and then third is 0
#help-0
near apex
Meaning that third is not possible
near apex
You can. It's not much. Right?
fast nest
i wouldn’t say it’s much
which is why i haven’t been
because it’s being pulled from the graph
and he doesn’t state to show work
fast nest
alright
near apex
Btw, i'm assuming that your matrix is correct. I haven't checked it.
near apex
Interesting interjection. Lol.
near apex
so i hope it’s correct
Let me check then.
fast nest
yeah i would literally have to start all over
near apex
It's correct.
near apex
Similarly, you can fill the last matrix.
near apex
but idk how to do the last one
Come on, you know it. Be more confident.
We just learned it.
near apex
like idk how to fill it out
Oh. See If row number is 1 and column number is 2, then you need to find number of ways you can go from 1 to 2 while stopping in exactly one city on the way.
near apex
or were you talking about that
Yes. I was talking about matrix. You know it.
near apex
Oh. See If row number is 1 and column number is 2, then you need to find number ...
Similarly do for all.
fast nest
i’m not comprehending sorry
fast nest
row 1 column 1
near apex
yes
Now, remember that row number is the starting city while column number is the end/destination city.
So for B11, where do you have to go and from where?
fast nest
i’m not sure i’m sorry
near apex
row number is the starting city while column number is the end/destination city.
What is row number in B11 ?
near apex
row 1 column 1
You just told me here.
fast nest
yes
near apex
Okay. tell me row and column for B24.
fast nest
row 2 column 4
near apex
Nice.
Now row is the starting city.
That means for B24, we see the paths which start at 2.
Column is destination.
That means for B24, we see the paths which end at city 4.
Overall, B24 means that paths which start at city 2 and end at city 4.
Makes sense yet?
fast nest
yes
near apex
Good. This was the general logic.
But
For matrix B, they have given extra conditions as well.
What is it?
fast nest
well i was confusing it i thought you were telling me to say the actual number to write down in the matrix
i know how the row/column works
and
near apex
You have to write actual numbers in the matrix.
fast nest
i know
i’m saying i thought you were telling me to already do it
when i didn’t know how to
near apex
I'm trying to tell you what each entry $B_{ij}$ means so that you can compute it.
ocean sealBOT
Enemagneto
fast nest
but the conditions are going from one city to another while stopping in one other city
near apex
when i didn’t know how to
But we just did it.
near apex
but the conditions are going from one city to another while stopping in one othe...
Exactly.
So, B24 finally means - how many ways are there of going from city 2 to city 4 while you can only stop in one city in between.
Possible cases - 2 1 4 and 2 3 4
Just calculate and put in the matrix.
Similarly, do for all.
Still confused?
fast nest
is it 2
near apex
You mean B24?
fast nest
nvm it’s 4?
near apex
We can.
near apex
In fact, we did. In q5 (a)
near apex
See. It's the same thing.
near apex
it says to another city
No. That's just the way of writing. They meant that from every row to every column.
fast nest
oh alright
near apex
so all 16 possibilities.
fast nest
just wanted to clarify
near apex
= 8
Yes
In fact, you have already calculated all diagonal elements already in question 5.
B11, B22, B33, B44
near apex
Hopefully, those are correct.
near apex
I have to scroll up to matrix again and again. It's a bit irksome.
near apex
No. I have faith in you. Lol
fast nest
oh ok
near apex
So, can i extend my faith into taking it that you'll do the rest?
near apex
Awesome. I have to go to sleep.
near apex
this is what i’m doing
Okay.
near apex
Yes. Correct. Add these two.
fast nest
ok
and yeah same i have to sleep too but i can’t
have to stay up doing this
thank you so much for the help though
you’re a life saver truly
near apex
have to stay up doing this
It shouldn't take long.
fast nest
.close
misty moat
need help
atomic harbor
!status
lone heartBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
Okay
what does lim_x--> -3⁻ f(x) mean?
misty moat
it means that the limit is -3
atomic harbor
No
misty moat
then idk
atomic harbor
That means the value the function f(x) is approaching as x approaches -3 from the left
misty moat
ok
atomic harbor
So can you figure it out now?
misty moat
no
atomic harbor
f(x) = 3x+11 for x < -3
What value this function is approaching as x approaches -3?
misty moat
what?
atomic harbor
lim_x-->-3 (3x+11)
misty moat
11?
atomic harbor
It's a polynomial. How do you calculate the limit of a polynomial function?
misty moat
finding the sum of the limits of the individual terms
atomic harbor
Yes
atomic harbor
lim_x-->-3 (3x+11)
So what should this be?
misty moat
20?
frosty knoll
misty moat
idk how to do it
atomic harbor
3(-3)+11
misty moat
so then this would be -(-3) + 1?
misty moat
i know
misty moat
so then this would be -(-3) + 1?
but for this question the answer would be 4?
atomic harbor
so then this would be -(-3) + 1?
