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1 messages · Page 328 of 1

wary stream
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Now you can just plug in the value of C and leave it alone, like what you did with A

kind patio
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I have a question

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using the same methods we got for A and C

wary stream
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$1(x^2 + 9) + (B * x + C)(x - 1) = 10 \to 1(x^2 + 9) + (B * x+ -1)(x - 1) = 10$

ocean sealBOT
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dldh06

kind patio
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why am I not able to do Bx-C=x^2+9

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Or Bx-1=x^2+9

wary stream
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What happened to the 10?

kind patio
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oh so it would be Bx-1=10(x^2+9) ?

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naw u def wouldn’t get the right answer

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w that

wary stream
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And you can't plug in x = 0 else you lose B

kind patio
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so then Bx-1=-x^2+1

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but that square messes it all up

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well u could divide x by both sides

wary stream
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No don't do that

kind patio
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so B=x+2

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oh

wary stream
kind patio
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yes

wary stream
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So you have want to solve for B, but you have to deal with that x, if you make x = 0, then B gets eliminated which is no good

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If x = 1, B gets eliminated, also no good

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So the values of x, you can use that doesn't eliminate B is any value that is not 0 or 1

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x = 2 is the most simpliest value to use

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Because if x = 2 then $1(x^2 + 9) + (B * x+ -1)(x - 1) = 10 \ to 1(2^2 + 9) + (B * 2+ -1)(2 - 1) = 10$

ocean sealBOT
#

dldh06

wary stream
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And 2 - 1 = 1

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You can make x whatever you want but x = 2, is the easiest

kind patio
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so they simply made it 2 because it was the easiest

wary stream
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Yes

kind patio
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why not just plug in 1 and get rid of B entirely

wary stream
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Why?

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You're trying to solve for B

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Not eliminate it

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You have $1(x^2 + 9) + (B * x+ -1)(x - 1) = 10$

ocean sealBOT
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dldh06

wary stream
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If x = 1 then B is gone

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And you can't solve for B

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The goal is to solve for A, B, and C

kind patio
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so theoretically

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if i wanted to

kind patio
wary stream
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Yes

kind patio
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and B would give me the same number?

wary stream
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Try it

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Plug in x = 3

kind patio
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that checks out

wary stream
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And see what you get for B

kind patio
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if tan^2(x) +1 =sec^2x

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why can’t secx = tanx+1

wary stream
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Did you sqrt both sides?

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Because $\sqrt{a + b} \neq \sqrt{a} + \sqrt{b}$

ocean sealBOT
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dldh06

kind patio
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well like if i sqrt tan^2x do I not get tanx?

wary stream
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You do, but if it's $tan^2(x) + 1$, $\sqrt{tan^2(x) + 1} \neq \sqrt{tan^2(x)} + \sqrt{1}$

ocean sealBOT
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dldh06

kind patio
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ok finally so I don’t keep you here too long

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for number 4

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is it incorrect to use the sin2x= 2sinxcosx

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on the right

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as I got 1-cos4x instead of 1+cos4x

wary stream
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No clue sorry

lone heartBOT
#

@kind patio Has your question been resolved?

lone heartBOT
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native bramble
lone heartBOT
native bramble
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I understand that 5pi / 6 is 150 degrees, which means it is before pi so pi - theta is correct

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but how did they get from - (cos pi - 5pi / 6) to - cos (pi / 6)

lunar ravine
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1-5/6

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is 1/6

native bramble
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what

gleaming ridge
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it's not a property or anything

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all they did was compute pi - 5 pi / 6

sonic ridge
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$\pi-\frac{5\pi}{6}=\frac{6\pi}{6}-\frac{5\pi}{6}$

ocean sealBOT
sonic ridge
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thats all there is to it

lone heartBOT
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@native bramble Has your question been resolved?

alpine sable
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Let m/n be a fraction, where m and n are positive integers. Consider the operation defined by replacing m/n by (m+1)/(n+1) and then writing the result in lowest terms. For example, applying this operation to 5/14 would give 2/5. How many times must this operation be repeatedly applied to 1/2005 before we obtain 2004/2005?

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I don't understand where to start

lone heartBOT
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median ledge
#

Guess who's bacccc

My broddas this is a comprehensive review of the first unit of precalculus which covers subjects like transformations, implicit and explicit functions, domain of functions, transformations of all functions, table reading with inverses, compunding inverses.
I left out peicewise functions because I ForGOR
just skip to the par...

