My brain doesn’t comprehend these kinda things
#help-0
high phoenix
south mountain
So you have the triangle
high phoenix
Yeah
high phoenix
Yeah the tic marks on 10 then I subtracted 10 for 38 and got 28
south mountain
So 35 is the hypotenuse and 28 is one of the sides
Just apply Pythagoras
So a² + 28² = 35²
a² + 784 = 1225
a² = 441
So a= 21
high phoenix
One of these right?
south mountain
Yes
That's how i got the 21
And since the part of the triangle is 21
The part below it will be 26-21
Which is 5
south mountain
Ok
high phoenix
Sorry I have my geometry final Tmmr
south mountain
That's fine
high phoenix
I need to understand this more
south mountain
Alright give me a minute
high phoenix
#2
ocean sealBOT
south mountain
Number 2 as in the 6th question?
high phoenix
Yeah
south mountain
Oh ok
So the diagonal of a square is √2 times the side
Assume the side to be x
Diagonal = √2 x
8= √2 x
x= 8/√2
Oh wait you need it as a 45 45 90 triangle
high phoenix
Yep
south mountain
This would be the figure
So the 8 inch side is basically the hypotenuse of both the triangles
Now in a 45 45 90 triangle
high phoenix
Mhm
south mountain
Sides opposite to 45 are 1/√2 times the hypotenuse
So your sides would be 8 times 1/√2
Which when simplified will be 4√2
Now for the perimeter you just multiply the side by 4
And for the area you'll square the side
Thats it
south mountain
Yea?
south mountain
What part are you confused on
high phoenix
On of you got 1/ square root of 2
south mountain
That is a property of 45 45 90 triangles
high phoenix
Lemme check my note book
south mountain
Sides which are opposite to 45 are 1/√2 times the hypotenuse
high phoenix
south mountain
Which in this case is 8
Its there at the very right corner
Of the page, in the triangle
south mountain
In high school yes
south mountain
I see
high phoenix
Lol
south mountain
Did you understand it now though?
south mountain
Ah alright
high phoenix
Lol
high phoenix
Yes please that would be great
bleak osprey
brandon you alright?
high phoenix
I’m not
bleak osprey
what's wrong
high phoenix
I’m dumb
south mountain
Yea exactly
bleak osprey
sahad got it?
high phoenix
Yeah he’s helping me
south mountain
Just DM me directly if you need any help Brandon
high phoenix
I don’t know if you’re supposed to solve square roots
My teacher never specified 🤔
south mountain
No, in this question you're not supposed to
Let them be roots
Plus there will be no roots in the area
high phoenix
Oh ok
It’s totally fine if you say no you’ve helped me so much and I appreciate it but
There’s another
bleak osprey
u need to state units squared u can't just put a number
high phoenix
south mountain
Sorry Brandon I've got to go eat rn
high phoenix
Ok that’s fine have a good one
high phoenix
Ty
high phoenix
in ur answer u need u^2
Wym ?
bleak osprey
Wym ?
write down
1.4 units squared
but u just put the little 2 above the letter u
uk what i mean
bleak osprey
noo
just do a little u
1.4u2
but put the 2 like a squared
rememeber u represents a unit
like a foot
wait
no
i think that question has feet
so u do feet squared
high phoenix
Buts it’s a 45 45 90 triangle
I thought I was doing good until we started doing this
Tan cos and sin was so much easier
naive flare
Tan cos and sin was so much easier
do you mean sin?
lone heartBOT
@high phoenix Has your question been resolved?
haughty valve
lone heartBOT
haughty valve
How do i make
2sin(theta)cos(theta) in terms of a
wind cloak
$\tan \theta = \frac{a}{2}$
ocean sealBOT
NEONPerseus
wind cloak
Draw a triangle and figure everything out
wind cloak
I meant draw a right triangle with legs of length a and 2
haughty valve
Oh
wind cloak
Then you can find the hypotenuse and find the values of sine and cosine
Using the Pythagorean theorem
south mountain
There's a direct formula for sin2x in terms of tanx
There are two half angle formulas for sin and one of them has tab with half the angle in it
Sin2x = (2tanx)/1+ tan²x
Try this @haughty valve
lone heartBOT
@haughty valve Has your question been resolved?
