#help-0

1 messages · Page 269 of 1

sharp sail
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and yea if t=0, dy/dx just equals 0

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Sorry for confusing you again

tender anchor
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no worries thanks for ur help

sharp sail
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you can ask for help for part b though

tender anchor
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i figured it out

sharp sail
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great

tender anchor
#

had to make it so denominator was = to 0 so its undefined so i made 3t^2=243 and solved for ts -9 and 9

sharp sail
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nice

tender anchor
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yu

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alr imma close it thanks

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.close

lone heartBOT
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worldly ermine
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help me with the second one, I tried conjugate multiplication but It kinda hard since I cant get 1 - cos^2

lone heartBOT
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@worldly ermine Has your question been resolved?

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meager terrace
lone heartBOT
meager terrace
#

Hello, this is a calculus 1 course and we are learning displacement functions, velocity and accleration. I have provided one definition for the -35km/hr but I'm sure of what a second would be. Anyone have any ideas?

tight locust
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this seems unclear

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there's only one definition of velocity, not too sure what they want you to do here

meager terrace
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i know it makes no sense

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maybe it's the accleration ? like it's velocity is slowing with respect to time?

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but accleration would be time squared. i think

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teachers give no help because it's an online class as well

austere lagoon
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The negative sign indicates that the vehicle's direction is opposite to the reference direction. the vehicle is moving in the opposite direction of the positive direction

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both seem similar

meager terrace
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Yeah, I provided that as one of the two ways it can be interpreted.

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or maybe my explanation is actually two

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back towards the origin and a movement in the negative direction (opposite of ref)

austere lagoon
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its certain that the only thing it means that its displacement is decreasing

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u just gotta say that in two diff ways

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idk what that

meager terrace
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hmm, okay. thanks for the help.

lilac condor
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maybe they want m/s?

lone heartBOT
#

@meager terrace Has your question been resolved?

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scenic wing
#

are the two triangles produced attached to each other do they exist at the same time or do they exist separately

lone heartBOT
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@scenic wing Has your question been resolved?

fair cobalt
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Basically there's two ways to build a triangle with those measurements. There's not necessarily any connection, it's just two distinct possibilities.

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Either shape works.

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thick lynx
#

Show that for any functions $u, v$ and $w$, $u \circ (v \circ w) = (u \circ v) \circ w$.

thick lynx
wind flax
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u(vow) = u(v(w))
u(v)ow = u(v(w))

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not really much to prove here imo

thick lynx
wind flax
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just use your text book's definitions if you want to make it more rigorous

worn fox
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writing something like u((v(w))) doesn't really make sense, you want to just evaluate each at a general point in the domain, you will essentially get the same thing but just makes sense when applied to an element

thick lynx
worn fox
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like you want to write what $(u \circ (v \circ w))(x)$ means

ocean sealBOT
worn fox
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$u \circ (v \circ w)$ is the name of a function and so if you want to see if its equal to another function you have to see what it does to things in its domain

ocean sealBOT
thick lynx
worn fox
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you've basically already done it you just left out the application to an element

thick lynx
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$u \circ (v \circ w) = u((v(w(x)))) = u(v(w(x)))$.

worn fox
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you need to be applying it to an element from the start

thick lynx
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Oh

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$(u \circ (v \circ w))(x) = u((v(w(x)))) = u(v(w(x)))$

worn fox
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right and then carry on by undoing what you did but in a different order so that you get the other composition

thick lynx
worn fox
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your first step should be $(u \circ v)(w(x))$

ocean sealBOT
thick lynx
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Oh

worn fox
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because again writing something like u(v) in isolation doesnt make sense

thick lynx
worn fox
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yes exactly

thick lynx
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Thank you!

#

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hybrid ivy
#

hey guys,
i have this hw question that i cant seem to figure out, just wondering if i can get some help

hybrid ivy
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i am unsure how to get the correct answer

raven rover
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(number in degrees) * pi / 180 = (number in radians) @hybrid ivy

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In other words, 180 degrees = pi radians

hybrid ivy
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ive been trying that

worn fox
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it already has the pi there for you

hybrid ivy
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the website says this is the asnswer

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and idk how it got this

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since im getting a different asnswer

worn fox
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use the formula, and enter the part without the pi

hybrid ivy
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ohhhh

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Thank youuu!!

lone heartBOT
#

@hybrid ivy Has your question been resolved?

lone heartBOT
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quick moth
lone heartBOT
quick moth
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Hi can someone work me through the first steps to working this out

finite flax
quick moth
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Thanks

finite flax
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"converse of corresponding angles postulate"

quick moth
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I still don’t understand

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I need someone to run me through it please

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@mellow saffron

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Mb

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<@&286206848099549185>

finite flax
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where are you stuck

quick moth
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With that first step

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I need someone to run me through it

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Because IXL is different to what he does

finite flax
quick moth
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yeah

finite flax
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they told you it is equal to the radius of the circle

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so you should have a tool

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that draws arcs or circles

quick moth
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Yeah

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Like this?

finite flax
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ok, draw a line from the circle center to one of the points

