help-0

[wary stream]

Because as mentioned, coordinates are in the form of (x, y)

[alpine sable]

Wait…

Omg

Is it 3/-2

[wary stream]

You displayed (35, 2) meaning over 35, over 2. Is that correct?

[wary stream]

No

[alpine sable]

[wary stream]

You also need to pay attention to the scale

[alpine sable]

Well no 2 over 35

[wary stream]

You're going down 3 squares, not down by how many units each square is

[alpine sable]

35 is X

And 2 is Y

[wary stream]

No

As mentioned, coordinates are (x, y)

Meaning over then up

So are you going over 35 units first?

Or over 2 units?

[alpine sable]

Oh wait

Im going over 15

Right?

[wary stream]

Do you know what direction over/across and up/down means?

[alpine sable]

Ye

[wary stream]

Over means left or right

[alpine sable]

Maybe

[wary stream]

So are you going left or right 15 units?

[alpine sable]

Left

[wary stream]

This is your line

[alpine sable]

Yes exactly

[wary stream]

The blue line, how many units is that?

[alpine sable]

3

[wary stream]

Apply the values that are on the y axis

That's 3 squares but not the proper value

[alpine sable]

Which is 15

Right?

[wary stream]

And what direction is that 15 going in?

[alpine sable]

Up

Which is Y

[wary stream]

So then why did you say it was going left before?

[alpine sable]

Oh

Ohhh

Damn

Im dumb

Couldnt comprehend the situation srry

So then

Its over 2 and up 15?

[wary stream]

Recall that slope is rise over run

Rise is the y direction

[alpine sable]

Ah ok

So

The equation is

Y=15+x2

[wary stream]

No

[alpine sable]

Explain

[wary stream]

Because it's wrong

[alpine sable]

It is?

[wary stream]

Yes it's wrong

What is the slope of that plot?

[alpine sable]

Uh

3 and 2?

[wary stream]

No

Stop backtracking and guessing random things

[alpine sable]

Ok

So

What is it? Maybe ill realize something

[wary stream]

I'm not saying it

That's your job to find out

[wary stream]

Use this

[alpine sable]

Oh

[wary stream]

As mentioned, slope is rise over run

Meaning y over x

That blue line, how many units is it and in which direction?

[alpine sable]

Up

[wary stream]

No

[little peak]

I have plenty of money, should I just spend the extra 30 dollars for the luxury?

[alpine sable]

Oh

5

5 each unit

Right?

[tacit arch]

Please move to a new channel this is now @alpine sable 's

[wary stream]

Between the two connected points, what direction are you going in?

[alpine sable]

Over and then up

[wary stream]

Then recall that if you go left or down, for slope, it is a negative value

[alpine sable]

Wait so thats

Negative 15?

On the blue like?

Wait no

-2 right?

[wary stream]

If you are going over to the left, then it's negative

Are you going over left or right?

[alpine sable]

Left

[wary stream]

Now what direction are you going for the blue line?

And how many units?

[alpine sable]

Up and 3 units

Or 5 if were making sense

[alpine sable]

One unit=5

[wary stream]

So how many total units up did you go?

[alpine sable]

15?

[wary stream]

So now apply rise over run, with the above statements

Find the slope

[alpine sable]

Rise over run?

[wary stream]

Yes slope is rise over run

[alpine sable]

Ok so the slope is

15 over -2?

[wary stream]

Yes

[alpine sable]

Omg

Hurray

[wary stream]

Now, the standard form for a line is y = mx + b

[alpine sable]

Which m is + right?

[wary stream]

What?

[alpine sable]

Can u uhhh help me write that… and let it slide

[alpine sable]

M is the slope

[wary stream]

No

[alpine sable]

Uhmm

[wary stream]

y = mx + b, m is the slope, b is the y intercept

[alpine sable]

So whats the B

Ah

So the slope is 15 and -2 but

Wouldnt I have to write

[wary stream]

It's not 15 and -2

It's a fraction

[wary stream]

It's this

[alpine sable]

Ah

Finally done

[wary stream]

What was the equation of the line you got?

[alpine sable]

I got

Dis

[wary stream]

No

First, equations of a line are y = mx + b

That x is important

Second b is the value of the y intercept, aka where it crosses the y axis

What is the value where it crosses the y axis?

[alpine sable]

Which is where?

50?

Only place I can think of

Sorry to interrupt but think of b like the amount of y you would have with no x

[wary stream]

Is that the y value, along the y axis?

[alpine sable]

?

[wary stream]

Do you know what the y intercept means?

[alpine sable]

Doesnt it mean like

Actually idk

(0, y) is its coordinate pair

Since a coordinate pair is (x,y), when x = 0 you can look on the graph to see what y would be

It's on your original sheet

Ermm

[wary stream]

This is my advice for you. You are lacking too much prior knowledge, aka not knowing how to find the y intercept or finding slope. I suggest asking your teacher for help

[alpine sable]

I think Ill stick to dldh06

[wary stream]

Look up resources

[alpine sable]

Am I rlly lacking that much knowledge?

