help-0

[vast arrow]

awesome that all I wanted to double check over

appreciate it guys

[nocturne cypress]

🙂

[vast arrow]

.close

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[tame yacht]

What are the a) average velocity b) average acceleration c) average displacement of the tip of a 25cm long minute hand clock in the interval 4:00 to 4:30

[tame yacht]

how do you calculate the average acceleration

[outer lark]

so a clock could just be a circle and the clock hand length could just be the radius of that circle

the period of the motion is just the time at a->b

and we know centripetal acceleration is (4pi^2)/ T^2

or v^2 / r

[tame yacht]

so i should use my answer to a to work it out right

[outer lark]

you can if you want, I assume that's intended however not required

[tame yacht]

what does T stand for here

the time?

[outer lark]

period

time taken from A->B on the circumference on the circle

[tame yacht]

so the half hour

[outer lark]

so it would be from straight up to straight down

yep

[tame yacht]

where v = av velo?

[rocky grove]

Yep

[tame yacht]

i got the av velocity = 1.67

so does av acceleration = 1.67^2 / 25

[rocky grove]

What are the units?

[tame yacht]

cm/min

[rocky grove]

It's better if you express the speed in cm/seconds so that you can express acceleration in cm/s^2

[tame yacht]

the question asks for it in cm/min

would it be easier if convert it now and then change it back at the end

[rocky grove]

Hmm

Wait what are the required units for acceleration?

[tame yacht]

cm/min^2

[rocky grove]

Oh so keep it then

But it's easier to deal with s^2

Because it's sensible

Anyways

[rocky grove]

This is correct

[tame yacht]

so it should be 0.11

[rocky grove]

Wait

How did you get v again?

[tame yacht]

i did 50/30

where 50 is the total displacement

and 30 is the time

[rocky grove]

Hmm

Wait do they mean radial velocity or the vertical velocity?

[tame yacht]

ummm

it says u cn use vectors to solve it right

so if u calculate it the horizontal components cancel

[rocky grove]

Sure but the radial component is the one that gives the acceleration

Velocity goes tangent to the circle

And the acceleration is normal to it

In any circular motion

[tame yacht]

so i need to figure out the velocities at 4:00 and at 4:30 ?

[rocky grove]

The average velocity in a clock stays the same

It's the arc length divided by the time

That's for the radial/tangential velocity

[tame yacht]

so that would be 5/6 pi

[rocky grove]

Yeah

[tame yacht]

so i use that velocity instead in v^2/r

wait

okay no im just confused lol

[rocky grove]

It's fine lol

V in V^2/r is the tangential/radial velocity

[tame yacht]

right

[rocky grove]

That also stays constant as long as the velocity stays constant

And in your case, it is constant

[tame yacht]

okay this is irrelevant but why would a clock have acceleration

[alpine sable]

because the velocity changes

[rocky grove]

A clock hand*

[tame yacht]

but isnt it constant

yes mb

[rocky grove]

It is constant radially

[alpine sable]

its not speed, its velocity so its direction changes

you arent finding the change in speed, you are finding the change in direction

[tame yacht]

right okay

[rocky grove]

The question should specify whether the velocity is tangential or vertical

Anyways

[tame yacht]

What is the magnitude of the average velocity during the half hour?

thats the exact quesiton

im just confused

[alpine sable]

ok its asking you what the speed is

[rocky grove]

Magnitude of the average velocity should be the tangential velocity

So yeah the arc length/time

5pi/6

cm/min

[alpine sable]

simpler explanation

[tame yacht]

right

[alpine sable]

velocity has a speed and directional component

as it is asking you for the average magnitude(speed)

it is just distance/time

[tame yacht]

so thats 1.67 cm/min

wait

[rocky grove]

[tame yacht]

huh

do u use the total displacement to calculate it tho

[rocky grove]

distance

[tame yacht]

so the arc length

[rocky grove]

Yes

[tame yacht]

wait okay but where does that get me

[rocky grove]

Gets you to the speed and to the acceleration

[tame yacht]

so its 5/6 pi

[rocky grove]

V = 5pi/6 cm/min

Yes

[tame yacht]

okay right

so do i put that value into v^2 / r

[rocky grove]

Yes

[tame yacht]

so the av acceleration should be 0.27 cm/min^2

[rocky grove]

Yep

[tame yacht]

it says its wrong for some reason

[rocky grove]

Hmm

Is the acceleration only wrong?

Or is the velocity also wrong?

