And yes, you can
#help-0
carmine reef
eternal tulip
edgy gull
how does it transition from the 1st step to 2nd step?
lone heartBOT
how does it transition from the 1st step to 2nd step?
edgy gull
even with integration by parts
carmine reef
u = 300+t, v = cos(t)
magic tartan
lone heartBOT
gray isle
show work
magic tartan
tacit arch
On the right track
tacit arch
Should write out p(k) explicitly
Then algebraically get p(k) in your p(k+1) expression. Your last line is close
Or second to last line
Don't distribute the 7 quite yet
magic tartan
mm
damn still confused
kinda seem to have
reverted to the same mistake
cant seem to find whats wrong
oak perch
You want to prove 9|a_(k+1), you just need to prove 9| a_(k+1)-a_k
Which is (3k+4)7^(k+1)-(3k+1)7^k=7^k(21k+28-3k-1)=7^k(18k+27)
lone heartBOT
@magic tartan Has your question been resolved?
magic tartan
You want to prove 9|a_(k+1), you just need to prove 9| a_(k+1)-a_k
im not sure i understand
oak perch
9 | a_k Is the condition
Say a_k=a, a_(k+1)=b
9| a is the condition
Then 9|b if and only if 9|(b-a)
So you only need to show that 9|(b-a). And I have already written the steps already
9|18 and 27
magic tartan
.close
blissful mortar
I am not sure how to solve this.
lone heartBOT
I am not sure how to solve this.
sonic ridge
do you know what the sine ratio is?
blissful mortar
Like SohCahToa?
sonic ridge
yeah
blissful mortar
So opposite/hypotenuse
sonic ridge
yup
now determine what the opposite side to theta is
and what side is the hypotenuse
wary stream
Yes
wary stream
So opposite/hypotenuse
Now make the ratio based on this
blissful mortar
But we do not have any numbers how do I solve it?
Its AC/AB
But there are no numbers
wary stream
You don't need numbers
blissful mortar
I put AC/AB it says it is wrong
wary stream
Did you type in AC/AB exactly?
blissful mortar
One second.
grave island
lol
wary stream
Did you notice the tool bar on the bottom? There's a fraction button, use that if you didn't
blissful mortar
I just forgot that its case sensitive.
I did no put it make it caps.
It worked now
grave island
Bro I told you that stop acting smart bud.
ty
lethal belfry
I know this question is kind of stupid, but what does this notation mean
lethal belfry
,rotate
ocean sealBOT
ocean sealBOT
dusk moth
Summation
tardy tapir
summation
lethal belfry
Yeah, but the product is confusing me
oak perch
There is no product
lethal belfry
So summation of the I terms into the summation of the j terms?
tardy tapir
no
alpine sable
It's iterated
tardy tapir
the variables are different
alpine sable
Not multiplied
oak perch
(To solve this problem you divide the square [1,10] times [1,10] into two parts cut by y=x BTW)
lethal belfry
(To solve this problem you divide the square [1,10] times [1,10] into two parts ...
Ok, thanks
.close
weary grail
i am completely stuck on how to even start on part c)
lone heartBOT
i am completely stuck on how to even start on part c)
weary grail
for a) would P(N=n) = p^n * (1-p)
because we need to make sure that the next question answered is incorrect
for c), using the hint, I assume they want me to use this expression for P(Y=k)
lone heartBOT
@weary grail Has your question been resolved?
lone heartBOT
weary grail
.reopen
lone heartBOT
✅
lone heartBOT
@weary grail Has your question been resolved?
