#help-0

1 messages · Page 228 of 1

twilit cypress
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like that is the alternate solution?

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holy mackeral

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thank you so much

fossil latch
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Alternate...?

twilit cypress
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that actually makes complete sense

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everything above my line was taking one route, and the stuff below the line was taking your route, no?

fossil latch
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Nah the one above the line is just a preparing step to do the below step

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Because we're using the fact that floor(x)+floor(-x)=-1 below the line

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Which we haven't known before

twilit cypress
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q23, directly before it does show that as well. So I almost think I can just skip that and assume that floor(x) + floor(-x) = -1

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but also, I dont really see how that is helpful for the stuff below the line

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oh nvm

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@fossil latch, @copper delta , thank you so much! I really appreciate all yall time and effort helping my slow ass out here

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just for a quick final clarification, the stuff before that line is effectively q23, eh?

fossil latch
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Yes

copper delta
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yeah i thought you were going for 23

twilit cypress
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okay, cool bean! I think i understand everything at this point. I am not sure if I actually need the stuff from above since we were only asked to do q24 (which seems like it was a bad idea), but I will ask the prof about that

twilit cypress
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seems like you kinda need to do 23 to do 24

copper delta
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yes

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it’s just a slight modification

twilit cypress
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ahh okay, okay. Thank you again, I really appreciate it!

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toxic hedge
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I've got issues in these three sums. Been stuck on these for a good while now. Much thanks

toxic hedge
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It's better to say I haven't started them

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Please ping me 🙏

tacit arch
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Show your work

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For ONE of them

toxic hedge
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That's gonna be difficult atm

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But I tried the third question and couldn't show for (a). I encountered a similar question before but this was harder

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The first question I didn't know what to do in all honesty and the second question I had no idea where to start

toxic hedge
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@tacit arch

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Arigathanks gozaimuch 🙏

lone heartBOT
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@toxic hedge Has your question been resolved?

toxic hedge
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<@&286206848099549185>

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Ah I'm thought to be in the middle of an exam

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@toxic hedge Has your question been resolved?

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chilly urchin
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I am using Classic Orbital Elements (Keplerian) from Nasa/JPL to plot the orbits of our planets in Unreal Engine. Nasa/jpl provide the eccentricity and semi-major axis which should be enough to plot the shape correctly. To plot these in Unreal Engine I create points in a spline that together create an ellipse. I haven't been in a mathematics course for a couple years so I am really rusty. I found the equation of an ellipse is (x^2/a^2)+(y^2/b^2)=1 but I am confused. Whenever I plotted functions in the past it was as y= not 1=. Why is it 1= and how do I use that formula to get 8 points (as x, y) around the ellipse? If you're confused let me know because I don't know what it is I don't know so my explanation might be wack

sullen juniper
chilly urchin
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Do I need to reformat it to be in y= to be useable I’m confused

sullen juniper
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It'd* probably be fine though

tacit arch
sullen juniper
ocean sealBOT
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Semipika123

lone heartBOT
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@chilly urchin Has your question been resolved?

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tulip helm
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how do i solve this bottom question

lone heartBOT
tulip helm
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Question L

alpine sable
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first combine the two fractions by subtracting

tulip helm
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it says solve by first multiplying by an appropriate expression

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ahhh

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holdon

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.close

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warped horizon
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hmm how do i frame an equation for this ?

tacit arch
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Sells = subtraction

warped horizon
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oh

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hmm what's the equation though ?

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dang im weak at this equation formation in these word problems

alpine sable
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let's see

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chairs = tables + 10

warped horizon
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oh i thought it was tables = 10 + chairs

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cuz 10 more chairs than tables ?

waxen plinth
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10 more chairs THAN tables

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meaning chairs > tables

alpine sable
warped horizon
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oh i see

alpine sable
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ok next

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let chairs = x and tables = y

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x - 4 + y - 4

warped horizon
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oeh alr

alpine sable
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twice as many chairs as tables would mean:
chairs = tables * 2

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x - 4 + y - 4 = 2y

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i think

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wait no

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hmm

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ignore that

warped horizon
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oh why doe

waxen plinth
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the y will cancel out

alpine sable
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wait let me restart

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x = chairs
y = tables

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x = y + 10

warped horizon
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mhm

alpine sable
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final stock is

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x = 2y

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selling stock is

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x - 4 + y - 4

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ok so

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you can rewrite x - 4 + y - 4 in terms of y

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y + 10 - 4 + y - 4

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2 y + 2

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=

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hm

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i feel like i'm overthinking this

waxen plinth
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dude, same. I'm getting negative chairs and tables 😭

warped horizon
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hmmmm

lament forge
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i got 24 chairs and 14 tables

warped horizon
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ye ye that's it

lament forge
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(i don't know why you're using "x" and "y", "chairs" and "tables" are reasonable variable names that are a lot less confusing)

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admittedly it's a bit weird to use a multiple-letter name but meh

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so

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we have 10 more chairs than tables
chairs = tables + 10

