help-0

[last ether]

So you know the answer to (a)

[alpine sable]

It’s just literally 1?

Ok what about b

[last ether]

https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:quadratics-multiplying-factoring/x2f8bb11595b61c86:factor-quadratics-intro/v/factoring-quadratic-expressions

I could go through the entire steps and algebra but I think a video would be better

[alpine sable]

Thanks

Could you dm me a bunch off videos that are about topics in gcses

[last ether]

You can literally google them

[alpine sable]

What do I google

[torn elk]

Robb, you can do that in a funny way, doing this

You then add the numbers and do the difference of squares

[alpine sable]

Why have you done 5 over 2

[torn elk]

so you have the x^2-5x+25/4

but because you don't have 25/4 in the first place, you substract it to make it equal

so you get this, and the rest is easy

[twilit ferry]

list down ur topics one by one in google, and search for tutorials? khan academy is very trustworthy, so u can just add khan academy at the end of every search to get their videos

[alpine sable]

And apparently there’s some website that predicts papers that is very reliable

[twilit ferry]

nope

[alpine sable]

I still don’t get it

[twilit ferry]

absolutely not

dont get into those stuffs

[torn elk]

maybe you see it clearly from here

a^2-b^2 = (a+b)(a-b)

[wary stream]

This is honestly just slightly overcomplicating it

[twilit ferry]

these r simple concepts, go thru a few videos, ask around help if ur still stuck on problems, get ur concepts clear

[torn elk]

how is this complicating it? i think it's the most natural way to do

any kind of factoring

[alpine sable]

I’ll watch the videos dld maybe I’ll get it in voice explanation

[last ether]

You just think of two numbers whose product is -36 and sum is -5

[wary stream]

Because you don't need to complete the square. The simpliest method is the AC method

[torn elk]

i hate that way

[last ether]

Which isn't real hard

Like I found it almost immediately lmao

[torn elk]

my way you don't have to think any number, you just get them right away

[twilit ferry]

i think simple factorization, i.e x^2-9x+4x-36, is much easier to understand at this level than directly going to squares and stuffs

[alpine sable]

Alr thanks guys

I appreciate it, I’ll dm directly if I get stuck on summin

[last ether]

Close the channel if you're done

[alpine sable]

How?

Forgot

[torn elk]

.close

like that

[alpine sable]

.close

[lone heart]

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[twin hawk]

As i understood in this question, we just take everything from the table
Like a) 233+s

[twin hawk]

And BTW S =5

Or should I gather all the frequency and then divide the number by the sum of the frequency

Then a) = 59/639

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[odd hound]

I'm a bit confused on how to do this, need some guidance!

[wet atlas]

First, can you find the equations of the three lines by looking at the graph

[odd hound]

x=4
y=-2x+12
y=x+3

[wet atlas]

ok, we can also express them as x-4, y+2x-12, and y-x-3, then put x=0, and y=0 and find whether you get a positive number or a negative number for each equation of the line

[odd hound]

how can it be expressed as a "-"?

so (?)
0-4= -4
0+2(0)-12=-12
0-0-3=-3
im kinda confused on that...

[wet atlas]

A line divides the coordinate plane in 2 sections

[odd hound]

hmm..

so by substituting a 0 for the x an y values, that's how i can solve the question?

[wet atlas]

Oh we substituted zero to find which is the -ve and +ve section

[odd hound]

ohh i see

[wet atlas]

Now in this if you look at the green zone, the points in the green zone will be a -ve value for x + 2y -12 and give a +ve value for x-4

We can express it as an inequality,
x + 2y -12 <0
x-4 >0 represents the green zone

Now can you find the inequality the third line, also look at the given graph carefully given in the question

[odd hound]

y<x+3?

i substituted like a random coordinate from the unshaded region into the y=x+3 (but i rearranged it into y-x=3) and got 2, and since 2 is less than 3 from the equation, my guess is that the inequality is y<x+3

<@&286206848099549185>

[wet atlas]

Yes, that is the third inequality,
What are the three inequaties which give the white section in your problem

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[ebon zinc]

hello

[ebon zinc]

may I ask what is the derivative of 4πr^2?

is it 4π(2r)?

[ruby current]

yes

,w derivative 4πr^2

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[ebon zinc]

ohhh

alright, thank you very much

ill close this now, thanks for the help

.close

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[lone heart]

@grizzled garden Has your question been resolved?

[exotic belfry]

first you assumed a well ordered set which is not isomorphic to any ordinal and then you constructed an isomorphism.

[lone heart]

@grizzled garden Has your question been resolved?

[lone heart]

@grizzled garden Has your question been resolved?

[lone heart]

@grizzled garden Has your question been resolved?

