#help-0
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@dim oxide Has your question been resolved?
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Is $\lim_{x\to c} f(x)g(x) = \text{DNE}\$ if $\lim_{x\to c} f(x)$ diverges?
Frosst
you mean, if lim f(x) is known not to exist, does lim f(x)g(x) also not exist?
@median oar
Yeah
Hmm true
lim x-> 0 (1/x) DNE
lim x-> 0 (x) = 0
and lim x->0 x/x = 1
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Can someone help here , i can't find my mistake
Why completing the square dosen`t work , but quadratic formula works
x = {1,2,3} ;A = {1,{1,2},{{1,2,3}}}
is X subset of A?
can u answere this guys?
and what are the power set?
ok i forget the 1/2 , but the next step is right ? Or not ? cos^2(x) + cos(x)/2 + 1/4 = (cos(x) + 1/2)^2?
Sorry english is not my main languague
Toby
you would need (cos(x)+1/4)^2
@vestal shell Has your question been resolved?
,rotate
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If we have an impulse of two things, does the conservation of energy still hold?
that has always wierded me out aswell
Mechanical energy is always conserved as long as the only forces acting on the system are conservative
Can we ask physics questions in here too?
@thick lynx Has your question been resolved?
Thank you. So does that mean that if we have an impulse, the energy before the impulse is the same as the energy after it, if the system is closed?
Provided the above condition is met, then yes
Impulse is just the change in momentum anyways
People have asked physics questions in the past and the moderation hasn't done anything in the past
I thought this is more theoretical/mathematical physics so it's fine
So if we have something like this
Tarzan wants to save someone from a crocodile
his energy at first is m * g * h
ig I don't have to try find a similar server for physics then ._.
And we can calculate the height he will reach with the person by setting m * g * h = (m + m_otherPerson) * g * h_2, right?
Solving or h_2
m1gh1 + 1/2m1v^2 = (m1 + m2)gh2
He starts with 0 speed
Yeah then I guess it makes sense
I did that, and I got a different result than when I set m * g * h equal to the speed he will be going with when he reached the person, used the momentum conservation theorem and then the conservation of energy again.
And it seems that the latter is the correct way, setting m_Tarzan * g * h_1 = (m_Tarzan + m_Person) * g * h_2 seems to give a wrong result for h_2
So from that, I would conclude that the conservation of energy doesn't hold here the whole time
Just until before the impulse
Are you sure there are only conservative forces on the system?
Well, nothing gets transformed into heat or something here (atleast not in theory), right?
Maybe friction when Tarzan saves the person from the alligators or whatever
That's all I can think of
Well, when using the mometum conservation theorem, that friction gets ignored aswell, I guess
Yet that gives a different answer
Friction doesn't affect momentum
As long as net force is 0, you can conserve momentum
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All the points must lie on a certain line
What's the function that represents this line?
@alpine sable Has your question been resolved?
@alpine sable Has your question been resolved?
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A biquadratic polynomial f(x) has zeroes-2, 3, 5 and 7. If f(0)=1, then the remainder when f(x) is divided by (x-1) is
Did you figure out what f(x) is
that is a way to write the f(x) with help of given zeroes and then to solve it
but I want to know any alternate way
How
from the first bit of info, f(x) = k(x+2)(x-3)(x-5)(x-7)
(x+2)(x-3)(x-5)(x-7)
from the second bit you can find out k
for the last part u can use remainder theorem
and how much time would it take to do it?
not much
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how do i find the algebraic formula for every nr
so the H_n = 2 + 2*n
what class sum would that be?
and you do that for every body part and sum them up
for example for the head consider, h_{n+1} - h_{n}
what the fuck is H
ok
7, 19, 37
it increases by 12, then by 18
if you consider the next one the increase will increase by 6
so [ h_{n+1} - h_{n} = 12 + (n-1) * 6 ]
Jester
there might be an easier way like just guessing the n-th term
@tough thistle Has your question been resolved?
wtfffffffffffffffffffffffff
im nevver getting that
im just gonna take a C- gg
@tough thistle Has your question been resolved?
need help
!help
Please read #❓how-to-get-help
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are there?
bc like 3,13,23,...
What about 31 ,32 ,33 ,34 ....
