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1 messages · Page 284 of 1

distant ivy
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What are those symbols lol

lone heartBOT
lament ferry
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propositional logic, discrete math

distant ivy
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I’m sorry I don’t think I’m at that level of math yet

lament ferry
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anyone else?

shadow verge
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Do u mean Y has (0-8)
And
X has (0-7)
This making it 998

distant ivy
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so let’s say x is 7
That leaves y with 0-9 excluding 7
Hence, instead of 10 possibilities you’re left with 9

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Sorry if my explanation is odd I haven’t taken stats classes

distant ivy
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Because it’s also 0-9
But since x and y are both taken
10-2 = 8 possibilities

shadow verge
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Oh ok I understand

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Wait nvm

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Does anyone know how to do the second one

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<@&286206848099549185>

distant ivy
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Is it 64?

shadow verge
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No

distant ivy
shadow verge
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I think I do

distant ivy
shadow verge
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Yup

distant ivy
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Whew

shadow verge
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Genius

distant ivy
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Ok

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I’ll try my best to explain

shadow verge
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🫡

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I will try my best to understand

distant ivy
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Again I apologize for anything that sounds off i haven’t taken stats courses

distant ivy
shadow verge
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Ok

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...

distant ivy
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Ok so first things first let’s take the example of
XYZ

It says the numbers that are 700 or greater. Which means x has to be either 7,8,9

Also, “Z” has to be either (1,3,5,7,9) for the number to be odd (for example: 705)

Let’s take all the possibilities:

7YZ

If x is 7, then “z” is either (1,3,5,9). Which means 4 possibilities for “z”

Since Y is in the middle, it doesn’t matter if it’s even or odd.
It ranges from (0-9)
But two of the numbers are taken by x&z. That leaves us with 8 combos

That makes up 8x4 = 32 numbers that begin with “7” with odd and different

Do the same thing for 8
You get
8YZ

“Z” now has 5 possible combinations, since X is even
Y again has 8 since one is taken by x and other by z
8x5 = 40

For 9:
9YZ

Z now has again 4 possibilities. Y again with the 8
8x4 = 32

32+32+40 = 104

shadow verge
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Holy shit

distant ivy
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Basically I took the possibilities of the number being 700- something
800- something and 900-something

shadow verge
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And added it up

distant ivy
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Yes

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Every possibility

shadow verge
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Can u do this method for the first question?

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Wait

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Why did u do 84 and 85

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Bruh wuts with discord

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8 times 4 and 8 times 5

distant ivy
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Because

shadow verge
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Why 8?

distant ivy
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There are 5 possibilities for z and 8 for y
You need to find how many possible combinations of that there are

Imagine you have 2 numbers and each have 3 numbers possible
There would be 9 combinations

shadow verge
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Oh ic

distant ivy
# shadow verge Why 8?

Bcz y can be any number it’s free, it’s in the middle. But it cannot be repeating, hence not whatever x is or z is

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So from 0-9
Remove 2 of the numbers

shadow verge
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Ty man so much 🥹

distant ivy
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Anytime man

shadow verge
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.close

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slim yarrow
lone heartBOT
slim yarrow
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Not sure where im going wrong

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median oar
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In the case that T is a vector function does var(T) become a covariance matrix?

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wintry gazelle
#

This is the question that i made myself, but i havent fully solve it
I proved (i) by consider the range manually for f(x), f²(x), f³(x), etc. and show that the initial minimum and maximum of f^n(x) will swap at f^n+1 (x).

But now idk how to prove that both minimum and maximum of range converges to a single value (question ii). I tried to make my life easier by only consider 2nd case of range (even n), but still idk how to continue
Note that i know how to find the value of l after the limit is proven converge, but i need to prove the converge itself at the first place

wintry gazelle
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For notation sake, f^n(x) is same as f(f(f(...(f(x))...))) where f(x) self composited n times

lone heartBOT
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@wintry gazelle Has your question been resolved?

wintry gazelle
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Im thinking of probably show that f^n+1 (1) > f^n-1 (1) and f^n(cos 1) < f^n-2(cos 1)

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Aka new minimum > old minimum and new maximum < old maximum

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Then show that min and max converges seperately to their respective value

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Lastly show that they converge to same value

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But idk where to start tho

wintry gazelle
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<@&286206848099549185>

lone heartBOT
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@wintry gazelle Has your question been resolved?

lone heartBOT
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@wintry gazelle Has your question been resolved?

lone heartBOT
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@wintry gazelle Has your question been resolved?

wintry gazelle
#

<@&286206848099549185>

upbeat hornet
wintry gazelle
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Okie ima try my luck there

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.close

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alpine sable
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Whats the easiest way to factor cubic polynomials

alpine sable
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For example this

echo socket
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Find out its roots if possible

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Here the coefficients are integers, so you may apply rational root theorem

alpine sable
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Do I first factor the 2x^2-5x-10

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Then factor out the 1x

echo socket
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No, you will have a rational function there

alpine sable
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So how do I solve it

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Im confused

lone heartBOT
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@alpine sable Has your question been resolved?

lone heartBOT
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@alpine sable Has your question been resolved?

hot wadi
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you will find a integer root of equation is: x=-2

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Can you make it to this step? @alpine sable

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@alpine sable Has your question been resolved?

hot wadi
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Hey @alpine sable

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@alpine sable

hot wadi
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Hey @alpine sable

alpine sable
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Ok Tyy!

hot wadi
alpine sable
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Yes

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modern gorge
lone heartBOT
modern gorge
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hey there

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i need some help in what to do

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.cxlose

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.close

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cold frigate
#

Triangle MNO and triangle PQR are shown on the coordinate plane.
What sequence of transformations proves ΔMNO ~ ΔPQR?

