#help-0

1 messages · Page 246 of 1

timber latch
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Yes

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Fractions is 1/3

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And get the rest

magic pollen
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simplify?

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okay thank you

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.clos3

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.close

lone heartBOT
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wheat isle
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Would it make sense to say the range of e^x would be all yER such that y>0 or would it only be y>0 and why?

alpine sable
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imo, both are fine since its implied that y is a real number

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but if you want to be extra clear, the first option is good

wheat isle
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and I can write it like {yER:y>0} right

alpine sable
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yes

wheat isle
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Alright thanks

alpine sable
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yw

wheat isle
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.close

lone heartBOT
#
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vale wigeon
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.reopen

lone heartBOT
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vale wigeon
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if you can't type the set membership symbol ∈, it's better to replace it with in rather than E

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{y in R : y > 0}

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just a style thing

lone heartBOT
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@wheat isle Has your question been resolved?

wheat isle
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yER looks better sotrue

vale wigeon
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it really does not.

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that or you have bad taste sotrue

wheat isle
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yER visually more appealing than y in I stand my point hmmCat hmmCat

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mic drop

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or how y’all mathematicians call it

lone heartBOT
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lyric geyser
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i dont quite understand where the red 1/x comes from, id like a bit of help ty

lyric geyser
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heres the function

vale crag
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le rouge ou le bleu ?

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ou les deux

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@lyric geyser

lyric geyser
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je ne comprends pas trop d'où viens le rouge

vale crag
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ils ont juste sorti le 1/x

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1/x dépend pas de y

lyric geyser
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mais ensuite le bleu?

vale crag
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$$\pdv{}{y}\left(\frac{1}{x}yh'_t(t)\right) = \frac{1}{x}\pdv{}{y}\left(yh'_t(t)\right)$$

ocean sealBOT
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_aplatypus

vale crag
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un peu comme à la 1ère étape

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t'as $$\pdv{}{y}\left(yh'_t(t)\right) = \pdv{}{y}\left(y\right) h'_t(t) + y \pdv{}{y}\left(h'_t(t)\right)$$

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euh

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il me manque un truc là

ocean sealBOT
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_aplatypus

vale crag
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ah voila (ça c'est juste une product rule pas trop de problème là dessus normalement)

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la dérivée partielle tout à droite c'est une fonction composée

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t dépend de x et y ici

lyric geyser
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pourrais-tu faire le d/dy(h't(t))?

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juste pour que je comprenne bien les étapes

vale crag
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yes

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$$\pdv{}{y}\left(h'_t(t)\right) = \pdv{}{t}\left(h'_t(t)\right)\pdv{t}{y}$$

ocean sealBOT
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_aplatypus

vale crag
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d/dt (h' (t)) c'est h''(t)

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et dt/dy = 1/x

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là c'est la fonction composée que j'utilise

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@lyric geyser

lyric geyser
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oooh okaay

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ok j'ai catch

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faut réapliquer la chain rule

vale crag
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yus

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même en plusieurs variables, les dérivées ça reste très mécanique

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c'est juste un peu plus le bordel à gérer

lyric geyser
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ok merci bcp

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j'ai compris

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.close

lone heartBOT
#
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raw jetty
#

assume there is an equilateral triange ABC with lenghts 10, and there is a circle that touches sife AB and AC and touches the outer triangle circle, and the points where the circle touched AB and AC arecalled f and g. what is the area of triangle AFG?

raw jetty
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currently i have no idea on what to do

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all i know is that AFG is an ewuilateral triangle i think

heady panther
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2 5 7 10 what is next number ?

raw jetty
heady panther
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So Say Answer

vale wigeon
raw jetty
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oh wsit nvm

gray isle
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it's not even a series

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have you drawn a diagram for your own question?

raw jetty
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i just scanned trough the wuestion and thought it was a diffrence of 3 series

heady panther
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NO ANY ONE CAN ANSWER MY QEUSTION

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I KNOW THE ANSWER BUT I WANT KNOW HOW MUCH YOU KNOW

raw jetty
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then tell the answer kid

heady panther
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OK YOU KNOW I ASK YOU QUESTION

raw jetty
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guys how much your precdicting hes underaged

raw jetty
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uhh

heady panther
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THE ANSWER IS 15

vale wigeon
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if you haven't then now's as good a time as ever to make one

heady panther
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IS TERM TO TERM ADD 2 THEN ADD 3

raw jetty
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the question is in text so i have to make one myself

vale wigeon
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yes you do

raw jetty
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wajt

heady panther
raw jetty
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10+2=12

heady panther
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THEN ADD 3

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IS 15

raw jetty
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why

gray isle
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if you want genuine help, claim your own channel, don't invade others