[exotic belfry]

Lets start with the part "otherwise let B = A". In this case you create an isomorphism for an ordinal alpha to B which is A, so you have the contradiction.

Now to the other (first) case where you assume that there is an a in A with the (same) property which means a is not isomorphic to any ordinal.or which is the same to say there is an initial segment with the property not being isomorphic to any ordinal. now you set B = a and create an isomorphism to an ordinal alpha. which is again an contradiction. so this assumed a in A cannot exist.

So if you assume there is an a in A you get a contradiction. if you assume there is no such an a in A you get an contradiction for A directly.

no.

BTW: from where are your screenshots? book? lectrure notes? ...

[lone heart]

@grizzled garden Has your question been resolved?

[exotic belfry]

what is A_a and what is a?

but anyway.: the point is: you get a contradiction, so there is no such a

but thats the point of ordinals. A_a = a.

ok, thats right. but as i said before:

[exotic belfry]

this.

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[mild saffron]

Where did I get wrong?

This is about finding potential functions

And that's the answer key in the 2nd pic

God, finding a potential function is so confusing

[tacit arch]

show the full paragraph

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[forest fiber]

!status

[lone heart]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[forest fiber]

1

[chrome salmon]

[remote heron]

do you know what a relation is

[chrome salmon]

equivalence?

[remote heron]

i mean properties like transitivity

i guess thats not gonna help this relation is usually the example used to introduce that stuff

[forest fiber]

not really its been a good while

[chrome salmon]

yeah greater follows the propoerty of transitivity

[remote heron]

but

well you could either look up the properties the relation has

and know what the words mean

or draw a number line

[forest fiber]

A relation cannot be both reflexive and irreflexive. Hence, these two properties are mutually exclusive. If it is reflexive, then it is not irreflexive. If it is irreflexive, then it cannot be reflexive is this a good definition

[remote heron]

👀

did a human write this

[forest fiber]

i just looked up the definition

is it bad?

[tacit arch]

you probably looked up an english one

[remote heron]

just use a number line

[tacit arch]

use a math book

[remote heron]

if a > b

draw a and b in the appropriate positions

add c

[forest fiber]

how do you want me to draw them in a line like this ? a-----b------c?

[remote heron]

just use a number line

[forest fiber]

ima be honest i haven't used a number line in geometry is it as simple as it sounds

[remote heron]

yes

draw a line

then an arrow indicating which way is bigger numbers

which way is more positive which way is more negative

thats it

[remote heron]

no, dont mark any numbers

you dont know what a or b are

[forest fiber]

so just an arrow?

[remote heron]

yea

[remote heron]

😌

draw a>b

[forest fiber]

like this?

[remote heron]

? this is a > b ?

[remote heron]

👀

have you ever used a number line before

here lemme do one of these

[tacit arch]

bigger numbers are on the right like this shows

[remote heron]

this is wasting time

[forest fiber]

not in geometry like in the second grade

[forest fiber]

ok

[remote heron]

here a > b

now, b is bigger than c

so c goes to the left of b

[forest fiber]

ok

[remote heron]

F asks you if this means a > c

[forest fiber]

ok so f?

[remote heron]

yea, im drawing F

[forest fiber]

ok i understand thanks for the help

.close

[lone heart]

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[remote heron]

really?

[forest fiber]

what?

[remote heron]

sorry if i wasnt helpful

im in a weird mood

[forest fiber]

no you good i mean i understand it good now so thanks

[lone heart]

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[grim wagon]

I only need help with question 3. How would I find the time at which I must fire the cannon? In the second image, I tried solving it by dividing the minimum distance by 150cos(45). I'm stuck on how I would consider the speed of the drone and if my approach was correct.

[worldly pier]

The drone speed is given

[lone heart]

@grim wagon Has your question been resolved?

[grim wagon]

<@&286206848099549185>

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@grim wagon Has your question been resolved?

[lone heart]

@grim wagon Has your question been resolved?

[grim delta]

figure out how long it will take the drone to arrive from the detection point to 1000m using the same formula
thats part of the solution but also consider the time it takes the cannonball to reach 1000m from being fired (you already found this value)

obviously you want them to meet each other at the same time at 1000m or so

[grim wagon]

Would I need to consider the height?

[grim delta]

dont think so, its just a straight line, and we dont seem to be considering gravity or anything

nvm maybe you are

but then you need a mass of the cannonball and such

not 100% sure what the angle stuff is all about, since there will only be 1 angle that works if everything just goes in a straight line and assuming the drone has the same origin point

is there more to this problem

[grim wagon]

I dont know if this change much

[grim delta]

that doesnt make any sense lol
gravity is the reason it's parabolic, because it acts on the mass pulling it down towards the earth
ignoring gravity AND air resistance/friction, it would just travel at the initial velocity and initial angle in a straight line forever, or at least until something else exerted a force on it

think the problem is messed up tbh

[grim delta]

but based on the information this is what id do

[grim wagon]

The only response I got from my teacher is that "The speed of the drone is not taken into consideration in question 3." I think the question is less physic base and more on trigonometry.

