#help-0

1 messages · Page 132 of 1

trail cairn
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what do i do

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you guys are writing things everywhere

alpine sable
trail cairn
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Amy and Ben live 17.2 km apart. They cycle to meet each other. Ben travels at
12 km/h and Amy travels at 10 km/h.
a How long (in minutes) until they meet each other?
b What distance have they both travelled?

gray isle
#

setting up your equation and fixing units
you had
12x+10x=17.2 (where x represents the time in hours)

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do you have any issue with that so far?

trail cairn
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nope

gray isle
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then continue solving

trail cairn
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i dont know what to do

gray isle
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can you simplify the 10x + 12x

trail cairn
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22x

stoic ledge
#

And that is equal to? 17.2 right?

trail cairn
stoic ledge
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22x = 17.2 right?

trail cairn
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idk

#

.close

lone heartBOT
#
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kind forum
#

can anyone help with this??

lone heartBOT
kind forum
#

hello?? someone is typing??

graceful sluice
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Hello guys, I need to prove whether this group is maximally consistent or just consistent,
I would be happy to help which organs fall into the above group

kind forum
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ummm what??

graceful sluice
pseudo ice
vale wigeon
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@kind forum so you are looking at the problem and its solution but there is something in the solution which you do not understand, is that so?

kind forum
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yes

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the soultion is confusing

slow vine
kind forum
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i dont really get what variables they re using and how 4x and 3x came

vale wigeon
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Let the perimeter and breadth of the rectangle be 7x and 2x, respectively.

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do you understand this line?

kind forum
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yes

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srry i was afk

vale wigeon
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Perimeter of the rectangle = 2(length+breadth)

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and this line?

kind forum
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yes

vale wigeon
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7x = 2(length + 2x)
and this line?

kind forum
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whats the bracket mean

vale wigeon
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?? why didn't you ask the same about the previous line?

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the parentheses are parentheses, they do not carry any special meaning here...

kind forum
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ohk

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wait i gtg can you help me solve later???

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around 8

vale wigeon
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... no guarantee it'll be me

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you will be gone for 8 hours?

kind forum
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yess

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srry

vale wigeon
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i don't know what timezone you are in, so if you actually meant that you'll return at 20:00 in your timezone, i don't know when that is.

kind forum
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okie ill just open some other channel you can close this one

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BYE

vale wigeon
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.close

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icy dagger
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Hello

lone heartBOT
icy dagger
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This is False right?

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because -4 isn't a natural number and 3 isn't an even integer.

lone heartBOT
#

@icy dagger Has your question been resolved?

lone heartBOT
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stray knot
lone heartBOT
stray knot
#

How exactly do I solve this?

median oar
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,rotate

ocean sealBOT
median oar
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what do you know about trigonometry?

stray knot
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Pythagorean theorem and the basic trig ratios

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This question is in the Pythagorean theorem chapter so I dont think trig ratios are needed

modern meadow
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All you need for this is pythagoran

stray knot
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yep but how do I apply it in this case

median oar
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oh that's true

median oar
modern meadow
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You divide h by 2 and put it in the formular

stray knot
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Didnt think that would work at all

median oar
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why are you dividing H by 2

stray knot
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If you half the triangle in the middle isnt it a right angled one

median oar
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yes, ∆THU is a right angle triangle

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with that you should be able to solve for the unknown side in a right angled triangle with pythag

stray knot
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Ah

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Thanku for the help

modern meadow
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The height pf the triangle is equal to
sqr(height)==sqr(9.6)-sqr(15.4/2)

stray knot
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Ah I see

#

Well that answers my question then

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.close

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final tundra
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solve for x

lone heartBOT
final tundra
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wait no

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replace x^2 by 2x^2

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like this

plain flame
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right

alpine sable
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hmm that'd result in complex roots

final tundra
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disclaimer: i'm dumb and the education system here is pretty late

plain flame
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do you know what a complex number is

final tundra
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well

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i have a very vague idea

plain flame
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oh

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seems like youre lacking some theory

final tundra
plain flame
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where is this question from

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school?

final tundra
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yep

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hw

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and i'm curious on how this is solved

plain flame
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and school didnt teach you about complex numbers?

final tundra
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only up to real ones

plain flame
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what the hell

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well this equation has complex roots only

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so

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probably watch this video

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Courses on Khan Academy are always 100% free. Start practicing—and saving your progress—now: https://www.khanacademy.org/math/algebra2/x2ec2f6f830c9fb89:complex/x2ec2f6f830c9fb89:complex-eq/v/complex-roots-from-the-quadratic-formula

Complex Roots from the Quadratic Formula

Practice this lesson yourself on KhanAcademy.org right now:
https://w...

