#help-0

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chilly idol
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thank you for helping me

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rotund crater
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what happen if x is x<0?

lone heartBOT
tardy stag
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negative things to non-integer exponents very quickly get out of hand

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or you could say they go sideways

rotund crater
rigid prawn
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if you are asking anything else make it clearer

rotund crater
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I'm not that advanced but can derivatives exist in the complex world?

rigid prawn
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well yeah

rotund crater
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thank you

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surreal topaz
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Hello, I am having an issue with solving for a variable in the exponent of a fundamental theorem of calculus problem.

surreal topaz
rigid prawn
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what s p(t)

surreal topaz
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it should be 225/(t+1)^r

rigid prawn
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that s p'(t)

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p(t)?

young finch
surreal topaz
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225(t+1)^-r+1/r+1?

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it would be solving for r on the interval when it is =375

rigid prawn
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everything you ve done seems correct what s the problem

surreal topaz
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I need to find what r is on the interval 0<x<13

rigid prawn
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for question d right?

surreal topaz
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yes

rigid prawn
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what s the equation you ll use?

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to find r

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oh you ve written something

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this isnt correct

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you need to evaluate this at 13 and 0

surreal topaz
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ok, I will give that a try

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So then I have (2925^-r+1)/-r+1, would I then use logarithms to evaluate the rest of it?

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I am still having some issues with this

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<@&286206848099549185>

alpine sable
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Question?

surreal topaz
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I don't know how to finish this problem, I am trying to solve for r and I don't know how

rigid prawn
# rigid prawn

from here we have 225(t+1)^(-r+1)/(-r+1) evaluated at 13 and 0 is 225*14^(-r+1)/(-r+1) - 225/(-r+1)

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correct?

surreal topaz
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yeah, it should be (2925^-r+1)/-r+1

rigid prawn
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you just multiplied 225 with 14?

surreal topaz
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and then subtracted it by 225

rigid prawn
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no u did 225*(14^...-1)

surreal topaz
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oh I see

rigid prawn
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when you have a*b^x it is not (ab)^x

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225(14^(-r+1)-1)/(-r+1) is not 225(13^(-r+1)/(-r+1)

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which is also NOT (225*13)^(-r+1)/(-r+1)

surreal topaz
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So, when I get to this point how do I solve for r?

rigid prawn
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1^(-r+t)=1

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so you got 225(14^(-r+1)-1)/(-r+1)) =375

surreal topaz
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Thank you, I have been having a lot of trouble with this. I appreciate your patience.

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dawn crest
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i feel like there has to be a smart way to do this . but idk how

dawn crest
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i tried using taylors expansion but it didnt really help

vapid shuttle
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maybe use cos(a)sin(b) identity

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not sure if it would help

vale wigeon
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well you can simply not worry about the cos(1-x^2) factor

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since it approaches 1

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focus just on the $\frac{\sin( (x-1)(x+1) )}{(x-1)^2}$

dawn crest
ocean sealBOT
vale wigeon
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ah hold on thonk

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(x-1)^2 in denom is troublesome

dawn crest
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i thought about using sinx/x but i cant ;-;

vale wigeon
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you can

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you'll just end up with...

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$\frac{\sin(x^2-1)}{x^2-1} \cdot \frac{x+1}{x-1}$

ocean sealBOT
vale wigeon
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and (x+1)/(x-1) explodes so

dawn crest
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why would i end up with that?

surreal meadow
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factor the left term of the denominator

surreal meadow
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you should see things cancelling out to give you the original denominator

dawn crest
twin nimbus
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\begin{align*}
\frac1{(x-1)^2} &= \frac1{(x-1)^2} \frac{x+1}{x+1} \
&= \frac1{(x-1)(x+1)} \frac{x+1}{x-1} \
&= \frac1{x^2 - 1} \frac{x+1}{x-1} \
\end{align*}

vale wigeon
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$\frac{1}{(x-1)(x-1)} = \frac{x+1}{(x+1)(x-1)(x-1)} = \frac{1}{x^2-1} \cot \frac{x+1}{x-1}$

ocean sealBOT
vale wigeon
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also parentheses

surreal meadow
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\cot opencry

ocean sealBOT
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omnipotententity

dawn crest
twin nimbus
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There are two copies of (x-1) and one of (x+1) in the denominator, I just used commutativity to swap their order

dawn crest
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Why isn’t it like this?

twin nimbus
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It looks like you're mixing up (x-1)^2 and x^2 - 1

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(x-1)^2 = (x-1)(x-1)
x^2 - 1 = (x-1)(x+1)

dawn crest
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omg thats true

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sorry

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nooo i really have to go rn but can i reopen the channel later asking about the same limit? bc im still a bit confused

twin nimbus
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You can open a different one, and link back to this

dawn crest
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that works too, thank you :)

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@dawn crest Has your question been resolved?

