#help-0

1 messages · Page 200 of 1

spare abyss
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wait why don't i just set it firmly equal to 90

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nvm that doesn't work

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I don't know how to incorporate the fact that i'm trying to calculate an average in my algebra

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(178.03920 + x)/3 = 90

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178.03920 + x = 270

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x = 91.9608

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I guess could someone check this?

fierce prairie
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did you solve that by hand?

spare abyss
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i just did it here

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calculator

fierce prairie
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okay good

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well the process looks right

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that is indeed how you find an average

spare abyss
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ok i'm a bit rusty on math since i haven't taken classes since high school

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thank you

fierce prairie
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np

spare abyss
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drowsy sedge
#

Hey everyone, I am having a bit of trouble formally proving inequalities for things like the Direct Comparison Test, I formulated this inequality, and did not really know how to prove it (well, I tried just doing algebra, but I got it being false so im doing something wrong)

Here is it in Symbolab:

drowsy sedge
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well actually, nevermind I think I solve this one but in generally proving inequalities can be challenging

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if anyone has a general guide that would be nice/tips/explanation for this one (although I got it, seeing someone else do it is nice)

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alpine sable
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need help

lone heartBOT
alpine sable
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by calulating the chain rule on BP

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I cannot find that -1 is from where ?

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can someone show the details for this step

lone heartBOT
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@alpine sable Has your question been resolved?

alpine sable
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<@&286206848099549185>

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@alpine sable Has your question been resolved?

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stiff jasper
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How do I figure this out

lone heartBOT
edgy cliff
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C

stiff jasper
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Yeah but why

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Because the max f(x) value is 18?

edgy cliff
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no

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and you can't find which is its max

stiff jasper
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Oops

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I meant between the interval

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Is it bc the y values between [1,3] have to be in between 10-18?

edgy cliff
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no, it could have other value

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but between [1,3] ,it must have 10-18

stiff jasper
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Hm I kind of see it

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So the graph can go up and down but since f(3) is positive then 17 has to be a solution??

last ether
edgy cliff
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Not exactly

last ether
last ether
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You're not guaranteed f(1) or f(18) are maxes or mine

edgy cliff
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yes

stiff jasper
last ether
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It could look like this

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However IVT primarily focuses on values between f(1) and f(3)

last ether
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Stating that there exists all values between f(1) and f(3)

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But that does not mean that the function is strictly confined f(1) < f(x) < f(3) for all x in (1,3)

last ether
stiff jasper
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Hmm, ok

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Im still slightly confused but I’ll get the hang of it 😭

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Ty

last ether
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What part of it is confusing

stiff jasper
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Like

stiff jasper
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Is it just that values exist but they’re not guaranteed to be between f(1) and f(3)

last ether
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No IVT guarantees that as long as f(x) is continuous in [a,b], f(x) will kick out all values between f(a) and f(b) sometime within the interval

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They guarantee only the outputs between f(a) and f(b)

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Anything out of that, not guaranteed

last ether
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Output

stiff jasper
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Oh ok

last ether
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Like if put in 2 into f(x) and it kicks out whatever f(2) is

stiff jasper
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Ohhhhj now I get it 😭

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Thank u 🦦

last ether
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Np

stiff jasper
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💪💪

last ether
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Close the channel if you're done

stiff jasper
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.close

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high falcon
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Hi

lone heartBOT
high falcon
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I need help with this differential equation

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I have tried to do it by using the partial derivative method but it doesn't work

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<@&286206848099549185>

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sick thistle
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I need help with Average Rate of Change. I’m stuck on the part where you factor the numerator. The problem is find the ARC of 9x^2-8 on the interval [1,t]

sick thistle
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<@&286206848099549185>

remote heron
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@sick thistle so you need to factor $9t^2-9$?

ocean sealBOT
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jan Niku

sick thistle
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Yes I believe

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I’m little confused and hoping someone can teach me finding the ARC using an interval

remote heron
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can you identify anything common between the two terms

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i mean youre almost there

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you just need to factor

sick thistle
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Would it be

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9(t- )(t+ )

remote heron
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i mean youre missing the number but yea

sick thistle
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Is the number 3?

remote heron
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no

sick thistle
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Or is it 1 because t is 1

remote heron
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try factoring 9 first

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9(t^2-1)

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how do you factor t^2-1

sick thistle
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(T+1)(t-1)

remote heron
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yea

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so $9t^2-9 = 9(t-1)(t+1)$

ocean sealBOT
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jan Niku

sick thistle
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So the -9 just disappears?

remote heron
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its still there

sick thistle
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Oh

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But the denominator is (t-1) and that cancels out the one on top

remote heron
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it does

sick thistle
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Then it equals 9t-9

remote heron
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yea

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wait

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no

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sign error

sick thistle
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9t+9

remote heron
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9(t+1) yea

sick thistle
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You’re a genius