▶ Play video
final tundra
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oh

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this might help: it's part of a function

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where g(x) = the equation above

median dirge
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And then?

final tundra
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well

median dirge
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Youre supposed to find x?

final tundra
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it doesn't equal 0, the question is: if g(x) = 0, then what's x

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with g(x) = 2x² - 16x + 64

median dirge
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If g(x) = 0, the roots (or the values of x) will be complex numbers

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If you have an idea of complex numbers, that could help

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But if you don't, and they just want you to keep the answer halfway, then you can solve it using the quadratic formula, and see for yourself

final tundra
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funny: i never learned the quadractic formula

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i'm literally not gonna answer the question, and i'll provide the reason why, because we haven't learned this

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i'll look for good courses online so i can actually learn stuff in english instead of arabic

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anyways thnx

#

.close

lone heartBOT
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jaunty rapids
lone heartBOT
jaunty rapids
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How do i do part a

median dirge
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Do you know how to write probability distributions?

jaunty rapids
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Yes

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this is the answer

median dirge
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So, can you calculate probabilities of red appearing "X" times when you spin the spinner five times

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Well uh?

jaunty rapids
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i understand everything except for the yellow:

median dirge
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Whyd you send

jaunty rapids
median dirge
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the answer

jaunty rapids
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i got everything except for the part in yellow

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i dont uunderstand that part

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help

vale wigeon
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are you familiar with the concept of a binomial distribution

jaunty rapids
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no

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my textbook has that as the next topic

vale wigeon
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:|

jaunty rapids
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so i probably can answer it without binomial distribution as they prob wouuldnt have put it as a question in the topic before

vale wigeon
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well, ok, to say it without the fancy name...
X = 2 means the spinner landed on red exactly twice out of 5 spins

jaunty rapids
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yes

vale wigeon
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there are 5C2 = 10 ways for it to do that

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if we look at all possible orders in which red and non-red could have occurred

jaunty rapids
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Yes

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Oh

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i get it

vale wigeon
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and each one has probability 0.4^2 * 0.6^3, so summing them all up you get the same times 10

jaunty rapids
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i know binomial expansion so i understand it

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thanks

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got it

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i spent 2 hours tryna understand this

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shi

whole shell
#

that markscheme looks familiar

lone heartBOT
#

@jaunty rapids Has your question been resolved?

jaunty rapids
lone heartBOT
#
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dense oasis
lone heartBOT
dense oasis
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could anyone help with number 4?

split oriole
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Sure

vale wigeon
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3/2 * 4/3 * 5/4 * ... * 101/100

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notice anything peculiar about this product?

dense oasis
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numerator is one more than denominator each time?

main kraken
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what's 3/2 * 4/3

vale wigeon
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well yes sure but

main kraken
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then think about 3/2 * 4/3 * 5/4

vale wigeon
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there's something else that can help you greatly simplify its calculation

main kraken
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notice how everything cancels each other out

dense oasis
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yeah 3/2 * 4/3 would be 2

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but then what

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wait what am i saying

main kraken
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then what's 3/2 * 4/3 * 5/4 * ... * 101/100

dense oasis
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101/2

main kraken
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why

dense oasis
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idk

main kraken
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do you know how to do multiplication with fractions

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or at least how terms can cancel each other out

dense oasis
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yeah

main kraken
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now here

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look at the 2nd + 3rd fractions

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does the 4 get cancelled out?

dense oasis
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yep

main kraken
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how about the 3

dense oasis
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but the 3 and 5?

main kraken
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in the 1st and 2nd

dense oasis
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yeah

main kraken
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6/5, right?

dense oasis
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6/5

main kraken
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so 5 also gets cancelled out

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but how about 6?

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then you gotta look at the 5th fraction

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and so on

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there's a pattern here

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the numerator on the left cancels the denominator on the right

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in the end you're left with 1/2 * 101/1

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which is 101/2

dense oasis
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ok i got it

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thanks

main kraken
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yw

dense oasis
#

how do i close?

main kraken
#

.close

dense oasis
#

.close

lone heartBOT
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regal ridge
#

hello

lone heartBOT
regal ridge
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I need help with a problem

#

so basically:

In a Company A there are 300 employees and 15% of those employees are women.

In a Company B there are 30% women.

in Company A & B together there are 20% women

How many employees are in Company B?

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I calculated the number of women in Company A and it's

300×15/100= 4500/100= 45 women

marsh rapids
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Write an equation in B's number of employees and solve for it

regal ridge
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hm ok

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I think I need hints

marsh rapids
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Letting b be B's number of employees, we have

regal ridge
#

I think there will be 2 unknowns?

marsh rapids
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$\frac{45+0.3b}{300+b} = 0.2$

ocean sealBOT
#

mateo713

regal ridge
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I need some explanation

marsh rapids
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top = number of women
bottom = number of employees
20% = 0.2

regal ridge
#

b=150?

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damn yes

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$\frac{45+45}{300+150} = 0.2$

ocean sealBOT
#

KhalilCool

regal ridge
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yes

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$\frac{90}{450} = 0.2$

ocean sealBOT
#

KhalilCool

regal ridge
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$\frac{0.2}{1} = 0.2$

ocean sealBOT
#

KhalilCool

marsh rapids
regal ridge
#

oops

marsh rapids
#

You're not bothering anyone in your own channel of course

regal ridge
#

well thanks for helping imma close the channel

lone heartBOT
#
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regal ridge
#

.reopen

lone heartBOT
#

regal ridge
#

one more question @marsh rapids, how did you get to:

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also are there any other methods of solving it?

marsh rapids
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You can also use a more barycentric approach (i.e. center of gravity)

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20 = 2/3 * 15 + 1/3 * 30 so A weighs twice as much as B: it got double the employees

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So b = a/2 = 150

regal ridge
#

yeah I thought about that thanks!

