help-0

[spare fern]

Okay so when I do that I get the distance travelled to be 15.95m

Is this correct?

@jagged cobalt

[jagged cobalt]

i seem to have something different

oops one moment

nvm, still different

what did you do?

[spare fern]

4.88m?

[jagged cobalt]

80 something

[spare fern]

That can't be right

[jagged cobalt]

,w integrate (1.2sqrt(x))

[ocean seal]

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[spare fern]

Oh not that question

I meant this

[jagged cobalt]

oh right

,w integrate (6-5/(x+1)) from x=3 to x=4

[ocean seal]

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Requested by aldrnari_

[jagged cobalt]

seems so

[spare fern]

Alright thanks

I just get confused on how to integrate for these type questions

So if it asks "How far did the object travel in it's 8 seconds of motion" I would find the integral from 0 to 8 of v(t) right?

And if it asks "How far did the object travel in it's 8th second of motion" I would have to find the integral from 7 to 8 of v(t) right?

[jagged cobalt]

yeah

[jagged cobalt]

also yeah

[spare fern]

Oh okay, yeah I get it now.

Thanks for clarifying 👍

[jagged cobalt]

👍

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[sour bridge]

Original qn is: f: R->R
f(xf(x)+f(y)) = (f(x))²+y

[sour bridge]

||P(c,x) ; c any constant => f is surjective
P(k,x) ; f(k) = 0 => ff(x)=x
P(f(x),y) =>( f(x) )² + y = x² + y => f(x) ={+x,-x}||
||Now the point wise trap||
||let a,b such that f(a) = a and f(b) = -b; with a,b != 0. Then by P(a,b) we get:
f(a²-b)=a²+b
Case 1: f(a²-b) = a²-b
=> a²-b = a²+b => b = 0 (contradiction)
Case 2: f(a²-b) = -a²+b
=> -a²+b = a²+b => a = 0 (contradiction)||

Can smb check this soln

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[sour bridge]

. reopen

.reopen

[lone heart]

✅

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[gritty pond]

How can I find a functions with images being f: R-> R ?

[ocean seal]

cookie2

cookie2

cookie2

cookie2

[gritty pond]

Anyone know what this even means lol?

[pseudo ice]

f1 outputs all possible real numbers, f2 outputs just positive numbers, f3 inputs real non-integers, and f4 outputs only integers

[f1, f2 and f4 should be relatively easy to find examples of, f3 might need a bit of thinking for...]

[lone heart]

@gritty pond Has your question been resolved?

[gritty pond]

So in that case, how are these functions?
i: f(x) = x
ii: f(x) = e^x
iii: attachment #1
iv: attachment #2

[pseudo ice]

Because for each possible input, you have one and only one output

Hopefully plotting x and e^x should show why their images are all real numbers and strictly positive real numbers respectively

[gritty pond]

yes

[gritty pond]

What do u think about iii and iv? i feel like im cheesing it

[pseudo ice]

Those work, f3 would have been the hardest of them all to think of an example, but yours is something that I would have thought of

[gritty pond]

Do u know if there's a non piecewise function that works for f3?

and f4?

[pseudo ice]

[for f4, you could e.g. take the floor or ceiling of x]

[gritty pond]

Wdym?

[pseudo ice]

floor rounds you down, ceiling rounds you up

[gritty pond]

Are there actually notations for that lol

I've probably never seen one then

[pseudo ice]

Yep, $\floor{x}$ for the floor and $\ceil{x}$ for the ceiling

[ocean seal]

@pseudo ice

[gritty pond]

The hell

Never seen that notation in my life

[pseudo ice]

Well now you have

[gritty pond]

So if x was replace by pi

for the floor function

it become 3?

and 4 for the ceiling?

[pseudo ice]

Yep to both

,calc ceil(pi)

[ocean seal]

Result:

4

[pseudo ice]

,calc floor(pi)

[ocean seal]

Result:

3

[gritty pond]

What is this

[pseudo ice]

can't remember, think that rounds you to the nearest integer if I recall properly, though I might be wrong on that one(!)

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[jaunty spade]

is my first step correct

[jaunty spade]

i dont think it is but idk how else to approach this question wihtout using integration?

umm what do i do

[vale wigeon]

$g(x) = \exp[3f(x) \ln(f(x))]$, apply chain and product rules to get a formula for $g'(x)$.

[ocean seal]

Ann

[jaunty spade]

ok let me try that

wait g(x)=3f(x)lnf(x)????

[vale wigeon]

no

i did not say that.

[jaunty spade]

what does exp mean

[vale wigeon]

$\exp(z) = e^z$

[ocean seal]

Ann

[vale wigeon]

i am using this notation for convenience

[jaunty spade]

so g(x)=e^(3f(x)ln(f(x)) then?

[vale wigeon]

yes that is what i said.

[jaunty spade]

okk ty

umm how do i proceed since i dont know f(x) or ln(f(x))

or is this evem correct

[alpine sable]

this seems correct to me!

