help-0

[old hazel]

u need to find the values of x where its not zero

so basically everything except the x intercepts of the quadratic

[loud tundra]

Ok so

It becomes this?

Sorry its vertical

[old hazel]

its 2x^2

because the 24^x = 22^2x

[loud tundra]

Ohhh

Ok i see

Lol 2^2 Is 4 therefore 4^x Is 2^2x

[old hazel]

yeah cause

2^2x is 2^x times 2^x

so thats x times x which is x^2

[loud tundra]

So i get this

[old hazel]

all you need to do is find where the quadratic = zero

because it is allowed to be negative

[loud tundra]

But with the quadratic formula delta Is negative

[old hazel]

b^2 - 4ac

25-8 = 17

[loud tundra]

Isnt It 25/4 -4(2)(1)?

[old hazel]

oh i see where its wrong

the 2(4^x)

becomes 2(2^2x)

which is 2(2^x times 2^x)

so u get 2x^2

not 4x^2

[loud tundra]

So like this

[old hazel]

No

The 2^x is becoming x

[loud tundra]

Yes i fixed It in third step

[loud tundra]

Ookkk becouse its (2^x times 2^x) and we said that 2^x Is x

[old hazel]

Yes

Then use quad formula to find when x is zero

[loud tundra]

It should come 2 and 1/2 right?

[old hazel]

Yes

But then

[old hazel]

Sub 2^x back in for x

Then solve with logs

[loud tundra]

And its 1 and -1

Which Is the solution

Ok thanks a lot you really helped me

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[knotty leaf]

hi guys, i want to know why when x -> infinity this part is going to be 1

[ionic vine]

Either divide top and bottom by x

Or as x goes to infinity x-1 is basically x

[knotty leaf]

is not like -infinity -1 / -infinity then i got inderterminante form ?

[ionic vine]

How did you get minus infinity

[knotty leaf]

sorry it's infinity

XD

[ionic vine]

Doesn’t matter go to 1

[knotty leaf]

why ?

[lone heart]

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[hallow vessel]

what is the subscript 50

matrix times by 50?

like

multiplied by itself 50 times?

like, what is going on

[mortal trellis]

yes that's it

A^50 means A to the power of 50. A multiplied by itself 50 times

just like 2^50 means 2 multiplied by itself 50 times

[lone heart]

@hallow vessel Has your question been resolved?

[hallow vessel]

ok so

[hallow vessel]

why does it just equal the original matrix

[mortal trellis]

it doesn't

[hallow vessel]

what

tf is going on bruh

[mortal trellis]

do you know what an eigenvector is

[hallow vessel]

what is this

yes

[mortal trellis]

so what is A*(2,3)

[hallow vessel]

uhh lambda*(2,3)

[mortal trellis]

well and what is lambda?

[hallow vessel]

oh i need to actually do it

lmao

[mortal trellis]

well the question tells you

[hallow vessel]

i get

(2a +3b, 2c +3d)

[mortal trellis]

huh?

(2,3) is an eigenvector with the eigenvalue 1

[hallow vessel]

did i do my matrix multiplication wrong

oh what

oh lmao

Ohh

insee

what the question is

everytime u get a*(2,3)

it simplifies to (2,3)

so u keep reducing power down by 1

[mortal trellis]

yes

exactly

[hallow vessel]

if u split a^50 up 50 times

tf is this question testing

oh well

thanks

[mortal trellis]

understanding of eigenvalues and eigenvectors

[hallow vessel]

i guess ill be fine if know to look out for it

[mortal trellis]

what would the answer be if the eigenvalue instead was 2 ?

[hallow vessel]

im ngl i didnt see the eigen value lmao

[mortal trellis]

in that case it also tests reading

[hallow vessel]

100

*the eigenvector

[mortal trellis]

no

[hallow vessel]

it isn't?

wait

uhh

1 sex

zec

sec

2^50

i think

[mortal trellis]

yes

[hallow vessel]

lmao

i did 2 cases

i shouldve done 3

that was pretty dumb

[mortal trellis]

happens

[hallow vessel]

eigenvalue^n

thats interesting

well then

[mortal trellis]

and another question

what would be (A^3+A)*(2,3)

[hallow vessel]

Eigen value is 2?

[mortal trellis]

yes

or you can directly do it with eigenvalue lambda

[hallow vessel]

10

[lone heart]

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[hallow vessel]

right?

. reopen

.reopen

wth ahaha

[lone heart]

✅

[hallow vessel]

wtf just happened lmao

[mortal trellis]

you didnt answer this question

then after some time it closes

[hallow vessel]

ohh i clicked the button and closed my laptop

[mortal trellis]

anyway, 10 is correct, yes

what if the eigenvalue was 3?

