help-0

[shy dove]

that's it? You've found a and b expressed in terms of theta

that's the question

[shy skiff]

oh wow lol

I thought it was an actual integer ty mate

[shy dove]

no worries. Yeah it couldn't be a number because you didn't know theta. If you knew theta, then you would've found a number

[shy skiff]

same thing for this?

[grizzled aspen]

inverse trig functions

[shy skiff]

may you enlighten me 🙂

[ocean seal]

Broken

[shy skiff]

oh is this the Sina/a =sinB/b

oh nvm

[grizzled aspen]

this turns into $\Theta =tan^{-1}(\frac{x}{5})$

[ocean seal]

Broken

[shy skiff]

ohhh

I'll try bottom one

cos theta = 3/x

then theta = cos^-1 (3/x)

[grizzled aspen]

yes

[shy skiff]

thanks mate:)

[grizzled aspen]

np

[shy skiff]

the angle is 80 degrees

how do I go about this one?

this the law of sines?

[grizzled aspen]

what is it asking to find

length of ladder?

[shy skiff]

how high up the ladder touches the building

so the opposite of theta

[granite inlet]

This isn't law of sines this is just a trigonometric equation

[shy skiff]

gotchya

[grizzled aspen]

i mean you could do law of sines

[granite inlet]

You can equate a trig function of theta to your base a and the height against the building and solve

You could but, law of sines can give you triangles that don't exist it's best to avoid it

Especially for something as direct as this

[shy skiff]

could u show an example?

[granite inlet]

Because this is a right triangle we don't need to use law of sines

[shy skiff]

^ I'll have to do law of sines in a moment

but not now

[ocean seal]

Broken

[granite inlet]

Yup

X is what you want and solve for x

[grizzled aspen]

where a = 6 and theta is 80

[shy skiff]

opposite and adj, solving for hypo

oh okay

[granite inlet]

Nah you don't need the hypotenuse if you use the appropriate trig function

[ocean seal]

Broken

[shy skiff]

that's what I got just not sure how to move the x over again

it's not tan^-1 or is it

[granite inlet]

In general for problems with right triangles the trigonometric functions themselves are defined as ratios of sides of the triangle relative to a particular angle in the triangle so you can use them to solve for the entire triangle

You won't need arctangent here

[grizzled aspen]

you could just calculate tan(80)

[granite inlet]

You aren't solving for a triangle

Angle*

[grizzled aspen]

and then multiply both sides by 6

[shy skiff]

oh yes lol mb

[ocean seal]

Broken

[shy skiff]

34 feet

[grizzled aspen]

you could also see how they do it in another example when you practice another

if thats available for that question

[shy skiff]

it's more off a review right before an exam

I've done all this before but it's so much

and I couldn't comprehend the differences between questions when there was so much

I think the next one though is law of sines

the Asa or ssa etc

[grizzled aspen]

sinA/a = sinB/b

[shy skiff]

ahhh okay I'll try this one on my own for a sec

fuck lol

I even have notes I replicate but I've no idea why I did what I did

different problem that I did

what's with the x^2? on the right?

yeah I've no clue

[grizzled aspen]

not sure

[shy skiff]

got it lol

cryptic shit but

[lone heart]

@shy skiff Has your question been resolved?

Channel closed

Closed by @shy skiff

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[strong summit]

Can someone do this?

[proven leaf]

,rotate

[long axle]

Someone can do this but someone that is not u should not do this

Someone that is not u can help u do this

If you are so inclined to be inclined

[vernal thunder]

What have you tried

[proven leaf]

bro Stephen my man, what are you saying? lol 💀

[strong summit]

I tried 1 way but it was hella confusing and hurt every brain cell I had that I took a 30 minute break

[vernal thunder]

The moment you said straightforward integration

[strong summit]

But here it is

[strong summit]

I didn't even bother 😭💀

[proven leaf]

"" 😂

anyways

your idea was pretty good, expanding then integrating each term via the power rule of integration

were you getting confused on the expanding?

[strong summit]

The fractions were really annoying to deal with and took way too long

This shouldn't take more than 3 minutes

[proven leaf]

try writing it all out and doing is slowly rather than going on algebra autopilot

right?

[vernal thunder]

You just solved it for them

[strong summit]

Wdym

[proven leaf]

were you getting confused about the expanding?

[strong summit]

Is it correct

[strong summit]

Yeah specifically the fractions part it got really annoying

[proven leaf]

they're integrating I don't think expanding two linear terms would be considered solving it for them, but eh I'll relax it a bit

[strong summit]

But I have to expand first right?

[proven leaf]

so try to expand $(x^3-3)(\sqrt{x}-1)$ first

[ocean seal]

XxMrFancyu2xX

[vernal thunder]

Oh

You forgot +C

[vernal thunder]

,w integral of \frac{(x^3 - 3)(\sqrt{x} + 1)}{x^2}

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by % Openglobe %#3085

[proven leaf]

well he was right

[vernal thunder]

God damn

He solved it

But they forgot +C

So ratio

[proven leaf]

F

[strong summit]

Wait so I did it right 😅😅

Why did it feel like I did everything wrong

I feel like my steps were too messy

[proven leaf]

what made them feel messy?

cause after looking at ur image they seemed coherent?