[wary stream]

.

Can you answer that?

[alpine sable]

The point where the line crosses the Y axis

?

[wary stream]

Can you determine the y intercept based on that info?

[alpine sable]

Hmmm

Should be 50 on my graph

Look

@wary stream

[wary stream]

So then plug it into the equation of the line

y = mx + b

[alpine sable]

So B is 50

[wary stream]

So then the equation of the line is?

[alpine sable]

?

[wary stream]

What is the equation of that line

Of the plot you are working with

[alpine sable]

Y=15/-2

[wary stream]

No

[alpine sable]

Idk what the equation of the line is

[wary stream]

As stated, the equation of a line is in the form of y = mx + b

Where m is the slope

b is the y intercept

You determined what m and b are

Plug those into that equation

[alpine sable]

So B is actually 50

[wary stream]

I still stand by this

[alpine sable]

Ik…

But is B 50

[wary stream]

Is that the y intercept?

[alpine sable]

Im assuming yeah

[wary stream]

It's a yes or no question

[alpine sable]

Uh

Yes

[wary stream]

No where during a test will you get to play 20 questions with your test to confirm answers

So is 50 the y intercept?

[alpine sable]

So

The y intercept is 0?

Is what ur saying

[wary stream]

The y intercept is where is crosses the y axis

Meaning x = 0

What is the value of y when x is 0?

[alpine sable]

Undefined?

0

?

Wait

[alpine sable]

Y intercept

So basically its 50

[wary stream]

So then plug in those values into y = mx + b

[alpine sable]

So ur making me do extra stuff for no reason when I knew it all along

[wary stream]

No I'm not

[alpine sable]

You willingly asked for help

@wary stream well thank u for putting up with me

[wary stream]

It's the process you need to apply to determine the equation of the line

[alpine sable]

Oh right the

Question isnt over

It says

Interpret the slope and y intercept in the context of the situation

Its saying explain it in words

[wary stream]

Still suggesting this

[alpine sable]

💀

[wary stream]

You should just ask your teacher for help

[alpine sable]

I can tomorrow but unfortunately try to help me finish this 1 question

[wary stream]

You spent nearly 2 hours, to do one part of a question that's not even over yet

[alpine sable]

Yes….

[wary stream]

So I'm suggesting to ask your teacher for assistance

That one part should have taken max 10 minutes

[alpine sable]

Sorry man I just got off of winter break why would I remember any of this

[wary stream]

Because it's something you apply repeatedly

[alpine sable]

Well uhm

Can u help with part B of this question

[alpine sable]

E

[wary stream]

Look at the axes

[alpine sable]

U a teacher?

[wary stream]

No

[alpine sable]

Oh

Well uh

I cant explain the context of the situation…

Well Ill try

I cant..

Im skipping part B on all my questions I guess

Thx for the help

[lone heart]

@alpine sable Has your question been resolved?

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[twin oxide]

Can someone kindly help me out with this problem:

A vendor at a carnival sells cotton candy and caramel apples for $2.00 each. The vendor is charged $60 to set up his booth. Furthermore, the vendor’s average cost for each product he produces is approximately $0.80.

a. Write a linear cost function representing the cost C(x) (in $) to produce x products.
b. Write a linear revenue function representing the revenue R(x) (in $) for selling x products.
c. Determine the number of products to be produced and sold for the vendor to break even.

[median oar]

Do you know what a linear cost function is?

[twin oxide]

I know of it but dont really understand

[median oar]

Ok what is a linear cost function

It’s pretty self explanatory from its name

[twin oxide]

its to determine the total costs that goes with the amount of production

[median oar]

ok to be honest what i was looking for is

"it's a function that relates the costs and is linear"

so we know it's some sort of f(x)

that's the function part

it's linear so it would have a general form of f(x) = ax + b

and it has something to do with costs

so C(x) = ax + b in some way

[twin oxide]

I see

[lone heart]

@twin oxide Has your question been resolved?

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[alpine sable]

-1/4 times 1 / -1/4
-1/4 -4 =
-1/4 -4/1 =
-1/4 -16/4 =
-17/4 ?

so 4 and 1/3 ?

how do you graph that

[limpid galleon]

Hey

You can graph the line by first trying to get the x and y intercepts

You can perhaps look at the gradient as well

[alpine sable]

ok so x=1

[limpid galleon]

Um where does the graph intercept the x axis?

[alpine sable]

wait -4/4 = 1 -4 = -5

nvm

.close

[lone heart]

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[sour jolt]

How do I solve for A?

[worn fox]

Start by expanding the bracket

[tacit arch]

The emoji is technically parentheses

[pliant cedar]

or use the difference of two squares

[tacit arch]

We need :brackets:

[alpine sable]

What

[pliant cedar]

i thought the emoji was of a horseshoe at first lol

[alpine sable]

There is no difference between the two

Am I missing something

One is more American the other is more British

[serene junco]

in elementary school I was taught that "brackets" refers to square brackets. But that distinction disappeared somewhere along the way

[pliant cedar]

are parentheses specfically the curved ones, and brackets like an umbrella term for square brackets and all other tyoes etc

[alpine sable]

Interesting we call [ ] closed brackets specifically

But parentheses and brackets are synonyms to the same thing ()

[sour jolt]

k
then I will get a^2-a^2-6a+9=117, right?

