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I need help with pedal equation
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(x – 9) (3x +4) + (9−x) (7−2x) incase we factorize what is the comon factor here ?
notice (9-x) = -(x-9)
yes i know but what other comon factor
only x-9?
make sure if it is 100% correct
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you can do 2 things
first would be to factorize it with b because it's in common with every part
I tried to do it by completing the square, this is what I did;
I changed it to b (b^2 + b + 1/4), then the bit inside the brackets I got b = 0 and b = -1, but up until now ive kinda been ignoring the b that was outside the brackets, so I dont really know what to do with it
what
you can keep it that way
the bit inside the brackets i got b=0 and b=-1
just use quadratic formula on the expression with b as a factor
what did you even do???
quadratic probably
let op speak
it sounds like you either did something extra
or did something that decidedly wasn't completing the square
certainly nobody asked you to solve the equation b^2 + b + 1/4 = 0.25
Ah ye I see my mistake
I forgot to square + half the coefficient of b
I just halved it
But yeah my question still kinda stands, like is my method wrong
it sounds like you have bigger planning errors going on.
without seeing your work i can't tell whether that is the case.
but i probably wouldn't want to see your work anyway.
you are right in setting out to complete the square on b^2 + b + 1/4
in so doing you should get (b + __)^2 + __ where the blanks are raw numbers
So ye same thing kinda
b^2 + b + 1/4 = (b + 1/2)^2 actually
I got that cause of pascals triangle but im trying to do it another way just incase I dont spot something like that in an exam
But yeah still not sure what to do with the b outside of the brackets
just leave it alone
??????
its wrong?
it's another planning error
you still think you are solving an equation
when you are not...
you're not supposed to get any values for b at all because you are not solving an equation for b
Thats the thing I dont really know what to do about the b outside the brackets
I got (b + 1/4)^2 = 1/4
b + 1/4 = +- 1/2
b = -3/4 and b = 1/4
At what point do I do something with the b outside the brackets
@warped topaz Has your question been resolved?
you talking about the last part?
@warped topaz Has your question been resolved?
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can someone help me on this
Please don't occupy multiple help channels.
i dont know where to start
@ionic sedge Has your question been resolved?
<@&286206848099549185>
@echo socket yo
a) or b)?
@ionic sedge Has your question been resolved?
do you know what newton's method is
if not google it
First of all label the point that's above x_0 and on the graph
You didn't do what I said though
lol
A bit to the right
Yup
Can you draw a line tangent to the graph at that point?
That’s not a tangent line
Good
x1 is located at the intersection of that line with the x-axis
So just write x1 there
newton's method is to repeat that process with the new x value
so plot a point there?
They are asked to visualize only x1
but it's helpful info anyway to know what newton's method is
So this is it for the first рart
Alright
For the second one you just use the formula
oh, is my last image all thats needed?
Yes
do I need to plot a point at x1 or just the label is fine
x1 is equal to x0 - f(x0)/f’(x0)
The label is fine
is this a good explaination: newtons method involves drawing tangent lines to the curve of the function starting with x0, then you find the points where the tangent line intersects the x-axis, and use these points to get the next approximation (x1)
Not really 
yea, it doesnt really say whats going on
I would say Newton’s method involves finding approximating the zero of a function as the zero of the function’s linear approximation
you mean finding the approximate of
Approximate is a not noun, no
?
it can be...
The word approximation works nonetheless though, right?
how should i word that so it says whats going on in the graph
I need help with this. Trying to use excel to solve it.
@ionic sedge Has your question been resolved?
On the graph we are visualizing the zero of the linear approximation
alright, now part b
i got 1.75
thanks
i have a multi part question that I completed, but can you check if i did it right
Show it
It does but hand-drawn graphs don't have to be 100% accurate
If it looks right then it's fine
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here is my work:
Looks good, all of it
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I only got 1 question before I start this problem, k is element of what?
is this just A-R?
or is it different when the symbol is at an angle
A without R, setminus
\ / - iirc are all the same
or wait
you know
this could be the quotient
usually the /R would be a subscript, but actually i think its the set of equivalence classes of A under R
it just depends if R is a set or a relation
@ripe oriole Has your question been resolved?