lone heartBOT
#

@regal ridge Has your question been resolved?

lone heartBOT
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stiff forum
#

V = span{(1,1,-i),(0,i,1+i)}
and I have set of vectors:
{(1,0,-1)} and I have to add vectors to this set to make base of V from it

stiff forum
#

In V I checked that vectors are linearly Independent

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And (1,0,-1) is linearly Independent with (1,1,-i) and linearly independent with (0,i,i+1), but set of all thre these vectors is linearly dependent

mortal trellis
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lets call the first two vectors v1 and v2 and call the third vector u. what is span(u, v1) ?

stiff forum
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yea that's my problem i don't know how to figure out what space is span(v1,v2)

mortal trellis
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well V=span(v1,v2)

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lets say U=span(u, v1)

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what is the relationship between U and V. is maybe one a subspace of the other?

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what is dim U and dim V

stiff forum
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hmm u is in the V because its lineraly dependent with vectors that span it so U is subspace of V?

stiff forum
#

?

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Is that mean that optional base of V may just be U?

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Yyy not u

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{u1,v1}

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Or {u1,v2}

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Is that right?

mortal trellis
#

U is a subspace of V and dim U = dim V=2

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that means U=V

stiff forum
#

Thank u

#

./close

#

.close

lone heartBOT
#
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silent onyx
#

The diagonal of the base of a regular four-sided pyramid is 8√2cm, and the surface of one side is 20cm squared. determine the surface and the volume of the pyramid. <@&286206848099549185>

lone heartBOT
#

@silent onyx Has your question been resolved?

silent onyx
#

<@&286206848099549185>

exotic belfry
#

if you know the diagonal of the base (and this is a square) you can calculate a side of a base. the surface of the pyramid is the area of the base and 4 times the area of a side.

sharp wind
silent onyx
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then 8 times 8 is 64

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and 20 times 4 is 80

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and surface area is 144?

silent onyx
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and isnt h 6

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why did you write 8x8x5

sharp wind
#

Yes am sorry

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It should be 320/3

silent onyx
#

shouldnt it be 384/3

sharp wind
#

Bro h is 5

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That's just my bad handwriting

silent onyx
#

ohh ok lol

#

and surface area is 144 right

lone heartBOT
#

@silent onyx Has your question been resolved?

silent onyx
#

.close

lone heartBOT
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river swan
#

Hi all came across this and wasn't sure what to do. I have got it incorrect and not sure what to do. Below are my wrong workings/answers
a.)
T=m1a +1.5=0.42.5+1= 1+1.5 I believe this is correct but I could be wrong (1.5N is the resistance from firction)
b.)
F=ma
Mg-T=Ma
10M-2.5=2.5M
7.5M=2.5
3M=1
M=1/3

But these don't appear to be correct. Any help would be appreicated

river swan
frigid stream
#

@river swan Your work seems good, but did you write them down with 2 significant figures?

river swan
#

Oh so my answers are correct?

frigid stream
#

I would say so

river swan
#

thank you, thought i was doing something wrong

#

I'll make sure to give my answer in 2 sig figs tho

frigid stream
#

Yep!

lone heartBOT
#

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spare kayak
#

hello, im doing maths gcse and im unsure on how to find the minimum co-ordinates of a curve with the equation 10x^2 + 9x + 5. id really appreciate it if someone could help :))

last ether
#

Like the minimum y-value?

wind jolt
#

min = c - b^2/4a

spare kayak
#

i think both, the minimum x and y

last ether
#

Couple ways:

• function analysis/behavior
• derivatives

spare kayak
#

thats odd we havent learnt either of those yet

last ether
#

Well the problem is this: you have a polynomial

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What's true about the domain of all polynomials

spare kayak
#

that theyre all real numbers??

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oh god idk

gray isle
#

this is a quadratic, to find the min here you can consider completing the square and/or properties of the vertex

spare kayak
#

ok, i think i can complete the square, it just ends up looking a bit strange

last ether
spare kayak
#

ohhhhhhh

gray isle
#

i think both, the minimum x and y
should just be asking for coords with min y

spare kayak
#

it says "find the coordinates" and then gives two spaces so i presume that means both an x and y value but i guess not

#

would it be more helpful if i sent a photo of it?

lone heartBOT
#

@spare kayak Has your question been resolved?

lone heartBOT
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wind cloak
#

$$x = \frac{3(t^2 + 1)}{t^2 - 1}$$ $$y = \frac{3t}{t^2 - 1}$$

wind cloak
#

How do I eliminate the parameter

ocean sealBOT
#

NEONPerseus

solid cave
#

Hello Im really sorry for bothering but I need help with my math homework. So, the question is: 12 people came to the confectionery and sat down at several tables.
At each table, everyone shook hands with everyone. All in all
there were 19 handshakes in the confectionery. At how many tables were people sitting?
How many were there at each table?

last ether
lone heartBOT
# ocean seal **NEONPerseus**

What step are you on?