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fickle oyster
lone heartBOT
kindred anchor
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!status

lone heartBOT
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What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
fickle oyster
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what i tried is i made a sample space

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A B C
2 0 0
0 2 0
0 0 2
1 1 0
1 0 1
0 1 1

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if number of jobs of B is 0

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then those cases would be

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2 0 0
0 0 2
1 0 1

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and from these probability of getting 2 jobs for A is the first case

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so

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1/3

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but this is wrong

kindred anchor
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Use conditional probability formula

fickle oyster
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P(X=2 ∩ Y=0)/P(Y = 0)

vale wigeon
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wait hold on

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there's only two contracts right

fickle oyster
kindred anchor
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1 0 1 can occur in two ways

vale wigeon
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so i think it's better to consider the sample space as {AA, AB, AC, BA, BB, BC, CA, CB, CC}

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that way we can be certain the outcomes are equiprobable too

kindred anchor
vale wigeon
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and P(X=2 | Y=0) now means "whats the probability both contracts were given to A, given that B didn't get any?"

fickle oyster
vale wigeon
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yes

kindred anchor
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A getting the first contract and C getting the second contract is not the same as A getting the second contract and C getting first contract

fickle oyster
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1/4 seems correct

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thx for the help

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mossy wedge
lone heartBOT
mossy wedge
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is this C) Conditional? i'm now sure what exactly im meant to do here

lone heartBOT
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@mossy wedge Has your question been resolved?

upbeat hornet
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find the probability that x is 2 given x less than or equal to 2

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mossy wedge
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TY

lone heartBOT
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lapis fjord
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Guys, how do I find the equation of a line for two points with the same x-co-ordinate?

tall shuttle
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y = y-coordinate

lapis fjord
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x-co-ord, my bad.

tall shuttle
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x = x-coordinate

lapis fjord
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I don’t quite understand, I think. I’m trying to find an equation for a line segment AB where A(2,-2) and B(2,6).

tall shuttle
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The equation is x = 2. y can be any real number and this equation will be true, including -2 and 6

lapis fjord
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Right, wow, that solved the whole sum for me. Thanks a lot, man.

tall shuttle
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vale wigeon
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???

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what are you talking about

upbeat hornet
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the derivative remains the same expression

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this is a true statement

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the derivative of x^2 is always 2x

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the slope of the tangent is the derivative

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the derivative changes

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at each x

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the derivative is a function of x

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No, the derivative of x^2 is 2x, and 2x evaluated at 2 is 4

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That is false if x is a variable and true if x means “times”

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The first or the second?

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Yes

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4x is an expression, not an equation, and y = 4x does not go through (2,4)

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It’s ok

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y = 4x does not go through (2,4), but y = 4x - 4 does, and that’s the tangent to y = x^2 at that point

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Because then it isn’t a tangent

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The derivative tells you the slope, and the point together with it determines the line

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What do you mean

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what is epsilon

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there are no infinitesimals in the reals, maybe you were thinking of h?

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you know the slope, and you know the point, so you can get the equation

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try shifting right by 2 and see what you get

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this is right

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it should, did you try?

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oh wait, you only have to shift right by 1

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look again

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the point was that shifting this line right by 1 and shifting down by 4 are exactly the same

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Yes!

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Should be the same

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find the derivative at a point, which is the slope of the tangent, then use the fact that it goes through the point

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You can think of it that way

lone heartBOT
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brittle portal
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I still do not understand what was this algebraic manipulation

brittle portal
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for context, T is a linear map from V to W

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oh

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upbeat hornet
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brittle portal
# upbeat hornet what is the answer?

I just wrote it down and realised that by the definition of function composition this was the same as
T(S(T(v)))
so you can write the composing symbol (the little ball) in both places

brittle portal
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upbeat hornet
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checks another item off mathcord bingo

brittle portal
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oh I found in on the internet, lmao

long axle
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Don’t expose state secrets…

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smoky tangle
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could someone explain these markings? I'm new to constructions in geometry and would help a lot if someone could introduce me to them:

next patrol
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hi

smoky tangle
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I know the first image shows corresponding and congruent angles, but what is the smaller arc on like HF?

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ping @smoky tangle when responding

next patrol
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essentially showing these r equal

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@smoky tangle

smoky tangle
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okay

next patrol
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need explanation on II?

smoky tangle
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all 3 yeah

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just the markings

next patrol
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okay so the second one

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they have bisected the angle

smoky tangle
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yeah

next patrol
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which means splitting it into two equal smaller angles

smoky tangle
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yeas

next patrol
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how they did it is

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one second

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they measured a certain length up BE

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and put their compass on that point

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and used the compass to draw a curve

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which is this one

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then they got the same length they went up BE

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and went up BF

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and put the compass on that point

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and drew the other cure

smoky tangle
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oh okay

next patrol
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which is here

smoky tangle
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does it mark anything?

next patrol
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and then they draw a line from the angle through it

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where they cross

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which bisects it

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equally

smoky tangle
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oh so thats where the angle bisector passes throguht

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yeah

next patrol
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yeah

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u can try it urself

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on a piece of paper

smoky tangle
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and iii?