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that will be the transversal

quick moth
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Meaning it’s wrong

finite flax
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undo all that

quick moth
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Ok

finite flax
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start over

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draw a line from A to either B or C

quick moth
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Ok

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Done

finite flax
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show me.

quick moth
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Thanks bro

finite flax
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you didn't start over

quick moth
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I did

finite flax
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why is there so much junk here

quick moth
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It’s the answer

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I did the 2nd part

finite flax
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ok

quick moth
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It was 😑

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Wrong

finite flax
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you are confusing me

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are you done or not

quick moth
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No

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I got it wrong

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The question now

finite flax
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ok, same thing

quick moth
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The first step?

finite flax
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STOP IT

quick moth
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Mb

finite flax
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if you aren't going to listen I will leave

quick moth
finite flax
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I have better things to do

quick moth
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Ok

finite flax
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Start over and draw a LINE through AC or AB

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not a circle.

quick moth
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Ok

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Like this

finite flax
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alright, that is your "transversal" line.

quick moth
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Ok

finite flax
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now, construct an arc (or circle, if you must) centered at point C and passing through point B. This arc (or circle) will have the same radius as Circle(A)

quick moth
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Like this?

finite flax
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yes

quick moth
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Ok

finite flax
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...

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in fact, this step might be extraneous since you begin with a circle whose radius is equal to the distance between B and C

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anway

quick moth
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finite flax
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draw a point where line AC intersects circle A

quick moth
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How?

finite flax
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you havea tool called "segment"

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use that

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oh, sorry

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Point

quick moth
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Ok

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Like this?

finite flax
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no

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that is where AC intersects circle C

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anyone could make that mistake

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also, we don't need the first circle, sorry

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start over

quick moth
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Ok

finite flax
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this only needs two steps I think

quick moth
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Ok

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So…

finite flax
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when you start over, draw the transversal again

quick moth
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Ok

finite flax
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the line.

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then, where the line intersects the only circle you have, copy the circle at that location. Draw a point there first if you are required to.

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show me when you are done.

quick moth
finite flax
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good

quick moth
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Ok

finite flax
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now draw the point D where the circles interect ABOVE line AC

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then draw a line through AD.

quick moth
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Like this

finite flax
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yeah

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that doesn't look right though, huh

quick moth
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Yeah

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I’ll try any way

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Yeah it was wrong

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This seems complicated

finite flax
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I kinda see where the problem happened

quick moth
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Ok

finite flax
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start over, draw the transveral again

quick moth
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Ok

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Done

finite flax
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ok, construct a copy of this circle where AC intersects circle A, in the LOWER LEFT area

quick moth
finite flax
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why is it so much bigger

quick moth
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Idk

finite flax
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also that is the wrong place

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I will show you in voice chat

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I'll find some paper

quick moth
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Just show picture or something

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I can’t vc

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Otherwise I’ll get the beating of my life

finite flax
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oh, well I mean you don't have to talk I guess

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ohhhh...I see. ok

quick moth
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Yeah….

finite flax
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I'll try to post the steps then

quick moth
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Thanks

finite flax
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I only have a quarter and an envelope so I found the centers of these circles

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Which are just traces of the quarter

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Ok, let's draw transversal AC

quick moth
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Ok

finite flax
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Now, I need an arc centered at A, but I already have that from Circle A

quick moth
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Yeah

finite flax
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Now I draw a point D where line AC intersects Circle C:

quick moth
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K

finite flax
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Also point E:

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Now I need to sweep an arc centered at E with radius BD through circle A...using a compas...which I don't have.

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BUT

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I can copy that radius length BD to my envelope:

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And construct point F:

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...and draw a line through AF

quick moth
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This wouldn’t work in IXL and I can’t tell u why because I don’t know

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So I’m just gonna leave this one

hollow jackal
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what tools do you have?

finite flax
finite flax
quick moth
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Thanks I guess?

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U could of left at any time ?

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Your not forced against your will to be here

hollow jackal
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he's saying he went through the effort to show you how to do it and you still give up

finite flax
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@quick moth Constructions are either the most fun or least fun you will have in math but if you can understand even a little bit of it you will be in good shape for two very challenging units.

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so please don't give up.

lone heartBOT
#

@quick moth Has your question been resolved?

lone heartBOT
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brazen berry
#

Lin Alg 2:

lone heartBOT
brazen berry
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I'm wondering what i did wrong for matrix B?

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Is it because one of the entries is 0?

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I worked it out and this solution should work but maybe im forgetting some theory

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i'll work on a different solution while i wait

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hmmmm

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another solution i tried didnt work upon entry but works when i work the math out

lone heartBOT
#

@brazen berry Has your question been resolved?

brazen berry
#

i think there may be something wrong with the question.

