help-0

[ripe elk]

that would solve that problem

[manic wind]

the structures can be in any direction, sure you could check the max bounding box and determining whether you'd go vertically or horizontally before hand, but I'm not sure how big of a difference that would make

but it could be worth it to test

[ripe elk]

well it would turn this from 5 rectangles to 3

[manic wind]

eg

there's no one best way

[ripe elk]

well just make it favor horizontals then

a tiny bias

it doesnt really matter for that

[manic wind]

what would be the point of any bias at all

always going horizontally would probably be sufficient

[ripe elk]

true

also remember that not all maps can be made

cause of the offhang

[manic wind]

not sure what you mean, for the overhang you would just add the overhang tiles and perform the GDM on that

[ripe elk]

like this is not possible

[gaunt dirge]

thats totally possible

here one sec

actually i don't even need to draw it

after you add overhang, it would just become a 7x5 rectangle grid

you're essentially just bordering the squares (their faces and corners) with another square

similar to the stroke effect in photoshop

[manic wind]

formal definition would probably just be looping through all tiles and adding a 3x3 outline, and the new shape formed includes the overhand

[gaunt dirge]

yes thats good

i think of it similar to minesweeper rules

where you count how many empty squares are adjacent and diagonal to each square

and put new squares there

[ripe elk]

oh wiat

nvmd

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[obsidian tapir]

i need help 😦

[violet wagon]

it looks like cofactor expansion and then factoring

[lone heart]

@obsidian tapir Has your question been resolved?

[obsidian tapir]

i have to use the matrix properties

[lone heart]

@obsidian tapir Has your question been resolved?

[lone heart]

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[sturdy sequoia]

help

[karmic pulsar]

What have you tried?

[naive valley]

"the" graph is misleading, there are infinitely many functions that satisfy these conditions

see if you can come up with a parabola that works

[lone heart]

@sturdy sequoia Has your question been resolved?

[lone heart]

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[ornate condor]

what do they mean order of elements?

so for n=1, we have s, 1 for a total of 2 elements?

idk what does order of each element mean tho

like i guess the order of the group would be 2?

[limpid turret]

Order is the value m such that x^m=1

[ornate condor]

so what does it mean for say D6

we have

{1, r, r^2, s, sr, sr^2}

so the order would be

{0, 1, 2, 0, 1, 2}?

for each of those elements respectively

[ornate condor]

wait or are they all order 3

[limpid turret]

Does r^1=1 for D6?

[ornate condor]

no

[limpid turret]

Does s^3=1?

[ornate condor]

i guess they r all order 3?

hm no

order 6?

[ornate condor]

so its this, for any x?

[limpid turret]

Each element will typically have it's own order

[ornate condor]

wait every element has a different order right

[limpid turret]

Ya

[ornate condor]

{1, r, r^2, s, sr, sr^2}

has orders

{0, 3, 3, 2, 2, 2}

like this?

or is 1 actually 1

[limpid turret]

1 is 1, yes

[ornate condor]

the rest r fine?

[limpid turret]

(sr)^2 is not right

Nor the last

[ornate condor]

hm

isnt that

srsr = sr r^-1 s = s^2 = 1

[limpid turret]

Oh word you're right

Haven't done algebra in a good while

[ornate condor]

yayy

im right

ok thanks

💕

.close

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[civic dagger]

how many triangles can be formed by joining vertices of polygon such that no two triangles share a common side?

[solid pasture]

need help on cos of EHF

[civic dagger]

I was trying to divide number of possible sides a polygon have to 3, but I realised some sides can just not intersect

Can someone give me a hindsight to solve the problem please?

[solid pasture]

hmm well
HF=7.5
FG=9
HG=10
EH=5
EF=6
and it said fond the cos of EHF and i have to idea

[civic dagger]

use cosinus law

[solid pasture]

doesnt that only work on 90 degree trangle?

[civic dagger]

no

[solid pasture]

ow
well Thank you very much

hyp is the longest
opp is shortest
adj the middle man
so
hyp=7.5
opp=5
adj=6
am i right?

cos=adj/hyp

6/7.5 ?

@civic dagger is it right?

<@&286206848099549185>

[manic wind]

@solid pasture open up your own channel, this one is occupied #❓how-to-get-help

[fallen verge]

I wanna say number of vertices choose 2 divided by 3

Rounded down

[civic dagger]

let n=5, your formula gives 3 while in this case it is 2 so no I guess

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@civic dagger Has your question been resolved?

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[polar trout]

what equation would I use to relate the variables?

[polar trout]

diag

I also drew a diagram for easier understanding

[lone heart]

@polar trout Has your question been resolved?

