#help-0

1 messages · Page 201 of 1

green solstice
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could I please get some help with this

ionic oak
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is there a particular part that you're stuck on?

mortal trellis
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how old are you?

vale wigeon
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@green solstice how old are you?

green solstice
vale wigeon
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as you say.

fallen verge
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13 year old with a 6 year old account...

green solstice
vale wigeon
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well she is 13 now so. nothing unkosher in the present

fallen verge
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aight fair

vale wigeon
green solstice
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yeah I started discord quite young

green solstice
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but if its like 27

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I get confused

vale wigeon
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you're able to do 20 * 6 as 6 * 10 * 2, great

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21 * 6 = 20 * 6 + 1 * 6

green solstice
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and it takes me a long time to figure it out

vale wigeon
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98 * 9 = 90 * 9 + 8 * 9, etc.

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you may have heard of the distributive law.

green solstice
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I havent heard of it

green solstice
vale wigeon
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shame, bc that's what is happening.

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but then again, 21 groups of 6 is the same as 20 groups of 6 plus 1 group of 6 -- you might be able to get this even without it being phrased with the scary word "distributive law"

green solstice
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hm

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I dont really understand what you are saying sorry

vale wigeon
green solstice
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ohhh

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so 21 * 6 you can just do 20 * 6 and then 1 * 6 and then add them together?

vale wigeon
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yes that's what i said

green solstice
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okay yeah I get it now

silk fox
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Anyone know what problem is this

green solstice
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I am kinda dumb

silk fox
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Our prof just write it in the board

vale wigeon
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@silk fox open your own channel

green solstice
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@vale wigeon is there a fast way to figure out two double digit multiplication in your head?

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like 53 x 27 for example

vale wigeon
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two-digit by two-digit?

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meh

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i can't say i've ever needed that much in the way of mental math

green solstice
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oh, well whats the best way you think to approach that question

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mental or on paper

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like in general

vale wigeon
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may wish to learn long multiplication

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that's for doing stuff on paper

green solstice
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is that advanced?

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or difficult I mean

quasi sand
vale wigeon
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"advanced" and "difficult" are both subjective

green solstice
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it would probably be dificult for me but easy for you

quasi sand
vale wigeon
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it's a matter of how much you have had to practice with it i guess

green solstice
quasi sand
fallen verge
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the only method i can suggest is a "factor breakdown" method:
for example if have 28x15, you can break it down into (2x14)x(3x5)
you can rearrange it to be 14x3x2x5 which you can make to be (14x3)x(2x5)
this equals (42)x(10)=420

this does mean you have to know how to divide fast or know the factors of numbers

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this is also unhelpful for prime numbers

green solstice
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thank you

fallen verge
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also abacus math is really cool, if you get super good at it, you look superhuman

green solstice
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how does abacus work

fallen verge
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you learn how to use an abacus, then your muscle memory kicks in and you can do the math with an imaginary abacus

green solstice
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woah

fallen verge
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some people can get some big numbers

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but thats beside the point for now, start small and make your way up

green solstice
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thanks

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I will try it

lone heartBOT
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@green solstice Has your question been resolved?

fast lichen
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but doing mental math for large numbers isnt very useful. learn a method to do it by pen and paper and thats all you need really

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alpine sable
lone heartBOT
alpine sable
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i'm not sure how to even begin with this problem

fast lichen
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figuring out the number of rows and columns for A can be a start

alpine sable
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how?

fast lichen
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first columns. you are multiplying with a 2x1 vector so for matrix multiplication to even be legal how many columns should A have?

alpine sable
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2?

fast lichen
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yes

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and the 'output' is a 3x1 vector

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av+bw is

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so from that you can determine the rows of A

alpine sable
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2?

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im not sure how to determine it

fast lichen
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if A was 2x2 matrix

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2x2 multiplied 2x1 = 2x1

alpine sable
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ye it would be 3 rows right?

alpine sable
fast lichen
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its just matrix multiplication

alpine sable
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oh right nvm

fast lichen
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go through an example

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also i think in general

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a x b multiplied b x c = a x c

alpine sable
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ye

fast lichen
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the b's have to match to be legal

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you can go through giving the elements in the 3x2 matrix variable names and multiplying it with (a b) to solve for the values

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or just revise in your textbook what matrix multiplication looks like

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maybe that will give you an aha moment of what values it should be

alpine sable
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would u create a new matrix to solve the new equations u have?

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and solve it?

fast lichen
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wdym?

alpine sable
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one sec, ill try it out to see if im crazy or if it works

edgy cliff
alpine sable
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thanks for the help

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it just works out

fast lichen
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btw

alpine sable
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ye

fast lichen
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it literally is the definition of matrix multiplication

alpine sable
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ye ive never done it before

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i skippde it

fast lichen
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oh ok

lone heartBOT
#

@alpine sable Has your question been resolved?

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errant dagger
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errant dagger
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How would I do ii?

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this is a practice exam

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@errant dagger Has your question been resolved?

