> (11111) -> (10101) -> (1100110011)
(1111111111) -> (101010101010) -> (00000) -> (01010) -> (0011001100)

am I correct ?

[mortal trellis]

you apply 4 functions so there should be 4 steps

[leaden aspen]

ahh i see i missed the first step in the second example

so there is an inverse ?

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[leaden aspen]

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[wide sable]

need some clarification here because I am confused

[wide sable]

i factored all of them out to

14a - 21a^2 = 7a(2-3a)
6a^2 + 13a + 6 = 3a(2a+3)2(2a+3)
4a^2 + 12a + 9 = 2a(2a+3)3(2a+3)
9a^2 - 4 = (3a-1)(3a+2)

Once I rewrite my expression with the new factorization, I am so confused on how I simplify from there.

If someone is able to teach me how that would be great

[lone heart]

@wide sable Has your question been resolved?

[upper stone]

many of the factors will cancel out

assuming you did your factorization correctly (i didn't check) the denominator of the first fraction will pretty much completely cancel out the numerator of the second fraction

[wide sable]

I just watched a video that helped me solved it, thx

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[crimson shore]

WHERE IS @static tree ?

[crimson shore]

I Demand an audience.

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[jagged cobalt]

what on earth

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[alpine sable]

So I have the distance from B to the line, how would I then get that closest point on the line to B?

[alpine sable]

<@&286206848099549185>

[upper stone]

find the vector projection and then add it to point A to get a new point C

to find the distance from point B to point C use the distance formula

[alpine sable]

🤦‍♂️ so simplee...

thank you!

.close

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[pallid shadow]

so basically im doing this

im on step 4, for step 1 to 3 i wrote a function that worked perfectly

now i get an error here

[sour dove]

hi I don't know matlab very well but I am in CS.

So what it's telling you is that the value of z2 is negative

you're trying to call a reference for the position of z2 and it's not liking it because you can't have a negative index with arrays

[pallid shadow]

my value of z2 is z2 = 1 + 2i

[sour dove]

right that's not an integer, that's a complex number

it's like this

[pallid shadow]

but it works just fine with z1

thats what i dont get

[sour dove]

can you show the full code?

[pallid shadow]

and it worked before

can i copy paste it to ur dm?

[sour dove]

yeah sure

[pallid shadow]

so thats the code

i can also send you the function version for general cases

which, as i said, works just fine

[sour dove]

yeah can you do that too?

is angle() defined somethere or is that something that is given to you by matlab?

[pallid shadow]

its given to me by matlab

[sour dove]

ah yeah I see the doc now

...huh

let me mull it over one moment

[pallid shadow]

another thing is

the first time it stops on line 33

the rest of the time it stops on line 12

if you clear all it once again stops on line 33

[sour dove]

huh

well at least it's failing in the same place (where it's calling angle())

[pallid shadow]

yes

so thats the issue i need to solve

but what is another way of getting the angle of a complex number

passing it to polar form maybe

but idk, it works just fine at first

ok, i did something in the main one

i just put

function [results] = rotation_scaling_UO302282(z1,z2,alfa,beta, lambda1,lambda2)
z1 = 1+1i;
z2 = 1+2i;
lambda1 = 2;
lambda2 = 3;
alfa = pi/2;
beta = 3*pi/2;
%function to determine the complex numbers z1 and z2 as well as lambda 1
% and lambda2

% A real number lambda1 to scale z1's modulus
z1 = z1 * lambda1;
...

so basically in the function one

i substituted for values

(so the function is basically useless)

and it works

well

if it works it works

it gets me my results

[sour dove]

aaaaaye

nice

[pallid shadow]

but im still confused over what went wrong

[sour dove]

yeah I'm not sure. I'm looking through forums right now with that error message and using angle() and not getting very far

[pallid shadow]

when deleting the function

[sour dove]

here trying running this command real quick and screenshot the results
which angle -all

[pallid shadow]

ok lemme try

where do i run this command? im kinda new in matlab and just know basic stuff

[sour dove]

oh ummm

lemme find out haha

[pallid shadow]

if i run it on the command window this pops up

[sour dove]

aaaaah

yeah see there where is sasy "angle is a variable"?

