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1 messages · Page 194 of 1

woeful wind
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awesome thank you

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humble siren
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I need help with pedal equation

lone heartBOT
humble siren
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agile monolith
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(x – 9) (3x +4) + (9−x) (7−2x) incase we factorize what is the comon factor here ?

quasi vector
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notice (9-x) = -(x-9)

agile monolith
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only x-9?

quasi vector
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yes

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why do you need more than one common factor

agile monolith
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warped topaz
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Im trying to solve this via completing the square

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But idk if im doing it correct

viscid pawn
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you can do 2 things

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first would be to factorize it with b because it's in common with every part

warped topaz
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I tried to do it by completing the square, this is what I did;

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I changed it to b (b^2 + b + 1/4), then the bit inside the brackets I got b = 0 and b = -1, but up until now ive kinda been ignoring the b that was outside the brackets, so I dont really know what to do with it

vale wigeon
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what

viscid pawn
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you can keep it that way

vale wigeon
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the bit inside the brackets i got b=0 and b=-1

viscid pawn
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just use quadratic formula on the expression with b as a factor

vale wigeon
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what did you even do???

viscid pawn
vale wigeon
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let op speak

warped topaz
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I completed the square

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But just the bit inside the bracket

vale wigeon
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or did something that decidedly wasn't completing the square

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certainly nobody asked you to solve the equation b^2 + b + 1/4 = 0.25

warped topaz
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Ah ye I see my mistake

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I forgot to square + half the coefficient of b

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I just halved it

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But yeah my question still kinda stands, like is my method wrong

vale wigeon
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it sounds like you have bigger planning errors going on.

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without seeing your work i can't tell whether that is the case.

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but i probably wouldn't want to see your work anyway.

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you are right in setting out to complete the square on b^2 + b + 1/4

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in so doing you should get (b + __)^2 + __ where the blanks are raw numbers

warped topaz
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uuuh I got (b + __)^2 = __

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Oh

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stupid formatting

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(b + X)^2 = Y

vale wigeon
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b^2 + b + 1/4 = (b + 1/2)^2 actually

warped topaz
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I got b = -3/4 and b = 1/4

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for the bit inside the brackets

warped topaz
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But yeah still not sure what to do with the b outside of the brackets

vale wigeon
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just leave it alone

vale wigeon
warped topaz
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its wrong?

vale wigeon
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it's another planning error

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you still think you are solving an equation

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when you are not...

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you're not supposed to get any values for b at all because you are not solving an equation for b

warped topaz
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Thats the thing I dont really know what to do about the b outside the brackets

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I got (b + 1/4)^2 = 1/4
b + 1/4 = +- 1/2
b = -3/4 and b = 1/4

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At what point do I do something with the b outside the brackets

lone heartBOT
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@warped topaz Has your question been resolved?

ionic sedge
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you talking about the last part?

lone heartBOT
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@warped topaz Has your question been resolved?

lone heartBOT
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ionic sedge
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can someone help me on this

lone heartBOT
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Please don't occupy multiple help channels.

ionic sedge
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i dont know where to start

lone heartBOT
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@ionic sedge Has your question been resolved?

ionic sedge
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<@&286206848099549185>

ionic sedge
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@echo socket yo

echo socket
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a) or b)?

lone heartBOT
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@ionic sedge Has your question been resolved?

frank apex
ionic sedge
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both, but a for now

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@echo socket

echo socket
echo socket
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sully You didn't do what I said though

ionic sedge
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lol

echo socket
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A bit to the right

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Yup

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Can you draw a line tangent to the graph at that point?

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That’s not a tangent line

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Good

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x1 is located at the intersection of that line with the x-axis

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So just write x1 there

frank apex
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newton's method is to repeat that process with the new x value

ionic sedge
echo socket
frank apex
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but it's helpful info anyway to know what newton's method is

echo socket
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So this is it for the first рart

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Alright

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For the second one you just use the formula

ionic sedge
echo socket
ionic sedge
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do I need to plot a point at x1 or just the label is fine

echo socket
echo socket
ionic sedge
# echo socket The label is fine

is this a good explaination: newtons method involves drawing tangent lines to the curve of the function starting with x0, then you find the points where the tangent line intersects the x-axis, and use these points to get the next approximation (x1)

echo socket
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Not really catThink

ionic sedge
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yea, it doesnt really say whats going on

echo socket
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I would say Newton’s method involves finding approximating the zero of a function as the zero of the function’s linear approximation

ionic sedge
echo socket
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Approximate is a not noun, no catThink ?

echo socket
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The word approximation works nonetheless though, right?

ionic sedge
nocturne sail
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I need help with this. Trying to use excel to solve it.

lone heartBOT
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@ionic sedge Has your question been resolved?

echo socket
ionic sedge
echo socket
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Just apply the formula

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You have x0 = 2 and f(x) = x^2 - 3

ionic sedge
echo socket
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Ight, let's see

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Yup, that's correct

ionic sedge
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thanks

ionic sedge
echo socket
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Show it

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It does but hand-drawn graphs don't have to be 100% accurate

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If it looks right then it's fine

lone heartBOT
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ionic sedge
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.reopen

lone heartBOT
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ionic sedge
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here is my work:

echo socket
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Looks good, all of it

ionic sedge
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.close

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ripe oriole
lone heartBOT
ripe oriole
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I only got 1 question before I start this problem, k is element of what?

