help-0

[alpine sable]

zit echt vast met deze vraag

[golden canyon]

in ieder geval we hebben nu 3 / 5 - (3 * 5)/5

[alpine sable]

ja

[golden canyon]

en nu hebben de breuken dezelfde noemer

[alpine sable]

ja

[golden canyon]

dus kan je de tellers van elkaar aftrekken

[alpine sable]

maar

wat is 3*5

[golden canyon]

15

[alpine sable]

ooh die * is maal

ok ok ik snap het

dus je doet 3-15

[golden canyon]

ja, met nog steeds 5 in de noemer

[alpine sable]

-12/5

[golden canyon]

ja

[alpine sable]

toch?

omggg

wtf

het is ook gwn juist

dankjeee

[golden canyon]

graag gedaan

[alpine sable]

waarom ben jij zo slim

[golden canyon]

lol, valt mee heb dit jaren geleden al gehad

[alpine sable]

hoe oud ben jij dan?

[golden canyon]

dat is persoonlijk, maar ik zit op de middelbare

[alpine sable]

oooh top

ik ook.

ik heb weer een moeilijke

ik dacht dat het -4/6 was

maar het is fout

[golden canyon]

je kan de 2 weer schrijven als een breuk met noemer 3

[alpine sable]

dus het is 2/3

[golden canyon]

6 / 3

[alpine sable]

het is fout

[golden canyon]

nee, 2 = 6/3, nu moet je -2/3 - 6/3 uitrekenen

[alpine sable]

oooh

ok

dankjewel

maar hoe kwam je aan die 6?

[golden canyon]

2 = 6/3, je wilt het schrijven als iets gedeeld door 3, want dan zijn de noemers hetzelfde van de 2 breuken

[alpine sable]

ooh

dankjewel

weetje wal vierkantswortel is?

[golden canyon]

ja

[alpine sable]

dit is toch -9?

het zeg dat het fout is

[golden canyon]

je hebt een 3 in de exponent staan(de kleine 3), dus het is -3 * -3 * -3

[alpine sable]

-3*3 = 9

-3*3=27

dus -27

[golden canyon]

ja

[alpine sable]

jaaa

nog zo 1.

[golden canyon]

je hebt weer een 3 in de exponent, dus je moet (2/3) * (2/3) * (2/3) doen

weet je nog hoe je breuken kan vermenigvuldigen

[alpine sable]

nee dat was echt een tijdje geleden dat we het hebben gedaan op school.

[golden canyon]

het is niet heel moeilijk, je moet de noemer en de teller apart vermenigvuldigen, dus (2 /3) * (2/3) = (2 * 2)/(3 * 3)

[alpine sable]

oooh

dus het is 8/27

[golden canyon]

ja

[alpine sable]

dankje

btw speel je spelletjes

?

[lone heart]

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[alpine sable]

still cant figure this out

seems convergent but how to find the limit

[lone heart]

@alpine sable Has your question been resolved?

[alpine sable]

<@&286206848099549185>

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@alpine sable Has your question been resolved?

[alpine sable]

.close

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[mellow wraith]

find x and y of N
(x-2)(y+6)=23

[echo socket]

Notice that 23 is a prime

Meaning there are 2 cases

x-2 is 1 and y+6 is 23 or x-2 is 23 and y+6 is 1

[mellow wraith]

ohh i understand now,thanks a lot.

.close

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[gritty pond]

fastest way to do this derivative?

[alpine sable]

convert it to sin2x

[echo socket]

With 2 in front of it

[spark lion]

how can i solve this using laplace transform

[echo socket]

Post your question in an available help channel

[lone heart]

@gritty pond Has your question been resolved?

[ashen moon]

how do i graph y=-4x^2

[lone heart]

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[lament jackal]

how do i write a function to represent this data (1, 3), (2, 6), (3, 12), (4, 24)

[fallen verge]

Notice how the y terms have a common ratio

[lament jackal]

i think i know what you mean, could you explain it for me though?

i know the data is an exponential function, because i put it into a graph and for one the line is curved, two the rate of increase is changing

[open urchin]

find the ratio of concecutive y terms

[fallen verge]

We know that the function increases by a factor of 2, so it is of the form y=a2^x

[open urchin]

since it's exponential this ratio must be constant

[lament jackal]

and i do that by

ive been trying to do this and my brain is like fried

[open urchin]

the y terms are 3, 6, 12, 24

find the ratio between the consecutive terms

aka

6/3, 12/6, 24/12

and see if there's a pattern

[lament jackal]

so basically dividing them>

?*

because they all equal 2 when dividing

so what garlic bred said, y=a2^x is correct for this? except it is a function so wouldn't it be put as f(x)

[open urchin]

yes f(x)=a*2^x

find a

[lament jackal]

sorry, is the astric showing the 2 is an exponent

[lament jackal]

and this means to isolate the variable by dividing each side by factors that dont contain the variable

[open urchin]

no just a times 2^x

[open urchin]

sub in x=1

[lament jackal]

ohh okay i see now.