[hallow vessel]

3^n

+3

[mortal trellis]

no

[hallow vessel]

rly?

[mortal trellis]

what is n

[hallow vessel]

A^n

(A^n+A)

so i guess 30

[mortal trellis]

I asked about A^3+A

but ok

and what if the eigenvalue is lambda?

[hallow vessel]

if the question is (A^3+A) solution is (lambda^3 + lambda)

[mortal trellis]

yes

do you see where I'm going with this?

[hallow vessel]

yea lmao

Av=lambda v

i didnt do matrices in high school bcoz i skipped a year of maths and i havent watched lectures for this course bcoz ive been focused on the 2nd course

so i just havent worked w matrices enough

i should be fine for the exam but im doing a 2nd yr course over the holidays and i think it goes over orthnomality and stuff

so i thought its better to ask questions about matrices than skip over

but yea ty for the help

i appreciate it

<3

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[sleek sigil]

how would i isolate for x if there is (2x+3) in the exponent

like how would i get rid of just the 3

cause right now I have

(2x+3)/x = (log5 x log3)/(log4.6 +log1.06)

which in itself i dont think is right

[slender gull]

a^(2x+3) = (a^3) * (a^2)^x

So
4.6 * (1.06)^3 * 1.06^(2x) = 5 * 3^x
Now isolate all the terms with Exponent = x.

[quiet vector]

mind elaborating how? @slender gull

[slender gull]

Surely.

First

Are we considering "." A decimal or multiplication

I'm considering it's a decimal. Just in case you thought otherwise.

[ocean seal]

What the hell am I doing here?

[slender gull]

@quiet vector

[quiet vector]

thnxs

[lone heart]

@sleek sigil Has your question been resolved?

[sleek sigil]

OH

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[alpine sable]

Having troubles understanding what's going on there

[alpine sable]

No idea what dU actually represents

Couldn't find anything satisfying on the Internet

You guys are my last hope

[weary wyvern]

I'm guessing U is some voltage

And C is capacitance

E is energy

[alpine sable]

Exactly

But that's the math I can't understand

Especially the integral of U times dU

It somehow becomes the integral of just U

[weary wyvern]

It's the integral of U with respect to U

$\int U \dd{U}$

[ocean seal]

giannis_money

[alpine sable]

So it just cancels out?

And leaves me with just the integral of U

That would explain why the integral on the left side disappeared as well

[weary wyvern]

The multiplication by dU and dt is really just an abuse of notation, which is to be expected from a physics class

[alpine sable]

You supremacist

Thanks a lot

.close

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[signal brook]

need help

[nimble anvil]

umm ??

[tall topaz]

Where r there 3 people here

[calm ember]

bruh

[signal brook]

someone rdy to help?

[nimble anvil]

bro

[tall topaz]

#❓how-to-get-help

[nimble anvil]

ikr

[nimble anvil]

can i get help with this now

all ik is i gotta proof that OG and GJ are collinear

or smth like that

[alpine sable]

Deux vecteurs u et v sont collinéaires si on peut écrire u = c*v avec c une constante

Si tu arrives à écrire un vecteur égal trois fois l'autre par exemple alors ils sont collinéaires

[last ether]

Mfw french

[lone heart]

@nimble anvil Has your question been resolved?

[nimble anvil]

je le sais

mais i ve been sitting here for hours

en vain

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[signal brook]

need help

[lone heart]

Please don't occupy multiple help channels.

[signal brook]

.close

[lone heart]

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[patent burrow]

Need help in understanding linear combination and linear transformation

In quora, i found this real life scenario as follows ,Say you want to buy some fruits from a shop. You grab 3 apples and 4 bananas. Now you go check out.

What is the process of ``checking out’’? Well, it is a linear transformation sending your purchase to its price. You can easily see that price(3 apples + 4 bananas)=3 price(apple) + 4 price(banana).

In the above case 3apples+4bananas is the linear combination?

Calculating it's price is linear transformation?

[chrome plank]

👋 Open a new channel, #❓how-to-get-help This is claimed by some one else

[patent burrow]

.close

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[autumn plank]

how does this work

[lone heart]

@autumn plank Has your question been resolved?

[autumn plank]

.,close

.close

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[restive salmon]

How to find all possible combinations of multiple variables for a specifik sum

[restive salmon]

Example:

You bought some stuff for 90$
The items avaviable for purchase is listed for each 6$, 8$ and 15$
How to find all the combinations?

Of course i could just start doing them each individually, but i was wondering if there was a way to get it easier/faster, or for example, if the problem was too big for doing it "manually"
I tried using CAS and solving 6x + 8z + 15y = 90 but i could only solve for a single one at a time

[lone heart]

@restive salmon Has your question been resolved?