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is this just A-R?

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or is it different when the symbol is at an angle

sage stag
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A without R, setminus

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\ / - iirc are all the same

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or wait

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you know

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this could be the quotient

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usually the /R would be a subscript, but actually i think its the set of equivalence classes of A under R

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it just depends if R is a set or a relation

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@ripe oriole Has your question been resolved?

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wispy salmon
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Hey guys need help how to solve this one

wispy salmon
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This is what i got so far

lone heartBOT
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@wispy salmon Has your question been resolved?

stuck sinew
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use squeeze theorem@wispy salmon

stuck sinew
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@wispy salmonuse ful or not ☠️

wispy salmon
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Man me and my friend sitting here and have no idea what u have done so sorry

stuck sinew
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dm me

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1 sec

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so I can discord call

wispy salmon
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Oh lovely

wispy salmon
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bright coyote
lone heartBOT
bright coyote
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The answer is (a) apparently and I don't understand why wouldn't the answer be (d)

sage stag
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because this is the principal root

bright coyote
sage stag
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if it said 4=x^2, then x=+/- 2
we would write x=+/- sqrt(4)

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sqrt(4) on the other hand is always positive

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so sqrt(4) is the principal root
and +/- sqrt(4) are the roots

bright coyote
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SO in these type of problems I have to consider only the principal root as the answer

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I'm guessing

sage stag
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yeah

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anytime you see sqrt actually

bright coyote
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Okay thanks

sage stag
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its always the principal root

bright coyote
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Thanks brother

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unique herald
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I need a little clarification on this problem
30=j^2+7j

I'm not sure what I've done, but I somehow ended up with this:
-7/2 plus or minus 26/2

ocean hawk
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quadratic formula?

alpine sable
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j²+7j=30
j²+7j-30=0
We have some formula that our fellow mathematician mentioned it above me

unique herald
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for the problem, i'm using squares if that makes sense

lone heartBOT
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@unique herald Has your question been resolved?

ocean hawk
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well show your work

unique herald
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i know for sure there was some type of error i made, but it was how i was taught so i genuinely have no idea

ocean hawk
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what is the square root of 169/4

unique herald
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13/2

ocean hawk
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yes, so where did the 2 go on the RHS (3rd from the last line)

unique herald
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ahh makes sense, thank you

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my brain processed it as division for some reason

ocean hawk
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it probably would've been easier just using the quadratic formula, IMO

unique herald
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true, we started with this for some reason tho

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.closed

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heady rune
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Could someone help me find how to write out the class equation for the direct product A4 x Z2?

alpine sable
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hello is there anyone who knows about the Pytagora's theorem?

heady rune
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I have found conjugacy classes for A4 and Z2 respectively, I know the direct product should add up to the order (24), but am stuck on how to construct the final class equation

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I have that for A4: 12 = 1 + 3 + 4 + 4

keen mason
merry depot
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wouldn't those be the same cardinalities for conjugacy classes in A4xZ2? Since the conjugacy classes in Z2 are trivial?

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and in the direct product of groups, all operations are done componentwise.
So you'd have 8 conjugacy classes for 3 cycles, 4 with 0 and 4 with 1

lone heartBOT
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@heady rune Has your question been resolved?

heady rune
merry depot
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That's what it seems like to me

heady rune
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Perfect yeah, don't know why I couldn't wrap my head around the direct product being so simple

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thank you though

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stuck sinew
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How do I start?

lone heartBOT
stuck sinew
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my work is

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this

vague coral
slender quiver
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is

stuck sinew
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IS!!!