[strong summit]

Cause I do most of the work in my head instead of write it down ig

Which usually makes me mess up on the easy stuff

Alright thank yall 🙏

[proven leaf]

yw!

[lone heart]

@strong summit Has your question been resolved?

Channel closed

Closed by @strong summit

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vernal thunder]

,rotate

[vernal thunder]

You can find the area of this trapezoid

All you need is the formula

Do you know it

[timid iron]

yes

.close

[lone heart]

Channel closed

Closed by @timid iron

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[willow wraith]

I got y=@^3sec(@) + @^3

but it should be

I dont get where the negatives game from

[vernal thunder]

Can you make you work a bit cleaner and show one step per separate line

[willow wraith]

ok

open it in browser for full res

brother this room is occupied

you need to post in open rooms

[cobalt mauve]

Oh, sorry 0.0

[willow wraith]

pls delete and use the ones above

anyways I still dont get why it should be negative

[lone heart]

@willow wraith Has your question been resolved?

[lone heart]

@willow wraith Has your question been resolved?

[willow wraith]

damn hello?

[frosty niche]

i think it's right

may be answer is wrong

[willow wraith]

you think so

cause i just dont see where the negatives would come from

let me get a second opinion if someone else thinks the same ill just close it

.close

[lone heart]

Channel closed

Closed by @willow wraith

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solemn agate]

How would one go about solving these? Surface area is being asked (on the first 3)

[solemn agate]

I have no idea about how I'd go about the second one

On the first and third ig I'd just calculate the rectangles then add the pyramids on the first and the half cylinders on the third?

But since some 2 sides of the rectangles are covered idk what to do

[grizzled aspen]

the second one you can just find the area of the whole rectangular prism then subtract 1/2 the area of the cylinder

[solemn agate]

Makes sense

Thanks

[grizzled aspen]

np

[solemn agate]

Anyone know about the other ones?

3. surface area of rectangle = 2(wl+hl+hw)=2·(18·45+22·45+22·18)=4392

4392 - 2 sides of the rectangle = 45x18 = 4392 - 810 = 3582

surface area of cylinder = 2πrh+2πr2=2·π·9·45+2·π·92≈3053.63 - the 2 sides of the halves glued to the rectangle = 810 x 2 = 1620

3053.63 - 1620 = 1433.63

surface of rectangle 3582 + surface of cylinder 1433.63 = 5015.63

<@&286206848099549185>

[frosty niche]

shouldn't it be 3528+3056.63

[solemn agate]

for what

[frosty niche]

TSA for 3

[solemn agate]

with tsa meaning?

[frosty niche]

total surface area

[solemn agate]

did u make any typos?

i dont see me writing any of those numbers

what did i do wrong?

[frosty niche]

..

[solemn agate]

what

[frosty niche]

you have written in the last line

[solemn agate]

i wrote 3582 not 3528

[frosty niche]

oh yeah 3582*

[solemn agate]

is the 3056.63 also a typo

[frosty niche]

main thing is you don't have to subtract the 2 surfaces of cuboid from cylinder

[solemn agate]

i wrote 3053.63

so only the 2 from the rectangle?

[frosty niche]

yeah sorry for that

[solemn agate]

makes sense didnt think it through that much

[solemn agate]

is this correct?

[frosty niche]

like take complete surface area for cylinder

and add cuboid surface area with subtracting two surfaces

[solemn agate]

could i also just not change the rectangle and remove the 1 side that is touching the rectangle on eac hhalf cylinder?

[frosty niche]

that's what i am saying

and it's a cuboid

[solemn agate]

u said to remove 2 sides from the cubod

[frosty niche]

yeah that are touching half cylinder

[solemn agate]

im asking if i can remove 1 side from each half cylinder

[frosty niche]

that will eventually be same

[solemn agate]

ok that was the question

thanks

[frosty niche]

any other?

[solemn agate]

whys he subtracting 2 sides?

1 from the pyramid one from the cuboid?

O = surface area G = the base side of the pyramid

[frosty niche]

yes it's right

if you take pyramid area you will get that rectangle area also with it but we don't need it

same for cuboid

surface area is area of visible surfaces like you dont have to include the rectangle which is between pyramid and cuboid

[lone heart]

@solemn agate Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lime holly]

determine the angle formed by the two vectors geometrically

[vale wigeon]

and represent it geometrically.

do you know in general how to find the angle between two vectors?

