@long cave Has your question been resolved?
#help-0
lone heartBOT
long cave
yea im actually all good thank you so mnuch @alpine sable
wicked wave
Hello
wicked wave
Oh sorry
This is the problem
Here is my work I thought I had to get rid of the h so that the denominator would be 0
alpine sable
@wicked wave Please go back to the other channel and close it with .close before continuing with this one
wicked wave
How does the h in the denominator go away?
wicked wave
<@352271114245767169> Please go back to the other channel and close it with `.cl...
Did it sorry
alpine sable
This is probably far from the best solution but you could multiply the top and bottom with x before applying l'Hopital's
Wait no actually nevermind me
Yeah sorry I tried :/
wicked wave
Yeah sorry I tried :/
So you don’t know how to solve?
alpine sable
So you don’t know how to solve?
Unfortunately no
cobalt eagle
The function g(x) is a reflection of the function f(x) = -2(x - 3)^2 - 9 over the line y = x + 2. What is g(x)?
can som1 explain how to do this^^^
lone heartBOT
The function g(x) is a reflection of the function f(x) = -2(x - 3)^2 - 9 over th...
@cobalt eagle Has your question been resolved?
cobalt eagle
<@&286206848099549185>
slate monolith
The function g(x) is a reflection of the function f(x) = -2(x - 3)^2 - 9 over th...
I think you can just replace y with x + 2 and x with y
and see what that gets you
yep it works
i dont know why though
just my first guess
hollow hound
replacing is kind of like doing inverse functions
like y = e^x, e^y = x, those are inverse functions
because you switch different value\
values
slate monolith
yeah thats simple enough
slate monolith
i cant prove in my mind that its the same when y is not just = x
cobalt eagle
can u explain how to do this
A parabola f has focus (3, 2) and directrix x = 5. Find the equation of f.
cobalt eagle
what
cobalt eagle
focus of parabola y = a(x-h)^2+k is (h, k+(1/(4a)))
how to use the given info in that
hollow hound
h = 3, 4ak + 1 = 8a
cobalt eagle
h = 3, 4ak + 1 = 8a
how u get the second part
hollow hound
use the directix
cobalt eagle
ok so a = -5?
hollow hound
a = 1/5
cobalt eagle
how
cobalt eagle
huh
hollow hound
i couldnt explain it in discord but check out this link
are you able to find the solution?
ripe turret
does k always = 1
lone heartBOT
does k always = 1
ripe turret
for a left sum
fallen verge
you have to give us a little more context
ripe turret
you have to give us a little more context
summations
Left summation right summation
does k always = 1 for left usmmation
and k = 0 always for right
fallen verge
that sounds like the wrong way round
ripe turret
why did they right k = 1 then?
fallen verge
depends on the bounds of the integral
fallen verge
oh ok
ripe turret
when its supposed to be 0
fallen verge
thats because are focusing on x_1, x_2 and so on
ocean sealBOT
ripe turret
thats because are focusing on x_1, x\_2 and so on
.this is what i did
left sum is 0
so am i not right?
@fallen verge
bruh
why bother trying to respond then not helpign and ghosting
.close
alpine sable
lone heartBOT
frail crow
15X + 10Y
alpine sable
what
whole shell
you just multiply everything in the bracket by the thing outside it
alpine sable
Ohh
Hold on one second tho
There's another question breaking my break
What do I do with g
alpine sable
so the answer is 0
how can you explain this 5x better then my teacher
So how would I do this one
.close
dusky wraith
I was wondering if someone can check my work
lone heartBOT
I was wondering if someone can check my work
whole shell
@dusky wraithyou couldnt use desmos?
dusky wraith
No but
Okay so
the question is this
the options are these
but both g(x) and h(x) have similar graphs when i put into desmos
and these are the only 4 options
dusky wraith
<@438517295334031380>you couldnt use desmos?
so im confused
alpine sable
@dusky wraith you can close this
dusky wraith
.close
heady crown
umm hello
heady crown
how do i get the missing number
wild trail
Is this like a reasoning puzzle?
