#help-0

1 messages · Page 169 of 1

cinder spindle
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not sure how to do d

lone heartBOT
#

@cinder spindle Has your question been resolved?

cinder spindle
tacit bobcat
#

!status

lone heartBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
remote heron
#

you know the relative scale of the components

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if you take arccos(.8/1.8)

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@cinder spindle

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does getting the angle give you enough of a push to get the time?

cinder spindle
remote heron
cinder spindle
#

the guy's going too fast

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what the fuck am i even saying

remote heron
#

idk

tacit bobcat
#

Can you draw the problem out

remote heron
#

you should know ive taken sleeping pills so i'm pretty sleepy

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can you explain anything more about your confusion?

cinder spindle
#

i mean, i just don't really know how to start at all

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i've tried drawing diagrams

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but i don't know

tacit bobcat
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What don't you know

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I've seen 0 posted diagrams

remote heron
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The motivation of the diagram is of vectors

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a boat moving across the river in the context of the problem has velocity drawn from 2 components

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one is the speed of the river, and it pushes directly parallel to the bank

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the other is the speed of the paddling, and it pushes directly parallel

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the resultant moves from bank to bank

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All that babbling to say you should draw a triangle

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do you have any triangles?

cinder spindle
remote heron
#

yea that looks pretty good

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but id add

cinder spindle
#

the final answer won't be a right angled triangle

remote heron
#

it will

cinder spindle
#

hm

remote heron
#

tell me this

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lets say that piece you have labelled as 1.8

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lets say some time has passed

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and its now 3.6

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after this amount of time, what has the piece labelled 0.8 become?

cinder spindle
#

1.6

remote heron
#

right

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so no matter what length they are

cinder spindle
#

i tried doing

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64 / 0.8

remote heron
#

you can write them as 1.8a and 0.6a

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where a is just some number that scales them together

cinder spindle
#

right

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wait

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FUCK

remote heron
#

so you can definitely get the angle now

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try adding the a, and using trig functions

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or whatever letter you like i guess

cinder spindle
#

you're referring to x in my diagram

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?

remote heron
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x looks like an angle?

cinder spindle
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right

remote heron
#

my point is

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you can write the diagram more generally

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ANY triangle for this specific set up can be written as 1.8a and 0.8a

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for some a

cinder spindle
remote heron
#

right

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oh

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you mean

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yea i was saying this is sufficient to solve for x

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i mean it was before but

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(since the angle doesnt change)

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its specifically the insight that they have to scale together that allows you to get the angle

cinder spindle
#

yea but solving for x rn won't give me the right answer

remote heron
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use a trig function

cinder spindle
#

yeah ik

remote heron
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what ratio relates these sides

cinder spindle
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tan(1.8/0.8)

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well inverse tan

remote heron
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so tan isnt what you want

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wait

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did i use the wrong one

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but i got the right answer

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i knew i shouldnt have started helping

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but no one else was and i wanted to know the answer

remote heron
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so whats wrong with the diagram, then

cinder spindle
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wha?

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you can't do inverse cos(1.8/0.8)

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that's undefined

remote heron
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no, flip em

cinder spindle
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the fuck

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bru

remote heron
#

$\arccos \qty( \frac{0.8}{1.8} ) \approx 63.31$

ocean sealBOT
#

jan Niku

remote heron
cinder spindle
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63.61

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but ye

remote heron
#

ah, ye

cinder spindle
#

welp

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fuck

remote heron
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sorry man like i said im a little woozy

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but helping with math isnt flying a plane

cinder spindle
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how old are you btw

remote heron
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old man

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👴

cinder spindle
#

nice

remote heron
#

so cosine of

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my guess is

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hrm

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lemme screw around

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if another helper comes, need help with D

cinder spindle
#

i think now's a good time to ping helpers

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@mental coyote

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for fuck sake

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what degenerate named himself helperssss

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specifically

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to fuck us over

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<@&286206848099549185>

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lord and savior maximo

surreal meadow
surreal meadow
cinder spindle
#

aids

remote heron
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well chromium at the very least ill be able to help once i get some sleep

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it may just be 3-12 hours

cinder spindle
#

ah

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that's nice

#

fuck this

#

.close

lone heartBOT
#
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pliant nymph
lone heartBOT
pliant nymph
#

ii and iv

lone heartBOT
#

@pliant nymph Has your question been resolved?

gusty gorge
#

what about it don't you understand

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silent sage
lone heartBOT
silent sage
#

Have inquired regarding this doubt previously; My question is:

How do I prove that |(u-v)/2| = pi/3?

