#help-0
1 messages · Page 99 of 1
no
then i neglected the u
is that on the left?
yes
oh
left the line right after
but that's not a union complement a
that's a union a
i have not once wrote a complement there
btw if you find explaining it complicated we can hop into voice chat and you lead me through the solution
if that's ok with you
no, i have no mic here
you'd need de morgans Laws to prove that, so I did it visually
picture is loading
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If I get all the successors of a given variable in a probability graph
Do I then have all variables that contain that parent variable in their conditional probability table?
It cannot appear anywhere else right?
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What is this task?
do you know the euler torrient function?
that funny symbol before (k)
Ah yeah, that might be it. actually funny that we've been using slighlty different notation for euler in handwriting 😄
yeah, a lot of handwritten and computed greek symbols look different, but this is the euler torrient function
you need any help on that or do you know what to do now?
I think I can manage it, haven't started yet as I didn't know what this was, but thanks!
.close
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I set the X on my calculator to -10000 but I want the X to represent the variable X when putting it into a function since I want to write X as an exponent (^X). How do I turn X = -10000 to X = a normal X?
Calculator TI-84
Don’t set X=-10000 then?
If you are asking how to revert that for example just system reset or whatever it is called
I did but nothing changed
I want to get back to the normal X
okey now it worked, I had to clear the memory of the calculator but it just set X = 0
which isn't optimal
I'll just google
Google can answer most questions and should really be a 1st step
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the drawing shows a sketch of the graph of the function f(x)= ln(ax)/x. g(x)= -ln(ax)/x, when a > 1. Pass a straight line through the extreme points of the two functions f(x),g(x). the area bounded by the straight line, by the graphs of the two functions and by the line x = e, equals to (ln(2e))^2 -1. find the equation of the line that passes through the point of inflection of f(x) and through the inflection point of g(x). please help whoever's got free tim
have your drawn the area?
hmm so inflection point is when second derivative is 0
im struggling to find the area
can you write it as an integral?
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plz help
do you remember what nabla^2 is
yeah, but do you recall the definition of nabla^2
In mathematics, the Laplace operator or Laplacian is a differential operator given by the divergence of the gradient of a scalar function on Euclidean space. It is usually denoted by the symbols
∇
⋅
∇
{\displaystyle \nabla \cdot \nabla }
,
∇
...
apply definition directly
yeah i know that, its not that easy
what have you tried so far
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Hey guys, you can say anything about me but pls let me help with my math I don't really get it.. I'm a slow learner
I failed dnd I don't wanna fail this time again
yoo stop bullying 🙂
This is the question
R u in the wrong Channel
I'm new i don't know 💀
Okay
and 2x-y=3 as 2nd equation
So I'm gonna answer the first equation
so u can see that x and y is squared in equation 1 right?
so square all the numbers on the 2nd equation to get x^2 and y^2
ok so do u see the 2x on the 2nd equation?
Ok hold on
I have solve that actually but it different
ok so
You guys got this?
oui oui monsieur

So first I solve the equation for y
could you please get me some help at #help-11 ?
cheers!
And move the variable to the right handed side and change its sign
ahh right
Yeah sorry I haven’t seen ordered pairs so idk what they are
ahh all g mate
oh ok cool!
y = - 3 + 2 x
ahh nice
i actually did that once but I got marked down 😦
so I had to do the square method instead
And then substitute the given value of y into the equation
yep easy m8
out of curiosity what year/grade r u?
8
bruh im in 11
So it x^2 + ( - 3 + 2x)^2 = 27
xD
Am I right
yeah thats right
In Aus?
ouioui
u?
Finished yr12 vce
oh so vic?
