#help-0

1 messages · Page 302 of 1

vale wigeon
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@vapid shuttle 0 isn't an eigenvector

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it is the one edge case

vapid shuttle
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and thus any constant multiple of this eigenvector

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is also in this nullspace

echo socket
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I think by k they mean the eigenvalue

vapid shuttle
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excluding 0

vale wigeon
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this has already become a trainwreck

lime sluice
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(4k,k) and (-4k,-k) both are the same eigen vector?

echo socket
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Eigenvalue can be equal to 0 btw

vapid shuttle
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yes, because they are constant multiples of the vector <4,1>

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which is inside of the nullspace

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of A-lambda I

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(assuming you found that correctly)

lime sluice
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So here k will not be 0 right?

vapid shuttle
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right

echo socket
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Depends on the matrix

vapid shuttle
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if the nullspace is spanned by <4,1> then k will not be 0

lime sluice
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This is eigen vector (4k,k) can be k=0?@echo socket

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Eigen values can be 0

echo socket
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Eigenvalues can be 0, yes, but idk why you are using k in (4k, k)

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If by k you mean the eigenvalue

lime sluice
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Suppose (-1,1) is eigen vector

echo socket
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Right

lime sluice
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Then (1,-1) also eigen vector?

echo socket
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Yes

lime sluice
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Hmm i understand now

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Thank you all

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Now my focus on austin explanation about null space

vapid shuttle
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A matrix only has a 0 eigenvalue when it does not have full rank.
An eigenvalue of 0 indicates that when you input a vector, it comes out scaled by 0, meaning it gets sent to 0. This implies that the vector is in the nullspace of the original matrix, which equally implies that this nullspace is nonempty, which equally implies that the matrix does not have full rank. Of course the 0 vector always lives in the nullspace so we do not actually consider this.

lime sluice
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Because i have no idea what is actually null space is

vapid shuttle
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The null space, is the space of vectors that when you input them into your matrix, get sent to 0

lime sluice
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Determinants is zero?

vapid shuttle
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determinant being zero means the nullspace is non empty yes

lime sluice
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Like we find zeroes and we put back into it

echo socket
vapid shuttle
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yes excluding 0 of course

lime sluice
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It will be null space surely

vapid shuttle
ocean sealBOT
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Austin

vapid shuttle
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think about which vectors you can put into this matrix, that come out only being scaled

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can you put a vector that has a nonzero 3rd component into this matrix, and have it come out being only scaled?

lime sluice
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Nope

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I multiplied and it will be zero

vapid shuttle
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consider it being scaled by zero also Arjunn

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we can put any vector of the form <0,0,b> with b nonzero, and it will come out being scaled by 0

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right?

lime sluice
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Because determinant is zero by 3rd row

vapid shuttle
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Can you try to just follow along with what I said, do you agree with that last part?

vapid shuttle
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perform the matrix multiplication $$\begin{bmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 0 \end{bmatrix} \begin{bmatrix} 0 \ 0 \ b \end{bmatrix}$$

ocean sealBOT
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Austin

vapid shuttle
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what do you get?

lime sluice
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0,0,0

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Colomn

vapid shuttle
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so when we input <0,0,b>, we get out, <0,0,0>, and this is our input vector, <0,0,b> scaled by 0. Now do you see?

lime sluice
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If last 3rd row is 0,0,0 then we cannot get any scaled matrix

vapid shuttle
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arjunn

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what is <0,0,b> scaled by 0

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tell me please

lime sluice
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Nope it's not

vapid shuttle
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no

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I said what is it

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What is <0,0,b> scaled by 0????

lime sluice
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After multiplying by that 3×3 matrix no?

vapid shuttle
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no forget about everything

lime sluice
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Okay done

vapid shuttle
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forget about your question and everything you've ever known

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and consider just this one thing

lime sluice
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Sure sure

vapid shuttle
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Scale the vector <0,0,b> by 0. What is the resultant vector?

lime sluice
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0,0,b

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As it is

vapid shuttle
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Incorrect

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Do you know what I mean by scale?

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I mean multiply

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If I asked you to scale by 2

lime sluice
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Ohh i added

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Then surely 0,0,0

vapid shuttle
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Yes okay

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surely <0,0,0>

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so anyways let us go back now to the example at hand

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I asked you

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is there any vectors you can put into this

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that come out, scaled by 0

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Now, what do you think?

lime sluice
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I didn't understand the question

vapid shuttle
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Do you understand now?

lime sluice
vapid shuttle
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This is the entire premise of an eigenvector, it is a vector that goes into your matrix and comes out in the same direction it went in (with the possibility of being scaled- scaled meaning multiplied by a constant-)

vapid shuttle
lime sluice
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Why b

vapid shuttle
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because we can put in

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<0,0,1>

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or

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<0,0,2>

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or <0,0,10>

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and they all come out

lime sluice
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It can be like (b,0,0) (0,b,0) too

vapid shuttle
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<0,0,0>

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no

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it can't

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because when we input <b,0,0>

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we get out, <b,0,0>

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this is not a version of the input vector that was Scaled by zero

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it is scaled by one instead

lime sluice
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Wait a minute i am confused here a little bit... because we are first talking about 3×3 matrix or 3×1 matric or their multiplication result?

vapid shuttle
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$$\begin{bmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 0 \end{bmatrix}$$ This is our matrix

ocean sealBOT
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Austin

vapid shuttle
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We are considering vector inputs to it, $$\begin{bmatrix} a \ b \ c \end{bmatrix}$$ like this

ocean sealBOT
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Austin

lime sluice
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Okay fine.

vapid shuttle
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Tell me if you understand the following

lime sluice
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I understand these two explanation

vapid shuttle
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A vector is an eigenvector of a matrix, if when you input it into the matrix it comes out only being scaled by a constant value.

