#help-0

1 messages · Page 99 of 1

royal plank
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A and all not A

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combined

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is everything

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not A

lucid depot
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ok but that's what i did

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i made it u

royal plank
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no

lucid depot
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then i neglected the u

royal plank
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you probs misswrote

lucid depot
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is that on the left?

royal plank
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yes

lucid depot
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oh

royal plank
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left the line right after

lucid depot
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but that's not a union complement a

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that's a union a

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i have not once wrote a complement there

royal plank
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oh sorry

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it was hard to read

lucid depot
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btw if you find explaining it complicated we can hop into voice chat and you lead me through the solution

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if that's ok with you

royal plank
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no, i have no mic here

lucid depot
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ok that's a better picture

royal plank
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anyway, in that exact line, you can just remove A

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proof in a sec

lucid depot
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if you can solve it and compare your solution with mine

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okay

royal plank
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its the
A split (A union B) = A rule thingy

royal plank
lucid depot
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picture is loading

royal plank
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alternatively you could've just eliminated A from the first line

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since

lucid depot
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ooooooh

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got it

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thanks man

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.close

lone heartBOT
#
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quartz cave
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If I get all the successors of a given variable in a probability graph

quartz cave
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Do I then have all variables that contain that parent variable in their conditional probability table?

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It cannot appear anywhere else right?

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blazing grail
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What is this task?

lone heartBOT
royal plank
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that funny symbol before (k)

blazing grail
royal plank
blazing grail
#

I think I can manage it, haven't started yet as I didn't know what this was, but thanks!

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dull phoenix
#

I set the X on my calculator to -10000 but I want the X to represent the variable X when putting it into a function since I want to write X as an exponent (^X). How do I turn X = -10000 to X = a normal X?

dull phoenix
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Calculator TI-84

noble sinew
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Don’t set X=-10000 then?

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If you are asking how to revert that for example just system reset or whatever it is called

dull phoenix
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I did but nothing changed

dull phoenix
noble sinew
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Google clear variable ti-84

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And follow instructions

dull phoenix
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okey now it worked, I had to clear the memory of the calculator but it just set X = 0

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which isn't optimal

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I'll just google

noble sinew
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Google can answer most questions and should really be a 1st step

dull phoenix
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okey I just reset the whole calculator to factory new

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thanks

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.close

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sharp peak
#

the drawing shows a sketch of the graph of the function f(x)= ln(ax)/x. g(x)= -ln(ax)/x, when a > 1. Pass a straight line through the extreme points of the two functions f(x),g(x). the area bounded by the straight line, by the graphs of the two functions and by the line x = e, equals to (ln(2e))^2 -1. find the equation of the line that passes through the point of inflection of f(x) and through the inflection point of g(x). please help whoever's got free tim

woeful pulsar
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have your drawn the area?

sharp peak
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yes ill show you

woeful pulsar
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hmm so inflection point is when second derivative is 0

sharp peak
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im struggling to find the area

woeful pulsar
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can you write it as an integral?

sharp peak
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yes one moment

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?

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marble prawn
lone heartBOT
marble prawn
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plz help

woeful pulsar
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do you remember what nabla^2 is

marble prawn
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what do you mean? this is the whole question

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plus nabla^2 is a set equation

woeful pulsar
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yeah, but do you recall the definition of nabla^2

marble prawn
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yeah its the laplacain

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laplacian

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polar coords

woeful pulsar
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In mathematics, the Laplace operator or Laplacian is a differential operator given by the divergence of the gradient of a scalar function on Euclidean space. It is usually denoted by the symbols

    ∇
    ⋅
    ∇
  

{\displaystyle \nabla \cdot \nabla }

,

...

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apply definition directly

marble prawn
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yeah i know that, its not that easy

woeful pulsar
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what have you tried so far

marble prawn
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i just dont know how to sub and apply the given f

lone heartBOT
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light flame
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Hey guys, you can say anything about me but pls let me help with my math I don't really get it.. I'm a slow learner

light flame
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I failed dnd I don't wanna fail this time again

lucid socket
light flame
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Bro

obtuse mango
light flame
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This is the question

light flame
obtuse mango
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This is quite straightforward

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but I am shitass at explaining

lucid socket
obtuse mango
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post in free channels

obtuse mango
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lets treat x^2+y^2=27 as 1 (1st equation)

light flame
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Okay

obtuse mango
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and 2x-y=3 as 2nd equation

light flame
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So I'm gonna answer the first equation

obtuse mango
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so u can see that x and y is squared in equation 1 right?

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so square all the numbers on the 2nd equation to get x^2 and y^2

obtuse mango
light flame
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Ok hold on

obtuse mango
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aight no worries

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Im waiting for help myself ahahaha

light flame
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I have solve that actually but it different

obtuse mango
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oh cool

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what did u do? im curious

light flame
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ok so

void solar
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You guys got this?

obtuse mango
void solar
light flame
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So first I solve the equation for y

obtuse mango
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cheers!

obtuse mango
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did u substitute?

light flame
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And move the variable to the right handed side and change its sign

void solar
obtuse mango
light flame
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And change the signs on both sides of the equation

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That will get

obtuse mango
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oh ok cool!

light flame
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y = - 3 + 2 x

obtuse mango
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ahh nice

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i actually did that once but I got marked down 😦