you're basically overwritting it

[pallid shadow]

ooohh

[sour dove]

can you open that file real quick and see where declaring that?

try changing that reference name (and also all the palces it's called) and try again

what's happening is called a race condition where this variable is defined somewhere and it's a crapshoot whether or not matlab is going to call that or the intended angle() function

[pallid shadow]

ohhh

thats why it lets it run 1 time in z1

then blocks on z2

and then blocks again on z1

function p = angle(h)
%ANGLE Phase angle.
% ANGLE(H) returns the phase angles, in radians, of a matrix with
% complex elements.
%
% Class support for input X:
% float: double, single
%
% See also ABS, UNWRAP.

% Copyright 1984-2010 The MathWorks, Inc.

p = atan2(imag(h), real(h));

this is what says

so i should clear the angle(z1) after doing angle(z2)

[sour dove]

no wait

hmmm

that's the code from that file?

[pallid shadow]

yes

[sour dove]

...the hell?

haha

[pallid shadow]

well, dont overthink it, it works now

so i just sent it

xD

[sour dove]

there ya go

[pallid shadow]

im a future engineer

if it works

who cares how its done

[sour dove]

lmao

amen brother

[pallid shadow]

amen

[sour dove]

okay glad you got that resolved!

[pallid shadow]

u2, u really helped me understand some matlab better

good rest of the day!

.close

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[sour dove]

you too!

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[subtle blade]

for this problem, to find acceleration would it be sum of u-direction forces so Friction - Wu = ma?

[subtle blade]

so then it would be (0.1)(mgcos12)-mgsin12=ma?

and solve for a?

[deft sage]

there are 2 forces that drag it down (negative) friction (0.1)(mgcos12) and gravity mgsin12 so they would add up instead of that

[subtle blade]

@deft sage isnt friction positive since its pushing up the incline?

to prevent the crate from slipping down the incline

[deft sage]

but the initial velocity is going up

so friction will slow it down instead of pushing it

[subtle blade]

ohh i see

could you help me draw a free body diagram?

so ican understand this better

[deft sage]

sure

[subtle blade]

i thought it was something like tthis?

where going up the incline is the positive direction

[deft sage]

generally the friction would be opposite to the gravity

but in this exact case, the direction is 'up', so friction would push it the opposite way 'down' gravity here does the same thing

after the body reaches a velocity of 0, then the friction pushes 'up' against gravity

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[gusty dust]

I’m just lost

[alpine sable]

yo

i gotchu

[gusty dust]

yup

[alpine sable]

so since that line divides that one big triangle into two triangles

you have 45 degrees for both automatically

cuz 90/2=45

[gusty dust]

but what if it’s not straight in the middle

Cuz it’s not

[alpine sable]

Well then i have no idea what else it could be, but let me solve the y and x for you and try putting it in

[gusty dust]

okie dokie

It don’t look like it

[alpine sable]

wait

nvm

nvm

[hot bluff]

look at the two tick lines

[alpine sable]

i solved a stupid way mb

[hot bluff]

what does it mean when a triangle has two similar sides

[gusty dust]

it’s isosceles

[hot bluff]

good, so whats an easy angle we can find for that isosceles triangle

[alpine sable]

hes getting at that the two base angles are equal

[gusty dust]

dunno

[hot bluff]

a straight line is how many degrees

[gusty dust]

180

[gusty dust]

So x is 20

[hot bluff]

think we can find the missing part of that?

[gusty dust]

o

[hot bluff]

yes

x = 20

[gusty dust]

I did the math wrong

Wait tho

[hot bluff]

think you can find y now?

[gusty dust]

how u do this one

x and y

So y is 5

but how get x

[alpine sable]

the equilateral triangle has all angles being 60 degrees

[gusty dust]

yup

[alpine sable]

then you can use it for the isoceles triangle

oh wait nvm

[hot bluff]

you cant assume its isosceles

[alpine sable]

you’re looking for x and y

not angles thats mb

[gusty dust]

okie dokie

so how u do it

[hot bluff]

same concept

[gusty dust]

ok ok

So 60

• 180

and

that’s like

20

how get x

[alpine sable]

180-60=120

[gusty dust]

I forgot the 1

wait

[alpine sable]

then bonglord is right we cant assume its isoceles but idk how to find x in any otehr way

[gusty dust]

Is it isocolese

if all size is 40

And other is 40

and 2 sides congruent

That means is isocoles

[alpine sable]

x would be 30 if it was isoceles

[hot bluff]

think about the big triangle

[gusty dust]

what big triangle

[alpine sable]

the two together

[gusty dust]

it ok we done with that

teamwork made dream work

next

only one more after this trust

cmon guys

more teamwork

[faint monolith]

simultaneous equation

[gusty dust]

no can do?