OPTIONS
1) ΔMNO was rotated 180° clockwise about the origin, then dilated by a factor of 2 about the origin to form ΔPQR.
**2)**ΔMNO was translated up 6 units, then dilated by a factor of 2 about the origin to form ΔPQR.
**3)**ΔMNO was reflected across the x-axis, then dilated by a factor of 3 about the origin to form ΔPQR.
**4)**ΔMNO was reflected across the y-axis, then dilated by a factor of 3 about the origin to form ΔPQR.

nimble latch
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what do u think is the answer

cold frigate
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no idea on this one.

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Maybe 1) cause its rotated?

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on the other side

nimble latch
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yea

cold frigate
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so that's the answer?

nimble latch
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yea

cold frigate
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aight

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merry arch
#

I've attached my work and a key of what I'm suppose to do. I got the equations, and was able to graph the quadtratic, but that's all. How do I graph the linear equations? Everytime I do, I seem to get the wrong point (i've erased them and forgot to take pictures).

lone heartBOT
#

@merry arch Has your question been resolved?

grand umbra
#

FYI the photo of your work is a file that does not open

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merry arch
#

.reopen

lone heartBOT
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merry arch
wild umbra
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you need not to open the file

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file contains his work

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ques is right there

merry arch
wild umbra
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whats the answer?

merry arch
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there is no answer?i just need help graphing the linear equations

smoky adder
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Substitute something greater than 7/2, 7/2, and then something less than 7/2 in for k. It's in slope intercept form, so your lines will have the same slope but hit different points on the y axis (whatever you choose for k)

merry arch
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so would i use -8k+28 or y=2x+k?

smoky adder
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Second one

merry arch
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so y=4 if i decide to do k=8/2 (4)?

smoky adder
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You're not necessarily solving for y, just graphing the line.

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Try getting out a separate sheet of paper and graphing the line y=x, then y=x+3, then y = 2x

merry arch
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okok

smoky adder
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Then go back and graph y = 2x + (>7/2), y = 2x + 7/2, and y = 2x + (<7/2)

merry arch
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oml tysmmmmm

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keen pagoda
lone heartBOT
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@alpine sable Has your question been resolved?

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frigid pendant
#

I have a question

lone heartBOT
frigid pendant
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Is there a mathematical function that maps a finite set of numbers to a infinite set of number?
if so: would be there an hasing algorithm that has NO hash collisions ever (or near no because of a VERY LARGE finite set of numbers mapped to a small finite set of numbers (the pigeonhole principle states that it takes a specific time to compute all possible inputs and outputs to the hashing function because there are so many pigeonholes to fill first) => that would result in a very long time to compute all possible computational results of the finite very large such set to a small finite set such we can store in a reasonable physical disk space

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a infinite set never has pigeonhole collisions because there "always enough free pigeonholes" because there INFINITE pigeon holes

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like imagine there would be an infinitely large wall and you were at some random position in this infinite space. if you throw a dart against this wall you will never hit another dart thrown before

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the wall meets one of these conditions:

  1. the wall is infinetely small such/zero/nothing that you can zoom out and into forever
  2. the wall is infinetely large such that you can zoom out and into forever
remote heron
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is there a mathematical function that maps a finite set of numbers to a infinite set of numbers?
wouldnt this violate the defn of a function

remote heron
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a function must map any element in the domain to only one element in the codomain

frigid pendant
remote heron
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i have no idea what youre talking about with the rest

remote heron
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maybe you are envisioning something else that does this mapping but its not a function

frigid pendant
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only if the size of the finitecodomain is bigger than the size of the domain set

frigid pendant
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why not?

remote heron
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use pigeonhole

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every element of the domain has to be mapped to an element in the codomain

frigid pendant
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exactly 😄

remote heron
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there are fewer elements in the codomain than the domain

frigid pendant
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this cant be

remote heron
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you just said so 👀

frigid pendant
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because of the pigeonhole principle

remote heron
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idk in what way youre misapplying it

frigid pendant
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are the digits of pi truly random?

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is it like actually a infinitely long set of random numbers which patterns cannot be extracted to a function that describes the patterns

median oar
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I mean we can calculate it

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So they most definitely aren’t random

vocal quiver
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Let f : N -> {0 ... 9} be the function that returns the nth digit of pi :)

frigid pendant
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is there a uncalculateable array of numbers that has no repeating patterns

median oar
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You could try random number generators is that what you want?

frigid pendant
remote heron
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yes

frigid pendant
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then how could i go from the finite codomain to all element of the infinite domain

remote heron
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go?

frigid pendant
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i can only throw 10 pigeons in the base 10 number system to a infinitely big grid of pigeonholes

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so it just cant fill all the infinitely many states

vocal quiver
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You can have a function with a finite domain and infinite codomain, it just can't be a surjection.

frigid pendant
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can you give me a proof why?

