#help-0

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plain vortex
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@wary stream guess what

lone heartBOT
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@dim oxide Has your question been resolved?

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median oar
#

Is $\lim_{x\to c} f(x)g(x) = \text{DNE}\$ if $\lim_{x\to c} f(x)$ diverges?

median oar
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$\lim_{x\to c} f(x)g(x) = \text{DNE} \lim_{x\to c} f(x)$

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$hi$

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Bot dead 😦

ocean sealBOT
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Frosst

vale wigeon
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you mean, if lim f(x) is known not to exist, does lim f(x)g(x) also not exist?

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@median oar

median oar
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Yeah

vale wigeon
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no

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take g(x) = 1/f(x)

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or g(x) = -f(x)

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whichever

median oar
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Hmm true

sharp sail
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lim x-> 0 (1/x) DNE
lim x-> 0 (x) = 0
and lim x->0 x/x = 1

median oar
#

Ok never mind then thank you

#

.close

lone heartBOT
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vestal shell
lone heartBOT
vestal shell
#

Can someone help here , i can't find my mistake

ocean sealBOT
vestal shell
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Why completing the square dosen`t work , but quadratic formula works

alpine sable
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you lost some factors of 1/2

ancient lantern
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x = {1,2,3} ;A = {1,{1,2},{{1,2,3}}}
is X subset of A?
can u answere this guys?
and what are the power set?

vestal shell
# alpine sable

ok i forget the 1/2 , but the next step is right ? Or not ? cos^2(x) + cos(x)/2 + 1/4 = (cos(x) + 1/2)^2?

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Sorry english is not my main languague

alpine sable
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thats not correct

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,tex .cts

ocean sealBOT
alpine sable
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you would need (cos(x)+1/4)^2

lone heartBOT
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@vestal shell Has your question been resolved?

chrome salmon
#

,rotate

ocean sealBOT
lone heartBOT
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thick lynx
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If we have an impulse of two things, does the conservation of energy still hold?

whole shell
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that has always wierded me out aswell

wind cloak
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Mechanical energy is always conserved as long as the only forces acting on the system are conservative

coarse vale
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Can we ask physics questions in here too?

lone heartBOT
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@thick lynx Has your question been resolved?

thick lynx
wind cloak
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Provided the above condition is met, then yes

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Impulse is just the change in momentum anyways

wind cloak
thick lynx
thick lynx
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Tarzan wants to save someone from a crocodile

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his energy at first is m * g * h

coarse vale
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ig I don't have to try find a similar server for physics then ._.

thick lynx
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And we can calculate the height he will reach with the person by setting m * g * h = (m + m_otherPerson) * g * h_2, right?

wind cloak
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Uh

thick lynx
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Solving or h_2

wind cloak
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m1gh1 + 1/2m1v^2 = (m1 + m2)gh2

thick lynx
wind cloak
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Yeah then I guess it makes sense

thick lynx
# wind cloak Yeah then I guess it makes sense

I did that, and I got a different result than when I set m * g * h equal to the speed he will be going with when he reached the person, used the momentum conservation theorem and then the conservation of energy again.

And it seems that the latter is the correct way, setting m_Tarzan * g * h_1 = (m_Tarzan + m_Person) * g * h_2 seems to give a wrong result for h_2

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So from that, I would conclude that the conservation of energy doesn't hold here the whole time

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Just until before the impulse

wind cloak
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Are you sure there are only conservative forces on the system?

thick lynx
wind cloak
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Maybe friction when Tarzan saves the person from the alligators or whatever

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That's all I can think of

thick lynx
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Yet that gives a different answer

wind cloak
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Friction doesn't affect momentum

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As long as net force is 0, you can conserve momentum

thick lynx
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Thanks

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lone heartBOT
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last ether
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All the points must lie on a certain line

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What's the function that represents this line?

lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
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@alpine sable Has your question been resolved?

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foggy brook
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A biquadratic polynomial f(x) has zeroes-2, 3, 5 and 7. If f(0)=1, then the remainder when f(x) is divided by (x-1) is

foggy brook
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please let me know how to approach such a question

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tag me

quick peak
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Did you figure out what f(x) is

foggy brook
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that is a way to write the f(x) with help of given zeroes and then to solve it

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but I want to know any alternate way

quick peak
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Why

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Lol

foggy brook
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LOLLL

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this is time taking

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way

alpine sable
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How

quasi vector
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from the first bit of info, f(x) = k(x+2)(x-3)(x-5)(x-7)

alpine sable
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(x+2)(x-3)(x-5)(x-7)

quasi vector
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from the second bit you can find out k

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for the last part u can use remainder theorem

foggy brook
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and how much time would it take to do it?

quasi vector
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not much

foggy brook
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yet

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did u solve it?