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and don't test helpers

heady panther
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TERM TO TERM MEAN THE REALIZED NUMBER

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TERM TO TERM 2ADD 3ADD

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HIHAHAHAHAH

raw jetty
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do you guys think he is 10 or 11

gray isle
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and don't talk in all caps

raw jetty
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or maybe 9

vale wigeon
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@heady panther stop.

heady panther
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WHY

vale wigeon
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@raw jetty do not encourage channel intrusion.

heady panther
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I COME TO USE APP

vale wigeon
gray isle
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think this is more than worthy of a <@&268886789983436800>

heady panther
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BUT YOU NOT RESPECT TO ME

raw jetty
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do you reccomend any website/app to draw those geometric stuff on phone?

gray isle
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draw on paper

heady panther
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GOOD BYE THAT NOT MY PLACE

raw jetty
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i dont have a pen

gray isle
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pencil?

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no paper and/or writing tools at all?

raw jetty
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i have paper but no writing tools

gray isle
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do you have a stylus for your phone?

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i think you're going to be better of coming back to this problem when you can properly write down the work

raw jetty
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heres the diagram

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@vale wigeon

vale wigeon
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hm

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right

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nothing comes to mind at the moment

raw jetty
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sorry if the drawing sucks

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the last time i tried to approach it i set the point where the smaller circle touches the outer circle to be like N or smth, then i tried to find it ysing the basis that AFG=FGN but i have no idea if that was even correct or not

lone heartBOT
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@raw jetty Has your question been resolved?

lone heartBOT
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@raw jetty Has your question been resolved?

raw jetty
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<@&286206848099549185>

gray isle
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draw the radii from the centre of the small circle to the points of contact
and to A as well

subtle birch
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Okay so here is what I did
Find radius of bigger circle and find height of triangle
Now set three variables GC=y
OC=r
OD=x
where O is centre of smaller circle and D is the bisector of BC
Now you have OG is perpendicular to AC
So you got two right triangles OAG and ODC

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you'll get two equations in r,y,x

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Observe the length DE is just diameter of larger circle minus height of triangle
where E is the point of contact of two circles

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So you can get another relation between r and x

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3 equations and 3 variables

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solvable

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@raw jetty

raw jetty
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uh how is DE diameter of larger circle-height of triangle

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i need to go

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.close

lone heartBOT
#
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subtle birch
#

All the time I invested...

lone heartBOT
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sick lion
#

Find at positive x the minimum value x^4+3/x

sick lion
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Pls help

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<@&286206848099549185>

subtle birch
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$\frac{x^{4}+3}{x}$
This?

ocean sealBOT
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beard420

charred summit
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or $\frac{3}{x}+{x^{4}}$

ocean sealBOT
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sherif_player

sick lion
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Second

charred summit
#

So did you study calculus?

sick lion
#

No

charred summit
# sick lion No

Oh
So solving this problem would be mush easier if you have studied it.

But in what way do you want it

sick lion
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I need to solve it.

wind cloak
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How would you even do this without derivatives

charred summit
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$\frac{-3}{x^2} + {4x^3}$

ocean sealBOT
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sherif_player

sick lion
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Yes, that's derivative

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To level further to zero?

charred summit
sick lion
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X = (sqrt5{24})/2

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I misunderstood what you meant.

charred summit
lone heartBOT
#

@sick lion Has your question been resolved?

lone heartBOT
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autumn vigil
#

x^2+(a-b)x+(1-a-b)=0 find the condition for a for which roots are imaginary ∀ b∈R

autumn vigil
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I have been taught the method of taking D>0 and then making another quadratic in b and then taking its D>0 for the other part (which was real and unequal roots) but i am not able to understand what to use in this

wet nest
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First D<0

autumn vigil
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did that...and i get b^2+(4-2a)b +(4a-4+a^2)

wet nest
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And when you get the quadratic in b. It's Discriminant must be greater than 0 since b is a real number

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Questions has said for all b belongs to R

autumn vigil
wet nest
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Wait there is no solution, right

autumn vigil
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yes

wet nest
autumn vigil
wet nest
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What condition must a quadratic follow to be always negative

wet nest
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And b<0

autumn vigil
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ohh yes

wet nest
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You don't have that

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So no solution

autumn vigil
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ummm lemme see what u wrote and think again lmao

autumn vigil
wet nest
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Yeah

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But it doesn't matter

autumn vigil
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ohh so can i write it like this? b^2+(4-2a)b +(4a-4+a^2)<0 but for a quad to be <0 a<0 but it has >a so there is no sol? @wet nest

wet nest
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D<0

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not a

autumn vigil
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but if i make D<0 then i get a>1

wet nest
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Leave a

autumn vigil
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alright

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got it

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can u solve another question related to range of quad??

