oh ok
#help-0
fathom orchid
oh , ok then . thx for ur help 🙂 , i will go study it
have a gd nd take care ! 🙂 c ya around
.close
alpine sable
is this correct?
lone heartBOT
is this correct?
alpine sable
i don't have a final solution, although I think it is correct
oak perch
Correct
alpine sable
.close
lone heartBOT
lone heartBOT
Available help channel!
alpine sable
like 4*0 is 0
lone heartBOT
like 4*0 is 0
full kettle
I guess if sqrt(4x) is going to negative infinity, the function as a whole will approach zero from the negative side
alpine sable
was limx->0 (sin2x/x)
full kettle
Yeah but that’s approaching 0
Oh I misread it
It looked like it was approaching infinity
alpine sable
ik but i cant just writte 0 on exam
alpine sable
.close
hasty turtle
what the frick
lone heartBOT
what the frick
hasty turtle
it's about convergence/divergence of sequences
I did this one, which I just used normal convergence which I learned in high school, but not sure about the one above
alpine sable
Hi wy
hasty turtle
hi
alpine sable
I think we are learning the same school material calcilus
hasty turtle
this is a private test which you need like an account to log in on
alpine sable
oh
hasty turtle
but if youy use google translate https://wiki.math.ntnu.no/tma4100/2023h/start this the course home page
you might be able to naviagte around and find some problems there
but i'll close this one cause i need help with the problem
alpine sable
hmm this shoud be easy
multiply by the opposite value
what is it called
wait
this
1 step maybe?
hasty turtle
what
alpine sable
can we do that here?
hasty turtle
whatu mean?
hasty turtle
yeh i have no idea what to do
alpine sable
We're waiting for help. In the meantime, I'll also try to solve it. It'll just be practice
fickle musk
are all trig function with f(1/x) oscillatory type limits?
lone heartBOT
are all trig function with f(1/x) oscillatory type limits?
zealous lichen
yes they all oscillate as when x approach 0 1/x approach infinity, and the trig functions are periodic
lone heartBOT
@fickle musk Has your question been resolved?
echo socket
Works for any non-constant periodic function as well
vagrant basin
hello
vagrant basin
can someone help me with circles
so
we have a circle
and now i will draw a radius
this is line A, and line B
how do i calculate the angle
so that b and a have a different angle value
ok well im very bad with formulating my question for now i will close this and make a better question
.close
lone heartBOT
lone heartBOT
Available help channel!
lapis escarp
lone heartBOT
lapis escarp
I think i solved this correctly
i found the derivative of that equation f'(x)=3ax^(2) + 2bx - 5
then i just subbed in the y and x values for both equations
and i got a=4 and b=2
but that feels wrong, because im subbing in a and b values from the other non derivative equation to the derivative one
is this correct or did i miss a step?
gray isle
,w 4x^3+2x^2-5x+9 when x=-1
ocean sealBOT
tardy tapir
your answer is correct
gray isle
,w 12x^2 + 4x - 5 when x=-1
tardy tapir
why do you feel its incorrect?
ocean sealBOT
lapis escarp
why do you feel its incorrect?
idk, it feels weird subbing in values across derivatives these feel like two separate equations in my mind. i dont understand why that works
gray isle
the resulting equations are just conditions
doesn't matter whether they came from derviatives
its ultimately just solving a system of equations with two variables
rancid hatch
lone heartBOT
rancid hatch
@oak perch do uk how to do this
tardy tapir
do not ping an individual helper.
oak perch
Laplace transform probably
rancid hatch
do not ping an individual helper.