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its both a perpendicular and angle bisector

next patrol
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is the triangle an equilateral

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idts

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one sec

smoky tangle
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thats the image

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the question says "which of the following are a construction of an angle bisector?

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you can choose more than 1

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the answers were 2 and 3

next patrol
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yeah

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basc

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the guidlines is the same thing as II

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theyve gone up the length of the traingle

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draw the cruves at the bottom

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and bisected it

smoky tangle
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lenfth of a side?

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gone up that for slant 1, marked a cuve, then sllant 2, and marck another

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and marked where they intersecty

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and drawn a line through that to the angle

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which also bisected the base on the way in

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it has to be an equilateral triangle

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am i right?

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@next patrol

next patrol
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yes you are right

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sorry for the late reply

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@smoky tangle

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it would be helpful to try it urself on a piece of paper

lone heartBOT
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vast sonnet
lone heartBOT
vast sonnet
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is it correct to apply l'hopital like this?

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individually to each fraction?

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since i rewrote them so that they both equal infin/infin

neat sierra
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Looks right.

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Youre not doing any calculus up to that point.

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Just basic fraction manipulation

vast sonnet
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yep

neat sierra
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But the derivative of the denominator

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is wrong

vast sonnet
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its the red box im mainly asking baout

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oh yeh

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i forgot to add 1 right?

neat sierra
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yeah

vast sonnet
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so its fine to apply it like that?

neat sierra
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yep.

vast sonnet
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i c

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thankis

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tall talon
#

What are the necessary steps in doing induction? E. g. If i wanted to prove that the sum of n smallest odd positive integers = n^2 , what would I need to do?

vale wigeon
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do you know the "induction as stairway to heaven" metaphor

tall talon
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yes, i am only confused with steps involving k

vale wigeon
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you have your base case and you have your inductive step

pallid scarab
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So induction has 2 steps, the rest is simply logic. Think of it as dominoes.
1st step : initialisation. You tip the first domino, as the sum of 1 smallest odd positive integers is = 1².
2nd step : "Induction". You make sure that for each domino tipped, the next one will tip as well. So, knowing that the sum of n smallest positive integers is n², we need to prove the sum of n+1 smallest positive integers is (n+1)²

vale wigeon
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those are the only two "steps" that the method of induction itself is concerned with

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how you prove either one is a different matter entirely

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but it does help to have your statement written down formally

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in your case $\sum_{i=1}^n (2n-1) = n^2$

ocean sealBOT
tall talon
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right

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what comes next?

pallid scarab
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Once you know that the first domino is tipped, and that for each domino tipped, the next one is tipped, for sure, all the dominoes will be tipped in the end

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So in your case :

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We easily can see that for $n=1$, $\sum_{k=1}^12k-1 = 1$

ocean sealBOT
#

rafilou2003

wind cloak
pallid scarab
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And 1² = 1

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Now for the induction step

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Let n be any positive integer

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Let's suppose we know that $\sum_{k=1}^n(2k-1) = n²$

ocean sealBOT
#

rafilou2003

pallid scarab
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We need to prove the following : $\sum_{k=1}^{n+1}(2k-1) = (n+1)²$

ocean sealBOT
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rafilou2003

pallid scarab
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And now we do some calculations :

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$\sum_{k=1}^{n+1}(2k-1) = \sum_{k=1}^n(2k-1) + 2(n+1)-1$

ocean sealBOT
#

rafilou2003

pallid scarab
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But because of our assumption, we know that :

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$\sum_{k=1}^n(2k-1) = n²$

ocean sealBOT
#

rafilou2003

pallid scarab
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So $\sum_{k=1}^{n+1}(2k-1) = n² + 2n + 1 = (n+1)²$

ocean sealBOT
#

rafilou2003

pallid scarab
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Which is the proof that we needed for "if a domino is tipped, the next domino is tipped as well"

pallid scarab
tall talon
pallid scarab
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Yes in a certain way

tall talon
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thanks a lot

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flat roost
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just started learning non-homogeneous odes, not really sure how to get the complementary and particular solution thanks

tacit arch
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Well did you do the substitution

flat roost
tacit arch
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No

silk patio
flat roost
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whaat

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ive only learnt constants (for example a times d^2y/dx^2 + b times dy/dx + c times y) are c1 e^rx + c2 e^rx

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sorry for bad notation

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not sure how to do this type of question since its x^2 times the second derivative, not a constant

lime rose
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I need help 😭

ebon sparrow
lone heartBOT
ebon sparrow
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this channel is occupied

lime rose
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I'm seriously lost

ebon sparrow
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bruh get your own channel

lone heartBOT
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@flat roost Has your question been resolved?

flat roost
twin nimbus
#

@flat roost start with the substitution, after you perform the substitution (remember the chain rule for the differentials) share what you have and we can go from there. You'll generally use an ansatz to get the particular solution, but there are other more systemic methods as well, such as variation of parameters. To get the general solution you just add the homogeneous solution to the particular solution.

twin nimbus
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A fancy word for guess

flat roost
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i dont get how chain rule can be used here though?

twin nimbus
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You need to convert dy/dx into dy/dt

flat roost
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times dt/dx?

