#help-0
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@rotund crater Has your question been resolved?
Empieza por graficar la función.
Sabes que P es el punto (15, 250).
Llama Q1 al punto (5, a), Q2 al punto (10, b) etc
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what do we call tenth, hundreds, thousands, and so on?
like a word for that
units?
Place values?
like order of magnitude
powers of tenth
i need a concice name for my program
for one of my variable
It’s called a place value
@flat vale Has your question been resolved?
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!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
also what are you asked to do with this
i strongly suspect this might be as far as you can simplify it
also i suspect there might be something you have mistakenly cropped away
wwolfram alpha said the other
@stuck ruin Has your question been resolved?
ccan i ask other ppl?
can you provide the full instructions of the question?
Done. Next question?
?
If there's nothing more on that, that's the simplest form that number can take.
Thus, it's simplified, and you're done.
bruh
wwhy does wolfram alpha said its can be simplified more????
????
bruh
can i ask other ppl or just wait for the answer?
Try and do the math, show us your progress and then we can help
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can anyone help me create two triangles with two equal sides and one equal angle? but they cant be congruent
that not possible
its the same thing
no
If the angle not between them they are not necessarly congutent
first one is impossible second one is possible,
i need two triangles that have two equal sides and one equal angle that are not congruent
Look closely. Isosceles so others angles also become equal.
theyre not isosceles tho
thats not the point
when i say two equal sides i mean between the triangles
like a triangle with sides 3,4,5 and one with sides 2,4,5
they have two equal sides
(4 and 5)
Okay. Yes, i get it. I misunderstood.
no problem
what i tend to do with these is imagine a physical model
I still find it hard to imagine if that would be possible.
with like sticks and springs
i mean im trying, i used my imagination a bunch on this question
it is, SSA is not a congruency case
Okay. I got how you can do it. Angles don't have to be corresponding.
hint: it won't work with a right triangle
yeah cuz of that special case
wdym by that
Actually, it's only possible if angle is not corresponding.
Let's assume that equal sides are a and b.
i don't think it will work with isosceles either
Draw a side of a for one triangle. Draw b for another one. Then draw equal angle for both. Take a on angle arm for one. On another side for another.
hint: SSA does not constrain you to one triangle, but it nearly does
you mean it almost constrains to scalene?
ok drew a for one triangle and b to another
same angle for both
wdym by "take a on angle arm for one. On another side for another"
I'm not sure
what i would do is choose an angle and two side lengths and then construct a triangle with that in that order, paying attention to where you're making hidden assumptions
i think i did it?
first proving sides are equal
then proving A is the same angle on both, though not quite let me see if i can fix that
i think thats good enough and sides are still equal
thx for the help
@thorn pebble Has your question been resolved?
ok i see they share two sides, but are you sure angle A is divided into two equal parts?
wait they dont even have two equal sides
parallel lines what?
AB and CD are parallel
yeah but so what?
Alternate angles made by a transversal intersecting two parallel lines are equal.
well only one equal side and no equal angles
OOh i see
C is equal to A
top C and bottom A
yeah im dumb
two equal sides and one equal angle
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hey
i dont get 3d
numbers that are divisible by 5 end in 0 or 5
5, 10, 15, 20, ...
agreed, therefore
8* 7* 2 ??
it can't start with 5 because 5 must be the last digit
i mean
are you saying 510 is not divisible by 5
it has to be divisible by 5
no wait
you're right
but my solution isn't correct
for some reason you have to split it
one calculation includes 0 being the last digit
the other one is 5 being the last digit
but i dont see it
the sense
doesn't this include 0 or 5 as the last digit
it does
this is what you're missing
yes it has to do something with this
but i still dont see why 8x7x2
isnt correct i mean
this calculation misses 510
so you need to add those cases to 8 * 7 * 2
so identify how many of them there are
@alpine sable Has your question been resolved?
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pls chelp me what is this monstrosity
@alpine sable Has your question been resolved?
@alpine sable Has your question been resolved?
@alpine sable Has your question been resolved?
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d
You didn't need to close your previous channel
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@alpine sable Has your question been resolved?
@alpine sable do you need this channel?
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algebra 2
Okay what is the question?
okay so i need 2 equations since this is elimination
25x +10y = 180
for time
but where do i get the second equation
it’s elimination
i have to eliminate either x or y to single out a single variable
that’s why i need a second equation
i can show u a previous problem of u need me to
yeah i did too but 12 and 180 are two different variables
that’s why i get confused
i’ll solve that and see if the answer makes sense
So what would you like me to do?