[serene junco]

a^2 - [a^2-6a+9]=117

You'll want to distribute that negative sign

[sour jolt]

ohh k

then I will get 6a-9=117, right?

[serene junco]

yep

[sour jolt]

k then
i got it. tysm

.close

[lone heart]

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[alpine sable]

Help

[alpine sable]

To put it briefly, I'm having trouble with counting. I've been attempting to count for 10 minutes but I can't seem to get the correct result. Could you help me out?

[limpid galleon]

what are you even doing

[alpine sable]

you understand these numbers above?

with that we will multiply the column of the matrix

[zinc bison]

ohhh, matrixes

[alpine sable]

because we want to get a triangular matrix at the end

so

[limpid galleon]

I am a bit lost honestly

[pseudo ice]

Ah, column operations(!)

[alpine sable]

you multiply the first column by -1 and add it to the second

the first one does not change

[limpid galleon]

Can you show me the whole question

[alpine sable]

the task is to determine the rank of the matrix

I don't need help with that, I can't count this

i know simple stuff

[pseudo ice]

,rccw

[alpine sable]

this is the solution

you understand what the idea is now?

[pseudo ice]

As in you want to get that solution, or?

[alpine sable]

we do column transformations

I want the process how did we get that solution

[worn fox]

P sure they're just getting it into echelon form

[alpine sable]

echelon what?

[pseudo ice]

Then basically what you said here

[worn fox]

Use your first column to kill everything in the first row

And ur basically done

[alpine sable]

and that part is good, solution matches ,frst column , the problem is when I want to get the third, and I get the third by multiplying the second by -4 and adding it to the third column

1*(-4)=-4+4=0

okey that is good but how

if I follow that procedure

then

1*(-4) +0=

-4

the solution is zero

how?

position in the solution picture is 23

where is 0

I think I confused you all

[alpine sable]

I want to see how the professor got 0 and I got -4 for position 23, I won't give up and find other solutions

[pseudo ice]

As in here, you have -4?

[alpine sable]

yes

[pseudo ice]

Remember that here, you're (supposed) to use the first column to zero out the first row (barring the first entry)

Did you use the second column to remove the zero in the 1,3 position?

As that's how I can see you'd get that -4

[alpine sable]

do you want me to briefly write the entire procedure of how the professor did the assignment?it will probably help

[pseudo ice]

Basically, I'm guessing they did:
C2 -> C2 - C1
C3 -> C3 - 4C1
C4 -> C4 - 2C1

From that, because all the other entries of the first column are zero, that doesn't affect any of the other row entries

But that does get rid of all entries (barring the first) in row 1

[alpine sable]

if we talk with numbers, here's how we got the head of the second column:1*(-1)+1=0, 0*(-1)+1=1 and 0 third

can you write me like this how we got the 3rd column

this is how i got third,1*(-4)=-4+4=0,1*(-4)+0=-4? 0*(-4)+0=0

[pseudo ice]

For the third, it's
4 - 4(1) = 0,
0 - 4(0) = 0,
0 - 4(0) = 0

[alpine sable]

where did you get that 0-4(0)?

0

[pseudo ice]

Looks to me as if you used the second column?

[alpine sable]

i used second column

i used second to get third?

[pseudo ice]

Hmmm, well was that your first step? If so, it's better to work with the first column because it's already zero, but if that's your first, you will get:
$$
\pmqty{1 & 1 & 0 & 2 \ 0 & 1 & -4 & 0 \ 0 & 0 & 0 & 0}
$$

[ocean seal]

chartbit

[alpine sable]

by multiplying the second column by -4 and adding it only to the third

[pseudo ice]

Which is fine, but then you still need to get rid of the 1 in 1,3, the 2 in 1,4 and the -4 in 2,3

For that, say if you used the second column again to remove the 2 in 1,4, you get:
$$
\pmqty{ 1 & 1 & 0 & 0 \ 0 & 1 & -4 & -2 \ 0 & 0 & 0 & 0}
$$

[ocean seal]

chartbit

[pseudo ice]

(from C4 -> C4 - 2C2)

Now of course, you want that 1 in 1,2 gone, and anything else wouldn't be helpful, so do $C_2 \mapsto C_2 - C_1$, get:
$$
\pmqty{ 1 & 0 & 0 & 0 \ 0 & 1 & -4 & -2 \ 0 & 0 & 0 & 0}
$$

[ocean seal]

chartbit

[alpine sable]

okey thanx

.close

[lone heart]

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[sullen vortex]

does varied singly just mean I pick a variable to differentiate and treat everything else as constants?

