@reef flame Has your question been resolved?
#help-0
lone heartBOT
reef flame
I got help but basically yeah
It's like an example thingy I just followed that and answered it but I'm not sure if it's right
<@&286206848099549185>
tacit arch
It's like an example thingy I just followed that and answered it but I'm not sur...
what do you mean "example thingy"
reef flame
Nvm just can someone check if it's correct
tacit arch
Nvm just can someone check if it's correct
which part exactly are you unsure of
reef flame
Final answer I used the a*r^(n-1) formula and then added up all the payouts but idk if that's the right step
lone heartBOT
@reef flame Has your question been resolved?
sand quest
I'm struggling to answer this without graphing, the equation is y^3-4y = x^3 - 2
thick grail
lone heartBOT
@sand quest Has your question been resolved?
willow mango
why is it r-sqrt(r^2-x^2 ) and not just r^2-x^2
lone heartBOT
why is it r-sqrt(r^2-x^2 ) and not just r^2-x^2
fallen verge
This is a problem where you need to washer method
willow mango
ohhhhhh ok ty
modest marten
Guys
vapid shuttle
modest marten
Ok so
If there are 6 numbers on a jackpot and each number maxed on 99 what would be the probability of you getting the jackpot
I’m not planning on gambling just debating with family
So each number went 1-99
vapid shuttle
So
are you saying
there are 1-99, 1-99, 1-99, 1-99, 1-99, 1-99 6 numbers in between 1 and 99
in an ordered list
vapid shuttle
the chance of you getting the first number in between 1 and 99 is 1/99
vapid shuttle
the chance of you getting the first number, and the second number is 1/99 * 1/99 , etc...
modest marten
Don’t feel like doing that on a calculator
Isn’t there a bot here for calculating lol
vapid shuttle
think about a simpler question
yes there is
but imagine this
you are rolling a dice
and you want to know the chances of picking the first 3 rolls correctly
the chance you pick the first roll
is 1/6
the chance you pick the second roll
is 1/6
modest marten
Yeah I did this math in school 2 months ago I would have been able to answer this question on my own 2 months ago
modest marten
I just forgot because the school system is garbage
They make you remember not learn
Anyways thx
.close
exotic crescent
Im stuck on how solve for these angles and can't really find out how. If anyone can quickly help it's due in like 7 minutes 😭
celest terrace
Im stuck on how solve for these angles and can't really find out how. If anyone ...
review your 30-60-90 and 45-45-90 triangles
lone heartBOT
@exotic crescent Has your question been resolved?
exotic crescent
45-45-90 triangles are isosceles right triangles and they don't really look to be that
like this?
prisma lintel
how did you get 22.5?
exotic crescent
135/2 - 45
prisma lintel
thats correct
exotic crescent
oh
alpine sable
hi I'm doing some revision for my add maths exam in 2 weeks and I'm a little stuck on this one 
elder valve
Well, we can find where the vertex is since it is a parabola and then can substitute the x and y values into k and h to get our formula
alpine sable
the vertex should be 5, no?
elder valve
Yup
(5,7) would be the coordinates
So if you substitute the h for the x value and k for the y, you get:
alpine sable
so h = 5 and k = 7..?
elder valve
Yup
alpine sable
wait but I'm not sure about what a would be tho
elder valve
You should be able to do this with any point on the graph, but we just happen to know the vertex
alpine sable
Do you need to find a, tho?
I think I'll try figuring that out myself first ~~if I can't I'll ask again here 
~~
alpine sable
(Also it's .close I think)
à oke thank u 🙏🏻
alpine sable
.close
novel siren
lucid ridge
Hello
lucid ridge
How can I represent a f(x) = e*x graph?
tacit arch
How can I represent a f(x) = e*x graph?
,calc e
ocean sealBOT
Result:
2.718281828459
Do you know how to plot lines?
lone heartBOT
lone heartBOT
Available help channel!
queen jay
lone heartBOT
merry pelican
when you have a quadratic in vertex form, for instance: f(x)=(x-1)^2-1,
how come the vertex is (1,-1)?
I'd assume h and k are both negative 1, but it seems like when they say the vertex is (h,k), that it secretly means (|h|,k) or (-h,k)
merry pelican
This is my first time working with parabolas and vertex form btw
slender gull
h is the value of x at which that perfect square becomes zero.
k is the resulting y value when you do that.