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ionic oak
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For what values of N does $\lim_{x\rightarrow\pi} \frac{d}{dx}(|\sin x |^{\frac{1}{N}x^2})$ exist?

ocean sealBOT
ionic oak
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I took a derivative, graphed it in desmos, and immediately got stuck

lone heartBOT
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@ionic oak Has your question been resolved?

ionic oak
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lol no

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.close

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polar trout
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polar trout
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how is ln n > 1

edgy cliff
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because n>3>e,and ln (e) = 1

polar trout
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ohhhhhhhh

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aight thanks

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.close

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gilded marten
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can anyone help me with this

lone heartBOT
gilded marten
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simple geometry but i cant get no.8

languid bolt
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In a parallelogram, such as this, the diagonals gets divided into 2 equal parts no?

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by that i mean like...

For line DEB
DE = EB

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cmiiw

gilded marten
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yes

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but the problem is, im trying to solve for the exact measurements for up and pl which is ul cut in half by trying to get x and y

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so that means up and pl are of the same length

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x=1, y=2 gives 5 for both up and pl

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but y=7x-3 contradicts it

ionic oak
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there are lots of x and y that satisfy x+2y = 3x+y

gilded marten
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i only got 1,2

ionic oak
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0,0

gilded marten
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true

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but this needs to add up too

ionic oak
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i think you should start by substituting y = 7x - 3 for the lengths of UP and PL

gilded marten
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hmm how though

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ahbhhh

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ok i get it

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i'll try

barren token
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cant we put UP=UL and solve for x or y

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and then sub

gilded marten
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OH WAIT

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up = ul?

barren token
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mb mb

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UP=PL

gilded marten
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ahhh

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ok

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thats what we got, 1,2 and 0,0

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but the other statement said y=7x-3

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i think i got it

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0.6 and 1.2?

ionic oak
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sounds right to me 👍

gilded marten
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ok ty ty\

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.close

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clear juniper
#

"Given the equation (a-2)x-2y-1=0, find for what value of a represents a straight line:
a) parallel to the x axis
b) parallel to the y axis"

lone heartBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
clear juniper
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4

lone heartBOT
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Show your work, and if possible, explain where you are stuck.

clear juniper
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i mean point a) was pretty easy i guess
a-2=0
a=2

b) is what i'm confused on

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-2y=0

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?

mortal flame
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hello

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-3 + 4 = ........... + (-3)

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.reopen

clear juniper
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?

mortal flame
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-3 + 4 = ........... + (-3)

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i want answer

clear juniper
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open your own channel

mortal flame
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how

clear juniper
mortal flame
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then what should i do now then*

ionic oak
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whats the form of the equation for a line thats parallel to the y axis

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its gotta be x = c or something like that right

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the given equation distributes out to ax - 2x - 2y = 1 so i imagine you want to cancel out the y term... is it legal to put a = 2y/x?

clear juniper
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no

ionic oak
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why not

lone heartBOT
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@clear juniper Has your question been resolved?

lone heartBOT
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hallow vessel
lone heartBOT
hallow vessel
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i know that the theorem is

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if a <= b and b <= a, then a = b

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but how do i use

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like what are the steps in a proof for this

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do i just count out the elements

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and say that each one has a correlating value

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0 -> 3

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1 -> 4

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2 -> 5

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therefore mod(a) = mod(b)

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?

lone heartBOT
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@hallow vessel Has your question been resolved?

lone heartBOT
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@hallow vessel Has your question been resolved?

lone heartBOT
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@hallow vessel Has your question been resolved?

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obtuse parrot
#

Hey guys

lone heartBOT
obtuse parrot
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this is a small excerpt from a paper im reading

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so the author takes the inverse Fourier transform of the top equation (equation 10)

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but, the results of which in the next equation dont make sense

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how does taking the fourier transform of u(k, t) somehow transform it into u(k, t+dt)?

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this isnt a typo, because he goes on to take full advantage of it

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and this "transformation" is critical to the paper but never explained

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the final result works, meaning that it is correct, but i cant possibly fathom how

lone heartBOT
#

@obtuse parrot Has your question been resolved?

lone heartBOT
#

@obtuse parrot Has your question been resolved?

tender mirage
#

Out of curiosity, what is k is in this context?

obtuse parrot
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wavenumbers, theyre precaculated in this context

tender mirage
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Ah ok. I can't speak to the nitty-gritty, but the Fourier transform is a subset of Laplace and just converts from the time domain to the frequency domain. τ is actually just a constant (in general, maybe not here) https://en.wikipedia.org/wiki/Time_constant
Also, notice that the function on the left-hand side of the equation, u, has a "hat" in (10) but not in (11) - this denotes the Fourier transform of u, so to find u you just take the inverse. Applying the inverse Fourier to the left-hand side leaves you with just u. Applying it to the right-hand side translates the whole thing from the frequency domain into the time domain, so now you have to introduce time into the equation. I'm not sure why it's delta-time as opposed to just t here. But I think, from a quick google, the inverse of the right-hand side will be a convolution of of the two terms with respect to t.

In physics and engineering, the time constant, usually denoted by the Greek letter τ (tau), is the parameter characterizing the response to a step input of a first-order, linear time-invariant (LTI) system. The time constant is the main characteristic unit of a first-order LTI system.
In the time domain, the usual choice to explore the time resp...