[lone heart]

@lament jackal Has your question been resolved?

[lament jackal]

so basically its just f(x) = a*2^1?

[lament jackal]

.close

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[fervent girder]

help pls

[long axle]

So do u know what y-Intercept means

@fervent girder

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[shut kite]

what is 0-(-6)

[shut kite]

hi

i have been stuck on this question for 2 hours, what is 0-(-6)

PLEASE

[velvet cliff]

6

[shut kite]

how

[velvet cliff]

just think about it

if you subtract negative six

the 2 negatives would undo

[shut kite]

i believe you, im stupid bro

[velvet cliff]

it's like saying
that drink is not untasty

well not really but my effort to explain

[shut kite]

it makes sense what you are saying

double negative is positive

[velvet cliff]

mhm

[shut kite]

.close

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[idle steppe]

hi

[idle steppe]

it says if rank(T) = dim(V)

then its injectiive

then its surjective

[short leaf]

guys i have a mathematic exam what's ur advices

[worn fox]

T : V --> V linear map?

[idle steppe]

T: V->W

should it say rank(T) = dim(W)

[worn fox]

rank(T) = dim(Image(T))

So if rank(T) = dimW then ImT=W and T is surjective

[idle steppe]

ok so i wrote the theorem down wrong it should say dim(W) not dim(V)

[worn fox]

Yeah

Can't say anything about injectivity using rank unless V=W

[idle steppe]

ok thanks!

.close

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[atomic bobcat]

https://media.discordapp.net/attachments/278629721451790336/1038938185369124924/4CF35E2D-71E1-4D89-B817-4B968EA10864.jpg?width=672&height=896

[atomic bobcat]

here i do -(1/5) < x < (1/5) then test the endpoints for the interval of convergence right?

[alpine sable]

Third times the charm

[atomic bobcat]

heh

[alpine sable]

This is probably the last time I will be able to help though because I need to sleep lmao

[atomic bobcat]

sorry i keep coming back here i was sick the day we learned this lesson so i have to teach it to myself

[alpine sable]

Yeah basically me with parametric curves

I'm only like a unit ahead of u rn more or less

But anyways

[alpine sable]

I believe so yes

Also just a tip

You can just remove the -1 At the beginning when u r doing root test

Because it is going to be gone regardless, saves you writing space

[atomic bobcat]

i see ty

.close

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[reef rock]

!help

[reef rock]

Would the rotational symmetry order of this shape be 1?

[lone heart]

@reef rock Has your question been resolved?

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@reef rock Has your question been resolved?

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@reef rock Has your question been resolved?

[urban pine]

if you're sane and only rotating in the plane, yes

[urban comet]

!help How to find y intercept I already got the gradient 0.04

!help How to find y intercept I already got the gradient 0.04

Bsd

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[ruby tusk]

Hi! If I am not mistaken here I have to use midpoint formula x1+x2/2 to find both values p and q being "5" and "-1/2" but then im not sure what to do for b maybe the distance between 2 points formula?

[karmic solstice]

SG

[lone heart]

@ruby tusk Has your question been resolved?

[peak bough]

How did you get p = 5 and q = -1/2?

[ruby tusk]

I did 2+8/2
And -6+5\2

[peak bough]

That's not how the mid-point formula works

[ruby tusk]

Oh what am I supposed to do?

You gotta go to another channel bra 😁 this one is in use try help 10 👍

[peak bough]

For points A(x1, y1, z1) and B(x2, y2, z2) we have that the midpoint M(x3, y3, z3) is calculated as x3 = (x1 + x2)/2, y3 = (y1 + y2)/2 and z3 = (z1 + z2)/2.

[ruby tusk]

Ohh so all the x together all the y together and all the z together

[peak bough]

Yes

[ruby tusk]

So 2+-6+-2/2

[peak bough]

Please use parenthesis

I can't read that

[ruby tusk]

2+(-6)+(-2)/2 for x

[peak bough]

Let's take it from the formula. You have that the y-value of A is p, the y-value of B is 5 and the y-value of the midpoint is 3. What would the equation look like from here?

[peak bough]

Were you trying to show the calculation for the x-value of the midpoint here?

[ruby tusk]

3=A+5/2?

[peak bough]

p instead of A, yes. And remember to use parenthesis around (p + 5)

[ruby tusk]

Perfect thank you so much!

[lone heart]

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[faint quiver]

Hello guys

[faint quiver]

I need help

Guys, could someone help me with this question: "Consider a regular triangular pyramid whose base edge measures 16 cm and height 20. Braiding a plane parallel to the base such that the volume of the trunk formed is 7 times the volume of the smaller pyramid formed, calculate the base edges, side edges and the height of the pyramid's trunk.

Maes?

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@faint quiver Has your question been resolved?

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@faint quiver Has your question been resolved?

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[little patio]

I have an isosceles triangle, I know its angles and one of its measures, how do I get the perimeter?

[lone heart]

@little patio Has your question been resolved?

[alpine sable]

when you say one of its measures

you mean you know one side?