What are you confused onto available
On so I can help you
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f(x) = x^2 − 3x
Im trying to find the domain of this function, but Im not sure where to go from here, or if i even did it right.
,w graph x^2 - 3x
Make sure you know the definition of "domain"
You'll need a more specific definition
its a set of inputs, that are allowed in a function
what would be your first step in getting the domain to this? I am not sure if " = 0" was correct, or not
You don't need to do any rearrangements
What values can you plug into f(x) = x² - 3x?
Or to ask the opposite, what values "mess this function up"?
i see
ima try it, one min
yea im lost
i know how to find domains to something like this, but its the multiple x’s that are confusing me
@placid zinc
So x = 4 is an element of the domain, since you can plug it in
What can't you plug in?
Helps to look at the graph
,w graph x^2 - 3x
you can plug in any domain
You can plug in any point, yes!
Note that every polynomial has "all real numbers" as a domain
Not a waste at all. Thx for thinking through it with me
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the way youve written it is saying: -3<x<-inf or 3<x<=0 which doesnt really make sense
the numbers are right but youve written it wrong
whats the correct order lmfao
the left one for example should be (-inf,-3)
left boundary goes on the left, right boundary on the right
[0,3)
@ripe stone Has your question been resolved?
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how do I solve these? (probability)
@main cedar Has your question been resolved?
@main cedar Has your question been resolved?
i can try to help @main cedar
if 5 specific persons insist on following each other, their order is fixed
so take the 5 specific people as one person
why?
they insist on following each other
so they stick to each other and their order is fixed
so they are "one" value
so 5! x something. right?
why is it 5!
because any sequence of those 5 people need to be accounted for?
really?
idk
because I thought that the 5 people have a fixed arrangement
its fixed, but that doesnt change the fact that the question wants all possible ways of arrangement.
if they have a fixed arrangement, why do we need to account for the sequence of those 5 people?
I'm sorry, are you testing me, so I can give the correct justification even though i have the right answer? Or am I actually wrong?
no, I'm also confused about what the question is asking for
I need to understand what it means by the 5 specific persons insist on following each other
it could mean that they have to be adjacent in line to one other, and the fact that they could change the order theyre standing in line together, means there are 5 x 4 x 3 x 2 x 1 ways they could stand in line together
they have to be adjacent
can they change their order while staying adjacent to one another?
yeah
ok so, if they can change their order, the no. of combinations, as you said, is 5!
now, treat the five people as one entity
ok
so that means there are 4 total entities?
yes
5! X 4!
that should be correct 
i just submitted the answer on my class's hw page and it came out correct. Thanks man i appreciate it!
Thanks to your help, I already solved it: 8! - 2!7!. It uses quite the same logic.
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so
is there an infinite number of point slope forms
because you can get y2-y1/x2-x1 as like an infinite number of varriations right
in the same line
because any point can be either x1,y1 or x2,y2 right
tell me I'm not crazy
missing a lot of (), but yes
using the slope and any random point on the line will give a point-slope form for that line
yes. though in questions they'd usually ask you to use a specific point
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I need help with this guy
Show that $(x+1+O(x^{-1}) )^x = ex^x + O(x^{x-1})$ as $x \to \infty$
jan Niku
? to get $\qty( x \qty( \frac{x+1}{x} + O(x^{-2})))^x$
jan Niku
TooManyCooks
But more to the point
You have $x^x (1+1/x)^x$
TooManyCooks
Limit as x-> infinity that parenthesis is e
it should be $\qty( x \qty( 1 + \frac 1x) + O(x^{-1}) )^x$ still
jan Niku
what happens to the rest of the expansion
x goes to infinity
the behavior is dictaed by the leading term in the expansion
which is x^x
how do you know this?
Think of it this way
sorry my teacher is not very good
If I had $(x+1)^2$ I get $x^2 + 2x + 1$
TooManyCooks
oh youre using leading to mean something different than what im thinking
okay
i get what you mean
ok good
so wait
yeah that's all i meant
Sure
i wanna write some more out so i have a good example
@forest cobalt so the order of the error would be the next term? thats $$\qty( x \qty(1 + \frac 1x ) ) ^{x-1} O(x^{-1})$$
jan Niku
but this doesnt seem like its going to match the RHS
why is the power to x-1
wouldnt this have order $O(x^{x-2})$?
jan Niku
you miss one by not being in the leading term
the leading term takes the ^x
the next one which hits O(x^-1) loses a power of the other factor, right?
like (x+3)^3 would have leading term x^3 + O(x^(3-1))O(1)
@forest cobalt 
lmao wait
@remote heron Has your question been resolved?