[faint monolith]

can u do simultaneous equations?

[gusty dust]

idk

Oh

[faint monolith]

one triangle is equaliateral and one is isoceles

[gusty dust]

I thought

u meant

[faint monolith]

u can set up a order of operations

and solve

[gusty dust]

Stimanious questions

like u not allowed to asked more than 1

yea I got it

Thx

[faint monolith]

np

[lone heart]

@gusty dust Has your question been resolved?

[lone heart]

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[gusty ocean]

some help me wt all questions plz

[gusty ocean]

<@&286206848099549185>

[jagged cobalt]

people dont like opening files

just send images

[gusty ocean]

oh

[tacit arch]

!ss

[lone heart]

Please post images (such as PNGs or JPGs) of the question rather than other filetypes such as PDFs which have to be downloaded. Non-image downloads can potentially contain viruses or other security risks.

[tacit arch]

Also just ask ONE question to work on first

And you should try it yourself

[gusty ocean]

k

there we go

can someone plz help

[tacit arch]

"Test the pairs" means plug in the numbers to each of the equations in a,b,c

[gusty ocean]

wdym by that im dum

[tacit arch]

(0, -5) is a pair of (x,y)

Plug it into y = 3x-7 and the other equation to see if they're both true

True for that point (0,-5) would mean
-5 = 3 * 0 - 7, does it equal?

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[royal crystal]

no clue wher to start

i was told to rref it but then it only has 3 pivots

[empty moth]

Well first one is not bad

Just write it as a sum of 4 vectors

Then combine all of those vectors into rref

See if there is any nullity columbs

If there is

Get rid of those vectors

Then the basis would just be the remaining vectors

Dimension is the amount of elements in the basis

[empty moth]

a + 2b - c = 0

2a + 3c = 0

You can easily find the matrix whose kernel is that

It should be

1 2 -1

2 0 3

[lone heart]

@royal crystal Has your question been resolved?

[royal crystal]

oh shoot

[royal crystal]

dont even know what this means

[royal crystal]

When i rref it has 3 pivots

[empty moth]

Then

The dimension is 3

[empty moth]

A column without a pivot

[royal crystal]

doesnt that mean that S isnt a span of a set of 4 vectors in r4

[empty moth]

What

[royal crystal]

idk

thats what the questions asking me to prov

dont i need 4 pivots to prove that its a span of 4 vectors in r4

<@&286206848099549185>

[lone heart]

@royal crystal Has your question been resolved?

[royal crystal]

<@&286206848099549185>

[lone heart]

@royal crystal Has your question been resolved?

[empty moth]

what???

absolutely not

they don't have to be linearly independent

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[vale gulch]

why is this still wrong

lol

[gray isle]

you didn't identify all the products that result in a y^3 term

[vale gulch]

wym

how many is there god dayum

(5) (2y) (4y^2)?

[gray isle]

that's one of the ones you missed

[vale gulch]

one? 😭

(5y^2) (-9) (-2y)

is there anything else

[gray isle]

that seems to be it

[lone heart]

@vale gulch Has your question been resolved?

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[lone heart]

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[granite badger]

what about it

[lone heart]

@rapid basalt Has your question been resolved?

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[alpine sable]

pretty sure its -3/4 but my teacher says its 3/4?

[slender gull]

Your teacher would be right here.

if both, cosine and sine of an angle are negative, wouldn't their ratio be positive?

[alpine sable]

oh wait

sorry i misread

sin a

i thught that meant sin a > )

0

oh ok thanks

!close

how do u close?