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holy moly so blurry wtf

slate monolith
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that looks like an answer key

vague coral
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first line is wrong ?

stuck sinew
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if ykyk

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for latex output

slow hound
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how does gpt spit that out wtf

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oh damn

stuck sinew
slow hound
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thats impressive ngl

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gpt4 kek

stuck sinew
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I copy and paste into latex compiler 😂

slate monolith
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yeah lol first line wrong

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dont use gpt

stuck sinew
slate monolith
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you wrote that out?

vague coral
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imagine using chatgpt

slow hound
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gpt is good at general idea, sucks at computation

stuck sinew
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this was my prompt 😂

slow hound
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it cant even evaluate definite integrals

stuck sinew
slate monolith
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oh

stuck sinew
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works like a charmino

slate monolith
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yeah dont use chat gpt to do hw...

slow hound
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kekw its trained on leetcode so its good for cpp

vague coral
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so anyway, first line is already wrong

slate monolith
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yeah

vague coral
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you can solve this limit asymptotically

slate monolith
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@stuck sinewalso when I ask for work I dont mean chatgpt's "solution"

stuck sinew
stuck sinew
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yo anyone go to UCI for math

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or UCLA

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fuck even berkeley

vague coral
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what are these things

stuck sinew
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universities ☠️

wispy salmon
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lol thanks man im the guy in need of help but i got it you can close man

stuck sinew
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i'm planning to transfer to

vague coral
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gl then

slate monolith
#

.close

lone heartBOT
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rocky quest
lone heartBOT
rocky quest
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How do I do 2.a)

slender quiver
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!show

lone heartBOT
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Show your work, and if possible, explain where you are stuck.

rocky quest
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I don’t know how to do it

vague coral
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free body diagram and shit

rocky quest
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I know but how would I draw it if it moves up and down

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Would the child remain at rest?

vague coral
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draw it like a pendulum

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wait a sec no

rocky quest
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Something similar

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Simpler*

sage stag
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velocity adds no extra force

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downward acceleration is the same no matter how fast we go (assuming it stays 9.81)

rocky quest
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Yes

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That’s the acceleration

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So I don’t have to take into account of the velocity

sage stag
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then f=ma from there

rocky quest
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Because it doesn’t change the force

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Okay

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Thank you

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Y doesn’t the velocity effect the force

sage stag
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because velocity is relative

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to that child, they are not moving

rocky quest
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Mmm I see

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.close

lone heartBOT
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rocky quest
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.reopen

lone heartBOT
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rocky quest
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Can you look at 3?

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I tried doing

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Fnet=ma and rearranged for a

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And it was wrong

sage stag
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so, we know their mass, we want to find out an upward force because this will give use mass*g

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with g=9.81

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im assuming

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we also know their downward force

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our upward force, by the third law becomes opposite

rocky quest
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Ya

sage stag
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do you see what to do from here?

rocky quest
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Yes thank you

#

.close

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jaunty sierra
#

can someone pls help with this?

An airplane passes over the airport in Ottawa at 1:00 PM heading south at a speed of 350 km/h. At the same time another plane is 400 km East of the airport and travelling towards the airport at a speed of 300 km/h. At what time will the distance between the airplanes be a minimum? What is the minimum distance?

lone heartBOT
#

Please don't occupy multiple help channels.

slate monolith
#

.close

lone heartBOT
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jaunty sierra
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do i just post in the other help channel

limpid turret
#

Either close the other one and ask here, or keep this closed and ask there

jaunty sierra
#

.close

lone heartBOT
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dim haven
#

note: my question is pretty simple only reason i’m asking here is idk what to search for on google.

how can i learn to read this kind of a proof: https://www.mathcounterexamples.net/a-function-continuous-at-all-irrationals-and-discontinuous-at-all-rationals/

i’m an high school student and was just really interested in this function i saw in a video (it was briefly mentioned). i looked it up but i can’t seem to understand it’s proof bcs i don’t have enough knowledge to properly read(?) the proof.

sage stag
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this is just set theory and analysis

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you could learn naive set theory in maybe an hour or two, which is good enough for this

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you just need to know calculus

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its basically saying, f is defined by x=0 if it isnt rational, and all rationals a/b become 1/b

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briefly,
f(a/b)=1/b
f(a)=0 when a isnt rational

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it uses gcd (greatest common denominator) to accomplish this

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then it just uses the definitions of continuity using limits

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basically it boils down to this

dim haven
sage stag
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in the limit definition, to reduce the power properly

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i should have specified that f(a/b)=1/b when a and b share no common multiples

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this is what gcd tells us

dim haven
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basically when they r relatively primes?

sage stag
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yeah

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coprime

dim haven
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kk

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ty

sage stag
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it boils down to this: there are many, many more reals than rationals, since we are 0 where we arent rational, we can consider this continuous because it is at 0

dim haven
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the set theory knowledge i need,

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(1 sec i'm trying to think of a way to properly put this)

sage stag
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you only really need to know logic to learn it entirely, but (you actually dont need it)

dim haven
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is it like knowledge from different parts of the subject?