[daring patrol]

The canon is fixed to 45° right?

[grim wagon]

yes

[daring patrol]

Since it is fixed, it must have a mximum height isnt it?

[grim wagon]

That I'm not sure

[daring patrol]

If you throw a ball at a constant velcoity and angle, will it reach higher?

[grim delta]

cannon is fixed on the ground

[daring patrol]

For the bullet i mean

I dont think mass is required here

Try dropping steel ball and the plastic one

Air resistance neglected

@grim wagon do you know there is 2 velocity involved?

[grim wagon]

The drone is flying at a speed of 50 meters per second, and the cannon has a muzzle velocity of 150 meters per second

[daring patrol]

Velocity is a vector isnt it?

[grim delta]

ye
was just thrown off by the first description, which does seem wrong in the way it was worded (ignore gravity, parabola)
But you are right

[grim delta]

you can break these down into vectors like this
at any instant in time vx and vy will have a value
The drone is supposed to stay constant i think, but you will get a parabola from the cannonball because gravity acts upon the components, i.e. they vary with time

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@grim wagon Has your question been resolved?

[lone heart]

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[restive basin]

I got part i) but no idea how to start ii)

[restive basin]

i) is x=13.9 and x=-0.9

[alpine sable]

,w x^2-13x-13=0.0

[ocean seal]

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[alpine sable]

yes

[restive basin]

how do i figure out ii)

[alpine sable]

find the vertex of the quadratic

[restive basin]

whats a vertex of a quadratic

[alpine sable]

use symmetry to find it

oh wait

is N the natural numbers here?

[restive basin]

yes

n is natural number

[alpine sable]

I misinterpreted the question, sorry

sketch the quadratic using the roots from i

[restive basin]

is sketching the only way?

[alpine sable]

you should see that the quadratic is negative if x<13.9

[alpine sable]

it helps with intuition

[restive basin]

why would x<13.9

how would i know that

[alpine sable]

if you sketch it, you will see that

[restive basin]

i dont?

<@&286206848099549185>

.close

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[slender quiver]

hi

[limpid spade]

hi

[small panther]

hi

[limpid spade]

really?!

[split oriole]

Post question

[limpid spade]

https://tenor.com/view/meryl-streep-booo-gif-13311304

[gray isle]

<@&268886789983436800>

its not 1 + 1 but still...

[limpid spade]

[split oriole]

Let me ask something

In which grade you are studying?

[limpid spade]

clearly a grade not old enough for discord

[gray isle]

bad idea

not a good first impression

[limpid spade]

go make bad jokes in #chill

[gray isle]

trolling is likely to lead towards muting or an outright ban

and aware of your non-seriousness people may not even interact further with you
as anything could potentially be a "joke"

[lone heart]

@blissful lotus Has your question been resolved?

[next brook]

.close

[lone heart]

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[pastel granite]

hello

[pastel granite]

can anyone tell me why this isnt correct or what im doing wrong

[proven leaf]

9=3*3

[pastel granite]

ah yes

ty

[proven leaf]

yw

[pastel granite]

careless mistake

its right now

.close

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[proven leaf]

happens more often than you like unfortunately 😅

[pastel granite]

haha

yes

[lone heart]

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[steady basin]

hi

[steady basin]

need some help on part a plz

rly stuck

[chrome salmon]

What is your thought process

[steady basin]

first i thought to draw a diagram

but im stuck on that as well

[chrome salmon]

Why is that so?

You know it's just an equation of plane

[steady basin]

@chrome salmon idk if this is a correct sketch

[chrome salmon]

It is indeed

[steady basin]

just did the intercepts and joined them together

so

we keep z constant

so the limits are between 0 and c

[chrome salmon]

You can see that the z coordinate varies from z=0 to z= 1 - (x/a) - (y/b) , so these will be the limits of integration for z

[steady basin]

u mean z/c = 1 - (x/a) - (y/b) ?

[chrome salmon]

Yes

Well multiply c on the other side

[steady basin]

ok

btw

what r we keeping constant

z y or x

?

[chrome salmon]

One of the y or x

It's not constant just the limits of integration will be constant there

[steady basin]

lets keep x limits constant

so what will the limits of y be?

[chrome salmon]

Okay

What do we have on the x-y plane?

[steady basin]

a triangle?

[chrome salmon]

You know how to integrate on that?

