#help-0
1 messages · Page 302 of 1
I think by k they mean the eigenvalue
excluding 0
this has already become a trainwreck
(4k,k) and (-4k,-k) both are the same eigen vector?
Eigenvalue can be equal to 0 btw
yes, because they are constant multiples of the vector <4,1>
which is inside of the nullspace
of A-lambda I
(assuming you found that correctly)
So here k will not be 0 right?
right
Depends on the matrix
if the nullspace is spanned by <4,1> then k will not be 0
Eigenvalues can be 0, yes, but idk why you are using k in (4k, k)
If by k you mean the eigenvalue
Suppose (-1,1) is eigen vector
Right
Then (1,-1) also eigen vector?
Yes
Hmm i understand now
Thank you all
Now my focus on austin explanation about null space
A matrix only has a 0 eigenvalue when it does not have full rank.
An eigenvalue of 0 indicates that when you input a vector, it comes out scaled by 0, meaning it gets sent to 0. This implies that the vector is in the nullspace of the original matrix, which equally implies that this nullspace is nonempty, which equally implies that the matrix does not have full rank. Of course the 0 vector always lives in the nullspace so we do not actually consider this.
Because i have no idea what is actually null space is
The null space, is the space of vectors that when you input them into your matrix, get sent to 0
Determinants is zero?
determinant being zero means the nullspace is non empty yes
Like we find zeroes and we put back into it
Nontrivial you mean? Because nullspace is nonempty always by default
yes excluding 0 of course
It will be null space surely
Consider the matrix,
$$\begin{bmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 0 \end{bmatrix}$$
Austin
think about which vectors you can put into this matrix, that come out only being scaled
can you put a vector that has a nonzero 3rd component into this matrix, and have it come out being only scaled?
consider it being scaled by zero also Arjunn
we can put any vector of the form <0,0,b> with b nonzero, and it will come out being scaled by 0
right?
Because determinant is zero by 3rd row
Can you try to just follow along with what I said, do you agree with that last part?
How??
perform the matrix multiplication $$\begin{bmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 0 \end{bmatrix} \begin{bmatrix} 0 \ 0 \ b \end{bmatrix}$$
Austin
what do you get?
so when we input <0,0,b>, we get out, <0,0,0>, and this is our input vector, <0,0,b> scaled by 0. Now do you see?
If last 3rd row is 0,0,0 then we cannot get any scaled matrix
Nope it's not
After multiplying by that 3×3 matrix no?
no forget about everything
Okay done
forget about your question and everything you've ever known
and consider just this one thing
Sure sure
Scale the vector <0,0,b> by 0. What is the resultant vector?
Incorrect
Do you know what I mean by scale?
I mean multiply
If I asked you to scale by 2
Yes okay
surely <0,0,0>
so anyways let us go back now to the example at hand
I asked you
is there any vectors you can put into this
that come out, scaled by 0
Now, what do you think?
I didn't understand the question
Do you understand now?
Only 3rd row
This is the entire premise of an eigenvector, it is a vector that goes into your matrix and comes out in the same direction it went in (with the possibility of being scaled- scaled meaning multiplied by a constant-)
so any vectors of the form <0,0,b> correct?
Why b
because we can put in
<0,0,1>
or
<0,0,2>
or <0,0,10>
and they all come out
It can be like (b,0,0) (0,b,0) too
<0,0,0>
no
it can't
because when we input <b,0,0>
we get out, <b,0,0>
this is not a version of the input vector that was Scaled by zero
it is scaled by one instead
Wait a minute i am confused here a little bit... because we are first talking about 3×3 matrix or 3×1 matric or their multiplication result?
$$\begin{bmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 0 \end{bmatrix}$$ This is our matrix
Austin
We are considering vector inputs to it, $$\begin{bmatrix} a \ b \ c \end{bmatrix}$$ like this
Austin
Okay fine.
Tell me if you understand the following
I understand these two explanation
A vector is an eigenvector of a matrix, if when you input it into the matrix it comes out only being scaled by a constant value.
Do you understand that?
The constant value that the vector comes out scaled by, is called the eigenvalue for that eigenvector.
Example:
$$\begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}$$ Any vector we put into this, comes out exactly the same. This is to say, all vectors come out scaled by 1. Which tells us that, by our definitions, all vectors are eigenvectors of this matrix, and their eigenvalues are 1.