I am not quite sure how to plot it without being aware of the values of the vectors involved. (Have referred to the video previously linked by Mr. Riemann)

lone heartBOT
#

@silent sage Has your question been resolved?

thin maple
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oh hi

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:(

silent sage
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#discussion / #chill

I may've misconstrued your intentions since you are new to the server; assistance will be appreciated.

thin maple
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i think its by definition of summing the vectors

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as long as |uxv|=sin(theta) is valid you can do this

silent sage
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It's already been proven that |uxv| = sin pi/3

thin maple
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think abt it geometrically

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|(u-v)/2|=sin(theta/2)

silent sage
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But all the vectors were visualised here had values.

thin maple
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its 1

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unit vectors

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so throw away the values

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theyre just equal length lines

silent sage
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Facing two arbitrary directions such that the angle between them is pi/3 right?

thin maple
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sure

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doesnt have to be

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but in this case yes

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2pi/3 right?

silent sage
thin maple
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theyre vectors

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the angle itself cant just

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change

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they hv direction

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even though sine is identical

silent sage
#

Right. It would've altered the value if it was some other trigonometric function.

thin maple
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yep

silent sage
#

I do need to assume some values for plotting u-v/2 though right?

thin maple
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theyre 1

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it says there

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unit vectors

silent sage
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They're unit vectors so I can only think of (1,0), (0,1) etc. but the angle between these isn't pi/3..

thin maple
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(rt(2)/2,rt(2)/2)

silent sage
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😮

frosty marsh
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Help

silent sage
frosty marsh
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Ok

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Done

silent sage
#

Kindly delete them from here now. 😅

#

@frosty marsh

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I don't have OCD but this channel doesn't look neat anymore.

thin maple
#

@frosty marsh

silent sage
# thin maple (rt(2)/2,rt(2)/2)

Anyways getting back on track in the meantime; is it possible to predict two vectors in this manner which would have pi/3 as the angle between them?

thin maple
#

uh

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just convert between cartesian and polar

lone heartBOT
#

@silent sage Has your question been resolved?

silent sage
#

Trying to figure it out.

thin maple
#

what else btw

lone heartBOT
#

@silent sage Has your question been resolved?

silent sage
#

waaaaaaaaaaaaaaaaaaaaaaaaaaaait a little longer

thin maple
#

oki!

silent sage
#

yass I think I've got it.

#

I let u = (1,0) v=(1/2,√3/2)
[(1,0) and (1,2pi/3) respectively in polar coordinates first, converted them to cartesian]

(u-v)/2 = (3/4,-√3/4); Its modulus value is √3/2 which is = sin 2pi/3.

Hope everything above is correct.

#

Had to study what polar coordinates were again (had forgotten about them) so took a while.

lone heartBOT
#

@silent sage Has your question been resolved?

silent sage
#

@thin maple Could I get a confirmation?

thin maple
#

yepp seems correct

silent sage
# thin maple yepp seems correct

This was my third time inquiring regarding this question; the first two times the bot closed the channel overnight so I really appreciate the help.. Thank you for your time and assistance.

#

.close

lone heartBOT
#
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static mica
#

Hey, i need some help again with proving trig identities, i asked a similar question yesterday, and i eventually got it. Ik all the identities and stuff but i dont always catch on what im supposed to do to proceed PES2_SadGeCry

static mica
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this is the question

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so what i initially started with was the left side and i converted cos^2t-1 to sin^2t

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then i tried breaking down tan or cos

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after i did that i realized it was useless

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and im debating where its the right side i should manipulate

quasi vector
#

you just multiply the numerator and denominator by tan^2(t)

static mica
#

when?

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what

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if i do that then i lose than tan^2t on the bottom

quasi vector
#

how?

static mica
#

denominator section

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oh wait

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u said multiply not divide

quasi vector
#

yep

static mica
#

then it would be tan^2(t) tan^2(t)

quasi vector
#

how

lone heartBOT
#

@static mica Has your question been resolved?

static mica
#

sorry

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i got sidetracked for a second

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here ill write it and send

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thats what i got

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when i did that

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im gonna start a new ticket

#

.close

lone heartBOT
#
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opal topaz
#

Can someone dumb down what happened here for me? I'm really lost in what happens even if it's very simple.

opal topaz
#

The internet will tell you power rule but im not sure how to apply that

alpine sable
#

are you confused about the application of the power rule for integrals?

opal topaz
#

yess

alpine sable
#

okay

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so

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do you know what the power rule is?