[polar trout]

<@&286206848099549185>

[tacit arch]

Try watching this
https://youtu.be/dUBeikdfK10

[polar trout]

alright thanks

.close

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[median oar]

Confidence Interval:

if i am given some normally distributed data, with an average ${\bar {X}}$, a standard deviation $S$ and a sample size of $n$

from the wikipedia page, $\Pr \left({\bar {X}}-{\frac {cS}{\sqrt {n}}}\leq \mu \leq {\bar {X}}+{\frac {cS}{\sqrt {n}}}\right)=0.95$

do i just plug and get the range? and let c = 0.975 for a 95% confidence

[tribal haven]

0.95 = 95%, not 0.95**%**

everything else looks correct

[ocean seal]

Frosst

[median oar]

example:
$\{\bar {X}} = 9584.70\
S = 291.41\
n = 1000\$

plugging in the values,

$\Pr \left({9584.70}-{\frac {0.975\cdot 291.41}{\sqrt {1000}}}\leq \mu \leq {9584.70}+{\frac {0.975\cdot 291.41}{\sqrt {1000}}}\right)=0.95\$
We can be 95% certain that the true mean is within $9575.72\leq \mu \leq 9593.68$

[ocean seal]

Frosst

[lone heart]

@median oar Has your question been resolved?

[median oar]

Can someone just check this is correct please

[tribal haven]

no, you're incorrectly plugging values for c

c is the point corresponding to the cth quantile of the distribution of the variable of interest

[median oar]

So I’m putting in 0.025 for the lower bound?

[tribal haven]

you plug in the x value corresponding to the 0.975 quantile of the distribution of mu, which since you've normalized it is just the standard normal distribution

should be something like 1.96

[lone heart]

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[lone heart]

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[weak pagoda]

hi, I need help differentiating this

[weak pagoda]

where y=y(x)

[limpid turret]

you know about implicit differentiation?

[weak pagoda]

yeah I do, but I think my answer is wrong

[limpid turret]

show

[weak pagoda]

dy/dx(y*x^(1/3)=ln(y))

=

1*(dy/dx)x(1/3)+y1/3x^-(2/3)=1/y*dy/dx

hard to type math on discord lol

[limpid turret]

looks good

[weak pagoda]

and then further

[limpid turret]

well so far so good at least

Surround text in backticks (`) to remove formatting

1*(dy/dx)*x*(1/3)+y*1/3*x^-(2/3)=1/y*dy/dx

[weak pagoda]

dy/dx(x^(1/3))-(1/y)=(-1/3x^-(2/3)*y)/(x^1/3)-(1/y))

ahh it got kinda messy there

[limpid turret]

I'm not good at LateX, but here's what you wrote so far at least:

[weak pagoda]

uhmm

end answer i got was dy/dx=(-1/3x^-2/3)y/(x^1/3)-(1/y)

[limpid turret]

I think you accidentally combined two steps here.

[weak pagoda]

I did, its so hard to type so I just skipped ahead

[limpid turret]

for sure

Yes that answer looks right

I got the same

so good work

[weak pagoda]

thanks, but when I type it into wolframalpha and symbolab i get something completely different

so idk whats right or wrong, I guess I just needed someone to double check it

[limpid turret]

Probably just does extra algebra

Well yeah, I got exact same answer

[weak pagoda]

but this answer is still fine, right?

[limpid turret]

yes

you could probably simplify the fraction stuff a bit, but I don't see a need personally

[weak pagoda]

nahh im good 😄

[limpid turret]

Wolfram will sometimes give strange looking answers which -in reality- are just your answers but with some aggressive algebra changes

[weak pagoda]

ahh okay, I see

[limpid turret]

A byproduct of how it solves things and using limited resources to respond to your queries.

[weak pagoda]

makes sense

but yea, there's two parts to this problem really

this is the full problem, in norwegian though but I can translate

[limpid turret]

Better be speedy, because I'm off to bed in like 5 min

[weak pagoda]

alright

so it says that y=y(x) which is a function of x

which is fair

such that y(1)=-1

[limpid turret]

you're given y(1)=-1, then user Euler's method to approximate y(2)?

Did I get that right?

[weak pagoda]

yes

[limpid turret]

So you need to find the equation of the tangent line at (1, -1)

you have one of the points, (1, -1)

Now you just need the slope

which is dy/dx

You can calculate that since the x and y were given to you.

[weak pagoda]

ah so we use x=1

[limpid turret]

yee

[weak pagoda]

which is y=-1?

gotcha

and then we just put in the values in the differentiated equation?

[limpid turret]

yup

that will give you dy/dx (your slope)

[limpid turret]

Then you have your y=mx+b line

[weak pagoda]

alright

but where does eulers method come into play?

[limpid turret]

Oh right it's a repeated process.

(Been a good decade since I've done this stuff)

I think just reading up would be more helpful

https://en.wikipedia.org/wiki/Euler_method

[weak pagoda]

we're supposed to find a numerical approximation to the value y(2)

[limpid turret]

There's a nice example in there so that should help

wish I could stay to help but I'm an hour past my bedtime

So best of luck

[weak pagoda]

alright, thank you for the help

hope you sleep well ^^

[ripe glen]

Hi

I need help for this

[lone heart]

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[sudden nebula]

Scenario: Mr. and Mrs. Torre are planning to have their own home but have limited budget. They went to a bank for some advice as to how they can produce enough for the down payment on a house and lot they have chosen. This is the advice of the bank:

[sudden nebula]

If you will invest P20,000 at the end of each year for 5 years in an account that pays interest at 10% compounded annually, you will have the amount for the down payment of the house and lot at the end of 5 years.

What type of annuity is being asked in the problem?

