#help-0

1 messages · Page 195 of 1

night geyser
#

(since operations on infinity are either infinity or undefined, except division by infinity which typically yields 0)

#

like its totally possible to do this but its just not a useful thing to do and it adds a lot of complications to our system

#

and now all our theorems need to be phrased with "let x be a complex number that's not infinity..."

#

youll see it if you end up doing high-level mathematics (complex analysis, differential geometry, etc) but its not really worth it at a lower level

#

now thats just the riemann sphere - its natural to ask if theres another way to divide by 0 thats more algebraically well-behaved

#

there have been multiple attempts at this

#

one people often reference is wheel theory, which seeks to be an algebraic structure where dividing anything by anything is always allowed

#

theres a problem: wheel theory is utterly useless

#

like it is genuinely just a curiosity, no one has found any serious reason to study it

#

so its been relegated to a "fun fact: we can technically do this" type deal

#

rather than something taken seriously

#

but it does exist, so that you can say "technically, there is a context where division by 0 is perfectly fine"

#

this context is just way, way more complicated than standard arithmetic.

#

tl;dr its possible to do, sometimes (riemann sphere) its even useful, usually it isnt — but at a non-advanced level, its typically more effort and confusion than its worth

#

in general, the answer to "Why can't we do [x]" in mathematics is rarely "it's utterly impossible"; instead, its usually "doing so is way more trouble than it's worth and has some negative consequences on the wider structure"

#

width?

surreal crystal
#

Nah my bad

#

Misunderstood what you were talking about

#

I can add that it can make sense to divide zero

#

1/0 is a distinct object

#

Namely we only really know that 0*(1/0)=1

#

But hey, that means something

#

Just not a number

lone heartBOT
#

@main ruin Has your question been resolved?

lone heartBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

naive aspen
#

Can someone help me with this problem?

lone heartBOT
alpine sable
#

like unsing a secant line

lone heartBOT
#

@naive aspen Has your question been resolved?

#
Channel closed

Closed by @naive aspen

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

zenith olive
#

hi

lone heartBOT
zenith olive
celest blaze
#

Use trigonometric functions

#

tan(x) = o/a

#

We can take o = altitude, and a is the distance

zenith olive
#

how do i find the distance

#

actually what distance am i meang to find

celest blaze
#

Rearrange it:
tan(x)=o/a
tan(x)*a=o
a=o/tan(x)

#

Then plug in o and x

zenith olive
#

how do i find a or x

celest blaze
#

x is angle, o is altitude

zenith olive
#

yea

#

alt is 400

celest blaze
#

Try drawing a triangle to represent the situation

zenith olive
#

is x 5 or 1.5

celest blaze
#

The short leg will be height, the long leg will be distance

#

the angle between the hypoteneuse and the long leg is the angle of depression

zenith olive
#

ok

#

but there ar 2 angle of depressions

celest blaze
#

Plug both numbers into the equation, then find the difference

#

That gives you distance travelled

zenith olive
#

tan(1.5)=400/a
tan(5)=400/a ??

celest blaze
#

yes, solve for a

zenith olive
#

tan(5)=400/a = 4572.020921

#

tan(1.5)=400/a =15275.38372

celest blaze
#

Yes, those are the correct distances

zenith olive
#

= 10703.3628

#

?

celest blaze
#

yes, that is the distance travelled

zenith olive
#

ok so

#

10703.3628 travelled in 2 mins?

celest blaze
#

yes

zenith olive
#

now i just solve for speed

celest blaze
#

Yes, you want to convert that to km/h

zenith olive
#

oh

#

right

#

uhhh

#

ii think i did smth wrong

#

10703.3628 divided by 2

#

thats in 1 min

#

5351.6814

#

oh wait no

#

right

#

and times that by 60

#

321100.884

#

m

#

divide by 1000

#

= 321km/h

#

OHH

#

OKK

#

tysmmm

celest blaze
#

np :)

zenith olive
#

wai

#

could u also help me with another question?

celest blaze
#

Sure!

zenith olive
#

okk tyy

#

gotta find x

celest blaze
#

for the first one, start by ignoring the 60 degree angle

#

use the 3 and the 20 degrees to find the length of the long leg

zenith olive
#

oh no no

#

only c

#

ive done b

celest blaze
#

oh kk

#

Use algebra to write an expression for the long leg

#

l = 10+n

#

then use that as the length to find x

#

tan(25) = x/(10+n)

#

tan(50) = x/n

#

U should be able to solve for x

zenith olive
#

wait uhh

#

yeah im confused

#

how do i find n

#

n = l-10

celest blaze
#

If you isolate n in both of the equations, then equate them, you should get x

zenith olive
#

oh wait right

#

ill write it

#

like this?

celest blaze
#

Yes, now isolate n

#

you want to find x, so it's easier if n is alone on the right

zenith olive
#

oh

#

okay then

celest blaze
#

Bc the lone variable will dissappear

zenith olive
#

uhh for the 2nd one i can solve for n but could u help withe the first please

celest blaze
#

x/tan(25)-10 = n

zenith olive
#

oh yeah i just got that and was gonna ask u if it was right lol

#

the other is x/tan(50)=n?

