#help-0
1 messages · Page 87 of 1
lemme see whats radical operations lmao
Adding and subtracting radicals
there's laws
$a\sqrt m ± b\sqrt m = (a±b) \sqrt m\a\sqrt m \cdot b\sqrt m = ab \sqrt m\a\sqrt m \cdot a \sqrt n = a \sqrt{mn}$ etc
n11
a little oopsie. in the second one it'll be sqrt m²
Thanks
Btw for the last one
U didn’t multiply a because the radicals are different?
this was confusing but my bad
Nah it’s all good lol
Ima close they channel for now I gotta catch a bus ride to school
Thanks for the help 🙏
npp
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how do i go about solving this?
im sure itll be obvious but just cant see how
i was thinking to try and make c = 1 and make it the identity 1 + sin^2(x) = cos^2(x)? but other than that im not sure
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Okay, I thought I already knew how to do stuff, guess not...
I guess we start with ³√3²
Hm
Am I correct
Yes, go on, show what you have tried
Wrong.
$\sqrt[a]{b} = b^{\frac{1}{a}} \implies \sqrt[a]{b^c} = b^\frac{c}{a}$
trololol !
Yes ^
same mistake
$\sqrt[4]{2^3} = (2^2)^{\frac{1}{4}} = 2^{\frac{2}{4}} = 2^{\frac{1}{2}} = \sqrt{2}$
trololol !
it won't help to write it as $\sqrt{2}$, but i put it there in case it helps you understand
trololol !
trololol !
I thought so
Now
To get rid of the big ones
2¼ • 3 ⅔•¼
9⅓ • 2¾•⅓
Should I write it down?
Hellooooo
Right.
You keep sending the same image
Lol, why did you do that?
?
I guess he mis-clicked the image to be sent.
3 times? 💀
💀
Ight what to do now
I wouls
Wouls
Would
Turn them to
⁶√3
³√9
Although it won't help much
The top already seems so wrong
Okay
Any thoughts?
Nothing pops up for the top half
Yeah I had that in my mind for the bottom
Ye do that
⁶√3
³√3²
Hmm
Wouldn't it be possible to get rid of the top one
Why don't u remove the root overs and get fraction powers?
Wish I knew what that meant
Let's take an example
Wait do you possibly mean
Ye ye
3⅙
3⅔
It somehow does
If bases are same(multiplication) powers get added if bases are same(division) powers get Subtracted
I feel I can connect this exponent law somehow
Don't u think the same?
Ye
I'm actually not sure
2³
2¹
Continue
Now this feels awfully similar
3⅙-⅔
I'm so goated
So basically
Was that ur hw or a fun question?
Stop trying before learning the laws
I'm studying for my semester uni exam, this is supposed to be the 1st part of 20 different parts, basically highschool recap, but I don't remember highschool math being so difficult
I was going off pure thoughts sometimes, but I tried to remember some from highschool
Just go through it I'm sure ya Will recall everything easily
It's just so long and tiring to get one damn question right
Ya want a question?
No, I had enough of this first part
Time to move to the next one
I've already done about 10, but with this one, I'm sure I can do this
Sure
@unique salmon slide the question so that i can access it if in case ya get stuck
I see
Can I keep this open
I'll keep studying for at least 3 hours
Been doing it for 3 hours already oof
I think you can if u keep asking questions in atleast an interval of half an hour
Okay
I thought that I was a math genius for a second, but then I saw that none of the optional answers matched mine
@green folio
I don't know what that is
The 2nd one obviously
Ye ye
I think I skipped something
THATS A GOOD QUESTION
What are the mcq options?
Oki
Bro ya just sending one step I won't understand anything lol
I basically did all and got here
But I assume that if there is nothing
You should write 1
Instead of 0
Right
also theres no way you are getting a 0 in the denom
(x+2)(x+2)-(x-2)(x-2)=?
Everything won't cancel out tohhh
thats your numerator
I won't question it
mmy hands arent typing well today idek wth is up
i editd it
now? what is it?
Now time to meow
wrong one again?
Nope was showing ya the time 💀
I feel offended after using most of my brain
bhoot
There is literally minus
Bhootnaath
How did ya get 4x+8?
My man is more confused then we are frfr
$$(x+2)(x+2)-(x-2)(x-2)$$
$$(x^2+4x+4)-(x^2- 4x+4)$$
Deol
Latex pro here
Right
Affirmative
Okay
i just added $$ 💀
💀
Add "a" Before those dollar signs for extra luck yk 💀
I had it in me all along
Next question yayyyy
looks good
e
Bro doesn't feel secure enough to expose
Dating with shinobu
lol 10th
If only she was real

Cosplayers look bad ASF after putting 2 tons of makeup and getting a hairwig, eye contacts to look like a character
What to do?