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so I had to do the square method instead

light flame
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And then substitute the given value of y into the equation

obtuse mango
light flame
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8

obtuse mango
light flame
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So it x^2 + ( - 3 + 2x)^2 = 27

obtuse mango
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xD

light flame
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Am I right

obtuse mango
void solar
obtuse mango
obtuse mango
void solar
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Finished yr12 vce

obtuse mango
void solar
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Yep

light flame
obtuse mango
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oh cool! from west aus ahaha

obtuse mango
obtuse mango
void solar
obtuse mango
obtuse mango
light flame
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Ye thx

obtuse mango
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so for this you have to expand (-3+2x)^2

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have u learnt factorising polynomials

light flame
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I'm confused but what I first did

obtuse mango
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about>

light flame
obtuse mango
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Oh oof

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ahh crap mums telling me to go to bed :/

light flame
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oh it fine

obtuse mango
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I have to go

light flame
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You can sleep

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Bye

obtuse mango
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cya

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hope u get help with ur question

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Or search up an app called Photomath

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dont use it all the time though

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use it to check ur answers

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it has all the steps

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peace man

light flame
void solar
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I can step in

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What part are you stuck at

void solar
lone heartBOT
#

@light flame Has your question been resolved?

lone heartBOT
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viscid silo
#

a . b . c are real number no nul whit ab +ac + bc = 0
Show that a+b/c + a+c/b + b+c/a =-3

slender gull
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Do you mean (a+b)/c + (a+c)/b + (b+c)/a

viscid silo
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Yeah

slender gull
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So to add these you have to take LCM.

viscid silo
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Ok

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I already did that

slender gull
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And?

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If you've already attempted something, why would you not show your attempt first thing?

viscid silo
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But i didn't continue

alpine sable
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why not

gray isle
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doesn't matter

viscid silo
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Lemme send what i did

viscid silo
scenic socket
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Hello! I'm not sure exactly if I should be answer part a) with a hypothesis/conclusion format or simply a formalized format.. Also for part b) I am totally lost on how to prove this

lone heartBOT
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boreal verge
#

hey can anyone check my work cause this was kinda confusing and im not sure i did it right

lone heartBOT
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Please don't occupy multiple help channels.

boreal verge
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oh right l

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forgot i had that one open

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if x is 0 it would just be $1 + 2 + 3 + ... + n \ge 59 => \frac{0(0-1)}{2}+\frac{n(n+1)}{2} \ge 59
=> (n)(n+1)\ge 118 =>n²+n \ge 118\\vdot\
\vdot\
\vdot\$
if x is 2, it would mean $|2-1|+|2
-2|+|2-3|+...+|2-n| = 1 + 0 + 1 + 2 + 3 + ... + |3-n| = \frac{2(2-1)}{2} + \frac{|3-n|(|3-n|+1)}{2}\
\vdot\
\vdot\
\vdot\$
for a general scenario, it could be interpreted as 2 sums, one of x-1 terms and one of n-x+1 terms (the +1 being the case where x = n)

therefore, a general formula would be:
$|x-1|+|x-2|+...+|x-n| = \frac{x(x-1)}{2} + \frac{|x-n|(|x-n|+2)}{2}=\frac{x(x-1)+|x-n|(|x-n|+1)}{2}$

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i wanted to rewrite the sum |x-1|+|x-2|+...+|x-n|, where x is any real number and n is any natural number

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tried induction and noticing some things in regards to how the sum behaves when x increases

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and i assume it applies when x is decreasing as well

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its just that with a minus in front

ocean sealBOT
#

Kel.plush

hollow lodge
#

The steps you have taken to derive a formula are generally correct, but there are a few errors in the final formula you have given. The formula you have given is not correct because the first term of the sum, $|x-1|$, is not being included in the formula. Also, the second term of the formula, which should represent the sum of the remaining terms, is not correct.

The correct formula for the sum of the absolute values of the numbers from $1$ to $n$, where $x$ is an integer between $1$ and $n$, should be as follows:

$|x-1| + |x-2| + |x-3| + ... + |x-n| = |x-1| + \frac{(n-x)(n-x+1)}{2}$

This formula is derived as follows:

The sum of the absolute values of the numbers from $1$ to $n$ can be split into two parts: the sum of the absolute values of the numbers from $1$ to $x-1$, and the sum of the absolute values of the numbers from $x$ to $n$. The first part is simply equal to $|x-1|$ because the absolute value of a positive integer is just the integer itself. The second part is a bit more complicated, but can be derived as follows:

$|x-1| + |x-2| + |x-3| + ... + |x-n| = |x-1| + (|x-n| + |x-(n-1)| + |x-(n-2)| + ... + |x-1|)$

We can rewrite the second part of the sum as follows:

$|x-1| + (|x-n| + |x-(n-1)| + |x-(n-2)| + ... + |x-1|) = |x-1| + (|x-n| + |n-x| + |n-1-x| + ... + |1-x|)$

Now, we can see that the sum of the absolute values of the numbers from $x$ to $n$ is simply the sum of the integers from $1$ to $n-x$, which is equal to $\frac{(n-x)(n-x+1)}{2}$. Therefore, the final formula for the sum of the absolute values of the numbers from $1$ to $n$ is as follows:

$|x-1| + |x-2| + |x-3| + ... + |x-n| = |x-1| + \frac{(n-x)(n-x+1)}{2}$

ocean sealBOT
#

MeatBagFrank

boreal verge
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oh alr

#

ty

hollow lodge
#

np bro

lone heartBOT
#

@boreal verge Has your question been resolved?

lone heartBOT
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void canyon
lone heartBOT
iron widget
#

your answer true

void canyon
#

nice

iron widget
#

7 units down

void canyon
#

is this right

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i think it is

last ether
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It's just finding the change in x and change in y

void canyon
#

like 90% sure

last ether
#

Is this homework

iron widget
#

@void canyon if your x coordinates increase or decrease you can go left or right

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y coordinates increase or decrease you can go up or down

void canyon
void canyon
iron widget
#

true

void canyon
#

last one

iron widget
#

true

alpine sable
lone heartBOT
#

@void canyon Has your question been resolved?