celest blaze
#

yes

#

next, x/tan(25)-10=x/tan(50)

zenith olive
#

okay

#

i wonder if that legible

celest blaze
#

x*tan(50)/tan(25)-10*tan(50)=x
-10*tan(50)=x-x*tan(50)/tan(25)

#

-10*tan(50)=x(1-*tan(50)/tan(25))

#

Something like than, then isolate x

zenith olive
#

oh ok

#

-10*tan(50)/(1-*tan(50)/tan(25))

#

= x

celest blaze
#

Use Wolfram Alpha to check it

#

It looks right

zenith olive
#

uhh is there like an easier way to solve this perhaps 💀

celest blaze
#

idk, any way I can think of is similar

#

sin(50) = x/n, sin(25) = x/(n+10)
n = x/sin(50), sin(25) = x/(n+10)
sin(25) = x/((x/sin(50))+10)

zenith olive
#

💀💀

#

😭

#

this is too complicated for my pea brain

#

like i couldd use the cosine rule, but im not allowed to use it for this question so 💀

lone heartBOT
#

@zenith olive Has your question been resolved?

zenith olive
#

.close

lone heartBOT
#
Channel closed

Closed by @zenith olive

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

alpine sable
#

Class: Intro to Linear Algebra; Topic: Differential Equations;

alpine sable
#

I would like to verify that this answer is correct. Some other classmates have had issues with this question and I would like verification before taking it to the professor.

limpid turret
#

By inspection I immediately see that y1' is wrong

limpid turret
alpine sable
#

Part 1

#

Part 2

#

Sorry bad scans

limpid turret
#

Step 4

#

Your last -0+1 needs to be -0-1

#

The fact that you still got integer solutions in your cubic was admittedly kinda unlucky

#

@alpine sable

alpine sable
#

your talking about when taking the determinant?

#

@limpid turret

#

I did make that mistake originally. The eigenvalues should be correct though.

#

that notation was from a prior attempt which was missed in correction.

limpid turret
#

Nah the eigenvalues you wrote are for the cubic with the wrong coefficients

alpine sable
#

So matrix A is incorrect?

limpid turret
#

Hold on

#

It's actually correct

#

But only because you wrote -28 instead of +28 in your last submatrix

#

You just got really lucky that the two mistakes worked out there

alpine sable
#

The determinant again. My apologies with that.

#

I corrected it in the step above, but did account for every instance that I missed a sign.

#

Did mess up with the eigenvectors then?

#

Or the diagonal?

limpid turret
#

Your second eigenvector doesn't look right. But I can't really read it

alpine sable
#

Is P called the eigen matrix? P2 can be seen there.

#

P2 was [-1/7, 1, t] but was multiplied by 7 to keep it in whole numbers.

#

and the t removed.

limpid turret
#

But I can see that what you eventually get for P2 is correct

#

P3 is also correct

#

You didn't finish your work

#

$Y=Pe^DP^{-1}$

ocean sealBOT
limpid turret
#

That's why it's not correct

#

You need to find P^-1

#

I'm off to bed now

#

Good luck

alpine sable
#

.close

lone heartBOT
#
Channel closed

Closed by @jolly dagger

Use .reopen if this was a mistake.

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

harsh swallow
#

I need some help. I need to prove that $A \Leftrightarrow B$ but i only know how to prove $\neg A \Rightarrow \neg B$

ocean sealBOT
#

Katharine

worn fox
#

Are we meant to be guessing what you're trying to prove?

echo socket
#

You prove that by showing A -> B and B -> A are both true

harsh swallow
#

sorry i meant to add can i use this

#

i need to prove f is injective if and only if f has a left inverse

#

but i only know how to prove that if f is not injective f does not have a left inverse

worn fox
#

That only proves half of the statement

echo socket
#

By contrapositive that's the same as f has left inverse -> f is injective

#

So now you need to show f is injective -> f has left inverse

harsh swallow
#

i do not know how to because i feel like i'm pulling stuff from my ass when i try

worn fox
#

You have to explicitly construct a left inverse

harsh swallow
#

the problem is i don't see why it is forbidden for a map to have the property of a1 != a2 meaning f(a1) != f(a2) and not a left inverse

#

all i have is these definitions

worn fox
#

Maybe try and see what goes wrong if you tried to find a left inverse of the function f(x) = x² in the reals

harsh swallow
#

that i understand but that is proving the not A therefore not B

#

not injective therefore no left inverse

#

but that doesn't mean injective therefore left inverse

lone heartBOT
#

@harsh swallow Has your question been resolved?

lone heartBOT
#

@harsh swallow Has your question been resolved?

lone heartBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

potent forge
#

Simplify/find the derivative of ln(5x)/x^2. The answer I got was x-2xln(5x)/x^4, but the task says the answer is actually -2ln(5x)/x^3, why did the two x'es above disappear and not the one in ln(5x)?

worn fox
#

Your second term is exactly exactly what they have, simplify using power laws

#

Why you also have a +x is impossible to say without seeing your work

potent forge
#

I used the quotient rule to get the answer I got, since ln(5x)=1/x and 1/x * x^2 becomes x, take that minus ln(5x)*2x which just is 2xln(5x) and all of this divided by x^4