[lime holly]

nop

or i might

hold up

[vale wigeon]

do the words "scalar product" ring any bells

[lime holly]

yes

a x b = |a| x |b| x cos theta

nvm i just answered my own question didnt i

[vale wigeon]

bad notation

one, don't use the letter x as a multiplication symbol
two, NEVER denote the scalar product with the letter x or even ×

[lime holly]

ok

i guess that becomes a problem when theres vectors huh

[stone gulch]

I use as '×' but my X is curvy, hence I don't get confused

[lime holly]

hey i got the airplane question now 😃 thanks

[vale wigeon]

with vectors × denotes cross product

never the scalar product, which is always written with a dot · or with angle brackets <u, v>

[lime holly]

but wait how am i supposed to know the magnitude of each vector

[stone gulch]

There's a formula

[lime holly]

wait

[stone gulch]

√[ (x component)² + (y component)² + 2 ab cos (angle between them. 90° here if it's components on axis) ]

[lime holly]

i dont know if ive seen that yet tbh

[stone gulch]

Wait

In other words, it's the distance between the end points

[lime holly]

that looks a lot like cosine law

[stone gulch]

Rightmost side

PARALLELOGRAM LAW

[lime holly]

but i dont know c or the angle

so i would be missing two variables?

[stone gulch]

You have to find c, isn't it?

[lime holly]

yes

[stone gulch]

Wait

[lime holly]

well

[stone gulch]

"determine the angle formed by the two vectors geometrically"

[lime holly]

i need the angle between both vectors

and to represent it geometrically

now i am unsure ;-;

[stone gulch]

,rccw

[stone gulch]

You can find the last bit, as your wish.

If they need to be approxed, you can.
I left it for you to adjust according to your question

[lime holly]

it says the answer is 55.8

[stone gulch]

Almost close

[lime holly]

what is this part from

[lime holly]

ah ok

thank you

[stone gulch]

☺️ you're welcome

Your book needs exact values.

My textbook never asked for exact values, my questions were mostly that cos (theta) came out as 1 and hence, theta = 0

[lime holly]

mine never specified

so i guess its just 0 from now on haha

anyways it probably wont be long until im back with another question but thank you so much :)

.close

[lone heart]

Channel closed

Closed by @lime holly

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vale wigeon]

fucked up here

you cannot multiply both sides by (1-4x) because (1-4x) is not sign-constant

[real cipher]

what

is a non sign-constant

[vale wigeon]

an expression or function is sign-constant if its value is always the same sign for all admissible values of its input variables

i.e. if it is either always positive or always negative

then you can tell whether or not to flip the inequality sign when multiplying through by it

[real cipher]

oh so x can be both postive or negative so the inequality may change i get it

but what now what should i do

[vale wigeon]

oh so x can be both postive or negative
no, it's (1-4x) that can be both positive or negative.

[vale wigeon]

well, you could visualize the graph of y=1/x and notice that 1/(1-4x) ≥ 7 is equivalent to 0 < (1-4x) ≤ 7

or if you want to go more formal you could rewrite 1/(1-4x) ≥ 7 as 1/(1-4x) - 7 ≥ 0 and then (1 - 7(1-4x))/(1-4x) ≥ 0 and do a sign analysis (after cleaning up the numerator)

[real cipher]

(1 - 7(1-4x))/(1-4x) ≥ 0
what are u doing here?

[real cipher]

..

@vale wigeon

$$ (1 - 7(1-4x))/(1-4x) ≥ 0$$

[ocean seal]

JXHN

[vale wigeon]

i combined the fractions into one

[real cipher]

$$ (1 - 7 + 28x)/(1-4x) >= 0 $$

[ocean seal]

JXHN

[vale wigeon]

$\frac{1}{1-4x} - 7 = \frac{1-7(1-4x)}{1-4x}$

[ocean seal]

Ann

[vale wigeon]

this is what i did

[real cipher]

oh, so i just have to simplfy this? let me do in latex here : PP

$$\frac{1-7-28x}{1-4x} \geq 7 $$

[ocean seal]

JXHN

[real cipher]

$$ \frac {-6-28x}{1-4x} \geq 0$$

[vale wigeon]

0 not 7

[real cipher]

oh oh right

[ocean seal]

JXHN

[real cipher]

so i can use recporical property now ?

of inequality
a > 0
1/a > 0

$$ (1-4x)(-6-28x) \geq 0 $$

[ocean seal]

JXHN

[real cipher]

@vale wigeon is this right?

[stone gulch]

You know about wavy curve?

[real cipher]

nope

[stone gulch]

It's EASIER

Wait

[real cipher]

no bro it's in my course but it's little bit farther away

this is from the section of basic stuff

I want to learn this way too

[real cipher]

if this is right should I solve it with zero product rule?

@vale wigeon

[stone gulch]

What did the rule say?

[real cipher]

ab = 0
either a = 0 or b = 0

[stone gulch]

Both can be 0 too?

[real cipher]

yeah i used "or"

or is logical operator(it's true when one statement is true or other statement is true or both statement is true)

[stone gulch]

You're right for the operator

The last part is generally done by wavy curve.

[real cipher]

@stone gulch I need help i couldn't solve can you redo the solution the process that Ann recommended ?

[stone gulch]

I'm trying

[real cipher]

okay ping me okay gonna take a lil break

[vale wigeon]

you're gonna need that but it is not enough

[real cipher]

yeah i am completely lost after i didn't get the right answer

@

can u solve it for me ://

x <= 1/4 and x <= 3/14

yeah i am completely lost

@vale wigeon

[vale wigeon]

sorry, am busy

[real cipher]

okay

[lone heart]

@real cipher Has your question been resolved?

