#help-0
1 messages · Page 169 of 1
@cinder spindle Has your question been resolved?
!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
well the angle is easy enough
you know the relative scale of the components
if you take arccos(.8/1.8)
@cinder spindle
does getting the angle give you enough of a push to get the time?
it gives too much push

idk
Can you draw the problem out
you should know ive taken sleeping pills so i'm pretty sleepy
can you explain anything more about your confusion?
i mean, i just don't really know how to start at all
i've tried drawing diagrams
but i don't know
The motivation of the diagram is of vectors
a boat moving across the river in the context of the problem has velocity drawn from 2 components
one is the speed of the river, and it pushes directly parallel to the bank
the other is the speed of the paddling, and it pushes directly parallel
the resultant moves from bank to bank
All that babbling to say you should draw a triangle
do you have any triangles?
the final answer won't be a right angled triangle
it will
hm
tell me this
lets say that piece you have labelled as 1.8
lets say some time has passed
and its now 3.6
after this amount of time, what has the piece labelled 0.8 become?
1.6
you can write them as 1.8a and 0.6a
where a is just some number that scales them together
so you can definitely get the angle now
try adding the a, and using trig functions
or whatever letter you like i guess
x looks like an angle?
right
my point is
you can write the diagram more generally
ANY triangle for this specific set up can be written as 1.8a and 0.8a
for some a
right
oh
you mean
yea i was saying this is sufficient to solve for x
i mean it was before but
(since the angle doesnt change)
its specifically the insight that they have to scale together that allows you to get the angle
yea but solving for x rn won't give me the right answer
use a trig function
yeah ik
what ratio relates these sides
so tan isnt what you want
wait

did i use the wrong one
but i got the right answer

i knew i shouldnt have started helping
but no one else was and i wanted to know the answer
if you use cosine you get the right answer
so whats wrong with the diagram, then
no, flip em
$\arccos \qty( \frac{0.8}{1.8} ) \approx 63.31$
jan Niku

ah, ye
how old are you btw
nice
so cosine of
my guess is
hrm
lemme screw around
if another helper comes, need help with D
i think now's a good time to ping helpers
@mental coyote
for fuck sake
what degenerate named himself helperssss
specifically
to fuck us over
<@&286206848099549185>
lord and savior maximo
it's for when people ping helpers too early i think
also i do not want to think about this problem rn. kind of just annoying trig
aids

well chromium at the very least ill be able to help once i get some sleep
it may just be 3-12 hours
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ii and iv
@pliant nymph Has your question been resolved?
what about it don't you understand
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Have inquired regarding this doubt previously; My question is:
How do I prove that |(u-v)/2| = pi/3?
I am not quite sure how to plot it without being aware of the values of the vectors involved. (Have referred to the video previously linked by Mr. Riemann)
@silent sage Has your question been resolved?
I may've misconstrued your intentions since you are new to the server; assistance will be appreciated.
i think its by definition of summing the vectors
as long as |uxv|=sin(theta) is valid you can do this
My concern is |(u-v)/2|; I need to prove that its = sin pi/3
It's already been proven that |uxv| = sin pi/3
I was linked to this video by Mr Riemann: https://www.khanacademy.org/math/linear-algebra/vectors-and-spaces/vectors/v/linear-algebra-vector-examples
But all the vectors were visualised here had values.
Facing two arbitrary directions such that the angle between them is pi/3 right?
Sin 2pi/3 == sin pi/3 so we can take either?
theyre vectors
the angle itself cant just
change
they hv direction
even though sine is identical
Right. It would've altered the value if it was some other trigonometric function.
yep
I do need to assume some values for plotting u-v/2 though right?
They're unit vectors so I can only think of (1,0), (0,1) etc. but the angle between these isn't pi/3..
(rt(2)/2,rt(2)/2)
😮
Help
Kindly repost your message in #help-8 or any of the other unoccupied help channels!
Kindly delete them from here now. 😅
@frosty marsh
I don't have OCD but this channel doesn't look neat anymore.
@frosty marsh
Anyways getting back on track in the meantime; is it possible to predict two vectors in this manner which would have pi/3 as the angle between them?
@silent sage Has your question been resolved?
Trying to figure it out.
what else btw
@silent sage Has your question been resolved?
waaaaaaaaaaaaaaaaaaaaaaaaaaaait a little longer
oki!
yass I think I've got it.
