#help-0
1 messages Ā· Page 294 of 1
so i went -2 down and went to the closets point
which was (2.5, -2)
and so i put for one of them a(2.5)/a(#) = -2
but then I used desmos and got # = -1.25
and then when i go to point-
wait
nvmn
@alpine sable
i got it
its a(2.5)/a(-1.25) = -2
literally just look at the y values
and find
an a(x) that is -2
and another that is 1
its dividing
space
$$\frac{2.5}{-1.25}$$
$\frac{2.5}{-1.25}$
Umbra
One person
so a(a)/a(b) isnt a/b?
One person
$$f(10) = 10$$ ???
One person
ohhh
i was doing the wrong thing
a(x) = the amount of steps (y) to get to a point
k
i see
k yes it works
a(-3) + a(2) worksa
works*
@alpine sable
I GOT IT!
the answer to number 14 is
$$ \frac{a(2.5)}{a(2)} = -2 $$
Umbra
Am I right?
no
what is a(2.5)
2
no
what??
oh wait..
-2.
bruh
so that makes positive
omgg
this stupid graph
$$ \frac{a(2.5)}{a(-2)} = -2 $$
Umbra
correct
YES
FINALLY
ty
anyway im done
see ya and ty for the help
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Good job
ty
bye bey
bye
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from my answer book: How'd they get the -k/2 i always get a k or something like that
@merry arch Has your question been resolved?
<@&286206848099549185>
is that kumon?
just wondering and also i cant help you with this because i havent gotten that far in math srry
you can always ask someone whos experienced with this
yeah itis
don't have time š i have to try in two days if i want help (that's why im also asking here lol)
<@&286206848099549185> that can plz help me this time? (no offense umbra)
uhm
cant your kumon instructors help you?
cuz i have been to kumon before but quit like 2 years after
i can't go there rn for two days im too busy
@merry arch Has your question been resolved?
i got it solved lol
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yo i need help
so i got two lines
one that goes from 0-1
another that goes from 0.4-0.6
however there is a scale line which makes 0.4 into 0 and 0.6 into 1
and now i got two points
0.2 raw (aka from line 1) and 0.8 raw
it converts into the scale line of line 2 as -0.2 and 1.2
my question what is the math for this conversation
@mighty crypt Has your question been resolved?
@mighty crypt Has your question been resolved?
If you didn't understand I am looking for a forumla that translates a point from Line 1 (0 to 1) to Line 2 (0.4 to 0.6), but in such a way that 0.2 in Line 1 becomes -0.2 in Line 2, and 0.8 in Line 1 becomes 1.2 in Line 2. This forumla must include the 0.4 and 0.6 which are sizes of line 2!
@mighty crypt Has your question been resolved?
@mighty crypt Has your question been resolved?
your transformation isn't very clear
or at least isn't linear
because the interval between 0.4 and 0.6 (which has length 0.2) is transformed into a region of length 1
but you're also saying that 0.2 should be sent to -0.2, which means that the interval between 0.2 and 0.4 (which has length 0.2) is transformed into an interval of length 0.2
back
i found the issue
and i got it working
using chatgpt
bro told me i got it wrong, it knows what doing and i tried in my code and it worked
Also chat gpt can be wrong
Itās wrong with me 70% of the time
For whatever reason maybe it hates me
Like the thought process is probably correct but the math sometimes does not math
chat gpt is terrible at math, i would not recommend using it for specific problems
it may be able to explain concepts in math, but it sucks at doing the actual arithmetic
@mighty crypt Has your question been resolved?
don't use chatgpt for math. waste of time
!help
Please read #āhow-to-get-help
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I am following this paper: https://arxiv.org/pdf/2008.07669.pdf
Background:
The gist of it is that they initialize the weight matrices of an discretized ODE with a orthogonal polynomial basis which behaves recurrently, in the form of c' = Ac + Bu, where A and B are weight matrices (N x N) and (N x C) respectably (N is a hyperparameter and C is the number of channels) , c are coefficients that describe the orthogonal polynomial at each time step (this behaves as the state that is passed between time steps) and u is the input at each time step.
