deft lagoon
ello
#help-0
exotic belfry
how many sticks do you need to get from one pattern to the next?
chilly dove
3 for n1 to n2 but n2 to n3 its 4
modest osprey
When y=0 x=-2/3 and when x=0 y=2
From this you can find slope and then just put it in y=mx+2
ocean hawk
no
ocean hawk
still no, be careful w/ your arithmetic
modest osprey
still no, be careful w/ your arithmetic
I think he got the formula wrong
Slope=y2-y1/x2-x1
So slope=2/(2/3)=3
It's given in the question
ocean hawk
those are givens
modest osprey
Y intercept is when x=0 and x intercept for y=0
ocean hawk
what is the point-slope form of an equation of a line, in general
and you're given 2 points to figure out what "m" is
ocean hawk
don't use decimals
modest osprey
don't use decimals
Yeah they suck
ocean hawk
you just do the same arithmetic as if there weren't fractions
don't let it trip you up
the two points you are given are these: $(-\frac{2}{3}, 0)$ and $(0, 2)$
ocean sealBOT
cwatson
ocean hawk
calculate the slope how you would with any two points on a line
do it step by step, being careful with arithmetic
yes
start with the numerator
don't feel stupid, just take one step at a time
what is the formula for slope when you have 2 points?
modest osprey
What grade are you in?
Ok from this reply ig above 8th grade
That's the end btw
Yeah i think someone wrote it up there
ocean hawk
so you have m=3
now use either of the 2 points you're given for the point-slope form of the equation
ocean hawk
that's the slope-intercept form
I guess it could be both depending on which one you picked
but it's right anyway
modest osprey
but it's right anyway
Hey so do you get paid for this or are you just that free?
ocean hawk
lol no I don't get paid
modest osprey
lol no I don't get paid
That's sad
ocean hawk
That's sad
lol why is it sad?
modest osprey
lol why is it sad?
Isn't it hard to deal with kids like these all day?
ocean hawk
Isn't it hard to deal with kids like these all day?
A. I don't "deal with" them all day, and B. it's good to keep in practice. and C. it's helping people
modest osprey
A. I don't "deal with" them *all day*, and B. it's good to keep in practice. and...
Bro you are the second kindest person i have ever seen
ocean hawk
Bro you are the second kindest person i have ever seen
there are lots of helpers on here who have infinite patience
modest osprey
there are lots of helpers on here who have infinite patience
Yeah patience is good.How do you practice that?
ocean hawk
yes
ocean hawk
Yeah patience is good.How do you practice that?
it's easier online, just don't be hasty in responding, don't be rude, etc. it's easier as you get older TBH
modest osprey
Honestly I think sometimes people even troll you guys by asking dumb questions but still you reply to each one of them to make them understand mad respect bro
modest osprey
it's easier online, just don't be hasty in responding, don't be rude, etc. it's ...
Hmm
ocean hawk
sometimes I might think to myself "how are you not understanding this" but you have to realize everyone learns at a different pace. if they're willing to take it one step at a time I don't mind taking the time to do that. if they're just looking for the answer then I won't help
modest osprey
sometimes I might *think to myself* "how are you not understanding this" but you...
Wise words. Wish school teachers would think like that
ocean hawk
never let someone make you feel stupid
modest osprey
Ok i am gonna change that to 9th grade
ocean hawk
what's the context?
those are both parentheses, it's just the 2nd set are "stretched out" to fit the fraction
but square brackets will still usually have the same function as parentheses
cyan rampart
wait so a [] at the value of n would exclude or include the value of n?
modest osprey
wait so a [] at the value of n would exclude or include the value of n?
Include
cyan rampart
ah i see thanks gman
ocean hawk
oh, well when dealing with intervals it's different
but when grouping terms in a formula they're the same
like $[(x + 1) + 5]$ is the same as $((x + 1) + 5)$
ocean sealBOT
cwatson
modest osprey
but when grouping terms in a formula they're the same
Well she sent an inequality so probably was trying to ask about intervals
ocean hawk
true, but it's a less than sign so they'd have to be open intervals
ocean sealBOT
IHateSaturn
cyan rampart
So you gotta ensure that: a. the value doesnt equal to 0 (x does not = 1)
And that (x-7/2)<0
ocean hawk
actually good point, the answer for that interval problem should just be $x < 7/2$
ocean sealBOT
cwatson
cyan rampart
Yeah it should be x < 7/2 and x ≠ 1
ocean hawk
oops, yea and x can't equal 1. so the picture looks correct
lone heartBOT
@lone atlas Has your question been resolved?
coral beacon
How do you find the concavity of a function
lone heartBOT
How do you find the concavity of a function
coral thorn
what does the first derivative tell us about the function?
modest osprey
what does the first derivative tell us about the function?