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after selling four of each, we have twice as many chairs as tables
chairs - 4 = (tables - 4)*2

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then you can just solve that
tables + 6 = 2*tables - 8
tables + 14 = 2*tables
tables = 14
chairs = 24

warped horizon
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hmm i see

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lemme just go through the question again

warped horizon
lament forge
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that's just algebra
chairs = tables + 10, so chairs - 4 is the same as (tables + 10) - 4 which is tables + 6

warped horizon
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Oehh i see

lone heartBOT
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@warped horizon Has your question been resolved?

lone heartBOT
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knotty siren
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I dont understand whats happening from the arrow onwards in this answer. i just want a verbal explanation of whats happening ty

lone heartBOT
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@knotty siren Has your question been resolved?

lone heartBOT
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tulip helm
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how do i find x by using pythagoras

lone heartBOT
gray isle
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did you make an attempt to set up an equation?

tulip helm
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Yes

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here

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not really clear but ill send it

gray isle
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continue

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with your work

tulip helm
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i cant find any other factors for 84 that add up to 6

gray isle
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you're not supposed to

tulip helm
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and multiply to get 84

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oh wait

gray isle
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why are you attempting to factor the left with stuff still on the right side

tulip helm
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84 = 6x

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x = 13

tulip helm
gray isle
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it was right before you edited

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(your updated result of x=13 isn't correct)

tulip helm
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square root of 13?

gray isle
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no

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how are you getting x=13 from
84 = 6x

tulip helm
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hm

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you’re right

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x is 14

gray isle
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yes

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that's what you had before you changed it

tulip helm
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OHHH

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I WAS LOOKING AT THE WRONG ANSWER SHEET

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no wonder why i kept getting confused

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i skip questions sometimes

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thanks for your help bro

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.close

lone heartBOT
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barren portal
lone heartBOT
barren portal
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How do I do this?

wind cloak
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Your image is incredibly poor quality

alpine sable
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i can hardly read that

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i think it asks for the derivative of that

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and i see an intgeral

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the derivative of an integral is just the function

barren portal
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Oh wait

barren portal
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I’m aware, if it’s 0 to x then it’s the function

lone heartBOT
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@barren portal Has your question been resolved?

lament forge
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The derivative of $g(x) = \int_2^{3x} \sqrt{1+t+t^2}\dd t$ is

ocean sealBOT
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bee [it/its]

lament forge
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given that the limit is just 3x i think it shouldn't be too hard to mess with it a bit

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like if you define $h(x) = \int_2^x \sqrt{1+t+t^2}\dd t$ then $g(x) = h(3x)$

ocean sealBOT
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bee [it/its]

lament forge
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then the derivative of h is easy, and the derivative of g is the chain rule

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@barren portal

barren portal
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yes

lone heartBOT
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tough gull
lone heartBOT
tough gull
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How come when I replug pi/4 to the equation it doesn’t work out?

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I end up getting 2 different values

undone mango
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Can anyone pls tell me how to solve these two equations

tough gull
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when I plug pi/4 into this

heady void
undone mango
heady void
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Just go into an available help channel and type your question

undone mango
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Isn't this a help channel

lament forge
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yes but it's a help channel someone else is using

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the help channels nobody is using yet are in the "available" category

undone mango
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Okay

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Thanks

undone mango
tough gull
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x = pi/4

tough gull
undone mango
undone mango
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The answer comes out to be 0 for this

lone heartBOT
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@tough gull Has your question been resolved?

tough gull
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and I just realized the reason It wasnt working out

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was bc my calculator was on

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degrees mode not radians

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silk lintel
#

Guys I need help!!!

lone heartBOT
silk lintel
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I'm in class 10 CBSE, NCERT and I can't understand a single stuff of creating quadratic equations from word problems

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Tomorrows my exam and I still cannot understand creating quadratic equations from word problems like, tap filling 2 tanks, a car taking x km/hr speed with reference to other car and so on...

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No matter how much practice I do, I get back to square 1 and don't understand anything 😭

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Pls helppppp

crisp cargo
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okay, dont overthink it

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give an example problem that you dont understand

silk lintel
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Exactly what happens to mee

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There are soo many

crisp cargo
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give one

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i cant help you if you just say you dont understand anything

silk lintel
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Two water taps together can fill a tank in 9(8/3) hours. The larger tap takes 10 hours less
than the smaller one to fill the tank separately. Find the time in which each tap can
separately fill the tank

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A person on tour has Rs.360 for his expenses. If he extends his tour for 4 days, he has
to cut down his daily expenses by Rs.3. Find the original duration of the tour

crisp cargo
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it helps to break it into smaller steps

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assign the thing you want to solve for a variable

silk lintel
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wdym?

crisp cargo
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for example in the first one you want to know how long it takes each to fill the tank

silk lintel
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x

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no video nor can i understand a single method to solve

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for every question theres a diff case