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or is it from the beginning to a specific point

sage stag
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honestly, you just need to learn all the operations and the general ideas behind it, then you need to learn russles paradox when youre done

dim haven
sage stag
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logic is literally just and, or, not, implies, equivalent

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they take and give true or false

dim haven
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how does implies work

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and the "equalivent", is it the normal equalivent i am familiar with?

sage stag
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->
we say a->b (a implies b) like this
assume i say
if it rains, then i go inside
then it rained and i went inside: true
it rained and i didnt go inside: false
it didnt rain and i did go inside: true
it didnt rain and i didnt go inside: true

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yeah, equivalent is what you think it is

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<->

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only when both are true or both are false

dim haven
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so basically

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implies is only false if there is contradiction

sage stag
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yeah

dim haven
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kk

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ty good sir

sage stag
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np

dim haven
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i am now closing this discussion if u don't have anything else to add

sage stag
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unless you have any other question

dim haven
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nope

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that's all

#

ty again

#

.close

lone heartBOT
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loud thunder
lone heartBOT
loud thunder
#

I don't understand how to do this

sage stag
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there isnt enough context here

loud thunder
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I need to simplify the equation

sage stag
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ok

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so

#

we have this rule $a^n\cdot a^m=a^{n+m}$

ocean sealBOT
#

ThisGuy

loud thunder
#

oh

alpine sable
#

And you've got identical bases

#

For both x and y

sage stag
alpine sable
#

Yes. That.

loud thunder
#

thank you

#

i overthought it

alpine sable
#

Happens to the best

loud thunder
#

.close

lone heartBOT
#
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alpine sable
lone heartBOT
alpine sable
#

how did they derive that equation from the top one

sage stag
#

what is in the sqrt

#

i see l?g

alpine sable
#

L/g

#

length divided by gravity

#

@sage stag

sage stag
#

okay, what is T

#

tension?

alpine sable
#

period

sage stag
#

oh, its a pendulum?

#

okay, so yeah
$T=2\pi\sqrt(\frac{L}{g})$

ocean sealBOT
#

ThisGuy

sage stag
#

draw me a free-body diagram of the pendulum

#

ill walk you through it geometrically

alpine sable
#

i appreciate the offer but im kinda busy and was just hoping for a quick reply. ty tho

#

.close

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#
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oblique latch
#

Hey,  Can somebody walk me through this problem? I don’t know how to start solving this problem. Thanks.

lone heartBOT
#

@oblique latch Has your question been resolved?

waxen flame
oblique latch
#

Mhm

#

What do I do

#

@waxen flame

waxen flame
#

Solve for n(0) and a(0).

oblique latch
#

How do I do that?

waxen flame
#

You are given the equation for each function. Just plug zero into each.

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#

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pale depot
#

So I was trying to rederive the quartic formula on my own. So I tried to set up a system of equations (see only first four lines in first image) by drawing parallels with the coefficients of the depressed quartic with (x + y)^4 (where z = x + y). Finding y and z is remarkably simple doing this and it’s most certainly not the quartic formula. I feel like I’ve overlooked something obvious but I can’t tell what it is.

tacit arch
#

Just read the quartic wikipedia

pale depot
#

No but I want to do this on my own

#

And I don’t know why this method is incorrect

#

<@&286206848099549185> please help

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#

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junior warren
lone heartBOT
junior warren
#

could anyone help me out on how to solve a here?

#

i have a bit of a start but not certain on much

#

i set 2 different time variables and plugged into x

#

but all i got is that a=+-b

#

but i guess i know that a=-b, as if a=b either they are the same time or b is negative anyways?

chrome salmon
junior warren
#

just set two random variables equal to time

#

since for it to intersect it self, x coord must be equal 2 itself at 2 different times

#

was my thinking atleast

chrome salmon
#

you mean, you did t=a and t=b and gthen equated, right?

junior warren
#

yes

#

and made the x equal to itself at times a and b

#

to find the relation between a and b

chrome salmon
#

and you got a = +-b

junior warren
#

yup

#

but just to generalize i will say a=-b

#

since a=b is basically useless

#

as it is obvious equal to itself at the same time

#

then i used that relation, subbed into y

#

let those two equal themselves

#

that being

#

y(a)=y(-a)

#

and then isolate for a

#

got a = +-sqrt6

chrome salmon
#

i doubt you got b = +- a

junior warren
#

unless i computed it wrong

chrome salmon
#

you did it right but you want it such that y(a)=y(-a) satisfy

junior warren
#

yes that was just to find a relation for the two times

chrome salmon
#

what do you get value of a after this

junior warren
chrome salmon
#

ok so your points are $(x(\sqrt{6}),y(\sqrt6))$ and (x(-\sqrt6),y(-\sqrt6))$

ocean sealBOT
#

fäf
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

junior warren
#

im noticing i messed up some arthimetic but it ended up fixing itself lol

#

yes i think those would be my points

#

and i need these point as my bounds for integration

chrome salmon
#

bounds for t yes

junior warren
#

right

chrome salmon
#

what are you integrating

junior warren
#

and since the nature of the functions

#

my lower bound is actually

#

the pos sqrt6

#

since as time gets greater the functions produce smaller values

#

i am integrating this area

#

or rather

#

the area bounded by it

#

thus i need those intersections

chrome salmon
#

it depends on integration is done closkwise or anti-clockwise

junior warren
#

how can i determine that?

