#help-0

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rotund crater
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stewart calculus numer 2.1 exercise 1 . helpm with letter c

rotund crater
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my work is alriught?

lone heartBOT
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@rotund crater Has your question been resolved?

opal jolt
#

Empieza por graficar la función.
Sabes que P es el punto (15, 250).
Llama Q1 al punto (5, a), Q2 al punto (10, b) etc

lone heartBOT
#

@rotund crater Has your question been resolved?

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flat vale
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what do we call tenth, hundreds, thousands, and so on?

flat vale
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like a word for that

atomic harbor
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Place values?

flat vale
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like order of magnitude

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powers of tenth

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i need a concice name for my program

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for one of my variable

idle bay
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It’s called a place value

lone heartBOT
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@flat vale Has your question been resolved?

flat vale
#

.close

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stuck ruin
lone heartBOT
vale wigeon
#

!status

lone heartBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
vale wigeon
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also what are you asked to do with this

stuck ruin
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simplify?

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i cant really find a solution

vale wigeon
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i strongly suspect this might be as far as you can simplify it

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also i suspect there might be something you have mistakenly cropped away

stuck ruin
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wwolfram alpha said the other

lone heartBOT
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@stuck ruin Has your question been resolved?

stuck ruin
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ccan i ask other ppl?

opal jolt
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can you provide the full instructions of the question?

stuck ruin
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oopps not that

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simplify

opal jolt
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Done. Next question?

stuck ruin
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?

opal jolt
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If there's nothing more on that, that's the simplest form that number can take.
Thus, it's simplified, and you're done.

stuck ruin
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bruh

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wwhy does wolfram alpha said its can be simplified more????

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bruh

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can i ask other ppl or just wait for the answer?

surreal trail
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Try and do the math, show us your progress and then we can help

lone heartBOT
#

@stuck ruin Has your question been resolved?

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thorn pebble
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can anyone help me create two triangles with two equal sides and one equal angle? but they cant be congruent

coral flower
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that not possible

thorn pebble
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yes it is

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the angle doesnt need to be inbetween them

coral flower
thorn pebble
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its not sas

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its ssa

coral flower
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its the same thing

thorn pebble
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no

frank briar
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If the angle not between them they are not necessarly congutent

thorn pebble
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first one is impossible second one is possible,

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i need two triangles that have two equal sides and one equal angle that are not congruent

near apex
# thorn pebble

Look closely. Isosceles so others angles also become equal.

thorn pebble
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S is not measurement

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it just means its a Side

near apex
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I know.

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Still, look closely.

thorn pebble
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theyre not isosceles tho

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thats not the point

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when i say two equal sides i mean between the triangles

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like a triangle with sides 3,4,5 and one with sides 2,4,5

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they have two equal sides

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(4 and 5)

near apex
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Okay. Yes, i get it. I misunderstood.

thorn pebble
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no problem

tardy stag
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what i tend to do with these is imagine a physical model

near apex
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I still find it hard to imagine if that would be possible.

tardy stag
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with like sticks and springs

thorn pebble
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i mean im trying, i used my imagination a bunch on this question

thorn pebble
near apex
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Okay. I got how you can do it. Angles don't have to be corresponding.

tardy stag
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hint: it won't work with a right triangle

thorn pebble
near apex
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Actually, it's only possible if angle is not corresponding.

near apex
tardy stag
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i don't think it will work with isosceles either

thorn pebble
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hmhm

near apex
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Draw a side of a for one triangle. Draw b for another one. Then draw equal angle for both. Take a on angle arm for one. On another side for another.

tardy stag
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hint: SSA does not constrain you to one triangle, but it nearly does

thorn pebble
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you mean it almost constrains to scalene?

thorn pebble
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same angle for both

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wdym by "take a on angle arm for one. On another side for another"

tardy stag
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I'm not sure

what i would do is choose an angle and two side lengths and then construct a triangle with that in that order, paying attention to where you're making hidden assumptions

thorn pebble
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i think i did it?

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first proving sides are equal

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then proving A is the same angle on both, though not quite let me see if i can fix that

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i think thats good enough and sides are still equal

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thx for the help

near apex
lone heartBOT
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@thorn pebble Has your question been resolved?

thorn pebble
# near apex

ok i see they share two sides, but are you sure angle A is divided into two equal parts?

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wait they dont even have two equal sides

near apex
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No. CAB and ACD are equal.