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like 360/x + 360/x-5

crisp cargo
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thats because its not a matter of memorizing formulas or "cases"

silk lintel
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or 45/x+5 - 45/x = what not

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then how do i solve these type of word problems

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i mean i know how to solve quadratic equations but creating them is a big object blocking my road

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its the biggest pain and i have gone thro many lectures, i just dont understand how

crisp cargo
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turn the problem into a series of smaller steps and work through it carefully

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lets do the first problem u posted

silk lintel
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75/8 hrs

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thats all i know i can do in this prob

crisp cargo
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@silk lintel r u still here

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first tell me what exactly u want to solve for and give them variable names

silk lintel
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i need to find the time for each tap which can fill one tank separately

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you can take x and y

crisp cargo
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okay, x = time it takes small tank to fill

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now for easy part: y = x-10

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do you get this?

silk lintel
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yes

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i know till there

crisp cargo
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okay great

silk lintel
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but the way you implement that in the equation the problem

crisp cargo
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now when dealing with problems like this it helps to think in terms of rates

silk lintel
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terms of rates?

crisp cargo
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it also helps to give everything a name

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yea so let rx = rate at which x fills the tank (smaller one)

silk lintel
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ok

crisp cargo
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let V = volume of the tank (the volume does not change)

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$r_x = \frac{V}{x}, r_y = \frac{V}{x-10}$

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heres why it helps to think in terms of rates

silk lintel
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can you pls write this using the bot so i can understand

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wait

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x = v/x??

crisp cargo
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here

ocean sealBOT
silk lintel
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oh

crisp cargo
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if v is the volume, and x is time, then r_x is a rate (units volume per time)

silk lintel
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so rate is time right?

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oh

crisp cargo
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rate is how much water it fills per unit of time

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now for the crucial part (why it helps to use rates)

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filling the tank together means this: some time * (r_x + r_y) = V

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and we know what the "some time" is: 75/8 hrs

silk lintel
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how does adding them equal up to volume?

crisp cargo
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its not adding the times

silk lintel
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so does that mean 1/x + 1/x-10 = 1

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nvm im overthinking it again

crisp cargo
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you know 75/8 is how long it takes both to fill it right?

silk lintel
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it happens with me

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yes

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not both, its both the taps together in 1 tank

crisp cargo
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so we get the following: $\frac{75}{8}(\frac{V}{x}+\frac{V}{x-10})=V$

ocean sealBOT
crisp cargo
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then u can cancel the V and solve

silk lintel
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i still didnt understand how you make the equation

crisp cargo
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which step specifically

silk lintel
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all of that v/x + v/x-10

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im just getting more confused

crisp cargo
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okay, lets go back to the rates

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do you get that the rate of y is V/(x-10)

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(volume per time, time is x-10)

silk lintel
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yes ok

crisp cargo
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okay now literally imagine 2 taps filling a tank

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they each will pour out water at different rates presumably

silk lintel
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yes

crisp cargo
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the total time it takes for both multiplied by r_x gives the total volume x pours out

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and same for y

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then when u add that up u get exactly the equation i wrote

crisp cargo
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okay tell me what the 75/8 hrs is

silk lintel
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time taken to fill 1 tank together

crisp cargo
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now in that time, each tap will pour out its own amount yes?

silk lintel
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yes

crisp cargo
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so if x pours out r_x per hour, how much does it pour out in 75/8 hrs

silk lintel
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75/8 * r_x?

crisp cargo
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yes

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now y pours out its own amount, given by its own rate r_y

silk lintel
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yes

crisp cargo
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the total volume V will equal the amount poured out by x + the amount poured out by y

silk lintel
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so 75/8 * (r_x + r_y)?

crisp cargo
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yes exactly

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and we already know what r_x and r_y are

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they will have a factor of V, which u can then cancel at the end

silk lintel
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V/x, V/x-10

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oh

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what about the second one

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thats where im facing more difficulty

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A person on tour has Rs.360 for his expenses. If he extends his tour for 4 days, he has
to cut down his daily expenses by Rs.3. Find the original duration of the tour

crisp cargo
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what rs

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btw did u understand what we did for the first one?

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all the other problems will be very similar

silk lintel
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rupees

crisp cargo
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im gonna go, but try to think about how you would do a similar process for this one as we did in the first one

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(think about how much he spends per day)

silk lintel
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ok ty for help

lone heartBOT
#

@silk lintel Has your question been resolved?

silk lintel
#

i just dont get how for every question they create cases

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sometimes its 1/x, sometimes its 360/x

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i just cant comperihend each and every question i practice and have search up for every SINGLE question 😭 😭

safe tartan
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umm

lone heartBOT
#

@silk lintel Has your question been resolved?

dusk thicket
#

bhai

#

tujhe hindi aati hai?

dusk thicket
#

so that it will be easier for u to understand

dusk thicket
#

Also, there is assumption that his money balance will be Rs.0 after his tour is complete.

lone heartBOT
#

@silk lintel Has your question been resolved?

lone heartBOT
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cinder sundial
lone heartBOT
cinder sundial
#

How to get those two value

silk lintel
#

.reopen

foggy copper
#

no, the point is that this relation holds for any theta

silk lintel
foggy copper
#

i think

wind cloak
#

You have an expression in theta

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It doesn't equal anything in particular

foggy copper
#

my man there's like two questions already being dealt with in this channel use one of the available ones please

lone heartBOT
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@cinder sundial Has your question been resolved?

lone heartBOT
#

@cinder sundial Has your question been resolved?