got it sry
rancid hatch
Laplace transform probably
u mind explaining to me
oak perch
Let Laplace transform of y be F(s)
oak perch
I don’t look at it. I solve it first
rancid hatch
I don’t look at it. I solve it first
got it boss
oak perch
Laplace transform of y” is s^2F(s)-sy(0)-y’(0)=s^2F(s)-s-1
So (s^2+1)F(s)-s-1 equals Laplace transform of the right hand side, which is e^-s/s
Therefore F(s)=(s+1+e^(-s)/s)/(s^2+1)
We just need to calculate the inverse Laplace transform of it
And that can be done by factoring (s+1+1/s)/(s^2+1) and search them on table
rancid hatch
Same I don’t know what to ask about it…
according to my forumla sheet i have
okay wait
gimme a minute to do the part ik first
rancid hatch
Laplace transform of y” is s^2F(s)-sy(0)-y’(0)=s^2F(s)-s-1
this part how u get -s-1
like ik the s^2F(s) remains
oak perch
y(0)=1, y’(0)=1
oak perch
Laplace transform of y” is s^2F(s)-sy(0)-y’(0)=s^2F(s)-s-1
Here
rancid hatch
oh
oak perch
Laplace of it is F(s)…
rancid hatch
Laplace of it is F(s)…
not y'' but the y
rancid hatch
L(y”)+L(y). L(y) is F(s)
and L(y'') is s^2F(s)-sy(0)-y’(0)
oak perch
Yeah
rancid hatch
wont that give me s^2F(s)-sy(0)-y’(0) + F(s)
oak perch
That is what I wrote
rancid hatch
im at herep
oak perch
Yeah…
rancid hatch
So (s^2+1)F(s)-s-1 equals Laplace transform of the right hand side, which is e^-...
but how come u have the (s^2+1)
is that the y
oak perch
And better not ping me in the future…
proud wyvern
This is what I learned so far in my first day of my online calculus course. Is my reasoning valid at the question at the end?
paper mango
This is what I learned so far in my first day of my online calculus course. Is m...
the idea you have is great, just notation-wise it currently doesn't make sense :)
proud wyvern
the idea you have is great, just notation-wise it currently doesn't make sense `...
On Which parts
paper mango
as the point Q approaches the point P, the secant becomes increasingly close to the derivative at the point P
proud wyvern
as the point Q approaches the point P, the secant becomes increasingly close to ...
I understand that
paper mango
On Which parts
since you'd not use two points approaching each other in a limit and currently the equation doesn't utilise the points
proud wyvern
I noticed in the limit definition delta x goes to 0 but if that happens the distance decreases right?
paper mango
but you could instead formulate it as f'(x) = lim[dx -> 0] dy/dx
proud wyvern
In the picture
paper mango
I noticed in the limit definition delta x goes to 0 but if that happens the dist...
Q to P would be equivalent to delta x going to zero
yes the distance decreases but you get an increasingly accurate approximation for the slope
proud wyvern
It makes more sense now. I just wanted to understand the conceptual side of calculus
paper mango
It makes more sense now. I just wanted to understand the conceptual side of calc...
absolutely, this kind of limit is used more often to prove other concepts as well
lone heartBOT
paper mango
Thanks for the clarification .Someone probably needs this channel
there are a ton, it usually doesn't matter when keeping them open 🐧
lone heartBOT
Available help channel!
dapper echo
lone heartBOT
dapper echo
How do you multiply radicals like the middle step?
tardy tapir
we generally multiply the denominator by its conjugate to get rid of the surds (known as rationalising).
dapper echo
Yeah, but how do I get 20 and 100 as my answers from the multiplication?
near apex
Yeah, but how do I get 20 and 100 as my answers from the multiplication?
Well, factor out the 5 from $(5\sqrt{5} - 5)$ in numerator and see if you can use some identity there.
ocean sealBOT
Enemagneto
dapper echo
$5(1\sqrt{1} - 1)$
ocean sealBOT
Stat
near apex
Uh. No.
It seems like you don't really understand how to factor out.
See. If you have $(ab - ac)$, which is same as $(a\times b - a\times c)$, you can factor out the $a$ as it's common in both the terms.
ocean sealBOT
Enemagneto
near apex
So, once you factor out a common, you write the rest of the remaining term inside the bracket so that meaning doesn't change.
so, we write
$$a(b - c)$$
ocean sealBOT
Enemagneto
near apex
Similarly, you have $(5\sqrt{5} - 5)$, which is same as $(5\times \sqrt{5} - 5\times 1)$.
ocean sealBOT
Enemagneto
near apex
We have written 5 as "five times one" which is the same thing.
Now, can you factor out the 5?