[stone gulch]

She did with wavy curve too

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[median oar]

On the second line isn’t there supposed to be a minus at the front

[wanton roost]

Can I have some help understanding this problem

[golden canyon]

Yes, but doesn't matter since it will be set to 0 anyway

[wanton roost]

huh

what does that mean

[golden canyon]

#❓how-to-get-help

[median oar]

Ah that’s why the 2 disappears on the next line as well

.close

[lone heart]

Channel closed

Closed by @median oar

Use .reopen if this was a mistake.

[median oar]

Thanks

[wanton roost]

.open

.claim

.reopen

.help

[lone heart]

Commands:
clopen: .close, .reopen, .solved, .unsolved
consensus: .poll
factoids: .tag
help: .help

Type .help <command name> for more info on a command.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wanton roost]

10 - 12 + 17 x 10/5

[wanton roost]

I dont know where I am stuck

[wanton nova]

$10-12+17 \cdot \frac{10}{5}$

[ocean seal]

Oogy Boogy

[wanton nova]

Like this

[wanton roost]

wha

[wanton nova]

?

Yes or no

[wanton roost]

no

oh yes

[wanton nova]

Ok

We can get rid of the fraction first

[wanton roost]

how

[wanton nova]

Whats 10/5

[wanton roost]

2

[wanton nova]

Good

$10-12+17 \cdot 2$

[ocean seal]

Oogy Boogy

[wanton roost]

?

[wanton nova]

Now what do we do

[wanton roost]

uh multiply?

[wanton nova]

Ehat

Why did you put ?

[wanton roost]

bc that equation looks very scary

[wanton nova]

Ok

Do the multiplication

[wanton roost]

34

[wanton nova]

$10-12+34$

[ocean seal]

Oogy Boogy

[wanton roost]

46

[wanton nova]

No

[wanton roost]

oh

what do i do

[wanton nova]

I suggest doing the addition first

[wanton roost]

12 + 34 is 46 correct?

[wanton nova]

No

You have -12

Not 12

[wanton roost]

ohhhhhhhhhh

22

[wanton nova]

Yes

[wanton roost]

YayaayYAYay

[wanton nova]

But you still have the 10

Left

[wanton roost]

uh

hmm

12?

[wanton nova]

No

[wanton roost]

120

[wanton nova]

With + or -?

[wanton roost]

I added

[wanton nova]

Is it

22 or -22?

[wanton roost]

22

[wanton nova]

Ok

$10+22$

[ocean seal]

Oogy Boogy

[wanton roost]

32

[wanton nova]

Yes

[wanton roost]

But why do we add?

[wanton nova]

You just answered that

I asked you

22 or -22

And you said 22

Which is the same as +22

[wanton roost]

So we basically just added again ,with the ten?

[wanton nova]

$10-12+34$

[ocean seal]

Oogy Boogy

[wanton nova]

Go from left to right

Whast the first operation

[wanton roost]

add

[wanton nova]

No

From left to right

[wanton roost]

oh

10 - 12

[wanton nova]

And whats that

[wanton roost]

-2

[wanton nova]

And whats -2+34

[wanton roost]

OMG

32

[wanton nova]

Yes

[wanton roost]

OMG SO OBVIOUS

TYSM

.close

[lone heart]

Channel closed

Closed by @wanton roost

Use .reopen if this was a mistake.

[wanton nova]

Np

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[normal flicker]

can anyone help me figure this out as an equation? thanks

[naive valley]

how far did you get?

!status

[lone heart]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[normal flicker]

1

just doing some revision but for this type of question i have probably forgetton

[naive valley]

try rearranging so that all terms involving x are on one side, and all terms not involving x are on the other side

[normal flicker]

ok will do

[lone heart]

@normal flicker Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[copper pendant]

can anyone please help me with this

[copper pendant]

<@&286206848099549185>

[dry fern]

Is this a test

[copper pendant]

nope

homework

[rocky atlas]

(25 marks): do I even exist

[copper pendant]

please help

its part of a past paper

like past exam paper

[rocky atlas]

25 marks: so I'm a thing of past, alright

[copper pendant]

yes

dude i need help on this

[dry fern]

bro read the rules

[copper pendant]

i did

bro this is 2020 exam paper

this is for homework for me

[dry fern]

electronic exams

[copper pendant]

no dude

if this was an exam there would be option or smthn

literally a pdf of exam questions

[rancid atlas]

sounds believable my teacher also gives past papers

[copper pendant]

please help

am so close to finishing this

[stone gulch]

Wait

What's the problem?

[rocky atlas]

Problem is a or b?

[copper pendant]

a)

[obsidian hornet]

well then just find where they are and use pythagoras?