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or i have to create another channel?

wet nest
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Send the question

autumn vigil
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y=(x^2-3x-2)/(x^2-2x-5) find range

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instead of x there was tan but as tan has its range as all real values so i took it as x

wet nest
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What is the answer?

autumn vigil
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dont know

timber latch
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ok so

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first perform long division

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or

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lets do it without division

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we see limits at both inf and -inf are 1

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now we need all critical points

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they are

autumn vigil
timber latch
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zeroes of f'(x) and places where its undefined

timber latch
autumn vigil
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we are taught a method of taking the denomintor to left and making a quad in x and solving by suing D formula

timber latch
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thats gonna make this a whole lot more annoying

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thats the harder method

autumn vigil
timber latch
#

diffrentiation is simpler method

timber latch
autumn vigil
timber latch
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knew it

autumn vigil
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lmao

timber latch
#

i did diffrentiation early

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so i always use that for these questions

autumn vigil
#

ohh in maths? or in physics

timber latch
#

the discriminant method is annoying af

timber latch
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lack of diffrentiation makes this hella annoying

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ok so

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take denominator to other side

autumn vigil
autumn vigil
#

<@&268886789983436800>

tacit arch
#

<@&268886789983436800>

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someone got an F on their addition exam

autumn vigil
timber latch
#

<@&268886789983436800>

autumn vigil
timber latch
#

what

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how

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where the y go

autumn vigil
#

x

timber latch
#

just close this channel and go to a new one

autumn vigil
sleek gyro
#

jeez

autumn vigil
#

..close

sleek gyro
#

im sorry, taken care of

autumn vigil
#

.close

lone heartBOT
#
Channel closed

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autumn vigil
#

oh....i closed

lone heartBOT
#
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alpine sable
#

Hey, I am currently working on my terrible math, and seem to not be understanding this rather basic principle.

What exactly is the reason that in this exercise y isn't 2/(p+q) but 8/(p+q+4), why can't you simplify?

gray isle
#

basic fraction simplification involves
multiplying/dividing the whole of the numerator and denominator by the same value,
(effectively multiplying by 1)
and/or cancelling a common factor

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you can't divide the numerator by 2
while only dividing only a single term in the denominator by 2

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in your case it's not quite that,
but either way, not valid

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which changes the ratio

alpine sable
gray isle
#

no

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4/4 isn't 0

alpine sable
#

mhm

gray isle
#

don't overthink the value of 4/4

tardy stag
#

$y = \frac{2}{\frac{p}{4} + \frac{q}{4} + \frac{4}{4}}$

ocean sealBOT
#

Hayley

alpine sable
#

or am i misunderstanding still?

gray isle
#

+1 in the denominator, in the place of the 4/4,

alpine sable
#

mhm yeah

#

of course

tardy stag
#

$y = \frac{2}{\frac{p}{4} + \frac{q}{4} + \cancel\frac{4}{4}1}$

ocean sealBOT
#

Hayley
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

tardy stag
#

oh god

alpine sable
#

lol

gray isle
#

$y = \frac{2}{\frac{p}{4} + \frac{q}{4} + \cancelto{1}{\frac{4}{4}}}$

ocean sealBOT
#

ℝamonov

gray isle
#

good enough

alpine sable
#

okay thanks for the answers & help guys, this makes sense now; even though latex doesnt seem to enjoy this very much :p

#

.close

lone heartBOT
#
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strong summit
lone heartBOT
strong summit
#

For e I got this

#

How do I put this as an inequality

#

Is it x bigger than or x smaller than 1?

tacit arch
#

"increasing" means the derivative is nonnegative

strong summit
tacit arch
strong summit
#

Yeah Ik that but how does that help

tacit arch
#

have you seen these symbols before
< , >

strong summit
#

Yeah inequalities which is supposed to be the final answer

tacit arch
#

< is "less than"

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e.g. 2 < 3 is a true statement

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and > is "greater than"

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e.g. 1 > 0 is also a true statement

strong summit
#

Ik that

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But here I got 2 answers for x that equal the same

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Idk what to do with that

lone heartBOT
strong summit
tacit arch
#

what do you mean "equal the same"

strong summit
#

(X-1)(x-1)

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If I put ‘‘em in a number line