Austin
Yes this is the definition i understand it but i didn't understand <0,0,b> explanation what was that?
when we input <0,0,b> into our matrix we get out <0,0,0>. This is <0,0,b> * 0, meaning that the output we get is the vector scaled by 0. This is true for all values of b
I can't explain it in any simpler terms
We are considering for the sake of example, if any vectors come out scaled by 0. The only vectors for our matrix that do this, are of the form <0,0,b>. That is why we are considering them.
If we choose 0,b,0 or b,0,0 the. It will also scaled by 0 because 3rd row is 0,0,0 which makes all the Vectors zero and determinant 0
If we choose <0,b,0> we get out <0,b,0>. This IS NOT SCALED BY ZERO IT IS SCALED BY 1 Same for <b,0,0>
Let me check by multiplying
Ohh yes left side we have 1
That will not be 0,0,0
I understand now
Why you were taking 0,0,b so next step now
For null space 🚀
to demonstrate when a matrix has an eigenvalue of 0
you understand now that, that matrix has an eigenvalue of 0 right?
because there are vectors, of the form, <0,0,b> that come out scaled by 0.
and this is equivalent to the matrix's nullspace being non trivial
I will need to learn these terms
Non trivial means not 0 right?
yes
Because 0 always satisfy
Yes true
So null space of a matrix A is set of all the possible vectors x which lead it to 0,0,0
Or any given form of matrix
precisely
Is this thing connected to nullity,rank?
very connected yes
If you have sometime time please explain
all I have time for is this
when the null space is trivial, the matrix is full rank, the matrix's nullity is 0
when the null space is non trivial, the matrix is not full rank, and the matrix's nullity is not 0
I'll need to learn more for these statements. Btw thanks for all the simplest explanations
When null space is trivial then we can take matrix as x= (0,0,0) and it will lead our any matrix A to 0
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i don't understand this
i've made the triangle and found cos x = √7/4
!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
2
what can you say about its sign?
x lies in the interval pi/2 to pi
use the fromula for sin(2x)
its positive right
NO
guys, I finally get into a top-class university.
OH WAIT
positive or negative?
What do you think
I am going to study courses combined with calculus and that would be a bit hard as what I have heard from my senior schoolmates
Yes
so now apply sin(2x) formula
Write in #discussion !!
okok
hold on hold on
isn't sin positive in the second quadrant
or is it because of the cos
Yes it is
sin(x) is positive since x lies in (pi/2,pi)
2x lies in (pi,2pi)
which is third and fourth quadrant
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What are the right options and why?
a and c are horribly worded
my main doubt was regarding a)
is it true. I know the trace of a matrix is a fixed natural number (right?)
But it's somewhat vague.
b) d) is true too
thank you @vale wigeon exactly my point
if they meant tr(I_n) = n then it's true, if they meant tr(I_n) = 69420 no matter what n is then it's false
they gave some natural number, you went with 69420
sus lol
thank you again
btw, c is true too right?
because the trace will always be k*n where n is the order of the scalar matrix
yeah ig
you have a nice day! this is the second question you have solved for me! I am closing this as soon as @winter light finishes typing 🥲
But also (b) is correct, right?
Alright thanks
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whys the principle argument of z, a complex number, defined between -pi < z < pi?
Complex numbers cannot appear in inequalities
They are not an ordered field
Hence -π < z < π is meaningless
Unless z is purely real, then it would be ok to write that
im trying to question 1 right
and i go okay tan^-1(1/-1) = tan^1(-1)
Yes
and i get -pi/4
What are the angles that has that tangent?
Is there another angle that has that tangent?
Remember that tangent has a periodicity of π
Did you draw the number -1 + i in the complex plane?
yeh its the 2nd quad
Exactly, and π - π/4 is in the 2nd quad and has tangent = 1
Therefore that's the correct angle
its at 3pi/4
Yes
the orgional drawinhg
Wdym with original?
this
AHHH okay so arctan is defined on that range
And so adding π or -π allows you to reach all angles between -π and π
Okay so how am i supposed to realize this without graphing it
Do i need to always think about this when finding this
That's why it's very important to first draw the complex number on the plane and then you can compute the argument
Yes
There's actually a math function that returns the arg taking this thing into account but I never remember it
You can use cos and sin to solve these angles as well and the same problem would apply like cos is defined same as tan and sin is quad 1 and 2 right
anyways thanks for the help alberto. Gracias!!!