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Parallel lines.

thorn pebble
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parallel lines what?

near apex
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AB and CD are parallel

thorn pebble
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yeah but so what?

near apex
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Alternate angles made by a transversal intersecting two parallel lines are equal.

thorn pebble
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well only one equal side and no equal angles

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OOh i see

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C is equal to A

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top C and bottom A

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yeah im dumb

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two equal sides and one equal angle

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alpine sable
lone heartBOT
alpine sable
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i dont get 3d

tacit arch
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5, 10, 15, 20, ...

alpine sable
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agreed, therefore
8* 7* 2 ??

tacit arch
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well it can start with 5

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does your calculation include numbers like 510

alpine sable
alpine sable
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i mean

tacit arch
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are you saying 510 is not divisible by 5

alpine sable
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it has to be divisible by 5

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no wait

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you're right

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but my solution isn't correct

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for some reason you have to split it

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one calculation includes 0 being the last digit

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the other one is 5 being the last digit

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but i dont see it

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the sense

tacit arch
alpine sable
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it does

tacit arch
tardy stag
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i think it has to do with the fact that 015 is not a three digit number

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but 510 is

alpine sable
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but i still dont see why 8x7x2

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isnt correct i mean

tacit arch
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so you need to add those cases to 8 * 7 * 2

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so identify how many of them there are

alpine sable
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8

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wait..

lone heartBOT
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@alpine sable Has your question been resolved?

lone heartBOT
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lone heartBOT
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dull prawn
#

.solved

brave stump
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alpine sable
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pls chelp me what is this monstrosity

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#

@alpine sable Has your question been resolved?

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@alpine sable Has your question been resolved?

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@alpine sable Has your question been resolved?

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alpine sable
#

d

lone heartBOT
alpine sable
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need help with this, someone please help asap

wary stream
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You didn't need to close your previous channel

alpine sable
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i need help with this

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<@&286206848099549185>

lone heartBOT
# alpine sable <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

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@alpine sable Has your question been resolved?

alpine sable
#

<@&286206848099549185>

#

i need help

rocky grove
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@alpine sable do you need this channel?

wary stream
#

.close

lone heartBOT
#
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wary stream
#

They have #help-34

lone heartBOT
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heady tendon
lone heartBOT
lavish cedar
#

Hello!

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I wanted to know is this pre algebra?

heady tendon
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algebra 2

lavish cedar
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Okay what is the question?

heady tendon
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i can type it out if u want me to

lavish cedar
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No no no. What do you?

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Not understand

heady tendon
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okay so i need 2 equations since this is elimination

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25x +10y = 180

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for time

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but where do i get the second equation

lavish cedar
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Could you clarify that?

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Two equations

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And elimination what do you mean?

heady tendon
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it’s elimination

lavish cedar
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So between what equations?

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Are you trying to eliminate?

heady tendon
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i have to eliminate either x or y to single out a single variable

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that’s why i need a second equation

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i can show u a previous problem of u need me to

lavish cedar
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Solve this system of equations

25x+10y=180
x+y=12

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That's what I got

heady tendon
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yeah i did too but 12 and 180 are two different variables

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that’s why i get confused

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i’ll solve that and see if the answer makes sense

lavish cedar
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Okay

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Here's what I wrote

heady tendon
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that makes sense but it isn’t solved used elimination

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i would get points off

lavish cedar
#

?

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What do you mean by elimination

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I'm not understanding what you're saying

heady tendon
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i’ll send a pic one sec

lavish cedar
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So what would you like me to do?

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What are you confused onto available

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On so I can help you

heady tendon
#

wait never mind i did it

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ty tho

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.close

lone heartBOT
#
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pulsar spire
lone heartBOT
pulsar spire
#

f(x) = x^2 − 3x

Im trying to find the domain of this function, but Im not sure where to go from here, or if i even did it right.

placid zinc
#

,w graph x^2 - 3x

placid zinc
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Make sure you know the definition of "domain"

pulsar spire
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domain is just the x axes>

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?

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or what it can be ig

placid zinc
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You'll need a more specific definition

pulsar spire
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its a set of inputs, that are allowed in a function

pulsar spire
# pulsar spire

what would be your first step in getting the domain to this? I am not sure if " = 0" was correct, or not

placid zinc
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You don't need to do any rearrangements

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What values can you plug into f(x) = x² - 3x?

Or to ask the opposite, what values "mess this function up"?

pulsar spire
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i see

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ima try it, one min

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yea im lost

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i know how to find domains to something like this, but its the multiple x’s that are confusing me

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@placid zinc

placid zinc
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So x = 4 is an element of the domain, since you can plug it in

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What can't you plug in?

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Helps to look at the graph

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,w graph x^2 - 3x

pulsar spire
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you can plug in any domain

placid zinc
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You can plug in any point, yes!

pulsar spire
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finallyyy

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i went dumb bro

placid zinc
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So the domain is all values of x.

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All real numbers, I should say

pulsar spire
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sry for wasting ur time

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ty

placid zinc
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Note that every polynomial has "all real numbers" as a domain

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Not a waste at all. Thx for thinking through it with me

pulsar spire
#

.close

lone heartBOT
#
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ripe stone
lone heartBOT
ripe stone
#

need help asap

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cant find f(x)<=0

jagged cobalt
#

the way youve written it is saying: -3<x<-inf or 3<x<=0 which doesnt really make sense

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the numbers are right but youve written it wrong

ripe stone
jagged cobalt
#

the left one for example should be (-inf,-3)

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left boundary goes on the left, right boundary on the right

ripe stone
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right is correct?