lone heartBOT
lone heartBOT
Available help channel!
light ravine
wild trail
.close
queen raven
lone heartBOT
queen raven
How can I prove this expression?
viral pagoda
What have u tried
queen raven
Well, I've tried just using brute force with algebra
didn't seem to work
I tried squaring both sides of the expression
viral pagoda
Tried sin-cos format?
queen raven
but that just seemed to make it more complicated
viral pagoda
Multiplying numerator and denominator?
queen raven
Multiplying numerator and denominator?
multiplying the numerator and denominator?
viral pagoda
Sec2-tan2=1
queen raven
Sec2-tan2=1
yes but does that apply here?
viral pagoda
1/x= sec+tan
queen raven
you cant square individual terms?
viral pagoda
It's an identity
viral pagoda
Tan squared + 1 = sec sq
queen raven
its not sec^2 - tan^2
viral pagoda
a^2-b^2= (a+b) (a-b)
This is a general algebraic formula
viral pagoda
1/x= sec+tan
This makes sense ryt
queen raven
sorry, could you explain how that would work in this scenario?
viral pagoda
This makes sense ryt
Y/n
viral pagoda
Things cancel
queen raven
how does 1/x = sec + tan
viral pagoda
Sec2-tan2=1
.
queen raven
im sorry if im being an idiot but i dont see how that relates to 1/x
since its not squared?
viral pagoda
What does not make sense here
queen raven
thank you, that makes a lot of sense now
viral pagoda
@queen raven u can also start with 2 sec theta and end up with x+1/x
queen raven
i guess my mistake was working backwards
viral pagoda
<@385705507597451264> u can also start with 2 sec theta and end up with x+1/x
Working backwards....2sec(theta) =sec - tan + sec + tan
queen raven
anyways, thank you
viral pagoda
👍
queen raven
is there anything i can do to pick up on these kinda of things better?
i always seem to miss such simple things
viral pagoda
is there anything i can do to pick up on these kinda of things better?
Practice... Start with what youre asked to prove
queen raven
everything looks easy in hindsight but i just miss these things
viral pagoda
where do you find resources?
Try exemplar
viral pagoda
Ncert exemplar trigonometry
viral pagoda
Ncert exemplar trigonometry
Try this resource @queen raven
queen raven
is this the correct pdf?
is this all there is or are there other chapters to cover that would help as well? @viral pagoda
viral pagoda
https://ncert.nic.in/pdf/publication/exemplarproblem/classX/mathematics/jeep208....
Ye ig
I did it 2 yrs ago
queen raven
okay, thanks a lot for your help
viral pagoda
is this all there is or are there other chapters to cover that would help as wel...
Prerequisites?
queen raven
i understand all the concepts in here, i guess i just have to solidify them with practice like you said
onyx shell
lone heartBOT
onyx shell
this is the conditions I look at for this questions
viral pagoda
Yea all three 4
onyx shell
so f(a) = 4
viral pagoda
Yup
onyx shell
therefore, f is continuous at x = 1
alpine sable
I am stuck on part a, i just don't understand. the total distance i put down as (u+v)t, and total time taken d(u+v) and it just kinda making me confused
oak chasm
That's not correct because the times aren't the same. Both segments are the same distance and so, when you go faster, it takes less time.
You want total distance traveled over total time taken.
Total distance traveled is pretty easy to get.
What would that be?
alpine sable
u+v?
oak chasm
No.
Distance is in km.
But u and v are km/h, and adding them will also be km/h, so that can't be it.
Read the introductory sentences.
