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lone heartBOT
#
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night lodge
lone heartBOT
night lodge
#

where does the 1/2 come from

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ah 9^1/2 = 3

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not entirely sure how im supposed to find that out tho?

alpine sable
#

Bases are equal now.

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So, 2y = 1.

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y= 1/2.

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Just practice the questions. You'll get a hang of it.

proven leaf
ocean sealBOT
#

XxMrFancyu2xX

night lodge
#

ahh got it

#

ty both of u

#

.close

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proven leaf
lone heartBOT
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potent flame
#

I only got 2 are there more than 1 answers?

lone heartBOT
#

Show your work, and if possible, explain where you are stuck.

potent flame
#

I got the answer but Im not sure if there is more than one for this question

alpine sable
#

how did you get x=2?

potent flame
#

simplified the left side of the log then just continued with solving it and got 2, and-18 but -18 does not make the equation true

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so idk if 2 is the only answer i put or -18 also

alpine sable
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yes, you are right

potent flame
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so i only put 2?

alpine sable
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x>0 is assumed

potent flame
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what that got to do

alpine sable
#

you cant take logs of negative numbers

potent flame
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oh ok

#

thanks

lone heartBOT
#

@potent flame Has your question been resolved?

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night zephyr
#

Hello! I need help with this question where do I start

night zephyr
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Im not quite sure what to do, as I cannot find it in any of my homework

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hasnt been quite 15 minutes but <@&286206848099549185>

proven leaf
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lol ok I can help, is your goal only to sketch?

night zephyr
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yes, i am pretty sure i can find the domain and range

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after the sketch

proven leaf
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so first off let's look at where f(x)=0

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where are those numbers?

night zephyr
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-3 and 0

proven leaf
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yep ok good, so because $\sqrt{0}=0$ those will be zeroes of root f(x) as well :))

ocean sealBOT
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XxMrFancyu2xX

night zephyr
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okayyy sooo can i just find the root of those

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right?

proven leaf
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yep

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wait hang on

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what do you mean by root of those?

night zephyr
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like this?

proven leaf
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that is not $\sqrt{f(x)}$

ocean sealBOT
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XxMrFancyu2xX

night zephyr
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im not sure,

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uhhh do I take f(x) = (x + 3)(x - 0)

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no

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ahh

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my thinking behind that was if its sqrt root i need to take that point and square root it

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every point where the line passes through

night zephyr
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The domain for y = f(x) is (x, infinity) and the range is (y equal to and greater than -3)

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sorry i should say -infinity to infinity for the domain

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Mr. Fancy?

tawdry urchin
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if you take a square root of a negative number, it will be complex, and therefore unrepresentable on your graph

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so any value > 0 will not satisfy your function

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so your domain will be from 0 to inf

night zephyr
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okay

tawdry urchin
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do you know if you have to take plus-or-minus when you take sqrt?

night zephyr
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im still lost sorry, I just not sure what exactly what to do. I know my zeros are -3 and 0

tawdry urchin
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because i know some teachers like to get rid of the negative solution

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i don't think the zeroes matter?

night zephyr
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we didn't even go over this question, well i don't remember it so im a little lost as to how to convert the graph from y = f(x) to y = sqrt f(x)

tawdry urchin
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what course ru taking?

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alg 1 or 2

night zephyr
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Mathematics 30-1

tawdry urchin
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which country?

night zephyr
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Its not public school.

tawdry urchin
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ah

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alr

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ima just assume plus or minus then

night zephyr
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aight

tawdry urchin
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so do you know that $\sqrt{4} = \pm{2}$

ocean sealBOT
#

Dork9399

night zephyr
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yes

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sqrt of 4 = 2

tawdry urchin
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so therefore you have to take whatever you have above the y-axis, and also put it below the y-axis

night zephyr
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the horizontal line?

tawdry urchin
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wait, let me make a graph real quick

night zephyr
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here is the original if you wish

tawdry urchin
#

ty

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so i just copied it onto desmos

night zephyr
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aight

tawdry urchin
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now as we discussed, for the square root, everything where x<0 doesn't matter because this is a normal plane, not a complex plane

night zephyr
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okay

tawdry urchin
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so all that matters is where x>0

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good so far?

night zephyr
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yes

tawdry urchin
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so firstly, our domain is obv x>0, since x cannot be less than 0

night zephyr
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right

tawdry urchin
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also, when we take sqrt, we have to take plus or minus

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here is a sketch of the sqrt function(red

night zephyr
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okay

tawdry urchin
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so your range will be from $\sqrt{2}$ to $-sqrt{2}$

ocean sealBOT
#

Dork9399

night zephyr
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sorry my power cut out and my computer crashed

night zephyr
tawdry urchin
#

isnt that your answer?

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ight i gtg

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hopefully u get an answer

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gtg

night zephyr
night zephyr
#

.close

lone heartBOT
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alpine sable
#

would this be non linear ?

lone heartBOT
placid zinc
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It's linear if it's of the form
y = mx + b

alpine sable
#

so thats not in that form

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im trying to follow this

placid zinc
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The z makes me sus.

placid zinc
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Because xz can't be put into that form

alpine sable
placid zinc
#

But I can write it as
-ex - y = -100

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So -100 takes your b slot

alpine sable
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thats right

placid zinc
#

Don't let e confuse you, it's a constant as well

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So this one is linear

alpine sable
#

ye

lone heartBOT
#

@alpine sable Has your question been resolved?