Future Value Simple Ordinary Annuity
Present Value Simple Ordinary Annuity
Future Value General Ordinary Annuity
Present Value General Ordinary Annuity

I'm very confused with this problem I hope someone can help me and sorry for bad English

<@&286206848099549185>

please help :< this is the only question im stuck at :>

[lone heart]

@sudden nebula Has your question been resolved?

[lone heart]

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[rigid island]

Hey, I’d like help with a problem

[rigid island]

4x-2=6

I’m starting algebra so I don’t really know how to even begin this

[thorny haven]

Hello zoraida

$4x-2=6$

[ocean seal]

ItzAine

[thorny haven]

if youre still new to algebra, theres a whole number of different ways to look at these equations

personally I look at them as sides, left side or right side

when you move something to the other side, a + becomes a -, a * becomes a /

in our real day to day life we dont say we have positive 6 apples, we just say we have 6 apples. In algebra we dont need to write the + if there is no addition to it

lets move the -2 to the other side of the =

[thorny haven]

remember this rule

-2 becomes +2 when you move it to the other side of the =

the = will be the "middle"

we then have $$4x=6+2$$

[ocean seal]

ItzAine

[thorny haven]

can you complete this? @rigid island

[rigid island]

so

would i move the two back to the other side

because that’s how they gave it to us

@thorny haven

[thorny haven]

just complete the right side

[sly comet]

bro why are u teaching it incorrectly @thorny haven

[thorny haven]

wdym @sly comet

[sly comet]

4x-2 = 6

because whenever u wanna get rid of 2

[thorny haven]

theres a ton of ways to do it

[rigid island]

so would the right side be 4

[sly comet]

u subtract

so its 4x -2 -2 = 6-2

which is 4x = 4

[thorny haven]

bruh

u add 2 not subtract 2

[sly comet]

no because ur trying to get rid of 2 bro

stop trolling

[rigid island]

why don’t we divide it

[thorny haven]

yea -2 -2 is not 0 dumbo

🤦‍♂️

[sly comet]

stop fucking calling me dumb

ur so stupid bro

[thorny haven]

bro look at ur math

[sly comet]

im gonna get my proffessor

[rigid island]

guys relax

[sly comet]

to prove it

[thorny haven]

u said 4x-2-2

[keen pine]

What

[sly comet]

yeah mother fucking fucking

[thorny haven]

when is negative 2 minus 2 a 0

LMAOO

-2 -2 = -4

[rigid island]

but we don’t we divide it

[keen pine]

Yea

[rigid island]

why don’t we divide it

[thorny haven]

because we cant

[rigid island]

why

[thorny haven]

we need to have 4x alone to divide

not 4x-2

[rigid island]

why do we need to have it alone

[sly comet]

bro r u fucking clapped in the mind???? u can divide both sides by 4x-2

and then its equal to 1

[rigid island]

but why are we dividing

YOURE CONFUSING ME DUDE

[keen pine]

Bro what

Ok what's the question

[rigid island]

please stop i need to submit this tmrw please

[keen pine]

💀

[sly comet]

we divide because like u want to solve the thing and dividing cancels out everything to get x

[rigid island]

4x-2=6

[sly comet]

@thorny haven bro

sometimes u need to not troll because people nbeed genuine help

[keen pine]

X is 2

[rigid island]

so then we would divide both sides by 4x-2

[keen pine]

Because 4x = 8

[rigid island]

and that gives us 2

[thorny haven]

well u can divide but u gotta do both sides

[rigid island]

is that why it’s 2

[thorny haven]

and not one side

[keen pine]

4 * x has to be 8

So x is 2

[rigid island]

how

[thorny haven]

mans is talking with bubbles coming out his mouth

[keen pine]

4x/4 = 8/4

[rigid island]

where did the 8 come from

[thorny haven]

6+2

[keen pine]

Ok so

[rigid island]

but then where did 6+2 come from

[keen pine]

4x - 2 = 8

[rigid island]

aren’t we looking at 4x

[keen pine]

Bro 💀💀💀💀

[rigid island]

yeah

[thorny haven]

Yo we going everywhere with this 😭

[keen pine]

Ok so

[keen pine]

Fr man

[sly comet]

bro he has a point and ur just ignoring it actual fking troll like wtf bro fucking

[keen pine]

Chill dude

[rigid island]

STOP SWearing and let me learn

so 4x-2=8

[thorny haven]

4x-2=6

was the original question

[rigid island]

the we times both sides by 2

[keen pine]

No

[sly comet]

aight laters im going deuce and peace 🤘

[rigid island]

oh sorry that one

[keen pine]

What grade are you in?

[rigid island]

year 5

[keen pine]

I see

[thorny haven]

they teach algebra in YEAR 5

[keen pine]

💀

[thorny haven]

damn

[sour jolt]

4x-2=6
4x=6+2=8
x=8/4=2
Am I right?