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Keeping in mind I learned the basics of this in a controls class 5 years ago :|

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tender mirage
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wrong place @alpine sable, you gotta take a channel in the available pool

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spare crane
#

trying to calculate further Information gain, already found out odor is the best classifier but now i need to find the next attribute for cases where odor is "okay" and somehow my information gain turns out to be -0.02 which ISNT nonnegative so it cant be the answer. what did i do wrong

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spare crane
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<@&286206848099549185>

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@spare crane Has your question been resolved?

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@spare crane Has your question been resolved?

spare crane
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.close

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icy plank
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if sin(pi/7) = 0.434 what is sin(6pi/7)

lone heartBOT
pseudo ice
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What's pi - pi/7?

icy plank
#

.close

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old mirage
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old mirage
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What're the bounds for this integral problem?

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I messed up and had theta going from 0->2pi and r from 0->pi/2

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But I'm thinking it should be theta from 0->pi and 0->1

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alpine sable
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alpine sable
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am I correct that this cant be solved conventionally?

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you need to use algebra right

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like you can't simply do 3a+b / 3

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you have to let PQ = xa + yb

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then solve it that way

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or is there a shorter way

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alpine sable
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.close

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alpine sable
lone heartBOT
alpine sable
#

can you help me write the equation

olive oar
#

Apply transformations to a standard hyperbola

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alpine sable
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Hello

lone heartBOT
clever nimbus
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hey

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?

versed escarp
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Do you have a question?

lone heartBOT
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primal galleon
#

I'm struggling with the following integral:

$$\int_{-2}^1\left(\frac{1}{x}-3 e^{-x}+\sin (\pi x)\right) d x$$

ocean sealBOT
primal galleon
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We've not been taught integration by parts for this problem. How do I solve it?

fierce prairie
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I would split the 3 terms into 3 integrals and solve each separately

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1/x is just ln|x|

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the other 2 are u-sub

primal galleon
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$$\int_{-2}^1\left(\frac{1}{x}-3 e^{-x}+\sin (\pi x)\right) d x$$

$$=\int_{-2}^1\frac{1}{x}dx - \int_{-2}^1 3 e^{-x} dx + \int_{-2}^1 \sin(\pi x)dx$$

ocean sealBOT
primal galleon
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Like this?

fierce prairie
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Yeah

primal galleon
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To compute the definite integral $\int_{-2}^1\left(\frac{1}{x}-3 e^{-x}+\sin (\pi x)\right) d x$, we can apply linearity and split it into three separate integrals: $\int \sin (\pi x) d x-3 \int e ^{-x} d x+\int \frac{1}{x} d x$.
\\
The first integral can be solved by substituting $u=\pi x$ and using the standard integral $\int \sin (u) d u=-\cos (u)$, which gives us $-\frac{\cos (\pi x)}{\pi}$.
\\
The second integral can be solved by substituting $u=-x$ and using the exponential rule $\int a ^u d u= \frac{ a ^u}{\ln ( a )}$, with $a = e$, which gives us $- e ^{-x}$.
\\
The third integral is a standard integral, which gives us $\ln (x)$.
\\
Plugging these solved integrals back in, we get $\int_{-2}^1\left(\frac{1}{x}-3 e^{-x}+\sin (\pi x)\right) d x=\boxed{-\frac{\cos (\pi x)}{\pi}+\ln (x)+3 e ^{-x}}$

ocean sealBOT
primal galleon
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So now we just evaluate the definite integral between -2 and 1?

fierce prairie
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Yep

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Btw don't forget the absolute value in ln|x|

primal galleon
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\begin{align*}
&\left(-\frac{\cos (\pi \cdot 1)}{\pi}+\ln (1)+3 e ^{-1}\right)\bigg|_{-2}^{1} = \
&\left(-\frac{\cos (\pi \cdot 1)}{\pi}+\ln (1)+3 e ^{-1}\right) - \left(-\frac{\cos (\pi \cdot (-2))}{\pi}+\ln (|-2|)+3 e ^{2}\right) \
=& \left(-\frac{\cos (\pi)}{\pi}+0+3 e ^{-1}\right) - \left(-\frac{\cos (-2\pi)}{\pi}+\ln (2)+3 e ^{2}\right) \
=& \left(\frac{1}{\pi}+3 e ^{-1}\right) - \left(\frac{1}{\pi}+\ln (2)+3 e ^{2}\right) \
\approx& \boxed{-21.12}
\end{align*}

ocean sealBOT
primal galleon
#

Btw, I was supposed to solve this without a calculator @fierce prairie

fierce prairie
primal galleon
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cos(2π), cos(π) is fine…

fierce prairie
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I mean it can probably be simplified with constants like pi and ln(2) left

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Yeah

primal galleon
#

But I am not sure about 3e^2 etc.

#

Too many decimals…

fierce prairie
#

That can be left as well

primal galleon
#

I don't think they wanted the numerical answer

#

Leet me check

#

@fierce prairie It says the right answer is "Integral doesn't exist (divergent)"

#

Because of the 1/x?

fierce prairie
#

Hmm

fierce prairie
#

I honestly haven't seen one like this but symbolab is also saying it diverges

lone heartBOT
#

@primal galleon Has your question been resolved?