@dapper echo
dapper echo
$(sqrt{5} - 1)$
ocean sealBOT
Stat
ocean sealBOT
Stat
deep harbor
I need help with 1.25 not the one over that
lone heartBOT
I need help with 1.25 not the one over that
deep harbor
show that ... can be transformed into ...
finite flax
I need help with 1.25 not the one over that
Were you going to translate this into English or wait for somebody who speaks German
deep harbor
Were you going to translate this into English or wait for somebody who speaks Ge...
Well it’s not German
deep harbor
show that ... can be transformed into ...
^
finite flax
Which language is it
deep harbor
Norwegian
finite flax
Ok
What is the greatest factor of 50 that is a perfect square?
Perfect squares are 1, 4, 9, ...
(Or just square numbers)
@deep harbor
deep harbor
2 * 5^2?
finite flax
Right
So if you take the square root of 50, that is the same as taking the square root of each factor of 50
$\sqrt{50} = \sqrt{2}\sqrt{5^2}$
ocean sealBOT
Disorganized
deep harbor
I don’t really understand why its written like V2V5^2
finite flax
I don’t really understand why its written like V2V5^2
If c = a*b, then
$\sqrt{c} = \sqrt{ab} = \sqrt{a}\sqrt{b}$
ocean sealBOT
Disorganized
finite flax
This is a law of radicals
Basically a law of exponents
(Since nth roots are another notation for rational exponents with index 1/n. In this case, n=2)
$c^{1/2} = (ab)^{1/2} = a^{1/2}b^{1/2}$
deep harbor
**Disorganized**
why is it written like VaVb instead of Vab
ocean sealBOT
Disorganized
deep harbor
.close
lone heartBOT
lone heartBOT
Available help channel!
rigid lion
So is the answer DNE?
lone heartBOT
So is the answer DNE?
rigid lion
Because the limits are not the same
foggy current
You mean question 1?
rigid lion
Yea
foggy current
Do you know about the squeez theorem?
rigid lion
If the limit of the top and bottom are equal and the omit of the middle is inbetween then u can assume the middle is the same as the top and bottom
But I’m just confused because the notes don’t show any problem like that
This is the closest
foggy current
This is the closest
Well you can do a similar thing as you've done here
foggy current
You can just ignore the x≥0 since we're just considering values close to 4
foggy current
And also is this limit inferior?
rigid lion
What’s limit inferior
foggy current
It's a type of limit
rigid lion
Oh I didn’t mean to put that line
foggy current
Ok
foggy current
Which question?
lone heartBOT
foggy current
Ok bye
lone heartBOT
Available help channel!
rigid beacon
Guys in the integration √1-x/√1+x i took x as cos2m
I'm getting a different answer from another approach
rigid beacon
i got arcsinx+√1-x²
tardy tapir
!show
lone heartBOT
Show your work, and if possible, explain where you are stuck.
lone heartBOT
@rigid beacon Has your question been resolved?
wind cloak
,w integrate sqrt(1-x)/sqrt(1+x)
ocean sealBOT
wind cloak
Well $2\arcsin x = \arcsin (2x\sqrt{1 - x^2} )$ for appropriate values of $x$
ocean sealBOT
NEON
rigid beacon
@wind cloak do you find any mistake in my steps?
wind cloak
no
rigid beacon
,w differentiate arcsinx -(√(1-x²))
ocean sealBOT
lone heartBOT
wind cloak
why do you have the reciprocal
lone heartBOT
Available help channel!
rigid beacon
i got the wrong answer by another method
lone heartBOT
i got the wrong answer by another method
meager plinth
what does the 16 mean?
lone heartBOT
what does the 16 mean?
zealous lichen
The 16 on bottom right indicate it's hexidecimal/base16
And the question want you to turn them to binary/base2
serene isle
it wasnt necessary to write the 16s given the question at the top but people do it anyway for clarity
dawn portal
it is saying that this wrong I get the same answer I just need a second opinion part b btw
fluid prawn
it is saying that this wrong I get the same answer I just need a second opinion ...
