#help-0
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nvm that doesn't work
I don't know how to incorporate the fact that i'm trying to calculate an average in my algebra
(178.03920 + x)/3 = 90
178.03920 + x = 270
x = 91.9608
I guess could someone check this?
did you solve that by hand?
ok i'm a bit rusty on math since i haven't taken classes since high school
thank you
np
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Hey everyone, I am having a bit of trouble formally proving inequalities for things like the Direct Comparison Test, I formulated this inequality, and did not really know how to prove it (well, I tried just doing algebra, but I got it being false so im doing something wrong)
Here is it in Symbolab:
well actually, nevermind I think I solve this one but in generally proving inequalities can be challenging
if anyone has a general guide that would be nice/tips/explanation for this one (although I got it, seeing someone else do it is nice)
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need help
by calulating the chain rule on BP
I cannot find that -1 is from where ?
can someone show the details for this step
@alpine sable Has your question been resolved?
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@alpine sable Has your question been resolved?
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How do I figure this out
C
Oops
I meant between the interval
Is it bc the y values between [1,3] have to be in between 10-18?
Hm I kind of see it
So the graph can go up and down but since f(3) is positive then 17 has to be a solution??
Practicing for AB/BC lol?
Not exactly
That's because f(x) is continuous. IVT guarantees that as long f(x) is continuous on a closed interval [a,b] that f(x) outputs all values between f(a) and f(b)
if min<= 17 <=max
You're not guaranteed f(1) or f(18) are maxes or mine
yes
Sadly
It could look like this
However IVT primarily focuses on values between f(1) and f(3)
Ohh ok
Stating that there exists all values between f(1) and f(3)
But that does not mean that the function is strictly confined f(1) < f(x) < f(3) for all x in (1,3)
So I'd take this statement with a grain of salt
What part of it is confusing
Like
This part
Is it just that values exist but they’re not guaranteed to be between f(1) and f(3)
No IVT guarantees that as long as f(x) is continuous in [a,b], f(x) will kick out all values between f(a) and f(b) sometime within the interval
They guarantee only the outputs between f(a) and f(b)
Anything out of that, not guaranteed
Kick out?
Output
Oh ok
Like if put in 2 into f(x) and it kicks out whatever f(2) is
💪💪
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Hi
I need help with this differential equation
I have tried to do it by using the partial derivative method but it doesn't work
<@&286206848099549185>
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I need help with Average Rate of Change. I’m stuck on the part where you factor the numerator. The problem is find the ARC of 9x^2-8 on the interval [1,t]
@sick thistle so you need to factor $9t^2-9$?
jan Niku
Yes I believe
I’m little confused and hoping someone can teach me finding the ARC using an interval
can you identify anything common between the two terms
i mean youre almost there
you just need to factor
i mean youre missing the number but yea
Is the number 3?
no
Or is it 1 because t is 1
(T+1)(t-1)
jan Niku
So the -9 just disappears?
its still there
it does
Then it equals 9t-9
9t+9
9(t+1) yea
You helped me better than the teacher

@remote heron can I dm you with questions?
im probably too busy to help like that
Dang dang
just killing time before bed right now
but you should ask more on the server 
there are other helpers
hm?
This one I’m completely lost in
what question
composition
you put one function as the input of another
29(3t+1.1)^2-152(3t+1.1)+91
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hello
does anybody know how to do these questions?
,rotate
im not really sure if i should firstly simplify or cancel the common factors
Doesn't really matter too much
should i firstly simplify and then multiply?
like in question a should i simplify the 3 x square of 40 or take out the common factors straight away
yes i meant that
anyway, there is no prescribed order in which to do these things
so i can just do any?