Yep
And I'm 15yo but I failed so I came back to 8
oh cool! from west aus ahaha
bro thats sad man
😭😭
As long as you keep trying
you'll achieve your goals and dreams
keep it up
oh sorry
so for this you have to expand (-3+2x)^2
have u learnt factorising polynomials
I'm confused but what I first did
about>
Ye I did but the teacher isn't understandable
oh it fine
I have to go
really sorry!
cya
hope u get help with ur question
Or search up an app called Photomath
dont use it all the time though
use it to check ur answers
it has all the steps
peace man
I'm on PC
Just google it
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a . b . c are real number no nul whit ab +ac + bc = 0
Show that a+b/c + a+c/b + b+c/a =-3
Do you mean (a+b)/c + (a+c)/b + (b+c)/a
Yeah
So to add these you have to take LCM.
And?
If you've already attempted something, why would you not show your attempt first thing?
But i didn't continue
why not
doesn't matter
I get the lcm but i think the factorization is false
Hello! I'm not sure exactly if I should be answer part a) with a hypothesis/conclusion format or simply a formalized format.. Also for part b) I am totally lost on how to prove this
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hey can anyone check my work cause this was kinda confusing and im not sure i did it right
Please don't occupy multiple help channels.
oh right l
forgot i had that one open
if x is 0 it would just be $1 + 2 + 3 + ... + n \ge 59 => \frac{0(0-1)}{2}+\frac{n(n+1)}{2} \ge 59
=> (n)(n+1)\ge 118 =>n²+n \ge 118\\vdot\
\vdot\
\vdot\$
if x is 2, it would mean $|2-1|+|2
-2|+|2-3|+...+|2-n| = 1 + 0 + 1 + 2 + 3 + ... + |3-n| = \frac{2(2-1)}{2} + \frac{|3-n|(|3-n|+1)}{2}\
\vdot\
\vdot\
\vdot\$
for a general scenario, it could be interpreted as 2 sums, one of x-1 terms and one of n-x+1 terms (the +1 being the case where x = n)
therefore, a general formula would be:
$|x-1|+|x-2|+...+|x-n| = \frac{x(x-1)}{2} + \frac{|x-n|(|x-n|+2)}{2}=\frac{x(x-1)+|x-n|(|x-n|+1)}{2}$
i wanted to rewrite the sum |x-1|+|x-2|+...+|x-n|, where x is any real number and n is any natural number
tried induction and noticing some things in regards to how the sum behaves when x increases
and i assume it applies when x is decreasing as well
its just that with a minus in front
Kel.plush
The steps you have taken to derive a formula are generally correct, but there are a few errors in the final formula you have given. The formula you have given is not correct because the first term of the sum, $|x-1|$, is not being included in the formula. Also, the second term of the formula, which should represent the sum of the remaining terms, is not correct.
The correct formula for the sum of the absolute values of the numbers from $1$ to $n$, where $x$ is an integer between $1$ and $n$, should be as follows:
$|x-1| + |x-2| + |x-3| + ... + |x-n| = |x-1| + \frac{(n-x)(n-x+1)}{2}$
This formula is derived as follows:
The sum of the absolute values of the numbers from $1$ to $n$ can be split into two parts: the sum of the absolute values of the numbers from $1$ to $x-1$, and the sum of the absolute values of the numbers from $x$ to $n$. The first part is simply equal to $|x-1|$ because the absolute value of a positive integer is just the integer itself. The second part is a bit more complicated, but can be derived as follows:
$|x-1| + |x-2| + |x-3| + ... + |x-n| = |x-1| + (|x-n| + |x-(n-1)| + |x-(n-2)| + ... + |x-1|)$
We can rewrite the second part of the sum as follows:
$|x-1| + (|x-n| + |x-(n-1)| + |x-(n-2)| + ... + |x-1|) = |x-1| + (|x-n| + |n-x| + |n-1-x| + ... + |1-x|)$
Now, we can see that the sum of the absolute values of the numbers from $x$ to $n$ is simply the sum of the integers from $1$ to $n-x$, which is equal to $\frac{(n-x)(n-x+1)}{2}$. Therefore, the final formula for the sum of the absolute values of the numbers from $1$ to $n$ is as follows:
$|x-1| + |x-2| + |x-3| + ... + |x-n| = |x-1| + \frac{(n-x)(n-x+1)}{2}$
MeatBagFrank
np bro
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your answer true
7 units down
It's just finding the change in x and change in y
like 90% sure
Is this homework
@void canyon if your x coordinates increase or decrease you can go left or right
y coordinates increase or decrease you can go up or down
yeha on saturday
thats good to know im writing this down right now
true
last one
true
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Hey there,
I'm currently trying to figure out how to do a Progressive Calculation in Context of the Etsy Marketplace. The goal is to be able to easily calculate for what price I need to list a product to be profitable.