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alpine sable
#

Hello I could use some help in trig

lone heartBOT
alpine sable
#

cos theta / csc theta -1 * csc theta +1 / csc theta +1

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The first thing i did was combie the bottom into a id and got the top / -cot^2

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i think thats right so far

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hello...

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anyone

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fallen verge
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Thats a plus/minus symbol

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Hmm idk if it has a specific name

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Yes

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For example

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If you have a problem like x^2=4, both -2 and 2 are solutions

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So you can say x=±2

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lets say you just have b-3=2, can you solve for b?

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How did you do that?

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fallen verge
#

Youre welcome

lone heartBOT
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opal merlin
#

I’m confused where to even start

keen mason
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Have you solved 4th order polynomials before?

opal merlin
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a while back

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I know it’s p/q

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which is p and which is q?

alpine nacelle
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if you're thinking about rational roots theorem, then for all rational roots p/q written in the form such that p and q are relatively prime, p divides the constant term, and q the leading coefficient

keen mason
#

1

opal merlin
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then you figure out 20/1

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possible roots?

proven leaf
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that is not all the possibile cases

opal merlin
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it would be plus or minus 1,2,4,5,10,20

proven leaf
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yep :))

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I was just about to type them all out lol

opal merlin
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what do I do with that

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lol

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wait how can I figured out the end behavior of the graph

proven leaf
opal merlin
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wdym

proven leaf
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is it even or odd?

opal merlin
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even

proven leaf
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yep :)) this means it is either up-up or down-down

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think of quadratics

opal merlin
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the main thing that determines if it’s even or odd is the highest exponent

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so the x^4 is even?

proven leaf
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well the entire function is even but x^4 also is

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because $x^4$ will dominate the $x^3 \gg x$

ocean sealBOT
#

XxMrFancyu2xX

opal merlin
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so what determines if it will be up down

proven leaf
#

the coefficient of the largest exponent thusky

opal merlin
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oh right

proven leaf
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so we have a positive even highest exponent, what does that tell us about our end behavior? :))

opal merlin
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up up

proven leaf
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yep!

opal merlin
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thanks

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For the next part

proven leaf
opal merlin
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don’t I have to solve?

proven leaf
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yep

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test small numbers first especially considering you have small coefficients

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I would probably test a number like 1 first

opal merlin
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alright thanks

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using synthetic division?

proven leaf
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yep!

gusty gorge
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test by plugging in

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synthetic division if it comes out to zero

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otherwise you're wasting a lot of time calculating terms that you'll toss

opal merlin
#

thanks!

#

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lone heartBOT
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lone heartBOT
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barren scroll
lone heartBOT
barren scroll
#

how tf do i do this

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can someone please guide me through this

fallen verge
#

' <- this represents minutes

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A minute is 1/60 of a degree

olive shell
#

Help

fallen verge
#

So 30' is how many degrees?

lone heartBOT
olive shell
#

??

alpine sable
olive shell
#

How

alpine sable
#

just go to any empty one and send a msg

barren scroll
#

read that

olive shell
#

Already read it it says go to zero to ask

barren scroll
alpine sable
#

they used 0 as an example

lone heartBOT
#

@barren scroll Has your question been resolved?

tardy stag
grizzled echo
#

how to find out apha

cerulean garnet
#

channel is taken

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wheat isle
#

For 4e

lone heartBOT
wheat isle
#

I need the y value as well right

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And to find that do I sub t=0 into the function ?

proven leaf
#

to find the slope of the tangent of the point at $a$ we need $\left.\frac{\mathrm{d}}{\mathrm{d}x}\right|_{x=a}$

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plugging in zero would give the minimum/maximum i.e. points with slope=0

wheat isle
#

dx/dx?

proven leaf
#

d/dx*

wheat isle
#

oh

ocean sealBOT
#

XxMrFancyu2xX

proven leaf
#

dx/dx lol kekw

wheat isle
wheat isle
proven leaf
#

ok hang on first what is f'(x)?

wheat isle
#

Let me do it real quick

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16t^3 - 21t^2

proven leaf
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oh ok for e

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i though you were doing d and got a really wrong answer

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anyways

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i digress

wheat isle
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lol

proven leaf
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yes that is the derivative

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at t=2 we will get an output which our y

wheat isle
#

Alright I’ll do that now

proven leaf
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I mean into the function btw

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not the derivative @wheat isle lol

wheat isle
#

Oh

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ohh ok

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What would happen if we plugged that into the derivative instead of the original function?

proven leaf
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we'd get the slope of the function at t=2 which is our next step :))

wheat isle
#

Ah okay

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So this is what I got for subbing in 2

proven leaf
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v(2)=6 but yes

wheat isle
#

Ohh

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Right

proven leaf
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ok good, we have our point! thusky

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now what is the slope of the function at t=2?

