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1 messages · Page 90 of 1

raven rover
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It's rounding, some of the differences are odd, when divided by 2 you get a fraction

lone skiff
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look in the screen

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the mid in the first one was (2nd eleemtn) but
line 2
it was 3rd element

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.

lone heartBOT
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@lone skiff Has your question been resolved?

lone heartBOT
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lavish monolith
#

can someone explain how did we find -1.33333 from normcdf

lavish monolith
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it's Normal Distribution

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i tried to put in this formula but i got totally different answer

lone heartBOT
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@lavish monolith Has your question been resolved?

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lime tangle
#

Let $f(\theta) = 2\cos{\theta} + \cos^2{(\theta)}$

lime tangle
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when finding the 2nd derivative, and making it equal to 0, u get theta to be

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pi, pi/3 and 5pi/3

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this is to find inflection point. Why is pi completely disregarded as an inflection point

drifting vector
#

Perhaps because f’(pi) is also zero?

lime tangle
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yes it is

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f'(pi) is 0

drifting vector
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Yeah, so it can’t be an inflection point or a critical point if the function you are deriving from is undefined or zero at that same point

lime tangle
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pi isnt a critical point either?

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pi is a critical point

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because f'(pi) = 0

lime tangle
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but its not an inflection point for some reason

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an inflection point can be a CP

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like take x^3 for example

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it has a CP at 0, and inflection at 0

gray isle
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solving f''(x)=0
gives you potential locations of inflection points

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they might not be and more work is needed

lime tangle
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how do i know if it is or isnt

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what extra work is needed

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like how do i for sure know its not an inflection poiint

drifting vector
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So if the function you are deriving from is undefined or zero at the same point as your critical point it’s not a critical point

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The same applies to inflection points

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Since f’(pi) = 0

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That’s a critical point for the function f

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However since we’re dealing with second derivatives

lime tangle
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but what about x^3

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f'(0) = 0

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f''(0) = 0

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f(0)= 0

drifting vector
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f’’(pi) cannot be an inflection point as f’(pi)=0

gray isle
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you could check the slopes before and after

drifting vector
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^this too

gray isle
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inaccurate Sasaki, x^3 is a clear counterexample

drifting vector
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I see it, my bad then.

lime tangle
gray isle
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of what

lime tangle
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of why its not an IP

lime tangle
gray isle
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you could check the slopes before and after

lime tangle
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the slope of pi before and after?

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the slope before pi

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and after pi

drifting vector
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Second derivative test

lime tangle
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nah thats 1st

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the slope before pi is negative and the slope after is positive

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@gray isle therefore, pi is not an inflection point

drifting vector
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we're dealing with second derivatives right?

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so second derivative test

lime tangle
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well its 1st and 2nd

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because pi is also a critical point

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pi is a critical point

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the slope before pi is negative

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the slope after is positive

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through the 1st deriv test

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therefore, pi is not an inflection point

drifting vector
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what matters is what the second derivative test tells you since we're looking for inflection points

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my previous thinking was flawed please ignore it

lime tangle
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the 2nd dervative says that pi is an inflection point, well, it puts pi as a potential inflection point

lime tangle
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ok so thats the answer then

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when the slope before is not equal to the slope after, the point is not an inflection point

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@gray isle correct?

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agree or disagree

lone heartBOT
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celest aspen
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please explain borwein integrals but simple

mortal trellis
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what about them

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3b1b made a video recently discussing them

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celest aspen
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mortal cedar
#

How do you math

lone heartBOT
outer lark
#

get a good book

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cup of tea

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reading glasses

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11/10 method right here

slate jolt
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i dont do math

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i only pretend

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faking it until i hopefully make it

manic wind
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Usually I just make an uneducated guess

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and it ends up being the answer

tacit arch
#

.close

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gilded pawn
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i need help

lone heartBOT
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Please don't occupy multiple help channels.

outer lark
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do you know what perpendicular means ?

gilded pawn
#

.close

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outer lark
gilded pawn
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wet frigate
lone heartBOT
wet frigate
#

can i get some help on this

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devout yew
#

from where does de -30b comes from and why ?

lyric stream
#

$(a-b)^2 = (a-b)(a-b) = a^2 - 2ab + b^2$

ocean sealBOT
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cantprogram

lyric stream
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$(a-b)^2 \neq a^2 - b^2$

ocean sealBOT
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cantprogram

devout yew
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so if i have 2 items inside parentesis i cant just do this? i can only do that when it's only 1 item ?