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prof posted earlier saying an error with it was fixed but who knows

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scuffed ahh class

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our syllabus link redirects to assignment 2 💀

lone heartBOT
#

@brazen berry Has your question been resolved?

lone heartBOT
#

@brazen berry Has your question been resolved?

echo socket
#

,w characteristic polynomial of {{39, 36}, {2, 1}}

echo socket
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,w characteristic polynomial of {{-6, 0}, {43/8, 17/8}}

echo socket
#

Yeah, doesn't happen to match up though

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Oh, wait, phi doesn't get you the characteristic polynomial here, right

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My bad

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Wait let me check

echo socket
brazen berry
#

weird.

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thx for the reply

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glad to know im not crazy

brazen berry
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grave eagle
#

yo

lone heartBOT
grave eagle
#

im trying to prep for the sat

tight locust
#

lol

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URL fail!!!

grave eagle
#

Join Huzefa as he shares the secrets to getting a perfect 800 on the SAT math! After earning an 800 on the math sections of three official SATs, studying and tutoring for the SAT for 6 years, and dissecting past practice and official tests from the College Board meticulously, Huzefa has unearthed 13 critical strategies to help eager students ach...

▶ Play video
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this guy

tight locust
#

how embarassing!

grave eagle
#

at 20:20

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ik man

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epic fail

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at minute 20:20

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he divided $60x<270$

ocean sealBOT
grave eagle
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and did not flip the sign!!!!!!

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dont you flip the sign when you divide/mutliply?!??!?!

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(both sides)(

tight locust
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let me show you an example

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do you agree that 2 < 3?

grave eagle
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yes sir

tight locust
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ok

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what if we multiply both sides by 2?

grave eagle
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ok i see what you mean here

tight locust
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then we get 4 < 6

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is that still true?

grave eagle
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so the rule i sa lie?

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is a lie

tight locust
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not quite

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now let's take the original statement 2 < 3

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this time, let's multiply both sides by -2

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then we get -4 < -6

grave eagle
#

ohhhh

tight locust
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is that true?

grave eagle
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its only when negative?

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only when u flip signs

tight locust
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yes. you only flip the direction of the inequality when you mulitply or divide by a negative number

grave eagle
#

thanks

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.close

lone heartBOT
#
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viscid coral
#

How do I find inverse cos of -0.2 on casio calculator? I typed in cos -1 (-0.2) by pressing shift and cos then -0.2 but it gave me 101.53... instead of the value i want 1.7721...

nimble latch
#

change into radian mode

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usually with shift+mode

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and select the radian

viscid coral
#

I got it!

viscid coral
#

.close

lone heartBOT
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vapid steppe
#

does $\lim_{x\to \infty}{x-x}$ equal zero or indeterminate

ocean sealBOT
#

jashxdlol

vapid steppe
#

cuz if u do direct sub u get ∞-∞

tight locust
#

well why don't you try simplifying

naive valley
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it equals zero, because x-x equals zero for every x

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so you are seeking $\lim_{x \to \infty} 0$

ocean sealBOT
vapid steppe
#

but like if you split up the limit you get lim as x→∞ of x minus limit as x→∞ of x

tight locust
#

if you want a cool limit that involves a subtraction then try taking the limiting difference between the integral of the logarithm and the trapezoidal approximation

naive valley
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signal violet
#

how do i do this?

lone heartBOT
tight locust
#

Yea

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Looks like a cube root function

signal violet
#

im just not sure how to like

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hit all the points

nimble latch
signal violet
#

uhh

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so

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helpu pls

fathom harness
#

y = a(x-k)^(1/n)
0 = a(1-k)^(1/n)
=> k = 1

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y = a(x-1)^(1/n)
-3 = a(-1)^(1/n)
=> a = 3

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y = 3(x-1)^(1/n)
6 = 3(8)^(1/n)

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2 = 8^(1/n)

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@signal violet hey done

signal violet
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uhhh

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lemme read through this

fathom harness
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I'm starting with assuming the general equation, y = a(x-k)^(1/n)

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Then using the different points and plugging in their values, I find their possible values.

clever coral
#

Hii can anyone explain me what's rational

fathom harness
clever coral
fathom harness
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p and q have to be integers

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So like

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1 is rational because it can be written as 1/1

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69 is too

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Because 69/1 or 138/2

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But

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A number like √2 is not rational

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You can try any combination of p/q

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But it's value will never exactly be √2

fathom harness
clever coral
#

Ohh

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Oh wait

clever coral
fathom harness
clever coral
fathom harness
#

I mean combination for which number? π?

clever coral
#

"You can try any combination of p/q" like try any combination what does it mean😭

fathom harness
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Oh lol

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Like let's say someone gave you the number 6.999999...

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... means the 9 keeps on repeating

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And asks you to find whether this number is rational or not

clever coral
#

Ohhh

fathom harness
#

Wait 1 moment

clever coral
#

Sure

fathom harness
#

That was a bad example 💀

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Let's take a new one

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Let's say someone gives you the number 3.25

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And asks you to figure out whether this is rational or not

clever coral
#

Yeah

fathom harness
#

First of all

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What do you think?