#

Its a fraction, so I had to use the quotient rule to get that answer

#

It just seemed like I fell one step short

#

Which I know

harsh swallow
#

1/x^2

#

not x^2

potent forge
#

But why didnt ln(5x) lose its x?

potent forge
harsh swallow
#

$\frac{d}{dx} \frac{\ln(5x)}{x^2}$

ocean sealBOT
#

Katharine

harsh swallow
#

right?

vale wigeon
#

since ln(5x)=1/x
misuse of equals sign.

potent forge
harsh swallow
#

no the original

potent forge
worn fox
#

Why would it?

potent forge
#

Because 2x isn't raised to any power, just like 5x or the standalone x?

worn fox
#

Also the answer is not just -2ln(5x)/x³

potent forge
#

Thats what it said in the guide

harsh swallow
#

what expression do you have to take the derivative of?

worn fox
#

Your second term has x/x⁴ in it which is 1/x³

vale wigeon
#

but the task says the answer is actually -2ln(5x)/x^3
can you please show us where it says that

worn fox
#

Oh you're not using bracket correctly

vale wigeon
#

yes even if its in arabic we still want to see it

worn fox
#

You mean you got (x-2xln(5x))/x⁴ sully

potent forge
#

Yes

#

That one

keen bear
#

Factor an x out

potent forge
#

Sorry

#

Yes, at the cost of x^4, makes sense, thats why its becomes the power of 3, im just confused why it doesnt affect ln at all since it has an x inside of it as well

keen bear
#

ln(5x) is not a multiplication, it is a function with an argument.

worn fox
#

The 5x can't "see" the division by x⁴

#

It's inside a function that doesn't care what's happening outside

potent forge
#

Ah, I gotcha

#

That makes sense, ill write that down for my notes, thanks dude

keen bear
#

It's like how sin(2x)/x doesn't simplify to sin(2)

potent forge
#

but the final answer, itl be (1-2ln(5x))/x^3 then?

#

Since zac brought up a good point of x/x is 1 and not just, gone

potent forge
#

.close

lone heartBOT
#
Channel closed

Closed by @potent forge

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wraith flame
lone heartBOT
wraith flame
#

Hallo guys can you help me answer no. 9

alpine sable
#

Since we know one officer will be woman already, that leaves us with only 4 possibilities left, two men and two women

wraith flame
#

yes then the probability is 50 50 rigth?

alpine sable
#

50%, 1/2, however you guys write it

#

But yeah

prime badge
#

it's 1/3 tho

lone heartBOT
#

@wraith flame Has your question been resolved?

wraith flame
#

is the answer 1/2 or 1/3?

prime badge
#

it's 1/3

#

like it's not really a contradiction to say 1/2, since they don't say what "randomly" means

#

if it's equally likely to be 1-1, 2-0, 0-2, that's still random

#

but this sort of question is never like that

wraith flame
lone heartBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

wraith flame
#

.reopen

lone heartBOT
#

prime badge
#

man+woman, woman+woman, man+man

#

if they choose in a way that gives these results equal probability, you can say the answer is 1/2

#

and that's still "random"

wraith flame
#

but they already chose one and that a woman and there is just one spot left

prime badge
#

they don't choose like that, they just choose 2 people

#

it's not like they chose one woman

#

they already chose both people

#

maybe they chose 2 women, maybe not, but it's not half and half

#

there's 9 possibilities where one person is a woman

#

call them AB | CDE
AC ,AD, AE, BC, BD,BE, CD,CE,DE

#

3 out of 9 is 2 women

#

that's how you're meant to interpret it

solemn juniper
#

Two child paradox wearing a fake moustache

prime badge
#

girl-boy

wraith flame
# wraith flame

wait but here its asking what is the probability of 2 woman is chosen

prime badge
#

yes

#

conditioned, "updated" on the information that one is a woman, there's no argument about that

wraith flame
prime badge
#

you can't just imagine they chose 1 woman, they already chose both people

#

you're told they are not both men

#

you just examine all possibilities
one thing to notice is you already almost knew what they told you, it was 90% that at least one is a woman anyway

wraith flame
#

now im starting to get it

#

ok now I get it thank you for all the help

#

.close

lone heartBOT
#
Channel closed

Closed by @wraith flame

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tepid aurora
lone heartBOT
tepid aurora
#

Can someone explain how I break the interdemated formula

#

Please

limpid spade
#

,rotate

ocean sealBOT
surreal crystal
#

We can reciprocate the x and set the limit to 0 here

#

Then we can use lhopitals rule easily

random steppe
#

🤓

limpid spade
#

or u can stimulate it into the form of euler limit

tepid aurora
#

Using hospital i must

surreal crystal
#

Its certainly easier with lh

#

Just set x=1/y, then y->0 and its in the form to do lh

placid swallow
#

or with Taylor series

tepid aurora
#

Wait what

lone heartBOT
#

@tepid aurora Has your question been resolved?

lone heartBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

olive kestrel
#

need help to derive this

lone heartBOT
carmine reef
#

product rule

lone heartBOT
#

@olive kestrel Has your question been resolved?

olive kestrel
#

yes I know but I there are two multiplications

#

-288 x (x-9) and (x-9) x e

ocean hawk
#

you can treat -288(x - 9) as one function

olive kestrel
#

because -288 derives to 0 ?

ocean hawk
#

well because it's a valid function

#

you can write it as -288x + 2592 (or whatever it multiplies out to) if you like

olive kestrel
#

ah I get what u mena

#

mean

#

solutions also suggest to multiply -0,1 into (x-9)²

#

but its a part of the mutliplication can I just do that ?

lone heartBOT
#

@olive kestrel Has your question been resolved?