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@cinder sundial Has your question been resolved?

lone heartBOT
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ivory oracle
#

hi

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how can i get this domain fast ? f(x,y) = sqrt(x+y) + sqrt(x-y)

lone heartBOT
ivory oracle
#

figured it out

#

.close

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ivory oracle
#

hi

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.close

lone heartBOT
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royal marsh
#

How can i go on from here?

lone heartBOT
native ether
#

what are you trying to do??

royal marsh
#

Calculate the limit

native ether
#

maybe use algebra of limits?

fleet vale
#

you notice that you just need to calculate the limit of the exponent

#

but if you just fill inf for x, you get inf * 0 , right?

lone heartBOT
#

@royal marsh Has your question been resolved?

royal marsh
royal marsh
#

But idk why, and i asked here wishing for help

native ether
royal marsh
#

No derivatives here, only transformations

#

Since you are so good at using Cauchy why dont you help me here

fleet vale
#

no derivatives? dang

royal marsh
#

With de L'hopital would be piece of cake

#

But without its hard

#

:/

#

Actually i figured out

#

Wrong transformation

#

/close

#

.close

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lone condor
#

How would I integrate this without getting into a loop of integration by parts after?

lone condor
#

I have a pretty limited knowledge of calculus for reference, but my maths exam is Tuesday and I still get a bit lost for these integrals

lone condor
#

I did, but that leaves you with this no?

steady basin
#

cool

lone condor
#

Then this takes you into the integration by parts loop

steady basin
#

now use parts

#

hmmm

steady basin
# lone condor Then this takes you into the integration by parts loop

Integration by parts by using the DI method! This is the easiest set up to do integration by parts for your calculus 2 integrals. We will also do 3 integrals to illustrate the 3 stops of the DI method.

Dear calculus teachers, please let students use the DI Method (& why it is really the same as integration by parts) 👉 https://youtu.be/8xPfNuXLS...

▶ Play video
#

watch this from 10 minutes onwards

#

shows u how to do that inetgral now using the DI methods

#

its basically a trick u can do to avoid the loop

lone condor
#

Oh wow cool, thanks I’ll take a look

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deep karma
#

ples help

lone heartBOT
deep karma
#

i heff exam tmr

#

in 6 hours

#

and i got r = root -3r sin theta

#

here is my work

#

ignore the pajamas

modern sedge
#

that r is in terms of r?

echo socket
#

Are you sure it shouldn't be -6rsin(theta)?

#

Also, -3rsin(theta) doesn't stay as -3rsin(theta) when you move it to the right hand side of the equation

lone heartBOT
#

@deep karma Has your question been resolved?

deep karma
#

but i dont know why

#

sorry for replying so late

#

i was doing meths

echo socket
#

I am afraid to tell you that it should be -6rsin(theta) there

deep karma
#

where do you think i messed up tho

#

cus idk where

echo socket
deep karma
#

omg bro

#

i just realized

#

this is so funy

#

funny

#

aiyt thanks yall

lone heartBOT
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glacial nimbus
#

Math teacher didnt teach well and idk how to do this

glacial nimbus
#

Can someone give me a guide

ocean sealBOT
glacial nimbus
#

Whats rhi

#

This

modern sedge
#

I'd multiply both sides by 12 to get rid of all the fractions

violet wagon
# glacial nimbus Can someone give me a guide

$x(\dfrac{23}{6}+1)=\dfrac{-29}{12}$

  1. Distributive Law

$x(\dfrac{23}{6}+\dfrac{6}{6}) = \dfrac{-29}{12}$

  1. Like Terms in Denominator

$x\times\dfrac{29}{6} = \dfrac{-29}{12} $

  1. Addition

$x\times\dfrac{29}{6}\times\dfrac{6}{29}=\dfrac{-29}{12}\times\dfrac{6}{29}$

  1. Multiply both sides by same fraction

$x=-\dfrac{6}{12}$

ocean sealBOT
#

SirMonkey

glacial nimbus
#

How would i do one with a variable at the bottom of a fraction?

glacial nimbus
#

Oh wait i think i can just cross multiply

#

I feel dumb 🫠

#

What

silk lintel
#

27=10a + 20

#

10a = 7

glacial nimbus
#

Yea wouldnt it be 7/10

silk lintel
#

a = 7/10

violet wagon
#

yes, it would be 7/10

glacial nimbus
#

Well anyways ty for helping me my math teacher didnt teach half of algebra so i’m below level in almost everything

lone heartBOT
#

@glacial nimbus Has your question been resolved?