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shell cloak
#

Hey there,
I'm currently trying to figure out how to do a Progressive Calculation in Context of the Etsy Marketplace. The goal is to be able to easily calculate for what price I need to list a product to be profitable.

However, Etsy calculates their fees in a very cross-linked way, so it is grilling my brain right now. Due to the cross-linking, I don't even know whether it's possible, but you can prove me wrong ^^
The Retrograde Calculation has worked fine (See right side of the sheet).

Note, this isn't the entire calculation, but the relevant part, for this question

Note, I've marked all base values with the purple arrows (e.g. The base value of VAT is Net Etsy Selling Price)

Retrograde Calculation: $9,98 -> ?Selling Price
Progressive Calculation: $5,88 -> ?Gross Etsy Selling Price

cheers

ocean sealBOT
#

BennoDev

Hey there,
I'm currently trying to figure out how to do a **Progressive Calculation** in Context of the Etsy Marketplace. The goal is to be able to easily calculate for what price I need to list a product to be profitable.

However, Etsy calculates their fees in a very cross-linked way, so it is grilling my brain right now. Due to the cross-linking, I don't even know whether it's possible, but you can prove me wrong ^^
The Retrograde Calculation has worked fine (See right side of the sheet).

**Note**, this isn't the entire calculation, but the relevant part, for this question

**Note**, I've marked all base values with the purple arrows (e.g. The base value of `VAT` is `Net Etsy Selling Price`)

**Retrograde Calculation:** `$9,98` -> `?Selling Price`
**Progressive Calculation:** `$5,88` -> `?Gross Etsy Selling Price`

cheers
lone heartBOT
#

@shell cloak Has your question been resolved?

lone heartBOT
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@shell cloak Has your question been resolved?

lone heartBOT
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fluid flame
lone heartBOT
fluid flame
#

Hi i need help making a curved line for this

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best i could do was y = 1000x^-1

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or 1000/x = y

peak python
fluid flame
#

i didnt learn integrals or any form of calculus yet

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b r e h

last ether
last ether
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Wait it follows a very distinct pattern

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Lol each y value gets halved

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That's just 2000(0.5)^x

fluid flame
#

That's it?-

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B r u h

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no way that's it

last ether
#

$$A_0(r)^x$$

$A_0$ is the initial, (when $x = 0$), and then $r$ is the rate

ocean sealBOT
#

Umbraleviathan

last ether
#

A_0 is 2000

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And then it gets halved every time so

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r = 1/2

fluid flame
#

Oh that's neat!

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i didn't know

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thanks for your help dude!

last ether
#

Np

peak python
last ether
#

Dude stop

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This ain't your channel

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Get your own

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@fluid flame are you done?

peak python
#

bro it aint showing one

last ether
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There's legit 3 available

fluid flame
#

Oh yeah

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Im done

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sorry forgo to close

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.close

lone heartBOT
#
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fluid flame
#

Thanks again!

lone heartBOT
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snow orchid
lone heartBOT
#

Please don't occupy multiple help channels.

snow orchid
#

help please

#

i found

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14 x^6 -4y - y' *4x-21 y^2 y'

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<@&286206848099549185>

elfin tendon
#

i think you just need to find the first derivative like you did and substitude x for -2 or f`(x)= 2

lone heartBOT
#

@snow orchid Has your question been resolved?

snow orchid
#

is this equation = 0

#

@elfin tendon

#

can you tell me the result i cant understnad

lone heartBOT
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alpine sable
#

how do you use partial fraction decompositon

alpine sable
#

for this

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how to integrate this

echo socket
#

Did you mean to write x instead of t?

alpine sable
echo socket
#

Factor the polynomial in the denominator by first noticing that x = 1 is one of its roots

#

After doing long division you should be able to discover that x = 1 is actually a double root, making the polynomial eventually equal to (x - 1)^2(x^2 - x + 1)

alpine sable
echo socket
#

Do you know how to do long/polynomial division?

alpine sable
#

little bit

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i can try

echo socket
#

Try dividing x^4 - 3x^3 + 4x^2 - 3x + 1 by x - 1

alpine sable
#

1-x

echo socket
#

1 - x = -(x - 1)

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Dividing 1 - x by x - 1 yields -1

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So, did you get x^3 - 2x^2 + 2x - 1 as the quotient?

alpine sable
#

yess

echo socket
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And, clearly, x^3 - 2x^2 + 2x - 1 has a root at x = 1

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Meaning you have to divide by x - 1 again

alpine sable
#

the quotiont right?