#

i was just thinking

#

as t increases

#

x decreases

#

thus it is counter clockwisee?

chrome salmon
junior warren
#

which part of the question is it given in?

#

or does time always have to be from negative to positive?

chrome salmon
junior warren
#

am i forgetting about something?

#

i havent touched parametrics in a bit lol

chrome salmon
#

why is the area solution so long

junior warren
#

our software sometimes rejects rounded answers so i just put it in exactly

#

however as it can be seen i threw a -ve sign infront as i must have gotten the direction wrong lol

lone heartBOT
#

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#
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zenith olive
#

hi

lone heartBOT
zenith olive
#

14 please

lone heartBOT
#

@zenith olive Has your question been resolved?

zenith olive
#

.cose

#

.close

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signal monolith
#

hi could someone please help me with this question on complex numbers 😅

vale wigeon
#

any progress so far?

alpine sable
#

most likely

signal monolith
signal monolith
vale wigeon
#

you forgot the case x=0 when you divided both sides by 2x

alpine sable
signal monolith
#

thank you so much guys

#

i couldn’t figure out where x=0 came from looking at the mark scheme 🤦‍♂️

signal monolith
alpine sable
#

you have assumed w = x + iy

#

so for different values of x and y there will be different values of w

#

and you will have multiple solutions

signal monolith
signal monolith
#

.close

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#
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alpine sable
lone heartBOT
alpine sable
#

Not sure how to approach this

#

Did a similar previously so I'm thinking ii) is !4 but not sure if thats correct (nvm wasnt correct)

vale wigeon
#

ellipsis consisting of one number

alpine sable
#

I dont follow sad

vale wigeon
#

this wasn't a step

#

this was just me remarking upon the fact that

#

yknow

#

why {-10, -9, ..., -7} instead of {-10, -9, -8, -7}

vale wigeon
alpine sable
#

yeah

vale wigeon
#

incorrect

alpine sable
#

I know I tried it just now

vale wigeon
#

there are 4! one to one functions

alpine sable
#

hmm so, -8 maps to -9, so then 3 things mapping to 3 things left

vale wigeon
#

and (i) is 3! yes that's exactly why

alpine sable
#

ohhh

#

Yeah my brain short circuited thank you!!!

#

.close

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#
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alpine sable
#

So I got the answer -f^'(-x)

lone heartBOT
alpine sable
#

but how is that an odd function

echo socket
#

So f'(x) = -f'(-x)

#

Which is the definition of an odd function

alpine sable
#

? I thought -f(x)=f(-x)

echo socket
echo socket
#

You get -f'(x) = f'(-x)

vague coral
alpine sable
#

ty

#

.close

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#
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stone ruin
#

What is the meaning of a spectral decomposition

stone ruin
#

what does it mean

stable pivot
#

matrices?

stone ruin
#

yeah

#

spectral decomposition of a matrix

stable pivot
#

it's a theorem

vague coral
stone ruin
#

thats it?

vague coral
#

if i remember

stone ruin
#

but its like a whole operation

vague coral
#

like ?

stable pivot
#

yeah you need to find eigenvectors

#

and eigenvalues

stone ruin
#

doesnt diagonilization just mean that all the eigenvalues are real

stable pivot
#

for the spectral decomposition

vague coral
#

yes

stone ruin
#

??????

vague coral
#

but be careful

stone ruin
#

I don't understand

vague coral
#

whats wrong

stone ruin
#

is spectral decomposition

#

does it involve

stable pivot
#

Theorem 1 (Spectral Decomposition): Let A be a symmetric n×n matrix, then A has a spectral decomposition A = CDCT where C is an n×n matrix whose columns are unit eigenvectors C1, …, Cn corresponding to the eigenvalues λ1, …, λn of A and D is the n×n diagonal matrix whose main diagonal consists of λ1, …, λn.

stone ruin
#

Q(upside down V)QT

stable pivot
#

it's just a notation

vague coral
stone ruin
#

Q is a matrix of normalized eigenvectors for the symmetric matrix

#

upside down V is the diagonilization

vague coral
#

which contains all the eigenvaluea

stone ruin
#

its not called a diagonolization matrix?

vague coral
#

and Q is the matrix where the columns are the eigenvectors normalized

vague coral
stone ruin
#

Nowhere

#

I just thought it was called that for some reason

vague coral
#

its just a diagonal matrix that represents the symmetric matrix on a basis composed of eigenvectora normalized