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you already did this catGiggle

wheat isle
proven leaf
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yep! 🙂

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ok now we have the slope and the point

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do you know any linear equation that takes these two inputs and gives a line thonk

wheat isle
#

y-y1=mt(x-x1)

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?

proven leaf
#

yep :))

wheat isle
#

but we need a y value for that unless we’ve already found that hmmCat

proven leaf
#

so you have x1,y1 and m

wheat isle
#

Oh we do have y1?

proven leaf
wheat isle
#

That’s 6 right

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Hahaha right

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I’ll plug those values in now

proven leaf
#

now Bob's your Uncle! thusky

wheat isle
#

Wooooo

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Thank you for the help! : ‘ )

#

.close

lone heartBOT
#
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lone heartBOT
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frosty solstice
#

wo functions f1, f2 : A → B are equal if and only if they agree on each element of the
domain, i.e., f1(a) = f2(a) for all a ∈ A.
(a) Show that if f : A → B has an inverse g : B → A, then this inverse is unique. It therefore makes
sense to speak of the inverse of a function, and to write f −1 for the inverse going forward.
(b) Show (by example) that a function f : A → B may have several distinct left inverses.
(c) Show (by example) that a function f : A → B ma

pls help

ivory fern
frosty solstice
#

the inverse of f: A--> B may be g: B --> A

ivory fern
#

But how do you define it?

frosty solstice
#

what do you mean?

ivory fern
#

What condition must an inverse of f hold?

frosty solstice
#

a = f(b)
b = f(a)

this one?

ivory fern
frosty solstice
#

im afraid i dont understand your question

ivory fern
#

Doesn't your book say something like this?

Definition. Let f: A--> B be a function. g is an inverse of f if...

frosty solstice
#

nope

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it does not

#

as far as im concerned it should be the most general one?

ivory fern
# frosty solstice it does not

I will assume that you should use the following definition: g is an inverse of f: A -> B if g(f(a)) = a for all a ∈ A and f(g(b)) for all b ∈ B

frosty solstice
#

okay

#

makes sense

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I'll email my professor tomorrow and ask him if it's okay but i see no reason for it to not be

ivory fern
#

So in this case, you have to show that if h is some inverse of f, it equals g

frosty solstice
#

is this answer correct

#

Suppose f : A → B has an inverse g : B → A, and let h : B → A be another inverse of f. We want to show that g = h.

To show that g = h, we need to show that g(b) = h(b) for all b ∈ B.

Let b ∈ B. Since g and h are inverses of f, we have:

f(g(b)) = b and f(h(b)) = b

Now, consider the composition of functions f(g(b)) and f(h(b)). We have:

f(g(b)) = f(h(b))

Since f is a function, it means that g(b) = h(b) for all b ∈ B. Therefore, g = h, and the inverse is unique.

ivory fern
#

That applies only in the case that f is injective

frosty solstice
#

hmm

ivory fern
frosty solstice
#

The function f: A → B is injective and has inverse functions g: B → A and h: B → A.

To show that g = h, we need to prove that g(b) = h(b) for all b ∈ B.

Let b ∈ B. Since g and h are inverses of f, we have:

f(g(b)) = b and f(h(b)) = b.

Now, consider g(b) and h(b). We want to show that g(b) = h(b).

Assume, for the sake of contradiction, that g(b) ≠ h(b).

Since f is injective, we know that if f(a₁) = f(a₂), then a₁ = a₂ for any a₁, a₂ ∈ A.

Considering f(g(b)) = b and f(h(b)) = b, if g(b) ≠ h(b), then f(g(b)) ≠ f(h(b)).

However, this contradicts the fact that both f(g(b)) and f(h(b)) equal b. Therefore, our assumption that g(b) ≠ h(b) must be false.

Consequently, we can conclude that g(b) = h(b) for all b ∈ B, and thus g = h.

#

@ivory fern

ivory fern
ivory fern
#

However, there is a theorem which says that a function with an inverse is bijective (and therefore injective), which perhaps you can use

frosty solstice
#

f: A → B has an inverse g: B → A and another inverse h: B → A, then f is an injective function.

#

does this work?

ivory fern
frosty solstice
#

what exactly is the theorem

ivory fern
#

Was it proven previously?

ivory fern
lone heartBOT
#

@frosty solstice Has your question been resolved?

lone heartBOT
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desert prism
lone heartBOT
desert prism
#

would I set f(x)=g(x)

#

then isolate for a and then sub it back into f(x) and then isolate for b and solve?

tardy stag
#

you need the function and its derivative to be continuous

#

just f(x) on its own won't be enough to find both a and b

desert prism
#

oh ok

#

so i take the derivative of both sides and i end up with 2a=-8/sqrt(2+b)

#

multiply each side with the denominator i assume?

tardy stag
#

sure

desert prism
#

but then the isolation gets tricky

#

2a(sqrt(2+b))=-8

#

what would i do next?

tardy stag
#

go to the next equation :P

#

or you can try to get the sqrt(2+b) on its own and square both sides

desert prism
#

ok nvm figured it out

#

ty

#

.close

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chrome monolith
#

Help

lone heartBOT
plucky token
lone heartBOT
#

@chrome monolith Has your question been resolved?