[jaunty spade]

okk i thought so, but how do i proceed and find g'(0) since this equation has both f(x) and ln(f(x)) which i dont know?

[alpine sable]

hmmm but you do know what f(0) is

[jaunty spade]

no, whats in the question is all i know

so f'(0)=3x+2

and i cant use antiderivatives cause its not been taught yet

[alpine sable]

No that's wrong

[jaunty spade]

oh

[alpine sable]

you are misinterpreting

[jaunty spade]

is this why ive been stuck bruh 💀

[alpine sable]

the equation of any line is $y = mx+b$, with $m$ being the slope of the line and $b$ being the $y$-intercept of that line

[alpine sable]

so like Include the tangent to it here

[jaunty spade]

ok so f'(0) is 3 then?

[alpine sable]

yes

[jaunty spade]

and f(0) is 3x+2?

[alpine sable]

no

that doesn't make sense even how are you evaluating at x = 0 but still getting an expression with x? 😅

[jaunty spade]

😔

[alpine sable]

anyways like this is the tangent line of the function f(x) at x = 0

meaning the equation of the tangent line, y, and the function f(x) share a common point at x= 0

if you evaluate the tangent line at x = 0 you also find f(0)

[jaunty spade]

umm so f(0)=2?

[alpine sable]

yeahh

[jaunty spade]

ohhh ok

and ln(f(0)) would just be ln(2) then?

[alpine sable]

yeppie

[jaunty spade]

omg yay

so basically i have everything i need to solve now?

[alpine sable]

yeah just plug and chug 😎

[jaunty spade]

omg yayy

[alpine sable]

alrighty I trust you for the rest with the algebra as I have to go now 😅

byebyee

[jaunty spade]

okk tysm

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[storm verge]

What do i do with the curve ontop of 2 and 4

[tacit arch]

What's the question

[storm verge]

Whag are the zeros

What*

The end behavior, what is a

[tacit arch]

What's a

[storm verge]

Also the x any y intercepts

[storm verge]

Solving for a

[tacit arch]

What is a

[storm verge]

I dont know how to describe a

[tacit arch]

What were you told the definition of a is

[storm verge]

Lemme check my notes

Uh sry for wasting your time cause i cant even find what a is or its definition in my notes or the presentations provided by my school ;w;

[vale wigeon]

are the instructions for your problem written down anywhere?

[storm verge]

Nope

I think cher didnt put any instructions as he taught us last last week how to solve the problem ;w;

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[torn pawn]

for starters all i got is maximize p= 2x+y+z

not sure what to set the variables to

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@torn pawn Has your question been resolved?

[torn pawn]

<@&286206848099549185>

https://tenor.com/view/angai313-spongebob-sad-spongebob-crying-gif-21679826

i figured it out

.close

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[spiral lotus]

question: where did the t+4 go? xD

[noble frost]

0*(t+4)=0

[coral flower]

multiply t+4 on both sides

[spiral lotus]

o h

[noble frost]

unless t=-4

you can do that

[spiral lotus]

ok this makes sense, tyyy <3

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[prime seal]

find all X for which this holds true

does this have solution?

because i came to this

0=1 and that is vontradicuton

[mellow knoll]

if you've got a contradiction then theres no solutions

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@prime seal Has your question been resolved?

[rare gale]

,rotate

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[gleaming lily]

I'm having a problem with a question in my Mathematics class in computer science. Let me break it down.

We have a set A containing the following 5 sets:
{1}, {2, 3}, {2, 4}, {1, 5}, {5, 6}

We have a set B containing the following 3 sets:
{1, 2}, {2, 3, 4}, {5, 6}

Let R ⊆ A × B be the binary relation defined as
(X, Y ) ∈ R ⇐⇒ X ⊆ Y

How can I describe the relation R?

[gleaming lily]

I first need to map it with arrows, something like this:

but connected by arrows

So far I've come to the conclusion that:

{1} --> {1,2}
{2,3} --> {2,3,4}
{2,4} --> {2,3,4}
{1,5} (not sure about this one)
{5,6} --> {5,6}

{1,5} is the only part I'm struggling with

[echo socket]

Why do you think there should be a set S from B s.t. ({5, 6}, S) is in R?

If there's no such S, then just don't mention any pairs containing {5, 6}

[gleaming lily]

I dont really know what you mean by this. Sorry

[echo socket]

R is just {({1}, {1, 2}), ({2, 3}, {2, 3, 4}), ({2, 4}, {2, 3, 4}), ({5, 6}, {5, 6})}

That's it

[gleaming lily]

So {1,5} and {2,4} map to nothing?

[echo socket]

No, they don't

Ah wait

{2, 4} does, my bad

[echo socket]

It's fixed now

[gleaming lily]

Alright, {1,5} to nothing then

[echo socket]

But {1, 5} still does not map to anything

[gleaming lily]

I thought that to start but I wasnt sure because I then have to say if theyre total, single-valued, injective and surjective

And given {1,5} maps to nothing, it cannot be total, single-valued or injective

I'm still not sure if its surjective or not, the definitions I find are very unclear. I know that the broader definition states that every element in the co-domain must be mapped to however I'm not sure if every element in the domain needs to be used. Can you help with this definition?