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I venmo you

remote heron
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you did all the work

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venmo urself

sick thistle
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You helped me better than the teacher

remote heron
sick thistle
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@remote heron can I dm you with questions?

remote heron
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im probably too busy to help like that

sick thistle
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Dang dang

remote heron
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just killing time before bed right now

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but you should ask more on the server happy

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there are other helpers

sick thistle
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Makes sense

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Can I ask you another question?

remote heron
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hm?

sick thistle
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This one I’m completely lost in

remote heron
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what question

sick thistle
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Composite function?

remote heron
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composition

sick thistle
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Oh wait

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Oh wait

remote heron
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you put one function as the input of another

sick thistle
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29(3t+1.1)^2-152(3t+1.1)+91

remote heron
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sure

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idk if you have to simplify

sick thistle
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Gotcha

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😚

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You’re the best amigo

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alpine sable
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hello

lone heartBOT
alpine sable
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does anybody know how to do these questions?

tacit arch
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,rotate

ocean sealBOT
alpine sable
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im not really sure if i should firstly simplify or cancel the common factors

tacit arch
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Doesn't really matter too much

alpine sable
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should i firstly simplify and then multiply?

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like in question a should i simplify the 3 x square of 40 or take out the common factors straight away

vale wigeon
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you meant "square root of 40" not "square of 40"

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"square of 40" would mean 40^2

alpine sable
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yes i meant that

vale wigeon
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anyway, there is no prescribed order in which to do these things

alpine sable
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so i can just do any?

vale wigeon
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if you can cancel out a pair of matching factors then go for it, if you can simplify a root then also go for it

alpine sable
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alright thanks

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do you know how to do question 3 e

alpine sable
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for some reason i got 42 over square root of 3

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<@&286206848099549185>

edgy cliff
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wait

alpine sable
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alright

edgy cliff
alpine sable
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oh thank you very much

edgy cliff
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you're welcome

vale wigeon
lone heartBOT
# edgy cliff

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

alpine sable
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can i ask

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nvm i figured it out

alpine sable
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rn i have holidays

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im just studying through textbook in case suprise test

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when i go back to school

tacit arch
vale wigeon
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still only hurts you to have shit like this handed out

alpine sable
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how

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i didnt know how to do working

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now i know

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bcz i was first doing common factor

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instead of simplyfying

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  • im still gonna try to do the question by myself and do more of the similar ones
edgy cliff
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it's flexible😊

lone heartBOT
#

@alpine sable Has your question been resolved?

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analog nymph
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dont even know where to begin

lone heartBOT
frank apex
analog nymph
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no

frank apex
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integral of xf(x) dx

analog nymph
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oh wait

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got it! thank you

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wheat isle
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i just drew a perpendicular line there because im not what else to do

wheat isle
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should i label the sides ABC and abc

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a/sinA = b/sinB

tacit arch
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does that give you x?

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it really doesn't matter what variable names you give

wheat isle
tacit arch
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it'd help if you found the length of the vertical red line you drew

wheat isle
wheat isle
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and the length 10.7cm wouldnt help

tacit arch
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oh you're right i'm completely wrong.

tacit arch
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10.7 / sin(...) = x / sin(...)

wheat isle
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wouldnt sinA = h/b

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or do we disregard the perpendicular line because its not important here

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oh sinA is just 43.35 degrees

wheat isle
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i think im confusing myself with the labelling of the triangle

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did i label it wrong

wheat isle
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so uh

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did i label something wrong

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because 10.7cm is side c

tacit arch
wheat isle
#

ahhhh okay

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this is what i have

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$\frac{x}{\sin\left(43.45\right)}=\frac{10.7}{\sin\left(79.2\right)}$

ocean sealBOT
#

waterr beam

wheat isle
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what should I do next?

tacit arch
#

do you know what sin(43.45) means?

wheat isle
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xsin(43.45)?

wheat isle
tacit arch
#

right

wheat isle
tacit arch
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yes

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solve for x

wheat isle
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0.69?

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That’s what sin(43.45) is equal to

tacit arch
#

if your equation were instead x/2 = 3, would you know how to solve for x?

wheat isle
#

Yes

tacit arch
wheat isle
#

Alright

tacit arch
#

great

wheat isle
tacit arch
#

yes

lone heartBOT
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@wheat isle Has your question been resolved?

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stark lagoon
lone heartBOT
stark lagoon
#

Is inverse of f’(-1) equal to 1/13???

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<@&286206848099549185>

tiny robin
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(the first derivative of inverse of f) of -1?

edgy cliff
tiny robin
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and use 1/f'(x).

edgy cliff
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my fault

lone heartBOT
#

@stark lagoon Has your question been resolved?

tiny robin
#

wait, i guess the first one is correct.