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just makin sure

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its my last attempt

jagged cobalt
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right is wrong for the same reason as the left one

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youre basically implying 3<0

ripe stone
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(0,3)

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or (0,3]

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brackets confuse me

jagged cobalt
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[0,3)

ripe stone
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(-infin,-3)u[3,0)

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thanks

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0,3

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not

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3,0

lone heartBOT
#

@ripe stone Has your question been resolved?

lone heartBOT
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main cedar
#

how do I solve these? (probability)

lone heartBOT
main cedar
#

i know the first one is 8!

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I got stuck on the 2nd one.

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<@&286206848099549185>

lone heartBOT
#

@main cedar Has your question been resolved?

lone heartBOT
#

@main cedar Has your question been resolved?

graceful pawn
#

i can try to help @main cedar

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if 5 specific persons insist on following each other, their order is fixed

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so take the 5 specific people as one person

main cedar
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why?

graceful pawn
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they insist on following each other

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so they stick to each other and their order is fixed

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so they are "one" value

main cedar
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so 5! x something. right?

graceful pawn
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why is it 5!

main cedar
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because any sequence of those 5 people need to be accounted for?

graceful pawn
#

really?

main cedar
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idk

graceful pawn
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because I thought that the 5 people have a fixed arrangement

main cedar
#

its fixed, but that doesnt change the fact that the question wants all possible ways of arrangement.

graceful pawn
main cedar
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I'm sorry, are you testing me, so I can give the correct justification even though i have the right answer? Or am I actually wrong?

graceful pawn
#

no, I'm also confused about what the question is asking for

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I need to understand what it means by the 5 specific persons insist on following each other

main cedar
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it could mean that they have to be adjacent in line to one other, and the fact that they could change the order theyre standing in line together, means there are 5 x 4 x 3 x 2 x 1 ways they could stand in line together

graceful pawn
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they have to be adjacent

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can they change their order while staying adjacent to one another?

main cedar
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yeah

graceful pawn
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ok so, if they can change their order, the no. of combinations, as you said, is 5!

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now, treat the five people as one entity

main cedar
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ok

graceful pawn
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that means (5 people) (1 person) (1 person) (1 person)

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how would u arrange this

main cedar
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so that means there are 4 total entities?

graceful pawn
#

yes

main cedar
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5! X 4!

graceful pawn
#

that should be correct holoYay

main cedar
#

i just submitted the answer on my class's hw page and it came out correct. Thanks man i appreciate it!

graceful pawn
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for the third part

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i think I can help you as well

main cedar
#

Thanks to your help, I already solved it: 8! - 2!7!. It uses quite the same logic.

#

.close

lone heartBOT
#
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charred dock
#

so

lone heartBOT
charred dock
#

is there an infinite number of point slope forms

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because you can get y2-y1/x2-x1 as like an infinite number of varriations right

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in the same line

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because any point can be either x1,y1 or x2,y2 right

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tell me I'm not crazy

gray isle
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missing a lot of (), but yes

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using the slope and any random point on the line will give a point-slope form for that line

charred dock
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okay

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so there's no 1 point slope form?

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as many point slopes as there are points?

gray isle
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yes. though in questions they'd usually ask you to use a specific point

charred dock
#

yes yes

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thank you

#

.close

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#
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remote heron
#

I need help with this guy

lone heartBOT
remote heron
#

Show that $(x+1+O(x^{-1}) )^x = ex^x + O(x^{x-1})$ as $x \to \infty$

ocean sealBOT
#

jan Niku

remote heron
#

is there some kind of binomial trickery or something

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im not sure how to even start

forest cobalt
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ok

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factor x inside that parenthesis

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factor x from x+1

remote heron
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? to get $\qty( x \qty( \frac{x+1}{x} + O(x^{-2})))^x$

ocean sealBOT
#

jan Niku

forest cobalt
#

not quite

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$x(1+1/x)$

ocean sealBOT
#

TooManyCooks

forest cobalt
#

But more to the point

remote heron
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sure the limit here is e^x

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but

forest cobalt
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You have $x^x (1+1/x)^x$

remote heron
#

err

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wait

ocean sealBOT
#

TooManyCooks

forest cobalt
#

Limit as x-> infinity that parenthesis is e

remote heron
#

hold on 1s

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im not sure i follow

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how are you ditching the rest?

forest cobalt
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I'm not

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x^x is still there

remote heron
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it should be $\qty( x \qty( 1 + \frac 1x) + O(x^{-1}) )^x$ still

ocean sealBOT
#

jan Niku

remote heron
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what happens to the rest of the expansion

forest cobalt
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x goes to infinity