What x value makes (x-1)^2 = 0?
merry pelican
oh, 1
I see
this makes a lot more sense to me. I feel like my search results were way too simplified. You explained it a lot better (and I've written it down now so I won't forget haha)
Thank you
slender gull
👍
merry pelican
.close
scenic wing
idk what it is
lone heartBOT
idk what it is
scenic wing
can what i wrote for c be simplified
vale wigeon
what you wrote for c is incorrect even if it were simplified (and even if that first x was meant to be an x^2)
do you have work to show here?
@scenic wing
vale wigeon
its on a white board
ok, but can you take a picture of it
vale wigeon
i plugged in f(x) into f(x)
that is the right plan of action, but i think you made an error in executing it.
scenic wing
$\frac{\frac{x}{1}}{\frac{x-7x+49}{x-7}}$
vale wigeon
was this your first step?
ocean sealBOT
putridplanet
scenic wing
was this your first step?
i multiplied -7/1 by x-7
vale wigeon
stop right there.
vale wigeon
**putridplanet**
is this your first step, yes or no
as in, is this what you got IMMEDIATELY after plugging f into itself
vale wigeon
i'll be back in 10
scenic wing
$\frac{\frac{x}{x-7}}{{\frac{x}{x-7}}{-7}}$
scenic wing
i'll be back in 10
.
boom first try
im actually cracked at latex
<@&286206848099549185>
tardy stag
keep simplifying
scenic wing
keep simplifying
$\frac{x^2-7x}{-6x+49}$
ocean sealBOT
putridplanet
woven adder
Take LCM and boom u get a very simplified equation 😂
scenic wing
i realized x-7x simplified
ocean sealBOT
putridplanet
scenic wing
wait fuck
woven adder
Still u have to take lcm
vale wigeon
**putridplanet**
this is incorrect
vale wigeon
you fucked up the num of the big fraction
$f(f(x)) = \frac{\frac{x}{x-7}}{\frac{x}{x-7}-7}$
ocean sealBOT
Ann
scenic wing
i did have that
vale wigeon
no you didn't
scenic wing
but then i changed it after i got gas lit
vale wigeon
you had lone x on top
vale wigeon
but then i changed it after i got gas lit
gaslit by whom
scenic wing
im being melodramatic
ocean sealBOT
putridplanet
vale wigeon
yeah sure that's the denom of the big fraction
ocean sealBOT
putridplanet
vale wigeon
ok now you should be good to go
vale wigeon
?
scenic wing
ok now you should be good to go
it was right
vale wigeon
great
ocean sealBOT
putridplanet
vale wigeon
p sure you want x != 7 rather than x != 0? there's nothing wrong w 0 lmao
scenic wing
p sure you want x != 7 rather than x != 0? there's nothing wrong w 0 lmao
what about the left
i set the denom to cant equal zero ffs
tardy stag
what left
tardy stag
right but what's wrong with x=0?
vale wigeon
what about the left
your x != 49/6 is correct. i was pointing out where your error was.
scenic wing
your x != 49/6 is correct. i was pointing out where your error was.
then what should i put for the num
it said just 49/6 wasn't right
tardy stag
we the num can't be zero
... why not?
scenic wing
ok then whats the other number than can't be x
vale wigeon
p sure you want x != 7 rather than x != 0? there's nothing wrong w 0 lmao
scenic wing
> p sure you want x != 7 rather than x != 0? there's nothing wrong w 0 lmao
why 7
vale wigeon
7 is not a valid input for f itself
vale wigeon
words mix jumble hard understand?
vale wigeon
i have no idea wtf YOU said
vale wigeon
7 is not a valid input for f
vale wigeon
$f(x) = \frac{x}{x-7}$
ocean sealBOT
Ann
vale wigeon
f(7) is undefined
scenic wing
f(7) is undefined
oh in the original function and the new one ?
vale wigeon
f(7) is undefined, thus f(f(7)) is also undefined
scenic wing
f(7) is undefined, thus f(f(7)) is also undefined
upbeat hornet
HOW IS THIS WRONG
Have you found the right answer?
surreal meadow
.close
alpine sable
Does anyone know any good YouTube videos that explain graphing questions like this?
