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cos(picosx)=0 for -pi/2 to pi/2, i tried rewriteing the domain for picosx
and i got x is larger than 0 but less than 0
i jsut did
picos(-pi/2) < picosx < picos(pi/2)
maybe you dont do this for when you apply cos but not sure
Can you send the original question? @safe tartan
Ah ok you have to solve it, so you can start with the outer cosine, whose argument must be π/2 + kπ since the result must be 0
It is.
picosx=pi/2 + kpi right
That's why your reasoning here is wrong.
cosx isn't monotone in -pi/2 to pi/2.
yes. This is the way to go.
monotone as in continuously decreasing/increasing?
right
So πcos(x) = π/2 + kπ, hence cos(x) = 1/2 + k. Since -1 ≤ cos ≤ 1, k (which is an integer) must be 0, giving you cos(x) = 1/2, that happens at x = ±π/3
k could be -1 right
You are not supposed to give solutions.
i mean im not doing it for answers though just tryna learn
I didn't just give the solutions, but also the method to get them
Yes
Yeah, I know it, didn't want to break the rules sorry
Either just directly find solutions from your domain.
Or find general solutions and take intersection with domain.
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I have no idea how to solve this
my idea was taking two arbitrary points
then measuring the surface area with both and seeing if i get teh same result
but idk if that's correct
You are on right track. Just take two varible points (x1,y1) and (x2,y2) and calculate surface area for both.
You'll come to see that their area is same.
oh so it's right
Surface area of triangle is just area of triangle or perimeter ?
1/2 x b x h
Alright another question but simpler
I managed to find the point where the two lines cross but
but i dont think showing two points is true shows that all the points are true
how do i find the tangent line equation's slope
i just checked my answers and apparently
Points are arbitrary. I'm not saying put values in there. Just in form of variables.
right, i see
Same value, and same derivative at the intersection
That's what the condition for two graphs touching boiks down to
yeah but
what i did was plug -1 into y = x^2
and then did 1 = (-1)(-1) + b which is wrong i think
like i managed to find the point by equating the derivatives
then plugging -1 into the original formulas
yeah idk where to go from here
Yeah idk what you're trying to do here
Just check the two functions have the same derivative for x=-1
If they do, you won
@vale crag
I wanna find the tangent line
that relates to these two points
but i have no clue how
Yeah
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i have question about definition of f(x)=e^x
yes?
So in a math book im studying from rn I get the definition for f(x)=e^x where all real x values are allowed and result definition as y > 0
im not sure if the word definition is correct here btw, studying in swedish
definition is fine here yea
Where did y come from
you're using the word in two different senses
the INPUT set of e^x is the entire number line.
Df=xeR and Vf=f(x)>0
the OUTPUTS on the other hand are only positive
right, outputs ill use that word
in english they're called domain and range respectively
Okay so outputs allowed are defined as greater than 0
provided your input was real, yes
but than I have a function f(x)=e^x-1
$e^x - 1$ or $e^{x-1}$?
Ann
first one
ok
So output should now be greater than or equal to 0
no
no
that's only for e^x itself
i think, since if I set x=0 than I get f(x)=0
no, the range of e^x itself is (0, +∞).
but the range of e^x - 1 is obviously shifted down by 1 from that, so (-1, +∞).
(0, +∞) <- dont really understand this part
it's the interval from 0 to +infinity
do you know about interval notation
if not i will have to translate that back into inequalities
(not including either of those)
the range of e^x itself is y > 0
right
okay that makes sense
and now I also see I actually misread one of the solutions in the book
thank you for the help :d
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Could I get help on question 14?
Four steel discs, each with radius 1 cm, are placed in a square frame as shown.
(a) Find the length of the sides of this frame.
(b) In order to brace the frame, a diagonal support is to be added to the frame. Find the length of this support.
(c) Find the length of material needed to build the frame, including the diagonal brace.
which part is troubling you?