[stuck cape]

i think this question is of physics

[gentle jackal]

I believe yes you would just take the partial derivatives

and treat the other variables as constants

[lone heart]

@sullen vortex Has your question been resolved?

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[alpine sable]

i am not getting question 8 b

[vale wigeon]

do you know in general what the median of a data set is

@alpine sable

[lone heart]

@alpine sable Has your question been resolved?

[alpine sable]

.reopen

[alpine sable]

i have learnt how to apply the formula of median on a raw data this is a table given and the formula specifically isnt working on it

[vale wigeon]

so, you know of a formula that computes something you've been taught is called the "median", but it was never explained to you what the median actually is.

[alpine sable]

they mentions look for the number of days in the middle position for median on a table

[vale wigeon]

...

sorry, i'm a little annoyed that my question was not answered directly.

[alpine sable]

i think i am not sure which formula for median should i use

[vale wigeon]

yeah, so this brings us back to:

do you know what the median IS, outside of any formula you'd use to compute it?

[alpine sable]

the formula of a median that i learnt was (n + 1/2) ^ t term

[vale wigeon]

so you learned it in a PURELY formulaic, and not conceptual, fashion.

[alpine sable]

oh

[vale wigeon]

the median of a data set is the point that appears exactly in the middle when you sort the data in ascending order.

was this ever mentioned in class?

[alpine sable]

i think no that was not mentioned

[vale wigeon]

for shame.

that's very shitty of your teacher to do.

anyway,

[alpine sable]

the teacher explains maths like a story and i understand the concepts

so that i can directly practice and apply those

[vale wigeon]

reposting the data table here for my own convenience

how many data points does this table summarize?

[alpine sable]

there are two data points

one is the number of days and its frequency being the second

[vale wigeon]

no

that's not what "data point" means

a data point in this case is one number reported by one student

[alpine sable]

it should be one or something

[vale wigeon]

so you have 30 data points

the size of your data set is 30

Thirty students were asked ...

[alpine sable]

i get it now

it says at the start of the question

[vale wigeon]

yeah, so now

[lone heart]

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[vale wigeon]

uh

.reopen

[lone heart]

✅

[vale wigeon]

no idea why that happened.

anyway,

[alpine sable]

it was the timeout

[vale wigeon]

how could it have been a timeout when we were talking lmao

anyway the data set has 30 points

so arranging them in order and looking at the middle, we would be looking at the 15th and 16th data points

and the median is their average, by convention

[alpine sable]

so on every table youll have to calculate median the same way?

[vale wigeon]

i suppose i could say yes for your own peace of mind.

[alpine sable]

i didnt get this what do you have to arrange

[vale wigeon]

you sort the data points in ascending order.

[alpine sable]

i mean the frequency onli

[vale wigeon]

in your case

0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 2 2 2 2 2 2 2 3 3 3 3 4 4 5 5

this is what your data set looks like when written out explicitly

[alpine sable]

that is the frequency of every one of days

so this is arranged in ascending order

[vale wigeon]

no

those are

the students' responses

raw

the freq table is a shorthand summary of this

[alpine sable]

is this preferred to do on an exam paper

like writing and arranging in ascending order

[vale wigeon]

i don't know, ask your teacher

i was trying to impart understanding

[alpine sable]

there is no any other way of calculating median

well thank you for explaining it i think i can do this

.close the channel

[lone heart]

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[rough ice]

How can i solve i^2n+1=-i

[rough ice]

Where n is a positive number ^

[strange meadow]

is i the complex number?

[rough ice]

Yes

It’s a imaginary number not complex number lol

[tacit arch]

Is this your equation $i^{2n+1}=-i$

[pseudo ice]

Imaginary numbers are complex numbers

[rough ice]

Complex numbers come in the form of a+bi

Where a is a real number

[pseudo ice]

a=0

[rough ice]

And b is a real number

and u can search it on google too

‘Iota’ is a imaginary number

No -i is the answer

[ocean seal]

riemann

[rough ice]

yea

That’s it

[vale wigeon]

do you claim that "complex number" should refer to ONLY those numbers whose real and imaginary parts are BOTH nonzero?

[tacit arch]

New math meme: Google imaginary number

[rough ice]

Well i do not claim, i just started complex numbers so idk

That’s what they’re teaching us

[pseudo ice]

I mean, I guess I don't know what I'm talking about most of the time 🤷‍♀️

[rough ice]

Can someone help me with my equation?

[tacit arch]

Is n an integer?

Try plugging in a few small integers and see if you find a pattern and come up with a conjecture

[rough ice]

Yea n is a positive number

So i got n=1 for starters

Do i continue to find a pattern

Ok so i got n=1,3,5,7,9…..