#
Channel closed

Closed by @olive kestrel

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#
Channel closed

Closed due to the original message being deleted

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

soft stag
#

hello

lone heartBOT
gray jewel
soft stag
#

its very weird

#

i dont understand

#

do you mind helping?

#

uh hello?

#

@gray jewel

gray jewel
#

Hello there

soft stag
#

Hello

#

uh so?

gray jewel
#

I'm not sure what the question wants

soft stag
#

its a two way table

tiny dew
#

I think I could help @soft stag

soft stag
#

alright

tiny dew
#

At least as far as I understand

soft stag
#

alright

tiny dew
#

okay, so, do you know how to calculate the probability here?

soft stag
#

yea

#

is it like the mean?

#

Average?

tiny dew
#

I mean, what do you think is the probability of a mid school student (being chosen at random) being in favor?

soft stag
#

Because a Decimal is /100

tiny dew
#

And how did you come to this conclusion?

soft stag
#

.25

#

50/200

tiny dew
#

yes

#

you do the same with not in favor

#

and, as you will be able to see, .25 and 150/200 = .75 add up to 1

soft stag
#

yea

tiny dew
#

so it's 25% chance

#

for a mid schooler to be in favor

soft stag
#

okay

#

and for infavor its 75%

tiny dew
#

yes

#

because 150/200 = .75 and .75 * 100% = 75%

soft stag
#

yup

#

i think i can do the rest

#

60300

#

.2

#

and 240/300 = .8

#

means its 20% for favor and 80% for non

#

(Highschool)

tiny dew
#

exactly

soft stag
#

total is 45% for favor and nnon is 175

#

155%*

tiny dew
#

whoa

soft stag
#

lmao

tiny dew
#

that's a big number you've got there

#

might want to get it checked up again

soft stag
#

75+80 = 155

tiny dew
#

nope~

soft stag
#

ong/

tiny dew
#

you've got that total column

soft stag
#

alright

tiny dew
#

you can't add percentages like this

soft stag
#

ahhh

tiny dew
#

very illegal here

soft stag
#

so both are wrong

#

LMAOOO

#

how do i calculate?

#

OH x100

#

or /100

tiny dew
#

neither

soft stag
#

oh

tiny dew
#

look at this bit

#

it's all you need here

#

treat it like you did with mid schoolers and high schoolers b4

soft stag
#

copy them down?

tiny dew
#

not really

soft stag
#

but it maked sence

#

bc thats what they did for the same thing

#

50+60=110

#

OH

#

its bc they arnt doing it in percentages

tiny dew
#

when you wanted to calc. the probability of "in favor", you divided the number of (mid/high) schoolers in favor by the number of every student

#

it's basically the same here

soft stag
#

45/110

#

.40

tiny dew
#

where did you even get that 45 from

soft stag
#

added 25 and 20

#

lmao

tiny dew
#

oh dear

#

the total of in favor is 50 (mid) + 60 (high)

#

which equals 110

#

the total of not in favor is 150 (mid) + 240 (high)

#

which equals 390

#

the total number of all students is equal to 500

#

so when you have all of those 500 students in a room, and you want to see which ones are in favor, you need to divide the number students in favor by the number of all students

soft stag
#

i got it

#

it 22% and thrn 78%

tiny dew
#

good job cowboy

soft stag
#

i have another

#

its a complicated boy

tiny dew
#

coming back to that previous ex. for one last time

soft stag
tiny dew
#

there's a formula for that

soft stag
#

is that correct

tiny dew
#

gimme a second

soft stag
#

alroight

tiny dew
#

the first one is good

soft stag
#

alr

tiny dew
#

and the second one's good too

soft stag
#

alr

#

i bet the last one is right

#

50/50

tiny dew
soft stag
#

right?

tiny dew
#

I mean, yea, sure, it is correct

soft stag
#

alright

#

1 laaaaast one

tiny dew
#

but I don't recommend playing like that on a big test

soft stag
#

i picked it bc 16/27=59.259259

#

so round it up to 59.3

tiny dew
#

it says "students"

#

not specific 8th grade students

#

all students

soft stag
#

ahhh

#

but it says 8th students

tiny dew
#

yes, we have room full of students and pointing randomly, we want to choose a student who's in 8th grade and prefers studying at the library

tiny dew
#

at least here

soft stag
#

i passed!

#

90/100

#

tysm!!

#

.close

lone heartBOT
#
Channel closed

Closed by @soft stag

Use .reopen if this was a mistake.