lyric stream
lyric stream
devout yew
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ok, thank you

lyric stream
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@devout yew .close 🙂

regal rose
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@devout yew i like to use the box method to do this type of multiplication

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this probably makes a bit more sense than the formula cantprogram provided

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you multiply each term and then add them up

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▶ Play video
#

also foil method

devout yew
#

ty, i'll try it too

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tawny relic
lone heartBOT
tawny relic
#

I need help with a and** b**

tacit arch
tawny relic
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But there are three situations in this question:hours:situations:weeks

sour pewter
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Do I get a vouch if I help

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Cuz I'll love to help

tacit arch
tawny relic
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a recognition for his help

tacit arch
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who gives out recognitions

tawny relic
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the person whose telling the story

tawny relic
tawny relic
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<@&286206848099549185>

sour pewter
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Okay

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for a) let's break it down

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the Stems going down are the first digit

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and the leafs are the second digit

tawny relic
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understood

sour pewter
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For a you just count the leafs

tawny relic
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but how do u know

sour pewter
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Stem 0: 21
Stem 1: 11
Stem 2: 6
Stem 3: 5
Stem 4: 2

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$11+21+11+6+5+2$

ocean sealBOT
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Vinnin

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Vinnin

tawny relic
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but the answer is 45

sour pewter
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Oh you don't count the reoccurring ones

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My apologies.

tawny relic
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that's fine

sour pewter
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OOPS

tawny relic
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My answer comes as 24 for me tho

sour pewter
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I got it

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thats y

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21+11+6+5+2

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I added an extra 11

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That was my mistake

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See Stem 1: it has 11 leafs
See Stem 2: it has 6 leafs
See Stem 3: it has 5 leafs
See Stem 4: it has 2 leafs
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If you add 21+11+6+5+2=45

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So I hope that clears up a

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For clustering that's when there's a lot going on in the data

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1-19

tawny relic
#

that does! You get my vouch but I hope not from the judicial persopective

#

.close

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craggy token
#

how do i solve this?

lone heartBOT
craggy token
#

my friend said to do partial fraction decomposition which would involve cotangent at some point, and that the answer is n = 1, but i dont know how to split each fractions into two separate fractions.

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all of them are in degrees

tacit arch
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do this for each term:

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$\frac{1}{xy} = \frac{A}{x} + \frac{B}{y}$

ocean sealBOT
#

riemann

tacit arch
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And find $A, B$ for each term

ocean sealBOT
#

riemann

craggy token
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ah okay

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thanks

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one more thing..

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what about this one?

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it's equivalent to 2cos^2(74) but how can it be 1 - cos32?

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oh nevermind..

#

.close

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keen mulch
lone heartBOT
keen mulch
#

can anyone help me with this qn?

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we need integrate it

tacit arch
#

complete the square in the square root

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gritty verge
#

Oops im back

lone heartBOT
gritty verge
#

,rotate

ocean sealBOT
gritty verge
#

For qs 4 the first part, we can just use comparison test right?

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And second part im not able to tell oof

vale wigeon
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for the second part, consider what happens if you pick a_n nonzero such that sin(a_n) is 0

gritty verge
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if an is 0 hmm

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wait

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oof i read that wrong

vale wigeon
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pi

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not 180

gritty verge
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oh oop apologies

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180 degrees is pi right o.0?

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welp nvm ye so when an is pi sin(an) will be 0

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but i still dont get how that answers part b?

vale wigeon
gritty verge
#

@rose sigil hehe do u think u could help me out here? Sorry for the disturbance!

rose sigil
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i can try haha

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what is it?

gritty verge
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The second part lol

rose sigil
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hmm

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what about what ann said?

gritty verge
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i cldnt really understand what ann was tryna tell like i understand the 0 part but idk how to imply it in my qs

rose sigil
#

you could have asked her haha

gritty verge
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i didnt know how to phrase my qs lol

gritty verge
rose sigil
#

so sin(pi) = 0

gritty verge
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mhm

rose sigil
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what's the simplest sequence ever you could make out of pi?

gritty verge
#

out of pi?