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t = lnx?

twin nimbus
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That would be how I approach it.

flat roost
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so now we are only trying to have y and t?

twin nimbus
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Exactly

flat roost
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ohh i see

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thanks, ill try that

#

wait but

#

dy/dt x dt/dx

#

which one do i do?

#

i mean i dont even know what dy/dt is

#

but i do know dt/dx which would return something with x

twin nimbus
#

To be fair you don't know what dy/dx is either

flat roost
#

thats why im chain ruling

twin nimbus
#

Yup

flat roost
#

which would give dy/dt times dt/dx

twin nimbus
#

Yup

flat roost
#

do i solve dt/dx?

#

i mean, t = lnx

twin nimbus
#

So dt/dx = 1/x = e^(-t)

flat roost
#

oh

#

oh'oh

#

right

#

i still did it with x haha sorry

#

like this?

twin nimbus
#

I will need to double check it, but that looks about correct other than you dropped the t somehow on the rhs of the equation

#

@flat roost

flat roost
#

This is for the complimentary part(?)

twin nimbus
#

Ok

flat roost
#

like the c1e^rx + c2e^rx

twin nimbus
#

Unfortunately, it seems like I'll need to be afk for a while.

flat roost
#

thats alright

twin nimbus
#

Hopefully, you can take it from here, or another user can help

#

cat_wink you got this

flat roost
#

Thanks so much

#

just wondering is this university stuff

flat roost
#

wolfram says otherwise 😭

flat roost
#

can someone please help me double check, tysm

lone heartBOT
#

@flat roost Has your question been resolved?

nimble fern
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alpine sable
#

does this sum mean something like, assuming n is "4":

1/4 + 1/4 + 1/4 + 1/4

or

1/1 + 1/2 + 1/3 + 1/4

alpine sable
#

and what would 1/k be?

#

"1/1" n times?

#

or just the index

sinful nebula
#

bruv

#

this is sign of sigma

#

it means multiply

#

so it means

#

1/1

#

+1/2

#

+1/3

#

+1/4

#

hope it helped :)

alpine sable
sinful nebula
#

oh shit

#

wait

#

the question is worng?

#

wut

alpine sable
#

nah its not

sinful nebula
#

wtf

alpine sable
sinful nebula
#

i wait wait

alpine sable
#

this is the whole image

sinful nebula
#

oh its 2 variables

#

alr

#

as n is constnt

alpine sable
#

it's approaching infinity

sinful nebula
#

it will come out to be (1/n + 1/n +1/n ..... n times)

#

thus

#

it will be

alpine sable
#

idk if it's still considered constant

sinful nebula
#

1/n * n

#

thats all they did here

#

n is a constant

#

cuz index is k

alpine sable
#

so assuming n is the number 9

#

it would 1/9 9 times?

sinful nebula
#

yes

#

add 1/9 9 times

#

so it will be 1/9 * 9

#

and it gets cut

alpine sable
#

oh ok otherwise it would've been k

#

1/k would've been normal summation

#

n times

sinful nebula
#

yes

alpine sable
#

positive integers

sinful nebula
#

from k to n

alpine sable
#

I got it, thanks

sinful nebula
#

yes

#

np g

#

<3

alpine sable
#

😄

#

.close

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#
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vast sonnet
lone heartBOT
vast sonnet
#

How come these have different results?

#

Or did the calculator just mess up?

minor needle
#

different due to what?

#

answer in the book?

vast sonnet
#

Yes

minor needle
#

what's the answer in the book

vast sonnet
#

Calc says it's -2

#

Book says it's-0.5

minor needle
#

I'd say -2 is right

vast sonnet
#

U really reckon the book is wrong?

#

Hm

minor needle
#

I've checked it on 2 different calcs

#

and by graphing

vast sonnet
#

Ig so then

#

Thanks

#

.close

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alpine sable
lone heartBOT
alpine sable
#

hi i'm trying to apply the rule to rationalize the expression and getting tripped up. how can i arrange the denominator properly to start

#

i'm getting really close but mixing up on algebra somewhere

nimble fern
#

or you can just use (a+b)(a-b)=a²-b²

alpine sable
#

i'll try

#

trying to get rid of that sq rt

nimble fern
#

$\frac{x+3}{4-\sqrt{2x+22}}\cdot\frac{4+\sqrt{2x+22}}{4+\sqrt{2x+22}}$

ocean sealBOT
#

biscuityxd

alpine sable
#

i keep getting a sign wrong somewhere

#

need to factor in such a way that i wind up w (x+3) in the denom

nimble fern
#

$\frac{(x+3)(4+\sqrt{2x+22})}{4²-(\sqrt{2x+22})²}$

ocean sealBOT
#

biscuityxd

alpine sable
#

yeah so here is where i'm getting mixed up. let's say the squared and the square root cancel each other out? then do i have to multiply a negative one through that expression? the implied negative one out front of it???