  1. I don't know where to begin
  2. I have begun but got stuck midway
  3. I got an answer but I'm told it's wrong
  4. I got an answer and would like my work checked
  5. I have a question about someone else's worked solution
  6. None of the above
fallen verge
#

:D

wind cloak
#

1

last ether
#

Oh shut up it's useful I know

#

Anyways

#

Hm

wind cloak
#

I mean I sort of have a plan but idk if it's.gonna work

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Like dx/dt and dy/dt

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And then dy/dx

fallen verge
wind cloak
#

Maybe some easily subbable stuff

last ether
#

And see where that goes

delicate jacinth
wind cloak
#

Well I tried dividing both of them

last ether
fallen verge
wind cloak
#

Isn't that in essence the same

last ether
#

Wdym dividing both of the@

wind cloak
#

x/y

#

Got rid of the denominators and the 3

last ether
#

Hm

#

,w ( 3(t^2 + 1)/(t^2 -1) )/(3t/(t^2-1))

ocean sealBOT
last ether
#

So $\frac x y = \frac{t^2 + 1} t = t + \frac{1}{t}$

#

Hm

#

There's no easy way to isolate t tho

#

Actually

ocean sealBOT
#

$e^{\text{Umbraleviathan}}$

last ether
#

There might be

#

Well nvm

delicate jacinth
#

this is kinda hard

#

wait

#

x-2y = 3?

#

nah

lone heartBOT
#

@wind cloak Has your question been resolved?

wind cloak
wind cloak
keen plinth
#

,w expand (1/3 (3(t^2 + 1)/(t^2 - 1)))^2 - (2/3 (3t/(t^2 - 1)))^2

keen plinth
#

nice 1 wolfie

#

thats 1

alpine sable
#

can some help me

lone heartBOT
#

@wind cloak Has your question been resolved?

wind cloak
#

Thanks a lot

lone heartBOT
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hot bison
#

can someone explain, my teacher assigned this question and she hasnt taught us riemann sums yet?

hot bison
#

im just really not sure how it works

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#

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hot bison
#

can you help <@&286206848099549185> ?

tacit arch
# hot bison can someone explain, my teacher assigned this question and she hasnt taught us r...

This calculus video tutorial provides a basic introduction into riemann sums. It explains how to approximate the area under the curve using rectangles over a closed interval. It explains how to determine the area of the region using left endpoints and right endpoints. The area under the curve is also equal to the definite integral of the func...

▶ Play video
hot bison
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wanton kiln
#

How many solutions does $e^{2n} = -1$ have?

ocean sealBOT
#

CoffeeMan

wanton kiln
#

I think my brain has withered completely

#

Here n is a natural number

worn fox
#

How many do you think

wanton kiln
#

Wops

#

I meant $x^{2n}=-1$

ocean sealBOT
#

CoffeeMan

wanton kiln
#

And 2n I think by fundamental thm of algebra, but my brain can only find n currently for some reason

lone heartBOT
#

@wanton kiln Has your question been resolved?

wanton kiln
#

Fucking forgot about multiplicities I guess

#

So n solutions seems right

#

What am I even talking about...

#

<@&286206848099549185>

#

Nevermind

#

2n roots

#

Good

#

.close

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austere jetty
#

can someone explain what is happening here? Where do the roots come from?

alpine sable
#

use the log power law

ocean sealBOT
austere jetty
#

OHHH truee

#

thankss bro:)

#

.close

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graceful forge
#

hi

#

...

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graceful forge
#

is anyone online?

lone heartBOT
thorny root
#

many are

#

you can just ask

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alpine sable
#

Hi everyone, I need a help please. I'm trying to demonstrate why when you do -1 * both sides of inequality you have to change the direction of inequality. I started from this
0<=a and 0<=b -> 0<=ab
And I used (a<=b -> a+c<=b+c) -a
b as c and it changes to -ab<=ab-ab and after some steps it goes into -ab<=0. Is this right? because axioms says it with opposite number but I used more than one number.

rocky grove
#

The key is in starting with 0<=a. You defined a to be at least 0. If you multiplied it by -1, then your definition will have to change since your first definition was a is at least 0. If it's the negative value of a, then it has to be the opposite definition, which is at most 0.

#

It's like your negating your inequality. (0<=a) * -1 implies 0>= -a

alpine sable
#

Sorry, but so you are using knowledge that axioms don't have, because using 0<=a multiplied by -1 you will have 0<=-a, but my target is using axioms I wanna arrive to have it automatically. For example 0<=a i add -a to both sides and I have -a<=0 so maybe I demonstrated that negative number is lower than 0. In same way I wanted to know if I can add 2 numbers which are multiplied each other as an opposite number. Sorry if I'm not clear but English isn't my main language

merry depot
#

two numbers multiplied together is itself a number. So if you know it's true for 'a number' then you know it's true for the ab product you're trying to use.

alpine sable
#

Because I used it how you said that 2 numbers multiplied each other it become a number

lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
#

@alpine sable Has your question been resolved?

limpid turret
#

@alpine sable which axioms are you using?

#

What knowledge is available and what isn't?

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#
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fair musk
lone heartBOT
fair musk
#

How do I find the area inside that?

last ether
#

shit

#

nb

#

wdym area inside

#

you mean volume?

fair musk
#

Oh yah

#

I meant volume

fallen verge
#

do you have some dimensions?

fair musk
#

I need to write an expression for the volume 𝑉 of the region within the cylinder and below the plane in terms of 𝑟

fallen verge
#

45 degrees is what i needed

alpine sable
#

Please help in channel 4.

fallen verge
#

do not promote your help channel

alpine sable
#

After finding volume ofc

#

sorry

fallen verge
#

the problem can be rephrased like "given a shape with a semicircular base and cross sections that are isosceles right traingles with one leg on the base, find the volume"

fair musk
#

How did we get to that?