I let u = (1,0) v=(1/2,√3/2)
[(1,0) and (1,2pi/3) respectively in polar coordinates first, converted them to cartesian]
(u-v)/2 = (3/4,-√3/4); Its modulus value is √3/2 which is = sin 2pi/3.
Hope everything above is correct.
Had to study what polar coordinates were again (had forgotten about them) so took a while.
@silent sage Has your question been resolved?
@thin maple Could I get a confirmation?
yepp seems correct
This was my third time inquiring regarding this question; the first two times the bot closed the channel overnight so I really appreciate the help.. Thank you for your time and assistance.
.close
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Hey, i need some help again with proving trig identities, i asked a similar question yesterday, and i eventually got it. Ik all the identities and stuff but i dont always catch on what im supposed to do to proceed 
this is the question
so what i initially started with was the left side and i converted cos^2t-1 to sin^2t
then i tried breaking down tan or cos
after i did that i realized it was useless
and im debating where its the right side i should manipulate
you just multiply the numerator and denominator by tan^2(t)
how?
yep
then it would be tan^2(t) tan^2(t)
how
@static mica Has your question been resolved?
sorry
i got sidetracked for a second
here ill write it and send
thats what i got
when i did that
im gonna start a new ticket
.close
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Can someone dumb down what happened here for me? I'm really lost in what happens even if it's very simple.
The internet will tell you power rule but im not sure how to apply that
are you confused about the application of the power rule for integrals?
yess
yeah
state it

2
no it is not
okayy
so what is your overall expression, now that you have recognised that n = -2?
okayy thankss
no worries 
i might ask more questions as im doing an assignment should i close the channel
if you have currently, you can ask it right now
you can open more if you have any other
just make sure to close the channel you have open if you don't have any current questions
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@river swan Has your question been resolved?
@river swan Has your question been resolved?
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hellloo
how do i know to subtract 4-15 and not 15-4?
so this one is wrong?
yeah
so left to right then?
yeah
thanks i have another question
<a,b> - <c,d> = <a-c, b-d>
for this one
but not <c-a, d-b>
why is it 3 sqr rt of 2
They left out a squared sign in the second to last step
seems to be
ohhh that’s so cool
mods have a blue name
so your just a helper?
yeah
ah sure
your in under grad?
yeah
@twin bolt Has your question been resolved?
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this is super silly but how do you do this operation
16/9 - 16/16 = 7/9
i can't find any common factors between these denominators, how was this answer reached?
.close
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donut
its not though
the terms are decreasing not increasing
do you mean -2/3
yes
its the other way around
the ratio is what you multiply to get to the next term, not divide
donut
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i mean you could just say
as n increases the value of 1 will be irrelevant
2^n /7^n
= (2/7)^n
when you raise a fraction to a poitive power it gets smaller
or you could just say the difference between 7^n and 2^n increases as n increases
i dont know if thats enough though
its probably neater to divide top and bottom by 7^n
if you are asking, then i assume you dont know how to use lhoptial theorem
and then yh ^
wait if you know the lhopital theorem
why cant you use it
wdym
(2/7)^n / (1/7^n + 1)
^
why though ?
you can take the limit of that
1/7^n goes to 0
so does (2/7)^n
its a more mathmatical way than just saying 1 is irrelevant and 7^n is bigger than 2^n
oh okay
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ok I know how to do this but
how do I find ABC
3x+6+7x-18= ????
wait do I do 3x+6=7x-18
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.close
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Why does the example say the function becomes h(3)
For the sake of example ig? Without the diagram being referred to, it's hard to say more.
Yes
So would it turn into (2x-1)(3x^2)
That would be f(x) multiplied by g(x)
so just (2x-1) • (3x^2)
Where does the 3x^2 go?
Oh
I’m a little confused on the part where the 2x-1 gets split into this part
Why?
You're not splitting anything, 2x-1=f(x) has an input of x, but you want an input of g(x), so replace x and g(x)
Oh alright
So the 2x-1 stays the same but you’re just inputting g(x) into the middle of the equation
It's not an equation, it's a function. But yes, you're just taking g(x) as your input into f(x) rather than x.
@wheat isle Has your question been resolved?