▶ Play video
median ledge
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straight precalc

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boy this came from math three

fickle sandal
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!status

lone heartBOT
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What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
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@median ledge Has your question been resolved?

lone heartBOT
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tough lily
lone heartBOT
tough lily
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i am having some confusion on how to sollve

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do i use f(x)-f(a)/x-a or do i find the derivative of each eqaution

barren glade
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derivative

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u/v

tough lily
barren glade
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or wait

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no thats it

tough lily
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i see.
so would that look like this :
((x-5) d/dx (x+3) - (x+3) d/dx (x/5))/(x-5)^2

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which would then simplfy to

barren glade
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yes

tough lily
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((x-5)-(x+3) )/ (x-5)^2 ?

barren glade
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mhm

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now just plot in the value of x

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to find the slope at the specified point

tough lily
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whats the mathematical reasoning for it to simpfly like that

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ik to do it like that but im not sure how/why

barren glade
median oar
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$\frac{d}{dx}uv^{-1}=u’v^{-1}+(-1)v^{-2}v’u=\frac{u’v-v’u}{v^2}$

ocean sealBOT
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Frosst

barren glade
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for these

median oar
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This is just a fancy product rule

barren glade
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you know how to find the gradient of a normal curve right?

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think of this as the exact same as that

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but here

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you need to apply a "fancy product rule"

tough lily
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not sure by name

barren glade
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but you can't do it the regular way with this

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practice more and u'll get used to it

tough lily
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taking calc 1 online was not a good idea... 🥲 😂

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thank you

barren glade
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np

upper moat
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i need help

tough lily
lone heartBOT
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@tough lily Has your question been resolved?

tough lily
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then for a problem like this to find the slope

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I would fine the derivitive of √x which would be

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(1/2)x^(-1/2) or 1/x^(1/2)

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so would the slope be 1/a^.5

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<@&286206848099549185>

fickle sandal
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$\frac{d\sqrt x}{dx}=\frac{1}{2\sqrt x}$

ocean sealBOT
#

chlamydia

lone heartBOT
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@tough lily Has your question been resolved?

tough lily
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how do i find the slope in accordance to x = a

lone heartBOT
#

@tough lily Has your question been resolved?

lone heartBOT
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alpine sable
lone heartBOT
#

Please don't occupy multiple help channels.

alpine sable
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#3 first time doing this

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i am unsure of why the integral on the right becomes -2?

fickle sandal
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you perform partial fraction decomposition on the LHS

alpine sable
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OH then A and B = 1/2 so multiply by 2? but why is it negative?

fickle sandal
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A and B might be -1/2

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so the 1-x flips to x-1 too

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uh

alpine sable
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thats why theres a minus sign in front of 1/x+1 tho

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wait

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thats not right

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why did they do that lol

fickle sandal
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1\x-1-1\x+1=x+1-(x-1) \x^2-1

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which is 2/x^2-1

alpine sable
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why didnt they just leave 1/x+1 in front of -1/x-1

fickle sandal
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which is -2/1-x^2

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no it's right

alpine sable
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bro youre gonna have to separate your fractions

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use parentheses

fickle sandal
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$\frac1{(1-x)(1+x)}=\frac a{1-x}+\frac b{1+x}=\frac12(\frac1{1-x}+\frac1{1+x})$

ocean sealBOT
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chlamydia

fickle sandal
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yeah

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and then they multiplied both sides by -2

alpine sable
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yes i got that but why not just rearrange so its 1/1+x + 1/1-x then apply linearity so its 1/x+1 - 1/x-1

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so no need for negative, ya?

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because theres a negative in front of 1/x-1 now

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does that not work?

fickle sandal
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what's the point of that?

alpine sable
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you dont need -2 then

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its just 2

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right?

fickle sandal
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full spamming

simple portal
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srry

alpine sable
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thats what youd get by using my method

lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

.close

lone heartBOT
#
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twin thunder
#

why does k = n-1?

lone heartBOT
pale kestrel
#

"let k = n-1"

twin thunder
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yea but why

pale kestrel
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thats just a designation

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no reason, they just thought it was nicer to work with.

twin thunder
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i see

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so say this kind of question appears on an assessment... would it be easier to use induction instead of direct proofing?

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by easier i mean faster

pale kestrel
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either works

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i dont think its faster in terms of writing it down, but if its simpler to understand for you, go for it.

tender crane
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if k = n-1 and if n=0 then k = -1 or there's a thing that makes that not possible

twin thunder
#

how so

twin thunder
pale kestrel
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theres no need.

