help-0

[rocky grove]

We got R(x) = ax+b

Right?

[raw jetty]

yeah

[rocky grove]

This is correct but instead of a, you use x

[raw jetty]

oops

so thats the final answer?

[rocky grove]

Yep

-2x+3

[raw jetty]

god damn tankyou very much!

[rocky grove]

[raw jetty]

.close

[lone heart]

Channel closed

Closed by @raw jetty

Use .reopen if this was a mistake.

[rocky grove]

Hope you understood :)

[raw jetty]

i did :]

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[orchid perch]

the random variable $X$ has a geometric distribution with an expected value of 6
what is the probability that the first success is after atleast 3 attempts

[orchid perch]

im clueless here

.close ass

[lone heart]

Channel closed

Closed by @orchid perch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[charred sapphire]

Halp I ran into another one, later on in the chapter. It’s similar to the last one. I’ll take pictures.

[charred sapphire]

The question is “break out y”

One moment

[royal plank]

first one was right

[charred sapphire]

Yeah wait I just confused the ending on b)

As you can see neither is correct, the correct answer is to the right and my answer is the end of the chain

[royal plank]

ah yes, I mean that

[charred sapphire]

I put the correct ones in brackets from the back of the book

[royal plank]

I only saw the right, the other stuff is hard to read

so for a) its simple, you can combine the terms on the left

[charred sapphire]

Maybe I can get a better picture sorry

[royal plank]

no don't bother

we just do it now right

$\frac{1}{x}+\frac{1}{5x}=\frac{1}{y}$

[ocean seal]

Jigglyproff

[royal plank]

how would you combine the terms on the left here

[charred sapphire]

Oh

Lmfao yeah it’ll be 2/6x

[royal plank]

no what

thats not how to combine fractions

you need a common denom

[charred sapphire]

Lol f my life why can’t I think today

[royal plank]

so you need to do something to $\frac{1}{x}$ so the x becomes 5x

[ocean seal]

Jigglyproff

[charred sapphire]

Yeah I did try this before when I wasn’t so tired, but ended up getting this “y=1/(5x/6)

So there was an extra 1 in there

[royal plank]

yeah u made a mistake after

but anyway

$\frac{5}{5x}+\frac{1}{5x}$

[ocean seal]

Jigglyproff

[royal plank]

thats on the left now

so 6/5x

how to solve $\frac{6}{5x}=\frac{1}{y}$?

[ocean seal]

Jigglyproff

[charred sapphire]

Hmm, both parts times 5xy?

[royal plank]

what why

do you know the reciprocal rule over equations?

[charred sapphire]

That’s how you solve it according to the book, when there’s two fractions

I swear it worked before

[royal plank]

$\frac{a}{b}=\frac{c}{d}\rightarrow \frac{b}{a}=\frac{d}{c}$

[ocean seal]

Jigglyproff

[royal plank]

you can 'swap' both sides just like that

[charred sapphire]

See this one was never taught to me, in any book

[royal plank]

its 4 operations

[charred sapphire]

I must have missed it in school

[royal plank]

no, its just a trick

its division and multiplication

you multiply both sides by d and b, then divide by a and c

thats the 'swapping' in 4 steps

[charred sapphire]

I seee

[royal plank]

so you end with $\frac{5x}{6}=y$

[ocean seal]

Jigglyproff

[charred sapphire]

I’m trying it

[charred sapphire]

Alright it worked, I’m gonna try it on b)

[median oar]

I mean you don’t need to

You can multiply the right side by 6/6

And equate the denominators

[charred sapphire]

I will need further explanation, English is not my first language 😦

[median oar]

You also have to be careful the bottom doesn’t equal 0

[royal plank]

https://cdn.discordapp.com/attachments/490557019623915520/1069554552476545045/IMG_1049.jpg

[royal plank]

it means to make the numbers under 2 different fractions the same

[charred sapphire]

If you could take me through b) it would be super kind

Because my brain has shut down

[royal plank]

we aren't quite done with a)

[charred sapphire]

This is what happens when you wake up at 11 pm

[charred sapphire]

I solved it!

[royal plank]

almost

you see how you divide by x?

like the term 1/x

division by 0 is forbidden, so for this task you need to provide an condition

$x \neq 0$

[ocean seal]

Jigglyproff

[charred sapphire]

I think I did but maybe it’s wrong

[royal plank]

I don't know if you already have to care for that, but formally you have to add it

[royal plank]

the solution is fine, but x cannot be 0

[charred sapphire]

Where do you mean?