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modern maple
#

How do I solve example 3

lone heartBOT
marble coral
#

y = ax + b
a = 3 right?

tardy stag
#

they give you a chart so you might as well use it

#

you know one of the points, go ahead and draw that

#

and then you know slope is rise/run, right?

modern maple
#

Yes

#

What now

tardy stag
#

okay so can you draw a line of slope 3 coming from that point?

#

then see what value it has for x=3 to find y

modern maple
#

Oh

#

I’m dumb thanks

#

y = 3 I think

#

Is that right

tardy stag
#

modern maple
#

How do I do 4 and 5

#

What does x- axis mean

tardy stag
#

the horizontal axis

modern maple
#

I mean what does the - beside the x mean

surreal meadow
#

it’s meant to say x-axis

#

it’s just a hyphen

modern maple
#

Idk how to do the problem

#

Oh wait does it mean

#

Y needs to be 0?

#

So it’s on the black line

tardy stag
#

yeah

#

4 is going to be fairly similar to 3

modern maple
#

So would B be 6,0

#

For coordinates

tardy stag
#

modern maple
#

Thanks ima try example 5

#

Is example 5 (5, 0)

tardy stag
#

#

you seem to understand this pretty well

modern maple
#

I’m not sure about these

tardy stag
#

I can't really read the top one

#

5 you've already done

modern maple
#

Not allowed to graph it

#

And the top one is the same but with x values

tardy stag
#

do like

x   y
4   6
5   8
6   10

or extend it backwards if you need to

modern maple
#

Thanks

#

It’s late tho I gotta sleep now

#

Goodnight

#

.close

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quasi kettle
lone heartBOT
quasi kettle
#

Anybody know why this keeps happening? Am I using the options wrong?

tardy stag
#

you're grepping stdin

#

you probably want to give it a filename to look through or use -r (recursively search the current directory)

quasi kettle
#

Supposedly h is a no file name option but I don’t know if the syntax is correct

#

How do I get out of the blank line with the blinking cursor?

tardy stag
#

ctrlC should stop the process

quasi kettle
#

Thank you!

tardy stag
#

-h means don't print a filename with the output, let me get an example

quasi kettle
#

Ahh okay

tardy stag
quasi kettle
#

Ahh so h doesn’t affect the redirection just what is printed

tardy stag
#

correct

quasi kettle
#

You are the best! Thank you Hayley

tardy stag
quasi kettle
#

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plucky tree
#

am i totally stupid or does this not make any sense

plucky tree
#

its either A or B, but which one

#

where does t and p

#

and p and q come into play

carmine reef
#

Without a diagram it definitely doesn't make any sense

plucky tree
#

thats all there is to the question

vapid shuttle
#

that is not true

#

what are p and t

#

random letters?

#

no

#

they come from a diagram that you aren't including

#

what are angle 1 and angle 7?

plucky tree
#

there is no diagram 😭

#

@vapid shuttle thoughts? catthonk

vapid shuttle
#

what are these questions from?

plucky tree
#

a quiz

vapid shuttle
#

we can't help you with your quiz anyways

plucky tree
#

it says tests or exams!

vapid shuttle
#

are you allowed outside help with this quiz in your class?

plucky tree
#

yes its online

vapid shuttle
#

it being online doesn't mean your teacher said you could get outside help with it

plucky tree
#

no but she explicitly said if you don’t understand anything to use the resources around you

vapid shuttle
#

I'm not so sure that this is what she meant by that. But anyways, either there is a picture above or below this question that is meant to be part of it, or the question is not solvable and whoever made the quiz made a mistake with this question.

plucky tree
#

💀

#

W teacher

#

thx

#

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alpine sable
#

This may be aweird one but does anyone know why im getting an error

alpine sable
#

with this matrix

tardy stag
#

you missed a digit

#

or maybe more

alpine sable
#

i swear i did all

#

lemme ceck

tardy stag
#

first row has 7 elts, second row has 6

#

or 6 and 5 whatever

#

point is they're different hmmCat

alpine sable
#

ye your right lol

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heady finch
#

22nd question please

lone heartBOT
heady finch
#

I got this

vale wigeon
#

you should get better handwriting

#

those x's do not look like x's at all lol

heady finch
#

But the answer key says (-∞, -3) U [1, ∞) - {4} U {-2}

vale wigeon
#

anyway (x+3)^2021 is an odd exponent

heady finch
vale wigeon
#

so the curve should cross, not touch, at x=-3

heady finch
#

Ah okay

vale wigeon
#

also keep in mind that (a) your inequality is weak and (b) -3 and 4 should not be part of the solution set nmw

heady finch
#

I see

#

Also wdym it's weak

heady finch
vale wigeon
#

why are you concerned about values between 2 and 3?