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also meanwhile, how do you understand which has what root?

echo socket
#

Guess and check, usually I try out x = -1 and x = 1

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If those don't work, try x = -2 and x = 2

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But I don't go further than that most of the times

alpine sable
#

ohhh

echo socket
#

Or, if the coefficients of the polynomials are all integers, you may wanna look at the rational root theorem

alpine sable
#

ohhhhh thankss

#

also i got the second root

#

x^2-x+1

echo socket
#

Did you get x^2 - x + 1?

#

Alright, x^2 - x + 1 actually has no roots so the factoring is done

#

x^4 - 3x^3 + 4x^2 - 3x + 1 = (x - 1)^2(x^2 - x + 1)

#

(x - 1)^2 is squared because we got x = 1 to be the root twice

alpine sable
#

ohhhh i see

#

may i ask why we took x-1 to divide?

echo socket
#

If x = a is a root of polynomial P(x), then (x - a) is a factor of P(x)

#

So P(x) is divisible by that

alpine sable
#

ahhh

alpine sable
#

can you help me undestand why it got written as such?

#

we have the root, but how did it got subtracted

#

<@&286206848099549185>

hazy cloak
#

if you try to go backwards, ie cross multiply and subtract you will see you are getting your previous line

#

like 1/n(n-1) = (n+1-n)/n(n-1) = 1/(n-1) - 1/n

alpine sable
hazy cloak
#

look at the numerator, it is 1, you can write 1 as 1+n-n

alpine sable
#

ohhhh yea i got it now

#

you cancel both

hazy cloak
#

yess

alpine sable
#

ahh thanksss!!

alpine sable
#

by the way you mentioned?

hazy cloak
#

let me try and write it down

alpine sable
#

oh wait i got it, add aand subtract (x-1)^2

#

expand (x-1)^2+x and it doesnequate to that

#

thanks alott man

hazy cloak
#

i wrote it very roughly i hope you understand

hazy cloak
alpine sable
#

finally ahaha

#

really appreciate it

#

.close

lone heartBOT
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hot delta
lone heartBOT
hot delta
#

where did i go wrong ?

golden geyser
#

this is matrix/eigenvalues?

abstract fractal
#

I would double check how you distributed

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hot delta
#

thx

lone heartBOT
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opal imp
#

ok so i'm doing a math assignment due on November 12th on mortgage and finance where i am given a scenario about buying a house and have to do payment calculations using a TVM solver. i need to know which is the best interest rate from each mortgage term as well. If someone can help me and check out the assignment i would greatly appreciate it

vital sail
# opal imp ok so i'm doing a math assignment due on November 12th on mortgage and finance w...

To determine which is the best interest rate from each mortgage term, you will need to consider a few factors, such as the total cost of the loan, the monthly payment amount, and the length of the loan term. You can use a TVM solver, which is a tool that allows you to input different values for the interest rate, loan amount, and loan term, and then compute the monthly payment and total cost of the loan. By comparing the results for different interest rates, you can determine which rate offers the best combination of monthly payment and total cost for your specific situation.

opal imp
#

jus the price of the house and the downpayment

#

with different interest rates for a fixed-rate mortgage (for 1, 2 and 5 years) and i gotta find out which one is the best from each

#

3 different banks too

#

it's confusing 😭

#

@vital sail

lone heartBOT
#

@opal imp Has your question been resolved?

lone heartBOT
#

@opal imp Has your question been resolved?

lone heartBOT
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@opal imp Has your question been resolved?

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abstract sorrel
#

If there are 5 different candies in a jar and a child wants to take out one or more candies, in how many ways can this be done?
Combination

abstract sorrel
#

Nvm got it

#

.close

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quiet blade
#

I solved this problem but I'm not sure if I did the bounds correctly. I assumed since you need to make the bounds with respect to z, y, and x, I would just set them to 0 but I'm not sure if that is a correct assumption.

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primal galleon
lone heartBOT
primal galleon
#

how do they get 1<x<2?

wanton tusk
#

(x-1)(x-2)(x+1)<0

#

sketch a rough cubic graph

#

ull be able to see why

primal galleon
#

why (x-1)(x-2)(x+1)

#

isn't it (x-1)(x-2)

#

the numerator is (x-1)(x-2)

#

and denominator (x-1)

plain flame
#

its because negative times positive is negative

primal galleon
#

$$\frac{x^{2}-3x+2}{x+1} <0\Leftrightarrow \left( x^{2}-3x+2<0\ \wedge x+1>0\right)$$
$$\vee \left( x^{2}-3x+2>0\ \wedge \ x+1<0\right)$$
$$\Leftrightarrow \left( x^{2}-x-2x+2<0 \wedge \ x>-1\right)$$
$$\vee \left( x^{2}-x-2x+2>0\ \wedge \ x<-1\right)$$

#

This is my understanding so far.