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issit like

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uh pi, 2pi, 3pi

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im not sure just guessing

rose sigil
#

you could go even simpler but that'll work

gritty verge
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oh oop i see

gritty verge
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like the example?

rose sigil
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yep happy

gritty verge
#

oooooooooh

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see ur pro at this and good at explaining i got it now hahah!

rose sigil
#

pi, pi, pi, pi... also works

gritty verge
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lmao true

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i love making life complex why hais

rose sigil
#

haha

lone heartBOT
#

@gritty verge Has your question been resolved?

gritty verge
#

,rotate

ocean sealBOT
gritty verge
#

for part 2(a) a_k is (2/3)^k right?

rose sigil
#

wdym a_k?

gritty verge
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like the test uk how alt series is (-1)^k(a_k)

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or do ppl call it an/a_n not sure lol HAHA

rose sigil
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oh

gritty verge
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yep TvT

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sorry i confused u haha

rose sigil
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nooo it's ok dw

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i think for these it's a better idea to see if they are absolutely convergent first

gritty verge
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mhm

rose sigil
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because if you use alternating series test and get that it converges you'll still need to check if it converges absolutely anyway

gritty verge
#

ah mhm

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gritty verge
#

.reopen

lone heartBOT
#

rose sigil
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so i'd just look at $\sum_{k=1}^\infty \left|\left(-\frac{2}{3}\right)^k\right| = \sum_{k=1}^\infty \left(\frac{2}{3}\right)^k$ first

ocean sealBOT
#

💜𝓁𝒶𝓎𝓁𝒶💜

gritty verge
#

ohhhh

rose sigil
#

for this one you won't need it but we can look at another example after 🙂

gritty verge
#

oh alright!

gritty verge
rose sigil
#

it's a geometric series

gritty verge
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yep

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wait i think my brain has vanished

rose sigil
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the ratio is 2/3 (which is between -1 and 1) so it converges

gritty verge
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OHH

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so like if the absolute series converges

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the alt series will converge absolutely

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And when absolute series diverges but normal one converges, it converges conditionally,

rose sigil
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yep exactly

gritty verge
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but if both diverges its just divergent

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ah it all makes sense

rose sigil
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you just need the original series to diverge to say it diverges

gritty verge
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ooh icic

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okay i get it tysm again!

rose sigil
#

yay c:

gritty verge
#

i shall close the channel to take some rest haha a bit tired

rose sigil
#

enjoy!

gritty verge
#

i have been grinding math since the morn lol

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tyty bye bye cya arnd!

#

.close

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steel minnow
lone heartBOT
steel minnow
#

how do I sketch this?

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taking the first derivative, I can not find any zeros of the first derivative

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hang on

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am i supposed to use natural log

vale wigeon
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why don't you show what you got for the first derivative?

steel minnow
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i don't know syntax so,
-e^(-x) * sin(x) + e^(-x) * cos(x)

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e^(-x) can be factored out

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e^x is never zero

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can't really figure out where sin(x) = cos(x) without a calculator

vale wigeon
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sure you can.

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sin(x) = cos(x) is equivalent to tan(x) = 1.

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(knowing of course that no value of x that makes cosine vanish could possibly be a solution to this equation, so we really are not missing anything)

alpine sable
#

A dome of a building is in the form of a hemi sphere. From inside, it was white-washed at the cost of Rs. 4989.60. If the cost of white-washing isRs20 per square meter, find the

(i) inside surface area of the dome (ii) volume of the air inside the dome

(Assume π = 22/7)

steel minnow
#

arctan(1) = x

vale wigeon
#

dunno what "quadrant method" means but arctan(1) is something you should know off the top of your head

steel minnow
#

i see

lone heartBOT
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limpid moss
#

could someone help with (ii)

strange meadow
lone heartBOT
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@pale merlin Has your question been resolved?

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@pale merlin Has your question been resolved?

pale merlin
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.remind

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.close

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sage vector
lone heartBOT
sage vector
#

part 3 is what i'm confused on

#

this is the diagram i made using technology

vale wigeon
#

well, you know that $\overrightarrow{OD} = \mu \overrightarrow{OB}$ for some scalar $\mu$

ocean sealBOT
vale wigeon
#

(you can even say right from the picture that mu is between 0 and 1)

sage vector
#

oh yeah i can see that

vale wigeon
#

so you have that (2 - 3λ/2) a + (λ/2) b = μ b

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and since you know that a and b aren't parallel, the coefficients must match.

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thus 2 - λ/2 = 0 and λ/2 = μ

sage vector
vale wigeon
#

...

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hang on

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oops yeah sorry i missed the 3

sage vector
#

all good all good

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wait so would it be 2 - 3λ/2 = 0 and λ/2 = μ

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what part would show the 2:1 ?

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the second half of it where λ = 2μ ?

sage vector
vale wigeon
#

yes

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or i would rather say the coefficient on a on the right is zero

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precisely because there is no a term

sage vector
vale wigeon
#

overthinking it.