[echo socket]

Not every element from the domain needs to be used to prove surjectivity

Is surjectivity in your case defined only for functions or for relations in general?

[gleaming lily]

Simply checking if the relation R satisfies it or not. No mention of functions.

"For each of the properties listed below state whether R satisfies it or not."

So I would say relations in general

In which case it would be surjective i guess

[echo socket]

Alright, this R is indeed surjective then

[gleaming lily]

Would I be right in saying R is not total, single-valued or injective?

[echo socket]

I think it is single-valued though

Assuming by that you mean that if (x, y) and (x, z) are both in R, then y = z

Is that your definition?

[gleaming lily]

The definition I've been working with is "To be single valued it must map each input to at most one image"

[echo socket]

Yeah, that's the same

[gleaming lily]

Oh I see how that could be seen as single-valued

[echo socket]

This R is single-valued

[gleaming lily]

becuase 0 is at most one isnt it

[echo socket]

Right

[gleaming lily]

Cool, thanks for all your help. I really appreciate it 🙂

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[radiant quarry]

I need help with this riddle please.

47 21 63
27 48 95
16 35 ?

[radiant quarry]

<@&286206848099549185>

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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[radiant quarry]

ok

[mortal trellis]

joke answer: 42, because the polynomial f(x) = -72 + (183013 x)/168 - (21180617 x^2)/10080 + (2430277 x^3)/1440 - (4024453 x^4)/5760 + (23257 x^5)/144 - (60533 x^6)/2880 + (14491 x^7)/10080 - (1619 x^8)/40320 has values f(1)=47, f(2)=21, ..., f(8)=35 and f(9)=42

[radiant quarry]

Joke answer?

I do not need jokes.

Sorry,

[limpid spade]

No jokes! He's serious

[mortal trellis]

the point is more that riddles of these form always have more than one solution because you can make up a solution

like I did

[radiant quarry]

It has a pattern.

[mortal trellis]

yes. the polynomial I gave

[radiant quarry]

I am too dumb for that.

[subtle birch]

well, if you could provide any options, it would really narrow down possible solutions

[radiant quarry]

It isn't 49

[zealous lichen]

calculate the difference of each column

[radiant quarry]

😎

[vernal prawn]

I doubt it's 1364189472 either

[zealous lichen]

the pattern is kinda obvious

[radiant quarry]

Please tell me

[limpid spade]

Do it yoursel

[radiant quarry]

Please

I need my left arm please

[subtle birch]

27-21=6

[limpid spade]

Math hard

[radiant quarry]

Yes

[zealous lichen]

oh wait

I can't do subtraction

[radiant quarry]

Why not?

[limpid spade]

Because it's hard

[radiant quarry]

Reverse continuation from a, b times.

[limpid spade]

I would rather solve TDSE with a time dependant complex potential

[radiant quarry]

a - b = a <- b times

[mortal trellis]

could also be 113204/1689 because then the matrix is singular

[radiant quarry]

What

[mortal trellis]

jokes aside, I dont see the pattern

[radiant quarry]

Goodbye then

I failed so I must leave

.close

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[candid pike]

i can find a and c

but when i try for b i get it wrong

nvm

.close

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[past gull]

i need help on q54

we havent learnt quadratic inequality yet

[opal jolt]

substract 2 on both sides

operate so you only get one fraction

when is a fraction positive?

[alpine sable]

Yea it would seem so

But actually you have to times the top and the 2 by (x^2-4x-5)^2

To solve the quadratic inequality

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[alpine sable]

Yo give me a second @past gull

[past gull]

yo

ok

[alpine sable]

@past gull

Hopefully that helps

[past gull]

yo tysm

thats so hard

[alpine sable]

Yea

It's ext 1 work (if you're in Australia)

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[calm willow]

herro

[calm willow]

,, \sum_{n=0}^{\infty}\frac{5+2n}{(1+n^2)^2}

[ocean seal]

HeccinTech

[calm willow]

how in the fucc do i calculate the convergence of this

its literally my last question and im so stucc

what i have tried

i have tried breaking them up in to different equations like 5/((1+n^2)^2) + 2n/((1+n^2)^2)

and knowing 5 goes to zero ur left with

2n/((1+n^2)^2)

i know it converges to 1/4

but this doesnt proove it

im so stucc

i tried to also do limit testing

but that shiets its self because n goes to zero

and by limit comparison test n is supposed to start at 1

so

can someone with neurons that actually fire

take a shot at this

cuz my neurons have decicided to stop existing

[lone heart]

@calm willow Has your question been resolved?

[calm willow]

<@&286206848099549185>

[deep basin]

сссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссссс

[calm willow]

man

<@&286206848099549185>

<@&286206848099549185>

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@calm willow Has your question been resolved?