Monotonicity?
coral beacon
this is grade 12 math
coral thorn
yes
modest osprey
this is grade 12 math
I know
coral beacon
don't you need to find the second derivative
modest osprey
don't you need to find the second derivative
Well he wanted to explain like a proper teacher ig
coral thorn
after finding the second derivative, find the inflection points i.e. when the second derivative = 0
modest osprey
after finding the second derivative, find the inflection points i.e. when the se...
And now he is angry that you interrupted his flow therefore he is gonna explain in a rush lol
coral thorn
if the s.d. is positive, it’s concave up, if it’s negative, it’s concave down
if it switches from positive to negative or vice versa over the inflection point, you have a switching concavity
modest osprey
He really made him angry lol
coral thorn
huh
coral beacon
ic
modest osprey
Continue on
coral beacon
so you get concavity after setting the second der to 0 to get inflections point and if it's positive then its concav up?
coral thorn
well, the inflection points tell you where there’s a switching concavity but say you have a constant as your second derivative, the sign of that constant, +ve/-ve will tell you if it’s either concave up or concave down
modest osprey
so you get concavity after setting the second der to 0 to get inflections point ...
I don't think that's how it works right?
coral beacon
modest osprey
It's something like when you get the point of inflection put a value more than it in 2nd derivative to see if it's positive then the the concavity is up and if it's negative the concavity after that point is down similarly test it for the point before inflection
coral beacon
ic
coral thorn
if the s.d. is positive, it’s concave up, if it’s negative, it’s concave down
i...
that’s what i meant in this
coral beacon
that makes more sense
coral thorn
but i was talking about constant derivatives
coral thorn
like in the case of x^2
coral beacon
alright
modest osprey
<a:aPES_CoolClap:655414093045563392>
Why do I think you are just here to test the knowledge of other people and are enjoying them giving you wrong answers.That personality is seriously messed up.
modest osprey
perhaps you're gravely mistaken
Maybe
coral beacon
because i actually understood you
modest osprey
because i actually understood you
Finally someone understands me🥲
coral thorn
you can type .close to close the channel
coral beacon
.close
lone heartBOT
coral beacon
??
slender quiver
as it comes form the negative side
coral thorn
approaching -2 from the left/negative side
coral thorn
what is the question
slender quiver
where is -2 on the x axis
modest osprey
does anyone know where to start to answer this question
The question is what is the question
lapis parcel
this is the question
coral thorn
let them explain the answer bruh
lapis parcel
x_x
slender quiver
x_x
modest osprey
||you gave the answer||
Wait we aren't supposed to do that?
slender quiver
no
lapis parcel
it's infinitely going down
slender quiver
supposed to teach how to get it
slender quiver
where
sour sinew
in the c one
modest osprey
in the c one
Wait why is your profile pic a female but the role assigned to you male? Kinda sus
lone heartBOT
sour sinew
Wait why is your profile pic a female but the role assigned to you male? Kinda s...
i like
female
slender quiver
np
sour sinew
.close
obtuse current
im practicing for my exam
obtuse current
wdym
carmine reef
looks very tricky
carmine reef
i think you need to represent each directional derivative in terms of f_x and f_y
then solve the system of equations
obtuse current
like fx=2, fy=3?
obtuse current
why sqrt2?
modest osprey
that looks like the exam
Lol
obtuse current
bc its 2
carmine reef
use the formula for computing directional derivative from the gradient vector
obtuse current
ah ok
modest osprey
Btw if I may ask why is google maps running in the background doxxing you?
obtuse current
Btw if I may ask why is google maps running in the background doxxing you?
wdym
modest osprey
wdym
Uhh I can see your location in the image or it could be that's just some random address you opened
obtuse current
idk if its doxxing me since i was just looking up a restaurant in nyc lol i dont live there 😅
modest osprey
Lol ok
obtuse current
i wish
potent forge
You get to know that f(0)=100 and f(6)=250, show that a=4 b=ln(4)/6
potent forge
Idk how to even begin approaching this task since the info i get is, hard to use
Also since this is part of an exam where you cant use calculators or external tools
Im even more lost on how to do this
potent forge
I know I should plug in the value of t, but idk how to solve -b with e, as for the expressions for f(0) be, do you mean how the function will look like with 0 in the t? I didnt learn math in english so there are some things I dont understand
potent forge
That would give 500/1+a no?
limpid turret
That would give 500/1+a no?