3, 13, 23, 30, 31, 32, 33, ..., 39, 43, ...
and then there is the entirety of the 300-399 range as well
well those are there too
there are more than 10 fitting cards within each hundred
so then there are 19 threes in each hundred
not in each
yes, that gets us the number of cards containing a three
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hi
when you say log is that log10
yh
You remember valuw of log 5?
no
You can't do it in head
:;()
so the answer is 8.4?
@alpine sable Has your question been resolved?
😭
@alpine sable Has your question been resolved?
Can anyone help me please
My work is on hegarty maths theres two questions
I know how to do them its just the writing them out bit
@lone heart
@alpine sable Has your question been resolved?
And no there is no easy way to do 5log(50) mentally as it results in messy decimal values
You could try to approximate it
5log(50) = 5+5log(5), so approximate log(5)
5^8 = 340625 ≈ 10^5.5 so log(5)≈5.5/8 = .6875
5+5log(5) ≈ 5+3.4375 ≈ 8.4375
,w 5log_10(50)
5log(50) = log(312500000) ≈ 8.5 ig lol
My method was $5\left(\frac{\log_5(25)+ \log_5(2)}{\log_5(5)+ \log_5(2)}\right) = 5 \left(\frac{2 + \log_5(2)}{1 + \log_5(2)}\right)$ but that gets messy too
dldh06
ah I see
This is definitely the way to go if you know the right small powers
5log(50) = 8+log(3.125)
that 8+ is so much better than the 5+
Mine isn't too bad of a method
no doing better than this
@alpine sable Has your question been resolved?
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I have to calculate the volume of a solid limited by:
I did it by setting triple integrating and setting the parameters of the figure as I imagined
is that correct?
Can't say for sure if you are without the work
But it can certainly be done as a triple integral
However, I suggest doing it as a double integral, which seems easier to me
No matter what, a picture of everything going on will be important
for example: in the z axis the figure varies from 0 to the point where x^2+2*y^2=2 meets x+y+2z=2
by using cilindrical coordinates?
my questions is: is it possible to calculate the volume without a sketch of the whole figure? and the triple integral will be something like ///1dzdxdy?
@trail yacht Has your question been resolved?
Possible? Yeah. I would never try it though, haha
Triple integral would be something like that, yeah
Thank you very much!
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@quiet sandal Has your question been resolved?
we cant see the questions from that
can you send a picture of them
also i suggest you delete that link, people could input anything they want for your teacher to see
sure
its not a teacher thing
it was from a math comp
and its practive
but alr
still, people can write in anything
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.reopen
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this is a very wide range of questions
you have basic algebra, geometry, probability
uh
This looks like a test.
it was for a old math competition
I wanted to study for the next one
it said sample test on the link they posted
nvm then!
they dont look at responses
it dosn't matter
but I gtg sleep now, if you can tell me some resources that I can use in dms that would be appreciated
otherwise its fine
its supposed to be liek the real one
idk
why
i listed some of the topics. your best bet is to just look it up, or ask your teachers for help

waiting for your question maximo...
.close
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forgot i opened this lol
rare maximo question
maximo buddy you are supposed to put questions in the help-channel once you open it
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I don’t understand why it should be (7sin(pi*x))/(pi)
The solution's notation is wrong
They found the antiderivative already but left the integral sign
,w int 7cos(pi x) dx
Chain rule
And fundamental theorem of calculus
<@&268886789983436800>
<@&268886789983436800>
Don't click on that link
i didnt hehe
@uncut epoch Has your question been resolved?
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y'' - 8y' + 16y = -2e^4x
im struggling to find a general solution
!status
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!show
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Too much rough
theres two parts to a general solution right
Don't use -2e^(4x) on right
you need an extra power of x for your guessed solution
-2e^4x is just part of the equation?
Nah I misunderstood that
Didn't see PI
by x^2
You already have xe^(4x) and e^(4x) in CF
your guessed solution should be (Ax^3 + Bx^2)e^(4x)
what does that do tho
Yeah this
why do i multiply thru by x^2?
because 4 is a double root of the auxiliary equation, which shows up as e^4x in the right hand side
review the method of undetermined coefficients
i just thought a double root meant the guessed solution will take the form (Ax + b)e^mx
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.reopen
✅
@surreal meadow i watched a 40 minute video on methods of undetermined coefficients it didnt say anything about multiplying by x or anything like that
can you just explain it to me
im pretty sure i get everything else
@surreal meadow is this just some special rule or what
it’s the method of undetermined coefficients
@surreal meadow but this is only for equations equal to Ct^(m)e^(rt)?
how is that different from what you have?
it works for my equation its just ive never seen this specific rule for equations in that form
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could someone help rq
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what am i doing wrong here?