[tiny finch]

help

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[wraith gazelle]

Yo

[wraith gazelle]

I need help again

I can't even make sense of this question

Anyone??

Can any of yall atleast explain what I should do

I am confused

Hello???

[pseudo ice]

Maybe try describing the set they ask you about in words?

[magic haven]

or you can try drawing a venn diagram

[analog sierra]

Bro

Just use de Morgan's law

Or whatever it's called

[magic haven]

that always helps me when i thinkof set operations on two sets

[wraith gazelle]

Tf is Morgan's law

[wraith gazelle]

I am gonna do that wait

Okay so

How do I draw this in a Venn diagram

[wraith gazelle]

A minus B union B minus A ??

[pseudo ice]

Kinda: I meant more like “stuff in A that isn’t in B, and…”

[wraith gazelle]

The thing is, I don't know which one is greater

It just says both A and B are non empty sets

[analog sierra]

A-B is A intersect. ~B

[wraith gazelle]

Oh

Does that work like that

Damn I have forgotten algebra

B-A= -B?

[wraith gazelle]

Thanks bro

I still don't understand

[lone heart]

@wraith gazelle Has your question been resolved?

[wraith gazelle]

I got it yall

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[zenith belfry]

The characteristic polynomial of this system is $-(\lambda - 4)^{3}$. I'm confused on finding the general solution to this system since the solutions are repeating (multiplicity of 3). Any help is appreciated!

[ocean seal]

zoga

[limpid turret]

If I recall.... If $f(t)$ is a triple solution to your DQ, then your three homogenous solutions are $f(t)$, $t\cdot f(t)$, and $t^2\cdot f(t)$.

[ocean seal]

SWR

[lone heart]

@zenith belfry Has your question been resolved?

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[vague needle]

A and b

[lone heart]

Please don't occupy multiple help channels.

[vague needle]

<@&286206848099549185>

[lone heart]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[upbeat eagle]

What do you know

[tacit arch]

close one of your channels

[vague needle]

I think the quadratic function of the first graph is f(x) = -2(x-3 ) ^2

[vague needle]

Ok

[exotic canopy]

can't be -2

[upbeat eagle]

That makes a sad face graph

-#

[vague needle]

2(x-3)^2

[exotic canopy]

yes

[vague needle]

Yes because it's upwards

[exotic canopy]

mhm

[vague needle]

And the second one

[upbeat eagle]

y= a(x-h)^2 +k

What do you know

About Graph 2

[vague needle]

Is that right

[upbeat eagle]

Thats how the form goes

[vague needle]

f(x) = -x^2- 2.5x + 1

Graph 2

[upbeat eagle]

Yep its correct

[ocean whale]

Plot it in desmos and check

[upbeat eagle]

You can just sub in x = -2, and -1 and see y value

[ocean whale]

That too

[upbeat eagle]

Funny question how did you get that?

[vague needle]

Ok

[lone heart]

@vague needle Has your question been resolved?

[vague needle]

Are you sure

Quadratic equation for graph 1

[exotic canopy]

yes

same thing as 2(x-3)^2

[vague needle]

Yes

[lone heart]

@vague needle Has your question been resolved?

[vague needle]

Not yet

<@&286206848099549185>

[vague needle]

I think this is wrong

And this too🥲

Are u sure

[vague needle]

?

[upbeat eagle]

For the second graph

This is correct

[upbeat eagle]

.

[lone heart]

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[tardy nebula]

how can I rationalize this?
$\frac {1}{K \sqrt{K+1} + (K+1) \sqrt{K}}$

[ocean seal]

beautiful man

[limpid turret]

Painfully

Multiply top and bottom by $K\sqrt{K+1}-(K+1)\sqrt{K}$.

[ocean seal]

SWR

[tardy nebula]

oh, so just the conjugate, i thought there was something more

i rushed and expanded the brackets

thanks

.close

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[gritty pond]

Anyone know why this is true?

[gritty pond]

x here is cartesian product apparently

How does the and symbol turn into cartesian product?

[ocean seal]

cookie2

[lone heart]

@gritty pond Has your question been resolved?

[coarse vale]

Here, x denotes all the elements of A and C together (no reputation of common terms).

Same with y with the case of B and D.

As x and y are variables, think of them as sets containing all the elements of A and B ; C and D respectively ||(respectively means for the 1st variable takes the 1st value and 2nd variable takes 2nd value (always used to think why I need to give them respect...))||.

And a Cartesian product can be denoted by (x, y) for which both x and y are values.
And × is another notation for when u want to use the name of the set.

So it's just teaching the notation, not anything complicated till this point.

[lone heart]

@gritty pond Has your question been resolved?

[gritty pond]

So let me get this straight

If there's a x e.g. cartesian product symbol anywhere in the proof question, I make it (x, y) right?

If there is no x cartesian product symbol, i just make it x ?

[coarse vale]

Yes, but it depends on what the question wants you to do.