[royal plank]

x just cant be 0 lol

1/0 is forbidden

[charred sapphire]

No 0s only my terrible handwriting

[royal plank]

https://cdn.discordapp.com/attachments/490557019623915520/1069554552476545045/IMG_1049.jpg

look at a)

there is 1/x

[charred sapphire]

Yes sir

[royal plank]

so x cannot be 0

[charred sapphire]

No sir

[royal plank]

anyway, lets move to be

[charred sapphire]

5x divided by 6 equals y

Is what I’ve written. But maybe the 6 is so badly written it looks like a 0 haha

[royal plank]

you again want something like $\frac{1}{y}=\frac{something}{something}$

[ocean seal]

Jigglyproff

[royal plank]

in b)

[charred sapphire]

So rejig it a bit so I get 1/y alone first

[royal plank]

y

[charred sapphire]

Now I have 1/y = 1/x - 1/z

[charred sapphire]

. Sorry I forget to reply

[royal plank]

now combine the right side

combine $\frac{1}{x}-\frac{1}{z}$

[ocean seal]

Jigglyproff

[charred sapphire]

I got x/zx - z/zx

[royal plank]

so.. combine a little more

[charred sapphire]

x-z/zx

[royal plank]

so we have $\frac{1}{y}=\frac{z-x}{zx}$

[charred sapphire]

z-x actually

[ocean seal]

Jigglyproff

[royal plank]

yeha right

[charred sapphire]

Yes so now we do the switcheroo?

[royal plank]

yes

[charred sapphire]

Aha, I think I get it now

[royal plank]

so $y=\frac{xz}{z-x}$

[charred sapphire]

This is the “hardmode” part of the chapter so that’s a good thing

[ocean seal]

Jigglyproff

[charred sapphire]

Which is the answer!

Thank you, you’re like a proper teacher up in here

.close

[lone heart]

Channel closed

Closed by @charred sapphire

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wheat umbra]

Question 16

Please

I have the answer to the question but I don’t know how to do it?

[lone heart]

@wheat umbra Has your question been resolved?

[wheat umbra]

<@&286206848099549185>

[wheat umbra]

I need help with question 16 projectile motion

[lone heart]

@wheat umbra Has your question been resolved?

[lone heart]

@wheat umbra Has your question been resolved?

[pliant cedar]

okay what have u tried

[wheat umbra]

I tried integrating from y and x double dot

and didn’t get the answer

[restive cloak]

Hello I'd like to get helped with this exercise, thank you.

[mortal trellis]

read #❓how-to-get-help and get your own channel.

[lone heart]

@wheat umbra Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[obsidian edge]

can somebody assist with explaining the inductive step here?
I've proved the base case already

[obsidian edge]

I just dont understand how to set up how I need to prove

[rare gale]

first, check the case for n = 1

confirm that is true

then check that if you assume that it's true for n = 1, ..., k (up to some k) it implies that it's true for k + 1

[obsidian edge]

yes the base case is true, LHS would be a_1=2, and RHS 3^0-3^0 (1-1) + 2 = 2

so LHS = RHS

then assume true for some integer k, replacing n for k in a_n

then need to prove for k+1

[rare gale]

now set up the equation for k + 1 and try to get transform it in such a way that you can use the equality being true for k, which will be your assumption

[obsidian edge]

so with the statement it would be

uh one sec ill type in lated

sorry for my ignorance, ive not done a PMI question like this and hard to find videos about it

I know this cant be it

because im missing a step obviously

[rare gale]

so thats the case for n, but what you want to look at is n = k + 1

so if n = k + 1, you'd have 3^k - 5^k + 2 i guess

[obsidian edge]

so replace n with k+1

ye

[rare gale]

sure, you can use n but it would probably be clearer to use another variable name to be clear youre doing that part of the induction proof, but however you prefer, im just used to k i guess

[obsidian edge]

ye i mistype i use k

simpler

so now with

oh wait

nbm

nvm

yeah idk lol

[lone heart]

@obsidian edge Has your question been resolved?

[obsidian edge]

.close

[lone heart]

Channel closed

Closed by @obsidian edge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worldly summit]

Hi

[worldly summit]

I need help with a problem

But its in spanish

[smoky adder]

is it a word problem

[worldly summit]

Yes

[smoky adder]

you're gonna get the best help if you translate it

[worldly summit]

Ok

I have to found a parabola with this ecuation

And i have the tangent line in x=1 who have slope 4 and pther tangent line in x=-1 whit -8 slope and this parabola pass for 2,15

(2,15)

I tried looking for a, b numbers

And i get this

I derive and i stratted looking for the a b numbers

Because the parabola derive has two constants

A and B

[smoky adder]

are you sure A is -3?

check your division

[worldly summit]

Its 3

Positive

[smoky adder]

yup

so your equation so far is $y=3x^2-2x+C$

[ocean seal]

baro | awake

[worldly summit]

But how i can find c?

[smoky adder]

plug in the point that it passes through

$15 = 3(2)^2 - 2(2) +C$

[ocean seal]

baro | awake

[smoky adder]

and solve for c

[worldly summit]

Ahhhh ya entiendo

I understand

[smoky adder]

good job!

[worldly summit]

Thks baro

[smoky adder]

np

remember to .close

[lone heart]

@worldly summit Has your question been resolved?

Channel closed

Closed by @worldly summit

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pure tree]

help

[pure tree]

so

AB= 5/6 of CB

CB=AC

AK=CH+4

AB=?
AC, BC=?

like i don't how to proceed

[lone heart]

@pure tree Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[pure tree]

<@&286206848099549185>

[sly cairn]

Yes what is the issue

because here we don't have the exercice

[pure tree]

how

[sly cairn]

or instruction of ur issue

[pure tree]

.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vast arrow]

Just want to double check I did this correct

[vast arrow]

-2 would mean it moves 2 to the right and -4 would be the y intercept right

[serene junco]

The -4 shifts the graph down four units

It is not necessarily the y-intercept

[vast arrow]

gotcha

So 4 down from its original point then right 2 correct?