Let me search it
Here it is, if you'd like @tough lintel
But it's pretty uglier than drawing the number on the plane for me
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Better with 1/2
Because with taking 1/3 power you wouldn't cancel any exponents
At least with ^½ you cancel the ² in the x
You're welcome
*or be mad and try use cubic formula by letting x = a^9
Lol
instead of trying to remove the power on the right side , try to do it on the left side
so after for second step , just raise both to the power of 3/2
$x^{\frac{2}{3}}= 3^2\(x^{\frac{2}{3}})^{\frac{3}{2}}=(3^2)^{\frac{3}{2}}$
male-blu
from this you get x = 3^3= 27
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How does this work? I understand 91 and 84 is divisible by 7. But where or how did 48 become 4? All I can think of is 48/12 = 4, and the 12 came from 84/7 = 12... i'm confused.
shoddy phrasing on their part
here is how to write the same idea but better
$\frac{48 \cdot 91}{84} = \frac{(4 \cdot 12) \cdot (13 \cdot 7)}{12 \cdot 7} = \frac{4 \cdot \cancel{12} \cdot 13 \cdot \cancel{7}}{\cancel{12} \cdot \cancel{7}}$
Ann
my God, did you just write that in free hand and the bot generated it?
btw this command was unnecessary
yes i did
it's a markup language called LaTeX
It's been a while since my mind has been blown. Incredible, Ann. Thank you.
So they just* chose factors of the original numbers and cancelled out?
yeah could put it that way
What stops me picking 6 and 8 for (48)?
$\frac{6 \cdot 8 \cdot 13 \cdot 7}{4 \cdot 21} = \frac{(2 \cdot 3) \cdot (2 \cdot 4) \cdot 13 \cdot 7}{4 \cdot 21}$
Ann
ahh i see
so get the denominators cancelled out ASAP
so you can simply multiply what's left on top
Wonderful!
Thank you again. I think that's it.
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can i use this method?
what should i write then
what were you applying to get from
$$\frac1x = \frac13$$
to
$$\red{-}x = \red{-}3$$
ℝam()n()v
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Could someone check question 5
Result:
270
Ah okay
Thank you
Whilst your here
How would I do question 6
I’ve not done exact values when it’s sin^2
let's see
since
-1≤sin(x)≤1
what are the ranges for sin²(x)
now
ohhhhh
you just need to calculate
my bad
let's start again
sin²(x) is just sin(x) times sin(x)
@weary quartz
Dyssrupt
so
sin²(750°)=sin(750°)*sin(750°)
ahh that’s kinda what i was thinking just couldn’t put it into words
no problem
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how come the graph here doesnt go down to infinity like the other ln graphs?
note that you have **-**ln(x)
which is a reflection transformation of ln(x) about the x-axis
so instead the graph shoots up to (+)inf there
i understand but why is the range limited for ln(x+1)
when it is not limited for other ln graphs such as ln(x-1)
if you're referring to that, its just a shitty graph
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Problem: Each successive row of a triangular stack of bricks has one less brick until there is only one brick on top. How many rows does the stack have if there are 210 total bricks?
Hello. I don't know how to start solving this problem. I really want guidance on what I can do so I can solve this problem, here are the information I have gathered (please correct me if there's something wrong):
A1 = ?
Nth term (what the question is looking for) = ?
Sn = 210
An = 1
d = -1
we can start backwards
Backwards?
if row 1 has 1 brick, row 2 has 2 bricks and row n has n bricks
Yes
Oh wait, row with 210 bricks? But it should be total of bricks
like
an = an-1 + 1
where n is the number of bricks on row n
if a1 = 1
a2 = a1 + 1 = 1 + 1 = 2
Yes
do you understand the general pattern
Yes I do, but you said the row with 210 bricks. But 210 should be the total of bricks, no?