[tame yacht]

it says 1.7 cm/min for av velocity is correct

[rocky grove]

Okay

[tame yacht]

also regarding the av, acceleration

The velocity of minute hand is purely horizontal (pointing right) at start of half-hour, and purely horizontal (pointing left) at end of half-hour. What would the average acceleration have to be to cause this change?

so during the half hour the av acceleration vector should be pointing left ?

wait no

this is confusing me more lmao

[rocky grove]

0

Ugh

[alpine sable]

as i said

it asks for the magnitude of the average velocity

ie the average speed

it does not once mention acceleration in the question

and direction is not important as it asks for magnitude

[tame yacht]

im trying to figure out the average acceleration tho

[rocky grove]

Hmm

It lost what it gained tho

[alpine sable]

no it didnt

[rocky grove]

Like it started at a certain horizontal speed

[alpine sable]

i c what u mean

[rocky grove]

Then it came back to that speed but in reverse

So in total, its acceleration is 0

[alpine sable]

ye

[rocky grove]

Right?

[alpine sable]

idk why you would try to calculate the average acceleration

[tame yacht]

idk either

[alpine sable]

like the question is about average speed

[tame yacht]

no its not

[alpine sable]

whats the question

[rocky grove]

It asked about acceleration

What are the a) average velocity b) average acceleration c) average displacement of the tip of a 25cm long minute hand clock in the interval 4:00 to 4:30

[tame yacht]

^

[rocky grove]

Average displacement is 50cm pointing down

[alpine sable]

then the average acceleration is 0

[tame yacht]

but its not 0

[rocky grove]

That's still wrong?

[tame yacht]

well i tried 0 alreadyu

yeah

[rocky grove]

Wow

[tame yacht]

that was the first thing i tried

[rocky grove]

Okay try 1.7^2 / 25

[alpine sable]

calculate the total change in velocity

[rocky grove]

Weird stuff happening

[tame yacht]

yeah i tried that as well

[alpine sable]

over total time

[rocky grove]

[tame yacht]

but what is the total change in velocity

[rocky grove]

Hmm

[tame yacht]

does that mean i calculate the velocities at 4:00 and 4:30

[rocky grove]

Wait did you take this formula: $v = \omega r$?

[ocean seal]

VulcanOne

[tame yacht]

so the i component would be going in the opposite directions

[tame yacht]

no

[alpine sable]

for every point other than 1, the clock's velocity can be cancelled out with another

so the hand's velocity at 4:15 must be the change in velocity

[rocky grove]

Try out (2*1.7)/30

[tame yacht]

thats not it either

[rocky grove]

[tame yacht]

me rn

[rocky grove]

[alpine sable]

isnt it an integral

[rocky grove]

esre did you take integrals?

[rocky grove]

Also no it's a derivative

[tame yacht]

well i know basic differentiation and integration

[alpine sable]

differentiate it then

[tame yacht]

what am i differentiating

[alpine sable]

average velocity

[rocky grove]

Circular velocity is sine and cosine

Wait but it's average tho

[alpine sable]

yeah thats fine

its just the derivative over time

[tame yacht]

okay i still dont quite get it

[rocky grove]

Hmm

Did you try 0.12?'

Which is supposed to be v^2/r

[tame yacht]

yea i alrdy tried it

[rocky grove]

That's just weird

[tame yacht]

am i supposed to use vectors to figure it out somehow

like the velocity when 4:30 = -(velocity at 4:00)

so the i components r different

idk anymore

[rocky grove]

But they are the same magnitude

[tame yacht]

but theyre going in opposite directions

[rocky grove]

Yep

But regardless of whether they are changing directions, the acceleration should be the square of tangential velocity divided by the radius

https://www.youtube.com/watch?v=kLN9W73ASrQ

Or you could use 1.7/25 (50/30)

[tame yacht]

= 0.11

but its wrong apparenlty akdsfhasdfa

[rocky grove]

Which is $\frac{V}{r} * \frac{\Delta r}{\Delta t}$

[ocean seal]

VulcanOne

[rocky grove]

Does it say to round to the nearest tenth?

[tame yacht]

2sf

[rocky grove]

Try 0.17

[tame yacht]

ITS RIHGT

right

[rocky grove]

Okay

So

[tame yacht]

wait how

[rocky grove]

V is the tangential velocity

Which was 5/6 pi

[tame yacht]

right

[rocky grove]

You use this formula

https://cdn.discordapp.com/attachments/490557019623915520/1062114762131001554/1000057838007226480.png

Delta r is 50 cm

r = 25 cm

Radius

[tame yacht]

right

ah

and that gives u 1.7

the website also gave me an alternative way of calculating it

[rocky grove]

Khan Academy?