@teal frigate Has your question been resolved?
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13th question
,rotate -12
Ohhh right
Yeah thanks
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how am i supposed to use venn digram in this
its just a formula i have to apply and check if it matches the number of subsets right
?
just tag me if someone answers thx
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Universe U = {2, 3, 4, 7, 8, 9}
P(x) = even number
Q(x) = uneven number
R(x,y): x is factor of y
Is this true or false ? Explain the formular in your language ?
a) ∃x∃y (Q(x) ∧ Q(y) ∧ ¬∃z (R(z,x) ∧ R(z,y)))
b) ∃x ∀y (P(x) ∧ Q(y) → R(z, x) )
Universe U = {2, 3, 4, 7, 8, 9}
P(x) = x is even number
Q(x) = x is uneven number
R(x,y): x is factor of y
Is this true or false ? Explain the formular in your language ?
a) ∃x∃y (Q(x) ∧ Q(y) ∧ ¬∃z (R(z,x) ∧ R(z,y)))
b) ∃x ∀y (P(x) ∧ Q(y) → R(z, x) )
is this correct ? There exist two numbers x and y such that both x and y are odd numbers, and there is no number z that is a factor of both x and y.
@strong marten Has your question been resolved?
@strong marten Has your question been resolved?
@strong marten Has your question been resolved?
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$\int \left(f^{\left(p\right)}\left(x\right)\right)^nf^{\left(p+1\right)}\left(x\right)dx$
m4x70
Evaluate the following integrals in which
the function ƒ is unspecified. Note that ƒ^(p)
is the pth derivative of ƒ and ƒ^p is the pth power of ƒ. Assume ƒ and its derivatives are continuous for all real numbers. where p is a positive integer, n ≠ -1
where p is positive and n =/ -1
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Okay so
If I'm substituting
And I have
- 2x + y = 6
- 3x - 2y = 2
How do I begin the isolation process to make a new line for 1
Idk flip image command
,rccw
Okay sic
On the left side I isolated then made new version
I don't get how for this side. There was 9 to subtract but this side is just y
rccw stands for "Rotate CounterClockWise"
@hot eagle Has your question been resolved?
@hot eagle Has your question been resolved?
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Don’t know how to solve this, did 4000/25 and that’s about all I know.
how did u simplify 4000/25
By dividing them, I got 160.
cbrt(160)
Maybe try using approximation next
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A small theater had 8 rows of 23 chairs each. Workers just removed 9 of these chairs. How many chairs are left?
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It makes 175
Chairs
im not good at math so like i need help a lot 😭
No worries i'm not so good either
But trying to improve is good , have a nice one
you too
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!status
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i dont know where to begin
ok
what is the formula for the area of a rectangle?
isnt the formula the numbers on the outside
dont you times it
oh yh
what is it?
so normally i just add it all up i think that the area i might be wrong
that is the perimeter
oh
Omg tysm I literally have had to explain this process so many times I didn’t realize there was a command for it
lmao np
okay, how do you find the area if we have a length of 5 and a width of 4?
let's go back a bit
wait it says the area is 15
no ignore the picture
ok
for now
sorry
we'll get back there soon
so, how do you find the area if we have a length of 5 and a width of 4?
let's review for a sec
you get the you add 5+5 and 4+4 the add it all up
umm times 5 by 4
20
correct
okay now
from what we did
we just multiply the length and width together
to get the area
correct?
yes i think so
it should
since that is what you just did
you just multiply the width and length together
so with that in mind
we can conclude that the formula for the area of a rectangle is
$A=\ell w$
gekka
where l is the length
and w is the width
and A is the area
okay now let's look back at the problem
ok
what is the area of that rectangle on the picture you sent?
15
gekka
cool
cm2
now, what is the length of the rectangle from the picture?