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Do you understand that?

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The constant value that the vector comes out scaled by, is called the eigenvalue for that eigenvector.

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Example:
$$\begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}$$ Any vector we put into this, comes out exactly the same. This is to say, all vectors come out scaled by 1. Which tells us that, by our definitions, all vectors are eigenvectors of this matrix, and their eigenvalues are 1.

ocean sealBOT
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Austin

vapid shuttle
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excluding the zero vector like usual

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and of course I mean vectors in R2

lime sluice
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Yes this is the definition i understand it but i didn't understand <0,0,b> explanation what was that?

vapid shuttle
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when we input <0,0,b> into our matrix we get out <0,0,0>. This is <0,0,b> * 0, meaning that the output we get is the vector scaled by 0. This is true for all values of b

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I can't explain it in any simpler terms

lime sluice
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It can be anything no?

vapid shuttle
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We are considering for the sake of example, if any vectors come out scaled by 0. The only vectors for our matrix that do this, are of the form <0,0,b>. That is why we are considering them.

lime sluice
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If we choose 0,b,0 or b,0,0 the. It will also scaled by 0 because 3rd row is 0,0,0 which makes all the Vectors zero and determinant 0

vapid shuttle
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If we choose <0,b,0> we get out <0,b,0>. This IS NOT SCALED BY ZERO IT IS SCALED BY 1 Same for <b,0,0>

lime sluice
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Let me check by multiplying

vapid shuttle
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<0,b,0> = 1 *<0,b,0> != 0*<0,b,0>

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!= (for not equals to)

lime sluice
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Ohh yes left side we have 1

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That will not be 0,0,0

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I understand now

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Why you were taking 0,0,b so next step now

vapid shuttle
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Okay

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so the point there was

lime sluice
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For null space 🚀

vapid shuttle
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to demonstrate when a matrix has an eigenvalue of 0

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you understand now that, that matrix has an eigenvalue of 0 right?

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because there are vectors, of the form, <0,0,b> that come out scaled by 0.

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and this is equivalent to the matrix's nullspace being non trivial

lime sluice
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Non trivial means not 0 right?

vapid shuttle
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yes

lime sluice
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Because 0 always satisfy

ocean sealBOT
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Austin

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Austin

lime sluice
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Yes true

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So null space of a matrix A is set of all the possible vectors x which lead it to 0,0,0

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Or any given form of matrix

vapid shuttle
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precisely

lime sluice
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Is this thing connected to nullity,rank?

vapid shuttle
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very connected yes

lime sluice
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If you have sometime time please explain

vapid shuttle
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all I have time for is this

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when the null space is trivial, the matrix is full rank, the matrix's nullity is 0

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when the null space is non trivial, the matrix is not full rank, and the matrix's nullity is not 0

lime sluice
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I'll need to learn more for these statements. Btw thanks for all the simplest explanations

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When null space is trivial then we can take matrix as x= (0,0,0) and it will lead our any matrix A to 0

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.close

lone heartBOT
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languid gust
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i don't understand this

lone heartBOT
languid gust
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i've made the triangle and found cos x = √7/4

subtle birch
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!status

lone heartBOT
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What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
languid gust
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2

subtle birch
heady void
languid gust
subtle birch
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NO

modern kelp
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guys, I finally get into a top-class university.

languid gust
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OH WAIT

languid gust
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positive or negative?

subtle birch
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What do you think

languid gust
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no its negative

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because thats 90-180

modern kelp
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I am going to study courses combined with calculus and that would be a bit hard as what I have heard from my senior schoolmates

subtle birch
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Yes

subtle birch
modern kelp
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okok

languid gust
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hold on hold on

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isn't sin positive in the second quadrant

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or is it because of the cos

subtle birch
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Yes it is

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sin(x) is positive since x lies in (pi/2,pi)
2x lies in (pi,2pi)

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which is third and fourth quadrant

languid gust
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oHHH

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okok thank you so much

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.close

lone heartBOT
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halcyon monolith
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What are the right options and why?

lone heartBOT
vale wigeon
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a and c are horribly worded

halcyon monolith
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my main doubt was regarding a)

is it true. I know the trace of a matrix is a fixed natural number (right?)

But it's somewhat vague.

b) d) is true too

halcyon monolith
vale wigeon
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if they meant tr(I_n) = n then it's true, if they meant tr(I_n) = 69420 no matter what n is then it's false

halcyon monolith
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they gave some natural number, you went with 69420

sus lol

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thank you again

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btw, c is true too right?

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because the trace will always be k*n where n is the order of the scalar matrix

vale wigeon
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yeah ig

halcyon monolith
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you have a nice day! this is the second question you have solved for me! I am closing this as soon as @winter light finishes typing 🥲

winter light
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But also (b) is correct, right?

halcyon monolith
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yes b is correct

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it's a property 🙂

winter light
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Alright thanks

halcyon monolith
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.close

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tough lintel
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whys the principle argument of z, a complex number, defined between -pi < z < pi?

winter light
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Complex numbers cannot appear in inequalities

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They are not an ordered field

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Hence -π < z < π is meaningless

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Unless z is purely real, then it would be ok to write that

tough lintel
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im trying to question 1 right

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and i go okay tan^-1(1/-1) = tan^1(-1)

winter light
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Yes

tough lintel
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and i get -pi/4

winter light
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What are the angles that has that tangent?

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Is there another angle that has that tangent?