nimble fern
#

good questions

#

the denominator:
16-2x-22

alpine sable
#

see i don't know how i would know that or how to memorize that

#

seems counterintuitive or arbitrary

nimble fern
alpine sable
#

my issue is w the algebra

nimble fern
#

well, you can just rough work to just write the denominator out step by step

#

like
4²-(2x+22)
16-(2x+22)
16-2x-22

alpine sable
#

if it were instead addition, one could simply remove the parenthesis at the second step? no changing of signs?

nimble fern
#

if it's addtion
like 4+(3+2)
we don't have to change sign inside brackets

alpine sable
#

oh i see it now. minus the quantity 2x and 22

nimble fern
#

just remember
-(2x+22)
is
negative of ( postive 2x + positive 22)

alpine sable
#

the 22 being positive would make no sense

#

you'd be ignoring the fact that you're subtracting it

#

alright thanks. you'd shudder if you knew what grade and program i'm in 😉

#

i might be stuck on the next if you're still around

nimble fern
alpine sable
#

ok

#

thanks again

nimble fern
#

remember to close this one first ;P

alpine sable
#

.close

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unreal badger
#

I need help finding angle EDC the topic is about cyclic quadriliaterals

unreal badger
weary wyvern
#

Deduce whatever angles you can

unreal badger
#

i did n im stuck

#

next page has a question asking for angle EDC

slow wraith
#

Since EF is parallel to CH, angle HCF = angle CFE = 46 °

unreal badger
#

oh

slow wraith
#

angle FBD = 90° - angle FBG = 90° - 58° = 32°

unreal badger
#

i see it now, thanks so much

slow wraith
#

You're welcome 🙂

unreal badger
#

.close

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scenic wing
#

how do you do the power of -2

lone heartBOT
tardy stag
#

,tex .exp rules

ocean sealBOT
#

Hayley

scenic wing
scenic wing
ocean sealBOT
#

putridplanet

scenic wing
#

.close

lone heartBOT
#
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tardy stag
#

i'm sorry?

#

@scenic wing why did you send me a message just containing the word "booba"?

scenic wing
coral thorn
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fleet siren
#

Do similar triangles have to have all the same angle measures?

alpine sable
#

Yes

mental flame
#

Yeah, else they wouldn't be similar

alpine sable
#

Thats basically the definition of similar triangles

#

And if the have the same sides length they are called congruent

fleet siren
alpine sable
#

Yes

#

If all angles are the same the triangles are similar. If the ratio of the sides are the same they are also similar. Or if the ratio of two sides are the same and the corner in between those sides is the same then they are also similar

lone heartBOT
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vast sonnet
lone heartBOT
vast sonnet
#

How would you solve this?

#

. close

#

.close

lone heartBOT
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safe cape
#

how do I differenciate 1^2-x^2 into (1-x)(1+x)

safe cape
#

is there a method or is it just memorising

minor needle
#

a^2 - b^2 = (a-b)(a+b)

safe cape
#

no diff

#

I mean factorise

minor needle
#

it's called

mortal trellis
#

its called difference of squares

#

just well known fact

minor needle
#

difference of squares

safe cape
#

so it's basically memorise

minor needle
#

it isn't that hard, let's be honest

safe cape
#

it is for me

#

because you know

#

I'm here for a reason

minor needle
#

few examples and you'll master it

#

believe me

safe cape
#

yeah

#

first time encountering it though

#

might be why

minor needle
#

ah ye

safe cape
#

is there like a complete list?

#

like before I come here and ask something similar

minor needle
#

you can search for short multiplication formulas

safe cape
#

on a side not

#

note*

minor needle
#

there should be a list or something like that

safe cape
#

what do you guys use to do maths when on paper

minor needle
#

with many examples

last tendon
#

The factorization is "obvious". Consider f(x) = 1-x^2. This is a quadratic polynomial with 2 roots. So either see what they are directly, x = +-1 or use the quadratic formula. In either case, take your pick of a factorization theorem to get (1-x)(1+x).

safe cape
last tendon
#

Difference of squares is the shortcut here. Anyone that would know it without it would probably have memorized difference of squares long ago

minor needle
#

necessarily do examples, not just learn them by heart

sour dove
#

Also if you need need a visualization, here's why the diff of squares works:

$\\ (a + b)(a - b)$
$\= a^2 -ab + ab - b^2$
$\= a^2 - b^2\\$

So now when you run across two squares (including an implicit $1^2$) being subtracted, then you can use the difference of squares trick.

