help-0

[hollow thicket]

so are both answers technically correct?

[queen river]

Maybe your book is wrong

cuz it contract first

or im wrong

let me plot the graph

[hollow thicket]

how do you know if it dilates first or second?

[queen river]

em

like

first change from g(x) to g(4x)

after that g(4x+3)

if +3 go first it will be like

g(x) to g(x+3)

then g(4x+12)

[hollow thicket]

OHHHHHHHHHHHHH

[queen river]

cuz enlargement or contraction will time the whole thing

in the bracket

s

[hollow thicket]

yeah that makes so much sense thanks

[queen river]

let me check the answer first

,w plot (4x)^2 + 8x

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by MochaOhwelp#8034

[queen river]

,w plot (4x + 3)^2 + 2(4x + 3)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by MochaOhwelp#8034

[queen river]

@hollow thicket bruh my bad

[hollow thicket]

wait so wahhhh what happedn

[queen river]

i realized that in this kind of equations add and minus always go first

like you cant just change g(4x) to g(4x-3) by moving rightward by 3

-3 will go first like

g(4x) to g[4(x-3/4)]

forgot a lot about graph of functions

so no matter which one comes first

the graph will still be move rightward by 3/4

My bad my bad

@hollow thicket

,w plot (x+ 3/4)^2 + 2(x+ 3/4)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by MochaOhwelp#8034

[queen river]

,w plot (4x+3)^2 + 2(4x+3)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by MochaOhwelp#8034

[hollow thicket]

oh understandable

[queen river]

great

[hollow thicket]

.close

[lone heart]

Channel closed

Closed by @hollow thicket

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vital whale]

i don't get how the second equation is rewritten

[queen river]

cosx=-cos(x-5pi)

[vital whale]

how was that found?

[queen river]

have you learnt that cos(2pi-x)=cos(x)

anyway

cos(-x)=cos(x)

so cos(x)=cos(x-2pi)

[vital whale]

haven't heard this one

[vital whale]

heard this one though

[queen river]

well

let me draw it

wait before that have you learnt astc

[hollow thicket]

first quandrant all positive

second quadrant sin positive etc

[queen river]

yes

[vital whale]

oh yes i heard

[queen river]

ok good

simply

we let an angle be less than 90degree

and when we use 360degree aka 2pi to minus the angle

The line will be on the 4 quadrant

4th

so that cosx=cos(360-x)

Like this

[vital whale]

okk

makes sense

[queen river]

so as sinx=sin(pi-x)

etc

but 90 and 270 are special case

you learn later

so now we have x

x can be any degree but we just let it be less than 90 degree

[vital whale]

okie

[queen river]

so cos(x-pi) is actually the opposite of cos(2pi-x)

so cosx= -cos(x-pi)

[vital whale]

ahh aoright i understand the logic

[queen river]

great

[vital whale]

since 1 and 4th quadrant is positive for cos 2nd and 3rd are negative

[queen river]

and cos(x-5pi) is actually the same thing as cos(pi-x)

understand?

[vital whale]

understand

[queen river]

great

done

so cosx= -cos(x-5pi)

[vital whale]

wiat so what is with the negative sign in front of cos?

on the right hand?

[queen river]

yes

[queen river]

see this

[vital whale]

so what does the negative sign represent

[vital whale]

that it is in the second or third quadratn?

oh wiat doest the negative sign just represent

a reflection in the y-axis

do if cos was -0.5 for example

-cosx would equal 0.5?

[lone heart]

@vital whale Has your question been resolved?

[queen river]

No

It's like

In the above imagine you can see that

The line is in 2 quadrant

So it will be negative

Only in first and the fourth quadrant will cosx be positive

If still confused dm me

[lone heart]

@vital whale Has your question been resolved?

[queen river]

Of course it is

[lone heart]

@vital whale Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[real cipher]

in 1 number what the question is asking to find?

[lone heart]

@real cipher Has your question been resolved?

[real cipher]

.close

[lone heart]

Channel closed

Closed by @real cipher

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[noble frost]

F(x) = x⁴-x³+x²-x+1
How do I prove that F(x) > 9/16
I was told that I had to use integrals but I dont know how to do it

[molten pivot]

you don't have to integrate

you have to differentiate

[noble frost]

i cant get the roots for F'(x)

so i prob have to use something else

<@&286206848099549185>

[wet atlas]

Ok, find the minima of the function

[noble frost]

I cant

I wouldnt even ask if I could

[lone heart]

@noble frost Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glacial kestrel]

What topic do I need to study if I want to solve such questions.
I ve numbered them so if they are in different topic you can put the number infront of the suggested topic/
THANK IN ADVANCE!!!