Yes
Oh alright
ok so
to find the sum of the first x natural numbers, we can use $\frac{x(x+1)}/2$
$\frac{x(x+1)}2$
aysob_ay212
(note we will scrap the backwards approach i was talking about)
we know that we have x total number of bricks
in a row
and then to find all number of bricks in each row before x
we can do x + (x-1) + (x-2) + ... + 1
because 1 is the base case
we know that this must equal 210
and using this formula
we can do x(x+1)/2 = 210
x(x+1) = 420
x^2 + x - 420 = 0
then solve for x
x = 20, or x = -21, since x > 0, therefore x = 20
does that make sense
Yes it does
But how did you know that we can use the formula x(x + 1) / 2 so we can find the sum of the first x natural numbers
or is that just commonly known?..
i feel like its commonly known
Oh
you should've learnt this in your sequences/series
Derivation of the formula in a way which is easy to understand. It will also help student to remember the formula easily. This is the foundation for next few videos on Arithmetic progression. This will also help u in solving mental ability problems asked in various competitive exams. This Method of addition is also useful in finding the sum of v...
Actually before you were going to present the formula I was doing a trial of error of for example let's say n is 10, n is 20 and so on
But yeah it wouldn't be efficient I guess
I see
yeah it wouldnt, because if i gave you a huge number, it would take forever
10th grade hasn't started for me, I'm just learning in advance
I was learning in math libretext
Thank you for the help
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Hello everyone, I urgently need help with this example. There are no errors in the example and the answer should work. (Text on the photo: Solve the equation. If there are several solutions, then indicate the largest root.)
а срочно-то почему?
просто тут часто так бывает, что люди пытаются здесь на экзаменах/контрольных списать
ладно, проехали. прогресс какой-нибудь с решением уравнения есть?
короче решить мог бы и сам
но походу решения нет
посмотрел график, даже пересечений нет
но на счет условия ничего сказать не могу, что есть пока, то есть
задание из подготовки для экзамена, списать ничего не пытаюсь
и что он тебе выдал?
скрин есть?
ща
решается вполне себе, только надо некоторые нюансы с корнями
так-то мы здесь таким не занимаемся
я же все правильно ввел
все верно
да-да, я неправильно прочла
а чем тут занимаются
ну модельно помощь проводится так: у тебя спрашивают, в чем проблема (не можешь начать / застрял / ответ не тот / не понимаешь какое-то понятие и т.д.), а затем уже именно эта проблема прицельно лечится, чтобы ты мог сам задачу решить
короче да, ты прав, мн-во решений тут пусто
какое множество
множество решений уравнения
или если просторечно, но нет их
таки все равно photomath'ом некошерно пользоваться
ну так а как я должен был понять то
please open your own channel. read #❓how-to-get-help for instructions.
this channel is occupied.
ну например можно начать с того, что одну корнюгу отнять с обеих частей: $$\sqrt{x + 2\sqrt{x+1}} = 2 - \sqrt{x - 2 \sqrt{x-1}}$$ потом возвести в квадрат, еще похимичить, и в конце концов свести к полиномиальному уравнению. здесь вроде бы всего 2-й степени будет, так что решится все
Ann
Ok, thanks
хотя может вылезти и четвертая степень. вот тогда будет грустно.
@vale wigeon how do i create one for myself
!help
Please read #❓how-to-get-help
Channel
@zinc pier что характерно, если бы вместо x+1 там было x-1 (как сначала подумала я), то уравнение было бы в разы приятнее. а сейчас мне мерещится какая-то жуть полнейшая.
ты же написала нет решений
возможно, не отрицаю
нет решений ≠ уравнение невозможно решить
решить уравнение -- значит найти все его решения или убедиться, что таковых не существует
ну так мы убедились же что их нет
пока еще нет
Inside your second square root is a square , so your second square root =|sqrt(x-1)-1|. Since you are looking for the maximal solution we can now let it be (sqrt(x-1)-1). Then your question in the end becomes sqrt(x+1)+3sqrt(x-1)=4. Let t=x-1 this can become quadratic in terms of t
в смысле да, но способ некошерен
там написано черным по белому, что решение (в смысле письменные вычисления) надо прикрепить
думаю, что за скриншот из photomath тебе влетит
да это просто пробник, его никуда не отправляю
я ж просто готовлюсь
ну и хз на счет прикрепление решений, в других заданиях протсо ответ например: х = 2
не ну ладно, тогда просто надо написать "решений нет". я хз, как в твоей системе это сделать.