[tacit arch]

The main thing is to calculate $i^4$ and use exponent rules

[ocean seal]

riemann

[rough ice]

yea i did that i got an answer

Thanks

.close

[lone heart]

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[spare fern]

could someone help me out with this

[spare fern]

first I multiplied both numerators by 12

giving me 12/3 = 4 and 12/4 = 3

which simplified to 4x > or equal to 3(2x-1)

which is 4x > or equal to 6x - 3

I added 3 to both sides = 4x + 3 > or equal to 6x

then I subtracted 4x from both sides = 3 > or equal to 2x

after dividing both sides by 2 my final answer was 3/2 > or equal to x

[ruby current]

that’s correct

looks like you just input it wrong

[serene junco]

look closely at your choices

[ruby current]

your explanation corresponds to to a different answer

[serene junco]

3/2 ≥ x
and
x ≥ 3/2
are not the same

[spare fern]

yeah I see my bad

must of just clicked it without looking properly

thanks for clarifying

[vale wigeon]

you can write >=

[spare fern]

.close

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[alpine sable]

this is grade 6 math but and im grade 7 but i forgot how to solve it and idk how

[pliant cedar]

if Jean drove for 2 hours at that speed, how far would she have driven?

[alpine sable]

160

[pliant cedar]

yeah

[ruby current]

What about x hours?

[alpine sable]

my calculations say 26.666.66667 minutes

[jade hollow]

show your work

[alpine sable]

80/60 x20

80 divided by 60 is 1.33333333x20= 26.666.66667

[jade hollow]

why will speed x distance give time?

[alpine sable]

speed divided by distance

[jade hollow]

but you multiplied here

[alpine sable]

wdym

oh

[jade hollow]

⁸⁰/₆₀ Is speed
20 is distance

[alpine sable]

so what should it be?

[alpine sable]

yea

[jade hollow]

what is the formula of speed?

[alpine sable]

teacher did not talk about it

its first session

and im reviewing

b4 class

[jade hollow]

it's pretty basic

4th or 5th grade

[alpine sable]

oh

could u help tho

i rlly dont get it

so 80/60 is correct?

@jade hollow

[jade hollow]

no

speed=distance/time
=>time=distance/speed = ²⁰/₈₀ = 0.25 hours or 15 minutes

[alpine sable]

huh

so distance is

80 km

time is 60m

[jade hollow]

??

distance is 20km

speed is 80km/h

[alpine sable]

so it should be

20km = 60?

[jade hollow]

why are you bringing 60 here

calculate it in hours and then convert to minutes since speed is given /hr

[alpine sable]

holy shit

im so stupid

so its 80/20

=4

60 divided by 4

[jade hollow]

no

[alpine sable]

is 25

huh

[jade hollow]

no

it's not 4 hours

[jade hollow]

and no, 60÷4 isint 25

²⁰/₈₀

[alpine sable]

skull

Oh-

i see

tysm

[jade hollow]

time=distance/speed

[alpine sable]

how is 80 considered the speed

and 20 is considered the distance?

[lone heart]

@alpine sable Has your question been resolved?

[spare fern]

Ok, so Raj, the question says Jean drove at a "speed" of 80 km/h, and the question is asking to find how long it took her (in hours) to drive 20 km.

using the formula v = xd/xt

we can rearange this for time which is t = xd/xv

[spare fern]

hence the formula McMystic has sent

plugging in our values ---> 20/80

[alpine sable]

oh ok

thank you

[spare fern]

no problem 👍

[alpine sable]

I almost thought you are the real Lex.

[lone heart]

@alpine sable Has your question been resolved?

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[granite sundial]

Bro what’s 10+1

[sonic egret]

11

[granite sundial]

Thanks bro the teachers about to get our test

Sending good vibes

[hard patio]

Huh?

[lone heart]

@granite sundial Has your question been resolved?

[sonic egret]

.close

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[sterile lantern]

hallo, just having trouble with this elimination problem. 1/2x+2/3y=79/18 and 1/2x+4y=4/3. (not too great with fractions), i know to multiply the second equation by -1, but then im lost from there!

[median osprey]

Coefficient of x is same in both equations, so just solve how you usually do when using elimination method

[sterile lantern]

how would i go about adding 2/3y and -4/1y

[naive valley]

put them over a common demoninator

[sterile lantern]

i need to multiply the denominator of the -4/1y by 3, yes? and then the other numbers as well?

[naive valley]

or just get rid of the denominators

[sterile lantern]

to get rid i can multiply everything by the denominator as well?

(in the equation)

[naive valley]

the first equation you could multiply everything by 6 to get rid of the denoms

oh wait there's an 18

ok multiply everything by 18 then

second one you can just multiply by 6

[sterile lantern]

so it would be multiply by largest common denominator to eliminate fractions?

sorry if this is all basic, math has never been my strong suite- taking a 4 week winterim course rn too lol

[naive valley]

you can multiply by any number that is a common multiple of the denominators

e.g. in the first one your denominators are 2, 3 and 18

so you know you need to multiply by at least 18

and luckily 18 is a multiple of 2 and 3 as well

[sterile lantern]

multiply 18 as well correct?\

[naive valley]

sure, try it

[median osprey]

Take 1/y common

And then add

[naive valley]

is y in the denominator? i assumed not

[median osprey]

Seems like

[sterile lantern]

it is not

[median osprey]

lol

Why are you writing like that then

You should write 2y/3

[naive valley]

or (2/3)y

[sterile lantern]

ah sorry

[median osprey]

2/3y seems like in denominator

[naive valley]

avoids ambiguity

although actually in most programming languages, 2/3y = (2/3)y haha

in math it's just ambiguous

[median osprey]

Like you add or subtract fractions, in other words use LCM

y won't change the rule of addition

It will still be same

[sterile lantern]

right then i end up with my first equation as 9x+12y=79 correct? would i simplify all by 3 then?

after multiplying all terms by 18

[median osprey]

Yes

You got correct equation

Now multiply other one by 18

[sterile lantern]

the second equation?