[keen pine]

Ikr

[keen pine]

Yes

[rigid island]

i go to advanced school

wait so

[keen pine]

Nice

[rigid island]

4x-2=6

then we times both sides by 2

[keen pine]

Yes

No

[rigid island]

because x=2

[thorny haven]

whaa

nonno

[keen pine]

Not times

Add

Ok I learnt it like this:

Take -2 to the right hand side of the equation

-2 becomes positive

So it's plus

[thorny haven]

yes thats how i learned it as well :)

[keen pine]

But you could also think of it by adding 2 to both sides

[keen pine]

Nice

[rigid island]

why are we adding 2

[keen pine]

To get 0

Because -2+2= 0

[rigid island]

but why aren’t we getting 4x

but isn’t x what we trying to find

[keen pine]

We're getting it by itself

[keen pine]

Yes

We dont know what 4x is

[thorny haven]

to get 4x by itself from 4x-2, we need to add 2

[keen pine]

But we know when we -2 from 4x we get 6

So 4x has to be 8
Because 8-2=6

[rigid island]

so to if we took the second derivative of both side then divided it by e, and multipled it by i, then intergrated by parts we would get x=2

[keen pine]

Yes

[thorny haven]

yo what the heck we dont need to do derivatives

[keen pine]

Not second derivative what 💀💀💀💀

[thorny haven]

this not no calculus 😭

[rigid island]

but we did that today at school

[keen pine]

Lmaoaoa

[thorny haven]

YOURE TROLLUIBNG

[keen pine]

Ok this guy's trolling

[rigid island]

what

[keen pine]

Yea

My godddd bro

Lmao

[rigid island]

so wait let me try again

[rigid island]

4x-2=6

[keen pine]

e^πi = -1

[rigid island]

that’s beautiful

idk how they calculated that

when both e and pi are irrational

[keen pine]

When you skip algebra and jump straight to calculus:

[keen pine]

Yes

[rigid island]

wait pi * i would need to give you an even integer no

[keen pine]

No

[rigid island]

since e^pi i would need to be real

[keen pine]

I actually haven't studied this yet so idk

I just know e^pi i = -1

[rigid island]

yeah

[keen pine]

yeah

I have no idea why it's e

[lone heart]

@rigid island Has your question been resolved?

[pliant estuary]

it comes from eulers identity

[keen pine]

Oh yea

[lone heart]

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[vale wigeon]

show work

[keen pine]

If each side increases by 5m/s then the volume will increase at 125m³/s

Yes

Wait I got it

So the initial volume is 1000m³

So each side is 10m

If one side increases by 5m every second

The volume increase per second would be 5×10×10 which is 500m³/s

Yea

Yea

Let's just think any one side increases by 5, maybe the L

Yea

[open hound]

i think all sides increase by 5, thats why it refers to it as a cube, stupid worded question tho

[lone heart]

@grizzled raptor Has your question been resolved?

[keen pine]

Very

[open hound]

you could also argue that

mhm

thats why its a stupid question

[lone heart]

@grizzled raptor Has your question been resolved?

[lone heart]

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[haughty yoke]

hey how do i compute the minimal distance between an ellipse(the edge) and a point?
i know how to calculate the distance between two points but im not very good at math in general?)
is there any way i can find like a equation for a ellipse if i have the two radius?
im trying to make a code that checks if two ellipses are overlapping.

[lone heart]

@haughty yoke Has your question been resolved?

[lone heart]

@haughty yoke Has your question been resolved?

[haughty yoke]

i give up whatever

[ocean seal]

Mehdi_Moulati

[haughty yoke]

What is a what is b?

[haughty yoke]

Hmm this us complex

[hollow sparrow]

What language do you work with?

[haughty yoke]

c++

I mean the programming is easy or atleast i can figure it out

Im just unsure how id check if two ellipses are overlaping

[hollow sparrow]

there is three variable to draw an ellipse
the center , major axis and minor axis

[haughty yoke]

Yes

I have a framework that allowes me to draw ellispes

Using these three variables

My makeshift solution is just checking if the distance between all point on the circumfrence on ellipse 1 and ellipse 2 are < 1 pixel

Essentially

But this is a very bad solution

And doesnt work if one ellups is fully inside the other

[hollow sparrow]

you can optimize that and check only the distance between the center of two ellipse

[haughty yoke]

For what

I have to check a number against something XD

I cant just check a number

[hollow sparrow]

if the distance between the center > 2*Max(a,b) than is not overlapping

[haughty yoke]

Whats Max(a,b)

[hollow sparrow]

function

a and b are distance

[haughty yoke]

A+b?

What does Max() do

Tehec

[hollow sparrow]

find the maximum value between a and b

[haughty yoke]

The max value between two radius?

What does that even mean

And i have 4 radius 2 a's and 2 b's

Since theres two ellipses

[hollow sparrow]

let me see your code

[haughty yoke]

Ok

any specefic code you want?

you're asking me for code that doesnt work.

[hollow sparrow]

one loop is enough

take one point from an ellipse

[haughty yoke]

if i remove a loop i will only check if they are perfectly overlapping

and even then this is a bad solution

[hollow sparrow]

i know

[haughty yoke]

cause it only take into account the circomfrence

[hollow sparrow]

let E1 is ellipse with center (cx,cy) and radius X and Y

[haughty yoke]

the annoyence is that the intersection isnt on the line

from 1 center to another

[hollow sparrow]

the equation of an ellipse in generale :
$\frac{(x-cx)²}{X²} + \frac{(y-cy)²}{Y²} \le 1$

[ocean seal]

Mehdi_Moulati

[hollow sparrow]

if one point from other ellipse

<= 1 of this function then the two ellipse are overlapping

[haughty yoke]

i have no clue wht x and y are

[hollow sparrow]

x and y are coordination of a point (x,y)