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nocturne garden
#

Question:
A florist sells two types of bouquets. A bouquet of the first kind consists of
5 roses, 5 tulips and 5 carnations and is sold for e 35. A bouquet of the second kind
consists of 3 roses, 6 tulips and 6 carnations and is sold for e 20. The florist cannot
sell loose flowers or differently composed bouquets and has 50 roses, 70 tulips and 60
carnations available.
(a) What is the maximum number of bouquets the florist could sell?
(b) What is the maximum turnover he could achieve?

I used lineair programming to solve this problem.
step 1. define of variable
x = the number of bouquet of the first kind that the seller sells
y = the number of bouquet of the second
kind that the seller sells

step2: funtion to maximalize
z = x+ y (for the first problem)
W(x,y) = 35x+20y (for the second problem)

step 3: set conditions
5x+3y <= 50
5x+6y <= 70
5x+6y <= 60

step 4: positiveconditions
x>= 0, y>= 0

Now I am stuck because I found 3 points for each condition:
A: (0, 16.67) and (10,0)
B: (0, 11.67) and (14,0)
C: (0, 10) and (12, 0)

Which one do I use to evaluate for z= x+y?
Can I choose?
Can I just do z= 0+16.67, z = 0+11.67.... or can i use the second points? How do I do it?

nocturne garden
#

please helppp

sick mirage
#

what is "e" here? is it a variable?

#

and are the numbers next to it in the problem, like 35, coefficients to e?

#

and is sold for e 20
is 20 the coefficient to e?

lone heartBOT
#

@nocturne garden Has your question been resolved?

nocturne garden
lone heartBOT
#

@nocturne garden Has your question been resolved?

lone heartBOT
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alpine sable
#

The area of the cube is growing at a rate of 20 cm/s. at what rate does its volume increase if the length of the edge of a cube is 10 cm?

alpine sable
#

I literally have no idea how to do it

#

like

#

if S(x)=6x^2 is the area of the cube

#

then the question says that d/dx S(x) = 20?

#

or what

#

well not dx but dt

hasty hill
#

no

alpine sable
#

d/dt S(x) = 20

hasty hill
#

yep

alpine sable
#

sooo

#

12x = 20?

#

or what

#

you took dx, which is not correct

#

oh okay

#

6x^2 = 20t

#

so x = sqrt(20t/6)

#

x^3 = sqrt(20t/6)^3

#

thus dx^3/dt = (calculate the above)

#

ohh

#

okay makes sense now

#

thanks!

#

what

#

*wait

#

but how do we use the fact that side length is 10?

#

unless I'm missing something

#

u use it to find t

#

then plug it back in

#

oh alright

#

how much yo got?

#

i got ~27.38cm^3/s

lone heartBOT
#

@alpine sable Has your question been resolved?

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indigo pasture
#

Find the derivative of the function. x(6x + 1)4

whole shell
#

x(6x+1)^4

indigo pasture
#

yes

whole shell
#

@indigo pasture do you know product rule

#

and chain rule

indigo pasture
#

yes f'g+fg'

whole shell
#

@indigo pasture product rule first

#

then chain rule

#

for that question

indigo pasture
#

chain is f'(g)g'

whole shell
#

yh

#

well i say this

#

because when you do product rule

#

youll need to know what the derivative of (6x +1)^4 is

#

which you need to use chain rule for

indigo pasture
#

4(6x+1)^3+6

#

the product in this one will look like (6x+1)^4+24

#

.cloes

#

.close

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pseudo seal
#

what do i need to do here?

lone heartBOT
alpine sable
#

what will -5x^2 + 10x + 15 equal when it hits the water?

pseudo seal
#

how can i calculate that?

soft pulsar
#

Nothing to calculate yet. Read the word problem and try to figure out what value that equation has when the stone hits the water

alpine sable
#

what will the height = ?

#

hint: that equation models the height

pseudo seal
#

i got 3 seconds, but i calculated with the quadratic formula, how could i have done it without using any process?

whole shell
#

it into (5x+5)(-x+3)

#

or rather 5(x+1)(-x+3)

pseudo seal
#

thanks

#

.close

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tough shard
lone heartBOT
tough shard
#

Not sure where to start. I don't know how to adjust the equation for a rotation

lone heartBOT
#

@tough shard Has your question been resolved?

tough shard
#

<@&286206848099549185>

#

I'm guessing that the surface is a hyperboloid and an x^2 needs to be added to the equation to create a 3-D surface

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#

@tough shard Has your question been resolved?

tough shard
#

.close

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raven scroll
#

I understand there is a reflection in the y-axis, and a horizontal compression. I just don't understand how to figure out what factor of horizontal compression there is.

raven scroll
#

ohhhh thank you.