@weary grail Has your question been resolved?
lone heartBOT
@weary grail Has your question been resolved?
tacit arch
for a) would P(N=n) = p^n * (1-p)
Show your work for a and b
lone heartBOT
lone heartBOT
Available help channel!
alpine sable
ok so i have 3 sliders that i can drag to select a number. They all go thru 1-4 how many combinations could there be?
carmine reef
would you know how to solve if there were 2 sliders
alpine sable
would you know how to solve if there were 2 sliders
not wihtout writing every one out lol
carmine reef
11 12 13 14 21 22 23 24 31 32 33 34 41 42 43 44
Is there any kind of structure here
alpine sable
yuh
carmine reef
Could you maybe write it as a table
alpine sable
got example?
carmine reef
11 12 13 14
21 22 23 24
31 32 33 34
41 42 43 44
Kind of like one of those number chart things
so how do we find the number of possibilities without counting them all 1 by 1
maiden glen
the slider goes from 1 to 4, so you shouldn't have zeros there
and we're trying to find a simpler way to find the possibilities without having to list them all like that
maiden glen
yes
alpine sable
hmm im being told multiple things from dif people
my dad said same thign as u
but chatgpt saying 64
looks right aswell idk
maiden glen
4 * 4 * 4 is 64
tacit arch
but chatgpt saying 64
Don't use chatgpt for math
alpine sable
Don't use chatgpt for math
i think its right
tacit arch
A broken clock is right twice a day
alpine sable
wouldnt it be once day
cuz then its night
lul
but thanks for help fr fr
how do i mark it as resolved or whatever
tacit arch
Do .close
alpine sable
cuz then its night
7am 7pm
maiden glen
do .close
alpine sable
.close
rotund crater
the derivative is the tangent line?
lone heartBOT
the derivative is the tangent line?
mental flame
the derivative is a formula for the slope of the tangent line on f(x) at a given point, x.
rotund crater
gpt chat told me that the derivative is not the tangent line but an extension that gives information about a given point on a graph.
mental flame
you shouldn't use chat gpt for math, but it is correct about the derivative not being the tangent line. you can however use the derivative to find the tangent line of a graph
lone heartBOT
mental flame
np
lone heartBOT
Available help channel!
rustic coral
det(B^3) = det(B)det(B)det(B)?
lone heartBOT
lone heartBOT
✅
alpine sable
is the answer $5 \cdot 3 \cdot \frac{1}{9} (-\frac{1}{2}) \cdot (-8)$?
ocean sealBOT
kyou
pallid scarab
👍
lone heartBOT
@alpine sable Has your question been resolved?
lone heartBOT
lone heartBOT
Available help channel!
vapid shuttle
lone heartBOT
vapid shuttle
is a kilogram really a "mass"
or do I still need to divide by gravity
the weight is 2 kilograms
so do I divide by 9.8, to find the mass?
vapid shuttle
So
the equation for free damped motion
$$\frac{d^{2}x}{dt^2}+\frac{\beta}{m}\frac{dx}{dt}+\frac{k}{m}x=0$$
ocean sealBOT
Austin
vapid shuttle
beta is the damping constant
m is the mass
so m=2 ?
and k is the spring constant
so k=32
no damping is present
so beta=0
Is all of this a correct interpretation of the scenario?
worn fox
yes then you just recover the SHM equation for a spring
worn fox
simple harmonic motion
vapid shuttle
are kilograms not a measurement of weight on earth?
I am confused because if it was something like
8 lbs
then in this equation
I would use
8/32
as the mass
but it is kilograms
worn fox
colloquial language would use weight
vapid shuttle
So, we are sure though that in this scenario I need not divide by gravity?
maiden glen
when you measure yourself on a scale, it's really measuring the force of gravity, then doing the conversion into mass
worn fox
its bc the scales really are measuring your weight but then accounting for gravity to give you your mass
vapid shuttle
why is this different than if it was pounds?
maiden glen
in this question, it's given to be mass
worn fox
wow desync we really are, in sync
maiden glen
😭
worn fox
every equation involving mass is expecting a value in kilograms
vapid shuttle
what if it uses slugs
vapid shuttle
this is adding to the confusion Shuri
pale kestrel
what if it uses slugs
is this not a joke 
vapid shuttle
no
slugs are a unit of mass
I think?
or of weight
I just found them in one of these problems
I had to google it
pale kestrel
vapid shuttle
yesthat
pale kestrel
sorry, I thought you were joking and done
pale kestrel
every equation involving mass is expecting a value in kilograms
Did this make sense
vapid shuttle
no
pale kestrel
its just like every calculus thingy
involving trig functions
is in radians
not degrees.