sudden igloo
i think its 1
1st block up is -1 then add 2 u get to second block down then add 2 u get third block up then add 2 u get 4 block down and all remaining blocks is just cube of whats written down or up
so cube of 1 is 1 and thats answer
lone heartBOT
lone heartBOT
Available help channel!
alpine sable
can someone help me understand where i read the chart wrong so i can fix my mistake
vale wigeon
how many scenarios are there in total?
alpine sable
4
vale wigeon
no, there are 8.
lone heartBOT
@alpine sable Has your question been resolved?
verbal stratus
lone heartBOT
verbal stratus
I don't understand 7b
I know that the mode is n
so the probability of getting n successes out of 2n trials is 35/128
lone heartBOT
@verbal stratus Has your question been resolved?
verbal stratus
<@&286206848099549185>
stiff marten
yes
stiff marten
heelo
verbal stratus
i tried looking at inverse binomial functions on my graphing calc but cant find anything useful
but i know that P(X=n) = 35/128
just not sure where to go from here
verbal stratus
<@&286206848099549185>
summer stratus
lone heartBOT
summer stratus
I got half of the working given but im stuck
zinc dagger
$\frac {2^x} {8^y}$
ocean sealBOT
❤ Pauli Excluder ❤
median oar
I got half of the working given but im stuck
show this "half of the working"
summer stratus
hold on im writing it down digitally
median oar
can take a picture of your pencil and paper work
summer stratus
summer stratus
can take a picture of your pencil and paper work
it's pretty messy
summer stratus
oh alr
3x=2+y
x-3y=0
x=3y
3(3y)=2+y
9y=2+y
8y=2
y=1/4
this was another given example
how do i know what should be on top?
@median oar
median oar
$a^m=a^{\frac{m}{1}}$
ocean sealBOT
Frosst
summer stratus
why negative tho
median oar
typo
ocean sealBOT
Frosst
summer stratus
oh ok
ocean sealBOT
Frosst
summer stratus
**Frosst**
don't rlly understand this
median oar
$m=\frac{m}{1}$
ocean sealBOT
Frosst
summer stratus
but the denominator here is 2 tho
median oar
**Frosst**
this is in general
for any a to the power of m
it's the same as a to the power of (m divided by 1)
median oar
**Frosst**
this uses $({a^k})^h=({a^h})^k=a^{h\cdot k}$
ocean sealBOT
Frosst
ocean sealBOT
Frosst
summer stratus
oh ok i get it now
do u mind if i send another question?
@median oar
r u free?
median oar
Sure just making dinner
summer stratus
1+x?
summer stratus
sorry wdym by common factor
ocean sealBOT
Frosst
fiery cliff
(1+x)^(3/2+1/2)?
(1+x)^1/2 is common factor here
now use this logic and try to solve further
gusty gorge
bro what
median oar
This is equal to $\sqrt{(1+x)}\sqrt{(1+x)}\sqrt{(1+x)} - \sqrt{(1+x)}$
ocean sealBOT
Frosst
lone heartBOT
@summer stratus Has your question been resolved?
solid night
hey guys
solid night
i need help
unique imp
Hi!
solid night
whats 2 plus 2
unique imp
21
echo socket
,w 2 + 2
ocean sealBOT
echo socket
.close
regal copper
lone heartBOT
echo socket
Now you need to consider the cases when x-1 and 2+y are both positive or both negative
echo socket
In the first case, yeah
regal copper
and less than equal to -1
and y is less than equal to 2
and greater than equal to -2
am I correct?
echo socket
I) x >= 1, y >= -2
II) x <= 1, y <= -2
echo socket
Had a typo there, my bad
regal copper
but not the second one
still can’t understand
echo socket
In the second case x - 1 and y + 2 are both negative
So x - 1 <= 0 and y + 2 <= 0
Meaning x <= 1 and y <= -2
regal copper
regal copper
In the second case x - 1 and y + 2 are both negative
Negative? so do I have to just do that for all the questions like this?
fiery cliff
still can’t understand
(x-1) (2+y) >= 0
this equation tell us that the product of (x-1) and (2+y) is 0
now to satisfy this, one of those quantities (x-1) or (2+y) needs to be 0
so either x-1 >= 0 or 2+y >=0
so x>=1 or y>= -2
echo socket
Not all of them require considering cases
regal copper
(x-1) (2+y) >= 0
this equation tell us that the product of (x-1) and (2+y) is 0 ...