[haughty yoke]

which point

[hollow sparrow]

any point

[haughty yoke]

which point

[hollow sparrow]

any point from the space

[haughty yoke]

k

[hollow sparrow]

for example point (1,2)

if i replace x by 1 and y by 2

[haughty yoke]

i dont understand how a random point in space has effect on my ellipse

[hollow sparrow]

and i found that the equation is less or equal 1 then that point is inside the ellipse

,w graph x²/9² + y²/1 <= 1

[haughty yoke]

a ellipse

so do you want me to check for every point of a ellipse if its forfill that equation?

cause like i think an ellipse has alot of points

[hollow sparrow]

you can make it like a function

bool isOverlapping(point,Ellipse){


float X_2 = pow(Ellipse.radiusX,2);
float Y_2 = pow(Ellipse.radiusY,2);
float C_X = Ellipse.center.x;
float C_Y = Ellipse.center.y;

return (pow(point.x - C_X,2)/X_2 + pow(point.y - C_Y,2)/Y_2 <= 1);
}

[haughty yoke]

yeah

[hollow sparrow]

this code is to test if a point is inside an Ellipse

[haughty yoke]

its not working

[hollow sparrow]

so we will take every point from the other ellipse and test it

[hollow sparrow]

i didn't give the type to point and Ellipse (parameters)

[haughty yoke]

oh bruh you mispeled radius

[hollow sparrow]

i just want to give you the hint about what i'm saying

[haughty yoke]

it work

okay i see this is a good start

so now i need to figure out what points would go inside of eachother ?

[hollow sparrow]

if a point in the edge of an ellipse inside other ellipse

then both ellipses are overlapping

[haughty yoke]

well the thing is id be silly if i have t check every single point

[hollow sparrow]

there is a way

[haughty yoke]

i mean effeciency wise

[hollow sparrow]

i know

but you need to solve an equation

more complicated

[haughty yoke]

i guess i could like get a few points from ellipse 2

using a for loop and chaning an angle

no wait then i get the same problem

[hollow sparrow]

what problem ?

[haughty yoke]

well if my first ellipse is smaller then my second one

then the point on circomfrence will all be outside the ellipse

[hollow sparrow]

now you need to test the distance between the centers

[haughty yoke]

i have a distance etween centor function

i have a distance function

i have all these function that sortof do what the name suggests

OMG

wait i can determin ethe angle

between the centers maybe

[hollow sparrow]

return getDistance(Ellipse.center,Ellipse1.center) <=
 min(Ellipse.radiusX,Ellipse.radiusY)

[haughty yoke]

im still not sure what min is supose to be

[hollow sparrow]

the minimum

[haughty yoke]

i get that min implies the word minimum

but what is minimum of two numbers

???

[hollow sparrow]

in C language you need to import #include<math.h> to use it

[haughty yoke]

you mean a subtraction?

[hollow sparrow]

i don't know for c++

[haughty yoke]

like what does min do

i want to understand it

[hollow sparrow]

min(1,2,3) = 1

[haughty yoke]

AHHH

wow

ok

[haughty yoke]

this would not work

[hollow sparrow]

i guess in c++ :
std::min()

[haughty yoke]

im just saying that it wont work

two ellipses can overlap

when

they are next to eachother

[hollow sparrow]

when at least one point is commun between two ellipse

i know

[haughty yoke]

like look if i do the distance between the centers

is less then either the x radius or y radius of onl one

then its not gonna work

like do you understand what i mean

[hollow sparrow]

the distance of the centers is less then both radiusX and raduisY

[crude brook]

what

[haughty yoke]

?

[hollow sparrow]

#❓how-to-get-help #rules

[haughty yoke]

the distace of the center doesnt matter

i dont know how to explain this to you

the intersection of two ellipses doesnt happen on the distance with the two centers

Look my two ellipses are overlaping but the distance from the centers is larger then the radius

[hollow sparrow]

we will use it only if we find that the ellipse inside the other one

we that happend

be sure that the center of one of them will be inside the other one

[haughty yoke]

right..\

so you want me to check if all the points of the circomference of one ellipse inside the other ellipse

and or if the distance from the two centors are withing a certain radius

[hollow sparrow]

if(ellipse intersect with other )
return true
else
take point from an ellipse1 and test on ellipse 2
if true
return true
else take point ellipse2 and test on ellipse 1
if true
return true
else
return false

[haughty yoke]

right

but like what is the first thing supose to be

[hollow sparrow]

the for loop that you did

[haughty yoke]

but thats terrible

[hollow sparrow]

you take all the point in the edge

[haughty yoke]

i chec all the poiints on the edge??