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Remember that tangent has a periodicity of π

tough lintel
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yeah but why do i need to go pi - pi/4

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i understand that it has a periodicy of pi

winter light
tough lintel
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yeh its the 2nd quad

winter light
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Exactly, and π - π/4 is in the 2nd quad and has tangent = 1

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Therefore that's the correct angle

tough lintel
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its at 3pi/4

winter light
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Yes

tough lintel
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the orgional drawinhg

winter light
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Wdym with original?

winter light
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Yes

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-1 + i is in the 2nd quad

tough lintel
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tan^-1(-1) is in the 4th

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so i need to get them to line up

winter light
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Exactly

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The problem is that the arctan gives values between -π/2 and π/2

tough lintel
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AHHH okay so arctan is defined on that range

winter light
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And so adding π or -π allows you to reach all angles between -π and π

tough lintel
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Okay so how am i supposed to realize this without graphing it

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Do i need to always think about this when finding this

winter light
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That's why it's very important to first draw the complex number on the plane and then you can compute the argument

winter light
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There's actually a math function that returns the arg taking this thing into account but I never remember it

tough lintel
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You can use cos and sin to solve these angles as well and the same problem would apply like cos is defined same as tan and sin is quad 1 and 2 right

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anyways thanks for the help alberto. Gracias!!!

winter light
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Let me search it

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Here it is, if you'd like @tough lintel

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But it's pretty uglier than drawing the number on the plane for me

tough lintel
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oh yeah ill just draw it 😮

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thanks lol

tough lintel
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.close

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frosty gull
lone heartBOT
frosty gull
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i am stuck here

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should take 1/2 on both sides or 1/3?

winter light
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Better with 1/2

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Because with taking 1/3 power you wouldn't cancel any exponents

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At least with ^½ you cancel the ² in the x

frosty gull
winter light
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Yes

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And now you can cube both sides

frosty gull
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oh okay thanks

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we x=27

winter light
mellow grail
winter light
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Lol

alpine sable
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instead of trying to remove the power on the right side , try to do it on the left side

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so after for second step , just raise both to the power of 3/2

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$x^{\frac{2}{3}}= 3^2\(x^{\frac{2}{3}})^{\frac{3}{2}}=(3^2)^{\frac{3}{2}}$

ocean sealBOT
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male-blu

alpine sable
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from this you get x = 3^3= 27

lone heartBOT
#

@frosty gull Has your question been resolved?

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lost mica
#

.reopen

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How does this work? I understand 91 and 84 is divisible by 7. But where or how did 48 become 4? All I can think of is 48/12 = 4, and the 12 came from 84/7 = 12... i'm confused.

vale wigeon
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shoddy phrasing on their part

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here is how to write the same idea but better

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$\frac{48 \cdot 91}{84} = \frac{(4 \cdot 12) \cdot (13 \cdot 7)}{12 \cdot 7} = \frac{4 \cdot \cancel{12} \cdot 13 \cdot \cancel{7}}{\cancel{12} \cdot \cancel{7}}$

ocean sealBOT
lost mica
#

my God, did you just write that in free hand and the bot generated it?

vale wigeon
vale wigeon
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it's a markup language called LaTeX

lost mica
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It's been a while since my mind has been blown. Incredible, Ann. Thank you.
So they just* chose factors of the original numbers and cancelled out?

vale wigeon
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yeah could put it that way

lost mica
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What stops me picking 6 and 8 for (48)?

vale wigeon
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nothing

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you'll just have the cancellation go in a different way

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slightly longer

lost mica
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can you show me via latex?

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what you would have done

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had you gone the 6 and 8 route

vale wigeon
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$\frac{6 \cdot 8 \cdot 13 \cdot 7}{4 \cdot 21} = \frac{(2 \cdot 3) \cdot (2 \cdot 4) \cdot 13 \cdot 7}{4 \cdot 21}$

ocean sealBOT
vale wigeon
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or something

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then cancel out 2*2 with 4 and 3*7 with 21

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off the top of my head

lost mica
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ahh i see

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so get the denominators cancelled out ASAP

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so you can simply multiply what's left on top

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Wonderful!

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Thank you again. I think that's it.

#

.closed

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.close

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frosty gull
lone heartBOT
frosty gull
#

can i use this method?

vale wigeon
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sure why not

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last two lines are a little strange (though not illegal)

frosty gull
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what should i write then

gray isle
#

what were you applying to get from
$$\frac1x = \frac13$$
to
$$\red{-}x = \red{-}3$$

ocean sealBOT
#

ℝam()n()v

frosty gull
#

ok

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.close

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weary quartz
lone heartBOT
weary quartz
#

Could someone check question 5

nimble fern
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x=305

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,calc 305-35

ocean sealBOT
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Result:

270
nimble fern
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yea

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no degrees sign, because it's given in the function

weary quartz
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Thank you

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Whilst your here

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How would I do question 6

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I’ve not done exact values when it’s sin^2

nimble fern
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let's see

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since
-1≤sin(x)≤1

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what are the ranges for sin²(x)

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now

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ohhhhh

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you just need to calculate

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my bad

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let's start again

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sin²(x) is just sin(x) times sin(x)

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@weary quartz

weary quartz
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right

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so could i do it as

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actually nvm

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still don’t know

ocean sealBOT
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Dyssrupt

nimble fern
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so
sin²(750°)=sin(750°)*sin(750°)

weary quartz
nimble fern
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no problem

weary quartz
#

.close

lone heartBOT
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bright remnant
#

how come the graph here doesnt go down to infinity like the other ln graphs?

bright remnant
gray isle
#

note that you have **-**ln(x)

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which is a reflection transformation of ln(x) about the x-axis

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so instead the graph shoots up to (+)inf there

bright remnant
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when it is not limited for other ln graphs such as ln(x-1)

gray isle
#

if you're referring to that, its just a shitty graph

bright remnant
#

ohh okay

#

that tripped me up

lone heartBOT
#

@bright remnant Has your question been resolved?