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they wanted their equivalence classes mod 3 to be
0 + 3n
1 + 3n
2 + 3n

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rather than

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-1 + 3n
0 + 3n
1 + 3n

twin thunder
#

wouldnt the answer be the same

lone heartBOT
#

@twin thunder Has your question been resolved?

lone heartBOT
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deft stag
lone heartBOT
deft stag
#

im not sure how to make the bases the same

vale wigeon
#

125 is 5^3

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27 is 3^3

lone heartBOT
#

@deft stag Has your question been resolved?

deft stag
#

alr thx

lone heartBOT
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glossy cloud
#

How do I get the answers to these questions? Please don't tell me the answer, I just want to know how.

glossy cloud
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I think I need the tangent function, but for the first one I keep getting 1.64, but it isn't that.

median oar
#

What is the tangent function

glossy cloud
median oar
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What does it do

glossy cloud
little wave
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yeah exactly its tan function

glossy cloud
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What would you say the answer to the first one is, to see if we got the same

little wave
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let me 5min

glossy cloud
#

sure. lmk

little wave
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~9.9

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you want me to explain ?

glossy cloud
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Yes please

little wave
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(i apologise for bad english)

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so first the formula is

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tan () = opposite / adjacent

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so

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adjacent = opposite / tan()

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we remplace with number

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adjacent = 4/tan(22)

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=~9.9

glossy cloud
#

Bro you're a lifesaver, I couldn't find that formula anywhere

little wave
#

its okay buddy

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you want the other ones ?

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sin and cos ?

unkempt robin
#

I mean, it's not really a formula

glossy cloud
#

Nah I've got them.

little wave
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okay perfect

unkempt robin
#

You know $\tan{\theta}=\frac{opposite}{adjacent}$

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You've got theta and you've got opposite, so you just solve the equation for adjacent

little wave
#

yeah it's an equality

unkempt robin
#

I meant tan

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**

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There

ocean sealBOT
#

USS-Enterprise

lone heartBOT
#

@glossy cloud Has your question been resolved?

lone heartBOT
#
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next mantle
#

can anyone explain how it turned into the 2nd equation?

vestal stag
#

f’g + g’f = d/dx (fg)

next mantle
#

oh right

#

thank you

#

.close

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coral flower
#

how to find the points where a functions value is increasing

coral flower
#

ik how to find a point using maxima and minima

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but how to find points , i got this question as a MCQ
Find the points at which fx = 2x^2 + 8x +3 value is increasing

vale wigeon
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"increasingness" is a property of a function itself not of its value.

vestal stag
#

if f’(x) > 0 means it’s increasing since it has positive slope

vale wigeon
#

^

vestal stag
#

Likewise with f’(x)<0

vale wigeon
#

was gonna type that but got interrupted

coral flower
#

i dont understand

vestal stag
#

Derivative

coral flower
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i only know how to find the critical points using 2nd order defferentiation

vale wigeon
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f increasing <=> f'(x)>0

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1st derivative

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not 2nd

vestal stag
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f’(x) > 0 means it has positive slope

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Means it should be increasing

coral flower
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what does it mean? f`(x) is greater so its positive

vale wigeon
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now solve the inequality 2x+8>0

coral flower
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the options to this mcq was (i am giving these options from memory so the brackets type could be wrong but they were something like this)
(negative infinity , 2] [2,infinity)
(negative infinity 0) (0,infinity)

vestal stag
#

To find the points where the function is increasing, just look for the value where f’(x) > 0

vestal stag
coral flower
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x is lesser than 0 so its decreasing?

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x can be positive also so it can be increasing ?? im confused

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<@&286206848099549185> ??

vale wigeon
#

so your function is increasing on (-4,+infty)

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the sign of x is actually irrelevant here

coral flower
#

i still dont get it

coral flower
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@coral flower Has your question been resolved?

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glacial cargo
#

How do i solve this differential equation it is in my book : sinx*y’ + cosx * y = x

glacial cargo
#

I am trying to use integrating factors, as that is what the chapter in the book is about

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Now I have the equation y’ + (cosx/sinx)* y = x/sinx

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But I Dont know how to take integral of cosx/sinx to create the integrating factor e^G(x) där G’(x) = g(x)

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What have I missed?? Am i supposed to know the integral becouse I were not thaught that in the book

pallid horizon
#

A general way to solve this type of exercise is trying to write sin(x)y'+cos(x)y as (fy)' for some f you have to find.

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So compute (fy)' and try to find f.

glacial cargo
#

Yes the book tells my that in this case were I have first order of differential equation, f = e^G(x)

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That far I have solved already

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But how to integrate????