[little patio]

Yes, the smallest

[alpine sable]

if so you can draw the altitude

[vague mirage]

$2×r×sin\frac{\theta}{2}=chord$

[ocean seal]

𝓐𝓡𝓝𝓐𝓑 𝓟𝓐𝓛

[vague mirage]

Construct a circle

[little patio]

Oh wait sorry

I have 2 measures

I mean, the same measure

The two same sides

Its 8cm

[vague mirage]

Means you have two same side and you need the third unequal side?

Do you have a angle?

[little patio]

Yes

[alpine sable]

you dont need to construct a circle 💀

[little patio]

The same-sides angle is 72 degrees

[alpine sable]

what are the angles?

[vague mirage]

No we can do it like that but if we have all the angle then your one is easy

[alpine sable]

oh this is a well known triangle

[faint quiver]

Hello! Could you help me with that question?

[vague mirage]

Make a help channel

[faint quiver]

Oh, ok

[little patio]

So, two 72° angles

And the other one idk

[alpine sable]

so what you can do here

well first you can find the third angle

the angles all add up to 180

so whats the third angle?

[little patio]

I got this

Is 36°

Right?

[alpine sable]

yes

[little patio]

180-(72*2)

[alpine sable]

so this is the triangle

and we draw the angle bisector of this angle

so you ahve 3 isosceles triangles now

[little patio]

Oh

And what should i've do then?

[alpine sable]

then these three sides

can all be labelled x

and then that side is 8-x

because the whole thing is 8

now,

do you see the smiilar triangles in the figure

[little patio]

Yes

[alpine sable]

okay

then write the similarity ratio

that should give you an equation to find x

then you can find the perimeter

[little patio]

Emm

Idk

I tried

[alpine sable]

okay

so whats the equation from similarity

it should be (8-x)/x = x/8, right?

[little patio]

Maybe...

Why?

Im so bad for this

Sorry

[alpine sable]

its okay

ill show you

[little patio]

I'm watching u

[alpine sable]

basically this triangle

is similar to the whole triangle

[little patio]

Yes

[alpine sable]

therefore

(8-x)/x = x/8

[little patio]

Where's the 'x/8' from?

[alpine sable]

the big triangle

the bottom of the big triangle

is x

the side of the big triangle is 8

[little patio]

And what im getting by doing that

[vague mirage]

$2×8×sin\frac{\theta}{2}
\newline \rightarrow 2×8×sin16°\rightarrow 2×8×0.2756≈4.4096
(\because sin16°≈0.2756)$
Can we do it like that

[alpine sable]

well you need sin72 for that

36

[ocean seal]

𝓐𝓡𝓝𝓐𝓑 𝓟𝓐𝓛

[vague mirage]

Oh ok

[alpine sable]

im assuming that you dont have a calculator on this question

[vague mirage]

Yes if we don't have an calculator then we simply fluorine_ uranium _ carbon_ pottasium_, UP

[alpine sable]

well no

you can do it without calculator

[alpine sable]

using this

[vague mirage]

Yeah I ment that if I use my method

[alpine sable]

yeah

ic

[vague mirage]

😂

[little patio]

Guys

How can I vacate the "help" chat

[alpine sable]

you can .close

if you solvedc the problem

[little patio]

I didn't solved xd

But want to sleep

Thanks too guys

Have a nice day

.close

[lone heart]

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[wintry kestrel]

why does the lim of h->0 of ((x^h)-1)/h equal ln x?

[wintry kestrel]

I asked this in another channel but I wasn't quick enough to reopen it my bad

[ornate condor]

not fast enough

um

try taylor series mayb

i think that gets u the ans

never gets old

[alpine sable]

L'hopital

simply use the hopsitlal rule

[wintry kestrel]

but d/dx of 1/h is 0

that would be dividing by 0

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[stray valley]

hey @wintry kestrel you still here?

[lone heart]

@wintry kestrel Has your question been resolved?

[lone heart]

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[tawny tree]

Need some help with figuring out necessary population and value of k

[sour dove]

,rccw

[tawny tree]

Was able to determine the size of initial population and after 4 days, but having trouble with the other two parts.

Just having some trouble finding the time it took to have population reach down to 60. Do I need to get *t * by itself?

[sour dove]

okay so for (c), we're basically solving when the population will get to $60$. So then $P = 60$ which means that $60 = 3200 \times 2^{-t} + 50$. So now we just solve for $t$

[ocean seal]

MellowDramaLlama

[tawny tree]

Gotcha, so we need to get variable *t * by itself?

[sour dove]

bingo!

[tawny tree]

Subracting the 50 and to the other side makes it 10= 3200 \2^ {-t}
This is where I'm getting a little stuck

[sour dove]

yep no problem

so then we need to get 2^{-t} by itself

so I would say divide both sides by 3200

[tawny tree]

I should end up with a decimal of 0.003125 = 2^{-t}?