Please send the whole question if any

[gritty pond]

is a and b a subset of A? why or why not?

$$A\cap B \subseteq A$$

[ocean seal]

cookie2

[coarse vale]

Tell me what do u understand by A∩B

[gritty pond]

x is in A and x is in B

[coarse vale]

Correct.
That means x is in A too.

[gritty pond]

Is (x is in A) the same as saying (x is a subset of A)?

[coarse vale]

So what is the problem with this question that u are facing.

[gritty pond]

$$\in=\subseteq$$?

[ocean seal]

cookie2

[gritty pond]

oh wait

[coarse vale]

What do u understand by subser.

[gritty pond]

is x not a subset?

x is element right

[coarse vale]

Yes

[gritty pond]

subset of A means that this area is just part of A?

[coarse vale]

The selection of all those "x"s is a subset.

[gritty pond]

Part of A and it can also be

$$A \subseteq A$$

[coarse vale]

Subset means it's inside of the set.

[gritty pond]

?

[ocean seal]

cookie2

[coarse vale]

Yes.

[gritty pond]

Ok makes sense

[coarse vale]

now tell me is A U B will be a subset of A Or not.

[lone heart]

@gritty pond Has your question been resolved?

[lone heart]

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[warm arch]

Hi i need help on #3 and #4 and im not sure if im doing this correctly

[long axle]

Well if X is a discrete RV such that X~Unif[5,8]

Find pmf of X

[warm arch]

Okay are 1 and 2 correct?

[long axle]

Uh lemme see

Yea they look right

[warm arch]

okay thank you

ill try 3 and 4 now

.close

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[vernal lance]

where did I mess up in this distribution with [1-cos^2x]? I multiplied it with sinx

[vernal lance]

sorry if it's very obvious

[long axle]

(1-cos^2)* sincos^2 = sincos^2 - sincos^4

[vernal lance]

oh so you multiply [1-cos^2x] with the entirety of sinxcos^2x?

I was distributing sinx

[tribal haven]

ye, have to distribute everything

$$(1-1)\cdot2\cdot3= 0 = 2\cdot3 - 2\cdot 3 \ne 2 - 2\cdot3 = -4$$

[ocean seal]

IV

[tribal haven]

sometimes constructing small sanity checks helps

[vernal lance]

yeah I think it makes more sense now

thank you for helping

.close

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[grand mountain]

not sure how to do this, could anyone help?

[grand mountain]

i understand that

[high rapids]

Yeah look up exponent rules

[grand mountain]

thats not the issue, its a negative exponent on the right tho

[vapid shuttle]

Your problem is the exact same as that

It doesn’t matter

[grand mountain]

i have to express it as positive exponent

[snow furnace]

well, what happens when you subtract a negative number

[grand mountain]

^ forgot to mention this MB

[high rapids]

Just do it brother

You will get positive I promise you

[bright lichen]

anyone know this??

Educational institutions – Suppose that someone can buy multiple licenses for Word Search Maker software (for making word puzzles) at a total cost of C(x)=24√(20x^2+250) dollars for x software disks. Do not include the units in youir answer

a. Find the marginal cost function rounded to 4 decimal places at x=200

answer

b. Find C(201 ) -C(200) rounded to 4 decimal places

answer

c. Are the answers close? Type Y for yes and N for no.

answer
N

[grand mountain]

go into anotha thread dawg

[snow furnace]

#❓how-to-get-help

[bright lichen]

thanks

[grand mountain]

im so stupid i overcomplicated it @high rapids

i tried flipping -1/4 to make it positive

and got 1/3 as my answer

its supposed to just = k

[snow furnace]

so

$k^{\frac{3}{4}}/k^{-\frac{1}{4}}=k^{\frac{3}{4}-(-\frac{1}{4})}$

also, you cant just flip the exponent, a negative exponent different

[ocean seal]

InfinityMango

[snow furnace]

https://www.youtube.com/watch?v=TKj8kEofbAw

[high rapids]

Org chem is the goat

[snow furnace]

he has carried me since my freshman year of highschool, if you ever dont understand a concept he probably has a video on it

[high rapids]

Bro's a wizarding genius

[lone heart]

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[mystic holly]

welll

im not sure

but is this where you do

1/csc(x) ?

[exotic canopy]

no

i'm pretty certain this is arccsc

so like, inverse of csc

[exotic canopy]

may be not obvious but can you see that csc^-1(x) = sin^-1(1/x)?

[vapid steppe]

why

[exotic canopy]

what is csc in terms of sin

csc, not csc^-1

[vapid steppe]

csc=1/sin

[exotic canopy]

mhm

[vapid steppe]

why doesnt csc^-1 = 1/sin^-1

[exotic canopy]

why would it

[vapid steppe]

cuz csc = 1/sin

[exotic canopy]

but it doesn't work like that with inverse functions

look

csc(y)=x

solve for y

[vapid steppe]

oh when u take arccsc of both sides you get x=arccsc(1/sinx)

[exotic canopy]

y=arccsc(x)

[vapid steppe]

ye

[exotic canopy]

but csc(y)=1/sin(y)

in that case

1/sin(y)=x

solve for y

1/sin(y)=x
sin(y)=1/x

therefore, y=arcsin(1/x)

[exotic canopy]

which is what i claimed

[exotic canopy]

does that make sense?