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the behavior is dictaed by the leading term in the expansion

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which is x^x

remote heron
forest cobalt
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Think of it this way

remote heron
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sorry my teacher is not very good

forest cobalt
#

If I had $(x+1)^2$ I get $x^2 + 2x + 1$

ocean sealBOT
#

TooManyCooks

remote heron
#

oh youre using leading to mean something different than what im thinking

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okay

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i get what you mean

forest cobalt
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ok good

remote heron
#

so wait

forest cobalt
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yeah that's all i meant

remote heron
#

one second lemme right

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write

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can i ping in a bit if i get stuck

forest cobalt
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Sure

remote heron
#

i wanna write some more out so i have a good example

#

@forest cobalt so the order of the error would be the next term? thats $$\qty( x \qty(1 + \frac 1x ) ) ^{x-1} O(x^{-1})$$

ocean sealBOT
#

jan Niku

remote heron
#

but this doesnt seem like its going to match the RHS

forest cobalt
#

why is the power to x-1

remote heron
#

wouldnt this have order $O(x^{x-2})$?

ocean sealBOT
#

jan Niku

remote heron
#

the leading term takes the ^x

#

the next one which hits O(x^-1) loses a power of the other factor, right?

#

like (x+3)^3 would have leading term x^3 + O(x^(3-1))O(1)

#

@forest cobalt sadcat

forest cobalt
#

lmao wait

lone heartBOT
#

@remote heron Has your question been resolved?

forest cobalt
#

I promise I'm still thinking this through

remote heron
#

oh wait

#

@forest cobalt its big O right

#

so like x is O(x^2)?

forest cobalt
#

ye

remote heron
#

then wouldnt x^(x-2) be O(x^(x-1))?

forest cobalt
#

I'm trying to get the $+O(x^{x-1})$

ocean sealBOT
#

TooManyCooks

remote heron
#

right, i think im there

#

I'm saying that like

#

(x + O(x^-1) )^2

#

so this would be

forest cobalt
#

I have (1+ $+\frac{O(x^{-1})}{x+1})^x$

ocean sealBOT
#

TooManyCooks

forest cobalt
#

i fucked up the + sign. wtver

remote heron
#

$(x + O(x^{-1}) )^2 = x^2 + O(x^0) = x^2 + O(x^{0+1})$

ocean sealBOT
#

jan Niku

remote heron
#

i think im really abusing notation here

forest cobalt
#

Lemme type what I have

#

$(x+1+O(x^{-1}))^x = x^x (1 + \frac{1}{x} + O(x^{x-2}))^x = x^x (1+\frac{1}{x})^x (1 + \frac{O(x^{-1})}{x+1})^x$

ocean sealBOT
#

TooManyCooks

remote heron
#

I mean can we agree up to $\qty(x+1 + O(x^{-1}) )^x = ex^x + O(x^{x-2})$

ocean sealBOT
#

jan Niku

forest cobalt
#

What?

remote heron
forest cobalt
#

It better be

#

but we haven't shown that yet

remote heron
#

so you agree?

#

well sure we have

forest cobalt
#

my intuition says yes

remote heron
#

just use binomial thm

#

that term will be $C \qty( x \qty(1 + \frac 1x) ) ^ {x-1} O(x^{-1})^1$ right

ocean sealBOT
#

jan Niku

forest cobalt
#

i can sort of bs my way through it

remote heron
#

this is an applied math class bs is fine

forest cobalt
#

$(1+ \frac{(O(x^{-1})}{x+1})^x \approx (1+ \frac{(O(x^{-1})}{x})^x = (1+ O(x^{-2}))^x \approx (1+ O(x^{-2}))$ in the limit as $\x\to\infty$

ocean sealBOT
#

TooManyCooks
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

forest cobalt
#

to be honest i'd turn that shit in hahahaha

remote heron
#

its not graded

#

lol

remote heron
#

or not

#

but ill mark this as resolved i guess

#

thanks for the help @forest cobalt

#

.close

lone heartBOT
#
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upbeat hornet
#

How do you do this? I tried replacing each of the derivatives with the limit definition, but now I have 2 h’s going to 0

vapid shuttle
#

:p

upbeat hornet
vapid shuttle
#

totally fair, I always ask here too

#

have you tried any Lhop

upbeat hornet
#

actually I ended up helping for an hour before asking this question

upbeat hornet
lone heartBOT
#

@upbeat hornet Has your question been resolved?

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opaque heart
#

What is this called?

lone heartBOT
opaque heart
#

I know why this works but is there a name for this thing that was used to get rid of the 6 on the bottom?

hard mountain
#

Cancelling out numbers?

opaque heart
#

Is that all it's called?

tardy tapir
#

its an operation of dividing both the numerator and denominator by 6, sometimes called 'cancelling'

hard mountain
#

You could also say that youre reducing the fraction to its lowest terms

#

By cancelling out common factors

opaque heart
#

Got it

#

"cancelling" or "cancelling out common factors in a fraction"

#

thank you!