ocean sealBOT
#

mellowdramallama

safe cape
#

I see ty

#

.close

lone heartBOT
#
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safe cape
#

I want some opinions

lone heartBOT
safe cape
#

would you guys say dy/dx is the exact same as y;

#

y'*

alpine sable
#

Yes

safe cape
#

like can I get away with writing y' entirely in the exam

#

and not be risk of mark deduction

alpine sable
#

Yes

plain flame
#

well usually

safe cape
#

"usually"

plain flame
#

if y is a function of x

#

then dy/dx = y'

safe cape
#

more like

alpine sable
#

Right

safe cape
#

do you guys think there is a risk

#

to do the shortcut

alpine sable
#

No provided y is a function of x

safe cape
#

to just write y' instead of the full thing

alpine sable
#

y’ is fine notation

safe cape
#

if I have time I'll write the full thing ig

#

but if I'm running out of time I'll do y'

#

tq

#

.close

lone heartBOT
#
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safe cape
#

.reopen

lone heartBOT
#

safe cape
#

yes

sour dove
safe cape
#

true

#

but I'm in a situation where I might not know who is marking the paper

#

but yeah I'll ask him if I can

#

.close

lone heartBOT
#
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proven leaf
#

that may help avoid confusion but kinda ruins the whole time saving point blobsweat

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vapid shuttle
lone heartBOT
vapid shuttle
#

I am done with this, I just have it on paper. One second while I type my question

#

Okay so my solution is $$y=\frac{1}{2}-\frac{e^{-2x}}{2}$$ for $0\leq x \leq 3$ and $$y=ce^{-2x}$$ for $x>3$

ocean sealBOT
#

austinu

vapid shuttle
#

I am wondering about part (c)

#

is the reason that this is not a "solution" because it isn't necessarily continous

#

depending on the choice of (c) this function may not be continous over the interval of our solution

#

so we can't really say it is a "solution" by the strict definition

#

that requires both y(x) and y'(x).... to be continous over the interval of solution

#

does that sound about right?

mortal trellis
#

sounds about right

surreal meadow
#

if that’s how “solution” was defined then i agree

#

but it depends on how they defined a sokution

vapid shuttle
#

well, a solution has to satisfy the equation over the interval of said solution, and also the solution and its nth derivatives (for an nth order equation) have to be continous over the interval of said solution

#

so this piece-wise function of mine satisfies the equation, but the continous part depends on my choice of c

mortal trellis
#

I think it should be impossible that both the function and the derivative are cont. feels like it

vapid shuttle
#

well I can easily verify tht

mortal trellis
#

they require different choice of c

vapid shuttle
#

there should only be 1 c that makes it continous

#

then I can plug that in and check if the derivative is continous

#

it probably wont be

#

got it

#

ty guys

#

.close

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normal heath
#

i need help

lone heartBOT
normal heath
#

look im not smart like everyone else i struggle with math

tacit arch
mental flame
#

Send what you need help with and we'll be able to help

normal heath
#

is there someone that can call me and explain this to me

unborn stag
#

whats confusing about it to you

normal heath
#

i dont understadn how to solve it

#

look i dont learn by reading text i learn by someone being there

#

and telling me how to do it

lone heartBOT
#

@normal heath Has your question been resolved?

mental flame
# normal heath

first thing we need to do is determine how many solutions these systems have

#

do you know how to do that?

sleek swallow
#

???

tacit arch
lone heartBOT
sleek swallow
#

i did

#

we are in help 0

tacit arch
#

that image says AVAILABLE help channel

mental flame
#

this isnt your channel

tacit arch
#

you're in an occupied one

tacit arch
lone heartBOT
#

@normal heath Has your question been resolved?

lone heartBOT
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ornate ore
#

I'm having trouble figuring out how to apply this formula

ornate ore
#

To this equation

#

For further context I am talking numerically so

#

I have the values for Psi(Z) along a horizontal line in the complex plane described by x + is where x goes from -inf to inf and s is a fixed constant

#

I know there are poles at Z = Pe^(i*theta)

#

Which mess up my attempt at creating a contour integral around r (r is real here)

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#

@ornate ore Has your question been resolved?

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ashen shore
#

How can I tell which has rotational symmetry? They both don't look like equilaterals

tardy stag
#

triangles only have rotational symmetry if they're equilateral

#

i don't see any here

ashen shore
#

full image: i removed c and d because i knew they had rotational symmetry unless the star doesn't?