Yea,that's the right hand limit at x= -3
atomic harbor
but for this question the answer would be 4?
Yes
misty moat
what would you do if it was just -3
atomic harbor
Are the left and right limits same?
atomic harbor
Yes
misty moat
so then would the answer be for this one 3?
atomic harbor
Yep
alpine sable
what would I do for this, I know its not dne
-5
atomic harbor
what would I do for this, I know its not dne
It's - 5 as the denominator (x+3) tends to infinity as x tends to infinity
misty moat
ok
alpine sable
🆗
misty moat
atomic harbor
lim_x-->a p(x) = p(a) if p(x) is a polynomial
.
alpine sable
just substitue the values until you get stuck into an indeterminant form
misty moat
ok
alpine sable
🆗👍
misty moat
-6?
alpine sable
(probably)
alpine sable
yup
misty moat
alpine sable
do yk lhop?
alpine sable
lhopitals rule?
misty moat
nope
alpine sable
what do you think should you do with this que tbh
misty moat
plug 3 into the values
opal basalt
try to factorize the numerator a bit
misty moat
ok
opal basalt
lhopitals rule?
or use this
misty moat
x+4/x+3
opal basalt
you told me to factorize them
show the steps
misty moat
x-3 x+4 and x+3 x-3
opal basalt
x-3 x+4 and x+3 x-3
correct
alpine sable
and then you can substitue
misty moat
opal basalt
factorize again then substitute
alpine sable
uh
misty moat
not sure how to factor
alpine sable
you need to cancel the roots
can you use some identity to turn (x-49) into (sqrt(x) +- smth) ?
misty moat
7
misty moat
1/14
alpine sable
the answer is probably 14
tacit bobcat
That's not going from the left
Or from negative infinity if you do not like 'left/right' descriptors
tacit bobcat
Whatever (\lim_{x \to 3^{-}}) indicates
ocean sealBOT
Watson
misty moat
need help
gray isle
do you know how to evaluate one sided limits
gray isle
one sided limits refer to limits taken from the left or right
for the left side limit you consider what's happening on the left side of 3,
for which you'd use the piece where x<3
gray isle
read how the function behaves for x<3,
and take the limit as x→3 of that
misty moat
2(3)-5 = 1
misty moat
what if it was this
gray isle
the superscript + indicates right side limit
and you'd consider what's happening to the right side of 3
and use the relevant piece
misty moat
so we're using x>3
gray isle
yes
misty moat
1 still?
gray isle
yes
gray isle
for that you'd consider the results for the individual one sided limits
if they are the same constant value, then that will be the limit
misty moat
so 1 again?
gray isle
that's asking for that value at x=3
for that, look at the piece that contains x=3 in its condition
gray isle
yes
misty moat
so 1?
gray isle
yes
misty moat
is x=3 continous?
gray isle
poor wording
misty moat
f(x) continous at x=3 i mean
gray isle
do you know the definition of continuity
misty moat
its not continous
since it isnt continous at each point in the interval
hello?
.close
lone heartBOT
gray isle
no
gray isle
.reopen
lone heartBOT
✅
misty moat
youre back
gray isle
please don't close / make new channels like that again
misty moat
I read that A function is said to be continuous if it is continuous at each point in the interval.
gray isle
where did you read that
misty moat
on your link
gray isle
read the equation above that
gray isle
see if that applies to what you have
misty moat
it doesnt
gray isle
from your work what is
$$\lim_{x\to 3} f(x)$$
ocean sealBOT
ℝam()n()v
gray isle
no
misty moat
7-2x
gray isle
the limit isn't an inequality
misty moat
and 2x-5
gray isle
i just want you to restate the final numerical value
because we already did all the work for this
misty moat
alright lets move on since we're getting nowhere
misty moat
how do you do this
gray isle
so you're just abandoning the previous question now?
misty moat
well yeah
gray isle
are you going to abandon this too if i'm halfway throuhg explaning?