#

.close

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dawn crest
#

why is e^((-1)/n) = 0?

lone heartBOT
dawn crest
#

Actually i just realized that 1^x is always 1 so of course the denominator is bigger. Nvm

#

.close

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small shuttle
#

It asks to me the area between
x = 3 + y^2
x = 2 - y^2
y = 1
and y = -2

lone heartBOT
#

@small shuttle Has your question been resolved?

small shuttle
#

<@&286206848099549185>

lone heartBOT
#

@small shuttle Has your question been resolved?

north canopy
#

look at the graph sideways and integrate dy. thats what i would do

#

from y=-2 to y=1

#

@small shuttle

small shuttle
#

Oh, okay thanks

#

.close

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clever timber
#

hello

lone heartBOT
clever timber
#

do you guys know how I could solve lim x->-infinity 3^x*x

slender quiver
#

yeah

clever timber
#

how?

slender quiver
#

3^x goes to infinity

clever timber
#

it's -infinity

slender quiver
#

oh

frail stump
slender quiver
#

3^x goes to 0

#

x goes to -inf

clever timber
#

yeah,it's undefined then

frail stump
#

( have an indeterminate form of the type "infinity * 0" )

clever timber
slender quiver
#

on the denominator

clever timber
#

why is that since there's no -infinity involved?

#

i mean,how does that work

frail stump
#

Take the derivative of the numerator and denominator:

clever timber
#

cus it's the form before the -infinity is inputted

clever timber
#

i just don't understand how i can suddenly go to writing 3^x as 3^(-x)

slender quiver
#

3^x = 1/(3^(-x)

clever timber
#

oh

#

oops,I got it

frail stump
#

since x approaches negative infinity, and 3^x approaches 0

clever timber
#

yeah

#

total sense

#

thanks y'all

#

.close

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#
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low moat
#

Lets say there is a circle drawing competition, where people draw circles without equipment. This means the circles are imperfect. How do you determine how close/far it is to a perfect circle by using standard deviation, variance, etc?

low moat
#

this was one of the questions on the blackboard the other day during math class, but I couldnt get a photo of it, so I just typed it out here

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#

@low moat Has your question been resolved?

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vagrant tide
#

Can someone help me understand what I did wrong? Im also gonna send a photo of my work

vagrant tide
frail bison
#

when you cancel the x-63, the remaining stuff (sqrt(x+1)+8) will be in the denominator.

vagrant tide
#

wait so is it 1/16?

frail bison
#

yes

vagrant tide
#

okay thanks!

#

.close

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ember dagger
#

This isn’t 7?

lone heartBOT
ember dagger
#

<@&286206848099549185>

#

How I Solved It
• Given : 50,62,50,54,56,60,54,57,57

  • x̄ : 55.5555 ≈ 55.5
  • ox: 3.8329 ≈ 3.8

——————————————-
55.5 + 3.8 = 59.3
55.5 - 3.8 = 51.7
Highest - 59.3
Lowest - 51.7

—————————————
Given : 50,62,50,54,56,60,54,57,57
7 of them are within the standard deviation of the mean

lone heartBOT
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stiff surge
lone heartBOT
stiff surge
#

I have no idea what to do

#

Does it have something to do with gradient?

gilded magnet
#

For all three sides

naive crystal
#

Show that two sides of the triangle are equal

gilded magnet
#

Wait

#

Also Pythagoras

ocean sealBOT
#

realhuman

gilded magnet
#

Not -

#

Plus in between

stiff surge
#

Typo

gilded magnet
#

Knvms

#

Allgud

ocean sealBOT
#

Random Guy

stiff surge
#

So like

#

I still don't have an idea on what to do

gilded magnet
#

Find AB BC CA

stiff surge
#

and can I know why we are using the distance formula?

gilded magnet
#

To find the distance of these sides

surreal meadow
#

two show two sides have the same length

stiff surge
#

Ohh

gilded magnet
#

Also for Pythagoras

stiff surge
#

Which ever two side is equal shows it is an isoceles

gilded magnet
#

Yup

#

And Pythagoras for right angle

stiff surge
#

But isn't pythagoras theorem just used to find the side

gilded magnet
gilded magnet
stiff surge
#

I should just show the side?

gilded magnet
#

If Pythagoras theorem is working...it !eans the triangle is right angled

gilded magnet
stiff surge
#

a2+b2=c2

#

Actually I get it

gilded magnet
#

Yes

#

Kool

#

Like my pfp

proven leaf
stiff surge
#

lol

#

Anyways length of ab and length of bc are the same

proven leaf
#

now verify it's a right triangle

stiff surge
#

Okay

proven leaf
#

oh also you're going to need to find the length of the third side

#

then verify it using Pythag

stiff surge
#

Thank you all for helping me out

#

I successfully got the same answer

proven leaf
stiff surge
#

.close

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#
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stiff surge
#

For these kind of questions can the x be negative

stiff surge
#

Well it is not a question it is just a clarification

wary stream
#

Which x?