I have been trying to, for fun, create a modified form of the chebyshev polynomial that behaves in a similar way to LegS (Scaled Legendre). I will put all the latex for this below. What I am having a question on is this:
Question:
I have been trying to understand the derivations more thoroughly as I have been going through this myself. I am wondering how, within section B.1.3, specifically section Derivatives of Chebyshev polynomials how the author goes from the first equation defined as:
\begin{align}
2T_n(x) = \frac{1}{n+1}\frac{d}{dx}T_{n+1}(x) - \frac{1}{n-1}\frac{d}{dx}T_{n-1}(x) \qquad \text{for } n \geq 2
\end{align}
to the equation 11 also descibed in the same subsection.
Again, I will provide the derivations below
BeeGass
I could only get this far:
yeah I made a post here so that way I can reference the question better
@tidal bane Has your question been resolved?
@tidal bane Has your question been resolved?
@tidal bane Has your question been resolved?
@tidal bane Has your question been resolved?
try to just stick to one place. adv-analysis is more apt than here since all your details are already there
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Hello, I think I have easy to solve problem but its kinda unclear for me and I can't find 100% clear answer anywhere, I roll a dice twice, I need probability A- that in 1st roll it would be "4" , B - there is only one "4" , my results are that P(A)=1/6 and P(B)=10/36, but now I need to get P(B|A) and i have no idea how to solve this problem, I get reult more than 1 so it's obv wrong
The definition $P(B|A) = \frac{P(A \cap B)}{P(A)}$ is useful here
Jangler
What is your result for $P(A \cap B)$?
Jangler
16/36
How did you get that?
No you don't
You use that to calculate $P(A \cup B)$ IF A and B are disjoint
Jangler
it's unclear for me to be honest
$A \cap B$ means, that A and B happen simultaneously
Jangler
i have 1st A than B
Which results fit to die description: "The first number is 1 and there is only one 4?"
What do you mean with that?
I roll 2 dices, in 1st roll I want to roll 4 P(A)=1/6, and second roll I want to have only one "4" P(B)=10/36 (but now im confused if its not wrong also)
No. A is the set of all results, where the first of the two dice is 1 (and the second one can be any value)
B is the set of all results of the form (4, x) or (x, 4) with xā 4
$A \cap B$ is the set of results, which are both in A and in B
Jangler
set you mean amount of this possibilites ?
No with set I mean a collection of results
so for A(4,1 4,2 4,3 4,5 4,6)
for B(1,4 2,4, 3,4 ,5,4 ,6,4 and that from A)
is it correct?
Oh wait why did I read that the first result has to be 1, I'm dumb
Your notation is not correct
so what i should change?
You should write $A = { (4,1), (4,2), (4,3), (4,4), (4,5), (4,6)}$
Jangler
yea thats right
Also, (4,4) is in A
ohhh okay!
B contains all the pairs of A without (4,4) , and the flipped pairs
So what is $A \cap B$?
Jangler
$B = {(1,4), (2,4), (3,4), (5,4), (6,4), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6)}$
Thic
thats B right?
No, (4,4) should not be there
$B = {(1,4), (2,4), (3,4), (5,4), (6,4), (4,1), (4,2), (4,3), (4,5), (4,6)}$
Thic
(there should be exactly one 4)
Yes, that's correct
$A \cap B$? is what is diffrence between right?
Thic
(you need to write \ before { and } because otherwise they won't be shown)
oh oki doki
No that is the intersection of A and B
So the set of all elements, which are in A and in B
so its A without (4,4) $A \cap B = { (4,1), (4,2), (4,3), , (4,5), (4,6)}$
Thic
Correct
how i use it now?
So what is $P(A \cap B)$?
Jangler
5/36
Yes
Now you have to plug everything in and you are done
plug where ?