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if every number in a infinite set would be mapped to a random number in the finite set

remote heron
vocal quiver
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I'm talking about a function from a finite set, to an infinite set

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What you suggested is the opposite

frigid pendant
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if the domain is smaller than the codomain of a function then the function cannot be surjective

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right?

vocal quiver
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If by smaller you mean smaller cardinality, then yes, although you might need choice to prove it for arbitrary sets.

frigid pendant
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ellobarate the last part please

vocal quiver
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Suppose |A| < |B|. If you assume the axiom of choice then the existence of a surjection from A to B means that |B| <= |A|. Then since |A| <= |B| from cantor schroeder bernstein you have |A| = |B|, a contradiction to the fact that |A| < |B|. So there cannot be such a surjection.

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But for a finite domain you don't need any of this, you can just use induction.

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If A = {a_1, ..., a_n} is finite then the image of A is {f(a_1), ..., f(a_n)} which is also finite as it has at most n elements.

lone heartBOT
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alpine sable
#

can someone explain me pls how vectors in physics which means quantity (arrow) that has magnitude and direction which you can draw wherever you want and vectors in math which means whatever that you can add to other "whatever"and multiply by the number is the same things because i really dont understand that(sorry for my english )

young finch
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principles of vector math are the same in physics for the most part

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just different concepts I guess

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and vectors in math don't always have to be physical

alpine sable
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yeah but i dont understand how it connects together

gloomy wolf
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What do you think a vector is?

tardy stag
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vectors (physics) obey the axioms of vectors (mathematics)

the mathematical vector is kind of a generalization of the idea of a physics vector, in that sense

alpine sable
gloomy wolf
alpine sable
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but in math even a real number is a vector

gloomy wolf
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Right, the diagonal of a 1-d rectangle (height 0)

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All the rules of vectors still apply

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Just for real numbers, there are only two directions

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Left (-) and right (+)

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In 2-d (R^2) you have infinitely many directions, one for each angle of the unit circle

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And in R^3 you have even more, because you can travel away from the origin in a sphere

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We can’t really draw 4-d and higher on paper but vectors in those contexts behave the same way algebraically as the lower dimensional ones we can easily visualize

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4-d vectors are super common in physics though, and you can’t draw them (on one piece of paper) 🙂

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prime folio
#

someone please help me with this question idk if i did the correct working out

prime folio
solemn juniper
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close, you just compounded for one year too many

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he invests his first 1000 at the end of the first year, meaning it compounds for three years

prime folio
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ohhh so do i start on n=3 down to n=1?

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oh i get it now thank you

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ocean pagoda
lone heartBOT
ocean pagoda
#

Im getting (x-4y)(x+y)/x(x+3y)

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textbook says

frozen tiger
ocean pagoda
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$(x-4y)(x+y)/x(x+3y)

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$ (x-4y)(x+y)/x(x+3y)

frozen tiger
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how you got to your answer

ocean pagoda
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oh I factored all terms and let them cancel out

frozen tiger
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write it down and show a picture

ocean pagoda
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sure but my process is pretty messy

frozen tiger
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I think I know where you got it wrong

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just show me the pic

ocean pagoda
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got it one sec

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@frozen tiger

frozen tiger
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has a -28y^2

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before it

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You sort of missed that

ocean pagoda
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oh my fucking god

frozen tiger
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and you also missed the 3y when factoring x^2+3xy

ocean pagoda
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wait no hold up

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ok so yeah

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i dumb

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thanks bro

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was so confused where the hell a 7 came from

frozen tiger
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now close the channel

ocean pagoda
#

.close

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craggy spire
lone heartBOT
craggy spire
#

how would i do tis

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this

frozen tiger
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4z-6 and z+11>0

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just find the minimum value there

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seems like 4z-6>0 is the inequality to solve

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since any solution to that would produce a nonzero value for z+11

craggy spire
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would that work

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as z

frozen tiger
craggy spire
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1.5

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@frozen tiger

frozen tiger
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a-b=0, a=b
a-b>0, a>b

frozen tiger
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nvm you got it

craggy spire
frozen tiger
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humble fog
#

if you have a diamond like this, how do you calculate the correct tangents that will give you a circle

humble fog
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the result would be this

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each point has an inTangent = [x,y] and an outTangent = [x, y]

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which are coordinates offset from the respective point

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so [100,0] on point 1's inTangent would position it 100 pixels to the right of the point

molten pivot
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those aren't tangents

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those are secants

humble fog
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oh, im just going by the name they're called in the program

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these are them on display visually

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4 points, 8 tangents/secants

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@molten pivot when the radius of the circle is 100 pixels, the standard value for the tangents is 55.25. does this number have any significance to you?