I dont get how'd you find the length of the frame? Would I add the 1cm together or ?
and then apply pythag?
are you talking about part a or part b here or what
A
right
you don't need pythag for part a just yet
it is just visible that the side of the outer square is twice the diameter of each circle
half the circle
you're not only not answering my question, you're also wrong.
isnt the diameter just a straight line that goes through it?
"it"
in this case the circle
...
no, "a straight line that goes through the circle" does not describe the diameter.
and you still haven't answered my question:
what is [the length of] the diameter of a circle whose radius is 1cm?
2 cm
4cm
exactly
and for be would it be:
c^2 = 8^2 + 8^2
c^2 = 64 + 64
c^2 = 128
as its four wouldnt u double it for each side?
that sounds a lot better now
thank you, im sorry aha i just struggle to articulate what im thinking! thanks for the help
.end
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Imagine a gambling game, my probability of losing is 1/25, I have to play this game 10000 times. What is my probability of losing at least 240 times?
!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
1
How many ways can you lose 240 games out of 10000 games ?
My chance of losing each round is 1/25 (4%) im playing this game 10000 rounds. What is the probability of me losing at least 240 times in total?
Briefly chance of losing at least 240 out of 10000 rounds
Do you know what losing at least 240 games imply ?
it means all my money is gone
Lol. I meant what cases does it include.
Sorry im not a mathematician xD
I just want to ensure that you understand this:
Losing at least 240 games means that you lost 240 or more games.
Not exactly 240.
"Losing at least 240 games means that you lost 240 or more games." yes this is
not 240
is that clear?
yes
Good.
So we need this probability actually.
probability of losing exactly 240 games + probability of losing exactly 241 games + probability of losing exactly 242 games + ... + probability of losing exactly 10000 games
oh you better do it i'm not very good at math
Oh. I can't do it for you fully. I can only guide you.
probability of losing exactly 240 games + probability of losing exactly 241 games + probability of losing exactly 242 games + ... + probability of losing exactly 10000 games
Here, let's try to compute the first term i.e.
probability of losing exactly 240 games = ?
i found it as 0.67%
Yes, it seems like a very high number to me.
an ai
Woah. Lol
xD
Let's just do it via maths. I haven't computed it myself. So, i can't say if it's that or not with certainty.
Isn't the probability of every number between 1 and 10000 equal anyway?
like isnt the probabilty of losing 240 times and 241 times equal?
It is. But there are different number of ways for losing n number of games.
They are equal.
But you can lose 241 games in more number of ways than you can lose 240 games.
Oh i didnt know that
Think this way: Let's say you play 4 games.
How many ways can you lose exactly one game ?
4?
Yes
Either you lose the first one, or the second one, or the third one, or the fourth one.
I got it
Now, how many ways can you lose exactly two games?
It's 6.
yes
How are you getting two?
it was a misunderstanding nvm
Possibilities of losing exactly two games out of 4:
first and second
First and third
First and fourth
second and third
second and fourth
Third and fourth.
Thus 6 ways.
Okay. Good
So, we have established that there are different ways of losing 240 games and 241 games. Right?
Yeah thanks
Okay. Now, how many ways are there of losing 240 games out of 10000?
btw, i just noticed this. No, they aren't same. They could have been same if probability of losing or winning was same i.e. 50% each. But it's not in your question.
true
Also even if probability of losing or winning was same i.e. 50% each, they'd only be same if we disregard number of ways we can lose those many games. Which we dont.
So, technically, it's never equal by default.
yes.
So, basically, losing 240 games out of 10000 is like choosing 240 games out of 10000 which we'll then lose.
So, we need to see how many ways can we choose 240 games out of 10000.
Are you familiar with formula for choosing r objects out of n ?
formula looks better
Do you know the formula ?
no
Okay. Fine.
if i took too much of your time i can close the channel then i get help from someone else
or later
For, now i'll just tell you the formula. You can watch a video on it later and understand better.
no, we are almost there.
haha thanks
So, number of ways of choosing r things out of n is ${n \choose r}$.
Damn it.
I dunno latex well. Brb
Okayy
Enemagneto
Now,
$${n \choose r} = \frac {n!}{r! \cdot (n-r)!}$$
Enemagneto
This is basically the number of ways of choosing r things out of n.