[steady basin]

lemme try

@chrome salmon got this so far

bit stuck on what the top limit would be for the double integral

for dx

[chrome salmon]

Not right

[steady basin]

ah

[ocean seal]

fäf

[steady basin]

yh

thats what i said

[chrome salmon]

No

[steady basin]

wait

i got my dx dy mixed up

sry mgb

[chrome salmon]

And limits too

[steady basin]

right so how do we find the top limit

for dy

[chrome salmon]

Writing x in terms of y

[steady basin]

from what tho

[chrome salmon]

The equation of line is (x/a) + (y/b)=1

[steady basin]

but then

why have u neglected the z/c

[chrome salmon]

We already did that part

Once we are done with z we only see the figure in x-y base

[steady basin]

ok

lemme have a go now

[chrome salmon]

Lord namington

[lone heart]

@steady basin Has your question been resolved?

[steady basin]

idk if im doing this right

@chrome salmon is there an easier way to do this

feel like i expanded for no reason

[chrome salmon]

No buddie

[steady basin]

pretty sure ive messed up

since i aint getting abc/6

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@steady basin Has your question been resolved?

[lone heart]

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[tame nebula]

the answer 1-2x should be the same as -2x+1 right?

j ust making sure

[quasi vector]

yes

[tame nebula]

great great thanks

.close

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[tall shuttle]

Let F: A contained in R²-> R³ a differentiable function such that dF_p is injective for all p. Prove that for every p in A, there is a neighborhood U of p contained in A such that F restricted to U is injective.

[tall shuttle]

Is there something equivalent to the mean value theorem?

dF_p being injective means that dF_p(w) = 0 implies w = 0

Which means the partial derivatives are linearly independent for all p

But I don't know if any of that is useful

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@tall shuttle Has your question been resolved?

[tall shuttle]

<@&286206848099549185>

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@tall shuttle Has your question been resolved?

[lone heart]

@tall shuttle Has your question been resolved?

[tall shuttle]

<@&286206848099549185>

[proven timber]

I regret having this role

[tall shuttle]

What I have for now:

If F(a,b) = F(b,c) then F_i(a,b) = F_i(c,d) for i=0,1,2.

F_i(a,b) = F_i(c,d) implies F_i(a,b) - F_i(c,d)= 0.

There I should use mean value theorem

[lone heart]

@tall shuttle Has your question been resolved?

[alpine sable]

Lmfao

[lone heart]

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[opal quest]

i am stuck at the whole thing idk what to do or where to start

[opal quest]

<@&286206848099549185>

[plain vortex]

What qn

[opal quest]

what does qn mean

[plain vortex]

Question

[opal quest]

all of it

[plain vortex]

I'll just do the first first

Alright

So

Since they are both tangents

[plain vortex]

U learnt cosine rule yet?

[opal quest]

yea idk what that is i am in the 9th grade and my teacher is giving me sum 10-11th grade stuff

[plain vortex]

Pretty sure u need cosine rule

[opal quest]

this?

[plain vortex]

Yep

U find all angles in triangles TQO

Which is 112/2, 90(tangent property) and 180- the other two

Wait no what

Sorry no that makes no sense

[opal quest]

yea

[plain vortex]

Use sine rule

U can't use cosine

Sine rule is simple

I'll do it here

U know the radius length right

5.5cm

And find all angles

Which is 56, 90 and 34

The one opposite the radius is 34

[opal quest]

alr

[plain vortex]

So 5.5/sin34° = TQ/sin56°

Thus (5.5/sin 34°)sin 56° =TQ

,calc (5.5/sin 34deg)sin 56deg

[opal quest]

thankss for the help

[ocean seal]

The following error occured while calculating:
Error: Unexpected type of argument in function multiplyScalar (expected: number or Complex or BigNumber or Fraction or Unit or string or boolean, actual: function, index: 0)

[plain vortex]

Wtf is wrong with this

[verbal jewel]

how do u find the y intercept since its not at 0,0

[plain vortex]

Buddy

Not here

[verbal jewel]

oh

[wary river]

,calc (5.5/sin 34) * sin(56)

[ocean seal]

The following error occured while calculating:
Error: Unexpected type of argument in function multiplyScalar (expected: number or Complex or BigNumber or Fraction or Unit or string or boolean, actual: function, index: 0)

[wary river]

Ye idk

[plain vortex]

U need deg to signify it's degrees

[wary river]

You tried that it didn't work

[lone heart]

@opal quest Has your question been resolved?