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Oh yes sorry G(x) inte this case is cosx/sinx

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The general form for the equation in the book is: y’+g(x)y= f(x)

royal meadow
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cos(x) is derivative sin(x)

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so let y = sin(x)

pale kestrel
#

is this the integral of tan?

royal meadow
#

no

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but similar

pale kestrel
#

you know how to integrate the general form f'/f

royal meadow
#

integral of cot

pale kestrel
#

oh ok

pale kestrel
royal meadow
#

then $\frac{cos(x)}{sin(x)} = \frac{1}{sin(x)} cos(x) = {\frac{1}{y}} y'$

ocean sealBOT
#

Kaisheng21

royal meadow
#

and this is easy to integrate

ocean sealBOT
#

Statufi

glacial cargo
#

should I use substituion?

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do I need to?

lone heartBOT
#

@glacial cargo Has your question been resolved?

lone heartBOT
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hazy anvil
lone heartBOT
hazy anvil
#

"find all functions f(x) = y from X = {a, b} to Y = {u, v}. Express the answer as a set with valid functions defined by lists in the form of [f(a) = ... , f(b) = ]"

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"find all functions from X = {a, b, c} to Y = {u}"

pallid horizon
#

What's your question?

hazy anvil
#

my question is how do I find the answer?

pallid horizon
#

Well the best way is to draw your two sets side to side and find all the way to link their elements

hazy anvil
#

I wrote f(a) = u, f(b) = u, f(a) = v, f(b) = v

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and that was wrong somehow

pallid horizon
#

Actually you found 2 functions yes, one is constant equal to u, other constant equal to v, but there are others

hazy anvil
#

how many are there?

pallid horizon
#

Well, do what I proposed: draw the two sets and all functions you can find by linking their respective dots

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You will see

hazy anvil
#

will do

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it has to go from x to y, right?

pallid horizon
#

Yes

lone heartBOT
#

@hazy anvil Has your question been resolved?

lone heartBOT
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indigo solar
#

Oh

#

Also should my trial function be
y = Cx + D + E(x^2)e^2x
If λ was = 2

lone heartBOT
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wet cloak
lone heartBOT
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@wet cloak Has your question been resolved?

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spare compass
lone heartBOT
vale wigeon
#

unambiguously 1/6

spare compass
#

but here

#

they

vale wigeon
#

$\frac32$ would have been $\frac{1}{\ \frac23 \ }$

ocean sealBOT
spare compass
#

oo

#

i get it

#

there is a difference between

#

numerator fraction and denominator fraction

vale wigeon
#

there sure is.

spare compass
#

:).

#

thanks

#

.close

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#
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cinder sundial
lone heartBOT
cinder sundial
#

Are they equivalent

pale kestrel
#

what is P, E, H

cinder sundial
#

Probability, Events

pale kestrel
#

So H is an event

#

what is H'

cinder sundial
#

The non-H event

pale kestrel
#

ok but i would not use that logical not symbol

cinder sundial
#

Really

pale kestrel
#

thats not a predicate

#

\lnot applies to predicates.

cinder sundial
#

Do you mean it is obscure uncommon to use the prime to mean “non”

pale kestrel
#

I can understand ' fine.

#

i think \not is improper notation

cinder sundial
pale kestrel
#

,,\lnot

ocean sealBOT
cinder sundial
#

Yes

pale kestrel
#

unless events are predicates, i dont think they are, idk.

#

its just notation anyways. doesnt matter as long as its understood in the end

cinder sundial
cinder sundial
pale kestrel
#

🤨

#

I dont understand your original query

cinder sundial
#

We have to know when situation to use which

pale kestrel
#

the notation means exactly what it is defined to mean

#

it must be defined within some context, else it is meaningless

#

If you showed the definitions youre working with maybe your question would be clearer

cinder sundial
#

Would you use the prime or that weird notation

#

Which do you prefer

pale kestrel
#

ive told you the previous one looks better

lone heartBOT
#

@cinder sundial Has your question been resolved?

dawn kettle
#

anyone ?

lone heartBOT
#
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dense wolf
#

i've solved it up to the factors

lone heartBOT
dense wolf
#

i dont know why i got the factors, but when i asked help they said "get the factors" so i did

#

(x+4)(x-3)

#

im supposed to solve for x

real parrot
#

how did you get x+4 and x-3 ??

dense wolf
#

first i made them same base because originally on the right side it was 25^4x+5

dense wolf
#

then computed it and got 5^8x+10

#

now i solved the exponents since bases are equal, and when bases are equal i assumed that the exponents must also be equal