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steel olive
lone heartBOT
steel olive
#

why is x taken as 1 here

gloomy wolf
#

Because it’s at the point (1,2)

molten pivot
#

Lol

steel olive
#

also if this said curve was a circle,how to get the second tangent

steel olive
#

shi lol

gloomy wolf
#

It’s not a circle but the answer is implicit differentiation

steel olive
#

no like if im given a circle then

#

could u exlain with an example

#

let the circle be x^2 + y^2 - 4x - 8y -5 = 0

gloomy wolf
#

I’m gonna do x^2+y^2 = 1

#

Assume the equation defines y as a function of x.

#

Differentiate on both sides

#

$\dv{(x^2 +y(x)^2)}{x} = 0$

ocean sealBOT
#

JamesH

gloomy wolf
#

Then don’t forget chain rules

#

We get $2x + 2(y(x))y’(x)=0$ now solve for y’ in terms of x and y

ocean sealBOT
#

JamesH

steel olive
#

what is y'

gloomy wolf
#

The derivative of y wrt x

steel olive
#

ok

gloomy wolf
#

Since it’s a function of x we need chain rule which is why y’ shows up

#

Once you solve you should have $y’(x) = - \frac{x}{y(x)}$

ocean sealBOT
#

JamesH

gloomy wolf
#

Take the derivative on both sides. In the right you’ll need quotient and chain rules

#

On the left you’ll have y’’

#

I assume that’s what you meant by second tangent (second derivative)

steel olive
#

thnx a lot

lone heartBOT
#

@steel olive Has your question been resolved?

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warped topaz
lone heartBOT
warped topaz
#

I want to find a video that explains all of this better, but if I search 'direction and support vector' or anything like that in youtube I cannot get any relevant results, does it have a different name or something?

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cinder sundial
lone heartBOT
cinder sundial
#

the key for that question is we have to get the ratio between these intergral

#

from the the perspective of geometry

#

what does the input x being doubled indicates on the graph?

echo socket
#

Is there nothing else given about f/its graph?

cinder sundial
#

no

echo socket
#

With a substitution you can show that $\int_0^1f(2x)\dd{x} = \frac12\int_0^2f(x)\dd{x}$

cinder sundial
#

here's a poor diagram i drawn

ocean sealBOT
#

A Lonely Bean

echo socket
#

So that's gonna be half the area from 0 to 2

cinder sundial
cinder sundial
#

from u-substition?

echo socket
#

Substitute for 2x

cinder sundial
echo socket
ocean sealBOT
#

A Lonely Bean

cinder sundial
#

emm

#

that's the whole question

echo socket
#

Anyway, the value of $\int_0^1f(2x)\dd{x}$ can't be determined of the only information about $f$ that we know is the value of $\int_0^1f(x)\dd{x}$

ocean sealBOT
#

A Lonely Bean

echo socket
#

Oh

#

So you were given more information

echo socket
ocean sealBOT
#

A Lonely Bean

echo socket
# cinder sundial

For the other integral you can do a substitution as well, substitute for x/2 this time

cinder sundial
cinder sundial
echo socket
cinder sundial
#

do you mean sth like putting x=2x into f(x) then it become f(2x)

#

im not sure what you mean by substituing

echo socket
#

Say $u = 2x$, then $\dd{u} = 2\dd{x}$ and we have
[ \int_0^1f(2x)\dd{x} = \int_0^2f(u)\frac{\dd{u}}2 = \frac12\int_0^2f(u)\dd{u} ]
$u$ is just a dummy variable, what we call it doesn't really matter, so we can rewrite the latter as
[ \frac12\int_0^2f(x)\dd{x} ]
We know that $\int_0^2f(x)\dd{x} = 8$, so the answer to the first integral is:
[ \int_0^1f(2x)\dd{x} = \frac12\int_0^2f(x)\dd{x} = \frac12\cdot8 = 4 ]

ocean sealBOT
#

A Lonely Bean

cinder sundial
echo socket
#

Undoubtedly

cinder sundial
#

im sort of a expert at this method, but i wonder if i can solve it through geometry

cinder sundial
# echo socket Undoubtedly

also what do you want to use "u-substitution" here? how do you know u-substitution could be applied to solve this question

echo socket
#

The resulting area is the same as the area of f from 0 to 2, but since it got squished, we divide it by 2

cinder sundial
echo socket
#

Like I said, the area gets squished from (0, 2) to (0, 1)

cinder sundial
echo socket
#

Well solve the integral algebraicly then if you are skeptical

cinder sundial
echo socket
#

Yeah

cinder sundial
#

im astonished

cinder sundial
echo socket
#

Well we just proved it algebraicly

#

Remember, we got 1/2 * area from 0 to 2

cinder sundial
#

ohh the u-substitution!!

echo socket
#

Yes

lone heartBOT
#

@cinder sundial Has your question been resolved?

lone heartBOT
#

@cinder sundial Has your question been resolved?

lone heartBOT
#
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alpine sable
lone heartBOT
alpine sable
#

How do I find the equation

upbeat hornet
#

You know the outputs of the function for some points

alpine sable
#

I am guessing I can find the slope?