@crisp moon Are you familiar with factorials ?
No actually im not familiar with complete maths
Umm... It's then almost impossible to do without that. Try watching a video on what factorials are.
Also what's number of ways of choosing r things out of n.
Ok then, i will save this chat, is there anything more to say about this ?
or will this chat help me
There's some more about the probability computation.
Okay, let's finish it then.
So, for now, we'll assume that number of ways of losing 240 games is some m.
Now, let's try to calculate probability of losing 240 games out of 10000 disregarding the order.
So, to lose one game - probability is 1/25.
To lose another game at top of that - probability = 1/25 * 1/25 = 1/(25^2)
Similarly for losing 240 games, it'll be 1/(25^240).
However, if exactly 240 are lost so rest 9760 must be won.
So, probability of winning 9760 games = (24/25)^(9760)
Now, probability of exactly losing 24 0 games(disregarding the order) = 1/(25^240) * (24/25)^(9760).
Taking the order into account, it is equal to:
$${10000 \choose 240} \cdot \frac{1}{25^{240}} \cdot \left (\frac {24}{25}\right )^{9760}$$
Enemagneto
woah
Okay probably i can do with a program, thanks now i can close the channel
thank you btw
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Doing practice papers for NSAA and I’m stuck on how to do these two questions. The first one I’m not even sure where to start and the second one I think you have to do the next term in the sequence subtract the current one to get an equation which I did but now I’ve got no idea how it’s going to end up as a/3 or a/sqr3
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This may be an easy question but from the script my professor provided i couldn't figure this out. I need to find the singular points of a curve (0 = f(x,y) so multivariable function) and classify them with the help of the Hessian matrix. I was working on an example, in which i found singular point as 0,0 and the
Hf(0,0) = [2q^2 0, 0 -2]
I of course researched about how to classify them (double points, cusps and hermits?) but somehow I couldnt find how. Could you kindly explain to me what should I do after setting up the Hessian matrix?
@quiet lynx Has your question been resolved?
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The diagonal light can rotate about the point
Doing some engineering with cams and a hinge so I want to know how to do this
If the parameters of the diagonal was 1
At 45° the red line is at 0.5 on the X axis
I can't decrypt what you've written on the paper
How does the height of follower (RED) correlate with theta
Is it's position on the x axis fixed ?
The only thing that is moving is the follower up and the diagonal line rotating
Does the follower move horizontaly ? Or Is at a fixed distance from the vertical line on the left
And what do you want ?
To know how the height of the follower correlates with the angle of theta
Do you have a length for the red Line ?
You're problem isn't really clear
Yes but to know which one I need to better understand the question
So with the red follower when it goes up it makes the thing on top rotate as it’s fixed to a point
But in it's initial state the red bar IS on the ground and 25mm in height right ?
Yea
To solve this you need the difference in x coordinate from the hinge point to where the red bar is
This IS a constant because neither one IS moving sideways
Yea
What do you know in trigonometry ?
Ok then you really need to make a clear drawing of you're problem (see how I needed to Ask a lot of questions to even understand what you were trying to tell me)
Okay
This should help you have a clear Idea any make a triangle appear on which you Can Do some trigonometry
Imma simplify this
Damn it’s easy to represent but putting it in its simplest form is hard
Wait I’m going to stop and try to understand how to represent this
So I will come back maybe in an hour
Wait I need to kill a spider
I killed the spider
And I think I have a bit of a better understanding
Here's a nice drawing with :
H : the fixed height of your hinge point
d : the fixed lateral distance between your hinge point and the red bar
L : the fixed length of the bar
and two variables x the height at which the bar is and theta the angle
Now you can see the blue triangle and do trigonometry in that
The key is to do a clear drawing
paint
I drew by hand
but use a sheet of paper that's better
So yea hopefully I can get a good cam toy
For my sister
So yea thx again
Now time to model
@dusty wigeon Has your question been resolved?