#

i dont know what the hell i did but for some reason i got to x^2-x=12

#

that's when they told me to get the factors

long axle
#

That ain’t it chief

dense wolf
#

yeah it sure aint it 💀

long axle
#

So u set the exponents equal

#

$x^2 + 6x -14 = 2(4x+5)$

ocean sealBOT
#

Stephen

real parrot
#

yup

long axle
#

Now get everything on one side and simplify

real parrot
#

and solve the equation

dense wolf
#

$x^2+6x-14 = 8x+10$

ocean sealBOT
dense wolf
#

i switch -14 and 8x places right?

long axle
#

Get everything to the left side

#

Bring the 8x and the 10 over

dense wolf
#

and equate them to 0?

long axle
#

Yes ofc

dense wolf
#

x^2-2x-24=0

#

am i on the right path here?

#

@long axle

#

<@&286206848099549185>

lone heartBOT
#

@dense wolf Has your question been resolved?

dense wolf
#

<@&286206848099549185>

pseudo nymph
#

what is it?

dense wolf
pseudo nymph
#

i can just do quadratic equation

#

and polynomal division mabye so idk

dense wolf
#

.-.

#

weeeelp guess i'll just continue this tomorrow

pseudo nymph
#

google it

#

or ask chat gpt

dense wolf
#

google aint know nothin

dense wolf
#

it dont even know what to do

pseudo nymph
#

use photomath

#

or ask a teacher or somthing

dense wolf
pseudo nymph
#

the thing you do is use another example and se how it solve it

#

thats how i learn shit

#

or i google it

pseudo nymph
dense wolf
#

ogey well ty anyways

pseudo nymph
#

idk i am not so good at math

dense wolf
#

.close

lone heartBOT
#
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long axle
#

.reopen

lone heartBOT
#

long axle
#

@dense wolf

long axle
#

Now do u know how to factor

dense wolf
#

yeah

#

(x-6)(x+4)

#

@long axle

#

@long axle

#

.-.

#

.close

lone heartBOT
#
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regal vine
#

can some one help me with this angerysad

regal vine
#

its real hard fr

abstract crystal
#

IDK if this is hard

regal vine
#

anyway lol, can u help me with this

abstract crystal
#

Wait

#

You sure there is no any other conditions?

#

I'm confused

regal vine
#

yes im very sure

#

this is all the infor

abstract crystal
#

I guess the only way you can solve it is to prove that these triangle are similar triangles

#

And find the ratio

#

Let me see if i could solve it

regal vine
#

yes thats a good point

#

i will try by myself 2

abstract crystal
#

Oh wait

#

I get it

regal vine
#

wow

abstract crystal
#

this triangle had two 90 degrees angle

#

which it means

#

there is an invisible circle arround the 90 degrees

regal vine
#

in the center of the big tri?

abstract crystal
#

I had a long time not doing this kind of math question

#

But it probably got many ways to solve it

regal vine
#

but how can we use this circle to solve it

#

im a little bit confused rn

abstract crystal
#

I guess

#

Let me show you

regal vine
#

ok thx

abstract crystal
#

Inscribed quadrilateral of a circle

#

yeah

#

Have you learned that before

#

∠C=∠B

regal vine
#

nope XD

abstract crystal
#

I mean

#

my bad

#

∠C+∠B=180

#

Probably useless condition

regal vine
#

but is that c + b = 90 lol

#

cuz its a tri?

#

idk actutally

abstract crystal
#

The sum of angles in quadrilateral i 360

#

two angles is already 180 degrees

#

so the rest of em has to be 180

#

but this is weird

regal vine
#

ohhh ic, but idk where is the quadri that includes c and b

abstract crystal
#

I don't think this might help

regal vine
#

its ok lol its hard fr

abstract crystal
#

lol

#

its ∠EDA

#

I forgot about it

regal vine
#

XD

#

maybe we can prove it is silmiar then we can use ratio

#

like

abstract crystal
#

yea

regal vine
#

cuz tri bde and tri bac share a same angle

#

and they both have 90 angle

#

therefore they are similar?