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grand berry
#

Problem: Each successive row of a triangular stack of bricks has one less brick until there is only one brick on top. How many rows does the stack have if there are 210 total bricks?

Hello. I don't know how to start solving this problem. I really want guidance on what I can do so I can solve this problem, here are the information I have gathered (please correct me if there's something wrong):

A1 = ?
Nth term (what the question is looking for) = ?
Sn = 210
An = 1
d = -1

granite badger
#

we can start backwards

grand berry
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Backwards?

granite badger
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if row 1 has 1 brick, row 2 has 2 bricks and row n has n bricks

grand berry
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Yes

granite badger
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we can find the row with 210 bricks then

#

1+2+3+...+n

grand berry
#

Oh wait, row with 210 bricks? But it should be total of bricks

granite badger
#

like

#

an = an-1 + 1

#

where n is the number of bricks on row n

#

if a1 = 1
a2 = a1 + 1 = 1 + 1 = 2

grand berry
#

Yes

granite badger
#

do you understand the general pattern

grand berry
#

Yes I do, but you said the row with 210 bricks. But 210 should be the total of bricks, no?

granite badger
#

oh i see

#

we know that sn = n/2(t1 + tn) for an arithmetic series, right?

grand berry
#

Yes

granite badger
#

ok lets say Sn = 210, n = 1, tn = ?, t1 = 1

#

hmm lemme think

grand berry
#

Oh alright

granite badger
#

ok so

#

to find the sum of the first x natural numbers, we can use $\frac{x(x+1)}/2$

#

$\frac{x(x+1)}2$

ocean sealBOT
#

aysob_ay212

granite badger
#

(note we will scrap the backwards approach i was talking about)

#

we know that we have x total number of bricks

#

in a row

#

and then to find all number of bricks in each row before x

#

we can do x + (x-1) + (x-2) + ... + 1

#

because 1 is the base case

granite badger
granite badger
#

we can do x(x+1)/2 = 210

#

x(x+1) = 420

#

x^2 + x - 420 = 0

#

then solve for x

#

x = 20, or x = -21, since x > 0, therefore x = 20

#

does that make sense

grand berry
#

Yes it does

#

But how did you know that we can use the formula x(x + 1) / 2 so we can find the sum of the first x natural numbers

#

or is that just commonly known?..

granite badger
#

i feel like its commonly known

grand berry
#

Oh

granite badger
#

you should've learnt this in your sequences/series

#

Derivation of the formula in a way which is easy to understand. It will also help student to remember the formula easily. This is the foundation for next few videos on Arithmetic progression. This will also help u in solving mental ability problems asked in various competitive exams. This Method of addition is also useful in finding the sum of v...

▶ Play video
grand berry
#

Actually before you were going to present the formula I was doing a trial of error of for example let's say n is 10, n is 20 and so on

#

But yeah it wouldn't be efficient I guess

granite badger
#

yeah it wouldnt, because if i gave you a huge number, it would take forever

grand berry
#

10th grade hasn't started for me, I'm just learning in advance

#

I was learning in math libretext

grand berry
#

.close

lone heartBOT
#
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lone heartBOT
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zinc pier
#

Hello everyone, I urgently need help with this example. There are no errors in the example and the answer should work. (Text on the photo: Solve the equation. If there are several solutions, then indicate the largest root.)

vale wigeon
zinc pier
#

о

#

ну можно не очень срочно)

#

просто сейчас нужно решение

vale wigeon
#

просто тут часто так бывает, что люди пытаются здесь на экзаменах/контрольных списать

#

ладно, проехали. прогресс какой-нибудь с решением уравнения есть?

zinc pier
#

короче решить мог бы и сам

#

но походу решения нет

#

посмотрел график, даже пересечений нет

#

но на счет условия ничего сказать не могу, что есть пока, то есть

#

задание из подготовки для экзамена, списать ничего не пытаюсь

vale wigeon
#

ты где и как график строил

zinc pier
#

в онлайн калькуляторе

#

фотомаф

vale wigeon
#

и что он тебе выдал?

zinc pier
#

ну график без пересечений

#

нет пересечений = нет решения

vale wigeon
#

скрин есть?

zinc pier
#

ща

vale wigeon
#

а то десмос выдает не такой

#

а еще хорошо бы решить эту хрень алгебраически

zinc pier
#

ну да

#

можешь?))

vale wigeon
#

решается вполне себе, только надо некоторые нюансы с корнями

zinc pier
vale wigeon
#

не так ввел

#

там под первым корнем x + 2sqrt(x-1), а ты написал плюс

vale wigeon
zinc pier
#

я же все правильно ввел

vale wigeon
#

неа

#

а

#

стоп

#

я вру значит

zinc pier
#

все верно

vale wigeon
#

да-да, я неправильно прочла

zinc pier
vale wigeon
# zinc pier а чем тут занимаются

ну модельно помощь проводится так: у тебя спрашивают, в чем проблема (не можешь начать / застрял / ответ не тот / не понимаешь какое-то понятие и т.д.), а затем уже именно эта проблема прицельно лечится, чтобы ты мог сам задачу решить