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im getting 100/21 for some reason
i got 21/31
oh hold up
.
u sure its a whole num?
do u have the sol?
nah bro i checked online too
the ans is 109/19
its decimal
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where'd the 3 go?
there is supposed to be a 3
bro chatgpt is wrong 💀 💀
chatgpt high
the ans is 109/19
where did the 3 go?
3(1-3x) = 3 - 9x
where the 3 at 💀
i did it 3 times u got me trippin
chatgpt wrong
haha
k so
dont multiply 21 w everything
take the lhs and take 21 as lcm
simplify ull get (52 - 23x)/21 = 7 - 2x
u can do it later too doesnt matter
now take the 21 there and ye multiply
look
what nah
google is dumb
hold on leme understand how to type this
proly some prof
k so
look just whatever u typed earlier
not everything
add a + 3 before the -9x
then simplify
because 3 (1-3x)
equals to 3 - 9x
multiply 3 with both terms
yes
wdym
what about the variable
"x"
ye
u write the varible as it is
2 into 3x is 6x
2x into 3x is 6x^2
multiply constants with constants and varibles with varibles
only the varible "x" is sqaure
because there are 2 "x"
bro
m into m?
yes
just an example
2m into 3m is 6m^2
what grade u in?
damn
cool
im surpsied this hasnt been taugh earlier
trust me the q u did is nothing 💀
u got me trippin fr
i was questioning reality
fr bru
aint no way i cant do some algebra 😭
have u learnt trigno
oh
the chart?
like angles
sin 45?
bruh
cool
i really like trigno
i doubt you know the basics
im trash at teaching literally search 2- (2x+1)/3 + (1-3x)/7 = 7 -2x on google
youll find every step easily
uh
about algebra
m^5/m^2
??
lol
what
tf u on bro
lmfao no
bruh imma sleep
gn
m^5/m^2 = m^5 - m^ 2 = m^5-2 = m^3
add me imma talk later
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is $e^{-{(x^2+y^2)}}$ and even function of x?
What I mean by even function of x is to treat y constant
{-x^2 + y^2}?
I mean, it clearly satisfies f(-x, y) = f(x, y)
i think they mean $e^{-(x^2 + y^2)}$
right so, clearly the I can use twice the integral property between -a to a right?
$\int_{-1}^{1} $e^{-(x^2 + y^2)}dx$
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$\int_{-1}^{1} e^{-(x^2 + y^2)}dx$
A Lonely Bean
Yeah sure you can use the property here
Where?
when i find the antiderivative
Antiderivative of e^(-x^2) is nonelementary though, what do you mean
Try differentiating $\frac{e^{-(x^2 + y^2)}}{-2x}$
A Lonely Bean
Does it give you the integrand?
Yeah, you can simple divide by the derivative of the inside only when the derivative is constant
That’s what i meant
are you xy probleming here
like this integral is very suspicious
where did you even get it from
Yeah I don't think you would be asked to evaluate that
Why do you think it’s non elementary?
this is a well known result
I can use substitution right?
it's not elementary, in the sense that people had to define a function for it, namely the error function
notice im differentating with fixed y
but the error function is widely available in software and its properties are well known, so it's not really any worse to deal with than say sin or cos
partial integral it is
if you express the exponential as a product, you can pull the y part out as it's a contant with respect to the integral
why do you need this integral
this doesn't have a good answer
thought to use even function property
well in 2 dimensions you want to respect the circular symmetry
but hit the wall
but you've made the domain of integration a square
so you're gonna have a hard time doing it by hand
,w integral -1 to 1 integral -1 to 1 exp(-x^2 - y^2) dx dy
erf is defined as the antiderivative of e^(-x^2) with some scaling factors
Its non elementary double integral ig
what suprises me, is the inner integral is possible when limits are -1 to 1 but not when 0 to 1
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what should be the aproach to this question
im stuck
also in the last step
the equal has 18
hm?
instead of doing ln do log2
oh?
alright i will try that
1 sec
OHH
Damn
thats it right?
so option (b)?
yeah cool got it
thanks
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i dont know how to start this question
physicsrocks
I believe they mean angles
yeah, my bad, sorry
LHS,if possible
ok i will try..
