#help-0

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lone heartBOT
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@trim tendon Has your question been resolved?

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acoustic wave
#

When multiplying series, do the two series indicies have to start at the same point?

acoustic wave
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<@&286206848099549185>

plucky sluice
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Example?

acoustic wave
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I am wanting to multiply these series together

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Should I pull out the first term in the second series first?

plucky sluice
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I think that will make it simpler, yes

acoustic wave
#

Okay sweet, I will definitely take simpler 😭

#

This whole problem is very arduous

#

.close

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slate vortex
#

I don't really get how to explain these types of problems. Could someone help?

lone heartBOT
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@slate vortex Has your question been resolved?

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@slate vortex Has your question been resolved?

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empty pelican
#

Hello!

I am trying to prove that for a binomial raised to a prime power, the binomial expansion of that binomial will only have coefficients that divide that prime power.

I started working on it, by trying to prove it directly but....given the equation for the coefficient, wouldn't it just be true more generally for any binomial raised to a power, not just a prime power?

empty pelican
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Sorry, I meant for any coefficient between 1 (incusive) and p-1 (inclusive)

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Oh, nevermind lol!

ocean sealBOT
lone heartBOT
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@empty pelican Has your question been resolved?

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tribal valve
lone heartBOT
tribal valve
#

okay so its improper

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so just limit t approaches infinity and the staff is t and 1

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and then just use usub, u = lnx to get $\frac{1}{2}(lnx)^2$ from t and 1

ocean sealBOT
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dabbingpotato

tribal valve
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now just sub in 1 and you get 0

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if you sub in t you get ln infinity

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is that possible

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or is this divergent

lone heartBOT
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celest stump
#

does no acceleration mean no one speeds up/slows down the entire time?

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without much understanding, i think the answer would be D by counter example, if there is no acceleration then Charlie could of just sat still at the start of the race

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making the race 18 meters long

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isnt it all dependent on how far charlie went?

lone heartBOT
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@sinful dome Has your question been resolved?

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raven shale
lone heartBOT
raven shale
#

I just wanted to know if this is correct?

placid zinc
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Try subbing it into the original DE to check

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There is a sign error

raven shale
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How do I deal with the sign?

raven shale
placid zinc
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Using your solution, what's dV/dP?

raven shale
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Its -C

placid zinc
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And then, what's -V/P?

raven shale
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Its dV/dP ?

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I don't get it

placid zinc
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V = -CP
So
-V/P
= -(-CP)/P
= C

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But dV/dP should be the same as -V/P, as per the question. So, the solution doesn't work

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The problem is when you take the exponent of both sides. The negative is out of place

lone heartBOT
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@raven shale Has your question been resolved?

raven shale
#

Hmm

lone heartBOT
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@raven shale Has your question been resolved?

lone heartBOT
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icy herald
lone heartBOT
vale wigeon
#

you know you can select a thing in paint, and ctrl+c ctrl+v it directly into discord right

icy herald
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Ok didint know ty

vale wigeon
#

also are these meant to be two different problems?

icy herald
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I have to brb

vale wigeon
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for which you've done the working out and want it checked?

icy herald
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Ye

vale wigeon
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well im gonna tell you that the top problem is wrong all around

icy herald
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I have to go for 5 min

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Brb

vale wigeon
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also for the second problem, 1/3 is not equal to 0.3330

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also x^(-4)/x^(-2) ≠ x^(-4/-2)

lone heartBOT
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@icy herald Has your question been resolved?

icy herald
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i will look at chat soon

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back

icy herald
vale wigeon
icy herald
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ya

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so cant solve it then?

vale wigeon
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"solve" is a strong word

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there is absolutely no reason here to convert 1/3 into a decimal

icy herald
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just let it be as 3^-1 or 1/3

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ok

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(2xA^6)/(X^6 x 3^-1)?

icy herald
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@vale wigeon

vale wigeon
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there are many things wrong with how you are writing this

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  1. don't mix UPPERCASE and lowercase
  2. don't use the letter x as a multiplication symbol
icy herald
lone heartBOT
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@icy herald Has your question been resolved?

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covert kiln
#

Function 4x^2+8x-9

lone heartBOT
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hollow niche
#

yo

lone heartBOT
hollow niche
#

nvm!!

#

.close

lone heartBOT
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lone heartBOT
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amber frigate
#

hi, let f : R -> R, if f(R)=R+, then f is not injective
is it true ?
I have no counterexample

lone heartBOT
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@amber frigate Has your question been resolved?