What distance does it talk about?
alpine sable
2d would be total distance
oak chasm
"Xiu travels from town A to town B at u km/h and then returns at v km/h. Town A is d km from town B."
Right.
So, now we know the numerator.
How long does it take to go from A to B?
alpine sable
d/u
oak chasm
What about B to A?
alpine sable
d/v
oak chasm
OK, so what's the total time taken?
alpine sable
2d/u+v
alpine sable
d/u
oak chasm
What time does it take for the second part?
alpine sable
d/v
oak chasm
What time does it take for both parts?
alpine sable
d^2/uv
oak chasm
No.
Why are you multiplying two times together to get a time?
What will the units be if you do that?
oak chasm
Yes, but remember to put parentheses around numerators or denominators that aren't single variables or single numbers.
Otherwise, it's hard to tell what's in the numerator and denominator and so forth.
OK, so we have 2d as the total distance and (du + dv)/(uv) as the total time.
ocean sealBOT
Chai T. Rex
oak chasm
Now simplify that.
oak chasm
Right.
oak chasm
No problem.
oak chasm
No, this stuff isn't the easiest to think about it when you're new to it.
oak chasm
You're welcome. You too.
alpine sable
.close
viral pagoda
lone heartBOT
viral pagoda
Don't just tell answer
Give me hints
Help me to gain something which will help me solve other such problems
#mathematicalmetacognition
lone heartBOT
@viral pagoda Has your question been resolved?
lone heartBOT
@viral pagoda Has your question been resolved?
viral pagoda
<@&286206848099549185>
lone heartBOT
@viral pagoda Has your question been resolved?
ember dagger
Don’t understand
lone heartBOT
Don’t understand
crimson totem
Don’t understand
which step?
crimson totem
How did 32 and 40 go in a ratio
ig its coming from the parent problem?
south mountain
I'm saying that the final step is incorrect
It should've been multiplied, but got divided?
south mountain
What are you solving for
crimson totem
This is the pathagoream theorem
show the problem
ember dagger
CAH
ember dagger
south mountain
Yep it is
ember dagger
I was looking through my notes from last year
I tried to create my own notes cus my teacher didn’t give us anything
south mountain
So you wanted the cos of that angle but one of your sides was missing so you applied the Pythagoras theorem to find the missing side
You got the adjacent
ember dagger
Yes
south mountain
And basic formula for cos is adjacent over hypotenuse
So that would give you 32/40 which is 4/5
crimson totem
or you could use $sin^2(x)+cos^2(x) = 1$ to do it even faster
ocean sealBOT
Shockshwat
south mountain
Yep, but do whatever feels easier
crimson totem
meh same thing anyways
south mountain
You should delete these from here and post them in one of the help channels
versed lava
which channel?;0
lone heartBOT
@ember dagger Has your question been resolved?
storm oar
lone heartBOT
storm oar
am i stupid or is the first one wrong?
shouldnt it be sin20? not -sin20?
oh
wait
is it like, i find out how much i need to get to the x axis?
so i either add an amount or take away an amount?
i'm trying to figure it out myself bcus the slides don't explain anything
vocal hawk
so i either add an amount or take away an amount?
what do you mean by this?
storm oar
so like for 200 degrees i need to get to 180
so i minus 20
for the 2nd one i want to get to 180 again
so i add 30
rare gale
should be sin -160 i think
storm oar
ie get to the closest 180 whether that's 180 or 0/360
rare gale
every +/- 360 is an equivalent angle, so 200-360 = -160
storm oar
it asks for an acute angle
vocal hawk
every +/- 360 is an equivalent angle, so 200-360 = -160
it says acute angle
rare gale
oh, sorry, i see
rare gale
yeah it would be -20 then because thats where the sin will be negative
storm oar
because the closest 180 is 0/360
vocal hawk
the sign depends on the function
so sin(340) = -sin(20)
but cos(340) = cos(20)
do you understand why?