Im having difficulties
vale wigeon
Please claim a new channel and do NOT delete the first message of any future channel you claim.```Oh okay
lone heartBOT
Available help channel!
wicked palm
does anyone know how to find the slant height just from the given height and the diameter of a cylinder (trying to find the Volume of it)
devout summit
Notice that there's no restriction on how slanted the cylinder can be
wicked palm
ah
devout summit
But only given the fact that it's slanted in such a manner that each horizontal cross section is a disc with same radius all of those variants have same volume
wicked palm
ohhh
tyy
wait so do i solve for the base of the circle which is pi 3^2=9 pi then do a V of a triangle V=base x height 9pi * 8 which gives me 72pi would that be the answer? ( i’m really bad at explaining things )
lone heartBOT
@wicked palm Has your question been resolved?
lone heartBOT
lone heartBOT
Available help channel!
alpine sable
lone heartBOT
maiden glen
2sqrt6 * (sqrt7 - sqrt5)
distribute through the bracket, you have 2sqrt6 * sqrt7 - 2sqrt6 * sqrt5
alpine sable
2sqrt6 \* (sqrt7 - sqrt5)
So the ss i just sent is wrong?
alpine sable
distribute through the bracket, you have 2sqrt6 \* sqrt7 - 2sqrt6 \* sqrt5
Wait
Why theres another 2sqrt6?
alpine sable
OHHHH
OMG I FORGOT
I understand now
And btw
One more question
Do yk why
It suddenly multiples
8?
maiden glen
you want to compare all the values
alpine sable
But how do yk its 8 tho
maiden glen
so making them have the same denominator means you can just look at the numerators
you want 40 on the bottom
40/5 = 8
alpine sable
So i have to figure it out how to make their denominator the same?
Like all of them
maiden glen
yes
you take the least common multiple of the denominators of all the simplified fractions
so you have 6/5, 5/8, 1/2, and 3/5
so you find the least common multiple of 5, 8, 2, and 5, which is 40, and get that as the denominator for all
wanton cosmos
lone heartBOT
echo socket
(x - 2) and (x + 1) being factors of a polynomial means that 2 and -1 are the roots of that polynomial, right?
wanton cosmos
yea
echo socket
So, if we plug in x = 2 and x = -1 into the x^4 + 4x^3 - x^2 + ax + b, we get 0
wanton cosmos
mh,
echo socket
So we have a system of two equations with unknowns a and b
wanton cosmos
mhm
echo socket
2^4 + 4 * 2^3 - 2^2 + 2a + b = 0
(-1)^4 + 4 * (-1)^3 - (-1)^2 - a + b = 0
Simplified:
$\begin{cases}
2a + b = -44 \
-a + b = 4
\end{cases}$
ocean sealBOT
alonelybean
echo socket
Can you solve for a and b here?
echo socket
Yup
echo socket
2^4 + 4 * 2^3 - 2^2 + 2a + b = 0
(-1)^4 + 4 * (-1)^3 - (-1)^2 - a + b = 0
Just simplified these equation as follows:
2^4 + 4 * 2^3 - 2^2 + 2a + b = 0
16 + 4 * 8 - 4 + 2a + b = 0
12 + 32 + 2a + b = 0
44 + 2a + b = 0
2a + b = -44
(-1)^4 + 4 * (-1)^3 - (-1)^2 - a + b = 0
1 - 4 - 1 - a + b = 0
-4 - a + b = 0
-a + b = 4
wanton cosmos
wait thats all?
echo socket
**alonelybean**
Yup, the rest is solving this
wanton cosmos
o my that is much for simple
echo socket
You can express x^2 - 1 as a product of two linear terms
Perhaps it becomes obvious if you view it as x^2 - 1^2
echo socket
You got (x - 1)(x + 1), right?
It means that x = 1 and x = -1 are roots of the polynomial
wanton cosmos
You got (x - 1)(x + 1), right?
yep difference between 2 squares
echo socket
So just plug in those two values, equate the results to 0 and go through the same process as before
wanton cosmos
So just plug in those two values, equate the results to 0 and go through the sam...
oh alright thanks
let me try solve it first
vapid shuttle
let me try solve it first
did you figure it out?
wanton cosmos
did you figure it out?
yea i did
is it a = -16, b = 12
im js doin the 2nd question rn
vapid shuttle
Cool
echo socket
is it a = -16, b = 12
Should be b = -12
echo socket
**alonelybean**
Subtracting second equation from the first yields 3a = -48 and a = -16, sure, but 16 + b = 4 then
Alright
wanton cosmos
yea my bad
@echo socket um
how u do this again
a - b = 3
a + b = 1
i literally forgot
echo socket
The b's cancel out if you add up the equations
wanton cosmos
wait wym by that?