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halcyon mirage
#

no idea what the question means

lone heartBOT
halcyon mirage
#

but i still need a starting push to start

vague coral
halcyon mirage
#

ye but

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fk

vague coral
#

?

halcyon mirage
#

ill figure it out

#

.close

lone heartBOT
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icy herald
#

@languid gust

lone heartBOT
icy herald
#

Yo i forgot one thing

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can you help me?

frozen blaze
#

Hey

languid gust
#

wassup

icy herald
#

40 billion monkeys per milliliter

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how many monkeys volume = 1.5 dl

frozen blaze
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40money/ml

icy herald
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40x10^9?

languid gust
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ok how many mililitres in a litre

icy herald
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1500

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i think

languid gust
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theres 1000ml in a L

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how many L in a dL

icy herald
#

then 40x10^9 x 150

languid gust
#

stop stop no jumping ahead slow down

icy herald
frozen blaze
#

Unitary method

icy herald
languid gust
#

there are 40x10^9 monkeys per mL

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thats 40 billion

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now

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you are trying to find how many in a decilitre

icy herald
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how many monkeys in 1.5 dl

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40 billion x 150ml

languid gust
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no

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we need to convert mL to dL

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because they are not the same measurement

icy herald
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40 billion monkeys is per mL

languid gust
#

now, there are 1000ml in a litre

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and 10 litres in a dl

icy herald
#

ya

languid gust
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so therefore there is 10,000 ml in a decilitre

icy herald
#

no

languid gust
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because 10 x 1000

icy herald
#

ye

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10 ml?

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10 dl is 1l

languid gust
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other way around

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its implied in the word decilitre

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10 litres

icy herald
#

decimal

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deci?

icy herald
languid gust
#

its not though

icy herald
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how ?

languid gust
#

HOLD ON HOLD ON

icy herald
#

lol

languid gust
#

some random source telling me wrong

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1dl is 0.1L so 1.5dl is 0.15L which would be 150 mL you are correct my friend

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my mistake

frozen blaze
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How's 40 billion monkey in litre ?

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sorry i mean in ml

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It must be volume

languid gust
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mL is volume

frozen blaze
#

Yes

languid gust
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monkeys aren't 2 dimensional

frozen blaze
#

Sorry i mean

icy herald
#

40 billion monkeys in 150 ml

frozen blaze
#

Is money a liquid to put in tank

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Anyway

icy herald
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they are not asking for monkeys i just said it because its easier to explain

languid gust
#

you need to times 40 billion by 150

frozen blaze
#

Bruh

icy herald
#

ye and the answer i need to write in weird way

languid gust
#

probably scientific notation

icy herald
#

i get 6x10^13

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but book says

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6x10^12

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wtf?

frozen blaze
#

40×10^12 money per 1 d

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L

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Wait

languid gust
icy herald
#

150 x 10 = 1500

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1500 x 10

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=

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15000

frozen blaze
#

4×10^10 moneky per 1dl

icy herald
#

15000 x 10 = 150000

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150000 x 10 = 1500000

icy herald
#

fact or cap?

languid gust
icy herald
#

you cant split it up?

languid gust
#

very cap

icy herald
#

and multiple by 10

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just 4 times?

languid gust
#

definitely not

icy herald
#

it made sense tbh

languid gust
#

just out of curiosity what grade are you in

icy herald
#

12

languid gust
#

so you're trolling

icy herald
#

no

frozen blaze
#

Wtf

icy herald
#

I am not

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I study math 18 hours a week now

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self study

languid gust
#

you have a calculator right...

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use it

icy herald
#

ye

frozen blaze
#

Good then

icy herald
#

so

languid gust
#

gives you the asnwer

icy herald
#

its 40 billion x 150

languid gust
#

we're forgetting the billion for now

#

6000 x 10^9

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6000 is like 6x10^3

icy herald
languid gust
#

6x10^3x10^9 is 6x10^12

frozen blaze
#

How you get 6

icy herald
#

because

#

it get lower value you do ^+

frozen blaze
#

4 trillion monkey per 1dl

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ain't it

icy herald
#

??????????

languid gust
#

6 trillion

frozen blaze
icy herald
#

3+9 = 12

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6^12

frozen blaze
#

4 trillion in 1 dl
And
6 trillion in 1.5dl

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Thats why

icy herald
#

@languid gust how did you make it into 6 again?