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.close

lone heartBOT
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tough thistle
lone heartBOT
tough thistle
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how do i find the algebraic formula for every nr

alpine sable
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consider every part of the insekt

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for example the "horns" grow by 2

tough thistle
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yeah

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so the horns are

alpine sable
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so the H_n = 2 + 2*n

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what class sum would that be?

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and you do that for every body part and sum them up

tough thistle
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yeh the horns are easy to find

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but the rest are hard for me

alpine sable
tough thistle
alpine sable
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H for Horns

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h for head

tough thistle
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ok

alpine sable
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7, 19, 37

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it increases by 12, then by 18

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if you consider the next one the increase will increase by 6

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so [ h_{n+1} - h_{n} = 12 + (n-1) * 6 ]

ocean sealBOT
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Jester

alpine sable
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there might be an easier way like just guessing the n-th term

lone heartBOT
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@tough thistle Has your question been resolved?

tough thistle
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im nevver getting that

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im just gonna take a C- gg

lone heartBOT
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@tough thistle Has your question been resolved?

alpine sable
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need help

quiet vector
lone heartBOT
lone heartBOT
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lethal dock
lone heartBOT
lethal dock
#

In each 100, there are 10 threes that can come

vale wigeon
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are there?

lethal dock
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bc like 3,13,23,...

alpine sable
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What about 31 ,32 ,33 ,34 ....

vale wigeon
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3, 13, 23, 30, 31, 32, 33, ..., 39, 43, ...

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and then there is the entirety of the 300-399 range as well

lethal dock
vale wigeon
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there are more than 10 fitting cards within each hundred

lethal dock
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so then there are 19 threes in each hundred

vale wigeon
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not in each

lethal dock
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except the 300 one

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it will have 99

vale wigeon
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why 99 and not 100

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which number did you exclude from the count?

lethal dock
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nvm its 100

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i excluded 300

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sorry

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so can we do 19*9 plus 100

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271

vale wigeon
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yes, that gets us the number of cards containing a three

lethal dock
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ohh thus its 271/1000

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thanks

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.close

lone heartBOT
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alpine sable
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hi

lone heartBOT
alpine sable
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i need help with log

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5log50

copper delta
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you can use a calculator?

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what do you mean

alpine sable
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yeah

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but iw anna do it out of my head

copper delta
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when you say log is that log10

alpine sable
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yh

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You remember valuw of log 5?

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no

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You can't do it in head

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:;()

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so the answer is 8.4?

lone heartBOT
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@alpine sable Has your question been resolved?

proven timber
#

@alpine sable just close the ticket dawg

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😭

alpine sable
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😭

lone heartBOT
#

@alpine sable Has your question been resolved?

gloomy raven
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Can anyone help me please

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My work is on hegarty maths theres two questions

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I know how to do them its just the writing them out bit

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@lone heart

lone heartBOT
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@alpine sable Has your question been resolved?

wary stream
#

You rounded wrong

wary stream
carmine reef
#

You could try to approximate it

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5log(50) = 5+5log(5), so approximate log(5)

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5^8 = 340625 ≈ 10^5.5 so log(5)≈5.5/8 = .6875

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5+5log(5) ≈ 5+3.4375 ≈ 8.4375

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,w 5log_10(50)

carmine reef
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eh not great

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,w 5.5/8

carmine reef
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5log(50) = log(312500000) ≈ 8.5 ig lol

wary stream
ocean sealBOT
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dldh06

carmine reef
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ah I see

carmine reef
#

5log(50) = 8+log(3.125)

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that 8+ is so much better than the 5+

wary stream
#

Mine isn't too bad of a method

carmine reef
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3.125 ≈ 3.16*.99 ≈ 10^.5 / 10^idk

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Dividing the 2 logs really doesn't look fun

carmine reef
lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
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trail yacht
#

I have to calculate the volume of a solid limited by:

trail yacht
#

I did it by setting triple integrating and setting the parameters of the figure as I imagined

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is that correct?

placid zinc
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Can't say for sure if you are without the work

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But it can certainly be done as a triple integral

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However, I suggest doing it as a double integral, which seems easier to me