#

should be -2 for y

upbeat hornet
#

so you can substitute those points into the plane equation to find the unknown coefficients a, b, c

alpine sable
#

alright let me try

#

yeah i don't get

#

@upbeat hornet can you provide a step maybe

#

like do I create a system of equations by plugging in different points or something?

upbeat hornet
#

what is f(0,1), from the graph?

alpine sable
#

the orange line

#

should be z = b + c

upbeat hornet
alpine sable
#

wait a minute is that the z value?

#

for the line

#

oh shit that's the level

#

so if it's x + y = a

#

a = 5 in this case?

upbeat hornet
alpine sable
#

ah i see

upbeat hornet
alpine sable
#

nah ignore that part that was stupid

#

so to go from

#

(0,1) to (0,3)

#

i need to increase the z value by 5

#

so maybe i can use an increase formula?

#

like this?

upbeat hornet
#

or you can do this: since you know f(0,1) = 5, and f(x, y) = ax + by + c, you can substitute in x = 0, y = 1, then get a linear equation relating a,b,c

#

and then do this with a few other points and you have a, b, and c

alpine sable
#

wait what i did is actually right somehow

#

i found a and b

alpine sable
#

makes sense

#

i can do that to find c then

upbeat hornet
alpine sable
#

yeah but it's gonna take a millennium i think

#

yeah i got it then

#

ty 🫡

#

.close

lone heartBOT
#
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upbeat hornet
alpine sable
#

i mean im guessing for 3 variables you need 3 equations?

upbeat hornet
#

.reopen

lone heartBOT
#

alpine sable
#

yea that was just a guess but

#

im assuming it's because you need to substitute 3 times so you need 3 equations

upbeat hornet
#

the idea to solve n linear equations with n variables simultaneously is this:

#

take one equation and multiply it by a number so that the coefficient of the first variable, x, is 1

#

then you can subtract this equation from all the others so that none of the others have x

#

and then you now have n - 1 equations without x, but with n - 1 other variables

#

then repeat

#

and you’ll eventually get down to 1 equation with 1 variable

#

which you can solve

alpine sable
#

ahhh i see

upbeat hornet
#

then you can substitute it into the previous ones

#

and keep doing this back-substitution

alpine sable
#

i was just winging it when i did the ones i had but i did exactly what you just said

#

better to have a system in mind for it tho

#

ty i'll save this

upbeat hornet
#

.close

lone heartBOT
#
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stable grotto
#

how to prive this ?

lone heartBOT
stable grotto
lone heartBOT
#

@stable grotto Has your question been resolved?

stable grotto
#

<@&286206848099549185>

stable grotto
#

.close

lone heartBOT
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twin jolt
lone heartBOT
twin jolt
#

I need help with 4b

#

I know 4a from the formula sec theta is 1 over cos theta

#

But idk how to do b

vale wigeon
#

well you've found cos(θ) = -8/17, yes?

#

you know cos(θ) and you know what quad θ is in, can you find sin(θ)?

twin jolt
#

It can either be 2nd or 3rd

#

Uh

#

How am I supposed to find the ratio

wanton pebble
twin jolt
#

Whoops

#

Yeah

#

Um so I know it’s 2nd

#

But how do I find the ratio of sin

#

Pythagoras?

wanton pebble
#

cos²x + sin²x=1

#

i think

twin jolt
#

Let me try

#

Oh yep

#

Got it

#

Thanks

#

.close

lone heartBOT
#
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flint notch
#

A storage container in the shape of a cone has a base of radius r and a height of h. Write and simplify an expression for the ratio of the volume of the conical container to its surface area (including the base). For a cone,

wanton valley
#

!status

lone heartBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
flint notch
#

1

#

V = pi/3 r^2h and S. A. = pir^2+pirsqrtr^2+h^2

wanton valley
#

Is the last expression the full area of a cone?

flint notch
#

yea

wanton valley
#

Owkay and where are you stuck?

flint notch
#

I don't know where to begin

wanton valley
#

What do you need to do

flint notch
#

A storage container in the shape of a cone has a base of radius r and a height of h. Write and simplify an expression for the ratio of the volume of the conical container to its surface area (including the base). For a cone,

wanton valley
#

So the second sentence how can you begin

flint notch
#

Yea I understand the question but I don't konw how to make a ratio of Volume and Sa

wanton valley
#

Its a division

#

One divide by the other

#

Thats a ratio

flint notch
#

yea but but is it just the pi/3r^2h over the SA?

wanton valley
#

Sounds about right

flint notch
#

alr I have another question

wanton valley
#

Keep em coming

flint notch
#

bet

#

there

wanton valley
#

Whats ur question about it

flint notch
#

I got 2x-3

#

So would the solution be considered odd or even

wanton valley
#

Lets think about it

#

When you multiply a number by 2 which one will it be

flint notch
#

positive

wanton valley
#

Not necessarily and its between odd and even

flint notch
#

yea mb

wanton valley
#

No worties

#

Try agaun

#

Again

flint notch
#

alr Not necessarily and its between odd and even

wanton valley
#

Wait no

#

Okay

#

What is odd

#

What does it mean for a number to be odd

flint notch
#

idk how 2x-3 can be odd or even

wanton valley
#

I mean in general

flint notch
#

yea Ik what odd or even is

wanton valley
#

Tell me

#

Part of the process

flint notch
#

numbers that can't be divded by 2

wanton valley
#

Yes yes owkay and even is it can

#

So 2x-3

#

Divide it by two

#

You understand where i am going?