I'm jus thorwing ideas that may work, I've not tried it myself
understandable
Is the implication there that the equation is true for all values of a?
no, it's obviously not true when a=0. but I suggested that as the RHS iis purley in terms of cos(a)
Hmm ok
I've never seen a problem like this but I'd agree trig identities seems like a good first step
Also, are k, w, and p all supposed to be integers?
hm??
Cause it talks about factors, but it doesn't explicitly say
where did the 4 come from?
ah,ok
2cos a . sin a = sin 2a
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thanks
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how does this simplify to this
Modus
i suppose that makes sense
x-x/2 and if lets say x=5 then:
5-5/2= 5-2.5=2.5
5/2 = 2.5
yes, but
this is how it works, I mean for every x, even for the expression like -voy^2/g
well
is is the same if what we talk about is constant
5, 20, (17/200)^2 or -vy^2/g
or so i suppose
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I am confused on how they got the maximum value
I know for the minimum value, they just took the vertex
but how did they get the maximum value mathimatically
because it does not give me a graph
if the part of the graph given doesnt contain the vertex it would be the lower end of the arch
you just have the range of y value as the lower y of it and the upper y of it
however if the vertex is included only one side of the arch can be the maximum (or both be)
taking the coefficient of the squared term as positive that is
so the maximum value is just the 2^2?
what
I am as confused as you are
how did they get the numbers 4 and 6 for the maximum mathematically
or just take the two end points of the graph, plus the vertex if it's included in the range, and the lowest y and highest y would be the y bound over the range
I am not given coordinates
6 is the given x upper bound
you don't need the coords to do that you just have to plug in the bounds and the x for the vertex in the original function to get the y values
huh
im not given any numbers on my graph
wdym
its just a raw graph with a parabola
how would you ahve the graph if you dont have the numbers
and the graph is drawn with the information given
both the formula for the function and the range
for you to find the y range
let me take a photo
ok
yeah and?
I have no clue on how to get the maximum value
from the minimum value of a quadratic, either going to the left or to the right the value should always be increasing if the coefficient of the squared term is positive
so the maximum value can only be at one end of the x range or the other, given that the x range crosses the vertex of the quadratic function
the squared term is positive
yes
so you can just plug in the two ends of the x range into the original function to see which one is higher and that would be the value for the y maximum
mhm
and also you can look for which ever end is farther from the vertex
since quadratic graphs are symmetrical around the vertex vertical line and the farther end point from the vertex woulda grown higher
np
ohhh
wait this makes way more sense
so like 0 is 3 away from 3, and 5 is 2 away from 3, so 0 would be the bound other than the vertex bound
wait thats cool
:)
thank you for making math math
XD np
it's cooler when u'd be able to see it at calculus level
but thats not to be worried about for now
hf wiht math
I gotta worry about that next year 💀
XD
full IB
what year are u in
going into 10
sameeeee
nicee
thats cool
enjoy the rest of your day :)
u2 <3
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Doing practice papers for NSAA and I’m stuck on how to do these two questions. The first one I’m not even sure where to start and the second one I think you have to do the next term in the sequence subtract the current one to get an equation which I did but now I’ve got no idea how it’s going to end up as a/3 or a/sqr3
@buoyant mirage Has your question been resolved?
No
hi. what happens if the function starts decreasing within the small interval you’ve given it?
for the second one that is
you’ve said, well, the function increases if f(x+1)-f(x)>0, which is somewhat going in the right direction, but it leaves room for error
if you’re allowed to use calculus, it becomes trivial. Think of the derivative
now for the first one. try to establish a relationship between L and m, and p and M. Then you can try applying the fact that LM is 5 units long
Ok thanks!
