#help-0
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Alternate...?
that actually makes complete sense
everything above my line was taking one route, and the stuff below the line was taking your route, no?
Nah the one above the line is just a preparing step to do the below step
Because we're using the fact that floor(x)+floor(-x)=-1 below the line
Which we haven't known before
q23, directly before it does show that as well. So I almost think I can just skip that and assume that floor(x) + floor(-x) = -1
but also, I dont really see how that is helpful for the stuff below the line
oh nvm
@fossil latch, @copper delta , thank you so much! I really appreciate all yall time and effort helping my slow ass out here
just for a quick final clarification, the stuff before that line is effectively q23, eh?
Yes
yeah i thought you were going for 23
okay, cool bean! I think i understand everything at this point. I am not sure if I actually need the stuff from above since we were only asked to do q24 (which seems like it was a bad idea), but I will ask the prof about that
no, I was going for 24, but thats ok
seems like you kinda need to do 23 to do 24
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I've got issues in these three sums. Been stuck on these for a good while now. Much thanks
It isn't
Show your work
For ONE of them
That's gonna be difficult atm
But I tried the third question and couldn't show for (a). I encountered a similar question before but this was harder
The first question I didn't know what to do in all honesty and the second question I had no idea where to start
In that question I had the first term and common difference but not for this sum, hence I'm confused
@tacit arch
Arigathanks gozaimuch 🙏
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@toxic hedge Has your question been resolved?
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I am using Classic Orbital Elements (Keplerian) from Nasa/JPL to plot the orbits of our planets in Unreal Engine. Nasa/jpl provide the eccentricity and semi-major axis which should be enough to plot the shape correctly. To plot these in Unreal Engine I create points in a spline that together create an ellipse. I haven't been in a mathematics course for a couple years so I am really rusty. I found the equation of an ellipse is (x^2/a^2)+(y^2/b^2)=1 but I am confused. Whenever I plotted functions in the past it was as y= not 1=. Why is it 1= and how do I use that formula to get 8 points (as x, y) around the ellipse? If you're confused let me know because I don't know what it is I don't know so my explanation might be wack
It's because x^2 + y^2 = 1 is the equation for the unit circle, and changing a and b in the equation for an ellipse simply dilates the circle in the x and y directions
Do I need to reformat it to be in y= to be useable I’m confused
I think doing that might remove solutions for y<0 (I'm just being dumb, look below)
It'd* probably be fine though
Missing +-?
Oh shoot
Semipika123
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Question L
first combine the two fractions by subtracting
it says solve by first multiplying by an appropriate expression
ahhh
holdon
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hmm how do i frame an equation for this ?
Sells = subtraction
oh
hmm what's the equation though ?
dang im weak at this equation formation in these word problems
well in my equation, lets say tables = 5, chairs will be 15
oh i see
oeh alr
twice as many chairs as tables would mean:
chairs = tables * 2
x - 4 + y - 4 = 2y
i think
wait no
hmm
ignore that
oh why doe
I thought the same thing, but the y cancels out
the y will cancel out
mhm
final stock is
x = 2y
selling stock is
x - 4 + y - 4
ok so
you can rewrite x - 4 + y - 4 in terms of y
y + 10 - 4 + y - 4
2 y + 2
=
hm
i feel like i'm overthinking this
dude, same. I'm getting negative chairs and tables 😭
hmmmm
i got 24 chairs and 14 tables
ye ye that's it
(i don't know why you're using "x" and "y", "chairs" and "tables" are reasonable variable names that are a lot less confusing)
admittedly it's a bit weird to use a multiple-letter name but meh
so
we have 10 more chairs than tables
chairs = tables + 10
after selling four of each, we have twice as many chairs as tables
chairs - 4 = (tables - 4)*2
then you can just solve that
tables + 6 = 2*tables - 8
tables + 14 = 2*tables
tables = 14
chairs = 24
how did u get tables + 6 here
that's just algebra
chairs = tables + 10, so chairs - 4 is the same as (tables + 10) - 4 which is tables + 6
Oehh i see
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I dont understand whats happening from the arrow onwards in this answer. i just want a verbal explanation of whats happening ty
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how do i find x by using pythagoras
did you make an attempt to set up an equation?
i cant find any other factors for 84 that add up to 6
you're not supposed to
why are you attempting to factor the left with stuff still on the right side
i didnt notice there was nothing else left 😭
square root of 13?