I promise I'm still thinking this through
ye
then wouldnt x^(x-2) be O(x^(x-1))?
I'm trying to get the $+O(x^{x-1})$
TooManyCooks
I have (1+ $+\frac{O(x^{-1})}{x+1})^x$
TooManyCooks
i fucked up the + sign. wtver
$(x + O(x^{-1}) )^2 = x^2 + O(x^0) = x^2 + O(x^{0+1})$
jan Niku
i think im really abusing notation here
Lemme type what I have
$(x+1+O(x^{-1}))^x = x^x (1 + \frac{1}{x} + O(x^{x-2}))^x = x^x (1+\frac{1}{x})^x (1 + \frac{O(x^{-1})}{x+1})^x$
TooManyCooks
I mean can we agree up to $\qty(x+1 + O(x^{-1}) )^x = ex^x + O(x^{x-2})$
jan Niku
What?
like that this is the highest order of the rest of the expansion
my intuition says yes
just use binomial thm
that term will be $C \qty( x \qty(1 + \frac 1x) ) ^ {x-1} O(x^{-1})^1$ right
jan Niku
i can sort of bs my way through it
this is an applied math class bs is fine
$(1+ \frac{(O(x^{-1})}{x+1})^x \approx (1+ \frac{(O(x^{-1})}{x})^x = (1+ O(x^{-2}))^x \approx (1+ O(x^{-2}))$ in the limit as $\x\to\infty$
TooManyCooks
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to be honest i'd turn that shit in hahahaha
im not sure i agree with this
or not
but ill mark this as resolved i guess
thanks for the help @forest cobalt
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How do you do this? I tried replacing each of the derivatives with the limit definition, but now I have 2 h’s going to 0
:p
figured I’d get faster help here
actually I ended up helping for an hour before asking this question
No, I’ll try it
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What is this called?
I know why this works but is there a name for this thing that was used to get rid of the 6 on the bottom?
Cancelling out numbers?
Is that all it's called?
its an operation of dividing both the numerator and denominator by 6, sometimes called 'cancelling'
You could also say that youre reducing the fraction to its lowest terms
By cancelling out common factors
Got it
"cancelling" or "cancelling out common factors in a fraction"
thank you!
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am i being asked to find the derivative?
derivative at 3
ok so like
how do i get the 3 out of the parenthesis so i can do the simple power rule
(3-x)^2 = (3-x)(3-x) then expand this
i get $x^2-6x+9$
Black Hat
and then i distribute the 4 and get $4x^2-24x+36$
Black Hat
yes
yes
but then im not sure what im supposed to do with the point they gave us
just plug it into that equation?
yes
hm ok, so, 8(3) - 24 = 2
how are you getting 2 from that...
💀
im actually sped
sorry
0
jesus christ
got it
LMAO
tysm
so what exactly does this mean
do you know what a horizontal tangent line is?
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My math book says this is how to start solving the equation. But why can't it be for example -3x = 2x?
, rotate
I know that by why cant it become -3x = 2x, not -3x = -2x
it can
So i just choose
3x=2x is the same as -3x=-2x
and 3x=-2x is the same as -3x=2x
so sure, just choose your favorites
the solution guide is making use of the property that cosine is an even function, meaning that cos(-x)=cos(x)
How about sin. In that case would you also be able to choose which one would be negative
np
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why not do that from the get go
cause i thought it won't be necessary as we would have to compute the integral anyway
no you cannot compute the integral of e^f(x) in general
can we not solve this integral
oh
it is nonelementary even for such tame f(x) as -x^2
okay
i love the gaussian integral
thanks
wait i have one more que
why is this is true ?
@vale wigeon
my math teacher just gave it as a note but did not elaborate o it
a pair of straight lines is $(a_1 x + b_1 y + c_1)(a_2 x + b_2 y + c_2) = 0$
Ann
yes
ie the product of two general-form straight line equatoins
so like
if you expanded all that, then collected all the coeffs, and went thru the pain of calculating that determinant
thatd be your answer ig
theres probably some kind of clever linear-algebraic way to look at it which i do not currently have the energy to articulate fully
that's really not intuitive idk why
yeah it is not
the one that's not ticked
Ann
we don't know r but we want this thing to have rational solutions...
yes
no it's not
i wouldnt be surprised if you can fit infinitely many points on it but i do not see how
no way they could ask such questions in an exam with limited time
Hi
there must be a simpler way
i am drawing a blank here still
can't we do something using parametric coordinates
@wary lantern hi, if you have a math question of your own then please open your own channel (see #❓how-to-get-help for instructions), otherwise go to #discussion or #chill
@young finch do you know a way to do this
if ann doesnt know i definitely dont know
so u wont even try
im not that smart lol
i wonder if it's 1
@alpine sable Has your question been resolved?