flint notch
#

x-3/2

#

x = 3/2

#

o its positive

wanton valley
#

Andddddddd

flint notch
#

odd it is

wanton valley
#

It is odd

#

Yes

#

Since 2x-3 can never be a multiple of 2

#

You can never write it as one of... if x is a whole number

maiden glen
#

3*7 doesn't give 14 so the simplification isn't right

wanton valley
#

You forgot -1 at the end

flint notch
#

yea yea

maiden glen
#

right yeah

wanton valley
#

2x-2 will always be even because you can write it as a multiple of 2

flint notch
#

alr bro thanks

#

have a great day

wanton valley
#

You too :)))

flint notch
#

.close

lone heartBOT
#
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clear minnow
#

%I'm trying to figure out how to write a formula in which the set of X has a bijection onto Y, in which F must satisfy Y before it's number. X is for a set of infinite numbers; so that Y must be in the set of X. Can we solve this by stating that F and Y are within the same superset of X and pair them together under Y, so that we can have a bijection of X onto Y?%
%I put X as the following%
$$|X| = \aleph$$

ocean sealBOT
clear minnow
#

<@&286206848099549185>

#

I'm going to bed, but please give me a response to this so I can type it up 😭

ruby current
#

I have no idea what you are asking

lone heartBOT
#

@clear minnow Has your question been resolved?

lone heartBOT
#
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rapid plover
lone heartBOT
rapid plover
#

ping me

upbeat gorge
lone heartBOT
# rapid plover
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
rapid plover
#

1

upbeat gorge
#

Do you understand the question?

rapid plover
#

yes

#

i 'am stuck where it says u1=2u2=1

#

im not sure if it is u1=u2=1/2

upbeat gorge
#

u2 is 1/2, but u1 isn’t

rapid plover
#

then what is u1

upbeat gorge
#

It’s given in the equation

rapid plover
#

its 2u_2?

upbeat gorge
#

Well, yes

rapid plover
#

hmm i will try

#

with this perspective

upbeat gorge
#

Note if a=b=c, then a=c

rapid plover
#

then u1=1

naive crystal
#

Also, a=b=c => b=c

#

You can get u2

#

From here

#

After that, you'll have u1,u2 then proceed with || n=1,2,3 to get the value of u3,u4,u5 ||

rapid plover
#

for n=1 i got u3=1

upbeat gorge
#

not quite

rapid plover
#

how so

naive crystal
#

u3 = u2÷u1

upbeat gorge
#

Your u1 is 1 and u2 is 1/2, right?

#

Yeah there you go

rapid plover
#

si

#

then u3=1/2

naive crystal
#

Yes

upbeat gorge
#

Ok

#

Now solve u4 and u5

rapid plover
#

and u4=1

upbeat gorge
#

yes

rapid plover
#

buut

#

these are the aswers respectively

upbeat gorge
#

u1 is definitely 1 lol

#

Must have been a typo somewhere lmao

rapid plover
#

i tried the same with different it is wrong

upbeat gorge
#

Maybe they intended u1=2u2=2

#

Or u1=2u2, u2=1

rapid plover
#

let me try

#

yes but u1 is not 2 and u2 is definetly not 1

#

hmm maybe i will have a talk with my teacher

lone heartBOT
#

@rapid plover Has your question been resolved?

lone heartBOT
#
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vale wigeon
#

you should probably not doxx yourself 💀

#

i can see your full name

#

also is this a current exam?

wispy pine
#

Couldn’t care less tbh

glossy fox
#

Find the domain
(x)

wispy pine
#

How

#

It’s min and max

#

But sometimes is high

#

And other times it’s low

#

But then

#

It’s left to right

#

Domain to Y or X

glossy fox
#

x is domain

#

x' to x

#

-x to x

wispy pine
#

So from left to right

#

Okay

#

Lemme get it

rapid plover
#

update ur os

glossy fox
#

Yes

rapid plover
#

old version of macOS, u are prone to being hacked

wispy pine
#

Min is -11 and max is 4?

rapid plover
#

yes

wispy pine
glossy fox
#

-11≤x≤4

rapid plover
wispy pine
glossy fox
wispy pine
#

Or if it’s <,>, or geq or leq

rapid plover
#

or 10

wispy pine
rapid plover
#

ha dealt with that stuff, u have hell coming towards you my friend

wispy pine
marsh rune
#

SCfall2 lol

lone heartBOT
#
Channel closed

Closed due to the original message being deleted

rapid plover
#

trust me graphs will get 10x harder.