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first and foremost

opal topaz
#

yeah

alpine sable
#

state it

opal topaz
#

d/dx x^n = nx^n-1

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iirc

alpine sable
#

thats for derivatives

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i am asking you the power rule for integrals

opal topaz
#

oh then uhh is that

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u^n du = (u^(n+1))/n+1

quasi vector
alpine sable
#

okay right

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so first let's recognise what our n is in your case

opal topaz
#

2

alpine sable
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no it is not

opal topaz
#

OHHHH

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-2

alpine sable
#

yep!

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okay

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so apply it now

opal topaz
#

okayy

alpine sable
#

so what is your overall expression, now that you have recognised that n = -2?

opal topaz
#

integral x^(-2)dx
= (x^(-1))/(-1)
so u get -1/x^(1) hooray

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so jsut x

alpine sable
#

yes! exactly!

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you got it, good job!

opal topaz
#

okayy thankss

alpine sable
#

no worries catclap

opal topaz
#

i might ask more questions as im doing an assignment should i close the channel

alpine sable
#

if you have currently, you can ask it right now

#

you can open more if you have any other

#

just make sure to close the channel you have open if you don't have any current questions

opal topaz
#

okss

#

.close

lone heartBOT
#
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lone heartBOT
#

@river swan Has your question been resolved?

lone heartBOT
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@river swan Has your question been resolved?

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twin bolt
#

hellloo

lone heartBOT
small panther
#

hi

#

what your issue ?

twin bolt
#

how do i know to subtract 4-15 and not 15-4?

carmine reef
#

Because the 4 is on the left of the minus sign

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and the 15 is on the right

twin bolt
#

so this one is wrong?

carmine reef
#

yeah

twin bolt
#

so left to right then?

carmine reef
#

yeah

twin bolt
#

thanks i have another question

carmine reef
#

<a,b> - <c,d> = <a-c, b-d>

twin bolt
#

for this one

carmine reef
#

but not <c-a, d-b>

twin bolt
#

why is it 3 sqr rt of 2

carmine reef
#

They left out a squared sign in the second to last step

twin bolt
#

wym?

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but the answer is correct right?

carmine reef
#

seems to be

twin bolt
#

bet thank you so much man

#

i appreciate it

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how do you become a mod like you?

carmine reef
#

I'm not a mod

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but if you help enough people someone will give you a green name

twin bolt
#

ohhh that’s so cool

carmine reef
#

mods have a blue name

twin bolt
#

so your just a helper?

carmine reef
#

yeah

twin bolt
#

that’s awesome mind if i add you as a friend?

#

you cool fr

carmine reef
#

ah sure

twin bolt
#

your in under grad?

carmine reef
#

yeah

twin bolt
#

that’s awesome

#

where you go?

#

ima be in undergrad next year

carmine reef
#

I'm at siu rn

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I gotta go atm but I sent a friend request

twin bolt
#

bet see you man

#

appreciate it fr

carmine reef
#

that's cool, I'm most of the way through now

#

Np, cya

lone heartBOT
#

@twin bolt Has your question been resolved?

lone heartBOT
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faint salmon
#

this is super silly but how do you do this operation

faint salmon
#

16/9 - 16/16 = 7/9

#

i can't find any common factors between these denominators, how was this answer reached?

#

.close

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ocean sealBOT
slate monolith
#

the terms are decreasing not increasing

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do you mean -2/3

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yes

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its the other way around

#

the ratio is what you multiply to get to the next term, not divide

ocean sealBOT
lone heartBOT
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flint belfry
#

i mean you could just say

#

as n increases the value of 1 will be irrelevant

2^n /7^n
= (2/7)^n
when you raise a fraction to a poitive power it gets smaller

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or you could just say the difference between 7^n and 2^n increases as n increases

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i dont know if thats enough though

plain flame
#

its probably neater to divide top and bottom by 7^n

whole shell
#

if you are asking, then i assume you dont know how to use lhoptial theorem

whole shell
#

wait if you know the lhopital theorem

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why cant you use it

whole shell
plain flame
#

^

flint belfry
#

why though ?

whole shell
#

1/7^n goes to 0

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so does (2/7)^n

flint belfry
#

oh

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do you have to break it up like that

whole shell
#

its a more mathmatical way than just saying 1 is irrelevant and 7^n is bigger than 2^n

flint belfry
#

oh okay

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gentle pine
lone heartBOT
gentle pine
#

ok I know how to do this but

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how do I find ABC

#

3x+6+7x-18= ????