echo socket
(a - b) + (a + b) = 3 + 1
2a = 4
echo socket
Yes
echo socket
Yes
wanton cosmos
.close
marsh ridge
is a and b the same thing
lone heartBOT
is a and b the same thing
vapid shuttle
yes they are
multiplication is commutative
meaning ab=ba
order of multiplication doesn't matter
vapid shuttle
nope
marsh ridge
oh okay ty
vapid shuttle
no problem
maybe it would be preferred to actually do the multiplication honestly
like just writing it as 36
would be preferred
marsh ridge
this was the original equation actually
just wanted to make sure they're both the same thing
vale wigeon
they are both the same thing and you should not worry about which one is "better" presentation-wise unless you have explicit instructions to that effect
also you should cross your sevens
lone heartBOT
@marsh ridge Has your question been resolved?
vale wigeon
yes
safe tartan
lone heartBOT
safe tartan
i think i made a mistake when i simplified, but i cant find it
ive tried it twice and got the same thing
original question is prove using mathematical induction
ocean sealBOT
minor needle
after taking 2^(k+1) outside the bracket you should get 2k^2 + 4
you got k^2 - 2k + 4
then it's just
2^(k+1) * 2(k^2 + 2) - 6 = 2^(k+1) * 2^1 * (k^2 + 2) - 6 = 2^(k+2) * (k^2 + 2) - 6
safe tartan
after taking 2^(k+1) outside the bracket you should get 2k^2 + 4
wait really?
its a plus though
+2^k+1
at the end
minor needle
how +
minor needle
then it's wrong
$$\sum\limits^{k+1}{r=1} r^2 \times 2^r = \sum\limits^{k}{r=1}r^2 \times 2^r+(k+1)^2 \times2^{k+1}$$
ocean sealBOT
modus7591
safe tartan
oh my yeah i messed up
i wrote r^2+2^r
ty alot woulda never found that
.cloes
.close
lone heartBOT
safe tartan
.reopen
lone heartBOT
✅
safe tartan
.close
lone heartBOT
lone heartBOT
Available help channel!
lone heartBOT
question 6A please
opal pendant
it would be the max turning point
lone heartBOT
@remote fulcrum Has your question been resolved?
bitter ermine
maximum flow rate occurs when the derivative of the function defining flow rate is equal to 0
so set the derivative of the function R, R', equal to 0, and solve for t
if you get multiple t values, plug each t value into the original function to see where R is at the highest value
bitter ermine
if you get multiple t values, plug each t value into the original function to se...
some questions have an interval for the funciton provided, and on these, when you reach this step
plug in the t values (or whatever the equivalent of the independent variable is) of the endpoints of the interval
remote fulcrum
hold on @bitter ermine
lone heartBOT
hold on <@729362018355642438>
remote fulcrum
the answer is 25l/min
i did 10-2t = 0 and t isn’t 25
i’m solving for R arent I; the rate
bitter ermine
yeah i gotchu
bitter ermine
the funciton R is measured in liters/minute
if you integrate that
what units will the new quantitiy represented by the integral of R give you
@remote fulcrum
lone heartBOT
@remote fulcrum Has your question been resolved?
lone heartBOT
lone heartBOT
Available help channel!
reef flame
lone heartBOT
modern sedge
I would start by finding the common ratio
then you can apply formula for geometric series
lone heartBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
do you know how to find the sum of a geometric series?
upbeat hornet
I know it but I'm not confident in it
can you apply it here? we can check it after you do it
reef flame
Ok
languid bolt
did you do it?
lone heartBOT
@reef flame Has your question been resolved?
reef flame
did you do it?
I couldn't
languid bolt
what have you done?
upbeat hornet
I couldn't
can you show what you did?
reef flame
Ok I'll show you in a few min
reef flame
can you show what you did?
I got up to (-4)^13
@upbeat hornet
@languid bolt
The place I put a star is wrong
<@&286206848099549185>
mossy field
Please do not spam mentions.
reef flame
Please do not spam mentions.