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

minor goblet
#

hey can someone explain how the 0.46773 becomes 1.46773?

mortal trellis
#

-x-0.46773x = (-1-0.46773)*x = -1.46773x

minor goblet
#

where does the -1 come from?

mortal trellis
#

-x = -1*x

minor goblet
#

ooooh

minor goblet
mortal trellis
#

yes

minor goblet
#

wtf

lime holly
#

Yes

minor goblet
#

i thought the -x would just clash with the x in 0.46773x

#

and become like neutral

mortal trellis
#

you have -1 apple and then -0.46773 apples and together that gives -1.46773 apples

minor goblet
#

oh.

#

ok that makes total sense now

#

hm so if i had 1 apple and -0.46773 apple came it wuld be 0.53227 apples?

minor goblet
#

ok got it

#

thank you guys

lone heartBOT
#

@minor goblet Has your question been resolved?

#
Channel closed

Closed by @minor goblet

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

barren aurora
#

Hey, I am doing an assignment where I have to explain the proofs of the different Pythagorean theorems. Our teacher required us to do Euclid's bride chair (or windmill) proof and allowed us to choose our second. He told us not to choose one that is not difficult, or that doesn't require much math. I was wondering if anyone here was familiar with a proof similar to the difficulty of the bride chair one and could potentially provide resources that help explain it? Thank you so much!

gray jewel
#

(a + b)^2 - 2ab = c^2
a^2 + b^2 = c^2

#

They are pretty similar

lone heartBOT
#

@barren aurora Has your question been resolved?

barren aurora
#

That helps but I've seen this one before, is there maybe more a little bit more challenging?

#

@gray jewel

gray jewel
#

From google images

#

But I don't think you should be asking that

polar fulcrum
#

Guys how can I solve these , they’re for an assignment I have

#

But I can’t really understand it

lone heartBOT
#

@barren aurora Has your question been resolved?

lone heartBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

deep girder
#

Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence interval for a sample of size 327 with 44% successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places.

deep girder
#

really need help with solving these type of problems

#

<@&286206848099549185>

lone heartBOT
#

@deep girder Has your question been resolved?

deep girder
#

no

#

<@&286206848099549185>

lone heartBOT
#

@deep girder Has your question been resolved?

lone heartBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

scarlet quarry
#

Here's my question here, and my work so far. I have absolutely no clue why it doesn't work for 2 and 4.

lone heartBOT
#

@scarlet quarry Has your question been resolved?

scarlet quarry
#

<@&286206848099549185>

lone heartBOT
#

@scarlet quarry Has your question been resolved?

scarlet quarry
#

Well I presume nobody here knows at this point

scarlet quarry
#

Figured it out, I used 16 for both vectors, not 13 for the second

#

That took too long for me to figure out

#

.close

lone heartBOT
#
Channel closed

Closed by @scarlet quarry

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

candid ginkgo
#

Can someone help me with how I figure this out, I'm not sure what I should do with the extra number in the intersection

candid ginkgo
#

.close

lone heartBOT
#
Channel closed

Closed by @candid ginkgo

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

night spade
#

the formula for volume of a pyramid is lwh/3 right? what did i do wrong

bitter kestrel
#

lwh/3 is for a square pyramid, you have a triangular pyramid so you have to divide that in half to get lwh/6

night spade
#

ok thanks

#

.close

lone heartBOT
#
Channel closed

Closed by @night spade

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

coarse oasis
#

why is the integral of 3cos(pi/2x) = 6/piSin(pi/2)??

coarse oasis
#

why multiply by the reciprocal of the inside

#

wouldnt it just be 3pi/2

lone heartBOT
random junco
#

oops my bad

lone heartBOT
#

@coarse oasis Has your question been resolved?

coarse oasis
#

<@&286206848099549185>

proven leaf
ocean sealBOT
#

XxMrFancyu2xX

coarse oasis
#

oohhhhh is because of u sub

#

i forgot about that, thanks

#

.close

lone heartBOT
#
Channel closed

Closed by @coarse oasis

Use .reopen if this was a mistake.

proven leaf
#

👍

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#

Please don't occupy multiple help channels.

#
Channel closed

Closed due to the original message being deleted

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

peak mist
#

help

lone heartBOT
peak mist
#

why is the radius of convergence not an/an+1 for this one

surreal crystal
#

because an/an+1 is what we use to check convergence

#

we take |an/an+1|=L here
if L < 1, it converges
if L > 1, it diverges
if L = 1, the test fails

#

we want the biggest and smallest x that make L < 1

#

their difference is the radius of convergence

#

does this make sense?

lone heartBOT
#

@peak mist Has your question been resolved?

#
Channel closed

Closed by @peak mist

Use .reopen if this was a mistake.

peak mist
#

thank you

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

rotund crater
#

someone can demonstrate me tan^-1(tan x) = x

alpine sable
#

its just like taking the ln of both sides

#

or rasing to the power e

north hemlock
ocean sealBOT
#

Juke | ping me if no response

north hemlock
#

the inverse of the function and the fucntion essentially "cancel out"

north hemlock
#

wym by this

alpine sable
#

i mean like same idea when u use ln for exponantioal functions

#

isnt the ln the invers of e

north hemlock
#

ah

#

okay

#

I read what u wrote as "it's taking the ln of both sides or or rasing to the power e"

alpine sable
#

yeah i just didnt know how to explain

#

xD

north hemlock
ocean sealBOT
#

Juke | ping me if no response

north hemlock
#

the inverse of a function "undoes" what the function does

#

vice versa

rotund crater
#

you mean is 1?

ocean hawk
#

have you learned about inverse functions?