gray isle
yes, for the previous example, yes, f(x) will indeed be continuous at x=3
as the limit and the value of the function is 1 at x=3
misty moat
ok
gray isle
as for this, do you know what average rate of change is?
gray isle
the definition of average rate of change in general
misty moat
10
gray isle
(not specific to this question)
gray isle
do you know the definition of average rate of change in general
misty moat
yeah
gray isle
tell me the definition
misty moat
the average rate at which one quantity is changing with respect to something else changing
gray isle
can you express that with math
misty moat
an average rate of change function is a process that calculates the amount of change in one item divided by the corresponding amount of change in another
misty moat
can we focus on the question?
gray isle
it looks like you copied that definition out of a source
which should also have the mathematical expression/equation for the average rate of change
that's what I want you to show here and subsequently try applying
gray isle
which should also have the mathematical expression/equation for the average rate of change
that's what I want you to show here
gray isle
i'm aware of the question, no need to repost it
misty moat
1920?
gray isle
how are you getting 1920
gray isle
that just says C(40) = 1920
will be need in your calculations but by itself says nothing about change
misty moat
ok so can you help me
gray isle
yes,
misty moat
I dont have a lot of time so I would appreciate it if we sped this up
gray isle
it will speed up if you follow my instructions
gray isle
did you copy this out of a book / online resource
an average rate of change function is a process that calculates the amount of change in one item divided by the corresponding amount of change in another
gray isle
in that resource did you see a mathematical equation / expression / fraction
related to that
misty moat
no
misty moat
gray isle
click inside the link
misty moat
gray isle
instead of just taking the first paragraph google cut out
gray isle
you'll see an equation telling you how to get the average rate of change from a to b
misty moat
ok?
gray isle
try applying that
gray isle
i'll go even slower
gray isle
it will speed up if you follow my instructions
gray isle
because you're refusing to comply
gray isle
is this a test?
misty moat
NO
gray isle
timed HW?
misty moat
yeah
youve spent 30mins going on and on about a definition when that doesnt help me at all
atomic harbor
The average rate of change of a function f(x) over the interval $\left[ a,b \right]$ is $\frac{f(b)-f(a)}{b-a}$ $\$
Try applying this to the question
ocean sealBOT
Normed
misty moat
that equation doesnt help
gray isle
to know how to do stuff, you NEED to know the relevant definitions
atomic harbor
youve spent 30mins going on and on about a definition when that doesnt help me a...
You need to know what you're doing just getting answer isn't enough
misty moat
THATS WHAT I WAS TRYING TO DO
gray isle
how the heck are you supposed to do stuff with aroc if you don't know its definition
gray isle
you're spending time arguing here instead of spending that last precious 3 minutes
trying to finish the question
misty moat
46.5
the answer was 46.5
and you just wouldnt fucking help me
goodjob
fucking go on and on about a definition
when that isnt the fucking answer and isnt helping me getting the answer
gray isle
<@&268886789983436800> get this person get a stern taking to
lone heartBOT
tardy stag
$\f{C(40)-C(30)}{40-30}$
ocean sealBOT
hayley!
lone heartBOT
Available help channel!
hearty citrus
What method can I use to solve this differential equation?
lone heartBOT
What method can I use to solve this differential equation?
hearty citrus
when I put it into wolfram alpha it tells me to do step 2. but why?
<@&286206848099549185>
tardy stag
it's called an integrating factor
a standard method for certain differential equations
lone heartBOT
@hearty citrus Has your question been resolved?
dark path
can anyone help in a circle theorem math
lone heartBOT
can anyone help in a circle theorem math
heavy shale
Hmmm
heavy shale
Let me do
lone heartBOT
<@&286206848099549185>
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
dark path
pls
heavy shale
Hmm thnx
dark path
lemme know
lone heartBOT
@dark path Has your question been resolved?
modern nymph
the refex angle DOE is 2×75=150 bc angle at centre = 2× angle at the circumference
lone heartBOT
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
modern nymph
I can't give out answers so yo come here so that I can explain
dark path
the refex angle DOE is 2×75=150 bc angle at centre = 2× angle at the circumferen...
ohh tyy got it
lone heartBOT
@dark path Has your question been resolved?
dark path
anyone
willow frost
Ok so, O is the center of the circle
we can figure out OED is 65 degrees
so we can also figure out AED, since we can subtract from the triangle on the right
then from there, we can figure out AEB
The angle AEB = the angle of OAE, since it would form an isosceles triangle
then from there we can figure out AOE
and ABE is half that from this theorem:
dark path
we can figure out OED is 65 degrees
alternate angle?
dark path
yh yh ik this one
willow frost
yep, it would be alternate angle
and triangle AOE is iscoceles because the perpendicular bisector of any chord goes through the center
dark path
so AEB would b 45?
dark path
and triangle AOE is iscoceles because the perpendicular bisector of any chord go...
yupp
willow frost
so AEB would b 45?