#

.close

lone heartBOT
#
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wise jewel
lone heartBOT
wise jewel
#

am i being asked to find the derivative?

gray isle
#

derivative at 3

wise jewel
#

ok so like

#

how do i get the 3 out of the parenthesis so i can do the simple power rule

gray isle
#

you could choose to expand first

#

or alternatively apply power chain rule

winter shadow
#

(3-x)^2 = (3-x)(3-x) then expand this

wise jewel
#

i get $x^2-6x+9$

ocean sealBOT
#

Black Hat

wise jewel
#

and then i distribute the 4 and get $4x^2-24x+36$

ocean sealBOT
#

Black Hat

gray isle
#

yes

wise jewel
#

ohhh

#

wait

#

8x-24

#

thats the derivative

gray isle
#

yes

wise jewel
#

but then im not sure what im supposed to do with the point they gave us

#

just plug it into that equation?

gray isle
#

yes

wise jewel
#

hm ok, so, 8(3) - 24 = 2

gray isle
#

how are you getting 2 from that...

wise jewel
#

💀

#

im actually sped

#

sorry

#

0

#

jesus christ

#

got it

#

LMAO

#

tysm

#

so what exactly does this mean

winter shadow
#

do you know what a horizontal tangent line is?

lone heartBOT
#

@wise jewel Has your question been resolved?

lone heartBOT
#
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exotic ingot
#

My math book says this is how to start solving the equation. But why can't it be for example -3x = 2x?

vapid shuttle
#

, rotate

ocean sealBOT
vapid shuttle
#

-3x=-2x is the same as 3x=2x

#

divide both sides by -1

#

and you will see

exotic ingot
#

I know that by why cant it become -3x = 2x, not -3x = -2x

vapid shuttle
#

it can

exotic ingot
#

So i just choose

vapid shuttle
#

3x=2x is the same as -3x=-2x

#

and 3x=-2x is the same as -3x=2x

#

so sure, just choose your favorites

#

the solution guide is making use of the property that cosine is an even function, meaning that cos(-x)=cos(x)

exotic ingot
#

How about sin. In that case would you also be able to choose which one would be negative

vapid shuttle
#

sin(x) does not have this same property

#

it is an odd function

#

sin(x)=-sin(-x)

exotic ingot
#

Ok

#

Thx

#

.close

vapid shuttle
#

np

lone heartBOT
#
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alpine sable
#

pls

#

help me

lone heartBOT
alpine sable
vale wigeon
#

impossible/nonelementary in general

#

do we know what f is?

alpine sable
#

wait

#

i'll send the complete question

vale wigeon
alpine sable
#

cause i thought it won't be necessary as we would have to compute the integral anyway

vale wigeon
#

ok but like post the full problem

#

,rccw

ocean sealBOT
vale wigeon
#

just differentiate x^5/5 ??

alpine sable
#

ok

#

but

#

like

#

is there not a different way

vale wigeon
#

no you cannot compute the integral of e^f(x) in general

alpine sable
#

can we not solve this integral

vale wigeon
#

it is nonelementary even for such tame f(x) as -x^2

alpine sable
#

okay

young finch
alpine sable
#

thanks

#

wait i have one more que

#

why is this is true ?

#

@vale wigeon

#

my math teacher just gave it as a note but did not elaborate o it

vale wigeon
#

a pair of straight lines is $(a_1 x + b_1 y + c_1)(a_2 x + b_2 y + c_2) = 0$

ocean sealBOT
alpine sable
#

yes

vale wigeon
#

ie the product of two general-form straight line equatoins

#

so like

#

if you expanded all that, then collected all the coeffs, and went thru the pain of calculating that determinant

#

thatd be your answer ig

#

theres probably some kind of clever linear-algebraic way to look at it which i do not currently have the energy to articulate fully

alpine sable
vale wigeon
#

yeah it is not

alpine sable
#

how do I deal with questions like the 1st one

#

,rccw

ocean sealBOT
alpine sable
#

rational coordinates one

#

@vale wigeon

vale wigeon
#

question #1...?

alpine sable
#

the one that's not ticked

vale wigeon
#

well ok like

#

$(x - \sqrt{5})^2 + y^2 = r^2$ is the equation of the circle

ocean sealBOT
vale wigeon
#

we don't know r but we want this thing to have rational solutions...