[tame yacht]

Correct!
think of initial velocity to the right and final to the left. The change is of magnitude 2x the instantaneous speed. Divide this by the 30 minutes needed for the change

isaac physics

[rocky grove]

Ooo

So I was using 2*1.7/30 correctly but on the wrong speed

[tame yacht]

ah yeah

[rocky grove]

Anyways that was interesting

[tame yacht]

but for some reason when it asks for average velocity it wants 1.7 instead of 5/6pi

yes

that took like

over an hour

[rocky grove]

delta r is the average distance so your average speed is delta v = delta r/delta t

And average distance is 50 cm

[tame yacht]

wait why is average distance 50

[rocky grove]

Because that is the distance vector

And since the angle is 180 degrees

[tame yacht]

isnt that the displacement tho

wait huh

[rocky grove]

Yeah that is true

[tame yacht]

i think ive stopped functioning tbh

now its asking for average displacement in the vertical and horizontal directions

[rocky grove]

Well the average in the horizontal is basically 0

[tame yacht]

aha guess what

its not

[rocky grove]

Lmao

Then the word displacement is just wrong

[tame yacht]

OH whoops

[rocky grove]

Distance is appropriate

[tame yacht]

magnitude of av horizontal displacement

huh

[rocky grove]

Make sure that vertical displacement is 50

[tame yacht]

okay so i guess i need to resolve it and average it over the first 15 mins for horizontal

[rocky grove]

See if that is correct

[tame yacht]

yeah its not

that was the first thing i tried as well

average downwards displacement

[rocky grove]

I guess you'd need to use vectors

[tame yacht]

guess so

[tame yacht]

for the horizontal one its (2/pi)*25

[rocky grove]

So delta r/theta?

[tame yacht]

umm

basically resolve it and average it over the 15 mins

im working backwards rn

@rocky grove can i dm u? i dont have much time rn

[rocky grove]

Sure I guess

[tame yacht]

alr tysmm

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[steep ember]

hi

[steep ember]

so today i wanted to learn all about basic logarithms. All the rules and exercises im in first semester and have exam in a month

can u recommend any websites to learn about it from almost zero

im looking for german or english websites

[smoky adder]

khan academy

[steep ember]

ok

[smoky adder]

https://www.khanacademy.org/math/algebra2/x2ec2f6f830c9fb89:logs

this should give you essentially everything you need to know

[steep ember]

Ok thx

.close

[lone heart]

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[warm wind]

How do i go about this question? Its a multiple choice question where i need to select the proposition which is always true,

[limpid spade]

Are E and F subspaces of V?

[warm wind]

yes

[limpid spade]

What does Vec mean?

[warm wind]

I thinks its span in english

yes

i just checked

[warm wind]

got a clue how to solve this?

[limpid spade]

I'm not really into stuff like this I'm more into computational stuff

In lineair algebra

[warm wind]

oh ok np

anyone?

[tender dew]

I think 2,4 are true

[warm wind]

only one is true

[tender dew]

shit

[warm wind]

ye

[tender dew]

2

seems most legit

[warm wind]

why do you say that

[tender dew]

due to how common operator works

[warm wind]

shit idk

i have no intuitive guess here

[tender dew]

I'd check one more time smth

[placid zinc]

Okay yeah, so E and F are non-empty subsets. They need not be spaces

Taking their span, then unioning will always be smaller than unioning, then taking their span. First one is false

[warm wind]

agreed, since span(E) is in E right?

[placid zinc]

You might mean the other way. E is always a subset of span(E)

[warm wind]

inverse*

yes yes

[placid zinc]

2 does look pretty legit, I'll think on a reason why

[warm wind]

thanks 🙂

[placid zinc]

Intersection of two subspaces is a subspace, that's probably very related

[tender dew]

so in 3rd and 4th both sides have to not be related?

that's weird

[placid zinc]

I wasn't clear haha. This is a random theorem that the intersection of two subspaces is a subspace.

I think that this is enough to prove the second one true

I wasn't making any statement about the 3rd or 4th line

[warm wind]

Why though?

I have a possible reasoning line but idk if its correct: Vec(E inter F) congru Vec(Vec(E) inter Vec(F)) =? Vec(E) inter Vec(F)

[placid zinc]

Let x be a member of span(E n F). That means x can be made using linear combinations of things that are in both E and F. But that means E or F can make x by themselves. So x is also a member of span(E) n span(F)

Didn't end up touching my subspace theorem

[warm wind]

Right, thanks it makes sense. Would you mind just telling me if my thing up there makes any sense

[placid zinc]

congru?

[warm wind]

= Is in

E congru V = E is in V

[placid zinc]

Taking the span of span(E n F) is equal to span(E n F)? That's true because E n F is a space

I don't think 2 is true anymore if you use =

Only subset

Namely my proof doesn't work backwards

[warm wind]

So span ( span (E n F)) is in span (E n F) or no?