In the definition of the conditional probability
$P(B|A) = \frac{P(A \cap B)}{P(A)}$
Thic
to this but written correctly
Yes
Yes
so it 5/36/1/6 = 5/35 * 6/1 = 5/6
Yes (but with 36 instead of 35)
yes yes missclick
great, thanks a lot I'm so dumb with this stuff
diffrent question should be posted in diffrent topic right ?
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!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
1
may i ask what grade of school you are in?
just curious
is this a very simple problem that a first grader can solve š
what i would do is get a function for the x value of the dot and a function for the y value of the dot
it is not easy if i am reading it correctly
do you know how to do it
i don't understand that
well i do
but how
that is the difficult part
we can solve this in two/three steps
first, we ignore the rotation
then the x value will just be 20(mi/h)*t
and y will be 0
then we ignore the velocity and only look at the rotation
that is the difficult part
that would be like
a sine
wave thingy
right
yes
we are looking at a wheel spinning without moving here
the dot starts at the bottom
so to easier discribe it we can rotate the whole thing (including the axes) so that the dot starts on the right side and moves counterclockwise
we want the x value, which after the rotation is the y value
so we use r*sin(omega t)
where omega is the angular velocity
which we will get later
try to get the y value with a similar approach
this part doesn't make sense
how did you get that
hmm
that is what you would write in physics
so i just used that here
usually we have something like sin(theta)
where theta is the angle
How do I get help
$\theta=\frac{\theta}{t}t=\omega t$
Martin
Martin
radius
sin only ranges from -1 to 1
but we want it to range from -r to r
so we scale it up with a factor r
ok and i don't understand this either
here we just divide and multiplied by t, that is legal if t is not 0
then we call this theta/t to be omega
which is the angular velocity
it is like saying
$x=\frac{x}{t}t=vt$
Martin
this works because our velocity is constant btw, otherwise we would have to use diferentiation
so in total, the idea is:
-get x and y functions
-then notice that distance will be sqrt(x^2+y^2)
to get x and y:
-get the x and y of the entire wheel
-then go into the reference frame of the wheel where it stands on one point and rotates
-get x and y there as well
-combine what we get
to get x and y in the rotation:
-know that we pretty much always have x = r cos(theta), y = r sin(theta)
-however notice that we dont start on the right and instead on the bottom so we change it up a bit
(a drawing helps here a lot)
-feel pain by converting feet and miles into one unit
@frank ridge Has your question been resolved?
btw i think this is not what you are meant to do
this doesnt sound like something i did in 10th grade
that is what got me confused
as a tenth grader i definitely can't understand anything
is there a way to say what you said in a kindergartener level way
lets say we look at a car that moves
on the tire of the car is a dot
to describe the movement of that dot, we can say
the movement of the dot is the movement of the car plus the movement of the dot relative to the car
that is the idea
wdym
im just determining what value the vertical stretch and other stuff are
is this correct?
@frank ridge Has your question been resolved?
ā¦
Have you tried anything since
$\theta
Well itās hard to help you if you donāt try
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@real shore Has your question been resolved?
!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
@real shore which one are you at
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!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
1
which one is it guuys? with justification ofc ;w;
<@&286206848099549185>
please guys send help
I think number 1
reason and motives?
please also tell the name of the waifu in your profile pic . . .
It's not 2 since the "door" and the "window" are on opposite sides
Not 3 because there should be a window on the front
And not 4 because the window should be on the back
I mean on the front
Hah
Idk
!15m
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
;w;
Fate/kaleid liner PrismaāIllya
Found this anime on the internet
looks like a very sexy anime lady}
thank you sir .
understood capitan, tysm!
Her name is 'Iriyasufīru fon Aintsuberun'
.close?
.close
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Yeah!!!!
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if you know a function is differentiable does that imply that the first derivative is continuous?
differentiable everywhere?
sure
No
whatās the counter example
That seems intuitive but I can't think of an example. Show us dark magic, Riemann
,w integral of |x|
,w graph x^2sin(1/x)
since I'm now curious, is there a counterexample that is not a piecewise function?