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solve $f^{-1}(x)$ as you did before, then use this formula.

ocean sealBOT
#

Z_char

edgy cliff
tiny robin
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well, but you can not simply = 1/f'(x).

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how can i explain this...

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if you have a function, but inverse if not a function. you may have three different [f-1(x)]'(-1), right?

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but follow you rule, it will be only one.

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well, a simply explanation is you do not have this rule.(

edgy cliff
tiny robin
#

like i showed before.

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you got (f-1)(-1) first, then get [f-1]'(x).

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you need to follow this rule.

edgy cliff
#

i seecatthumbsup

tiny robin
#

a wrong sample for this

tiny robin
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alpine sable
lone heartBOT
alpine sable
#

Why is it wrong to do something like:
M_a / M_b = 5/6 -> 6M_a = 5M_b

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S_a / S_b = 2/3 -> 3S_a = 2S_b

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Then money per student would be:
6M_a/S_a = 5M_b/S_b

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Subbing the values of S_a i'd hae:
6M_a/ (2/3 S_b) = 5M_b / S_b
so the ratio between the money per student on team A to team B would be:

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$9M_{a/p} = 5M_{b/p} \to \frac{M_{a/p}}{ M_{b/p}} = \frac 59 \text{ or } 5:9$

ocean sealBOT
#

!Kiz__

frank apex
alpine sable
#
S_a and S_b is the students in team A and B
M_(a/p) and M_(b/p) is the money per student for team a and b```
alpine sable
frank apex
#

idk about all the sentences above it but that equation transfer is right

alpine sable
#

Well that's not the right answer

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The answer is B or something

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Yeah i think it's B

alpine sable
frank apex
#

can't you just use the values they give you, and set the multiplier to be 1
5 dollars for A, 6 dollars for B
2.5 dollars each for A, 2 dollars each for B
2.5/2 = 5/4

alpine sable
#

I still don't get why what i did was wrong though

frank apex
#

for the life of me I can't find the error

alpine sable
#

💀 idk why tf i wrote that

alpine sable
#

It should've been M_{a/p} = M_a/ S_a

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M_{b/p} = M_b/ S_b

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M_b = 6/5 M_a and S_a = 2/3 S_b

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then divide M_{a/p} and M_{b/p}

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,w (3/2)/ (6/5)

alpine sable
#

@frank apex thank you for the extra pair of eyes btw!

frank apex
#

yw

alpine sable
#

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celest perch
lone heartBOT
celest perch
#

how do i find the inverse of this

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@celest perch Has your question been resolved?

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sand scarab
#

can someone please help me?

lone heartBOT
sand scarab
#

<@&286206848099549185>

earnest saddle
#

!15m

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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

sand scarab
#

💀

earnest saddle
#

what have you tried @sand scarab

sand scarab
#

everything i just can't seem to get the answer

earnest saddle
#

can you find <prq?

sand scarab
#

no i need help

earnest saddle
#

you know angle subtented at centre is twice angle subtended on circumference?

sand scarab
#

kinda

earnest saddle
#

then can you find $\anglePOQ$

sand scarab
#

okay thank youu

earnest saddle
#

!nosols

lone heartBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

hoary ether
#

I didn't copy!

earnest saddle
#

do you understand English? @hoary ether

hoary ether
#

No,I'm from Russia

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I use Google translator

delicate yew
hoary ether
#

also translator

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and

mint sierra
#

oh

delicate yew
hoary ether
earnest saddle
hoary ether
#

I went there

#

5 years already

hoary ether
earnest saddle
#

.close

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alpine sable
#

Need help solving this one.
Cannot use ranks and dets. Only concepts from row echelon form

alpine sable
#

I thought that if I will be able to prove that A^t and A has the same leading entries then I will be able to prove it. But can't think of a way without using ranks

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@alpine sable Has your question been resolved?

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@alpine sable Has your question been resolved?

lone heartBOT
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@alpine sable Has your question been resolved?

alpine sable
#

HELP SOMEONE??

#

How can I prove that?

#

Let $A\in M_{n\times n}\left(\mathbb{R}\right)$ such that $Ax=\vec{0}$ has infinitely many solutions.

Do $A^{t}x=\vec{0}$ has infinitely many solutions?

Note. I can't use ranks and dets. Only things I can deduce from row echelon form. For example, I can't use the theorem $rank(A)=rank(A^t)$

ocean sealBOT
#

CStudent

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@alpine sable Has your question been resolved?