[placid zinc]

Yes. They are also the same

[warm wind]

But then couldn't i do the same reasoning and get 1 to be true?

[placid zinc]

How did you prove 2?

Can you relate those to span(E) n span(F)?

[warm wind]

span( E u F) is in span ( span(E) u span(F) ) which is equal to span(E) u span (F)

[placid zinc]

You're using a lot of things we haven't talked about in that

[warm wind]

this is what i meant to write before

[placid zinc]

span(span(E) u span(F)) is equal to span(E) u span(F)?

Can you slow it down for me lol

[warm wind]

So that isn't true?

sorry i have very bad intuition for algebra

[placid zinc]

No I don't believe it is. Note that span(E) u span(F) need not be a space and span() may enlarge it

[tender dew]

not exactly the thing

[warm wind]

why wouldn't span E u span F be a space?

[tender dew]

but an analogue

[warm wind]

so i guess + is analogue to u

[tender dew]

yup

[warm wind]

and the x?

[tender dew]

multiplication

analogue to union

[warm wind]

isn't + for union?

[placid zinc]

Can hit this with an example. If span(E) and span(F) are a line,

then span(E) u span(F) is just two lines. That's not a space

[tender dew]

sorry, I meant multiplication is analogous to an intersection

[warm wind]

If E is a subspace of V, is span(E) also in V?

[placid zinc]

Yes. In fact, E = span(E)

If E is a subset of V, span(E) may not be in V

[warm wind]

and simply being in V doesn't mean he's automatically a space as well?

[placid zinc]

Subspaces have the properties of a vector space

Subsets don't need to have any properties at all

[warm wind]

okay thanks

thanks a lot for taking the time to help

[placid zinc]

You may remember doing subspace tests. Subspaces need to be closed under addition, under scalar multiplication, and needs to contain 0

[warm wind]

yes, just a last question. If E is a subspace of V, does it have the same propreties as V?

since if i remember it doesn't always have to be addition and multiplication?

[placid zinc]

E has to use the same operations as V, if that's what you mean

As for general properties, no. For example, E might have a lower dimension than V.

[warm wind]

okay yes thats what i meant

thank you very much!

[placid zinc]

Np. Feel free to ask if you have anything else

[warm wind]

Okay, thank you

[lone heart]

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[steady basin]

hi

[steady basin]

Is this the same as this?

Like the final answer?

[hollow sparrow]

what is the original question ?

[steady basin]

I’ve done it two ways

Wanna know

If both the final answers r the same?

Could u maybe check if it’s the same via wolfram here?

[hollow sparrow]

,w int 1/sqrt(-3x² + 12x -8) dx

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Mehdi_Moulati#1210

[hollow sparrow]

nope

[steady basin]

What have i done wrong here then?

Wait

[steady basin]

What have I done wrong here then?

[minor needle]

u is 3(x-2)

and u did

u^2 = 3(x-2)^2

which is wrong

[steady basin]

ahhhh

ok yh

calm

cheers

yhy

kl

[minor needle]

It wasn't about me

[hollow sparrow]

sorry

[steady basin]

when u integrate do u get v?

with the sub

ye u do

kl

i meant this part

or v even

which is arcsin u

calm

bosh

[lone heart]

@steady basin Has your question been resolved?

[lone heart]

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[tender creek]

Can solve this with step by step😢

[lone heart]

Please don't occupy multiple help channels.

[tacit arch]

stick to one channel

.close

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[spare fern]

hey guys

[spare fern]

how would I turn this into a quadratic?

m^3 - 7m - 18 = 0

[wary stream]

To do what exactly?

[spare fern]

In order to solve for m

[alpine sable]

use the rational root theorem

[spare fern]

how do I use it?

[alpine sable]

$m = \pm \frac{\text{factors of -18}}{\text{factors of 1}}$

mfw

[spare fern]

hold on I'll send the full question

[wary stream]

The only suggestion I have, is to graph

[ocean seal]

45

[wary stream]

There's no rational roots

[alpine sable]

bruh

[placid zinc]

bruh

[wary stream]

Technically you can, if you have the proper terms and a rational root, you can do polynomial long division

[placid zinc]

So 9^x = (3^x)²

[wary stream]

$(3^x)^3 \neq 9^x$

[ocean seal]

dldh06

[wary stream]

It's this

So if you did it properly, it would have been a quadratic

[alpine sable]

hmm is he here

@spare fern

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@spare fern Has your question been resolved?

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[stark lagoon]

(The 45.75 is correct)

But why is the other one not correct

It is just integral?