No idea. Make one up
Using the floor function you can (probably) define any piecewise function as a non-piecewise function
I'll let you judge whether that counts
I'm not motivated enough to explain how you'd do that
The construction is kind of long
@summer dirge Anyways, unless you have more questions you can now .close this channel
this wasn't my channel lol
@vapid steppe did that answer your question ^
frick
@vapid steppe Has your question been resolved?
wait
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Why is the formula for inverse proportion y = K/x?
Because when x goes up, y goes down
but how did they get K/x?
y = 1/x is just a relation that shows up in a lot of places, hence why people gave it a name, "inversely related"
The K is just a "proportionality constant": it affects how strong the relationship between y and x is, but it doesn't change the qualitative behavior of it
Think about what happens as x increases, this means the denominator goes up, watch what happens with numbers: $\frac{1}{2}=0.5\to\frac{1}{3}=0.33\bar{3}\to\frac{1}{4}=0.25\ldots$.
Notice, that as we increase the denominator our output decreases in value, this is what \textit{inverse} proportion is. As x increases/decreases, y decreases/increases respectively :)
MrFancy
$k$ is just some constant, it's doesn't matter what we chose, the same principle still holds:
$\frac{2}{3}=0.66\bar{6}\to\frac{2}{4}=0.5\to\frac{2}{5}=0.4\to\frac{2}{6}=0.33\bar{3}\to\ldots$
MrFancy
oohh okay i understand, where does the K come from though and why?
usually it's something that you measure experimentally
so you collect a bunch of data and then figure out the best "K" value that fits the data
$k$ was just chosen, we can choose any variable, it could $n$ or $b$ for all we care :) but generally you choose $k$ for this stuff
MrFancy
sorry i didn't mean the letter chosen, i mean the value for k sorry for the miscommunication
for that you are usually given a set of points and have to find the inverse proportion from those points
it is similar to gradient?
do you mean like y = kx?
if so then yes
the k serves the same function in that equation
but isn't the gradient in a curve not a constant?
gradient is slope
yeah
for y=kx, k is the slope, k is the gradient
Yes, the k in y = k/x is not exactly the gradient
But it serves a similar role in determining how steep the graph is overall
ohh okay
The higher the value of k, the steeper the graph
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no problem at all!
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How to prove that 10 is a solidary number?
what do you mean by solidary?
solitary
Do you mean a number that doesn't have any friendly pairs?
can you provide the definition?
It's a number that doesn't have any friends according to mathworld
what is a friendly pair
Can you define āfriendā?
10 is not a solitary number...
This appears to be an open problem
It is believed that 10, 14, 15, 20, 22, 26, 33, 34, 38, 44, 46, 51, 54, 58, 62, 68, 69, 70, 72, 74, 76, 82, 86, 87, 88, 90, 91, 92, 94, 95, 99, 104, 105, 106, and many others are also solitary, although a proof appears to be extremely difficult.
can you prove it please
yea I was looking at math world which said it's wasn't my fault 
i wouldn't even know where to begin... 
Says I have to prove it, teacher gonna whoop me if I don't put something in the answer
Well no one here can help you with it
whoop as in give you actual, for realzies physical punishment?
Unless you misread the problem
It appears to not be known whether 10 is a solitary number
Could it be a trap question where I have to say this
We cannot help you figure out the intentions of your teacher
dang
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.reopen
ā
you should bring it up with the higher ups if he uses corporal punishment btw
like that's not something that a teacher should be doing in this day and age
@split forge
or any day and age
I'm a big guy, don't worry about it, I'm just not good with maths so I need a tutor even if I'm old
I can take it, thanks tho
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you want to prove that there does not exist $n$ such that $$\frac{\sigma(10)}{10} = \frac{\sigma(n)}{n}$$
tushar
(This appears to be an open problem.)
big guy or not, it's still not ok to face the risk of physical abuse from his end!!!!