#

wait do I do 3x+6=7x-18

tacit arch
#

also use the definition of bisects

#

yes

gentle pine
#

bruh I am dumb

#

thanks

#

.close

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gentle pine
#

2

#

very pro

#

it's this question

outer lark
#

.close

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wheat isle
#

Why does the example say the function becomes h(3)

rustic coral
wheat isle
#

Oh alright

#

Do you know how I would work out example 4

#

f o g means f(g(x))right?

rustic coral
#

Yes

wheat isle
rustic coral
#

That would be f(x) multiplied by g(x)

wheat isle
#

so just (2x-1) • (3x^2)

rustic coral
#

That's the same thing you just said.

#

Do you know what f(g(x)) actually means?

wheat isle
#

The function of G applied by F right?

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Or is it the other way around

rustic coral
#

It means you input g(x) into f(x).

#

In other words, f(g(x))=||2g(x)-1||.

wheat isle
rustic coral
#

g(x)=3x^2

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Just substitute it in.

#

I'm showing you the initial setup

wheat isle
#

Oh

wheat isle
rustic coral
#

Why?

#

You're not splitting anything, 2x-1=f(x) has an input of x, but you want an input of g(x), so replace x and g(x)

wheat isle
#

Oh alright

#

So the 2x-1 stays the same but you’re just inputting g(x) into the middle of the equation

rustic coral
#

It's not an equation, it's a function. But yes, you're just taking g(x) as your input into f(x) rather than x.

wheat isle
#

Oh okay

#

Thanks

lone heartBOT
#

@wheat isle Has your question been resolved?

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lunar lintel
lone heartBOT
lunar lintel
#

had a quick question

#

so the sequence

#

converges by taking the limit

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and an does not = 0

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so by divergence test it tells us that the series diverges right?

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ok but

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why does it go to infinity

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or how i suppose

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just by taking limit of n as it approaches infinity?

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because why cant we do the same thing that we did for the sequence by taking the limit

#

so i was confused how they got infinity

pseudo ice
#

Well for the sum, you can e.g. find that the terms in the sequence from some point on will be "close" to 9/6

#

in a way you're kinda adding loads of 9/6's together and all

#

(well not exactly, that's kind of an oversimplification there - but the best explanation I can think of before going into definitions involving epsilon and etc haha)

lunar lintel
#

so if the divergence test says if the sequence is not = to 0 then the series diverges to infinity all times?

pseudo ice
#

If the sequence does not converge to zero, then you could have that:

  • the series diverges to ♾️ (e.g. the sequence has a positive limit or diverges to ♾️ as well)
  • the series diverges to -♾️ (e.g. a negative limit or diverging to -♾️)
  • the series doesn't have a limit (e.g. (-1)^n alternates between -1 and 1, and the sum of that will alternate between values)
lunar lintel
#

i dont think u get my confusion

#

im saying why cant we do the same thing we did for the sequence for series

#

like how do you know what it diverges to

#

like just plug in infinity for n?

pseudo ice
#

What do you mean "the same thing we did for the sequence for series"?

#

And you're taking sums of multiple terms there so erm

pseudo ice
#

Well the closest you could reasonably do is find an expression for the partial sums and then try and find the limit of that, for which you might be able to do it similar to the sequence way

lone heartBOT
#

@lunar lintel Has your question been resolved?

earnest spruce
#

can't you use l'hôpital's rule @lunar lintel

cosmic steeple
#

$$s_n = \sum_{i=0}^n a_n$$

ocean sealBOT
#

theREALyumdub

cosmic steeple
#

Rewrite the series this way if you wanted to do an actual calculation. But the point is a divergent series won't show you anything - it should diverge

#

@lunar lintel

#

You could theoretically get a sum of the sequence a_n but if you evaluate the limit it wouldn't help you calculate the value, just get a divergent value

lone heartBOT
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steel temple
#

I am having trouble with Question 3. I marked down that the first coordinate is cosine and the second coordinate of P is sine. I know that csc = 1/sin but does that mean that I just flip the value of sine?

vital epoch
steel temple
#

By copying them down

#

I dont use LATED

#

*LATEX

#

<@&286206848099549185>

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@steel temple Has your question been resolved?

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@steel temple Has your question been resolved?

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stoic delta
lone heartBOT
stoic delta
#

Hi

#

I’m not sure how to do this

#

This is the answer

thick grail
#

First write it without exponents

stoic delta
#

Ok

thick grail
#

Send the working when you’re done

stoic delta
thick grail
#

Oh …

stoic delta
#

):

thick grail
#

That’s not how you do it

stoic delta
#

Oh

thick grail
#

I’ll send working

stoic delta
#

Ok thank you

thick grail
#

For the fractional and negative exponents, I really recommend looking at videos if you don’t understand

stoic delta
#

Oh

#

Ok

thick grail
#

Btw, if you have no more doubts, just type .close

stoic delta
#

Oh yea

#

.close

lone heartBOT
#
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alpine sable
#

Calculating the equation of the normal curve with 8 over x

alpine sable
#

Hello!

west girder
#

lmao kookie

rugged pond
#

I'm getting my threads stolen all the time

alpine sable
#

do i ask here

rugged pond
#

you can

alpine sable
#

oh my bad

west girder
#

yea go ahead

alpine sable
#

i have a very stupid question

#

so

#

for calculating the equation of the normal to the curve
y = 8 over x-x+3^2

#

I know how to solve it and find y, but i’m getting stuck with 8 over x

#

do we need to simplify it first?