180 - 65 - 75 = 40
dark path
The angle AEB = the angle of OAE, since it would form an isosceles triangle
didnt get this part
willow frost
75 from the triangle on the right
oh, I drew an imaginary line from A to O
to make the isosceles
willow frost
ye! no prob
stark path
if u r done, consider closing the channel @dark path
dark path
.close
crimson blade
how would i do this question?
lone heartBOT
how would i do this question?
rose sigil
write out some of the sets being unioned in $\bigcup_{i\in\bN}M_i$ and see if you see what’s going on
ocean sealBOT
layla
lone heartBOT
@crimson blade Has your question been resolved?
crimson blade
write out some of the sets being unioned in $\bigcup_{i\in\bN}M_i$ and see if yo...
how would i do that? i dont really understand the actual process of unioning this set
i understand how to union 2 sets. like {1, 2, 3} U {3, 4, 5} is {1, 2, 3, 4, 5}
but i dont understand unioning these types
<@&286206848099549185>
loud monolith
nvm
median oar
what have you tried
median oar
what have you tried
sullen geode
You can just check by hit and trial method
sullen geode
this one
loud monolith
for first i tried using ln and subbing x and y into their values
but idk where to go from then
for 2nd idk where to even start
median oar
let's do the first one first
$x=-2, y=1$ satisfies $y=b^{x+c}$ and$\
x=2, y=81$ also satisfies $y=b^{x+c}$
ocean sealBOT
Frosst
loud monolith
ye
median oar
do you agree?
loud monolith
i do
median oar
so the first thing i notice is this
y=1 is a special number
we either have x+c = 0 or b = 1
do you agree?
loud monolith
okay yeah that i agree
median oar
and we know something to the power of something else (a^c) means either a = 1 or c = 0
like 1^x = 1 for all x
and x^0 = 1 for all x (x ≠ 0)
loud monolith
okay
median oar
that's the first thing i notice here
(it might not lead us anywhere, or it might be a quick way to solve this i have no idea yet)
but when doing math problems it's good to try things even if you dont know whether it'll lead to the answer
median oar
doesn't matter we'll get there
loud monolith
ok
median oar
we either have x+c = 0 or b = 1
anyhow so maybe we should try this
now if b = 1
we run into a problem
because if b = 1 then no matter what x is
y will always stay at 1
but clearly since (2, 81) is on the curve
loud monolith
true
median oar
because if b = 1 then no matter what x is
it must mean this is impossible
median oar
but clearly since (2, 81) is on the curve
since we clearly see this doesn't have y = 1
loud monolith
hmm
median oar
do you agree?
loud monolith
yee
median oar
alright so then it must mean x + c = 0
median oar
**Frosst**
and we know x = -2 from the point
so evidently c = 2
does that make sense?
median oar
so the next step is also kinda simple
we jsut sub it into the next equation
when $x=2, y=81$ it satisfies $y=b^{x+2}$
ocean sealBOT
Frosst
median oar
so evidently c = 2
we know what c is because we just found it already here
loud monolith
yee
ocean sealBOT
Frosst
loud monolith
holy shot thanks
median oar
looks like the trick we saw at the beginning did help make it easier
median oar
y=1 is a special number
we quickly saw what c must be via this observation
median oar
now for the 2nd question, have you seen "systems of linear equations" or "simultaneous equations" before?
loud monolith
not really
median oar
now for the 2nd question, have you seen "systems of linear equations" or "simult...
so you have seen these before
loud monolith
yee
median oar
if i told you that x + y = 5, and x - y = 1
solving something like this is exactly what solving systems of linear equations are
loud monolith
ah okay u meant like that
median oar
ok add them
loud monolith
8 and thats the answer
median oar
sure
loud monolith
what is the natural log of a constant
ocean sealBOT
Result:
1.6094379124341
could it ever be 0
median oar
,calc log(1)
ocean sealBOT
Result:
0
😔
median oar
👍
loud monolith
i might need some more help later, gonna be starting another paper soon
have a test tmrw
timid lark
So ultimately this is a geometric gradient question, but I think I've boiled it down to a natural log equation... I'm having trouble solving for a:
3(1.1^a) - 3(1.1^(a-1)) = .363
timid lark
Remove the 3 from the left...