In a similar fashion.
There are some equations which do not work for arbitrary units of mass.
vapid shuttle
so mass is kilograms?
worn fox
so slugs is a measurement of mass
pale kestrel
(idk which ones)
pale kestrel
so mass is kilograms?
kg is SI unit for mass
worn fox
and you could put them in the equations, i misspoke earlier
but we have standard units for a reason
pale kestrel
and you could put them in the equations, i misspoke earlier
Would it not fail for some thonk
vapid shuttle
If mass is kilograms, and kilograms are like 2.2x lbs, then how come something with like 100lbs is said to be a mass of 100/32 instead of 100*2.2 ?
pale kestrel
it would be 100/2.2 kg right?
vapid shuttle
no that is not what I have been using for all of these
my textbook tells me that if I am given a weight in pounds
I divide it be 32 (gravity)
to find the mass
it says M=W/G
maiden glen
it's a weight in pounds, so it's 100 pounds of force, not 100 pounds of mass
maiden glen
the problem is that "lb" is sometimes used to refer to both mass and weight
vapid shuttle
okay but wtf is this then because is this a weight in kilograms or a mass in kilograms?
maiden glen
but kg should always be mass, and newtons for force
when people say they weight X kg, it's a colloquialism
vapid shuttle
but don't british people use kilograms as weight
maiden glen
yes, but that's because we're used to being on earth's gravity
so mass is proportional to weight
pale kestrel
worn fox
here you have two separate things both called pounds
pale kestrel
my textbook tells me that if I am given a weight in pounds
a weight in pound-force, I believe.
and in ft/s^2 is where 32 comes from...
vapid shuttle
see this is why I was thinking to divide by 9.8
for meters instead of feet
because kilograms instead of lbs
pale kestrel
if your entire question works in metric units
(or SI units)
then yeah, g = 9.8 m/s^2 makes sense
One thing that could clear up confusion is writing down the units for all quantities
and like this for equations
(they should match on both sides)
vapid shuttle
then yeah, g = 9.8 m/s^2 makes sense
so, let me ask something here. if g=9.8m/s^2, and I am given a weight in kilograms, do I divide by 9.8
as opposed to I am given a mass in kilograms here so I don't divide
maiden glen
yes
but in a maths question
you shouldn't really be given weights in kg
only newtons
pale kestrel
so, let me ask something here. if g=9.8m/s^2, and I am given a *weight* in kilog...
weight aint in kg
vapid shuttle
bruh
maiden glen
the problem is imperial doesn't have a separate unit for force
it just reuses (the amount of force required to move x) pounds
pale kestrel
In natural language/everyday speak, we talk about our 'weight', but we mean our mass.
vapid shuttle
our weight is our mass times gravity
pale kestrel
vapid shuttle
this is physics right?
pale kestrel
that bottom equation with units hopefully makes some sense
worn fox
lol right now this is just unitsofmeasurementology
worn fox
cant handle the pressure
vapid shuttle
yeah okay I don't understand but that's okay because I'm not @limpid turret and I don't need to know physics
I just wont divide
I can solve the quesiton
lol
thanks though Shuri and ZAC and Desync
pale kestrel
well its absolutely cursed to take this shit and involve imperial units
vapid shuttle
what is cursed
maiden glen
mfw slug is a unit
pale kestrel
slugs...
vapid shuttle
me or the question
worn fox
honestly i ignored you mentioning slugs everytime bc i thought you were joking
pale kestrel
lmao none of us knew
vapid shuttle
bro I was so confused when I read slugs in my questions for the first time
I hate this kind of thing it is so dumb
pale kestrel
excuse me for meming earlier...
vapid shuttle
no worries lol
if I have the equation I can solve and interpret it
but if I have to like disect slugs and mass and weight or whatever
to make the equation
I just would rather die
anyways
ty everyone
.close
plush valve
i need help
lone heartBOT
i need help
plush valve
really badly
vapid shuttle
plush valve
I need to figure out the y coordinate of the vertex using only this information
here is my answer so far "We have no graph, so we can assume that the x intercepts of the 50 yard hill are 0, and 50. Therefore, the axis of symmetry is 25. The parabola is also a negative as it's going down."