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grave niche
#

The answer is 2/0 or 0 right?

lone heartBOT
remote heron
#

you should factor

finite flax
#

How did you get there

#

Can't do 2/0 so clearly not

grave niche
finite flax
#

You were asking about the answer I thought

#

It is indeed indeterminate form

remote heron
#

can you really not just factor

grave niche
#

Ya i guess the right move would be to Factor right?

finite flax
#

You have already covered LHospital's Rule?

remote heron
#

i see a common factor

wary stream
finite flax
#

Ya know, factoring, actually, I agree that's all you need

remote heron
#

you have to do something special since its complex right

wary stream
#

I agree with factoring too but you did LHospital's wrong

finite flax
#

Zeros won't hurt you after you factor out common factor in top and bottom

remote heron
#

ensure the limit is not at a singular point

#

or something

finite flax
#

Ooh...top will be odd power of z though

#

Does that matter?

#

I think the limit is same from LHS and RHS anyway

remote heron
#

well there is no lhs and rhs

#

you can approach from any path

grave niche
#

Welp i guess i over complicated myself lol, thanks guys

remote heron
#

or youd need the limit to be the same approaching from any path

finite flax
remote heron
#

right but isnt z complex

#

im just assuming

#

so theres no lhs or rhs of 0, theres a region surrounding it

finite flax
remote heron
#

is it not complex?

finite flax
#

If it's in R we aren't dealing with regions

#

Just factor already

remote heron
#

well then why did they use z angerysad

finite flax
#

This is like a Monty Python sketch now

remote heron
#

no its not

finite flax
#

DOES THIS SHOP HAVE ANY CHEESE AT ALL???

remote heron
#

what i said is true and reasonable

finite flax
#

$\lim_{x \to 0} \frac{z+1}{z^2 - 1}$

remote heron
#

$\lim_{z\to0}\frac{z+1}{(z+1)(z-1)}$

ocean sealBOT
#

jan Niku

remote heron
ocean sealBOT
#

Disorganized

finite flax
#

Oh, yep: then @remote heron

#

1/(z-1)

#

So LHsopital doesn't need to come into this

#

@grave niche

grave niche
#

Well it technically can.... right?

#

wait.... nvm its the same thing lol

finite flax
remote heron
#

its a sin to use the hospital rule where you dont have to

finite flax
#

We had to learn how to prove LH before we could use it

grave niche
#

So LH is basically a cheat code?

remote heron
#

you should learn to prove it

#

not that i understood it bearlain

grave niche
#

im pretty sure in order to use LH you need to get 0/0 or ♾️ /♾️ in a limit right

remote heron
#

analysis can kill

grave niche
#

Umm I feel like it didd something wrong here

#

.close

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#
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tired nexus
#

How would I graph this?

lone heartBOT
tired nexus
#

this is in general form

lone heartBOT
#

@tired nexus Has your question been resolved?

real cipher
#

place y alone

#

in ur case

#

y = 3x - 9

#

now put any value of x in your equation u would get the value of y and then plot in the graph

#

for e.g
if x=2
y = 3*2 - 9 = -3

#

(x,y) = (2,-3)

#

similary follow this process 2 or three times

tired nexus
#

I see

#

!close

#

-close

#

.close

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orchid forge
lone heartBOT
orchid forge
#

Im confused on how to integrate this

#

I got until here but then when i integrate this it just gives me 1 which isnt the answer

vale wigeon
#

$\int u^{-1} \dd{u} = \ln|u| + C$ though

ocean sealBOT
vale wigeon
#

so where are you getting just 1 from

coral thorn
#

power rule cannot be used when exponent is -1

digital galleon
#

It will just be ln|u| tho

#

+c ofc

orchid forge
#

Wait what

#

But what happens to the numerator then?

limpid turret
#

where?

left trellis
#

$u^{-a}=\frac{1}{u^a}$

ocean sealBOT
#

ℕαv

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#

@orchid forge Has your question been resolved?

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orchid forge
#

Oh shit yeah thx

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agile grove
#

What is the application of the unit circle in the real world, and what is the reasoning behind the specific unit of 1? Also are we limited to just the 2 special triangle cases where they are labelled on the unit circle. Or can we use any value for the angles and thus find the proper lengths of its sides and it stuff? I know its good for trigonometric rations.

limpid turret
#

Real-world application is always subjective to someone's skill-set

#

unit circle is used for trigonometry

#

So you're asking what the real-world applications to trig are, which is a heckin' lot

#

If by 2 triangle cases you mean 45-45 and 30-60, then no

#

Those are just the easiest to memorize

#

We use 1 because it's literally a "unit". It makes the math easiest

#

If it was anything besides 1, we'd have to divide or multiply to account for the non-unit ratio

#

Or can we use any value for the angles and thus find the proper lengths of its sides and it stuff
I don't know what you mean by this

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#

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thick beacon
lone heartBOT
thick beacon
#

how do I even start doing this question ?

#

I know how to differentiate it, but how do I form that equation

#

?

wind cloak
#

Just differentiate and chuck everything into that equation

#

It will all cancel to 0

thick beacon
#

I kinda understand but can you like show me how to do it ?

winter light
#

Compute first and second derivative of the y they give you above, and substitute those into the diff. eq. and check whether you reach an identity or not

limpid spade
#

real chads solve the diff equation first

remote tapir
#

Bro am doing it right now

#

Partial fraction

limpid spade
#

what

remote tapir
#

ITS CONFUSING

lone heartBOT
#

@thick beacon Has your question been resolved?

untold forge
#

24 minutes?

