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Closed by @sharp wharf
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What is 1+1
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Closed by @night geyser
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what is cardinality of n ?
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only total functions can have inverses right?
because if its not a total function it cant be injective?
total functions can be injective. Injective just says $\forall y_1,y_2 (f(y_1) = f(y_2) \implies y_1 =y_2))$
992qqoloy
If f(y1) or f(y2) doesn't exist then obvs theyre not equal
So the implication is true since the start is false
@orchid perch Has your question been resolved?
you can just make the domain smaller and then you have a total function
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How can I graph the function F(n) = the sigma notation formula above in Geogebra?
That summation makes no sense
You are summing from 0 to 0. Idk about geogebra but if you thought you knew how buts it not working, that is probably the issue
are you sure you didn't screw up this notation
cause it looks screwed up to me
You’ll just have 18x, 36x, 54x, …
Wait what
n to n
Sorry, yes you're right it's a problem of variables.
18n is the intended equation
I haven't tried putting it in Geogebra as I have not found a way of doing it
This still makes no sense
hm
You do not sum from n=smth to n
Cuz that would just be 0
Maybe you want something like k=0 to n of 18k
I'm not sure I do understand what you're saying
starts at n=0. f(0) would be 0, yes. f(1) = 18. f(2) = 0+18+36
the pattern continues
For f(1)=18 example, you are saying n=1, but the sum says n=0, which is it?
what sum are you refering to
Whoops did not mean to reply to that
Basically what im saying is your defining the same variable as 2 different values
n=0 indicates that, for example, f(3) would be f(0)+f(1)+f(2)+...
if n=1 then we would have f(3)= f(1) + f(2) +...
this is how I understood this at least
I get what you are trying to do, im just pointing out a notational error
That if you try to enter in geogebra or any other calculator will cause errors
I think you just need to stare at it for a minute and think about this
Yeah I fail to grasp what I have done wrong
do you mind showing what the correct notation is supposed to look like?
Change the circled n’s to any letter besides n
normally we use i,j,k
but as long as its not n it is fine
The majority of the sigma notations do look indeed like you're way of doing it, okay
can you explain why putting n here doesn't work, though?
Yeah
Tell me what the n at the top of the sigma is equal to
If you are trying to do f(3)
okay, then I believe I got it
Btw from my 1 minute google search it appears you would do something like
f(n) = Sum(18i, i, 0, n)
Ok I have came to the conclusion that plotting it is impossible (you can still calculate values though, it just wont plot it). ChatGPT also agrees with me but its knowledge only goes back to sept 2021
@swift tangle Has your question been resolved?
apologies for late reply
thank you for going through the hassle for me, it’s a bummer tbh that it doesn’t allow it
maybe converting it to one of those (n-1)n functions will work for some of the notations
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Percent changes
$____ increase by % = $
$_____ increase by %= $_
$____ decrease by % = $
$_____ decrease by %= $
10,20,25,35,40,50,60,70,75,80,90,100
Rules:Use each number once
Fill in the gap with the given number
chill
alright
dont ping anyone till 15 min
sorry
whats your question?
i am new
Percent changes
$()increase by % = $
$()increase by %= $_
$()decrease by % = $
$()decrease by %= $
10,20,25,35,40,50,60,70,75,80,90,100
Rules:Use each number once
Fill in the gap with the given number
this
i don’t think so
is this off a worksheet?
ah gotcha
tysm
ok, easy peasy
alright
can you use a calculator in your exam
yae
super easy peasy
:0
fill in the numbers where ever
mhm
then we will calculate the money
exactlyyy
thats so stuipd
that what i was saying
alright
do you know how to do percents?
how fast can you do 25% of 60
pretty much
lol
alright well an obvious one is 10,100,20
mhm
25,60,75
figured
write those down and cross them out
done
cool
now for decrease
alright, what do you got
so now 10,100,20,25,60,75 is gone
oh alright
so, what's a trio that would work?
i mean, if you know how to do percents really well and your confident in your abilities, then I would ask an ai to just do it for you, as this is a pretty usless and tedious assignment
ik
i am confident
but the ai
isn;t working-
he doesn't understand the assimignet
im sure you can figure it out
alright
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how to get to the answer?