[lone heart]

@glacial kestrel Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[low moat]

this is a probability question and I really dont know how to solve it

someone help plss

[random agate]

How do you solve this kind of problems usually?

[low moat]

well

I dont

[wild trail]

[random agate]

Do you know basic probability formula?

[fallen verge]

Well no

[random agate]

No there is a trick in his problem

[low moat]

I wish it was that easy martin

[wild trail]

This is a common counting problem

[heady pollen]

turns out im incapable of reading

[wild trail]

the trick is that since the 3 books always need to be together you can treat it as one single book

[fallen verge]

Well no

[low moat]

hm

[fallen verge]

Actually yeah

Thats one way

[wild trail]

Garlic don't scare me like that

[fallen verge]

Boo 👻

[wild trail]

This is why I don't like garlic bread

[fallen verge]

D:

Alright lets get back to the problem

So the probability of an event is (number of favorable cases)/(number of all cases)

[low moat]

so in this case:

6! (number of math books) x 7! (all the books, but treating the science books as one) x 3! (number of science books)

all divided by 9!

(6! x 7! x 3!)/9!

[modern sedge]

why 6!?

[low moat]

cuz

hm

yeah you do have a point

so 6! isnt needed here?

[wild trail]

we're treating the 3 books as 1 single book right? So there are no longer 6 books

(talking about the favourable cases)

[low moat]

true

so 7! x 3!

divided by

9!?

[fallen verge]

Indeed

[wild trail]

noice

[low moat]

thanks guys

.close

[lone heart]

Channel closed

Closed by @low moat

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[regal lagoon]

I don’t understand how to get the solution set of {3,2} from this

[fallen verge]

Let y=2^x

Then it becomes a quadratic equation in y

[regal lagoon]

what happens to the 2x-1?

Would it just turn into 2x^2 -2x +10?

[wild trail]

expand it using properties of exponentiation

[regal lagoon]

In the 2x-1?

[wild trail]

yep

$a^{(x+y)} = a^x \cdot a^y$

[ocean seal]

numbpy

[regal lagoon]

Would that not result in 2x^2 -2x+10?

[wild trail]

are you saying $2^{(2x - 1)} = 2x^2 - 2x + 10$

[ocean seal]

numbpy

[regal lagoon]

No just the 2^(2x-1) would equal 2x^2

[wild trail]

how are you bringing the x down?

you're not allowed to do that

[regal lagoon]

Through the y=x^2

So I guess I really mean 2^(2x-1) = 2y^2

[wild trail]

okay but then what happens to the -1 in the power?

[regal lagoon]

Doesn’t a -1 exponent not valid

[wild trail]

wdym not valid?

if you have 2^(3-1) is it invalid?

[wild trail]

use this property

[dawn lotus]

hi I have a question about trig functions

Im not sure about the one at 30.8s

[lone heart]

Please read #❓how-to-get-help

[wild trail]

get a different channel @dawn lotus

[dawn lotus]

ok

mb

[wild trail]

nw

did you understand @regal lagoon

[lone heart]

@regal lagoon Has your question been resolved?

[regal lagoon]

So it would be 2^2x -2^-1

But what does that do afterwards

[lone heart]

@regal lagoon Has your question been resolved?

[alpine sable]

do you know what exponent -1 is

its dividing instead of multiplying

2^-1 is 1/2

[lone heart]

@regal lagoon Has your question been resolved?

[ocean hawk]

<@&268886789983436800>

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sharp ember]

.open

Hey so like I'm a fresher and currently pursuing my bachelors in computer science and to be honest I want to improve my calculus and don't know where to start, it would be helpful if someone could guide me through like a roadmap or some, Thank you.

[rain mauve]

I would watch essence of calculus by 3Blue1Brown

[sharp ember]

any books for reference ?

[alpine sable]

#books-old
#books

[sharp ember]

So like I want to be able to finish my bachelors with no problems and also that will help me when I pursue higher degree

uhhhh no but like just passed because of other topics also existing other than calculus

also calculus that would be helpful or needed since I will be studying Artificial Intelligence and Machine Learning now

[ocean hawk]

all of standard calculus will be important for that

well, calc 1 & 2

[sharp ember]

but like you know classes wont clear the topic clearly , so like on my summer break I want to hone my calculus skills so I can easily go through mathematics for the rest of the college

[sharp ember]

alright

okay okay thank you good sire

.close

[lone heart]

Channel closed

Closed by @sharp ember

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quasi trail]

How is the degrees of freedom (3-1)(2-1) when it should be (4-1)(2-1) right ?

[quasi trail]

How is the degrees of freedom (3-1)(2-1) when it should be (4-1)(2-1) right ?

[lone heart]

@quasi trail Has your question been resolved?