[wary stream]

Because you have the info to find C

[stark lagoon]

Oh i see

[wary stream]

The last sentence

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[last ether]

Just compare the bounds I guess

Remember your sum rule

$\int_a^b f(x)dx + \int_b^c f(x)dx = \int_a^c f(x)dx$

[ocean seal]

Umbraleviathan

[heady pollen]

or to make it a bit to complicated (sum rule is more straight forward):
integral from a to b of f(x) dx is F(b)-F(a)
thus we get in this case:
F(5)-F(9)+...
stuff will cancel out and we can reverse the expression into an integral

but what Umbraleviathan said is probably simpler haha

[alpine sable]

help

[gritty pond]

how does this work and wouldn't it be different if we flip the two integrals on the left side?

[last ether]

It works because of the Riemann sum. It's like tying two regions together to make one.

[last ether]

Due to addition rules, no

It won't be different

[alpine sable]

help

[last ether]

#❓how-to-get-help

[alpine sable]

here help

[heady pollen]

@alpine sable #❓how-to-get-help

read that first

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@gritty pond Has your question been resolved?

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[stable relic]

if you have a function thats a line like y=x but at x=3, y= 100 or something, is that still referred to as continuious?

[stable relic]

how do you refer to it since its definied for all x

[last ether]

Wdym

Like if you vertically shift y=x?

If you vertically shift a continuous function that's continuous for all x, then it's still gonna be continuous for all x

[tribal oxide]

Maybe google piecewise functions, then you can frame a better question

[stable relic]

ok bruh

{y =x x !=3

{y=100 x=3

[last ether]

I mean, I guess it's a continuous curve

Well actually

No

[stable relic]

theres definitely a jump

i mean

[last ether]

That's not continuous I think

[stable relic]

removable discontinuity

[last ether]

That's not even a function

[stable relic]

yes it is

[last ether]

How can x = 100 at x = 3

[stable relic]

skull

ookie

fixed

[last ether]

Then it's discontinuous

[lone heart]

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[glacial ether]

how to do

[glacial ether]

casework counting terrifies me

[smoky adder]

idk if there's a mathy way to do it but i would start with the highest denomination and just brute force it lol

[glacial ether]

too hard

[smoky adder]

valid

[glacial ether]

ur a undergrad 😭

they having me do this in 8th garde

[smoky adder]

naur i just take undergrad courses as a highschooler

[smoky adder]

oh then i think that's how you're supposed to do it

[glacial ether]

wdym

[humble remnant]

brute force

just count them

[glacial ether]

thats way too many bro

[smoky adder]

by brute forcing it

there's not that many

[glacial ether]

ill have to slowly cut out the pennies right

what if i miss one or dupe oen

[smoky adder]

well the pennies are going to be in multiples of 5

[glacial ether]

oh ya

thanks

i got it

[smoky adder]

cool

[glacial ether]

.close

[lone heart]

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[lone heart]

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[night path]

how do I find slope and y intercept of 4y=16-8x

[tacit arch]

Put the equation in the form y=mx+b

[night path]

how

[tacit arch]

You have 4y on the left. How do you get just y?

[night path]

divide idk

[tacit arch]

Yes. Divide by what?

[night path]

4y

[tacit arch]

4y divided by 4y equals 1

You want just y

[night path]

idk then

[tacit arch]

What do you multiply y by to get 4y?

[night path]

4

[tacit arch]

That means 4y divided by 4 equals?

[night path]

1y

or y

[tacit arch]

Yes they're the same

[night path]

oh ok

[lone heart]

@night path Has your question been resolved?

[lone heart]

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[honest apex]

Can anyone help me with this im stuck with 8,9, and 10

[left trellis]

What have you tried?

Do you know how to construct an equation for the line?

[honest apex]

no

[left trellis]

(Knowing 2 points on it)

Do you know y=mx+b

[honest apex]

oh

yea

[left trellis]

Or point slope form if you know that too, would be easier

[honest apex]

yea

ok

thx

[honest apex]

yo how would I determine if it has inf sol. or many sol or no sol

[plain sundial]

i think you do simultalneous equation here

& see if the answer is 0, less than 0 or more than 0

[honest apex]

ok

would -2 - 3 be -5?

[plain sundial]

yes

[honest apex]

ok

I got 1 and -1

for 8

would it be one solution?

[plain sundial]

many

[honest apex]

oh

[left trellis]

set them equal to each other (iirc)

[plain sundial]

1 and -1 are two different numbers

[honest apex]

would 0-4 be -4?

[left trellis]

yes

[honest apex]

k

what do u do if u get 1 half

I got 0 and a half

[left trellis]

well then that would be a solution if you did everything right, wouldn't it?

[honest apex]

yes

[left trellis]

you can also check graphically

[honest apex]

I got 1 half for each one on number 10

would that be many solutions?