!show
Show your work, and if possible, explain where you are stuck.
well i tried it
fbd?
the free body diagram?
oh i havent learnt that? just draw the triangle separately?
ok no
oh-
Usually you would like to have the triangle towards up.
what do you think the measure of this angle would be?
25?
yea good
now, can you do components of normal vector along horizontal and vertical axis?
of vector n?
yes
Remember that drawing components, it should be drawn as dotted lines.
for x ais wouldnt that be Nsin25 and for y axis that would be Ncos25?
i drew that from snipping tool lol, i cant handle my mouse for making line dotted lmao
yes
from n1 you can get the value of n from that you can then find F from second equation
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Question number 3
When finding out a series of function
Do you first work out the difference between f(1), f(2), f(3) then work with the resulting ratio
Or is there a better method?
@vast sonnet Has your question been resolved?
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A person tried by a three-judge panel is declared guilty if at least two judges cast votes
of guilty (i.e. a majority verdict).
Suppose that when the defendant is in fact guilty, each judge will independently vote
guilty with probability 0.85, whereas when the defendant is in fact not guilty (i.e.
innocent), this probability drops to 0.25.
1
If 70% of defendants are guilty, compute the conditional probability that judge number
3 votes guilty given that:
(a) judges 1 and 2 vote guilty
is it 0.85×0.7?
no idea
basically I use bayes theorem
so probability that judges 3 vote guilty given the others have
is equal to probability that the others vote guilty given three does times probability 3 voted guilty over probability 1 and 2 vote guilty
i have probability 3 votes guilty
it’s 0.7*0.85
it’s not given 1 and 2 vote guilty tho
<@&286206848099549185>
@jade wasp Has your question been resolved?
these helpers aren't helping xD
<@&286206848099549185>
@jade wasp Has your question been resolved?
<@&286206848099549185>
<@&286206848099549185>
yes
hey man I'm stuck on this question
tell me
so basically I know I have to use Bayes theorem
I explained it above
@subtle flame Are you still here?
Cool it with the multiple Helpers pings. Those tend to make helpers annoyed at you, and therefore less likely to want to help at all, which is not in your interest.
@jade wasp Has your question been resolved?
Yeah then thag becomes k^2+16 for the discriminant I think?
yes
k^2+16 is strictly positive so discriminant is positive so two real roots
btw u need to go in the available channels for help
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stealing this :D
going through old exams trying to make sure im all ready for next week
a spiral is drawn with halfcircles with centrum alternating at A and B. Start with centrum in A with radius (?) r > 0 för the smallest halfcircle and continue with bigger and bigger halfcircles like in the picture. what's the total curvelength for a spiral that's built from n halfcircles? the answer should be as simplified as possible.
so, my attempt at this was something like this
first off, paint it on my own
and name each halfcircle L1, l2 etc
then make a small table to see the trend
and since the circumference is 2pir, this is pi * r
and then the radius increases with R each time, starting at 1 going up.
so now I want an expression for this that's applicable to the N'th halfcircle
so since we can see that we're just increasing by 1, we want to start at 1 and go up until n, multiplying m* pi* r and adding them together
which gives us this beautiful little thing
feeling all good about myself i decided to check the grading paper aaand
is my answer not good enough? or is it even possibly wrong?
would i possibly lose points for the way i wrote this? is there a better way to write this mathematically?
$\sum_{m=1}^n m = \frac{(n)(n+1)}{2}$
GarlicB
This is what is called a closed form
Generally, you want to get rid of sums, and most sums can boil down to a formula
but the formula itself is correct?