i got 93.88 not 94.88 for b
dawn portal
im just put in the cacl and i got 93.92
fluid prawn
dawn portal
well got two attempts left time to roll the dice
why didnt you times it by four
for 11.36
fluid prawn
2006 is t = 0 so 2008 is t=2
dawn portal
ohhhhh
fluid prawn
N(2)= 2.99 * 2^2 + 11.36 *2 + 59.2
dawn portal
no just hw
i got 5 attempts to get it correct
or its considered wrong
thanks @fluid prawn
.close
alpine sable
lone heartBOT
maiden glen
it's the set containing the pair (0,0), and all pairs of the form (1,r), where r is a real number
alpine sable
Okay thank you
but I don't see any brackets around the ({1}xR)
I find it a little bit strange
alpine sable
Ah ok I will read about cartesian product
maiden glen
the outer brackets are just to make sure you read it as {(0,0)} U ({1} x R) and not ({(0,0)} U {1}) x R
because the product and union have ambiguous operator precidence
maiden glen
Ah ok I will read about cartesian product
and the cartesian product A x B is the set {(a,b) : a in A and b in B}
simple saddle
lone heartBOT
simple saddle
simple saddle
in here the probability isn't divided by any total value
simple saddle
but here its divided by total why is it?
serene isle
in here the probability isn't divided by any total value
it kinda is
how do you calculate the first one
simple saddle
how do you calculate the first one
(1/6)^3 x (5/6)^2
simple saddle
the bottom of that fraction at the end is the total
which i don't understand
simple saddle
which i don't understand
the 1/6?
serene isle
(1/6)^3 x (5/6)^2
actually where is the 5 coming from
simple saddle
actually where is the 5 coming from
the remaining 5 choices?
serene isle
yeah gotcha
mystic vortex
(1/6)^3 x (5/6)^2
I'm pretty sure this is wrong
simple saddle
I'm pretty sure this is wrong
oh its should be multiplied with 5!/ 3!*2! =10
mystic vortex
That looks like the odds to roll some specific series of numbers with exactly 3 3s, but you need to multiply by the number of orderings
simple saddle
That looks like the odds to roll some specific series of numbers with exactly 3 ...
yaya
mystic vortex
oh its should be multiplied with 5!/ 3!*2! =10
I believe so, yes
simple saddle
I believe so, yes
id did this but there was ambiguity about denominator so was thinking to divide by (1/6)^6 thinking of it as total
can you highlight why it isn't needed or already is there then what is that term
serene isle
the total is already represented by the denominator
mystic vortex
I'm a little confused what you mean
simple saddle
the total is already represented by the denominator
which one is it?
serene isle
bc ur using a probability to begin with rather than counting options
simple saddle
bc ur using a probability to begin with rather than counting options
oh that way
serene isle
in question 2 you find probability by counting and dividing by total. in 1 you find it by manipulating other probabilities
the 1/6 you found by counting and dividing by total tho
simple saddle
so if i calculate probability i dodn't need to woory about denominator then?
serene isle
you did in the 1/6
the 6 is the total
1 option out of 6 is correct
similarly with the 5/6 5 options are correct
simple saddle
the 6 is the total
understood got it
simple saddle
similarly with the 5/6 5 options are correct
but just one quest then 1/2 so 2 was total in 2nd quest then ?
serene isle
yeah
simple saddle
but then still we divided no?
serene isle
oh its should be multiplied with 5!/ 3!*2! =10
this no?
serene isle
(1/2)^6 x 6! ?
serene isle
but the heads and tails can come in any order
serene isle
That looks like the odds to roll some specific series of numbers with exactly 3 ...
like here
simple saddle
that way 2^6
simple saddle
the odds of getting the right one are 1/2
yeah
thats what im sayin that we divide this by 2^6
all cases
serene isle
isnt it just this $(\frac{1}{2})^6 = \frac{1^2}{2^6} = \frac{1}{2^6}$
ocean sealBOT
Poelymole
serene isle
then times by 6!
simple saddle
then times by 6!
i think so
but its 720/64 >1
@serene isle
not possible
ok let it be
.close
thin path
how does 2k here turn into 0k?
lone heartBOT
how does 2k here turn into 0k?