[hollow sparrow]

i know but for now

i m trying to find a better solution

[haughty yoke]

math is too hard

[hollow sparrow]

like you did in the photo

[haughty yoke]

why is it so hard

[hollow sparrow]

haha who knows

it's hard for our brain

[haughty yoke]

i really want to like it but like why am i so bad at it

[hollow sparrow]

you need to start from the basic

that's why I join this group

[clear current]

can someone. help with 17

[hollow sparrow]

#❓how-to-get-help

[hollow sparrow]

@haughty yoke i guess something like that

bool isPointInEllipse(point,Ellipse){
    float X_2 = pow(Ellipse.radiusX,2);
    float Y_2 = pow(Ellipse.radiusY,2);
    float C_X = Ellipse.center.x;
    float C_Y = Ellipse.center.y;

    return (pow(point.x - C_X,2)/X_2 + pow(point.y - C_Y,2)/Y_2 <= 1);
}

bool  isOverlapping(Ellipse,Ellipse1){
  if(isPointInEllipse(Ellipse.center,Ellipse1) ) return true
  else if(isPointInEllipse(Ellipse1.center,Ellipse) ) return true
  else{
    for(deg = 0 ; deg < 360; deg+=1){
      double rad = Math.pi *deg /180
      double x = Ellipse.center.x + Ellipse.radiusX * cos(rad)
      double y = Ellipse.center.y + Ellipse.radiusY * sin(rad) 

      if(isPointInEllipse( point(x,y),Ellipse1)) return true;
    }
  }
  return false;
}

[lone heart]

@haughty yoke Has your question been resolved?

[hollow sparrow]

i have an idea

i just need to verifier something

we can test only four point (the points intersect between the black line and the two ellipses)

[hollow sparrow]

A and B are centers of the ellipse

i just need to know if there's a function (already build-in) to find the angle between tree point

[haughty yoke]

Between three point?

What

Theres many angles between three point

I havw a function between two points

An the x axis

[hollow sparrow]

what i want to do is find the coordination of points D, C, E and F

and that by find the angles GBF and GBC

if one of the points D, C, E or F inside both of the Ellipses then the two ellipse overlapping

[haughty yoke]

that might work

i mean do i evne need to check all four points?

no that doesnt work actully

[haughty yoke]

look t this image

your assumption that the overlap is on the line connecting the 2 centors which isnt always true

[haughty yoke]

?

[hollow sparrow]

it's not true if we could rotate the ellipse

[haughty yoke]

?

no like im saying checking those four points

wont work

cause if you look at my picture

none of those four points are in both

ellipses

yet the ellipses are overlapping

[hollow sparrow]

we are not check if the point is on the edge

we check if the point is inside the ellipse

[haughty yoke]

yes

you said four points

right

you wanna check four point for if they are in both ellipses?

[hollow sparrow]

at least one of them

[haughty yoke]

and you say the points

that are intersetting the circumference of the ellipse

and the line made my the two centers

which would mean this

[hollow sparrow]

the point D and E of the orange Ellipse are inside the blue Ellipse

[haughty yoke]

for mycase it doesnt work

[hollow sparrow]

ohh

now I understand your point

[haughty yoke]

the intersections isnt always on the line

yeah...

i guess i wait for smart math people to help

[lone heart]

@haughty yoke Has your question been resolved?

[lone heart]

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• Show your work, and if possible, explain where you are stuck.
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[flint badge]

There are twice as many quarters as half-dollars and two more than twice as many dimes as half-dollars. If the total for the coins is $5, how many coins of each type are there?

[icy crane]

any ideas?

@flint badge

[flint badge]

Let quarters = 25x
Let half-dollars = 50x
Let dimes = 10x

25x * 50x + 2(10x)*2 = 5?

[icy crane]

hmmm no no you're starting off wrong

[flint badge]

i got stuck there

[icy crane]

instead write it like this.
let quarters = x
let half-dollars = y
let dimes = z

[flint badge]

ok

[icy crane]

(these are the quantities of coins. what you wrote was how many cents each coin is worth)

ok. so now write the first sentence in terms of x,y,z

"There are twice as many quarters as half-dollars"

[flint badge]

x * y?

wait no

[icy crane]

no no, it has to be something = something else

[flint badge]

2x

2x = y

[icy crane]

close, but in fact it's the other way around

[flint badge]

2y = x?

[icy crane]

yes

[flint badge]

k

[icy crane]

now the second sentence

"two more than twice as many dimes as half-dollars"

[flint badge]

2y + 2 = z

2z + 2 = y

[icy crane]

one of those two is correct 😄

[flint badge]

2z+2=y?

[icy crane]

nope

the other one

[flint badge]

2y + 2 = z

[icy crane]

yes.

now the 3rd equation

5 dollars in total

[flint badge]

i got stuck on the third equation

[icy crane]

alright... how many quarters did we say we have

[flint badge]

twice as many as half dollars

[icy crane]

sure sure. but without mentioning half dollars

we just said we have "x" quarters

[flint badge]

right

[icy crane]

if we only look at our x quarters, how much money would we have? remember that one quarter is 0.25 dollars

[crude brook]

1÷0=0 certain?

[flint badge]

2(25x) = 50

50x=50
x=1

[icy crane]

@crude brook go to another help channel

[icy crane]

no, no

before you write any equations

answer this very simple question:
if we have 1 quarter we have 0.25$
if we have 2 quarters we have 0.5$
if we have 3 quarters we have 0.75$
if we have 4 quarters we have 1$.

if we have x quarters we have ???

[flint badge]

x?

no

wait

[icy crane]

the answer contains x but is not just x

[flint badge]

ok uhh

1x?

no

[icy crane]

1 times x equals x so no 😄

[flint badge]

25x?