Yes
You basically are one step away from what they consider the right solution though
im looking at this and my brain outright refuses to accept that npir + 2npir + 3npir + 4pir is the same as 10pir
could also be that i've sat with math for too long today 😅
ok thank you for the help
wishing you the best <3
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How do you find the height of a shape when you only have the width and length?
what's the original question
@alpine sable Has your question been resolved?
This one, its in french but in translation its asking me to find the total area of the ramp.
are you given more info
This is the other page
But it doesnt really explain anything else..
Its just asking me to describe what type of shape these things are
It just basically gave me the width (1.2m) and length (2.4m)
I've asked it before, but to this day I'm still not sure
So I skipped it, but now I need to do this.
Help please

Someone

tu connais la pente de la piste?
si c'est incurvé ça semble impossible à calculer sans autre information
Non malheureusement.
Oui , j'ai parlé avec mon prof
Il m'a dit que je peux sauter ce question
Merci bcp! Je vais fermè ce probléme
@alpine sable Has your question been resolved?
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these are two geometric series.
do you know what a geometric series is, and how to find the sum thereof?
missing parentheses, but yes. they did.
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please can someone explain how SUVAT equations link to graphs?
The formulas of motions right?
yeah
It'd be better to refer an indivitual formula's graph at a time
Mostly in those equations time 't' is used in the X axis where 's', 'v', 'a' are used in the Y one
@slim chasm Has your question been resolved?
hmm
ok thank
@slim chasm Has your question been resolved?
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Can someone walk me through this problem
,tex .FTC2
riemann
can i replace my prime symbol with d/dx
yea try it
its not d/dt right
can i have d/dx in the front as well?
instead of the right hand side
...
i think i got it but im stuck on a part
i have d/dx[F(x^5)-F(x^3)]
so now i just do [ f(x^5)(5x^4) - f(x^3)(3x^2) ]
is that right
right
I have 5x^4 ln(1 + 4x^10) - 3x^2 ln(1 + 4x^6)
yes?
is that right?
yes
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Anyone help
do you understand what parallel and perpendicular mean?
@alpine parrot Has your question been resolved?
Jope
I do not
parallel means they do not intersect
What does that mean
Keep in mind I got a 0 on my maths test
And I’m in year 22
I mean 11
Should you not be on discord if you are 11?
@alpine parrot Has your question been resolved?
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How exactly do we get (sinu)/(1+cosu) and (1-cosu)/(sinu) from tan u/2 = +-sqrt((1-cosu)/(1+cosu))?
inside the sqrt
if you multiply the top and the bottom of the fraction by 1+cos u
u get 1-cos^2 u on the top
which is the same thjng as sin^2 u
and on the bottom you get (1 + cos u)^2
this is difference of squares btw
this is pythagorean identity
and this is just cuz ur multiplying it by itself
so if u have sin^2 on the top
and (1 + cos)^2 on the bottom
the square root of that is just sin / (1 + cos)
same principle for the other one
except this time multiply both sides by 1 - cos^2
top will become (1 - cos)^2
oops made a mistake
i’ll edit those portions
ok yeah
and bottom will become 1 - cos^2
or sin^2
same principle square root it
and you get (1 - cos) / sin
does that make sense sorta??
It makes a ton of sense!
A clarifying question if you've got the time: I'm trying to write this out so that I can see how it works.
go for it
Oh wait, no. I made a math error.
So we're eventually left with sqrt((sin^2u)/(1+cosu)^2), which we then take the square root of and are left with just sinu/1+cosu
yep
Sick.
that’s if you multiply both sides by 1 + cosu
Indeed, and if you multiply by 1 - cosu, we're left with 1-cosu / sinu.
yep
Rad. Hey, thanks a ton! You've answered this exactly the way my brain needed it to be answered. I really appreciate it!
lol no problem
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I am not sure the purpose of the proof. What am I trying to find and why am I trying to find it? Also how do we choose what value to shove in?