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Hey guys need help how to solve this one
This is what i got so far
@wispy salmon Has your question been resolved?
use squeeze theorem@wispy salmon
Man me and my friend sitting here and have no idea what u have done so sorry
Oh lovely
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The answer is (a) apparently and I don't understand why wouldn't the answer be (d)
because this is the principal root
what's a principal root
if it said 4=x^2, then x=+/- 2
we would write x=+/- sqrt(4)
sqrt(4) on the other hand is always positive
so sqrt(4) is the principal root
and +/- sqrt(4) are the roots
SO in these type of problems I have to consider only the principal root as the answer
I'm guessing
Okay thanks
its always the principal root
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I need a little clarification on this problem
30=j^2+7j
I'm not sure what I've done, but I somehow ended up with this:
-7/2 plus or minus 26/2
quadratic formula?
j²+7j=30
j²+7j-30=0
We have some formula that our fellow mathematician mentioned it above me
for the problem, i'm using squares if that makes sense
@unique herald Has your question been resolved?
well show your work
i know for sure there was some type of error i made, but it was how i was taught so i genuinely have no idea
what is the square root of 169/4
13/2
yes, so where did the 2 go on the RHS (3rd from the last line)
it probably would've been easier just using the quadratic formula, IMO
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Could someone help me find how to write out the class equation for the direct product A4 x Z2?
hello is there anyone who knows about the Pytagora's theorem?
I have found conjugacy classes for A4 and Z2 respectively, I know the direct product should add up to the order (24), but am stuck on how to construct the final class equation
I have that for A4: 12 = 1 + 3 + 4 + 4
new channel buddy
wouldn't those be the same cardinalities for conjugacy classes in A4xZ2? Since the conjugacy classes in Z2 are trivial?
and in the direct product of groups, all operations are done componentwise.
So you'd have 8 conjugacy classes for 3 cycles, 4 with 0 and 4 with 1
@heady rune Has your question been resolved?
Oh I see, much more simple than I was thinking lol. Would 24 = 2 + 3 + 4 + 4 + 3 + 4 + 4 be the correct class eq then?
That's what it seems like to me
Perfect yeah, don't know why I couldn't wrap my head around the direct product being so simple
thank you though
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How do I start?

is
first line is wrong ?
I asked my boy gpt 😂
if ykyk
for latex output
I copy and paste into latex compiler 😂
AYOOOO
you wrote that out?
gpt is good at general idea, sucks at computation
this was my prompt 😂
it cant even evaluate definite integrals
I use it for c++ ☠️ as well
oh
works like a charmino
yeah dont use chat gpt to do hw...
its trained on leetcode so its good for cpp
so anyway, first line is already wrong
yeah
you can solve this limit asymptotically
@stuck sinewalso when I ask for work I dont mean chatgpt's "solution"
i was asking for a friend 😂 but he got it I think
💯
yo anyone go to UCI for math
or UCLA
fuck even berkeley
what are these things
universities ☠️
lol thanks man im the guy in need of help but i got it you can close man
i'm planning to transfer to
gl then
.close
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How do I do 2.a)
!show
Show your work, and if possible, explain where you are stuck.
I don’t know how to do it
free body diagram and shit
I know but how would I draw it if it moves up and down
Would the child remain at rest?
velocity adds no extra force
downward acceleration is the same no matter how fast we go (assuming it stays 9.81)
then f=ma from there
Because it doesn’t change the force
Okay
Thank you
Y doesn’t the velocity effect the force
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Can you look at 3?
I tried doing
Fnet=ma and rearranged for a
And it was wrong
so, we know their mass, we want to find out an upward force because this will give use mass*g
with g=9.81
im assuming
we also know their downward force
our upward force, by the third law becomes opposite
Ya
do you see what to do from here?
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can someone pls help with this?
An airplane passes over the airport in Ottawa at 1:00 PM heading south at a speed of 350 km/h. At the same time another plane is 400 km East of the airport and travelling towards the airport at a speed of 300 km/h. At what time will the distance between the airplanes be a minimum? What is the minimum distance?
Please don't occupy multiple help channels.