[sour dove]

nah I would keep it as a fraction

$\frac{1}{320} = 2^{-t}$

[ocean seal]

MellowDramaLlama

[sour dove]

now we can take the log of both sides (any base is fine, but I usually prefer ln() personally)

[tawny tree]

Would it still be ok if I still used Log?

[sour dove]

yep!

doesn't matter what base

so you could do $log$ which is really $log_{10}$ (log base 10)

[ocean seal]

MellowDramaLlama

[sour dove]

so then take the logs of both sides

[tawny tree]

Would the right side have a base of two or just 10?

[sour dove]

the base would need to be the samej

[sudden swallow]

is this is problem you all are discussing about ?

[tawny tree]

This is where we first started

[sudden swallow]

which ques ..the mosquito one orrr ?

[tawny tree]

Just the mosquito one

[sudden swallow]

okie

[tawny tree]

If the left side has a base of 10, will the right side end up as log_{10}2^{-t}?

[sour dove]

yep!

that's fine

$log_{10}\left(\frac{1}{320}\right) = log_{10}\left(2^{-t}\right)$

[ocean seal]

MellowDramaLlama

[sour dove]

Then $log{10}\left(2^{-t}\right) = -tlog{10}(2)$

[ocean seal]

MellowDramaLlama

[sour dove]

now we have $log{10}\left(\frac{1}{320}\right) = -tlog{10}(2)$.

[ocean seal]

MellowDramaLlama

[sour dove]

Solve for t 🙂

[sudden swallow]

got it

t = [ 1+5log2 ] / log2 .... base is 10

[sour dove]

also, as a small hint $log_{10}\left(\frac{1}{320}\right) = -log_{10}(320)$ since $log\left(\frac{a}{b}\right) = log(a) - log(b)$. So $log_{10}\left(\frac{1}{320}\right) = log_{10}(1) - log_{10}(320)$, but $log_{10}(1) = 0$

[ocean seal]

MellowDramaLlama

[sudden swallow]

?

my answer is correct right ?

[sour dove]

wiat where did 1 + 5log(2) come from?

[sudden swallow]

can i send solution photo

[sour dove]

sure

[sudden swallow]

okie

[sour dove]

@tawny tree you still following?

[tawny tree]

Yeah, still following

Just got my logs, gonna attempt to solve for t

[sudden swallow]

5log2 can also be log32 if u want

[sour dove]

huh very clever! So yeah your t then would be $t = 5 + \frac{1}{log_{10}(2)}$

[ocean seal]

MellowDramaLlama

[sour dove]

which you simplified further

[sudden swallow]

yepsies 🙂

[tawny tree]

Ok, I was able to get where t equals

[sour dove]

yay!!

[tawny tree]

Where $t = 5 + \frac{1}{log_{10}(2)}$

[ocean seal]

PlayfulPercy

[sour dove]

bingo!

nice work

[tawny tree]

I was also able to simplify the log further

[sour dove]

❤️

so then for the last part it's just asking to solve for when the population is k

same steps

[tawny tree]

So if the population was 60, would it take a little over 8 days?

[sour dove]

yep bingo! 🙂

[tawny tree]

So the appox. time it takes for it to be 60 would be 8.32. To find k, we can input the 8.32 and solve for k with the original steps right?

[sour dove]

nah (d) is asking basically what (c) is asking but instead we solve for P = k

[tawny tree]

But do I still follow some of the same steps as we did in c? Like subtracting 50 and dividing 3200 after?

[sour dove]

yep!

[tawny tree]

So after that, I would end up with -50 + k/3200 = 2^-8.32?

[sour dove]

nah here t is just t

(c) and (d) are separate problems

wait

hold on

nah that's not right

I think I'm at the end of my rope tonight lol

I can't read anymore lol

[tawny tree]

No worries

[sour dove]

oooooh I see okay.

so we have our model as $P = 3200 \times 2^{-t} + 50$ right?

[ocean seal]

MellowDramaLlama

[tawny tree]

Yeah, it's just solving for k this time, not using the time from c

[sour dove]

nah not quite

sorry I misled youlol

[tawny tree]

No problem, I saw what happened

[sour dove]

so at some point and time though, we will see the model does stabilize

[tawny tree]

But we will still have {-t} right?

[sour dove]

yes

so at t = 0 our population is 3250 like you put in (a)

at t = 8.32, our population was down to 60

which is quite a heavy decrease

now if you have a calculator, do me a favor and and find where t = 10 and say t = 20

[tawny tree]

A very big number

[sour dove]

wait really?

oh no sorry

t is always negative lol

do -10 and -20

[tawny tree]

Oh my bad

Saw I didn't put a negative for the exponent

[sour dove]

no worries lol

[tawny tree]

So after 20 days, the population would be approx. 50

[sour dove]

okay good!

[tawny tree]

But why would -t=20?

[sour dove]

no so t represents the days

but it's exponentially decaying

so as t gets bigger, our P gets smaller

that's it

so you plug in t = 10, but really it's -10

since it's -t

[tawny tree]

As it keeps decaying exponentially, after -20 would be -30?