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Is it rational or not?

clever coral
#

Idk??? Aren't you supposed to tell mez_nickistop z_nickistop

fathom harness
#

Nope

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U make a guess

clever coral
#

I think it's rational ig

fathom harness
#

And why

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What was the reasoning behind that guess

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Don't say randomly chosen

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🔫

clever coral
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I said it because it has two digit..

fathom harness
#

Lol

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Actually its a good reasoning

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Any number with finite number of digits is rational

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Cuz

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3.25 is the same as 325/100

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We can see that it is in the form of p/q

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So it must be rational

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What about numbers with inifnite digits tho

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Like

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3.333333...

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... means the decimal part keeps on repeating

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here we can do a little bit of guess work

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10/2 is 5

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Nope too big

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@clever coral I actually have to go now

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Got an urgent call

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I'll just finish this one and then go

fathom harness
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,calc 10/4

ocean sealBOT
#

Result:

2.5
fathom harness
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Meh didn't work

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10/3

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,calc 10/3

ocean sealBOT
#

Result:

3.3333333333333
fathom harness
#

Eeee it worked

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So we know that 3.33333... is rational as well

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Generally

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Any number with finite number of digits

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Or

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A repeating pattern

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Is rational

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3.333... has a repeating pattern

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Even 3.5656565656... would be rational

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Make a guess yourself how

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But something like 1.262861718816868198162.... would be irrational

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There's no repeating pattern

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Obviously the math behind how to know whether a number is rational or not

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Is a not just guesswork

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But guesswork is a good step if you are a beginner

clever coral
#

Hii my wifi die for a second

fathom harness
#

I got a call as well lol

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Anyways, gtg now.

clever coral
#

Alr byee tyy

fathom harness
#

Ttyl!

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@signal violet did you understand my answer?

#

If not, then :p
Ping the helpers role

signal violet
#

i found how to get it but like

#

im not sure in terms of like a step by stpe

fathom harness
#

I gave you all the steps tho

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rotund crater
#

why is zero

lone heartBOT
vale wigeon
#

Since ln(y) is constant with respect to x,

clever coral
thorny patio
#

A better question is how to find or figure out something is irrational

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empty spade
lone heartBOT
empty spade
#

,rotate

ocean sealBOT
empty spade
#

so I got these 6 equations by labeling the unknowns in the pic but idk what to do from there

quick moth
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#

@empty spade Has your question been resolved?

empty spade
#

<@&286206848099549185>

#

after adding the first five equations i get

2000 + 5c + 2d + 2e + a + b = 3(a + b + d + e + 1000)

and using the sixth equation
2000 + 5c + 2d + 2e + a + b = 18c
which can be further simplified into
2000 + 2d + 2e + a + b = 13c

#

correct me if im wrong

fading comet
#

<@&286206848099549185>

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west girder
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west girder
#

Can I have a hint

austere lagoon
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cyan valve
#

how do i turn this into a graph on google sheets

cyan valve
#

pls help

shut pewter
#

Just select the data you want to create a graph with

#

It's called chart in google sheets

lone heartBOT
#

@cyan valve Has your question been resolved?

cyan valve
#

uhh

#

hold on

#

so i drew my results on a line graph

#

and plotted the avgs

#

and this is what it looks lole

#

do i draw the trend line

#

@shut pewter

#

i changed the incrmements

#

i went up by 2

shut pewter
#

I mean if your research is all about trends

#

You can use any charts, but if this is a trend for the number of plies and number of water absorbed, then you can use line graph

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alpine sable
lone heartBOT
alpine sable
#

Im stuck

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@alpine sable Has your question been resolved?

alpine sable
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<@&286206848099549185>

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@alpine sable Has your question been resolved?

ocean sealBOT
#

kebesque

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alpine sable
#

could someone explain the process to answer

mellow grail
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mental hearth
lone heartBOT
mental hearth
#

i did not understand this step

#

can someone help

echo socket
#

Well, could you explain what |x| denotes?

mental hearth
#

so it will return the positive value of input

#

on removing the sign it may give a +ve or -ve

echo socket
#

Right, so |x| = x if x is positive

mental hearth
#

inside

echo socket
#

And |x| = -x if x is negative

mental hearth
#

and its also x if x is -ve

#

how

echo socket
#

These two cases insure |x| is always nonnegative

mental hearth
#

mod of -2 is 2 right

echo socket
#

Yes

#

And -x is 2 when x is -2

mental hearth
echo socket
mental hearth
#

ohhhhhhh

#

like thattt

#

i get it now thank you

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warped topaz
lone heartBOT
warped topaz
#

I know how to solve these kinds of questions once I have an idea of how to rearrange it but im not really sure how to rearrange this one

#

I dont know any formulas for cos or sin to the 3rd power, and if I make it sin(x)sin^2(x) or something like that I will have 1 sin or cos left over, so I wont be ale to do u-substitution

#

(sin(x)) (sin^2(x)) (cos^3(x))
(sin(x)) (1 - cos^2(x)) (cos^3(x))
But then I still have 1 sin right?

#

So I cant substitute u

#

Nvm I got it

#

Thank you!