vale wigeon
2 is congruent to 0 mod 2
thin path
.close
lone heartBOT
lone heartBOT
Available help channel!
proud lynx
Hey
proud lynx
<@&286206848099549185>
tardy tapir
!15m
lone heartBOT
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
zealous lichen
!show
lone heartBOT
Show your work, and if possible, explain where you are stuck.
proud lynx
I havent started
I started over
And erased
Also
Im doing all of this on a phone outside
Let me get it started
Holdon
70 + 38p <= 4500
P representing person
zealous lichen
What about 38
proud lynx
Oh i already had it
I just didnt see the round down
So i thought i fucked up with the decimal
zealous lichen
Oh ok
lone heartBOT
@proud lynx Has your question been resolved?
lone heartBOT
onyx plaza
Can someone help me solve this question:
lone heartBOT
Available help channel!
lone heartBOT
Can someone help me solve this question:
lone heartBOT
Can someone help me solve this question:
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
sonic ridge
do you know what the absolute value does?
shut crest
I dont know where to begin
Do you know what absolute value is
|2| = 2
And |-2| = 2
What do you think |-3| is?
onyx plaza
Do you know what absolute value is
I am new to online classes so how would this be dotted
onyx plaza
yes 10
shut crest
Oh ok
onyx plaza
then 4
shut crest
So you get it
shut crest
Put a dot on 10
onyx plaza
shut crest
And one on 4
onyx plaza
And one on 4
are you still there
frail wren
oopsie
shut crest
Like do you understand the math
onyx plaza
Like do you understand the math
I do not, All i know is that b is less than 0 so thats why I thought to place the dot on 0, and -11
shut crest
No
onyx plaza
please explain to me
shut crest
I don’t think it has anything to do with the last problem
Or does it
Bro that site is trippy lol
onyx plaza
No the original one we did was another problem.
shut crest
Ok
onyx plaza
so you won't have to scroll
shut crest
It’s weird cuz what’s b
Okay I’ll explain how it works though
If it is just greater than or less than, it doesn’t include the number itself
So x<4 doesn’t include 4 as a solution for x
But if it is has an equal it includes 4
$\leq$
ocean sealBOT
amukh1 | JS,Axler Fanboy
shut crest
When we graph one that doesn’t have an equal we have an open circle, and a line going in the direction of the solutions
When it includes the number we use a closed circle
That’s the stuff on the side
b>0
Is 0 included
onyx plaza
you mean the non solid circle
onyx plaza
shut crest
Also delete the 4 and 10
onyx plaza
I dont understand
I thought we should be in the negatives
one on zero and another below?
onyx plaza
anything below 0
shut crest
No
Think of the < and > as alligators
It wants the bigger number cuz it hungry
so b is bigger than 0
Any positive number works
0 doesn’t work, because 0 isn’t bigger than 0
onyx plaza
yes it is greater than
shut crest
Ok so put an open circle on 0
Because the open circle means the inequality starts there, but it doesnt include 0
That is why it is open
And then draw a line going into the positives
onyx plaza
I get it
shut crest
Ye
onyx plaza
then I can close circle on 10?
shut crest
No
onyx plaza
or 11?
onyx plaza
I see what you mean
shut crest
It goes on for infinity
Any number works, even greater than 10 or 11
If you stop at 10 or 11 anything after isn’t a solution which isn’t true
shut crest
Yea
shut crest
:D
shut crest
a^n * a^m = a^(n+m)
onyx plaza
a^n * a^m = a^(n+m)
what do you mean
shut crest
w^3 times w^4 is w^7
Well
I’m just naming rules
You need to distribute the term outside the parenthesis
The term they wrote for you
With the 18
onyx plaza
ok that what I did and this is my answer.
shut crest
Yeah
onyx plaza
so this looks good?
shut crest
Yep
lone heartBOT
@onyx plaza Has your question been resolved?
onyx plaza
yes
safe tartan
d/dx (5y) = 5 dy/dx but for something like y=5t then dy/dx=0 so when do you use implicit and when do you treat it as a constant
median oar
The second one is still right
When y = 5t
d/dx (5y) is indeed equal to 5 dy/dx
Except dy/dx = d(5t)/dx which isn’t dependent on x
So it’s equal to 0
So you have 5 * 0 = 0
safe tartan
So are those two different?