OHHH
I WAS LOOKING AT THE WRONG ANSWER SHEET
no wonder why i kept getting confused
i skip questions sometimes
thanks for your help bro
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How do I do this?
Your image is incredibly poor quality
i can hardly read that
i think it asks for the derivative of that
and i see an intgeral
the derivative of an integral is just the function
yes. But i see the limits
I’m aware, if it’s 0 to x then it’s the function
@barren portal Has your question been resolved?
The derivative of $g(x) = \int_2^{3x} \sqrt{1+t+t^2}\dd t$ is
bee [it/its]
given that the limit is just 3x i think it shouldn't be too hard to mess with it a bit
like if you define $h(x) = \int_2^x \sqrt{1+t+t^2}\dd t$ then $g(x) = h(3x)$
bee [it/its]
then the derivative of h is easy, and the derivative of g is the chain rule
@barren portal
yes
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How come when I replug pi/4 to the equation it doesn’t work out?
I end up getting 2 different values
Can anyone pls tell me how to solve these two equations
#❓how-to-get-help bruh it's the 2nd time alr
I tried I can't understand anything
Just go into an available help channel and type your question
Isn't this a help channel
yes but it's a help channel someone else is using
the help channels nobody is using yet are in the "available" category
What's the final answer for this??
x = pi/4
what ru tryna solve for
No 7
I can't do much trigonometry but I solved the logarithm part for u
The answer comes out to be 0 for this

@tough gull Has your question been resolved?
na I figured it out
and I just realized the reason It wasnt working out
was bc my calculator was on
degrees mode not radians
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Guys I need help!!!
I'm in class 10 CBSE, NCERT and I can't understand a single stuff of creating quadratic equations from word problems
Tomorrows my exam and I still cannot understand creating quadratic equations from word problems like, tap filling 2 tanks, a car taking x km/hr speed with reference to other car and so on...
No matter how much practice I do, I get back to square 1 and don't understand anything 😭
Pls helppppp
Two water taps together can fill a tank in 9(8/3) hours. The larger tap takes 10 hours less
than the smaller one to fill the tank separately. Find the time in which each tap can
separately fill the tank
A person on tour has Rs.360 for his expenses. If he extends his tour for 4 days, he has
to cut down his daily expenses by Rs.3. Find the original duration of the tour
it helps to break it into smaller steps
assign the thing you want to solve for a variable
wdym?
for example in the first one you want to know how long it takes each to fill the tank
x
no video nor can i understand a single method to solve
for every question theres a diff case
like 360/x + 360/x-5
thats because its not a matter of memorizing formulas or "cases"
or 45/x+5 - 45/x = what not
then how do i solve these type of word problems
i mean i know how to solve quadratic equations but creating them is a big object blocking my road
its the biggest pain and i have gone thro many lectures, i just dont understand how
turn the problem into a series of smaller steps and work through it carefully
lets do the first problem u posted
@silk lintel r u still here
first tell me what exactly u want to solve for and give them variable names
yes
i need to find the time for each tap which can fill one tank separately
you can take x and y
okay, x = time it takes small tank to fill
now for easy part: y = x-10
do you get this?
okay great
but the way you implement that in the equation the problem
now when dealing with problems like this it helps to think in terms of rates
terms of rates?
it also helps to give everything a name
yea so let rx = rate at which x fills the tank (smaller one)
ok
let V = volume of the tank (the volume does not change)
$r_x = \frac{V}{x}, r_y = \frac{V}{x-10}$
heres why it helps to think in terms of rates
here
chaac
oh
if v is the volume, and x is time, then r_x is a rate (units volume per time)
rate is how much water it fills per unit of time
now for the crucial part (why it helps to use rates)
filling the tank together means this: some time * (r_x + r_y) = V
and we know what the "some time" is: 75/8 hrs
how does adding them equal up to volume?
its not adding the times
you know 75/8 is how long it takes both to fill it right?