if you can cancel out a pair of matching factors then go for it, if you can simplify a root then also go for it
from here
for some reason i got 42 over square root of 3
<@&286206848099549185>
wait
alright
oh thank you very much
you're welcome
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
no its not homework
rn i have holidays
im just studying through textbook in case suprise test
when i go back to school
Doesn't matter
still only hurts you to have shit like this handed out
how
i didnt know how to do working
now i know
bcz i was first doing common factor
instead of simplyfying
- im still gonna try to do the question by myself and do more of the similar ones
it's flexible😊
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dont even know where to begin
do you know how to find expected value from pdf
no
integral of xf(x) dx
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i just drew a perpendicular line there because im not what else to do
i dont know but i see people draw a perpendicular line to make right angles so im not sure
it'd help if you found the length of the vertical red line you drew
not sure how i would do that
i only have one angle which is 43.35 degrees
and the length 10.7cm wouldnt help
oh you're right i'm completely wrong.
wouldnt sinA = h/b
or do we disregard the perpendicular line because its not important here
oh sinA is just 43.35 degrees
isnt 10.7 side c
i think im confusing myself with the labelling of the triangle
did i label it wrong
yes
use c/sin(C) then
ahhhh okay
this is what i have
$\frac{x}{\sin\left(43.45\right)}=\frac{10.7}{\sin\left(79.2\right)}$
waterr beam
what should I do next?
do you know what sin(43.45) means?
xsin(43.45)?
like what its equal to?
right
Yeah what about it? Is it used for the next step
if your equation were instead x/2 = 3, would you know how to solve for x?
Yes
do the same thing here
great
Would that be our final answer for x (after inputting into calc
yes
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(the first derivative of inverse of f) of -1?
and use 1/f'(x).
@stark lagoon Has your question been resolved?
wait, i guess the first one is correct.
\
solve $f^{-1}(x)$ as you did before, then use this formula.
Z_char
well, but you can not simply = 1/f'(x).
how can i explain this...
if you have a function, but inverse if not a function. you may have three different [f-1(x)]'(-1), right?
but follow you rule, it will be only one.
well, a simply explanation is you do not have this rule.(
this's just a (f-1)(-1),instead of (f-1)'(-1)
like i showed before.
you got (f-1)(-1) first, then get [f-1]'(x).
you need to follow this rule.
i see
🙂
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Why is it wrong to do something like:
M_a / M_b = 5/6 -> 6M_a = 5M_b
S_a / S_b = 2/3 -> 3S_a = 2S_b
Then money per student would be:
6M_a/S_a = 5M_b/S_b
Subbing the values of S_a i'd hae:
6M_a/ (2/3 S_b) = 5M_b / S_b
so the ratio between the money per student on team A to team B would be:
$9M_{a/p} = 5M_{b/p} \to \frac{M_{a/p}}{ M_{b/p}} = \frac 59 \text{ or } 5:9$
!Kiz__
this is true
S_a and S_b is the students in team A and B
M_(a/p) and M_(b/p) is the money per student for team a and b```
what i did is right?
idk about all the sentences above it but that equation transfer is right
Well that's not the right answer
The answer is B or something
Yeah i think it's B
can you go over the sentences above? I'm just curious 💀 if i'm bugging with some kinda dumb logic or not
can't you just use the values they give you, and set the multiplier to be 1
5 dollars for A, 6 dollars for B
2.5 dollars each for A, 2 dollars each for B
2.5/2 = 5/4
yeah you're right
I still don't get why what i did was wrong though
whered you get this
for the life of me I can't find the error
you found it i think
It should've been M_{a/p} = M_a/ S_a
M_{b/p} = M_b/ S_b
M_b = 6/5 M_a and S_a = 2/3 S_b
then divide M_{a/p} and M_{b/p}
,w (3/2)/ (6/5)
@frank apex thank you for the extra pair of eyes btw!
yw
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can someone please help me?
<@&286206848099549185>
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💀
what have you tried @sand scarab
everything i just can't seem to get the answer
can you find <prq?
no i need help
you know angle subtented at centre is twice angle subtended on circumference?
kinda
then can you find $\anglePOQ$
okay thank youu
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
I didn't copy!
do you understand English? @hoary ether
then how you understand pro hecker quseion
oh
im getting brain freezing
and
I got the error, sorry
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Need help solving this one.
Cannot use ranks and dets. Only concepts from row echelon form
I thought that if I will be able to prove that A^t and A has the same leading entries then I will be able to prove it. But can't think of a way without using ranks
@alpine sable Has your question been resolved?