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you can find the values of lambda and mu!

sage vector
#

ohh that's it? damn mb mb

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tysm for the help i'll try and finish this off !!

#

.close

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opaque coral
#

guys help

#

3√2 x 2√2

4√2

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and then what

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12

4√2

echo socket
#

Cancel 12 and 4

opaque coral
#

wdym cancel

echo socket
#

Divide 12 and 4 by 4

#

You should get
3

√2

opaque coral
#

so the answer is

#

3

√2

#

??

echo socket
#

I mean, yeah, unless you want a rational denominator

#

Then you should have cancelled √2's out

remote knot
#

can someone expain me vectors im in 8 grade and vectors is really hard like you gotta addd the y and x idk but please help

echo socket
remote knot
#

oh alr

opaque coral
#

ok tx

#

thx

#

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opaque coral
#

guys

lone heartBOT
opaque coral
#

help

#

wtf is thi

#

s

soft ore
#

Whats 9+10?

#

yes thank you

opaque coral
#

guyhs im genuingly confused

#

(32) -4/5

#

wtf

echo socket
#

32 = 2^5

#

Use this

opaque coral
#

32 = 32

#

0

mellow reef
#

32^-4/5

#

32 becomes 2^5

opaque coral
#

ohh

#

sorry

mellow reef
#

5 cancels out

#

its gon be 2^-4

#

since the exponent is negative

#

u get reciprocal

#

4 square is 16

#

so answer is 1/16

opaque coral
#

OHH

#

i understand

mellow reef
#

nice

opaque coral
#

so if i write it it looks like this?

#

@mellow reef

#

sorry for the ping

mellow reef
#

yep

opaque coral
#

ok tysm

#

.close

mellow reef
#

np

lone heartBOT
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alpine sable
#

how do you make a table of signs??

lone heartBOT
alpine sable
#

In my assignment we were told to get the x intercept of f(x) = x^4-x^3-2x^2
then to put it on table of signs, ive been trying to use yt tutorials but i still dont get how

i am not sure if my answer is correct but i factored it into :
x^2(x-1)(x+2)

i dont know how to put this in the table of signs

#

also please read this part: is my teacher even talking about this kind of table of signs
this was the instruction "explain table of signs of graphs of polynomial function and behaviour of the graph oh polynomial function using the leading coefficient test"

#

<@&286206848099549185> help me please

#

could you explain i dont really get it

#

what should i put in it

#

sorry but i dont understand

#

yea i got x intercepts 0, -1, 2

#

like this?
(-3) -2 (-1) 0 (?) 1 (2)

#

alr wait let me put those

#

like this?

#

like this???

#

oh

#

@sturdy tiger is my interval correct?

#

?

dry berry
#

help 💀

#

its basics for u lot prob

#

since im dumb

alpine sable
dry berry
#

but yh i need some help

#

huh

#

ok

alpine sable
#

man can only answer 1 question at a time

dry berry
#

ok

#

wheres that

#

nvm

alpine sable
#

yo hey

#

whats next

#

the test values

#

this? @sturdy tiger

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

@sturdy tiger do i put negative or positive

#

if the answer is 0?

#

oh ok

#

is this correct?

#

where?

#

the x-1 column?

#

oh this one

#

@sturdy tiger

#

whats next

alpine sable
#

can you say which test value ?

#

i cant tell where ur pointing

#

Squared?

#

Uh, graphing?

#

polynomial table of signs

#

Oh

#

sorry but can you circle it or something

#

ok

#

positive

#

so far correct?

#

Am not good in math but . . .

#

My answer is just too far from truth

#

2x^2?

#

Gtg

#

is that correct?

#

this?

#

thnx whats the next step?

#

sadly school doesnt see it that way

#

alr thnx man! btw last question

#

in the yt vids i watched they always said to invert the x intercept you found

#

for the roots in the table signs

#

did i have to do that?

#

or nah

#

like turn x intercept negative to positive and positive to negative

#

for it to become roots for the table of signs

#

its in a different language

#

so im not sure ull understand

#

this is the part where he inverts the factors

#

the factors

#

of y=

#

oh i thought u had to do that for the x-intercept

#

oh alr thnx man

#

oh ok

#

thnx again

#

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dire grail
#

iteration is hardOhNo_cat

wicked dagger
#

Why do you think it is hard?

dire grail
#

i dont know how to get started

wicked dagger
#

Keep n=0

#

You will see that x1 will also be 1

dire grail
#

wdym?

wicked dagger
#

They gave that x0 is 1

#

By keeping n=0
You can find value of x1

dire grail
#

ok

wicked dagger
#

Did you get value of x1 as 1?

dire grail
#

yes thank you, my sister talked me through it

#

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thick lynx
#

Why can an endpoint not be a local extremum?