#

$$x^{2}-x-2x+2\Leftrightarrow x\left( x-1\right) -2\left( x-1\right) \Leftrightarrow \left( x-2\right) \left( x-1\right)$$

ocean sealBOT
primal galleon
#

But how do you turn (x-2)(x-1) to 1<x<2?

gray isle
#

consider the graph of y= (x-1)(x-2)

#

a rough sketch with x-intercepts and correct concavity is sufficient

primal galleon
#

,w graph (x-1)(x-2)

primal galleon
#

i don't have access to a graphing calculator on the exam

gray isle
#

don't need one

primal galleon
#

so i write (x-1)(x-2) = 0

gray isle
#

a rough sketch with x-intercepts and correct concavity is sufficient

primal galleon
#

find the x-intercepts

wanton tusk
#

the shaded area

primal galleon
#

how do we know it's a third degree polynomial

wanton tusk
#

we have 3 x’s multiplied

primal galleon
gray isle
#

you can multiply both sides by (x+1)^2, (a non-negative value) which leads to the third line

wanton tusk
#

yepp

gray isle
#

the work just posted was more efficient approach

#

the question you were initially asking is very similar

#

your quadratic

(x-1)(x-2)
is in factored form, you should have no issue identifying the zeros
and concavity

#

i don't have access to a graphing calculator on the exam
don't need one
a rough sketch with x-intercepts and correct concavity is sufficient
your sketch could be as horrid and bare bones like

primal galleon
#

the zeros won't change if it's <0, >0, or =0 right?

gray isle
#

and from that very rough sketch

#

you should be able to see when the curve is less than zero and when its greater than 0

primal galleon
#

so the area of the curve under the abscissa is when (x-1)(x-2) < 0?

gray isle
#

whut

primal galleon
#

the x-axis

gray isle
#

what's this about area

primal galleon
#

is this (x-1)(x-2) < 0?

gray isle
#

its not really about area

#

but the part of the curve itself

primal galleon
#

okay

#

soo

  1. find the zeros
  2. from there, identify when the graph is below the x-axis
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#

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fast shell
#

hi

lone heartBOT
fast shell
#

in Applied Optimization whats the difference between the objective and the constraint

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#

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@fast shell Has your question been resolved?

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@fast shell Has your question been resolved?

gusty gorge
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mellow grail
#

Construct a sector AOB with angle AOB equal to 45 deg. Now, create an angle bisector that bisects AOB and the arc AB. Finally, extrude the bisector to point C, so that OC = 20 units. Then construct a semi-circular arc ACB. Find ACB, and the arms of the sector OA and OB

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#

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alpine sable
#

Please help to calculate the Fourier transform of the function f(x) = sin(2π10x)

naive valley
#

i assume you're meant to do this in terms of dirac deltas?

naive valley
alpine sable
#

no

naive valley
#

what fourier transforms do you know?

alpine sable
#

<@&286206848099549185>

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#

@alpine sable Has your question been resolved?

alpine sable
#

.close

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gaunt depot
#

A math olympiad problem, i got problems with

gaunt depot
#

i tried to do this by using tan as a a,b,c

#

and it seems working but i cant progress i dunno why

#

Udowodnij że means- prove

alpine sable
#

how do you find what part is 225 of 2000

lone heartBOT
#

@gaunt depot Has your question been resolved?

gaunt depot
alpine sable
gaunt depot
#

but its not my problem

#

or i dont see it

#

<@&286206848099549185>

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#

@gaunt depot Has your question been resolved?

dim temple
#

hi

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#

@gaunt depot Has your question been resolved?

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forest coyote
lone heartBOT
forest coyote
#

can someone please tell me the answer??

#

<@&286206848099549185>

alpine sable
#

We cannot give you the answer. But we can help/guide you to it

forest coyote
#

yup that will do

alpine sable
forest coyote
#

ohh sorry im just in a hurry beacause i still have to review😓

alpine sable
# forest coyote

Well, we can start with the first one. The domain describes the input values (the x's) for the function, do you know how to discern the x values for a function from its graph?

forest coyote
alpine sable
#

yeah thats okay

#

lets start off with the first dot

#

Do you see that horizontal axis in the middle labelled as 'x' in the far right? @forest coyote

alpine sable
#

That's called the x-axis and it tells you the values of your x values, the labelled numbers on that axis are those values

alpine sable
#

x = -2, for example would be this point

#

we are speaking strictly one dimensionally here though, so ignore the vertical axis for now

forest coyote
#

okay following🤍

alpine sable
#

alright, so do you see all of those black dots?

forest coyote
#

yes

alpine sable
#

i want you to look at them and look at the correspondent x value of that point

#

so for example

forest coyote
#

-3 -2?

alpine sable
#

this black dot is at the point x = 2 (again we are only concerned with the x values for now)

alpine sable
#

exactly

forest coyote
#

ohh okay🤩

alpine sable
#

can u tell me where all of the rest lie?

forest coyote
#

-3 -2 -1 0 1 2 3

alpine sable
#

yep! you are doing amazing good job

#

okay, so those x values you just listed down are what we call the domain of the function

#

think of the domain as, ALL of the x values on that graph

#

if that makes sense

#

so your domain of that function would be the x values of -3, -2, -1, 0, 1, 2, 3

#

please tell me if u r confused at all at any point btw

#

is it alright so far?

forest coyote
alpine sable
#

but i am unsure because i dont think i have used that term in a long time 😅

forest coyote
alpine sable
#

okay so like, here is where i need your help a bit

forest coyote
#

owkey!

alpine sable
#

i need to ask from you how exactly would you write a set or domain, if you were asked to write down one

#

if you dont know thats fine, but then we kinda have to talk about something else for a bit

forest coyote
#

{(-3, -2, -1, 0, 1, 2, 3)}

#

like this?

alpine sable
#

yep! that sounds good to me

#

good job, thats ur domain of the function

#

now, lets talk about the range

forest coyote
#

ohhh well i thought it was going to be hard😅

alpine sable
#

Nope! u already got it hahaa

#

now, we have to find the range

#

u see what we did with teh domain and the x values? well we are going to do the same exact thing