#

❤️

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.close

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tender anchor
#

I gotta use L’hopital rule for
lim x->1 (x^3-1)/(x-1)

tawny crown
#

Not necessarily

tender anchor
#

does it start out like 3x^2 / 1

tawny crown
#

You can factorise x³-1

tender anchor
#

o my prof wants me to do it using the rule it’s the unit we’re learning

tawny crown
#

Ah I see

#

Do you know u/v rule then

tender anchor
#

u/v?

tawny crown
#

Quotient rule

#

Of differentiation

tender anchor
#

yeah

upbeat hornet
tender anchor
#

yeah it’s 3

upbeat hornet
#

Has your question been resolved?

tender anchor
#

yes thanks guys

upbeat hornet
#

.close

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fallen verge
#

Testing something, i do not need help

lone heartBOT
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fallen verge
#

Interesting

echo socket
#

!status

lone heartBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
fallen verge
#

D:<

long solstice
#

lol

worn fox
daring totem
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bronze ridge
#

I'm doing some repetition questions in linear algebra and I have some minor questions regarding injective transformation matrices. Namely, what is the preferred way to check if a given transformation matrix A is injective or not? The method I've used involves solving for Ax = 0 and verifying that the only allowed solution is x = 0 (0 vector that is). However, by doing this, am I really verifying that the transformation is injective? Because checking for Ax = 0 only checks the trivial solution, what about the other ones?

I guess the bulk of the question is if the method I described works reliably and in that case why. Also, if there exists alternate ways to check if a transformation is injective.

vale wigeon
#

However, by doing this, am I really verifying that the transformation is injective? Because checking for Ax = 0 only checks the trivial solution, what about the other ones?

waxen osprey
#

its coz its linear

#

its fine

vale wigeon
#

Av = Aw is equivalent to A(v-w) = 0

waxen osprey
#

ker=0 means a linear map is injective

vale wigeon
#

it is an easy exercise to verify that a map is indeed injective if and only if its kernel is trivial

bronze ridge
#

So in other words, if the null space consists of only the null vector, then the transformation is injective? That's the way I understood it at least

waxen osprey
#

yes if the transformation is linear

bronze ridge
#

Ah, right

#

Now I get it, because it wouldnt be linear if the origin shifted

pine fractal
#

how can i prove: degree of p(x)=n, p(x)*(p(x)+2)=0 at most (n+2) root , where p(x) belong Z[x] integral coefficient

bronze ridge
#

.close

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#
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alpine sable
lone heartBOT
alpine sable
#

Could anyone please confirm if I did this correctly? I'd appreciate it.

#

Q is to find the line integral

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

<@&286206848099549185>

zealous lichen
#

I think you parametrized the curve in the opposite direction

alpine sable
#

Oh I was confused about that, should I use pi/2 to 0? (I thought we go from min to max value)

zealous lichen
#

or just multiply by -1 not to do all the work again

alpine sable
#

Oh okay will do that, thank you so much!!

zealous lichen
#

wait it shouldn't be negative on line 2

alpine sable
#

Um

#

Where, sorry can't find

zealous lichen
#

-cost(sint)^3 on the circular curve

alpine sable
#

Oooh

#

Yess

#

I'll fix it, thank you so muchhh!

alpine sable
#

.close

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alpine sable
#

Hi, I have to find and sketch the domain of the given function

Function is : 1/(x+1) + 1/(y-1) + 1/(x+y-z)

alpine sable
#

I have found the domain which is x+1=/0
y-1=/0
x+y-z=/0

#

But I'm not sure how to sketch this

#

Can anyone please guide me?

#

Should I make like a 3D plot with these planes

#

And shade the outer area?

#

But that's very complicated

tardy stag
#

sketching something in 3d seems very complicated

#

especially something like that which is basically the whole universe minus some planes

alpine sable
#

Yes, is there any other way?

#

To go about this question

tardy stag
#

are you sure that this is a function of 3 inputs? and not two?

#

your domain seems to be right

alpine sable
#

Yes it is f(x,y,z)= that stuff

tardy stag
#

huh

#

i guess i would sketch the planes that cut out the domain

#

and just say "everything except these"

alpine sable
#

f(x,y,z) = 1/(x+1) + 1/(y-1) + 1/(x+y-z)

#

Oh

#

Okay, I'll do the same then, thank you so much!

lone heartBOT
#

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left nimbus
#

How can the derivative of an integral be equal to the function? For example, if v(t) describes the velocity of an object with respect to time, then shouldn’t the rate that the area increases by be equal to v(t)*dt?

left nimbus
#

Wouldn’t it be better to say that the derivative of an integral is proportional to the function instead of equal?

echo socket
#

By definition they are equal

left nimbus
#

So they just… defined them that way?

echo socket
#

Unless you are defining with the Riemann sum, then it's not immediate

left nimbus
#

What do you mean?

#

I’ve seen the mean value theorem proof of the ftc, it’s just weird how the rigorous definition doesn’t really match with the concept to me

echo socket
#

Proof using ftc you mean?