#

Differentiation ^

#

i’ll send a photo

#

for example if it was just y = 8x - x + 3x^2
it would be f(x) = 8 - 1 + 6x

#

correct me if i'm wrong

#

in other words idk how to work with the 8 over x

granite pike
alpine sable
#

8/x, would differentiate to what exactly, is what i mean

#
  • x + 3x^2 = - 1 + 6x
#

8 over x = ?

granite pike
#

1/x^n = x^(-n)

Hopefully you know that the derivative of x^n is n * x^(n - 1)

alpine sable
#

Thank you!!

granite pike
#

Np

#

Please type .close if you're finished

alpine sable
#

.close

lone heartBOT
#
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teal shale
#

is there anyone here in french

lone heartBOT
#

@teal shale Has your question been resolved?

molten pivot
#

No

lone heartBOT
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spare fern
#

Could anyone help me out with a physics problem?

quasi vector
spare fern
#

My assessment is tomorrow I really have to learn how to do this

#

It would mean a lot if someone could help me out

quasi vector
#

i think you'd be better off asking this question in a physics server

spare fern
#

I've already tried

#

no luck

quasi vector
#

you tried asking here?

lone heartBOT
#

@spare fern Has your question been resolved?

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lucid yoke
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@lucid yoke Has your question been resolved?

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thorn tapir
#

I'm having a problem solving a particular indefinite integral.

thorn tapir
#

$\int \frac{x^6 - x^3}{(2x^3 + 1)^3} dx$

ocean sealBOT
#

rikusp2002

thorn tapir
#

Someone suggested Ostrogradsky's method, but I was looking for any simple ways like substitution or similar ideas.

strange meadow
#

u=2x^3?

#

Are there bounds

vapid shuttle
#

you will get a replacement for dx that includes 1/(3x^2) so that wouldn't work

#

its an indefinite integral

strange meadow
#

But sub x for that

vapid shuttle
#

?

strange meadow
#

x in terms of u

vapid shuttle
#

you're going to further complicate the integral that way

strange meadow
#

don’t think so

#

The denominator being a linear thing cubed is easier

vapid shuttle
#

it won't be linear

strange meadow
#

Maybe trig sub?

#

Yes it would?

vapid shuttle
#

it would include the 1/2x^3 with x in terms of u..

#

as a factor

thorn tapir
#

Nvm, dividing by x^6 in both numerator and denominator solves the problem

strange meadow
#

What reallyb

thorn tapir
#

Tru

#

Yes

strange meadow
#

Omg

#

That’s crazy

thorn tapir
#

Yeah

#

Thanks for the help btw

#

.close

lone heartBOT
#
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raw apex
#

Prove that { n/5, n belongs to Z } is a group with respect to addition.

raw apex
#

It's my channel

#

It's occupied

#

Alright

rose sigil
#

what do you need to do to show it's a group?

raw apex
#

Yea

rose sigil
#

wat?

raw apex
#

Yes I need to prove that its a group

rose sigil
#

i wasn't asking that loll

raw apex
#

Heh

#

I don't get it

rose sigil
#

you need to show the addition associates, there's an identity element, etc

raw apex
#

Yes

#

But how

rose sigil
#

can you list all the things you need to show first?

#

that's pretty important haha

raw apex
#
  1. Closure property
  2. Associative property
  3. Identity property
  4. Inverse property
rose sigil
#

ok good

#

any progress at all?

raw apex
#

Hmm I kinda get it how to do it

#

But idk how to

rose sigil
#

???

raw apex
#

Fractions aren't integers right

#

Like 1/5

rose sigil
#

no, 1/5 is not an integer

#

but { n/5, n belongs to Z } contains all the integers

raw apex
#

What if n is 1

#

And 1 belongs to Z

#

But 1/5 doesn't

#

And it's not closed

#

So it doesn't satisfy the closure property

#

Hence it is not a group

#

Is it?

rose sigil
#

that makes no sense

raw apex
#

This whole group theory doesn't make any sense

#

Ughhh

rose sigil
#

:c

#

closure means if you take two things in { n/5, n belongs to Z } and add them, you get something in that set

raw apex
#

@rose sigil see

#

If you take two elements

#

Suppose n and m

#

And we get n/2 + m/2 under addition

#

We get n + m/2

rose sigil
#

n/2 and m/2 what where did those come from??