@alpine sable can you ping and/or dm me if you do find a solution? i am actually kind of interested what im missing here.
sure
@alpine sable Has your question been resolved?
hmm if it was integer coordinates then i would have a solution for this
wait i might have got it
lemme try
$(x - \sqrt{5})^2 + y^2 = r^2$
ItzKraken
$(x - \sqrt{5})^2 = r^2 - y^2$
ItzKraken
$x = \sqrt{5} \pm\sqrt{r^2 - y^2}$
ItzKraken
ItzKraken
where a is any real
(0,r) will be on circle
put y=r
we obtain $a=\mp\sqrt{5}$
ItzKraken
hmmm actually u can put (r,0) in this only
Find r (r = sqrt(5)/2)
Then put this value here
Wait no it still doesn't help
Hmm
If you put x=0 (assuming a point on the circle) if you find all possible rational solutions...that might help
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So basically our lesson here is Mathematical Reasoning
hi can someone help me with this
Who made that question 😭
I DONT KNOW HUHU
it's so....woke

ohh thank u!!
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What is 5x1
My teacher said that it is 44
and I confused
Please fast
I type in branli and it say 200
do not troll.
the heck is branli
@tepid drum do not feed the troll.
your teacher could not have said 5 * 1 = 44, unless they lied to you.
or to your brother.
i am not feeding it just telling him that he is troll but as you wish
<@&268886789983436800>
Then why are you on discord
<@&268886789983436800>
then you can only come back in 6 years, sorry.
wow, I am witnessing a true troll
Hmm, the account has less immature contributions that this, so I'm going to assume it was taken over by a younger sibling or something.
isnt this exciting?
Timing them out for 24 hours while the proper owner has a chance to get it back.
and he is gone
.close
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anyone know how to do this?
Which one?
3rd
the left and right speeds
i got 88 and 0 first
think it was wrong
Do you know how you can determine the body's speed at any time t, using the position f(t)?
the deriv and just plug t in?
Yes
so 88 and 0?
No
1/4
No, 88 is wrong, 1/4 too (slightly)
let me retry
What expression do you get for the derivative at time t?
-32/t^3 +4/t^2
Yes
Yes, the left endpoint is at t = 1, the right endpoint at t = 4.
Ah, the argument is probably that speeds can't be negative
i gtg to class
can you help me later?
Just ask in a help channel again, like you did, and someone who sees it can help
I might not be here later
ok
up to what math dyk?
I don't think there is an "up to"
Some people might know abstract algebra but not linear algebra
It's not that well-ordered
@strong drum Has your question been resolved?
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how can i find the equation of the circle if it is tangent to both axes, and it passes through (1,-8)?
think this might be ambiguous...
@wind hill Has your question been resolved?
well ig do you know calc 1-2?
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how do I solve e^x = 2
in exact form
take ln both sides
xn + yn = zn when n is greater than 2, where x,y and z are not equal to each other.
Can someone prove this theorem?
I need help
Please read #❓how-to-get-help
- don't troll
- post in your own chnnel
What troll?
Ok
i can never beat ann in typing
ln(2) is by definition the one and only solution to e^x = 2 ...
90 wpm
how
$\ln(2)$ is the answer to ``$e$ raised to what power gives 2?''
Ann
no?
you're confusing yourself
and you don't know what logarithms are, or have purposefully erased it from your mind AGAIN.
it doesnt make sense
how do I solve e^x = 2
just look at this eqn, LHS is e^x other side is 2, which means e was raised to some power to get 2
because you fucking forgor again
dude really is MIB character
i never understood that to the what power gives x stuff
.
you got me there 
ln(x) is the inverse function of e^x
so whats the inverse of a^x
log_a(x)
again by definition
you know all these
i myself told you that like 10 times
except every single fucking time you consciously choose to forget
Im not doing it on purpose i have a massive yearly test for all of my subjc next week and its a lot of pressure
ok you might not be doing this on purpose but like
do you not have notes
do you not even have notes of ANY kind from the times we speak
i do but im revising like every single topic for math and whenever i relearn one again i seem to forget another
'
💀
i mean that's what notes are for...