Can’t understand what you are talking about. Are you saying it’s 2? Because I got 4+1/sqrt(2)
i am saying that there are no solutions at all
and both photomath and desmos confirm it
No solution? Okay I need to check my steps…
Oh indeed … sqrt(x-1)>=1 doesn’t work since x<=2, I had to take sqrt(x-1)<=1, then x+2sqrt(x+1)=(1+sqrt(x-1))^2
sqrt(x+1)=sqrt(x-1), no solution indeed…
Result:
2.3375417889607
I checked 2 is not even a solution
кажись, в условии опечатка.
Sum of two roots=2, so the first root<=2 right, so x<=2, meaning |sqrt(x-1)-1|=1-sqrt(x-1).
-____-
Condition: enter the largest root in the answer
largest positive integer root.
$$\sqrt{x+2\sqrt{x+1}}+|\sqrt{x-1}-1|=2$$
$$\sqrt{x+2\sqrt{x+1}}+1-\sqrt{x-1}=2$$
$$\sqrt{x+2\sqrt{x+1}}=1+\sqrt{x-1}$$
$$x+2\sqrt{x+1}=(1+\sqrt{x-1})^{2}=x+2\sqrt{x-1}$$
$$\sqrt{x+1}=\sqrt{x-1}$$
No solution
Cogwheels of the mind
Ладно, рас уж мы закончили, всем спасибо) Я просто для друга решение искал, он не мог решить, а потом там оказывается кнопка проверить ответ была)
ну и ну нас третий друг математик сидел и сразу сказал что там ошибка в условии и если второй знак заменить, то выйдет 2
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Answer will be D) I can explain in DMS if you want
Sure
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
@alpine sable @near lion this server is not for giving solutions, and please do not offer to dm users.
For future reference
Oh
Then what should we do ?
I'm new so idk what to do I thought we are supposed to help them
I believe
has some guidelines
uhhh
@real gazelle could u link up guidelines for helping people, not loading for me
!nosols
Bot seems to be slow today
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
The goal of any helper should be to enable the helpee understand how to do a similar problem, so they don't come back again with it.
Ok sorry
No worries, now you know!
@near lion Has your question been resolved?
No
@near lion Has your question been resolved?
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Find h
angles are 15 and 18
i got 1.24 but im not sure if im correct and theres no answers
don't you need some side elngths to find h?
Ah, AB=6?
Correct
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I am looking for a quick sanity check. I did work breaking down the vectors into their components, but I cannot figure out why this is wrong.
I drew out the vectors as well. My assumption is that I misinterpreted the direction of the wind vector.
Alas, nothing else make sense to me at the moment
Reading the given information, the vector of wind is "S 30(deg) E at a speed of 37mph"
@quick laurel Has your question been resolved?
S30°E would be mostly south
like S1°E would be almost entirely south but just a smidge east
that makes sense, I did actaully get to that point and attempt it using 60(deg) from the x axis
and it still didnt work
would be -60°
This is what I have mathwise
So for the wind vector I have, 37cos(-60)i - 37sin(-60)j
and combining the two vectors gives me 131.637i + 145.18j
which apparently isn't the correct answer
why combine them yet? it looks like you just need the wind vector itseld
Because, I had only 5 attempts at that portion and I can no longer change it
and It did not give me the correct answer (annoyingly)
why the - between i and j
Isn't the direction of the vector in the y direction negative
since it points S
therefore, the j component is negative?
yeah but the sin(-30) already does that for you
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am stuck
@steep drift Has your question been resolved?
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@lapis stream
Is c=16-4t-0.25t^2 then plug two into t?
This is wrong because it would entail that c=5
It probably doesn't work because you can't solve a quad equation when it equals anything other than zero
this is your teachers work? they dont write very well
whats the left hand limit of B?
why is t still there
the limit is along t
think of it like if i gave you f(x) and asked you what the value of f is at x=4
and you told me x+6
that doesnt make sense
f(4) cant be something involving x
4 replaces x
its kinda the same with a limit
if it exists
He just equaled the two sides then plugged two
he evaluated the limit
neither of these are right
whats the left hand limit?