so we get the following: $\frac{75}{8}(\frac{V}{x}+\frac{V}{x-10})=V$
chaac
then u can cancel the V and solve
i still didnt understand how you make the equation
which step specifically
okay, lets go back to the rates
do you get that the rate of y is V/(x-10)
(volume per time, time is x-10)
yes ok
okay now literally imagine 2 taps filling a tank
they each will pour out water at different rates presumably
yes
the total time it takes for both multiplied by r_x gives the total volume x pours out
and same for y
then when u add that up u get exactly the equation i wrote
i didnt understand ^
okay tell me what the 75/8 hrs is
time taken to fill 1 tank together
now in that time, each tap will pour out its own amount yes?
yes
so if x pours out r_x per hour, how much does it pour out in 75/8 hrs
75/8 * r_x?
yes
the total volume V will equal the amount poured out by x + the amount poured out by y
so 75/8 * (r_x + r_y)?
yes exactly
and we already know what r_x and r_y are
they will have a factor of V, which u can then cancel at the end
V/x, V/x-10
oh
what about the second one
thats where im facing more difficulty
A person on tour has Rs.360 for his expenses. If he extends his tour for 4 days, he has
to cut down his daily expenses by Rs.3. Find the original duration of the tour
what rs
btw did u understand what we did for the first one?
all the other problems will be very similar
rupees
yes
im gonna go, but try to think about how you would do a similar process for this one as we did in the first one
(think about how much he spends per day)
ok ty for help
@silk lintel Has your question been resolved?
how tho?
i just dont get how for every question they create cases
sometimes its 1/x, sometimes its 360/x
i just cant comperihend each and every question i practice and have search up for every SINGLE question 😭 😭
umm
@silk lintel Has your question been resolved?
"do u know hindi"
so that it will be easier for u to understand
this is very simple to solve. U just need some basics.
Also, there is assumption that his money balance will be Rs.0 after his tour is complete.
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.reopen
no, the point is that this relation holds for any theta
Yes can you help me pls
i think
my man there's like two questions already being dealt with in this channel use one of the available ones please
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@cinder sundial Has your question been resolved?
@cinder sundial Has your question been resolved?
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what are you trying to do??
Calculate the limit
maybe use algebra of limits?
you notice that you just need to calculate the limit of the exponent
but if you just fill inf for x, you get inf * 0 , right?
@royal marsh Has your question been resolved?
Good morning felix, how did you know?
Thats why you need to solve the indeterminate form
But idk why, and i asked here wishing for help
i didn't. It works when I use Cauchy or Heine limits :shrug:
No derivatives here, only transformations
Since you are so good at using Cauchy why dont you help me here
no derivatives? dang
With de L'hopital would be piece of cake
But without its hard
:/
Actually i figured out
Wrong transformation
/close
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How would I integrate this without getting into a loop of integration by parts after?
I have a pretty limited knowledge of calculus for reference, but my maths exam is Tuesday and I still get a bit lost for these integrals
usen a sub
u = lnx
I did, but that leaves you with this no?
cool
Then this takes you into the integration by parts loop
Integration by parts by using the DI method! This is the easiest set up to do integration by parts for your calculus 2 integrals. We will also do 3 integrals to illustrate the 3 stops of the DI method.
Dear calculus teachers, please let students use the DI Method (& why it is really the same as integration by parts) 👉 https://youtu.be/8xPfNuXLS...
watch this from 10 minutes onwards
shows u how to do that inetgral now using the DI methods
its basically a trick u can do to avoid the loop
Oh wow cool, thanks I’ll take a look
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ples help
i heff exam tmr
in 6 hours
and i got r = root -3r sin theta
here is my work
ignore the pajamas
that r is in terms of r?
Are you sure it shouldn't be -6rsin(theta)?
Also, -3rsin(theta) doesn't stay as -3rsin(theta) when you move it to the right hand side of the equation
@deep karma Has your question been resolved?
yes
but i dont know why
sorry for replying so late
i was doing meths
I am afraid to tell you that it should be -6rsin(theta) there
That
And that
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Math teacher didnt teach well and idk how to do this
Can someone give me a guide
I'd multiply both sides by 12 to get rid of all the fractions
$x(\dfrac{23}{6}+1)=\dfrac{-29}{12}$
- Distributive Law
$x(\dfrac{23}{6}+\dfrac{6}{6}) = \dfrac{-29}{12}$
- Like Terms in Denominator
$x\times\dfrac{29}{6} = \dfrac{-29}{12} $
- Addition
$x\times\dfrac{29}{6}\times\dfrac{6}{29}=\dfrac{-29}{12}\times\dfrac{6}{29}$
- Multiply both sides by same fraction
$x=-\dfrac{6}{12}$
SirMonkey
How would i do one with a variable at the bottom of a fraction?