However, Etsy calculates their fees in a very cross-linked way, so it is grilling my brain right now. Due to the cross-linking, I don't even know whether it's possible, but you can prove me wrong ^^
The Retrograde Calculation has worked fine (See right side of the sheet).
Note, this isn't the entire calculation, but the relevant part, for this question
Note, I've marked all base values with the purple arrows (e.g. The base value of VAT is Net Etsy Selling Price)
Retrograde Calculation: $9,98 -> ?Selling Price
Progressive Calculation: $5,88 -> ?Gross Etsy Selling Price
cheers
BennoDev
Hey there,
I'm currently trying to figure out how to do a **Progressive Calculation** in Context of the Etsy Marketplace. The goal is to be able to easily calculate for what price I need to list a product to be profitable.
However, Etsy calculates their fees in a very cross-linked way, so it is grilling my brain right now. Due to the cross-linking, I don't even know whether it's possible, but you can prove me wrong ^^
The Retrograde Calculation has worked fine (See right side of the sheet).
**Note**, this isn't the entire calculation, but the relevant part, for this question
**Note**, I've marked all base values with the purple arrows (e.g. The base value of `VAT` is `Net Etsy Selling Price`)
**Retrograde Calculation:** `$9,98` -> `?Selling Price`
**Progressive Calculation:** `$5,88` -> `?Gross Etsy Selling Price`
cheers
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Hi i need help making a curved line for this
best i could do was y = 1000x^-1
or 1000/x = y
What do they look like
Wait it follows a very distinct pattern
Lol each y value gets halved
That's just 2000(0.5)^x
$$A_0(r)^x$$
$A_0$ is the initial, (when $x = 0$), and then $r$ is the rate
Umbraleviathan
Np
bro it aint showing one
There's legit 3 available
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Thanks again!
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i think you just need to find the first derivative like you did and substitude x for -2 or f`(x)= 2
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how do you use partial fraction decompositon
Did you mean to write x instead of t?
oh yea ye sorry
Factor the polynomial in the denominator by first noticing that x = 1 is one of its roots
After doing long division you should be able to discover that x = 1 is actually a double root, making the polynomial eventually equal to (x - 1)^2(x^2 - x + 1)
im sorry but im bad at maths and i dont know how to factorise
Do you know how to do long/polynomial division?
Try dividing x^4 - 3x^3 + 4x^2 - 3x + 1 by x - 1
i did and the remainder is
1-x
1 - x = -(x - 1)
Dividing 1 - x by x - 1 yields -1
So, did you get x^3 - 2x^2 + 2x - 1 as the quotient?
yess
And, clearly, x^3 - 2x^2 + 2x - 1 has a root at x = 1
Meaning you have to divide by x - 1 again
Guess and check, usually I try out x = -1 and x = 1
If those don't work, try x = -2 and x = 2
But I don't go further than that most of the times
ohhh
Or, if the coefficients of the polynomials are all integers, you may wanna look at the rational root theorem
Did you get x^2 - x + 1?