[lone heart]

@quasi trail Has your question been resolved?

[ocean hawk]

hmm. I think it should be. where did you see this?

[quasi trail]

It's an AQA paper 2 AS Further Maths June 2018

[ocean hawk]

I don't know what "AQA" or "AS" stand for

[quasi trail]

AQA is an examboard

AS is first year of the further maths, there is the two years for further maths

[quasi trail]

(It's just a reference for what paper this was from)

[ocean hawk]

oh. since you say "maths" does that mean "paper" = "exam"? anyway, it should be (4 - 1)(2 - 1)

[quasi trail]

Yes the paper is an exam and thank you for your help 👍

[lone heart]

@quasi trail Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[peak canopy]

Currently stuck on part iv

Here’s the coordinates I got for part ii

The area of triangles OAC and OAB are just (sinα)/2 and (sinβ)/2

Here’s a really messy sketch from part i

Also I can’t use any trigo formulas (like sum-to-product) to do this since it’s supposed to be a very beginner question

[lone heart]

@peak canopy Has your question been resolved?

[peak canopy]

Nop

<@&286206848099549185>

[lone heart]

@peak canopy Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

For the question 39b?

the answer is given in rad/s

but how do yk its in rad/s

couldnt it be in degrees/s

[wary stream]

Most of the time, trig functions are defaulted in radians

[alpine sable]

so when i do the calculations on related rates i assume that trig functions will always be measured in radians

and so if its a function of time it will always be rad/s?

[wary stream]

Unless it states that it's in degrees

[alpine sable]

ah i c

so if like dtheta/dt is given in degrees/s

could u convert the dtheta/dt to rad/s if its given in degrees/s?

its just simple unit cancellation right

[wary stream]

You could but it's best to keep it in whatever units it originally gave. Meaning that if it's in radians, leave the answer in radians and don't covert to degrees

[alpine sable]

mhm ok ill keep that in mind

thx

.close

[lone heart]

Channel closed

Closed by @carmine basin

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[young canopy]

for the slope in the solution picture that says .01Q is that just rounded from the question that states .005Q

[young canopy]

or is it deeper than that and i missed it

[lone heart]

@young canopy Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stable merlin]

Could someone explain Z Scores and how/why they're used?

[stable merlin]

Like what it represents and stuff

[whole shell]

its a good way of normalising your welll normall distribution

to a common standard

[sour dove]

It has two uses:
(a) it allows us to calculate the probability of a score occurring within our normal distribution
(b) it enables us to compare two scores that are from different normal distributions.

it's hard to compare two distributions with such wildly yielding variances, etc

it's a way to make all distributions on an even playing field for comparison

[stable merlin]

For (a) what is meant by a "score"

[whole shell]

if you are measuring height

and you find some people who are like 6'2

you would convert that into a Z score

and so you could have a number that

other people would be able to know

how rare it was

that you found those heights

[stable merlin]

ok

so im reading through my study material thing

(thanks btw)

but i dont understand the solution

to an example problem

question

solution

where did the 35% come from

@whole shell wouldn't it be 20% above and below the mean?

[whole shell]

thats wierd

should be

30%

above and below the mean

so your both wrong

lol

wait

[stable merlin]

isn't it middle 40% tho

[whole shell]

no no

im stupid

i was thinking

30% from the ends

and said the middle

[stable merlin]

yeah i had that thought too

so the rest of the solution would be correct right?

[ocean hawk]

yes, they say from .3 to .7 so I assume they did it right

[stable merlin]

statistics is so fun

[whole shell]

honestly, Z score is for the plebs who dont use calculators

most calculators can do inverse normal distribution

[stable merlin]

idk what that is sooo

im just in algebra 2

[whole shell]

inverse normal distribution

just

reverses it

so you give it your SD and mean

and the area

from the end

and itll give you the value

[stable merlin]

normal distribution is just a type of data right

one that's symmetrical

so you wouldn't use it for skewed ones

[whole shell]

yh

https://onlinestatbook.com/2/calculators/inverse_normal_dist.html

[stable merlin]

dats cool

which courses should i take online

[whole shell]

cant help you out there, not an american so dont really know how ap and stuff works

[stable merlin]

aw alr

thanks a lot for the help tho

now i shall take quiz

.close

[lone heart]

Channel closed

Closed by @stable merlin

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wheat isle]

Is there an easy way to solve optimisation problems

[wheat isle]

coming up with the function for the problem is just really confusing

[last spire]

huh?

[wheat isle]

for example

Those fence questions where you have a certain amount of fencing and you need to find what’s the most amount of area you can cover with it

[vernal thunder]

Those ones where you have to differentiate and set it equal to 0?

And then do that sign test?