.close

[lone heart]

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[vapid shuttle]

I'm trying to follow a proof for this, but I am missing what is going on at one of the steps

it states

[ocean seal]

Austin

[vapid shuttle]

I'm confused about how in the third integral, they got the absolute value sign on f

[ocean seal]

Austin

Austin

[vapid shuttle]

could anyone explain?

[rose sigil]

i don’t understand the confusion

[remote heron]

should i try to help ill probably be wrong, but isnt this just from absolute value

[vapid shuttle]

we need the absolute value sign inside the integral to get the conclusio

n

[remote heron]

like a < |b| -> -b < a < b

[vapid shuttle]

yes that is what we want to use

but I don't see how they got the absolute value sign, inside the 3rd integral in my first textit

[remote heron]

oh, im dumb

[rose sigil]

austin take the thing before the implication

[vapid shuttle]

yes

[rose sigil]

just with the negative sign

[vapid shuttle]

yes

integral -f <= int |f|

[rose sigil]

then multiply by -1

[vapid shuttle]

integral f >= -int |f|

ah

done

[vapid shuttle]

https://tenor.com/view/hug-love-hi-bye-cat-gif-5848836

[vapid shuttle]

https://tenor.com/view/hug-love-hi-bye-cat-gif-5848836

I tried that

but I did it wrong

poop brain

ty

.close

[lone heart]

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[fresh flame]

2w√80w+√(45w^2 )

[alpine sable]

i thbink i can do that question

is it just simplify? @fresh flame

[glacial patrol]

!nosols

[lone heart]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[glacial patrol]

wot I just say

[fresh flame]

this is how far I get.

[alpine sable]

what si the question asking?

[fresh flame]

simplify

correct

[storm musk]

Then just seperate √5 and √w^2

[alpine sable]

for the second root

[glacial patrol]

!nosols

[lone heart]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[glacial patrol]

Jesus

[alpine sable]

you can just get sqrt w

yeah

[storm musk]

Ok

[fresh flame]

I'm sorry this is a little hard to follow

[storm musk]

What would √(w^2) be

[alpine sable]

got it

basically you go from that last step

which is

[fresh flame]

oh ok

I just

this?

[alpine sable]

Yep

[fresh flame]

ok thank you

[alpine sable]

U can continue

And like factorise ig

Idk if that’s needed tho

[fresh flame]

I do need to

i just put it in and it's like

do it again

the problem is

how do I factorize when one side is \sqrt(5w) and the other is \sqrt(5)

[alpine sable]

i mean you can factorsie a w

thats the common factor

[fresh flame]

I'm not sure what you mean?

[alpine sable]

if you have (ab+ac)

you get a(b+c)

same thing here, the variable w is in both terms

[fresh flame]

yeah so like

if it's 8w√5w+3√(5w^2 )

how can I factorize

if one side is squared and the other is not

[alpine sable]

we got to this step right

[fresh flame]

sorry a better question is

[alpine sable]

in both terms, it is multiplied by w, in 8w and 3w

[storm musk]

Put an absolute sign around the w

[fresh flame]

OH

gotcha

ok we are factoring the outside

[glacial patrol]

!nosols

[lone heart]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[alpine sable]

broski we get it

[glacial patrol]

Then stop

[storm musk]

Stop what

[glacial patrol]

Giving sols

[alpine sable]

then stop 🤓

bro we hvaent been giving any solutions

[fresh flame]

.close

[lone heart]

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[errant dagger]

practice test

[errant dagger]

how is this wrong>

case of all

• case of 1

• case of 2

the fuck

anyways yeah

.close

[lone heart]

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[faint monolith]

The city council estimates that a typical house uses 64 Litres of water a day just in the kitchen. This is 9.2% of the total household water usage. Estimate the total use of water by a typical household in one year. Round your answer to the nearest 1000 Litres.

[faint monolith]

I did $9.2/100 * x = 64$

[ocean seal]

`

[faint monolith]

Then i got 16000/23

then i multiplied the result by 365

and i got 254000L rounded

but chatgpt says its 23000L

what did i do wrong

[vapid shuttle]

!nogpt

[lone heart]

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

[faint monolith]

o

ok

so am i right

or wrong

[cyan drum]

that is correct

but what is the x you are calculating