500/(1+a)
Use parentheses
potent forge
so you should be able to solve for "a"
gives me 1
potent forge
500/(1+a)
Use parentheses
Thanks, I forgot about those
ocean hawk
show your work, how do you get a=1
potent forge
I timed by 500 on the side leaving 1+a, got rid of 1 leaving me with...0, not even one
$500/(1+a)500=0500$
ocean sealBOT
Cloudstains
potent forge
$500-a-a^2=0$
ocean sealBOT
Cloudstains
ocean hawk
sorry i stepped away
potent forge
np
ocean hawk
you were given that $f(0) = 100$, yes? and you also calculated that $f(0) = \frac{500}{1 + a}$? so set those equal to one another
ocean sealBOT
cwatson
potent forge
wym set them equal, as in 500(1+a)=500/1+a
ocean hawk
no
coral thorn
100 = 500/(1+a)
ocean hawk
$f(0) = 100$ and $f(0) = \frac{500}{1+a}$
ocean sealBOT
cwatson
ocean hawk
the left-hand side of both those are equal, so you can set the right-hand side equal to each other
ocean sealBOT
Cloudstains
potent forge
Like this?
ocean hawk
yes, exactly
potent forge
You get to know that f(0)=100 and f(6)=250, show that a=4 b=ln(4)/6
But now I have the monster that is b, ill asumme ill have to use f(6) and plug in t as 6?
ocean hawk
yes, and be sure to use whatever you find for "a" as well
potent forge
so plug in a as 4 as well?
ocean hawk
yes, did you get a=4 yourself?
potent forge
Ah yeah since I prooved it
I mean you did
I did do the equation myself but you guys helped set it up
Again lots of thanks
ocean hawk
no worries. then yes, you'll write "4" instead of "a" and you'll be able to solve for "b"
potent forge
Okay so, Here is the question, can e^-(ln(4)) get turned into 1/e^(ln(4)) which is same as 1/4?
ocean hawk
yes
potent forge
Because then 4*1/4 becomes 1, which gives us 1+1
AH YES
I got it
Thanks so much dudes!
Thanks so much Cwatson
ocean hawk
hang on, what did you get for b?
potent forge
b = ln(4)/6
And since t becomes 6, the numerator gets canceled
leaving only e^-ln(4)
by numerator i meant the bottom number in a fraction, idk if thats the right word for it
is that right?
ocean hawk
numerator is the top, denominator is the bottom
but yes, your understanding is correct
potent forge
numerator is the top, denominator is the bottom
Thanks, im not familiar with the terms, but again I appreciate your guidance
Imma close this then teach, thanks!
.close
glossy sinew
for the function f(x) = \root(3)(x)-10, find f^(-1) (x)
lone heartBOT
for the function f(x) = \\root(3)(x)-10, find f^(-1) (x)
limpid turret
Do you mean $f(x)=\sqrt[3]{x}-10$?
ocean sealBOT
SWR
glossy sinew
yes
limpid turret
What have you tried
glossy sinew
im not sure
cyan seal
Do you know what you have to do? @glossy sinew
ocean hawk
how do you find the inverse of any function? what if it was $f(x) = x - 10$?
ocean sealBOT
cwatson
lone heartBOT
@glossy sinew Has your question been resolved?
ocean hawk
?
lone heartBOT
lone heartBOT
Available help channel!
alpine sable
hello
alpine sable
why does mclaurin and taylor series work???????????
like, why derivates and factorial
stark yew
why does mclaurin and taylor series work???????????