[hushed wolf]

draw a diagram first

[rocky atlas]

Find the displacement travelled by ship A and ship B individually after 30 minutes

[hushed wolf]

where will they be

[copper pendant]

alr

so waht is step 1

[stone gulch]

This is step 1

[obsidian hornet]

so ship A will be 7.5km out and b will be 15km out

and then you find that from port b ship a is um 82.5km out

and then yeah you have 15km and 82.5km use pythag

[copper pendant]

alr so this is what i have

to find displacement

correct if im wrong

75/2 for ship A is 7.5km

30/2 for ship B is 15km

so whats the next step

[hushed wolf]

draw a diagram

[copper pendant]

alr

[hushed wolf]

show their new positions

and then you will see the triangle

[rocky atlas]

Do 90-7.5 then use pythagoras

[hushed wolf]

if you connect the new point A and B

[rocky atlas]

This point will be clear if you show diagram

[copper pendant]

alr

[hushed wolf]

can you see the triangle

[copper pendant]

yes

[hushed wolf]

okay so do the pythagorean theorem now

[copper pendant]

ok so this is where i am

inside square root is

(90-7.5) square + (15)square

ans:83.86km

@rocky atlas question

why did you find the displacement first

[rocky atlas]

you could have asked the question, not specifically to me

But since you asked

[copper pendant]

no cos your pro

[rocky atlas]

We find displacement first to find the targetted triangle for using Pythagoras theorem

[rocky atlas]

Not really

We see that the there are two ships and they are moving perpendicularly to each other so as long as we find the displacement done by both ships individually, we can trace a triangle where hypotenuse can be the distance between the ships

[copper pendant]

ohhh okkayy

makes more senes

actually

i dont get the hypotenuse triangle part

the one to sketch that

how do you work that out

[rocky atlas]

That's related to geometry

[copper pendant]

proof of past paper

[copper pendant]

wait but could you sketch a triangle of this

so i can understand

[rocky atlas]

Well when there is a triangle whose one angle is 90 degree, there will always be a hypotenuse and we use Pythagorean theorem there

In this case both ships move 90 degree to each other so I figured out that it's hinting us to make a 90 degree triangle

[copper pendant]

alr thats all i needed thanks guys

.close

[lone heart]

Channel closed

Closed by @copper pendant

Use .reopen if this was a mistake.

[rocky atlas]

@copper pendant the triangle will be smh like this

[copper pendant]

.reopen

[lone heart]

✅

[copper pendant]

oh so 15 on vertical

[rocky atlas]

Yes

[copper pendant]

82.5 on horizontal

wait so last question

why take away 90-7.5

why cant it just be 7.5

[rocky atlas]

It's 90 on horizontal actually

The ship moved 7.5

And the point at which you can see a triangle

So the horizontal of our triangle is 90-7.5

Even thou total horizontal is 90

[copper pendant]

is this where B is then

[rocky atlas]

Yea

[copper pendant]

alr i'll send you what im seeing

[rocky atlas]

Sure

[copper pendant]

Sorry using McDonalds wifi

[rocky atlas]

I see

How do I trust it's not a virus?

After all you send me a file

It could be risky for me

@copper pendant

[copper pendant]

Why would it be a virus du

Dude your helping me

[rocky atlas]

Yeah

But I can't take risk

[copper pendant]

Trust me it's a pictur

[rocky atlas]

If it was just a picture you would screenshot and send it here

[copper pendant]

Alr I ll show you

[rocky atlas]

You sending it in file format is suspicious

[copper pendant]

Sussy indeed

[rocky atlas]

Yeah that's the thing basically

[copper pendant]

Told you now click that file above

[rocky atlas]

Wait no

[copper pendant]

What

[rocky atlas]

7.5 should be on the position of 82.5

And 82.5 should be on position of 7.5

[copper pendant]

Ohhh

[rocky atlas]

Ship a travels 7.5km from Port A

You even found displacement yourself

[copper pendant]

Alr got you

[rocky atlas]

You should have figured it out

Alright

[copper pendant]

So we calculating the distance

[rocky atlas]

Yeah

[copper pendant]

90 is distance overall

[rocky atlas]

Triangle is made up of sides

So we are looking for distances

[copper pendant]

15/2 gives us displacement BUT NOT distance

[rocky atlas]

Yes

[copper pendant]

So in order to find the distance 90 which is overall distance-7.5 which is the partial distance

But to get the distance from port a to where ship a is 82.5

[rocky atlas]

Yeah

[copper pendant]

Alr thanks calamity

[rocky atlas]

Wait

[copper pendant]

Your a real one

[rocky atlas]

Thank you

[copper pendant]

What

Thank you honestly

[rocky atlas]

Port a to where ship A is 7.5

Not 82.5

[copper pendant]

Wait so what is 82.5

[rocky atlas]

I told you

The image you posted

Just exchange the position of 82.5 and 7.5

That's their true position

[copper pendant]

Ale

Alr

[rocky atlas]

Wdym find distance 90

Distance 90 is already given!!