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do i just post in the other help channel
Either close the other one and ask here, or keep this closed and ask there
okay, i'll close this one. do you mind helping me in #help-5 ?
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note: my question is pretty simple only reason i’m asking here is idk what to search for on google.
how can i learn to read this kind of a proof: https://www.mathcounterexamples.net/a-function-continuous-at-all-irrationals-and-discontinuous-at-all-rationals/
i’m an high school student and was just really interested in this function i saw in a video (it was briefly mentioned). i looked it up but i can’t seem to understand it’s proof bcs i don’t have enough knowledge to properly read(?) the proof.
this is just set theory and analysis
you could learn naive set theory in maybe an hour or two, which is good enough for this
you just need to know calculus
its basically saying, f is defined by x=0 if it isnt rational, and all rationals a/b become 1/b
briefly,
f(a/b)=1/b
f(a)=0 when a isnt rational
it uses gcd (greatest common denominator) to accomplish this
then it just uses the definitions of continuity using limits
basically it boils down to this
at which part do they use gcd?
in the limit definition, to reduce the power properly
i should have specified that f(a/b)=1/b when a and b share no common multiples
this is what gcd tells us
basically when they r relatively primes?
it boils down to this: there are many, many more reals than rationals, since we are 0 where we arent rational, we can consider this continuous because it is at 0
1 more thing
the set theory knowledge i need,
(1 sec i'm trying to think of a way to properly put this)
you only really need to know logic to learn it entirely, but (you actually dont need it)
is it like knowledge from different parts of the subject?
or is it from the beginning to a specific point
honestly, you just need to learn all the operations and the general ideas behind it, then you need to learn russles paradox when youre done
but a little bit right? cuz i haven't seen any logic signs that idk of yet
logic is literally just and, or, not, implies, equivalent
they take and give true or false
how does implies work
and the "equalivent", is it the normal equalivent i am familiar with?
->
we say a->b (a implies b) like this
assume i say
if it rains, then i go inside
then it rained and i went inside: true
it rained and i didnt go inside: false
it didnt rain and i did go inside: true
it didnt rain and i didnt go inside: true
yeah, equivalent is what you think it is
<->
only when both are true or both are false
yeah
np
i am now closing this discussion if u don't have anything else to add
unless you have any other question
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I don't understand how to do this
there isnt enough context here
I need to simplify the equation
ThisGuy
oh
as in, x^1/3 and x^1
and y^1 and y^3/2
Yes. That.
Happens to the best
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how did they derive that equation from the top one
period
ThisGuy
i appreciate the offer but im kinda busy and was just hoping for a quick reply. ty tho
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Hey, Can somebody walk me through this problem? I don’t know how to start solving this problem. Thanks.
@oblique latch Has your question been resolved?
The initial amount of active ingredient will be at t = 0.
Solve for n(0) and a(0).
How do I do that?
You are given the equation for each function. Just plug zero into each.
@oblique latch Has your question been resolved?
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So I was trying to rederive the quartic formula on my own. So I tried to set up a system of equations (see only first four lines in first image) by drawing parallels with the coefficients of the depressed quartic with (x + y)^4 (where z = x + y). Finding y and z is remarkably simple doing this and it’s most certainly not the quartic formula. I feel like I’ve overlooked something obvious but I can’t tell what it is.
Just read the quartic wikipedia
No but I want to do this on my own
And I don’t know why this method is incorrect
<@&286206848099549185> please help
@pale depot Has your question been resolved?
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could anyone help me out on how to solve a here?
i have a bit of a start but not certain on much
i set 2 different time variables and plugged into x
but all i got is that a=+-b
but i guess i know that a=-b, as if a=b either they are the same time or b is negative anyways?
where did a and b come from?
just set two random variables equal to time
since for it to intersect it self, x coord must be equal 2 itself at 2 different times
was my thinking atleast
you mean, you did t=a and t=b and gthen equated, right?