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tacit arch
#

<@&268886789983436800>

night geyser
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.close

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vale pulsar
#

How should I find function of g?

lone heartBOT
echo socket
#

Well first of all we are gonna need g(1) to know what g is

#

For that you can let x = 1 yielding 2g(1) = 6 and g(1) = 3

#

So, simply isolate g(x) in g(x) + 3 = 4x + 2

vale pulsar
#

To find value of g(1)?

echo socket
#

So that I could solve for g(1)

#

Yes

vale pulsar
#

.close

lone heartBOT
#
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alpine sable
lone heartBOT
ocean hawk
alpine sable
#

<@&286206848099549185>

lone heartBOT
#

@alpine sable Has your question been resolved?

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alpine sable
lone heartBOT
alpine sable
#

Im atuck

#

Stuck

alpine sable
#

.

alpine sable
wary stream
#

That step is not legal. Because you went from a subtraction expression to multiplication

alpine sable
#

Noo

#

I wasnt tryna subtract it

#

Wait

alpine sable
#

Its still like( -1)

wary stream
#

The original problem, you factored out -1, it's separated by subtraction

alpine sable
#

This is what I was tryinf to do

wary stream
#

You can't make it multiplication

alpine sable
#

I grouped them doe

#

Because ai dont know how to factorize 4 terms

#

And for 4 terms

#

You group them to two

wary stream
#

I know how factor by grouping works

tiny robin
#

well, you have $x^2 - (y+3)^2$.

ocean sealBOT
#

Z_char

wary stream
#

When you do this, there's an invisible plus sign you need

#

(x^2 - y^2) + (-6y - 9)

alpine sable
#

So whenever you group two terms in factorization

tiny robin
#

then use formula of the difference of square.

alpine sable
#

You put a + in between?

wary stream
alpine sable
wary stream
alpine sable
#

,w (x^2-y^2) (-6y-9)

alpine sable
#

Nvm anyway thanks

wary stream
alpine sable
#

Yea

wary stream
#

(x^2-y^2) (-6y-9) = (x^2-y^2) * (-6y-9)

#

Not (x^2-y^2) + (-6y-9)

alpine sable
alpine sable
#

Ok I tet it

#

Thanks

#

.close

lone heartBOT
#
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modern sedge
#

next time picture please

marsh rapids
#

Don't make people download files. Post a picture/screenshot instead

reef tendon
#

sorry

lone heartBOT
#
Channel closed

Closed due to the original message being deleted

modern sedge
#

you will have to claim new channel now

reef tendon
#

okej

#

np

marsh rapids
#

Generally avoid deleting your original message for this reason

#

Edit it instead

lone heartBOT
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alpine sable
#

Why do sine and cosine normally relate to an x and y value? (im new to trig)

tacit arch
#

like $y = \sin(x)$ ?

ocean sealBOT
#

riemann

alpine sable
#

yeah

tacit arch
#

x and y are just names for different numbers

#

do you know input/output tables?

alpine sable
alpine sable
#

ive worked with linear equeations

tacit arch
#

like $y = x^2$ is a function

ocean sealBOT
#

riemann

alpine sable
#

Well yes

lone heartBOT
tacit arch
#

delete your message

lone heartBOT
tacit arch
#

to plot the graph of y = sin(x), plot a few points

alpine sable
#

k

#

in radians or degrees btw

tacit arch
#

radians usually

alpine sable
#

k

#

it makes a sine wave

tacit arch
#

but degrees is fine too if you know how to convert

alpine sable
#

done

tacit arch
alpine sable
#

Not really

#

Like i mean in this sens

#

btw would u understand in a coding sense

tacit arch
alpine sable
#

its not really a question, its just a statement ill send that im trying to understan

#

So while trying to find the shortest distance between a wall(which from our position we dont know where it is), why would we use sine and cosine to determine shortest values for these.

outer lark
alpine sable
#

We are a player on a grid trying to "cast" rays to draw walls and give them size based on their distance.

#

this is called a raycaster

#

Im kinda making the problem a bit harder sry.

#

but any help is appreciated

outer lark
#

no, posting the original question gives context to what you want to do, and helps to avoid the xy problem :D

alpine sable
#

k

#

//makes a ray and draws it function ray(angle, i) { let x = player.x let y = player.y while (map[Math.floor(y)][Math.floor(x)] == 0) { x += Math.cos(angle)/wallSize/4 y += Math.sin(angle)/wallSize/4 } if (Math.abs(Math.round(x)-x)>Math.abs(Math.round(y)-y)) { y = Math.round(y) } else { x = Math.round(x) }

this might help if u understand, but its a function(in programming context) that draws rays.