#

but now, we are doing it for that vertical line, thats called the y-axis

#

is this okay with u so far? @forest coyote

forest coyote
#

yesss!!

alpine sable
#

okay! thats great

#

Okay, so the domain describes the x values or the "inputs" of that function

#

the range describes the y values or the "outputs" of that function

#

it goes like this, think of it

#

x -----> function -----> y

#

the function is just this like, fancy machine, that converts your x to a y, if that makes sense

#

well anyways

alpine sable
#

for the graph, this point would have y = 1

#

for example

#

you see how it is x = -3, and y = 1 at the same time?

forest coyote
#

okay then it is the range?

alpine sable
#

yep! thats a part of the range

#

can u try to tell me what the rest are going to be?

forest coyote
#

so basically if the set is (-3, 1) (-2,-1) the domain is -3 and -2 then the range is 1 and -1?

alpine sable
#

if the function is like, just those two points

#

then yeah

#

thats it

forest coyote
#

ohhhh

alpine sable
#

but thats a very small function haha, functions usually are huge and go on forever, and we are going to see that in a bit

alpine sable
#

like, just list off the y values

#

for the points

forest coyote
alpine sable
#

yep!! you are actually doing fantastic, good job

#

okay so here is the thing, actually

forest coyote
alpine sable
#

in sets (if you dont know what that is, just think of the domain and range for now) repeated numbers don't matter

#

like

#

you wrote down -1 twice right? because it appeared twice right?

#

actually u can just write down a single -1

forest coyote
alpine sable
#

yep! but can u write out the range properly now?

#

like how u did with the domain earlier

forest coyote
#

{(1, -1, -2, 2, 0)}

alpine sable
#

amaaaaaaaazing

#

woooohoooo

forest coyote
#

yey!

alpine sable
#

you are done! for the first question

#

now we can move on for the second question

forest coyote
alpine sable
#

okay before we get into the second question, i want to mention a few important things first

#

do you notice how we have arrows at the red parts, but just a dot at the yellow part?

#

do you know the difference between the arrow and the dot?

forest coyote
alpine sable
#

mm alrightyy

#

so basically, there are three types of lines

#

one is called a segmented line, the second a ray, and the third just a "line" actually haha

forest coyote
alpine sable
alpine sable
alpine sable
forest coyote
alpine sable
alpine sable
# alpine sable

a "line segment" is actually probably what you refer to as a "line" normally in your mind

#

a line segment is just a line from like one point to another

#

it has a specific length

#

like 4, 5, 6 whatever it may be! but we know how long it is

forest coyote
#

ohhh

alpine sable
#

thats the reason it begins with a dot and ends with a dot

#

it has like a starting point and an end point

forest coyote
#

ohhhhhhh that makes sense

alpine sable
#

now, with a ray, things are a bit different

#

we have a "Start" point

#

but like, if u notice, at the end we have an arrow instead of a point like we did with a line segment

#

the little "Arrow" actually means that the line...continues on forever!

#

it has a starting point, but it never stops

forest coyote
alpine sable
#

like we had with a line segment

forest coyote
alpine sable
#

like u can continue drawing it forever in the direction where it is heading

alpine sable
#

yep!

#

like here

#

i exteded it a bit, but it really does just go on forever

#

in the direction that it is shown

forest coyote
#

ohhh i see i get it

alpine sable
#

yep!

#

okay here is the thing, thats all fine and dandy, but now for the "line"

#

it is kind of like the same story as a ray, buuuuut, it actually doesnt begin anywhere either

forest coyote
#

an infinite line then

alpine sable
#

it doesnt have a beginning point neither does it have an end point like we had with a line segment

#

yep!

#

to illustrate

#

(the lines need to be straight, but my art skills are just not that great ahaha)

#

is the idea fine by you tho btw?

forest coyote
forest coyote
alpine sable
#

yeahh i am just bad at drawing

#

ahahaha

#

okay so actually, the arrow and dot stuff isn't just for lines

#

if you see like anything on a graph right? and u see it has some end with an arrow, just realise that it goes on forever after that point

forest coyote
#

but im still confused how to get the range having an infinite line🤔

alpine sable
#

we will get into that!

#

to illustrate what i meant earlier, here for example, the orange line is just a simple line that goes to infinity like i told u

#

the yellow weird thing, if you notice, has yellow arrows at its end too

#

those arrows basically mean that it continues to grow forever and forever and forever in those directions

forest coyote
alpine sable
#

yep!

#

u got it

#

it goes to infinity

#

to where the arrows are heading

#

okay so knowing this, lets head into question 2

forest coyote
#

ohh okayy!!

alpine sable
forest coyote
#

getting exciting!!

alpine sable
#

okay so like, off the bat, we can realise that the thing is going to infinity right

#

because of the arrows

#

it is a line that goes left and right to infinity and forever and forever

#

okay so here is the tricky part! finding the domain and range here is going to be a bit more interesting for us

#

lets find the domain first

#

you can ignore the y values for now, i want you to just look at the x values

#

like we already talked about you knoww

#

what do u guess the domain is?

forest coyote
#

probably 0??

alpine sable
#

not quite! lets think this through a bit more

#

this line continues going on forever right?

forest coyote
alpine sable
#

i want you to look at it on the right, and imagine if it continued going right and right and right

#

it would reach x = 20, x = 100, x = 1000, x = 10000

#

and larger and larger numbers

forest coyote
#

yep!

alpine sable
#

is that alright with you?