Ok my bad they were helping me before that's why
mellow grail
.close
tall shuttle
How would one solve $x = 7^{1632} \mod (2023)$
lone heartBOT
How would one solve $x = 7^{1632} \mod (2023)$
ocean sealBOT
talestitan
ocean sealBOT
vale wigeon
ok yeah true
tall shuttle
Also $\phi(2023) = 1632$
ocean sealBOT
talestitan
vale wigeon
7^1631 mod 289
tall shuttle
Oh
ocean sealBOT
talestitan
vale wigeon
,calc 1632 mod 272
ocean sealBOT
Result:
0
i mean
7^1632
literally has so many sevens in its prime factorization
that requiring yourself to ASSUME it divisible by 7 is super asinine
2023 is divisible by 7 as i verified in front of you
tall shuttle
So $\dfrac{x}{7} \equiv 7^{1631} \equiv 7^{271} \mod 289$
ocean sealBOT
talestitan
tall shuttle
Because 7^{272} = 1 mod 289
vale wigeon
should not be that bad with some repeated squaring
lament forge
...didn't you just say that 7^{272} = 1 mod 289
tall shuttle
$x \equiv 1 \mod 289$
ocean sealBOT
talestitan
lament forge
yep
lament forge
x/7 is 7^271
tall shuttle
**talestitan**
I multiplied by 7 both sides here
lament forge
and 7^272 is 1 so 7^271 is 1/7
ocean sealBOT
talestitan
tall shuttle
Python says the solution is 868
(7**(1632))%2023
868
Oh i got it
$\dfrac{x}{7} = 7^{-1} \mod(289)$
The inverse of 7 mod 2023 is 124
ocean sealBOT
talestitan
tall shuttle
So $\dfrac{x}{7} = 124 \mod(289)$
ocean sealBOT
talestitan
tall shuttle
So $x = 868 \mod(2023)$
ocean sealBOT
talestitan
tall shuttle
.close
tiny cobalt
I need to find a, b and i am stuck
lone heartBOT
I need to find a, b and i am stuck
strong sierra
How do I solve this question? I keep getting a different answer to my textbook. The question is "Sandy jogs 19.7 miles in 4.5 hours. how many miles does she jog each hour? Round your answer to the nearest hundredth". I solved it by doing 19.7 * 10 = 197 and 4.5 * 10 = 45, Then did 197 ÷ 45 = 4.3777 and then rounded it up to 4.38. My textbook suggests the answer is 4.26
strong sierra
So then is it a typo?
ocean sealBOT
marsh rapids
So then is it a typo?
Though that's more of an error than a typo
strong sierra
.close
tranquil osprey
how does the distributive property of multiplication turn (a + b)^3 = (a + b) . (a + b) . (a + b)
into
a^3 + 3a^2b + 3ab^2 + b^3
??
echo socket
Yup, it's not just the distributive property though, multiplication commuting also plays a role
gray isle
$(\red{(a+b)(a+b)})(a+b)$
ocean sealBOT
ℝamonov
lone heartBOT
@tranquil osprey Has your question been resolved?
tranquil osprey
I understand why a and b are powered to three, but not the 3a etc etc part
rare pier
is there anyone who can help me quick with a simple substitution with complex numbers?
tranquil osprey
Yup, it's not just the distributive property though, multiplication commuting al...
how? where?
echo socket
How are you gonna add up ab and ba without knowing that they are the same thing
tranquil osprey
How are you gonna add up ab and ba without knowing that they are the same thing
i know that's the same thing, i just dont get where we get 3a^2b + 3ab^2
echo socket
So far you got (a^2 + 2ab + b^2)(a + b), right?
tranquil osprey
So far you got (a^2 + 2ab + b^2)(a + b), right?
lets start over from the beginning please
echo socket
Can you multiply (a + b) by (a + b)?
tranquil osprey
Can you multiply (a + b) by (a + b)?
a^2 + 2ab + b^2
echo socket
Right
So, to get (a + b)^3, we now multiply that by (a + b)
It should get you a(a^2 + 2ab + b^2) + b(a^2 + 2ab + b^2) and then a * a^2 + a * 2ab + a * b^2 + b * a^2 + b * 2ab + b * b^2
Simplifying: a^3 + 2a^2b + ab^2 + a^2b + 2ab^2 + b^3
Can you see common terms here?
tranquil osprey
Simplifying: a^3 + 2a^2b + ab^2 + a^2b + 2ab^2 + b^3
ohh
2a^2b + ab^2 + a^2b + 2ab^2
so 2a^2b + ab^2 gives us 3a^2b
a^2b + 2ab^2 gives 3ab^2
tranquil osprey
It should get you a(a^2 + 2ab + b^2) + b(a^2 + 2ab + b^2) and then a * a^2 + a *...
this is from (a + b) + a^2 + ab + ab + b^2 right?
echo socket
`a^2b + 2ab^2` gives `3ab^2`
Yup
echo socket
this is from `(a + b) + a^2 + ab + ab + b^2` right?