[vapid steppe]

oh ye

[vapid steppe]

then what

[exotic canopy]

then you get arcsin(3/2sqrt(3))

[vapid steppe]

which is arcsin sqrt3 /2

=pi/3

[exotic canopy]

yep

there you go

[vapid steppe]

wait

,w arccsc(2sqrt3/3)

[ocean seal]

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[vapid steppe]

oh wow

[exotic canopy]

magic, right?

[vapid steppe]

ye lol

[lone heart]

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[rustic bronze]

Hello math expert. I know a lot about politics and I argue about politics a LOT. But one thing I'm not good at is MATH. I'm so bad at it. I'm currently faced with a math problem I cannot answer with 100% honesty and truthfulness. I am all about having the truth go out to the people

[rustic bronze]

Here is the information I have

The first image is the graph of the demographic of people who rape animals

The second image is the demographic numbers of people who are apart of the furry community

What I am trying to find here is the correlation percentage of each statistic

Here are factors I'd like to contribute

1. Gender
2. Race
3. Age range

[violet urchin]

first of all

[rustic bronze]

I'd like to find how similar these groups of people are by percentage

[violet urchin]

those are random google statistics

[rustic bronze]

the number I've gotten is

That's correct

[violet urchin]

random google stats are not credible

you cant use them to make good faith arguments

secondly

thats a weird ass question buddy

[rustic bronze]

You're right by the images show the source and the source provides the info. But that's off topic

I know its a weird ass question and I'm sorry

I'm not a math guy, I'm just a political debater

the number I've gotten is 99.18%

[violet urchin]

clearly a bad one given you use questionable sources

[rustic bronze]

But I'm not good at math again

[rustic bronze]

The first image is from JAAPL

[violet urchin]

how'd you do that??

[rustic bronze]

but I didn't think we'd get into this debate

[violet urchin]

the other ones arent even from the sources themselves

[rustic bronze]

THis is JAAPL

[violet urchin]

theyre google excerpts

you haven't even read the damn sources on those in full

[rustic bronze]

Correct but the google excerpt takes from the source which is "Furscience"

and the other source is

Furry Fandom Wiki

[violet urchin]

and your reason to believe something called "furscience" is credible is...?

[violet urchin]

you are joking...

[rustic bronze]

Becaues it's the home of the furry community

[violet urchin]

you must be a garbage debater

ngl

[rustic bronze]

Who better to ask of the demographic of furries than the furries themselves

[violet urchin]

if youre using freaking fandom wikis

[violet urchin]

next youre gonna tell me you went on 4chan to find info

the hell

[rustic bronze]

Riddle me this. If you wanted to find info on the backrooms, the best person to ask is the backrooms wiki writers is it not?

[violet urchin]

but thats entirely fictional

[rustic bronze]

This is unrelated we're getting very off topic

Please remove emotion

[violet urchin]

its really not?

if youre using questionable statistics

you get questionable answers

[rustic bronze]

Yes. All I'm trying to find is the numbers

[violet urchin]

and thats bad math

[violet urchin]

but they are bad numbers

and misleading

[rustic bronze]

I have all the sources you'd like I'm not an anecdotal type of guy

They're not misleading. They're almost intertwined with each other and by my findings 99.18% intertwined

but I may be wrong

thats why I need your help to get the true number

[violet urchin]

you have 2 sources related to the demographics and they aren't credible

if you cite that shit people will laugh in your face

[rustic bronze]

The JAAPL is not credible?

[violet urchin]

the other 2

the google results

[rustic bronze]

https://jaapl.org/content/jaapl/early/2019/05/16/JAAPL.003836-19/F1.large.jpg?width=800&height=600&carousel=1

[violet urchin]

what exactly did you find are 99.18% intertwined?

you have 3 categories

which ones are intertwined with which?

because you are looking for statistics

statistics are very different from fictional info

for info that is not based in reality you can ask the people who believe in it

you don't have any actual informatino on the demographics because the fucking furry wiki isn't a credible source

its not political

youre doing bad stats

its mathematical

anyone who is an actual data scientist

who would have access to the resources necessary to perform a decent study

that is entirely false

and an assumption that comes from where?

for all you know they pulled them out of their asses

you cant do data analysis on data you don't know is accurate

yes but if youre part of the academic community its much more unlikely

and these people are...

not

so find me actual studies

and then you can do data analysis

you ARE the god damn misinformation

youre promoting fake stats

ok then

show me the methodology of the studies done to find them

show me the authors of the study

show me those author's careers

show me the institutions theyre associated with

hmmmmm

they do seem to be backed by some actual reu's

what do their statistics have to do with their skill in math

one is data collection

the other is analysis

hmm

alright

lets say i believe these stats

how'd you get 99.18%

Ok ok hold on

Explain why you are doing these

What

No

Explain why you’re doing the addition

Is that covariance or something

Why is that statistically relevant

The sum I mean

I do not care whether or not you do mental math

What relevance does the sum have

What is the significance of the sum of those percentages

What

No??