@alpine sable Has your question been resolved?
@alpine sable Has your question been resolved?
HELP SOMEONE??
How can I prove that?
Let $A\in M_{n\times n}\left(\mathbb{R}\right)$ such that $Ax=\vec{0}$ has infinitely many solutions.
Do $A^{t}x=\vec{0}$ has infinitely many solutions?
Note. I can't use ranks and dets. Only things I can deduce from row echelon form. For example, I can't use the theorem $rank(A)=rank(A^t)$
CStudent
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<@&268886789983436800>
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How should I find function of g?
Well first of all we are gonna need g(1) to know what g is
For that you can let x = 1 yielding 2g(1) = 6 and g(1) = 3
So, simply isolate g(x) in g(x) + 3 = 4x + 2
Why did you let x=1?
To find value of g(1)?
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@alpine sable Has your question been resolved?
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Are you gonna help or not
That step is not legal. Because you went from a subtraction expression to multiplication
I just took -1 out
Its still like( -1)
The original problem, you factored out -1, it's separated by subtraction
You can't make it multiplication
I grouped them doe
Because ai dont know how to factorize 4 terms
And for 4 terms
You group them to two
I know how factor by grouping works
well, you have $x^2 - (y+3)^2$.
Z_char
So whenever you group two terms in factorization
then use formula of the difference of square.
You put a + in between?
When doing this, you changed the expression from subtraction to multiplication
?
Yes
,w (x^2-y^2) (-6y-9)
Nvm anyway thanks
This makes it multiplication
Yea
That is x
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next time picture please
Don't make people download files. Post a picture/screenshot instead
sorry
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Why do sine and cosine normally relate to an x and y value? (im new to trig)
what do you mean "relate"
like $y = \sin(x)$ ?
riemann
yeah
well i get that in an algebraic sense, but i mean like in functions and graphs
sin and cosine are functions
like $y = x^2$ is a function
riemann
Well yes
delete your message
Please read #❓how-to-get-help
to plot the graph of y = sin(x), plot a few points
radians usually
but degrees is fine too if you know how to convert
done
does that answer your question?
and this one?
what's the actual question
its not really a question, its just a statement ill send that im trying to understan
So while trying to find the shortest distance between a wall(which from our position we dont know where it is), why would we use sine and cosine to determine shortest values for these.
are you trying to implement a distance function from one thing to another?
We are a player on a grid trying to "cast" rays to draw walls and give them size based on their distance.
this is called a raycaster
Im kinda making the problem a bit harder sry.
but any help is appreciated
no, posting the original question gives context to what you want to do, and helps to avoid the xy problem :D
k
//makes a ray and draws it function ray(angle, i) { let x = player.x let y = player.y while (map[Math.floor(y)][Math.floor(x)] == 0) { x += Math.cos(angle)/wallSize/4 y += Math.sin(angle)/wallSize/4 } if (Math.abs(Math.round(x)-x)>Math.abs(Math.round(y)-y)) { y = Math.round(y) } else { x = Math.round(x) }
this might help if u understand, but its a function(in programming context) that draws rays.
just realized ur in the unity discord, which is literally what i was just doing and i still have it open lol
where's the math question
I think I get what you mean and in answer to your original question, if you have a coordinate system, (x,y) and you have two objects in that system, you can relate x=rcos(theta) and y=rsin(theta), where r is the magnitude of distance between the two entities
are you confused about this part?
in your code it looks like that is the iteration between the player position and the wall.
@alpine sable Has your question been resolved?
yeah
this is what ive been stuck on
have you played around with the values and checked the outcome?