[sour dove]

that's the theory

but notice that for larger values of t

(that is -t)

it doesn't go below 50

[tawny tree]

Because if {-t}=-50, would the population be 0?

[sour dove]

nah put t = 50 in to your calculator

see what happens

if you graph your equation

[tawny tree]

Ah, it would still be 50

[sour dove]

yep

we have a horizontal asymptote at y = 50

[tawny tree]

That's why it won't go past 50

[sour dove]

yep!

now the reasoning for this is that we know that $3200 \times 2^{-t}$ has a horizontal asymptote at $y = 0$

[ocean seal]

MellowDramaLlama

[sour dove]

but in our equation we're adding 50

[tawny tree]

Hence the asymptote right?

[sour dove]

yep!

[tawny tree]

Gotcha

I have an answer as well and was able to determine we found the right answers for -t and k.

[sour dove]

well for d we don't really have to worry about t

we just needed k

[tawny tree]

Yeah, just k

[sour dove]

so the population will never be 50, but it'll get dang close to it

[tawny tree]

Yeah, that's what I can see

[sour dove]

so there ya go 🙂
For an answer I would just say that we know that $3200 \times 2^{-t}$ has a horizontal asymptote at $y = 0$. Our function takes $3200 \times 2^{-t}$ and translates it up by 50, so we have a horizontal asymptote at $y = 50$. Thus the population stabilizes around $k = 50$

[ocean seal]

MellowDramaLlama

[tawny tree]

So yeah, if the population was 60, it would take approx. 8 days for it to be 60. Finding k it would be 50 because of it continuous exponential decay and how it would never actually reach 50 because of the asymptote.

[sour dove]

yep bingo!

we can show this by setting P = 50, then trying to solve

we run into a problem taking logarithms since log(0) is undefined

[tawny tree]

I see

[sour dove]

and if you really want to show case this, then you can show that for example, that the population reaches 51 after about 11 days

The population reaches 50.1 after about 14 days

[tawny tree]

Ah I see. But I'll stick with just my answers for 8.32 days and k=50

[sour dove]

The population reaches 50.00001 after about 28 days

etc etc

[sudden swallow]

Can anyone help in Q 23 😄

[sour dove]

sorry @sudden swallow I gotta get some sleep lol. I'm already going to regret my day tomorrow as it is. I recommend opening a channel #❓how-to-get-help that way you get pushed to the top of the stack

[sour dove]

nice work and take care! 🙂

[tawny tree]

Thanks for the help, you too

.close

[lone heart]

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[indigo sable]

i need help with this question.
“state the domain and range of each relation. use correct set notation.”

[indigo sable]

<@&286206848099549185>

think i’ll just give up and go to sleep gn

[lone heart]

@indigo sable Has your question been resolved?

[lone heart]

@indigo sable Has your question been resolved?

[lone heart]

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[idle gate]

Hi what would \frac{149}{4}% as a simplified fraction?

[echo socket]

$\frac{149}{4}$

[ocean seal]

A Lonely Bean

[echo socket]

Well they don't have common factors

[idle gate]

ye ty, its that but instead of that its 35 whole and 1/4

%

thats what it looks like

it says write it as a simplified fraction

[echo socket]

Wouldn't that be 149/4?

[idle gate]

ik the decimal of that is 0.3725

[echo socket]

Or you wanna express it with decimals?

[idle gate]

is that what simplified fraction means?

just an improper fraction?

[echo socket]

It's simplified as long as the nominator and the denominator don't share a common factor

So yeah

[idle gate]

oh aight

[echo socket]

149/4 is a simplified fraction

[idle gate]

also, to find the angle of a right angle triangle with hypotenuses being 23 and adjacent being 18

when u use cos

it shows a decimal

is the angle the 0.67?

or is the angle just really tiny?

[vague mirage]

,w cos^-1(18/23)

[ocean seal]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by 𝓐𝓡𝓝𝓐𝓑 𝓟𝓐𝓛#6985

[vague mirage]

Ummmmmm

Yeah

,w sin^-1(18/23)

[ocean seal]

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Requested by 𝓐𝓡𝓝𝓐𝓑 𝓟𝓐𝓛#6985

[vague mirage]

Nah it's anything else

It can't happen

,w tan^-1(18/23)

[ocean seal]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by 𝓐𝓡𝓝𝓐𝓑 𝓟𝓐𝓛#6985

[vague mirage]

Can any Trigonometry king with biggest concepts explain this

Oh I got it

@idle gate bro it is in radians

It's the degree values @idle gate

[idle gate]

oooh

[vague mirage]

Yeah

[idle gate]

ah lmao i usually use my graphing calc which is set to degrees, this is like my first time using desmos smh sorry

[vague mirage]

No problem

[idle gate]

"The price P dollars of a soccer ball is discounted by $6. If four discounted soccer balls cost 32, write an equation for P and solve it"

is P the price before or after the discount

[vague mirage]

the price of ball = p
After discount = p- 6
4(p-6)=32

[lone heart]

@idle gate Has your question been resolved?