.close
All good
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,rotate
help pls
Do you know the formula for arc length?
2 Ļ r (Īø/360°)
Idk the easy way to solve (b).
But you can do it with some basic trig
k
@brittle current Has your question been resolved?
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How does this work?
First, try differentiating (2x - b)^a
d/dx or d/da
d/dx
whats the derivative of b
a is a constant, differentiating with respect to it would not make much sense
b is a constant, so d/dx [b] = 0
$a(2x-b)^{a-1}\cdot2$?
A Lonely Bean
yeah
Okay, and we want this to be equal to 24x^2 - 24x + 6 for all x
First of all, what degree does this polynomial have?
n-1?
yeah well i only put n because n = some number but ig makes more sense to say a
Yeah, and, since we want this to be equal to 24x^2 - 24x + 6, we need to make sure the degree of this polynomial is equal to 2 as well
So a - 1 = 2 and a = 3
Okay, so $f'(x) = 6(2x - b)^2$
A Lonely Bean
Can you expand this?
2 * a = 2 * 3 = 6
ok
Yes
Try expanding the right hand side
b^2 -4bx + 4x^2
Yeah, and don't forget to multiply by 6 to get 24x^2 - 24bx + 6b^2
yeah
We want to find the value of $b$ such that $24x^2 - 24bx + 6b^2 = 24x^2 - 24x + 6$ for all values of $x$
A Lonely Bean
Do you know what condition should two polynomials satisfy in order to be equal everywhere?
not sure
The corresponding coefficients must be equal
So, in this case we must have -24b = -24 and 6b^2 = 6
Can you solve for $b$ here?
[ \begin{cases} -24b = -24 \ 6b^2 = 6 \end{cases} ]
A Lonely Bean
has to be 1 right?
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is it just me or does the first solution here seem egregiously wrong
would you mind posting the first solution here?
sure
ummm
no idea what they're saying
but sounds right
Think they're just using
similar triangles
to find the x and y
that's exactly right, they're doing something called linear interpolation between points 0 and 1
here is the original post for some better context
it just doesn't add up for me, if you have points (3, 3) and (4, 4) in euclidean space. They will have a distance of root 2. The points returns from using the answer formula is about (1.4, 1.4) if d sub t is 0.2
Do you know trig?
yea
hmm
you sure you aren't doing it wrong 
I just did it in desmos and it's correct
If you know trig you should be able to come up with the solution yourself. (Maybe not the (1-t) part that's kinda hard :>)
I messed up yeah, the windows calculator isn't the most straight forward to use š . The solution is correct
Thanks for the help!
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Hi I need help again
Couldn't find an attached image in the last 10 messages.
huh?
depends
sorry i was scrolled way the heck up mb
@toxic swift please post the original question in full
that's it?
Yes
so no other instructions?
you have a blank sheet of paper that only has this expression on it? zero words written elsewhere?
Callisto can you answer this question for me?
A5-Z7+9M
No
oh, i know.
you wanted to evaluate X^3 + Y^2 + Z^3 when X = 4, Y = 20 and Z = 69
,w 4^3 + 20^2 + 69^3
this will be neither 96 nor 95
wow how could we all have been so naive this whole time
Hold on theres more to the question
I forgot to take a picture of this
Would it be 97 then
did you crop too much again
what is X^2 + Y^2 + Z^2 supposed to be
have to say you're making it very hard for us to help you
think?
Yeah
is 34 written on the page or not
can you like take an uncropped original image, leaving nothing out nothing relevant to the question
come back when you have a question to ask.
I do
you've failed to show it to us, like three times now.
@rose sigil snow reference
Wouldn't you need a value for all three of those to constrain the variables?
Even knowing sum of squares shouldn't be sufficient
i love snow
yeah also the first two equations are symmetric in X, Y and Z while the expression whose value we are (supposedly) asked for isn't!
but good luck getting that out of OP
The answer is 34 for the second one
"the answer"?
thin air
from a book? teacher? worksheet?