Why would it do this

What are you applying

What theorem or statistical use

Shouldn’t be

If you’ve taken statistics

You should know the names

Then you aren’t qualified to do statistical analysis

??

Maybe instead

You should be focusing on statistics that’s been done

The numbers you got aren’t really relevant to anything

Of course it didn’t you made up random formulas to use

Why do you think that

Do you even know the correlation function

No no

Like

Have you calculated correlation

There’sformulas for this

What if I told you that’s because most crimes committed are by men and most nerds are men

Or most people with weirder hobbies are men

That doesn’t follow

At all

Your analysis is flawed

Dude

If you don’t know anything about statistics

Don’t do statistical analysis

You think you see patterns

They don’t work

There’s probably a correlation to be found

I’m sure

But it’s not going to be as high as you think it is

At all

No

Lmao

It’s probably around a quarter of that

I’m just eyeballing

But like

No

Please just quote professional research

Until you know stats

You aren’t the right person to do that yet

Since you dint have information

It’s a good goal tho

Nope

You kinda aren’t

No you don’t

Lmao

You haven’t taken stat

No but this server is for learning math not getting others to validate your weird dislike for furries

This server isn’t for validating your personal phobias for other people

Please go somewhere else fox this question

Well

You shouldn’t be

Not because of what you are trying to accomplish

But because you are unqualified

You can’t combat misinformation if you dint even have information

[soft finch]

please chumchumlol for the love of god go learn some statistical analysis

im not an expert, but the fact that 86% of animal rapists are male and 84% of furries are male does not constitute evidence of a correlation between furries and animal rapists

where is that number coming from

THE SAMPLE SIZE IS 60

yes i could guess that

where was the study done

yes

are you serious

these are just people found randomly on omegle?

quizzes*

you did this?

you conducted this study?

YOU WHAT!?

yes I know and i'm just going to ignore the fact that that's really messed up right now

Yes. It's my opinion that it's wrong to deceive and manipulate people into trusting you with information they wouldn't have otherwise

YOU DON'T SEE A PROBLEM WITH THAT!?

YOU CAN'T JUST MAKE THAT GENERALIZATION

I agree, but this is not an example of that

[real gazelle]

yeah this has gone on long enough

.close

[soft finch]

especially because you went in not thinking that furries are raping animals

[lone heart]

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[violet urchin]

You said you wanted to give these numbers to organizations. What analysis could you possibly do that would be better than the analysis of the phd statisticians those organizations already have

[lone heart]

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[tranquil tulip]

How does the limit when b is infinity on 2arctanx = pie

[long axle]

arctan(infinity) = arctan(1/0) = pi/2

That’s why we say tan(pi/2) is undefined

Therefore 2arctan(1/0) = 2 * pi/2 = pi

@tranquil tulip

[tranquil tulip]

How does 1/0 get pi/2?

[long axle]

Do u know what tan(pi/2) = ?

Aka tan(90)

[tranquil tulip]

yes nothing

Or 1/0

[long axle]

Wdym by nothing

Correct 1/0

So if tan(pi/2) = 1/0

Then arctan(1/0) = pi/2

[tranquil tulip]

Ohhh ok, I understand that part now but how does the arctan(inf.) get to (1/0)

Why do we use pi/2 specifically

[long axle]

Range of arctan is (-pi/2, pi/2)

[tranquil tulip]

Ohhh ok

Is the range of arcsin and arccos pie to -pie

[long axle]

,w arcsine

[ocean seal]

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[long axle]

,w arccosine

,w arctangent

[ocean seal]

Results provided by WolframAlpha

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Requested by northsteve

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by northsteve

[long axle]

There

[tranquil tulip]

Woah

[long axle]

Wolfram gives the ranges for all 3

And look at the last image

lim x-> infinity arctan x = pi/2

[tranquil tulip]

Ok thank you so much

[long axle]

Np

[tranquil tulip]

.close

[lone heart]

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[elfin kernel]

for this one, the sum is 1

[elfin kernel]

so I thought it should converge

but my book says its divergent?

but I thought divergent was only for plus minus infinity and stuff that does not exist

[long axle]

How’s the sum 1

Take n=1

1 + 1/1 = 2

[elfin kernel]

Oh i meant limit

I was following this snippet

[long axle]

$\sum_{n=1}^{\infty} 1 + \frac 1n= \sum_{n=1}^{\infty} 1 + \sum_{n=1}^{\infty} \frac 1n$

[ocean seal]

Stephen

[elfin kernel]

we can split it up like that?

interesting

[fickle heath]

Funny thing is even the last sum diverges

[elfin kernel]

what does this mean ;-;

am i not suppose to take limits?