ionic jewel
#

if you have to choose a single answer, B must be equilateral

#

so then it's gonna be A

ashen shore
#

oh

ionic jewel
#

but this is a bad question with bad art

tardy stag
#

the star looks kinda stretched too

ashen shore
#

ill just go with A

#

seems like the best choice i can do

#

.close

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scenic wing
#

why do they convert it to ln

lone heartBOT
scenic wing
#

so whenever you use the change of base the num and denom become natural logs

gray isle
#

you can change to any valid base you want

scenic wing
#

ok so why did they make it ln here

gray isle
#

part of the question was to get a rounded value
which requires you to use common log or ln in your calc, they've chosen ln

scenic wing
gray isle
#

what are you getting

scenic wing
#

0.092

young finch
#

,w calculate ln(9/7)/(6*ln9)

gray isle
#

can you show exactly what you're putting into your calc

scenic wing
#

$ln(9/7)/6*ln(9)$

ocean sealBOT
#

putridplanet

gray isle
#

order of operations

young finch
#

paranthesis are your best friend

gray isle
#

you want to divide by "6ln(9)"
entering that, you're only dividing by 6 and then multiplying by ln(9)

scenic wing
young finch
#

cool

lone heartBOT
#

@scenic wing Has your question been resolved?

flat roost
#

i wanna know if the quadratic is correct tho

lone heartBOT
#
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harsh crow
#

i brute forced it and got the answer

lone heartBOT
harsh crow
#

but surely theres another way to do it

tacit arch
#

(a^2 - b^2) =(a+b)(a-b)

harsh crow
#

ik that but how do i apply it to the question

tacit arch
harsh crow
#

ohh wait

tacit arch
#

1-(1/2)^2 =?

harsh crow
#

i see

#

but then i have to go multiply 3/4 by 8/9 and so on and so forth

#

is there any way to make that part easier

tacit arch
#

3/9=?

harsh crow
#

1/3

tacit arch
#

Do similar cancellations for all the terms

upbeat hornet
harsh crow
#

oh thats what i did

#

i was looking for an easier way but ig i already did it

tacit arch
#

Welp that's not what brute force means but ok

harsh crow
#

oh ok mb

young finch
#

brute force would be doing 3/4*8/9*15/16 etc

#

up to 224/255

gray isle
#

leave (1-1/2)(1+1/2) as (1/2)(3/2)

#

etc

harsh crow
harsh crow
young finch
harsh crow
#

ohh no i multiplied them

#

but cancelled it out

#

nvm

#

im just dumb dont mind me

#

how do i close the channel

tacit arch
#

Type .close

lone heartBOT
#

@harsh crow Has your question been resolved?

tacit arch
#

.close

lone heartBOT
#
Channel closed

Closed by @tacit arch

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#
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short blaze
#

help

lone heartBOT
short blaze
#

whats the difference

#

between 2 and 4

thorn monolith
#

There are typos

upbeat hornet
#

one is open and one is closed

short blaze
#

what does that mean

upbeat hornet
thorn monolith
#

Oh i havent seen that one

upbeat hornet
short blaze
#

is the fourth one saying everything but -2 and 2

#

and 2nd one is saying only -2 and 2

#

?

#

😭

#

@upbeat hornet

#

i actually hate math so much

young finch
#

i believe its the same as (-2,2)

gleaming ridge
#

2nd: All numbers from -2 to 2 (-2 and 2 included)
4th: All numbers from -2 to 2 (-2 and 2 excluded)

young finch
#

exclusive

#

right

#

so -1.999999 is in the range but -2 is not

short blaze
young finch
#

for the 4th option

#

[U] would mean the end points are not included

short blaze
#

oh so its the same

young finch
#

]U[ would mean the end points are included

short blaze
#

ok thanks

young finch
#

i dont like that notation

upbeat hornet
young finch
#

i wouldnt think so?

#

cause like [0,2[U[4,6] 2 isnt included right but 4 is

#

cause the [] is faced away

gray isle
#

omitting too much making it hard to read

young finch
#

() is superior notation for exlusive ranges

short blaze
#

ok so what would the answer be?

#

wouldnt it be [-2, infinity]?

gray isle
#

no

short blaze
young finch
#

i thought it was infinite domain

short blaze
#

im dumb asf

young finch
#

desmos checks that out too but theres no option for ]-inf,inf[

short blaze
#

its number 3

#

.close

lone heartBOT
#
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lone heartBOT
#
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proven leaf
#

How would I solve something like $\frac{\dd y}{\dd x}=e^{y}$

proven leaf
ocean sealBOT
#

XxMrFancyu2xX

proven leaf
#

Kinda new to diff. eq so would really appreciate a kindergartner explanation kekw

vale wigeon
#

ain't this separable tho

sour dove
#

that's solvable by separation. Divide both sides by e^y and "multiply" both sides by dx

#

then take the integral of both sides

#

it becomes $\int e^{-y} dy = \int dx$

ocean sealBOT
#

mellowdramallama

proven leaf
#

ohhh ok that makes sense, I only did the dx to both sides shenanigans 🫠

#

thanks Mellow helper_heart

sour dove
#

anything for you

proven leaf
#

.close

lone heartBOT
#
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dapper bison
#

Bob goes to run. From his starting point, he runs due east at 10 ft per sec for 250 ft. He then turns and runs north at 12 ft per sec for 400 ft. He then turns and runs west at 9 ft per sec for 90 ft.
Express the (straight-line) distance from Bob to his starting point as a function of t, the number of seconds since he started.
That's the question and solution from here - https://www.freemathhelp.com/forum/threads/word-problem-find-distance-as-a-function-of-time.72575/

lone heartBOT
#

@dapper bison Has your question been resolved?

lone heartBOT
#

@dapper bison Has your question been resolved?

lofty fractal
#

What's your Question ?