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because 40 x 10^9?

frozen blaze
#

1.5 dl

icy herald
#

x 150

frozen blaze
#

Thats why

icy herald
#

= 600000000000000000

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then 6 x 10^9

languid gust
#

yup

icy herald
#

ok make sense

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but then

icy herald
#

wait dont answer

#

i will check something

frozen blaze
#

Sorry 1.5 dp

icy herald
#

its not the problemm lol

#

,rotate

ocean sealBOT
icy herald
#

my calculator dont let me see what 40 x 10^9 is in numbers

frozen blaze
#

I solve same problem using unitey method

languid gust
#

ok im gonna write this out for you, and then i have to go because i have other things to do

icy herald
#

ok t

#

y

icy herald
#

but thanks i can look back at chat

frozen blaze
#

Do u know about cramer's rule

icy herald
#

no

languid gust
frozen blaze
#

6Trillion

icy herald
icy herald
frozen blaze
#

?

icy herald
#

for help too

frozen blaze
#

I didn't help actually

#

I just came because i was suprised from question

#

40 billion monkey in 1 ml ?

icy herald
#

ye original question didint say that

#

i just changed from bacteria to monkeys

lone heartBOT
#

@icy herald Has your question been resolved?

#
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Ask your math question in a clear, concise manner.
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After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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shadow igloo
#

Analytic geometry, I'm suck at understanding the question

halcyon mirage
#

hey

shadow igloo
#

Can anyone change the wording of the question? I don't know how?

halcyon mirage
#

ah

#

let me see

#

give me 1 mimnute please

shadow igloo
#

Sureee no need to rushh

halcyon mirage
#

oh ok i see how this wors

#

so you have point P correct?

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you want the distances $PR=PQ$

ocean sealBOT
#

i like cheese

shadow igloo
#

Yes, but what should be my point P?

halcyon mirage
#

there is a line, whch for all points fits the equation

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you need to find that line

#

if you dont know how to solve it algebraically, i would recommend finding 2 poitns which are along the line, then figure out the equation.

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does that help?

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or do you want me to clarify furhter

shadow igloo
#

But on the graph it looks like PR is not equal to PQ, soo I need to find a point that would give me two equal distance?

halcyon mirage
#

yes

#

note, dont trust graphs

#

they arent always drawn to scale

#

sometimes they are

#

well

#

usually

#

but

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if it doesnt feel correct

#

dont trsut it

shadow igloo
#

Oohhh okaayy Okayyy

halcyon mirage
#

so

#

let me get on desmos rq

shadow igloo
#

Aightt I'll tryy noww if it would work soo two distance formula equal to each other?

halcyon mirage
#

just find the nromal

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then make it pass through the middle of QR

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thatll be my idea

#

yk what the normal is correct?

alpine sable
#

Excuse me, is 9x+y = 7 the answer?

#

@shadow igloo

halcyon mirage
#

no, i dont think so

shadow igloo
halcyon mirage
#

i think

shadow igloo
#

It would look like this but not twice of the distance??

halcyon mirage
#

the constant is wrong

#

the gradient of the equation is -9/5 btw

shadow igloo
#

OOHHHH THAT LINE in the middle

halcyon mirage
#

yes

alpine sable
#

Thanks

shadow igloo
#

Yeahh it would give both equal distancee

#

Alright, I think I can do it noww, Thanks guyss

halcyon mirage
#

here we go @shadow igloo

#

u should be able to figure out the working

snow sail
#

oh dang.....

halcyon mirage
snow sail
shadow igloo
snow sail
#

damn im suck at math

halcyon mirage
#

nup

#

ur good

#

layla its ok

#

haha

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@shadow igloo do u know how to

#

uh

#

calculate the gradient

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of P

shadow igloo
#

Nooo but I think I can get the equation I think, anyways what is gradient? :0

snow sail
#

NervousSweat IM FEELING nervous today cuz of this test math

shadow igloo
#

First time hearing thaat @halcyon mirage

shadow igloo
halcyon mirage
#

gradient is

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uh

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the gradient

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;-;

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ok so

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go to desmos

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now type in equation y = mx

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m would be the gradient

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now add a slider of m

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and see what the gradient does

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ooh i have an explanation

#

the gradient is practically the angle of th eline

shadow igloo
#

Ohh like slopee or no?

halcyon mirage
#

mhm

snow sail
#

ff uck myself

halcyon mirage
#

ur good

snow sail
#

hyperhonk WHATTTT

#

thonkzoom WHAT should i do if i cheat on test

halcyon mirage
#

haha dont

#

if u need help just ask

#

👍

shadow igloo
#

Yeaahh don't xD

halcyon mirage
#

aries did u figure it out?

shadow igloo
#

It's better if you know how

#

Yeahh the equation and distance, I'm kinda working on it

halcyon mirage
#

aight

#

tell me if u ned further help

shadow igloo
#

Yepp, thanks a bunch to youu catthumbsup

halcyon mirage
#

no probs!