#

nothing too deep

stone ruin
#

sorry im digesting that fact

vague coral
#

Or in simple words, its an other expression of the matrix but in an other basis

#

and that basis is composed of his eigenvectors

stone ruin
#

okay, so I did out the operations, and I don't

#

I don't really get how tf this works

#

What is Q(upside down V)

#

just by itself

vague coral
#

Let M be a symmetric matrix with real coefficients

#

M can be diagonalized and we have :

#

$M = QDQ^T$

ocean sealBOT
#

Herels

vague coral
#

where D represents the diagonal matrix composed of eigenvalues

stone ruin
#

yeah

vague coral
#

and Q the matrix where the columns represent the eigenvectors of M

stone ruin
#

yeah

vague coral
#

normalized

#

i forgot to add that

stone ruin
#

yeah I know

#

but why is that the case??????

vague coral
#

You want a proof of this theorem ?

stone ruin
#

like I'm not asking for a proof really, more a justification

#

not really

vague coral
#

I cant really tell how it works

stone ruin
#

fair enough

#

What actually is Q??

#

like

#

what is the matrix Q

#

what does it mean

#

I get that D like

#

scales the eigenvectors in Q by the amount that they would be scaled by the original matrix

pale depot
vague coral
stone ruin
#

ah okay

#

also

#

if the homework says "find the spectral decomposition of M" and then gives a matrix M

#

what do you actually put down?

pale depot
vague coral
stone ruin
#

Just that?

#

like without actually doing it out

vague coral
#

nah but you need to find Q and D of course

stone ruin
#

yeah I know

stable pivot
#

well you'll need to find each matrix and then write the actual spectral decomp as M = your matrices

vague coral
#

And state what they are

stone ruin
#

but i mean without doing the multiplication

#

ah okay

vague coral
#

I said you diagonalize M

stone ruin
#

too late ._.

stable pivot
#

no that's the decomposition you decompose your matrix M into 3 matrices

vague coral
#

You diagonalize M : characteristic polynomial, eigenvaluea eigenvector blablabla

#

Now that you have the basis formed by eigenvectors

#

you normalize it

#

Graam-schmidt is the classic way

#

When you are done fiding the orthonomal basis, you use it for Q

#

and thats it

stone ruin
#

wait

#

why do I have to use graam schmidt

#

cant I just find the eigenvectors, normalize them, and cram them into Q?

vague coral
vague coral
#

Thats the spectral decomposition

stone ruin
#

ah okay

#

thank you!

vague coral
#

np

stone ruin
#

.close

lone heartBOT
#
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cunning fog
#

Write down each statement and its negation. Which of the statement and its negation is true and which is false?
10 is divisible by 2 or 3

according to the works soluitions the answer is:
P : 10 is divisible by 2 or 3 (false)
not P : 10 is not divisible by 2 and 10 is not divisible by 3 (true)

but i got the reverse answer. I was wondering where my thinking went wrong.
Here is a picture of my working out on a paint picture.

lone heartBOT
#

@cunning fog Has your question been resolved?

cunning fog
#

!15m

lone heartBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

summer cobalt
cunning fog
#

@crisp iron

cunning fog
echo socket
lone heartBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

lone heartBOT
#

@cunning fog Has your question been resolved?

lone heartBOT
#

@cunning fog Has your question been resolved?

lone heartBOT
#

@cunning fog Has your question been resolved?

cunning fog
#

@crisp iron

cunning fog
#

Write down each statement and its negation. Which of the statement and its negation is true and which is false?
10 is divisible by 2 or 3

according to the works soluitions the answer is:
P : 10 is divisible by 2 or 3 (false)
not P : 10 is not divisible by 2 and 10 is not divisible by 3 (true)

but i got the reverse answer. I was wondering where my thinking went wrong.
Here is a picture of my working out on a paint picture.
Image

tidal sun
#

anyone can help?

cunning fog
#

@crisp iron

#

<@&286206848099549185>

cunning fog
cunning fog
#

<@&286206848099549185>

stable pivot
#

first proposition is true second is false

#

since 10 is divisible by 2 P or Q is correct and for the second since 10 is not divisible by 2 is false and its an and statement it suffices to say its false

#

solutions are therefore incorrect

cunning fog
#

Thanks!