#

just realized ur in the unity discord, which is literally what i was just doing and i still have it open lol

tacit arch
#

where's the math question

outer lark
#

I think I get what you mean and in answer to your original question, if you have a coordinate system, (x,y) and you have two objects in that system, you can relate x=rcos(theta) and y=rsin(theta), where r is the magnitude of distance between the two entities

modern sedge
#

are you confused about this part?

outer lark
#

in your code it looks like that is the iteration between the player position and the wall.

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
outer lark
#

have you played around with the values and checked the outcome?

alpine sable
#

No

outer lark
#

give that a go

alpine sable
#

k

outer lark
#

just comment what it was originally ;P

alpine sable
#

like which value should i try

alpine sable
outer lark
#

just play around with it

alpine sable
#

No like which value here:
x += Math.cos(angle)/wallSize/4
y += Math.sin(angle)/wallSize/4

#

the 4?

outer lark
#

ye

alpine sable
#

x += Math.cos(angle)/wallSize/0.1
y += Math.sin(angle)/wallSize/0.1

#

x += Math.cos(angle)/wallSize/10
y += Math.sin(angle)/wallSize/10

Note: Making it higher has resulted in a large performance loss

#

Its smoother(walls are) but laggier

outer lark
#

expected

outer lark
alpine sable
#

ig

#

Thats what it does

outer lark
#

opposite for the secondary screeny

alpine sable
outer lark
#

well its incrementing at a very low number so there will be lots of instances I suppose? like going from 0->1 in gaps of 0.5 only takes 2 iterations, but going from 0->1 in gaps of 0.1 takes 10

alpine sable
#

i see

#

btw can we go back to the original question,which was why the x and y correspond to cosine and sine

outer lark
#

oh I answered it earlier in general terms

alpine sable
outer lark
#

hmmm

alpine sable
#

im kinda new to trig and im self teaching

outer lark
#

if you go through the khan academy trig section im sure it would help

alpine sable
#

love it btw

#

but the vids are rly old and quality is low, so a cirlce looks like a hexagon

outer lark
#

essentially the distance (between two objects) is the 'hypotenuse' and the components of x and y (of that distance) are h x cos(theta) and h x sin(theta) respectively

alpine sable
#

wait

#

"are h x cos(theta) and h x sin(theta) respectively "

what do u mean

#

"hxcos"

outer lark
#

h * cos(theta)

alpine sable
#

k

#

h is wat

outer lark
#

cos(theta) = adj/hypot

#

of a right angled triangle

#

tbh just go through the khan section

alpine sable
#

k

outer lark
#

it will explain all this

alpine sable
#

sry for kinda wasting any time

outer lark
#

all good

alpine sable
#

k

outer lark
#

always fun looking and trying to understand code

#

don't think I did a very good job NervousSweat

alpine sable
#

u do unity right?

outer lark
#

I don't typically use game engines for graphics

alpine sable
#

i literally was working on a chess game in unity lol

alpine sable
#

i just saw u in the mutual server

outer lark
#

yeah ill occasionally ask questions in those servers just to get help as they know the required math very well

alpine sable
#

well ig thats it

#

thnx

#

cya

#

.close

lone heartBOT
#
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balmy geyser
#

hello

lone heartBOT
balmy geyser
#

i needed help with this if theres any one that can assist?

tacit arch
#

evaluate it inside out

lone heartBOT
#

@balmy geyser Has your question been resolved?

balmy geyser
#

uhh

#

i got it the first one

#

but now idk wtf im doing w this one

#

okay i looked at the circle thign and got pi over three

#

but i had to like

#

look at the Y coordinate from the sin

#

and then match it witht he X for the cos

#

why is that

tacit arch
balmy geyser
#

i solved it by thus

#

but u see 1/2 is in the Y coordinate for the first match

#

but the final its in the X

#

why is that

lone heartBOT
#

@balmy geyser Has your question been resolved?

#
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balmy geyser
#

.reopen

lone heartBOT
#

balmy geyser
#

my bad gang

deep moon
#

Can you tell me what's your problem again?

lone heartBOT
#

@balmy geyser Has your question been resolved?

balmy geyser
#

just find that out i guess

balmy geyser
#

lik

#

why do i have to bounce between X and Y

#

is it cause of some rules with Sine and Cosine

tacit arch
#

do you know what $\sin^\inv$ notation means?

ocean sealBOT
#

riemann

tacit arch
#

in words

balmy geyser
#

like i started there right

#

looked at the Y

tacit arch
balmy geyser
#

and used it for the X

#

its written on the screen

#

at the start thing

#

i wrote it

tacit arch
balmy geyser
#

and some arrows

#

dawg

tacit arch
tacit arch
balmy geyser
#

thats a separate questions

#

i had to move on since i aint rlly get an answer for the other one

tacit arch
tacit arch
balmy geyser
tacit arch
#

do you know what sin(pi/6) is?

tacit arch
lone heartBOT
#
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analog nymph
#

we are finding r(x), the black line on the diagram. but why is y0 = x0?

alpine sable
#

the diagonal line is y=x

analog nymph
#

could you elaborate?