The mclaurin series is a special case of the taylor series. Therefore a proof of Taylor's theorem is sufficient. You can find the proof and links to more reading material on the wikipedia page for Taylor's theorem.
https://en.m.wikipedia.org/wiki/Taylor's_theorem
Also, this question is better fitted for #math-discussion. Feel free to message there to engage in further discussion on the subject.
lone heartBOT
@alpine sable Has your question been resolved?
sharp pine
Tried it several time but still can't figure out how to solve this problem . Any help would be appreciated!
sharp pine
when i pressed hint, it said half life in minutes so I mutiplied 3 times 24 times 60
rocky grove
Well
You can use t in days but you have to account for it
You can also use t in hours too
Just make sure the units in the exponents work out
sharp pine
Ok let me try solving for r this time
wary stream
You can use t in days but you have to account for it
Not if the question says amount of ... in t hours so I'm assuming it wants an equation where t is in hours
rocky grove
1/2 = e^{r*(3*24)}
rocky grove
Not if the question says `amount of ... in t hours` so I'm assuming it wants an ...
Yeah but the units can be worked out in the exponent
rocky grove
That is if r is in 1/days
You want it in 1/hour
So how do you convert 1/days to 1/hours?
sharp pine
times it by 24
rocky grove
What do you multiply by 24?
sharp pine
the r?
rocky grove
Hmm
r is in 1/days
And 1 day has 24 hours
So you take the days unit and replace it with 24 hours
So 1/days = 1/(24 hours)
Right?
Or am I missing something?
rocky grove
So like
$\frac 12 = e^{3\times 24 r} \ \
\ln(\frac 12) = 72r \ \
r = -\frac{\ln 2}{72}$
Should work out
sharp pine
so it's Q(t) = 50e^0.00694t
hot bluff
huuuuuh
ocean sealBOT
VulcanOne
rocky grove
Yeah we're fixing that together
sharp pine
This one's correct
rocky grove
so it's Q(t) = 50e^0.00694t
Hmm
rocky grove
ln(2)/72 gives me 0.0096 or something
sharp pine
it's Q(t)= 50e^-0.009627t
sharp pine
oh ok
rocky grove
6 mg
Then you get the t that makes your P = 6 mg
Your t will be automatically in hours
Same way you solved for r
hot bluff
220.28712
hot bluff
wait though
hot bluff
you need the right answer
sharp pine
you need the right answer
it's right
hot bluff
@sharp pine how did you get the decay rate
because its wrong imo
what im seeing up above
rocky grove
<@627901958493044777> how did you get the decay rate
The question says 3 days for half life
sharp pine
nah its correct bro
hot bluff
its not because you got the wrong answer
sharp pine
i put in the answer and it shows its correct
hot bluff
decay rate should be -0.231
hot bluff
you only need to convert to days in the second part at the final answer x 24
decay rate should be days
hot bluff
part 1 in the screenshot shows exponential growth too
because k is positive when it should be negative
Q(t) = Pe^kt is our start point, m(0) = 50mg or our initial mass
which is also = P
rocky grove
hot bluff
we know 3 days our mass is 1/2 the original
hot bluff
but he didn't get the right answer. he only got close
sharp pine
i have one more question if u dont mind
rocky grove
Sure
sharp pine
The first answer is correct however for the second answer its close to 76 but it say i am rounding it too much
rocky grove
Hmm
hot bluff
alright
rocky grove
How much did you round when you found r?
sharp pine
How much did you round when you found r?
76.77
hot bluff
m(30.17) = 1/2m(0)
sharp pine
in my calulator it says 76.77779 something
sharp pine
correct
rocky grove
Are you doing this on a scientific calculator?
sharp pine
yeah ti-84 calc
wary stream
in my calulator it says 76.77779 something
If you got this, why did you type in 75.4?
Why not 76.78?
sharp pine
If you got this, why did you type in 75.4?
i put 76.779 before but it did not work so putted random numbers around 76 to see if i get it correct
rocky grove
I think you can store values in letters
sharp pine
Why not 76.78?
i did but it says i have been rounding it too much
hot bluff
76.7779
hot bluff
sharp pine
says i have been rounding it too much
that's what i got too
with my scientific calc
rocky grove
with my scientific calc
Could you show me an image of your calculator?