alpine sable
#

yes

vale wigeon
#

drawing a blank here ngl

#

smells like some big brain number theory shit

alpine sable
#

no it's not

vale wigeon
#

i wouldnt be surprised if you can fit infinitely many points on it but i do not see how

alpine sable
#

because i am not taking a number theory class

#

its highschool math

alpine sable
wary lantern
#

Hi

alpine sable
#

there must be a simpler way

vale wigeon
#

i am drawing a blank here still

alpine sable
#

can't we do something using parametric coordinates

vale wigeon
alpine sable
#

@mellow saffron

#

lol

#

can we not ping help anymore

alpine sable
young finch
#

if ann doesnt know i definitely dont know

alpine sable
#

so u wont even try

young finch
#

im not that smart lol

alpine sable
#

no one is smart

#

lol

#

generation of smart ppl is gone

tardy stag
#

i wonder if it's 1

alpine sable
#

nope

#

i thought the same

lone heartBOT
#

@alpine sable Has your question been resolved?

vale wigeon
#

@alpine sable can you ping and/or dm me if you do find a solution? i am actually kind of interested what im missing here.

alpine sable
#

sure

lone heartBOT
#

@alpine sable Has your question been resolved?

mellow grail
# ocean seal

hmm if it was integer coordinates then i would have a solution for this

#

wait i might have got it

#

lemme try

#

$(x - \sqrt{5})^2 + y^2 = r^2$

ocean sealBOT
#

ItzKraken

mellow grail
#

$(x - \sqrt{5})^2 = r^2 - y^2$

ocean sealBOT
#

ItzKraken

mellow grail
#

$x = \sqrt{5} \pm\sqrt{r^2 - y^2}$

ocean sealBOT
#

ItzKraken

mellow grail
#

now x is rational

#

y is rational

#

therefore

#

$\sqrt{r^2 - y^2} = a \mp \sqrt{5}$

ocean sealBOT
#

ItzKraken

mellow grail
#

where a is any real

mellow grail
#

put y=r

#

we obtain $a=\mp\sqrt{5}$

ocean sealBOT
#

ItzKraken

mellow grail
mellow grail
#

Find r (r = sqrt(5)/2)

mellow grail
#

Wait no it still doesn't help

#

Hmm

mellow grail
# ocean seal **ItzKraken**

If you put x=0 (assuming a point on the circle) if you find all possible rational solutions...that might help

lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
#
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unborn kiln
lone heartBOT
unborn kiln
#

letter B

#

Ask

unborn kiln
# unborn kiln

So basically our lesson here is Mathematical Reasoning

high ferry
#

hi can someone help me with this

unborn kiln
high ferry
unborn kiln
#

it's so....woke

high ferry
remote iron
#

sorry just put it here to locate it

high ferry
#

ohh thank u!!

lilac imp
lone heartBOT
#

@unborn kiln Has your question been resolved?

#
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plush obsidian
#

What is 5x1

lone heartBOT
plush obsidian
#

My teacher said that it is 44

#

and I confused

#

Please fast

#

I type in branli and it say 200

vale wigeon
#

do not troll.

plush obsidian
#

I'm fr

#

Bruh

wind cloak
#

the heck is branli

tepid drum
#

yea i typed on wolfram and it says 1029402

#

you are troll my friend

vale wigeon
#

@tepid drum do not feed the troll.

plush obsidian
#

In not

#

My little brother needs help

#

An I fogot

vale wigeon
#

your teacher could not have said 5 * 1 = 44, unless they lied to you.

#

or to your brother.

tepid drum
vale wigeon
#

<@&268886789983436800>

plush obsidian
#

Im 7 years old

#

Chill don

stray kite
gray isle
#

<@&268886789983436800>

vale wigeon
hot snow
#

wow, I am witnessing a true troll

next brook
#

Hmm, the account has less immature contributions that this, so I'm going to assume it was taken over by a younger sibling or something.

hot snow
#

isnt this exciting?

next brook
#

Timing them out for 24 hours while the proper owner has a chance to get it back.

hot snow
#

and he is gone

next brook
#

.close

lone heartBOT
#
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strong drum
lone heartBOT
strong drum
#

anyone know how to do this?

thick lynx
strong drum
#

the left and right speeds

#

i got 88 and 0 first

#

think it was wrong

thick lynx
strong drum
#

the deriv and just plug t in?

thick lynx
#

Yes

strong drum
#

so 88 and 0?

thick lynx
#

No

strong drum
#

1/4

thick lynx
strong drum
#

let me retry

thick lynx
strong drum
#

-32/t^3 +4/t^2

thick lynx
strong drum
#

now plug in

#

-28

#

-1/4

#

so thats left and right?

thick lynx
#

Yes, the left endpoint is at t = 1, the right endpoint at t = 4.

strong drum
#

i swear i did that first

#

and it was wrong

#

ye see

#

it was 28 and 1/4

thick lynx
#

Ah, the argument is probably that speeds can't be negative

strong drum
strong drum
#

can you help me later?

thick lynx
#

Just ask in a help channel again, like you did, and someone who sees it can help

#

I might not be here later

strong drum
#

ok

thick lynx
#

Some people might know abstract algebra but not linear algebra

#

It's not that well-ordered

lone heartBOT
#

@strong drum Has your question been resolved?

lone heartBOT
#
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wind hill
#

how can i find the equation of the circle if it is tangent to both axes, and it passes through (1,-8)?

vale wigeon
#

think this might be ambiguous...

lone heartBOT
#

@wind hill Has your question been resolved?

strong drum
lone heartBOT
#
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wheat isle
#

how do I solve e^x = 2

lone heartBOT
wheat isle
#

in exact form

vale wigeon
#

definition of logarithm

#

x = ln(2)

wheat isle
#

?