After the definition of a local extremum, it's f(c) so that f(c) >= or <= f(x) for x in the neighborhood of c and x in the domain of f

thick lynx
#

If you are at the left endpoint, you could make the neighborhood just values right to c, no?

pallid scarab
#

It's regarding the definition of a neighborhood

#

If you take a neighborhood of c, you're gonna have to allow it outside of the domain

thick lynx
#

you just dont let it decrease, c is going to be the left endpoint of the neighborhood

pallid scarab
alpine sable
#

Help pls, It's about Functions

thick lynx
pallid scarab
pallid scarab
# thick lynx Why not?

A neighborhood of c is so that you can never approach c without getting into the neighborhood

pallid scarab
#

Yep

thick lynx
#

Alright, thank you

#

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pallid scarab
#

Np

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frigid raven
#

For G, consider using:
|G|^2 = |HF|^2 + |N|^2

lone heartBOT
#

Please don't occupy multiple help channels.

frigid raven
#

Closed the other one that was left.

nimble stratus
#

Hey guys can you tell me why the vertex formula is X=-b/2a ?

frigid raven
#

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tidal badge
lone heartBOT
tidal badge
#

Can someone check if this is correct

pallid scarab
#

Formulas are correct

#

I'm gonna guess the computations are also correct so...

#

👍

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@tidal badge Has your question been resolved?

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vapid jolt
#

Hey, how do you solve this for x. I know it is somehow done with the natural logarithm but the 250x is somehow in the way? Does someone know how to solve this?
Thank you
Nikolas

echo socket
#

Do you know lambert W function?

vapid jolt
#

No I don't, must it be used to solve this?

echo socket
#

Yes

#

Lambert W function is the inverse function of y = xe^x, so W(xe^x) = x

#

You can use this

#

Cuz here you get that xe^(-0.5x) = 3/25
-0.5xe^(-0.5x) = -3/50
-0.5x = W(-3/50)

vapid jolt
#

Ok, and then after what do you do? And is this the only way to solve it, or is there a simpler way=

echo socket
#

Not without the W

vapid jolt
#

Ohh wow, that's it. There is no way to determine a distinctive x?

echo socket
#

What do you mean by distinctive?

vapid jolt
#

Something like x = 6,5

#

for e.g

echo socket
#

No, I don't think there's a way to simplify W(-3/50)

vapid jolt
#

Ah ok, thank you very much for answering my question!

#

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untold pollen
#

This is basic maths, which is kinda humiliating to ask help for, but:

How many 5 digits dumbers can be made with 0,1,2,3,4,5,6,7,8?
9 x 8 x 7 x 6 x 5 right?

untold pollen
#

assumign you cant reuse a number

echo socket
#

That would be correct if you could use 0 as the first digit, so no

untold pollen
#

so 8 x 8 x 7 x 6 x 5 I assume then?

echo socket
#

Yes

untold pollen
#

Alright, thank you good sir

#

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#

.close

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dusk scaffold
lone heartBOT
dusk scaffold
#

I understand that it’s Pythagoras but when I do 24 squared + 40 squared then square root the answer apparently that’s not it

untold pollen
#

Not sure if the term in english is good, but 40 is the hypothenuse

echo socket
#

Cuz you're using it incorrectly

#

It's OB^2 + 24^2 = 40^2

rough crown
#

check which sides are the legs and which is the hypotenuse

dusk scaffold
#

Oh yeah I get it now

#

It’s a tangent so OB has a right angle

#

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@dire spade Has your question been resolved?

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@dire spade Has your question been resolved?

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@dire spade Has your question been resolved?

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@dire spade Has your question been resolved?

static tree
#

@dire spade has your question been resolved?

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alpine sable
lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

<@&286206848099549185>

alpine sable
#

<@&286206848099549185>

#

<@&286206848099549185>

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alpine sable
#

where did i go wrong in my problem solving?

tacit arch
#

error here

#

(a + b)^2 is not a^2 + b^2

alpine sable
#

what should it have been?

tacit arch
#

you combine the square root of x terms together first

#

$a \sqrt{x} + b\sqrt{x} = (a+b)\sqrt{x}$

ocean sealBOT
#

riemann

alpine sable
#

mm i see i think

#

so like -1√9x + √x = (-1 + 1)√10x ?

tacit arch
alpine sable
#

im confused then

tacit arch
#

put all the terms of square root x on its own side

alpine sable
#

so it would be like √10x = 16?