[serene junco]

Yes

So (2,-4) is in the right place on your graph

but (3, 1) is not

[vast arrow]

hmm

would -2 me you expand the graph?

[serene junco]

Nope, you were right about what the -2 does

It represents a shift of 2 to the right

Look at the point on the red graph

(1,6)

if you move 2 right and 4 down

You end up at (3,2), not (3,1)

[vast arrow]

yes I just was about to say that

because for 1 unit right it goes up 6

correcT?

[serene junco]

from the vertex, yes

[vast arrow]

so I would end up with this

[serene junco]

Looks good 👍

[vast arrow]

wonderful thank you

[serene junco]

no problem

[vast arrow]

I got one more question about a different problem I cant understand

if you are available

not sure what to do here

[serene junco]

f^-1 is the inverse of f

Do you know what that means?

[vast arrow]

its just x

correcT?

[serene junco]

I think you mean if you compose a function with its inverse, you just get x

$f(f^{-1}(x)) = x$

[vast arrow]

Yes something along those lines

[ocean seal]

tatpoj

[serene junco]

that's true but that's not what I was getting at

[vast arrow]

Got it

[serene junco]

The inverse reverses the input and output

so

if $f(a) = b$, then $f^{-1}(b) = a$

[ocean seal]

tatpoj

[vast arrow]

Oh

I thought when you ment reverse it would reverse the positive or negative

That’s where I was getting confused

[serene junco]

nope it just switches them

[vast arrow]

Got it

[serene junco]

so if you want f^{-1}(2)

You want to find some number c such that f(c) = 2

which we can find from your graph

[vast arrow]

I’m this case we would look at the x axis right

And see what is equal to 2

If that is true we match it to 3

[serene junco]

Yes

since f(3) = 2

then f^{-1}(2) = 3

[vast arrow]

Got it

Thank you so much for clarifying it’s going to help on my mid term

[serene junco]

Awesome, no problem 👍

[vast arrow]

Have a great day

.close

[lone heart]

Channel closed

Closed by @vast arrow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tepid badger]

Hi, I was wonder if someone could verify my solution 🙂

[whole shell]

you just want to know the minimum? of that function

then yh it is correct

[lone heart]

@tepid badger Has your question been resolved?

[tepid badger]

well I had to find min and max but there is no maximum I guess

thank you!

[lone heart]

Channel closed

Closed by @tepid badger

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[astral swan]

Construct a bijective function from (0,1) to (2,3)U(5)U(10,100)

[astral swan]

could this be done?

[lone heart]

@astral swan Has your question been resolved?

[serene junco]

Those are open intervals, right?

[astral swan]

yes?

[serene junco]

then yes

You can map
(0,0.5) onto (2,3)
{0.5} onto {5}
and (0.5,1) onto (10,100)

for example

[astral swan]

thank you

.close

[lone heart]

Channel closed

Closed by @astral swan

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[somber spoke]

Is it possible to get complex solutions to ln(3-sqrt(10))

[west girder]

,w ln(3-sqrt10)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by kappa#4417

[somber spoke]

How do u go abt doing it tho

I’ve tried setting it equal to a+bi but to no avail

[west girder]

ln(3-sqrt10)=ln(-1(10-sqrt3))

[somber spoke]

I see

And then log laws

And now I just need to find ln(-1)

[west girder]

yea just rewrite -1 in polar form and you’ll get all of your solutions

[somber spoke]

Haven’t done polar form yet but I’ll look into it

[west girder]

The motivation is to make the part inside the natural log real

[spice epoch]

Pretty good intuition anyway as to why complex log is multivalued

log(z) = log(-z) + iπ for all z, so log(z) = log(z) + 2iπ

Which doesn’t make sense as an equation lol so forgive my abuse of notation; think of log(z) as already representing all the solutions

[lone heart]

@somber spoke Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[proper sedge]

.open

!open

[proper sedge]

what am i doing wrong

[lone heart]

@proper sedge Has your question been resolved?

[proper sedge]

https://tenor.com/view/crazy-cuckoo-nuts-gif-7988440

it would be so awesome

it would be so cool

it would be the most incredible super hero movie the world has ever seen

the screens would light up

with real explosions

and special effects

and tons and tons of

special effects

and it would blow your mind

cause its my movie, my movie, my superhero movie

theyd be lining up to see a movie all about me

[opaque sandal]

help

what is this called

the line thing'

[proper sedge]

idk something probably

hold on let me just paste the bible in here

gotta spread the good word

wait theres a bunch of numbers in here (yucky)

here this should be better

"75 lines left"🤓

these new famngled computerss are baised aganst the woerd of god......

[proper sedge]

hang on I should have included this image at the start with the others my bad

oopsie poopsie😩

.close

[lone heart]

Channel closed

Closed by @proper sedge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ripe ingot]

Hi can anyone explain how to find X in a question such as the one above?