Please ping me if you reply
@empty bough Has your question been resolved?
@empty bough Has your question been resolved?
<@&286206848099549185>
@empty bough Has your question been resolved?
@empty bough Has your question been resolved?
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I tried implicit differentiation, which is essentially adding y' to y in the function
x^2 * y - 4x^2 = 0
First the Product rule
2xyy' + x^2y' - 8x = 0
send the 8x over and organize the y
y'(x^2 + 2xy) = 8x
y' = 8x/x^2 + 2xy)
now I'm not sure if I should factor the denominator, which would give me x(x+2y)
if I plug in (2,4). I get either 1.6 or 0.8
but it says both answers are wrong, did I make a mistake somewhere, perhaps when differentiating
im getting -8
what did you do differently to me?
well we have completely different answers for the differentiation
let me try yours
cause here it's asking for y' not dy/dx
same thing
ok
yea cause it's supposed to cancel out the x
You dont have to but u can
does it give the same answer?
yes
I'll do it again
alr
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i forgar on how to do the steps in i think pre algebra
I'm still not completed with my telepathy skills
So for now you have to send a pic of the problem for more context
Okay so you are supposed to solve for z?
i think
What have you tried?
well my friend said to just multiply the variables
MULTIPLY?
idk
Since we need to solve for z, we must isolate it on either side LHS or RHS
so what can you think of?
umm canncelling something out
Hint:||It's just adding a number both sides||
Add such a number so that the RHS only contains the 'z'
the number -8 would cancel out with the number added
$-3=z-8$\$-3+8=z-8+8$
B-eard
Adding '8' on both sides
wait so its 5=z
yes
welcome 
.close
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How do I do part ii?
@alpine sable Has your question been resolved?
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Struggling with problem 2 its not difficult I just dont understand what is happening
@alpine sable Has your question been resolved?
why is everyone but me and the other discrete math guy getting help
this is bullshit
@alpine sable Do you understand what you are being asked?
utterly no clue
also I cant do the truth table for P^S => R
We can start with #2
You have to come up with P, S and R such that P and S will imply R
I will give you an example, I think it's the best way
If you define
P : Visiting Canada
S : Visiting France
R : Visiting at least two continents
Then (P and S) implies R
Because if P and S are true, then R is necessarily true
so p and s have to be true
No, it means that if you suppose that they are true, then R will necessarily be true
I have utterly no clue what your saying
it is binary
it is true or it is false
All statements are true or false
isn't synonym of
For every statements, we know if that is true or false
You are assuming the latter
If the latter was true, why would the course even exist?
What do you want me to reply then?
ts
ts
ts = this shit
I replied ts
dude i just need to know how to write a truth table
idk how to write it if implies is involved
Do you think people will care to help you if you don't even care yourself?