$\lim _{t \to 2 ^-} \qty( 4-\frac 12 t ) = ?$
jan Niku
dont worry about me lol
as long as you understand it and can get the answer thats all that matters
I think that I can close this now
.close
Oh u are the one who can open and close channels
.close
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Trying to understand graf (1/2)^x
well if you raise 1/2 to higher and higher powers you get smaller and smaller numbers don't you
what's (½)³?
..
?
do you know what an exponent is
Im tryna understand why it goes opposite way
do you know what an exponent is?
you need to know what an exponent is first
Yeah ofc
whats 2^3
Its a polynom with a positive realla number as bas with a exponent
Bruh
doesn't have to be a polynomial
8
do you know property of exponents then
Can u give example
Oh
No i know already
,tex .exp rules
hayley!
I was thinking diffrently
A bit lost there
I was thinking with a diffrent question
so does it make sense 1/2^x decreases
I understand but i dont understand why y is negative
y isn't negative
In a graf
,w graph 1/2^x
it asymptotes at 0
Yeah you see that it goes left
,w compute 1/2^999
large values of x give a very small but positive result
,w graph 1/2^9999
essentially y=0
What
it's a line
I feel dumb why does it go that way
you just graphed a straight line
what's 1
1 should be it’s y
x=1?
x=0
what's that have anything to do with this
and youre asking why it decreases as x increases
graph
between what
Between 2^x
Yeah
obviously
Why’s that I just don’t get it
1/2^x is just 2^-x
Oh shoot
you would know this if you knew exponent rules
Why is that so
Is it too minuscule?
minuscule?
,w graph 2^-55
Why is it a straight line
cause you graphed y=2^-55
not a zoom in of y=1/2^x at a certain value of x
,w graph y=2
Is it going to left because
The exponential is negative and the base get higher up to y when base is higher
,w graph -2^-x
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What does Instantaneous Velocity mean?
if you were accelerating
instantaneous velocity is the velocity at one specific point in time
Is it calculated in real time?
speedometer
So technically it’s impossible to calculate instantaneous velocity
well its the same as saying its impossible to know any objects true mass
you can still get very close
Oh ok
So how would you get instantaneous velocity?
Is there like a specific formula
Inst. velocity is the limit of that as b -> a
yeah i just realized
And it should be with vectors but yeah that's the definition of derivative
Isn’t that Average Velocity
yes
this is better
but if you take average velocity
over a very small time frame
that becomes closer to instantaneous
I’m pretty confused what’s the difference between Instantaneous Velocity and Average Velocity?
velocity
In other words, instantaneous velocity is the first derivative of position @alpine sable
thats a good way to put it
basically just take a super close point to the right and to the left and find velocity between them
instantaneous velocity is the average velocity over a infinitesimal time frame
its not possible to actually measure this over literally 0s time, but you can get close by measuring over 0.01s time or something
You can calculate that with data right?
Previous data
Interesting
Wow interesting
unfortunately quite literally everything you measure has a delay
because of the speed of causality
Didn't know that
so youd be measuring the instantaneous velocity of however long it took the light to go from your radar gun to the object and vice versa
So like instantaneous
I could view it as a way of getting the exact velocity within a given set of distance precisely
Which is practically impossible
But you can still get very close
Am I right?
Also @whole shell @winter light thanks for helping me
If there’s anything I can do in return tell me
im lost as to what you mean by this
Like instantaneous is the velocity at a specific point in time and you can never get that velocity 100% accurately but still very close
Right?
yh
Ok thanks
also not just accurately though
like even if yourr radar gun has 100% precision
youll only ever measure the velocity the object had a little while ago (well the time is very very very small, but it is a small lag)
so you can never measure it in "real time"
@alpine sable if you were measuring the speed of a planet 5 light years away from you
youd be measuring the speed it had 5 years ago
Oh
That’s a pretty good way of putting it
That makes sense
Isn’t calculating average velocity the same then?
Because
Average velocity isng 100% accurate too
we have 2 seperate problems
the fact that we cant get this accurate velocity to be instantaneous
because we cant measure in 0 time
and the fact that anything we do measure is from the past
even radar guns cant detect the exact frequency change
thats just how life is
but other than those 2 issues that you will never really feel
yes
youll be very close
to the answer you want
as in your velocity in real time
So technically it’s also impossible to get a perfect average velocity too
well its impossible to measure the time or distance youve taken 100% accurately
but the time delay issue doesnt work here, since average velocity already refers to something in the past
Okay thank you for your help it’s very much appreciated
@whole shell what song do you like?