#

короче да, ты прав, мн-во решений тут пусто

zinc pier
#

какое множество

vale wigeon
#

множество решений уравнения

#

или если просторечно, но нет их

#

таки все равно photomath'ом некошерно пользоваться

zinc pier
#

ну так а как я должен был понять то

alpine sable
#

Hi

#

Kindly help me in drawing graphs

alpine sable
#

Two questions

vale wigeon
#

this channel is occupied.

vale wigeon
# zinc pier ну так а как я должен был понять то

ну например можно начать с того, что одну корнюгу отнять с обеих частей: $$\sqrt{x + 2\sqrt{x+1}} = 2 - \sqrt{x - 2 \sqrt{x-1}}$$ потом возвести в квадрат, еще похимичить, и в конце концов свести к полиномиальному уравнению. здесь вроде бы всего 2-й степени будет, так что решится все

ocean sealBOT
vale wigeon
#

хотя может вылезти и четвертая степень. вот тогда будет грустно.

alpine sable
#

@vale wigeon how do i create one for myself

vale wigeon
#

!help

lone heartBOT
alpine sable
#

Channel

vale wigeon
#

@zinc pier что характерно, если бы вместо x+1 там было x-1 (как сначала подумала я), то уравнение было бы в разы приятнее. а сейчас мне мерещится какая-то жуть полнейшая.

zinc pier
vale wigeon
#

решить уравнение -- значит найти все его решения или убедиться, что таковых не существует

zinc pier
#

ну так мы убедились же что их нет

vale wigeon
#

пока еще нет

oak perch
#

Inside your second square root is a square , so your second square root =|sqrt(x-1)-1|. Since you are looking for the maximal solution we can now let it be (sqrt(x-1)-1). Then your question in the end becomes sqrt(x+1)+3sqrt(x-1)=4. Let t=x-1 this can become quadratic in terms of t

vale wigeon
#

там написано черным по белому, что решение (в смысле письменные вычисления) надо прикрепить

#

думаю, что за скриншот из photomath тебе влетит

zinc pier
#

да это просто пробник, его никуда не отправляю

#

я ж просто готовлюсь

#

ну и хз на счет прикрепление решений, в других заданиях протсо ответ например: х = 2

vale wigeon
#

не ну ладно, тогда просто надо написать "решений нет". я хз, как в твоей системе это сделать.

oak perch
#

Can’t understand what you are talking about. Are you saying it’s 2? Because I got 4+1/sqrt(2)

vale wigeon
#

and both photomath and desmos confirm it

oak perch
#

No solution? Okay I need to check my steps…

#

Oh indeed … sqrt(x-1)>=1 doesn’t work since x<=2, I had to take sqrt(x-1)<=1, then x+2sqrt(x+1)=(1+sqrt(x-1))^2
sqrt(x+1)=sqrt(x-1), no solution indeed…

zinc pier
#

ответ 2 правильный

#

Answer 2 is correct

vale wigeon
#

да ну?!

#

,calc sqrt(2 + 2 * sqrt(2 + 1)) + sqrt(2 - 2 * sqrt(2 - 1))

ocean sealBOT
#

Result:

2.3375417889607
oak perch
#

I checked 2 is not even a solution

vale wigeon
#

кажись, в условии опечатка.

zinc pier
#

ну это и так понятно было)

#

там минус на втором знаке

oak perch
#

Sum of two roots=2, so the first root<=2 right, so x<=2, meaning |sqrt(x-1)-1|=1-sqrt(x-1).

vale wigeon
zinc pier
vale wigeon
#

largest positive integer root.

oak perch
#

$$\sqrt{x+2\sqrt{x+1}}+|\sqrt{x-1}-1|=2$$
$$\sqrt{x+2\sqrt{x+1}}+1-\sqrt{x-1}=2$$
$$\sqrt{x+2\sqrt{x+1}}=1+\sqrt{x-1}$$
$$x+2\sqrt{x+1}=(1+\sqrt{x-1})^{2}=x+2\sqrt{x-1}$$
$$\sqrt{x+1}=\sqrt{x-1}$$
No solution

ocean sealBOT
#

Cogwheels of the mind

zinc pier
#

Ладно, рас уж мы закончили, всем спасибо) Я просто для друга решение искал, он не мог решить, а потом там оказывается кнопка проверить ответ была)

#

ну и ну нас третий друг математик сидел и сразу сказал что там ошибка в условии и если второй знак заменить, то выйдет 2

lone heartBOT
#

@zinc pier Has your question been resolved?

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near lion
lone heartBOT
near lion
#

Qn no 4

#

Need help

alpine sable
#

Answer will be D) I can explain in DMS if you want

near lion
#

Sure

somber eagle
#

!nosols

lone heartBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

near lion
#

Yes I have

#

I had tried but couldn't get the ans

pale kestrel
#

@alpine sable @near lion this server is not for giving solutions, and please do not offer to dm users.

#

For future reference

alpine sable
#

Then what should we do ?

#

I'm new so idk what to do I thought we are supposed to help them

pale kestrel
#

I believe

#

has some guidelines

#

uhhh

#

@real gazelle could u link up guidelines for helping people, not loading for me

real gazelle
#

!nosols

#

Bot seems to be slow today

#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

pale kestrel
#

The goal of any helper should be to enable the helpee understand how to do a similar problem, so they don't come back again with it.

real gazelle
#

No worries, now you know!

lone heartBOT
#

@near lion Has your question been resolved?

near lion
#

No

lone heartBOT
#

@near lion Has your question been resolved?