Alright, x^2 - x + 1 actually has no roots so the factoring is done
x^4 - 3x^3 + 4x^2 - 3x + 1 = (x - 1)^2(x^2 - x + 1)
(x - 1)^2 is squared because we got x = 1 to be the root twice
If x = a is a root of polynomial P(x), then (x - a) is a factor of P(x)
So P(x) is divisible by that
ahhh
and for this part, we take the last quotient to equate and possible roots?
can you help me undestand why it got written as such?
we have the root, but how did it got subtracted
<@&286206848099549185>
if you try to go backwards, ie cross multiply and subtract you will see you are getting your previous line
like 1/n(n-1) = (n+1-n)/n(n-1) = 1/(n-1) - 1/n
how can you write (n+1-n)/n(n-1) = 1/(n-1) - 1/n ?
look at the numerator, it is 1, you can write 1 as 1+n-n
yess
ahh thanksss!!
let me try and write it down
oh wait i got it, add aand subtract (x-1)^2
expand (x-1)^2+x and it doesnequate to that
thanks alott man
i wrote it very roughly i hope you understand
yes exactly
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this is matrix/eigenvalues?
I would double check how you distributed
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thx
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ok so i'm doing a math assignment due on November 12th on mortgage and finance where i am given a scenario about buying a house and have to do payment calculations using a TVM solver. i need to know which is the best interest rate from each mortgage term as well. If someone can help me and check out the assignment i would greatly appreciate it
To determine which is the best interest rate from each mortgage term, you will need to consider a few factors, such as the total cost of the loan, the monthly payment amount, and the length of the loan term. You can use a TVM solver, which is a tool that allows you to input different values for the interest rate, loan amount, and loan term, and then compute the monthly payment and total cost of the loan. By comparing the results for different interest rates, you can determine which rate offers the best combination of monthly payment and total cost for your specific situation.
I don't see any loan info here
jus the price of the house and the downpayment
with different interest rates for a fixed-rate mortgage (for 1, 2 and 5 years) and i gotta find out which one is the best from each
3 different banks too
it's confusing 😭
@vital sail
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If there are 5 different candies in a jar and a child wants to take out one or more candies, in how many ways can this be done?
Combination
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I solved this problem but I'm not sure if I did the bounds correctly. I assumed since you need to make the bounds with respect to z, y, and x, I would just set them to 0 but I'm not sure if that is a correct assumption.
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how do they get 1<x<2?
why (x-1)(x-2)(x+1)
isn't it (x-1)(x-2)
the numerator is (x-1)(x-2)
and denominator (x-1)
its because negative times positive is negative
$$\frac{x^{2}-3x+2}{x+1} <0\Leftrightarrow \left( x^{2}-3x+2<0\ \wedge x+1>0\right)$$
$$\vee \left( x^{2}-3x+2>0\ \wedge \ x+1<0\right)$$
$$\Leftrightarrow \left( x^{2}-x-2x+2<0 \wedge \ x>-1\right)$$
$$\vee \left( x^{2}-x-2x+2>0\ \wedge \ x<-1\right)$$
This is my understanding so far.
$$x^{2}-x-2x+2\Leftrightarrow x\left( x-1\right) -2\left( x-1\right) \Leftrightarrow \left( x-2\right) \left( x-1\right)$$
But how do you turn (x-2)(x-1) to 1<x<2?
consider the graph of y= (x-1)(x-2)
a rough sketch with x-intercepts and correct concavity is sufficient
,w graph (x-1)(x-2)
i don't have access to a graphing calculator on the exam
don't need one
so i write (x-1)(x-2) = 0
a rough sketch with x-intercepts and correct concavity is sufficient
find the x-intercepts
the shaded area
how do we know it's a third degree polynomial
we have 3 x’s multiplied
how
you can multiply both sides by (x+1)^2, (a non-negative value) which leads to the third line
yepp
the work just posted was more efficient approach
the question you were initially asking is very similar
your quadratic
(x-1)(x-2)
is in factored form, you should have no issue identifying the zeros
and concavity
i don't have access to a graphing calculator on the exam
don't need one
a rough sketch with x-intercepts and correct concavity is sufficient
your sketch could be as horrid and bare bones like
the zeros won't change if it's <0, >0, or =0 right?