I'll start first
First
I would replace the 1s
I feel like they don't belong here
My personal opinion
Fr, I Aim for both 2D and 3D it doesn't matter
I aim for 1d
my hands are cold
you are gonna have to provide context
Determine the difference of the sum and product of the expressions
And mine are black
Based of Google translate
also wheres that trig questiom?
I forgot what kinda trig y'all used to do in 10
I can give u few class 12 ones
Ya focus on ur paper ☠️
Ok
I don't even understand what the question wants
@green folio
I don't even know what it means in Czech
I only understand math with examples
Bro i don't know what the question wants 💀
i think its {(1+a/a+1)+(1-a+1/a)}-{(1+ a/a+1)(1-a+1/a)}
like that?
ig?
SO WHAT DO YOU WANT ME TO DO, THATS THE DAMN QUESTION
(•_•)
LOL. JK.
Wish I knew what that says
Anyways
Let me find what the whole thing is called
modifying an algebraic expression
Oh ig the question wants you to
- Find the sum
- Find the product
- Get their difference
This is what the whole thing is called
Am I ryt deol?
i think so unless the translation messed up
(•_•)
Ye true
I think some monke is stalking this chat
i read that scrunchy or whatver that was
Should probably call 911 and send the monke to the zoo
Monkeypox
Yeah spreading monke pox
guys trollig
Okay so
Basically get rid of a
Or get a =
OH YE
Something
Idk
Wait
Aren't we supposed to put something instead of a
Like to assign a number
Chat died
Nah me trynna calculate
@ me
Rip
Oki
start brute forcing heh
Always works
My brain ded
what class you in?
💀💀💀💀
try it bruh
making us slave
Let me check some videos my teacher made
anand? you dont have to tell me
Bro wtf I got 0
12 commerce
with math?
Ye
Commerce without math is a dumb choice frfr
Isn't difference subtracting?
Or is it dividing?
cool, is it good? i cant decide what to choose tbh
Ya confused between sci and com?
Do u have the question go this soln?
Man this is direct question
Ya gave such an indirect question
Ur professor is bullying us
ist it simple though?
I'm not aure
WAITTT
I'm going to try
LEMME GET SOMETHING CLEAR
what values can you have for
BRO I DESERVE TO DIE FR
Answer quick
Oh addition
Nvm me not gae
lol what?
The question gae tho
why?
am i looking at the wring question or somthing?
Idk I just am unable to understand what the question wants me to do
Hmm I got lost again
Can something be
@unique salmon is this exam test?
a² + 1
Nope
Nah, just a random question
a becomes imaginary
a²+1=0
a²=-1
a=±√-1
Which makes a an imaginary number
Let's do the next questions then and ask this question tmr as doubt
What's that line in between?
💀
It will be 2a+1 not a²+1
There's difference between a+a and a*a
But now what to do
Determine the difference of the sum and product of the expressions
Hmm
Wait so you're in the same spot?
What is it?
Ye
Slide lemme see
Wdym?
Like
2 |. a+1
-----
a (a + 1)
Then we would get rid of a + 1
Then there will be 2 and a
Although idk why
i swear to god if its wrong i am gonna crawl under some rock somewhere
yo are talkinh about this oen?
One of them
Ye
Goodbye
"difference''
I too feel this is it
Ye
Btw
Ya said you're confused between sci and com ryt?
Oki
I won't recommend ya any particular stream but lemme clear some basic shit up before ya choose
(In ur dms later)
Try ur self first
^^
Already doing
With whom? 
With my pen and paper
DAMN
Sometimes, one has to be different
okay yes
is rs-r² different from r²-rs
factor out r
say you had to factor -1 from s-r
I don't think this was a math equation
-1(-s+r)
language.
NOT ADD
then what
💀
I know
R (r-s)
But I can't do that
I'm asking how to do the -1 thing first
So I can get r (r-s)
Then shift the minus to the numerator
So from minus to plus
Yeah i got this
Easy
Okay I'm back
Took a break
Lol
My progress
What to do now
Like
Can I remove the r
So I don't have to write r(r+s ) • (r+s) (r-s) • r(r-s)
But
(r+s)(r-s)
Only
Actually
I get it
That’s not a nap. That’s forcing yourself to stay up. No offence
Hard to read honestly
So far so good
I can't access
Click on it
Idk why
Click on it and read it
Idk how to approach no matter how i think
What about
x+2
Expand that and the denom(the expression on the bottom)
You’ll see stuff cancelling out
Expand the (x+2)²?