rare gale
so sin(340) = -sin(20)
i'd present this at sin(-20) though
its true that you can pull the - out in the case of sin but just to be clear to someone learning that you are starting out at angle -20
vocal hawk
i'd present this at sin(-20) though
sin(-20) = -sin(20), it asks for acute angle, means 0-90
storm oar
you've both 100% lost me lol
vocal hawk
ok
you are right in a sense that you get the closes angle that is less than 90 from 180 or 360
rare gale
sin(-20) is looking at an acute angle
vocal hawk
for example if you are calculating a sin or cos of 340
it will have the value of 20
but the sign is dependent on the function itself,
rare gale
measures of angles aren't negative, the convention is just that youre moving clockwise from the x axis if there's a negative sign, but it's still a 20 degree acute angle
storm oar
measures of angles aren't negative, the convention is just that youre moving clo...
but then that would mean the answer for the 1st one is wrong, right?
if it's measuring from the x axis it should be sin20, not -sin20
vocal hawk
measures of angles aren't negative, the convention is just that youre moving clo...
moving clockwise from the x axis
this is the definition of a negative angle
storm oar
but the sign is dependent on the function itself,
wdym by this btw
vocal hawk
wdym by this btw
so, are you familiar with the notion that cos is related to x axis and sin is related to y axis?
vocal hawk
yes
I guess that you were introduced to sin and cos with right triangles, but this only works for angles between 0-90, we want to extend the definition of sin and cos to include the whole 360 degrees
the extension is made with the unit circle that you see
vocal hawk
this pretty much explains it, tell me what you don't understand with this?
storm oar
ok nvm i get it
so, it corresponds to the sign b4 the trig ratio depending on the quadrant
so i find what sign it is
what quadrant it is
that gives me if it's +ve or -ve
wham bam
vocal hawk
yes
storm oar
ok :] tyvm
vocal hawk
so left is negative and right is positive, cos is related to x, left is negative cos and right is positive cos
top is positive and bottom is negative, sin is related to y, to top is positive sin and bottom is negative sin
storm oar
vocal hawk
if you check the angle 200, you will find that its in the 3rd quadrant, bottom left
tulip violet
am i stupid or is the first one wrong?
Sin(180+20)
storm oar
maybe the slides do explain it well lol
vocal hawk
because we are taking the sin, it either top or bottom, bottom is negative, so its negative 20
storm oar
got it
tulip violet
@storm oar have you learnt about the signs of the trigonometric ratios in the 4 quadrants
storm oar
yeah i'm teaching myself it rn
ig i'm done tbh
that was the last bit i was confused on
rare root
Minor question. Does a relation like:
y = a / (x)^0.5
In which a is some constant.
Have a name ?
nimble fern
y is inversely proportional to the square root of x
lone heartBOT
@rare root Has your question been resolved?
long heath
lone heartBOT
ruby shoal
for matrix A is true A^3 = -5*I_n^2 . Does A have eigenvalue of 0? Show it
lone heartBOT
for matrix A is true A^3 = -5*I_n^2 . Does A have eigenvalue of 0? Show it
@ruby shoal Has your question been resolved?
mortal trellis
from this information you can find a multiple of the minimal polynomial of A
then remember what you know about minimal polynomials and eigenvalues
lone heartBOT
@ruby shoal Has your question been resolved?
tawdry saffron
lone heartBOT
tawdry saffron
differential equation
what dummy function would you take?
I'm thinking axe^(x/2) + b?