#

n + m/2??

raw apex
#

Two things

#

(n+m) /2

rose sigil
#

what are n/2 and m/2 for?

raw apex
#

n and m belongs to Z

#

And to satisfy the closure property

rose sigil
#

do you mean n/5 and m/5?

raw apex
#

No /2

#

Not 5

rose sigil
raw apex
#

Oh frick it's /5

#

Shall I ping helpers

#

Been like 15 mins already

rose sigil
#

idk about pinging helpers but i'm gonna let someone else help

raw apex
#

Alright

#

<@&286206848099549185> help

lone heartBOT
#

@raw apex Has your question been resolved?

smoky hedge
#

?

true epoch
smoky hedge
#

Just check the properties

peak umbra
#

hello

#

can you guys help

#

im in middle school

#

and im so confused about math right now

true epoch
#

what help would oyu like?

#

algebra calc geometry

peak umbra
#

so like my family moved to another country and i didnt go to school for 1 year and when i did i went to language school for 3 years currently its years 4 and i have no idea what im doing

true epoch
#

ohkk

peak umbra
#

yeah

true epoch
#

so u need help

#

for understanding

#

the whole shiut

peak umbra
#

yeah

#

its so confusing

true epoch
#

then have to approach moderators for support

#

coz we only help for doubts

peak umbra
#

like i have NO IDEA why theres letters in math now algebra is fucked

true epoch
#

basically

#

imma tell you

#

stop associating things with maths

#

see it as something new

#

like u have never seen a letter

#

letter are a medium of seeing algebra

#

to solve unknown shit

#

for eg: Sam has 10 apples he gave 4 how many left?

peak umbra
#

6

true epoch
#

good

#

in algebra

#

u would say

#

x=10-4

#

which also six

peak umbra
#

oh

#

so its like a place holder?

true epoch
#

but u dont need variables like apple and shit

#

yeahhhh

#

exactly

peak umbra
#

huh

#

another thing im confused about division cause i almost did like none in elementery because of language school

true epoch
#

like the decimal one

#

?

peak umbra
#

yeah

true epoch
#

ok

#

so imma send you a one shot video

#

watch it

peak umbra
#

wait but whats the point of a place holder when you can just write a number?

true epoch
#

definitely u will solve all of those

peak umbra
#

oh

true epoch
#

like to calculate speed

#

from distance and time

#

when we reach higher class

#

we see that we dont even use the terms speed and distance

#

we write u = x/t

#

and others

#

so algebra is infact very important

peak umbra
#

whats x/t?

#

is it x=speed and t=distance?

true epoch
#

x=dist. t = time

#

u = speed

peak umbra
#

oh

true epoch
#

its written for convinence

#

its not necessary to write only x , t

#

write anything

#

but its like a tradition

#

to use them

peak umbra
#

oh ok

raw apex
peak umbra
#

wait can you explain division to me because any youtube video i see doesnt explain it well

raw apex
#

My problem isnt solved yet

true epoch
true epoch
raw apex
#

Alright

peak umbra
#

oh ok

true epoch
raw apex
#

A group ( G, • ) or ( G, *) is called a group when it satisfies following properties:

  1. Closure property
  2. Associative property
  3. Identity property
  4. Inverse property
true epoch
#

ohk

#

then whats the issue u encountered

raw apex
#

Idk how to make the given problem satisfy closure property

true epoch
#

how do you think we can do it

#

express your thoughts

#

so that we see where u are wrong

raw apex
#

I think we are going to suppose two elements n and m which belongs to the set Z

true epoch
#

flawless till here

raw apex
#

And by question we can do n/5 + m/5

true epoch
#

yes

raw apex
#

Which should belong to the same set but it doesnt

#

Right

true epoch
#

it will my dear

#

when u add both

#

the numerators add while the denominator

#

is 5

#

dont reduce the fractions

#

two integers give an integrs on addition

raw apex
#

Wait does fractions belong to integer?