I have no idea how the numbers 210 and 42046 were found. The lecturer for this module I am doing mentioned using the quadratic formula however his answers are as shown in decimal format and I am completely lost because he does not explain it at all.

[smoky adder]

do you know the quadratic formula at all?

[ripe ingot]

Yes I do have a bit of practice with it

But not in a case like this. The question doesn't quite have a "b" value or an "a" value

[smoky adder]

$$ax^2+bx+c=0$$ \\
$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$

[smoky adder]

you need to convert to standard form

[ocean seal]

baro | awake

[smoky adder]

well yes but i wouldn't use mathway lol

[ripe ingot]

So writing to standard form shows this though I don't have anything like "a" or "b"

In this case I'm doing a spot rate calculation for portfolio management

I just have a bunch of numbers and he mentions to solve it

This is his solution however he doesn't explain how to solve the quadratic. That's the only bit I am struggling at

[smoky adder]

i can't see that really

[ripe ingot]

Give me a minute I'll just send it a different way

[smoky adder]

in this case, a = -105, b = -5, and c = 100.05

[ripe ingot]

ah alright

I am going to quickly try that

[smoky adder]

it looks like he's setting $x = \frac{1}{1+rm}$

[ocean seal]

baro | awake

[ripe ingot]

yes that is what he is doing in order to convert it iirc

also inputting it in to the quadratic equation that way does not give the answer he has given. When using mathway to find x I get the exact same answer as he gets

So I am completely lost right now on how he works this out

[smoky adder]

can i see what you input?

i'm getting what he is

[ripe ingot]

I used a online tool to do it however this is what I am getting I could do it by hand plus calculator though as well

I keep getting math error on my calculator guess I am somehow inputting it wrong

[surreal mason]

signs

the c term is negative

[ripe ingot]

in the question itself that he gives for practice the c term 100.05 is positive am I missing something when reading the quadratic that he gave?

Also I think I need to program my calculator to try the quadratic equation otherwise it won't work

[surreal mason]

you can either flip the sign of both a and b or just c

[ripe ingot]

all of them are positive

[surreal mason]

100.5 - 5x - 105x2

[floral willow]

https://media.discordapp.net/attachments/490557019623915520/1069747911589646336/Screenshot_20230130_223631.jpg

[surreal mason]

doesnt look positive to me

[floral willow]

they won't be all positive

[ripe ingot]

so if this is the formula why would I need to flip and mish mash the numbers from positive to negative or vice versa for this specific case? In the video he just seemed to do it with positives without mentioning flipping the signs at any point

I think the video is mixing me up since on there he does not do two separate equations one pos and one neg

[floral willow]

well sometimes you flip it so you can make it easier for yourself

[ripe ingot]

I can't even seem to program my calculator to accept A,B and C

so my calculator cannot do quadratic equations ig

[smoky adder]

are you using a ti84

[ripe ingot]

No I am using a casio fx-83GT X

[smoky adder]

idk how to program that

[ripe ingot]

I am following a video on it but it does not work

[smoky adder]

¯_(ツ)_/¯

you should be able to just do the quadratic equation manually if the programming doesn't work

[ripe ingot]

nope it gives me math error if I try

I follow it exactly as above, tried to use brackets for a and c and have tried to just multiply them but it does not work

[smoky adder]

Can I see what you're inputting

[ripe ingot]

I must be doing something wrong

let me try again

@smoky adder

[smoky adder]

you're multiplying

[ripe ingot]

Ah that would explain why then

Damn I didn't add the brackets and didn't place the - I knew that I must have been doing something wrong

[ripe ingot]

Thanks for the help!

[smoky adder]

did it work?

[ripe ingot]

yes it did

[smoky adder]

yay!

[ripe ingot]

turns out I did do something wrong

same goes for everyone else

imma close the channel so others can get help too

.close

[lone heart]

Channel closed

Closed by @ripe ingot

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spare fern]

can anyone check my working?

[worn fox]

,w int from 0 to 4 of 2x+1

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by iCaird#6258

[worn fox]

you need to either "undo the chain rule" or do a u sub

[spare fern]

yeah but when I substitute I keep getting 40.5 for x = 4

and 0.5 for x = 0

[blazing thunder]

You can think of splitting the integral into two different ones

That might make it more apparent to you

[worn fox]

differentiate 1/2 * (2x+1)^2 and see if you get 2x+1

[spare fern]

well what did I do wrong with my working?

[spare fern]

.

[worn fox]

you took the antiderivative wrong

[spare fern]

Oh I see it should be (2x+1)^2/4 right?

[worn fox]

yep

[spare fern]

Ok thanks

[vale wigeon]

why not just integrate term by term

this is a polynomial why bother with any fancy shit

[spare fern]

how about this?

[blazing thunder]

Fr

[spare fern]

Here is my working

[lone heart]

@spare fern Has your question been resolved?

Channel closed

Closed by @spare fern

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mellow mural]

I know I need to use the larger angle theorem

but how do I solve this?

<@&286206848099549185>

[serene junco]

what theorem are you referring to?