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[buoyant vector]

Trying to solve x

[buoyant vector]

The answer is supposedly 4/3 but I don’t know how to get there

I’ve tried lots of ways

😢

[vale wigeon]

d or g?

[buoyant vector]

G

My bad

[vale wigeon]

can you show some of the things you've tried thus far

[meager knot]

idk

hard

[vale wigeon]

oh god what a mess

[buoyant vector]

Yeah no shot

<@&286206848099549185>

[vale wigeon]

i think perhaps what you should do to help yourself not get lost

is to give names to all relevant points on your diagram

and then identify, by name, a pair of similar triangles

and write down a similarity statement

[vale wigeon]

ok see now i can tell you that your similarity statement is written incorrectly

it shoul be ABE is similar to ADC

because vertices E and C are supposed to correspond to each other

[buoyant vector]

I was never taught that

Those are my triangles

[buoyant vector]

I think I got it

Can you please check my working out

<@&286206848099549185>

In my diagram 11 and 6 aren’t corresponding so how did I get the answer right

[lone heart]

@buoyant vector Has your question been resolved?

[lone heart]

@buoyant vector Has your question been resolved?

[lone heart]

@buoyant vector Has your question been resolved?

[lone heart]

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[meager sable]

if i have a word that is 8 letters long, and all the letters are either a, b, or c, how many possible words are there where there are at most 2 different letters in the word?

[meager sable]

<@&286206848099549185>

[alpine sable]

2/5 - -3/4

my question is 2/5 - -3/4

@limber cradle

[lone heart]

@meager sable Has your question been resolved?

[prime badge]

256 words with 2 different letters

times 6

oh, plus 3

oh my bad

only times 3

[limber cradle]

@alpine sableYes?

[prime badge]

still wrong lmao

so we want 6 mutually exclusive types of words made of a b c ab bc ac

and they have equal sizes if they have the same number of letters, so basically a a a ab ab ab
256 is a + b + ab so 768 is a a a a a a ab ab ab

so we subtract a a a, which is just 3 from 768

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@meager sable Has your question been resolved?

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[scarlet quest]

Am I doing it right? Kinda lost

[lone heart]

@scarlet quest Has your question been resolved?

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[mortal swallow]

I understand that if I have a bag of 5 balls with 2 black balls, 2 white balls and 1 green ball, the number of permutations for drawing 5 balls from the bag is 5! / (2! x 2! x 1!). How would I work out the number of permutations for draws of less than 5 balls (without just listing out every possible permutation and counting them)?

[lone heart]

@mortal swallow Has your question been resolved?

[mortal swallow]

<@&286206848099549185>

[dusty grove]

What's a permutation?

Do u mean the number of balls in the bag

[lone heart]

@mortal swallow Has your question been resolved?

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[clever hemlock]

1. a) Determine the remainders, according to the values of n, of the division of 3^n by 11?

[clever hemlock]

help plz

[mortal trellis]

calculate the first few remainders

see if you notice a pattern

[clever hemlock]

okay

3^0 = 10[11]

3^1 = 8[11]

[civic delta]

bro anyone i've been waiting over 30 mins but no one has been anwsering me

[clever hemlock]

3^2 = 5[11]

3^3 = 2[11]

then what ?

<@&286206848099549185>

[alpine sable]

it should repeat eventually (every 10) so keep going

find all the remainder

[clever hemlock]

oh god

[alpine sable]

can aynone help me

[blissful dust]

Hi

[alpine sable]

hi

[blissful dust]

Can anyone explain why I got this wrong?

Apparently the answer is C but I am confused why

[mortal trellis]

read #❓how-to-get-help , get your own channel

[lone heart]

@clever hemlock Has your question been resolved?

[reef rock]

wrong

[lone heart]

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[wanton hearth]

quickly question:
when we have arcsin(sin a) = x we have to verify that a€[-pi/2 ; pi/2]
when it's arccis(cos a) = x, is it a€[0; pi]?

[cunning swan]

ah dadi

[sullen dome]

Correct

[wanton hearth]

ok thx

.close

[lone heart]

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[visual arrow]

Hey i just to confirm that this is true :

[solid spruce]

what are you trying to confirm

[heady pollen]

this is not a statement, it is a term

a term cannot be true or wrong

[lone heart]

@visual arrow Has your question been resolved?

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[steel aurora]

For subspaces X, Y in R^n which are homeomorphic, could it be that X is closed and Y is not closed?

[steel aurora]

I want to say no but I'm having trouble justifying it

[alpine sable]

homeomorphisms preserve topological properties

[steel aurora]

Of course, is being closed a topological property?

[alpine sable]

yeah

you can show that it preserves closure by considering the definition of continuous

[steel aurora]

Does this apply only to R^n or is closure preserved in any arbitrary topological space?