yeah got it
regal copper
(x-1) (2+y) >= 0
this equation tell us that the product of (x-1) and (2+y) is 0 ...
and i guess this is right
.close
tired lance
hello can any1 help me out? Im struggling to calculate my gpa
alpine sable
okay what do you need help with
kindred anchor
tired lance
from 1 to 5 like not from 0 to 100 percent
i have 11 lessons and i get graded from all of them but i dont know how to calculate my average grade
vale wigeon
- "i don't know how to calculate averages in general"
- "i know how to calculate averages in general but calculating my GPA stumps me"
- "i know how to calculate averages, and i tried calculating my GPA, but i was told my answer is wrong"
@tired lance which of these best describes your issue
tired lance
- Bcs im dumb
vale wigeon
i made no remarks concerning your intelligence and i'm not going to.
the average of a set of numbers is found by calculating their total (i.e. adding them all up) and dividing by their count (how many numbers you had, in your case 11)
this assumes all subjects are weighted equally, which might not be the case! but you should be able to calculate something like your GPA from here.
past flume
So here's a complex analysis problem I'm a bit stuck on. I know I can't use Cauchy's Integral Formula but I know it probably involves Cauchy's Residue Theorem. The issue is that I'm having some problems finding the residue of the antiderivative. Here's the problem:
"Evaluate the integral $\oint _{C} e^{1/(z-1)} dz$ where $C$ is (i) the circle $|z| = 1/2$, (ii) the circle $|z| = 2$."
Any help is appreciated.
ocean sealBOT
蔵王
past flume
What I've established so far is that the integral is 0 in (i) and nonzero in (ii), since the contour encloses the singularity in (ii). When I try and apply the formula to calculate the residue of a simple pole, I seem to be having some issues with manipulating the limit (I tried L'Hopital's to no effect).
lone heartBOT
@past flume Has your question been resolved?
lone heartBOT
@past flume Has your question been resolved?
broken geyser
Can someone give me the answer for letter c pls
lone heartBOT
Can someone give me the answer for letter c pls
sudden igloo
u can take x values 0 1 2 3 etc and get their corresponding y then plot them on plane and join them all you get a straight line
lone heartBOT
@broken geyser Has your question been resolved?
lone heartBOT
broken geyser
u can take x values 0 1 2 3 etc and get their corresponding y then plot them on ...
Like this one ?
Just an example, not the same numbers ofc
lone heartBOT
Available help channel!
sudden igloo
@broken geyser i would say more like this one
lone heartBOT
<@847746765863911444> i would say more like this one
sudden igloo
.close
sand river
lone heartBOT
sand river
How would I do this?
errant idol
vague mirage
Do you know what's the formula for volume
First take out all the data which is given
And the radius of hemisphere = radius of cylinder
sand river
I don’t have the the symbols
But it’s pie r squared height right?
Or is that something else?
vague mirage
$\text{cylinder}=πr²h
\ \text{hemisphere}=\frac{2}{3}×π×r³$
ocean sealBOT
Arnab
sand river
Thx I didn’t know hemisphere
sand river
I didn’t learn it I missed 2 yrs due to covid so I never learned it
vague mirage
Me too
sand river
Missed yr 8,9, and some of yr 10
vague mirage
I didn't miss two years I just didn't pay attention
💀
sand river
I didn't miss two years I just didn't pay attention
Lol
vague mirage
Missed yr 8,9, and some of yr 10
I missed 7th grade and 8th grade
Now I am in 9 th grade
vague mirage
Yr 11 and 12
graceful quail
Can someone explain evaluating power reduction equations
lone heartBOT
Can someone explain evaluating power reduction equations
graceful quail
I'm following along with notes but one thing makes everything else fall apart
wind cloak
Wdym by power reduction equations do you have an example
flint belfry
I'm following along with notes but one thing makes everything else fall apart
could you send a screenshot?
or photo
vague mirage
Can someone explain evaluating power reduction equations
I am getting some vibes of chemistry
rose raven
it's probably trig
lone heartBOT
@graceful quail Has your question been resolved?
graceful quail
yeah its trig
and those are the equations
i need to reduce sin^4x
and this is where im getting at
without any help
lone heartBOT
@graceful quail Has your question been resolved?
graceful quail
No
novel kindle
how do i make graph of T vs t ?