#

but i still cant imagine how can we get the ratio

abstract crystal
#

Yeah

#

that is the problem

regal vine
#

maybe we can make a quation contain two vari

#

and solve it

#

lets try it ilol

#

ohhhhhhh

#

i figure it out

abstract crystal
#

you did?

regal vine
#

yes

#

i can send my steps rn

#

can u see that?

abstract crystal
#

wait

#

you still have to prove that its simlar

#

You can't just do like that aren't you?

regal vine
#

yes i have proved b4

abstract crystal
#

hmm

#

ok

regal vine
#

i think they r similar

abstract crystal
#

umm yea

#

Congrats

regal vine
#

thx XD

#

thanls for helping lol

#

i forgot we can use similar at first

abstract crystal
#

np

regal vine
#

thansk for reminding

abstract crystal
#

But i totally forgot the determine of similar triangle

#

lol

regal vine
#

its ok

#

see u then

abstract crystal
#

see ya

regal vine
#

.close

lone heartBOT
#
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charred dock
lone heartBOT
charred dock
#

how do i do this

#

like I very much did it wrong

#

I have to plug in 3/x into 7x-2 right

#

how do I do that?

vale wigeon
#

you were supposed to simplify $7\cdot \frac{3}{x} -2$

ocean sealBOT
vale wigeon
#

you didn't simplify, that's what it doesn't like...

charred dock
#

lol okay ummm

#

so how do I get 7 and 2 to be able to work with x in the denominator

#

I multiply by x/x?

#

no idk if that works

#

cause then I have 21/x - 2x/x which is 19/x

#

so umm what should i do

#

dang okay

#

well um surely I can do this?

#

.close

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sick solar
#

please help me w this question : int (1/1+tanx) dx

tacit arch
#

,w int 1/(1+tan(x))

tacit arch
#

oh multiply top and bottom by cos(x)

sick solar
#

i did

tacit arch
#

so what are you stuck on?

sick solar
#

the next step

#

cosx/cosx+sinx

tacit arch
#

add and subtract sin(x) in the numerator

sick solar
#

😭

#

sinx/cosx+sinx

#

now what

lone heartBOT
#

@sick solar Has your question been resolved?

sick solar
#

.close

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desert vapor
#

x+105º=87º+98º

lone heartBOT
desert vapor
#

<@&286206848099549185>

lethal citrus
desert vapor
#

.close

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alpine sable
#

Looking for someone to do some worksheets with me cause I have a test upcoming

alpine sable
#

Pythagorean theorem

#

And some equation solvings

#

On call

#

<@&286206848099549185>

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frank briar
#

Post your problem

lone heartBOT
#

@alpine sable Has your question been resolved?

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real breach
#

Name: Caspian
University Psychology Graduate
What I seek for: Providing Homework and Class help
Likes/Interests/Hobbies: Music, Video games, Movies, Languages
Dislikes: Not that much to put here

fallen verge
#

This is not an introduction channel lol

#

Do you meed help with a math problem?

#

We can help you

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#

@real breach Has your question been resolved?

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severe olive
lone heartBOT
severe olive
#

i put in sin(38 into calc and i get math error

#

cuz i think 1.5*sin(38) is right but ye

short gust
severe olive
#

ye but

#

calc say math error

#

WTF WHY IT WORK NOW

#

still not right ffs

hoary wasp
#

are you in degree mode on your calculator

short gust
hoary wasp
#

your probably in radians

#

@severe olive

severe olive
#

ye

#

plus question changed ffs

short gust
severe olive
#

gotcha, tysm

#

.close

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tribal narwhal
#

is it ok in a limit calculus (for exemple lim[h-->0]) to compute somewhere "h = 0" and somewhere else not ?

tribal narwhal
#

like, for exemple, do we all agree that what my friend did is completely wrong ? (i'm talking about the moment where he computes h =0 on some parts of the top, but not at the bottom)

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#

@tribal narwhal Has your question been resolved?

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@tribal narwhal Has your question been resolved?

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alpine sable
#

I need some help

lone heartBOT
#

@alpine sable Has your question been resolved?

fickle sandal
#

go on then

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fickle sandal
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fickle sandal
#

.close

lone heartBOT
#
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alpine sable
#

I need help with an accounting problem. I’ll send you the problem

#

.reopen

lone heartBOT
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pastel drift
#

unban benedictseo

lone heartBOT
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half smelt
lone heartBOT
half smelt
#

If someone could explain to me what’s going on, I would appreciate it. If it’s too much to write I understand

#

I’ll find a video instead if that would be better

violet urchin
# half smelt

do you know how to convert recursive formulas to explicit formulas

violet urchin
#

alright

#

so

#

wait this is khan academy right

half smelt
violet urchin
#

is this not in the lesson or did you not understand when they taught it

half smelt
violet urchin
half smelt
violet urchin
violet urchin
#

that's basically all you do, you just add 17 to the first term to get the second, add 17 to the second to get the third, and so on

half smelt
#

Thanks man

violet urchin
#

np

half smelt
#

Problem solved

violet urchin
#

make sure to close the channel with .close

half smelt
#

.close

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wide onyx
lone heartBOT
wide onyx
#

,rotate 270

ocean sealBOT
wide onyx
#

how do i do b

#

how do i figure

#

letters out

#

how di figute the vertical and horizontal stretchs or comrpessions

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#

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polar breach
#

Hello

lone heartBOT
polar breach
#

What do I do for d and e

flat sundial
#

so d and e are dealing with the function as x goes to infinity and negative infinity

#

so with these you are putting in an x value and getting out a y value

#

for a, b, and c the limits had y go off to infinity or negative infinity

#

do you see why d and e would be different?