(this is algebra btw)
is there a way i can plug in the x intercepts and axis of symmetry into an equation then find the y coordinate of the vertex?
im pretty sure there isnt enough information, but i still need to come up with an answer somehow
here is what my teacher said
"That's a great start!! So if the x-intercepts are 0 and 50, how would you write an equation in factored form?
Do the same for the second one - act as if that parabola is starting at (0, 0). What are the x-intercepts?"
<@&286206848099549185>
lone heartBOT
@plush valve Has your question been resolved?
scarlet tendon
34x - 16x divided by 189x
maiden glen
here is what my teacher said
"That's a great start!! So if the x-intercepts are...
I agree that there isn't enough information
I'd probably have just used the 50 yards and 25 yards measuring lines and estimate the heights from that
but from that response, it looks like they want something like -x(x-50) to match the x-intercepts
but that gives an absurdly high peak, so add in some scaling or something
not a great question either way imo
maiden glen
34x - 16x divided by 189x
also #❓how-to-get-help
scarlet tendon
?
lone heartBOT
@plush valve Has your question been resolved?
lone heartBOT
lone heartBOT
Available help channel!
iron orbit
Consider a regular n-sided polygon with vertices P_1P_2P_3...P_n. Let a, b, c be distinct numbers in range 1 to n inclusive with a < c. Find the size of angle P_aP_bP_c in terms of a, b, c and n.
iron orbit
i currently found a solution for the case that a, b, c are consecutive
i don't know how to procede after that
sorry about help-17, i accidentally clicked a key in there
<@&286206848099549185>
.close
oak pelican
apparently 7.5>x isn't true? Do you have to check if the inequality is true every time you solve for one?
wary stream
apparently 7.5>x isn't true? Do you have to check if the inequality is true ever...
Ideally yes, to find extraneous solutions
oak pelican
Ideally yes, to find extraneous solutions
uhh ok... So like do I have to check for basic ones where there is only x on one side of the equation (like |7x+9|>30)
lone heartBOT
@oak pelican Has your question been resolved?
alpine sable
Given the 2 end points from the diameter of a circle is (4,-10) and (-2,-3), put it into standard form.
(x - h)^2 + (y - k)^2 = r^2
so I calculated the distance between the two points and divided both axis by two and found the hypothenus, problem's that its the radius length, I seem to be having trouble finding the points which the origin would have to be in
gray isle
consider the relation between the centre of a circle and its diameteres
alpine sable
I was thinking of adding the halved distance from one of the initial points from the diameter
alpine sable
im not sure which word you're looking for tho
gray isle
given that green line is a diameter, can you indicate the location of the centre?
alpine sable
diameter divided by 2
gray isle
distance isn't a point
alpine sable
yeah that was my initial problem, what I thought was, since I know my initial points and I'm able to divide the distance in the x and y axis
gray isle
like mark it on the diagram,
alpine sable
I would just add them from one of the points
gray isle
and tell me the reasoning why you marked it in that specific location
left isle
i see what you're saying. say the diameter is 4, which means the radius is 2, so you go 2 units in the direction of the "line" passing through the two points to find the center
starting at one point and headed to the other
gray isle
(don't worry about doing any calculations for distance for what i'm asking)
alpine sable
alpine sable
i see what you're saying. say the diameter is 4, which means the radius is 2, so...
yeah
gray isle
and tell me the reasoning why you marked it in that specific location
alpine sable
> and tell me the reasoning why you marked it in that specific location
given between a line such that there are two equal lines in between, you wouldve found the center
alpine sable
there's an easier way is what ram is trying to tell you
that I do not see, although im curious
gray isle
that was it
midpoint
the centre is halfway between the end points of the diameter
thus you can apply the midpoint formula
alpine sable
ohh
gray isle
you could utilise the triangle you drew above, which is essentially what the midpoint formula does
alpine sable
hate to break it, its the first time ive heard of it
so that would lead to the center point of it in a plane then?
gray isle
yes
alpine sable
thanks
I have another situation which im just experimenting on for myself
given that I know one of the points within
(x-h)^2 + (y-k)^2 = r^2
and lets say
(-2-h)^2 + (-3-k)^2 = (4.09)^2
is it possible to find the h and k here?
deriving from that with algebraic properties I mean
gray isle
no
dapper lynx
Hey all! Quick question
lone heartBOT
Hey all! Quick question
dapper lynx
Part (a) - to be clear
It wants me to go FROM the nice little 1x1 square that is E
TO the triangle that is T, right?