#

do you have any work to show?

thick beacon
#

Thats it
I don’t know how to further differentiate and I tried to figure out a way to make it form the equation given but so far I don’t really know

cyan storm
#

dont take e^2x in common before differentiating again

#

in second last step itself you get two functions in addition both are similar to the original function so just differentiate them separately and then add together

cyan storm
# thick beacon

i can understand your frustration from the fact that you are doing it by assuming the functions being multiplied first
then differentiate individually and then apply the product rule

lone heartBOT
#

@thick beacon Has your question been resolved?

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vapid smelt
#

It would be of great help if someone could explain how the last step came to be. Appreciate it.
The question is:

marsh rapids
#

,w d/dx arctan(ax+b)

ocean sealBOT
limpid turret
marsh rapids
#

So if you adapt it you can find such antiderivatives

untold forge
#

hmmCat but it's 3/4

vapid smelt
marsh rapids
#

,w integrate 1/((x+a)^2 + b)

ocean sealBOT
limpid turret
#

You can do this, slowly, with a lot of u-substitution

vapid smelt
limpid turret
#

,w derivative 1/(x^2+1)

vapid smelt
#

xd

limpid turret
#

,w derivative arctan(x)

vapid smelt
#

i guess that was what it was intended for since its worth 6 marks

limpid turret
#

after a butt-load of u-subs, you can get here and solve your integral

vapid smelt
#

xd. Alright thanks, i'll try

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#

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noble ginkgo
#

hello

lone heartBOT
noble ginkgo
#

any help

#

i have a problem I am stuck on

vale sapphire
acoustic mirage
#

Seems like a tough problem

noble ginkgo
#

thanks for offering

#

but it seems like the answer was hidden in plain sight

#

all i did was watch a 2 minute video and i understood lmaoo

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@noble ginkgo Has your question been resolved?

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acoustic mirage
#

so this was the ques

can we simply cancel out the term which is present inside the mod and the denominator ?

wind cloak
#

Uh

#

Well not directly

acoustic mirage
#

?

wind cloak
#

Yeah but the inside of the absolute value is negative

#

So you'll get 4(2 - x)

#

Then you can cancel if you wish

#

You actually can lol

acoustic mirage
#

i already got the ans 😁
i'm wasn't able to figure out how to solve the mod fucntion thingy

acoustic mirage
wind cloak
acoustic mirage
wind cloak
#

Because the term inside the absolute value is negative

#

So we multiply it with -1 to make it positive

acoustic mirage
wind cloak
#

Yes

#

h is positive remember

acoustic mirage
#

is there any other way ?

wind cloak
#

Not really I mean

#

2^- is a number just smaller than 2

#

Think 1.99999

acoustic mirage
#

ok

wind cloak
#

Then you see for yourself that it's negative

keen plinth
#

the root of 4x - 8 is 2

wind cloak
#

If you put 1.99999 in the absolute value term

keen plinth
#

so it must be negative on the left

#

it's a linear graph

#

i'm sure you're familiar

acoustic mirage
#

ah yes as 4*(number less than 2) < 8

wind cloak
#

Yes

acoustic mirage
keen plinth
#

,w plot 4x - 8

acoustic mirage
#

how would i be able to plot such a graph so fast ?

keen plinth
#

it's a linear graph ...

#

have you plotted linear graphs before in your life

wind cloak
#

Not greater than

acoustic mirage
keen plinth
#

so it's literally just an upward sloping straight line passing through 2

acoustic mirage
wind cloak
#

Yes

acoustic mirage
#

so is 4x-8 = 0 ?

quasi sand
wind cloak
#

2- is approaching from the left

quasi sand
acoustic mirage
keen plinth
#

?

#

what is your question

acoustic mirage
#

when you said plot a graph, 4x-8 would be equal to 0 right ?

keen plinth
#

i said plot a graph to see that it's negative on the left

#

it should be a 1 second thing you do in your head to check how to evaluate the absolute value

keen plinth
#

well now you know

acoustic mirage
#

y-x=0
like this sort of a thing

keen plinth
#

is anything stopping you from plotting the graph of the function f(x) = 4x - 8

#

like it's just to determine the sign of the values inside the absolute value

#

you don't need to get caught up on this

acoustic mirage
#

i haven't been taught to do this
i am from somewhere where we are taught trigo without graphs 💀

acoustic mirage
keen plinth
#

sure

acoustic mirage
#

thanks tho

#

.close

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#
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arctic dirge
lone heartBOT
arctic dirge
#

@mental coyote

#

<@&286206848099549185>

muted furnace
#

here's how I'd do it

#
  1. find angle MOA
#
  1. OAM
#

also reminder that the whole shape is a regular octagon as mentioned in the question

arctic dirge
#

the answer key says this

#

.close

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weary void
lone heartBOT
weary void
#

how would you approach

#

v(t) = e^(-s)

#

I know that s(0) = 0

#

meaning
v(0) = e^(-0)
v(0) =1

echo socket
weary void
#

ok

echo socket
#

Hm, we still need s(t) though

#

I suppose we need to solve the differential equation then

#

ds/dt = e^(-s)

weary void
#

ye

echo socket
#

e^s ds = dt
e^s = t + C

#

You can solve for C by plugging in t = 0 and S = 0, yielding C = 1

#

So you end up with s(t) = ln(1 + t)