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#

@polar breach Has your question been resolved?

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last ether
#

You can try using L'Hopitals

#

If a limit of f(x)/g(x) goes to 0/0 or inf/inf, then you can take the limit of f'(x)/g'(x)

#

derivative

#

You can also try rewriting cot^2(x) as a fraction

#

Then go from there

#

Yeah

#

Yeah

#

1 = cos^2 + sin^2

#

With some manipulation from that and substitution, you get the other identity

#

cos(2x) = cos^2(x) - sin^2(x)
= 1 - sin^2(x) - sin^2(x)
= 1 - 2sin^2(x)

#

the fact that cos^2(x) + sin^2(x) = 1

#

I replaced cos^2(x) with 1 - sin^2(x)

#

Yeah

#

Yeah

#

Combine like terms

#

Try both

lone heartBOT
#
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hearty ferry
#

we want to find req of this situation, is anyone getting 5.163 for this?

hearty ferry
#

and whats the steps pls

lone heartBOT
hearty ferry
#

im not sure how to find the solution

#

of the equavalant thing

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resistantr

lunar ravine
#

It's more of physics than maths

wary stream
hearty ferry
wary stream
#

Show your full work

hearty ferry
#

oops i did it on my calculator

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i thin i got

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12.060 now

lone heartBOT
#

Show your work, and if possible, explain where you are stuck.

#

@hearty ferry Has your question been resolved?

lone heartBOT
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@hearty ferry Has your question been resolved?

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rich basin
lone heartBOT
rich basin
#

Answer for (c) but i don't get it

lone heartBOT
#

@rich basin Has your question been resolved?

rich basin
#

<@&286206848099549185>

nocturne lily
#

if you look at a graph of e^1/x on the left side of (0,0) the function is approaching 0 but on the right the function goes to infinity

lone heartBOT
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surreal nest
lone heartBOT
surreal nest
#

how do you get

#

exp(2iz) - 10exp(iz) + 1 = 0

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surreal nest
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.close

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strange heron
lone heartBOT
strange heron
#

Having a little trouble with this one

#

i think A is correct

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and C is false

#

I think D is true as well

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but I don't know about the rest

strange heron
#

.close

lone heartBOT
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alpine sable
lone heartBOT
alpine sable
#

For 1, is it telling me to find the displacement between A+B?

tacit arch
#

A+B is a single vector

lone heartBOT
#

@alpine sable Has your question been resolved?

heady cloud
#
2x +  = 20
alpine sable
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@alpine sable Has your question been resolved?

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@alpine sable Has your question been resolved?

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undone agate
lone heartBOT
undone agate
#

Im not sure how to continue here

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I think i drew it wrong too because basketball has 25 players

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And 8 + 6 + 15 = 29 > 25

lone heartBOT
#

@undone agate Has your question been resolved?

undone agate
#

<@&286206848099549185>

left isle
#

so you have 6 that play all 3, and 15 that play both basketball and football

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which means that 15-6 of them should go in the the Football and Basketball section

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repeat the process with track and basketball, and track and football

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then you take basketball, which has 6+x+y already in it and subtract this from the total that play basketball, 25, to get the number that goes in the only basketball section

undone agate
undone agate
#

But I am a bit confused because there are 70 students. Only 25 in football, 25 in basketball, 15 in track (total of 65)

#

And we need to find how many are not in any sport

#

It cant be just 5..?

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undone agate
#

.reopen

lone heartBOT
#

left isle
#

well yeah it would be 5 then

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if you have the total number of students and the total number that play sports, then the number that don't play sports would be 5

undone agate
#

wow okay yeah

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i thought it was 5 at the beginning

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but then we were going over venn diagrams

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so i thought we needed to draw it and pull information out

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lol

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thank you

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it was helpful with the concepts getting the venn diagram set up though

left isle
#

yeah it took me a hot minute to learn how to do it. glad u didn't need it tho lol

lone heartBOT
#

@undone agate Has your question been resolved?

undone agate
#

.close

lone heartBOT
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lone heartBOT
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undone pine
#

can someone explain c) please and thank you

fickle sandal
#

interpolated: estimated within data range

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extrapolated: outside of data range

undone pine
#

well N = 28.61 so would that mean it’s extrapolated data?

fickle sandal
#

there's no restriction on N though?