#
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potent quiver
#

Find h

lone heartBOT
potent quiver
#

angles are 15 and 18

#

i got 1.24 but im not sure if im correct and theres no answers

lethal belfry
#

don't you need some side elngths to find h?

potent quiver
#

this is my working out

lethal belfry
#

Ah, AB=6?

potent quiver
oak perch
#

(h/tan(15 degrees))^2+(h/tan(18 degrees)^2=36

#

Oh you got that already

oak perch
potent quiver
#

its supposed to be a triangualr pyyramid

#

oh ok

#

thx

#

.close

lone heartBOT
#
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quick laurel
#

I am looking for a quick sanity check. I did work breaking down the vectors into their components, but I cannot figure out why this is wrong.

quick laurel
#

I drew out the vectors as well. My assumption is that I misinterpreted the direction of the wind vector.

#

Alas, nothing else make sense to me at the moment

#

Reading the given information, the vector of wind is "S 30(deg) E at a speed of 37mph"

lone heartBOT
#

@quick laurel Has your question been resolved?

tardy stag
#

S30°E would be mostly south

#

like S1°E would be almost entirely south but just a smidge east

quick laurel
#

that makes sense, I did actaully get to that point and attempt it using 60(deg) from the x axis

#

and it still didnt work

tardy stag
#

would be -60°

quick laurel
#

This is what I have mathwise

#

So for the wind vector I have, 37cos(-60)i - 37sin(-60)j

#

and combining the two vectors gives me 131.637i + 145.18j

#

which apparently isn't the correct answer

tardy stag
#

why combine them yet? it looks like you just need the wind vector itseld

quick laurel
#

Because, I had only 5 attempts at that portion and I can no longer change it

#

and It did not give me the correct answer (annoyingly)

tardy stag
quick laurel
#

Isn't the direction of the vector in the y direction negative

#

since it points S

#

therefore, the j component is negative?

tardy stag
#

yeah but the sin(-30) already does that for you

lone heartBOT
#

@quick laurel Has your question been resolved?

lone heartBOT
#
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steep drift
#

am stuck

lone heartBOT
steep drift
#

the answer is 13-4cos^6

#

<@&286206848099549185>

lone heartBOT
#

@steep drift Has your question been resolved?

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remote heron
#

@lapis stream

lone heartBOT
remote heron
#
It is a limits question```
lapis stream
#

Is c=16-4t-0.25t^2 then plug two into t?

lapis stream
#

It probably doesn't work because you can't solve a quad equation when it equals anything other than zero

remote heron
#

this is your teachers work? they dont write very well

#

whats the left hand limit of B?

lapis stream
#

4-0.5t?

#

the other is sqrt(t+c)

remote heron
#

why is t still there

#

the limit is along t

#

think of it like if i gave you f(x) and asked you what the value of f is at x=4

#

and you told me x+6

#

that doesnt make sense

#

f(4) cant be something involving x

#

4 replaces x

#

its kinda the same with a limit

#

if it exists

lapis stream
#

He just equaled the two sides then plugged two

remote heron
#

he evaluated the limit

remote heron
#

whats the left hand limit?

#

$\lim _{t \to 2 ^-} \qty( 4-\frac 12 t ) = ?$

ocean sealBOT
#

jan Niku

lapis stream
#

I think I understand teach’s logic now

#

What is it you find weird

remote heron
#

dont worry about me lol

#

as long as you understand it and can get the answer thats all that matters

lapis stream
#

I think that I can close this now

#

.close

#

Oh u are the one who can open and close channels

remote heron
#

.close

lone heartBOT
#
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remote heron
lone heartBOT
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mellow skiff
#

Trying to understand graf (1/2)^x

lone heartBOT
mellow skiff
#

Compared to 3^x

#

1/2 goes the opposite way, whys that

vale wigeon
#

well if you raise 1/2 to higher and higher powers you get smaller and smaller numbers don't you

mellow skiff
#

No

#

You get higher y

young finch
#

cause its 1/((2)^x)

#

denominator gets bigger

#

makes a smaller value overall

tardy stag
#

what's (½)³?

mellow skiff
#

3/6

#

1/3

young finch
#

..

mellow skiff
young finch
#

do you know what an exponent is

mellow skiff
#

Im tryna understand why it goes opposite way

tardy stag
#

do you know what an exponent is?

young finch
#

you need to know what an exponent is first

mellow skiff
#

Yeah ofc

young finch
#

whats 2^3

mellow skiff
#

Its a polynom with a positive realla number as bas with a exponent

mellow skiff
young finch
mellow skiff
#

8

young finch
#

do you know property of exponents then

mellow skiff
#

Can u give example

young finch
#

(1/2)^3

#

1^3/2^3

mellow skiff
#

Oh

young finch
#

@tardy stag can you send exponent properties sheet

#

idk command

mellow skiff
#

No i know already

tardy stag
#

,tex .exp rules

ocean sealBOT
#

hayley!

mellow skiff
#

I was thinking diffrently

#

A bit lost there

#

I was thinking with a diffrent question

young finch
#

so does it make sense 1/2^x decreases

mellow skiff
#

I understand but i dont understand why y is negative

young finch
#

y isn't negative

mellow skiff
#

In a graf

young finch
#

,w graph 1/2^x

young finch
#

it asymptotes at 0

mellow skiff
#

Yeah you see that it goes left

young finch
#

,w compute 1/2^999

young finch
#

large values of x give a very small but positive result

mellow skiff
#

,w graph 1/2^9999

young finch
#

essentially y=0

mellow skiff
#

What

young finch
#

it's a line

mellow skiff
#

I feel dumb why does it go that way

young finch
#

you just graphed a straight line

mellow skiff
#

Yeah?