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#

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alpine sable
#

Anyone knows how to enter parametric EQN on Ti 84

alpine sable
#

Part 1

long axle
#

May be wrong abt this, but hit the mode button and see if Theres a parametric option

#

Can u show a picture of the screen when u hit mode

#

@alpine sable

lone heartBOT
#

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alpine sable
#

.reopen

lone heartBOT
#

alpine sable
#

But

#

It only comes out as only one value of y per x

#

But in reality

lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
#

@alpine sable Has your question been resolved?

dawn root
#

Proposition: The union of two finit sets is finite.
I was trying to prove it without induction...

Is my proof valid? (Here Jn means the set of first n natural numbers)

lone heartBOT
#

@alpine sable Has your question been resolved?

kind forum
#

Can anyone help with this??

#

ummm

rose sigil
#

reactangle hmmCat

sonic drum
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plain hill
#

I need help to solve it

lone heartBOT
plain hill
#

i try to start but after i made some mistake and now i try do to it again

modern sedge
#

You can modify the left side to a single log base 1/3, and then realize what does it mean when log(a)=0

plain hill
#

i should move for example -log1/3 (x-5) in the other side?

modern sedge
plain hill
#

is a property of log that we can us for divide?

modern sedge
plain hill
#

ok, whay you should me to solve it?

#

I move the 2term is the other side or i should use another method?

modern sedge
#

Here is how you can get rid of logs. Do you understand it? I use 0.33 instead of 1/3 because I couldn't type it

plain hill
#

ok, in this way bacame:
1/2 log1/3 (25-x) < log1/3 (x-5)

plain hill
#

ok, now wait one sec that i try to do the next step

#

ok, i try to do the next step but i'm not sure:
log1/3 (25-x) < log1/3 (x^2 +25 - 10x)

modern sedge
#

The next step is removing the log

plain hill
#

ok so became:
25 - x < x^2 -10x + 25 ?

modern sedge
#

Now move the terms to one side, and factor it out to find the solutions

plain hill
#

ok one thing, that remain "<" or we change in ">"??

modern sedge
plain hill
#

ok

modern sedge
#

Oh wait no it should change

plain hill
#

oh, why??

modern sedge
#

When you remove logs, you have to flip it

#

The same holds for adding logs. if a<b, then log(a)>log(b)

plain hill
#

ok

modern sedge
#

Like in your case

plain hill
#

became -x^2 + 9x > 0

modern sedge
modern sedge
plain hill
#

yes

modern sedge
#

great, so solve it and post the solution, there is one more thing you need to do

plain hill
#

the solutions are:

  • x>0
  • x<9
#

i think

modern sedge
#

So 0<x<9

plain hill
#

yes

modern sedge
#

Now you need to look back and check some conditions

#

What's log(negative number)?

plain hill
#

wait this is the second step

plain hill
modern sedge
#

You will see why it's so important

#

What's log(negative number)?

plain hill
#

sorry, where is the negative number?

modern sedge
#

log(negative number) is undefined. You find that x=1 could be solution. But what would log 1/3(x-5) be if x was 1?

#

It would be underfined. So x=1 cannot be a solution, although it's in interval 0<x<9

plain hill
#

can't be, should be a number > 0

modern sedge
#

So from this picture you can conclude 2 more inequalities for x

#

25-x>=0, and x-5>=0. Because they must be non-negative. >= means greater or equal

#

Do you understand it @plain hill

plain hill
#

for get the solution what can i do?

modern sedge
#

25-x>=0 can be written as 25>=x, or x<=25 and the second condition would be x>=5

plain hill
#

yes

modern sedge
#

So in conclusion, your solution is interval, where 0<x<9. and 25>=x and x>=5

plain hill
#

ok, wait one sec

#

for do it, we should like an axis with all the info?

modern sedge
#

All numbers between 0 and 9 are less then 25. So we are left with 2 inequations. x>=5 and 0<x<9. When are both the inequalities true?

#

Simply when 5<=x<9. Do you get it? This is the final solution

#

It's the same as when I combined This to 0<x<9

#

I gtg, sorry.

plain hill
#

.close

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#
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distant citrus
#

Hi i have a problem with my ti-84 plus ce-t my answers arent accurate if i want to calculate to surface of the binominal

distant citrus
#

.close

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bleak plover
#

i have a player pos and a mouse pos in 2D. when the player clicks, i want him to shoot a projectile in the direction of the cursor at a set speed s. how do i calculate what should be the velocity on x and y axis by knowing the relative mouse position to the player?

bleak plover
#

x and y velocty should add up to the speed (or up to 1 if speed not included)

#

also keep in mind that the mouse pos can be negative on one (or both) axis, whch should reflect in the velocity vector too

sterile idol
#

Probably get a unit vector pointing towards the mouse pos and scale it by the velocity with the set speed s

#

$\begin{bmatrix}
\frac{xs}{\sqrt{x^2+y^2}}\
\frac{ys}{\sqrt{x^2+y^2}}
\end{bmatrix}$

ocean sealBOT
#

King Dedede

sterile idol
#

so the velocity along the x direction becomes $\frac{xs}{\sqrt{x^2+y^2}}$ and along the y axis becomes $\frac{ys}{\sqrt{x^2+y^2}}$

ocean sealBOT
#

King Dedede

sterile idol
#

@bleak plover

sterile idol
#

Hey

bleak plover
sterile idol
#

You shouldn't be on discord then

bleak plover
#

this is a math help channel, not a dating site

#

.close

lone heartBOT
#
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worn horizon
#

can u help in a math prob

#

krish

#

can u help ?