How do I handle going from a region with four boundaries to a region with three?
alpine sable
thats the same as having the area between u = 1 and v = 1
lone heartBOT
Available help channel!
alpine sable
x + y = u, y - x = v or viceversa, you would have to try
lone heartBOT
x + y = u, y - x = v or viceversa, you would have to try
alpine sable
.close
meager dirge
I'm differentiating to find the equation of the tangent to the curve.
But I don't understand this step at the moment.
How did 2xsqrt(x) become 2xsqrt(x) 2sqrt(x) all over 2sqrt(x)
vapid shuttle
they multiplied by 2sqrt(x)/2sqrt(x)
which is just multipication by 1
and thus leaves the expression unchanged
meager dirge
Oh!
vapid shuttle
(unless x=0)
vapid shuttle
@median oar
icy violet
How do I even start this question
lone heartBOT
How do I even start this question
vapid shuttle
@median oar
paper mango
@icy violet hellu?
icy violet
<@244390699431100416>
Yea e
icy violet
<@585756159169003543> hellu?
Yea E
paper mango
Yea E
k how far are you aorn
or do you know how to calculate the vertical distance between two functions at any x?
icy violet
k how far are you aorn
I don’t really know anything in this question yet…
paper mango
I don’t really know anything in this question yet…
k, well you can start by creating a function that calculates the distance
which would be distance(x) = |g(x)-f(x)|
the absolute value of their difference
icy violet
Ok
paper mango
therefore distance(x) = |ax²-x|
icy violet
Is that the line
icy violet
Yea
paper mango
k, now we want to know the maximum distance right
between 0 & 1/a
what could you do to find it
icy violet
Uhh no clue yet..
icy violet
what could you do to find it
Differentiate?
paper mango
yup!
because if we find the maximum points of the function within that interval
we can find out the maximum value of the distance function between that interval
@icy violet now, there is the annoying part of the function having an absolute value
icy violet
I2ax-1I?
icy violet
So this question has nothing to do with kinematic
paper mango
when distance'(x)=0
icy violet
when distance'(x)=0
Yea I get that
paper mango
So this question has nothing to do with kinematic
uh not really I suppose
except you already have specific memorized formulas for this kind of question
but it wouldn't take long to solve otherwise either
icy violet
To solve for x do we do anything with the a or no
paper mango
To solve for x do we do anything with the a or no
consider a a constant no
icy violet
I haven’t learn how to solve between absolute values
paper mango
I2ax-1I?
oh wait I think this property of differentiation isn't true
solving for absolute values is fairly easy
since you just have to also consider the negative option
e.g. |5x+1| = 2
then either 5x+1 = 2 or -(5x+1) = 2
therefore x = 1/5 or -3/5
icy violet
distance'(x) = |2ax-1|
Is this formula wrong?
paper mango
Is this formula wrong?
yeah thinking about it we have to do two differentiations I think
to first get rid of the absolute value
so distance(x) = |ax²-x|
first case: distance(x) = ax²-x
then distance'(x) = 2ax-1
second case: distance(x) = -ax²+x
then distance'(x) = -2ax+1
hm it holds true here but I'm not sure if it does generally
paper mango
yes
same procedure
I'll briefly check if the f'(x) = |[...]'| works
no it doesn't
since the absolute value can decline of course
icy violet
When I solved both I got 1/2a
paper mango
yep, which means there is a maximum at 1/2a
well we can take the third derivative
and see that it decreases
therefore it's a maximum
icy violet
But it says to show its 1/4a
paper mango
yes you only found the x value
icy violet
Oh
icy violet
I get it lol
When u first looked at that question did u think it looked straight foward?