[left trellis]

at how many points do the graphs intersect?

[honest apex]

honestly

idk

[plain sundial]

you can try using desmos

make an equation using y=mx+c

then just put them on desmos

[honest apex]

idk how to use

1

[plain sundial]

do you know how to form an equation

using the points given

[honest apex]

no

[plain sundial]

do you know how to find the gradient

[honest apex]

nope

[honest apex]

oh

ik how to do those

no solution

thanks for helping me

.close

[lone heart]

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[dusky elk]

i need to find the diameter

[alpine sable]

Do you know much in trigonometry

[dusky elk]

yeah i tried using sin38° = 7.1/c

[alpine sable]

Yep that's exactly it

Solve for c

[dusky elk]

but the answer says that it is 5.8cm

my calculator says that it is 4.3

[alpine sable]

Hmm

[dusky elk]

oh wait that 90 degree symbol isnt supposed to be there

[alpine sable]

,w calculate 7.1/sin(38°)

[ocean seal]

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[alpine sable]

[dusky elk]

hmm

[keen plinth]

[alpine sable]

That doesn't make much sense because like that would mean the hypotenuse is shorter than the opposite side of the triangle

[keen plinth]

classic sine rule

,w 11.53/2

[ocean seal]

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[keen plinth]

probably means radius

[alpine sable]

Oh okay then yeah

[dusky elk]

ohh

thx guys

.close

[lone heart]

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[hard nacelle]

Could I have help with these questions? I need to find them to the nearest minute.

[serene junco]

Use the law of sines to find the un-labeled angle first

[hard nacelle]

Doesn’t theta need a matching side to find the angle though?

[serene junco]

Find whatever angle you can, even if it's not theta

Then you can find theta because all the angles in the triangle sum to 180

[hard nacelle]

Where do I take it from there?

Oh

So I could find 1 angle on the first one using 10 & 43 and then 12 and “theta” to find the angle next to 43, then add them and subtract them from 180 and that’s my 1st theta?

[serene junco]

yep

[hard nacelle]

Okay epic

Do I leave it unfounded until the end?

Unrounded

[serene junco]

Yeah I would, if possible

[hard nacelle]

Okay cool

Thank you!

[serene junco]

np 👍

[hard nacelle]

Didn’t work?

[serene junco]

hm?

[hard nacelle]

I’ve got an answer key and the answers I got from finding the other angle and them adding them and then subtracting 180 by them aren’t in the answer key

[serene junco]

What'd you get?

[hard nacelle]

I got for the 1st one

54.92475065

2nd one I got

33.16025607

They’re the unmarked angles

Then adding them with the angle given

54.92475065 + 43 = 97.92475065

And

21 + 33.16025607

= 54.16025607

[serene junco]

okay

those aren't the final results though, right?

[hard nacelle]

No

I took away the values of the unlabelled angle and labelled angle added together from 180

[serene junco]

So for the first one

82 degrees and some change?

[serene junco]

180 - 97.92475065 = 82.07524935

[hard nacelle]

Yep

And that is 82° 5’ nearest min

But that isn’t on the answer key

So that has confused me quite a bit

[serene junco]

ahh okay I see

So, when you're solving for a missing angle with the law of sines, sometimes there are two possible angles, one acute and one obtuse

[serene junco]

and the arcsin function will only give you the acute angle

so like for the first one

[hard nacelle]

Ohhhh okay is this where I get my unit circle out and take away my answer from 180?

To get an answer >90 meaning that angle would be obtuse?

[serene junco]

You don't need a unit circle, but yeah

[hard nacelle]

Ohhhhhh

[serene junco]

180 - this

would be the blank angle

[hard nacelle]

Ohh!!

that makes way more sense

Let me fill that in

I got 125° 5’ which is on the answer key!!

Thank you loadsb

!*

I’ll fill it in and find out

[serene junco]

wait hang on lol

that's just the blank angle

[hard nacelle]

Yep

Then take away those two from 180?

[serene junco]

like, 180 - 43 - 125.whatever

[hard nacelle]

Yes yes S

[serene junco]

For the first one I end up with 11 deg 55 min

for theta

[hard nacelle]

Okay sweet, thank you loads!

Yep I got that!

I’ll try the other one

[serene junco]

Awesome 👍

np

[hard nacelle]

That right?

[serene junco]

Yep, looks good

I'd advise using a symbol other than theta for the blank angle, though

since theta already means something else in this problem

[hard nacelle]

Yeah that sounds right

Thank you so much for the help!!

[serene junco]

np 👍

[lone heart]

@hard nacelle Has your question been resolved?

[lone heart]

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[lone heart]

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[clear tinsel]

How would you do this

?