im here bc I care
im trying to do math
not philosophy
for the love of god please help me
That's not what you said here though
im actually begging
why are we arguing about why im in math
ts is irrelevant
ill write you a 10 page paper in a day math just isnt my thing
Would you help is a soccer player if they don't care at all about playing
I'm sure you would not
im a soccer caoch I have tons of players that dont wanna play
i stil help them
bc its my job
You waste your time though
<@&268886789983436800> bro is arguing philosophy with me I just need help
like holy fuck why are you being so petty
<@&286206848099549185> for the love of god
I was trying to help you but you didn't even try to understand what I meant and said right away you didn't care about math, all of this even after you were being impatient for getting help (see the beginning)
wlmmm i don't think you being here is helping at this point
Alright, sorry 👋
i mean, their example was meant to help you understand the problem with a practical example
i dont think you have to be rude just for them trying to help
i didnt understand what he meant and then he barraged me with philosophy which I THEN PROVED WRONG
im on a time crunch
i was completely reasonable in what I said
I sent the example to get back on trakc but he wanted to continue shitting on me
liek holy fuck how are you defending him right now
with this
it was math until this
and then I explained myself
no need to keep pinging them after they left the convo
I pinged you
regardless, the point is that the statement:
(P and S) implies R
means that, whenever (P and S) is true, R is also true
in implication statements, we don't care about situations where the premise (left hand side) is false
we just mark those as "true"
you may wish to check your truth table for implication
so when constructing a truth table for (P ∧ S) ⇒ R, whenever P ∧ S are false, the entire implication will be true
that said, the truth table you wrote here does not have enough rows
there are 3 statement variables: P, S, and R
but you only have two variable columns (on the left of the table)
you should have 3 variable columns, for a total of 8 rows
i.e. your table should look more like this
i left out the entries for the implication (except the first one)]
note that we're considering all possible values for the three variables
there are 3 variables, and each have 2 options (true or false), so we expect to have 2^3 = 8 rows
and you can count the rows in my image to double-check that
in any case, as mentioned, for implication statements, whenever the premise (left hand) is false, the entire implication is true "by default"
so we can fill in all those
and are left with only one "blank", (true ∧ true) ⇒ false
as you correctly observed in your table, (true ∧ true) is just true
so this last remaining row is true ⇒ false
if you consult the appropriate row of your implication truth table, you should be able to fill in that last spot.
(to clarify: the one between the white and red Ts. i know that my writing was messy)
as for coming up with an example, they already provided one, but the idea is that (P ∧ S) ⇒ R is saying "whenever P and S are both true, then R is true as well"
we do not care about cases where P is false or where S is false (as mentioned, the implication is true by default when its premise is false)
we only care about the case where P and S are both true
in that specific circumstance, the conclusion R must be true as well
for the implication to hold
depends on convention.
is there a difference?
typically not
wait really? but wouldnt -> always just be something like 'approaches' or something
like in the limit
no, you can usually distinguish from context
yeah context wise
in model theory, you sometimes see → for syntactic implication and ⇒ for semantic implication; but the distinction is not relevant to the question so i'd rather not occupy their help channel with discussing it
alr mb
then whhy ar they all true
because the only scenario when implication is false is when its TF
because then it would make no sense for the initial premise to be true but the implication to be false
Think about it like this
Let's say Im a politician and I say "If I win the election, then I'll lower taxes"
This is an implication statement
I win election -> I lower taxes
Since there are 2 variables, we have 4 possibilities
I win the election and I lower taxes: I told the truth
I win the election and I did not lower taxes: I lied
So T -> T is true, and T -> F is false
Easy enough
But what if I lose the election?
and if you didnt win the election, nothing happens
^^^
I only said I'd lower taxes if I won the election
So if the premise "I win the election" is false, the implication itself is true automatically
(careful not to confuse the entire implication with the premise or conclusion)
so the only scenario when an implication is false is when the premise is true and the conclusion is false
so p is true, q is false, p -> q is false
In other words, F -> T and F -> F are both T
^^
And yeah, the only situation in which an implication is false is when the premise is true, but the conclusion is false
This should match with how we use implications "in practice"
Like if I say "if x is an integer, then x² is an integer"
I can justify this statement by only considering the situation when x is an integer
I don't have to think about situations where x isn't an integer
Since the implication is true by default in those cases
In the case of (P and S) implies R, this means that the statement can only be false if the premise (P and S) is true, but the conclusion R is false
Hence every other row of the truth table will be T
second implication is false though
whys that not drawn
Right, I omitted it
oh ok
Hoping they'd fill it in
oh i did not read what you wrote lmfao
It should be more clear about what are the last two columns actually are
I wrote it informally with my mouse
Apologies if it's not entirely clear but I think if they actually read my text they'll understand what I'm trying to say
i cant get over that hist im actually still tripped pout i spent 30 minutes on problem 1A ill tank the test tomorrow
thank you for the help
go fuckl yourslef
...
just make sure you know the truth tables for the different functions
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Please don't be a dick to helpers even if you think they weren't helpful
Indeed, but my point was, it should be written because it can be confusing with R (instead of the implication) 😄
Best of luck on your test
for the last column that is
At the first read I thought it was for R, since it was aligned with the R on the right
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Can anyone tell where I’m going wrong
Please don't occupy multiple help channels.