and from that very rough sketch
you should be able to see when the curve is less than zero and when its greater than 0
so the area of the curve under the abscissa is when (x-1)(x-2) < 0?
whut
the x-axis
what's this about area
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hi
in Applied Optimization whats the difference between the objective and the constraint
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objective is what you want to maximize / minimize, constraint is what the things have to satisfy
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Construct a sector AOB with angle AOB equal to 45 deg. Now, create an angle bisector that bisects AOB and the arc AB. Finally, extrude the bisector to point C, so that OC = 20 units. Then construct a semi-circular arc ACB. Find ACB, and the arms of the sector OA and OB
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Please help to calculate the Fourier transform of the function f(x) = sin(2π10x)
i assume you're meant to do this in terms of dirac deltas?
UPD: yes
do you know the fourier transform of e^(2πi10x) ?
no
what fourier transforms do you know?
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.close
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A math olympiad problem, i got problems with
i tried to do this by using tan as a a,b,c
and it seems working but i cant progress i dunno why
Udowodnij że means- prove
how do you find what part is 225 of 2000
@gaunt depot Has your question been resolved?
by dividing
divide 225 by 2000
@gaunt depot Has your question been resolved?
hi
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We cannot give you the answer. But we can help/guide you to it
yup that will do
Also please do not ping the helpers role until at least 15 minutes after your question has been up
ohh sorry im just in a hurry beacause i still have to review😓
Well, we can start with the first one. The domain describes the input values (the x's) for the function, do you know how to discern the x values for a function from its graph?
thats fine
uhmm not yet cuz this is an activity and im in modular so self learning sorry
yeah thats okay
lets start off with the first dot
Do you see that horizontal axis in the middle labelled as 'x' in the far right? @forest coyote
yes
That's called the x-axis and it tells you the values of your x values, the labelled numbers on that axis are those values
ohhh
x = -2, for example would be this point
we are speaking strictly one dimensionally here though, so ignore the vertical axis for now
okay following🤍
alright, so do you see all of those black dots?
yes
i want you to look at them and look at the correspondent x value of that point
so for example
-3 -2?
this black dot is at the point x = 2 (again we are only concerned with the x values for now)
ohh okay🤩
can u tell me where all of the rest lie?
-3 -2 -1 0 1 2 3
yep! you are doing amazing good job
okay, so those x values you just listed down are what we call the domain of the function
think of the domain as, ALL of the x values on that graph
if that makes sense
so your domain of that function would be the x values of -3, -2, -1, 0, 1, 2, 3
please tell me if u r confused at all at any point btw
is it alright so far?
or the abscissa right?
yep!!
hmm i think abscissa is like, the general term for any x values, not necessarily the domain of the function
but i am unsure because i dont think i have used that term in a long time 😅
ohhh thanked god i got corrected cuz i might put the wrong answer on our quiz
mhm the domain of a function is always safer, if you are trying to describe all the x values for a function
okay so like, here is where i need your help a bit
owkey!
i need to ask from you how exactly would you write a set or domain, if you were asked to write down one
if you dont know thats fine, but then we kinda have to talk about something else for a bit
yep! that sounds good to me
good job, thats ur domain of the function
now, lets talk about the range
ohhh well i thought it was going to be hard😅
Nope! u already got it hahaa
now, we have to find the range
u see what we did with teh domain and the x values? well we are going to do the same exact thing
but now, we are doing it for that vertical line, thats called the y-axis
is this okay with u so far? @forest coyote
yesss!!
okay! thats great
Okay, so the domain describes the x values or the "inputs" of that function
the range describes the y values or the "outputs" of that function
it goes like this, think of it
x -----> function -----> y
the function is just this like, fancy machine, that converts your x to a y, if that makes sense
well anyways
ohhhhh
for the graph, this point would have y = 1
for example
you see how it is x = -3, and y = 1 at the same time?