[alpine sable]

should work for any topological space

a f map from X to Y is continuous if f^-1(U) is open for all opens in Y

[steel aurora]

https://math.stackexchange.com/questions/191661/homeomorphism-that-maps-a-closed-set-to-an-open-set Would it be consistent with the counterexample offered in this answer?

with the Sierpinski space

[alpine sable]

oh weird

lemme read it

ah yeah mb, ig I was wrong lmao

[steel aurora]

no nw I had the same reasoning as you and I got confused 😭

[alpine sable]

I think we need the last sentence in the answer: that f homeomorphism from R^n to R^n, then f maps close sets in R^n to closed sets in R^n (ie f(X)=Y is closed)

[steel aurora]

yeah that makes sense

but now I'm not sure how to show that

[alpine sable]

https://math.stackexchange.com/questions/285058/can-open-sets-and-closed-sets-of-mathbbrn-be-homeomorphic

related maybe

[steel aurora]

I saw that but I haven't gotten to the material needed to prove that invariance of domain theorem, so I'm wondering if there's another way

also this is the rest of the question which was pretty straightforward so I think I'm just confusing myself

ohh wait I think I can use the same example as I did in 2. Since R (which is closed) is homeomorphic to (0,1) (which is not closed)

[alpine sable]

ah yeah, that works

I guess what I was thinking before amounts to saying that (0,1) is open in im(f)=(0,1), which is trivial.

[lone heart]

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[timid pond]

if someone may help

just a little confused

and if i miss another question i make an f

[keen mason]

20

the black line

when does it reach the y axis

at one point

[pine kettle]

dont say the answer

completely defeats the purpose of math help

[timid pond]

20?

[keen mason]

Yea but if he gets it wrong he gets an f

i cant do my homie like that

[keen mason]

Yea exactly the y intercept is when the line touches y axis

[timid pond]

ty

i need this one too

last one

bruh u a god mortta

[keen mason]

u want the answer

or help

[timid pond]

answer lmao

idc abt the help fuck that

[keen mason]

y=5x + 20

[timid pond]

jk, but tbh i really do just want the answer

[boreal verge]

you can work out the equation fkr that line, since we know m = 5 =>y =5x + 20

b being the intercept with the y axis

[timid pond]

appreciate broskis

[keen mason]

he doesnt know what y intercept is you think he gonna know what M is

[fierce prairie]

#❓how-to-get-help

[boreal verge]

go in the open help channel

[timid pond]

wait

[boreal verge]

i mean i tried

[timid pond]

sorry theres more

this the last one

[keen mason]

Go in the channels above this with no name next to it and put your question

[timid pond]

mortta?

[keen mason]

145

[timid pond]

ty

[keen mason]

now do .close or ur just a piss take

[timid pond]

OMFG

I FAILED

WTF

[boreal verge]

replace x with 25 mins since its the time, ot the x axis

[keen mason]

NICe

[timid pond]

I DID?

[keen mason]

ur one smart kid

[timid pond]

WTFFFF

LMAO

[keen mason]

How r u failing

[timid pond]

IDK

[keen mason]

i gave u all the right answers

[timid pond]

ISTG

[keen mason]

NICE>

[timid pond]

WTFFF

[boreal verge]

bro prob did so bad before he wasnt savable
no offense

[keen mason]

honestly i agree with u

[timid pond]

LOl

im retaking it

its a whole dif test lmaop

@keen mason stay here

im abt to finish the into again

and ur gonna help me 🙂

[keen mason]

Hm

ill think about it

[timid pond]

@keen mason

[keen mason]

5

[timid pond]

ik its inreases

but how much

[keen mason]

10

and 2

in that order

wait

no

click on the drop arrow

[faint acorn]

@keen mason do not encourage academic dishonesty. You are helping them cheat on a graded assignment

[keen mason]

True that is bad i shouldnt be doing that

however

what if he fails cant let me man do that

[faint acorn]

You can

Since it's against the rules of the server

[keen mason]

:(

fine

did u kick him

i cant tag him

kinda harsh

but fair enough

[sleek gyro]

in the future please only help people, giving out answers is not helping anyone @keen mason

[faint acorn]

We take cheating very seriously

[keen mason]

why?

[keen mason]

I shall

[sleek gyro]

we have high morals

i think this channel can be closed

.close

[lone heart]

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[summer trail]

$rank(\textbf{A})\not = dim\ N(\textbf{A})$

[ocean seal]

clip

[summer trail]

Does anyone know what the dim N(A) is

Not familiar with this notation

[rose sigil]

dimension of the null space probably

[summer trail]

Thanks

.close

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[molten goblet]

log x2 +5 - log 7x-1 =0

[molten goblet]

help me plis

[naive crystal]

You mean

$\log(2x+5) - \log(7x-1)=0$

[ocean seal]

Basudev

[naive crystal]

This

?

[molten goblet]

yes

no

log ( x Squared +5) - log (7x- 1) = 0

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[limpid ingot]

how do i do this

[limpid ingot]

i got the 2/n

idk whats inside the paranthesis

is ie e^2(k/n)

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[leaden prawn]

35 students are learning a new language. 17 want to learn Korean, 14 want to learn Japanese and 4 wants to learn both

[leaden prawn]

How many students do not want to learn either?