#

or 4√10x = 16

tacit arch
#

how are you getting sqrt(10)?

alpine sable
#

should i not be adding 9x and x together

tacit arch
#

$\sqrt{ax} + \sqrt{bx} \neq \sqrt{(a+b)x}$

ocean sealBOT
#

riemann

alpine sable
#

so it should just be 2√9x + 2√x = 16

tacit arch
#

yes

tacit arch
alpine sable
#

i am now ending up with 8/5... please help 😢

#

ahh ok

alpine sable
tacit arch
alpine sable
#

it should be 4√(9x + x) = 16 right

tacit arch
#

no

#

2a + 2b = 2(a+b)

alpine sable
#

ok

tacit arch
#

once you figure that out, use $(cd)^2 = c^2 d^2$

ocean sealBOT
#

riemann

alpine sable
#

umm so it would be 2√9x + 2√x = (2+2) * √16 ? but 16 isnt x

#

im so confused

alpine sable
#

where is 16 going in that formula

tacit arch
#

You're confusing yourself by writing sqrt (9)

#

You know what that is

alpine sable
#

i hope i do

tacit arch
#

Then you can square after that

alpine sable
#

6√x + 2√x = (6+2)√x ?

#

ahh i see

#

thank you for all the formulas

#

although where was i supposed to use (cd)^2 = c^2d^2? cause i just did 8√x = 16 to get 4

#

oh well, still thanks for the help though!

#

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full briar
#

Can someone help me out with this question?

#

I assume a would be 1

#

b would be 8

#

what would f(x) be?

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novel lichen
lone heartBOT
novel lichen
#

. The residents of a 14 meter high apartment building give a party in the shared backyard. Because it is going to rain, they stretch a sail to be able to party dry.

This tarp is attached to the gutter of the flat and the 2 meter high fence at the back of the garden. The sail is 35 meters long. How long is the garden?

Make the drawing on a sheet of paper.

Round to an inch. Give your calculation with this question and a decision.

#

does anyone know how id do this

#

how would i do this best

full briar
#

14 - 2?

novel lichen
#

35^2-14^2=1029

full briar
#

a^2 + b^2 = c^2?

novel lichen
#

yes

#

but i got 3 different numbers

full briar
#

what

novel lichen
#

my answer is 32.1

#

so i did

#

a^2= c^2-b^2

#

a^2=35^2-14^2

#

a^2=1029

#

a=32.1m

#

would that be the correct answer

full briar
#

maybe make it a triangle?

novel lichen
#

so like this then

#

hold on

#

i removed 2 meters

#

from both sides

#

that would make it

#

a^2= c^2-b^2

#

a^2=35^2-12^2

#

a^2=1081

#

a=32.88m

#

is that correct?

#

thats a difference

#

<@&286206848099549185>

modest lodge
#

Yes that looks correct.

novel lichen
#

so 32.88m would be correct

#

thank you

#

A window cleaner should wash a window on the second floor. The ladder must therefore be placed against the wall at 7 m above the ground floor. The base of the ladder should be 1.5 m from the house.

Make the drawing on the sheet of paper and add all sizes.

Calculate how long the ladder should be. Write down the steps to this question. (accurate at 0.01)

#

so i got this from that text

#

nvm thats wrong

#

i think

#

so

#

c^2=b^2+a^2

#

c^2= 7^2+1,5^2

#

c^2=51.25

#

c=√51.25

#

c=7.16m

#

<@&286206848099549185>

#

i find it wierd that if the wall is 7m

#

and it stands 1,5 m away from the wall

#

how the ladder only needs too be 7.16m

#

does that mean i did something wrong

#

i cant find it

daring palm
#

It's correct

#

@novel lichen

novel lichen
#

thank you!

#

.close

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weary beacon
lone heartBOT
weary beacon
#

I know I did something wrong just don't know what

tacit arch
#

Just find V in terms of W and maximize. Then plug W into L

weary beacon
#

k thanks

#

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pulsar hearth
lone heartBOT
pulsar hearth
#

Is it possible to make this series telescope

#

. Clos3

#

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arctic crane
lone heartBOT
#

Please don't occupy multiple help channels.

arctic crane
#

se sabe que = it's known that
calcula = calculate

lusty swift
#

use the value at 6 to find the first sum but make it so it goes to 5 instead of 6

#

expand the square in the second sun and tinker with coefficients

#

so that you’re able to express the third sum up to 5 in terms of the first two sums

#

and then just add f(6)^2

arctic crane
#

I did not understand, could you explain it to me on paint or something like that?