okay then it is the range?
so basically if the set is (-3, 1) (-2,-1) the domain is -3 and -2 then the range is 1 and -1?
ohhhh
but thats a very small function haha, functions usually are huge and go on forever, and we are going to see that in a bit
but for now, can u tell me the range for this?
like, just list off the y values
for the points
1, -1, -2, -1, 2, 0?
yep!! you are actually doing fantastic, good job
okay so here is the thing, actually
thank you!
in sets (if you dont know what that is, just think of the domain and range for now) repeated numbers don't matter
like
you wrote down -1 twice right? because it appeared twice right?
actually u can just write down a single -1
ohhhh i see
yep! but can u write out the range properly now?
like how u did with the domain earlier
{(1, -1, -2, 2, 0)}
yey!
yay!!
okay before we get into the second question, i want to mention a few important things first
do you notice how we have arrows at the red parts, but just a dot at the yellow part?
do you know the difference between the arrow and the dot?
uhmm not yet?
mm alrightyy
so basically, there are three types of lines
one is called a segmented line, the second a ray, and the third just a "line" actually haha
so the first one is line the other one is segmented? (just a guess)
you are right for the first!
i drew this quickly, but let me explain the difference
ohhh just observation based on the names hehe
haha thats great! it is good to be observant :))
a "line segment" is actually probably what you refer to as a "line" normally in your mind
a line segment is just a line from like one point to another
it has a specific length
like 4, 5, 6 whatever it may be! but we know how long it is
ohhh
thats the reason it begins with a dot and ends with a dot
it has like a starting point and an end point
ohhhhhhh that makes sense
now, with a ray, things are a bit different
we have a "Start" point
but like, if u notice, at the end we have an arrow instead of a point like we did with a line segment
the little "Arrow" actually means that the line...continues on forever!
it has a starting point, but it never stops
ohhhh but the dot means the end??
yep! the dot basically means the start or the end point
like we had with a line segment
ohhh im starting to gets things now
like u can continue drawing it forever in the direction where it is heading
an infinite line
yep!
like here
i exteded it a bit, but it really does just go on forever
in the direction that it is shown
ohhh i see i get it
yep!
okay here is the thing, thats all fine and dandy, but now for the "line"
it is kind of like the same story as a ray, buuuuut, it actually doesnt begin anywhere either
an infinite line then
it doesnt have a beginning point neither does it have an end point like we had with a line segment
yep!
to illustrate
(the lines need to be straight, but my art skills are just not that great ahaha)
is the idea fine by you tho btw?
it's a straaight line though
yessss
yeahh i am just bad at drawing
ahahaha
okay so actually, the arrow and dot stuff isn't just for lines
if you see like anything on a graph right? and u see it has some end with an arrow, just realise that it goes on forever after that point
but im still confused how to get the range having an infinite line🤔
we will get into that!
to illustrate what i meant earlier, here for example, the orange line is just a simple line that goes to infinity like i told u
the yellow weird thing, if you notice, has yellow arrows at its end too
those arrows basically mean that it continues to grow forever and forever and forever in those directions
so its infinite too??
yep!
u got it
it goes to infinity
to where the arrows are heading
okay so knowing this, lets head into question 2
ohh okayy!!
getting exciting!!
okay so like, off the bat, we can realise that the thing is going to infinity right
because of the arrows
it is a line that goes left and right to infinity and forever and forever
okay so here is the tricky part! finding the domain and range here is going to be a bit more interesting for us
lets find the domain first
you can ignore the y values for now, i want you to just look at the x values
like we already talked about you knoww
what do u guess the domain is?
probably 0??
not quite! lets think this through a bit more
this line continues going on forever right?
yes
i want you to look at it on the right, and imagine if it continued going right and right and right
it would reach x = 20, x = 100, x = 1000, x = 10000
and larger and larger numbers
yep!