#

what does the line y=x has to do with r(x) tho

tacit arch
analog nymph
#

ye

#

so on the y=x line, x0 = y0?

tacit arch
#

yes

lone heartBOT
#

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marble moth
#

Hi I need help

lone heartBOT
marble moth
#

Can someone here please explain to me partial ordered sets in simple terms? I'm too stupid to figure it out on wikipedia

#

If I understand somewhat... a partial ordered set is a relational set that comes about by a relational operation applied to a set

#

so if we apply less than 1 to a set of numbers {1, 2, 3}

#

the partial ordered set would be {NULLSET}?

#

or if we apply less than 2 to the same set we get

#

{{1, 2}}

placid zinc
#

We're not talking about the same thing. Have a reference for this?

marble moth
#

In mathematics, especially order theory, a partial order on a set is an arrangement such that, for certain pairs of elements, one precedes the other. The word partial is used to indicate that not every pair of elements needs to be comparable; that is, there may be pairs for which neither element precedes the other. Partial orders thus generalize...

#

Appreciate your fast help by the way 🙂

placid zinc
#

Okay. So yeah you seem to want some kind of operation which takes a set and returns one. That's not what a poset is

marble moth
#

What's a poset? 🙂

placid zinc
#

A poset is a set that is equipped with a "less than" operation

#

{1,2,3} can be made into a poset by saying 1 < 2, and 2 < 3

#

Or even by saying 3 < 2, 2 < 1 if you want

marble moth
#

Okay, so it's a set where the elements are ordered by a relation?

#

How is 3 < 2 or 2 < 1?

placid zinc
#

You can order your elements any way you want. There's no need to stick to a rule if you don't want to

#

Right. Now, we're talking about a partially ordered set. So the order operation can also be like "idunno" for some elements

#

We can say that 2 < 1, and 3 is not greater than, less than, or equal to 2 and 1.

#

That's a partial order on {1,2,3}

marble moth
#

But how is 2 < 1?

#

I don't get it

#

lol

vale sapphire
#

that's for a different, arbitrary definition of < that differs from the one you are used to, to be clear

placid zinc
#

Because I said it is, haha

marble moth
#

Oh okay

placid zinc
#

For my version of <

marble moth
#

Oh, so the relational operation is defined by the creator of the set?

#

And that was just an example?

placid zinc
#

Right. We want to make an order here

#

In order to turn {1,2,3} into a poset

marble moth
#

So is the set of all whole numbers ({1, 2, 3, ..., infinity) a partially ordered set ordered by < (being our conventional definition of less-than)?

placid zinc
#

Yep! Your usual idea of < is a partial order

marble moth
#

Okay great, I really appreciate it.

placid zinc
#

It's also a strict order, because it can order every element

marble moth
#

I'm about to start college and I want to major in math and physics... seems I got a lot to learn lol

#

But this Discord seems like it'll be very helpful

placid zinc
#

Oh yeah this place is great. Studying ahead?

marble moth
#

Yeah I start in August, I haven't been in school in over 4+ years. I'm 21 now

#

Kind of worrying considering I only know basic trigonometry calculus algebra but I want to learn more.

#

I think math is a great topic to increase our abilities intellectually so I want to study it more.

#

@placid zinc so a total ordered set is the requirement that all members of the set order satisfy the relational operation? While a partial order is only that some do?

placid zinc
#

Perfect.

marble moth
#

@placid zinc thank you for real. I'm grateful for your quick help 🙂

placid zinc
#

Np. Feel free to ask if you have anything else!

marble moth
#

@placid zinc will do 😉

#

Once again really appreciate it, this place seems like a great place to be on while I'm studying

#

I'm a complete noob lol

#

I took my math placement and got like a 50%

#

had no idea some of the stuff it was asking me...

#

like basic simplification of polynomials

lone heartBOT
#

@marble moth Has your question been resolved?

#
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upper bridge
#

I do not understand any 8th grade math I have a 57 in the class I need a 70

tacit arch
#

start watching and doing problems

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#

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thick egret
#

i need a refresher in what the signs mean

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#

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thick egret
#

.close

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coral prairie
lone heartBOT
coral prairie
#

i was wondering if i got the first step right as x-> 0

gray isle
#

you mean h?

coral prairie
#

yea

#

or like the first step before i simplify

gray isle
#

missing a +6

coral prairie
gray isle
coral prairie
#

ohh wait yea

#

but would i add

#

(x + h + 6)

#

or x+6

#

or h+6

gray isle
#

what is 6 when
x= i don't even care what this is

#

the value of x has no impact on 6

#

6 is 6

coral prairie
#

oh so id just add a 6 in there

gray isle
#

same principle as you'd apply when finding
y = x + 6
when x=0

#

6 is 6

#

are you required to do this using first principles/limit definition?
are you not allowed to use more efficient stuff like power rule?

coral prairie
#

so we just use the first way rn

gray isle
#

mmk.