[restive salmon]

<@&286206848099549185>

[restive salmon]

answer include 6 15$ items
and 15 6$ items etc.

@neat jewel

[neat jewel]

I see it

I’m certain there’s a faster way

[restive salmon]

Any idea?

I thought something along the lines of a graph

xyz, with a fourth one being the sum. Then to see where the sum is 90

[neat jewel]

You could think of it in 3 dimensions, but I don’t see how that’d help you

[restive salmon]

yea

kind of lost. i couldnt figure out a way to google the problem though

[restive salmon]

its just too.. specifik in a way? even though it would seem common

[neat jewel]

I was thinking something with factorials (something you use a lot for stuff like this), but I’m not sure

[sick perch]

can someone please help me with my annuities project?

i have no idea what im doing

[restive salmon]

ive never really done math with factorials in school

[hidden knoll]

this channel is already occupied
open up a different help chat/create a forum post

[neat jewel]

Yeah, I can’t think of a good way anyway

They’re more useful when you’re seeing how many ways you can put x into y

For instance, 30 villagers into 20 huts

[restive salmon]

hmm

[neat jewel]

But this is a bit different

What grade are you in

[restive salmon]

9th

i know its not expected for me in 9th grade

[neat jewel]

Honestly, if you don’t remember doing anything like this, you might just be supposed to count it

With 6 15s, there’s one solution (6x15)

With 5, there’s no solutions

[restive salmon]

its also mix like
2 · 15$
10 · 6$

[neat jewel]

With 4, you have 2 solutions (4x15+6+8x3, 4x15+6x5)

[restive salmon]

but i think ill just have to go
0 0 0 = 0$
0 0 1 = 15$
0 0 2 = 30$

like trying to break a code lock

and then mark each that goes 90$

[neat jewel]

Well, an easier way is like this

Start with 6 0 0

Find all solutions for that

Then go 5 0 0

[restive salmon]

isnt that the same though

[neat jewel]

Similar, but not quite

One way, you have to list every possible outcome

This way, you just figure out which outcomes are correct

It’s a bit denser, but it’s quicker

[restive salmon]

the thing that bothers me is

if it had been 2 different items

[neat jewel]

Then that’s nice and easy

[restive salmon]

i couldve made a 3d graph, and then just take each point at 90$

[neat jewel]

Heck, just a 2d graph

[restive salmon]

so it should be possible with another variable. its the same. just. another. variable

:(

[neat jewel]

6x+8y=90

[restive salmon]

i mean like

f(x, z) = 15x + 6z

y = 90

and then finde where they touch

[neat jewel]

That’s another way

[restive salmon]

so solving it graphically

visually? idk

[neat jewel]

In this case, 90 would be more like a radius

[restive salmon]

wdym

[neat jewel]

You’d have a circle with radius 90

[restive salmon]

yea

[neat jewel]

And when 6x+8y is a solution, it’s a solution

Er, actually, I think I’ve lost my head

[restive salmon]

i dont get it

[neat jewel]

It’d have to be x^2+y^2

[restive salmon]

i can see im my math program it can do "test"

[neat jewel]

I just use Desmos, no test button, just answers

[restive salmon]

this is in word

this is the symbol

[neat jewel]

Yeah, word has a lot of stuff

I’ve just stuck with Desmos

[restive salmon]

i imagine maybe it would do all the thins, and then do a √ for each one that is equal to 90

but idk how to use it

2 sec

bionomial test

idk

[neat jewel]

I haven’t heard it called that before

[restive salmon]

i dont know what it is

but

another way to do it

is do the 3d graph. but do 6 of them

each with + 15$ instead of a variable

maybe

[neat jewel]

Same idea as brute forcing a lock

[restive salmon]

Yes.

💪

do you think its a good idea..?

[neat jewel]

like I said, it’s the same idea again ¯_(ツ)_/¯

Just brute forcing it

[restive salmon]

yea

its just a bit faster in a way (is the idea

i mean if i had to do it personally out of math, i would just write a python script

or similar

it would be the simplest of all

[neat jewel]

It’s the same idea I had, where instead of listing every combination, you find the solutions to each of the possible $15s

[restive salmon]

yes

i will try that now

will be back

its hurting my computer

[restive salmon]

i couldnt figure it out

[lone heart]

@restive salmon Has your question been resolved?

[zinc canopy]

could anyone help with this?