like you could have a big visible section in your note book titled "EXPONENTIAL EQUATIONS"
to which you could then turn when faced with this equation
frankly this is like a professional runner forgetting how to crawl
idk how to explain to you why ln(2) is LITERALLY BY DEFN the solution of e^x = 2 except repeating it again and again and again and again and again and again and again and again and again and again
yes
ok
@vale wigeon can you tell me if im correct for solving $\log_{2}\left(x+1\right)+\log_{2}\left(x-1\right)=3$
water beam
water beam
$x^{2}-1=8$
water beam
so far so good
$x^{2}=9\to x=\pm3$
water beam
is x = ±3 your final answer?
yes or no
water beam
ok then you are wrong in a somewhat subtle way
only plus 3
logs dont like negative i remember that
indeed, x = -3 throws a log(negative) error if plugged into the original eq.
Need help guys
Please read #❓how-to-get-help
this channel's occupied
I'm sorry I don't know
np
So How should I get help
.
@wheat isle Has your question been resolved?
ok wait
i have some idea of what to do but i have trouble with solving for n, do I take the log of it or something and how would i do that
$100=2000\left(1-0.10\right)^{n}$
water beam
@vale wigeon but do i take ln of both sides maybe?
could do that, but i would have done a little differently
how would you do it?
divide both sides by 2000 first
then you have 0.9^n = 0.05
only then take logs
minimize mistake opportunities
so $\ln\left(0.9\right)^{n}=\ln\left(0.05\right)$?
water beam
im not sure im just guessing
$$\ln(0.9^n) = \ln(0.05)$$
or, if you don't like seeing the number 0.9 naked with an exponent,
$$\ln( (0.9)^n) = \ln(0.05)$$
also there is no room to guess here, my instruction was not ambiguous in a way that mattered
i suppose i did not specify the base of the log, but as long as you take logs with the same base on both sides, it doesn't matter. if you are Buridan's ass, then take ln.
Ann
hmmm
so I have $2\ln\left(0.9\right)=\ln\left(0.05\right)$
water beam
when am I allowed to drop the logs of both sides?
do I raise both sides by e^x or something?
when you have something that exactly matches the pattern
$\ln(\psq) = \ln(\osq)$
hayley!
sure that'll work
i dont actually know how i would do that
wait
i did something wrong
$n\ln\left(0.9\right)=\ln\left(0.05\right)$
water beam
not 2ln
yeah
i dont know why i put that there
so we're solving for n here right?
yeah
cool, ln(0.9) and ln(0.05) are just numbers
yeah
could you check somethinge else for me rq
I don’t know what I’ve done wrong
you haven't done anything wrong
are you sure?
for the x double dot
im confused
there ae no options for acceleration
unless im blind
but what would be the correct option
the one that matches what you have
but there is none
Factor out e^t
e^t * (something)
You're gonna have an equivalent answer but you need to algebraically manipulate your answer to see if it's equivalent to any of the choices
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How do we go from this
to this
This is the simplified form before we differentiate and I dont understand why both terms are positive
ah, this is using the even and odd properties of sin and cos
sorry, I was looking at it and disagreeing with it because I thought the differentiation had already happened.
yah i just realized what are the properties again so i can write them in my notes
is it sin(-x) = -sin(x) and cos(-x) = cos(x)?
essentially, it's a property of trig that sin(-x) = -sin(x), and cos(-x) = cos(x)
yeah
exactly
perfect thank you
yw
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does anyone knows how to make a inverse graph ?
mirror image along y = x
rewind
what do you mean by inverse
i thought inverse means 1 upon :-<
unfortunately math only has so many words
you know 1 / sin theta
if you want to graph csc
simplest way is to just graph some points and connect the dots
Sin inverse is not cosec 
oh my god i messed up things
can anyone guide in this ques
find the position the word AGAIN in dictionary
dictionary made by only AGAIN letters
7
Funny thing, one of my classmates asked me the same ques in the morning
yeah correct how did you do it ?
India
i know same ques my teacher told me today
India's famous ques lmao
It's simple arranging, first fix A in the first place then next on the 2nd place fix another A, 3 positions are can be filled in 3 factorial ways
Then after fix A in first again, then fix G, then next on dictionary would be A, then 4th letter will be I and last will be N
OOh yeah correct thanks
Which ques
AGAIN
U should try MALYALAM
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What do I fill in the blanks with ?
@tiny finch Has your question been resolved?
do you know how to find the slope of a function?