#

its fine, expanding is just gonna be a pain

coral prairie
#

ah yea i remember

#

haha

#

does this mean if i simify this

#

the bottom one

#

ill be one setp closer

gray isle
#

yeh

coral prairie
#

step

#

bet thanks

#

ima have fun

#

lol

lone heartBOT
#

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winter elbow
#

That’s the problem

lone heartBOT
winter elbow
#

That’s what I have so far, but it’ll leave me with 300x which is not good

#

I need the x’s to cancel and I’m 3 into these already and they aren’t, unless I’m dramatically screwing up

tight locust
#

Lets start directly from the definition

#

Distance(P,F1) + Distance(P,F2) = 10

#

sqrt((x+3)² + y²) + sqrt((x-3)²+y²) = 10

winter elbow
#

Yep yep

tight locust
#

sqrt(x²+6x+9+y²) + sqrt(x²-6x+9+y²) = 10

#

Square both sides:
(x²+6x+9+y²) + 2sqrt(x²+6x+9+y²)sqrt(x²-6x+9+y²) + (x²-6x+9+y²) = 100

winter elbow
#

Oh you’re going that way

#

Okay

#

Yeah it’s that that’s such a long term

#

My teacher moves it to one side and then squares so it removes one of the radicals, and then moves the remaining terms around and does it again to clear the last radical

tight locust
#

Square both sides:
2x²+18+2y² + 2sqrt(x²+6x+9+y²)sqrt(x²-6x+9+y²) = 100

100 - 2x² - 18 - 2y² = 2sqrt(x²+6x+9+y²)sqrt(x²-6x+9+y²)

50 - x² - 9 - y² = sqrt(x²+6x+9+y²)sqrt(x²-6x+9+y²)

Square both sides:
(50-x²-9-y²)² = (x²+6x+9+y²)(x²-6x+9+y²)

#

Yeah I see what you mean

#

This does work but its a lot of steps

#

All the other terms cancel and you're left with the form of an ellipse

winter elbow
#

Yeah, I feel like I’m so close on the other way and then I just run into the regular non exponent x terms not properly canceling for some reason

tight locust
#

Ok I see what you're doing that's actually a much easier way

#

Shouldn't you have 12x

#

On the left?

winter elbow
#

Oooo where’s that

tight locust
#

12x = 100 - 20sqrt((x-3)²+y²)

winter elbow
#

Oh my god yes

tight locust
#

6+6=?

winter elbow
#

Yeah wow

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Yeah that solves it

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Wow you’re the best, I must have made that same mistake in the same area

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I can’t thank you enough !

tight locust
#

Lol

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It's always the basic arithmetic

lone heartBOT
#

@winter elbow Has your question been resolved?

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amber epoch
#

How do you prove that the line passing through ax+by+c=0 and lx+my+n=0, (where, -a/b ,not equal to -l/m) can be written as (ax+by+c)+k(lx+my+n)=0

wheat bear
#

Were I can study for a quadratic math test?

lone heartBOT
#

@amber epoch Has your question been resolved?

lone heartBOT
#

@amber epoch Has your question been resolved?

median oar
#

What do you mean it “passes through” ax+by+c= 0

lone heartBOT
#

@amber epoch Has your question been resolved?

lone heartBOT
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tough gull
#

Stuck on how to find x, I'm trying to find a proportionality ratio but cant seem to get one

tough gull
#

got to this but this ratio wont work

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I dont think

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I could be wrong

#

its def wrong because it would make x 5.3 which is def incorrect

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@tough gull Has your question been resolved?

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sturdy crow
#

We weren't taught differential equations of higher order derivatives. Is there an easier way to match the quations like c and e without solving for the general form and then matching?

sturdy crow
#

Also, I figured out that a is very close in form to III when solved, but my solution had an absolute value sign around the x that would make it not match. Did I do something wrong in my work or is this correct?

lone heartBOT
#

@sturdy crow Has your question been resolved?

sturdy crow
#

.close

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polar trout
lone heartBOT
polar trout
#

why can you write the sum of 3 raised to n-1 over 4^n+1 from n=1 to infinity as the sum of 3^n over 3x4x4^n from n=1 to infinity

tacit arch
#

,tex .exp rules

ocean sealBOT
#

riemann

polar trout
#

wat

left trellis
#

you have 3^n*3^{-1}

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and 4^(n+1) is same thing as 4^n*4^1 and 4^1 is just 4

tacit arch
polar trout
#

ohhhhhhhhhhhhhh

#

okay okay thank you

#

.close

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true sandal
lone heartBOT
true sandal
#

how

#

I thought it was DNE

tacit arch
#

do you know squeeze theorem?