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No matter what, a picture of everything going on will be important

trail yacht
#

for example: in the z axis the figure varies from 0 to the point where x^2+2*y^2=2 meets x+y+2z=2

trail yacht
#

my questions is: is it possible to calculate the volume without a sketch of the whole figure? and the triple integral will be something like ///1dzdxdy?

lone heartBOT
#

@trail yacht Has your question been resolved?

placid zinc
#

Possible? Yeah. I would never try it though, haha

#

Triple integral would be something like that, yeah

trail yacht
#

.close

lone heartBOT
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lone heartBOT
#

@quiet sandal Has your question been resolved?

surreal meadow
#

we cant see the questions from that

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can you send a picture of them

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also i suggest you delete that link, people could input anything they want for your teacher to see

quiet sandal
#

sure

quiet sandal
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it was from a math comp

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and its practive

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but alr

surreal meadow
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still, people can write in anything

lone heartBOT
#
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quiet sandal
surreal meadow
#

.reopen

quiet sandal
#

.reopen

lone heartBOT
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surreal meadow
#

this is a very wide range of questions

surreal meadow
#

you have basic algebra, geometry, probability

quiet sandal
#

uh

vapid shuttle
quiet sandal
#

I wanted to study for the next one

surreal meadow
quiet sandal
#

ill send link

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ksea

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nmsc

vapid shuttle
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nvm then!

quiet sandal
#

they dont look at responses

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it dosn't matter

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but I gtg sleep now, if you can tell me some resources that I can use in dms that would be appreciated

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otherwise its fine

vapid shuttle
#

It's odd because it does say "sample" test, but it also has this

quiet sandal
#

idk

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why

surreal meadow
quiet sandal
#

alr

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thank you

vapid shuttle
#

waiting for your question maximo...

surreal meadow
#

.close

lone heartBOT
#
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surreal meadow
#

forgot i opened this lol

remote heron
#

rare maximo question

vapid shuttle
#

maximo buddy you are supposed to put questions in the help-channel once you open it

lone heartBOT
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uncut epoch
lone heartBOT
uncut epoch
#

I don’t understand why it should be (7sin(pi*x))/(pi)

tacit arch
#

The solution's notation is wrong

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They found the antiderivative already but left the integral sign

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,w int 7cos(pi x) dx

uncut epoch
#

But why is it over pi?

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Is it just a thing I gotta know?

tacit arch
#

And fundamental theorem of calculus

median oar
#

<@&268886789983436800>

sharp thorn
#

<@&268886789983436800>

vapid shuttle
#

Don't click on that link

sharp thorn
#

i didnt hehe

lone heartBOT
#

@uncut epoch Has your question been resolved?

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cold zenith
#

y'' - 8y' + 16y = -2e^4x

lone heartBOT
cold zenith
#

im struggling to find a general solution

surreal meadow
#

!status

lone heartBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
cold zenith
#

I'm trying to work out one of the constants but i keep going in circles

surreal meadow
#

!show

lone heartBOT
#

Show your work, and if possible, explain where you are stuck.

cold zenith
#

1 sec

#

@surreal meadow

chrome salmon
#

Too much rough

cold zenith
#

theres two parts to a general solution right

chrome salmon
#

Don't use -2e^(4x) on right

surreal meadow
#

you need an extra power of x for your guessed solution

cold zenith
#

i found the complementary function but i cant find the particular integral

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wdym

cold zenith
chrome salmon
#

#

Ax²e^(4x)

chrome salmon
#

Didn't see PI

cold zenith
#

you want me to just multiply through by x?

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or x^2?

surreal meadow
#

by x^2

chrome salmon
surreal meadow
#

your guessed solution should be (Ax^3 + Bx^2)e^(4x)

cold zenith
#

what does that do tho

chrome salmon
#

Yeah this

surreal meadow
#

what

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that is your y_cf

cold zenith
#

why do i multiply thru by x^2?

surreal meadow
#

because 4 is a double root of the auxiliary equation, which shows up as e^4x in the right hand side

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review the method of undetermined coefficients

cold zenith
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i just thought a double root meant the guessed solution will take the form (Ax + b)e^mx

surreal meadow
#

no

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i again suggest you review the method of undetermined coefficients

cold zenith
#

damn

#

foiled again

lone heartBOT
#

@cold zenith Has your question been resolved?

lone heartBOT
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cold zenith
#

.reopen

lone heartBOT
#

cold zenith
#

@surreal meadow i watched a 40 minute video on methods of undetermined coefficients it didnt say anything about multiplying by x or anything like that

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can you just explain it to me

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im pretty sure i get everything else

surreal meadow
cold zenith
#

@surreal meadow is this just some special rule or what

surreal meadow
#

it’s the method of undetermined coefficients

cold zenith
#

@surreal meadow but this is only for equations equal to Ct^(m)e^(rt)?

surreal meadow
#

how is that different from what you have?

cold zenith
#

it works for my equation its just ive never seen this specific rule for equations in that form

lone heartBOT
#

@cold zenith Has your question been resolved?

lone heartBOT
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copper apex
lone heartBOT
copper apex
#

could someone help rq

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@copper apex Has your question been resolved?