35-17 = 18 do not want to learn Korean

35 - 14 = 21 do not want to learn Japanese

[copper tangle]

Draw a venn diagram?

[leaden prawn]

18 + 21 - 35 = 4 students do not want to learn either. How do I understand this last equation?

[woeful torrent]

4(Xx3)+9-5

[leaden prawn]

Why do we subtract the total 35

Isnt it just 35 - 17 - 14 = 4 the answer

Total - Korean learners - Jap learners = Non learners

[alpine nacelle]

no, you substracted the people who want to learn both twice

(when you sub Korean, and when you sub Jap)

[leaden prawn]

but Teacher's answer is 4

I thought answers is 8 too

[woeful torrent]

is this the right one to ask 4(Xx3)+9-5

[leaden prawn]

Is this the right Venn diagram, so those that are not in the Union of Jap and Korean = 8

[woeful torrent]

ok

[leaden prawn]

Why do I subtract twice?

[alpine nacelle]

because those who want to learn both are counted with the ones who want to learn Korean AND the ones who want to learn Jap

so when you're subtracting Korean + Jap, you've subtracted the "both" ones twice

8 is definitely correct

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[fervent girder]

Ping me when ur able to help me pls

[harsh apex]

@fervent girder You can use point-slope form.

[fervent girder]

Pardon?

[karmic solstice]

y-y1=m(x-x1)

[ocean seal]

jacobmilo

[fervent girder]

oh

thats what i did

and it said i was wrong

y--8=-4/3(x-3)

oh nvm its correct this time

ty

.close

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[karmic edge]

Im so lost, anyone know what I’m doing wrong? (trig identity u-subs)

[lime peak]

hi

it is my problem

can someone help me?

[tacit arch]

this is adam's channel. please make a new one.

,w integral sqrt(36-x^2) dx

[ocean seal]

Results provided by WolframAlpha

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Requested by riemann#2529

[tacit arch]

you have to find what sin(2 theta) equals in terms of x. a double angle identity may help

Oh you did on the next line

The sin(2*arcsin(...)) Doesn't cancel that way

[tacit arch]

You incorrectly cancelled the sine and arcsine

[lone heart]

@karmic edge Has your question been resolved?

[karmic edge]

shouldn’t sin (arcsin (x)) = x? Is that logic wrong or did I apply that logic incorrectly?

[tacit arch]

yes. but that's not what you have

[tacit arch]

.

[tacit arch]

.

[karmic edge]

thank you!!! Got it now

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[jolly estuary]

I have a question about power series, can you solve for the radius and interval of convergence with different tests other than the ratio test or no?

[jolly estuary]

.close

[lone heart]

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[jolly estuary]

.reopen

[lone heart]

✅

[rose sigil]

yep there are lots of things you can do

[jolly estuary]

like which tests

[rose sigil]

hmm pretty much any could be helpful?

[jolly estuary]

how would i go about solving this?

[rose sigil]

probably ratio test?

[jolly estuary]

ok thank you i got the answer

.close

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[rose sigil]

yay

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[cyan rapids]

Anyone know the conversion rate of mph to ft/s^2?

[cyan rapids]

I have 39mph and need to convert it to ft/s^2 for a larger physics problem but my brain is cooked atm

[last ether]

Google can do that for you

[cyan rapids]

I tried, I keep getting it in ft/s

Although I was using startpage, not google, I'll try that

I was also putting in exact numbers, I should try a more general search

Got it, thanks, even if the answer was just google it, I just needed that idk

.close

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[wary stream]

Wait, what? That's a conversion from velocity to acceleration, is it not?

[last ether]

It is

But like

Apparently google can do that lol

[cyan rapids]

Conversion rate was 1.4666 repeating lol

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[proud locust]

I want to prove that, if A is a proper subset of B and B is a proper subset of C, then A is a proper subset of C

[proud locust]

I'm currently trying to use proof by contradiction

[plucky token]

you dont need contradiction

[proud locust]

Direct proof, I assume then?

Honestly I'm having trouble figuring out a similar hurdle, whether I'm using direct or contradiction

[plucky token]

if x in A then x in B then x in C

[proud locust]

yes

that part makes sense

[plucky token]

we just showed an element in A is also in C

[proud locust]

yup

but I need to also show that A is not equal to C

because I need to prove that A is a proper subset of C

not a normal subset

[plucky token]

ahh

[proud locust]

this is the part I'm having trouble with

[alpine nacelle]

if A = C, then C is a proper subset of B, and B is a proper subset of C

so you already have a contradiction

[golden stratus]

proof by contradiction is always the wrong answer

[proud locust]

ohhh

okay ty

my issue now is

The ~(A propsubset C) gives me this

so I have A = C but I can't detach it from A is not a subset of C

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[proud locust]

.close

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[mellow oriole]

98 help me

[mellow oriole]

can u help?

<@&286206848099549185>

[wary stream]

!15m

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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[mellow oriole]

mbmb

I forgot about the 15 mijs

[hard patio]

alr