[thorny root]

something like longer side implies larger angle I think

and vice verca. in a single triangle, talking about inner angles

[lone heart]

@mellow mural Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

l

[alpine sable]

$12x^2 - 60x + 75$

[ocean seal]

AllUtility

[alpine sable]

factor completely if polynomial is prime state this

3(4x^2 - 20 + 25)

3(4x^2 - 10 -10 +25)

3(2(2x^2 - 5) 5( -2 + 5)

.close

[lone heart]

Channel closed

Closed by @still horizon

Use .reopen if this was a mistake.

[alpine sable]

.reopen

[lone heart]

✅

[alpine sable]

no one came so I have to create a new one for someone to see it

[pale lance]

I figured you were about to solve it on your own

[raven haven]

do not do this please

[alpine sable]

how about just let me close the channel and make a new one

[raven haven]

no

do not do that

[alpine sable]

.close

[lone heart]

Channel closed

Closed by @still horizon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh forge]

How did the teacher split those fractions?

[marsh forge]

With Partial Fraction decomposition I got 11/(10-y)

[keen mason]

1/y(10-y) = A/y + B/(10-y)

1 = A(10-y) + B(y)

y = 0, 1 =10A, A = 1/10

That doesn’t look right

y = 10, 1 = 10B

B = 1/10

Ayee

That looks better

[mellow mural]

yeah

that's the one

[keen mason]

1/10y + 1/10(y-10)

And times both sides by 10

[marsh forge]

I got B=11/10

[keen mason]

1/y + 1/y-10

[marsh forge]

Where did I go wrong

[keen mason]

Let’s see your working

[marsh forge]

Ok I see it

Thank you

.close

[lone heart]

Channel closed

Closed by @marsh forge

Use .reopen if this was a mistake.

[keen mason]

Didn’t even need me bro it was all u

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crude gull]

"considering the following permutation S8, determine the composition in disjunt cycles and the order of σ ,where the order of permutation σ is the minimum natural number k that makes σ^k = Id"

[crude gull]

i decomposed it

but i dont understand the last part

"find the order of σ,where the order of permutation σ is the tiniest natural number k that makes σ^k = Id"

[raven haven]

do you know what the identity permutation is

[crude gull]

15,18,13,12,16,47 right?

[raven haven]

no

[crude gull]

this one?

[raven haven]

yed

yes

[crude gull]

and how can i find a k that makes σ^k = Id i dont get it

[raven haven]

okay

do you know about this result

actually do you know what an order is

Let $G$ be an arbitrary group with identity $e$. Let $g$ be any element from G. Then the order of $g$, denoted $|g|$ is the smallest integer $n$ such that $g^n = e$

[ocean seal]

active mental mutilation liker

[crude gull]

"lete g be any element from G"

[raven haven]

I'm giving you the definition of an order

[crude gull]

if i choose any of them i will get a different result no ?

oh

and what do i do with that

[raven haven]

Okay let me make this clearer for you

You want a $k$ such that $\underbrace{\sigma\sigma\dots\sigma}_{k , \text{times}} = I$

[ocean seal]

active mental mutilation liker

[raven haven]

and of course, k should be the smallest

[crude gull]

exactly

the only thing that i dont understand

is how is it possible to obtain the identity by multiplying σ k times

is it 4?

[raven haven]

consider the super super basic permutation (12)

[crude gull]

just because there are 16 elements?

[raven haven]

(12)(12) would be?

[crude gull]

144 ?

[raven haven]

err

no no

those are permutations

[crude gull]

havent done permutations multiplications i know its weird but the exam will have a lot of things mashed together

a lot of things but not elaborated*

[raven haven]

okay basically here's the idea

I'll compute (12)(12) for you

and you should probably be able to extrapolate from there

let $\alpha = (12)(12)$

[ocean seal]

active mental mutilation liker

[raven haven]

then $\alpha(1) = 1$

[ocean seal]

active mental mutilation liker

[raven haven]

and $\alpha(2) = 2$

[ocean seal]

active mental mutilation liker

[raven haven]

basically the idea is you just slowly check it

afterwards you will obtain disjoint cycles

and then use the theorem

[crude gull]

im looking at this for a bit and doesnt it just end at a(8)=8?

and at the end how can i literally end up with the identity permutation

[crude gull]

i cant understand this

is there something im missing

(well of course)

[raven haven]

yup

well I didn't write down everything

like what (12) is saying in S_8 is basically

(12)(3)(4)(5)(6)(7)(8)

implicitly everything that is being fixed is just not written down

[crude gull]

ohhh got it

so isnt it just 8?

[raven haven]

err

I recommend revisiting the definitions

I'll be off for a while

if someone else comes they could help you

I may be back

[lone heart]

@crude gull Has your question been resolved?

[lone heart]

@crude gull Has your question been resolved?

Channel closed

Closed by @crude gull

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fair musk]

All I need are the bounds

I've given up on anything else, I'm going to input the formula after I get the bounds

[slender marten]

Use Desmos to plot it if you want or you will have to mess about for a while to get a good sketch. You need to find where they intersect.

[fair musk]

how did u input theta?

[slender marten]

Use r(theta) =

It's obvious using the plot to see the theta bounds. But if you had no image you would set them equal and get theta that way and use the way they worded it to say which is bigger than the other in terms of distance from the origin.