Give an example?
Yea wouldnt it be 7/10
a = 7/10
my bad, this isnt a function so that isnt relevent
yes, it would be 7/10
Well anyways ty for helping me my math teacher didnt teach half of algebra so i’m below level in almost everything
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Question:
A florist sells two types of bouquets. A bouquet of the first kind consists of
5 roses, 5 tulips and 5 carnations and is sold for e 35. A bouquet of the second kind
consists of 3 roses, 6 tulips and 6 carnations and is sold for e 20. The florist cannot
sell loose flowers or differently composed bouquets and has 50 roses, 70 tulips and 60
carnations available.
(a) What is the maximum number of bouquets the florist could sell?
(b) What is the maximum turnover he could achieve?
I used lineair programming to solve this problem.
step 1. define of variable
x = the number of bouquet of the first kind that the seller sells
y = the number of bouquet of the second
kind that the seller sells
step2: funtion to maximalize
z = x+ y (for the first problem)
W(x,y) = 35x+20y (for the second problem)
step 3: set conditions
5x+3y <= 50
5x+6y <= 70
5x+6y <= 60
step 4: positiveconditions
x>= 0, y>= 0
Now I am stuck because I found 3 points for each condition:
A: (0, 16.67) and (10,0)
B: (0, 11.67) and (14,0)
C: (0, 10) and (12, 0)
Which one do I use to evaluate for z= x+y?
Can I choose?
Can I just do z= 0+16.67, z = 0+11.67.... or can i use the second points? How do I do it?
please helppp
what is "e" here? is it a variable?
and are the numbers next to it in the problem, like 35, coefficients to e?
and is sold for e 20
is 20 the coefficient to e?
@nocturne garden Has your question been resolved?
sorry e stands for euro
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The area of the cube is growing at a rate of 20 cm/s. at what rate does its volume increase if the length of the edge of a cube is 10 cm?
I literally have no idea how to do it
like
if S(x)=6x^2 is the area of the cube
then the question says that d/dx S(x) = 20?
or what
well not dx but dt
no
d/dt S(x) = 20
yep
sooo
12x = 20?
or what
you took dx, which is not correct
oh okay
6x^2 = 20t
so x = sqrt(20t/6)
x^3 = sqrt(20t/6)^3
thus dx^3/dt = (calculate the above)
ohh
okay makes sense now
thanks!
what
*wait
but how do we use the fact that side length is 10?
unless I'm missing something
u use it to find t
then plug it back in
oh alright
how much yo got?
i got ~27.38cm^3/s
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Find the derivative of the function. x(6x + 1)4
dont you mean
x(6x+1)^4
yes
yes f'g+fg'
chain is f'(g)g'
yh
well i say this
because when you do product rule
youll need to know what the derivative of (6x +1)^4 is
which you need to use chain rule for
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what do i need to do here?
what will -5x^2 + 10x + 15 equal when it hits the water?
how can i calculate that?
Nothing to calculate yet. Read the word problem and try to figure out what value that equation has when the stone hits the water
i got 3 seconds, but i calculated with the quadratic formula, how could i have done it without using any process?
well you couldve factorised
it into (5x+5)(-x+3)
or rather 5(x+1)(-x+3)
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Not sure where to start. I don't know how to adjust the equation for a rotation
@tough shard Has your question been resolved?
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I'm guessing that the surface is a hyperboloid and an x^2 needs to be added to the equation to create a 3-D surface
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I understand there is a reflection in the y-axis, and a horizontal compression. I just don't understand how to figure out what factor of horizontal compression there is.
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why is e^((-1)/n) = 0?
Actually i just realized that 1^x is always 1 so of course the denominator is bigger. Nvm
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It asks to me the area between
x = 3 + y^2
x = 2 - y^2
y = 1
and y = -2
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@small shuttle Has your question been resolved?
look at the graph sideways and integrate dy. thats what i would do
from y=-2 to y=1
@small shuttle
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hello
do you guys know how I could solve lim x->-infinity 3^x*x
yeah
how?