@ me when answering
lone heartBOT
@tawdry saffron Has your question been resolved?
drifting schooner
I'm thinking axe^(x/2) + b?
yeah that's what I'd try
tawdry saffron
Aight
stoic terrace
Can someone help me with this?
lone heartBOT
Can someone help me with this?
stoic terrace
incomplete question?
prime badge
puts it back or keeps it separate
stoic terrace
what do they mean by "keeps it back"
Oh that means that the card which was picked was kept back (replaced)
prime badge
how do you know
stoic terrace
cuz this language is used commonly in this book
prime badge
fair enough
stoic terrace
I think I should use Baye's theorem right?
prime badge
i doubt it requires bayes theorem
it looks normal
i don't know let someone else help
the answer is the average of 1/10 , 3/10, 5/10 ,7/10 and 9/10, so A
slow hound
is this not a symmetry problem?
stoic terrace
Ok turns out, there's no way to know the answer since they didn't provide the answer key. Thanks though
stoic terrace
is this not a symmetry problem?
umm probability
prime badge
i don't see how it's immediately 1/2 by symmetry
prime badge
that doesn't make sense
slow hound
oh whoops i didnt see the even condition
prime badge
the even condition doesn't matter
slow hound
i never said it was 1/2
stoic terrace
Its 1/4 got it
prime badge
okay
raven blaze
lone heartBOT
lone heartBOT
lone heartBOT
Available help channel!
steady spoke
lone heartBOT
steady spoke
@crisp iron
steady spoke
1/2*b*c*sinA
THANK you so mch
got one more!
i still have questions?
@sharp bloom are you here?
am i right with B?
nimble fern
should be correct
lone heartBOT
@steady spoke Has your question been resolved?
steady spoke
should be correct
you sure
nimble fern
i just used calculator to check, not sure though, you may ask for others to check too if you want
lone heartBOT
@steady spoke Has your question been resolved?
torpid jolt
I need help
cosmic nexus
I need help
lone heartBOT
I need help
cosmic nexus
What is 54 as a percentage of 216
rocky grove
lone heartBOT
lone heartBOT
Available help channel!
feral juniper
When you're taking the derivative of some matrix product that will end up becoming a vector, how do you know if it will become a row or column vector?
feral juniper
e.g. here, how did they know it would be a column vector from the first step after "Then,"?
Is it just convention?
royal crescent
How to do this?
lone heartBOT
How to do this?
last ether
I don't think that's elementary
royal crescent
integral by parts?
royal crescent
So we cant do that
last ether
You can't really do anything if you haven't done nonelementary integrals
lone heartBOT
Available help channel!
rigid flicker
I know that the answer to this is x/(4+x)is bigger of equals 0
But could anyone explain how we get ti this so I could get a deeper understanding on the subject?
rigid flicker
Do you know why we get the mark at 0 in thr X line?
Because it’s isn’t a nullpoint is it (sorry if that’s not a word in english)
If x were zero it would just be 4
rigid flicker
Yeah that would be 4 I believe.
keen mason
Hmm
plug it into a calculator and check
remember 0/x is just 0 * x^(-1)
and anything times by 0
is 0
rigid flicker
If x were zero it would just be 4
Okay no it would just be dividing 0/4 which ends uo being a fourth of nothing so ye im just goofy
Cheers for the help though!
!close
?close
Irbeidbsjsbdjdbd
This is tragic
.close
fast shell
lone heartBOT
serene junco
That looks right so far
How did you get 136?
oh wait
Yeah I get 136 as well
The question does not specify whether we're talking about cross sections perpendicular to the x-axis or y-axis.
Which is a problem, it definitely needs to.
fast shell
i'll just e-mail my professor i guess
fallen verge
its not y=x
fast shell
its not y=x
then what is it ?
fallen verge
try it
fallen verge
consider what points the line has to go through
lone heartBOT
@fast shell Has your question been resolved?
fast shell
Wdym
fast shell
Look at your graph. The line goes thru (0,0) and (3,5)
(4,5)
lone heartBOT
@fast shell Has your question been resolved?
lone heartBOT
@fast shell Has your question been resolved?
lone heartBOT
@fast shell Has your question been resolved?
zinc dagger
(4,5)
The slope of the line is not 1. The function there is not y=1*x. The slope is 5/3. Function: y=5/3 * x
fast shell
The slope of the line is not 1. The function there is not y=1*x. The slope is 5/...