#

I assume yes

north hemlock
#

where is 1 coming from

#

there are no numbers here

#

the idea is that a function can have an inverse function, and they undo one another

#

$\tan^{-1}$ is the inverse of $\tan$

ocean sealBOT
#

Juke | ping me if no response

rotund crater
north hemlock
#

okay so I think I found the issue

#

ur trying to visualize it I assume?

#

hope this helps

rotund crater
#

o thx

#

.close

lone heartBOT
#
Channel closed

Closed by @rotund crater

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

bitter sage
#

can anyone help with this

lone heartBOT
bitter sage
#

i understand i have to use u subsitution but how what do i do with the sqrt(4 - x^2)

naive valley
lone heartBOT
#

@bitter sage Has your question been resolved?

bitter sage
#

how would i do that

#

.close

lone heartBOT
#
Channel closed

Closed by @bitter sage

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

silver wasp
lone heartBOT
silver wasp
#

Can someone explain the second step to the third. I dont understand it

carmine reef
#

$\int f(x)+g(x)~dx = \int f(x)~dx + \int g(x)~dx$

ocean sealBOT
#

RedstonePlayz09

carmine reef
#

$\int cf(x)~dx = c\int f(x)~dx$

ocean sealBOT
#

RedstonePlayz09

silver wasp
#

How is A 6 and B 3x+1?

#

Like how do you find b?

carmine reef
#

you mean how do you go from the first step to the second?

silver wasp
#

Ye

carmine reef
#

you have to set $\frac{Ax+B}{x^2+1} + \frac{C}{x+1} = \frac{3x^2-4x+5}{(x+1)(x^2+1)}$

ocean sealBOT
#

RedstonePlayz09

carmine reef
#

remember you're solving for A,B,C here, not x

silver wasp
#

How do u find a b and c?

#

I got to this

carmine reef
#

that's not how you add fractions

silver wasp
#

Oh

#

Remove the plus at the bottom?

#

Mb

carmine reef
#

that and the numerator isn't quite right

silver wasp
#

Oh

#

Is it x and x+1

carmine reef
#

no

#

it seems like at some point you misapplied a distribution law or something

#

remember that $(a+b)*c = ab + ac$, not $a + bc$

ocean sealBOT
#

RedstonePlayz09

silver wasp
#

Yeah

#

I think

lone heartBOT
#

@silver wasp Has your question been resolved?

lone heartBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

chrome garnet
#

dms open if anyone wants to explain in specifis

surreal crystal
chrome garnet
#

thanks

surreal crystal
#

What do you need help with

chrome garnet
#

basically everything except 1a

surreal crystal
#

Alr

#

You can do all of 1 on your calculator

#

To start i will write the definition of log

chrome garnet
#

1b divide .25 by 8?

surreal crystal
#

No

chrome garnet
#

oh its 8 by .25

surreal crystal
#

,w calculate log_8 .25

ocean sealBOT
surreal crystal
#

Thats what you want

#

-2/3

chrome garnet
#

is that mutliplicagtion?

surreal crystal
#

No

chrome garnet
#

how does it get .6?

surreal crystal
#

$\log_{a}(a^b)=b=a^{\log_{a}(b)}$

ocean sealBOT
#

Cycadellic

surreal crystal
#

This is the definition of log

#

It essentially “undoes” our a^b

#

It tells us the b

#

Whereas root would tell us the a

#

Make sense?

#

Youre not gonna calculate this by hand

#

Very long and tedious

#

We need a calculator for it

chrome garnet
#

so the b would be (1a example) the 6 right

#

the mini a is 2 and the (ab) is 64?

surreal crystal
#

Lets say $a=\log_{2}(64)$

ocean sealBOT
#

Cycadellic

surreal crystal
#

Then $2^a=64$

ocean sealBOT
#

Cycadellic

chrome garnet
#

oh okay

surreal crystal
#

,w calculate log_2(64)

ocean sealBOT
chrome garnet
#

jes i had help with that one in class

surreal crystal
#

And to check

chrome garnet
#

im still confused as to how you know which number it equals to

surreal crystal
#

,w calculate 2^6

ocean sealBOT
surreal crystal
#

The calculator tells you

#

You really dont want to do this by hand

chrome garnet
#

,w 8^.66666666666

surreal crystal
#

Its guess and check basically

chrome garnet
#

look why does that one say 3.99

surreal crystal
#

They used to use tables for it

#

Cause .666666666 is a little off 2/3

chrome garnet
#

wasnt that the answer though???

surreal crystal
#

Yeah

#

,w calculate 8^(2/3)

ocean sealBOT
surreal crystal
#

Make sense?