It's on the page
take a picture of the page
I did
post the image of the page
Ok
(the whole page)
Well it's on my computer
log into discord on the computer
snapshot
why is the bottom equation cropped out wtf
bruh
THE WHOLE APGE
Baby steps come on guys
Are you just typing this yourself
Don't make me want AnyDesk access bruh šš
this is a real patrick lid moment
this has to be intentional
I don't wish to live in a world where this is non-intentional
Last chance @toxic swift , full equation or idk mods EQUATIONS*****
Okay
Mind the 'S'
š¤£
Not solvable
what are you giving us
not this
are you 1090% sure that you didn't omit anything?
?
,w omit
took us asking you many times before 34 magically appeared
Are you constantly thinking so as to what to add more in the question. Like there is a high chance you would put some value for x^3+y^3+z^3 in a while (you made it yourself or your friend gave it to you)
Guide How fail someone nevertheless 101
I agree
I didn't make it myself my teacher gave it to me
Can you show us how you went to determine the answer as 97 UNLESS you put the values themselves, ie. Trial and error
Why did it take you so long to show the 34
Cuz it wasn't there
Yes it was
where did the 96 come from??
Only way to check if you're true bro
Show us your 96 working
silence does hit hard
Isnāt this one of those solve and get one million US dollars questions?
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If im asked to prove a function ā” another function, am i allowed to start from the RHS and convert that to the LHS or not? Thanks
Surely
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I donāt really know where to go. I can get the perpendicular distance and the gradient but i donāt know what to do with it
<@&286206848099549185>
maybe you could find the equation of the line that passes through the segment and use the point of intersection to find the distance between that and C, which you could then use to find the coordinates of D
there may be a simpler way, but that's what came to mind first
AH I FORGOT ABOUT POINT OF INTERSECTION
lol
THANK YOU
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I have a few question about the answer.
Why answer is 4 i dont understand why D is false.
I don't understand what valid means
Should it be interpreted as the logic expression returning true?
yeah maybe
my sister study in python
Otherwise I would say they all are valid (for me valid = makes sense)
But are you given that the correct answer is 4?
yeah they said the correct is 4
Ok and you don't understand why it is true or why are the other answers not correct?
In other words, are you able to tell the result of the first expression?
I can remember a little bit about true false
like t or t = t , t or f = t
so i trying to make understanding about
A True and false = False right ?
B also false
C True
D False
E true
is that correct
@split rose Has your question been resolved?
A and B yes, but pay attention to C, D, E
Let's start with E which is easier, ok? @split rose
ahhh in understand that have no false in this right ?
i mean all of them make sense.
so they can be true
Nope, the issue is a little more subtle
But yes, they all make sense, but we have to figure out which of those 5 answers gives False in output for some integers. If you look carefully at the question, they ask which of those 5 expressions is valid (i.e. returns True) for EVERY integer x we give in input @split rose
ahhhh
That's the key of all the exercise, yeah. I admit it was tricky precisely because of this
The only thing now to pay attention to is answer C, because it seems to be always True, but not if x is 0 š
Yeah, I feel the same lol
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Iām struggling with Laplace transforms / partial fractions
Can someone pls help
part B of this question is what I am trying to answer:
Ur partial fractions are wrong?
Firstly
Your denominator for one of the fractions is a quadratic but your numerator is linear
oh yeah it should be = 1 right?
Yes
should they be A/(s+1) + B/(s+1) + C/(s+1)^2
Also brb
what rule is this called?
It is how partial fractions are defined
The numerator is a degree lower than their denominator counterpart
@late drum Has your question been resolved?
oh ok hold on im gonna give this a go
Is this right?