icy violet
I’m doing this in grade 11 and this is a scholarship question or paper
And like another question was
But we don’t have to do that
paper mango
And like another question was
it's a neat one though :)
lone heartBOT
paper mango
I think depending on how motivatingly it's taught the progress is faster and thereby the questions can be regarded easier quickly
@icy violet btw rest is just inserting in distance in case it's not clear
|ax²-x| -> |1/4a - 1/2a| = |-1/4a| = 1/4a
lone heartBOT
Available help channel!
icy violet
|ax²-x| -> |1/4a - 1/2a| = |-1/4a| = 1/4a
Yea I knew
lone heartBOT
Yea I knew
icy violet
.close
lone heartBOT
tacit arch
What's trial 1
paper mango
@vivid heath ?
paper mango
well you're given p_total
and have to show that it remains the same before and after
with p = m*v
since there are two objects here:
p_total = m1*v1 + m2*v2
vivid heath
okay allow me to try that!
paper mango
yup
twin nimbus
But ummm... The numbers don't work out seemingly?
twin nimbus
Ah, that makes significantly more sense
vivid heath
it was im sorry!
vale wigeon
such a mishap would not have happened if the author of the problem was not allergic to equals signs
paper mango
vivid heath
so i did get 3.0 m/s from that equation so that checks out!
im gonna try to run the simulation again and see why that first ones after collision hit is wrong
when it says after collision is that as soon as the two bodies collide?
vale wigeon
it's immediately after the two bodies collide
vivid heath
that super helpful
so thats alot more accurate i believe! haha
well thank you everyone!
.close
molten knot
lone heartBOT
tacit arch
,w int sin(x^2)
ocean sealBOT
lone heartBOT
@molten knot Has your question been resolved?
wind cloak
Are you sure you don't have limits involved
Or is the answer meant to be left as an infinite series
heady dome
Hey differentiation of (X/2) = 0 right?
lone heartBOT
Hey differentiation of (X/2) = 0 right?
echo socket
Derivative of x/2 (with respect to x) is nowhere equal to 0
heady dome
X = 1 so 1/2 where 2 and 1 are now constant so 1/2 = 0
heady dome
Differentiation of X is 1
echo socket
With that logic derivative of any function is 0
heady dome
So final answer is 0
echo socket
Differentiation of X is 1
Correct, so what would derivative of 1/2 * x be?
??
Derivative of x is 1
So derivative of x/2 is 1/2
heady dome
1/2 * 1
heady dome
2?
echo socket
1/2 * 1 is just 1/2
heady dome
Oh okie
alpine sable
😂😂
heady dome
Thanks
alpine sable
that's how it is
heady dome
This is 171th question I'm solving I guess I should stop
I solved 171 questions in 4 hours
echo socket
Take some rest
heady dome
Yeah
lone heartBOT
@heady dome Has your question been resolved?
lone heartBOT
lone heartBOT
Available help channel!
molten pivot
Every day the value of my $1 portfolio either doubles with probability p, or halves with probability 1-p. What is the expected long run value?
vale wigeon
every day your portfolio multiplies by a random variable whose mean is 1.25
molten pivot
Right. But can we express this as a function of p
vale wigeon
oh wait no hold on i thought it was a fifty-fifty chance of each mb
2p + (1-p)/2 is your expected value
(3p+1)/2
molten pivot
right that's what i thought too, just taking the weighted average. but the thing is that it doesn't make sense for the boundary cases
consider p=0 and p=1
molten pivot
like if p = 1 the value should be infinite because it's always doubling
vale wigeon
for p=0 your thing halves always, and (3*0+1)/2 = 1/2
molten pivot
i'm not asking about the value after just one day
vale wigeon
well im describing the effects after a single day
your long run EV will be 0 or infinity depending on whether p is greater than 1/3 or not
molten pivot
let me phrase it this way: what is the expected value on the nth day
cosmic scarab
this problem seems similar to the rabbit problem,
I rabbit is standing 2 meters away from a tree, each jump he makes covers half the distance between him and the tree.