chrome garnet
#

dude what

surreal crystal
#

-.6666666666≈2/3

chrome garnet
#

but that one makes 4

#

where the answer is at .25

surreal crystal
#

Computers can only calculate so much

chrome garnet
#

this is crazy

#

okay can we start over real quick

surreal crystal
#

Okay

#

Just use a calculator for 1

chrome garnet
#

,w log(8) .25

chrome garnet
#

what??????????/

surreal crystal
#

_

chrome garnet
#

its given 3 different answers so far

surreal crystal
#

You need an _

#

Log without an _ is 10

#

Or e, it depends

chrome garnet
#

w log_8 .25

#

,w log_8 .25

surreal crystal
#

Yeah

#

Thats -2/3

chrome garnet
#

so .6 =2/3

brave island
#

.

surreal crystal
#

.66666666666 is close to 2/3

#

We need infinitely many 6’s to truly be 2/3

chrome garnet
#

like pi

#

kinda?

surreal crystal
#

Yeah

chrome garnet
#

have you heard of mathway?

surreal crystal
#

So, we can use a calculator for all of 1

#

Yeah

#

Algebra calculator

chrome garnet
#

i tried punching in log_3 -9 but it said cannot solve?

surreal crystal
#

Cause negatives are tricky

chrome garnet
#

can you explain negatives in logs

surreal crystal
#

We are restricted a lot by - times - = +

#

Some negatives you cant get

#

(Unless you just make up a number that makes i^2=-1, but thats beyond this)

chrome garnet
#

oh because its like -x-x-x-x-x- and so on?

surreal crystal
#

Not quite

#

(-1)(-1)=1

chrome garnet
#

right

surreal crystal
chrome garnet
#

negative times - times negative times -

surreal crystal
#

I see

chrome garnet
#

(-1)(-1)(-1)(-1)

#

like that

surreal crystal
#

Yeah so since - times - = + it really messed with log

#

Equally + times + = +

chrome garnet
#

so is there an answer to 1c?

#

do you need me to resend the paper

surreal crystal
#

We can really multiply a number by itself to get - so all negative logs are undefined

#

Just do 1 on a calculator

#

Ill help you with 2 and the rest

#

$log_{x}(4x-3)=2$

ocean sealBOT
#

Cycadellic

surreal crystal
#

Is the problem for 2a

#

$\log_{a}(a^b)=b=a^{\log_{a}(b)}$

ocean sealBOT
#

Cycadellic

surreal crystal
#

Definition of log

chrome garnet
#

right

surreal crystal
#

How do i get log_x off the left of =

surreal crystal
chrome garnet
#

divide by ?

#

to move it to the right?

surreal crystal
#

Look at the right of that definition

chrome garnet
#

a^log_a?

surreal crystal
#

See how it “undoes” the log?

#

Yeah

surreal crystal
#

To undo log_x

chrome garnet
#

will you be mad if im wrong

#

does it have something to do with log10

surreal crystal
#

No

chrome garnet
#

since theres no number with the log

surreal crystal
#

You wont ever learn if youre never wrong

#

Focus on what is in the subscript

#

That little letter a little lower than the reat

chrome garnet
#

the big a?

surreal crystal
#

$log_{x}(4x-3)=2$

ocean sealBOT
#

Cycadellic

chrome garnet
#

the little x

surreal crystal
#

👍

#

How do we “undo” it

#

$b=a^{\log_{a}(b)}$

ocean sealBOT
#

Cycadellic

chrome garnet
#

the second part is super confusing

surreal crystal
chrome garnet
#

you dont mean subtract do you?

surreal crystal
#

This is what log means

surreal crystal
chrome garnet
#

can we do an example like 2a

#

is this converting to exponential form?

surreal crystal
chrome garnet
#

b?

#

big b?

surreal crystal
#

Because a is the base of the exponent, and a is the subscript on the log

surreal crystal
#

This is just what we mean by log

chrome garnet
#

like 2^6 being the 6 is the sub?

surreal crystal
#

I dont follow

chrome garnet
#

me neither dude

surreal crystal
#

Lol

#

Thats fine

chrome garnet
#

my teacher isnt too good at explaining things

surreal crystal
#

$b=a^{\log_{a}(b)}$

chrome garnet
#

language barrier kinda

ocean sealBOT
#

Cycadellic

surreal crystal
#

Lets start here

#

Do you understand what this is saying?

chrome garnet
#

not really

surreal crystal
#

This is telling us how to remove the log

#

If he have the log base and the exponent base the same, they cancel

#

Like addition and subtraction

chrome garnet
#

log base is little a?

surreal crystal
#

Yeah

chrome garnet
#

exponenent base is the big a?

surreal crystal
#

They are the same a

#

We just make the log one smaller so we dont confuse it with whats inside

chrome garnet
#

so exponent base=log base

surreal crystal
#

No, when exponent base= log base, they cancel

chrome garnet
#

whats b and whats (b)?