[wheat isle]

Well I think there’s multiple ways you can do it

I’ll try find an example

[vernal thunder]

That’s my way of doing it

There’s also graphing calculator, but I assume that’s off the table

[wheat isle]

Here’s one, it’s not the fence type question though

[vernal thunder]

Do you know the perimeter equation

[wheat isle]

The perimeter question?

[vernal thunder]

It says find the max perimeter

So the perimeter equation must be involved

Well not the max perimeter

But the max dimensions

In this case Q and R must touch the graph above

I haven’t done these in a while. Bear with me

[wheat isle]

Oh

I misread my bad

[vernal thunder]

Dimensions that give the max perimeter

[wheat isle]

Finding the equation of stuff like this is the hardest part for me

[vernal thunder]

So you know the rest

[wheat isle]

Well not necessarily

Just I struggle the most with finding the equation

[wheat isle]

You mean Q and P?

[vernal thunder]

My bad

Holdup

I only managed to solve this when it asks for maximum area

I got it

So the perimeter of this rectangle is:
P=2x+2y

And you substitute the equation for v into y

Assuming v=y

[wheat isle]

How did you get this?

[vernal thunder]

It’s the perimeter…

Do you not know the formula?

[wheat isle]

What formula?

[vernal thunder]

I gave you the perimeter formula. What part don’t you understand?

[wheat isle]

How did you get those numbers 2x and 2y

[vernal thunder]

A rectangle has a length of x and a width of y

[wheat isle]

Yes

oh

eight

Right*

That makes sense

[vernal thunder]

Now you see how I got the formula

[wheat isle]

Yes

[vernal thunder]

Also, assume v=y and substitute that equation in for the y part in the perimeter formula

[wheat isle]

What does v refer to?

[vernal thunder]

It’s a dummy variable

[wheat isle]

oh alright

[vernal thunder]

Do you know what to do next

[wheat isle]

So P=2x + 2v??

[vernal thunder]

Yes

And I assume you can substitute

[wheat isle]

Yeah

So are we trying to isolate a variable?

[vernal thunder]

What did you get after substitution

Ok. Since we have the perimeter equation, we need to find the maximum perimeter

How can we find the maximum perimeter

[wheat isle]

Wait I’m not sure what you mean. V=y so P=2x+2v but what did you want me to do with the y. You mean to plug it back into original eq?

[vernal thunder]

You now have v

So use the given v=-x^2 +6 and substitute

@wheat isle

[lone heart]

@wheat isle Has your question been resolved?

[alpine sable]

Hey

Can someone help?

I need help, on this one question. I can't figure it out.

[tacit arch]

!help

[lone heart]

Please read #❓how-to-get-help

[alpine sable]

!help

[lone heart]

Please read #❓how-to-get-help

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[safe zenith]

ik the first one is wrong

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[whole shell]

whats your issue

[safe zenith]

everything.. idk how to do ts😭 n it’s 2 weeks late so literally anything will help as long as it’s done fr

[whole shell]

@safe zenith question 1

i would assume

you only use pencil

and its your tutor

who did the pen markings

[safe zenith]

it was already like that. my teacher printed it out like that

but ik the first ones wrong anyways

[whole shell]

@safe zenith ok

so for the first one

you are splitting 360

into how much parts

[safe zenith]

i put 5 originally but someone said to do 6..

[whole shell]

well obviously

but why do you think

someone would say that

how much of those triangle pieces do you think there are

not the one thats shaded in, but the overall one

[safe zenith]

six

[whole shell]

so why would you answer 5

[safe zenith]

cause someone else told me to put 5 lmao

[whole shell]

you gonna use someone elses advice without thinking about it beforehand?

its a shape with 6 sides, you didnt think something was off when someone tells you to split it into 5

[safe zenith]

yeah i mean i shouldn’t have but this is 2 weeks late like i said n i just wanna get it done atp

[violet flare]

failed a test in second grade from that, always a good idea to check

[whole shell]

@safe zenith anyway

since its split into 6 parts

what is the overall angle

[safe zenith]

idk…?

[whole shell]

360

divided

by

6

[safe zenith]

60

[whole shell]

ok now

what is 60 divided by 2

[safe zenith]

30

[whole shell]

now

find the distance a

which you actually did get right the first time around

[safe zenith]

ok

so is it

[whole shell]

but your pperimeter

is wrong

6 sides, not 5

so 10*6

[safe zenith]

right

okay

so are 2 n 3 like that as well?

cuz if so then i think i can do those on my own

[whole shell]

and 4 honestly

but

4 wants you to use a different method

[safe zenith]

how tf i do 4 n 5😭

[whole shell]

i think

yh

they want you to find the area of the pentagon

but from a different method

instead of

0.5 * apothem * perimeter

they want you to do

5 * the area of that triangle

[safe zenith]

okay? i guess i understand

[whole shell]

wait

wait

show me

the full picture

@safe zenith

[safe zenith]

send the picture again?