[vale wigeon]

do you understand what you are asked to do?

[clear tinsel]

not really

we never learned how to do this

[vale wigeon]

what do you mean?

[clear tinsel]

idk

[vale wigeon]

have you learned about velocity and acceleration in general?

[clear tinsel]

no not really

so it says at the time acceleration equals 0

[vale wigeon]

no? so you don't know that they are the first and second time derivative of position?

[clear tinsel]

does that mean when s(t) = 0?

[clear tinsel]

no

that would've been helpful

[vale wigeon]

then how are you expected to do this problem?

[clear tinsel]

that's what I don't understand

[vale wigeon]

"Find the velocity at the time the acceleration equals zero." = "At one point in time, the acceleration of our object equals zero. What is its velocity at that time?"

[clear tinsel]

our final is tommrow and our teacher said to study this

[vale wigeon]

as such presumably you would first solve the equation s''(t) = 0 and then evaluate s'(t) at the point you got.

but since you have had the knowledge of velocity and acceleration withheld from you, you do not have the tools to do this.

quite the conundrum.

[clear tinsel]

alr it's fine I think she'll understand if I point it out to her

.close

[lone heart]

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[timid jolt]

How do you do 13?

[median oar]

,rotate

[median oar]

xy=u try differentiate both sides

I’d start there to get du/dx on the right

[timid jolt]

I don’t get what your saying

Wouldn’t du/dx just be y?

[pseudo ice]

remember that y also depends on x, so product rule

[median oar]

^

[timid jolt]

Can someone do it for me cos I still don’t get the answer

[median oar]

Show your working

@timid jolt it’s quite literally just 2 steps

[median oar]

It’s not x+y

[median oar]

.

[timid jolt]

Wait what

Why?

[young glade]

i need help

with D

[plain sundial]

wrong channel

go to empty help channels

[young glade]

where

[plain sundial]

try #help-7｜zen1thxyz

its empty now

[young glade]

thx u

[median oar]

y=u/x

xy=u

d/dx (xy) = d/dx (u)

@timid jolt

[timid jolt]

Wait I’m so confused rn

[plain sundial]

y=u/x

you multiply Both sides by x

xy=u

And then differnetiate both sides with respect to X

[plain sundial]

In othejr words like this

[median oar]

The question gives you y=u/x has a given

So you start here

[timid jolt]

Wait could you write it on paper

Sorry

[median oar]

$$y=\frac{u}{x} \$$
$$ xy= u\$$
$$\frac{d}{dx}[xy]=\frac{d}{dx} [u]$$

[ocean seal]

Frosst

[timid jolt]

How about the y tho?

[plain sundial]

it just becomes y

[timid jolt]

So that’s just the answer?

[median oar]

No you have to solve this

You’re trying to prove something

The process is the answer

[timid jolt]

What is d/dx(xy)

[median oar]

Product rule

[pseudo ice]

Or if you haven’t seen that notation before, “differentiate xy with respect to x”

[median oar]

$\frac{d}{dx}[x^2(x-3)]$

[ocean seal]

Frosst

[median oar]

How would you do this

[timid jolt]

I know how to do that but I don’t know how you got there

[plain sundial]

got where?

[timid jolt]

(X squared (x-3))

[plain sundial]

that's a different question

he's asking if you know how to do that using the product rule

you apply the same on the question you asked

[plain sundial]

you apply the same rule here

[timid jolt]

So wouldn’t it be x+y?

Aren’t I trying to prove thing

This

[median oar]

where does x+y come from

[timid jolt]

When you derive xy

Using product rule

Could you guys write out how to do it

Please

[lone heart]

@timid jolt Has your question been resolved?

[median oar]

show me

show me you differentiation xy using the product rule

actually no

tell me what the product rule is

write it down and take a picture

[timid jolt]

It’s uv’+vu’

[median oar]

ok

so u = x

v = y

uv' + vu'

that means

xy' + yx'

yeah?

[timid jolt]

Ohh wait yeah

[median oar]

$x\frac{d}{dx}[y] + y\frac{d}{dx}[x]$

[ocean seal]

Frosst

[median oar]

$x\frac{dy}{dx} + y$

[ocean seal]

Frosst

[lone heart]

@timid jolt Has your question been resolved?

[lone heart]

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[worn hearth]

Like where does the 4 in the denominator come from?

when i derivate arctan(2x), i get 2/(x^(2)+1)

but it says that the answer is 2/(4x^(2)+1)

[lone heart]

@worn hearth Has your question been resolved?

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[steady basin]

When dividing the 2/3 how does that come to 3/2

[pseudo ice]

$\frac{(2/3)^n}{(2/3)^{n+1}} = \frac{\cancel{(2/3)^n}}{\cancel{(2/3)^{n}} (2/3)}$

[ocean seal]

chartbit

[steady basin]

kl

cheers

[heady swan]

?