5cm
let's just assume that the numbers i put are centimeters
ok
gekka
what is the width?
q-2cm
gekka
well, we are finding q
and to get the area
the equation is just simply this
$5(q-2)$
gekka
and that equation must gives us 15
so 15cm
$=15$
gekka
$5(q-2)=15$
gekka
ok
we times it by the 5cm
on where?
im not sure
we are done with the picture so dont worry about that
to find q, all we need to do, is to just solve for q
like how you would normally solve equations
so with that in mind
how would you solve for q?
times q by q
that wouldn't work
think back on where you learn how to solve equations
what should you do to solve for q?
you’re closer than you think
No
gekka
how would you solve for x?

just take the 3 off it
Well yeah but
how, i ask?
wait bring it to 1 side
it’s already isolated though
no point in moving it
bring the values to the other
by doing what?
you can technically multiply by the reciprocal
oh
that still works
makes sense
switching it around
i definitely didnt struggle to type reciprocal lol
why is math so hard
can you demonstrate
seems you are struggling a bit
take a look on this
write down the way you think you would solve the equation
then come back
alr
make sure you come back every so often so this channel doesnt time out
no wait
wrong lesson
@gritty wraith wrong lesson
wait
and this is the 2nd question
?
here watch all of this
of my homework
it is possible
if you have the motivation to do so
but it's better off doing it at school for course credit
if you’re doing it during summer
then
you should be fine
but if you’re trying to learn on top of other schoolwork then u shouldn’t do it
yeppie
yep im dying rn
all this
by today
i might just give up and take the 2 weeks with no football
not really
if you plug in 2 in q
we get this
$5(2-2)=15$
gekka
and if we simplify the left hand side
\begin{align*}
5(2-2)&=15\
5(0)&=\
0&\not=
\end{align*}
gekka
ok
did you learn what to do?
nope
the thing you’re looking for is the distributive property
ive asked my parents for help but they just have ago at me so
well there is a better way of doing that
and say "im smarter then this" when they dont know the times tables
ok
let’s try an easier equation
i just wanna do this question
I want to try and help you understand so that you have the ability to do it in the future
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dang, I gotta find the P0
belonging to plane 2 (2x+4y-2z=-1)
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I need help on the possibilities
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A bag contains 30 lottery balls numbered 1-30. A ball is selected, NOT replaced, then another is drawn. Find P(two perfect squares)
5
How many outcomes can you get?
I mean, you need to choose the sample space you work with
It can be the set of all pairs of numbers
because the order doesn't really matter
it has to be from 1-30
Or you can choose ordered pairs for (first ball, second balls)
yes so, one possible outcome is "first ball =2 second ball =5"
if you want to consider the order of drawing the balls
Or you can think of it as unordered {2,5}
Choose one, what do you prefer?
(Both work)
@vapid steppe do you know what a sample space is?
yea
30!
Nope
I mean in general, not only perfect squares...
(1,2),(1,3),...,(1,30),(2,1),(2,3),...,(2,30),....,(30,1),(30,2)...(30,29)
i got the answer is 2/87 i did $\frac{5}{30}\cdot \frac{4}{29}$
Jash
but idk how
The number of pairs is
30*29
30 options for the first number, 29 for the second number
right?
ye cuz its not replaced
ye
Now for the numerator
idk why u do 5 * 4 tho
How many pairs with perfect squares do you have?
oh you take away a perfect square
5 for the first number, 4 remaining for the second
5*4
So it is $\frac{5\cdot4}{30\cdot 29}$
Cain
ok ty
You are welcome
A football team has 5 freshman, 8 sophomores, 11 juniors, 16 seniors. If two are chosen at random to participate in the coin toss, what is the probability that both players chosen are seniors?
do i just do probability of the first person times the probability of the second person
wow i got it right it was 2/13
yea
good
Ryan's mom randomly chooses two days each week for Ryan to do his chores. What is the probability that she picks Saturday and Sunday?
OK
Similar to what we already did with the pairs of numbers
Now it's between 1-7
its not 1/7 * 1/7
Nope
or 1/7 * 1/6
2/7 * 1/6
you have two options for the first
then you are left with 1
It's all very similar
Like we did before
i understand why the 7 goes to 6 but i dont get why the 2 goes to 1
You choose the first day between sat and sun
you have 2 options
After you choose the first, you can't choose it again
So you are left with 1 remaining day
from {sun, sat}
Got it?