Sorry bot
what happened to the (x+8)(x-3)
and it should be -8
also the limit does not exist as the denominator approaches inf as x -> -8
also this is wrong
it should be x^2/3 -4
why the/3?
i just havent written that yet as im seeng what to do
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(x^1/3 -2)(x^1/3 + 2) = x^2/3 - 4
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with number (2)
im able to expand out the taylor polynomial to the 3rd order, set x = a+h
and subtract f(x+h) - f(x-h)
and get the equation for number 2
the rest after phi is just the error term
can i use the same process to dervive number 5?
i just do the same thing except i set x = a + h/2?
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how do i solve C
someon give me a hint
is it simultaneous equations?
cause i can make two equations
but like
i cant use eliminitation or substitution to solve it i think
have you solved parts a and b?
yes
ok right
so then you know the follwoing:
a + 2b - c = 1/2 d
-2a + 2b = d
multiply both sides of the first equation by -2 and see if you get any ideas from there
oh wow
so i use the first and 2nd equation in the questions given to me
but i plug in value of x, y and k
and then through that
i add both of the equations
which gives me the equation very similar to this
which is uh
2a + b - c = 0
which means
p is 2
q is 1
and r is -1
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Hello
Are you dividing by a function?
log_2(21)/log_2, this makes no sense
Logarithms are injective, from log_2(21) = log_2(x) you directly have x = 21
U can just write x = 21
Oh
Since base is 2 in both sides
If u wanna add extra context u can go like this
log_2 (21) = y = log_2 (x)
=> 2^y = 21
log_2 (x) = y
=> 2^y = x
Hence x = 21
@strange fractal
But theres no need tbh
U shouldn't lose marks for that
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Why is an empty set is an open set?
My gut says that it has to with false implication true or false is always true
what's your defn of an open set
also like what class are you in so we don't saddle you with definitions irrelevant to it
Let me define real quick
‘A’ subset of R is open, if for all a in A, there exists an epsilion neighbourhood of a which is fully contained in A
an epsilon neighbourhood ???
(a-e, a+e)
more like there exists a ball of radius epsilon contained in A
(a-e, a+e)
there exists an interval of length epsilon from a?
you work with only R ?
I’m taking real analysis rn
but yeah i have complex too
So the ball is the just an interval in R right?
but a circle in C
an open ball in R is like this :
B(a,r) = {x € R / |x-a| < r}, r>0
makes sense, this is exactly my definition of epsilon neighbourhoods in R
^
Yeah, im trying to see if thats the case of being vacously true as I recall from logic and proof
I’ve seen cases if the antecedent is false, the implication will always be true
if you take the complementary of the empty set in R which is R itself, R is neighbourhood of all his points and also contains all the limits of all his converging sequences
Therefore empty set is open and closed
yeah. also you can see it but definition of open set too. There's a definition " if every point's neighborhood is in that set then it is open" . so for Empty set every point satisfies it( to be more precise there's no point to check)
yea 🤔
also close since all limit point of that empty set is in that set right
so no points to check is same as being sufficient condition failing right?
The truth table of implication will be always true even if p is false
i dont really like to reason like this tho but its a bit true 🤔
idk, are they related?