I wanna see if you have letters
That you can use to store values
wary stream
I wanna see if you have letters
Ti - 84 does, and you can store values
rocky grove
I'm pretty sure you can
hot bluff
76.762153
wary stream
There's a button labeled STO>
hot bluff
seems they want tons of precision
sharp pine
but the answer has been solved already
rocky grove
I suggest you store an expression like ln(0.5)/30.17 into a letter
Then you use that letter when finding the t
Like so
sharp pine
i did something like -ln(6/35)*(100000/2279)
wary stream
says i have been rounding it too much
You need to talk to your teacher about the tolerance on these questions, because 76.776 is like around less than 0.02% tolerance
sharp pine
You need to talk to your teacher about the tolerance on these questions, because...
yeah teacher wont actually mind it but the issue is the webwork program
it doesn't tolerate a minor rounding
rocky grove
I think the webwork can accept tolerance but it has to be programmed for it
wary stream
Most teachers don't design online hw to have a tolerance of less than 0.02%. They can set the tolerance level
Less than 0.02% is just crazy
hot bluff
0.5% should be plenty
stable portal
what does this mean?
scenic wing
$x^4-2=x^2$
lone heartBOT
$x^4-2=x^2$
ocean sealBOT
putridplanet
scenic wing
substitute a=x^2
ok
glass atlas
ax^2-2 =a
lone heartBOT
@scenic wing Has your question been resolved?
chrome plinth
can a midline be a positive number?
lone heartBOT
can a midline be a positive number?
chrome plinth
like 60
ignore the numbers at the bottom starting at 5, im going to fix that
besides that, is this sinusoidal function correct?
@ me if you respond
pallid scarab
@chrome plinth I mean the function you just graphed, assuming it is $f(x) = 60 + 20sin(ax+b)$, does have a midline at $y=60$
ocean sealBOT
rafilou2003
pallid scarab
does this answer your question?
chrome plinth
does this answer your question?
so the graph is correct as long as I use that formula?
pallid scarab
Yes
pallid scarab
**rafilou2003**
You might have to specify which values of a and b you used here
it also might be irrelevant
chrome plinth
ok
pallid scarab
is that the formula for all graphs where the midline is a positive number?
no, not at all
chrome plinth
**rafilou2003**
also, where did the 20 come from in that equation?
pallid scarab
also, where did the 20 come from in that equation?
I just saw that the lowest point was around ~40 ish
chrome plinth
I just saw that the lowest point was around ~40 ish
so 20 represents the lowest point?
pallid scarab
so 20 represents the lowest point?
20 represents the difference between the midpoint and the extreme points here
chrome plinth
oh, ok
pallid scarab
However, all functions may or may not look like that
chrome plinth
ik im asking a lot of questions, but which sinusoidal graphs require me to use this formula?
pallid scarab
ik im asking a lot of questions, but which sinusoidal graphs require me to use ...
The formula f(x) = Asin(ax+b) + M, where M is the mean and A is the amplitude of oscillations
This one?
well as long as you see a sinusoidal wave
pallid scarab
The formula f(x) = Asin(ax+b) + M, where M is the mean and A is the amplitude of...
you can bet this formula will be useful
pallid scarab
is that the formula for all graphs where the midline is a positive number?
However, here is a counterexample for this question
chrome plinth
i meant f(x)=y+20sin(ax+b)
(not sure what symbol 20 should be)
or is that the same thing you used?
pallid scarab
i meant f(x)=y+20sin(ax+b)
(not sure what symbol 20 should be)
the "20" here is the amplitude of oscillations
it can be anything
pallid scarab
The formula f(x) = Asin(ax+b) + M, where M is the mean and A is the amplitude of...
leading back to the general formula here, replacing "20" by any number
chrome plinth
leading back to the general formula here, replacing "20" by any number
both formulas you presented to me can work?
pallid scarab
The formula f(x) = Asin(ax+b) + M, where M is the mean and A is the amplitude of...
this formula works everytime for sinusoidal waves
pallid scarab
i meant f(x)=y+20sin(ax+b)
(not sure what symbol 20 should be)
this one, almost never except in this example where the amplitude was exactly 60-40 = 20
chrome plinth
the amplitude has to be 20?
so i cant use f(x)=y+amplitude of oscillations(ax+b) unless the amplitude is exactly 20.0?
pallid scarab
the amplitude has to be 20?
nonono
pallid scarab
so i cant use f(x)=y+amplitude of oscillations(ax+b) unless the amplitude is exa...
this works everytime
chrome plinth
for every sinusoidal function?
pallid scarab
yes
mossy veldt
please help me with this :
lone heartBOT
please help me with this :
long axle
Can u translate the directions please
mossy veldt
Ok i will translate it in english
Exercise 1 Calculate the derivative of the function f on the interval I in each case:
a) f(x) = √x³-3x² + 1
;1 = [3,+00 [
c) f(x) = 5cos²x ; 1= IR
scarlet oriole
it asks to derive the functions
long axle
I recommend logarithmic differentiation for number 2
lone heartBOT
@mossy veldt Has your question been resolved?