[fickle heath]

$\sum_{n=1}^{\infty} \frac 1n$

[ocean seal]

Nel

[fickle heath]

This one diverges

[elfin kernel]

and since this one diverges the whole thing does i see

[fickle heath]

I mean Stephen showed you it gets split into this one plus another one that very obviously diverges

My point is, even if the individual terms converge to zero, the sum may still diverge

[elfin kernel]

got it

cool thanks

.close

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[humble oak]

Can someone

help

[pseudo ice]

You could go by contradiction maybe?

[humble oak]

If thats the case

if A is invertible

what does that tell us

I recall the professor wanted us to stay away from determinants

[pseudo ice]

Well if A was invertible, and A^2 = 0, what's the value of A?

[ionic jewel]

the determinant way is the easy way :dismay:

[ionic jewel]

assume A is invertablw... then A^2= 0...

AxAxA^(-1) = 0xA^(-1)

@humble oak does this first step in the contradiction proof help at all

do you see how to continue to finish the contradiction?

[humble oak]

can you explain where you got this AxAxA^(-1) = 0xA^(-1)

[ionic jewel]

right multiply both sides by the inverse of A

@humble oak

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[faint frost]

i’m supposed to identify similar triangles and find each measure

[stark crater]

Do you see which triangles are similar

[faint frost]

HGD and HGJ

because of angle angle

[stark crater]

Yeah

I assume that 2x-2 is just for GD right

[faint frost]

yes

[stark crater]

Ok you can find another set of similar triangles. Think about what angle DJH must be

[faint frost]

wdym

[stark crater]

Since HGD and HGJ are similar, that means you know angle GHD and angle DJH are the same

[faint frost]

ah

wait

oh yeah third angle theorem

which helps me how?

[stark crater]

Try drawing all the triangles side by side in the same orientation and see if you can find the ratio between any of them

[faint frost]

ok

alright i found

so tedious

x = 8

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[cunning trout]

how do I show this on the complex plane?

[narrow garden]

e^ix

this is your standard e^ix format for a complex number

cosx + i*sinx

Which is a circle centred at the origin with radius 1

[cunning trout]

oh i see

wow ok

makes sense, thank you

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[cunning trout]

waittt that’s sus

[fair stratus]

?

[cunning trout]

because the ans shows a linear line graph

[fair stratus]

well yeah, Re(z) is the x coordinate and Im(z) is the y coordinate. Just plot x+y = 1

[errant thunder]

Yeah. Its easier to think of Re(z) and Im(z) as your x and ys on the cartesian plane. And yes, its just a linear line graph

[cunning trout]

i see

ok thanks for the clarification guys

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[shadow sparrow]

I have to solve this using Bayes Law/Theorem

[solemn juniper]

indeed

[shadow sparrow]

I'm just kinda confused on breaking down the problem, I guess

I have P(A), P(A|B), and P(A|B')

[solemn juniper]

what are A and B?

[shadow sparrow]

and P(B)

0.94 and 0.06

Husbands employed and not employed

[solemn juniper]

A is 0.94 and B is 0.06?

[shadow sparrow]

Or is it 1/2 and 1/2?

1/2 chance its a husband and 1/2 chance its a wife?

[solemn juniper]

so P(A) = P(0.94) = ?

[shadow sparrow]

It has us doing tree diagrams for it like this

[solemn juniper]

generally these questions are easier if you apply more natural letters to the events

[solemn juniper]

so try using H and W for the event that the husband or wife respectively is employed

[shadow sparrow]

Yeah

Well so what I'm debating is how I would want to first write this out

In this example of "rains" and "does not rain" for the first tree

I was thinking "Husband employed" and "husband not employed"

but I feel like thats wrong

[solemn juniper]

why do you think it's wrong?

[shadow sparrow]

I guess because I have no idea how I would solve for when the husband is unemployed

[solemn juniper]

solve for what?

[solemn juniper]

read the third sentence of the question again

[shadow sparrow]

Yeah, at least a husband or wife had to be employed

Which is also what confuses me

[solemn juniper]

so if the husband isn't employed

[shadow sparrow]

Yes, the wife has to be

[solemn juniper]

indeed

[shadow sparrow]

I just don't get how you would know.

[solemn juniper]

because the question tells you directly

[shadow sparrow]

What that percentage would be for the wife

I know that, I meant how would you tell what the chance for the wife to be employed would be seperately from the husband?

[solemn juniper]

if the wife has to be employed, what is the probability that the wife is employed? (conditioned on the husband being unemployed)

[shadow sparrow]

1?

[solemn juniper]

1

[shadow sparrow]

So the other one would be 0

Then its

(0.96*0.72)

for the success

and (0.960.72)+(0.041) for all possible occurrances of the woman employed?

[solemn juniper]

what's a "success"?

[shadow sparrow]

good branch, good result, good path, success

is used in another area

Basically just good results divided by possible results for what its asking for

Which is a employed woman with a husband

[solemn juniper]

an employed woman with an employed husband would be preferable

[shadow sparrow]

Yeah

So Bayes for this question would be..