true epoch
#

n+m = k

true epoch
#

they said that n belong to integer

#

not n/5

raw apex
#

Oh yes

true epoch
#

so now ig its done

raw apex
#

So how can we show it

true epoch
#

just write every step and explain it

#

and ye

#

you can tell

#

that two integers sum up to give an integer

#

say like as we know

raw apex
#

It becomes n/5 + m/5 = (n+m)/5 right

true epoch
#

yes

raw apex
#

And how does the result belong to the same set

true epoch
#

well

#

assume n+m to be K

#

then it become k/5

raw apex
#

Yes

#

And

true epoch
#

where K belongs to Z

#

and is of the form n/5

#

both satisfied

raw apex
#

Oh

#

I somehow get it but im still confused

true epoch
#

yes

raw apex
#

Alright im gonna try

#

I’ll close this channel

#

.close

lone heartBOT
#
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alpine sable
#

pls someone help ive been trying to answer this for the past 3 and a half hrs and my brain hurts so much already

alpine sable
#

<@&286206848099549185>

strange meadow
#

!15m

lone heartBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

strange meadow
#

!status

lone heartBOT
#
What step are you on?
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#

@alpine sable Has your question been resolved?

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valid merlin
#

Can someone help me with this question??

jagged cobalt
#

what have you tried?

lone heartBOT
#

@valid merlin Has your question been resolved?

valid merlin
#

well, by putting 2 in the middle of the two inequalities then subtracting the (a+2b)^2/blah from everything. Gets me pretty close. But I run into an issue with the direction of the inequalities.

jagged cobalt
#

i suppose you can do it like that - the way i first thought of was to move everything to a single side for both inequalities - which pulled the answer out almost immediately

However, if we continue the way you were going - could you show me what you have atm?

valid merlin
#

oop, nvm. got it. Thanks for the help anyways ig.

#

.close

lone heartBOT
#
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pseudo ore
#

guys what is 1+1=? 🤓

lone heartBOT
mortal trellis
#

17

#

dont troll

#

.close

lone heartBOT
#
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keen pasture
ocean sealBOT
#

MathIsAlwaysRight

keen pasture
modern sedge
#

Yay

mortal trellis
#

well I'm just working mod 5

modern sedge
keen pasture
#

Python

pseudo ore
modern sedge
#

"1"+"1"

keen pasture
#

Yeah

#

If you forgot that you're inputing numbers as variables this can happen

modern sedge
pseudo ore
#

.close

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high palm
#

how do i factorise this

lone heartBOT
alpine sable
#

set x^2 = t

high palm
#

OHHH

#

thanks so much

alpine sable
#

No wait

high palm
#

wait

alpine sable
#

That doesn't help much

high palm
#

not

#

yeah it's still unfactorisable

#

lol

modern sedge
#

It's full of golden ratios

alpine sable
#

You probably have to rewrite that x^2 term into two terms that can be factored nicely

#

Don't see what it can be right now though

high palm
#

if it helps the topic difference of two squares and perfect squares

modern sedge
#

This is difference of squares

alpine sable
#

Oh yeah

#

I see it now

#

You can get a nice perfect square by rewriting that x^2 term

high palm
#

lemme see

high palm
silent dock
#

Need help witht tgis

#

H*

high palm
#

i don't see anything

silent dock
high palm
nimble fern
#

!help

lone heartBOT
silent dock
#

!help

lone heartBOT
modern sedge
#

x^4 + 1 + sth is perfect square

high palm
modern sedge
#

it means something

#

you have to determine the "something" and then then split the x^2 term to get "something"

high palm
#

oh

alpine sable
#

Honestly might still help to write t = x^2

#

To see it better

high palm
#

ok so

#

after putting in t = x^2

#

you get t^2 - 3t +1

#

now t^2 + 1

#

is in (t+1)^2

#

t^2 + 1 = (t+1)^2 - 2t

#

but you still get 1 extra t?

#

oh wait t is x^2

#

so can u difference of 2 squares that

modern sedge
#

You still didn't rewrite t^2 - 3t +1

high palm
#

hang on

modern sedge
# high palm now t^2 + 1

you will get t^2 - 3t +1 = (t+1)^2 - 5t, so the (t+1)^2 might not be the best perfect square. Can you think of other perfect square that will contain these 2 terms?

high palm
#

how about (t-1)^2

modern sedge
#

try that

high palm
#

(x^2 - x -1) (x^2 + x -1)

#

i don't think t is the best way to do this

#

cuz in the second term "x"

#

u have to divide t

modern sedge
#

It's the best way I guess

mossy gust
#

You just need to factorize it into something like (x+a)(x+b)?

modern sedge
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a and b will be golden ratios

mossy gust
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I'm asking if there's anything else that is required.

ocean sealBOT
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MathIsAlwaysRight

modern sedge
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But I dont think that this is the best looking result

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(That's just factorization of one of the factors)

high palm
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for the help

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i appreciate that you didn't just give me the answer