[fair musk]

how would solve for theta?

[slender marten]

Notice for a ray theta = theta_0, the lower bounding curve is the line and the upper bounding curve is the circle. This is true for all theta 0 <= theta <= pi/2 and they intersect at the end points of the theta interval.

4sin(theta + pi/4) = 2 sec(theta - pi/4).

[fair musk]

It doesnt seem to be a value in terms of pi

and i cant click on the intersection in desmos for some reason

[slender marten]

Ok. I think you need a refresher on Polar coordinates.

[fair musk]

Oh is that 0

and the other one is pi / 2

[slender marten]

Yes. I got this using the graph and not by algebra though.

Remember that theta is the angle of the ray emanating from the origin with an angle theta with the positive x-axis.

So y = 0 for x > 0 would be theta = 0.

[lone heart]

@fair musk Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hollow ore]

I have a question, it's a graph question

[hollow ore]

Apply all transformations one-by-one (and in order) to the figures below & label each point in prime notation
on the graph.

1. Triangle ABC:

a. Reflection across the x-axis
b. Reflection across the y-axis

A:(-8,5)
B:(-3,6)
C:(-6,1)

I can provide pictures

[last ether]

I want you to imagine any point, and then reflect it across the x axis. What part of the coordinate would get affected

[hollow ore]

what do you mean by reflect and affect?

[heady pollen]

reflected like by a mirror

[hollow ore]

so I need to find out which angle is facing the X and Y axis?

[heady pollen]

with affected, he probably means:
a point has a x and y coordinate
now think about which part of this point changes after the transformation

think about it visually

then you wont have to calculate anything

[hollow ore]

hmm

I will look

but I don't really understand the word reflected

[heady pollen]

for example, what happens if we reflect the point (a,b) across the x axis?

[hollow ore]

how does a point become reflected

[hollow ore]

what happens?

[heady pollen]

one sec

[hollow ore]

they change places?

[heady pollen]

im gonna make a drawing

[hollow ore]

okay

[heady pollen]

the black line is the line of reflection

and we apply this reflection onto a point P

[hollow ore]

oh

so if the x axis was -8

it would reflect

and become 8?

[heady pollen]

depends on what the -8 is

a point has two numbers

[hollow ore]

yes

[heady pollen]

if we reflect this point across the x axis

which part will be changed?

[hollow ore]

the x axis

horizontal part

[heady pollen]

im gonna show you an example

[hollow ore]

alright

[heady pollen]

in this case as before we reflect across a line

this line is the blue line

in this case it is the x axis

and as we can see, the x value of the point does not change

[hollow ore]

so what changes?

the y value?

[heady pollen]

yes

in the picture, the height changes

[hollow ore]

so let's say this point is -3

it becomes...?

[heady pollen]

that is not a point

at least not in 2d

we are dealing with points like (-3,5)

[hollow ore]

in my case im not dealing with numbers

I'm dealing with a triangle on the graph

[heady pollen]

yep

and a triangle is defined by 3 points

[hollow ore]

yes

[heady pollen]

all of which are of the form (x,y)

[hollow ore]

ABC

[heady pollen]

reflecting the triangle across an axis is the same as reflecting all of it's points across that axis

so if we want to reflect it across the x-axis, we reflect every point of it

[hollow ore]

so if they want the reflection of the X axis

I must move the whole triangle down?

[heady pollen]

not moving, reflecting

[hollow ore]

yes

reflect it down

[heady pollen]

yes

[hollow ore]

if it was on the Y axis

I reflect it to the right

[heady pollen]

yes

basically:
reflection across x-axis -> change the sign of every y component
reflection across y-axis -> change the sign of every x component

(a,b) has x component a and y component b

so in your example, the point A: (-8,5) reflected across the x-axis will become (-8,-5)
reflected across the y-axis it becomes (8,5)

[hollow ore]

oh my god thank you

I never thought that I would understand it

all thanks to you man

[heady pollen]

nice! you're welcome

[lone heart]

@hollow ore Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[true vector]

wrong channel

.close

[lone heart]

Channel closed

Closed by @true vector

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fleet rivet]

Guys i need helps fast pls my test is in 3hrs

"One of the interior angles of a regular polygon is 108
Find the amount of sides in the polygon."

I aldready know that its a pentagon, but i need to understand the method incase the angle is different

This is what ive come up with

(n-2)x180
---------- = 108
n

Any further help?

[thick grail]

Oops I didn’t see that you had it as a fraction

[fleet rivet]

i just need to solve this equation

(n-2)x180
---------- = 108
n

[thick grail]

Do you need help in solving it?

[fleet rivet]

yes

[thick grail]

Multiply the n over to the other side

Expand the brackets on the lhs

180n - 360 = 108n

Collect like terms

And you’re done

[fleet rivet]

ok

so

(n-2)x180 = 108n

and

(180n - 360) = 108n

[thick grail]

There’s more

[fleet rivet]

wait i get it

[thick grail]

You got to solve for n

[fleet rivet]

-360 = -72n

[thick grail]

So what will the answer be

[fleet rivet]

5?