molten pivot
#

well it's not a continuous function over the reals, but you can take the discrete limit if you'd like

true sandal
tacit arch
#

try using squeeze theorem

true sandal
#

,w graph (-1)^x/x

ocean sealBOT
true sandal
#

,w verify (-1)^x/x > -1/x

ocean sealBOT
true sandal
#

i guess it is zero

molten pivot
#

<=

true sandal
#

.close

lone heartBOT
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burnt dust
#

Hi, I’m quite new to completing the square method. I am unsure of how the answer sheet got 49/8 and then 49/16. Please kindly explain that part

molten pivot
#

-2 * 9/16 - 5

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-18/16 - 5

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-18/16 - 80/16 = -98/16 = -49/8

burnt dust
#

Where did you get the -2, and why did you * the bottom part of the fraction only? Also how did you get 80/16

noble notch
#

In their solution

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they added 49/8

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to both sides

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then divided both sides by 2

burnt dust
#

But why 49/8? And how did they get 49/8?

noble notch
#

Mr gamer explained it

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but 49/8

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is just combining terms together

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so in the solutio

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nin line 5

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they have -2*(9/16) -5

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and by combining those terms

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you will get -49/8

burnt dust
#

Oh

burnt dust
noble notch
#

Sure

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ok

#

so

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they first multiply -2 with 9/16

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which becomes -9/8

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and then to subtract 5

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it needs to be put to the same denominator

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so -5 can be rewritten as -40/8

#

because dividing -40 by 8 gives -5

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and thenn they just combine the fractions

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(-9+40)/8

burnt dust
#

For the -40/8 is there a way to get it or is it just by knowledge

noble notch
#

Yeah

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so to add or subtract fractions

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they need to have the same denominator

burnt dust
#

Yup

noble notch
#

yeh

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so because 5 is a whole number

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who can just multiply and divide by 8 at the same time

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because 40/8 is the same as 5

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basically look at the denominator u need

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and multiply and divide the number by that

burnt dust
noble notch
#

not quite

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you cant change the number

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because then it would become a different question

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so you need to multiply by 8/8

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which wouldnt change the question as 8/8 is 1

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but 5/1 times 8/8

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becaomes 40/8

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which is what you need to combine the fractions

burnt dust
#

Haha im confused

noble notch
#

by which part

noble notch
#

ok

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ill try explain diff

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you said

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5/1*8

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which would give you 5/8

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or 40/1

burnt dust
#

Oh u cannot * the top?

noble notch
#

depending on which one u intended to multiply

noble notch
#

sorry

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just cant rlly tell with text

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but

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either way

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it doesnt matter

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multiplying top gives you 40/1

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and bottom gives you 5/8

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neither of those equal 5

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so you cant do it

burnt dust
#

Ok

noble notch
#

so to get what u need

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you need to multiply top and bottom

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by 8

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i.e multiply by 8/8

burnt dust
#

I can’t really visualise it

noble notch
#

those are the steps

burnt dust
#

Right

noble notch
#

multiplying by 8/8 doesnt actually change the number

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but it allows you to combine the fractions

burnt dust
#

Yes correct i understand it now

noble notch
#

ok

#

cool

burnt dust
#

But now how did you get 9/8?

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Is it okay if you do the entire question step by step and maybe explain along the way

noble notch
#

that comes from -2(9/16)

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uh ok

burnt dust
#

Right

noble notch
#

2x^2 -3x-5 =0

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so for completing square method

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you get the middle term

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which is -3x

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and take the -3

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divide by two and square it

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so (-3/2)^2

burnt dust
#

Yup

noble notch
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which becomes 9/4

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but you cant just add a number in

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so you have to subtract it aswell

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so you get

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2x^2 -3x +9/4 -5 -9/4

burnt dust
#

Correct

noble notch
#

oh wait

#

forgot a step

#

ok

#

so first

#

u need to dtake out two

#

2x^2-3x-5=0

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2( x^2 -3x/2) -5 = 0

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then you can complete the square

onyx creek
#

wheres the Q

noble notch
#

2(x^2 -3x/2 +9/16-9/16) -5 = 0

noble notch
#

now you can factor

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2[(x-3/4)^2 -(-3/4)^2] -5 = 0

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from here its what I explained earlier

#

just combining the terms together

lone heartBOT
#

@burnt dust Has your question been resolved?

burnt dust
#

Sorry just trying to do the question with what you have given me give me a moment

lone heartBOT
#
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