[lone heart]

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[dim stone]

Hi I am having trouble setting the domaine in y for this problem. I found that th edomaine in x is -2>x>7

[lone heart]

Please read #❓how-to-get-help

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[serene junco]

Your multiplication just went wrong somewhere

,calc 2(3.95)(2.52)

[ocean seal]

Result:

19.908

[serene junco]

np 👍

just another way to write it, I guess. Greek letters are common for angles

so I guess they might use $\alpha$, $\beta$, and $\gamma$ instead of A, B, and C

[ocean seal]

tatpoj

[unique trout]

alpha

[lone heart]

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[daring valve]

Absolutely dumbfounded on this PDE question

[daring valve]

This is the q

I’m currently at the 3rd boundary condition

And have no clue what to do

[lone heart]

@daring valve Has your question been resolved?

[tacit arch]

Do you have answers

[lone heart]

@daring valve Has your question been resolved?

[lone heart]

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[craggy token]

Can anyone tell me how the sum can be transformed like that?

[tacit arch]

Maybe try proving the sum from i=2 to j of i choose 2 = j+1 choose 3 with induction

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@craggy token Has your question been resolved?

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[alpine sable]

i need some help with probability

[alpine sable]

im about to gamble

is one chance at 30% or 3 chances at 10% better?

or are they the same

or one at 20% and the other at 10%

[naive valley]

one way to solve this is as follows:

work out the probability of failure in both cases

if you have one chance at 30%, what's the probability that you fail?

[alpine sable]

70%

[naive valley]

yep

and if you have three chances at 10%, what's the probability that you fail?

[alpine sable]

im not sure

[naive valley]

what's the probability that you fail on the first attempt

[alpine sable]

90

[naive valley]

and same on the second and third right?

[alpine sable]

i guess so

but 3 chances doesnt make it more likely?

[naive valley]

yes i'm doing this a step at a time

[alpine sable]

ok ok

[naive valley]

each of the three attempts, you have 90% chance of failing

so:

what's the probability that you fail on all 3 attempts

(assuming the attempts are independent)

[alpine sable]

they are yes

im not really sure on probability tbh

it cant be 90%

[naive valley]

when you want the probability of (A and B) where A and B are independent

you multiply their probabilities:

P(A and B) = P(A)P(B)

[alpine sable]

86.66...%?

[naive valley]

so if you have A,B,C each with probability 90%

what's the P(A and B and C)?

[alpine sable]

10% for the good outcome

so just 10%^3?

[naive valley]

A,B,C represent failure on attempts 1,2,3

[alpine sable]

90%^3?

[naive valley]

we want the probability that all three failures occur

yes!

aka 0.9^3

and that works out to what?

[alpine sable]

72.9

[naive valley]

yep

[alpine sable]

oh thats cool

[naive valley]

so what's the probability that you don't fail

for that case

[alpine sable]

100-72.9=27.1

[naive valley]

yep

so looks like the first situation is better

1 attempt at 30%

[alpine sable]

so then for 1 chance 20%, and 1 chance at 10%

72%

so 1 attempt is better overall

for 30%

[naive valley]

for 30% yes

[alpine sable]

doing a $45 tradeup here

so 1 chance will be my best luck lmao

[naive valley]

ha, always good to apply probability to real life situations!

[alpine sable]

100%

thank you

[naive valley]

gl with the win

[alpine sable]

have a good one

[alpine sable]

ty ty

[naive valley]

cheers

[alpine sable]

.close

[lone heart]

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[alpine sable]

hi

[alpine sable]

i started

so

what i have so far is that

each line with a || is equal to x

for the shaded area

I have

x^2pi - 9pi

after that idk what to do at all

[chrome salmon]

i see

[alpine sable]

do u know what to do

[chrome salmon]

I'm thinking

[alpine sable]

ok

hi

uhm

[swift shore]

I know

[alpine sable]

u do?

[swift shore]

Draw lines from the center of the small circle to the centers of the other circles

What do u see?

[alpine sable]

an isosceles triange

[chrome salmon]

yes

[alpine sable]

what tgen

[chrome salmon]

idk how to go from there

[alpine sable]

same

<@&286206848099549185>

what from here

looks around a lil bit

[raven rover]

What if you treat just say the radius of the larger circles is x and proceed through the problem anyway?

[alpine sable]

What do you mean?

[raven rover]

Like okay, your larger circle side length is x, instead of some known number like 5

What if you go through the problem anyway?

[alpine sable]

As of now

[raven rover]

I mean you get an isosceles triangle

[alpine sable]

The radius of the larger circle is 2x.

[raven rover]

Does that mean anything? Idk

[raven rover]

Largest yes

OH yup

the large semicircle has radius 2x

And the larger circle inside radius x

[alpine sable]

As of now

With X how it is, the radius of the small semi circles

I have the equation

X^2pi - 9pi

[raven rover]

And what does that represent?

The area of the shaded region?

[alpine sable]

X is the length of each line with the || .

Yes, the area of the shaded region.