yes
and made the x equal to itself at times a and b
to find the relation between a and b
and you got a = +-b
yup
but just to generalize i will say a=-b
since a=b is basically useless
as it is obvious equal to itself at the same time
then i used that relation, subbed into y
let those two equal themselves
that being
y(a)=y(-a)
and then isolate for a
got a = +-sqrt6
i doubt you got b = +- a
you did it right but you want it such that y(a)=y(-a) satisfy
yes that was just to find a relation for the two times
what do you get value of a after this
ok so your points are $(x(\sqrt{6}),y(\sqrt6))$ and (x(-\sqrt6),y(-\sqrt6))$
fäf
Compile Error! Click the
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im noticing i messed up some arthimetic but it ended up fixing itself lol
yes i think those would be my points
and i need these point as my bounds for integration
bounds for t yes
right
what are you integrating
and since the nature of the functions
my lower bound is actually
the pos sqrt6
since as time gets greater the functions produce smaller values
i am integrating this area
or rather
the area bounded by it
thus i need those intersections
that shouldn't be the case
it depends on integration is done closkwise or anti-clockwise
how can i determine that?
i was just thinking
as t increases
x decreases
thus it is counter clockwisee?
given in the question
which part of the question is it given in?
or does time always have to be from negative to positive?
when they give an integration question
why is the area solution so long
our software sometimes rejects rounded answers so i just put it in exactly
however as it can be seen i threw a -ve sign infront as i must have gotten the direction wrong lol
@junior warren Has your question been resolved?
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hi
@zenith olive Has your question been resolved?
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hi could someone please help me with this question on complex numbers 😅
any progress so far?
is w*, conjugate of w
most likely
yes this is what i have so far
yes i think so
you forgot the case x=0 when you divided both sides by 2x
for, 2xy + 2x = 0
you can write it as
2x(y+1) = 0
for which you have x=0 or y=-1
ohhhh
ohhh i seee
thank you so much guys
i couldn’t figure out where x=0 came from looking at the mark scheme 🤦♂️
and do i find w by using the equation in the question
you have assumed w = x + iy
so for different values of x and y there will be different values of w
and you will have multiple solutions
ohh right
okay thank you so much 😄
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Not sure how to approach this
Did a similar previously so I'm thinking ii) is !4 but not sure if thats correct (nvm wasnt correct)
ellipsis consisting of one number
I dont follow 
this wasn't a step
this was just me remarking upon the fact that
yknow
why {-10, -9, ..., -7} instead of {-10, -9, -8, -7}
what's !4 btw? derangement number?
yeah
incorrect
I know I tried it just now
there are 4! one to one functions
hmm so, -8 maps to -9, so then 3 things mapping to 3 things left
and (i) is 3! yes that's exactly why
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So I got the answer -f^'(-x)
but how is that an odd function
? I thought -f(x)=f(-x)

you are right
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What is the meaning of a spectral decomposition
what does it mean
matrices?
it's a theorem
it means that any symmetric matrix with real component can be diagonalized
thats it?
if i remember
but its like a whole operation
like ?
doesnt diagonilization just mean that all the eigenvalues are real
for the spectral decomposition
yes
??????
but be careful
I don't understand
whats wrong
Theorem 1 (Spectral Decomposition): Let A be a symmetric n×n matrix, then A has a spectral decomposition A = CDCT where C is an n×n matrix whose columns are unit eigenvectors C1, …, Cn corresponding to the eigenvalues λ1, …, λn of A and D is the n×n diagonal matrix whose main diagonal consists of λ1, …, λn.
Q(upside down V)QT
it's just a notation
define your variables, i have no idea what you wrote
Q is a matrix of normalized eigenvectors for the symmetric matrix
upside down V is the diagonilization
the diagonal matrix*
which contains all the eigenvaluea
its not called a diagonolization matrix?
and Q is the matrix where the columns are the eigenvectors normalized
where did you see that its called like that
its just a diagonal matrix that represents the symmetric matrix on a basis composed of eigenvectora normalized
nothing too deep
sorry im digesting that fact
Or in simple words, its an other expression of the matrix but in an other basis
and that basis is composed of his eigenvectors
okay, so I did out the operations, and I don't
I don't really get how tf this works
What is Q(upside down V)
just by itself
Let M be a symmetric matrix with real coefficients
M can be diagonalized and we have :
$M = QDQ^T$
Herels
where D represents the diagonal matrix composed of eigenvalues
yeah
and Q the matrix where the columns represent the eigenvectors of M
yeah
You want a proof of this theorem ?