[lone heart]

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[gray walrus]

What is the Value of Tan 11pi/6

[gray walrus]

According to my teacher it's - square(3) / 3

Photomath also says the same thing

But I got something different

I got -1/ square(3)

even this website has the same answer

https://www.cuemath.com/trigonometry/tan-11pi-6/

So I don't know what is wrong

[chrome plank]

-1/ sqrt(3) = -sqrt(3) / 3

[gray walrus]

uh? is that so?

so which answer should I give?

Ohhhhh

[chrome plank]

I can't remember what that's called in english, but basically when you get a fraction with a root in the denominator, you should perform some kind of algebra to make it go to the numerator

[gray walrus]

Yes, I just remembered the teacher talking about it

I am dumb

thanks

.close

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[alpine sable]

https://gyazo.com/0ebd57b71109c8990b9c3465d7451d09

What does minimized mean here?

[lone heart]

@alpine sable Has your question been resolved?

[worn fox]

Using the hint you have that its equal to something + (something)^2

this is lowest when that (something)^2 is zero

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[median cape]

hello, i am confused... i get different answers for -1 mod 11 and -1 mod 7

[median cape]

for e.g. for -1 mod 11 i either get 10 or -1
and for -1 mod 7 i get 6 or -1 so which one is correct now?

[supple flame]

They are both correct

Two numbers are equivalent modulo $n$ if they differ by an exact multiple of $n$.

[ocean seal]

moonside

[supple flame]

So -1 and 10 are equivalent modulo 11 because $-1 + 11 = 10$ (they differ by 11)

[ocean seal]

moonside

[supple flame]

modulo $7$, -1 and 6 are equivalent because $6 = -1 + 7$ (they differ by a multiple of 7)

[ocean seal]

moonside

[median cape]

oh okay :0
than my calculation is not wrong :)

[supple flame]

right

[median cape]

and maybe i will make 2 different calculation the first with 10 and the other with -1

[supple flame]

-1, 6, 13, 20, etc are all equivalent modulo 7

because they all differ by exact multiples of 7

-1, 10, 21, 32, etc are all equivalent modulo 11 because they differ by multiples of 11

[median cape]

alright :)

.close

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[vapid steppe]

hi

[vapid steppe]

did i do this right

[lone heart]

@vapid steppe Has your question been resolved?

[lone heart]

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[copper lily]

I'm assuming that I need to use ln to get it in 0/0 or oo/oo format so I can use L'hospital's rule, but what I have right now seems to be too intensive.

[dry echo]

If I'm not mistaken, you can take the limit of the expression inside the parenthesis first

ok nevermind that doesn't apply here I think

[copper lily]

At least looking at my textbook, my understanding was I needed to use log properties to convert it to this. e^((ln(15x)/(15x+4))/((1)/(3x)))

So now I have 0/0

And I can use L'Hospital's rule

But taking the derivative of all this ends up being super super intensive, so I think I'm missing something

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@copper lily Has your question been resolved?

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[lyric veldt]

what did i do wrong

[lyric veldt]

the math is right

🗿

[alpine sable]

Oops lol

[lyric veldt]

what does AB become

i bombed the shit out of this quiz and we arent done with the section so i need to know

[alpine sable]

You had to take out the square root

[lyric veldt]

wait

so AB=2

AB=2 or AB=sq2

@alpine sable

@alpine sable

🗿

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[near pewter]

How do I figure out an equation?

[tacit arch]

What first few values do you get

[near pewter]

I got
a0 = x
a1 = x/x+1
a2 = x^2+x/2x^2+3x+1

[sudden hinge]

factorize a2

you should be able to cancel something

[near pewter]

I was able to simplify it to x/2x+1

[sudden hinge]

right

see the pattern?

[near pewter]

I think I see it now

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[alpine sable]

Can anyone tell what the difference is between a single binomial and two binomials ?

[alpine sable]

is this a single binomial

[merry depot]

yes? a binomial is just a sum or difference of two terms.
I don't know what you mean by two binomials?

[alpine sable]

It is asking for a single or two binomials

I don't know what it is talking about but all I know is a binomials has 2 terms

so I can cross out everything except d,g,h,k

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@alpine sable Has your question been resolved?

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@alpine sable Has your question been resolved?

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[deep topaz]

Can someone help with this

[deep topaz]

I've redone it a bunch and I still keep getting the wrong answer

The answer is x=4

Idk what I'm doing wrong

[zinc dagger]

Between your second and third line, there’s a mistake

You should’ve ended up with 2^x * (1 - 5*2)

@deep topaz

[deep topaz]

Oh

Wait where did the one come from

[zinc dagger]

There is one 2^x and negative ten 2^x s

1 * 2^x - 10 * 2^x is how u should see the second line as

[deep topaz]

Uh

[zinc dagger]

You know how a - 10a is the same as (1-10)a is -9a? Same thing, except instead of a it’s 2^x

[deep topaz]

Alr

Thanks

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[gilded kiln]

to find measure of angle b, I setup

$\frac{sin\left(85\right)}{5.5}=\frac{sin\left(b\right)}{3.6}$

[ocean seal]

bababeeboo

[gilded kiln]

Multiplied both sides by 3.6, and then took the arcsin of both sides

and I get 0.7

which obv isnt right

what am i doing wrong?