[raven rover]

I see 👍

Hmmm

[alpine sable]

I have an isosceles triangle

[raven rover]

Tbh I'm not sure

[alpine sable]

I think I need to find X.

[raven rover]

Ye

[alpine sable]

I could do this

I'd have

6+y=2x

And

X^2 + (3+y)^2 = (3+x)^2

y = 2x-6

GOT IT

omg thank u

even tho u didnt do much

you're a life saver.

.close

[lone heart]

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[raven rover]

Oh nice! What did you end up doing?

[lone heart]

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[stable merlin]

I see many articles on how to find the confidence intervals for a sample, but how do I find the confidence level when given sufficient information?

[stable merlin]

I would assume the output would be a percentage, such as 70%.

Here's an example problem

[lone heart]

@stable merlin Has your question been resolved?

[lone heart]

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[half moat]

I need help understanding joint and marginal frequencies

[half moat]

Using a two way table

<@&286206848099549185>

[lone heart]

@half moat Has your question been resolved?

[half moat]

?

no?

ill just use ai or something

.close

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[orchid shard]

Help

[orchid shard]

,rccw

[pliant cedar]

well do u know about operator precedence

[orchid shard]

Yes

[pliant cedar]

okay so what does the first one evaluate to

[orchid shard]

13

[pliant cedar]

how

[orchid shard]

Wait

11 right?

[pliant cedar]

theres a -4

which operation do u do first

[orchid shard]

Multiply

[pliant cedar]

what two numbers did u multiply

[orchid shard]

-4 . 3

[pliant cedar]

what does that equal to

-4 multiplied by 3

[orchid shard]

-12

[pliant cedar]

yes

what do u do next

[orchid shard]

Add 1?

[pliant cedar]

yes and what does that give u

keep doing the rest like that and pick the one that gets u -13

[orchid shard]

kk

I attempted all of them alr but only 1 gives -13

Unless I did the math wrong

[pliant cedar]

which one gives -13

[orchid shard]

The last 1

[pliant cedar]

okay that is correct

what did the 4th one give u

[orchid shard]

Uh

13

[pliant cedar]

yes

3rd one?

[orchid shard]

13??

-13?

[pliant cedar]

yes

[orchid shard]

Finalllyy

So my math was wrong

Ty

.close

[lone heart]

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[orchid shard]

Help

[vale wigeon]

what's troubling you?

[orchid shard]

Starting the problem off

[vale wigeon]

do you know in general what it means to sort a list of numbers from least to greatest

[orchid shard]

Yes

[vale wigeon]

explain in your own words what it means

[orchid shard]

Least to greatest means the smallest number going up to the biggest number

[vale wigeon]

ok

what number is the smallest among the five that you're given here?

[orchid shard]

1.35 I think

[plain vortex]

There's negatives

Which means that much less than 0

So I don't think it's 1.35

[vale wigeon]

1.35 is not even present

there is -1.35

but those two numbers are not the same

[plain vortex]

Yeah

[vale wigeon]

@orchid shard do you understand that all negative numbers are smaller than all positive numbers

[plain vortex]

I think u should let him know that -x is 0-x

I'm gonna go find someone else, you probably got this covered

[orchid shard]

Yes

[vale wigeon]

ok

so this should at least let you narrow down the sorting to two sub-lists

{-3 1/4, -16/5, -1.35} and {4, 25/4}

do you understand how to proceed from here?

[orchid shard]

Yes

[vale wigeon]

ok

[orchid shard]

.clozw

.close

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[grand mountain]

"The graph of 𝑦 = 𝑥 & is compressed vertically by a factor of 3" as a number, how would i write this to make my transformation?

[grand mountain]

compressed vertically = 0 < a < 1

<@&286206848099549185>

[surreal meadow]

can you post your question

[grand mountain]

"The graph of 𝑦 = 𝑥 & is compressed vertically by a factor of 3" as a number, how would i write this to make my transformation?

[surreal meadow]

i don’t understand it as you’ve written it

[grand mountain]

oh

[surreal meadow]

i mean like a picture of it

[grand mountain]

yeah sorry

ignore the red sorry

[true sand]

Compressing is just multiplying a function by a value <1

[grand mountain]

if its compressed vertically it means that its lower than one but greater than zero

so how would i write the number if its '3'

because that's greater than 1 and zero

would it be a fraction?