#

bro
can someone help me in ellipse
if tangent are drawn to all point of the ellipse [x^2+(y^2)2 = 2] other then its 4 vertices find the locus of the mid point of these tangents upon intersecting the coord axis

lone heartBOT
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worn horizon
#

nope

sterile idol
#

Then that's the 2

#

Is it in division or in multiplication

worn horizon
#

multi

#

multi

sterile idol
#

Okay so $x^2 + 2y^2 = 2$

ocean sealBOT
#

King Dedede

worn horizon
#

correct

hazy totem
#

Technically you shouldn't be allowed to use discord then, you know that right?

worn horizon
#

u gotta bring it standard from which i did

bleak plover
#

Roman numerals are a numeral system that originated in ancient Rome and remained the usual way of writing numbers throughout Europe well into the Late Middle Ages. Numbers are written with combinations of letters from the Latin alphabet, each letter with a fixed integer value, modern style uses only these seven:

The use of Roman numerals contin...

sterile idol
#

It's the y axis, actually

#

Actually, nevermind

bleak plover
#

no

#

its (x * x) + (2 * y * y) = 2

lone heartBOT
#

@alpine sable Has your question been resolved?

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#
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pearl saddle
#

Hey, so I've been trying to learn how to factorize larger algebraic expressions and I'm not sure about this one

2x^2 - 6xy - 5xz + 15yz

I have managed to transform it into

x(2x - 6y - 5z) + 15yz

But I'm not sure where to go from there, i want to turn the entire expression into a product and not a sum

pearl saddle
#

?

vivid swallow
#

You can factor out z from the right part and x from the left and you'll get a product equation

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#

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neat cloak
#

Can i get help please

lone heartBOT
vale wigeon
neat cloak
#

When a VAT 21% is included, the price of a Laptop increases by €130.20.
Find the total cost of the Laptop including VAT.

weary wyvern
#

130.20 is 21% of the original price

#

the questions asks for the original price plus this 21%

neat cloak
#

What do i do
To get rhe original price

modern sedge
#

Alternative approach: let P be the price without VAT. You know that P+0.21P=P+130.20 (price+VAT=price+130.20)

#

Can you solve this? P+0.21P=P+130.20

neat cloak
#

I cant 🤣

modern sedge
#

Can you at least simplify it? Look at it :) P + 0.21P = P + 130.20

neat cloak
#

Is the 0.21 the 21%?

modern sedge
#

Yep

#

25% of some value is same as value*0.25, 50% of some value is same as value*0.5

neat cloak
#

Oh god im going foundation in 3 weeks time 😭

modern sedge
#

And can you solve this? If 130.20 is 21%, what is 100%?

#

(You don't need to find actual value, just post calculation you would do to find it)

neat cloak
#

Let me grab my calculator real quick

#

So i have to find 100% of 130.20

#

Do i Multiply or divide?

modern sedge
neat cloak
#

So i have to multiple

modern sedge
#

Try to rewrite it as equation. Let X be 100%. And you know, that 21% of X=130.2. Therefore 0.21X=130.2

neat cloak
#

100% with 130.20?

modern sedge
#

Can you solve this? 0.21X=130.2

#

How did you learn to work with percents in school?

#

Is there some tactics you used?

neat cloak
#

@modern sedge
My Maths teachers are horrible at teaching

#

Im a Leaving certificate student rn

modern sedge
#

Okay nvm, Can you solve this? 0.21X=130.2

neat cloak
#

We do things in Maths rn were they say we did it in first year which isnt true

neat cloak
#

I dont understand

modern sedge
#

What's your mother language?

neat cloak
#

Hungarian

#

English is my 2nd language

#

I want to understand the Language of Maths, is there help here?

fringe scroll
#

I have an idea

#

we have 21% of a price, that is 130.2

modern sedge
fringe scroll
neat cloak
#

I prefer English

#

@modern sedge

modern sedge
neat cloak
#

Thank you

modern sedge
lone heartBOT
#

@neat cloak Has your question been resolved?

lone heartBOT
#

@neat cloak Has your question been resolved?

neat cloak
#

How do you solve this

lone heartBOT
#
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tidal sun
lone heartBOT
near hollow
#

what have u tried?

lean lily
#

bro use a^n - b^n = (a-b)(sum a^k b^(n*k))

#

a^n will be your cos

#

b^n will be 1

#

so a will be your nth root

#

and b 1

#

so everytime (cosx-1)/(sum of k cosines) = nthroot(cos)-1

#

use the fact that lim cos(x)-1 / x^2 = 1/2

#

and that's basically it :))