Not sure what you mean here
tranquil osprey
Not sure what you mean here
we get a(a^2 + 2ab + b^2) + b(a^2 + 2ab + b^2) from (a + b) + a^2 + ab + ab + b^2)
lone heartBOT
@tranquil osprey Has your question been resolved?
echo socket
we get `a(a^2 + 2ab + b^2) + b(a^2 + 2ab + b^2)` from `(a + b) + a^2 + ab + ab +...
You mean (a + b) * (a^2 + ab + ab + b^2)?
tranquil osprey
You mean (a + b) * (a^2 + ab + ab + b^2)?
oops yeah
lone heartBOT
@tranquil osprey Has your question been resolved?
tranquil osprey
another question, could you explain frames of reference? i dont get them @echo socket
echo socket
Isn't a binomial just a sum of two terms?
tranquil osprey
sorry i meant frames of reference lol
hollow rose
.close
tacit arch
sorry i meant frames of reference lol
#old-network for physics server
raven rover
.close
oblique trail
I'm reading a paper, and I don't get how they got 1 - n (i know it's not n), shouldn't it be
vapid shuttle
context?
tacit arch
I'm reading a paper, and I don't get how they got 1 - n (i know it's not n), sho...
show the entire context
hollow rose
I'm reading a paper, and I don't get how they got 1 - n (i know it's not n), sho...
man said he chose maths in his higher subject
oblique trail
man said he chose maths in his higher subject
?
hollow rose
what does that even mean
tacit arch
mans learning goofy ahh math
can you not interrupt people's help channels
oblique trail
tacit arch
I'm reading a paper, and I don't get how they got 1 - n (i know it's not n), sho...
i don't see where this appears
hollow rose
can you not interrupt people's help channels
sorry didnt know the rules of the server i thought we all coul comment, btw its my first day so i didnt know im sorry guys wont happen again
oblique trail
sorry didnt know the rules of the server i thought we all coul comment, btw its ...
Child
vale crag
I'm reading a paper, and I don't get how they got 1 - n (i know it's not n), sho...
n you mean $\gamma$ ?
ocean sealBOT
_aplatypus
last tendon
They are referring to eta
vale crag
yeah indeed
that's weird
should be 1 - eta/4
or maybe they typo'd somewhere
what's that paper btw ?
last tendon
That line seems fine to me?
last tendon
Oh it's 2gamma not 2eta
vale crag
@oblique trail
vale crag
ah yeah sure
lone heartBOT
lone heartBOT
Available help channel!
alpine sable
My brain hurts
lone heartBOT
My brain hurts
ocean sealBOT
brandon_hu
ocean sealBOT
brandon_hu
alpine sable
also how do i make those symbols with latex?
tawny condor
$x \in A$
ocean sealBOT
redstoneplayz09
tawny condor
means that x is an element of x
now suppose you have 2 sets, A and B
for which every element thats in A, is also in B
so you can think of it as A being "contained" in B
in that case we say A is a subset of B
$A \subset B$
alpine sable
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb
ocean sealBOT
redstoneplayz09
alpine sable
😭 I used the wrong latex
tawny condor
yeah lemme google it
ocean sealBOT
brandon_hu
tawny condor
$A \subseteq B$
alpine sable
I forgot what i was even asking
ocean sealBOT
redstoneplayz09
alpine sable
idk
tawny condor
$A \subseteq B$ is subset
ocean sealBOT
redstoneplayz09
tawny condor
$A \subset B$ is proper subset
ocean sealBOT
redstoneplayz09
alpine sable
If is A a subset of B and A and are B not the same , so that there is some element of Bthat is not in A then we say
that A is a proper subset of B
$$ x $$
ocean sealBOT
brandon_hu
alpine sable
My brain fried on this sentence
alpine sable
the sentence
tawny condor
okay
alpine sable
Idk what they're trying to say
tawny condor
so A subset of B
can also happen when A = B
So every set is a subset of itself, right?
alpine sable
yes
tawny condor
But sometimes we want the notion of saying that A is a subset of B, but they aren't equal
so B has at least 1 additional element that isn't in A
ocean sealBOT
brandon_hu
ocean sealBOT
brandon_hu
tawny condor
yes
alpine sable
means that A is a subset of B but A could be B
tawny condor
yeah
they can be equal
its similar to < and <=
a <= b means its less than or equal to
sour dove
I like to think of it like this:
x < 2 : x can be, but not including 2
x <= 2: x can be up to and including 2.