Oh wait
I didnāt sub right lol
should be (1/2)/(s+1) + (s+(1/2))/(s^2 + 1)
I think it's right
But let's verify
,w 1/((s+1)(s^2+1)) = (1/2)/(s+1) + (s+(1/2))/(s^2 + 1)
B = -1/2
and then after I get A, B and C and sub back in I need to multiply by exp(-2(s+1)) right?
oh wait no
I just find the laplace transform of each of those partial fractions?
Yes
- the lapace transform of exp(-2(s+1))?
No hold up
First let's finish the partial fractions
We'll get to the Laplace
What did you get?
All in all
(1/2)/(s+1) + ((-s/2)+(1/2))/(s^2 + 1)
,w 1/((s+1)(s^2+1)) = (1/2)/(s+1) + ((-s/2)+(1/2))/(s^2 + 1)
Okay nice
But anyways yes
You now have
[
\cmap {\mathcal L}{\bmap{e^{-2(s+1)}}{\f1{2(s+1)} + \f{1-s}{2(s^2+1)}}}
]
This is what you are dealing with now @late drum
Yes
You are gonna be splitting the fractions too btw
The second one for example is just cos and sin
The first one will turn out to be e
alright ill give it a go
exp(-t)/2 for the first fraction and -sin(t)/2 for the second?
oh I see what you mean
[
\f{1-s}{2(s^2+1)} = \f1{2(s^2+1)} -\f s{2(s^2+1)}
]
yeah
Also where are Ur Heaviside funcitons
Are u sure u applied this?
No
You cannot skip it
You cannot do the Laplace transform for the insides first
It's why I wrote the L behind the e and not in front
Anyways just expand the e and do it concurrently
hmm
I am not sure how to š
[
e^{-2}\cmap {\mathcal {L}^{-1}}{\f{e^{-2s}}{2(s+1)} + \f{e^{-2s}}{2(s^2+1)} -\f{se^{-2s}}{2(s^2+1)}}
]
Does this help you
I think so, so I find the laplace transform for each fraction inside the brackets now?
ok I can do that but why is there still an exp(-2) out the front?
Do you see $e^{-2(s+1)}$ here
What happens when u expand the brackets
oh right I see
@late drum Has your question been resolved?
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I have decided that this is linear, but I don't know how to construct the matrix representation of T in the standard bases of P2 and P3
what?
Again a is not linear
For b find images of 1,x,ā¦
how do i do that
Find matrix such that
(T(1), T(x), T(x^2))=(1 x x^2 x^3)A
And I just gave you the last column
Itās like a Picard triangle when you finish it
kyou
No
P(1) = 0x^2 + 0x + 1
For forgot x^3
P(x) = 0x^2 + x + 1
And if itās P2->P2 itās still wrong
ok i think i got it thanks
Yeah
why 1 1 1 in the first row
@alpine sable Has your question been resolved?
Because coefficient of 1 in (x+1)^k is 1
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Help I suck at geometry
!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
1
Ok so Iāll explain how I would analyze this problem
So we want angle CPB, right?
What angle will help us find CPB?
APB?
@eternal tulip Has your question been resolved?
Idk
Well we have triangle APB
Yea
So we can take PAB and PBA and take that away from the sum of angles of a triangle
Isnāt PAB and PBA the same triangle
Angles PBA and PAB*
Isnāt that still same
Why are they the same
Whatās the difference between PBA and PAB
You tell me in what aspect are they the same
Ok, so hereās the key observation: what can you say about AP and BP?
@eternal tulip
Right
And A and B are points on the circumference of that circle
So what does that make AP and BP?
Radius?
Yep
Oh
And so what can we conclude on their lengths
Idk
Yea
That means triangle ABP is isosceles, yes?
So what can we say about angle PBA and angle PAB
Angle A = Angle B?
@eternal tulip Has your question been resolved?
How do I learn the Trigonometry table like the sin 30 is equal to and all?
Memorize sin 30, 45, 60, do the rest by comparing with unit circle
Hello, i need help with 5(b)
No, Like can you learn it mathematically