1.1^a - 1.1^(a-1) = .121
a ln (1.1) - (a-1) ln (1.1) = ln (.121)
I'm not sure what I'm doing wrong, because from this point it looks like my variable cancels itself out
long axle
$\ln {(1.1^a - 1.1^{a-1})} = \ln {0.121}$
timid lark
I know a=3, because this is a rewritten form of the original question in which I decided what the variable would be and just solved the equation... this is me trying to work it backwards
ocean sealBOT
Stephen
long axle
This is what happens after u take natural log of both sides
long axle
a ln (1.1) - (a-1) ln (1.1) = ln (.121)
Not this homez
timid lark
I can't add or subtract bases with different exponents, though
long axle
Ye
So this is what u wanna do
I’ll show u
$1.1^a - 1.1^{a-1} = 0.121 \newline 1.1(1.1^a) - 1.1^a = 0.121(1.1)$
ocean sealBOT
Stephen
long axle
Do u see what I did
timid lark
I don't follow the logic...
long axle
Let’s make it more abstract
Call x = 1.1
Now
$x^a - x^{a-1} = 0.121 \newline x^a - \frac {x^a}{x} = 0.121$ $\newline$ multiplying both sides by $x$ yields $\newline x(x^a) - x^a = 0.121(x)$
ocean sealBOT
Stephen
long axle
Does this make it clearer
long axle
x^1 * x^1 = x^(1+1)
This is true, but where r u seeing this?
timid lark
I don't see it anywhere, it's just a rule for multiplying bases with different exponents
long axle
Ah ok
long axle
**Stephen**
So do u understand this
timid lark
But... it just shuffles the problem, really... because looking at the left side of the original problem:
1.1^a - 1.1^(a-1)
Multiply this side of the equation by 1.1:
1.1(1.1^a - 1.1^(a-1)) = 1.1^(a+1) - (1.1^a)
the +1 on the first base is the (hidden) exponent on the 1.1 that was distributed
long axle
**Stephen**
Do u agree we get this
timid lark
But x * x^2 is x^3... you have to put the +1 there, or you'll come to the wrong conclusion
long axle
No u don’t have to put it up there
ocean sealBOT
Stephen
timid lark
Ok
long axle
Ok so back to this
$1.1^a - 1.1^{a-1} = 0.121 \newline 1.1(1.1^a) - 1.1^a = 0.121(1.1)$
ocean sealBOT
Stephen
timid lark
Factor out the 1.1^a
1.1^a (1.1-1) = .1331
1.1^a (.1) = .1331
Divide
1.1^a = 1.331
a ln(1.1) = ln(1.331)
There it is
Thanks!
long axle
Np
timid lark
How do I release the channel?
long axle
Do .close
glad basalt
lone heartBOT
tardy tapir
they noticed that the integral was derivative of t(log_2(t^3 + 1)) using product rule.
tardy tapir
product rule
tardy tapir
correct.
lone heartBOT
tardy tapir
yw
thick lynx
Well, the general limit can only be equal to some value if the left and right limits are equal to that value
So both should be 7, yeah
lone heartBOT
lone heartBOT
Available help channel!
gentle prism
how do i write g in terms of the parent function f
lone heartBOT
how do i write g in terms of the parent function f
eager blaze
alpine sable
how does it work?
lone heartBOT
how does it work?
rustic nimbus
multiply n to n and to -2 then multiply -3 to n then to -2
alpine sable
ohhh right
rustic nimbus
green sandal
how does the ln just spawn in then moves to the other side
lone heartBOT
how does the ln just spawn in then moves to the other side
jagged cobalt
if two things are equal, then when plugged into a function you should get the same value if x=y then f(x)=f(y)
it doesnt move to the other side
its just because of how ln is defined that ln(e^a)=a
vale wigeon
"one to one property" is a bad name for this tbh
i'd call this "apply ln to both sides"
and yes you CAN summon it out of thin air like that
as long as you do it on both sides
mystic nebula
how do i find the x intercept of a negative slope?
lone heartBOT
how do i find the x intercept of a negative slope?
thick lynx
how do i find the x intercept of a negative slope?