[icy crane]

well. close enough. it's 0.25x

[flint badge]

if we have x quarters we have 0.25x

[icy crane]

we have 0.25x dollars , yes

what if we have y half dollars? how many dollars is that?

[flint badge]

*0.50y

[icy crane]

yep

wait what's that star doing there 🤔

[flint badge]

oh i accidentally wrote 0.50x before and was making a correction

[icy crane]

alright alright

and what if we have z dimes? how many dollars is that

[flint badge]

0.10z

[icy crane]

great

now the total amount of money is the dollars we have from all our quarters half dollars and dimes put together

and it's equal to 5$

can you write the equation now?

[flint badge]

2(0.50y) + 2 = 0.10z?

0.50y+0.25x+0.10z=5

[icy crane]

the second thing you wrote is correct

[flint badge]

ok so

[icy crane]

so to recap we have three equations:
x = 2y
z = 2y + 2
0.5 y + 0.25x + 0.10z = 5

you can substitute x and z in the third equation and solve for y

[flint badge]

0.25 = 2(0.50)?

[icy crane]

not sure what you did here but it's definitely wrong

follow my instructions, "substitute x and z in the third equation and solve for y"

basically take the third equation. but wherever you see x, write 2y instead

and wherever you see z, write 2y+2

I have to go now, so I'll just tell you the solution.
the 3rd equation becomes:
0.5 y + 0.5 y + 0.2y + 0.2 = 5 . and if you solve it you get y = 4. then you go back to the other two equations and set y=4, so x = 8 and z = 10.

[lone heart]

@flint badge Has your question been resolved?

[icy crane]

@flint badge that problem was too hard for you. you have to go back and do simpler problems before you can understand it

[flint badge]

oh its my homework lol

[icy crane]

you have to look at the homework you did 2 weeks ago then. get the basics right first

[elfin moat]

dam

[lone heart]

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[stoic gyro]

So my prof told me we are not dealing with edges that loop in on itself

didn't teach it in the class and then asks a question about it

any suggestions on how to do this

[lone heart]

@stoic gyro Has your question been resolved?

[spice aspen]

how to make tht into a pie chart?

[stoic gyro]

@spice aspen I'm trying to use this channel right now. If you go up to the "math help(available)" section you can post your question in there

<@&286206848099549185> does anyone know how to solve my problem? or help guide me to the solution

[remote heron]

sub graph

i do not

[stoic gyro]

D:

[remote heron]

what is a subgraph

,w subgraph

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by jan Niku#2119

[remote heron]

oh

can it just be the powerset?

[stoic gyro]

I have no idea

what's throwing me off is the loop

our prof specifically said we are not going to cover those problems

[remote heron]

https://math.stackexchange.com/questions/2484069/how-many-subgraphs-of-this-simple-graph

[remote heron]

this part seems like itd be easier i think?

[stoic gyro]

erm give me a sec

What do you mean by this part

[remote heron]

the loop

it only adds two graphs

well

one it doesnt add

one it adds

[stoic gyro]

i mean How i was thinking about it

is the loop makes a group of sub graphs

if the loop is present point a -> b is counted once

if the loop isn't present point a -> b is counted

[remote heron]

[stoic gyro]

so whatever my final answer is shouldn't i just double it?

double it - 1

[remote heron]

well it might not exist in every subgraph

the loop cant exist if x2 doesnt

actually i think

i think you lose half the vertices if you remove x2

right

no, all but 1

[stoic gyro]

i'm talking about e1 sorry

if e1 isn't there

[remote heron]

okay we can find 2

lets start enumerating

1. No graph
2. Original Graph\

actually, screw 3

lets count it with combinatorics

so the 2 obvious ones

then you have uhh

$\sum _1 ^4 \binom4i$

[ocean seal]

jan Niku

[remote heron]

removing only vertices

sorry, edges

removing only edges

[stoic gyro]

4 choose 4 + 4 choose 3 + 4 choose 2 + 4 choose 1 ?

[remote heron]

yea

since you could remove all, only 3, only 2 or just 1

removing none is already counted

as 2 above

i think removing vertices takes more care

unless theres a nice formula

[stoic gyro]

This is the formula that is in our lecture

at the top?

[remote heron]

complete graph?

this isnt complete tho

maybe youre talking about something else

theres only uhh

theres only 6 cases

for removing vertices

id juts enumerate them by hand

[stoic gyro]

im not going to lie I have attempted to do that

[remote heron]

actually

its just 6 right

the only concern would be like

[stoic gyro]

4 choose 4 + 4 choose 3 + 4 choose 2 + 4 choose 1 isn't right either

[remote heron]

you have duplicates

but i dont think that will happen

[remote heron]

nah, were still no there yet

[stoic gyro]

okay i'm 100% lost

[remote heron]

so you have

in my mind

4 things

you can remove everything or nothing

[stoic gyro]

yes 4 edges

[remote heron]

or remove just some edges

or remove just some vertices

or both

weve enumerated the first 3

idk because this graph is so simple

you might not pick up any extra cases in the last one

also id say for sure idk how to do this the right way

im just trying to think of A way to do it

so what you need to check is

lemme draw the 6 graphs that result from removing vertices

[stoic gyro]

I thought i wasn't allowed to remove the x2, x3, x1

[remote heron]

why not

and

i think doing this constructively is the wrong way now

but

were close anyways

[stoic gyro]

erm if you say so? I have guessed everything between 12-20

[remote heron]

its more than that

we have 23 so far

plus i think there are at least another

4 or 5

[stoic gyro]

30

the answer is 30

[remote heron]

yea

getting close

[remote heron]

fun question

this would be a fun combinatorics problem

[stoic gyro]

i have no idea what's going on

:' )

[remote heron]

yea the MSO

read the MSO*

https://math.stackexchange.com/questions/2484069/how-many-subgraphs-of-this-simple-graph

its essentially a combination problem

with a tiny amount of graph rules strapped on

(edges can only connect vertices)

i wonder what the general form of this is

[stoic gyro]

I'll ask my prof for help tomm

to better understand + ill read this doc

thank you!!!