The same way you did with the seniors
ya
You chose one senior, then you had one less left
And as we did with the squares
You chose the first square (5 options), than you have 4 left
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I did
M= 2 - 4/6 - ‐2
To get -0.25, how do I finish the problem since I still need the other number?
a line generally has the equation
y=mx+b
you got your m
so you have:
y=-0.25x+b
you also have 2 points, so a set of (x,y) which you can input
How can I get my B then?
you have an equation with 3 variables
if we plug in our point, so 2 variables, only 1 will remain, which is the b
simplify this into y=mx+b form
How do I do that?
you have y-2 on the left. how do you make it so that it's only y?
you have to add the same thing to both sides of the equation, so you add that number to -0.25(x-6) on the right.
,tex .alg lesson
riemann
I got y = -0.25x + 3.5 from that
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Help find the Fourier transform of this function:
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I'm not entirely sure how to use an equation to describe such a thing
the xy-plane is the set of points such that z = 0
and you naturally get that the intersection between the sphere and the xy-plane is a circle
be careful with xz-plane tho, as the sphere doesn't intersect it
how would I figure out those coordinates?
maybe set the sphere equation equal to the xy plane?
z=0
let M be a point of intersection of the sphere and xy-plane
then (x-3)²+(y+11)²+(z-8)² = 100
z = 0
so (x-3)²+(y+11)² = 36
that's a circle
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Please someone help
Alr
Give me one second
lol
till then, what dont you understand
well a total of 141 books suggests that number of non fiction + 54 = 141
thus non fiction is 141 - 54
Okay ty
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Maybe I’m overthinking this but I need some help
The question is about interest and what not and I’m not particularly good with word questions so this sentence kinda threw me off
@subtle escarp Has your question been resolved?
I understand if no one can help
@subtle escarp Has your question been resolved?
Just the find the A value using the compound interest formula. Divide the A value by 84 (7 years= 84 months) because the loan is taken for 7 years
@subtle escarp
Mk so
30k would be the p
.029 would be the r
So what would be the n
Also thank you for taking your time to help me
the n would be 12 because the problem states that the interest in compounded monthly. There are 12 months in a year. So n is just the amount of times the interest is compounded in a year
wait lemme solve it too
Lol take your time
u would still have to divide by 84
Ohh
cuz 36k is the total payment
Ok that makes sense, Also I never considered it either
Thank you so much dude, I missed the 3 days we started and went over this unit because I had family problems I was dealing with so this is a huge lifesaver
Ty dude! I’ve kept my 4.0 this whole school year so it should be fairly easy
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What am I doing wrong?
I don't think that's right
the slope of the line should go down by 1/3 but not up
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ok
Yes
okay so
?
!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
What's sin(90-theta)
I’m not sure I just got it from the cosec
@wheat isle
Yeah
it's an identity
I don’t know what else to do from what I have
Are you aware of the angle identity?
okay so
Sin(90-theta) = cos(theta)
I haven’t done a question like this when there’s no angle given
gekka
this is a cofunction identity
Right
But how am I supposed to apply it here
$\sec\theta-\csc(90^{\circ}-\theta)$
gekka
okay so
Because $\csc(90^{\circ}-\theta)=\sec\theta$ is an identity, what do you think we should do next?
gekka
Sub in the identity in sec(theta)?
csc(90-theta) - csc(90-theta)
gekka
o
sub it the other way
these 2 would just cancel each other out
so what would that leave us at?
0?
bingo
This would also achieve 0 wouldn’t it
But it’s just easier with sec
i just think subbing it the other way works better
Ah okay
since it's much less clutter
but either works fine
here are the rest of the cofunction identity
pi/2 is another way of saying 90 degree
Radians?
Thanks
So would Q10 be 10
And Q11 be 68
yes
Because they both add to 90
you literally just change it
and you should easily find x or y
So wouldn’t x be 10
gekka
just use the identity to change that cos to sin
But 10 degrees is needed for sin80 to be equal to 90
and the answer should be obvious from there
you use the identity
$\sin(90^{\circ}-\theta)=\cos\theta$
to change from sin to cos
gekka
so it would be