#

oh thats amazing!

alpine sable
#

so if we know that it continues going forever and forever from both sides

#

it can be -10000, -1000, 0, 1000, 100000 and so on

#

if it can have ANY x value, like we can see, what do u think the domain would be?

alpine sable
#

yes!!

#

the domain is anything!

#

but..."Anything" isnt quite...the right word

#

if like you wanted to say that the function goes on to forever, we can just say it goes to infinity

#

okay so here is another thing, i need to know, if i told you the phrase "All Real numbers" would you know what i mean by that?

#

its okay if you dont

#

it just means, we have to go another way

forest coyote
alpine sable
#

oh so you know of it! thats good

#

that makes things a bit easier

#

but yes, a real number is any number you can think of (outside of complex numbers but thats for the future)

#

A real number is ANY number

#

So the domain here is All real numbers

#

but we can rewrite it in a different way

#

which is this

#

[-\infty, \infty]

#

hm, bot is down?

#

$f$

#

sigh what a bad timing

forest coyote
alpine sable
#

nice!!

#

thats amazing

alpine sable
#

the first one is called interval notation, and the second one...you can just call inequality notation

#

both of those mean all real numbers

#

are u familiar with either of those by any chance? @forest coyote

forest coyote
#

but wait

#

based on the example on our paper the domain and range is written like this any idea??

alpine sable
#

oh okay you guys are using set notation

#

can i know what year you are in?

#

just to figure out in which way i should give out the stuff to you

forest coyote
alpine sable
#

gotcha

#

this means u r good to go with set notation

alpine sable
#

the way u wrote it

forest coyote
alpine sable
#

$r$

#

aaa why did the bot break now smh

forest coyote
forest coyote
alpine sable
#

no ahah

#

i think i am like 2-3 years older than u or something

forest coyote
forest coyote
alpine sable
#

i have so much to study for, it is kind of hard to multitask 😅

forest coyote
#

if i can send you money i will your very good at explaining

alpine sable
#

nonono please dont, i just like teaching people and I don't want any money from here

#

it is also nice to see people learn more stuff you know?

forest coyote
#

well yeah but i mean if you need money its a good sideline

alpine sable
#

yeah but thank u a lot for ur kind wordss 🙏🏻

#

but lets go back to our topic

forest coyote
alpine sable
#

the bot is down so i cant just type stuff with it sadly, but i found this to explain

alpine sable
#

u will get used to it dw

alpine sable
alpine sable
#

the fancy ∈ letter just basically means "is in"

#

so like x ∈ R basically means "all x is in R"

#

{x | x ∈ R} is ur domain for the function u had above

forest coyote
#

ohhhh

alpine sable
#

okay so thats the domain down, is there anything confusing u at all about this btw?

forest coyote
alpine sable
alpine sable
#

set builder notation, which is what u used above, basically describes that more formally

#

if we were to properly write it out, it would be

#

D : {x | x ∈ R}, which read out basically means

#

"The domain of the variable x belongs to all real numbers"

#

if we were to write
R : {y | y ∈ R}
it would be read out as "The range of the variable y belongs to all real numbers"

#

and so on

#

if like

#

in our first example

forest coyote
alpine sable
#

with the points, we had the domain be {(-3, -2, -1, 0, 1, 2, 3)}

alpine sable
alpine sable
forest coyote
alpine sable
#

mm actually

#

i made a mistake

#

set builder notation is for continuous values

#

roster notation is for discrete values

#

you have three forms to write it in

#

Roster notation, set builder notation, and interval notation

forest coyote
#

oh

alpine sable
#

the last two dont work for our first example

#

because we had ONLY the points -3,-2,-1, etc.

#

set builder notation,
with like -3 < x < 3 is wrong here to use, because it means the domain is all x values between -3 and 3

#

but we dont have something like 2.5 or 0.5 yk

#

we only have -3, -2, -1, 0, 1, 2, 3 and nothing inbetween

#

okay this is really a confusing mess for you, lets just rewind it a bit for ya

#

lets go back to whats confusing you, can you tell me if anything is?

alpine sable
alpine sable
#

yeah so lets recollect what we have done so far

#

what is the domain of our function?

#

oh btw if you are tired, or busy, or this is maybe taking too long for you, we can continue this conversation later if u wanna

forest coyote
#

im doing 3 other subjects rn HEHEHHE

alpine sable
alpine sable
#

thats a lot of multitasking ahaha

#

maybe we can continue this later then after u finish off the other two? its easier on u as well

forest coyote
alpine sable
#

oof whats the time for u?

forest coyote
alpine sable
#

oh yeah u do have to speedrun this then ig

forest coyote
#

i'll also try to answer it but i'll be back for the explanation about 2:00am i guess

alpine sable
#

oh okay, just send me a message if u wanna

#

i will be up i think

forest coyote
alpine sable
#

for your last two questions on that list without a graph

#

i need you to realise that f(x) = x - 6 is just the function of a line (can be written as y = x - 6) and it goes on forever in both directions, and for the other one with the square root, just realise that the square root accepts any value for x EXCEPT what makes it negative

#

like, for y=sqrt(x) the domain is [0, infinity) and the range is [0, infinity) too

#

the function only accepts positive or zero x values and outputs positive or zero y values

#

those are ur hints 😵‍💫

#

but anyways we can continue this later, u can just type .close for now until then if u wanna

lone heartBOT
#

@forest coyote Has your question been resolved?