#

Thanks

lone heartBOT
#

@arctic crane Has your question been resolved?

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@arctic crane Has your question been resolved?

lone heartBOT
#

@arctic crane Has your question been resolved?

lone heartBOT
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rare spoke
#

I do not understand this can someone please help thank you

median vessel
#

For no. 6, I am using Gauss-Jordan Elimination in a matrix, but when I try to get the third column into triangle form, both variables cancel out. What do I do?

lone heartBOT
#

@rare spoke Has your question been resolved?

rare spoke
#

cool

lone heartBOT
#

@rare spoke Has your question been resolved?

clever folio
#

You'll basically substitute the stuff you know about sine into this equation and solve for cosine

#

Since the equation has a square on the cosine you will square root at the end

#

But recall cos^2(theta)=a tells you cos(theta)=sqrt(a) or cos(theta)=-sqrt(a)

#

The inequality involving cos(theta) in your problem tells you which one must be true.

rare spoke
#

Thank you I’ll try this once I can get a healthier state of mind

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bleak needle
#

i nedd help

lone heartBOT
bleak needle
#

i need help with balance method and division/multiplication with decimal numbers (im in 7th grade in swed, and im dumb lol) i have a test on this friday

#

i need someone to explain it to me

hard patio
#

Post a specific problem you are having trouble with?

lone heartBOT
#

@bleak needle Has your question been resolved?

bleak needle
hard patio
#

Huh

#

You mean like

#

Multiplying 5.66 by 943.45

#

And dividing

#

Watch videos online

#

Try “organic chemistry tutor”

#

Or “khan academy “

#

What ever works

bleak needle
#

uh

#

no

#

or yes but not really tho

#

illk take care of the decimal numbers n stuff

#

but what about the balance method?

hard patio
#

Context?

#

That’s a very vague name

bleak needle
#

ill take this pic as a example, i basically can really understand this

#

oh wtf, this pic is the worst tbh

hard patio
#

That’s just “solving linear equations in one variable”

#

You will find videos for that too

#

Really easily

bleak needle
#

yeah ik, but MY POINT is that i cant understand

hard patio
#

What do you not understand?

bleak needle
bleak needle
lone heartBOT
#

@bleak needle Has your question been resolved?

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#
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reef lark
lone heartBOT
reef lark
#

proving if its associative

#

a *b = 2(a +b)

#

2a + 2b

#

2^-1 •2a + 2^-1• 2b

#

a=b

#

a*b = a + b

#

is this enough to show it is associative?

#

or it's completely wrong?

echo socket
#

(a * b) * c = 2(a + b) * c = (2a + 2b) * c = 2(2a + 2b + c) = 4a + 4b + 2c, doesn't seem to be associative

reef lark
#

so (ab) c and a(bc) should i follow when proving associative

#

got it got it

#

thank you

vague coral
#

a * (b * c) = (a * b) * c

reef lark
#

how about the identity?

vague coral
#

a * 0 = 0 * a

reef lark
#

I'm still confused about identity

vague coral
#

neutral element, not identity

#

also a*(inverse of a for *) = 0

reef lark
#

so the if it's under multiplication it is always e=1? and addition e=0? is it still the same if it's 2n+2?

vague coral
#

under multiplication, its well known that its 1 (if you are dealing with Q, R, C), under addition its 0 (if Z, Q, R, C)

#

for matrix, identity matrix under multiplication and null matrix for addition

#

for function, identity function under composition law, and null function under addition

reef lark
#

okay okay

is there a source online that i can improve in binary operations, group and abelian group?

#

almost all in yt are concepts

vague coral
#

I use books, not internet worry

#

go to a library lmao

reef lark
#

i wish i could T_T

vague coral
#

in general, a quick google research and you find what you want

#

At least thats what I do, when im bored

reef lark
#

it was an assignment, i look up an answers but and conclude them

#

but not sure it was right

#

i don't want answers i just want to know if it was right or wrong

vague coral
#

it is

reef lark
#

thank you

#

.close

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#
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slow cargo
#