#

So

#

1/2^x

#

The higher number of x, the more away I am from 1

young finch
#

what's 1

mellow skiff
#

1 should be it’s y

young finch
#

x=1?

mellow skiff
#

x=0

young finch
#

then whats 1

#

what is its y

#

y only equals 1 when x=0

mellow skiff
#

1^0/ 2^0

#

1/1

#

1

young finch
#

what's that have anything to do with this

mellow skiff
#

Because that’s the function

#

Y=1

young finch
#

and youre asking why it decreases as x increases

mellow skiff
#

No I’m thinking more like at the grap

#

Graf

young finch
#

graph

mellow skiff
#

Because when I look at the graph

#

I see there is a difference

young finch
#

between what

mellow skiff
#

Between 2^x

young finch
#

and 1/2^x

#

?

mellow skiff
#

Yeah

young finch
#

obviously

mellow skiff
#

Why’s that I just don’t get it

young finch
#

1/2^x is just 2^-x

mellow skiff
#

Oh shoot

young finch
#

you would know this if you knew exponent rules

mellow skiff
#

I know that

#

But

#

w, graph 2^-3

#

,w graph 2^-3

mellow skiff
#

Why is that so

young finch
#

look at the scale

#

small value

mellow skiff
#

Is it too minuscule?

young finch
#

minuscule?

mellow skiff
#

,w graph 2^-55

young finch
#

small value

#

super small value

mellow skiff
#

Why is it a straight line

young finch
#

cause you graphed y=2^-55

mellow skiff
#

w, graph 2^-2

#

,w graph 2^-2

young finch
#

not a zoom in of y=1/2^x at a certain value of x

mellow skiff
#

Oh

#

,w graph 1/3^x

young finch
#

,w graph y=2

mellow skiff
#

Is it going to left because

#

The exponential is negative and the base get higher up to y when base is higher

#

,w graph -2^-x

mellow skiff
#

Now why is y=-1

#

.close

lone heartBOT
#
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alpine sable
#

What does Instantaneous Velocity mean?

lone heartBOT
whole shell
#

instantaneous velocity is the velocity at one specific point in time

alpine sable
#

Is it calculated in real time?

tardy stag
#

speedometer

alpine sable
#

So technically it’s impossible to calculate instantaneous velocity

tribal valve
#

no

#

its possible

whole shell
#

you can still get very close

alpine sable
#

So how would you get instantaneous velocity?

#

Is there like a specific formula

tribal valve
whole shell
#

distance travelled / time taken is the basic way

#

as shown ^

winter light
tribal valve
#

yeah i just realized

winter light
#

And it should be with vectors but yeah that's the definition of derivative

alpine sable
whole shell
#

yes

tribal valve
#

this is better

whole shell
#

but if you take average velocity

#

over a very small time frame

#

that becomes closer to instantaneous

alpine sable
#

I’m pretty confused what’s the difference between Instantaneous Velocity and Average Velocity?

whole shell
#

velocity

winter light
#

In other words, instantaneous velocity is the first derivative of position @alpine sable

tribal valve
#

thats a good way to put it

winter light
#

If you know what derivatives are of course

#

Otherwise it's more difficult

tribal valve
#

basically just take a super close point to the right and to the left and find velocity between them

whole shell
#

its not possible to actually measure this over literally 0s time, but you can get close by measuring over 0.01s time or something

alpine sable
#

Previous data

winter light
#

You obtain numerical approximations yes

#

Of course not exact value

alpine sable
#

Interesting

whole shell
#

in real liffe though

#

youd use a radar gun

#

which measures the doppler effect

winter light
#

Wow interesting

whole shell
#

unfortunately quite literally everything you measure has a delay

#

because of the speed of causality

winter light
whole shell
#

so youd be measuring the instantaneous velocity of however long it took the light to go from your radar gun to the object and vice versa

alpine sable
#

I could view it as a way of getting the exact velocity within a given set of distance precisely

#

Which is practically impossible

#

But you can still get very close

#

Am I right?

#

Also @whole shell @winter light thanks for helping me

#

If there’s anything I can do in return tell me

whole shell
alpine sable
#

Right?

alpine sable
#

Ok thanks

whole shell
#

also not just accurately though

#

like even if yourr radar gun has 100% precision

#

youll only ever measure the velocity the object had a little while ago (well the time is very very very small, but it is a small lag)

#

so you can never measure it in "real time"

alpine sable
#

Okay

#

Thanks

whole shell
#

@alpine sable if you were measuring the speed of a planet 5 light years away from you

#

youd be measuring the speed it had 5 years ago

alpine sable
#

That’s a pretty good way of putting it

#

That makes sense

#

Isn’t calculating average velocity the same then?

#

Because

#

Average velocity isng 100% accurate too

whole shell
#

we have 2 seperate problems

#

the fact that we cant get this accurate velocity to be instantaneous

#

because we cant measure in 0 time

#

and the fact that anything we do measure is from the past

whole shell
#

thats just how life is

#

but other than those 2 issues that you will never really feel

#

yes

#

youll be very close

#

to the answer you want

#

as in your velocity in real time

alpine sable
whole shell
#

but the time delay issue doesnt work here, since average velocity already refers to something in the past

alpine sable
#

Okay thank you for your help it’s very much appreciated

#

@whole shell what song do you like?

#

I’ll play it for you in return

whole shell
#

wdym

alpine sable
#

I play piano for anyone that helps me solve a problem

#

Of their specific song choice

whole shell
#

rush e abitoftroll

alpine sable
#

I’ll try

whole shell
#

@alpine sable i was joking, the actual song would be twinkle twinkle little star, specifically variation 1

#

timestamped

#

once you see rush E youll know why i did the troll face

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

but thanks for the help

#

.close

lone heartBOT
#
Channel closed

Closed by @wintry garnet

Use .reopen if this was a mistake.