#

The rest is solving for value t such that the second time derivative of s is equal to -4

weary void
#

ok so then you get derivative of s(t) as v(t) as 1/(1+t) right

#

then derive that again for a(t)?

echo socket
#

Yes

weary void
#

what is the derivative of 1/(1+t) then

#

nvm got it

#

what is the differential equation?

weary void
#

@echo socket e^s ds = dt
e^s = t + C

#

HOW DID you get that pleae

#

please

#

could you please @ me when your back

lone heartBOT
#

@weary void Has your question been resolved?

echo socket
#

Sorry for the late response

weary void
#

oh

#

so you integrate e^s ds to get e^s

#

and integral of dt is t + c

#

ok i think i get it

#

thank you btw

lone heartBOT
#

@weary void Has your question been resolved?

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errant dagger
lone heartBOT
errant dagger
#

this is a practice exam

#

how would I do this?

ocean hawk
#

what class is it for? calculus?

errant dagger
ocean hawk
#

so I don't know if this is the best way to solve it

#

but you're looking to find a substitution $u = x^n$ for some $n$.

ocean sealBOT
#

cwatson

ocean hawk
#

take the derivative of that, which gives you "du = ?? dx", where the question marks you can fill in

jolly widget
ocean hawk
#

you also know that 7u^2 du should equal 28x^11 dx. so you can combine the 2 equations

ocean hawk
lone heartBOT
#

@errant dagger Has your question been resolved?

errant dagger
#

u = x^n was perfect starting idea ty

#

i was very lost

#

.sloe

#

.close

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dark ibex
#

Is this wrong?

lone heartBOT
dark ibex
#

i dont understand where the cos(x) in the denominator came from.

marsh rapids
#

They factored out sec x = 1/ cos x

dark ibex
#

both the sec(x) ?

marsh rapids
#

You don't factor something there's only one of

dark ibex
#

oh ok

#

thanks

#

.close

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languid bolt
#

can I say

log_x (0) = -∞
for x > 1
and
log_x (0) = ∞
for x < 1

languid bolt
#

or not

median oar
#

No

#

Logs are not defined at 0

languid bolt
#

ok so no...

#

what if it's a limit

#

lim x -> 0 (log_10 (x))
for example

median oar
#

The limit of something doesn’t have to be defined at that point

#

It is entirely possible that the limit of a function is not equal to the function at that point

languid bolt
median oar
#

Consider the function f(x) = 1 for x<0 and x>0

#

And f(x) = 0 at x=0

#

The limit as x->0 of f(x) = 1

#

Even though f(0) = 0

languid bolt
#

oh okay

#

i think i get it

#

thanks

#

.close

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#
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lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
#

@alpine sable Has your question been resolved?

pseudo lily
#

u can ping helpers

#

<@&286206848099549185>

#

please help this kind whoever

torpid mirage
#

Put the above expression under the sum, and use the linearity of summation to split sums and get constant outside

#

in the end it ends up being a sum of k over k which is easy to do

pseudo lily
#

@alpine sable what they said

#

thanks bro

torpid mirage
# pseudo lily thanks bro

he probably won't follow it from the first time since it's all words so I will keep an eye for questions

pseudo lily
#

oh ok

torpid mirage
#

Just wanna show him how to do it rather than giving the answer

pseudo lily
#

yes that is the way

torpid mirage
#

Look

#

you got the expression for $f(a+k*\frac{b-a}{n})$ correct ?

ocean sealBOT
#

Mohamed Mohsen

torpid mirage
#

you can plug that expression in here $\sum_{k=1}^{n}f(a+k \times \frac{b-a}{n}) \times \frac{b-a}{n}$

#

tell me if you follow up to this point

ocean sealBOT
#

Mohamed Mohsen

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#

@alpine sable Has your question been resolved?

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prisma lantern
#

Hey, does the least squares methods still give a valid answer even if ker(A) != {0}

prisma lantern
#

Cause I know there's no unique solution, but I wonder if it still gives you something

lone heartBOT
#

@prisma lantern Has your question been resolved?

lone heartBOT
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prisma lantern
#

.reopen

lone heartBOT
#

prisma lantern
tacit arch
#

and how does A relate to least squares?

prisma lantern
#

Well if you have a system of linear equations

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like Ax = b

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and b isn't in the image of A, i.e. there is no solution for Ax = b

#

then you can find a vector x* thats the closest it possible can come to solving Ax = b

heady pollen
#

riemann, i just got the tex preamble
are you the one who made that? i saw your name and profile picture there

prisma lantern
#

And I know that if ker(A) has more than just 0

prisma lantern
#

HMMM VERY INTERESTING

#

Thanks toby!

alpine sable
heady pollen
#

crazy

prisma lantern
#

Hey so @alpine sable I'm not so good with statistics, whats the notation here?