[zinc dagger]

In degrees not radians?

,calc asin ( 3.6 * sin(85*pi/180)/5.5) * 180/pi

[ocean seal]

Result:

40.696698045171

[zinc dagger]

There u have it

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[sour dove]

hi there what have you tried so far?

[dawn oak]

y=2.25x+12.5

[sour dove]

yep that's exactly right!

nice work

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@dawn oak Has your question been resolved?

[dawn oak]

ohh okk

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[twin jolt]

I did 1= 1/2+ pr a - 1/5

And got pr a is 7/10

But non of the answers show or a as that

[merry depot]

You have assumed that AUB is the whole space.

Use the definition for probability of an intersection

P(A n B) = P(A) * P(B|A) and P(B) * P(A|B)

[twin jolt]

Got it

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[astral grove]

$x ^ {\log(x)} = 3 - \log_x{100}$

[ocean seal]

WhyWouldYouKap

[astral grove]

other help channel got hidden

sorry for clogging

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[woeful tartan]

y = kx + m

[woeful tartan]

can anyone help guide me into know what it could be?

with rules?

i know what k is i think its 2

[pale lance]

k refers to the rate it increases at (every 1 x, how much points up/down does it go?)

m refers to the starting point

[woeful tartan]

whats the starting point in this

is it none

0

[pale lance]

Where x=0, aka the y-intercept

[woeful tartan]

so -1

[pale lance]

Wherever it touches the y-axis is the m value

[woeful tartan]

no

[pale lance]

Which is 2

[woeful tartan]

its 2

2x + 2?

[pale lance]

Good

Yes

[woeful tartan]

y = 2x + 2

[pale lance]

The number next to x

That is the slope

That coefficient always refers to how fast the line increases every x

[woeful tartan]

so if i want to know value of y when x is given?

[pale lance]

If a number isn't multiplied by x, that will be the y value of the y intercept (aka where x=0)

[pale lance]

Just plug the number for x into the equation you made

[woeful tartan]

so the main rule here is whenever x = 0 then y = m

[pale lance]

yes

Because it's like saying y = k(0) + m

And since anything times 0 = 0, that makes y = m

[woeful tartan]

ohh

Another straight line has the equation y = 2.4x + 5
Are they parallel```

[pale lance]

Well, parallel lines need to head into the same direction

If the line went up 10 points in 4 x-values, what would the slope be? (this is the y2-y1 / x2-x1 formula, I simply abstracted it

[woeful tartan]

do i use the formula Y2 - Y1 / X2 - X1

[pale lance]

yes

[woeful tartan]

so i use this formula for the first one

[pale lance]

Mhm

[woeful tartan]

i will test it

[pale lance]

Parallel lines should have the same slope

Otherwise they are not parallel since they'll eventually come in contact with each other

[woeful tartan]

gradient is slope right

(x,y) it would be 14 - 4 / 4 - 0

14 - 4 / 4 - 0

equals to 2.5

so its not parallel

[pale lance]

COrrect

They're close, but not quite the same right?

[woeful tartan]

yes

[pale lance]

Then you have your answer

GOod

[woeful tartan]

is that intentional

[pale lance]

Yes

[woeful tartan]

thanks

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[indigo thorn]

can you tell me how these roots come I understand about the first 2 can someone tell me about the others ??

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@indigo thorn Has your question been resolved?

[vale wigeon]

"the first 2?"

also can you show the original problem

[indigo thorn]

wait

[vale wigeon]

oh so it's the same question you came here with yesterday

so what's your doubt?

[indigo thorn]

i found the first 2 roots but in the second pic how we get so many roots

[vale wigeon]

wdym by "the first 2 roots"?

in the second pic the same set of 3 roots is listed twice...