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had a quick question
so the sequence
converges by taking the limit
and an does not = 0
so by divergence test it tells us that the series diverges right?
ok but
why does it go to infinity
or how i suppose
just by taking limit of n as it approaches infinity?
because why cant we do the same thing that we did for the sequence by taking the limit
so i was confused how they got infinity
Well for the sum, you can e.g. find that the terms in the sequence from some point on will be "close" to 9/6
in a way you're kinda adding loads of 9/6's together and all
(well not exactly, that's kind of an oversimplification there - but the best explanation I can think of before going into definitions involving epsilon and etc haha)
confusion is occuring
so if the divergence test says if the sequence is not = to 0 then the series diverges to infinity all times?
If the sequence does not converge to zero, then you could have that:
- the series diverges to ♾️ (e.g. the sequence has a positive limit or diverges to ♾️ as well)
- the series diverges to -♾️ (e.g. a negative limit or diverging to -♾️)
- the series doesn't have a limit (e.g. (-1)^n alternates between -1 and 1, and the sum of that will alternate between values)
i dont think u get my confusion
im saying why cant we do the same thing we did for the sequence for series
like how do you know what it diverges to
like just plug in infinity for n?
What do you mean "the same thing we did for the sequence for series"?
And you're taking sums of multiple terms there so erm
Well the closest you could reasonably do is find an expression for the partial sums and then try and find the limit of that, for which you might be able to do it similar to the sequence way
@lunar lintel Has your question been resolved?
can't you use l'hôpital's rule @lunar lintel
$$s_n = \sum_{i=0}^n a_n$$
theREALyumdub
Rewrite the series this way if you wanted to do an actual calculation. But the point is a divergent series won't show you anything - it should diverge
@lunar lintel
You could theoretically get a sum of the sequence a_n but if you evaluate the limit it wouldn't help you calculate the value, just get a divergent value
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I am having trouble with Question 3. I marked down that the first coordinate is cosine and the second coordinate of P is sine. I know that csc = 1/sin but does that mean that I just flip the value of sine?
@lone heart how do u take notes
@steel temple Has your question been resolved?
@steel temple Has your question been resolved?
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First write it without exponents
Ok
Send the working when you’re done
Oh …
):
That’s not how you do it
Oh
I’ll send working
Ok thank you
For the fractional and negative exponents, I really recommend looking at videos if you don’t understand
Btw, if you have no more doubts, just type .close
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Calculating the equation of the normal curve with 8 over x
Hello!
lmao kookie
I'm getting my threads stolen all the time
do i ask here
you can
oh my bad
yea go ahead
i have a very stupid question
so
for calculating the equation of the normal to the curve
y = 8 over x-x+3^2
I know how to solve it and find y, but i’m getting stuck with 8 over x
do we need to simplify it first?
Differentiation ^
i’ll send a photo
for example if it was just y = 8x - x + 3x^2
it would be f(x) = 8 - 1 + 6x
correct me if i'm wrong
in other words idk how to work with the 8 over x
Do you mean to ask you dknt know how to differentiate 1/x?
8/x, would differentiate to what exactly, is what i mean
- x + 3x^2 = - 1 + 6x
8 over x = ?
1/x^n = x^(-n)
Hopefully you know that the derivative of x^n is n * x^(n - 1)
Thank you!!
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is there anyone here in french
@teal shale Has your question been resolved?
No
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Could anyone help me out with a physics problem?
My assessment is tomorrow I really have to learn how to do this
It would mean a lot if someone could help me out
i think you'd be better off asking this question in a physics server
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@lucid yoke Has your question been resolved?
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I'm having a problem solving a particular indefinite integral.
$\int \frac{x^6 - x^3}{(2x^3 + 1)^3} dx$
rikusp2002
Someone suggested Ostrogradsky's method, but I was looking for any simple ways like substitution or similar ideas.
you will get a replacement for dx that includes 1/(3x^2) so that wouldn't work
its an indefinite integral
But sub x for that
?
x in terms of u
you're going to further complicate the integral that way
it won't be linear
Nvm, dividing by x^6 in both numerator and denominator solves the problem
What reallyb
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Prove that { n/5, n belongs to Z } is a group with respect to addition.
what do you need to do to show it's a group?
Yea
wat?
Yes I need to prove that its a group
i wasn't asking that loll
you need to show the addition associates, there's an identity element, etc
- Closure property
- Associative property
- Identity property
- Inverse property
???