The best way to prove that a set is open is to show that his complementary is closed
but i only have the definition of an open set
ahh ?
my textbook says the logical structure of open set definitions makes the empty set open
then we can work by contradiction 🤔
hmm
no
Here, even if p is false, the implication is always true
so here, p being if a element of A
‘A’ subset of R is open, if for all a in A, there exists an epsilion neighbourhood of a which is fully contained in A
yeah note that for all a in A
yes
so here there's no a to check
thats like getting into one of the last two rows in that table right?
no how?
because the statement is an implication?
actually truth table don't do anything here's atleast for your p
read it properly. we just have to check for all "a" right
so if there's no "a" means?
no element to check so it's obvious
if for all a in A, there exists an epsilion neighbourhood of a which is fully contained in A then A is open
is this correct?
like (2,3) ... we only check for the elements inside the set. Honestly we don't care about other elements...
Makes sense
yeah that's right
yeah it definitely would
it is sufficient and necessary condition
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How do I rearrange the bottom intergral into the form of the first?
but that gives 1/lnx
in the bottom
wait nvm
i cant differnitate properly
let me try again
I get to the bottom left one, but there's still a u at the bottom
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This is what you want right?
But there is also an x in the denominator in the original integral
Try adding the integrals
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How is possible that ln(1+x) is an Infinite numbers of terms plus an arbitrary constant ?
The Infinite series stays the same but the constant can vary
So I can make ln(1+x) any value I want right ?
no. at x=0 the thing is supposed to be 0 and that's how you fix C
Oh I see
Oh yeah I didn't read lol
to the end of the example
Thank you !
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The two conditions are parallel I think(
And also in second condition, why "Ax = b has at most one solution x" can figure out "A has an left-inverse B"?
Why condition 1 is EXISTENCE and condition 2 is UNIQUENESS?
The context
<@&286206848099549185>
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Back at this…
The exercise is about writing a rigorous proof (with the definition of a limit) that $\lim_{x \to 1} 3x = 3$
wlmmm
I see
I tried to apply it the same way within this question
Would it still be applicable?
This looks good to me! 🙂
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hi
x^2 was factored and cancelled out
bro i feel rllly dumb rn could u show this to me on paper or something
i rlly cant get my head around it
@sick garnet
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a tv quiz program pays a contestant php 100 for each correct answer for 10 questions. if all 10 questions are answered correctly, bonus questions are asked. the reward for every correct answer is increased by php 50 for each bonus question correctly answered. any incorrect answer ends the game. if 2 bonus questions are answered correctly, the contestant receives php 200 for each of the 12 questions. if a contestant won more than php 3500, how many correct questions must have been answered correctly
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Try plugging in some real numbers. If, for example A = 3, then (5A - 3)^2 = (15 - 3)^2 = 12^2 = 144
because (5x -3)^2 is not equals to 5x^2 + 3^2
theres a bracket there that you need to respect
no the ^2 dosent uh
not how it works
haha
you need to treat everything in the bracket as a whole
let me illustrate
If what you're saying is true, then 25A^2 + 9 = 25*9 + 9 = 234 must be equal to 144, which is not the case
the bottom is what your misconception is
its just not how it works
what the bracket means is that you need to take x + 1 as if its together
which means you cant put the square inside the bracket like the bottom example
its a common misconception, dont worry
no
its 25x^2
you need to square the 5 as well
yes
but
when you add something to the 25
and square it
such as 25 + 1
25^2 + 1^2 is not equls to 26^2
so the rule of thumb here is
any addition inside a paranthesis that is raised to a power, you cant bring the power inside the paranthesis
as shown here
no
u cant
thats illegal
idk i dont speak math english
but (5+5)^2 is equls to 10^2
if you add the 2 fives together
then square
yes
correct
then you use whatever method thats taught to you
here we call it rainbow method
idk
dont see it as ^2 see it as whatever inside the paranthesis multiplied by itself n times
maybe itll be clearer though it means the same thing
wdym not variable
like integers?
like not x
yeah
so u can add those
and square the whole thing
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been stuck for more than 30 mins ,help me try some other way to solve it
whats u=
(xsqr +ysqr +zsqr) -root