[indigo thorn]

i found 1/2 and 1/4

1/2 and 1/2 what is that

[vale wigeon]

Thus, the required roots are (1/2-1/4), 1/2, and (1/2+1/4)
or
1/4, 1/2, 3/4

this is what the second pic says

written in a hopefully clearer manner

[indigo thorn]

ok

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[vestal talon]

Does anyone know how to do these sign charts i cant figure out the next step in checking

[vale wigeon]

,rccw

[vale wigeon]

your intervals are wrong
should be (-infty, 0), (0, 5) and (5, +infty)

also 3x^3-15x^2 factors as 3x**^2**(x-5)

[vestal talon]

Oh sorry yes

[vestal talon]

Oh man missed that obvious mistake

Okay so i fixed it

@vale wigeon im still not sure how i go about checking each of my chosen integers

[vale wigeon]

i mean you have successfully found that the value of 3x^2(x-5) at x = -1 is -18

[vestal talon]

my teacher continues on though

[vale wigeon]

what you care about in that value is that it is negative

[vestal talon]

She continues to get all this stuff in purple

[vale wigeon]

okay so like

let's maybe start from the beginning

bc it sounds like you've gotten yourself confused somewhat

you have written your inequality as 3x^2(x-5) < 0

so you are interested in the sign behavior of the function f(x)=3x^2(x-5)

the function consists of several factors, and these factors change sign at the points 0 and 5

these points break the number line into three intervals: (-infty, 0), (0,5), (5,+infty)

within each of these intervals, the function does not change sign

do you follow thus far

[vestal talon]

kind of

[vale wigeon]

is there anything that does not make sense to you

aside from not knowing what comes next, which i am about to explain anyway

[vestal talon]

by function does not change sign you mean doesnt cross the x right

[vale wigeon]

changing sign = crossing the x-axis on a graph yes

[vestal talon]

so we only cross x at the 0 and 5 points

[vale wigeon]

i wouldn't refer to the x-axis as just "the x" though

[vestal talon]

well I know what its meant to mean

x axis at 0 and 5

[vale wigeon]

so each of these 3 intervals is either completely included in our solution set or completely excluded from it

[vestal talon]

so theres an asymptote at 0 and 5

[vale wigeon]

no

there are no asymptotes...

[vestal talon]

kk

[vale wigeon]

and the way your teacher suggests you continue is that you pick a point from each interval, evaluate the function at it, and see whether or not the sign is the one you want

in this case negative

[vestal talon]

she wants us to know when its above so that we can get the interval notation I believe

[vale wigeon]

you want BELOW for problem not above

your inequality says the thing is LESS THAN zero. NEGATIVE. that's BELOW the x axis

[vestal talon]

ah yes ofc

nvm then notation for when its below zero

[vale wigeon]

idt i can continue this sorry

[vestal talon]

alrighty

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[hoary zenith]

Let G be a graph with 9 nodes such that every node in the graph has degree 5 or 6. Prove that the graph has at least 5 vertices of degree 6 or at least 6 vertices of degree 5.

I'm struggling with this exercise.

[vale wigeon]

try to prove that the number of degree-5 nodes is necessarily even

[hoary zenith]

why's that?

nvm

I'll try

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[alpine sable]

did you expand it before?

5/n^3 and -2/n^(5/2)

then apply the sum rule

np

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[alpine sable]

i get a free dairy milk if i work this out

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[vale wigeon]

are we sure this is the longest

[prime badge]

no

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[hasty reef]

Can someone help me solve this?

[hasty reef]

I think x is in the 1st quarter but idk what else to do

[trim wagon]

is it?

||hint:add 2pi||

[hasty reef]

Ah so second?

[trim wagon]

yes

[hasty reef]

Okay but how does that help me

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@hasty reef Has your question been resolved?

[old hazel]

@hasty reef give me a sec

Second quad

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[hasty reef]

.reopen

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✅

[hasty reef]

Yeah how does that help

<@&286206848099549185>

[old hazel]

@hasty reef

Wait sorry

It’s for

Cot

[hasty reef]

Ahhh okay okay

Thank you so much bro

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[fathom stag]

I have these numbers, and i'm having trouble finding any pattern or sequence in them. The formula i tried to use only got me like within 12 numbers

[vale wigeon]

where did these numbers come from

[fathom stag]

The number on the left represents a unique player, the power represents the value you have to hit precicely to get the corresponding player

Its fifa cards actually, but i just found a math problem within it

Im not sure if the rating have something to do with it, the thing i need to find out is the next power number

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@fathom stag Has your question been resolved?

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[knotty inlet]

For this question

Why dont matrices (00/11) and (00/10) work

/ is a new row

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@knotty inlet Has your question been resolved?

[knotty inlet]

<@&286206848099549185>

[little drum]

cause determinant 0 doesn't give singular matrices

look up for singular matrices

[knotty inlet]

Isnt it the other way around

Determinant 0 means a singular matrix?

[wind parcel]

matrix
0 1
0 1
works but matrix
0 1
0 0
doesn't work

[wind parcel]

and yes determinant = 0 is a singular matrix

[knotty inlet]

How come
0 1
00
Doesnt work?