Can you help me too here?
Type in #help-12
Wait so
a^3 - b^3
Oh tht
Okay
Okay
Done that
Now
I guess I should go back to what is in the bracket
But how do I approach that
(x+2)
No
No the whole thing inside the brackets
Add the fractions?
Can you write it down
$$\frac{x(x-2)}{(x+2)^2} + \frac{2(x^2 -4)}{(x+2)^3}$$
$$\frac{x(x-2)(x+2)}{(x+2)^3} + \frac{2(x^2-4)}{(x+2)^3}$$
Deol
That is what I meant
I get it
Now
K think
No
I actually don't
Well basically
Here are my thoughts
What if
(x²-4) = (x-2) (x+2)
I would be able to get rid of the ²
Yes
I'm still not sure what you did there, I know it went from ² to ³ and that you added a new bracket
But why
That I don't know
Write (x-2)(x+2) as (x^2-4) for now
It's already there as (x²-4)
Do you know how to add fractions?
Yes
2nd one?
Yes
As long as you multiply both the numerator and the denomerator by the same number
I understand now why you did that
But it feels so illogical
Like illegal
All of sudden to change it to make it multiply
First do this one
And I need to go in like 10 minutes
Bro
Trying my best to finish already
How
Like remove them?
Let's stop I don't think I'll get anywhere
I'll try to watch more videos
Thank you for the time
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bit confused by the final part
it says its not a pdf since fz doesnt integrate to 1
but what about fy
thats e^t-1
that doesnt integrate to 1
,w int from -inf to 1 e^(t-1) dt

why r u using limits 1 to - inf
i thought it was just the integral wihout taking any limits
How would you ever possibly get the result to be 1 if you had no limits?
The whole "integrates to 1" thing means "the probability of anything at all happening is 1", something has to happen
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Hey, quick question
What is a "functional equation" for a generating function?
In mathematics, a functional equation
is, in the broadest meaning, an equation in which one or several functions appear as unknowns. So, differential equations and integral equations are functional equations. However, a more restricted meaning is often used, where a functional equation is an equation that relates several values of the same func...
these things
Ahhh! Perfecrt
I swear, I looked
But nothing came up. I'll check this out
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In what different ways can you graph the expression for "a quarter of y"?
I need help with this question it's an algebra question.
you don't ask here lol
Can you help me tho
:D.
no? oki.
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i don't know where i went wrong in this proof but the expansion is not looking too good rn
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when solving for eigenvalues why do we set the determinant of it equal to 0?
well you start by writing $A\bf{v} = \lambda \bf{v}$
Gijs
then you can manipulate that
right
namely $A\bf{v} - \lambda \bf{v} = 0$
Gijs
ye
$(A - \lambda I)\bf{v} = 0$
Gijs
yup
which is only true if $A-\lambda I$ has determinant 0
Gijs
ohhh okay ye I get that but here is a maybe stupid quesiton
wait what happened to the v
when u take the det
cus its just det(a - lambaI) = 0
the v dissapears
well this only has a solution for v nonzero if determinant $A-\lambda I$ is 0
Gijs
bruv #❓how-to-get-help
its okay
sorry do u mind repeating that
we use that a property of full rank matrices (determinant not 0) dont map non zero vectors to zero vectors
v is a vector it has no determinant
no
I am sorry I am just so confused on what the purpose of v is
well v is an eigenvector
wut I thought (A-lambdaI) was
uhm okay lets go to the basics
okie
an eigenvector of a matrix "does not change direction" when you multiply that matrix by that vector
i can send a visualisation
A visual understanding of eigenvectors, eigenvalues, and the usefulness of an eigenbasis.
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its linked with the correct timestamp
you can see what a matrix does when multiplied by certain vectors
and eigenvectors are only ever stretched out or shortened
they dont "change direction"
alright so a matrix of full rank never maps a nonzero vector to the zero vector
i have to go for a min but feel free to dump all the info u think is important
that might be tough to understand at first but its very important
so since a matrix of full rank never maps a nonzero vector to the zero vector, $A-\lambda I$ must not be a matrix of full rank as it does map v (a nonzero vector) to the zero vector
Gijs
hence $det(A-\lambda I) = 0$
Gijs
@drowsy sedge Has your question been resolved?
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@keen orbit Has your question been resolved?