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teal frigate
#

what am i doing wrong here?

lone heartBOT
teal frigate
#

heres the question

#

im on part b

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finite mesa
lone heartBOT
#

Please don't occupy multiple help channels.

finite mesa
#

hsut

#

.close

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heady finch
#

13th question

lone heartBOT
heady finch
#

What have I done wrong in the calculation exactly

limpid turret
#

,rotate -12

alpine sable
#

In the last 3rd step

#

You multiplied by 3 , but you divided 600/3

ocean sealBOT
heady finch
#

Yeah thanks

#

.close

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alpine sable
lone heartBOT
alpine sable
#

how am i supposed to use venn digram in this

#

its just a formula i have to apply and check if it matches the number of subsets right

#

?

#

just tag me if someone answers thx

lone heartBOT
#

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strong marten
#

Universe U = {2, 3, 4, 7, 8, 9}
P(x) = even number
Q(x) = uneven number
R(x,y): x is factor of y

Is this true or false ? Explain the formular in your language ?
a) ∃x∃y (Q(x) ∧ Q(y) ∧ ¬∃z (R(z,x) ∧ R(z,y)))

b) ∃x ∀y (P(x) ∧ Q(y) → R(z, x) )

strong marten
#

Universe U = {2, 3, 4, 7, 8, 9}
P(x) = x is even number
Q(x) = x is uneven number
R(x,y): x is factor of y

Is this true or false ? Explain the formular in your language ?
a) ∃x∃y (Q(x) ∧ Q(y) ∧ ¬∃z (R(z,x) ∧ R(z,y)))

b) ∃x ∀y (P(x) ∧ Q(y) → R(z, x) )

#

is this correct ? There exist two numbers x and y such that both x and y are odd numbers, and there is no number z that is a factor of both x and y.

lone heartBOT
#

@strong marten Has your question been resolved?

lone heartBOT
#

@strong marten Has your question been resolved?

lone heartBOT
#

@strong marten Has your question been resolved?

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drifting glade
#

$\int \left(f^{\left(p\right)}\left(x\right)\right)^nf^{\left(p+1\right)}\left(x\right)dx$

ocean sealBOT
drifting glade
#

Evaluate the following integrals in which
the function ƒ is unspecified. Note that ƒ^(p)
is the pth derivative of ƒ and ƒ^p is the pth power of ƒ. Assume ƒ and its derivatives are continuous for all real numbers. where p is a positive integer, n ≠ -1

#

where p is positive and n =/ -1

lone heartBOT
#

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hot eagle
#

Okay so

lone heartBOT
hot eagle
#

If I'm substituting
And I have

  1. 2x + y = 6
  2. 3x - 2y = 2

How do I begin the isolation process to make a new line for 1

#

Idk flip image command

modern sedge
#

,rccw

ocean sealBOT
hot eagle
#

Okay sic

#

On the left side I isolated then made new version

#

I don't get how for this side. There was 9 to subtract but this side is just y

modern sedge
lone heartBOT
#

@hot eagle Has your question been resolved?

lone heartBOT
#

@hot eagle Has your question been resolved?

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spring galleon
lone heartBOT
spring galleon
#

Don’t know how to solve this, did 4000/25 and that’s about all I know.

limpid spade
#

how did u simplify 4000/25

spring galleon
#

By dividing them, I got 160.

wet nest
#

cbrt(160)
Maybe try using approximation next

lone heartBOT
#

@spring galleon Has your question been resolved?