Oooo
Tysm
zinc dagger
Np bro
tacit arch
!help
lone heartBOT
Please read #❓how-to-get-help
radiant orchid
Y=-1
6y-29=-35
+29 on both sides to maintain equality
6y=-6
Divide by 6
Y=-1
crimson totem
you did not
lone heartBOT
@fast shell Has your question been resolved?
gusty gorge
might as well use an alternate solution method if you're just going to give the answer
,w solve 6y-29 = -35
ocean sealBOT
astral briar
(An arithmetic sequence in which all terms are positive and have the same common difference as the first term)
Why is an = na1
worn fox
What's a_2?
astral briar
what
median oar
$a_1 = a_1\
a_2 = ?$
ocean sealBOT
Frosst
astral briar
why do you want to know that
i think you can get that from the problem
but they are asking for a_4
astral briar
ok
median oar
What do we know about arithmetic sequences
astral briar
a_n = a_1 + (n-1)d
median oar
Try let d = a_1
astral briar
a_n= a_1 + (n-1)a_1
median oar
Now factorise a_1
astral briar
na_1=a_n
median oar
So that statement is only true with d = a_1
median oar
(An arithmetic sequence in which all terms are positive and have the same common...
.
It’s not always true
astral briar
(An arithmetic sequence in which all terms are positive and have the same common difference as the first term)
median oar
But when d = a_1
Then it is
Oh wait
It says it in the statement
(An arithmetic sequence in which all terms are positive and have the same common difference as the first term)
This part reads as d = a_1
astral briar
as the first term
which means the first term has a common difference similar to the others?
unborn osprey
a third power of the number is 8 times smaller than its square. What is the number?
amber hollow
lone heartBOT
amber hollow
i^3/n^4 = 1/n * (i/n)^3
what do u do from there
vale wigeon
you write the limit of this sum as the integral from 0 to 1 of x^3 dx.
amber hollow
how do u know it's from 0-1
vale wigeon
as i goes from 1 to n, i/n ranges from 1/n (close to 0) to n/n (=1)
lone heartBOT
https://i.gyazo.com/1da53064d6ed8ffe914ad019823def50.png
warped topaz
the writing on the right is the solution for 17, but im confused about something
Im confused about the ∀x(tall(x) ^ tree(x)) part, I thought anytime theres a ∀x() you need to use a -> instead of ^, otherwise you would be saying 'Everything is tall and everything is a tree'
so how come its not ∀x(tall(x) -> tree(x))
pliant cedar
x can be anything, if anything is both a tree and tall then ben is fond of it
pliant cedar
so how come its not ∀x(tall(x) -> tree(x))
this is saying anything tall is also a tree
wary stream
so how come its not ∀x(tall(x) -> tree(x))
If you recall -> basically means implication. With this statement, you're saying "if it's tall then it's a tree" or something along those lines. So you need to say that it has to be a tree and tall
pliant cedar
If you recall -> basically means implication. With this statement, you're saying...
-> means implies and <-> means if and only if right?
pliant cedar
Im confused about the ∀x(tall(x) ^ tree(x)) part, I thought anytime theres a ∀x(...
to say eveything is tall and everything is a tree, u wud write forall x, tree(x) ^ tall(x)
warped topaz
Ok I think I get, one more thing though is it also possible to say ∀x((FondOf(Ben,x) -> (tall(x) ^ tree(x))) ?
Cause then its like saying if ben is fond of x, then x is a tall tree
which makes sense in natural english I think
pliant cedar
this is saying that anything ben is fond of, is both a tree and is tall
warped topaz
ah yeah
pliant cedar
so ben cant be fond of anything that is not a tree or not tall
warped topaz
yeye makes sense
Ok I think I understand everything now
thx you explained it very well!!