[surreal meadow]

1/3

[grand mountain]

okay i see

thank you

also

one more question

if i get a question where it asks me to convert the equation to vertex form

and its something like

y=-0.25x^2+12

[surreal meadow]

complete the square

[true sand]

Complete the square

[surreal meadow]

this is already in vertex form

[grand mountain]

how would i write it in actual vertex form

[surreal meadow]

,w vertex form

[grand mountain]

like y=a(x-h)+k

[surreal meadow]

yeah

[grand mountain]

would it be

[surreal meadow]

y = a(x-k)^2 + h

[grand mountain]

y=-0.25(x+0)^2+12

[surreal meadow]

it’s fine as it was

no need to put + 0

[grand mountain]

yeah but its

awkward

to interpret the vertex from that

yknow

[surreal meadow]

not really

it’s weirder to write “+0”

[grand mountain]

okay regardless though

how do i write that in full vertex form

[surreal meadow]

it already was in vertex form

[grand mountain]

do i just put the coefficient of x^2 outside of the brackets

[surreal meadow]

$y = 0.25x^2 + 12$ is in vertex form

[ocean seal]

maximo

[grand mountain]

i understand its in vertex form

but i want to write it as

y=a(x-h)+k

not just

[surreal meadow]

then write it like this

[grand mountain]

y=0.25x^2+12

[grand mountain]

okay yea thats what i was wondering

thanks

[surreal meadow]

but

[surreal meadow]

to answer this

the other form is already “full” vertex form

adding the +0 is unnecessary

[grand mountain]

i just personally like being able to see the vertex

[surreal meadow]

and some teachers may mark it as not simplified

[grand mountain]

yeah fair enough

so if i ever see an equation where its just

y=(number)x^2+(number)

it's really just

the coefficient of x^2 that goes outside of the brackets

so like y=5x^2+4 would really be y=5(x+0)+4

@surreal meadow

[surreal meadow]

sure

[grand mountain]

/close

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[alpine sable]

im not sure how to get the 1920 on b

pls help :(

[chrome salmon]

The last sum

The first sum

[alpine sable]

?

[chrome salmon]

Term*

What is area of a triangle?

[alpine sable]

what are u talking about

[chrome salmon]

Area of a triangle

For total distance we need the area under graph

The shape has been divided into some basic shapes

So what I'm asking is if you know the area of triangle formula

[alpine sable]

ah

okok thx

[chrome salmon]

Do you?

I found that I have skill issues in my diagnosis

[alpine sable]

.close

[lone heart]

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[raw jetty]

what would be y? i calculated it to be 191 but its not possible as there is a 3y+18 and it is bigger than 360

[raw jetty]

wait nvm im dumb

.close

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[heady finch]

How do I proceed with the 6th question

[heady finch]

I know d=an - an-1

[vale wigeon]

,rccw

[heady finch]

How I can use it in the question though I do not know

If I should at all

[patent terrace]

Multiply and divide each term in the lhs with d. And then proceed to take 1/d as a common factor from all the terms.

You'll be left with 1/d [ d/a1a2 + ... + d/a(n-1)an]

[patent terrace]

After this step use this to replace each d accordingly and proceed

[heady finch]

How'd you come up with that though

[heady finch]

no I mean how'd you come up with the step that you've to multiply and divide by d

if that makes sense

[lone heart]

@heady finch Has your question been resolved?

[lone heart]

@heady finch Has your question been resolved?

[heady finch]

.close

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[kind yarrow]

can someone please help me understand how i display a column graph

[kind yarrow]

<@&286206848099549185>

[lone heart]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[kind yarrow]

ok

<@&286206848099549185>

[chilly trail]

Just do the sum of the tomatoes

5+6+7+8+9+10

The column..

I think I don't understand either

Sorry

[kind yarrow]

all good thanks for trying

[chilly trail]

👍🏻

[kind yarrow]

<@&286206848099549185> \

.close

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[chilly trail]

<@&286206848099549185>

[chilly trail]

I need help calculating a 33cl C volume on volume alcohol concentration

alcohol is 1,2 cl

I need the %

Thanks

Wait.

56% is more than half

And

1,2 cl is a lot less than that

It's 1,2 divided by 33 then times 100

If I'm right

I got the answer

Thanks anyway

.close

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[carmine crypt]

can someoen help me recheck this

[carmine crypt]

also this

[lone heart]

@carmine crypt Has your question been resolved?

[carmine crypt]

nvm

.close

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[flat lantern]

how do i do this?

[alpine sable]

think about the structure of the given matrices

[flat lantern]

A is symmetric..? but B is not

[alpine sable]

what is the complex analogue to a symmetric matrix?

[flat lantern]

hermitian matrices?

[alpine sable]

yup

B is hermitian

[flat lantern]

yea

ohh

but i thought only real symmetric matrices are diagonalisable?

[alpine sable]

hermitian matrices are also diagonalisable

https://en.wikipedia.org/wiki/Hermitian_matrix#Diagonalizable

[flat lantern]

o ok i see

thanks for the help!