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alpine sable
#

A small theater had 8 rows of 23 chairs each. Workers just removed 9 of these chairs. How many chairs are left?

lone heartBOT
#
Channel closed

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alpine sable
#

8*23-9

#

thank you

crude meteor
#

But being more precise he's right

#

You need to do 8 x 23 and then minus 9

alpine sable
#

im not good at math so like i need help a lot 😭

crude meteor
#

But trying to improve is good , have a nice one

alpine sable
#

you too

lone heartBOT
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gritty wraith
lone heartBOT
wet lark
#

!status

lone heartBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
gritty wraith
#

i dont know where to begin

wet lark
#

okay so

#

tell me the area of a rectangle formula

#

let's start there

gritty wraith
#

ok

wet lark
#

what is the formula for the area of a rectangle?

gritty wraith
#

isnt the formula the numbers on the outside

wet lark
#

no, the equation where you find the area of a rectangle

#

how do you find the area?

gritty wraith
#

dont you times it

wet lark
#

ignore the problem for now

#

do you know how to find the area of a normal rectangle?

gritty wraith
#

oh yh

wet lark
#

what is it?

gritty wraith
#

so normally i just add it all up i think that the area i might be wrong

wet lark
#

that is the perimeter

gritty wraith
#

oh

wet lark
#

where you add all of the sides up

#

try again

gritty wraith
#

aint the top and and bottom the same

#

because there the same length

pearl dagger
# wet lark !status

Omg tysm I literally have had to explain this process so many times I didn’t realize there was a command for it

wet lark
#

let's go back a bit

gritty wraith
#

wait it says the area is 15

wet lark
#

no ignore the picture

gritty wraith
#

ok

wet lark
#

for now

gritty wraith
#

sorry

wet lark
#

we'll get back there soon

#

so, how do you find the area if we have a length of 5 and a width of 4?

#

let's review for a sec

gritty wraith
#

you get the you add 5+5 and 4+4 the add it all up

wet lark
#

that's the perimeter

#

not the area

gritty wraith
#

umm times 5 by 4

wet lark
#

yes correct

#

that is the area

#

which is..?

gritty wraith
#

20

wet lark
#

correct

#

okay now

#

from what we did

#

we just multiply the length and width together

#

to get the area

#

correct?

gritty wraith
#

yes i think so

wet lark
#

it should

#

since that is what you just did

#

you just multiply the width and length together

#

so with that in mind

#

we can conclude that the formula for the area of a rectangle is

#

$A=\ell w$

ocean sealBOT
wet lark
#

where l is the length

#

and w is the width

#

and A is the area

#

okay now let's look back at the problem

gritty wraith
#

ok

wet lark
#

what is the area of that rectangle on the picture you sent?

gritty wraith
#

15

wet lark
#

correct

#

so

#

let's plug that into A

#

$15=\ell w$

ocean sealBOT
wet lark
#

cool

gritty wraith
#

cm2

wet lark
#

now, what is the length of the rectangle from the picture?

gritty wraith
#

5cm

wet lark
#

mhm

#

so let's put that in

wet lark
gritty wraith
#

ok

wet lark
#

$15=5w$

#

now

ocean sealBOT
wet lark
#

what is the width?

gritty wraith
#

q-2cm

wet lark
#

mhm

#

so let's put that in as well

#

$15=5(q-2)$

ocean sealBOT
wet lark
#

now we have this equation

#

what do you think we do next to find q?

gritty wraith
#

uhh times it

#

by the length

wet lark
#

well, we are finding q

#

and to get the area

#

the equation is just simply this

#

$5(q-2)$

ocean sealBOT
wet lark
#

and that equation must gives us 15

gritty wraith
#

so 15cm

wet lark
#

$=15$

ocean sealBOT
wet lark
#

$5(q-2)=15$

ocean sealBOT
wet lark
#

we now have an equation

#

we don't have to worry about the picture anymore

gritty wraith
#

ok

wet lark
#

so, now we have this

#

what should you do to find q?

gritty wraith
#

we times it by the 5cm

wet lark
#

on where?

gritty wraith
#

im not sure

wet lark
#

we are done with the picture so dont worry about that

#

to find q, all we need to do, is to just solve for q

#

like how you would normally solve equations

#

so with that in mind

#

how would you solve for q?

gritty wraith
#

times q by q

wet lark
#

that wouldn't work

#

think back on where you learn how to solve equations

#

what should you do to solve for q?

charred bluff
#

you’re closer than you think

gritty wraith
#

do we just add it up

#

this is the hardest thing ive ever done

charred bluff
wet lark
#

okay let's go back for a second

#

let's do a short review

#

take this

#

$3x=6$

ocean sealBOT
wet lark
#

how would you solve for x?

charred bluff
gritty wraith
charred bluff
wet lark
gritty wraith
#

wait bring it to 1 side

wet lark
#

how

#

what do you need to do

#

to bring it to the other side?