#

.close

lone heartBOT
#
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prisma badger
lone heartBOT
prisma badger
#

<@&286206848099549185>

alpine sable
prisma badger
#

no

#

I haven't learnt it

alpine sable
#

ok so its kinda self explanatory, if you look at a bar graph for example, what do you notice about the x axis values

prisma badger
#

its continuous/unchanging

alpine sable
#

no - it is non continuous

#

beacuse there is no neumerical order

prisma badger
#

oh

#

ok

alpine sable
#

so to answer the question

#

a and a can

#

b cannot

prisma badger
#

and c can't?

alpine sable
#

c can

#

think about why and what i mentioned earlier

prisma badger
#

ok

#

oh I can somewhat understand it

#

thanks

#

.close

lone heartBOT
#
Channel closed

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prisma badger
#

.reopen

lone heartBOT
#

prisma badger
#

its incorrect

alpine sable
#

what were the reasons you gave

#

you had to write a sentence explaining the reason for each answere

prisma badger
#

I just had to tick if I wrote the explanation or not

fallen verge
#

thats beside the point

#

what was your selection

prisma badger
#

a can
b can't
c can

fallen verge
#

why a

alpine sable
#

oh crap

#

😭

#

buildings.....😭

fallen verge
#

you need to compare two quantitative variables

prisma badger
#

oh

#

that can be represented as an bar graph

fallen verge
#

i would be quite nice as a bar graph

alpine sable
fallen verge
#

quantitative- having quantity, a numerical value

#

favorite sport is a qualitative variable

alpine sable
#

ohhh - basically a number

prisma badger
#

tnx I got it now

fallen verge
#

thats why favorite sport cannot use a scatterplot

#

building height is one variable

prisma badger
#

I understand it now

fallen verge
#

just making sure

prisma badger
#

both variables should have a numerical value

fallen verge
#

pretty much

#

but just be careful that its not some trick question

#

i guess there arent very many trick questions i can think of, so you should be fine

prisma badger
#

alr then thanks and bye

fallen verge
#

have a good one

prisma badger
#

.close

lone heartBOT
#
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rugged spindle
#

i have to write a calibration algorithm that does something like this, i've done it with polynomials and linear regressions in the past but this is unfamiliar, ChatGPT suggests it might be piecewise linear interpolation, is that what I'm looking for here?

rugged spindle
#

I hope the diagram is somewhat readable

lone heartBOT
#

@rugged spindle Has your question been resolved?

lone heartBOT
#

@rugged spindle Has your question been resolved?

molten pivot
#

I mean it doesn't seem like there's much to it from the info given

#

True value + offset = observed value

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lyric mica
#

Hi guys, where did he get 11x/7 from? Also is there a better way of doing this question?

wary stream
#

And all it did was find the value for x, you still need to find the value for y

lyric mica
#

Still confused if I’m being honest

hushed wolf
#

x + 4x/7

#

what does it make up to

wary stream
#

Where are you confused?

#

Do you know how to add fractions?

#

4/7 is a fraction, 1 is not

#

You need to find a common denominator

#

And add fractions

lone heartBOT
#

@lyric mica Has your question been resolved?

lyric mica
lone heartBOT
#
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cobalt delta
#

If I take a question like

4 (77) - 72

And rearrange it to:

4 (77) + 4 (-18)

Then combine the two together to form

4 (77 - 18)

I know this works, but what properties of arithmetic would that final step be? I know that in step 2, I'm factoring out a 4, but what is the step that lets me combine the fours by grouping the 77 and -18 into a single arithmetic expression

I feel like I know how to do it intuitively from when I last practiced algebra, but I've got no idea what the rule was that let met do it?

placid zinc
#

Distributive property

cobalt delta
#

Alright ty, I think it threw me because I'm used to doing distribution in reverse

#

Thanks though, just doing some easier problems to get back into the swing of it and finding myself solving them using different concepts

#

.close

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tiny surge
#

how do i solve?

lone heartBOT
lament forge
#

is there a particular part of that that you don't know how to do?

tiny surge
#

i dont understand how to do an of it

coral thorn
#

starts with P ends with S

tiny surge
#

ok

#

pemdas

coral thorn
#

use that

tiny surge
#

k

#

.close

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alpine sable
#

Geometric probability

lone heartBOT
alpine sable
#

.open

fringe folio
#

ah mb I'll close mine for you

#

.close

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alpine sable
#

.reopen

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magic flax
#

i got 50.3 originally but i'm confused on how it's wrong, someone just walk me through the steps please

lone heartBOT
magic flax
#

i found the radius which is 4, 4^2 is 16, and so i did 16(pi) to get 50.3

wary stream
#

How did you find the radius?