I’ll play it for you in return
wdym
I play piano for anyone that helps me solve a problem
Of their specific song choice
rush e 
I’ll try
@alpine sable i was joking, the actual song would be twinkle twinkle little star, specifically variation 1
Clara Haskil plays Mozart's 12 Variations in C over the french song "Ah, vous dirai-je maman", also known as "Twinkle twinkle little star"
For more great, scored videos, check out my channel !
timestamped
once you see rush E youll know why i did the troll face
@alpine sable Has your question been resolved?
i cant really do it lol
but thanks for the help
.close
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Ask the employee at the gun range
what country?
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Why are you entertaining the behavior
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(a) Prove that if the roots of
[x^3 + ax^2 + bx + c = 0]form an arithmetic sequence, then $2a^3 + 27c = 9ab.$
(b) Prove that if $2a^3 + 27c = 9ab,$ then the roots of
[x^3 + ax^2 + bx + c = 0]form an arithmetic sequence.
dabbingpotato
Roots are z-r, z, z+r
$(x-(z-r))(x-z)(x-(z+r)) = \x^3-(z-r)x^2-zx^2+(z-r)zx-(z+r)x^2+(z-r)(z+r)x+(z+r)zx-(z-r)z(z+r)$
\\ for newline
dabbingpotato
Now we use vietas?
a = -3z
b = 3z^2 - r^2
c = - z^3 + zr^2
am i on the right track?
you might consider simplifying that a bit...
z^2 - rz + z^2 - r^2 + z^2 + zr
3z^2 - r^2
Now we substitute those values into $2a^3 + 27c = 9ab$?
dabbingpotato
yep
$-54z^3 + 27zr^2 - 27z^3 = -81z^3 + 27zr^2$
dabbingpotato
is that right?
Okay so now part b)
We know that this is true, so how can we use this to know that the roots form an arithmetic sequence?
Prove that if they don’t form an arithmetic sequence then 2a^3+27c doesn’t equal 9ab
This time three roots are z-r, z, z+s where r-s is not zero
I don't think thats what part b is asking though
P->Q is equivalent to (not Q)->(not P)
Show 2(3z+s-r)^3+27(z^3+(s-r)z^2-rsz) doesn’t equal 9(3z+s-r)(3z^2+(2s-2r)z-rs)
When r-s is not zero
That doesn't prove B tho
Just because when 2a^3 + 27c doesn't equal 9ab doesn't form an arithmetic sequence
That doesn't mean that when 2a^3 + 27c is equal to 9ab always has to form an arithmetic sequence
P: 2a^3+27c=9ab Q : form an arithmetic…
P->Q is equivalent to (not Q)->(not P)
Not Q: they don’t form an arithmetic sequence
Not P: 2a^3+27c doesn’t equal 9ab
How do you know
what is logic
can you give me another example of when this works
x is an integer-> x is a rational number
x is not a rational number-> x is not an integer
No
isn't that a contradiction
oh
okay i guess that works
$2(3z+s-r)^3+27(z^3+(s-r)z^2-rsz) = 9(3z+s-r)(3z^2+(2s-2r)z-rs)$
dabbingpotato
pain
okay so we use vietas again?
how we get this tho
so veitas
Yeah
So in the end it becomes proving 2(s-r)^3 doesn’t equal -9rs(s-r)
When s-r doesn’t equal 0. Obvious
okay
is this right for the vietas?
$a = - 3z + r - s$
$b = 3z^2 - 2rz + 2sz - rs$
$c = z^3 + z^2r + rzs - sz^2$
dabbingpotato
also shouldn't it be a and c not -a and -c
You got c wrong by the way
-z^3+…
Other terms are correct
did you get this by just powering through the expandsion
I expanded this
Coefficients of z^3,z^2,z are equal respectively
Only the constant term of LHS doesn’t equal the constant term of RHS left
Which is proving 2r^2+2s^2+5rs doesn’t equal 0 when s doesn’t equal r
is $2r^2+2s^2+5rs \neq 0$ just on one side $2(s-r)^3 \neq -9rs(s-r)$
dabbingpotato
Wtf mods