#

There's a lot

stiff surge
#

Like can the answer be: (-x-4)(x-7)

#

I am asking it generally

#

whether if the x inside the bracket can be negative

surreal meadow
#

yes

stiff surge
#

Okay tq

surreal meadow
#

this is related to the coefficient on the x^2

#

also note that these answers could all have negatives

stiff surge
surreal meadow
#

take question 1 for example

#

(x-24)(x-1) = (24-x)(1-x)

#

which one specifically

stiff surge
#

Actually nvm

#

The answer

#

I just wanna know if the answer can be negative

#

the variable not the numbers

surreal meadow
stiff surge
#

ok

#

tq

lone heartBOT
#

@stiff surge Has your question been resolved?

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inland isle
#

I am currently doing trig. This is not a full question, just a small part of the answer. How did the brackets on the RHS split to become sin and cos. I don't see any info regarding it on the formula sheet.

fallen verge
#

Double angle formula

inland isle
#

.close

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hot trail
lone heartBOT
hot trail
#

im confused at what to do here

#

how do i solve for a?

#

its not
1331/9

north canopy
#

and at n=3, u have 121/9

#

what can u conclude with those infos ?

hot trail
#

.cloise

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.close

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lone heartBOT
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warped horizon
#

hello, can someone help me out with this problem

vale wigeon
#

what's the goal? to solve for x and y?

warped horizon
#

yeah we have to find the values of x and y

vale wigeon
#

k

#

progress?

warped horizon
#

should i send the pic ?

vale wigeon
#

yes absolutely

warped horizon
#

oeh alr one sec

real cipher
#

ello ann

vale wigeon
#

hi, did you want to ask something to me specifically or did you just want to intrude in this channel for some chat

real cipher
#

damn how long have you been playing slay the spire i completed with all the character
the second one intrude

vale wigeon
warped horizon
#

there

vale wigeon
#

L.C.M. here?
are you asking about legality or helpfulness

#

oh yeah btw you actually fucked up the earlier step

warped horizon
#

hm like am i supposed to do it ?

vale wigeon
#

you should have had $-100x + \frac{x}{4} + \frac{y}{24} = 8$ as your equation

ocean sealBOT
#

Ann (glomed)

vale wigeon
warped horizon
#

oh woops

#

-100x

warped horizon
#

soo how do i proceed after that ?

vale wigeon
#

my suggestion? multiply both sides of the first equation by 24, and of the second equation by 5.

#

that way you will not have any fractional coefficients to worry about.

warped horizon
#

oeh

#

kay i will give it a try one sec

#

Hmm it feels like im hetging somewhere

#

Ah this is a long one

#

i just checked the answer

#

OH

#

i will use another method rather than elimination ig

#

maybe it could work

#

Hmmmm

#

Didn't get the answer

#

@vale wigeon can u try this once please ?

tacit arch
#

Just show your work

warped horizon
#

I think its wrong doe

vale wigeon
#

as in you got no answer at all?

#

or you got the wrong answer

warped horizon
#

Wrong answer

vale wigeon
#

yeah show your work

#

then we can pinpoint your fuckup

warped horizon
#

Alr

vale wigeon
#

there it is

#

you tried to kill two birds with one stone and let both escape

warped horizon
#

i didn't want to multiply 24 by 100 lmao

vale wigeon
#

for shame because you would have to do that

#

from (6x+y)/24 = 100x + 8 to 6x + y = 2400x + 192

warped horizon
#

💀 big numbers scare me fr

vale wigeon
#

and then to -2400x + 6x + y = 192

vale wigeon
#

plus 100 is a nice number for multiplication purposes

warped horizon
#

its like, oh shoot big number must be wrong

north canopy
warped horizon
#

but the answer is like

#

quiet different idk

#

alr lemme try again

#

0 f up's challenge

#

Is this correct so far ?

#

i should get the value of y if i equate them both right ?

#

-192-y/2394 = 50 + 5y/2

#

@vale wigeon

#

Les goooo

#

I got it :D

#

But the calculation part scares me

lone heartBOT
#

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turbid stratus
lone heartBOT
turbid stratus
#

hello may i ask how to do question (ii)?

lone heartBOT
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@turbid stratus Has your question been resolved?

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elfin tree
lone heartBOT
lone heartBOT
#

@elfin tree Has your question been resolved?

lime light
#

use desmos on the internet they have a very neat way to do Q1. a

lone heartBOT
#

@elfin tree Has your question been resolved?

elfin tree
lime light
#

write in the equation in question one, exactly

#

except change the square brackets for round ones

#

then click all : )

#

by save i think they mean screenshot then submit?