.close
tacit comet
Hi, if I have the following two lists
y_true = [1,1,2,2,3,3]
y_pred = [2,2,1,1,1,1]
how can I calculate the rand index by hand? I know that total DP = 15 but can not seem to figure out how to decide on a+b
lone heartBOT
Hi, if I have the following two lists
y_true = [1,1,2,2,3,3]
y_pred = [2,2,1,1,1...
@tacit comet Has your question been resolved?
short rapids
hello,
Can someone explain why this happens?
20cot(20)sin(θ)
wind cloak
$\frac{\cos \theta}{\sin \theta} = \cot \theta$
ocean sealBOT
NEONPerseus
short rapids
so cos/sin=cot?
short rapids
I constructed that with the capital letters
wind cloak
I see 
short rapids
can you express other variations of this
wind cloak
Wdym
short rapids
sin/cos=???
wind cloak
Tan
short rapids
cot is cotangent correct?
wind cloak
Yup
short rapids
whats the inverse of cos?
wind cloak
Secant
short rapids
how is that calculated?
gray isle
whats the inverse
depends on which inverse
short rapids
im trying to cover all variants of the sin cos tan combinations to get a clear note
wind cloak
Hmm
gray isle
the multiplicative inverse would be secant
the function inverse for a certain domain would be arccos
short rapids
cos/sin=
tan/sin
tan/cos
wind cloak
Well write tan in terms of sin and cos and you can figure that out for yourself
gray isle
im trying to cover all variants of the sin cos tan combinations to get a clear note
cos/sin=tan/sin
tan/cos
don't bother
knowing the basic definitions,
you can determine them all as needed when they come up
no point putting countless combos to memory
dusky notch
Hey all, I'm having a bit of trouble remembering back to partial differentiation. How would I go about this problem? Thanks.
dusky notch
keen mason
treat the other variables as constants
minor needle
treat P and R as constants (you can take them out) and you'll stay with the derivative of 1/T
- P/R
dusky notch
ohh so it just ends up being (P/R) * ln(T)
oh wait thats an integral oop
-(P/R) / (T^2) Do we just plug back in the constants after?
I think I was just overthinking this
keen mason
-(P/R) / (T^2) Do we just plug back in the constants after?
thats looks fine
minor needle
-(P/R) / (T^2) Do we just plug back in the constants after?
nope, that's the final result
dusky notch
gotcha, thank you guys!
last sage
How should one calculate this limit:
lone heartBOT
How should one calculate this limit:
pliant cedar
$a^b = e^{b\ln a}$
ocean sealBOT
SilverSoldier
pliant cedar
if thats what u r looking for
ocean sealBOT
C-H-I-T-A-N
last sage
I was not sure if I could use it when the equation is raised to a power
minor needle
but
you have limit of e^( . )
since e^x is continuous on entire real line
you can take the limit of the exponent only
last sage
The product of two limits is a limit, but I'm not sure about the [word for to the power] of two limits
ocean sealBOT
Modus
minor needle
then do e^(your result) and that's it
last sage
Thank you
lone heartBOT
@last sage Has your question been resolved?
last sage
I did get an answer this way
Seems like a good thing, but according to the graph 3 is an asymptote, so I guess the limit should not exist
$\lim_{x\rightarrow3}e^\frac{x+2}{x^2-6x+9} * \lim_{x\rightarrow3}e^{ln(x^2-6x+10)}$
ocean sealBOT
C-H-I-T-A-N
last sage
the right side is just 1
The left side evaluates to 0 in the exponential so it will be also 1 because e^0?
Nevermind
.close
royal quail
lone heartBOT
alpine sable
Sorry - open this or use another channel
lone heartBOT
Available help channel!
verbal venture
Hello Guys!
Why exactly is the harmonic-series divergent if it gets closer to 0?
ruby current
Hello Guys!