#

Is it probablility that rank(X) = n is 1?

alpine sable
#

yup

prisma lantern
#

Cool

lone heartBOT
#

@prisma lantern Has your question been resolved?

lone heartBOT
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violet ore
#

I don't understand their formula for the second derivative (in blue)

violet ore
#

I understand that are are differentiating with respect to x but dx/dy is in terms of t

#

so we must do something.. but I don't get why they do that

lone heartBOT
#

@violet ore Has your question been resolved?

vapid shuttle
violet ore
#

Yes but I don't see how to derive it

#

if I have a parameterized curve x = f(t), y = g(t) then I accept dy/dx = [dy/dt]/[dx/dt] but the second derivative I just don't see

#

So they're doing (d/dx)[dy/dx] = [(dy/dt)/(dx/dt)] but how do they reduce ?

lone heartBOT
#

@violet ore Has your question been resolved?

lone heartBOT
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high wolf
#

am trying to develop a working understanding of the integral test, comparison test, and p series...this was a question and answer on my study guide but I'm having trouble following

high wolf
#

Can someone help me understand from the first step. I think they applied u substitution firstly but I'm lost on what they did afterwards..

lone heartBOT
#

@high wolf Has your question been resolved?

high wolf
#

Is it not via u substitution?

#

So that turned into integral of 14/u^3? But how did he get -7/u^3 from that?

#

Can we start from the beginning? So we have the original function given to us, and we must apply substitution on 2+ root x. Shouldn't that give us instead 7/(root x)*u^3?

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Sorry, these sorts of functions are tricky for me to understand

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we multiply root x by u^3?

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What do we need to multiply u by?

#

ok.

#

Any advice?

ocean sealBOT
#

Azka Aska

high wolf
#

Is the above for u = 2+ root x?

terse rampart
#

thien

high wolf
#

So this is the process, correct?:

#

How exactly did it become -7/u^2 though...?

#

Alright, I'm fixing to solve it.

#

Still not sure how, but it's fine. Somehow, we get -7/(u^2)...then we plug our u back in and get this: now how do we apply this integral test?

#

How about this. What are they doing in these few steps?

#

^

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How are the getting 7/9 though?

#

What is going on?

#

Wait how do you get 1?

#

We have b there not 1?

ocean sealBOT
#

Azka Aska

high wolf
#

Wouldn't it be -7/9 though?

#

Aren't we meant to subtract upper bound from lower bound?

#

Okay, you're right. Sorry. So here we were doing integral test. But remind me, why do we set 7/9 less then infiniy?

#

What do I do with that information though?

#

How can I use it to determine if there’s convergence or divergence?

#

How do I know that this integral converges though?

#

What does this mean? That it’s finite?

#

Does it have to do with the 7/9?

#

How do we know it’s not infinite?

#

Now I’m understanding. But what about the other function?

#

The /7/(2+ root(b))^2?

#

This makes it of sense. May I ask more questions?

#

^

#

Give me one moment I am heading back to my computer to get the questions

high wolf
#

Hi Azka! I'm back.

#

Can we just go over the integral part again?

high wolf
#

Im at the point where I have 14 * integral of 1/(u^3)du

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I'm confused on the next step to integrate

#

yes

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like, add one to exponent and multiply

#

Can you visualize the steps for me? Functions like these are weird to me.

high wolf
ocean sealBOT
#

Azka Aska

high wolf
#

Like this?

#

Got it. I can understand it. My other question is related to another problem:

#

im doing it now..let me try and see

#

So does this also converge?

#

does it not go to 0 like the problem before?

#

oh wait!

#

Is it because it's a fraction and this isn't a fraction?

#

so it won't go to 0 in this case?

#

As long as b is in the denominator or a variable is in the denominator..?

#

when we plug infinity in, it goes to 0?

#

But when it isn't in denominator it goes to infinity?

#

How does it depend? Can you explain a little further. 😄

high wolf
#

Okay, are you still available?

#

Can we go over some more of these types of problems? They're called integral tests?

#

do these involve p-series as well?

#

Can we do this?

#

Okay, working on it rn

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Does the process look right?

#

🙂

#

And it converges because -1/ln(inf)) goes to infinity because infinity in the denominator as b goes to infinity?

#

like you said before?

#

Got it. Are you familiar with the comparison tests?

high wolf
#

Can we do a problem? I'm not good at comparison tests at all

#

Can we do this?

#

No problem!

#

I sent friend request. 🙂

shell widget
#

@high wolf Still need help?

high wolf
shell widget
#

As n approaches infinity, what do you think the numerator acts like?

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Same question for denominator

high wolf
shell widget
#

Yes but I'm not asking that

#

Like what does the expression 3n sqrt(n) + 1 acts like

high wolf
shell widget
#

3nsqrt(n) or 3n^(1.5)

#

Or even n^(1.5) will work

#

The denominator acts like n^2

#

So as n approaches infinity, the series acts like $\sum_{n=1}^{\infty} \frac{n^{1.5}}{n^2} = \sum_{n=1}^{\infty} \frac{1}{\sqrt{n}}$

ocean sealBOT
shell widget
#

So you can use the limit comparison test with this series

high wolf
shell widget
#

@high wolf From the original series

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3nsqrt(n) + 1 acts like 3nsqrt(n) = 3n n^(0.5) = 3n^(1.5)

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n^2 + 4 acts like n^2

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So your series acts like 3n^(1.5) / n^2 = 3/n^(0.5) = 3/sqrt(n)