[median osprey]

You will get coefficient 9 of x

Then subtract

Your problem of fraction will be solved

In both equations you will have integer coefficients of y

But i prefer normal addition of fraction

Instead of this

More easy

[sterile lantern]

a step back or two- i have 3x+9y=79/3 on the first equation. would i simplify 79/3 to 26/1?

[median osprey]

79 is not divisible by 3

Boi

[sterile lantern]

so we keep at 79/3- got it

im sorry man

i really am not a math guy, straight as through hs except for my maths, always a d or c lol

[median osprey]

Why don't you simply do (2/3-4)y

[sterile lantern]

i thought maybe i could write the frac that i can go into 79 with 3 a minimum of 26 times (78) and leave the 1 under

i think i will

[median osprey]

That's already easy

[sterile lantern]

i usually don't try to get rid of fractions

thank you for the help by the way. i greatly appreciate this, cramming for a middterm tomorrow.

[median osprey]

If you want to get rid of fraction and use elimination then you will have to multiply other equation by 18 too

In this case

And then subtract them

[sterile lantern]

okay so instead of ridding fractions im gonna stick to (2/3-4/3)y

[median osprey]

That's good too

Just do what you feel is easy

[sterile lantern]

apologies for the time waste on the getting rid of fractions @naive valley

[median osprey]

Say to the guy above me

I didn't even start this

lol

[sterile lantern]

alright i subtract (2/3-4/3)y to get -2/3(y)

[naive valley]

no worries!

[sterile lantern]

then my equation is 1/2(x)+ -2/3(y) = 79/18

[median osprey]

How did you get 3 under 4

It was only 4

[sterile lantern]

multiply by 3?

i can subtract -2/3(y)- 4(y)?

[median osprey]

(2/3-4)y

[sterile lantern]

-2/2? = -1y?

forgot my y in the 2s

sorry

[median osprey]

No need to multiply divide by anything extra just simply subtract both equations

You will get (2/3-4)y= 79/18-4/3

[sterile lantern]

where did we get the -4/3 on the constants side

ahh i wish i was good with fractions

[median osprey]

I don't know how you got it

[sterile lantern]

.close

[lone heart]

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[lone heart]

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[alpine sable]

How do i know if this is an odd or even function

How can i tell ?

[hollow sparrow]

if f is an even function then :
f(-x) = f(x)
if it's odd then :
f(-x) = -f(x)

[ruby current]

do you mean the periodic extension of this function?

this function doesn't have a definition for negative numbers

[alpine sable]

Yeah

Because its not symmetrical about the y axis

But the answer says it is an even function

@ruby current

[ruby current]

why is it not symmetrical about the y-axis?

[alpine sable]

Cos theres nothing on the other side ?

[ruby current]

you just said we are considering the periodic extension of the function

[alpine sable]

How do i extend the function

To form the other side

[ruby current]

this means that the graph you have drawn repeats to the left and right

the graph is identical over any two intervals of same size length three apart

[alpine sable]

How do i know this from the start tho ?

How can i tell

So it will be like this

What i dont understand is why/how to know its even

@hollow sparrow

[ruby current]

check whether the graph is symmetric about the y-axis

this well tell you that a function is even

[lone heart]

@alpine sable Has your question been resolved?

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[alpine sable]

Where have i gone wrong here

In solving the integral

[lone heart]

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[alpine sable]

Any help appreciated !

[manic jasper]

whats up

[manic jasper]

what you need help with

[alpine sable]

Where have i gone wrong in solving this

[manic jasper]

send the original question

so im able to work it out

[alpine sable]

Question at the top of the page

[manic jasper]

zoom in

[alpine sable]

Integral 1

[manic jasper]

or take a photo of the question in the book or sumin

tyty

[alpine sable]

Nws

[manic jasper]

so the I1 = 2/3)(x)xcos one

[alpine sable]

Thats the answer

?

[manic jasper]

no

thats the question

[alpine sable]

-1/pi

[ruby current]

also, how is this zero?

[manic jasper]

its x sin

3x cant be simplified fully by 3

can be made into x

and then you have sin 2 pi x

[alpine sable]

I have this now is this right so far

[ruby current]

think so

[alpine sable]

Ok thanks

I’ll continue

Got that as the final answer

[ruby current]

can you simplify it further?