#
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Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

alpine sable
#

Ask the employee at the gun range

tribal valve
#

bro

#

don't do it

alpine sable
#

what country?

dull dove
#

<@&268886789983436800>

#

<@&268886789983436800>

#

Oops

#

Mistake my bad

night geyser
#

.clsoe

#

.close

lone heartBOT
#
Channel closed

Closed by @night geyser

Use .reopen if this was a mistake.

alpine sable
#

HUH Wtf mods

#

Didn't even give them the hotline number

#

183

dull dove
#

Why are you entertaining the behavior

somber eagle
#

no way bro is coaching LoL for $20 an hour

#

wtf

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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#
Channel closed

Closed due to the original message being deleted

alpine sable
#

.close

#

.close

lone heartBOT
#
Available help channel!

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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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tribal valve
#

(a) Prove that if the roots of
[x^3 + ax^2 + bx + c = 0]form an arithmetic sequence, then $2a^3 + 27c = 9ab.$

(b) Prove that if $2a^3 + 27c = 9ab,$ then the roots of
[x^3 + ax^2 + bx + c = 0]form an arithmetic sequence.

ocean sealBOT
#

dabbingpotato

tribal valve
#

Roots are z-r, z, z+r

#

$(x-(z-r))(x-z)(x-(z+r)) = \x^3-(z-r)x^2-zx^2+(z-r)zx-(z+r)x^2+(z-r)(z+r)x+(z+r)zx-(z-r)z(z+r)$

tardy stag
#

\\ for newline

ocean sealBOT
#

dabbingpotato

tribal valve
#

Now we use vietas?

#

a = -3z

#

b = 3z^2 - r^2

#

c = - z^3 + zr^2

#

am i on the right track?

tardy stag
tribal valve
#

z^2 - rz + z^2 - r^2 + z^2 + zr

#

3z^2 - r^2

#

Now we substitute those values into $2a^3 + 27c = 9ab$?

ocean sealBOT
#

dabbingpotato

tardy stag
#

yep

tribal valve
#

$-54z^3 + 27zr^2 - 27z^3 = -81z^3 + 27zr^2$

ocean sealBOT
#

dabbingpotato

tribal valve
#

is that right?

#

Okay so now part b)

#

We know that this is true, so how can we use this to know that the roots form an arithmetic sequence?

oak perch
#

Prove that if they don’t form an arithmetic sequence then 2a^3+27c doesn’t equal 9ab

#

This time three roots are z-r, z, z+s where r-s is not zero

tribal valve
oak perch
#

P->Q is equivalent to (not Q)->(not P)

#

Show 2(3z+s-r)^3+27(z^3+(s-r)z^2-rsz) doesn’t equal 9(3z+s-r)(3z^2+(2s-2r)z-rs)
When r-s is not zero

tribal valve
#

That doesn't prove B tho

#

Just because when 2a^3 + 27c doesn't equal 9ab doesn't form an arithmetic sequence

#

That doesn't mean that when 2a^3 + 27c is equal to 9ab always has to form an arithmetic sequence

oak perch
#

P: 2a^3+27c=9ab Q : form an arithmetic…

#

P->Q is equivalent to (not Q)->(not P)

#

Not Q: they don’t form an arithmetic sequence
Not P: 2a^3+27c doesn’t equal 9ab

tribal valve
oak perch
#

Logic

#

High school stuff

tribal valve
#

what is logic

oak perch
#

Google

tribal valve
#

can you give me another example of when this works

oak perch
#

x is an integer-> x is a rational number

#

x is not a rational number-> x is not an integer

tribal valve
#

x is a square -> x is a rectangle

#

x is not a square -> x is not a rectangle

oak perch
#

No

tribal valve
#

isn't that a contradiction

oak perch
#

x is not a rectangle-> x is not a square

#

P->Q equivalent to (not Q)->(not P)

tribal valve
#

oh

#

okay i guess that works

#

$2(3z+s-r)^3+27(z^3+(s-r)z^2-rsz) = 9(3z+s-r)(3z^2+(2s-2r)z-rs)$

ocean sealBOT
#

dabbingpotato

tribal valve
#

pain

oak perch
#

Yeah

#

Not equal to

tribal valve
#

okay so we use vietas again?

oak perch
#

Not equal to

tribal valve
oak perch
#

-a=3z+s-r
b=… -c=…

#

Just like part a

tribal valve
#

so veitas

oak perch
#

Yeah

#

So in the end it becomes proving 2(s-r)^3 doesn’t equal -9rs(s-r)

#

When s-r doesn’t equal 0. Obvious

tribal valve
#

okay

#

is this right for the vietas?

#

$a = - 3z + r - s$
$b = 3z^2 - 2rz + 2sz - rs$
$c = z^3 + z^2r + rzs - sz^2$

ocean sealBOT
#

dabbingpotato

tribal valve
oak perch
#

I replace a with -a, c with -c

#

It doesn’t matter

oak perch
#

-z^3+…

#

Other terms are correct

tribal valve
#

crap

#

good catch

tribal valve
oak perch
#

Coefficients of z^3,z^2,z are equal respectively

#

Only the constant term of LHS doesn’t equal the constant term of RHS left

#

Which is proving 2r^2+2s^2+5rs doesn’t equal 0 when s doesn’t equal r

tribal valve
#

is $2r^2+2s^2+5rs \neq 0$ just on one side $2(s-r)^3 \neq -9rs(s-r)$

ocean sealBOT
#

dabbingpotato