No
give that a go
k
just comment what it was originally ;P
like which value should i try
this is the original code
one really high one really low
just play around with it
No like which value here:
x += Math.cos(angle)/wallSize/4
y += Math.sin(angle)/wallSize/4
the 4?
ye
x += Math.cos(angle)/wallSize/0.1
y += Math.sin(angle)/wallSize/0.1
x += Math.cos(angle)/wallSize/10
y += Math.sin(angle)/wallSize/10
Note: Making it higher has resulted in a large performance loss
Its smoother(walls are) but laggier
expected
so these are bigger increments of x and y, (less rays in the pov)
opposite for the secondary screeny
what do u mean
well its incrementing at a very low number so there will be lots of instances I suppose? like going from 0->1 in gaps of 0.5 only takes 2 iterations, but going from 0->1 in gaps of 0.1 takes 10
i see
btw can we go back to the original question,which was why the x and y correspond to cosine and sine
oh I answered it earlier in general terms
here
saw but kinda didnt understand
hmmm
im kinda new to trig and im self teaching
if you go through the khan academy trig section im sure it would help
thats where i go to where im stuck
love it btw
but the vids are rly old and quality is low, so a cirlce looks like a hexagon
essentially the distance (between two objects) is the 'hypotenuse' and the components of x and y (of that distance) are h x cos(theta) and h x sin(theta) respectively
is there any graphical representation i can see
wait
"are h x cos(theta) and h x sin(theta) respectively "
what do u mean
"hxcos"
h * cos(theta)
cos(theta) = adj/hypot
of a right angled triangle
tbh just go through the khan section
k
it will explain all this
sry for kinda wasting any time
all good
k
u do unity right?
I don't typically use game engines for graphics
i literally was working on a chess game in unity lol
oh
i just saw u in the mutual server
yeah ill occasionally ask questions in those servers just to get help as they know the required math very well
kk
well ig thats it
thnx
cya
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hello
evaluate it inside out
@balmy geyser Has your question been resolved?
uhh
i got it the first one
but now idk wtf im doing w this one
okay i looked at the circle thign and got pi over three
but i had to like
look at the Y coordinate from the sin
and then match it witht he X for the cos
why is that
why is what?
i solved it by thus
but u see 1/2 is in the Y coordinate for the first match
but the final its in the X
why is that
@balmy geyser Has your question been resolved?
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.reopen
✅
my bad gang
Can you tell me what's your problem again?
@balmy geyser Has your question been resolved?
oh wait actually it was this too
lik
why do i have to bounce between X and Y
is it cause of some rules with Sine and Cosine
what do you mean "bounce" ?
do you know what $\sin^\inv$ notation means?
riemann
in words
what is "there"
what's "it"
7/9?
where does 7/9 come in?
thats a separate questions
i had to move on since i aint rlly get an answer for the other one
right. you answered this to "what's your problem"
what question does this image pertain to then?
this one
do you know what sin(pi/6) is?
you labeled the angle
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we are finding r(x), the black line on the diagram. but why is y0 = x0?
the diagonal line is y=x
one end of r is on the line y=x
yes
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Hi I need help
Can someone here please explain to me partial ordered sets in simple terms? I'm too stupid to figure it out on wikipedia
If I understand somewhat... a partial ordered set is a relational set that comes about by a relational operation applied to a set
so if we apply less than 1 to a set of numbers {1, 2, 3}
the partial ordered set would be {NULLSET}?
or if we apply less than 2 to the same set we get
{{1, 2}}
We're not talking about the same thing. Have a reference for this?
In mathematics, especially order theory, a partial order on a set is an arrangement such that, for certain pairs of elements, one precedes the other. The word partial is used to indicate that not every pair of elements needs to be comparable; that is, there may be pairs for which neither element precedes the other. Partial orders thus generalize...
Appreciate your fast help by the way 🙂
Okay. So yeah you seem to want some kind of operation which takes a set and returns one. That's not what a poset is
What's a poset? 🙂
A poset is a set that is equipped with a "less than" operation
{1,2,3} can be made into a poset by saying 1 < 2, and 2 < 3
Or even by saying 3 < 2, 2 < 1 if you want
Okay, so it's a set where the elements are ordered by a relation?
How is 3 < 2 or 2 < 1?
You can order your elements any way you want. There's no need to stick to a rule if you don't want to
Right. Now, we're talking about a partially ordered set. So the order operation can also be like "idunno" for some elements
We can say that 2 < 1, and 3 is not greater than, less than, or equal to 2 and 1.