#

you've estimated with d=15 right

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and the question says it used measurements from d=5-17

undone pine
#

i don’t understand

tender crane
#

isn't d=-13 according to d=5-17 or am I wrong

undone pine
#

I think it means ranging from 5-17 cm

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#

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fickle sandal
#

vieta's?

#

then try to elaborate on what you mean

wary stream
#

That is Vieta's

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Alpha and beta are the roots of the equation

fickle sandal
#

it'd be -b/a btw

#

for a quadratic?

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-3b/a

lone heartBOT
#

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real tulip
#

how do i know where they will be the same?

lone heartBOT
real tulip
#

do i just exapand it fully?

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pls help

#

pls

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heeeeeeeeelp

tawny niche
#

Use binomial theorem

real tulip
#

i know that much but how

tawny niche
#

Assume that the power of the first term in the expression is a , the other one will be 6-a

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For the term having equal powers of x and y

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Equate the power and find a

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Then use a to find its coefficient

real tulip
#

sorry i dont get it

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the power of the first term will be 12 no?

tawny niche
real tulip
#

x^12 y^6

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no?

tawny niche
real tulip
#

oh ok

tawny niche
#

Man it's hard to explain this online

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Will have to write much

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Wait ,someone else will help u I gotta go

real tulip
#

<@&286206848099549185>

#

idk bro

tawny niche
#

Do you know the expression for a general term in a binomial expansion?

real tulip
#

ya

tawny niche
#

What's that?

#

Tell

real tulip
tawny niche
#

Yeah this

real tulip
#

mine or his

tawny niche
#

ur

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Now suppose the term having equal powers of x and y as , ⁶Cr (x²y)^r(-2y²)^(6-r)

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Now equate the power of x and y

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Here as the powers are equal

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And calc r

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Put r in the expression to find whole term eventually

real tulip
#

i reached till here:

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so r=6?

tawny niche
#

No

#

Calc mistake

#

Check again

real tulip
#

i went from x^(2r)y^r(-2^(6-r))y^(12-r)

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to the one on top

tawny niche
#

The power of y

real tulip
#

oh ya

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so r=4?

tawny niche
#

Yeah

real tulip
#

ok

tawny niche
#

Now put the value of r and get the term

real tulip
#

ok

tawny niche
#

Using the general term expression will save u time

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It will take hell lotta time if u go and expand the whole expression

real tulip
#

ya

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i didnt wanna do that

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so i asked if there was a better method

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thanks bro

tawny niche
#

Using this concept you can find the term of any given power

real tulip
#

final answer=60x^8y^8

tawny niche
#

Yeah

real tulip
#

thanks

#

.close

lone heartBOT
#
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alpine sable
lone heartBOT
alpine sable
#

been on this for ages + i still dont understand

split mantle
#

So with a, when y is less than x.

#

That means when we comes to a value of x, we get a y value that is corresponding to x value, and vice versa.

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Out of that, you're going to determine which of diagrams shaded area gives sense.

alpine sable
#

i still dont get it, sorry 😭

split mantle
#

It's alright, I'm also not satisfied with my explanation.

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If we got a graph of y = x, x and y value will be the same.

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If you look at the diagrams, the shaded areas are y values.

median oar
#

The shaded regions of the graph, have points (x,y) such that x and y satisfy a relation, namely the y < x relation

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So if you were to look at the (correct) shading, and pick any point that is shaded, it satisfies y < x

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This idea is the same when you have a line, the line on a graph are all the points that satisfies some condition (usually denoted as an equation)

alpine sable
#

i still dont undersatdsn

median oar
#

If I say y = x

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And “drew a graph”

alpine sable
#

ik what y=x

median oar
#

Where do I know to put the line

alpine sable
#

thru the origin

median oar
#

Well I can look at all the points on the plane, let’s pick (3, 4)

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Is 3 = 4?

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No, I don’t colour this point

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Let’s pick another point (0, 5)

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Is 0 = 5?

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No, I don’t colour this point

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Let’s pick another point (-1, -1)

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Is -1 = -1?

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Yes, let’s colour in this point

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Let’s pick another point (4, 4)

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Is 4 = 4?

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Yes, let’s colour in this point

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If you do this to every point on the plane

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You will get at the end

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,w graph y = x

median oar
#

These are all the points you “coloured in”

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All other points do not have y = x