#

There's no proof of FTC catThink, it's a set of axioms

#

Which definition are you talking about btw

peak bough
echo socket
#

hmmCat Then I need to look into how the connection between antiderivatives and areas under the curves was discovered

#

Although yeah Riemann sum is more natural as a definition

left nimbus
#

I was talking about the first one, where F(x)=integral from a to x of f(t)dt (sorry I don’t know TeX)

#

But really I’m trying to figure out how d/dx(integral of f(t)dt) = f(x)

echo socket
#

Uh there's a video of 3b1b explaining that in an intuitive and visual way

left nimbus
#

Yeah I saw that

peak bough
left nimbus
#

Ok, it was just weird conceptually to me

#

Integral of a derivative makes more intuitive sense somehow

#

ig it’s easier since I can think about adding up velocity * time over an interval

peak bough
#

I also saw a "proof" a few years back using the squeeze theorem if an area function for a given function exists (the existence is not part of the "proof", sadly), then its derivative is the given function. The proof didn't really connect it with any formal integral-definition, so the proof moreso gave a connection between direct area and the derivative of an area function. It also heavily relied on the given function to be strictly monotone, so it's very restrictive.

left nimbus
#

Ah ok

#

Well I appreciate the help anyways

#

.close

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arctic salmon
#

How do i justify that (-1)ⁿ doesn't have a limit?

worn fox
#

find two convergent subsequences that converge to different values

vale wigeon
#

it alternates between -1 and 1

#

where do you think it approaches

alpine sable
#

Verify the boundedness and monotonicity of (-1)^n

arctic salmon
#

K

#

.close

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#
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worn fox
arctic salmon
#

Thanks for the help ! I appreciate it !

lone heartBOT
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limpid shore
#

Let $m$ be any good old integer. Let $p<0$, then if $m2^p$ and $(m+1)2^p$ are not integers, how come $N=\lfloor m2^p \rfloor=\lfloor (m+1)2^p\rfloor $?

ocean sealBOT
#

sunside_

vale wigeon
#

what is p

limpid shore
#

sorry, $p$ is also an integer

ocean sealBOT
#

sunside_

vale wigeon
#

ah.

#

was about to present a counterexample

#

so letting n = -p for convenience

#

you're asking why m/2^n and (m+1)/2^n don't have an integer between them

limpid shore
#

I believe that's correct

vale wigeon
#

i believe it might not even matter that the denominators are powers of two here lol

#

but i have taken up the letter n. oops

#

m/r < k < (m+1)/r would mean m < kr < m+1 which cannot happen for m, r, k ∈ Z

limpid shore
#

Thank you for your help, I think I got it now : -)

#

.close

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#
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deep ember
lone heartBOT
surreal meadow
#

let 3t = x

deep ember
#

i know this equals one using the (sin^2t + cos^2t)=1 theorem but in this case im confused as to where 3 goes

surreal meadow
#

sin^2x + cos^2x = 1

vale crag
#

you're focusing too much on the symbols

#

sin^2(something) + cos^2(something) = 1 for any something you put inside

#

even if it's 3t it doesn't matter

#

it's still true

deep ember
#

ahhh okay, so its a general rule that if it falls within that identity, it doesnt matter what value is x right

surreal meadow
#

the t in "sin^2t" is arbitrary on purpose

#

it could be t

#

it could be 1

#

it could be 3x

#

it could be anything

deep ember
#

ahh thank you! :)

#

.close

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stuck mountain
#

hey

lone heartBOT
#
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rotund crater
#

how i can solve this ?

lone heartBOT
rotund crater
#

nvm thats not

#

these exercices 35-36 how i can solve that

worn fox
#

you would want to start by finding y'

rotund crater
#

after

#

?

rotund crater
#

what i need do?

alpine sable
#

You can fill in the x-coordinate to get the slope

#

After that you can find the b in y=ax+b because it has to go through (1,0)

lone heartBOT
#

@rotund crater Has your question been resolved?

rotund crater
#

x-1

#

but

#

But how i can calculate ln or log without calculator it is posible?

blissful temple
#

using log tables

rotund crater
#

oh

#

to get m_(x) i need choose the x-coordinate?

rotund crater
alpine sable
#

You need to find the equation of a line

#

A line is of the form y=ax+b

alpine sable
rotund crater
#

can illustrate me?

alpine sable
#

Wait is x-1 your answer for the question a?

rotund crater
#

i aplly y-y_1 = m(x - x_1)

alpine sable
#

Did you already find the slope of the tangent line?

rotund crater
#

humm yes

#

is m_x = 1

alpine sable
#

Yes

rotund crater
alpine sable
#

I dont really know how to explain but its just the rule.
The steps for solving the equation for a tangent line to the function f(x) at point (A,B) are:
Find the derivative f’(x).
Plug x=A into the derivative.
The answer is the slope of the tangent line.
Set equation of tangent line to y=ax+b.
You already solved for a (the slope).
Now plug x=A and y=B into the equation of the slope.
Solve for b.
Now you have the equation of the tangenr line

rotund crater
#

always is y=ax+b?