[ocean seal]

Mehdi_Moulati

[ruby current]

we need a ,Mehdi_Moulati bot command

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

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[steady basin]

does the probability P(A U B) also contain P(A intersect B)?

[steady basin]

ie does union always contain the intersection?

[rustic ruin]

Yes

[steady basin]

then how come the formula for P(A U B) is P(A) + P(B) - P(A intersect B)

if its subtracting the intersection doesnt that mean it doesnt include it?

[rustic ruin]

Because intersection comes twice in A+B

So we remove one intersection

[steady basin]

oh yh

cuz P(A) plus P(B) already contains the first intersection isnt it?

[vale wigeon]

wording issue

P(A ∪ B), P(A ∩ B) and P(A)+P(B) are numbers.

it is true that $A \cap B \subseteq A \cup B$ for any events $A$ and $B$ (in fact this is just a set-theoretic statement)

[ocean seal]

Ann

[ruby current]

maybe theyre asking whether P(A U B) >= P(A ∩ B)

[steady basin]

wait how does intersection come twice in P(A) + P(B)

[ruby current]

"containment" for numbers

[vale wigeon]

you could say, however, that when you compute $P(A) + P(B)$, you count $A \cap B$ \textit{twice}. and \textit{that's} why you subtract $P(A \cap B)$ to find $P(A \cup B)$.

[ocean seal]

Ann

[vale wigeon]

once from A and once from B.

[steady basin]

yh i see

i see

ok that makes sense

cheers

[steady basin]

yh kl

makes sense

[ruby current]

also a useful exercise to prove that A subset B implies that P(A) <= P(B)

[limpid spade]

bro doing probability now

[steady basin]

got calculus exam next wednesday

then prob stats same week friday

so gonna do prob stats now

why does this method not work for part C?

is it cuz G1 and G2 r not independent?

[vale wigeon]

no, it's because you didn't calculate P(G_2) properly.

it isn't 2/9.

it's not the method's fault.

[steady basin]

oh yh mb

but arent G1 and G2 not independent?

since G1 affects G2

hence we cant use G1 x G2 for the numerator?

[vale wigeon]

notation issue

but also, the numerator is in fact not $P(G_1)P(G_2)$!

[ocean seal]

Ann

[vale wigeon]

it is instead $P(G_1)P(G_2|G_1)$.

[ocean seal]

Ann

[steady basin]

ye nah i get that

i re did it

but how comes G1G2 still works here

is it just by chance?

[vale wigeon]

what do you mean by "G1G2"?

[steady basin]

P(A) x P(B) = P(A intersect B)

where A is G1 and B is G2

[vale wigeon]

again...

the numerator is not $P(G_1) P(G_2)$ !!!

[ocean seal]

Ann

[vale wigeon]

the numerator is $P(G_1) P(G_2|G_1)$ !!!

[ocean seal]

Ann

[steady basin]

k

do u agree with me tho that P(G1) and P(G2) are not independent?

[vale wigeon]

notation issue!!!

yes, G1 and G2 aren't independent. i never claimed they were independent.

[steady basin]

kl

[vale wigeon]

would you like to restate your question again

[steady basin]

what question

i understand now

i re did it

and got 2/9

[vale wigeon]

alright, that settles it then

do you have anything else to ask?

[steady basin]

possibly, im just going over a worksheet and ill drop a msg here if anything else needs to be asked

[vale wigeon]

k

[steady basin]

trying to do part F

why is part (D) and part (E) not independent

asking because im trying to calc P(part D intersect part E)

meant to say trying to do Part F sry

[hollow sparrow]

i guess because part (E) include part (D)

[steady basin]

possbily

[vale wigeon]

D ∩ E = D, though.

part F asks for P(D | E).

[steady basin]

yep

ok

so p(d) / p(e)

[vale wigeon]

uppercase, but yes.

[steady basin]

for this i did P(Binge intersect watches MES)

*intersect sry

but what would P(B given MES) be?

[vale wigeon]

well, P(MES | B) = 0.4

so you can calculate P(B | MES) with bayes' theorem if you so desire...

...or you could calculate P(B & MES) as P(MES | B) P(B)

and save yourself a bit of work

though P(B) will take a bit of work to calculate still

[steady basin]

thats 0.2 no?

literally given in the question

[vale wigeon]

oh, wait. hm.

that's right

i thought the second 20% might have been P(B|TA)

[steady basin]

from just reading the question, how did u understand from the text that P(MES given B) is = to 0.4 and not P(B given MES) is 0.4?

[vale wigeon]

the relevant sentence can be rephrased as "When Jeremiah binges, 40% of the time it's with MES."

[steady basin]

when i do stats/prob questions, its the wording of the sentences that throws me off

[vale wigeon]

sometimes it might be the question's fault.

[steady basin]

when i read the question, i thought the answer would straight up be 0.4

which is obv wrong

part D im struggling

.close

[lone heart]

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[undone hollow]

How and why does the bounds change in this step? Both upper and lower bound has halved. Is this related to the 2 that got factored out?