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otherwise i probably would've just copied it and moved on forgetting the reasoning

mossy gust
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@high palm You did factorize this into 4 different roots, right? If so, be sure to close the channel.

high palm
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i remmeber that in polynomials

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remind me please

mossy gust
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The "r"s in things that look like (x-r), where you multiply them together and recover the polynomial. They are where a graph of the polynomial cross the x axis.

high palm
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not sure what you mean

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you mean the zeroes

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maybe im tripping

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but i did get the answer

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so yeah im done

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.close

lone heartBOT
#
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fierce lark
#

Some of the derivative proofs in my textbook are pretty bad ngl, esp quotient rule. Do you think Id be able to use sum like this over the quotient rule proof in my textbook?

fierce lark
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this is whats in my textbook btw

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I got no idea whats going on lmao

vale wigeon
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if not then wdym by "use"

fierce lark
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id probabily be given a function and then get asked to prove it

ornate condor
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um

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do u mean find the derivative?

vale wigeon
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i mean...

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what's your problem here

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it's a little unclear what you want to ask or know

fierce lark
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1.Is the first proof that I showed valid? 2.Do yall think it would be fine to use on a midterm 3. Id appreciate if you could explain exactly whats happening in the textbook version of the proof

keen pasture
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  1. Assuming that you already know product rule and the derivative of 1/g, I'd say yes. 2. You can use it once it has been proven in lecture 3. They proved the 1/g derivative rule in your 2nd picture
lone heartBOT
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@fierce lark Has your question been resolved?

fierce lark
fierce lark
keen pasture
#

You're trying to unserstand the textbook proof?

fierce lark
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yes

keen pasture
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You added the fractions wrong

fierce lark
lone heartBOT
#
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fierce lark
#

.reopen

lone heartBOT
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keen pasture
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a/b+c/d = (ad+cb)/(bd)

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Not b+d

fierce lark
keen pasture
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I mean the denominator

fierce lark
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ah I see

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lemme try again 😓

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yep got it to work

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thanks!

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just also wanna make sure, normally when were working with rationals we arent able to just seperate the fractions like we did here (were allowed because the h is approaching 0 or somehting like that?)

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over here

lone heartBOT
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@fierce lark Has your question been resolved?

keen pasture
fierce lark
#

.close

lone heartBOT
#
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gusty coral
#

hi

lone heartBOT
gusty coral
#

could anyone help me w this q:

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Suppose that T: R2 → R2 is the transformation that first performs a horizontal shift that moves ⃗e2 to ⃗e2 − 0.5⃗e1 (while leaving ⃗e1 unchanged) and then reflects the result around the x2-axis. Knowing that T is linear, find its corresponding standard matrix

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i messed up my signs idont understand why

rocky grove
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Okay so

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Let's say e1 is "i" and e2 is "j"

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So you're saying that j becomes (j-0.5i)?

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Or is it like

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Let's say your vectors are mi + nj

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Oooo wait

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So like

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So is it like this?

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Red = after and dotted black = before.

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@gusty coral

gusty coral
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oh wait is the x2 axis the y axis ?

rocky grove
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Yeah

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This is what the matrix transformation will look like

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Purple is the target

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So the j becomes negative

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Since it got reflected about the y axis

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Wait

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Yeah

gusty coral
rocky grove
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Yeah I corrected it

gusty coral
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oh yes

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yes thats it ithink

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thanku🥺🥺🥺🥺

rocky grove
#

So yeah you flip all the positive i values into negative ones

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Which is supposed to be the first row

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I think

gusty coral
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yep i got it now:) thanku again!

#

.close

lone heartBOT
#
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glass crest
#

so we need to solve this indeterminate form and i'm so lost idk what to do 😔 thank u in advance!

quasi vector
#

l'hopital's rule

sharp thorn
glass crest
quasi vector
heady void
#

do you have the answer

sharp thorn
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divide the numerator and denominator by x

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or take the x out common

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so it is

heady void
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idk tho I would split the tanx into fractions

thick grail
#

you would have a cosine to deal with tho?

sharp thorn
#

$\lim_{x \to 0} \frac{x(1-\frac{tan x}{x})}{x(\frac{\sin x}{x} -1)}$

ocean sealBOT
#

bettim

thick grail
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btw this is doesn't work with cosine

sharp thorn
thick grail
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yeah

sharp thorn
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$lim_{x \to 0} \cos x =1$

ocean sealBOT
#

bettim

heady void
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yeah

sharp thorn
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messed up the command ignore

thick grail
#

ah

heady void
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I was thinking of using this

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as if that might help