mossy veldt
I didn't understand please can you explain more than that?
lone heartBOT
@mossy veldt Has your question been resolved?
half stream
on number 2 you should be using the chain rule in conjunction with the power rule, d/dx[f(x)^n] = n * (f(x))^(n-1) * f'(x)
lone heartBOT
@mossy veldt Has your question been resolved?
twin crown
I'm doing geometry and I was gone for about 2 weeks so I'm really behind
twin crown
I have a general idea of what i need to do but I'm not sure of the right formula to find the value of x
gray isle
what's your general idea
gray isle
you aren't being asked to find lengths, nor have you been given any lengths, Pythagoras isn't useful here
twin crown
oh
gray isle
since you're mentioning that, you seem to recognise that you have a right triangle
sharp thorn
you know any relations with tangent and diameters?
gray isle
and just consider the angle sum of a triangle
twin crown
nope
sharp thorn
well, they are perpendicular to each other
twin crown
so, what does that mean? O = 45?
sharp thorn
how can o = 45 it is the circle's center
see the point where the tangent and the dia meet
sharp thorn
what are the angles at two perpendicular lines
twin crown
congruent?
sharp thorn
wdym?
twin crown
yes
sharp thorn
what
twin crown
they intersect at a point
sharp thorn
thats it?
twin crown
they intersect at a right angle
twin crown
X = 133
sharp thorn
why are you adding
twin crown
X = 47
lone heartBOT
lone heartBOT
Available help channel!
ornate tundra
If 3f(2x-5)-1=x^2, what’s f(x)?
lone heartBOT
If 3f(2x-5)-1=x^2, what’s f(x)?
wanton pebble
what is 2[(x+5)/2] -5
ornate tundra
x
wanton pebble
so what is f(2[(x+5)/2] -5)
wanton pebble
yo
wanton pebble
yes
wanton pebble
good
ornate tundra
Now what do I do
ornate tundra
That’s it?
ornate tundra
Alright thanks
wanton pebble
welcome
ornate tundra
.close
lofty pollen
When the polynomial y ^ 3 + 3y ^ 2 - 2y + p is divided by (y+ 2), the remainder is R, When the polynomial is divided by (y-2), the remainder is 1/2R. Find the value of p.
lofty pollen
Help Pls
wanton pebble
do you know how to divide polynomial
lofty pollen
yes
wanton pebble
so solve them
lofty pollen
How?
lone heartBOT
@lofty pollen Has your question been resolved?
lone heartBOT
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ripe turret
lone heartBOT
ripe turret
DO I have to do that
Step for each term?
rose sigil
i would just shift the index first
ripe turret
i would just shift the index first
wdym
rose sigil
the original sum is equal to $\sum_{i=5}^{95}i^3$
ocean sealBOT
💜𝓁𝒶𝓎𝓁𝒶💜
ripe turret
the original sum is equal to $\sum_{i=5}^{95}i^3$
how did u get that?
rose sigil
write out a few terms in each and i think you’ll see they are the same 🙂
ripe turret
write out a few terms in each and i think you’ll see they are the same 🙂
no?
im saying
how did u get that
frank apex
(10 - 5)^3 + (11 - 5)^3 + ... (100 - 5)^3
ripe turret
?
frank apex
=
5^3 + 6^3 + ... 95^3
ripe turret
(10 - 5)^3 + (11 - 5)^3 + ... (100 - 5)^3
where did 5 come from
rose sigil
there’s a 5 in the problem loll
ripe turret
there’s a 5 in the problem loll
ok well im getting a completly different answer
i did this
n(n+1)/2 * n(n+1)(2n+1)/6
is that correct?
frank apex
why
rose sigil
no
frank apex
each sum is equal to its own thing then you gotta multiply them by the factors and add them together
rose sigil
n(n+1)/2 * n(n+1)(2n+1)/6
also you need more detail, saying you “did” this is really unclear
but whatever you did with it is not right
frank apex
the formula here isn't the product of the sum of squares and the sum of integers formula
you just kinda gotta look it up or memorize it
ripe turret
sum of k * sum of k^2
which is k^3
hm so how do we do this
if that is not correct
frank apex
you can look them up
they are handed down by the gods and not to be instantly figured out
austere trail
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frank apex
I recommend getting rid of the ln first
maybe that's not the method holdon
ugh that's not going to work mb
austere trail
this is the indefinite antiderivative btw
austere trail
ugh that's not going to work mb
no problem!