[alpine sable]

yw

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[rocky pendant]

hi i need some help with rational inequality stuff, i wasn't really on the subject because i was sick but i understand some things,
i got
x+2/x+6 < 0
now i know i should do
(x+2)(x+6)<0
and then i get x=-2 and x=-6 but i have no idea what comes after it

[subtle birch]

how did you turn division into multiplication?

[rocky pendant]

oh i did

x+2/x+6<0 * (x+6)^2

[subtle birch]

no

[rocky pendant]

and then

[subtle birch]

don't do that

[rocky pendant]

why

[subtle birch]

Because multiplying by a negative value can change the inequailty

example 5>-1
but 5(-1)<(-1)(-1)

[mortal trellis]

do you mean (x+2)/(x+6)<0? if yes, then please write it like that

[rocky pendant]

idk its typed like that in my book so its just x+2/x+6

[mortal trellis]

(x+6)^2 is positive so there is no problem with that

[rocky pendant]

theres no ()

[mortal trellis]

is it actually typed like that or is it a fraction

[rocky pendant]

lemme send it rq

[subtle birch]

Works here but doesn't work always

[vale wigeon]

is it $\frac{x+2}{x+6}$ or $x + \frac{2}{x} + 6$

[ocean seal]

Ann

[rocky pendant]

the first one

[vale wigeon]

yeah that's written in plaintext as (x+2)/(x+6)

the fraction bar carries with it invisible parentheses around the entire num and the entire denom

[subtle birch]

There should be an inequality sign here

[rocky pendant]

oh yeah

sorry bout that

[mortal trellis]

actually no, its a good idea to find where it equals 0. cause then you know the places where it could switch from positive to negative or vice versa

and then you can eg build a sign table to find out which one it is in the relevant intervals

[subtle birch]

Wavy curve?

[rocky pendant]

in my other thing i saw smth liek this but idfk how to do that lol

(the curve is random)

[subtle birch]

Yes that is wavy curve

[mortal trellis]

the point is that between -6 and -2 it can either be entirely above the x-axis or entirely below

but it cannot switch between those two points

[rocky pendant]

yeah and idk how do i know when its below or above

[mortal trellis]

so you can plug in one random point (eg x=-3) to find out which one it is

[subtle birch]

Take a value of x larger than marked values (example 0)

if the value of equation (here LHS) after putting that value is +ve then graph is drawn from above the number line

And if the value is -ve then draw from below

After intersecting one point you either go up or down. Now curve the line again to intersect the next point

Like this until all points are covered

[rocky pendant]

damn long english words

lemme translate that

idk

but i think it goes like this

[subtle birch]

yes

[mortal trellis]

well the new function you obtained, yes.

not the original function tho

[rocky pendant]

so it'll just be xe(-6;-2>

i have worse than that to go i have no idea how i will do them lmao

anyway thanks

.close

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[shut pelican]

how did they conclude in the third paragraph that the mean would be 16 if every month has 31 days?

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@shut pelican Has your question been resolved?

[slate roost]

Well if you had 31 days is 15 days, then 1,then 15 days. You are as likely to end up on the 15 lower than on the 15 upper, your mean is 16

An other way to see it is if your on the 16th day, there is the same amount of day behind and in front of you in the month, 15

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[shut pelican]

but how is that a valid way of finding the mean? isn't that how you find a median instead?

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[dim oxide]

How do I solve part a and b

vertical motion confuses me so much

[wet atlas]

Show your working

!status

[lone heart]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[dim oxide]

Don’t know where to begin

I only have a diagram

[acoustic beacon]

Well, think about it. For part a) you just have to calculate the distance when it's speed is 14.7m/s.

[dim oxide]

So I just take my final velocity as 14.7?

[acoustic beacon]

Yeah. Also, chatgpt is fairly good at explaining and solving these types of questions correctly so you can refer that too.

[dim oxide]

Oh didn’t not know that, I’ll check that out

[acoustic beacon]

@dim oxide You can verify your results using this for part a

[dim oxide]

Thanks

[acoustic beacon]

Also for part b, it will help if you made a sketch of the trajectory of the particle.

[dim oxide]

I got a different answer to this

But check the answer it shows 22 meters which is right

[dim oxide]

Yeah I’ve drawn it but I’m not sure really how it’ll come in use

[acoustic beacon]

Can you show how you got that answer?

[acoustic beacon]

The part where the particle's speed is more than 29.4 m/s is the orange part because the initial speed is equal to the final speed at point A.

[dim oxide]

I worded that wrong

I got half the answer some how

[acoustic beacon]

Okay so I double checked my answer and it is right. And you forgot to add the extra height.

[dim oxide]

Wdym by extra height?

[acoustic beacon]

Point A is 19.6 meters above the ground, you calculated for x=0.

[fair lodge]

1236781318+52525515417x5321=?

[acoustic beacon]

Erm, what?

[dim oxide]

I see alr