#

what?

tardy tapir
#

take ln both sides

keen thicket
#

xn + yn = zn when n is greater than 2, where x,y and z are not equal to each other.

Can someone prove this theorem?

#

I need help

vale wigeon
keen thicket
keen thicket
tardy tapir
#

i can never beat ann in typing

vale wigeon
vale wigeon
wheat isle
#

how

vale wigeon
#

$\ln(2)$ is the answer to ``$e$ raised to what power gives 2?''

ocean sealBOT
wheat isle
#

isnt it e to the what power gives x

#

e^x

vale wigeon
#

no?

#

you're confusing yourself

#

and you don't know what logarithms are, or have purposefully erased it from your mind AGAIN.

wheat isle
tardy tapir
#

how do I solve e^x = 2
just look at this eqn, LHS is e^x other side is 2, which means e was raised to some power to get 2

vale wigeon
tardy tapir
#

dude really is MIB character

wheat isle
#

i never understood that to the what power gives x stuff

wheat isle
tardy tapir
#

you got me there sotrue

vale wigeon
wheat isle
#

so whats the inverse of a^x

vale wigeon
#

log_a(x)

#

again by definition

#

you know all these

#

i myself told you that like 10 times

#

except every single fucking time you consciously choose to forget

wheat isle
#

Im not doing it on purpose i have a massive yearly test for all of my subjc next week and its a lot of pressure

vale wigeon
#

ok you might not be doing this on purpose but like

#

do you not have notes

#

do you not even have notes of ANY kind from the times we speak

wheat isle
#

i do but im revising like every single topic for math and whenever i relearn one again i seem to forget another
'

vale wigeon
#

💀

#

i mean that's what notes are for...

#

like you could have a big visible section in your note book titled "EXPONENTIAL EQUATIONS"

#

to which you could then turn when faced with this equation

#

frankly this is like a professional runner forgetting how to crawl

#

idk how to explain to you why ln(2) is LITERALLY BY DEFN the solution of e^x = 2 except repeating it again and again and again and again and again and again and again and again and again and again

wheat isle
#

so so ln(e^x) = nothing?

#

like it cancels it out

vale wigeon
#

no it's not "nothing"

#

ln(e^x) = x.

wheat isle
#

okay

#

so x = ln(2)

vale wigeon
#

yes

wheat isle
#

ok

#

@vale wigeon can you tell me if im correct for solving $\log_{2}\left(x+1\right)+\log_{2}\left(x-1\right)=3$

ocean sealBOT
#

water beam

wheat isle
#

so i got

#

$\log_{2}\left(x^{2}-1\right)=3$

$2^{\log_{2}\left(x^{2}-1\right)}=2^{3}$

ocean sealBOT
#

water beam

wheat isle
#

$x^{2}-1=8$

ocean sealBOT
#

water beam

vale wigeon
#

so far so good

wheat isle
#

$x^{2}=9\to x=\pm3$

ocean sealBOT
#

water beam

vale wigeon
#

is x = ±3 your final answer?

wheat isle
#

i think so

#

or i mean

vale wigeon
#

yes or no

wheat isle
#

$x^{2}=9\to x=\pm\sqrt{9}$ also works

#

yes

ocean sealBOT
#

water beam

wheat isle
#

wait

#

hold on

vale wigeon
#

ok then you are wrong in a somewhat subtle way

wheat isle
#

only plus 3

vale wigeon
#

yes

#

now you have fixed it

wheat isle
#

logs dont like negative i remember that

vale wigeon
#

indeed, x = -3 throws a log(negative) error if plugged into the original eq.

solar fulcrum
#

Need help guys

lone heartBOT
solar fulcrum
tardy tapir
#

this channel's occupied

solar fulcrum
#

I'm sorry I don't know

tardy tapir
#

np

solar fulcrum
#

So How should I get help

tardy tapir
lone heartBOT
#

@wheat isle Has your question been resolved?

wheat isle
#

ok wait

wheat isle
#

i have some idea of what to do but i have trouble with solving for n, do I take the log of it or something and how would i do that

#

$100=2000\left(1-0.10\right)^{n}$

ocean sealBOT
#

water beam

wheat isle
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@vale wigeon but do i take ln of both sides maybe?