#

the 1/2^n-1 will come from a multiplication of n-1 limits that converges to 1/2

tidal sun
#

ik

#

but

#

the sum

#

how to write it

lean lily
#

wait

tidal sun
lean lily
#

did he show y'all a^n - b^n ?

tidal sun
#

i only know (a+b)^n

#

or (a-b)^n

lean lily
#

Now you know

tidal sun
#

is there a method using nth root rules

lean lily
#

it's basically the one i told you

tidal sun
#

cuz

#

i cant use something

#

he didnt teach me

#

i need another method

lone heartBOT
#

@tidal sun Has your question been resolved?

tidal sun
#

<@&286206848099549185>

lone heartBOT
#

@tidal sun Has your question been resolved?

alpine sable
#

Help needed

#

I want examples of weight function in orthogonal differential equations

#

<@&286206848099549185>

#

-_-

#

Help me out plzz

#

<@&286206848099549185>

#

Please

low magnet
#

wassgud

#

what u need help wit

alpine sable
#

I've representation with tis

#

I need examples of weight function of orthogonal polynomial in differential function

alpine sable
low magnet
#

ω(x)=xex−1 on [0,+∞) well I think this could owkr

alpine sable
#

Thnks

#

A little more explaination

#

I've representation tomorrow

low magnet
#

im not sure my self too

#

lemme look into it

#

how much time u got?

alpine sable
#

<@&286206848099549185> anyone plzz

#

Tomorrow

low magnet
#

well i mean for today how much time u have?

alpine sable
low magnet
#

okk got it

#

try pinging some helpers

#

if no one fixes it then ill get back to you

alpine sable
#

<@&286206848099549185>

#

Plzz

low magnet
#

All known orthogonal polynomials, are solutions of differential equations that arise in various physical phenomena. Legendre developed his poylnomials as coefficients of expansion of a Newtonian potential. Hermite poynomials are eigenstates of the quantum harmonic oscillator. Only a chosen few will satisfy equations that have actual physical meaning, or would have "nice" explicit representations.

alpine sable
#

Help me out

low magnet
#

im guessing yk about this right?

alpine sable
#

Few of

low magnet
#

so the relatioship with the weights, should be able to have a explict representations

#

@alpine sable

alpine sable
#

Emm can I get more information

#

I've to make it 25 mins information

#

<@&286206848099549185>

#

In odes method

#

I'm done thnks @low magnet

#

Closed.

lone heartBOT
#

@tidal sun Has your question been resolved?

#
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#
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pearl saddle
#

how would i calculate this

lone heartBOT
pearl saddle
#

or calculus

gray isle
#

consider rationalising denominators

#

for all the fractions

#

and you'll notice something very nice

lone heartBOT
#

@pearl saddle Has your question been resolved?

#
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#
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pearl saddle
#

how can i solve this using short multiplication formulas

pearl saddle
#

meaning things like

#

(a + b)^2 = a^2 + 2ab + b^2

#

or

#

a^2 - b^2 = (a + b)(a - b)

#

okay nevermind

#

i figured it out

#

lol

#

.close

lone heartBOT
#
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#
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alpine sable
#

how do i calculate this?

lone heartBOT
alpine sable
#

translation: two graphs have these intersect, what is the area?

#

im stuck from step 1 basically

#

.close

lone heartBOT
#
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#
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golden ridge
#

guys why is 2| sin( (x-y) / 2 )| <= 2 | (x-y) / 2|

clever locust
#

$\abs{\sin\alpha}\leq\abs{\alpha}$ for all $\alpha\in\bR$

ocean sealBOT
#

Lorago

golden ridge
#

.close

lone heartBOT
#
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alpine sable
lone heartBOT
alpine sable
#

so I'm essentially

#

trying to do -379.48 = (1/2)(-9.8)t^2

ruby current
#

this one is occupied

lone heartBOT
alpine sable
#

which is change in y = initial velocity times time plus 1/2 times acceleration times time squared

#

change in y from the top of the throw, when velocity equal 0, is -379.48 given 92.5 and my previous answer

#

so i completed this and got 8.8 seconds from the top to the bottom of the cliff.

#

then i did 286.98/75 for the initial throw to the top height and got 3.8264

#

added that to the 8.8 and i got my answer which is apparently wrong. what did i miss?

keen mason
#

hm

modern sedge
#

What constant for gravitational accel are you using?

alpine sable
modern sedge
#

My result is 4 units away from yours, so it's probably not rounding error

keen mason
#

The time taken from the second it got released from the cliff, to the highest point is 7.653

#

than add on the time taken to travel 286.98

#

your answer is exactly half mine

alpine sable
#

did you do -4.9t^2 + 75t - 286.98 = 0 ?