That's a partial order on {1,2,3}
that's for a different, arbitrary definition of < that differs from the one you are used to, to be clear
Because I said it is, haha
Oh okay
For my version of <
Oh, so the relational operation is defined by the creator of the set?
And that was just an example?
So is the set of all whole numbers ({1, 2, 3, ..., infinity) a partially ordered set ordered by < (being our conventional definition of less-than)?
Yep! Your usual idea of < is a partial order
Okay great, I really appreciate it.
It's also a strict order, because it can order every element
I'm about to start college and I want to major in math and physics... seems I got a lot to learn lol
But this Discord seems like it'll be very helpful
Oh yeah this place is great. Studying ahead?
Yeah I start in August, I haven't been in school in over 4+ years. I'm 21 now
Kind of worrying considering I only know basic trigonometry calculus algebra but I want to learn more.
I think math is a great topic to increase our abilities intellectually so I want to study it more.
@placid zinc so a total ordered set is the requirement that all members of the set order satisfy the relational operation? While a partial order is only that some do?
Perfect.
*total
@placid zinc thank you for real. I'm grateful for your quick help 🙂
Np. Feel free to ask if you have anything else!
@placid zinc will do 😉
Once again really appreciate it, this place seems like a great place to be on while I'm studying
I'm a complete noob lol
I took my math placement and got like a 50%
had no idea some of the stuff it was asking me...
like basic simplification of polynomials
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I do not understand any 8th grade math I have a 57 in the class I need a 70
start watching and doing problems
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i need a refresher in what the signs mean
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you mean h?
missing a +6
wait wdym
what is 6 when
x= i don't even care what this is
the value of x has no impact on 6
6 is 6
oh so id just add a 6 in there
same principle as you'd apply when finding
y = x + 6
when x=0
6 is 6
are you required to do this using first principles/limit definition?
are you not allowed to use more efficient stuff like power rule?
i think we learn the power rule next unit
so we just use the first way rn
ah yea i remember
haha
does this mean if i simify this
the bottom one
ill be one setp closer
yeh
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That’s what I have so far, but it’ll leave me with 300x which is not good
I need the x’s to cancel and I’m 3 into these already and they aren’t, unless I’m dramatically screwing up
Lets start directly from the definition
Distance(P,F1) + Distance(P,F2) = 10
sqrt((x+3)² + y²) + sqrt((x-3)²+y²) = 10
Yep yep
sqrt(x²+6x+9+y²) + sqrt(x²-6x+9+y²) = 10
Square both sides:
(x²+6x+9+y²) + 2sqrt(x²+6x+9+y²)sqrt(x²-6x+9+y²) + (x²-6x+9+y²) = 100
Oh you’re going that way
Okay
Yeah it’s that that’s such a long term
My teacher moves it to one side and then squares so it removes one of the radicals, and then moves the remaining terms around and does it again to clear the last radical
Square both sides:
2x²+18+2y² + 2sqrt(x²+6x+9+y²)sqrt(x²-6x+9+y²) = 100
100 - 2x² - 18 - 2y² = 2sqrt(x²+6x+9+y²)sqrt(x²-6x+9+y²)
50 - x² - 9 - y² = sqrt(x²+6x+9+y²)sqrt(x²-6x+9+y²)
Square both sides:
(50-x²-9-y²)² = (x²+6x+9+y²)(x²-6x+9+y²)
Yeah I see what you mean
This does work but its a lot of steps
All the other terms cancel and you're left with the form of an ellipse
Yeah, I feel like I’m so close on the other way and then I just run into the regular non exponent x terms not properly canceling for some reason
Ok I see what you're doing that's actually a much easier way
Shouldn't you have 12x
On the left?
Oooo where’s that
12x = 100 - 20sqrt((x-3)²+y²)
Oh my god yes
6+6=?
Yeah wow
Yeah that solves it
Wow you’re the best, I must have made that same mistake in the same area
I can’t thank you enough !