molten pivot
if the mean multiplier is just (3p+1)/2 then i guess we can just consider the behavior of the function ((3p+1)/2)^n
which doesn't really make a difference actually, it just matters whether it's more or less than 1/3
cosmic scarab
if the mean multiplier is just (3p+1)/2 then i guess we can just consider the be...
btw can you tell me the criteria on what bases the amount doubles or halves? or is it random like any one option will be picked?
molten pivot
it's random
cosmic scarab
well considering a scenario where the amount keeps doubling it'll go on forever
vale wigeon
let me phrase it this way: what is the expected value on the nth day
[(3p+1)/2]^n
lone heartBOT
@molten pivot Has your question been resolved?
astral cliff
lone heartBOT
finite flax
,rotate
ocean sealBOT
finite flax
uhuh well what have you tried so far
astral cliff
nothing
astral cliff
Pls just tell me the answer I have 4 questions on this topic then I’m never gonna do this shit again
finite flax
Pls just tell me the answer I have 4 questions on this topic then I’m never gonn...
so you're never going to need to know how big a room is
astral cliff
nope
finite flax
or how much paint you need
astral cliff
I’m just gonna be a a garbage truck driver
I’m set for life
Now what’s the answerrrrrrrr
finite flax
...or what size bed sheets you need 😛
ocean sealBOT
ocean sealBOT
left isle
what are you stuck on
astral cliff
,rotate
ocean sealBOT
lone heartBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
okay so do you know what a is asking you to find?
astral cliff
nope
left isle
he wants to edge both the circular and the outside perimeter of the garden bed in timber
can you put that into math terms?
left isle
no?
no one here is going to just give you the answer
that's boring
say you have a square
and you want to put wood along the perimeter of the square
and you're given that the side length of the square is 6
can you tell me what the perimeter of the square is?
left isle
yep! how did you get that?
left isle
it's correct
left isle
right. because squares have 4 sides of equal length.
okay so now you have a circle in the middle
and you also want the perimeter of the circle
you're given its radius is 1
can you tell me what the perimeter of the circle is?
left isle
yep! more specifically it's 2*pi.
okay so a) is asking you the sum of the perimeters of the square and circle
are you asking about a) or b)?
astral cliff
Nvm
left isle
because we're working on a) currently
left isle
so b) is asking for the area available for planting. it's a square garden, with a fountain in the middle.
left isle
exactly
left isle
$A={\pi}r^2$
ocean sealBOT
Wumbo
left isle
for the area of a circle
astral cliff
So 35.86m^2
left isle
36-3.14?
astral cliff
left isle
So 35.86m^2
not 36^2
remember the side length of the square is 6, so the area is 6^2 which is 36
not 36^2
astral cliff
So just 36-3.14
astral cliff
So it’s 32.86m^2
astral cliff
Ez
left isle
mhm
astral cliff
Ty for helping
left isle
no problem
nocturne crescent
lone heartBOT
tall talon
Sorry, but what is the last word in the 1st line?
nocturne crescent
point
tall talon
point
thanks
Now, do you know the formula for the area of a triangle? We'll be working from that
tall talon
what does b represent?
tall talon
the left bootom corner for the triangle and rectangle
let me give you a hint: b is a lenght
nocturne crescent
of the triangle and square?
tall talon
if you are not sure, you can look it up = )
nocturne crescent
ok
tall talon
Maybe I'll tell you this: b is a lenght of any side of the triangle and h is the triangle's height perpendicular to b.
nocturne crescent
ok i got it
tall talon
If you set b to the lenght of BC in your picture, you can work out that the area of a triangle is half of the area of the rectangle it's inscribed in. What can we do about this fact?
@nocturne crescent Are you here?
nocturne crescent
yeah
tall talon
If you set b to the lenght of BC in your picture, you can work out that the area...
Please answer
oops, bbl
crystal oyster
@nocturne crescent do you want the calcution part?
nocturne crescent
yes
nocturne crescent
<@877746996474167316> do you want the calcution part?
how to do the caculation
i will get the numbers
nocturne crescent
yes
lone heartBOT
Available help channel!
next sonnet
Find the nth term of each sequecne.