[copper pendant]

I know

Wait

So what is 7.5km

What is 82.5km

[rocky atlas]

We got 7.5 by multiplying velocity of ship A to 30 minutes

At the start ship A was at Port A

[copper pendant]

Yes

[rocky atlas]

It then moved by some velocity for 30 minutes

We multiplied that velocity to 1/2 hour to get us 7.5km

[copper pendant]

Right

[rocky atlas]

So that's where 7.5 came

We then substracted 7.5 from overall distance 90

To get us the required side of the triangle

@copper pendant think of it like a story

Ship A is the hero who travels at a speed of 15km/hr towards right

[copper pendant]

alr so this is what i dont get

ship a travelled 7.5km correct?

[rocky atlas]

Ship B is the cindrella who travells vertically downward at a speed of 30 km/hr

[rocky atlas]

Yes

After 30 minutes

[copper pendant]

alr so 82.5 is amount of km needed in order to finish correct?

as you said required side of triangle

[rocky atlas]

Yes

[copper pendant]

alr and ship b was at port b

but then it travlled 15km

so

[rocky atlas]

82.5 km is the length of the required side of the triangle

[copper pendant]

since it said 30 minutes after they sail in the question

and it asks to find the distance

[rocky atlas]

It traveled after 30 mins yes

Yes

So see geometry

The distance between ship A and ship B after 30 minutes will be the hypotenuse

[copper pendant]

so ship a travelled 7.5km after 30 mins correct?
and ship b travelled 15km after 30 mins correct?

[rocky atlas]

Yes

[copper pendant]

alright

so this is where the cat in the hat is

[rocky atlas]

What is it

[copper pendant]

so why do we use 82.5km when thats how much km is needed to finish

[rocky atlas]

Because

[copper pendant]

instead of 7.5km

[rocky atlas]

Let me draw again for you

You will your answer then

[copper pendant]

alr bet

[rocky atlas]

There is no triangle formed if we consider 7.5km @copper pendant

[copper pendant]

OMGGG

NOW I UNDERSTAND

[rocky atlas]

lol nice

[copper pendant]

WOW

dude i've been so stuck on this for the past hour

alr now it all makes sense

[rocky atlas]

Nice

[copper pendant]

man you improved your maths skills with this question definitely

alr gtg

[rocky atlas]

[copper pendant]

thanks for the help man man

.close

[lone heart]

Channel closed

Closed by @copper pendant

Use .reopen if this was a mistake.

[rocky atlas]

Wlc

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[paper sage]

Can someone help me solve this

[dry fern]

German eh

Sorry comrade but I don't understand the question

It's german

[lone heart]

@paper sage Has your question been resolved?

[paper sage]

I should just calculate this integral

[paper sage]

Where gamma is the over half of the ellipse from (1.0) to (-1,0)

@dry fern

[lone heart]

@paper sage Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[haughty plank]

A company produces cocoa powder. The random variable x describes the filling weight of the packs in grams (g) and is assumed to be normally distributed. The expected value of the filling weight is 125g. The standard deviation is 2g. All weights are in grams, down to one decimal place. A manufacturer checks his filling machine. To do this, he examines 500 packs that were filled by this machine. The filling weight is too low if it is more than 4.5g below the expected value. Show the validity of the following statement using a binomial distribution: The probability that more than 2% of the packs have an insufficient filling weight is about 4.6%

[lone heart]

@haughty plank Has your question been resolved?

[haughty plank]

<@&286206848099549185>

[haughty plank]

<@&286206848099549185>

[woeful pulsar]

what have you tried so far

what's the probability a particular packet has insufficient filling weight

[haughty plank]

4.6%

well i have to determine if that is the right probability

[haughty plank]

i know the insufficient weight is 120.5 gs but i dont know how to determine the probability of it weighing less than 120.5gs

[woeful pulsar]

normally distributed

[haughty plank]

p(x<120.5)

so

125-x*2=120.5
x= 2.25
(z(2.25))= 0.9945
1-0.9945= 0.0055

the probability of packets weighing less than 120.5 gs

what do i have to do now

[lone heart]

@haughty plank Has your question been resolved?

[lone heart]

@haughty plank Has your question been resolved?

[lone heart]

@haughty plank Has your question been resolved?

Channel closed

Closed by @haughty plank

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[native nebula]

help

[native nebula]

is my solution correct?

[night atlas]

lemmes ee

[fleet vale]

yes

[golden canyon]

?

[fleet vale]

yeah I saw this too

lol

[night atlas]

yeah

correct

[native nebula]

i was not sure with the answer

[minor needle]

,w abs(4x-3)<=11

[golden canyon]

Well it is correct

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Modus#7591

[native nebula]

okk

.close

[lone heart]

Channel closed

Closed by @native nebula

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vapid shuttle]

What are you trying to solve?

can you send your original question? from the textbook or online or wherever

It looks like the bottom inequality is easiest

start there

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ruby frost]

not sure what went wrong. i did these exact steps for a previous problem and it worked

[ocean hawk]

the vectors should be 3x1

[ruby frost]

ohh

[ruby frost]

so should my 3rd row have 0's

oh the extra row should be the first row right?

so [0, 2, 1] and [0, -3, 0]?