#

dont close it yet haha, in case u mess up somehow :)

alpine sable
halcyon mirage
#

hmm

snow sail
#

my brain didnt make it

halcyon mirage
#

aditya let me have a look

#

how do you classify the direction of a point?

#

how do you get a

#

uh

#

the equation

#

of the point

#

cuz i dont think that works

#

@shadow igloo anything else you need help with?

alpine sable
#

uhh, I don't know much about this, I just used distance formula in coordinate geometry. I equated the distance between P point to r and q point as it is given in the question

snow sail
#

i already cheat on test i calculator it

halcyon mirage
#

skull

#

@alpine sable that is a good idea, and it along the way

#

basically here are the steps

#
  1. find the gradient of QR
alpine sable
#

From this I got a equation in which when we put the x and y coordinate of the point it gets solved.

halcyon mirage
#
  1. get the normal of QR
#
  1. find the midpoint of QR
#

get the equation of P using the normal as the gradient

shadow igloo
alpine sable
#

I haven't learned it till now but I will try learning it

halcyon mirage
#

aight

#

.close @shadow igloo

snow sail
#

i just download the math to cheat and learn catGiggle

shadow igloo
#

Thanks a bunch again guyss

halcyon mirage
#

gl with whatever u need to do

#

i need to sleep now

#

lmao

#

gn

shadow igloo
#

.close

lone heartBOT
#
Channel closed

Closed by @shadow igloo

Use .reopen if this was a mistake.

snow sail
#

and sleep well

lone heartBOT
#
Available help channel!

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After 15 minutes, feel free to ping <@&286206848099549185>.
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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

marsh echo
lone heartBOT
marsh echo
#

,rotate

ocean sealBOT
marsh echo
#

questikon b

snow sail
#

damn....

marsh echo
#

?

snow sail
#

nothing..... flonshed

zealous lichen
#

what is J+

marsh echo
#

a positive integer

zealous lichen
#

just show that $\frac{1}{1+t^n}\leq \frac{1}{1+t^{n+1}}$ for $0\leq t\leq 1$

ocean sealBOT
#

WhereWolf(ping if needed)

marsh echo
#

do i work each individualy/

#

?

zealous lichen
#

wdym

marsh echo
#

im also confused about the equal to part

#

also where do i start

zealous lichen
#

you can start from $t^n\geq t^{n+1}$

ocean sealBOT
#

WhereWolf(ping if needed)

marsh echo
#

oh i see

#

wait

#

but the inequality is flipped right

#

cause hes my concern

#

if f(x) > g(x) for the domain

frozen blaze
#

We can use any opreation on both side right

marsh echo
#

then in the area under f(x) > area under g(x)

#

right?

#

so i just need to prove that f(x) > g(x) for 0 < x <1

#

for for the function

#

how are the areas equal to each other

#

only as n approached infinity

#

do the integral of them equal each other

frozen blaze
frozen blaze
#

If ranges of f(x) is greater then g(x)

#

while we input same domain

marsh echo
#

how do i prove $\frac{1]{1+t^{n+1}} \geq \frac{1}{1+t^n}$

lone heartBOT
#

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paper sage
#

Why I’m getting two different answers since it same equation

pale kestrel
#

Why are you sure they're different.

paper sage
paper sage
coral flower
#

from left side they just factored out e^(2x-2) from numerator and denominator and canceled them

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#

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cyan mountain
lone heartBOT
cyan mountain
#

hello kind souls, can anyone help walk me thru this problem?

tardy stag
#

evaluate from the inside out

#

first find f(4)

cyan mountain
#

that is 5

#

f(4)=5

tardy stag
#

great, so now go the other way, look for x such that f(x) = 5 [this is how you calculate f^-1(5)]

cyan mountain
#

such x that f(x) =5

#

x=4

#

?

tardy stag
#

yeah lol

cyan mountain
#

so the inverse

#

is 4

tardy stag
#

yep

cyan mountain
#

HAHAH

tardy stag
#

since it's a one-to-one function, $f\inv(f(x)) = x$

cyan mountain
#

like

ocean sealBOT
#

jan Hayley

cyan mountain
#

yes

#

i knew

#

but i thought

#

maybe it would be

#

more complex

#

thank you so much

#

LOL

tardy stag
#

nah but it's good to do it by hand to check

cyan mountain
#

i really appreciate it 🙂

#

ty

#

.close

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#
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raven shale
#

Is this right

lone heartBOT
wind cloak
#

yes

raven shale
#

Thanksss

#

How about this?