It should work? Since determinant is 0

[wind parcel]

the determinant of
0 1
0 0

is -1

wait hold on

[knotty inlet]

Ad-bc?

[wind parcel]

actually it does work

[knotty inlet]

Thas 0, no?

[wind parcel]

my bad

so yeah it works..

[knotty inlet]

What abour
00
11 and
00
10

They should work too rightM

[wind parcel]

yeah all should work

[knotty inlet]

Ok seems like an error in mark scheme then

Tyy for your help

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[quaint schooner]

I was doing these equations for converting the Cartesian form and Apperantly the answers are wrong, does anyone know what’s up with it and could you calculate to compare

[quaint schooner]

<@&286206848099549185>

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@quaint schooner Has your question been resolved?

[worthy cipher]

Are you using radians or degrees?

I calculated each of the expressions you have listed there and yes, assuming you are using degrees, they are correct

But if you're trying to convert complex numbers from cartesian into mod-arg form then you would use radians

Why are the answers wrong, what are you comparing them with?

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[alpine sable]

hey how does this work

[worthy cipher]

the way I would do it is find the equation of the line, and then check each point to see if it works with the equation

are you familiar with how to do that?

[alpine sable]

well think of how much of a pain it is

to write all 33 NUMBERS!

[worthy cipher]

33?

[alpine sable]

y axis

not including negatives

[worthy cipher]

oh, are you trying to do it graphically?

you can do it algebraically, you don't need to draw it all out

[alpine sable]

plesase tell me how

[worthy cipher]

okay, so the first thing to do is find the gradient (m)

[alpine sable]

slope

[worthy cipher]

yep! that's rise over run, or change in y value over change in x value

[alpine sable]

y2-y1/x2-x1

[worthy cipher]

correct! so, what does that give you, using the coordinates (1, 5) and (3, 19)?

[alpine sable]

7

14/2

[worthy cipher]

yep! so, now we use point-gradient form to find the y-intercept

[alpine sable]

i bel=ieve its y=mx+b

[worthy cipher]

that's the equation for a line, yes, but we still don't have b

[alpine sable]

its simple ig

its -2?

[worthy cipher]

oh yeah you can do it on paper or in your head, i prefer to do it algebraically

that is correct though!

so, y = 7x - 2

[alpine sable]

5=7*1+-2

[worthy cipher]

oh right yeah duh i was overcomplicating things there lol

but, either way, we have the equation now

[alpine sable]

yup

[worthy cipher]

we can just substitute in each point and check

so (-1, -9)

x = -1
y = -9

-9 = 7(-1) - 2

which is true! so the point is on the line

[alpine sable]

OHHH

Thanks so much bruh

[worthy cipher]

np!!

[alpine sable]

as return would you like a joke

[worthy cipher]

i would love a joke

[alpine sable]

whats the difference between a guitar a fish and glue

[worthy cipher]

something something..... tuning?

idk about the glue

[alpine sable]

i knew you would get stuck there

[worthy cipher]

JKDSGHLKJSHGKJLSD

ok that was a good one

[alpine sable]

it was a play on your name actully

[worthy cipher]

oh, you got it! most people don't notice for ages lmao

i'm going to close this channel now, good luck with the rest of your hw! ^_^

[alpine sable]

aight

[worthy cipher]

.close

[alpine sable]

hope to maybe see ya soon

[lone heart]

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[pallid root]

could someone help me understand this question?

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[pallid root]

https://math.stackexchange.com/questions/1477949/show-that-the-set-a-nm-sqrt2n-m-in-mathbbz-is-countable

could someone help me understand this question

Show that the set $A={ n+m\sqrt{2}:n,m\in\mathbb{N} }$ is countable.

[ocean seal]

Zoroaster

[pallid root]

the solutions offered in that page are to show the bijection A to ZxZ but im not too sure what they mean by that

heres my solution:
define M = { m* sqrt2 : m in N}
then |M| = |N| = |MxN|
MxN can then be enumerated as (n1,m1sqrt2) , (n2, m2sqrt2) ..... (nn, mnsqrt2)
now we can enumerate the set S by letting si = ni + misqrt2 => S is countable
since MxN has countably infinite elements, S will also have countably infinite elements => S is countably infinite

Im not sure my solution is rock solid & i think its a bit convoluted too

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[floral zephyr]

find volume

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@floral zephyr Has your question been resolved?

[lofty burrow]

ight im too dumb to find this thing, whats |X-8| < 2

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[amber nymph]

I want to solve this recurrence relation

[amber nymph]

$$A_n=CA_{n/2} +d$$

Where C and d are constants

[ocean seal]

Ericsson

[tacit arch]

Where is the /2?