[ocean hawk]

no

you have the first 2 elements of each correct already

[ruby frost]

so it should be [2, 1, 0] and [-3, 0, 0]?

that doesn't make sense though

[ocean hawk]

no

if you have 0s in both then you're "ignoring" x3 =

[barren shuttle]

Yeah you forgot to set x3=x3

[ruby frost]

wouldn't this be no solutions?

there are more variables than equations

you can't get a pivot for every column so it's impossible to be consistent

[ocean hawk]

there are infinite solutions

[ruby frost]

oh bc of x_2

how do i know that x3 = x3 though too?

[ocean hawk]

no, because there must be at least 1 free variable; in this case there are 2

I don't know why they are insisting on saying x2=x2 and x3=x3. better to do something like x2 = s, x3 = t. but you'll get the same combination of vectors anyway

[ruby frost]

i'm not really sure how parametric vector form works

[ocean hawk]

you write $\begin{pmatrix} 2x_2 - 3x_3 \ x_2 \ x_3 \end{pmatrix}$ as a combination of vectors. in this case, as x2 times something plus x3 times something

[ocean seal]

cwatson

[ruby frost]

should c1x1 + c2x2 = 0?

c1 and c2 being constants?

[ocean hawk]

where do c1 and c2 come from?

[lone heart]

@ruby frost Has your question been resolved?

[ruby frost]

you said times something

so i made the something c1 and c2

[ocean hawk]

no, the "something" represents a vector

you almost had the answer to begin with...

[ruby frost]

you're saying it's this

but idk why

[ocean hawk]

I didn't say it was that, the first vector is wrong

it would be [2 1 0]

to see that it's right, combine them into 1 vector

[ruby frost]

i don't understand how you're getting these numbers

there just isn't a 3rd row

in the equations

[ocean hawk]

it's a 2x3 matrix

it has to be multiplied by a 3x1 vector

[ruby frost]

this gotta be right

imma drop this class and throw the computer out the window if it's wrong

[ocean hawk]

yes that looks right

[ruby frost]

oh good

so basically just don't forget that if a column doesn't have a pivot, then it's a free variable

which must be included in the system of equations

[ocean hawk]

yes

[ruby frost]

gotcha thank you

.close

[lone heart]

Channel closed

Closed by @ruby frost

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steady basin]

need some help in part a plz

[worn fox]

show that (u+w,v) = (u,v) + (w,v), there isn't really much of a hint to give you that isnt the answer

[ocean hawk]

<@&268886789983436800>

[worn fox]

use A1 and A3 in literally the only way you can

[steady basin]

ok

[mortal trellis]

(thats only additivity, you also need (au,v) = a(u,v) )

[lone heart]

@steady basin Has your question been resolved?

[lone heart]

@steady basin Has your question been resolved?

Channel closed

Closed by @steady basin

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[icy jewel]

i dont understand the question

[icy jewel]

guys pls

heres more context

<@&286206848099549185>

[graceful grove]

try “tan 6 = h/132”

[icy jewel]

thx, h/135 worked

.close

[lone heart]

Channel closed

Closed by @icy jewel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jaunty sierra]

did i draw v -2u correctly?

[frosty niche]

no ig

[jaunty sierra]

what did i do wrong?

[frosty niche]

direction of u vector you have shown is upward right?

[jaunty sierra]

oh

[jaunty sierra]

is this right?

[ivory fern]

Not yet

v is indeed right and -2u is right too now

But v-2u is wrong

[frosty niche]

head will be pointed towrds -2u

[lone heart]

@jaunty sierra Has your question been resolved?

[jaunty sierra]

roughly, would it look something like this?

[ivory fern]

No

You have to find v-2u = v + (-2u)

And you have drawn v and -2u

So you have to add them

[ivory fern]

However this is not the way vectors are added

[jaunty sierra]

how do i do it?

[ivory fern]

Don't you remember how to add two vectors?

[jaunty sierra]

i thought i did..

[ivory fern]

Like this

You have done something similar but in the wrong order

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[violet wedge]

this is a stats question, im trying to prove the pdf of Z=X+Y but i cant wrap my head around how that double integral for the cdf was formed:

[lone heart]

@violet wedge Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[icy jewel]

i dont get what im doing wrong

[surreal meadow]

cos has a range between -1 and 1

-sqrt{3} is outside that range

you have the right idea

[icy jewel]

oh

so would it be 1 - (sqrt3 - 1)

[surreal meadow]

no, how did you get that

[icy jewel]

idk

[surreal meadow]

normalize the point

treat it like a vector

and scale it down

[icy jewel]

oh ok

[surreal meadow]

so it’s magnitude is 1

[icy jewel]

cool thx

.close

[lone heart]

Channel closed

Closed by @icy jewel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[violet wedge]

im trying to prove the pdf of Z=X+Y but i cant wrap my head around how that double integral for the cdf was formed:

[violet wedge]

i just really dont understand how the outer integral is -inf to inf

[worn fox]

if you let y be whatever you want (the outer integral), then to have x + y <= a, you need x <= a - y

[violet wedge]

i see, that makes sense

then to get the pdf from the cdf

u just differentiate right

[worn fox]

from cdf to pdf you differentiate

[violet wedge]

yes

thank you

.close

[lone heart]

Channel closed

Closed by @violet wedge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[forest fiber]

is the answer 2403

[proven leaf]

Volume of the total solid is the volume of the rectangular and triangular prisms

[forest fiber]

yeah

[forest fiber]

i know that?