#

@wind cloak

wind cloak
#

looks good

raven shale
#

I don't know if that's the right thing
To multiply both sides to 6

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frosty swift
#

Is the answer zero (question is to evaluate this limit).

coral flower
#

yeah pretty sure

#

lne = 1
ln 1 = 0

frosty swift
#

Ok.

#

Thanks.

#

.close

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alpine edge
lone heartBOT
alpine edge
#

How to calculate the grey area

#

What I did is set the dotted lines to 2 making the grey area 8cm^2

#

but I did that from observation

manic flame
#

you can start by calculating the area of the entire square

#

and you can see the 2 smaller triangles are 2 x 2

alpine edge
#

that would be 36cm^2

alpine edge
manic flame
#

You know the triangle is right angle (90) and the sides are equally long. (8) This means the small triangles are 45c

alpine edge
#

I see, since the top angle of the small traingle is also 45° then the sides must be equal

manic flame
#

yea, and you will see if you remove the 2 smaller triangl they still maintain their 90 angle

alpine edge
#

Gotcha, cheers!

#

.close

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magic cipher
#

Can some

lone heartBOT
magic cipher
#

Can someone help me with this please?

lone heartBOT
#

@magic cipher Has your question been resolved?

manic flame
#

you know how to get the y=kx+m from those 2 points?

magic cipher
#

for the line?

#

Yes

#

Y=2.0625x-3.3

manic flame
#

ok

#

and you know the circle equation?

magic cipher
#

X^2 +y^2 = r^2

manic flame
#

ok

#

so you have the equation if its in origo

#

and it gives you the radius

magic cipher
#

So i plug in the line equation?

manic flame
#

yea once you have both equations

#

you replace the y in the circular equation with the line y

magic cipher
#

I can solve for x and then plug in the x points into the line to find y values?

manic flame
#

yea

#

since it a line, you can get 1 or 2 x

#

depending if it tangens or goes through it

magic cipher
#

Oh ok

#

Ty ima give it a shot

#

.close

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rugged sail
#

.open

fallen shuttle
#

Are these the same?

lone heartBOT
wind cloak
#

what

#

Left is a real number right is an expression

#

Is it meant to be an equation?

fallen shuttle
#

I am working with taylor series

#

so I want to create a taylor series for the one on the left, I want to know if I use the one on the right would it be the same for the series

vale wigeon
# rugged sail .open

this does nothing, you're supposed to post your own question right away no commands
but now you need to do it in your own channel

vale wigeon
fallen shuttle
#

I am sorry, I am lost with that

wind cloak
#

Well

#

What does a definite integral give you?

fallen shuttle
#

This is what I am working on

last ether
#

Do you know the Taylor series for cos(x)

fallen shuttle
#

yes

last ether
#

Yeah so just replace every x with πx^2 and that'll be your polynomial

fallen shuttle
#

I was thinking that, but the stuff on the left had me confused

tardy stag
#

the idea here is that you replace the $\cos(\pi x^2)$ with the series

ocean sealBOT
#

jan Hayley

fallen shuttle
#

Ok I will give that a try

lone heartBOT
#

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half flicker
#

Any idea how to solve this eq?

lone heartBOT
half flicker
#

Its w

#

i have found solution

#

i had to take the power -1 and then substitue

#

.closed

#

.close

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mellow mica
#

I am supposed to change the equation r^2 -z^2=0 into spherical coordinates and then simplify

mellow mica
#

I changed it into P^2sin^2p - P^2cos^2p = 0

#

Then, I grouped into P^2(sin^2p - cos^2p) =0

#

I then went P^2(1/2 - 1/2 cos 2p - 1/2 - 1/2 cos 2p) =0

#

I am currently at P^2(-cos2p) = 0.

#

I am told it can be simplified further, but I do not see how

lone heartBOT
#

@mellow mica Has your question been resolved?

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#

@mellow mica Has your question been resolved?

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paper sage
#

I found the stationary points which is (2,1) I don’t know what to do else

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fringe mist
#

Every how many zeros is next number?