You only terms defined on powers of 2?

[floral tinsel]

whats the answer

?

[amber nymph]

In the index

[tacit arch]

Go get your own channel and do your own work.

[floral tinsel]

how

[tacit arch]

Do you know the first few terms?

[floral tinsel]

im new

[tacit arch]

#❓how-to-get-help and by reading or watching videos on your topic

[amber nymph]

No, our professor just said that we will discuss these type of questions on Wednesday and I was thinking to study in advance

Can you point to any resource I can refer to?

[tacit arch]

Just make up some

A2=1

Or A1=2

[amber nymph]

Okay i see

Okay let me rewrite the problem

$A_n=A_{n/2} +1$ where $A_2=2$ and $A_1=1$

[ocean seal]

Ericsson

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[gritty pond]

Can anyone check if my preparation is correct?

N Stands for amount of nickel plating, S stands for amount of silver plating

(cm^2)

Also the 105 is 10s

actually i wonder if i could convert both the n and s to x

Oh shit i should also add the n and 10s instead of multiply

nevermind im pretty sure my whole problem is fucked

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[lone heart]

Please don't occupy multiple help channels.

[alpine sable]

For the first one :

A = C = {a}, B = {b, c},let be f(a) = b, g(b) = g(c) = a

Is it right ?

Like both statements are wrong and I have to disprove them…

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[pale cosmos]

İs anyone can speek turkish? İ have question about rationel numbers??🧐

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[proven grail]

help

[small panther]

you have to identify the powers of 10 and the coefficient before the 10's

First isolate a x 10^b

Then simplify the right hand side

Then identify a and b

Ask if you don't understand

[proven grail]

i kinda understand

im just struggling

to get the value of a and b

kinda confusing

[small panther]

Like : $a\times\ 10^b$ = $\frac{2.226}{5.3}\times\frac{10^4}{10^8}$

[ocean seal]

ByShaDowZ

[proven grail]

so how would u get a and b

what are the values

[small panther]

So $a\times\ 10^b$ = $0.42\times\ 10^{-4}$

[ocean seal]

ByShaDowZ

[small panther]

Here you can identify the terms

You have a = 0.42 and b = -4

@proven grail

[proven grail]

thank you very much 👍

[small panther]

hope u understood

[proven grail]

.close

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[alpine sable]

Can anyone show me how to do this 😭 and explain how ??

let x be in f^-1(M), show that it is also in f^-1(N)

[alpine sable]

Okey I Let x in f^-1 (M)

My goal is to prove that x is in f^-1 (N)

f(x) is in M

And M is included in N

so f(x) is in N

so x is in f^-1 (N)

which proves the statement ?

yup

So I can just write it down like this ?

😭😭

[lusty wren]

For 12 pencils and erasers, the student pays a total of HRK 11. The price of each pencil is 80 Lipa, and each eraser is HRK 1. How many pencils and how many erasers did he buy?

so just ignore the money currency, 1 hrk is 1, 11 is 11 and 80 lipa is 0.8

can someone help me? there has to be a specific way to solve this other than guessing, because if u guess and multiply 0.8 by 5 or 10, both work, but then there would be 2 answers, so i'm confused... help pls

[alpine sable]

#❓how-to-get-help

[alpine sable]

yes

thats a perfectly good proof as is

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@alpine sable Has your question been resolved?

[alpine sable]

😭😭tyyy

yw

[lone heart]

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[modern orchid]

If anyone knows a bit of physics any help on this would be appreciated!

[tacit arch]

#old-network for physics server

[modern orchid]

Okok

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[toxic stream]

Hello

[toxic stream]

So my problem is

[toxic stream]

Bro

my room

How do i go about solving this system

[agile cypress]

whith the firt line you have y = -xb

and you put this in your second line

[toxic stream]

Wait what

How did you get -xb

-close

.close

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[onyx hedge]

so I am trying to form n's at the bottom the m thing above
kinda failing though, any tips?

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[dusky igloo]

I have a question in math and I am not sure how to setup the equation since the wording was really weird:
A population of 100 bacteria increases to a population of 4500 in 12 hours. Write an equation to find the time in hours it takes for the population to double.

I tried doing 100*(2^*(X/12)) - 4500 = 0 into my graphing calculator to check but 65.902 did not seem like it would be the correct answer. How can I properly setup the equation to this question?

[astral grove]

hey mate

I think I can help u

so it starts at 100

it ends at 4500

and doubles every hour for 12 hours

100 * 2^12 = 4500

that doesnt seem right

[lyric stream]

it doesnt say it doubles every hour