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The answer could be positive if it’s less than or bigger than 1

tacit arch
#

do you know (x-1)(x-1) = (x-1)^2 ?

strong summit
#

Yeah

tacit arch
#

are squares of numbers ever negative?

strong summit
#

No

tacit arch
#

or equivalently, does the graph of (x-1)^2 ever go below the x-axis

strong summit
#

No

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So it’s all numbers?

tacit arch
#

right

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,w plot 3 + 3x - 3x^2 + x^3

strong summit
#

Do I just write all values of x are increasing?

tacit arch
#

the derivative of f(x) only equals zero at x=1. everywhere else it's positive

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yes

strong summit
#

Is there a mathematical way to write this?

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In an inequality form ?

tacit arch
#

just use words

strong summit
#

Alright thank u so much

#

.close

lone heartBOT
#
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proper heron
lone heartBOT
trim sorrel
#

Can you state the commutative property?

proper heron
#

What

trim sorrel
#

What is the commutative property

#

Do you know

proper heron
#

commutative property in math means you can switch the order of numbers being added or multiplied without changing the result.

trim sorrel
#

Right

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A + B = B + A

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How can you apply that here

spare canopy
#

oops

lone heartBOT
#

@proper heron Has your question been resolved?

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lone atlas
lone heartBOT
lone atlas
#

I thought the answer to this should be

#

$y=\frac{1}{4}x+\frac{3}{4}$

ocean sealBOT
#

v3ryberry

lone atlas
wary stream
#

It is

naive valley
#

your work all looks fine, but you didn't actually show the question

wary stream
# lone atlas

$\frac{1}{4} \left(x + 3\right)^1 = \frac{1}{4}x + \frac{3}{4}$

ocean sealBOT
#

dldh06

wary stream
#

I'm assuming the first image is the answer key

lone atlas
#

yeah the first answer is the answer key

naive valley
#

ahh i see thx

lone atlas
#

I was just wondering if my answer was wrong

naive valley
#

no wonder it looks correct haha

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i have no idea why they felt the need to put the 1 exponent

wary stream
# lone atlas

It's not clear what your answer as I don't see a y = answer

#

I see all the math, but what's the final answer you got?

naive valley
#

is that the equation in the upper right corner?

#

best if you can write stuff in order and maybe put a box around the answer 😁

lone atlas
#

ohh whoops

#

i ran out of space on my paper

wary stream
#

So what exactly is your question?

#

Your answer matches the answer key

lone atlas
#

No you guys answered it already

#

I didn't understand why my answer was different from the answer key

#

but if both the answers mean the same thing then it's ok

wary stream
#

Answer key was just in a different format, that was all

#

Because don't forget x/4 = (1/4)x

lone atlas
#

Ok

#

thank yu

#

.close

lone heartBOT
#
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harsh pewter
#

Hey guys I am currently in class 11th And on 7/7/23 I have my maths exam can Anyone Give me overview or idea about what exactly linear inequalities is ?

harsh pewter
#

thank you Bot you owe me

wary stream
#

What?

lone heartBOT
#

@harsh pewter Has your question been resolved?

tacit arch
#

.close

lone heartBOT
#
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woeful current
lone heartBOT
woeful current
#

Help plz

worn fox
naive valley
trim sorrel
#

HAHAHA

woeful current
#

95% of people can’t solve!

trim sorrel
#

More than 95

vague coral
tacit arch
#

!elliptic curve meme

lone heartBOT
#

🍎 = 154476802108746166441951315019919837485664325669565431700026634898253202035277999
🍌 = 36875131794129999827197811565225474825492979968971970996283137471637224634055579
🍍 = 4373612677928697257861252602371390152816537558161613618621437993378423467772036

tacit arch
#

!solved

woeful current
#

Ok at least explain why it can’t be solved then

trim sorrel
#

In number theory, Fermat's Last Theorem (sometimes called Fermat's conjecture, especially in older texts) states that no three positive integers a, b, and c satisfy the equation an + bn = cn for any integer value of n greater than 2. The cases n = 1 and n = 2 have been known since antiquity to have infinitely many solutions.The proposition was f...

woeful current
#

In 50 words or less

#

In 50 words or less

trim sorrel
#

I wrote the proof in the margin of my book but i cant find it

#

Sorry

#

I would be able to if i knew where it was tho

woeful current
#

No issue, shouldn’t be too hard to remember then

trim sorrel
#

Somehow its slipping my mind

hazy loom
# tacit arch !solved

btw srry if this isn’t math related but you haven’t used your boosts ok me out srry once again TT_iboringPersonOwO

lone heartBOT
#

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snow lichen
#

There are two parking garages in Beacon Falls. Garage A charges $7.00 to park for the first 2 hours, and each additional hour costs $3.00. Garage B charges $3.25 per hour to park. When a person parks for at least 2 hours, write equations to model the cost of parking for a total of x hours in Garage A and Garage B.
help?

tacit arch
snow lichen
tacit arch
#

no you don't

#

Garage A charges $7.00 to park for the first 2 hours, and each additional hour costs $3.00

snow lichen
tacit arch
#

again, no you don't

#

you eventually need to

tacit arch
snow lichen
#

right?

tacit arch
#

nope

snow lichen
#

how?

tacit arch
#

Garage A charges $7.00 to park for the first 2 hours

snow lichen
tacit arch
#

again, no

snow lichen
#

how?

tacit arch
#

$7 for two hours

snow lichen
#

OOHHHHHHHHHHHHHHHHHHHH

tacit arch
#

doesn't matter if you park for 1 minute

snow lichen
#

omg

tacit arch
#

or 120 minutes

#

you still get charged $7

snow lichen
#

yea

#

im so sorry

#

so after 2 hours we just add three?

#

so for three hours its 10?

tacit arch
snow lichen
tacit arch
#

A looks right. B does not

snow lichen
#

@tacit arch bro

tacit arch
#

are you done?

snow lichen
tacit arch
#

oh no you need equations

snow lichen
tacit arch
#

try plotting

snow lichen
#

huh?

#

can we just do algebra

tacit arch
#

sure you can

#

try it

snow lichen
#

how tho

#

wait

tacit arch
#

have you seen equations of lines before

snow lichen
#

if i park for 1 minute, is that still 7 dollars?

tacit arch
#

y = mx + b maybe

snow lichen
tacit arch
#

garage A is harder than garage B. i suggest working on B first

tacit arch
tacit arch
#

great you're done with B

snow lichen
tacit arch
#

indeed it isn't

snow lichen
tacit arch
#

no. it is

snow lichen
tacit arch
#

just english

snow lichen
#

how do we make it

tacit arch
#

you could do it with piecewise function

#

have you learned that yet

snow lichen
tacit arch
#

you specifically said you didn't want to graph

#

you don't need to graph to find the equation for garage A

snow lichen
tacit arch
#
Khan Academy

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snow lichen
#

ik what it is

#

but we need to make an equation

tacit arch
#

try making a piecewise one

snow lichen
tacit arch
#

you said you know what piece functions are

#

so try making one

snow lichen
tacit arch
snow lichen
snow lichen
#

he bases it off an equation

tacit arch
#

that picture is itself a piecewise defined equation

#

use your numbers from here to similarly define one

7, 7, 10, 13, 16,

snow lichen
#

like if i use 7

#

and do it from 1-5?

tacit arch
snow lichen
tacit arch
#

7 is the price for the first two hours

#

at hour 3, the price is $10

#

and at hour 5, the price is $16

#

so 7 wouldn't be the price for the first 5 hours

snow lichen
#

and graph it from 1-5?

tacit arch
#

i don't know what you mean by "use"

#

write a piece wise function

snow lichen
tacit arch
#

that's not an equation

#

can you turn the table into an equation

snow lichen
#

can we

tacit arch
#

try it yourself

snow lichen
#

like i cant find anything

#

and the calc cant either

#

hello?

tacit arch
#

Your piecewise function should be one function for x <=2 and another function for x> 2

tacit arch
snow lichen
#

.close

lone heartBOT
#
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rich moat
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digital moon
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digital moon
#

Status 1

willow patio
#

Do you remember how to complete the square @digital moon?

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wintry panther
#

Try to simplify $\frac{a^2+a(a+1)+(a+1)^2}{a^3(a+1)^3}$ and see what you get

ocean sealBOT
wintry panther
#

Try to get telescoping series

#

It's actually 1/a^3 - 1/(a+1)^3

#

I got to go now

#

Good luck

lone heartBOT
#

@alpine sable Has your question been resolved?

trim sorrel
#

,w expand a^2 + a(a+1) + (a+1)^2

trim sorrel
#

Tis the same

#

Cain was right

flat dawn
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trim sorrel
#

Oop

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midnight forge
#

1+1=?

lone heartBOT
wheat isle
#

3

glass estuary
#

which base?

#

10 in binary :D

tacit arch
#

.close

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icy jewel
lone heartBOT
icy jewel
#

help idk whats wrong

#

this is the triangle i made from the info

toxic comet
#

read the given distances carefully

icy jewel
#

o

#

i adjusted the calculations and got 209, but\ its still not working

visual girder
#

i probably shouldnt say this but have u tried googling the question lol

#

there could be a step by step solution thingy online that u can use

icy jewel
#

fair point

#

considering how lazy and stupid my teacher is she probably hasnt changed the hw in years

#

considering she doesnt even have the time to respond to emails

visual girder
#

dang 💀

icy jewel
#

yo the answer is on chegg

#

oh i dont have chegg

#

:(

#

i cant find answer

whole marten
#

o;-;

tardy stag
#

I can't tell what you did wrong

#

i mean you did something wrong

#

but I can't tell what it was, how did you get those values? like the angle

visual girder
whole marten
#

mine comes out near to 243 ;-;

icy jewel
#

rlly?

#

oh that worked

#

how did u get 243

tardy stag
whole marten
icy jewel
#

ok thx

#

.close

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wheat isle
#

I’m unsure how to approach part B and C

lone heartBOT
upbeat hornet
#

For b, you just have to substitute t = 0 into the equation since that's what it means

#

For c, it is very similar

wheat isle
#

So N = 450(3)?

#

For part B

#

Actually

#

It would just be 450 right

#

450(3^0) = 450(1)

upbeat hornet
#

Yes

wheat isle
#

And part C i is 450(3^3)?

#

Assuming you sub in 3 for t

#

Actually

#

450(3^(0.9*3))

#

Cheers

#

.close

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warped horizon
#

Are the steps i used here correct ?

lone heartBOT
warped horizon
#

I got the answer but im kinda skeptical about the simplification

#

Like where i cancelled 2 and 12

#

Is it right to do that step ?

tardy stag
#

near the beginning you went from $\frac{r}{1/2}$ to $\frac{r}{2}$ and that doesn't seem right

ocean sealBOT
#

Hayley

tardy stag
#

cancelling 2 and 12 is fine there

warped horizon
#

Oeh okay

warped horizon
tardy stag
#

oh okay

#

everything else seems fine algebraically

ornate ginkgo
#

I assume you want to find the distance of the point (x1,y1) intersection of both lines from (3,4)

warped horizon
tardy stag
warped horizon
#

One sec

ornate ginkgo
#

It's 12

warped horizon
#

Is that right ?

#

@tardy stag this

warped horizon
tardy stag
tardy stag
ocean sealBOT
#

Hayley

tardy stag
warped horizon
#

Oeh i see

#

Thank u for the help @tardy stag n @ornate ginkgo

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grave lily
lone heartBOT
grave lily
#

this is the problem i am working on

#

i was able to solve the differential equation but i am stuck on how to find the domain

lone heartBOT
#

@grave lily Has your question been resolved?

grave lily
#

<@&286206848099549185>

tacit arch
grave lily
#

I’m not entirely sure could you clarify for me

grave lily
#

<@&286206848099549185>

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@grave lily Has your question been resolved?

grave lily
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.close

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foggy reef
lone heartBOT
foggy reef
#

can someone pls explain to me why the inequality reverses

little hazel
#

because log_10(0.7) is negative

#

think about why

foggy reef
#

how is it negative?

little hazel
#

think about what value of k

#

would give log_10(k) = 0

foggy reef
#

aaaaaahh

#

ok

#

i get it

#

thx bro

little hazel
#

np

foggy reef
#

.close

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still wadi
lone heartBOT
still wadi
#

need some help here

lone heartBOT
#

Show your work, and if possible, explain where you are stuck.

still wadi
#

Mr. Bot, not possible cause I have no clue where to start. That's why I need help

#

<@&286206848099549185>

#

I finished that problem, now I need help with a new one

#

no

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alpine sable
lone heartBOT
alpine sable
#

When I set this up i get m = c1e^x + c2e^-x

#

does it matter which order i do this in

mortal trellis
#

c1 e^-x + c2 e^x is the same

alpine sable
#

okay i just want to verify, my solution manuel does it differently so i wanted to make sure there wasnt some rule i was missing

#

thank you 🙂

#

okay another question

alpine sable
#

im getting 2, e^xcoshx and e^-xcoshx

#

so i simplifly the 2 expressions on the right, divide them by 2 and then take the integral?

#

IE e^xcoshx = 1/2(e^2x +1)

#

then divide that by 2 and take the integral right?

mortal trellis
#

i don't remember enough about odes to help you there, sry

alpine sable
#

its no problem thank you for the assistance though 🙂

#

.close

#

.close

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ocean sealBOT
#

1shero1

mortal trellis
#

well if you combine all these fractions again you will be left with (some polynomial)/q(x)

#

and that (some polynomial) is p(x) if you choose the A_i correctly

#

there are proofs

#

but none that I know that give more intuition

#

than just "you can do it, here is even an algorithm for how to"

mellow grail
#

Idk, but I guess you could reason that any constant A_I times (x-a_i) will also be a polynomial as long as A_I is not 0

#

so when you do add these up

mellow grail
#

to be more formal, (sum of A_i)x - (sum of a_i)(sum of A_i)/q(x)

mortal trellis
#

but you dont want that because?

#

writing this down formally is just an exercise in using sum and product notation

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craggy trellis
#

Need help pls

lone heartBOT
#

Please don't occupy multiple help channels.

subtle birch
#

well, that was a coincidence and you occupied channel #help-13

#

Close it

craggy trellis
#

.close

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craggy trellis
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What step are you on?
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5. I have a question about someone else's worked solution
6. None of the above
ocean sealBOT
#

methisalwaysright

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#

@craggy trellis Has your question been resolved?

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@craggy trellis Has your question been resolved?

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chilly crag
#

That they are imaginary

#

Or actually

ruby current
#

the only nontrivial factors of a quadratic are linear

worn fox
#

You have to specify over what field it is not factorisable

ruby current
#

usually Q in the high school sense

ocean sealBOT
#

1shero1

#

1shero1

chilly crag
#

Likely that it has nor real roots

#

But it lacks context as Zac said

#

Or Sac or EAC idk how to write it sry

lone heartBOT
#
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ruby current
#

not sure about irrational roots

#

i think we regard irrational roots as not irreducible

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lone heartBOT
vale wigeon
#

do you know how percentages work

#

well you either do or you don't

#

why urgent?

#

are you in a test?

#

we don't help on tests.

#

it's against the rules and even bannable.

#

well that sorted itself out relatively quickly

#

.close

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primal flume
#

Could anyone help me with trigonometry and finding side lengths using trig ratios and multiplication

subtle birch
#

Question pic on the way?

primal flume
#

um yeah one sec

#

Im not sure how to do trig yet

#

i know the ratios though

subtle birch
#

so what values did you calculate

#

side length and angle value?

primal flume
#

one sec lemme pull up the powerpoint

#

so the angle was 32 degrees and the side length was 4.6cm

ebon sparrow
#

Use sine ratio

subtle birch
primal flume
#

k

#

sorry its kinda messy

subtle birch
#

okay

#

Do you know what sin(theta) is?

primal flume
#

no

subtle birch
#

it is the ratio of opposite side and hypotenuse in a right triangle

primal flume
#

oh like SohCahToa?

subtle birch
#

Yes

primal flume
#

yep i know what it is then

#

sorry i was confused

subtle birch
primal flume
#

yep got it

#

but how do i find the side length of the triange?

subtle birch
#

cos(32 deg) would be AB/AC

#

just put in values to find the length AC

primal flume
#

im sorry but I have absolutely zero clue what that means

#

do you think you could walk me through what the question is asking?

ebon sparrow
#

[sin(32) = \frac{4.6}{x}]

ocean sealBOT
ebon sparrow
#

@primal flume solve for x

primal flume
#

how do i solve x?

#

sin * 32?

ebon sparrow
#

Start with cross multiplication first

primal flume
#

is it like this?

ebon sparrow
#

Yes

primal flume
#

k

ebon sparrow
primal flume
#

not really

ebon sparrow
#

Okay so the angle doesn't have Hypotenuse

#

But you have Opposite

primal flume
#

yep

ebon sparrow
#

You need always remember sohcahtoa definitions

primal flume
ebon sparrow
#

That's good

primal flume
#

did i do that right?

ebon sparrow
#

Why did you put two x

#

On sin side

primal flume
#

isnt it sin32 times x?

ebon sparrow
#

Sin(32) x

#

You're dividing not multiplying

primal flume
#

oh yeah

ebon sparrow
#

,calc sin (32)

ocean sealBOT
#

Result:

0.55142668124169
ebon sparrow
#

Now divide this by 4.6

#

4.6 divide by sin 32

primal flume
#

8.341997506616519?

ebon sparrow
#

Yes

#

$\frac{\cancel{sin(32)x}}{\cancel{sin (32)}}=\frac{4.6}{sin(32)}$

ocean sealBOT
ebon sparrow
#

Did you do like this

#

If yes then you are correct

#

@primal flume

primal flume
#

yeah sorry just trying to process what i just did

ebon sparrow
primal flume
#

....

ebon sparrow
#

Your work

primal flume
#

one sec

#

so what we just did

#

was that finding the side length by division?

ebon sparrow
#

ye

primal flume
#

ohhhhhh

#

k

ebon sparrow
# subtle birch

Isn't the question asking to find AC? Then you need find the Hypotenuse

#

That's why we used the sine ratio

primal flume
ebon sparrow
#

Yeah

primal flume
#

oh

#

yeah i get it now

#

oh yeah

#

so sin(32) is opposite over hypotenuse

ebon sparrow
#

Yep

primal flume
#

and you use x because its an unknown value

ebon sparrow
#

Yeah

primal flume
#

but why use cross mulitplication?

ebon sparrow
#

Because you need to solve for x

#

After you added the 1

#

,tex .butterfly

ocean sealBOT
ebon sparrow
#

@primal flume

primal flume
#

oh yeah

#

ohhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

ebon sparrow
#

By cross multiplying these two fractions, you can easily solve for the variable at hand thanks to the reduction to only one equation

primal flume
ebon sparrow
#

Yes

primal flume
#

ah yes

ebon sparrow
#

Are you done?

primal flume
#

nearly

ebon sparrow
#

Okay

primal flume
#

oh wait

#

didnt we find out the adjacent side?

ebon sparrow
#

Angle CB?

primal flume
#

the opposite of a right angle triangle is the side opposite to the non right angle

#

isnt it?

ebon sparrow
#

It's the hypotenuse

primal flume
#

what?

ebon sparrow
#

Yes

primal flume
#

oh ok

#

so we figured out the adjacent right?

#

or sorry i measured the adjacent instead of the opposite

ebon sparrow
#

They already given you the opposite

#

Not sure if you need to find Hypotenuse or adjacent

#

Let's find adjacent

#

Tan or cos

#

But your question asking to find AC

#

Which is Hypotenuse

ebon sparrow
#

^^

primal flume
#

is this the adjacent side?

ebon sparrow
#

Oh yes

#

My fault I read this as opposite side

primal flume
#

all good

#

so we did Tan instead of Cos

#

correct?

ebon sparrow
primal flume
#

oh yeah

#

mb

ebon sparrow
#

It's fine

primal flume
#

one sec ill measure the opposite side

#

that was my mistake

ebon sparrow
#

Oh okay

primal flume
ebon sparrow
#

Is this a different one?

primal flume
#

no the same

#

i did the question wrong at the start

ebon sparrow
#

You added 2.8

#

Oh

primal flume
#

so i was supposed to measure the opposite but i measured the adjacent

ebon sparrow
#

I see

primal flume
#

sin(32)x = 2.8?

ebon sparrow
#

Yeah

#

Btw you can use wolfram to check your answer

#

Phone died I gtg

primal flume
#

oh

ebon sparrow
#

Have you heard of wolfram like do you know how to use it?

primal flume
#

no

ebon sparrow
#

,w sin(32)x = 2.8?

ebon sparrow
#

Like this

#

,w type smth

primal flume
#

k thanks

ebon sparrow
#

np

primal flume
#

do you have to go?

#

@ebon sparrow you probably wont see this but thanks for all your help :)

#

mods ill close it soon i just have to take notes

#

.

#

.

ebon sparrow
ebon sparrow
ebon sparrow
primal flume
#

ok thankyou

#

.

ebon sparrow
#

still stuck?

primal flume
#

no im just figuring out the other questions

ebon sparrow
primal flume
#

yep

#

finished that

ebon sparrow
#

oh so you're moving to another question

primal flume
#

yep

ebon sparrow
#

then you're all set

primal flume
#

yep

#

i might need help later on another question but im all good for now

ebon sparrow
#

you can still open a new channel at any time

primal flume
#

ok

#

i might just keep this one open because im nearly at the next question

#

which i dont know

ebon sparrow
#

can i see it

primal flume
ebon sparrow
#

okay so you need to use cosine ratio this time

#

what do you need find for A or H?

#

what are the numbers given

primal flume
ebon sparrow
#

okay

primal flume
#

,w tan(21)x = 3.6?

ebon sparrow
#

tan?

#

but the questio is asking for cos

primal flume
#

oh that was another question

ebon sparrow
#

oh lol

primal flume
#

so the adjacent is 3.3

#

oh wait

#

two sides

#

one sec

ebon sparrow
#

no thats opposite side

primal flume
#

....

#

oh yeah

ebon sparrow
#

opposite side always eye at angle

#

it's fine

#

btw what is H?