Given -dT/dt ∝ T-c
where c is any constant
so i removed proportionality sign by constant K
so -dT/dt = K (T-c)
now how do i plot a graph ?
rotund sonnet
novel kindle
.close
lone heartBOT
lone heartBOT
Available help channel!
alpine sable
Got stuck here
lone heartBOT
Got stuck here
alpine sable
Yeah but its divided by two and its messing me up
I usually dont have the denominator to deal with by comparison
coarse olive
u can multiply both sides by 2 if its easier for u
alpine sable
Multiply both sides by two?
alpine sable
So x-2i . 2?
coarse olive
yup
alpine sable
And y-yi . 2?
coarse olive
(y-yi)/2 • 2
ocean sealBOT
alpine sable
10 + x = 5
Um thatd be 10-5 = -x
coarse olive
we would -10 from both sides to get c by itself
coarse olive
Um thatd be 10-5 = -x
yea nice
alpine sable
X = -5
coarse olive
so for this egg
x/2 = 5
we would multiply by 2
on both sides
x/2 • 2 = 5 • 2
x=10
alpine sable
ooooooohhhhhh
coarse olive
yea
alpine sable
Wait lemme try dat
coarse olive
we do the same for ur thingy
coarse olive
no
alpine sable
coarse olive
yes!!
coarse olive
nah all g, im not judging
lone heartBOT
coarse olive
no worries
lone heartBOT
Available help channel!
flat galleon
hey, sorry for my impending stupidity, but if we have two masses that move under the mutual gravitational attraction between them, then is the centre of mass also the centre of gravity?
jagged cobalt
each body has a centre of mass - which is sometimes referred to as their centre of gravity
so they are the same - at least ive never heard of them having separate meaning
alpine sable
it is different things
flat galleon
in this case i mean the centre of mass of the whole system - if x1 and x2 are the position vectors of the masses then that would be (m1x1+m2x2)/(m1+m2).
wind cloak
I'm pretty sure they are different things by definition but end up coinciding with the center of mass in many cases I don't remember though exactly
lone heartBOT
@flat galleon Has your question been resolved?
flat galleon
.close
steady basin
lone heartBOT
thick kiln
what?
thick kiln
and bro
steady basin
especially with the word 'spans'
thick kiln
<@&286206848099549185>
worn fox
spans means you can write every element in R^n as a linear combination of your basis elements
worn fox
<@&286206848099549185>
What are you doing?
thick kiln
thx
steady basin
spans means you can write every element in R^n as a linear combination of your b...
right
steady basin
spans means you can write every element in R^n as a linear combination of your b...
when u say basis elements do u mean like i j k ?
shadow ibex
<@&286206848099549185>
what exactly seems to be issue? could you summarize?
worn fox
when u say basis elements do u mean like i j k ?
No I just mean the elements in your basis, whatever that might be
thick kiln
there is a problem we cant solve
worn fox
Doesnt have to be I,j,k even tho that is a basis of R^3
worn fox
there is a problem we cant solve
Can you go to another channel thanks
steady basin
there is a problem we cant solve
go away
steady basin
No I just mean the elements in your basis, whatever that might be
yh sry i just meant like an example ie i j k
thick kiln
stoooooop
worn fox
Yeah so I,j,k span R^3 but so do many other collections of vectors
thick kiln
you zac
worn fox
<@&286206848099549185>
<@&268886789983436800> won't leave
steady basin
Yeah so I,j,k span R^3 but so do many other collections of vectors
do all linearly independent vectors form a basis?
worn fox
No
i and j are linearly independent in R^3 but don't form a basis bc they don't span R^3
steady basin
i and j are linearly independent in R^3 but don't form a basis bc they don't spa...
heres an example
why do they form a basis?