[proven leaf]

that's why the volume is 2403

because that is the sum of the rectangular and triangular

unless ur question is on calculating those volumes.

[forest fiber]

i dont think you understand im just asking for a check if the answer is correct i think i know what to do

[proven leaf]

ohhh

gotchu

i don't think 2403 is correct

but then again it's kinda late where I am so I could be wrong

[forest fiber]

ill tell you what i did

[proven leaf]

aight

[forest fiber]

I found the volume of the rectangle which was 9 * 15 * 12 then I found the volume of the triangle which was 7.8 * 135 I added both volumes then I subtracted 135 twice

i forgot to add the sums 9 * 15 * 12 =1620 7.8 * 135=1053 1053+1620=2673 2673-135x2= 2403

<@&286206848099549185>

.close

[lone heart]

Channel closed

Closed by @forest fiber

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[flat vale]

how did they get from left to right

$A \neq [c_1 \mid c_2 \mid \cdots \mid c_k]$ right

[ocean seal]

TheWhiteShadow

[merry depot]

c1,...,ck are pivot columns of A
that's how you define matrix multiplication

[flat vale]

cuz c is the pivot column

[flat vale]

how?

[merry depot]

$\begin{bmatrix} v_1 & v_2\end{bmatrix}\begin{bmatrix} a_1 \ a_2\end{bmatrix} = a_1v_1 + a_2v_2$ where $v_1$ and $v_2$ are vectors.

[ocean seal]

Zybikron

[flat vale]

no i get that but

hol on

lets say this

the pivot columns are colum 1 and 3

$\alpha_1\begin{bmatrix}2\2\2\2\end{bmatrix}+\alpha_2\begin{bmatrix}3\3\4\5\end{bmatrix}=\vec{0}$

[ocean seal]

TheWhiteShadow

[flat vale]

so this is the same as

$\text{A}\begin{bmatrix}\alpha_1\\alpha_2\end{bmatrix}=\vec{0}$

[ocean seal]

TheWhiteShadow

[flat vale]

it doesnt make sense?

$A \neq \begin{bmatrix}2 &3\2& 3\2 &4\2 &5\end{bmatrix}$

[ocean seal]

TheWhiteShadow

[flat vale]

@merry depot

[merry depot]

ah. probably just some sloppy notation then

either they're taking A to be just the pivot columns (the other columns are lin dep on those, so they're unnecessary) or they got sloppy with the indices on the alphas

[flat vale]

[lone heart]

@flat vale Has your question been resolved?

[lone heart]

@flat vale Has your question been resolved?

[lone heart]

@flat vale Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[orchid perch]

is there a standard name to the operation of sum of vectors elements?

[orchid perch]

like magnitude of example is for the length

is there a special name for the sum

[remote heron]

maybe youre looking for norm?

[orchid perch]

magnitude is the same as norm isnt it

[solemn agate]

sides touching the cuboid too?

Am I allowed to reply to an old convo

[remote heron]

normal vector like

square root of the sum of the elements squared

thats a 2 norm

[orchid perch]

yeah thats magnitude

im looking for non-squared sum

i assume there's no special name for it

[remote heron]

the 1 norm?

thats just the sum of the magnitude of the elements

[orchid perch]

ohhh

so its called 1 norm

[remote heron]

https://mathworld.wolfram.com/L1-Norm.html

[orchid perch]

yup tysm

thats what i meant

.close

[lone heart]

Channel closed

Closed by @orchid perch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[minor merlin]

Is this correct?

[minor merlin]

I keep getting 4 root66 -4

But the answer says it’s 6 not 66

[merry depot]

how are you getting 66?

[ruby current]

when you change the bounds, you don’t undo the substitution

[minor merlin]

When I plug 6 into the equation in the bracket it gives me 4 root66 am I not supposed to do that

[ruby current]

6 is the bound you derived for u

you can either: keep the antiderivative in terms of u and use the bounds 1 to 6, or keep the antiderivative in terms of x and use the bounds 1 to 2

[minor merlin]

Oh ok I get it now

Thanks so much

.close

[lone heart]

Channel closed

Closed by @minor merlin

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hot bluff]

i got the same answers you did by law of sines

what do you need help with then?

how what works?

law of sines or other trig functions

trig functions like sine and cosine are just ratios

yes

i actually did the reciprocal but i got the same answers

you also gotta know that total angle measure in a triangle is 180, so you find the other angles pretty easily since every triangle is a right triangle (has one angle of 90 degrees denoted by a square)

[lone heart]

@alpine sable Has your question been resolved?

Channel closed

Closed by @worn cobalt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shut mantle]

$8e^-x -e^x = 2$

[ocean seal]

Bánh Xèo

[shut mantle]

How do I solve for x

that should be a powered x by the way