charred bluff
#

no point in moving it

gritty wraith
#

bring the values to the other

wet lark
wet lark
charred bluff
#

oh

wet lark
#

that still works

charred bluff
#

makes sense

gritty wraith
wet lark
gritty wraith
#

why is math so hard

charred bluff
#

keo

#

it’s okay

#

just try and think

charred bluff
wet lark
#

seems you are struggling a bit

#

take a look on this

charred bluff
#

write down the way you think you would solve the equation

wet lark
#

then come back

gritty wraith
#

ok

#

ill be back in a sec

wet lark
#

alr

#

make sure you come back every so often so this channel doesnt time out

#

no wait

#

wrong lesson

#

@gritty wraith wrong lesson

charred bluff
#

wait

wet lark
#

solving equations on both side oop

#

not that one

gritty wraith
#

ok

#

bru i gotta do this homework or i cant play football for 2 weeks

wet lark
gritty wraith
#

and this is the 2nd question

charred bluff
gritty wraith
charred bluff
#

oh

#

how many do you have

gritty wraith
#

its due tomorrow

charred bluff
#

oh lord

#

yes

wet lark
#

it is possible

#

if you have the motivation to do so

#

but it's better off doing it at school for course credit

charred bluff
#

if you’re doing it during summer

#

then

#

you should be fine

#

but if you’re trying to learn on top of other schoolwork then u shouldn’t do it

#

yeppie

gritty wraith
#

yep im dying rn

#

all this

#

by today

#

i might just give up and take the 2 weeks with no football

wet lark
#

for me, yeah

#

practice problems goes a long way

gritty wraith
#

its telling me the x is a 1

#

so

#

the q is a 2

#

?

wet lark
#

if you plug in 2 in q

#

we get this

#

$5(2-2)=15$

ocean sealBOT
wet lark
#

and if we simplify the left hand side

#

\begin{align*}
5(2-2)&=15\
5(0)&=\
0&\not=
\end{align*}

ocean sealBOT
wet lark
#

so q is not 2

#

try again

gritty wraith
#

ok

charred bluff
gritty wraith
charred bluff
#

the thing you’re looking for is the distributive property

gritty wraith
#

ive asked my parents for help but they just have ago at me so

wet lark
gritty wraith
#

and say "im smarter then this" when they dont know the times tables

charred bluff
#

let’s try an easier equation

gritty wraith
#

i just wanna do this question

charred bluff
#

I want to try and help you understand so that you have the ability to do it in the future

gritty wraith
#

ok

#

ima just give up

#

.close

lone heartBOT
#
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alpine sable
#

dang, I gotta find the P0
belonging to plane 2 (2x+4y-2z=-1)

alpine sable
#

so I can subtract it from (1,0,0)

#

and then do the < > multiplication

lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

.close

lone heartBOT
#
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urban hazel
#

I need help on the possibilities

lone heartBOT
urban hazel
lone heartBOT
#

@urban hazel Has your question been resolved?

lone heartBOT
#
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steady basin
lone heartBOT
steady basin
#

i cant find the mistake ive made for part b

#

My work

lone heartBOT
#

@steady basin Has your question been resolved?

steady basin
#

.close

lone heartBOT
#
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vapid steppe
#

A bag contains 30 lottery balls numbered 1-30. A ball is selected, NOT replaced, then another is drawn. Find P(two perfect squares)

wintry panther
#

How many perfect squares do you have?

#

between 1-30

#

1,4,9,16,25

vapid steppe
#

5

wintry panther
#

How many outcomes can you get?

vapid steppe
#

5?

#

oh you mean total

#

30

wintry panther
#

I mean, you need to choose the sample space you work with

#

It can be the set of all pairs of numbers

#

because the order doesn't really matter

vapid steppe
#

it has to be from 1-30

wintry panther
#

Or you can choose ordered pairs for (first ball, second balls)

#

yes so, one possible outcome is "first ball =2 second ball =5"

#

if you want to consider the order of drawing the balls

#

Or you can think of it as unordered {2,5}

#

Choose one, what do you prefer?

#

(Both work)

#

@vapid steppe do you know what a sample space is?

vapid steppe
#

yea

wintry panther
#

Good

#

So what is the size of the sample space? (how many pairs do you have?

vapid steppe
#

30!

wintry panther
#

Nope

vapid steppe
#

wait

#

15

wintry panther
#

I mean in general, not only perfect squares...