I cant really tell how it works
fair enough
What actually is Q??
like
what is the matrix Q
what does it mean
I get that D like
scales the eigenvectors in Q by the amount that they would be scaled by the original matrix
I’m so sorry I fell asleep
Q is an orthogonal matrix
ah okay
also
if the homework says "find the spectral decomposition of M" and then gives a matrix M
what do you actually put down?
Can I reask this in a different channel?
.
nah but you need to find Q and D of course
yeah I know
well you'll need to find each matrix and then write the actual spectral decomp as M = your matrices
And state what they are
no need to do a multiplication
I said you diagonalize M
too late ._.
no that's the decomposition you decompose your matrix M into 3 matrices
You diagonalize M : characteristic polynomial, eigenvaluea eigenvector blablabla
Now that you have the basis formed by eigenvectors
you normalize it
Graam-schmidt is the classic way
When you are done fiding the orthonomal basis, you use it for Q
and thats it
wait
why do I have to use graam schmidt
cant I just find the eigenvectors, normalize them, and cram them into Q?
.
thats the classic way but I said Q is composed of normalized eigenvectors
Thats the spectral decomposition
np
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Write down each statement and its negation. Which of the statement and its negation is true and which is false?
10 is divisible by 2 or 3
according to the works soluitions the answer is:
P : 10 is divisible by 2 or 3 (false)
not P : 10 is not divisible by 2 and 10 is not divisible by 3 (true)
but i got the reverse answer. I was wondering where my thinking went wrong.
Here is a picture of my working out on a paint picture.
@cunning fog Has your question been resolved?
!15m
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@crisp iron
Stop posting in others' channels
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
@cunning fog Has your question been resolved?
@cunning fog Has your question been resolved?
@cunning fog Has your question been resolved?
@crisp iron
Write down each statement and its negation. Which of the statement and its negation is true and which is false?
10 is divisible by 2 or 3
according to the works soluitions the answer is:
P : 10 is divisible by 2 or 3 (false)
not P : 10 is not divisible by 2 and 10 is not divisible by 3 (true)
but i got the reverse answer. I was wondering where my thinking went wrong.
Here is a picture of my working out on a paint picture.
Image
anyone can help?
bro i have been @ tting this poor guy for the last 5 hours😂
<@&286206848099549185>
first proposition is true second is false
since 10 is divisible by 2 P or Q is correct and for the second since 10 is not divisible by 2 is false and its an and statement it suffices to say its false
solutions are therefore incorrect
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help
<@&286206848099549185>
do you know what continuous and non continuous data is
ok so its kinda self explanatory, if you look at a bar graph for example, what do you notice about the x axis values
its continuous/unchanging
and c can't?
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✅
what were the reasons you gave
you had to write a sentence explaining the reason for each answere
I just had to tick if I wrote the explanation or not
a can
b can't
c can
why a
you need to compare two quantitative variables
i would be quite nice as a bar graph
whats a quantative variable
quantitative- having quantity, a numerical value
favorite sport is a qualitative variable
ohhh - basically a number
tnx I got it now
I understand it now
just making sure
both variables should have a numerical value
pretty much
but just be careful that its not some trick question
i guess there arent very many trick questions i can think of, so you should be fine
alr then thanks and bye
have a good one
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i have to write a calibration algorithm that does something like this, i've done it with polynomials and linear regressions in the past but this is unfamiliar, ChatGPT suggests it might be piecewise linear interpolation, is that what I'm looking for here?
I hope the diagram is somewhat readable
@rugged spindle Has your question been resolved?
@rugged spindle Has your question been resolved?
I mean it doesn't seem like there's much to it from the info given
True value + offset = observed value
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Hi guys, where did he get 11x/7 from? Also is there a better way of doing this question?
What's 1 + 4/7?
And all it did was find the value for x, you still need to find the value for y
Still confused if I’m being honest
Where are you confused?
Do you know how to add fractions?
4/7 is a fraction, 1 is not
You need to find a common denominator
And add fractions
@lyric mica Has your question been resolved?