ABCD is a sqaure, aef = 90°, FE=FB=FC. Find FE\AB

slow cargo
#

Nvm

#

I solvw it

#

.clise

#

.close

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alpine sable
#

question

lets say you find out that
x = 1 + 2

when writing an answer and working out on a test, can you write it as
x = 1 + 2 = 3
or do you have to do it like
x = 1 + 2 ∴ x = 3

median oar
#

it doesn't matter as long as 1 side has x and the other has 3

#

i personally would write x=3 somewhere below my working and put a box around it to make sure it's clear that is my final answer

alpine sable
median oar
#

you could do it downwards

alpine sable
alpine sable
median oar
#

x = 1 + 2
= 3

then i'd write x = 3 with a box

#

well it's mostly implied there's an x on the left side

alpine sable
#

ya but it doesnt hurt

#

anyway thanks for insight

median oar
#

yeah, but if there's a lot of intermediate steps you can skip it

#

and just write x = whatever at the bottom

alpine sable
#

👍

median oar
#

just because sometimes the left side can be cumbersome to write

alpine sable
#

valid

#

anyway i have to zzzzzzzzz tysm :D

#

.close

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marsh coral
#

How to find angle CBD?

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#

@marsh coral Has your question been resolved?

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@marsh coral Has your question been resolved?

drifting beacon
#

BP=DP

marsh coral
#

so isos triangle and angle sum of triangle

drifting beacon
#

true

marsh coral
#

thx

#

.close

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rotund forum
#

A student council consists of 15 members.
If the committee of 6 needs 2 co-chairs (picked from within the committee). How many different ways can the student council form a committee of 6 with co-chairs?

rotund forum
#

<@&286206848099549185>

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#

@rotund forum Has your question been resolved?

alpine sable
#

have you been taught about combinations in school ?

#

to find out in how many ways the 6 comitees can be found, do the combination $\binom{15}{6}$ - then multiply that with the number of ways in which co-chairs can be found - $\binom{6}{2}$

ocean sealBOT
#

trololol !

rotund forum
alpine sable
#

what

#

what do you mean

rotund forum
#

15*6= 90
6 * 2= 12
90/12= 7.5

alpine sable
#

were you taught combinations in school ?

rotund forum
#

Yes I thought we multiply

alpine sable
#

no

#

$\binom{n}{k} = \frac{n!}{(n-k)! \cdot k!}$

ocean sealBOT
#

trololol !

rotund forum
#

So 15 is n?

alpine sable
#

if you want i can also prove why the formula is this, but it's quite long

alpine sable
#

and 6 is k

rotund forum
#

I see then I would have to make a another one and multiple?

alpine sable
#

yes

rotund forum
#

Okay I see

alpine sable
#

because \textbf{for each} $\binom{15}{6}$ combination you have a $\binom{6}{2}$

ocean sealBOT
#

trololol !

alpine sable
#

for each

rotund forum
#

I got 75075 @alpine sable

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rotund forum
#

.reopen

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hexed trellis
#

hi! i am not sure how to answer this, i have managed to isolate x and have the expression X = C * (A + B^-1)ˆ-1 and not sure what to do next

surreal vapor
#

I'm not sure i understand correctly, but you should be able to just calculate the matrix X now, since you know A,B and C 🙂

hexed trellis
#

but how do i simplify the bracket?

surreal vapor
#

I would calculate whats inside the parenthesis first. 1. Find B^-1. 2. Calculate (A+B^-1) 3. Find the inverse of the matrix (A+B^-1) 🙂

hexed trellis
#

ok! thank you 🙂

median osprey
#

Pls help

surreal vapor
# median osprey Pls help

w+(2w+5)+4w > 61. Then find out the smallest value of w for this inequality to hold. (It ends up being 7w+5 > 61 which means w > 8.

median osprey
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stiff axle
#

.

lone heartBOT
echo socket
#

Have you tried using Pythagorean theorem?

stiff axle
#

I want to know, what the length of x and x-3 is and I have only 65 square

hard patio
#

pythagorean theorem

stiff axle
echo socket
#

x^2 + (x - 3)^2 = (sqrt65)^2

dim oasis
#

$x^2 + (x-2)^2 = (\sqrt{65})^2$

ocean sealBOT
#

lexitorius

stiff axle
#

And then? Should I calculate (x-3)²

#

And -/65²

echo socket
stiff axle
#

I think it was a typing mistake

echo socket
#

You should get 2x^2 - 6x - 56 = 0

#

x^2 - 3x - 28 = 0

stiff axle
#

Now I understand, thanks men!

#

.close

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alpine sable
lone heartBOT
tacit arch
alpine sable
#

1

#

2cot(2x)=2cos(2x)/2sin(2x)

#

i dont know what identities they are using to prove this