Why exactly is the harmonic-series divergent if it gets closer to 0?
use the integral test
alpine sable
$1+\frac12+\frac13+\frac14+\frac15+\frac16+\frac17+\frac18+\frac19+...$
ocean sealBOT
rbit ✨
alpine sable
now we use 1/3 > 1/4 and
1/5, 1/6, 1/7 > 1/8 and
1/9, ... > 1/16 ...
$> 1+\frac12+\frac14+\frac14+\frac18+\frac18+\frac18+\frac18+\frac1{16}+...$
ocean sealBOT
rbit ✨
alpine sable
now if we pair up the summands with the same denominator, we have 2*(1/4), 4*(1/8), 8*(1/16), ...
can you see where this is going?
verbal venture
One second
I dont really get it
I mean the theory yes, but not the general concept.
surreal meadow
rbit is saying that the harmonic series is larger than the other series they described
notice that if you join all of the 1/4 terms, you get 1/2. if you join all of the 1/8 terms you also get 1/2
and so on
so $\sum_{n=1}^\infty \frac{1}{n} > 1 + \frac{1}{2 }+ \frac{1}{2} + \dots$
ocean sealBOT
maximo
lone heartBOT
@verbal venture Has your question been resolved?
tacit arch
I mean the theory yes, but not the general concept.
what "general concept" are you talking about
it's just that there are some series that have terms that converge to zero, but the sum diverges.
verbal venture
Ah I think thats the confusion.
Because when I look at exercises and calculations for 1/n it goes to 0
tacit arch
just read/work out more examples
verbal venture
Appreciate the help everybody, I think I just need to work with it a bit more to get used to it.
.solved
simple mulch
lone heartBOT
alpine sable
simple mulch
room taken bro
alpine sable
beat me to it
alpine sable
undefined
flint pecan
therefore 140=5.5 x 11 +b
simple mulch
so i punch that in
ohhhh
yes yes i see that now
ok thats much easier thank u
.close
final badge
Did i get number 5 correct?
lone heartBOT
Did i get number 5 correct?
tacit arch
what are you even supposed to calculate
final badge
Probability
tacit arch
are you supposed to round?
final badge
are you supposed to round?
Yes
tacit arch
looks right
final badge
Thz
tribal oxide
What about number 3?
5/7 looks correct
lone heartBOT
lone heartBOT
Available help channel!
tardy tide
Inned help with geometry
lone heartBOT
Inned help with geometry
tacit arch
Inned help with geometry
lone heartBOT
@tardy tide Has your question been resolved?
swift halo
lone heartBOT
delicate jacinth
you mean derivative?
swift halo
Yes
delicate jacinth
!status
lone heartBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
Im just not sure where to begin
Is it correct if I find the derivative of the thing in root and then find the derivative of the logarithm and then just add them?
delicate jacinth
$\left(\dfrac{f(x)}{g(x)}\right)' = \dfrac{f'(x)g(x) - f(x)g'(x)}{g^2(x)}$
ocean sealBOT
sopinha
delicate jacinth
,w (sqrt(9-x^2) +ln ((x+1)/(x-2)) )'
ocean sealBOT
delicate jacinth
yeah, it is
scarlet shell
Hi, could u pls help explain me what do we mean by distance between first two zeros of the cardinal sinus
scarlet shell
tacit arch
Hi, could u pls help explain me what do we mean by distance between first two ze...
can you screenshot/take a picture of the question
or the text that you're quoting
scarlet shell
It's actually the text from physics
But I dont know about sinc
What does it mean zeros of sinc max and min points?
tacit arch
,w plot sin(x)/x for -3pi to 3pi
ocean sealBOT
tacit arch
What does it mean zeros of sinc max and min points?
take a picture/screenshot
scarlet shell
lone heartBOT
@scarlet shell Has your question been resolved?
lone heartBOT
@scarlet shell Has your question been resolved?
orchid perch
what does a path in a probability tree represent