median oar
So the main thing is what are you differentiating with respect to
If you differentiate wrt (with respect to) x
And y isn’t a function of x
It’ll be a “constant” in the “eyes of x”
median oar
No
safe tartan
F(x)
safe tartan
Oh
median oar
You can totally write y = 5t, d/dx (5y) = 5 dy/dx
This is completely valid and correct
safe tartan
Ah I see
median oar
It’s just that dy/dx = 0 when y isn’t a function of x
safe tartan
So implicit kind of is the bigger circle answer if you know what I’m saying
tight girder
Hey I solved this equation and got 4 and 1 as results 2^x = 4 and 2^x = 1 so I solved the equation and got x = 2 but what about 2^x = 1?
wild umbra
!nosols
lone heartBOT
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
tight girder
Why?
wild umbra
Hey I solved this equation and got 4 and 1 as results 2^x = 4 and 2^x = 1 so I s...
do you know
$a^{0}=1$
ocean sealBOT
yajatk07
wild umbra
where a is any number
tight girder
So the answer is 0 = 1?
wild umbra
this is written as $2^x=1$
ocean sealBOT
yajatk07
tight girder
0
tight girder
X = 0?
wild umbra
yes
crimson tundra
Hello I need help with conditional probability; This is the task : Mark is solving a test from History. The concept of the test is that he draws out 3 out of 100 questions. If he knows the answer only to one question he fails the test. If he knows the answer to two of the 3 he draws 2 more questions, if he manages to answer the 2 he passes the test. If he knows all 3 questions he will pass the test. Mark knows 70/100 questions from the test. What is the chance that he will pass his exam?
What I'm struggling with is figuring out how to solve the probability of him passing the test given that he managed to only answer 2 questions.
crimson tundra
In my material it says 68 choose 2 / 97 choose 2 and I'm having it hard figuring how to get to those numbers
pallid scarab
Knowing that he already answered only two questions from the batch of 3 questions picked, how many questions are there left to pick from ?
Out of those questions, how many does Mark know the answer to?
crimson tundra
Alright, get it and then when calculating the probability of him passing the exam I just multiply the events with their given conditional events?
And add them up
pallid scarab
Yes
crimson tundra
P(E1) x P(A\E1) for example where E is event and A is him passing the test
pallid scarab
anyone need help
Find an occupied channel where either no helpers are and you can help or sometimes chime in to add some important details other helpers might have missed
pallid scarab
P(E1) x P(A\E1) for example where E is event and A is him passing the test
Yes
Then take sum of those probabilities
crimson tundra
I have one more question for calculating the H2 - him knowing the answer to two questions - there is ((70C2)x30)/100C3
100C3 are all possible combinations, 70C2 are combinations of him picking the two questions from the 70 that he knows
What is 30?
crimson tundra
Alright, just having it hard rn understanding why are those two multiplied
Nevermind get it actually sorry
pallid scarab
Alright, just having it hard rn understanding why are those two multiplied
Because "the questions he knows the answer from" and "the question he doesn't know the answer to" can be picked independently
crimson tundra
30 remaining questions that can be in there
Thank you for your help, have a great day/night
pallid scarab
You too 👍
crimson tundra
.close
stoic turtle
Can you find x based on just this information?
lone heartBOT
Can you find x based on just this information?
mossy meadow
Can you find x based on just this information?
i think you can only solve this if the triangle is isosceles
vapid steppe
If you throw a stone upwards at 18 m/s, how high up in the air will it reach before returning to earth?
vapid steppe
Neglect air resistance
vapid steppe
If you throw a stone upwards at 18 m/s, how high up in the air will it reach bef...
since g=-10 m/s^2=a
can i like make an equation
for the position of the stone
so like if a(t)=a then v(t)=at+C and s(t)=at^2 /2 + Ct + C2
vapid steppe
so would the position of the stone be s(t)= -5t^2 + 18t ?