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How do you prove that the line passing through ax+by+c=0 and lx+my+n=0, (where, -a/b ,not equal to -l/m) can be written as (ax+by+c)+k(lx+my+n)=0
Were I can study for a quadratic math test?
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@amber epoch Has your question been resolved?
A line that passes through another line is the same line
What do you mean it “passes through” ax+by+c= 0
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Stuck on how to find x, I'm trying to find a proportionality ratio but cant seem to get one
got to this but this ratio wont work
I dont think
I could be wrong
its def wrong because it would make x 5.3 which is def incorrect
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We weren't taught differential equations of higher order derivatives. Is there an easier way to match the quations like c and e without solving for the general form and then matching?
Also, I figured out that a is very close in form to III when solved, but my solution had an absolute value sign around the x that would make it not match. Did I do something wrong in my work or is this correct?
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why can you write the sum of 3 raised to n-1 over 4^n+1 from n=1 to infinity as the sum of 3^n over 3x4x4^n from n=1 to infinity
,tex .exp rules
riemann
wat
use row 1 with a=3 and x+y = n-1
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why do you think it doesn't exist?
do you know squeeze theorem?
well it's not a continuous function over the reals, but you can take the discrete limit if you'd like
yeah
try using squeeze theorem
,w graph (-1)^x/x
,w verify (-1)^x/x > -1/x
i guess it is zero
is -1/x < (-1)^x/x
<=
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Hi, I’m quite new to completing the square method. I am unsure of how the answer sheet got 49/8 and then 49/16. Please kindly explain that part
Where did you get the -2, and why did you * the bottom part of the fraction only? Also how did you get 80/16
this solution
But why 49/8? And how did they get 49/8?
Mr gamer explained it
but 49/8
is just combining terms together
so in the solutio
nin line 5
they have -2*(9/16) -5
and by combining those terms
you will get -49/8
Oh
Can u breakdown this?
Sure
ok
so
they first multiply -2 with 9/16
which becomes -9/8
and then to subtract 5
it needs to be put to the same denominator
so -5 can be rewritten as -40/8
because dividing -40 by 8 gives -5
and thenn they just combine the fractions
(-9+40)/8
For the -40/8 is there a way to get it or is it just by knowledge
Yup
yeh
so because 5 is a whole number
who can just multiply and divide by 8 at the same time
because 40/8 is the same as 5
basically look at the denominator u need
and multiply and divide the number by that
Right so because the first fraction is this , then u have to make the denominator the same so you it becomes 5/1* 8
not quite
you cant change the number
because then it would become a different question
so you need to multiply by 8/8
which wouldnt change the question as 8/8 is 1
but 5/1 times 8/8
becaomes 40/8
which is what you need to combine the fractions
Haha im confused
by which part
This
Oh u cannot * the top?
depending on which one u intended to multiply
ye u can
sorry
just cant rlly tell with text
but
either way
it doesnt matter
multiplying top gives you 40/1
and bottom gives you 5/8
neither of those equal 5
so you cant do it
Ok
so to get what u need
you need to multiply top and bottom
by 8
i.e multiply by 8/8
I can’t really visualise it
Right
multiplying by 8/8 doesnt actually change the number
but it allows you to combine the fractions
Yes correct i understand it now
But now how did you get 9/8?
Is it okay if you do the entire question step by step and maybe explain along the way
Right
2x^2 -3x-5 =0
so for completing square method
you get the middle term
which is -3x
and take the -3
divide by two and square it
so (-3/2)^2
Yup
which becomes 9/4
but you cant just add a number in
so you have to subtract it aswell
so you get
2x^2 -3x +9/4 -5 -9/4
Correct
oh wait
forgot a step
ok
so first
u need to dtake out two
2x^2-3x-5=0
2( x^2 -3x/2) -5 = 0
then you can complete the square
wheres the Q
2(x^2 -3x/2 +9/16-9/16) -5 = 0
.
now you can factor
2[(x-3/4)^2 -(-3/4)^2] -5 = 0
from here its what I explained earlier
just combining the terms together
@burnt dust Has your question been resolved?
Sorry just trying to do the question with what you have given me give me a moment
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