,...625,125,25,5,1
lone heartBOT
Find the nth term of each sequecne.
,...625,125,25,5,1
winter light
Shouldn't it be 1, 5, 25, 125, 625, ... ?
next sonnet
5 power 2?
winter light
Those are the powers of 5
next sonnet
yeah
winter light
You have 5⁰, 5¹, 5², 5³, 5⁴, ... so the general formula is $a_n = 5^n$
ocean sealBOT
Alberto Z.
next sonnet
a powered n = 5 powered N right?
winter light
$$a_n \neq a^n$$!!!
ocean sealBOT
Alberto Z.
winter light
Exponents are above, indices are below
next sonnet
thank you sir
next sonnet
.close
hallow verge
Hey guys I have no idea
lone heartBOT
Hey guys I have no idea
wary stream
Didn't I help you with this yesterday?
hallow verge
Yes
wary stream
Where I suggested getting it into slope intercept form, y = mx + b
wary stream
So then what's the issue?
wary stream
$\frac{12}{-5} \neq -2.5$
ocean sealBOT
dldh06
wary stream
**dldh06**
Do you understand this?
wary stream
Which way is correct to sketch the graph of 8x-5y=20
It doesn't matter which way you use, you'll end up with the same graph, if you do the math correctly
hallow verge
Wdym x = 1
wary stream
When you plugged in 1 for x
hallow verge
For which method
?
U told me to use slope int form
So I got
Y=8/5x-4
What do I do after this?
wary stream
For which method
You asked to check the second method
wary stream
So then what's the issue?
Right here.... you asked about the second image when I asked what the issue was
hallow verge
So the 2nd image is someone else's working and he told me to do it like that
So I'm just wondering
Is both methods correct
hallow verge
OK what should they both look like then
Because u told me to use slope int method
Y=8/5-4
hallow verge
So I start at -4 on Y axis and go up 8 and across 4.
hallow verge
You dropped the x
Whoops my bad
wary stream
So I start at -4 on Y axis and go up 8 and across 4.
And that's not the slope
wary stream
But is that how I sketch it
Yes
wary stream
So I start at -4 on Y axis and go up 8 and across 4.
Because you typed it wrong here.... it's up 8, over 5
hallow verge
Oh ok
wary stream
But the process is correct
hallow verge
So the 2nd image
Is that also correct?
Don't worry bout it actually
I jus see if the graph are the same
wary stream
That's a different way to do it too
wary stream
What method
It does not matter what method you apply
wary stream
You can apply whatever method that makes it easier for you, whether you want to do slope intercept form or creating a table of values
hallow verge
Well which one is better in ur opinion
wary stream
4x + Y - 10 = 0
You should understand that this is a linear equation
wary stream
It doesn't matter which way you use, you'll end up with the same graph, if you d...
.
You can apply whatever method that makes it easier for you,
wary stream
Linear equation means?
An equation that is a line
hallow verge
What I got to do with tht then
wary stream
You can apply whatever method that makes it easier for you
whether you want to do slope intercept form or creating a table of values
hallow verge
But is it only those two methods
wary stream
There are probably others but those two are the most common ones
wary stream
https://www.youtube.com/watch?v=-u55GD_sGLA
https://www.youtube.com/watch?v=3H6iw42gyOc
https://www.youtube.com/watch?v=a2IMaUJfSpQ
Here are a bunch of videos, apply it
hallow verge
Because it's different
wary stream
Is that slope intercept form?
hallow verge
Dude what
wary stream
What's confusing you?
hallow verge
So my
wary stream
Y-10 =-4x+0
You need to make this be y = ...
wary stream
I never said it was wrong, I said it's not in slope intercept form
wary stream
Do you know how to manipulate an equation to set that equal to y = ....?
wary stream
If you were given x + y = 12, could you set that equal to y?
hallow verge
Yea
wary stream
How would you do it?
wary stream
You want it to be in the form of y = ...., that means the other stuff needs to move to the other side, how would you do that
wary stream
What's - -12 equal to?
wind cloak
Are you unfamiliar with what -(-12) would be?
hallow verge
12?