Oh yeah bruh I got it now thank you
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If I take a question like
4 (77) - 72
And rearrange it to:
4 (77) + 4 (-18)
Then combine the two together to form
4 (77 - 18)
I know this works, but what properties of arithmetic would that final step be? I know that in step 2, I'm factoring out a 4, but what is the step that lets me combine the fours by grouping the 77 and -18 into a single arithmetic expression
I feel like I know how to do it intuitively from when I last practiced algebra, but I've got no idea what the rule was that let met do it?
Distributive property
Alright ty, I think it threw me because I'm used to doing distribution in reverse
Thanks though, just doing some easier problems to get back into the swing of it and finding myself solving them using different concepts
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how do i solve?
is there a particular part of that that you don't know how to do?
i dont understand how to do an of it
starts with P ends with S
use that
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Geometric probability
.open
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i got 50.3 originally but i'm confused on how it's wrong, someone just walk me through the steps please
Show your work, and if possible, explain where you are stuck.
i found the radius which is 4, 4^2 is 16, and so i did 16(pi) to get 50.3
i used the distance formula but ig i some how miscalculated it because i re did it and got something else and it was correct
sorry for the waste of time
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not sure where to start
what value of x can you plug into the first series in order to get the second series?
@steep patio Has your question been resolved?
but how can we guarentee that the taylor series is equal to the function
well for that, you need to know something about analytic functions, do you have any theorems?
on the interval
well you can see from the coefficients that the series converges as long as |x-3| < 2, the question is whether it converges to the original function.. that's where the theory of analytic functions comes in
probably in the context of this question, you can just assume that it's true
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hi
thaTs the plan
divide by 3, square both sides, subtract 28, then square root to find x
ok thanks
wait divide what
riemann
why is 12 over the 2 then
idk that's the last question i'm stuck on
show the original question
that's it
screenshot or take a picture
yea no way your book wrote it like that
your fraction under the 12 is over the 2
12/2 = 6
so you either drew the line too long or it should be 6 on the right
it's like this mb
yea divide by 3/2 instead of 3
so what are the steps
divide what tho
no
o
those are 3 different equations
no like the steps
and would result in 3 different answers for x
3/2 is a number equal to 1.5
dividing by 3/2 on both sides would result in just the square rot on the left side
can you just send me like steps on how you did it i'm so confused
did you do this yet
is what 8?
.
,calc 12/(3/2)
Result:
8
yes
ok
After dividing by 3/2, what's your left hand side
just 3
no
0?
also no
nothing
what's this divided by 3/2
$\frac{\frac{3}{2}}{\frac{3}{2}} = ?$
riemann
do you know how to simplify this?
so you don't know how to divide fractions https://www.mathsisfun.com/fractions_division.html
Turn the second fraction upside down, then multiply, Ther are 3 simple steps:
@rustic yew Has your question been resolved?
@rustic yew Has your question been resolved?
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Need to determine if this is true, since they have the same truth values, we say this affirmation is true
@amber atlas Has your question been resolved?
What's with the o?
Supposed to be an "OR" judging from your work
The left side is true always.
The right side can be false
For example, if y = 4
So these two are not equivalent and so the whole thing is false
@amber atlas
Splitting them up into p,r,s and then forgetting what p, r, and s are is not a good strategy. Notably, on the left side, p and s are related
or
how can it be false if it has to be less than 3?
I noticed that sqrt(7)<3 too
so since one of the affirmations is true, we say that the disyunction is true if one of the affirmations is true
@amber atlas Has your question been resolved?
Let's look at the case y = 4.
Is y < 3? No. So that's false.
Is y² = 7? No. So that's false.
Is y³ = 27? No. so that's false.
Since we have F o F o F, we get a F.
@amber atlas
Notably, there's no rule against using y = 4.
@amber atlas Has your question been resolved?
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What is a possible way to divide by zero?
like a limit?
Whoever told you it’s possible is wrong
@main ruin Has your question been resolved?
But surely there must be some way, just because it has not been proven yet doesn't mean its not possible
mathematicians have certainly tried to add in division by 0 in a way consistent with existing algebra
its... kind of possible to do
the riemann sphere permits division by 0 in most cases, for example
but its not super interesting
in the riemann sphere you just get infinity which is not a very nice object to work with