okay so the domain tells us the x values that the function has
so if we know that it continues going forever and forever from both sides
it can be -10000, -1000, 0, 1000, 100000 and so on
if it can have ANY x value, like we can see, what do u think the domain would be?
ohhh anything?!
yes!!
the domain is anything!
but..."Anything" isnt quite...the right word
if like you wanted to say that the function goes on to forever, we can just say it goes to infinity
okay so here is another thing, i need to know, if i told you the phrase "All Real numbers" would you know what i mean by that?
its okay if you dont
it just means, we have to go another way
it include both rational and irrational numbers?
oh so you know of it! thats good
that makes things a bit easier
but yes, a real number is any number you can think of (outside of complex numbers but thats for the future)
A real number is ANY number
So the domain here is All real numbers
but we can rewrite it in a different way
which is this
[-\infty, \infty]
hm, bot is down?
$f$
sigh what a bad timing
ohhhh i get it!!
the first one is called interval notation, and the second one...you can just call inequality notation
both of those mean all real numbers
are u familiar with either of those by any chance? @forest coyote
yep im kind of familiar with the notation
but wait
based on the example on our paper the domain and range is written like this any idea??
oh okay you guys are using set notation
can i know what year you are in?
just to figure out in which way i should give out the stuff to you
second year highschool
do u know what this means
the way u wrote it
yep im just really really confused how she got this set
well yes but how to get it or to be exact how to make it is confusing for me
but lemme guess your a teacher?
ehh??!!
hmm okay! we can explain
i think you should do tutoring u might even earn money
i have so much to study for, it is kind of hard to multitask 😅
oh but actually from what your doing rn explaining and everything can be paid
if i can send you money i will your very good at explaining
nonono please dont, i just like teaching people and I don't want any money from here
it is also nice to see people learn more stuff you know?
well yeah but i mean if you need money its a good sideline
but getting the number even adding more than and less that is even harder
the bot is down so i cant just type stuff with it sadly, but i found this to explain
ahahahah it is okay
u will get used to it dw
the stuff ur teacher showed is basically this, when you have something of this form it is read out as "the variable x such that x is in all real numbers"
ohhh
the fancy ∈ letter just basically means "is in"
so like x ∈ R basically means "all x is in R"
{x | x ∈ R} is ur domain for the function u had above
ohhhh
okay so thats the domain down, is there anything confusing u at all about this btw?
ohhh but how do we turn this thing to that??
like, we already figured out the domain is all real numbers right?
yeppp
set builder notation, which is what u used above, basically describes that more formally
if we were to properly write it out, it would be
D : {x | x ∈ R}, which read out basically means
"The domain of the variable x belongs to all real numbers"
if we were to write
R : {y | y ∈ R}
it would be read out as "The range of the variable y belongs to all real numbers"
and so on
if like
in our first example
but the first one has domain?
with the points, we had the domain be {(-3, -2, -1, 0, 1, 2, 3)}
oh what do u mean?
this, we can write in set builder notation as
ohh so we don;t have to turn it into like this??{x | x ∈ R}
mm actually
i made a mistake
set builder notation is for continuous values
roster notation is for discrete values
you have three forms to write it in
Roster notation, set builder notation, and interval notation
oh
the last two dont work for our first example
because we had ONLY the points -3,-2,-1, etc.
set builder notation,
with like -3 < x < 3 is wrong here to use, because it means the domain is all x values between -3 and 3
but we dont have something like 2.5 or 0.5 yk
we only have -3, -2, -1, 0, 1, 2, 3 and nothing inbetween
okay this is really a confusing mess for you, lets just rewind it a bit for ya
lets go back to whats confusing you, can you tell me if anything is?
i mean unless u define x for integer values then it would be fine, but
YEPP!! I WILL!
yeah so lets recollect what we have done so far
what is the domain of our function?
oh btw if you are tired, or busy, or this is maybe taking too long for you, we can continue this conversation later if u wanna
uhmm im busy but i have to pass this assignment tommorrow so im kind of in a rash
im doing 3 other subjects rn HEHEHHE
mm thats okay, we can finish this quickly hopefully
oh WOW
thats a lot of multitasking ahaha
maybe we can continue this later then after u finish off the other two? its easier on u as well
umm i can do that but i have to atleast sleep at 3am cuz i have to wake up at 8am
oof whats the time for u?