[thick grail]

Yes

[fleet rivet]

Yes!

i forgot all about expanding

thank you!

[thick grail]

Nw

[fleet rivet]

.close

[thick grail]

All good

[lone heart]

Channel closed

Closed by @fleet rivet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

Hello

[alpine sable]

How can I find the A

From here

This is simultaneous equation

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[woven plaza]

[thin ivy]

;-;

[serene junco]

What is the question?

[thin ivy]

how do you graph it

[serene junco]

Hm

I'd choose some x-values that go conveniently into that log

(like 1/100, 1/10, 1, 10, 100)

and see what the outputs are

and just plot the points

[thin ivy]

thats all?

wait sorry if that sounded rude

I didn't mean it like that

I meant how do you find the anchor points, domain, and range as well?

[serene junco]

Oh, in that case do you know what a log graph typically looks like?

[thin ivy]

yea

[serene junco]

like if it was just f(x) = log_10(x)

[thin ivy]

I don't know that no

[lone heart]

@thin ivy Has your question been resolved?

[thin ivy]

.close

[lone heart]

Channel closed

Closed by @thin ivy

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

Please if somebody know I am stuck

[alpine sable]

I just dont know how to start it

this is calc -2

[gray ingot]

can you imagine what kind of shape it's forming?

I think a good starting point would be plotting the region in 2D space

[alpine sable]

so it is rotating somehow

if i am not wrong

[gray ingot]

can you shade the region?

yes it's rotating about the y axis

[alpine sable]

yes, give me a second

[gray ingot]

yup that's correct

now imagine taking that triangular shape and spinning it about the y axis (you get something that looks like a bowl)

[alpine sable]

ok

that is like the representation of what it would create

right?

[gray ingot]

kind of yeah but in your case it'll be this volume

[alpine sable]

like not the grey area?

[gray ingot]

nope

[alpine sable]

ohhhhh

[gray ingot]

since they've asked you for the yellow area here

although solving the problem will require you to find the volume of the grey area

and subtracting that from the total volume of the cylinder

[alpine sable]

would it look something similar to that?

[gray ingot]

this will give you the area for the yellow region yeah

[gray ingot]

although calculating the volume of the this grey region would be easier

[gray ingot]

.

[gray ingot]

the thing is calculating the area of the yellow region wouldn't be useful in this case

what you need is this red volume so first you should find the volume of the cylinder then subtract the volume of the part that's empty

and for that you can use the washer method

[gray ingot]

Yes exactly

you know the washer method right?

[alpine sable]

so like that right?

[gray ingot]

it'll be in terms of dy

and functions will in terms of y

wait my bad

it should be 64 not 8 in the diagram

[alpine sable]

so 0 to 64

[gray ingot]

yes

$\int_0^{64} \pi x^2 dy$

i forgot latex 💀

[ocean seal]

Swas.py

[gray ingot]

this is because pi r^2 h is the volume of that small yellow cylinder and r = x and h = dy in this case

[alpine sable]

ohhhh i was taking it in terms of x

i see

We started this topic a few days ago

[gray ingot]

yeah you need to think in terms of y here

[alpine sable]

I am still pretty bad at it

[gray ingot]

no problem you'll get better with practice

[alpine sable]

i went from regular integrals to weird things lol

so if i were to solve it i would get 64(pi)x^2

[gray ingot]

imo application of intergrals are more fun to solve than abstract indefinite integrals with no context 💀

[alpine sable]

around 201.06193

[gray ingot]

hmm integral of ydy would be y^2/2 wouldn't it?

y=x^2

after finding the volume don't forget to subtract it from the original volume of the cylinder

[alpine sable]

so the set up would look similar to that?

[gray ingot]

y was equal to x^2 so the integral would become ydy

and not y^2dy

you can't just replace y and x, they mean different things here 💀

[alpine sable]

ik, call it a hopeful attempt to get this question right

🥹

so ok ok let me see if i understood

so write again integral from 0 to 64

x^2 becomes ydy

so can i move pi to the left out of the integral

anf have like ydy by itself?

[gray ingot]

yes

$\pi \int_0^{64} y dy$

[ocean seal]

Swas.py

[alpine sable]

like that

ohhhhhh

siii

and then solve for that

[gray ingot]

yep that gives you the volume of the empty region and subtracting that from the volume of the cylinder will give you the required volume

you can watch this video on the washer method for a better understanding of it https://youtu.be/SAHSVg7Jw_A

[alpine sable]

ok

i will give it a try

[gray ingot]

I gotta go good luck

[alpine sable]

thank you so much

i will marry discord 😭

[lone heart]

@alpine sable Has your question been resolved?

Channel closed

Closed by @spiral sphinx

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[coral flower]

hi , can someone help me understand row echolean form of matrices

[vale wigeon]

what do you wish to understand about it?

what it is, how to get there, or its purpose?

[coral flower]

how to get there

how to convert a matrix to row echolean form

@vale wigeon

[vale wigeon]

right, sorry for the delay on my end

[coral flower]

np

[vale wigeon]

have you been taught row operations? and row reduction?

[coral flower]

no but i only understood a little bit of it

[vale wigeon]

did you at least understand what said operations are?