3^x goes to infinity
it's -infinity
oh
Notice that as x approaches negative infinity, 3^(-x) approaches 0 because the base of the exponent, 3, is greater than 1. Therefore, the expression can be simplified **further: **
lim x->-infinity x / 3^(-x) = lim x->-infinity x * 3^x.
and after that what?
yeah,it's undefined then
We can use L'Hôpital's rule to differentiate the numerator and denominator separately.
( have an indeterminate form of the type "infinity * 0" )
oh so i can write 3^x as 3^-x
on the denominator
Take the derivative of the numerator and denominator:
cus it's the form before the -infinity is inputted
i just don't understand how i can suddenly go to writing 3^x as 3^(-x)
3^x = 1/(3^(-x)
since x approaches negative infinity, and 3^x approaches 0
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Lets say there is a circle drawing competition, where people draw circles without equipment. This means the circles are imperfect. How do you determine how close/far it is to a perfect circle by using standard deviation, variance, etc?
this was one of the questions on the blackboard the other day during math class, but I couldnt get a photo of it, so I just typed it out here
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Can someone help me understand what I did wrong? Im also gonna send a photo of my work
when you cancel the x-63, the remaining stuff (sqrt(x+1)+8) will be in the denominator.
wait so is it 1/16?
yes
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This isn’t 7?
<@&286206848099549185>
How I Solved It
• Given : 50,62,50,54,56,60,54,57,57
- x̄ : 55.5555 ≈ 55.5
- ox: 3.8329 ≈ 3.8
——————————————-
55.5 + 3.8 = 59.3
55.5 - 3.8 = 51.7
Highest - 59.3
Lowest - 51.7
—————————————
Given : 50,62,50,54,56,60,54,57,57
7 of them are within the standard deviation of the mean
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@ember dagger Has your question been resolved?
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Just use distance for!ula
For all three sides
Show that two sides of the triangle are equal
Two of em equal n jobs don
Wait
Also Pythagoras
realhuman
Typo
Random Guy
Find AB BC CA
and can I know why we are using the distance formula?
To find the distance of these sides
two show two sides have the same length
Ohh
Also for Pythagoras
Which ever two side is equal shows it is an isoceles
But isn't pythagoras theorem just used to find the side
The sides enclosing the right angle
Pythagoras theorem only works for right triangle
But like
I should just show the side?
If Pythagoras theorem is working...it !eans the triangle is right angled
State the complete theorem
Converse of the Pythagorean Theorem if c^2=a^2+b^2 then triangle ABC must be a right triangle :))
now verify it's a right triangle
Okay
oh also you're going to need to find the length of the third side
then verify it using Pythag
yw! Have a good day :))
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For these kind of questions can the x be negative
Well it is not a question it is just a clarification
Like can the answer be: (-x-4)(x-7)
I am asking it generally
whether if the x inside the bracket can be negative
yes
Okay tq
this is related to the coefficient on the x^2
also note that these answers could all have negatives
For the question I worked out I got the x as negative
Actually nvm
The answer
I just wanna know if the answer can be negative
the variable not the numbers
did you read this
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I am currently doing trig. This is not a full question, just a small part of the answer. How did the brackets on the RHS split to become sin and cos. I don't see any info regarding it on the formula sheet.
Double angle formula
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you know that the sum is ar^(n-1)
and at n=3, u have 121/9
what can u conclude with those infos ?
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hello, can someone help me out with this problem
what's the goal? to solve for x and y?
yeah we have to find the values of x and y
should i send the pic ?
yes absolutely
oeh alr one sec
ello ann
hi, did you want to ask something to me specifically or did you just want to intrude in this channel for some chat
damn how long have you been playing slay the spire i completed with all the character
the second one intrude
L.C.M. here?
are you asking about legality or helpfulness
oh yeah btw you actually fucked up the earlier step
hm like am i supposed to do it ?
you should have had $-100x + \frac{x}{4} + \frac{y}{24} = 8$ as your equation
Ann (glomed)
Oeh
no such thing as "supposed to"
i see
soo how do i proceed after that ?
my suggestion? multiply both sides of the first equation by 24, and of the second equation by 5.
that way you will not have any fractional coefficients to worry about.
oeh
kay i will give it a try one sec
Hmm it feels like im hetging somewhere
Ah this is a long one
i just checked the answer
OH
i will use another method rather than elimination ig
maybe it could work
Hmmmm
Didn't get the answer
@vale wigeon can u try this once please ?