Like 1.000.000 this is one million, you’ll need one thousand millions to be a billion?

umbral cosmos
fringe mist
#

And then 1000 millions would be billion?

wind cloak
green knoll
#

1 one
1000 one thousand
1000000 one miion
1000000000 one billion

#

if thats what youre asking evrry 3 zeros you go to the next “number”

ionic jewel
#

This is true in English but not true in all languages

#

in chinese for example, it's every 10000 gives you a new "word"

fringe mist
#

What’s after billion?

ionic jewel
#

trillion is a thousand billions

#

(in English)

lone heartBOT
#

@fringe mist Has your question been resolved?

lone heartBOT
#

@fringe mist Has your question been resolved?

lone heartBOT
#

@fringe mist Has your question been resolved?

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toxic mulch
#

I am unsure what this question is asking I understand that a) is asking df/dL but I am unsure how to utilize implicit differentiation to specifically get the answer as for b) it would be df/dT. I guess I am just not sure how these would differ.

alpine sable
toxic mulch
alpine sable
#

no worries it happens

toxic mulch
lone heartBOT
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lilac jolt
#

Scientific Notation: is it possible to have a negative coefficient

lilac jolt
#

I mean, does that violate the rules of sn

gray isle
#

something like
$$-5.7 \times 10^3$$
is valid in scientific notation

ocean sealBOT
#

ℝam()n()v

lilac jolt
#

what's not valid then

plucky sluice
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@lilac jolt Has your question been resolved?

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dawn quail
lone heartBOT
dawn quail
#

I don't understand this last step

#

x^5

#

isn't it supposed to be ln(x)^5?

gray isle
#

bad/wrong notation

dawn quail
#

not ln(x^5)

dawn quail
gray isle
#

first step

dawn quail
gray isle
#

eeep. Leonard done fked up

dawn quail
#

where exactly?

#

i see that he wrote lnx

#

which I don't like

#

I prefer ln(x)

#

this is suuuper confusing.... is it ln(x)^5 or ln(x^5)??

gray isle
#

power should be in the argument
especially for the second and third term

#

ln(x^5)
ln((x^2+1)^(1/2))
ln((x-2)^4)

dawn quail
#

I thought power 5 is for log, not the argument

#

wow, brackets are super needed here

#

dunno why he's teaching without them

gray isle
#

yes

dawn quail
#

we are talking about arguments

#

brackets = requirement, not optional

#

alright ty

#

I will try this again

lone heartBOT
#

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sinful fossil
#

Had this question in geometry/chem. "You are hired to count the number of ducks in three northern lakes during the summer. Describe the procedure you would use to go about this task. Then, suppose your answer is around one million ducks. What would you do if, you are driving away from the lakes and see 15 more ducks fly in from the south and land on the last lake. Do you change the number of ducks that you report? Justify your answer."

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#

@sinful fossil Has your question been resolved?

naive valley
#

what's the context? this doesn't seem like a math question

lone heartBOT
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visual nest
#

$1.4.6 Convert is a function to change equations into their variable form, For example
ℂ(x) = 45x → y = ℂx
Shows that the normal equation was converted (ℂ) to it’s variable form. ℂ replaces the number 45 and the ℂ(x) was replaced by y, the common variable change.$

ocean sealBOT
visual nest
#

actuall

#

nvm

#

.close

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#
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radiant silo
#

I thought I proved x_(n+1)-x_n tends to zero implies it’s convergent as it’s Cauchy but this ain’t true can someone tell me why my proof is flawed

radiant silo
#

I have a counterexample I just dk why my proof is wrong

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#

@radiant silo Has your question been resolved?

radiant silo
#

<@&286206848099549185> elp

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lone heartBOT
#

@alpine sable Has your question been resolved?

icy crane
#

yeah kaz

#

what you posted already seems simple enough

#

maybe you can divide everything by -3 to make it even simpler

#

woahh dude

#

not cool

#

i didn't say divide by 0 😄

#

I said divide by -3

#

zero divided by anything (except zero) will remain 0 indeed

#

but coming back to the equation you posted, it depends on what you want to do

#

solve for x? solve for y?

#

ah

#

yes. not -3

#

that would be if you wanted to solve for x

#

what does it look like now?

#

heh you mean divide everything else by the coefficient 😄

#

and yes, that sounds good

#

I mean

#

you haven't solved for y yet

#

that's just a step

#

yep. ok so you know how to cancel terms and move them from one side to another

#

cool

#

what else?