Determine the slope
mystic nebula
yea i found it already
thick lynx
What is it?
mystic nebula
-1/3
thick lynx
Yes
mystic nebula
y = -1/3x + 6
thick lynx
You start at 6, now you want to find how long you need to go with that slope of -1/3 to reach 0
mystic nebula
yea
mystic nebula
18?
thick lynx
Yes
thick lynx
how do i find the zero of f
does the function f describe the line?
thick lynx
Then yes, the zero of f is at x = 18.
thick lynx
Did they already put the brackets or did you add them?
Maybe they just want 18 to be entered
mystic nebula
nope it has to be formatted correctly
i already lost a point for not including the brackets
wait nvm
it told me to type it as an integer
why though? the other one demanded it to be written as an ordered pair
why doesnt it have to be (18,0)?
thick lynx
(18, 0) would be a point. A zero usually means a single number, after its definition
thick lynx
why though? the other one demanded it to be written as an ordered pair
Maybe the other one asked for a point
thick lynx
if the x intercept is 0 is a line horizontal or vertical
It just means that the line crosses the x axis at 0, that would also be the case for f(x) = x, and it's neither horizontal nor vertical
thick lynx
since the intercept is 0
Where does it say the intercept is 0?
thick lynx
No
mystic nebula
oh shit its the slope
mystic nebula
so would the line be vertical?
thick lynx
No
When you go 1 in positive x-direction, you go 0 in positive y-direction
m = change in y/change in x
thick lynx
Yes, do you also need to mark the point P?
Or are those two blue ones just for you to drag it
mystic nebula
yea
well i marked the point and since its the line i needed it to end on the graph
thick lynx
Then yeah, should be correct
fiery tangle
Is the domain for this:
lone heartBOT
Is the domain for this:
atomic harbor
!show
lone heartBOT
Show your work, and if possible, explain where you are stuck.
fiery tangle
i can?
atomic harbor
Yes
atomic harbor
Not sure
fiery tangle
[-5,-3)∪[-3,-1]∪[1,5]?
atomic harbor
[-5,-3) U [-3,-1] = [-5,-1]
unreal kestrel
corrections?
lone heartBOT
corrections?
edgy path
corrections?
What’s the question you have? What is the constant?
cursive cosmos
edgy path
unreal kestrel
is leading co efficient -8
edgy path
Yep
edgy path
whats a constant term
A constant term is a term that is unaffected by the independent variable
covert wraith
am i missing anything
circle all the points where the graph crosses through y=0
you're only missing one right now
covert wraith
yess
covert wraith
its telling you to write no real solutions
unreal kestrel
SKULL
dim terrace
lone heartBOT
dim terrace
how do i do the bottom two
dim terrace
sorry i mean bottom 3
wet linden
Would make the function undefined
dim terrace
right
wet linden
So can you find what x value makes it 0?
dim terrace
uh
wet linden
2x-10=0
wet linden
,rotate
ocean sealBOT
wet linden
,rotate
ocean sealBOT
dim terrace
wet linden
,rotate
ocean sealBOT
wet linden
wait so only one of the values need to be 0?
what value of x would make the bottom 0
dim terrace
5
wet linden
yes
tidal fox
- x=5
wet linden
so 5 is not included
dim terrace
right
wet linden
so now try to work the one above it
wet linden
or you could just find the domain of the function
and then figure out which numbers trhat includes
@dim terrace
what did you get for the 2nd?
dim terrace
0.6
wet linden
.
dim terrace
-3
wet linden
yes
x cannot equal -3
because -3 +3 would equal 0
and anything divided by 0 is undefined
wet linden
oh
ok so for the final
theres 2 ways to do it
you can either plug in each value for x
or you can solve for the domain
dim terrace
right
wet linden
so
it might honestly be easier to plug in numbers
unless you know how to find the domain
wet linden
ok so ill help you with asnwer choice a
tidal fox
The function f(x)= (x-2)/(x+3) is not defined when the denominator is equal to 0. This occurs when x=-3. Therefore, the value of x that does not belong to the function is x=-3.
If you try to calculate f(-3), you get the following division:
f(-3) = (-3-2)/(-3+3) = -5/0
This division is undefined, therefore f(-3) is an undefined value.
wet linden
so 2(0) -7