since +18 is the initial velocity
mellow zephyr
seems good
vapid steppe
so find the y coordinate of the vertex of s(t)
mellow zephyr
yep
vapid steppe
i got 16.2 m
lime bobcat
g=10 💀
mellow zephyr
16.2 m sounds good though
dim terrace
lone heartBOT
dim terrace
help please
dim terrace
uh
lone heartBOT
@dim terrace Has your question been resolved?
gusty dagger
Are you still stuck with the last question? @dim terrace
dim terrace
yeah
dim terrace
From least to greatest
i didn’t see this mb, bca
gusty dagger
Good job
alpine sable
someone help
lone heartBOT
someone help
hot snow
what do you need help with?
alpine sable
the problem, it says its wrong
hot snow
the equation you have made is right
alpine sable
really?
hot snow
it is
proven leaf
maybe the program wants it in slope-intercept?
even though the question is asking for point-slope 
wary stream
maybe the program wants it in slope-intercept?
But it says point slope form?
hot snow
maybe its because of some extra "{blank space}" somewhere
lone heartBOT
@alpine sable Has your question been resolved?
thorn shale
This how do I do this🥲😭
lone heartBOT
This how do I do this🥲😭
thorn shale
Bruh I have to type it? Nawrrrrr
sturdy gale
Hi, I can help you with this problem!
thorn shale
Omg yassss tyyy
sturdy gale
It's a little blurry, but I think you're adding 6 to both sides?
thorn shale
Lemme get a clear photo
sturdy gale
k, thanks
ocean sealBOT
thorn shale
Nice
sturdy gale
ok, thanks
so you're adding 6 to both sides
however, you cannot do that
You would have to add 6x^3
You can't just add the coefficient
thorn shale
Like how to start the very beginning of the problem?
sturdy gale
Yup
sturdy gale
mmm well another way to do this is to make one side have all the stuff and the other side have 0
How can we do that?
sturdy gale
Well, if we subtract 3x^3 and 2x^2 on both sides, we get 5x^4-6x^3-3x^3-2x^2 = ||0||
sturdy gale
Ok, now combine like terms
sturdy gale
,rccw
thorn shale
Srry
ocean sealBOT
thorn shale
Holdup I still have to add the powers right for -6x^3 and -3x^3 right
sturdy gale
,rccw
ocean sealBOT
thorn shale
The X’s? Or the cos
sturdy gale
Identify the common term: While the powers of x are different, you can still factor out the highest power of x that is common to all terms
sturdy gale
Well, think about what the highest power of x that is common to all terms.
For example, if the equation was 5x^4-2x^5-3x^8, the common factor would be x^4, do you see why?
$5x^4-2x^5-3x^8$
ocean sealBOT
smathwizard
sturdy gale
Did you figure it out? It's ok if you still don't understand 🙂
sturdy gale
I haven't but that's a really good way to visualize it!
So what do you think is the 'common factor'
thorn shale
X^2?
ocean sealBOT
smathwizard
sturdy gale
And now we have a common factor of $x^2$
ocean sealBOT
smathwizard
sturdy gale
So that means $x^2(.....) = 0$
ocean sealBOT
smathwizard
sturdy gale
Do you know what to fill in the blank?
You can use the method you did earlier to help you!
basically you just cross out the circled stuff, and whatever you have left (like -5x^2) is what goes in the blank!
thorn shale
Omg yea! Ok this is all slowly like coming back it’s been a while
sturdy gale
Yay!
thorn shale
sturdy gale
Close! Don't forget the parenthesis, or else it won't be the same 🙂
So:
$x^2(5x^2-9x-2)$
thorn shale
ocean sealBOT
smathwizard
sturdy gale
Also, 5x^2 was never negative
thorn shale
Shoot idk why I even put that lol
sturdy gale
Haha it happens all the time
I have to go now, but I will give you the rest of the steps! I'm very sorry!
- Pretend like $x^2$ isn't there. Factor $5x^2-9x-2$.
ocean sealBOT
smathwizard
thorn shale
Ok TYSM !u literally saved me like I cannot thank you enough u were so much help😁😁
sturdy gale
Ok TYSM !u literally saved me like I cannot thank you enough u were so much help...
No problem!