#

(1,2),(1,3),...,(1,30),(2,1),(2,3),...,(2,30),....,(30,1),(30,2)...(30,29)

vapid steppe
#

i got the answer is 2/87 i did $\frac{5}{30}\cdot \frac{4}{29}$

ocean sealBOT
vapid steppe
#

but idk how

wintry panther
#

The number of pairs is

#

30*29

#

30 options for the first number, 29 for the second number

#

right?

vapid steppe
#

ye cuz its not replaced

wintry panther
#

good so this is the denominator

#

the size of the sample space..

vapid steppe
#

ye

wintry panther
#

Now for the numerator

vapid steppe
#

idk why u do 5 * 4 tho

wintry panther
#

How many pairs with perfect squares do you have?

vapid steppe
#

oh you take away a perfect square

wintry panther
#

5 for the first number, 4 remaining for the second

#

5*4

#

So it is $\frac{5\cdot4}{30\cdot 29}$

ocean sealBOT
vapid steppe
#

ok ty

wintry panther
#

You are welcome

vapid steppe
#

A football team has 5 freshman, 8 sophomores, 11 juniors, 16 seniors. If two are chosen at random to participate in the coin toss, what is the probability that both players chosen are seniors?

#

do i just do probability of the first person times the probability of the second person

#

wow i got it right it was 2/13

wintry panther
#

Alright, you did 16/(sum) * 15/(sum-1)

#

?

vapid steppe
#

yea

wintry panther
#

good

vapid steppe
#

Ryan's mom randomly chooses two days each week for Ryan to do his chores. What is the probability that she picks Saturday and Sunday?

wintry panther
#

OK

#

Similar to what we already did with the pairs of numbers

#

Now it's between 1-7

vapid steppe
#

its not 1/7 * 1/7

wintry panther
#

Nope

vapid steppe
#

or 1/7 * 1/6

wintry panther
#

2/7 * 1/6

#

you have two options for the first

#

then you are left with 1

#

It's all very similar

#

Like we did before

vapid steppe
#

i understand why the 7 goes to 6 but i dont get why the 2 goes to 1

wintry panther
#

You choose the first day between sat and sun

#

you have 2 options

#

After you choose the first, you can't choose it again

#

So you are left with 1 remaining day

#

from {sun, sat}

#

Got it?

#

The same way you did with the seniors

vapid steppe
#

ya

wintry panther
#

You chose one senior, then you had one less left

#

And as we did with the squares

#

You chose the first square (5 options), than you have 4 left

vapid steppe
#

Two dice are rolled, find the probability that the sum is a 6 or a 2

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lone heartBOT
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soft needle
#

I did
M= 2 - 4/6 - ‐2
To get -0.25, how do I finish the problem since I still need the other number?

heady pollen
#

a line generally has the equation
y=mx+b

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you got your m

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so you have:
y=-0.25x+b

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you also have 2 points, so a set of (x,y) which you can input

soft needle
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How can I get my B then?

vapid steppe
#

plug in (6,2) or (-2,4)

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into y=-.25x+b

heady pollen
#

you have an equation with 3 variables
if we plug in our point, so 2 variables, only 1 will remain, which is the b

soft needle
#

So
Y - 2 = -0.25 (x-6)?

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@heady pollen

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@vapid steppe

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Anyone there?

tacit arch
soft needle
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How do I do that?

tacit arch
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you have y-2 on the left. how do you make it so that it's only y?

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you have to add the same thing to both sides of the equation, so you add that number to -0.25(x-6) on the right.

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,tex .alg lesson

ocean sealBOT
#

riemann

soft needle
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supple yoke
#

Help find the Fourier transform of this function:

lone heartBOT
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sterile sparrow
lone heartBOT
sterile sparrow
#

I'm not entirely sure how to use an equation to describe such a thing

alpine nacelle
#

the xy-plane is the set of points such that z = 0

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and you naturally get that the intersection between the sphere and the xy-plane is a circle

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be careful with xz-plane tho, as the sphere doesn't intersect it

sterile sparrow
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how would I figure out those coordinates?

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maybe set the sphere equation equal to the xy plane?