Thanks I got the second one now
Why is great than or equal though and not just greater than?
probably just their definition of increasing
Weird
funny thing, I once got into a (verbal) fight with a teacher regarding exactly this
How?
in the exam he asked a question which asked for the exact same thing that you’ve been asked (different numbers)
It was a mcq. One of the choices included the endpoints, and the others didn’t. I picked the one that didn’t, and he claimed I was wrong
and I was extremely salty, it was the only question I got wrong. I took it up with him because he never set a definition for increasing properly in class
it doesn’t make sense for something to be increasing when it literally doesn’t increase or decrease at all at that point (f’=0) (to me, as I mention below, different people have different definitions)
but yeah
different book/curriculums/teachers have different definitions
it’s good this mcq you have doesn’t include both the endpoint included/not included though. Doesn’t leave room for questioning
anyways, I digress
Have you thought of a way for the first one
@buoyant mirage Has your question been resolved?
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What are the key features of radical functions
Im not sure what they are
like if there is a domain, range
asymptote
max min
mud please man
you got this
help
a radical function is a function containing an nth root
take the square root of x for example
sure
but for quadratic
which isn't a radical function
not really
So what would be the awnser for this
what's the radical function?
can you take a picture of the entire question?
ok
Task Goal: To demonstrate your knowledge of the functions you have investigated in this course.
Throughout this course, you have looked at the key features of a variety of functions, including quadratic functions, radical functions, reciprocal functions, exponential functions, and sinusoidal functions.
In this task, you will be demonstrating your knowledge of each of these functions by completing this Functions template. Make a copy and once completed, download the files as a PDF.
Complete the template for each functions using the linear function y=mx+b as a model.
so basically, function, representations, key features, and description?
have you seen what a radical function looks like?
mind showing them?
what are the key features
there's always going to be a domain and range for a function
no
if it is bigger than zero
for 0?
ya
like x^0?
Thats expo
sorry, i misunderstood your previous statement
a zeroth root is not defined
yep
the range depends on costant c right?
since it moves the graph up and down
so it's also limited
y
yer with the restrcition of y bieng smaller or equal to 1
yes
x+d
domain for this?
yes
just one more thing: the domain also depends on the sign of x
so besides domain and range...
yep
for even roots
?
there's only a domain and range restriction for even numbered roots
more like this
hm
you know how a radical can be rewritten into the radicand and a fractional exponent?
ya
Btw you wouldn’t write xER for this one
what would i replace it with
just x>=-3 works
^
because xER implies the domain exists for all real numbers of x
oh it isn't
nope
Like are you asking what functions would have the domain of all real x?
a radical can't ever be xer
it would
so there is no yER
you can see how the domain doesn't exist when x is negative
since the function doesn't exist there
alright
I fixed it
Do we have any more key feature or can we move to the reciprocal functions?
i can't think of any more you can put...
alright
which asymptotate are you talking about?
the vertical or the horizontal asymptote
just specify that
yes
Btw just a thing to note that reciprocal functions also have the domain where x cannot be 0
ya
depends
for this graph, x could be zero
True
I’m just thinking of the form 1/x where you cannot divide by 0
ah yes
Asymptote- A reciprocal function has an asymptote meaning that there is a restriction that the line will never reach a certain number.
Horizontal asymptote - The horizontal asymptote depends on the value of c since the value of c is the horizontal asympotote.
This is what I wrote so far
c?
ya
which variable shifts the graph left and right?
oh I didnt read the first half
mb
i thought you said what variable is that
ah
the verticle one depend on the d value
ya
Vertical asymptote - The vertical asymptote depends on the value of d since the value of d is the vertical asymptote.
the value of x = d
ya
basically just say
the vertical asymptote is a line where x = d
and the horizontal asymptote is a line where y = c
just a suggestion though, i'm not sure how your teacher would want it
let's start on domain
the x values
for the domain
x exists everywhere except for one value
So xer with a restriction
ya
since the only restrictions are the asymptotes
yep
same could be said for the range and the horizontal asymptote
Cant I just write this
Domain: X can be all real numbers beside the value of the horizontal asymptote.
Range: y can be all real numbers beside the value of the vertical asymptote.
that works
Is that all
instead of saying beside, try saying except
that should be all
ok
it should be
yep so domain
and range will be pretty similiar to the radical one
just vise versa
right
but?
okay
???