#

in this equation

surreal crystal
#

b

#

Just an arbitrary variable

#

Whatever goes into log goes into b

#

As for ()

chrome garnet
#

so 4x-3 would be the (b)

surreal crystal
#

Its the same as without () it just makes it clearer whats inside the log

#

Cause log x - 3 would be confusing

surreal crystal
#

Then x would be a

chrome garnet
#

okay but i still dont understand what you meant by removing the logx from the left

surreal crystal
#

Well

#

The a^ cancels log_a

#

Does all of this make sense?

chrome garnet
#

$log_{x}(4x-3)=2$

ocean sealBOT
#

El Fran

chrome garnet
#

not at all

surreal crystal
#

Alr

#

Lol

chrome garnet
#

x is subscript

surreal crystal
#

Do x^ on both sides

chrome garnet
#

4x-3 is ^

#

see i dont understand what you mean by do x^

#

how do i do x^

surreal crystal
#

Well

#

Lets say i have 2=2

#

The do 3^ to both sides

#

$3^2=3^2$

ocean sealBOT
#

Cycadellic

surreal crystal
#

There is only one possible number here right?

chrome garnet
#

so 2 becomes the exp

#

9

surreal crystal
#

It has to be the exact same #

#

On both sides of =

#

Right?

chrome garnet
#

yes

surreal crystal
#

So that means we can do it to both sides of the eq and it stays true

#

$log_{x}(4x-3)=2$

ocean sealBOT
#

Cycadellic

surreal crystal
#

Do it to both sides of this

#

x^

chrome garnet
#

i have to find x right

surreal crystal
#

Right

#

First we wanna get rid of the log term

chrome garnet
#

do i leave 4x-3 and the =2 alone?

#

or do i need those to get rid of the logx

surreal crystal
#

No we have to do x^ left side = x^ right side

#

Make sense?

chrome garnet
#

i dont understand the way you phrase this

surreal crystal
#

We have an equation

#

Lets just say two variables to vastly simply so you can understand me

#

$a=b$

ocean sealBOT
#

Cycadellic

surreal crystal
#

I want you to do

#

$x^a=x^b$

ocean sealBOT
#

Cycadellic

surreal crystal
#

When a=b is correct

surreal crystal
#

Because there is only one possible thing i could get

#

Im not gonna put x^y in my calculator and get more than 1 number, yk

chrome garnet
#

right

surreal crystal
surreal crystal
#

Make sense?

chrome garnet
#

🫤

surreal crystal
#

Do you know what i mean by ^

chrome garnet
#

exponent

surreal crystal
#

I did x^

#

Thats what i mean by x^

chrome garnet
#

x times x makes a

#

right

surreal crystal
#

No, it is x times itself, a times

chrome garnet
#

yeah x times x

surreal crystal
#

Potentially

#

If a=2

chrome garnet
#

2 times 2 a=4?

#

2=x?

surreal crystal
#

?

chrome garnet
#

duuuuuuuuuuuude

#

im stupid

#

my bad dawg

surreal crystal
#

Nobody comes in understanding all of math

chrome garnet
#

im genuinely so lost right now

surreal crystal
#

Do you understand what i mean by x^

#

Most importantly

chrome garnet
#

lets just say no

#

but i know its x times by however many times the ^ is right

#

like i said 2^2 is 4?

surreal crystal
#

Yeah

chrome garnet
#

or is that not what youre meaning at alllll

surreal crystal
#

^ is exponent

chrome garnet
#

right yes

surreal crystal
#

Now when i say x^

#

I mean

#

Start with this

chrome garnet
#

its x times x

surreal crystal
#

$a=b$

ocean sealBOT
#

Cycadellic

chrome garnet
#

can we use numbers instead

surreal crystal
#

$.2=.20$

ocean sealBOT
#

Cycadellic

chrome garnet
#

okay yes

surreal crystal
#

When i say

#

Do x^

#

To that eq

#

I mean i want this

#

$x^{.2}=x^{.20}$

ocean sealBOT
#

Cycadellic

surreal crystal
#

I want this

#

Thats what i meant by x^

chrome garnet
#

OH WAIT DID YOU WANT THE LOG TO BE THE EXPONENT

#

i thnk

surreal crystal
chrome garnet
#

like x^ to log makes it x^log

surreal crystal
#

Yeah

#

Thats it!

chrome garnet
#

ohohohohohohohho

#

yeah

#

i think i got that

#

$log_{x}(4x-3)=2$

#

so then

ocean sealBOT
#

El Fran

chrome garnet
#

is the goal for log to be the exponent here?

surreal crystal
#

Yeah

#

Exactly

chrome garnet
#

and what would it be the exponent to?

surreal crystal
#

x, because its in the base of the log

chrome garnet
#

so instead of log_x itd translate to x^log

surreal crystal
#

Itd still be log_x

#

But yeah

chrome garnet
#

it just adds another x?

surreal crystal
#

x^log_x

#

Right

chrome garnet
#

x^log_x?

#

got it

surreal crystal
#

Write that one

chrome garnet
#

is this how its written

#

thats not a 6 its (

surreal crystal
#

Yeah

#

Except do x^2 on the right of the =

chrome garnet
#

oh because you also turn 2 to exponent

surreal crystal
#

Right

chrome garnet
#

okay i got that part down

surreal crystal
#

And this gives us one thing so it keeps =

#

Good