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z=0

alpine nacelle
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let M be a point of intersection of the sphere and xy-plane
then (x-3)²+(y+11)²+(z-8)² = 100
z = 0
so (x-3)²+(y+11)² = 36

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that's a circle

sterile sparrow
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ahh ok gotcha

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sudden ginkgo
lone heartBOT
tired fossil
#

send pictures

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im not about to turn my head

sudden ginkgo
#

Alr

limpid turret
sudden ginkgo
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Give me one second

tired fossil
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till then, what dont you understand

sudden ginkgo
#

Could u help with this

tired fossil
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well a total of 141 books suggests that number of non fiction + 54 = 141

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thus non fiction is 141 - 54

sudden ginkgo
#

Okay ty

lone heartBOT
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subtle escarp
#

Maybe I’m overthinking this but I need some help

subtle escarp
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The question is about interest and what not and I’m not particularly good with word questions so this sentence kinda threw me off

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@subtle escarp Has your question been resolved?

subtle escarp
#

I understand if no one can help

lone heartBOT
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@subtle escarp Has your question been resolved?

little cloud
#

Just the find the A value using the compound interest formula. Divide the A value by 84 (7 years= 84 months) because the loan is taken for 7 years

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@subtle escarp

subtle escarp
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Mk so

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30k would be the p

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.029 would be the r

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So what would be the n

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Also thank you for taking your time to help me

little cloud
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the n would be 12 because the problem states that the interest in compounded monthly. There are 12 months in a year. So n is just the amount of times the interest is compounded in a year

subtle escarp
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Ah ok gotcha

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So I just did the math

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And idk if 36k would be the monthly payment

little cloud
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wait lemme solve it too

subtle escarp
subtle escarp
little cloud
subtle escarp
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Ohh

little cloud
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cuz 36k is the total payment

subtle escarp
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Ok that makes sense, Also I never considered it either

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Thank you so much dude, I missed the 3 days we started and went over this unit because I had family problems I was dealing with so this is a huge lifesaver

little cloud
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ur welcome man

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hope u ace the test!

subtle escarp
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Ty dude! I’ve kept my 4.0 this whole school year so it should be fairly easy

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soft needle
lone heartBOT
soft needle
#

What am I doing wrong?

karmic pulsar
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-1/3 * (-3) = 1

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The left point should be at y=6

soft needle
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I don't think that's right

slender quiver
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the slope of the line should go down by 1/3 but not up

subtle escarp
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Ya, whenever the x has a negative value

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The right side of the line goes down

soft needle
#

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wheat isle
#

I have this

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So far

slender quiver
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ok

wheat isle
#

Is like nothing but

wet lark
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simplifying it?

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,rotate

wheat isle
#

Yes

ocean sealBOT
wet lark
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okay so

deep moon
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?

wet lark
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!status

lone heartBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
deep moon
#

What's sin(90-theta)

wheat isle
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I’m not sure I just got it from the cosec

deep moon
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Yeah

wet lark
wheat isle
deep moon
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Are you aware of the angle identity?

wet lark
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okay so

deep moon
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Sin(90-theta) = cos(theta)

wheat isle
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I haven’t done a question like this when there’s no angle given

wet lark
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okay take a look at this

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$\csc(90^{\circ}-\theta)=\sec\theta$

ocean sealBOT
wet lark
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this is a cofunction identity

wheat isle
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Right

wet lark
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rest should be easy

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use the identity

wheat isle
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But how am I supposed to apply it here

wet lark
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$\sec\theta-\csc(90^{\circ}-\theta)$

ocean sealBOT
wet lark
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okay so

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Because $\csc(90^{\circ}-\theta)=\sec\theta$ is an identity, what do you think we should do next?

ocean sealBOT
wheat isle
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Sub in the identity in sec(theta)?

wet lark
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mhm

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so

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$$\sec\theta-\csc(90^{\circ}-\theta)$$
$$\sec\theta-\sec\theta$$

wheat isle
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csc(90-theta) - csc(90-theta)

ocean sealBOT
wheat isle
#

o

wet lark
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these 2 would just cancel each other out

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so what would that leave us at?

wheat isle
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0?

wet lark
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bingo

wheat isle
wet lark
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mhm

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it works the same way

wheat isle
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But it’s just easier with sec

wet lark
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i just think subbing it the other way works better

wheat isle
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Ah okay

wet lark
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since it's much less clutter

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but either works fine

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here are the rest of the cofunction identity

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pi/2 is another way of saying 90 degree

wheat isle
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Radians?

wheat isle
#

So would Q10 be 10
And Q11 be 68

wet lark
wheat isle
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Because they both add to 90

wet lark
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and you should easily find x or y

wheat isle
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So wouldn’t x be 10

wet lark
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well not exactly

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$\sin80^{\circ}\not=\cos80^{\circ}$

ocean sealBOT
wet lark
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just use the identity to change that cos to sin

wheat isle
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But 10 degrees is needed for sin80 to be equal to 90

wet lark
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and the answer should be obvious from there

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you use the identity

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$\sin(90^{\circ}-\theta)=\cos\theta$

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to change from sin to cos

ocean sealBOT
wet lark
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so it would be