- Solve for x by setting each factor equal to zero (including x^2)
- that's your solution!
sturdy gale
No problem!!!!
thorn shale
Byeeeee👋👋👋👋😁
sturdy gale
Bye!
mystic vortex
might be something obvious that's slipped my mind, but I can't think of any way to integrate g(x) here
mystic vortex
when I see a composite function like that I wanna do u-substitution, but I don't think I can get an x in there
to be du/dx
or ig in this case it'd be (pi/12)(2x+1)
mystic vortex
I'll still have a sin(x^2) somewhere that'll be hard to integrate, won't I?
tepid fulcrum
Integrate by pzrts
mystic vortex
ohhh interesting
celest spire
hlo guys can you help me out : i am facing confusion if the identity of cos(2θ) works on the cos(-2θ) and what would be its expansion.
celest spire
???
celest spire
yeah i know that but still what would be its expansion
hot snow
it would be exactly same as cos(2θ)
celest spire
for eg what would be the formula of (sin(-2θ))
hot snow
in case of sin(x) is not equal to sin(-x)
hot snow
yes it is
hot snow
ummm
celest spire
?
hot snow
fine I am confused too
celest spire
kk
hot snow
cos(-2θ)=1-2sin(-θ)^2
this is correct
celest spire
it is really an identity can u show me pic
celest spire
but in this (x) i mean angle is +ve
celest spire
but bro cos(-2θ)=cos(2θ)
celest spire
cos(-2θ)=1-2sin(-θ)^2 but here after minus sign gets out of sine it wil become cos(-2θ)=1+2sin(θ)^2
hot snow
no
celest spire
?y
hot snow
since its in square even if -ve comes out it will still be positive
think of sin(θ) = x
x^2 = (-x)^2
celest spire
oh so u mean {sin(-θ)}^2={-1×sin(θ)}^2
celest spire
yeah understood man tnx alot
hot snow
its alright
serene junco
neither is exact, just depends on how far you want to round it
hot snow
it is just calculating to 2 decimal places
trail summit
it is just calculating to 2 decimal places
Why?
hot snow
no clue
trail summit
neither is exact, just depends on how far you want to round it
So it doesn’t really matter how much you round it to?
Are you a helper?
hot snow
you can take it 4.3 for easier calculations
serene junco
anyone can help lol
serene junco
The directions should usually tell you how far to round
trail summit
For this time it doesn’t
wheat isle
So it doesn’t really matter how much you round it to?
Some questions get you to round it to different places
serene junco
if it doesn't specify, then you should be fine usually just rounding to 2 or so
trail summit
Maybe I am wrong
trail summit
if it doesn't specify, then you should be fine usually just rounding to 2 or so
Rounding it to 2 would be 4.33 right?
serene junco
yea
hot snow
Rounding it to 2 would be 4.33 right?
yes
trail summit
Ok so it doesn’t really matter then right? unless it tells me what to round it too. Because my teacher sometimes tell me I round it too close soooo.
hot snow
yeah
hot snow
16.07 feels better but it all depends on what is specified in the question
trail summit
Not really specified I will send you what it says and you tell me just to make sure
I sent the problem too
trail summit
Yea 16.1 seems to close
Alr 16.07 it is
Hopefully that’s correct
Thank you
.close
lone heartBOT
trail summit
.reopen
trail summit
.close
lone heartBOT
Available help channel!
vivid heath
I have a math problem
lone heartBOT
I have a math problem
vivid heath
it takes me 3 times as long to do process B
as it takes to do process A and C
i can complete all three processes in 108,000 seconds
how do i solve this?
upbeat gorge
as it takes to do process A and C
Is this process A or process C individually or processes A and C simultaneously
alpine sable
how do i solve this?
set up an equation to solve
vivid heath
Is this process A or process C individually or processes A and C simultaneously
id say sequentially
like process a
then b
then c
alpine sable
seems to me like (a+c) = 3b
vivid heath
so some context
alpine sable
Yea theres nothing to solve for rn
vivid heath
the machine takes 3 seconds to actuate
for process a
b
and c
process b has three actuations
alpine sable
do you have a pic of the question?