[ornate condor]

halved?

isnt it sqrt

its change of var

so weve to accordingly change each lower upper bound

as they did

[acoustic mirage]

During the substitution put the value of x in the equation
I.e.

U = root(4) = 2 (lower limit)
U = root(9) = 3 ( upper limit)

[lone heart]

@undone hollow Has your question been resolved?

[lone heart]

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[runic forge]

do you guys think this question is wrong as a whole in itself?? the 50 degrees is given to an angle over 90

[boreal verge]

what do you need to figure out?

[wary stream]

*Not to scale

[runic forge]

is this much correct?

y = 100

[boreal verge]

i dont think there's a way to exactly determine y and x separately

since we only know 2 angles you can find their sum

[runic forge]

i extended the lines at the top

[boreal verge]

ohh wait theyre paralel?

[runic forge]

yea

[boreal verge]

yea yea you can do it

[runic forge]

thats why extending it is possible

is the work for y correct?

[boreal verge]

well yes y is 100

[runic forge]

do the sum of all interior angles for a quadrilateral equal 360?

[manic jasper]

well it has 4 sides

[runic forge]

alr so i can basically do 360 - 80 - 100 - 50 to find x, correct?

[manic jasper]

yes

[runic forge]

it equals 130 but the angle is an acute angle as we can see

[boreal verge]

for all convex ones yes

[wary stream]

You can find the sum of interior angles for any shaped based on the formula s = (n - 2) * 180, where n is the number of sides

[wary stream]

*Not drawn to scale

[runic forge]

oh

so is my answer correct, y = 100, x = 130?

[manic jasper]

yes

[hollow sparrow]

look at 50°

[runic forge]

oh

[boreal verge]

doesnt that apply only to regular polygons

[runic forge]

its obtuse but 50

weird

[wary stream]

No

[manic jasper]

nop any shape

[runic forge]

tysm

.close

[lone heart]

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[manic jasper]

sound have a good day/night

[boreal verge]

ohh ty

[hollow sparrow]

what about a circle

[manic jasper]

scary shape

[boreal verge]

what about a torus' surface

[hollow sparrow]

he said any shape so

[lone heart]

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[red loom]

how do i get better a powers

[wary stream]

What exactly are you asking?

[ruby current]

better at dealing with powers (exponents)?

[red loom]

like that

same with square and cube

hello

[ruby current]

do you have a specific question?

[ruby current]

what are you trying to do?

[boreal verge]

in latex?

[red loom]

ok sorry

and just questions

[red loom]

show you

and i just need help

[ruby current]

i mean with 7^9

are you trying to compute it mentally?

[red loom]

yes

[ruby current]

this is a very large number

[red loom]

its an example

i want to start with low numbers the go to high

i know some answers in cube, square and power like 5^5 = 3125 68^2 = 4624 20^3 = 8000

[ruby current]

don't think much can be done to make these easier except potentially factoring the base

so 8^2 = (2^3)^2 = 2^6

[red loom]

ok that's fine bye

[ruby current]

see you later

[red loom]

bye

[ruby current]

Type the command .close to free the channel when you're done.

[red loom]

by the way how do I quit this

.close

[lone heart]

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[waxen osprey]

which question do you need help with?

[fringe token]

How is vB even conformable?

v has dimension nx1 whereas B is nxp

[worn fox]

v is a row vector, has dimension 1xn

[waxen osprey]

v is a vector so we can view it as a 1xn matrix in general we can multiply mxn matrices with nxp matrices

[fringe token]

My bad

Thanks

.close

[lone heart]

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• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

quick question about DFTs, according to what i read online, DFT converts a finite list of equally spaced samples of a function into the list of coefficients of a finite combination of complex sinusoids, ordered by their frequencies, that has those same sample values.

\vspace{3 mm}
But from what i also learnt, the DFT matrix would end up taking vectors of some coefficients $(c_0, c_1,...c_n-1)$ as input and then produces a vector of $(f(0),f(2\pi/n),...,f((n-1)*2\pi/2)$

\vspace{3 mm}
so you will have $f(x) = c_0 + c_ 1e^{(ix)} + ... + c_{n-1}e^{((n-1)ix)}$

[alpine sable]

but how does that make sense, the description i said at the beginning wouldn't be describing that would it

[waxen osprey]

Okay so

[ocean seal]

♡LexQa♡

[alpine sable]

actually it seems to be describing the IDFT matrix instead

[waxen osprey]

Discrete Fourier transform is basically trying to find the fourier transform using discrete points. You take sampling using nyquist frequency (because of Sampling theorem) and then you get a DFT matrix which looks like the roots of unity

so you do get something looking like that in fact

idk what a IDFT is but yh

[alpine sable]

inverse discrete fourier transform

[waxen osprey]

oh but the inverse and DFT look very similar

its just the +- signs in the power i think

[alpine sable]

yeah i am just confused

[waxen osprey]

what are you confused about

[alpine sable]

because there doesnt seem to be any like

set rule on where it would be +- for example

[waxen osprey]

do u want me to go throuygh the derivation

[alpine sable]

sure