#

@dapper bison

lone heartBOT
#
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merry herald
#

isnt the last step wrong?

lone heartBOT
echo socket
#

Yeah it should say -k

merry herald
echo socket
#

P_0/P = e^kh
P/P_0 = e^-kh
P = P_0 e^-kh

merry herald
#

ahhh

#

ok thanks

#

.close

lone heartBOT
#
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tawdry nest
#

State The Value Of Digit 3 in number 121134₅ in base ten

a)15
b)25
c)50
d)123

lone heartBOT
#
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pine surge
#

can anyone show me how to find range of this function:
f(x)= x|x|

whole otter
#

The range?

pine surge
#

Yes

whole otter
#

Isn’t it just y >= 0?

#

Oh nvm

pine surge
#

Idk

echo socket
#

The domain is R, right?

whole otter
#

It’s most likely just all ranges

pine surge
wind cloak
#

Write the function piecewise, it should make it easier to see

whole otter
#

All y values are in the range

pine surge
#

Are there any steps to solve this??

#

If yes pls write it

wind cloak
#

I just told you

pine surge
#

And range of this function:
f(x)= 3x/28-x

wind cloak
#

invert it and find the domain of the inverse

pine surge
#

I dont know inverse of function

wind cloak
#

no worries really

#

Replace f(x) with y

#

And write x in terms of y

whole otter
wind cloak
#

I don't really see where the confusion is

whole otter
pine surge
#

I got range = R-{-3}

cosmic lark
#

whatt

wind cloak
#

,w range of 3x/(28 - x)

cosmic lark
#

where did that come from

wind cloak
#

Correct

cosmic lark
#

oh sorry

#

i didn't see the original function

#

i thought it was f(x)= x|x|

pine surge
#

Does this method work on all types of function to find the range

wind cloak
#

invertible functions

#

any linear/linear should work

#

for quadratic/quadratic or any quadratic you'd need to use the discriminant

pine surge
#

Does this work on under root func.

wind cloak
#

if you can write x in terms of y it works

pine surge
#

And does this work on modulus function

#

To find range

#

??

wind cloak
#

well the modulus doesn't really have an inverse does it

#

there is no antimodulus

#

For modulus functions you need to just use the piecewise definition

echo socket
#

catThink Yeah |x| has no inverse although the function that you had earlier involving the modulus did

pine surge
#

So every modulus function have domain =R and range =R??

echo socket
#

But you will want to use the piecewise definition to find its inverse as well

wind cloak
#

does |x| have range R

pine surge
#

Yes

wind cloak
#

uh

echo socket
#

Can |x| be equal to -1?

pine surge
#

Yes

cosmic lark
#

what, no it cannot

vale wigeon
#

give us a real number whose absolute value is -1

wind cloak
#

for what value of x

pine surge
vale wigeon
#

also let this be on record

echo socket
#

Nonnegative would be more precise

wind cloak
#

indeed

pine surge
pine surge
wind cloak
#

What's |0|

echo socket
#

Because it includes 0 whereas positive R does not

pine surge
#

0

wind cloak
#

Is 0 positive

echo socket
#

And we want 0 to be in the image because |0| = 0

pine surge
echo socket
#

Nonnegative R

pine surge
wind cloak
#

it isn't

#

Saying the domain is positive R would not include 0

#

but the modulus function does have 0 in the range and domain

wind cloak
#

Which is why Lonely Bean insisted on non-negative R

pine surge
#

So, the question was can i use the method u said of writing x in terms of y work on modulus function

#

??

wind cloak
#

it doesn't

#

y = |x|

#

How will you write x in terms of y

#

$x = |y|^{-1}$

ocean sealBOT
#

neonperseus

echo socket
#

(You could write x in terms of y but the relation that you get would not be a function)

wind cloak
pine surge
#

Is there way to solve these question to find domain of mod. ( Without graph)

wind cloak
#

Piecewise definition I told you

echo socket
#

I think they meant the general case

#

Oh wait no nvm

pine surge
#

To find range and domain

cosmic lark
wind cloak
#

Find the range of $f(x) = x + |x - 1| + |x - 3|$

ocean sealBOT
#

neonperseus

pine surge
#

I think the domain is R

#

??

wind cloak
#

domain is R but I asked for the range

pine surge
#

About range i have to idea

#

?

wind cloak
#

you have to what

pine surge
#

No

#

No idea

wind cloak
#

write the piecewise definition

pine surge
#

How??

#

What even is piecewise definition

wind cloak
#

Write the function seperately for when x < 1, 1 < x < 3, and x > 3