worn fox
Because they are linearly independent and span R^3
The equation at the bottom is showing you they span R^3
steady basin
i think its this 'span r3' part im still kinda confused about
worn fox
You've taken a general element (x,y,z) in R^3 and written it as a linear combination of those 3 vectors
That's precisely what it means for those 3 vectors to span R^3
wild trail
if a set S spans a vector space V it means that every element of V can be written as a linear combination of elements of S
worn fox
any vector in R^3 is a linear combination of those 3 vectors so those 3 vectors span R^3
steady basin
You've taken a general element (x,y,z) in R^3 and written it as a linear combina...
ok kl makes sense
cheers mate
lone heartBOT
@steady basin Has your question been resolved?
steady basin
.close
stuck kestrel
lone heartBOT
stuck kestrel
lone heartBOT
@stuck kestrel Has your question been resolved?
copper rock
!status
lone heartBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
.close
lone heartBOT
lone heartBOT
Available help channel!
wide acorn
lone heartBOT
wide acorn
is it possible to solve this with the disk method?
lone heartBOT
@wide acorn Has your question been resolved?
wide acorn
<@&286206848099549185>
gusty gorge
yeah probably
lone heartBOT
@wide acorn Has your question been resolved?
covert kiln
2/square root of 3 -5
lone heartBOT
2/square root of 3 -5
covert kiln
so what i did was I multiple sqaure root of 3 +5 on both side
to get 2 square root of 3 +10/-22
and then I get -V3+5/11
plain flame
$\frac{2}{\sqrt{3}-5}$
ocean sealBOT
heavy
plain flame
$\frac{2}{\sqrt{3}-5} = \frac{2}{\sqrt{3}-5} \cdot \frac{\sqrt{3}+5}{\sqrt{3}+5} = \frac{2(\sqrt{3}+5)}{3 - 5^2}$
ocean sealBOT
heavy
plain flame
like that?
covert kiln
Yea
lone heartBOT
@covert kiln Has your question been resolved?
paper flame
1kg water at 80c is mixed with .5kg of tea at 20c
Find final temperature of water using the relationship Q=mcT and the law of heat exchange
Take specific heat capacity of water as 4200J/kgC
I've been trying this for hours and the solution that I've got from somewhere doesn't make any sense, where did the joules come from(3.36*10^5) and 5000J?
paper flame
lone heartBOT
@paper flame Has your question been resolved?
still wyvern
I'm struggling with part (c) in this algebra problem. In general, since the order $P$ divides the order of $G$, then [|P|=p^kl] where $k|n$ and $l|m$. I have been able to show as a result of part (b) that in fact $k=n$, so $|P|=p^nl$. Now I am struggling to show that $l=1$.
ocean sealBOT
ecurtiss
lone heartBOT
@still wyvern Has your question been resolved?
fallow drift
|x|=x^2-2 , how can I solve this equation?
lone heartBOT
|x|=x^2-2 , how can I solve this equation?
plain flame
consider the piecewise definition of |x|
alpine sable
$|x| = \begin{cases} x &\iff x \geq 0 \ -x &\iff x < 0 \end{cases}
ocean sealBOT
45
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
fallow drift
so
create two solutions
and sub |x| with x or -x \
x^2+x-2
(x+2)(x-1)
x^2-x-2
(x-2)(x+1)
fallow drift
well now I kinda have another question
I mean this is from finding area between some curves, and if I treat |x| as -x and x depending on x>0 or x<0 does that make it like two different curves?
should I integrate this horizontally now?
hardy sparrow
I mean this is from finding area between some curves, and if I treat |x| as -x a...