#

to get the time from release to highest point?

ocean sealBOT
#

Stephen

modern sedge
#

Or you can just set a formula like this and you will directly get the x. I included the initial velocity, and also the fact that on the start it was 92.5 units above ground

keen mason
#

ut = 0

#

0.5at^2 = s

#

sqrt(2s /a) = t

alpine sable
#

.close

lone heartBOT
#
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unkempt zinc
#

e) Through the intersection of lines
2x 5y 6  0
and
x 3y 3  0
place the rectangle on the line
4x  y 5  0
. Write it down
the equation of a rectangle.

alpine sable
unkempt zinc
#

delete i was first

alpine sable
#

or what

unkempt zinc
#

np i will change channels then

#

cya

alpine sable
#

Bye

unkempt zinc
#

.close

lone heartBOT
#
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alpine sable
#

.open

wild trail
#

.reopen

lone heartBOT
#

worn fox
#

.close

lone heartBOT
#
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pliant estuary
#

How should I solve this limit?
$$
\lim_{x\to\infty}(1+2x)^{\frac{1}{x}+3}
$$

ocean sealBOT
#

marejak023

pale kestrel
#

!status

lone heartBOT
#

What step are you on?

  1. I don't know where to begin
  2. I have begun but got stuck midway
  3. I got an answer but I'm told it's wrong
  4. I got an answer and would like my work checked
  5. I have a question about someone else's worked solution
  6. None of the above
pliant estuary
#

I know how to calculate it for x approaching 1, but dont know how to do it as we are going to infinity

last ether
#

Change the exponential statement so it has a base of e

pliant estuary
ocean sealBOT
#

marejak023

pale kestrel
#

to change exponent, use the identity

e^ln a = a

last ether
#

a^b = e^(bln(a))

modern sedge
pliant estuary
#

To be onest, I dont know how to continue from this step

quasi vector
pliant estuary
lone heartBOT
#

@pliant estuary Has your question been resolved?

hollow skiff
#

@pliant estuary when u replace "x with infinity" what you got?

lone heartBOT
#

@pliant estuary Has your question been resolved?

hollow skiff
#

so e^infty that means?

pliant estuary
hollow skiff
#

that should be the solution

pliant estuary
#

.close

lone heartBOT
#
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lone heartBOT
#
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wispy wing
#

Just would like someone to check if right if possible

lone heartBOT
wispy wing
#

Does ln cancel eachover out?

vapid steppe
#

yes

#

but how did you get 1.09

wispy wing
#

By substituting

#

Was my way of seeing if they equaled the same

vapid steppe
#

what does the instruction say

wispy wing
#

Solve

vapid steppe
vapid steppe
quasi vector
#

,rcw

ocean sealBOT
#

Couldn't find an attached image in the last 10 messages.

quasi vector
ocean sealBOT
#

Couldn't find an attached image in the last 10 messages.

wispy wing
#

Cool thanks

lone heartBOT
#

@wispy wing Has your question been resolved?

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alpine sable
lone heartBOT
alpine sable
#

These 2 methods right

#

and are they questions right too

#

?

lone heartBOT
#

@alpine sable Has your question been resolved?

mental flame
# alpine sable

btw when your adding stuff like 3y+y, there is an invisible coefficient oh y. so really 3y+y is just 3y+1y

alpine sable
#

Yeah

#

I renote my notes

#

i added that in

#

So it will be

#

4y

#

Right

mental flame
#

ok, i was just making sure 🙂

alpine sable
#

It will be 4y

#

correct

#

?

mental flame
#

yep

alpine sable
#

Ok

#

Is the methods right

#

and are the questions right?

mental flame
#

i think the one on the left is wrong

#

let me show you

alpine sable
#

Ok

#

the method or the question

#

?

mental flame
#

you have this right?

alpine sable
#

Yes

mental flame
#

you can just distribute that negitive in the middle to this

#

that will get you this

alpine sable
#

Thats what i did??

#

I changed the signs

mental flame
#

yep, but the middle term is wrong in your answer

alpine sable
#

This

mental flame
#

it should be 2y-3y right?

alpine sable
#

Mhm

mental flame
#

which is just -1y

alpine sable
#

There both negatives

mental flame
#

no? did you distribute the negative to both polynomials?

alpine sable
#

Yes

mental flame
#

ah ok

alpine sable
#

There were both positive

mental flame
#

your only supposed to distribute the negative to the one you are subtracting by

alpine sable
#

which is 2?

mental flame
#

distributing the negitive to both polynomials is like saying 3-2=-3+2

alpine sable
#

I see

#

bottom is correct 1

mental flame
#

i think you did the same mistake with the constant 15

#

-8-(-7)

#

should be -8+7

alpine sable
#

Lemme go over everything rq

lone heartBOT
#
Channel closed

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alpine sable
#

.reopen

lone heartBOT
#

mental flame
#

yep that should be the answer : D

alpine sable
#

Ok

#

So

#

Are the methods and questions good now

mental flame
#

should be, just remember when subtracting polynomials, distribute the negative to the one you are subtracting by. good luck 🙂

alpine sable
#

👍

#

thanks man

mental flame
#

any time

alpine sable
#

i got first part of the exam done

#

.close

lone heartBOT
#
Channel closed

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alpine sable
#

ill be back with more stuff maybe

mental flame
#

ok, see ya

lone heartBOT
#
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fair musk
lone heartBOT
ruby current
#

you can always reduce the base

earnest mortar
#

Use $$7\equiv 1\ [6]$$

ocean sealBOT
#

Silfer

fair musk
#

what does the [6] mean?

earnest mortar
#

mod 6

indigo saddle
#

Mod 6

fair musk
#

oh

worn fox
#

yeah thats terrible notation

ruby current