What if n is 1
And 1 belongs to Z
But 1/5 doesn't
And it's not closed
So it doesn't satisfy the closure property
Hence it is not a group
Is it?
that makes no sense
:c
closure means if you take two things in { n/5, n belongs to Z } and add them, you get something in that set
@rose sigil see
If you take two elements
Suppose n and m
And we get n/2 + m/2 under addition
We get n + m/2
what are n/2 and m/2 for?
do you mean n/5 and m/5?
and you did mean /5 here? not /2?
idk about pinging helpers but i'm gonna let someone else help
@raw apex Has your question been resolved?
?
Whats your doubt may i know?
Just check the properties
hello
can you guys help
im in middle school
and im so confused about math right now
so like my family moved to another country and i didnt go to school for 1 year and when i did i went to language school for 3 years currently its years 4 and i have no idea what im doing
ohkk
yeah
like i have NO IDEA why theres letters in math now algebra is fucked
basically
imma tell you
stop associating things with maths
see it as something new
like u have never seen a letter
letter are a medium of seeing algebra
to solve unknown shit
for eg: Sam has 10 apples he gave 4 how many left?
6
huh
another thing im confused about division cause i almost did like none in elementery because of language school
yeah
wait but whats the point of a place holder when you can just write a number?
definitely u will solve all of those
its uses are in physics
oh
like to calculate speed
from distance and time
when we reach higher class
we see that we dont even use the terms speed and distance
we write u = x/t
and others
so algebra is infact very important
oh
its written for convinence
its not necessary to write only x , t
write anything
but its like a tradition
to use them
oh ok
Prove that { n/5, n belongs to Z } is a group with respect to addition.
wait can you explain division to me because any youtube video i see doesnt explain it well
My problem isnt solved yet
its not possible coz i need a laptop and i dont have one currently
lets have a look
Alright
oh ok
what is a group
A group ( G, • ) or ( G, *) is called a group when it satisfies following properties:
- Closure property
- Associative property
- Identity property
- Inverse property
Idk how to make the given problem satisfy closure property
how do you think we can do it
express your thoughts
so that we see where u are wrong
I think we are going to suppose two elements n and m which belongs to the set Z
flawless till here
And by question we can do n/5 + m/5
yes
it will my dear
when u add both
the numerators add while the denominator
is 5
dont reduce the fractions
two integers give an integrs on addition
Wait does fractions belong to integer?
n+m = k
they never said that
they said that n belong to integer
not n/5
Oh yes
so now ig its done
So how can we show it
just write every step and explain it
and ye
you can tell
that two integers sum up to give an integer
say like as we know
It becomes n/5 + m/5 = (n+m)/5 right
yes
And how does the result belong to the same set
yes
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pls someone help ive been trying to answer this for the past 3 and a half hrs and my brain hurts so much already
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2. I have begun but got stuck midway
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4. I got an answer and would like my work checked
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6. None of the above
@alpine sable Has your question been resolved?
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Can someone help me with this question??
what have you tried?
@valid merlin Has your question been resolved?
well, by putting 2 in the middle of the two inequalities then subtracting the (a+2b)^2/blah from everything. Gets me pretty close. But I run into an issue with the direction of the inequalities.
i suppose you can do it like that - the way i first thought of was to move everything to a single side for both inequalities - which pulled the answer out almost immediately
However, if we continue the way you were going - could you show me what you have atm?
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guys what is 1+1=? 🤓
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11
MathIsAlwaysRight
First and second one for bingo
Yay
well I'm just working mod 5
Javascript?
Python
thanks bb gril 🤓 🤓
"1"+"1"
I would consider this as a proof of minn being underage
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how do i factorise this
set x^2 = t
No wait
wait
That doesn't help much
It's full of golden ratios
You probably have to rewrite that x^2 term into two terms that can be factored nicely
Don't see what it can be right now though
if it helps the topic difference of two squares and perfect squares
This is difference of squares
Oh yeah
I see it now
You can get a nice perfect square by rewriting that x^2 term
lemme see
how would i do that?
i don't see anything
get another channel
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x^4 + 1 + sth is perfect square
sth?
it means something
you have to determine the "something" and then then split the x^2 term to get "something"
oh
ok so
after putting in t = x^2
you get t^2 - 3t +1
now t^2 + 1
is in (t+1)^2
t^2 + 1 = (t+1)^2 - 2t
but you still get 1 extra t?
oh wait t is x^2
so can u difference of 2 squares that
You still didn't rewrite t^2 - 3t +1
hang on
you will get t^2 - 3t +1 = (t+1)^2 - 5t, so the (t+1)^2 might not be the best perfect square. Can you think of other perfect square that will contain these 2 terms?
how about (t-1)^2
try that
(x^2 - x -1) (x^2 + x -1)
i don't think t is the best way to do this
cuz in the second term "x"
u have to divide t
It's the best way I guess
You just need to factorize it into something like (x+a)(x+b)?