alpine sable
#

Yes thats the general equation for a line

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Just like a parabola is y=ax^2+bx+c

rotund crater
#

thx for the help

lone heartBOT
#

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tranquil osprey
#

if we have 4 casino chips, and 3 of those are prime numbers (2, 3, 5, 9)
how do we calculate the probability of getting two chips, picked randomly, and both of them being prime numbers?

tacit arch
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9 is not a prime

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Nor is 1

lone heartBOT
#

@tranquil osprey Has your question been resolved?

tranquil osprey
lone heartBOT
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tranquil osprey
#

.reopen

lone heartBOT
#

tranquil osprey
#

<@&286206848099549185>

foggy copper
#

that's selection without replacement, right?

tranquil osprey
#

yeah i think

foggy copper
#

in that case you'd want the odds of not picking a prime on the first draw times the odds of not picking a prime on the second draw

tranquil osprey
#

no

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its 1 draw

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1 draw of 2 things

foggy copper
#

mathematically it makes no different

tranquil osprey
#

we want a pair, and we want to calculate the percentage of that pair being composed of 2 prime numbers

foggy copper
#

*difference

tranquil osprey
foggy copper
#

you're just doing draws one and two simultaneously

foggy copper
# tranquil osprey really?

could you explain the difference between drawing two things at once and drawing one thing after another if no replacement occurs, mathematically speaking?

#

ig you could model all the different pairings but it really makes no difference for the question of "is either of my chips prime"

tranquil osprey
#

the odds of not picking a prime on the first time is 1/4, correct? that's 0.25
the odds of not picking a prime on the second draw would be 3/3 because there is nothing but primes left, so 0.25 x 1 x 100 = 25%

#

im trying to follow ur logic but i may have followed it wrong

foggy copper
#

no

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if you didn't get a prime on the first then your odds of a prime on the second are 1/3

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but what you want is the odds of not failing to choose a prime every time

#

which is 3/4, and then 2/3

#

do you see

tranquil osprey
#

3/4 would be if we wanted primes

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which we do

#

but u said "not wanting"

#

im confused?

foggy copper
#

we want all primes

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so the odds of that are (prime on draw 1)*(prime on draw 2)

tranquil osprey
foggy copper
#

yes

tranquil osprey
foggy copper
#

sorry

#

it's very late here

tranquil osprey
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no problem

foggy copper
#

i should have gone to bed ages ago

tranquil osprey
#

also, could you explain why say a set of size 4 has 4! ways of being arranged? i understand that it does, and i understand that we can prove it by counting ourselves manually, but i dont get it mathematically speaking

foggy copper
foggy copper
tranquil osprey
#

but it got the same answer my tutor got

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but i dont really trust my tutor

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plus our lessons r over

foggy copper
#

which comes to 4*3*2*1 options

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which is, by definition, 4!

tranquil osprey
#

ah okay thank you

lone heartBOT
#

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lone heartBOT
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bronze yew
#

how might I go about figuring out what percent of numbers between 0 and 96000000 have a sum greater than 66? I really dont know where to start

lone heartBOT
#

@bronze yew Has your question been resolved?

worn fox
#

it would be easier to figure out the percentage that have a sum that is less than or equal to 66

bronze yew
worn fox
#

well yeah the point is knowing one tells you the other

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but one is easier to calculate than the other

bronze yew
worn fox
#

just start counting systematically

#

also not even sure how to parse your inital question, you're asking for a percentage of numbers "that have a sum greater than 66"

#

thats not a property a number can have so you need to be more clear

lone heartBOT
#

@bronze yew Has your question been resolved?

bronze yew
worn fox
#

okay well that wasn't clear at all

lone heartBOT
#

@bronze yew Has your question been resolved?

bronze yew
old moat
#

It’s called generative functions if I’m not wrong about the translation

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In discrete math

#

I’d help you but I’m on my phone

lone heartBOT
#

@bronze yew Has your question been resolved?

rose sigil
# bronze yew 12345678 would be 1+2+3+4+5+6+7+8=36

any such number needs to have 8 digits because 9*7 < 66
if the first digit is 9, the possible numbers can be counted by staring at 95999999 and thinking about how many ways you can lower the last 7 digits while keeping the sum greater than 66. since 9+5+9+9+9+9+9+9 = 68, this can only be done by lowering one digit by 1 or not lowering any
for the rest, you can count in a similar, but slightly more complicated way working down from 89999999 and thinking about how many ways you can lower the digits by at most 4

#

the second case is same as the number of nonnegative integer solutions to x_1 + x_2 + ... + x_8 <= 4

#

perhaps you have a formula for that already

#

well it would be a formula for the number of nonnegative integer solutions to x_1 + x_2 + ... + x_8 = n

#

then you could use it a few times

lone heartBOT
#

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spark quartz
#

how do i find the dimension of this subspace?

spark quartz
#

i set up this equation: $\begin{pmatrix} w \ x \ y \ z \end{pmatrix} =
w \begin{pmatrix} 1 \ 0 \ 0 \ 0 \end{pmatrix} + x \begin{pmatrix} 0 \ 1 \ 1/3 \ 1 \end{pmatrix} + y \begin{pmatrix} 0 \ 3 \ 1 \ -3 \end{pmatrix} + z \begin{pmatrix} 0 \ 2 \ -1/3 \ 1 \end{pmatrix}$ which means the dimension should be 4, but its actually 3

ocean sealBOT
#

severed_toast

spark quartz
#

what am i doing wrong

winter light
spark quartz
mortal trellis
#

from where are you getting those equations

spark quartz
#

-x + 3y + z = 0 -> x = 3y + z

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etc.