I guess so
fallow drift
well alright
and do I just throw all the solutions into the equation to test which are valid and which are not?
hardy sparrow
Yes
fallow drift
so 2 and -2
hardy sparrow
Yes they work
fallow drift
now how would I integrate this with respect to y?
hardy sparrow
And yes they are the only solutions
fallow drift
I mean I can just add two integrals but y is easier?
plain flame
id argue just doing it wrt x is easier
well its symmetric you only need 1 integral
youre looking for the area between the functions right?
fallow drift
yea
fallow drift
I guess so
but isn't it like technically 3 curves because of this
plain flame
alright so you integrate |x| - (x^2 - 2) from -2 to 2
plain flame
$\int_{-2}^{2} |x| - x^2 + 2 \dd x = 2 \int_{0}^{2} x - x^2 + 2 \dd x$
hardy sparrow
Are these the curves you mean
ocean sealBOT
heavy
plain flame
by symmetry
fallow drift
hardy sparrow
Yes it is symmetric
lone heartBOT
lone heartBOT
Available help channel!
hot widget
hello so i want to figure out how to do this as i’m struggling with my homework
hot widget
if P = MVT
a p when m = 1600 v = 0.072 t = 10
(i have no idea what the formula means and searched the web topic is interest and depreciation)
b. m when p = 120 v = 0.3 t = 8
and finally c. v when p = 18, m = 60 and t = 5
thank you so much
versed escarp
@hot widget I think it means to multiply the values to get the answer? If not, more context please.
hot widget
yes that is for a i figured that out i don’t know what the formula means though for b and c
hot widget
thank you so much healthy
hot widget
ok thank you i’ll write that down
hot widget
thank you!
hot widget
will do thank you so much
versed escarp
welcome!
hot widget
i appreciate you
versed escarp
Also same for c, just swap v and m lol
hot widget
ok will try and see if i get the right answer
so for b it would be 0.3x8 x (1/120)?
if i’m understanding correctly? @versed escarp
hot widget
as the answer is meant to be 50 but that comes out as 0.02 so i’m not sure
versed escarp
oh
Um, lemme check
hmm
Let me see one mroe time
I might have done something wrong
Oh
Yeah I did something wrong lol
hot widget
ok
versed escarp
Ok let me get a new formula
hot widget
tysm
versed escarp
So basically
My goofy ahh mind
Is broken
Took me so long
To reliaze just divide both sides by vt
m = p/vt
💀
hot widget
ty for your help!
versed escarp
welcome lol
hot widget
tysm it worked
is it the same formula for c?
but v = p/mt
oh yes it is i got that one right
tysm
- close
-close
.close
carmine rapids
What type of problem is this ?
lone heartBOT
What type of problem is this ?
whole shell
What type of problem is this ?
wdym what type of problem
its just asking you what values of x gives you y = -4 on the graph
carmine rapids
um yeah id k how to do it at all
Usually I look up openmath videos but idk what to call this
whole shell
um yeah id k how to do it at all
wdym
literally
put your finger
on y= -4
then go left/right
till you touch the line
carmine rapids
left to right until I touch the line?
whole shell
@carmine rapids
well in this case you can only go right
since going left wont let you touch the graph
wary stream
No
Draw a line at y = -4
Find the interception
Basically where y = -4 and that function crosses at
lone heartBOT
lone heartBOT
Available help channel!
hollow cradle
is it possible to get the length between two points on a function?
if it is, how can i do it?
this is 5+cosx
vapid steppe
umm so the solution would be 2?
when is the y-value -4
serene junco
is it possible to get the length between two points on a function?
if it is, how...
I assume you mean the length along the curve, right?
Not the straight line distance?
hollow cradle
yes
hollow cradle
um i know some basics of integrals and derivatives
integral is the area beneath a function and derivatives are instantaneous rates of change
serene junco
The length along the graph of f(x) between two points at x=a and x=b is $S = \int_a^b \sqrt{1 + [f'(x)]^2} dx$
ocean sealBOT
tatpoj
hollow cradle
i see, thx
serene junco
Sure, np 👍
hollow cradle
.close
pliant gale
Is there a shortcut to this problem instead of going to each random choice and adding the sequences together 1 by 1? I know the answer is J. 23, but I'm trying to understand if there is a quicker way of doing this.
flint pecan
Look at the examples given
north hemlock
The number of odd terms is equal to the base of the perfect square
flint pecan
The average of 1 and 3 is 2, so 1+3=2^2
The average of 1 and 7 is 4, so 4^2
144 is 12^2, so find what numbers have an average of 12 with 1
north hemlock
that's better than mine rip
pliant gale
144 is 12^2, so find what numbers have an average of 12 with 1
ur a genius bro
thanks
.close
lone heartBOT
north hemlock
lone heartBOT
Available help channel!