wispy pine
#

Dude scared me

rapid plover
#

.reopen

wispy pine
#

So many ppl being in here 💀

#

lemme crop the photo

rapid plover
#

.reopen

wispy pine
#

.reopen

rapid plover
#

not working

wispy pine
#

So look

#

This is X

#

But then sometimes it says y axis

glossy fox
#

It's for range 😭

wispy pine
#

How do I know between x and Y

glossy fox
#

Domain is X
Range is Y

wispy pine
#

DUDE IM NOT THE BRIGHWST BULB 😭😭😭

#

oh

#

It says it on the top💀

rapid plover
rapid plover
wispy pine
rapid plover
#

bro send clear photo

wispy pine
#

When I finish this I never have to go back

#

Skip 12

rapid plover
#

are u doing specialist math

wispy pine
#

For Y it would say range right?

glossy fox
# wispy pine

If you don't understand
Just simply find all the coordinates of each and every point in the form of ordered pairs
then (x,y)

Domain = all x components
Range = all y components

glossy fox
rapid plover
lone heartBOT
#
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rapid plover
#

.reopen

wispy pine
lone heartBOT
glossy fox
#

Domain:
-11≤x≤4
Range:
-4≤y≤11

rapid plover
#

heheh

wispy pine
#

Hold on

#

So this one is X right?

rapid plover
#

domain is the length of the graph horizontally ; on x -axis

#

range is lenght of graph vertically ;y

#

in domain graph starts at -11 and ends at4

wispy pine
#

Are the open and close circles playing a part?

rapid plover
#

and in range highest part is 9 and lowest is -4

wispy pine
#

Wrong photo

rapid plover
wispy pine
#

What is that?

rapid plover
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the curve

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the zig zag curve

wispy pine
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so on this new one are is the min -10 and the max is 11?

rapid plover
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si

wispy pine
#

So how do I find out the symbol for it

rapid plover
#

bro u have a mac prob u have iphonje

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SEND A CLEAR PICUTRE

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or take a screenshot or send

wispy pine
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IT IS CLEAR

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OKAY WAIT

rapid plover
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its near 11 and i have cllg tmmrw BRO QUICK

wispy pine
rapid plover
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i also have to do 100 situps

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quickl

wispy pine
rapid plover
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bro send screenshot

rapid plover
wispy pine
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I DONT have discord on that

rapid plover
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DOWNLOAD IT

wispy pine
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Lemme log onto my phone

rapid plover
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fine

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quick

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quick zen-senpai

fading citrus
rapid plover
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idk

wispy pine
wispy pine
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@rapid plover

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WYA

rapid plover
#

This precalculus video tutorial explains how to find the domain and range of a function given its graph in interval notation. The domain represents all of the x values in the function and the range represents all of the y values. You should use parentheses for open circles and infinity symbols but you should brackets for closed circles. This ...

▶ Play video
wispy pine
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I’m cooked

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💀😭

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It’s only 2 questions

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That’s why I come here for quick learning

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And u guys explain it better and let me ask questions

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.close

lone heartBOT
#
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rapid plover
#

.reopen

#

@wispy pine

lone heartBOT
#
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wispy pine
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IM HERE

lone heartBOT
wispy pine
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@rapid plover

wispy pine
rapid plover
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yessir

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wtf is geq

wispy pine
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Greater than or equal too

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Since apple don’t wanna add it on keyboard

rapid plover
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it is -2 geq y geq 7

wispy pine
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Okay

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Lemme try

rapid plover
#

good night

wispy pine
#

Good night

rapid plover
#

ping someone else

wispy pine
#

Alr

rapid plover
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ur in specialist

wispy pine
#

What’s that

rapid plover
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or methods math

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nvm

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gn

wispy pine
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😭

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Gn

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.close

lone heartBOT
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minor gulch
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Can this be factored or is this a prime polynomial?

minor needle
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looks familiar

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like difference of squares

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have you considered it?

minor gulch
ocean sealBOT
minor needle
#

and so

ocean sealBOT
lone heartBOT
#

@minor gulch Has your question been resolved?

lone heartBOT
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warped topaz
lone heartBOT
warped topaz
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b, the 2nd part

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is it just me or is this the most confusingly worded question ever

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We dont know what p, xb, xc, dp or ep are

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I cannot even figure out what theyre asking

tardy stag
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it's a bit weird? but it's understandable eventually

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did you read the preceding paragraph?

warped topaz
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after b right?

tardy stag
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after a

warped topaz
#

Yeye thats the question im stuck on

tardy stag
warped topaz
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I solved a

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I had to read it like 10 times but I think I get it

tardy stag
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you're looking for max( f(x) - g(x) ) in that second region

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that's it

warped topaz
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The region between xb and xc?

tardy stag
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yes

warped topaz
#

What are they talking about with 'distance between points dp and ep'

tardy stag
warped topaz
#

its a straight line?

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Then how can I get the max?

tardy stag
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yes it's the vertical line x = p

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well, if p = xC then the distance will be 0 since the graphs are intersecting

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same with if p = xB

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you slide that vertical line across the interval

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and see where that distance is highest

warped topaz
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Ohhh does xC means the x value of C?

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And the same for B and xB?

tardy stag
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yes

warped topaz
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Okay

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Bruh this was on an exam

tardy stag
#

it is somewhat confusing

warped topaz
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Haha yep

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I think I get it now

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Oke I will try it

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Thank you!