12:30am
oh yeah u do have to speedrun this then ig
yahh i have to be flash😆
i'll also try to answer it but i'll be back for the explanation about 2:00am i guess
ohh okayy🤍
try to read your notes on how to construct with set builder notation, and for the rest of the graph questions, do the same thing of examining the x and y values for the domain and range respectively
for your last two questions on that list without a graph
i need you to realise that f(x) = x - 6 is just the function of a line (can be written as y = x - 6) and it goes on forever in both directions, and for the other one with the square root, just realise that the square root accepts any value for x EXCEPT what makes it negative
like, for y=sqrt(x) the domain is [0, infinity) and the range is [0, infinity) too
the function only accepts positive or zero x values and outputs positive or zero y values
those are ur hints 😵💫
but anyways we can continue this later, u can just type .close for now until then if u wanna
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Guys i have some homework that i need to be done in 2 hours. it is junior/senior level and i will pay the onw who makes it and able to explain it good 15 bucks. Anyone up?
against server rules
what is it then
no monetary discussions here, people are volunteers
its also sus when people are willing to do that especially when there's a time limit
i will translate
ok i wont pay but make a donation : )
that's effectively the same as paying
no
it is not paying you are volunteers and i accept that but as a token of thank you i will make a donation unless you want to help me out without the donation
@karmic apex Has your question been resolved?
Hi
How to prove that 2x + 1 = y is a bijection?
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Make polynomial function p using these. Answer in factored form.
the degree is 5
one zero is 0 multiplicity 2
the remainder when p is divided by (x + 1) is −40
the graph is tangent to the x-axis at (1,0)
2x^2 − 5x + 3 is a factor of p.
so i was thinking
degree of 5, 0 multiplicity 2, tangent to 1,0
that means that x^2(x-1)^2 and some other factor
that works
so i solve for the other factor
gotta get the other two condtions though
using the given quadratic functions
i find the zeroes of the quadratic equation
one of them should either be 0 or 1 and the other should be the final factor
but i got it wrong
i think it has something to do with when divided by x-1, = -40
how though
call the other one (x-r)
the zeroes of the given quadratic function is 3/2 and 1
and then i suppose you could just solve for r
hmm so i dont do anything with the quadratic function?
does $x^2(x-1)^2(x-\frac{3}{2})$ work at all
@ocean seal smh
f(x) = x^2(x-1)^2(x-r)
f(-1) = -40
(-1)^2 (-2)^2 (-1-r) = -40?
4(-1-r)
-4 - 4r = -40
4r = 36
r = 9
oh do u have to scale it?
oh?
yeah i have no idea
let me try to graph
f(x) = x^2 (2x^2 - 5x + 3) (x-r)
f(-1) = -40
1 ( 2 + 5 + 3 ) ( -1 - r ) = -40
10(-1-r)=-40
-10 - 10r = -40
10r = 30
r = 3
damn why are the rs different
wait where did 2 come from
nvm i see
solve for a
the quadratic roots were right
thanks!
.close
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f(1) is asking for the graph's y position at x=1
well f(1) is not a coordinate, just the y value
so just put 8
same idea for f(-1)
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Didnt mean to close this lol
What about the fractions ones? they seem a little more tricky
So would the last one be x-4y?
Wait, turns out x-4y is wrong @low quartz
Okay thanks
This is the next one I need help with
multiply by the conjugate of 4-3i
Multiply 4+3i to the top and bottom?
yes
41/25 - 13i/25?
srry
its correct
Is that standard form tho?