#

you can get rid of the 3, doesn't matter, so the series you are interested in is 1/sqrt(n)

high wolf
shell widget
#

Yes

#

@high wolf

lone heartBOT
#

@high wolf Has your question been resolved?

lone heartBOT
#
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charred valley
#

yo whats up with the coefficent for x =3

charred valley
#

heres what i did for this question, idk what to do next

#

pls 💀

hidden heart
#

if the planes are parallel dont they have the same normal?

charred valley
#

yeah thats what i did

hidden heart
#

so your plane should be 3x -3y + 2z = something not 6

charred valley
#

true

#

wait

hidden heart
#

oh wait

#

the planes arent parallel

#

the line in the planes are

charred valley
#

nah i did a mistake

#

cuz i did b instead of ab

#

ok i figured it out

#

.close

lone heartBOT
#
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alpine sable
lone heartBOT
alpine sable
#

Please simplify

alpine sable
raven dagger
#

What is the coefficient of x² ?

alpine sable
#

uhh

alpine sable
subtle birch
alpine sable
subtle birch
#

Take Lcm in denominator

raven dagger
#

Do you need to like factories it ?

subtle birch
#

More like rizz

raven dagger
#

No rizz so i call it factories

lone heartBOT
#

@alpine sable Has your question been resolved?

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#
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ornate imp
#

how do I know that the force at right end will be W-A or A-W
I'm solving other subject, but I thought this is simple maths

marsh rapids
#

The force needed to make it stable ?

ornate imp
#

yes

vapid shuttle
#

because if not then the thingy will tip

marsh rapids
#

Including rotation?

ornate imp
#

yes rotation too

marsh rapids
#

Yes exactly. Unless A = W/2 you can't have a force on the right end that won't lead to nonzero torque

#

And keep it vertically stationary

ornate imp
#

but I want in terms of A-W or W-A

#

just tell out of these two

marsh rapids
#

Look at the sum of forces

#

You want them to be 0 to have vertical stability

ornate imp
#

if I say we have to check the direction of rotation after finding reaction at right side

#

it's not actual force but we are just considering it

marsh rapids
#

Then you also look at the sum of torques

ornate imp
#

what if I write this. is this right

marsh rapids
#

Is the sum of forces 0 ?

ornate imp
#

what zero

#

they all have magnitude

marsh rapids
# ornate imp what zero

This is supposed to be a Galilean referential, in which the 3 laws of Newtonian mechanics apply. What does the first one say ?
Conclude

ornate imp
#

can I talk in terms of shear force or moment if you know those things

#

this is not mathematics, but I was trying to make it a simple question which would come under mathematics

marsh rapids
ornate imp
#

we are taking a section of a body, I drew only the section, and then we are finding the force at right side (from where we have cut the section)

#

it's fine anyway. close channel if I don't reply

marsh rapids
lone heartBOT
#

@ornate imp Has your question been resolved?

ornate imp
#

.close

lone heartBOT
#
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ember isle
#

This may be a silly question, but I'm still confused with this kind of notations, I know this is the second derivative but why it's not written dy^2/dx^2 ?

median oar
#

Because y is the function

#

You’re applying d/dx twice to it

earnest saddle
#

just notation

median oar
earnest saddle
#

$\frac{d^2y}{dx^2}=\frac{d(\frac{dy}{dx})}{dx}$

ocean sealBOT
#

Pro_Hecker

earnest saddle
#

we just write (dx)^2 as dx^2 for convienience

ember isle
#

ok thanks, after all it boils down to notation

median oar
#

Rather than differentiating the function y, twice

wind cloak
#

In the end it's just quirky Leibnitz notation

#

It looks like youre just multiplying the differential operators

ember isle
#

.close

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#
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noble hornet
#

Wassup guys

lone heartBOT
noble hornet
#

im in desperate need for some help regarding my math assignment

#

@wind canyon

wind canyon
#

yo

noble hornet
#

it doesnt seem like people are very keen to help over here

wind canyon
noble hornet
#

Sorry

#

Am i meant to enter with a humurous math joke?

wind canyon
#

bruh do u have a question

#

or not

raven dagger
hollow frost
#

what are you struggling with?

earnest saddle
wind canyon
#

.close

#

type that

#

and allow others a chance to speak

quasi sand
#

.close

lone heartBOT
#
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sweet hemlock
#

Whats the reason for r1 and r2? Because i know it equals 40 and r1 and r2 =20 but whats the reason

earnest saddle
#

is RS angle bisector?

sweet hemlock
#

Whats that?

median oar
#

The dots suggest that it is I think

sweet hemlock
#

😭

#

Im lost

earnest saddle
#

yes then using angle sum property of triangle in PRS

#

we get <PRQ=40

sweet hemlock
#

Yes

earnest saddle
#

what do you need then?

sweet hemlock
#

The reason for r1 and r2

earnest saddle
#

what is statement

#

then i will tell reason

sweet hemlock
#

I got PŔQ Ls bc its sum ls triangle

#

And i know that r1 nad r2 is 20

earnest saddle
#

what is statement?

sweet hemlock
#

Yeah

#

What is it?

earnest saddle
#

for what
a) <PRQ = 40
b)r1=20and r2=20
c)both a and b