[coral flower]

yes

[vale wigeon]

with poor presentation, "here are the things you can do" and "here's how to use them for such and such" can be conflated

the goal of row reduction is to "zero out" as many columns as you can, starting from the left.

zeroing out a column means making it so that column has 0's in all positions except one.

columns are zeroed out by means of row-addition operations.

[coral flower]

ok

but the book says that
0 0 1 2
0 1 3 -1
0 0 0 0
is not in echelon

[vale wigeon]

echelon*

[coral flower]

why? we have zeroed most of the things that can be

[vale wigeon]

yeah, you need to swap the first two rows

[coral flower]

why?

[vale wigeon]

for a matrix to be in row echelon form, the leading entries in every row have to be to the right of the leading entries in prior rows.

(leading entry = leftmost nonzero entry)

you might hear leading entries be called pivots too

[coral flower]

so
0 1 3 -1
0 0 1 2
0 0 0 0
is in echelon form?

[vale wigeon]

yes

[coral flower]

and how can u use it to find inverses?

[vale wigeon]

"it"?

[coral flower]

echelon

[vale wigeon]

...

echelon form is the result of some action, not the action itself

anyway

[coral flower]

ok i dont understand , why do we find the echelon?

[vale wigeon]

to answer your question about how to use row-reduction to find the inverse of a matrix, you can do it like this:

take your n by n matrix (i'll call it A). attach to it, from the right, an identity matrix of the same size to get an n by 2n matrix

row reduce the resulting "double matrix".

if A has an inverse and you did everything correctly, the left half will become the identity matrix, and then the right half will be A^-1.

[coral flower]

ok so make the original matrix into a identity matrix and the identity matrix we used before would be the inverse?

[vale wigeon]

you could say that

[coral flower]

ok i am understanding something

taking the first as an example

we could add row 1 with r2 and get and divide row 2 with r3
1 0 -3
0 1 0
-2 -2 2

but then how do we get rid of the -3?

@vale wigeon (sorry for pinging)

[tribal oxide]

Try to make the element in row 3 and column 1 0

Like row 3---> r3 +2 r1?

[tribal oxide]

Continuing from here btw

The focus on making element with row 3 and column 2 0

[coral flower]

so that would become
1 0 -3
0 1 0
0 -2 -4

maybe r3 + 2 r2

1 0 -3
0 1 0
0 0 -4

[tribal oxide]

Yea

[coral flower]

but how do we remove the 3 and 4?

[tribal oxide]

🤔

[coral flower]

we could divide r3 with -4 but what about r1

[tribal oxide]

wait divide r3 with -4 straight up is allowed?

If it is then -3 removed easily

[coral flower]

i think so

we are dividing the whole row with -4

[tribal oxide]

Because then you can do r1---> r1+3r3

[vale wigeon]

augh sorry i had to disappear

[coral flower]

np

[coral flower]

i think that solves it

[tribal oxide]

Im not sure abt this tho

[coral flower]

cant we write it as
R3 - 1/4R3

[tribal oxide]

Ah yes

[coral flower]

yea ty for help

so i just write ".close" now?

.close

[lone heart]

Channel closed

Closed by @coral flower

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

If after reducing the matrix I'm getting
0 0 0 1 in the last row

Will I say column 4 is the pivot column? Or no cause last column is the solution
Please help

[wild trail]

Show the complete question

@alpine sable

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

Find the pivot col

1 0 -9 0 4
0 1 3 0 -1
0 0 0 1 -7
0 0 0 0 1

[wild trail]

You mean columns? Cause there are multiple pivots

[alpine sable]

Yes we need to identify pivot columns

[wild trail]

That's easy, where you stuck

Do you know what a pivot is?

[alpine sable]

Column 1, 2 and 3 are pivot columns

Yes I do

But

Last column is the solution

[wild trail]

That's wrong

[alpine sable]

Should I say it us a pivot column or not?

Sorry

1,2, 4

Will column 5 be a pivot column?

[wild trail]

Let's make sure we are on the same page. A pivot column is a column which contains the pivot right?

[alpine sable]

Yep

[wild trail]

Then it's pretty evident that only 3rd column is not pivot

Rest all columns are pivot columns

[alpine sable]

Oh so last column will be considered as the pivot column

I thought we don't include the solution column

[wild trail]

Yeaah, it clear has a pivot

[alpine sable]

Yeah but isn't it the solution

For augmented matrix

[wild trail]

What's the solution then?

Bruh, you never mentioned that this is an augmented matrix

[alpine sable]

It is :((

Sorry my bad

It is like

0x+0y+0z+0s=1

Okay, so if it is augmented then last column won't be a pivot column otherwise it will be right?

[wild trail]

Hmm, then you need to clarify if you want pivots of the original matrix or the augmented matrix

Lemme put this in a bit of context

If the rank aka the number of pivots of the original matrix and the augmented matrix are same then the system of equations are consistent

[wild trail]

So, you need to think about this

[alpine sable]

Um, i dont think we need to determine consistency for this question

Just need to tell the pivot columns of the augmented matrix

[wild trail]

This pivot thing actually leads to consistently and you can talk about solution space