#

did you maybe mean between -3 and -2?

heady finch
#

Ah sorry no I meant 1, 4

vale wigeon
#

and now that's irrelevant to the issue i pointed out.

heady finch
#

Wouldn't (x-4)^2022 be positive for any real value of x

vale wigeon
#

it would be positive for all x except specifically x=4.

vale wigeon
#

this is the issue with your wavy curve

heady finch
#

Aight

vale wigeon
#

it is drawn correctly to the right of -3 but not to the left

heady finch
#

I see

heady finch
vale wigeon
#

yes, exactly.

heady finch
#

I still have a doubt tho
If we take any value between -∞ to -3 wouldn't the expression be negative
Cus (x-1)^2019 has an odd exponent and would be negative

vale wigeon
#

and (x+3)^2021 would also be negative.

heady finch
#

Ah yeah

#

Aight that explains that

#

Thanks

#

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alpine sable
#

Hello! Can I have some help please? it's about Numeric and Geometric patterns. I need some help understanding the formulas again 😅

alpine sable
#

So if there are 3600 meerkats, and 470 are added each year, that means after one year there will be 3600 + 470 = 4070 meerkats.

#

I need to figure out a formula where m = meerkats and n = years, to find out how many years I will need for the population of 3600 to double

minor needle
#

That's arithmetic progression

alpine sable
#

There are many names for it lol

#

And many different formulas depending on the country too

minor needle
#

So what's your general formula

alpine sable
#

Tn = 4n + 1 I think

#

That's the only one in the book that they explain

#

And that's for fences and sticks, so | - - - | - - - |

minor needle
#

Maybe you can think about something like $T_n = a_1 + (n-1)d$?

ocean sealBOT
#

modus7591

alpine sable
#

Please can you explain that?

minor needle
#

but in fact here we even don't need a formula, logical thinking should be enough

alpine sable
#

Sure, but I need to use the formula because it's half my marks

#

And if I get it wrong then questions following that will be wrong too

minor needle
#

if at the beginning there are 3600 meerkats and after each year amount of meerkats increases by 470

#

so it goes like

#

1st year: 3600 + 470 = 4070
2nd year: 4070 + 470 = 4540
3rd year: 4540 + 470 = 5010

#

and so on

#

notice that you can rewrite it as

#

1st year: 3600 + 470 * 1 = 4070
2nd year: 3600 + 470 * 2 = 4540
3rd year: 3600 + 470 * 3 = 5010
...
n-th year: ???

alpine sable
#

Wait

#

Ohhh ok

#

Yes that makes sense

#

But I really do need to understand the formula I have here

#

It's literally half my marks in the exam

minor needle
#

but 4n + 1 is just usage of the formula

#

haven't you got general formula in the book?

alpine sable
#

Yes

#

But they're changing it without explanation

minor needle
#

send it if possible

alpine sable
#

They use T_n

#

Ok

#

I'll just take pics

#

Those are the examples they give me

#

That is apparently the formula for the meerkats

#

Wait a minute

#

If m = meerkats, and n = years

#

And the end part of the sum is exactly as you explained it...

#

Ohhh I've got it!

#

So m is the total of meerkats from the sum

#

With the sum just being mixed about a little

lone heartBOT
#

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alpine sable
#

.close

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alpine sable
#

i dont understand (b)

lone heartBOT
vale wigeon
#

do you know what population density is

queen river
#

They actually defined it for you

alpine sable
#

oh do i have to look at what population density is and then move forward

#

okay make sense

#

tysm

#

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wise snow
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wise snow
#

I am trying to write 3 trigonometry related questions with this diagram

#

I want one question to be finding the area D

#

and then two other sort of precursor questions to that

#

thoughts?

lone heartBOT
#

@wise snow Has your question been resolved?

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@wise snow Has your question been resolved?

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craggy pendant
#

sin2x < root3/2

lone heartBOT
craggy pendant
#

is x (pi/6 +2kpi, pi/3 + 2kpi) correct?

vale wigeon
craggy pendant
#

um

#

i dont even know what that 2kpi means excatly

#

but my teacher said to add 2kpi always

vale wigeon
#

well in the literal sense 2kπ is just the product of 2, k and π

#

k here ranges over the integers

#

and usually you should write that explicitly

#

the addition of these things is how you account for periodicity of trig functions

#

and hopefully you do not do it blindly like your teacher is trying to make you

craggy pendant
#

i mean i do for now

#

since i learned it recently

vale wigeon
#

it should not be blind

#

i mean ok you know what a periodic function is right

craggy pendant
#

not really

vale wigeon
#

fairly important thing to be missing

#

a function f is said to be periodic if there exists some positive P such that f(x+P) = f(x) for every x

#

or to put it another way if the graph of f can be translated left or right by some nonzero distance and end up a copy of itself

#

any such P is called a period of your function

#

with the smallest one called the fundamental period or "the period" for short

#

sin and cos are probably the first periodic functions you learn about

#

they both have period 2pi

craggy pendant
#

okay my friend just told me that its always 2kpi for sin and cos

vale wigeon
#

because, yknow, 2pi means going once around the circle

#

jeez.

#

ok.

#

so you want to listen to your friend who again makes you blind

craggy pendant
#

probably for now

#

i havent really listened in class and its hard for me to understand complex things in english

#

.close

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#
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charred plank
#

Hey all I'm trying to prove that the only normal sub-groups of $S_n$ are $1,A_n,S_n$ for $n \geq 5$
So far I know that assuming there's another nomral sub-group denote K, $K\cap A_n$ should be normal too. But since $n \geq 5$ I can conclude that the only normal sub-groups of $A_n$ is 1. Therefore $K \cap A_n = 1$ I also know that according to that (proved earlier) that if $|K| > 2$ I get that $K\cap A_n \neq 1$ therefore $|K|=2$ and I'm kinda stuck at this point. Any help?

ocean sealBOT
#

meitar5674

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#

@charred plank Has your question been resolved?

charred plank
#

<@&286206848099549185>

#

didnt know thats a thing

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@charred plank Has your question been resolved?

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bronze helm
#

Slightly confused as to how a qq plot works.

Suppose if the sample data is [1,2,3,4,5], do we then consider 1 to represent the 20th percentile of the sample date, 2 is the 40th percentile of the sample data, etc…

Now when plotting sample quantile against theoretical quantile. Do I plot ‘1’ against the 20th percentile of the theoretical distribution?

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tiny onyx
#

Hi guys, I am now currently studying sequential circuits and I've got acquainted with SR latches, D latches and D flip flops.
Now I am supposed to study finite state machines (FSM), so Moore Fsm and mealy FSM
But I don't get what the hell is a moore fsm...

tiny onyx
#

wth is this

#

😢

#

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rancid trail
lone heartBOT
rancid trail
#

I think the answer will be F, because by applying triangular law of vector addition, it will become a regular hexagon. But I want to write it mathematically. How do I do it?

alpine sable
#

you could draw it and cancel opposite forces

#

if you want to do it algebraically, convert polar to cartesian

rancid trail
#

Wtf is polar? Like, I haven't drawn any bears?

rancid trail
alpine sable
alpine sable
#

basically using sin and cos to convert an angle to a coordinate

rancid trail
# alpine sable no

Is it 0???? Because I drew the diagram and the head of the last vector touched the tail of the first vector.

alpine sable
#

yes, you can pair each vector up with its negative

rancid trail
#

Alright

#

Now I will try to convert i.t.o. sin and cos, i.e. polar form

#

Well I turned my work in, and it seems that I don't need it to prove algebraically. Thank you for your help @alpine sable

#

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pseudo flume
#

can anyone help me with this

lone heartBOT
alpine sable
#

is [x] the integer part of x?

pseudo flume
#

yeah

alpine sable
#

write f as a piecewise function to get rid of [x]

#

then it should be routine to get the range of each part

pseudo flume
#

k i will try

#

thank you for ur help @alpine sable

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sharp thorn
#

Hi

lone heartBOT
sharp thorn
#

$\int \frac{1}{x^2-9}dx$

ocean sealBOT
#

bettim

sharp thorn
#

Here now I would write the denominator as (x-3)(x+3)

#

Which comes first (x-3) or (x+3)

upbeat hornet
sharp thorn
#

Okay

#

Because i did something similar and it gave me a wrong answer because i took it in the wrong order

#

Thank you

#

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coral crag
#

factorise x^2-55x+750=0

lone heartBOT
crimson carbon
#

Find some values alpha, beta such that alpha+beta=-55, and alpha * beta = 750

#

if that's not really doable (in the case that you'll possibly have complex roots, i.e. is irreducible over reals, prime coefs, and simply non integer coefs js pose challeges)

#

just use the quadratic formula

pseudo flume
coral crag
coral crag
crimson carbon
#

eh not necessarily

coral crag
#

for me tho

#

but for some of them it is easy

crimson carbon
#

you can't have someone pull smth outta their bum and then accept it

#

unless you do understand

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#

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limpid cypress
#

Let A be a set with 10 elements, B be a set with 2 elements, and C be a set with 5 elements. Let f be any function from A to B, and g be a function from B to C. Let h(x) = g(f(x)) = (f ∘ g)(x). How many different functions are there? I really do not get the answer ?

The answer is C(5,2)*(210 − 2) + 5 = 10225

limpid cypress
#

<@&286206848099549185>

#

<@&286206848099549185>

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limpid cypress
#

<@&286206848099549185>

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raven girder
#

Does l'hosptal allow me to just derive the whole thing?

raven girder
#

or do I need a fraction

#

I started by deriving this but I think that's wrong

minor needle
#

fraction

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e.g.

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for this

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log(1+1/x) / (1/x)

raven girder
#

ohh ok thanks

proven leaf
#

$\lim_{x\to c}\frac{f(x)}{g(x)}=\lim_{x\to c}\frac{'f(x)}{g'(x)}$

If $f'(c)$ and $g'(c)$ exist and $f(x)$ and $g(x)$ are differentiable

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needs to be a fraction of two functions

ocean sealBOT
#

XxMrFancyu2xX

raven girder
#

👍

#

.close

lone heartBOT
#
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raven girder
#

.reopen

lone heartBOT
#

raven girder
#

I'm not sure what to do when I have a sum like this

#

can I split into 2 limits or do I have to reform this?

proven leaf
#

$\frac{1}{x\sin(x)}-\frac{1}{x^2}=\frac{x^2-x\sin(x)}{x^3\sin(x)}$

ocean sealBOT
#

XxMrFancyu2xX

raven girder
#

got it thanks

#

x - sinx / x^2 sinx works too right

#

or why did you choose to mulitply with another x

proven leaf
#

because I used $\frac{a}{b}-\frac{c}{d}=\frac{ad-bc}{bd}$

ocean sealBOT
#

XxMrFancyu2xX

proven leaf
#

and x^2 times x is x^3

raven girder
#

oh lol I didn't know this formula

#

What I did

proven leaf
#

yes lol please don't use $\frac{a}{b}-\frac{c}{d}=\frac{a-c}{b-d}$

raven girder
#

what? kekw

proven leaf
#

ignore the emoji the tex bot handles it weird

#

,tex kekw

ocean sealBOT
#

XxMrFancyu2xX

raven girder
#

is it another one

proven leaf
#

no it's mathematics that you shouldn't do

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i actually messed it up

ocean sealBOT
#

XxMrFancyu2xX

raven girder
#

ah now I get it LOL

proven leaf
#

ok so now how do you evaluate this limit? $\lim_{x\to0}\frac{x^2-x\sin(x)}{x^3\sin(x)}$

ocean sealBOT
#

XxMrFancyu2xX

raven girder
#

I derive upper and lower function

proven leaf
#

yep! and what do you get?

raven girder
#

sec im not so fast kekw

proven leaf
#

dw :))

raven girder
#

I feel like I need to derive again

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cuz denominator is 0

proven leaf
#

but is numerator?

raven girder
#

numerator is 1

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1/0

proven leaf
raven girder
#

oh sry

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cos(0) = 1

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so it's 0/0

proven leaf
#

also I think you did ur bottom derivative wrong

raven girder
#

isn't sin(x)' = cos(x)?

proven leaf
#

$\frac{\mathrm{d}}{\mathrm{d}x}[x^3\sin(x)]=x^2(3\sin(x)+x\cos(x))$

ocean sealBOT
#

XxMrFancyu2xX

raven girder
#

I simplified ur fraction

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removed an x

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,w d/dx x^2 sin x

proven leaf
#

ah

#

very well

#

bottom checks out then sorry for confusion blobsalute

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yep we get another 0/0

#

l'Hôpital's Rule to save the day gigachad

raven girder
proven leaf
#

you have another indeterminate form...

raven girder
#

does lhospital always work?

proven leaf
raven girder
#

I mean does it always lead to a result

proven leaf
#

oh and if the limit of indeterminate

raven girder
#

,w lim x->0 1/(x sinx) - 1/x^2

raven girder
proven leaf
#

,w lim as x to 0 of (sinx)/(2sinx+2xcosx+2xcosx-x^2sinx)

ocean sealBOT
proven leaf
raven girder
proven leaf
#

sorry man gonna have to differentiate again KEK maybe their might be a more elegant way but honeslty idrk

raven girder
#

pls tell me i can stop now

#

does x^2 cos x -> 0 ?

proven leaf
#

you can stop now :))

raven girder
#

jfc

proven leaf
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plug in 0 to the top

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what do you get?

raven girder
#

1

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/ 6

proven leaf
#

pandaHugg 🎉

#

that was big boio

raven girder
#

why was it indeterminate before then tho

#

because numerator=0?

proven leaf
#

In calculus and other branches of mathematical analysis, limits involving an algebraic combination of functions in an independent variable may often be evaluated by replacing these functions by their limits; if the expression obtained after this substitution does not provide sufficient information to determine the original limit, then the expres...

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because it was indeterminate

raven girder
#

o

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we did 0/0

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ok

#

thanks sir

proven leaf
raven girder
#

x^2 log(1-e^x) / x ?

#

that not working

lone heartBOT
#

@raven girder Has your question been resolved?

raven girder
#

what the fuck am i doing

#

log(1-e^x) goes to infinity

#

pls send help

glad basalt
#

conditons for l'hospital rule is 0/0 or inf/inf

#

0/inf and inf/0 also applies i think(not sure)

raven girder
#

.close

lone heartBOT
#
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#
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wide plaza
lone heartBOT
wide plaza
#

help with q 4 and q5

#

i dont know how to do it

lone heartBOT
#

@wide plaza Has your question been resolved?

wide plaza
#

<@&286206848099549185>

#

<@&286206848099549185>

#

bro what the hell

#

ive been waiting for 30 mins

#

really no one?

wide plaza
#

hello?

#

<@&286206848099549185>

vernal current
#

Hi

lone heartBOT
#

@wide plaza Has your question been resolved?

wide plaza
#

<@&286206848099549185>

#

its been 2 hours

#

what is this?

tacit arch
tacit arch
wide plaza
#

ok

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ivory pumice
#

I am currently stuck on question 2(bottom). This question involves the Witch of Agnesi shown above. The following is known -
The witch is made from a circle shown in the figure.
Point E is the center of the circle.
The radius of the circle is a.
The x-coordinate of point P is x, and the y-coordinate of point P is y.
The distance between the origin and point B is d.
The angle d makes with the x-axis is theta.

I must show that d = 2a/sin(theta). Looking at it it makes intuitive sense, but I can't seem to prove it.

ivory pumice
#

What I have tried -
I've tried using the Pythagorean Theorem by acknowledging that x is equal to the x-coordinate of P, and that the height of d is always 2a. I have attempted to define x in terms of a by the equation x = a cot(theta). However, when attempting to evaluate the resulting expression via the Pythagorean Theorem, I come to a dead end as there is a root that cannot be simplified.

#

Another thing i tried was to turn 2a/sin(theta) into 2a csc(theta) to remove the quotient, however this leads to a similar dead end.

thorny patio
#

So do you have it given that the lines form a rectangle?

#

The one that d would be the diagonal of

#

@ivory pumice

#

If so the result is easy from there

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#

@ivory pumice Has your question been resolved?

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wheat isle
#

Where’d they get y= u^7

#

Did they just let y= u^7

lament forge
#

well u = 5x+4, and y = (5x+4)^7

wheat isle
#

I still don’t understand where y=u^7 comes from

lament forge
#

you're just taking y = (5x+4)^7, and replacing the 5x+4 with u

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which you can do because we decided that u = 5x+4

wheat isle
#

oh okay

#

I think I get it now

#

I think the notation confuses me a bit. Does du/dx mean you are differentiating u with respect to x? Or is it the other way around

lament forge
#

du/dx is differentiating u with respect to x

wheat isle
#

Ah okay

wheat isle
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naive oar
#

hi

lone heartBOT
naive oar
#

hello i need help with a question for linear algebra over matricies

lone heartBOT
#

@naive oar Has your question been resolved?

naive oar
#

no

#

<@&286206848099549185>

#

<@&286206848099549185>

true sand
#

Yee

#

You need to make a matrix and calculate the inverse

#

You can make a augmented matrix and use the identity matrix to find the inverse

#

The method listed wants you to do a coefficient matrix tho

#

Then multiply both sides by the inverse of the first matrix with the first row 3,-1,1

#

The left side simplifies to x,y,z. Because $I_n *B = B$

ocean sealBOT
#

Differential Equations

naive oar
# true sand

so this is the ax=b form, how would i do coefficient matrix

true sand
#

The matrix on the left is the coefficient matrix

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#

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high wolf
lone heartBOT
high wolf
#

Can someone help me solve this mb

placid zinc
#

∂/∂x of both sides

#

Keeping in mind that z is a function of x

#

This means y is a constant, and something like xz needs the product rule

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#

@high wolf Has your question been resolved?

lone heartBOT
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toxic kraken
#

2x+3y=13 2x+y=7 elimination answer x=2 y=3

toxic kraken
#

Is it correct

sonic ridge
#

yes

toxic kraken
#

Bruh that fast

sonic ridge
#

you can always check by plugging in the x and y's back into the original equations

#

see if LHS = RHS

toxic kraken
#

.close

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twin yoke
#

hey there, im struggling with the following calculus problem

twin yoke
#

so what ive tried so far was to parameterize our path in terms of two variables u,v

#

i got the paramterization s(u,v) = (u,sqrt(1-u),v)

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taking the derivatives w/rt to u and v to get our normal vector i get that ds/du = (1,-1/2sqrt(1-u),0) and ds/dv = (0,0,1)

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taking the cross product to get normal vector yields this mess

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heres where im certain i made a mistake, taking the magnitude of this, evaluating the vector field with such paramterization, and trying to integrate is insanely difficult

#

can i get some advice and potentially some help?

lone heartBOT
#

@twin yoke Has your question been resolved?

fading moth
#

ah, i don't think you want to take the magnitude

#

you want to take the dot product of the vector field and the cross product vector

#

you were thinking of this formula

#

where f is a scalar field

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#
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marsh gulch
marsh gulch
#

<@&286206848099549185>

tacit arch
#

What's the first line supposed to read. The handwriting isn't great

marsh gulch
marsh gulch
#

The problem is max that

tacit arch
tacit arch
ocean sealBOT
#

rie.mann

marsh gulch
#

They are functions

#

Price of X and Price of Y

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P(x) P(y)

tacit arch
ocean sealBOT
#

rie.mann

tacit arch
#

what does alpha: even mean

marsh gulch
#

Lagrange

tacit arch
#

so yes

marsh gulch
#

It is assumed to be an economic maximization using Cobb-Douglas

tacit arch
#

L = ...

#

do you know partial derivatives?

marsh gulch
marsh gulch
tacit arch
#

can you calculate this partial derivative

marsh gulch
#

Yes in the first part, the problem is Idk why the derivate of λ is just P(x)

tacit arch
#

only one of these terms depend on x

marsh gulch
#

Income and Price of Y becomes 0?

tacit arch
#

if you say so

marsh gulch
tacit arch
#

I and y are independent of x

#

so when you calculate partial derivative of those 3 terms, only 1 remains

marsh gulch
#

Ah, I see...

#

What if i want to do a partial derivate of λ?

#

All of those is just erased?

tacit arch
#

no

tacit arch
#

so when you differentiate wrt lambda, you treat that (...) as a constant

marsh gulch
#

So... It is literally the same inside the (...), right?

#

-px X - py Y + I

tacit arch
#

yes

marsh gulch
#

Oh, I see

#

Very Very Thanks, mate

#

.close

lone heartBOT
#
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rotund junco
#

Help part 2

lone heartBOT