The same with subsets.
A (proper subset) B means that all of A is in B, but not all of B is in A
A (subset B) means that all of A is in B, and might equal B.
tawny condor
good explanation
Thank you everyone for your help
lone heartBOT
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Available help channel!
dapper basin
what‘s my mistake? can‘t find it
lone heartBOT
what‘s my mistake? can‘t find it
dapper basin
the solution says it should be
2ln|x| - 4ln|x+1| + ln|x-1| + c
wary stream
the solution says it should be
2ln|x| - 4ln|x+1| + ln|x-1| + c
The solution is wrong, yours is right
Google an integral calculator and check your answer
tacit arch
what‘s my mistake? can‘t find it
Take a picture of the original integral
dapper basin
wolfram alpha
dapper basin
Take a picture of the original integral
1sec
oh wait the minus isnt right on wolfam alpha
wary stream
wolfram alpha
That's not the same equation
dapper basin
ye my mistake
well the wolfram alpha one is the correct one so that explains it
but wolfram alphas solution is still different
wary stream
but wolfram alphas solution is still different
It's not. I checked it, your answer is the same
You just have the negative factored
dapper basin
the solution says it should be
2ln|x| - 4ln|x+1| + ln|x-1| + c
this is the same as wolfram alphas solution?
wary stream
,w integral of - (x^2+5x-2)/(x(x+1)(x-1))
ocean sealBOT
dapper basin
yes right, sorry for the misunderstanding
wary stream
this is the same as wolfram alphas solution?
Now either you wrote the problem wrong or the solution is wrong
dapper basin
wolfram alpha
which is still different from this
wary stream
original problem
Then you did the wrong problem
wary stream
which is still different from this
It's the same still, wolfram does weird manipulation
wary stream
,w log(1-x)+2log(x)-4log(x+1) = log(x-1)+2log(x)-4log(x+1)
ocean sealBOT
wary stream
I forget how to check equivalency
dapper basin
i'll try on the website
tacit arch
,w does log(1-x)+2log(x)-4log(x+1) = log(x-1)+2log(x)-4log(x+1)?
ocean sealBOT
dapper basin
so no 🤔
wary stream
Hmmmmmmm I guess it was different? Wolfie is just wack sometimes
dapper basin
I dont know in what solution to trust anymore haha
wary stream
Use the integral calculator website
It shows work
Like Google "integral calculator" and it's one of the first links
dapper basin
Like Google "integral calculator" and it's one of the first links
just used it
hard to believe that wolfram alpha can make mistakes
buoyant storm
that’s because 1-x and x-1 can’t both be positive
At least one of the sides isn’t even defined
buoyant storm
hard to believe that wolfram alpha can make mistakes
it didn’t make a mistake, one of the sides has log(1-x) where the other has log(x-1)
buoyant storm
they’re not equal
they aren’t equal
at least one of them is not defined
so it can’t be equal at all
dapper basin
i am so confused
dapper basin
but the integral calculator comes up with the same result as the teacher
and wolfram has the different solution
buoyant storm
huh
dapper basin
buoyant storm
,w integral of - (x^2+5x-2)/(x(x+1)(x-1))
dapper basin
wolfram alpha
but this should be the same as
buoyant storm
different inputs of course have diffrent answers
dapper basin
this
buoyant storm
it’s -(x^2+5x-2) on the numerator
One of these has the first one as numerator
The other is second one
It shouldn’t be the same, if it was WA screwed up
Ok it doesn’t matter which version is correct, just follow the one given in the question
dapper basin
can you please show me on a screenshot where the inputs from the WA and the integral calc differ
ocean sealBOT
orthogonal_1
buoyant storm
uh just look at this
buoyant storm
There’s the input
ocean sealBOT
dapper basin
wait
its not different
oh my god
i'm sorry man i dont know whats wrong with me
thanks for sticking around and helping
.close
dawn quail
lone heartBOT
dawn quail
if I look at this on a graph...
seems to go on forever..
so what am I supposed to say for local max? t = Infinity?
tawny condor
you should probably zoom in a little..
vapid shuttle
so what am I supposed to say for local max? t = Infinity?
keyword local
dawn quail
you should probably zoom in a little..
here?
where it changes from negative to positive?
dawn quail
I'm using -8 and -7 approximate endpoints based on the graph above
but I don't think this is correct..