#

don't you mean the "height" of the equation when x = 0?

#

like, the slope is something that's always the same in linear equations

#

it's that "m" in your example

#

you mean depend on x? not in linear equations

#

how about you also show exactly what the exercise is asking

#

so we're clear on that

#

I think you want to find the value of y when x = 0

#

ok

#

so two different things

#

first: find the slope

#

well, solve for y and you'll see the slope appear

#

it will not have a specific value

#

right

#

yep

#

its value depends on x

#

yes

#

yes but don't do that part yet

#

just get y alone and tell me what the equation looks like

#

ok and divide by the coefficient like you said before

#

so you have y = .....

#

all of it

#

divide every term by -5

#

yea, except you keep jumblin numerator and denominator

#

it should be y = (-2)/(-5)x - 4 instead

#

haha make sure to be careful with that stuff in the future

#

alright so now you can see the slope

#

what is it?

#

no!

#

check again

#

ok the y stuff is correct

#

you put in x = 0, then y = -4

#

yes

#

you're welcome but you still gotta do the slope

#

yes, so what is M equal to

#

M is the slope

#

nope 😄

#

actually

#

yes it is

#

you are correct

#

this time I mixed numerator and denominator

#

you can also simplify it by cancelling the two -

#

-2 / -5 = 2/5

#

glad to help

lone heartBOT
#
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alpine sable
lone heartBOT
alpine sable
#

Do I just ignore the square root for this?

stark crater
#

What do u think it is

#

even if you cant show algebraically

alpine sable
#

Lemme solve rq then

#

Even I think

stark crater
#

Yeah

#

Do you know the formal definition of even

alpine sable
#

But only looked at the exponent so lucky guess lol

stark crater
#

Oh lol

alpine sable
#

It should come out the same

#

I think that’s what it was

stark crater
#

Yeah

chrome silo
#

ya it is even

stark crater
#

So check if sqrt(x^2-4) = sqrt((-x)^2-4)

alpine sable
#

So could I do the -x thing without looking at the square root and just solve like that every time?

chrome silo
alpine sable
#

Fuck Alr

stark crater
#

Informally, a function is even if when you flip it across the y axis it overlaps

#

Formally it is f(x)=f(-x)

alpine sable
#

Yeah and other one if you flip it 180

#

Should be the same

chrome silo
#

and 0 is the only function that is both even and odd

alpine sable
#

Just the algebraically that’s a pain

stark crater
#

Once you understand it is probably simple. You just literally plug in -x to the function

#

for x

stark crater
chrome silo
# alpine sable Huh?

f(x)=0 is both odd as well as even function and it is the only one of its kind

alpine sable
#

Just plug it into the calc and check?

stark crater
alpine sable
#

Ok so I can just ignore it then

#

That’s what I was wondering

stark crater
chrome silo
#

because of the square root the value of x can't be less than modulus 2

stark crater
#

(-x)^2=x^2 agree?

alpine sable
#

Yuh

chrome silo
stark crater
#

so then sqrt(x^2-4) = sqrt((-x)^2-4) implies sqrt(x^2-4) = sqrt(x^2-4) which is obviously true since theyre the same thing

#

so you have algebraically shown the function is even

chrome silo
#

true

alpine sable
#

Alr thanks g

stark crater
#

if you were trying to show it was odd you would do -f(x)=f(-x) which in this example would be confirming -sqrt(x^2-4)=sqrt((-x)^2-4) but this is false

#

so it is not odd

chrome silo
stark crater
#

Ye

chrome silo
#

r u guys in school

alpine sable
#

What if it was a fraction

#

F(x) = 1/x

#

How would I do that

chrome silo
stark crater
alpine sable
#

Ik it’s odd

stark crater
alpine sable
#

Cuz it’s from my notes

stark crater
#

then check if -F(x)=F(-x)

alpine sable
#

But like idk how I’d solve it lol

stark crater
#

You know what F(x) is

chrome silo
#

i know

stark crater
#

and F(-x) is just F(x) evaluated at -x

#

F(x)=1/x evaluated at -x is 1/(-x)