I appreciate you trying to help anyway
frank apex
I was thinking by parts ln becomes 1/x and reduces the x^2t to an x^2t-1 which allows a usub but that's not how by parts works
austere trail
There's 3 functions though
lone heartBOT
@austere trail Has your question been resolved?
austere trail
<@&286206848099549185>
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@austere trail Has your question been resolved?
alpine sable
how do you get these problems?
i dont think its an evil professor's assignment is it?
austere trail
i dont think its an evil professor's assignment is it?
I'm afraid it is.
alpine sable
I'm afraid it is.
from a math course or engineering course or sm?
austere trail
from a math course or engineering course or sm?
It's a math course on advanced calculus
lone heartBOT
@austere trail Has your question been resolved?
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@austere trail Has your question been resolved?
dreamy blaze
I have a geometry problem:
Construct a triangle ABC. Take H as the midpoint of BC. Connect A with H. Construct BK so that angle KBA = KBC and BK is perpendicular to AH at O. The area of OKA + OHB = 234cm2. Calculate the area of ABC
slender quiver
!status
lone heartBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
try your best and... read
lone heartBOT
@dreamy blaze Has your question been resolved?
dreamy blaze
<@&286206848099549185>
frank apex
I have a geometry problem:
Construct a triangle ABC. Take H as the midpoint of ...
must K be on AC
twin echo
<@&286206848099549185>
Note ∆AOB is congruent to ∆ HOB
As all angles are equal nd one side is common
dreamy blaze
must K be on AC
yes
dreamy blaze
Note ∆AOB is congruent to ∆ HOB
not neccessarily
we havent proven ao = oh
imma go to sleep soom
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daring inlet
A group of students recorded the number of hours they spent studying for a test. The data they
collected are: 2, 3, 1, 4, 2, 5, 3, 1, 6, 2. Classify the data into intervals of 2 hours and construct a
frequency table for the data.
daring inlet
anyone help
heady pollen
!status
lone heartBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
1
heady pollen
"intervals of 2 hours"
example:
how many students spent between 0 and 1 hours?
how many spent between 2 and 3 hours?
frequency = how many
heady pollen
ahh i see what you mean there
probably depends
i would argue 0-1 makes more sense here (also because of the data set is so small)
daring inlet
can u ask @earnest saddle to help me out
heady pollen
you could argue that 0-2 is a 2 hour difference
you could also argue that 0-1 is an interval with 2 possible values (0 and 1)
magic bison
Can I help?
daring inlet
ok sure
A group of students recorded the number of hours they spent studying for a test. The data they
collected are: 2, 3, 1, 4, 2, 5, 3, 1, 6, 2. Classify the data into intervals of 2 hours and construct a
frequency table for the data.
heady pollen
we can stick with your definition then
so we would get the following intervals:
0-2 hours
3-5 hours
6-8 hours
now look at how many students fall into these categories
magic bison
Ok do it it's simple 0-2,2-4,4-6and so onn
daring inlet
no
magic bison
now look at how many students fall into these categories
He is saying right things only
Can you explain what you want clearly?
daring inlet
Ok do it it's simple 0-2,2-4,4-6and so onn
but in 2, 3, 1, 4, 2, 5, 3, 1, 6, 2 what will the tally be?
i mean that of 6 numbers
which number's tally will it be
magic bison
Put a table for the class i stated
daring inlet
so which number will it be?
magic bison
in 0-2 will it be 1?
0<=X<2
magic bison
2
There are two 1 hour students
Am i right buddy can you understand or should I repeat
?
daring inlet
but
magic bison
Yeah
daring inlet
its 2 hour difference so 0-2 2-4 4-6 6-8 the value thats closer to 0 or 2 or 4 or 6 will be it right
magic bison
Be what?
daring inlet
the tally
magic bison
Nah what ever comes in range is acceptable for tally
If you got 100marks let's say
Does your mark come in between 95-105?
What about 100-105?