it looks closer to y= -16
should I replace t for something else? when calculating this
tawny condor
,w x^2+16x+48=0
ocean sealBOT
dawn quail
.close
stone basin
lone heartBOT
stone basin
can someone explain how to do this question? I know you have to use hypergeometric distribution but I couldn't figure out how and get the right answer ;-;
vapid steppe
what am i doing wrong
lone heartBOT
what am i doing wrong
vapid steppe
i got 150 by doing (50 ft/sec)(3 sec)
lone heartBOT
@vapid steppe Has your question been resolved?
spare fern
could anyone help me out with a physics problem?
lone heartBOT
could anyone help me out with a physics problem?
cyan nexus
ask
lone heartBOT
@spare fern Has your question been resolved?
spare fern
I am about half way through the problem
I got t = 0.109s and angular frequency = 6.684rad/s
@cyan nexus
cyan nexus
Sorry, I have no idea
rigid prawn
just find x=Asin(vt+θ) then u=Avcos(vt+θ)
ebon sparrow
could anyone help me out with a physics problem?
This is a math server not physics, if you want a physics server it's on #old-network
elder valve
Not sure if you still need help with this but I got almost exactly .1 m/s
lone heartBOT
@spare fern Has your question been resolved?
sweet wagon
lone heartBOT
sweet wagon
I have worked this problem a couple times, but I always get confused while trying to isolate dy/dx
lone heartBOT
@sweet wagon Has your question been resolved?
lone heartBOT
@sweet wagon Has your question been resolved?
lone heartBOT
@sweet wagon Has your question been resolved?
alpine sable
hi
alpine sable
can you recall the cosine law?
tacit arch
@alpine sable Delete your messages from all the other channels you spammed
alpine sable
alr
alpine sable
can you recall the cosine law?
a^2 = b^2 + c^2 - 2b cos(A)
A is the angle opposite to the side a
meaning that to use the cosine law you need the two other sides and the opposite angle
can you show your pic again?
you're allowed to send it here
@alpine sable
sure
alpine sable
meaning that to use the cosine law you need the two other sides and the opposite...
A and D works right
sorry i was gonen for a sec
i think so
alr thanks
lone heartBOT
✅
lone heartBOT
@alpine sable Has your question been resolved?
coral thorn
dawn spoke
ionic jewel
No idea what's happening here, but if someone has a new question open a new channel
.close
lone heartBOT
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Available help channel!
molten oak
I need help with number 15 and 16
lone heartBOT
I need help with number 15 and 16
molten oak
How do we get g?
lament forge
,rccw
ocean sealBOT
lament forge
well you have this graph
that doesn't give you a formula or anything for g, but for particular values you can just directly read them from the graph
molten oak
How do we get 6 because the solution our teacher gave us is
f(0) + g(0)
= 1 + 6
=7
I have no clue how you get g(0) if you only get f(x) in the table
lament forge
well you get it from the graph
alpine sable
I don't see anything in the graph, it doesn't point to 6 anywhere
It does
lament forge
well first, how large is each square in the graph?
molten oak
Idk
molten oak
5?
lament forge
yep
molten oak
OK how does that get 6?
lament forge
so if 5 squares is a distance of 5, that means each square is 1
well now that we know how large the squares are, we can measure other distances on the graph
here's the point that represents g(0) (i've marked it with a red dot)
how many squares above the x-axis is that?
lament forge
well this is the line x=0
molten oak
OK but how do u get 6?
alpine sable
Is it because the dots connect there?
Cuz the graph is of gx
alpine sable
g(x) means output of a function which usually is represented on the y axis and x is the ipute represented in x axis
lament forge
...i'm not sure what those yellow arrows are pointing at
it's because the x coordinate of that point is 0
molten oak
It's pointing at the black things
The one stretching out the horizontal and vertical lines
lament forge
it's because the x coordinate of that point is 0
the x of this point is 2, so this is where g(2) is
alpine sable
Can you read this do you know what this means?? @molten oak
molten oak
Ye that's the thing where u add dots in the graph
alpine sable
Ye that's the thing where u add dots in the graph
Yeah so when you add dots it creates a graph of that function
In the question they have directly given you the graph so now you have to make this table
molten oak
Ahhhh OK I get It now
alpine sable
You can see the g(x) and x and make this table yourself and by doing this you can find what is the value of g(0) is
lone heartBOT
alpine sable
.reopen
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verbal turret
hello how can I calculate fees that Im paying for example if one thing is 7$ and I pay 7.17$ what's the fee?