drowsy sedge
Hey everyone! This Volume problem has got me messed up
It's just a practice problem, and im using symbolab and I see big R is the curve, while little r is the line, which is confusing me I thought it would be the other way around
waxen flame
That is a weird way to do it. Assuming you used the line as R and the curve as r, you should get the same result regardless.
waxen flame
Symbolab
drowsy sedge
god damn it symbolab
waxen flame
The fact that it used an absolute value is suspect.
waxen flame
What did you do?
drowsy sedge
wait i think I forgot a square
waxen flame
I got 64pi/3.
waxen flame
Show your work.
drowsy sedge
ok well nvm its right
it just decided
instead of writing it in exact form
it decided to spit out 67.02..
well god damn it symbolab
i was staring at it
confused
for like 10 years
wtffffffffffffffffffffffffffff
thanks
.close
alpine sable
Help 0.
alpine sable
how would i go about doing this
i dont understand
the approach here
immediately
i think
i should just simplify
x^2+3x*sqrt(4-x)
but is that really it
ik how to get the domain
north hemlock
well since you aren't going to be using imaginary numbers, you're domain would be the domain of whichever has the stricter interval
north hemlock
wym grab
north hemlock
yeah so multiply them
ocean sealBOT
alpine sable
.
alpine sable
LOL
grizzled compass
need help in starting pre algebra
north hemlock
also i'm stupid for not realizing that it's already done with expanding
north hemlock
need help in starting pre algebra
get ur own channle
grizzled compass
?
grizzled compass
ok
flint pecan
You need to find p(q(x)), which is basically the same as subbing in x=q(x) in p(x)
flint pecan
Yeah
flint pecan
Basically just replace the x in p(x) with sqrt(4-x)
north hemlock
$\circ \cdot$
ocean sealBOT
Jukelyn
north hemlock
hm
alpine sable
**Jukelyn**
Finally.
The answer.
https://cdn.discordapp.com/attachments/490557019623915520/1076338865893290034/347216701055565827.png
alpine sable
Basically just replace the x in p(x) with sqrt(4-x)
so from p(x) = x^2+3x to p(x) = sqrt(4-x)^2+3(sqrt(4-x))
?
flint pecan
north hemlock
composition is when u basically slap a function inside another function
lone heartBOT
@alpine sable Has your question been resolved?
exotic belfry
This feels very incorrect
lone heartBOT
This feels very incorrect
exotic belfry
My reasoning that is
mainly because I don't really understand what the group is?
like it's the set of opposite faces
my actual guess is that is has more to do with the rigid motions about the diagonal
idk
lone heartBOT
@exotic belfry Has your question been resolved?
lone heartBOT
Available help channel!
cerulean kernel
so im working through this algebra problem. the question is there (the one not in handwriting) and the answer is handwriting from my lecturer. my question is, how come the y is on the outside of the brackets randomly when they solved it?
cerulean kernel
in fact, if anyone gets to this, please make sense of the working out to me and why it has been done this way because it doesn't make sense to me right now
flint pecan
They pulled out a common factor of the two terms 10yx^2 and 8y^3x, which is 2xy
cerulean kernel
got you, ok. how come this question utilizes this method specifically. as in the method of pulling out common factor
flint pecan
They wanted to cancel 2x in the denominator
Well you could just pull out 2x and that would still work
cerulean kernel
kk, so because they know it will be divided by 2x they need something to cancel out above?
flint pecan
Yeah
cerulean kernel
kk that makes sense. one last thing, i notice they divide 10yx^2 and 8y^3x by 2x but still have the 2x as the denominator. how come the 2x wasn't taken away after it had been divided, or am i reading it wrong
tropic oasis
lone heartBOT
tropic oasis
how woudl i start on this?
i get confused it being a fraction
ohh negative exponetes
timid jolt
How do I do q 11a?
lone heartBOT
How do I do q 11a?
woven plaza
cerulean kernel
could someone explain to me why 2x^4 is equal to 16x^4 in this expression?
lone heartBOT
lone heartBOT
Available help channel!
dusk bone
lone heartBOT
dusk bone
15 D
I tried doing this but the answer was wrong
Could anyone help me with this question
flint pecan
I'll set the three numbers as a, ar, ar^2
The sum of these are 14, so that's our first eq
a+ar+ar^2=14
Now a+1, ar+1, ar^2-1 results in a AP
So we can set our second eq as
(a+1)+(ar^2-1)=2(ar+1)
dusk bone
How can we start the second equation like that?