[whole shell]

as in, slightly to the left

take another pic

but slightly to the left

[whole shell]

yh there was a .5

this means that

they want you to find the area of that triangle

and times it by 5

thats what the $\times __$ is for

[safe zenith]

wth..

[ocean seal]

doctor99268

[whole shell]

youll learn how to use latex when youre older

[safe zenith]

yea

so..

[whole shell]

have you ever heard of the formula for the area of a trianlge

it is

thats what your q4 is referencing

in your case

a and b

are the same

[safe zenith]

okayy

so a n b is 7?

[whole shell]

yh

[safe zenith]

alr

so c.. would that be 72?

[whole shell]

yes

[safe zenith]

ok

so what do i do w the end?

[whole shell]

we want

to find the area of the pentagon

so how much of the triangles

make up the pentagon

[safe zenith]

five

[whole shell]

so

we times the entire thing by 5

[safe zenith]

okay 👍

1260sin(7) m or 827.80311

[whole shell]

turn

your calculator

off

radians

and put it on degrees

[safe zenith]

okay it’s not letting me put it in correctly or something..

cuz now i’m getting 8820

[whole shell]

also no

wtf

why did you put 7 inside the sin

and 72 outside

other way round

[safe zenith]

i asked if that’s what i was supposed to do n u said yeah

but alr

[whole shell]

i legitemately thought

you misstyped

7

and meant 72

[safe zenith]

LOL

[whole shell]

till i realised that, 1260 is 0.5 * 5 * 7 * 72

should be

0.5* 7 * 7 * sin(72) * 5

[safe zenith]

rt rt

anyways i got 122.5 sin(7) or 31.09336

[whole shell]

switch to degrees

also you wrote 7

[safe zenith]

what😭

imma show u

oh shi u rt

[whole shell]

how about this

instead of 72

use

0.4 * pi @safe zenith

inside the sin

[whole shell]

@safe zenith yh

thats the answer

[safe zenith]

okayy

ok for 5. would it b .5(8)(9)(sin63)?

[whole shell]

yh

[safe zenith]

okay thanks

[lone heart]

@safe zenith Has your question been resolved?

Channel closed

Closed by @safe zenith

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean cliff]

hi can someone help me with this? i have to use log and i kinda dont see what to do with the 5^2-x

[vale wigeon]

well you could rewrite the 3/5^(2-x) as 3 * 5^(x-2)

and that in turn as (3/25) * 5^x

[lean cliff]

wha-

do you think you could write it down somewhere like on paper idk i dont see what you mean exactly

[vale wigeon]

$\frac{3}{5^{2-x}} = 3 \cdot 5^{x-2} = \frac{3}{25} \cdot 5^x$

[ocean seal]

Ann

[vale wigeon]

better?

[lone heart]

@lean cliff Has your question been resolved?

[lean cliff]

hmm okay a bit better but then what do i do after?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ashen obsidian]

help

this may be clearer

[lean cliff]

hmm okay thanks - i'll show you the solution really quickly if thats okay maybe its easier

[ashen obsidian]

sure thanks

[ashen obsidian]

umm

[lean cliff]

i do understand why it says that - but now i struggle to like.. understand what to do next

[ashen obsidian]

soryy but i have no idea what just happened

[lean cliff]

HAHAHAHAH

okay thats completely fine

[ashen obsidian]

should we differentiate or integrate it?

[lean cliff]

idek what that means sorry idk the math language in english...

all ik is that we need to find out what x is

[ashen obsidian]

oh ok

well that is correct that we have to find x

[lean cliff]

yeah and they do log2 + log 3 because its a multiplicaton and in log its +

then minus log5 but bcs it had the ^(2-x) u put it in the front

but ughgushrhgid idk like i cant continue w it yk

[ashen obsidian]

wait are we on the same question?

[ashen obsidian]

i think you are solving for this

[lean cliff]

its the same math question- i understood now what they did in the solution

now im struggling with actually getting to x

[ashen obsidian]

i asked this

[lean cliff]

idk what that is really

thats why i sent the solution

[ashen obsidian]

lmfao ok

[lean cliff]

sorry..

its really weird

[wicked pivot]

Hi

What is 1+1 answer?

[lone heart]

@ashen obsidian Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

pretty dumb question, but why would $dy = f(x + \Delta X) - f(x)$ change into $f(x) + dy \approx f(x + \Delta x)$

[ocean seal]

!Kiz__

[alpine sable]

Another one being, why would $\frac{dy}{dx} = \lim_{\Delta x \to 0} \frac{\Delta y}{\Delta x}$

[ocean seal]

!Kiz__

[alpine sable]

is \Delta y -> 0 supposed to be assumed implicit because of \Delta x -> 0?

[lone heart]

@alpine sable Has your question been resolved?

[vapid shuttle]

add f(x) to both sides

[alpine sable]

yes i'm aware lol but uh why did it change from equal to \approx?

am i overlooking something

[vapid shuttle]

this is a terrible way of writing the limit definition of the derivative

imo

[alpine sable]

Also true, this is both off some random source

https://www.alamo.edu/contentassets/20691fef0c254307b473b980bb6648fb/differentiation/math1325-differentials.pdf

[vapid shuttle]

the most I can say is that it is probably because of the infinitesimals that it is only approximate, but I am prob not the guy for this

[alpine sable]

that makes sense, i just don't see the rationale behind the = changing to \approx though

if both were \approx then it makes sense

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prisma veldt]

hi

[prisma veldt]

i need help with plotting the critical region. i don't understand where the number 1.96 comes from here

[gilded turtle]

I Hope i explain this ok, but basically to find the critical region you need to do inverse normal, your area is 0.025 so the value that gives you that area is your critical region

[lone heart]

@prisma veldt Has your question been resolved?

[prisma veldt]

what is inverse normal?

[prisma veldt]

so i need to find 0.025 in the z-table?

[gilded turtle]

Yes, if your z table goes into negative numbers, if not find 0.975 because of the symmetry of the normal distribution

[prisma veldt]

https://www.math.arizona.edu/~rsims/ma464/standardnormaltable.pdf

this is the table they used

sorry i'm so clueless, for. context i never did stats in highschool

[gilded turtle]

Ah right so yes it goes into negative values so if you look for 0.025 then you should find the critical region

[gilded turtle]

No it’s ok I totally understand stats is actually awful sometimes

[prisma veldt]

in the middle of it or

so i know the alpha is 0.025 right

[prisma veldt]

sorry, cause there's values on the left of the table and then on the top

here?

[gilded turtle]

So this is the table I use, the thing circled is the area/probability and the values with the arrow pointing at them is value that gives that probability

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[prisma veldt]

.reopen

[lone heart]

✅

[gilded turtle]

I’m hoping I’m making sense, sorry if I’m not

[prisma veldt]

hold on, you said to find 0.025, but none of these numbers are anywhere close

it's okay i'm just a little clueless

[chrome salmon]

hopefully

[prisma veldt]

OHHH

OKOK

and then what do you do with the two other numbers?

[gilded turtle]

You just add them and that gives you your critical value

[prisma veldt]

holy crap

it was this easy all along? wtf

[gilded turtle]

But just ignore the - sign when you add them

What type of calculator do you use? (Sorry random question)

[prisma veldt]

scientific calculator

[prisma veldt]

so the critical value is always positive?

[gilded turtle]

No, if it’s on the left hand side of the mean it’ll be negative, but when you add the -1.9 and the 0.06 you ignore the negative just when adding the values

[prisma veldt]

so you just add 1.9 and 0.06?

not -1.9

[gilded turtle]

Yes

[prisma veldt]

oh okay so i got 1.96

[gilded turtle]

Because it’s obviously a two tailed test you work out one critical value and to find the other one just change the sign because it’s symmetrical

[prisma veldt]

alright and then the formula for the z thing gives you the value

[prisma veldt]

OKOK!! GOT IT

[gilded turtle]

Yes, then you see if your test statistic lies within either region to make your conclusion

[prisma veldt]

got it

thank you!

[gilded turtle]

Yay!

No problem

[lone heart]

@prisma veldt Has your question been resolved?

[prisma veldt]

WAIT LAST QUESTION

if it's a one tailed test do you still ignore the negative?

@gilded turtle

[gilded turtle]

It depends, if it’s an upper one tailed test then yes, but if it’s lower then no

[prisma veldt]

got it!

thank you

[lone heart]

Channel closed

Closed by @prisma veldt

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[novel stag]

1102092838828388388(888383838833)

[novel stag]

hi

[hard patio]

...

[vale wigeon]

troll?

[novel stag]

help

calculator doesnt work

[hard patio]

no.

have a good day:)

[novel stag]

ok

you too

cancel

.cancel

.close

[lone heart]

Channel closed

Closed by @novel stag

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wheat sparrow]

above is the question

above is my work ( my answer: -8/225π )

and that is the answer from the professor

I need to know if I'm wrong or the professor made an error

(related rates problem, calc 1)

[lone heart]

@wheat sparrow Has your question been resolved?

[lone heart]

@wheat sparrow Has your question been resolved?

[lone heart]

@wheat sparrow Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[forest fiber]

!status

[lone heart]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[forest fiber]

1

[wintry panther]

What is the formula for the surface area of a sphere

$4 * \pi * r^2$

[ocean seal]

Cain

[wintry panther]

@forest fiber, with this formula find the radius of the plastic ball, multiply the radius by two to get the radius of the sponge ball, and then use this formula again to find the surface area of the sponge ball.

[misty hedge]

oh then equate this formula with 196pie you will get the radius of sphere, lets say 'r'. The radius of spone ball=2r. then use the same formula to find the surface area of sponge ball

[forest fiber]

the radius of the plastic ball is 7 right?

[forest fiber]

the radius of the plastic ball is 7 right?

[wintry panther]

Probably not

oh wait let me check

[forest fiber]

ok

[wintry panther]

yes

It is

[forest fiber]

ok cool so then i do this rigth?

[misty hedge]

yupp

[wintry panther]

Write it in terms of pi

without multiplying by pi

[misty hedge]

yeah as in 22/7

[forest fiber]

how can i do that?

[wintry panther]

Just don't multiply by pi

4* 14^2

[misty hedge]

4*(22/7)1414

[wintry panther]

784 * pi

[forest fiber]

ok i got 884

yeah

[misty hedge]

nice

[forest fiber]

so when do i put pie in the calculator

[wintry panther]

You need the answer in the form x* pi

So you don't need to multiply by pi... You just add the *pi in the end

[forest fiber]

ok thank you

.clsoe

.close

[lone heart]

Channel closed

Closed by @forest fiber

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dapper python]

Is this okay?

[proven leaf]

i can't make out any of the writing anyways... anyway you can write it neater?

[dapper python]

😭

Yeah, give me a bit

@proven leaf

No cap looks the same

[proven leaf]

SO much more legible

[dapper python]

Ty ty x(

But yeah, basically what I do is say that sin(x) < x and 1/tg(x) < 1/x so I get the same without the sin & tg then I just substitute using polar coordinates

And uh yeah, the r in the denom gets cancelled and I'm left with r in nomin and bunch of trash which shouldn't be important when r -> 0

[proven leaf]

that's sounds correct

[dapper python]

Noice, thx

.close

[lone heart]

Channel closed

Closed by @dapper python

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

i need help can someone put me in a chat

[gilded turtle]

What is it you need help with?

[alpine sable]

I need to check my answers

Thisis the question

and thisis my answer

[gilded turtle]

Give me a minute and I’ll check it

[misty hedge]

you forgot to take the 5x dy/dx common which was on the rhs of equation

[misty hedge]

@alpine sable

[alpine sable]

wait so how do i fix it

[misty hedge]

take 5x dy/dx to the left side of equation in the 2nd last step of the 1st image and then take dy/dx common

then in the denominator its going to be 20x3y3+3y/2x3-5x

[misty hedge]

The second image in which you have calculated the things needs to be ommitted since you didnt consider -5x in the denominator

[alpine sable]

how about this

[misty hedge]

did you make corrections in the previous one?

[misty hedge]

seeing

[alpine sable]

ya

[misty hedge]

oh god whyy, you have done everything correctly but just 1 silly blunder

You thanos snapped the existing y from 80x6y

[alpine sable]

lol oops

[misty hedge]

just add those y's in the term and you will be good

[alpine sable]

thanks

appreciate it

[misty hedge]

glad to help ✌️

[lone heart]

@alpine sable Has your question been resolved?

Channel closed

Closed by @hollow flume

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[near cloud]

Why is this wrong?

[mortal trellis]

why did you multiply by a

and even if that were a correct thing to do, you didnt do it correctly

[wind cloak]

I read sqrt(9a) as sqrt(99) and was gonna say something

[mortal trellis]

you dont multiply every single term by a

[near cloud]

Hmm what do I do then to solve the roots

[mortal trellis]

well remember the definition of sqrt

sqrt(a) is the number that when multiplied with itself gives a

so sqrt(a)*sqrt(a)= ?

[near cloud]

a?

[mortal trellis]

yes

[near cloud]

Ohh damn okay, so it’s 12a^3?

[mortal trellis]

alternatively you could also use exponent laws. $\sqrt a \cdot \sqrt a = a^{1/2} \cdot a^{1/2} = a^{1/2+1/2} = a^1 = a$

[ocean seal]

Denascite

[near cloud]

Ohh damn ive never thought of that, that makes it much easier

[mortal trellis]

yes

[near cloud]

Makes putting a into roots in this case useless

Jeez okay sorry for not seeing that myself, guess I was focusing on the wrong thing

Thank you for helping me 🙏

[mortal trellis]

dw about it

its not a bad idea to put stuff into roots

makes some stuff more obvious

eg I see sqrt(9)=3 much quicker than 9^1/2=3

[near cloud]

Yeah well that’s true, but in this case the roots was what confused me

Yeah your right haha that’s true

[mortal trellis]

its good to know both worlds

[near cloud]

Very true, very true

Anyway thanks, have a good one ✌️

.close

[lone heart]

Channel closed

Closed by @near cloud

Use .reopen if this was a mistake.

[mortal trellis]

u2

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sour pilot]

Idk how to do this

[tacit arch]

,tex .log rules

[ocean seal]

riemann

[sour pilot]

Hmm

[tacit arch]

oh it's simpler than that

troll somewhere else

[sour pilot]

is this really simple hmms

[tacit arch]

use the definition of log

yes it is

[sour pilot]

I am in algebra 2

My teacher doesn’t teach he just hands us a packet

[tacit arch]

$\log_a(b) = x$ implies $a^x = b$

[ocean seal]

riemann

[sour pilot]

Ok let me think

Okay i get it now

Thanks

1st one is A

And i think

2nd one is B

Thanks bruc

Bruv

.close

[lone heart]

Channel closed

Closed by @sour pilot

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spiral sparrow]

How would i go about showing this

[tacit arch]

Stirling's formula

[spiral sparrow]

how about without that

[tacit arch]

why without it

[spiral sparrow]

well i wasnt taught that on my course so Im not sure if im allowed to use it. there should be a way to do it without

[tacit arch]

what course are you in

and what lessons have you learned recently

[spiral sparrow]

im on a computer science course

this limit is related to a series question im trying to solve

[tacit arch]

show the original question

[tacit arch]

and all your work up until this point

[spiral sparrow]

tried this

[tacit arch]

root test works better

[spiral sparrow]

ye that was my original method which i think works

[trim cloud]

this one please

[tacit arch]

!help

[lone heart]

Please read #❓how-to-get-help

[tacit arch]

and delete your image

[spiral sparrow]

but i was trying to use ratio test for an alternative method

and ended up getting stuck with that limit

[spiral sparrow]

do you reckon this is valid?

[lone heart]

@spiral sparrow Has your question been resolved?

[lone heart]

@spiral sparrow Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[buoyant pulsar]

can someone guide me through this step by step pls im really confused

[limpid turret]

Look at every two terms

[lone heart]

@buoyant pulsar Has your question been resolved?

[slate jolt]

didnt you already have a post on this?

as i said: separate odd and even terms and you'll have two blatently telescopic sums

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[slow basin]

can someone help me

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[chilly idol]

need to find measure of angle T

[slate jolt]

the sum of angles of a quadrilateral add up to?

[chilly idol]

um i dont know

360

[slate jolt]

yeah

[chilly idol]

ok

[slate jolt]

and also the lines are tangent to the circle

so they form a right angle with the radius

[chilly idol]

ok

[slate jolt]

so consider the quadrilateral CRTS

with C being the center

[chilly idol]

ok

so 360 - 103?

[slate jolt]

dont forget the other angles?

there isnt just one angle

[chilly idol]

theres two more

[slate jolt]

ok so subtract them aswell

[chilly idol]

so 360 - 103 - 90 -90

[slate jolt]

yes

77

[chilly idol]

yes

i got 77

thanks

.close

[lone heart]

Channel closed

Closed by @chilly idol

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[round meteor]

Hi, I forgot how to isolate a divided variable. Can someone show me the steps to isolate $0.8 = \frac{5}{x}$

[ocean seal]

Vulkanoid

[round meteor]

I was trying to use the reciprocal, but forgot how to use it.

[limpid aurora]

you want to multiply both sides by the reciprocal of the fraction

[slate jolt]

or by x on both sides and then divide by 5 on both sides (its the same)

[limpid aurora]

yeah i tend to use this more ^

[round meteor]

like this? $0.8 \frac{x}{5} = \frac{5}{x} \frac{x}{5}$

[ocean seal]

Vulkanoid

[slate jolt]

yeah

[round meteor]

Why do I see that as: $\frac{5x}{x5}$

[slate jolt]

but actually the divide by 5 was useless in this case

[ocean seal]

Vulkanoid

[round meteor]

like == 1

The part that I'm messing up is that I don't understand how the reciprocal cancels the 5 but not the x.

hello?

[limpid aurora]

the x on the top and bottom cancel?

[round meteor]

yeah

[limpid aurora]

but you also multiplied by x on the other side

so like, it still exists

[round meteor]

right. But, I'm trying to isolate the x, not move it to the other side.

[limpid aurora]

well now you have 0.8 * x/5 = 1