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❤️

#

.close

lone heartBOT
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elfin vector
#

Can someone pls help me with this? I'm not sure if it's correct. Thx.
It's about probability.

near lagoon
#

I think it's correct

elfin vector
#

for 2.b) i did it like this
1-(0.7x0.7x0.7x0.3) = 0.8971
which only accounts for the WWWL situation, not all of the games that are 4 or lesser

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but then i changed it to this

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cuz it makes more sense?

tardy stag
#

that does seem to make sense

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,calc 0.7^4

ocean sealBOT
#

Result:

0.2401
tardy stag
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why is that also a way to arrive at the same answer? ^

elfin vector
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wait hol up, what was that?

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is that a different method?

tardy stag
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yes

elfin vector
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can u pls explain it lol

tardy stag
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sur4e

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why would Anna have to play more than 4 games?

elfin vector
#

when she wins 4 or more games

tardy stag
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yes exactly

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so what's the chance of her winning the first 4 games in a row?

elfin vector
#

i think i get the logic, but isn't that only for the WWWWL case? Like what about winning five games?

tardy stag
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it covers everything that starts with WWWW

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you'll note that i didn't include an 0.3 in there

elfin vector
#

so the probability for WWWWL and WWWWWL would be the same?

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or it gets smaller

tardy stag
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no, those would be different

elfin vector
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oh wait nvm im stupid

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i get it now

tardy stag
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but 0.7^4 covers everything starting with WWWW

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yeah

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you see?

elfin vector
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yep

tardy stag
#

your method was also fine i want to be clear

elfin vector
#

thank you so much for the help

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really appreciate it

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have a nice day

#

.close

lone heartBOT
#
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flint notch
lone heartBOT
flint notch
#

help

subtle birch
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what have you tried?

flint notch
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I don't know where to stard bro

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do I just use pathag?

subtle birch
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Its pythag

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Yes

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you use that

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to find the shortest distance between ferris and butte

flint notch
#

Help me out with these as well bro

flat roost
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for 3, use law of cosine

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for 4, it is what sin and cos is fundamentally about

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good luck

flint notch
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what bout 5?

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<@&286206848099549185> can you help me with 2

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I got x = 18sin(23) when I plug it in the cal I get -15

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but hows that possible

sudden burrow
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,w 18*sin(23)

tardy stag
flint notch
#

oh thanks

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alr thanks

#

.close

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dim matrix
#

I got the regression equation, if I put the value of x in the equation, should it match the result I'd get with the value of y in the table?

dim matrix
tardy stag
#

it won't necessarily go through all - or any - of those points

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but it will be close to them probably

dim matrix
#

okay, one more thing, how can I plot the regression line? Should I just put the value of x in the equation I got and then get the corresponding values of y and simply plot the graph? @tardy stag

lone heartBOT
#

@dim matrix Has your question been resolved?

tacit arch
ocean sealBOT
#

riemann

dim matrix
#

Okay thanks @tacit arch @tardy stag

#

.close

lone heartBOT
#
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tardy stag
dim matrix
lone heartBOT
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blissful depot
lone heartBOT
blissful depot
#

How can I find the height. I have found alpha and beta but I don't think they have any relation to the final answer. Unable to find d.

subtle birch
#

Alpha and beta indeed have no relation with the height

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just consider the given angles

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and the main concept to be used here is tan(x)

blissful depot
#

So I take tan (23)?

subtle birch
#

Consider this distance. Try to find this distance in terms of 'height'

blissful depot
#

I'm getting a negative value when I do that

subtle birch
#

show your work

blissful depot
alpine sable
#

switch to degree

blissful depot
#

Wdym I am using degrees. 23 and 29 are in degrees

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And unfortunately I have not learnt about radians yet so I don't think I have been using radian

alpine sable
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check your calculator

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tan 23 should be 0.42 and tan 29 should be 0.55

blissful depot
#

Oh yup I found the setting. Thanks

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So now I do the same working?

alpine sable
#

ye

blissful depot
#

Alright got the answer. Thank you guys

#

.close

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winter night
#

Is someone here studying pre-algebra? I am and would like to have a study partner.

hidden widget
#

wut topic?

winter night
#

Bodmas at the moment. I am perhaps just days before switching to algebra

winter night
hidden widget
#

ahh im studying precalculus rn

lone heartBOT
#

@winter night Has your question been resolved?

lone heartBOT
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fluid ingot
lone heartBOT
fluid ingot
#

I need to do this using the epsilon n definition

#

In pink ink r my thoughts on approaching the problem, but they aren’t taking me anywhere

fluid ingot
#

.close

lone heartBOT
#
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fluid ingot
#

Gotta follow the instructions and find the limit using epsilon n concept. I’m not sure how to start

marsh rapids
#

squeeze theorem

hidden widget
#

sandwich

#

yea

lone heartBOT
#
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lone heartBOT
marsh rapids
#

dumb bot

subtle birch
marsh rapids
#

.close

lone heartBOT
#
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marsh rapids
#

(sparkle you can take a new channel if you want)

fluid ingot