[remote heron]

ah

more technical stuff here

and np

[molten pivot]

Lol

[remote heron]

do you like my link

[molten pivot]

You can delete the tracking

[remote heron]

i dont wanna be tracked

[molten pivot]

You are being tracked.

[remote heron]

https://media.discordapp.net/attachments/342850939306246145/846505250797387786/ezgif-2-fe5b02a4728d.gif

[molten pivot]

I am tracking you.

🐸

[remote heron]

oh crap

they bring in isomorphisms into this

so that would actually collapse some of your 30

[stoic gyro]

why did my thing get deleted

[remote heron]

i think

you lose at least

4?

wild

[stoic gyro]

well thank you again! on to the next impossible question

[remote heron]

[stoic gyro]

!answered

[remote heron]

.close

[lone heart]

Channel closed

Closed by @remote heron

Use .reopen if this was a mistake.

[remote heron]

[stoic gyro]

thank

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thorn patio]

anyone spot anything wrong with this?

[wind cloak]

Looks good to me

[thorn patio]

H was wrong 😦

apparently theres a specific case

where h is false

is mod(zw) = mod(z) x mod(w) ?

[remote heron]

well if $z = 6e^{i\theta_z}$ and $w=4e^{i\theta _w}$

[ocean seal]

jan Niku

[remote heron]

whats $wz$

[ocean seal]

jan Niku

[remote heron]

i realize this doesnt cover every case just

a way to think it through

[thorn patio]

$24e^{{i\theta_z}+{i\theta _w}}$

[ocean seal]

Techno

[remote heron]

it boils down to like

$|a||b| = |ab|$

[ocean seal]

jan Niku

[thorn patio]

so the same thing with argument?

but with addition

arg(wz) = arg(w) + arg(z)

[remote heron]

write your numbers as generally as you can in exponential form

that should give you the answer

[thorn patio]

i mean this shows me answer for this case

[remote heron]

obviously you have to be careful about Arg and arg

[thorn patio]

woah

whats the difference?

[remote heron]

i just mean

obviously you have non-uniqueness in the argument

you need to be aware of that

maybe

depends on your hw

[thorn patio]

im confused

is Arg and arg different notation?

do they mean different things?

[remote heron]

yea

Arg is unique

like $\arg (i) = \frac \pi 2 + 2k\pi$

[ocean seal]

jan Niku

[remote heron]

but $\text{Arg} (i) = \frac \pi 2$

[ocean seal]

jan Niku

[thorn patio]

i see

is Arg the principle argument?

[remote heron]

it might not be important

[remote heron]

yea, iirc

principle value, principle argument

Arg

[thorn patio]

then arg is just a general argument of the complex number

[remote heron]

sure

[thorn patio]

what does iirc mean as well

[remote heron]

if i remember correct

[thorn patio]

right ok

thank you for your help 👍

[remote heron]

[thorn patio]

.close

[lone heart]

Channel closed

Closed by @thorn patio

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[alpine sable]

The Casino at Monte Carlo uses a European Roulette wheel. It offers even odds against the ball landing in a red slot. What probability of landing on red would this correspond to if the offered odds (also called posted odds) of even were the correct odds?

Ive never been more confused in my life

[vale wigeon]

even odds means 1:1 odds

[alpine sable]

and its asking what percentage is that?

[vale wigeon]

you're asked to convert that into a probability yes

not necessarily a percentage, though it would do you no harm to give the answer that way.

[sly comet]

@vale wigeon do u like ur pfp?

[vale wigeon]

why are you asking me here and not in #discussion or #chill? help channels are not for casual chatter.

also who are you lmao

[sly comet]

sorry bro

loosen up though

[alpine sable]

dw u can ask me if i like my pfp

[vale wigeon]

don't call me bro.

[sly comet]

@alpine sable do u like ur pfp?

[alpine sable]

yeah i do thanks bro

[sly comet]

i call everyone bro but alright ill stop since u said so

[sly comet]

GREAT BRPO

[alpine sable]

bro and dude are gender neutral right?

[vale wigeon]

...can we get back on topic?

[alpine sable]

yeah sorry

[night geyser]

@sly comet please stop interrupting random help channels

[vale wigeon]

milkman, you have so far not said whether your question has been answered

[alpine sable]

yeah its answered

ty

how do i close

[vale wigeon]

alright, you can go ahead and .close

[alpine sable]

.close

[lone heart]

Channel closed

Closed by @outer hedge

Use .reopen if this was a mistake.