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hi can someon e help me with this?? is for a friedn
21519 ÷ 36,2
You can put that into a calculator
ye but with a process
You can multiply the numerator and denominator by 10 to get 215190 / 362. Then do the standard division algorithm
You can do long division, but that’ll be awful
^^
thx
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lets say you have a grid of squares in a random path-connected shape like this
(question continued below)
like, for instance, maybe you are building a platform in a game engine and the top of the platform is a seemingly-random shape like this
and lets say you want to add grass to the top of this shape by adding rectangles that align with the grid
and in this problem, the grass above is separated by rectangles like this:
and notice that the grass hangs beyond the platform by exactly 1 unit (and the overhang does include diagonally adjacent grid squares)
with this in mind, how would one determine the minimum number of grass rectangles and their locations on any given connected grid of squares?
For what purpose are you trying to minimise grass rectangles?
optimization
less rectangles = less polygons that the computer needs to render
Just run some kind of greedy algorithm
Find the biggest rectangle, place grass, do the same for all new ungrassed sections
well this question is sort of a theoretical one, im just using its application as a method to help people understand what the question is asking
I don't think this is going to have any kind of simple theoretical answer that isn't just running an algorithm
think about this
heres a valid answer for that diagram
it may or may not be the best answer, but it is one
it won't have an answer?
i mean its easy to just write an algorithm that spams rectangles until satisfied
but i find the problem itself interesting
Well there's not gonna be some magic formula that tells you "yes you can do it in 7 rectangles", the constructions will be algorithmic and proving whether they are or are not minimal it quite likely not so easy
what field of mathematics would problems like these be under then?
because i want to study further
i'll keep my question open for a little while longer to see if there's anyone around with a second opinion
Are you strict about your definition of overhang?
well, i don't really know how to word it
but uh
take an island with only 1 grid square
a grass overhang for only 1 grid square would be a 3x3 square of grass
because we include diagonally adjacent squares for the edge
“exactly” one overhang or minimum
hmmmm
because this diagram fails that test
where does it fail?
one minimum
like if you have some weird stuff like this
then you'd need a piece there to cover for the diagonals of the corners
Anyways, there are algorithms to find least rects in a grid. I don’t know it off the top of my head but I’m sure a google search will yield some results
if there's an algorithm like that, then the answer would be to take the original grid and outline it with more grid squares
Yes
and then to run that algorithm on the new grid
The overhang doesn't really factor into this problem does it?
It's just about finding the smallest number of rectangles needed to cover some mino
perhaps it doesnt
i suppose not every mino will correspond to an overhang situation but I don't think that will help
I’d start by trying some “naive” solutions and seeing where they fail, if at all
Could start from the left
It should be logical to start with the largest possible bounding box
Like look at the leftmost (nonempty) column
Cover it with rectangles, extend those right as far as they will go
then repeat
fails in some situations tho
Fails in the example diagram
she does want to hang off, so what if we just extend it, and then maybe a greedy algorithm?
Yeah
so unless you have one in 6
I’d say start with finding the largest bounding box
smallest bounding box?
this feels like a converse on the bin packing problem
ah I see
Trying to think of a case where it would fail
heres the og grid
It is more computationally complex tho
Yeah it would fail
Hmm
This would be terribly inefficient but maybe all possible rectangles could be generated
Where I was going with this doesn’t work prolly
Yeah
I mean not every case
Just generating rectangles, and using that to determine the “best” rectangles
Well all possible rectangles would be like O(n^4)
Generating all cases would run Marianna trench deep in recursion
Other thought is having some smart parameters to label "stray" rectangles, and seeing the largest areas that incorporate the most strays (without subdividing anything etc. to create more "strays")
In an actual application though, the cheapest, although slightly suboptimal, option would probably be the best
so searching it up gives this article http://library.utia.cas.cz/separaty/2012/ZOI/suk-rectangular decomposition of binary images.pdf
something about fast fourier transform
with it being able to do at O(MN log MN), with M and N being image dimensions
which is, as far i could tell, better than O(x^3), supposing a X by X grid
yeah I found some other "dissection" algorithms following O(n log n)
so if you need a fast, optimized algorithm, id go with the GDM, basically a fill in row by row with rectangle
but if the start and end points are the same, combine the rectangles
here is a js impl I found https://github.com/mikolalysenko/rectangle-decomposition
What with QTD?
?
i dont think thats a good one for you
nevermind
that one is if you wnat a low res basicly
Well in my game engine I'm trying to go for a like
lego look
which means low res basically
is this theoretical or not?
idk
from what he says here, apparently its applied
but on a theoretical level then yeah gdm is better
what i mean for low res is like, it gets a general shape first, then the details
oh ok
yeah gdm seems like the best bet
for GDM, this would be 7 rectangles i think
yep
as shown earlier
but GDM is way computationally cheaper
and its generalized for any map
worth it over minimal optimizations
although it will struggle against structures like this
i wonder if it would be also better that like if your height is bigger, you do vertical rectangles