It's possible
a and b will be golden ratios
I'm asking if there's anything else that is required.
MathIsAlwaysRight
But I dont think that this is the best looking result
(That's just factorization of one of the factors)
anyways thanks
for the help
i appreciate that you didn't just give me the answer
otherwise i probably would've just copied it and moved on forgetting the reasoning
@high palm You did factorize this into 4 different roots, right? If so, be sure to close the channel.
roots?
i remmeber that in polynomials
remind me please
The "r"s in things that look like (x-r), where you multiply them together and recover the polynomial. They are where a graph of the polynomial cross the x axis.
not sure what you mean
you mean the zeroes
maybe im tripping
but i did get the answer
so yeah im done
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Some of the derivative proofs in my textbook are pretty bad ngl, esp quotient rule. Do you think Id be able to use sum like this over the quotient rule proof in my textbook?
are you planning to rederive the quotient rule from scratch every time...?
if not then wdym by "use"
I doubt id be asked to show prove it from scratch to be honest
id probabily be given a function and then get asked to prove it
i mean...
what's your problem here
it's a little unclear what you want to ask or know
- Assuming that you already know product rule and the derivative of 1/g, I'd say yes. 2. You can use it once it has been proven in lecture 3. They proved the 1/g derivative rule in your 2nd picture
@fierce lark Has your question been resolved?
hes only used the textbook proof in lecture 😭
Im not sure what im doing wrong/how to keep going after this step in the proof
You're trying to unserstand the textbook proof?
yes
You added the fractions wrong
is it just the signs in the numerator or have I completely messed it up
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✅
yea but arent there 1s in both the numerators?
I mean the denominator
ah I see
lemme try again 😓
yep got it to work
thanks!
just also wanna make sure, normally when were working with rationals we arent able to just seperate the fractions like we did here (were allowed because the h is approaching 0 or somehting like that?)
over here
@fierce lark Has your question been resolved?
What do you mean with seperate the fractions? Rewriting like you did here? You can do this with rationals, too
ok ty, guess im totally lost gotta go prac
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hi
could anyone help me w this q:
Suppose that T: R2 → R2 is the transformation that first performs a horizontal shift that moves ⃗e2 to ⃗e2 − 0.5⃗e1 (while leaving ⃗e1 unchanged) and then reflects the result around the x2-axis. Knowing that T is linear, find its corresponding standard matrix
i messed up my signs idont understand why
Okay so
Let's say e1 is "i" and e2 is "j"
So you're saying that j becomes (j-0.5i)?
Or is it like
Let's say your vectors are mi + nj
Oooo wait
So like
So is it like this?
Red = after and dotted black = before.
@gusty coral
Yes i think thats it for j
oh wait is the x2 axis the y axis ?
Yeah
This is what the matrix transformation will look like
Purple is the target
So the j becomes negative
Since it got reflected about the y axis
Wait
Yeah
ithought the purple would be on the left side since its reflected around the y-axis no?
Yeah I corrected it
So yeah you flip all the positive i values into negative ones
Which is supposed to be the first row
I think
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so we need to solve this indeterminate form and i'm so lost idk what to do 😔 thank u in advance!
l'hopital's rule
too complicated
unfortunately that hasn't been taught to us yet so rip
which is why I crossed it out
do you have the answer
idk tho I would split the tanx into fractions
you would have a cosine to deal with tho?
$\lim_{x \to 0} \frac{x(1-\frac{tan x}{x})}{x(\frac{\sin x}{x} -1)}$
bettim
this is way better because you can actually apply the identities
btw this is doesn't work with cosine
it doesnt have to
yeah
$lim_{x \to 0} \cos x =1$
bettim
yeah
messed up the command ignore
ah