vale wigeon
#

could do that, but i would have done a little differently

wheat isle
vale wigeon
#

divide both sides by 2000 first

#

then you have 0.9^n = 0.05

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only then take logs

#

minimize mistake opportunities

wheat isle
ocean sealBOT
#

water beam

wheat isle
#

im not sure im just guessing

vale wigeon
#

$$\ln(0.9^n) = \ln(0.05)$$

or, if you don't like seeing the number 0.9 naked with an exponent,

$$\ln( (0.9)^n) = \ln(0.05)$$

also there is no room to guess here, my instruction was not ambiguous in a way that mattered

i suppose i did not specify the base of the log, but as long as you take logs with the same base on both sides, it doesn't matter. if you are Buridan's ass, then take ln.

ocean sealBOT
wheat isle
#

so I have $2\ln\left(0.9\right)=\ln\left(0.05\right)$

ocean sealBOT
#

water beam

wheat isle
#

when am I allowed to drop the logs of both sides?

#

do I raise both sides by e^x or something?

tardy stag
ocean sealBOT
#

hayley!

tardy stag
wheat isle
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i dont actually know how i would do that

#

wait

#

i did something wrong

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$n\ln\left(0.9\right)=\ln\left(0.05\right)$

ocean sealBOT
#

water beam

wheat isle
#

not 2ln

tardy stag
#

yeah

wheat isle
#

i dont know why i put that there

tardy stag
#

so we're solving for n here right?

wheat isle
#

yeah

tardy stag
#

cool, ln(0.9) and ln(0.05) are just numbers

wheat isle
#

okay

#

so i can multiply divide with them

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like anything else

tardy stag
#

yeah

wheat isle
#

and i get approximately

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28.43 years

#

thats a long time

wheat isle
#

I don’t know what I’ve done wrong

tardy stag
#

you haven't done anything wrong

wheat isle
#

are you sure?

#

for the x double dot

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im confused

#

there ae no options for acceleration

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unless im blind

tardy tapir
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the last option

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oh wait im blocked

wheat isle
tardy stag
#

the one that matches what you have

wheat isle
last ether
#

Factor out e^t

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e^t * (something)

#

You're gonna have an equivalent answer but you need to algebraically manipulate your answer to see if it's equivalent to any of the choices

wheat isle
#

okay

#

.close

lone heartBOT
#
Channel closed

Closed by @wheat isle

Use .reopen if this was a mistake.

#
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hoary topaz
#

How do we go from this

lone heartBOT
hoary topaz
#

to this

#

This is the simplified form before we differentiate and I dont understand why both terms are positive

twin nimbus
#

ah, this is using the even and odd properties of sin and cos

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sorry, I was looking at it and disagreeing with it because I thought the differentiation had already happened.

hoary topaz
#

yah i just realized what are the properties again so i can write them in my notes

#

is it sin(-x) = -sin(x) and cos(-x) = cos(x)?

twin nimbus
#

essentially, it's a property of trig that sin(-x) = -sin(x), and cos(-x) = cos(x)

#

yeah

#

exactly

hoary topaz
#

perfect thank you

twin nimbus
#

yw

hoary topaz
#

yah its been a while

#

.close

lone heartBOT
#
Channel closed

Closed by @hoary topaz

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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bold siren
#

does anyone knows how to make a inverse graph ?

tardy tapir
#

mirror image along y = x

bold siren
#

then how to make graph of suppose cosec theta

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1/sin theta

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i know sin theta graph

tardy stag
#

rewind
what do you mean by inverse

bold siren
#

i thought inverse means 1 upon :-<

tardy stag
#

unfortunately math only has so many words

bold siren
#

you know 1 / sin theta

tardy stag
#

if you want to graph csc

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simplest way is to just graph some points and connect the dots

bold siren
#

my teacher was doing something making sin graph

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then making opposite of every line

high sapphire
bold siren
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oh my god i messed up things

#

can anyone guide in this ques

#

find the position the word AGAIN in dictionary

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dictionary made by only AGAIN letters

high sapphire
#

Funny thing, one of my classmates asked me the same ques in the morning

bold siren
#

where r u from ?

#

country ?

bold siren
high sapphire
bold siren
high sapphire
#

Then after fix A in first again, then fix G, then next on dictionary would be A, then 4th letter will be I and last will be N

bold siren
#

OOh yeah correct thanks

bold siren
high sapphire
#

U should try MALYALAM

bold siren
#

ooh my god

#

try MISSISSIPPI

high sapphire
#

Just did that yesterday

bold siren
#

u r god

#

i want to touch your feets

high sapphire
#

Nothin much

bold siren
#

.close

lone heartBOT
#
Channel closed

Closed by @bold siren

Use .reopen if this was a mistake.

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tiny finch
#

What do I fill in the blanks with ?

lone heartBOT
#

@tiny finch Has your question been resolved?

tacit arch
tiny finch
#

Not really

#

I know how to use point slope form