#

@magic flax

magic flax
#

i used the distance formula but ig i some how miscalculated it because i re did it and got something else and it was correct

#

sorry for the waste of time

#

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steep patio
lone heartBOT
steep patio
#

not sure where to start

naive valley
#

what value of x can you plug into the first series in order to get the second series?

lone heartBOT
#

@steep patio Has your question been resolved?

steep patio
naive valley
steep patio
#

just taylor's theorem

#

but the derivatives of f(x) don't seem to be bounded

naive valley
#

well you can see from the coefficients that the series converges as long as |x-3| < 2, the question is whether it converges to the original function.. that's where the theory of analytic functions comes in

#

probably in the context of this question, you can just assume that it's true

steep patio
#

alright thanks

#

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rustic yew
#

hi

lone heartBOT
alpine sable
#

shit

#

sorry

rustic yew
#

oh mb

#

i'm sorry

alpine sable
#

all too

#

good

rustic yew
#

all i do now is post the question?

keen mason
rustic yew
#

how do you solve for x in this

#

<@&286206848099549185> please help me

tacit arch
#

divide by 3, square both sides, subtract 28, then square root to find x

tacit arch
#

oh maybe 3/2 instead of 3

#

is your equation $\frac{3\sqrt{x^2+28}}{2} = 6$ ?

ocean sealBOT
#

riemann

rustic yew
#

it's not 6

#

it's 12

tacit arch
#

why is 12 over the 2 then

rustic yew
#

idk that's the last question i'm stuck on

tacit arch
rustic yew
#

that's it

tacit arch
#

what you wrote is not standard

#

you think it is

#

but you wrote something wrong

rustic yew
#

holld up let me get it

#

yeah that's it

#

it's how it's supposed to be

tacit arch
rustic yew
#

i just drew it

#

my phone died

tacit arch
#

yea no way your book wrote it like that

#

your fraction under the 12 is over the 2

#

12/2 = 6

#

so you either drew the line too long or it should be 6 on the right

rustic yew
#

nooo

#

i did it long

tacit arch
rustic yew
#

so what are the steps

rustic yew
tacit arch
#

you first step should be 12 / (3/2)

#

do you know how to divide fractions

rustic yew
#

yeah

#

but this was my thing

#

is it right

tacit arch
#

no

rustic yew
#

o

tacit arch
#

those are 3 different equations

rustic yew
#

no like the steps

tacit arch
#

and would result in 3 different answers for x

rustic yew
#

oh okay

#

wym by 3/2

tacit arch
tacit arch
rustic yew
#

can you just send me like steps on how you did it i'm so confused

tacit arch
rustic yew
#

that's what i got

tacit arch
rustic yew
tacit arch
#

,calc 12/(3/2)

ocean sealBOT
#

Result:

8
tacit arch
#

yes

rustic yew
#

ok

#

can i send you like a jamboard so you can show me what to do?

tacit arch
#

no

#

just type out what you're doing here

rustic yew
#

ok

tacit arch
rustic yew
#

just 3

tacit arch
rustic yew
#

0?

tacit arch
#

also no

rustic yew
#

nothing

tacit arch
#

what's this divided by 3/2

rustic yew
#

what

#

the 3?

tacit arch
#

$\frac{\frac{3}{2}}{\frac{3}{2}} = ?$

ocean sealBOT
#

riemann

rustic yew
#

what

#

add?

tacit arch
rustic yew
#

uh

#

3 0/2 ?

#

3 wholes

tacit arch
rustic yew
#

ohhh

#

yeah

#

is it 2.25

lone heartBOT
#

@rustic yew Has your question been resolved?

lone heartBOT
#

@rustic yew Has your question been resolved?

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amber atlas
#

Need to determine if this is true, since they have the same truth values, we say this affirmation is true

lone heartBOT
#

@amber atlas Has your question been resolved?

placid zinc
#

What's with the o?

#

Supposed to be an "OR" judging from your work

#

The left side is true always.

#

The right side can be false

#

For example, if y = 4

#

So these two are not equivalent and so the whole thing is false

#

@amber atlas

#

Splitting them up into p,r,s and then forgetting what p, r, and s are is not a good strategy. Notably, on the left side, p and s are related

amber atlas
amber atlas
#

I noticed that sqrt(7)<3 too

#

so since one of the affirmations is true, we say that the disyunction is true if one of the affirmations is true

lone heartBOT
#

@amber atlas Has your question been resolved?

placid zinc
#

Let's look at the case y = 4.

Is y < 3? No. So that's false.
Is y² = 7? No. So that's false.
Is y³ = 27? No. so that's false.

#

Since we have F o F o F, we get a F.

#

@amber atlas

#

Notably, there's no rule against using y = 4.

lone heartBOT
#

@amber atlas Has your question been resolved?

lone heartBOT
#
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main ruin
#

What is a possible way to divide by zero?

lone heartBOT
plucky token
#

like a limit?

echo socket
#

Whoever told you it’s possible is wrong

lone heartBOT
#

@main ruin Has your question been resolved?

main ruin
#

But surely there must be some way, just because it has not been proven yet doesn't mean its not possible

night geyser
#

mathematicians have certainly tried to add in division by 0 in a way consistent with existing algebra

#

its... kind of possible to do

#

the riemann sphere permits division by 0 in most cases, for example

#

but its not super interesting

#

in the riemann sphere you just get infinity which is not a very nice object to work with