Just show your work
I think its wrong doe
Wrong answer
i didn't want to multiply 24 by 100 lmao
for shame because you would have to do that
from (6x+y)/24 = 100x + 8 to 6x + y = 2400x + 192
💀 big numbers scare me fr
and then to -2400x + 6x + y = 192
gonna need to overcome that fear.
plus 100 is a nice number for multiplication purposes
its like, oh shoot big number must be wrong
2400 aint such a big number
but the answer is like
quiet different idk
alr lemme try again
0 f up's challenge
Is this correct so far ?
i should get the value of y if i equate them both right ?
-192-y/2394 = 50 + 5y/2
@vale wigeon
Les goooo
I got it :D
But the calculation part scares me
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hello may i ask how to do question (ii)?
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@elfin tree Has your question been resolved?
use desmos on the internet they have a very neat way to do Q1. a
@elfin tree Has your question been resolved?
Idk how to use desmos properly
write in the equation in question one, exactly
except change the square brackets for round ones
then click all : )
by save i think they mean screenshot then submit?
play around with the sliders and note down what each one does in question 1b
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How should I go on to solve this question?
you know formulas for the volume of a cylinder or sphere?
yep
so what's the problem
I'm getting 1921.91
I'm going to go with 1921.68 for this, lemme see if it's right
it's correct
Result:
1921.68
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can someone solve this Q.E, the roots are 3 or 1
You solve
yeah i did
What u got
one sec lemme show it once
there
i sent the x^2 to the right side cuz of the negetive
in the first one
the roots shouldbe 3 and 1
but i am not getting em
3x-7x≠5x
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set one side of the equation to 0 then factor
id honestly just get another blank sheet and retry
id also maybe not use pen for solving next time
Lmao i was writing 3x - 7x as 5x instead of 4 💀
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Can someone tell me what this sideways T means
This one |-
Aahh thanks
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$x,y,z$ are positive reals such that $$\frac{x^2+yz}{y+z}+\frac{y^2+xz}{x+z}+\frac{z^2+xy}{x+y}>=m(x+y+z)$$ then find $m+12$
kheerii
I tried using AM-HM inequality by breaking up the terms in different ways but that didn't give me anything
<@&286206848099549185>
anyone?
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im trying
.reopen
✅
what are you trying
tried am-gm on
$$\frac{x^2}{y+z}+\frac{yz}{y+z}+... +\frac{xy}{x+y}$$
Jester
am-gm seems pretty unlikely
yeah i was also looking at this
but doesn't seem to work either
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hmm i didn't get this
First simplify and move everything to one side
Is this right ?
You can also factor out the 2 but you don't have to
I see
Yeh didn't write it yet
I think this one's also like the previous one u explained
But not ab
Maybe root a ?
Or root a²
@tawny condor what should i do here ?
In the denominator it should be just 2 * 2
Not 2 * (2a)
a is only in the coefficient of x
Oh woops
Ye ye
Soo what should i do now ? Do i do it the previous way ?
Like multiply with a
Oh kay
Hm in the first step should i use (a-b)² for (2-6a)² or the one in the pic
Hm most probably a - b whole sq
(2 - 6a)^2 isn't 4 + 36a^2
$(a+b)^2 = (a + b)(a + b) = a(a + b) + b(a + b) = a^2 + ab + ba + b^2 = a^2 + 2ab + b^2$
RedstonePlayz09
Yeye i was a lil bit confused if i can use that identity or not
Cuz it was on a fraction
Got this
Hmmm lmao at first the problems were easy i finished em quick with quadratic formula and factorizing, i get like confused when dealing with fractions
You should revise basic algebra then
Once you master it, questions like these will be a breeze
Oeh i see
Understand where your formulas are coming from as well
Like this for example
Yeah i know identities and their derivations
I didn't know we could still apply it when its on a fraction
What do you mean?
Can you give me an example where that confused you
Then look at your sum as
a being added to
b/2
So you have
$a^2 + 2 \cdot a \cdot \frac{b}{2} + \parens{\frac{b}{2}}^2$
RedstonePlayz09