#

play around with the sliders and note down what each one does in question 1b

lone heartBOT
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prime estuary
lone heartBOT
prime estuary
#

How should I go on to solve this question?

minor needle
#

you know formulas for the volume of a cylinder or sphere?

prime estuary
#

yep

minor needle
#

so what's the problem

prime estuary
#

I'm getting 1921.91

#

I'm going to go with 1921.68 for this, lemme see if it's right

#

it's correct

minor needle
#

pi = 3.14

#

,calc 3.14*(6^2)13+1/24/33.14(6^3)

ocean sealBOT
#

Result:

1921.68
prime estuary
#

oh right

#

small error from my side

#

.close

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warped horizon
#

can someone solve this Q.E, the roots are 3 or 1

limpid spade
#

You solve

warped horizon
#

yeah i did

limpid spade
#

What u got

warped horizon
#

one sec lemme show it once

#

there

#

i sent the x^2 to the right side cuz of the negetive

#

in the first one

#

the roots shouldbe 3 and 1

#

but i am not getting em

nimble fern
#

3x-7x≠5x

warped horizon
#

wait lmao

#

sht

#

i was reading it as 2 the entire time

#

💀 \

#

thx lmao

#

.close

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alpine sable
#

set one side of the equation to 0 then factor

#

id honestly just get another blank sheet and retry

#

id also maybe not use pen for solving next time

warped horizon
#

Lmao i was writing 3x - 7x as 5x instead of 4 💀

lone heartBOT
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calm grove
#

Can someone tell me what this sideways T means
This one |-

alpine sable
#

it prolly means that its a tautology

#

or sth

calm grove
#

Aahh thanks

lone heartBOT
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quasi vector
#

$x,y,z$ are positive reals such that $$\frac{x^2+yz}{y+z}+\frac{y^2+xz}{x+z}+\frac{z^2+xy}{x+y}>=m(x+y+z)$$ then find $m+12$

ocean sealBOT
#

kheerii

quasi vector
#

I tried using AM-HM inequality by breaking up the terms in different ways but that didn't give me anything

#

<@&286206848099549185>

#

anyone?

#

.close

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alpine sable
#

im trying

quasi vector
#

.reopen

lone heartBOT
#

quasi vector
alpine sable
#

tried am-gm on
$$\frac{x^2}{y+z}+\frac{yz}{y+z}+... +\frac{xy}{x+y}$$

ocean sealBOT
#

Jester

alpine sable
#

no yield

#

tryna fit this also

quasi vector
#

am-gm seems pretty unlikely

quasi vector
#

but doesn't seem to work either

lone heartBOT
#

@quasi vector Has your question been resolved?

quasi vector
#

.close

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#
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quasi vector
#

.reopen

lone heartBOT
#

quasi vector
#

<@&286206848099549185> anyone?

#

.close

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#
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warped horizon
#

hmm i didn't get this

lone heartBOT
tawny condor
#

First simplify and move everything to one side

warped horizon
warped horizon
tawny condor
#

Yeah

#

Factor out the x

#

In (2x - 6ax)/a

warped horizon
#

Yeah did that just now

#

So its coeff is 2(1-3a)/a

#

?

tawny condor
#

yea

#

just (2 - 6a)/a

#

Now use the quadratic formula

warped horizon
#

Oh i factored 2x

tawny condor
#

You can also factor out the 2 but you don't have to

warped horizon
#

I see

tawny condor
#

Your last line is wrong

#

where's the /a?

#

b = (2 - 6a)/a

warped horizon
#

Yeh didn't write it yet

#

I think this one's also like the previous one u explained

#

But not ab

#

Maybe root a ?

#

Or root a²

#

@tawny condor what should i do here ?

tawny condor
#

In the denominator it should be just 2 * 2

#

Not 2 * (2a)

#

a is only in the coefficient of x

warped horizon
#

Oh woops

#

Ye ye

#

Soo what should i do now ? Do i do it the previous way ?

#

Like multiply with a

tawny condor
#

Simplify as much as you can

#

First open the parenthesis inside of the square root

warped horizon
#

Oh kay

warped horizon
#

Hm most probably a - b whole sq

tawny condor
#

(2 - 6a)^2 isn't 4 + 36a^2

#

$(a+b)^2 = (a + b)(a + b) = a(a + b) + b(a + b) = a^2 + ab + ba + b^2 = a^2 + 2ab + b^2$

ocean sealBOT
#

RedstonePlayz09

warped horizon
#

Yeye i was a lil bit confused if i can use that identity or not

#

Cuz it was on a fraction

warped horizon
tawny condor
#

Should be /a^2 in the square root

#

instead of /a

#

You forgot that I think

warped horizon
#

Oh yeah

#

warped horizon
tawny condor
#

You should revise basic algebra then

#

Once you master it, questions like these will be a breeze

warped horizon
#

Oeh i see

tawny condor
#

Understand where your formulas are coming from as well

tawny condor
warped horizon
#

Yeah i know identities and their derivations

#

I didn't know we could still apply it when its on a fraction

tawny condor
#

Can you give me an example where that confused you

warped horizon
#

Like (a+b/2)²

#

I thought when its like that it won't apply

tawny condor
#

Then look at your sum as

#

a being added to

#

b/2

#

So you have

#

$a^2 + 2 \cdot a \cdot \frac{b}{2} + \parens{\frac{b}{2}}^2$

ocean sealBOT
#

RedstonePlayz09

tawny condor
#

And then simplifying:

#

$a^2 + ab + \frac{b^2}{4}$