[lone heart]

Please read #❓how-to-get-help

[steady basin]

do we do this limit via hopitals?

since its infinity / infinity

[pseudo ice]

I mean, you could...

[steady basin]

what would u do?

[pseudo ice]

Expand the (n+1)^2 on the top, simplify, them factor out n^2 from both top and bottom

[steady basin]

ok

[pseudo ice]

Then you'll have something nicer to work with

[steady basin]

Like this?

[steady basin]

mhm

[pseudo ice]

Yep, then factor the n^2's

[pseudo ice]

Cancel them out and you're pretty much there!

[steady basin]

yh

so 3/2

calm thanks

[pseudo ice]

gonna go get myself ready in a bit btw

[steady basin]

oooo

going out?

[pseudo ice]

Just to do bits and pieces really, nothing that exciting

Or maybe I should go get food while I’m out have a few things I need to get anyway

[steady basin]

did u sleep

?

[pseudo ice]

Well technically I slept until midnight-ish again, which to be fair is good enough

From yesterday to now I have a decent amount of sleep in total haha

[steady basin]

lmao

[hollow sparrow]

[pseudo ice]

Well at least I got some rest

[pseudo ice]

Also welcome back

[hollow sparrow]

||i just woke up 1 hour ago||

[hollow sparrow]

tnx

[lone heart]

@steady basin Has your question been resolved?

[steady basin]

Need some help finding the power series for cot x

I’ve done this so far

[steady basin]

mehdi could u have a look at this plz

[hollow sparrow]

okay , i will try

[steady basin]

thx

[steady basin]

im trying to compare coefficients

but my c2 is wrong

im getting c2 as 0

it should be -1/3

oh waity

[hollow sparrow]

you made a mistake

in the denominator

[steady basin]

ye

[hollow sparrow]

it's x²/3!

not x²/2

[steady basin]

c2 is -1/3

boshhh

ye

Ok

Kl

[hollow sparrow]

cheers

[steady basin]

.close

[lone heart]

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[undone cliff]

I need help with this idk where to start.
Ain't no way that I substitute it 1 by 1. I need the efficient way, please help me

[wanton pebble]

have you tried anything?

[undone cliff]

I tried to open it up

f(1/2016 + 3/2016 + 2013/2016 + 2015/2016)

That will be f(2)

And the ans will be 81/84 which is wrong

[wanton pebble]

i think u can't do this

[plain sundial]

plug it in

[wanton pebble]

try solving each one .and maybe something will cancel

[plain sundial]

What if he plug X in the equation

[undone cliff]

how u mean?

[plain sundial]

you can plug 1/2016 inside x in the equation

[undone cliff]

Ye i can do that find it 1 by 1

[wanton pebble]

can log help

[plain sundial]

not working

?

[undone cliff]

I want to find a efficient way to do this

[wanton pebble]

2013= 2016-3

2015=2016-1

use log

maybe it will help

[undone cliff]

Wait

[undone cliff]

I got a idea

Will it work

Its a pattern

[wanton pebble]

maybe

[undone cliff]

2016/2016 - 2013/2016 = 3/2016

2016/2016 - 2015/2016 = 1/2016

[wanton pebble]

so 1-2013/2016

[undone cliff]

lets say x is 2015/2016

Hm

if 1-x

[wanton pebble]

try log

nah

from start

[lone heart]

@undone cliff Has your question been resolved?

[undone cliff]

Btw I got 2

[undone cliff]

with this

[wanton pebble]

is this ans right?

[undone cliff]

idk

I should ask my teacher tomorrow

Its a practice question

[wanton pebble]

okie

[alpine sable]

The first 2 are about 1/2 and the second 2 are about 3/2, so I would say it’s 2

But idk I’m not that good in math

[undone cliff]

how do you do it sir?

[alpine sable]

For the last 2 I wrote 9 as 3^2 so u get 3^(20152/2016) = 3^2 and honestly i did the same for the third one (20132/2016) =1.99 so I don’t know if it’s right

(2015*2)

There is probably a better and faster way to do it

But idk

For the first 2 I basically did 9^0 = 1 and again idk but i got 2

[undone cliff]

okie :v

atleast u tried to do it

[alpine sable]

Yea ahah

[undone cliff]

Thanks for the help @alpine sable @wanton pebble

[plain sundial]

indonesia ?

[undone cliff]

ye

[wanton pebble]

wlcm..

[undone cliff]

ow thanks too

forgot about u hehe

[plain sundial]

Nah I did nothing

[undone cliff]

every words is important