#
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karmic apex
#

Guys i have some homework that i need to be done in 2 hours. it is junior/senior level and i will pay the onw who makes it and able to explain it good 15 bucks. Anyone up?

gray isle
#

against server rules

karmic apex
#

really?

#

it isnt homwork then

gray isle
#

what is it then

karmic apex
#

im gonna send it in

gray isle
#

no monetary discussions here, people are volunteers
its also sus when people are willing to do that especially when there's a time limit

karmic apex
#

i will translate

karmic apex
gray isle
#

that's effectively the same as paying

karmic apex
#

no

#

it is not paying you are volunteers and i accept that but as a token of thank you i will make a donation unless you want to help me out without the donation

lone heartBOT
#

@karmic apex Has your question been resolved?

karmic apex
#

no

#

but np

stiff tree
#

Hi
How to prove that 2x + 1 = y is a bijection?

lone heartBOT
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After 15 minutes, feel free to ping <@&286206848099549185>.
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magic falcon
#

Make polynomial function p using these. Answer in factored form.

the degree is 5
one zero is 0 multiplicity 2
the remainder when p is divided by (x + 1) is −40
the graph is tangent to the x-axis at (1,0)
2x^2 − 5x + 3 is a factor of p.

magic falcon
#

so i was thinking

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degree of 5, 0 multiplicity 2, tangent to 1,0

#

that means that x^2(x-1)^2 and some other factor

zenith latch
#

that works

magic falcon
#

so i solve for the other factor

zenith latch
#

gotta get the other two condtions though

magic falcon
#

using the given quadratic functions

#

i find the zeroes of the quadratic equation

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one of them should either be 0 or 1 and the other should be the final factor

#

but i got it wrong

#

i think it has something to do with when divided by x-1, = -40

magic falcon
zenith latch
magic falcon
#

the zeroes of the given quadratic function is 3/2 and 1

zenith latch
#

and then i suppose you could just solve for r

magic falcon
#

hmm so i dont do anything with the quadratic function?

zenith latch
#

i dont think so

#

wait let me see

zenith latch
#

@ocean seal smh

magic falcon
#

f(x) = x^2(x-1)^2(x-r)
f(-1) = -40

(-1)^2 (-2)^2 (-1-r) = -40?

#

4(-1-r)

-4 - 4r = -40

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4r = 36
r = 9

zenith latch
#

💀

#

tf

magic falcon
#

probably wrong

#

what happened

zenith latch
#

oh do u have to scale it?

magic falcon
#

wym scale

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only need the factors

#

hmm maybe i should use the quadratic function

zenith latch
zenith latch
#

let me try to graph

magic falcon
#

f(x) = x^2 (2x^2 - 5x + 3) (x-r)
f(-1) = -40

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1 ( 2 + 5 + 3 ) ( -1 - r ) = -40

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10(-1-r)=-40

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-10 - 10r = -40

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10r = 30
r = 3

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damn why are the rs different

zenith latch
#

ok i used desmos

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and got an answer

magic falcon
#

wait where did 2 come from

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nvm i see

#

solve for a

#

the quadratic roots were right

#

thanks!

#

.close

lone heartBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#

Please don't occupy multiple help channels.

#
Channel closed

Closed due to the original message being deleted

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Remember:
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After 15 minutes, feel free to ping <@&286206848099549185>.
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fast tiger
lone heartBOT
fierce prairie
#

f(1) is asking for the graph's y position at x=1

fast tiger
#

Okay

#

Do the first two look right?

fierce prairie
#

well f(1) is not a coordinate, just the y value

#

so just put 8

#

same idea for f(-1)

fast tiger
#

Okay, I got the rest of it down now

#

thanks

#

.close

lone heartBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fast tiger
#

Didnt mean to close this lol

lone heartBOT
low quartz
#

its simple

#

log36=2log6=2log2+2log3=2x+2y

fast tiger
low quartz
#

no

#

they r

#

easy

#

log8/9

#

=

#

log8-log9

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=

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3x-2y

fast tiger
low quartz
#

lemme

#

check

#

yes

#

@fast tiger right

#

do u get it?

fast tiger
#

Wait, turns out x-4y is wrong @low quartz

low quartz
#

ok

#

lemme check again

#

dude

#

logb3
=y

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answer is y-4x

#

you misplaced the variable

fast tiger
#

@low quartz Still wrong

#

Is it supposed to be a fraction?

low quartz
#

ohh

#

y/4x

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is the answer

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srry

#

try this

#

y/4x

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@fast tiger

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i didnt see that

fast tiger
#

Okay thanks

This is the next one I need help with

late mango
low quartz
#

the conjugate is 4+3i

#

multiply it to numerator and denominator both

fast tiger
#

Multiply 4+3i to the top and bottom?

late mango
#

yes

fast tiger
#

41/25 - 13i/25?

low quartz
#

no

#

thats

#

right

fast tiger
#

Hm

#

I keep getting the same answer

low quartz
#

srry

outer lark
#

its correct

low quartz
#

:).

#

wrong chat

fast tiger
#

Is that standard form tho?

outer lark
#

no

#

you want to split the denominator over each term and simplify as much as possible

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to keep a real and imaginary part

#

you're not gonna need to simplify anything here because 41 and 25 are coprime