#

oh

#

theres a mistake in the second row then

#

theyre stil linearly independent tho

mortal trellis
#

still not sure where you are seeing these equations

#

you are playing around wildly with the signs for some reason

#

you only have two equations

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-x+3y+z=0
2x-6y-2z=0

spark quartz
#

yes but you can manipulate them to isolate each variable

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hmm

mortal trellis
#

but that doesnt end up with 4 linearly independent equations somehow

spark quartz
#

here a similar question

#

and then i set up something like this

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and i tried to do the same thing here

mortal trellis
#

you cant keep isolating new variables for old ones

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at some point you run into loops

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if you already wrote x in terms of y and z then you cant next write y in terms of x and z

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cause x is already written in terms of y

spark quartz
#

ah yeah that makes sense

#

hmmm

#

so say i rewrite x as x = 3y + z

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then i have (w, 3y + z, y, z) right

mortal trellis
#

yes

spark quartz
#

then i would just have (w, 3y + z, y, z) = w * v1 + y * v2 + z * v3

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so dimU = 3

mortal trellis
#

yes

spark quartz
#

so if i rewrite x as x = 3y + z could i rewrite w as w = z + 2y

#

(just a general question, not specific to this)

mortal trellis
#

w doesnt even appear in the equations

spark quartz
#

if we pretend it does

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just a general question

mortal trellis
#

if you had an equation w-2y-z=0 then you could rewrite w=z+2y, yes

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but if you have more than 1 equations what you really should be doing is row-reducing

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to spot which of the variables are free and which can be written in terms of the other oness

spark quartz
#

i think that's what the markscheme does here right?

mortal trellis
#

yes

spark quartz
#

it just doesnt really make sense to me, writing the equations that define the set (the vectors in the set) into a matrix and row reducing

mortal trellis
#

if (w,x,y,z) is in the set, then it has to satisfy the linear system of equations

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so you have to solve the linear system of equations

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aka write in matrix and row reduce

spark quartz
#

and its just an efficiency choice to write them in as rows instead of columns right?

mortal trellis
#

not really

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that just turns out rather naturally when you write it as a system of linear equations

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if you call the matrix you posted M

#

you want that M*(w,x,y,z)=0

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writing those as rows fits perfectly with matrix-vector multiplication

spark quartz
mortal trellis
#

if you read what that matrix vector multiplication says, it is literally that -x+3y+z=0 (first row) and 2x-6y-2z=0 (second row)

spark quartz
#

yes, but why do we want it equal to 0?

mortal trellis
#

$\begin{pmatrix} -1 & 3 & 1 & 0 \ 2 & -6 & -2 & 0 \ 0 & 0 & 0 & 0 \ 0 & 0 & 0 & 0 \end{pmatrix} \cdot \begin{pmatrix} w \ x \ y \ z \end{pmatrix} = \begin{pmatrix} -x+3y+z \ 2x-6y-2z \ 0 \ 0 \end{pmatrix} = \begin{pmatrix} 0 \ 0 \ 0 \ 0 \end{pmatrix}$

ocean sealBOT
#

denascite

mortal trellis
#

the equations in the set definition tell you that it should equal 0

spark quartz
#

okay yeah i get it now

#

thank you for your patience and time

#

.close

lone heartBOT
#
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fervent ferry
#

hey hello!
i'm trying to understand what the prroof is trying to prove really..

fervent ferry
#

I'm not sure I undertstand what the "q leads to y". I mean i think i understand the general idea.
if i have many inputs, each act as a different "axis" and their sum is a linear combination. This makes so that also the solution is in the form of a linear combination

#

but where it explains the proof, i don't understand.
are we substituting the formula on the top with a linear combination?
or is there a clear passage that goes from

#

because the only way i can justify the right hand side is by substituting q.
Also is this a "proper" notation? or it's like pseudo code to illustrate a concept?

lone heartBOT
#

@fervent ferry Has your question been resolved?

lone heartBOT
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lime sluice
lone heartBOT
lime sluice
near apex
#

!status

lone heartBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
lime sluice
#

1

#

i put x=-a in the equations

#

then found 2 equations

near apex
#

good start

lime sluice
near apex
#

show me.

#

@lime sluice

lime sluice
near apex
#

Alright. Can you solve them to find value of a?

lime sluice
#

should i put value of a^2 in the first

#

ohh yes

near apex
lime sluice
#

got the answer thanks

#

.close

lone heartBOT
#
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lime sluice
#

I want to know how much time a polynomial intersects x axis

lime sluice
#

Is there any kind of theory

west girder
#

Descartes rule of signs

#

It kind of tells you

lime sluice
#

.close

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#
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