chrome silo
#

r u both in high school

stark crater
#

im in college

alpine sable
#

I just started college

#

This math is bs

chrome silo
#

ohhh

#

i am also in college

stark crater
#

college gang

chrome silo
#

didn't you guys had maths inhigh school

stark crater
#

yeah

alpine sable
#

Yuh id hope so

chrome silo
#

all of us are same

#

i also didn't had maths in my 12th grade

#

but i am now learning calculus

alpine sable
#

I’m in pre calc

#

Idk why I’d need this for my degree

#

But wtvr

#

As long as I don’t gotta take more math after pre calc

#

We chillin

chrome silo
#

r u in business degree

#

it is really necessary bro

#

math is fun

alpine sable
#

Don’t rlly know what ima major in but got told I had to do this no matter what so

chrome silo
#

in which uni do u study

alpine sable
#

In a community college rn cuz got scholarship for it

chrome silo
#

great

#

if you have any questions you guys can ask

stark crater
chrome silo
#

r u guys teen

alpine sable
alpine sable
#

I can’t for the life of me keep up with this math man

#

Like every class so much shit and I’m supposed to just know it by the next day like bruh

#

Out here studying like 6 hrs a day and still not keeping up

#

Yet alone my other classes smh

chrome silo
alpine sable
#

Ion rlly give my name out sorry

#

Never know these days

chrome silo
#

true

#

i can be a murderer

alpine sable
#

Fr

chrome silo
#

who knowsopencry

#

atleast tell me whether you r a girl or boy

alpine sable
#

Boy lmao

#

Anyways I gotta get back to my math but thanks for the help both you guys

#

.close

lone heartBOT
#
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#
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mystic nebula
lone heartBOT
mystic nebula
#

i got h = 16 +/- sqrt144/-32

#

so far

#

is that right

placid zinc
#

I don't think it's quite right. Note you don't need the quadratic equation here

mystic nebula
#

well im supposed to use the quadratic equation here

#

cause thats the way they're doing it

placid zinc
#

I think you set b = -16. The correct solution would set b = 0, and a = -16

mystic nebula
#

OH

mystic nebula
placid zinc
#

Yes that's it

mystic nebula
#

so what next

#

16sqrt3/-32?

#

i get -0.87 and +0.87

#

.close

lone heartBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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waxen turtle
lone heartBOT
waxen turtle
#

Idk where to start

winged lava
# waxen turtle

i assume the “weight” M is actually the mass. mass is proportional to volume, the constant of proportionality being density.
M = kV where k = vol
losing 200 ml meant losing ( 590-400) = 190 g of oil
therefore:
190 = 200k
k = 19/20
therefore:
M = (19/20)V

#

does this make sense,

#

?

waxen turtle
#

Umm it says that's wrong

sour dove
#

Oh!

#

yeah it's just a linear equation

waxen turtle
proven leaf
sour dove
waxen turtle
#

.close

lone heartBOT
#
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mystic nebula
lone heartBOT
mystic nebula
#

how do i factor 2x^2 - 92x - 3360

lone heartBOT
#

@mystic nebula Has your question been resolved?

#
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lone heartBOT
#
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waxen turtle
lone heartBOT
waxen turtle
#

@cunning frost

#

I have no clue

cunning frost
#

well, how many heartbeats occurred in the graph

#

and how many seconds passed in the graph

waxen turtle
#

Umm including the one going into the 2nd quarter thingy

#

I forgor

#

Quadrant

cunning frost
#

maybe a better way to do it is

#

can you tell how often the graph repeats horizontally

waxen turtle
#

@cunning frost

cunning frost
#

nahh this one is pretty easy to see

#

look at where it aligns with the grid

waxen turtle
#

WDYM

#

Uhh

#

8/10

#

A second

cunning frost
#

ok so

#

how far apart are the peaks

#

if you had to guess

#

pick two adjacent ones and look at the horizontal distance

waxen turtle
#

3/5

cunning frost
#

that’s a good guess

#

one way to check if 3/5 is exactly right is to count the number of pulses in 5 seconds

#

because 3/5 means 3 pulses every 5 seconds

#

wait

#

sorry that’s wrong lol

waxen turtle
#

Does the one on 0 count as a beat

#

And before it

cunning frost
#

actually this explanation doesn’t work as well as i thought

#

but yeah count the one on 0

#

it would be 3/5 means 5 pulses every 3 seconds

waxen turtle
#

So like

#

100 beats a minute fr

#

Wait

#

12 beats

#

Fr

#

A minute

cunning frost
#

well if it were actually 3/5

#

but the gap is actually 2/3

waxen turtle
#

Oh

#

So

#

40/3

cunning frost
#

notice how between x = 0 and x = 2 there are three pulses (non-inclusive of the end)

waxen turtle
#

Per minute