What about 95-100?
magic bison
Yuo
magic bison
And also 95-105 right
daring inlet
the tallies will be 2,3,1 rright
magic bison
Hmm nope your tallied should add up to total number of elements given
magic bison
2 for 0-2 (of 1 )
Two is right can you say the elements buddy?
daring inlet
can u pls solve for me its assignment
daring inlet
ok
magic bison
For 0-2 count number of elements lesser than 2 and greater than or equal to 0
daring inlet
yes
magic bison
How many elements and what elements did you get?
daring inlet
2, 3, 1, 4, 2, 5, 3, 1, 6, 2
magic bison
1,1 is the elements
magic bison
And frequency of the class is 2
We have to calculate frequency of class not each individual values
So next class try and do it yourself
For 2-4
magic bison
2 is also included right
Bottom limit is included
So 2 is also in this class
Now count
daring inlet
but i only have to write of only 1 right
magic bison
Wdym
magic bison
There are four different people right
daring inlet
i have to either write 2,2 or 3,3
tall pebble
Can someone explain the solution for part b of this question? Why is the formula for cost of fuel being multiplied by the distance of the trip (1000)? Why is there a 1000/v?
undone lantern
Can someone explain the solution for part b of this question? Why is the formula...
1000 km is the distance
v km/h is the speed
what do you think happens when you divide them?
marsh rapids
if it's fuel per kilometer, total fuel cost is cost * distance
tall pebble
what do you think happens when you divide them?
oooo it gives the amount of time the driver drives
tyty
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lone heartBOT
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Available help channel!
alpine sable
hello - how do i begin
lone heartBOT
hello - how do i begin
heady pollen
for the area, you need AC and BD
we have AC
so we need BD
we can divide BD into two parts, an upper and a lower part
to get those, pythagoras should work
also your definition of AC is a bit weird
$AC=(3+2\log(4)8)=3+16\log(4)$
ocean sealBOT
~Martin
alpine sable
also your definition of AC is a bit weird
how?
astral briar
2* log base 4 of 8?
heady pollen
or does it mean 2log(x) = log_2(x)
astral briar
i think they meant 2 * log base 4 of 8
heady pollen
weird notation
astral briar
well we can simplify it then
2*log base 4 of 8 = log base 4 of 8^2 = log base 4 of 64
alpine sable
oh i was just about to solve
okay so
we split the diagram into two pieces, one upper part and one lower part and then solve for BD? cause we're given that AC = 6
heady pollen
for me the answer will not be pretty 😦
alpine sable
dam why
astral briar
not rly hard
heady pollen
astral briar
heady pollen
here we can use pythagoras to get BM
where M is the middle point where everything intersects
gonna go eat something, cya in a few minutes
im sure blighter can help you in the mean time
alpine sable
sorry i went o eta food
lone heartBOT
@alpine sable Has your question been resolved?
dreamy swallow
Can someone please explain to me how to solve this
lone heartBOT
Can someone please explain to me how to solve this
finite flax
Where does the square root of two come from?
It always happens that way for 45 degree triangles
Special right triangle ratio
You can work it out yourself:
Right triangle with both legs equal (making it a 45 degree triangle)
It's just the standard ratio
(sqrt2,1,1)
if we multiply through by r, we get (sqrt(2)r,r,r), as required
You can derive this from pythagorean theorem where both legs measure r and the hypotenuse is unknown
lone heartBOT
@dreamy swallow Has your question been resolved?
tame dragon
can anyone find my stupid mistake please
lone heartBOT
can anyone find my stupid mistake please
lone heartBOT
gray isle
a better approach would be to use the prod to sum identity
tame dragon
I did it in another method
but I tried 2 methods to see if it worked
and the method I thought worked didn't lol
lone heartBOT
Available help channel!
stone solstice
lone heartBOT
stone solstice
Hey, i’m a little lost here tbh, any guidance to start the problem would be helpful!!
<@&286206848099549185>
slate monolith
i think you can use the fact that R + P for boys is a certain % away from each
which you can use to find the relative size of each school
@stone solstice
frank apex
rb, pb, rg, pg
=> set up some equations to find number of boys and girls at each
might be necessary
stone solstice
i think you can use the fact that R + P for boys is a certain % away from each
Uh
So like
stone solstice
i think you can use the fact that R + P for boys is a certain % away from each
That’s where i’ve gotten😭
slate monolith
i dont really follow
stone solstice
Ik, i think i’m completely off here