Set*
Ohh is it cause ar+1 is the mean?
flint pecan
Yes
dusk bone
ar=4 is that correct?
dusk bone
.close
hard remnant
how to solve this equation
lone heartBOT
how to solve this equation
echo socket
Consider applying sin to both of the sides
lone heartBOT
@hard remnant Has your question been resolved?
lone heartBOT
lone heartBOT
Available help channel!
acoustic geyser
Find a positive integer that multiplied by 333,333 gives the result a number made up of all ones.
acoustic geyser
Is there any formula for this?
Really got no idea besides multiplying like crazy
flint pecan
Yeah mb
acoustic geyser
The more number u have, the amount of the total will increase so
But it must ends up with 7
That's right
vale wigeon
well, try to construct the number digit by digit in this fashion
333333 * 7 = 2,333,331
so when you multiply 333,333 by the tens digit, you want the result to end in an 8
acoustic geyser
Mhm
acoustic geyser
so when you multiply 333,333 by the tens digit, you want the result to end in an...
1
All ones
For example: 111111111111
ripe pilot
is that possible
ripe pilot
imma try for a while
gray isle
read what Ann said carefully
vale wigeon
let me clarify what i said.
gray isle
or ^
ocean sealBOT
Ann
let the unknown number (whose product with 333,333 is made of all ones) be $\overline_{a_n a_{n-1} \dots a_2 a_1 a_0}$. we don't know how many digits long it'll be, so that'll have to remain unknown as of yet.
```Compilation error:```! Missing { inserted.
<to be read again>
}
l.33 ...33,333 is made of all ones) be $\overline_
{a_n a_{n-1} \dots a_2 a_1...
A left brace was mandatory here, so I've put one in.
You might want to delete and/or insert some corrections
so that I will find a matching right brace soon.
(If you're confused by all this, try typing `I}' now.)```
vale wigeon
augh
let the unknown number (whose product with 333,333 is made of all ones) be $\overline{a_n a_{n-1} \dots a_2 a_1 a_0}$. we don't know how many digits long it'll be, so that'll have to remain unknown as of yet.
ocean sealBOT
Ann
acoustic geyser
Mhm mhm
vale wigeon
we have so far established that the units digit, a_0, is 7
acoustic geyser
Ye
vale wigeon
so we have:
$333333 \cdot \overline{\dots a_2 a_1 a_0} = 333333 \cdot \overline{\dots a_2 a_1 7} \ = 333333 \cdot \overline{\dots a_2 a_1 0} + 333333 \cdot 7 \ = 333333 \cdot \overline{\dots a_2 a_1 0} + 2{,}333{,}331$
ocean sealBOT
Ann
acoustic geyser
Yes
vale wigeon
we want all this to have 1 in its tens digit
acoustic geyser
Mhm
vale wigeon
we already have 3 in the tens place from the 2,333,331
so we want another 8 in the tens place from 333,333 * [...a2 a1 0]
ocean sealBOT
ocean sealBOT
vale wigeon
,w 333333 * 66667
ocean sealBOT
vale wigeon
,w 333333 * 666667
ocean sealBOT
acoustic geyser
Yes
vale wigeon
and now we need 2+9 = 1
to put it in a somewhat clunky way
so the next digit is 3
,w 333333 * 3666667
ocean sealBOT
vale wigeon
and continuing in the same fashion...
acoustic geyser
,w 33333666667 * 333333
ocean sealBOT
acoustic geyser
,w 333333666667
ocean sealBOT
acoustic geyser
,w 333333666667 * 333333
ocean sealBOT
cunning bloom
I need some help with parttial fractions:
