help-0

[hard garden]

I'm getting confused on the last step where n=k+1

[rose sigil]

Did you see what I wrote before?

If a_n > 1 then a_n^2 > 1

And the thing inside the cube root is > 1

[hard garden]

yep

[rose sigil]

Which means a_{n+1} > 1

[hard garden]

ah i got it

thanks

[rose sigil]

🙂

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[ionic vine]

@tall topaz can you elaborate

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@ionic vine Has your question been resolved?

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[little mulch]

When are u allowed to cut x+4

From both sides

For what values of x

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@little mulch Has your question been resolved?

[red token]

is this :

x+4>4(4-x^2)?

[lone heart]

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[grizzled ember]

Hey, I am working through some problem sets from my Math Foundations 30 course. Right now I am doing some probability questions that involve using counting methods. In this specific context thinking about combinations. I got A and B right. When I got to C though, the wording is confusing me. To me it seems to imply that there needs to be equal number of both groups of students just like in question B. The answer key provides what appears to be some type of case statement for solving it. Can anyone explain to me the logic? I'm confused as to why the answer key for C is what it is. Some of the answers in the answer key have been wrong, but I'm not sure.

[lone heart]

@grizzled ember Has your question been resolved?

[grizzled ember]

<@&286206848099549185>

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@grizzled ember Has your question been resolved?

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@grizzled ember Has your question been resolved?

[remote heron]

still around?

youre missing all the cases that arent equality

[lone heart]

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[delicate fjord]

can someone show me how this was factored

[echo socket]

(-3)^(n-1) = (-3)^n * (-3)^(-1)

[lament glen]

write denom as 4 * 4^{n-1}

[delicate fjord]

so can i just pull out the 1/4 everytime like that?

[lament glen]

not sure what you mean by everytime

you can do it if it simplifies things for that question

for this one, moving the 1/4 out like that turns the problem into a geometric series

[delicate fjord]

yeah okay that makes sense

.close

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[kindred anchor]

What is your work on this?

[ocean ridge]

like what type of question is this?

its interpret Functions in Context

[kindred anchor]

Wait, is this a test that's currently going on?

[ocean ridge]

no

homework practice

its on studyisladn

i will show proof if ya want

[kindred anchor]

Ok ok, np.

[kindred anchor]

It should option (c).

[ocean ridge]

alr ty but i wanna know how to solve it

[kindred anchor]

Just plug in the value of the extreme points in the interval?

[ocean ridge]

oh alr

ty

thanks for the help

.close

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[halcyon rivet]

hi

[halcyon rivet]

i need some help

please let me know if i have made any mistake

so can you help @kindred anchor ?

[upbeat flame]

what kind of question is that xd Are a and b friends?

[halcyon rivet]

its predicate logic converted to english

i am also in agreement with you

its very confusing

[upbeat flame]

so they try to explain the meaning behind those variables as real life things?

weird af

[red quarry]

@upbeat flame discrete mathematics predicate logic

[halcyon rivet]

so i need to pick either true or false

(if its a predicate (true) ) or not (false)

i was wondering if any1 can help, i got thes answers

True
True
True
False
True
False
True

[upbeat flame]

20+x>3 can be false

but it can also be true

depends what you put in

[halcyon rivet]

yeah

i was thinking

[upbeat flame]

could be a negative number

[halcyon rivet]

20+-(number)

yeah

60-x-x^2

i think is false

now that i think about it

plz help 😄

[upbeat flame]

xd im confused sorry because im not from an english country thats why I dont understand the taks wants

[halcyon rivet]

oh ok

np

[upbeat flame]

predicate means something else in my language i believe

[halcyon rivet]

.close

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[alpine sable]

okay what's the problem

what have you done so far

or do you want a straight up answer

go to another help channel

[languid bolt]

help channel taken bro

[alpine sable]

this is already occupied

[open marten]

Where ?

Oh ok

[quiet jungle]

I got this

[alpine sable]

any that are available in the available category

[alpine sable]

did you solve it?

[quiet jungle]

Nope

I am trying

[alpine sable]

Okay

show what have you done so far

so we can try to help you

[alpine sable]

okay so first thing, how did you get to $x - 2\sqrt{x}$?

[ocean seal]

♡LexQa♡

[alpine sable]

when you composed h(x) to g(x)

[quiet jungle]

g(x)
h(x)

[alpine sable]

what?

[quiet jungle]

.

[alpine sable]

yes, but that is not true. How did you get there?

show the steps

Given that the roots of the equation x² - 14x +k = 0 and that m and n are the roots of the equation where 3m=4n. The value of the constant k is

[quiet jungle]

what do you mean

i just plug them

[alpine sable]

this channel is already occupied

[alpine sable]

well, your 'plugging' is incorrect

does $g(h((x)) = h(x)$ - 2 equal to $x - 2\sqrt{x}$?

ah forgot to remove the sign oop

[ocean seal]

♡LexQa♡

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[stoic oracle]

$A+C+D=0$,
$-4A+B-3C-D=0$,
$3A-4B=3$,
$3B=6$,
Doing a partial fraction problem, So far I have $A=\frac{11}{3}$ and $B=2$ but I am unsure of next step.

[ocean seal]

windy

[astral pond]

what is: x + 83984823 +y x e sqaure divided by 10

[stoic oracle]

sorry, this channel is currently occupied by my question

[astral pond]

aw ok

[zinc dagger]

Do u know that for a fact?

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@stoic oracle Has your question been resolved?

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[tepid drum]

hi

[tepid drum]

the answer i got for the number of sold suites is 34 is that correct ,if no then why , whats the correct answer and how to reach the correct answer . i need answers to these qquestions if possible if you please

[lone heart]

@tepid drum Has your question been resolved?

[tepid drum]

<@&286206848099549185>

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@tepid drum Has your question been resolved?

[tepid drum]

.close

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[desert zephyr]

I have a physics question. Hopefully I can ask it here. I am given the force upward of someone who jumps from the ground. Assuming no resistance aside from gravity, is it possible to calculate how high someone jumped?

[wanton nova]

i think so

Force=mass * acceleration

wait

that doesnt really help innit

just wait

[desert zephyr]

Bruh don't ask here

I need help myself

[wanton nova]

and someone will help

[desert zephyr]

<@&268886789983436800> someone asking for help in my channel

[wanton nova]

chillax

he is new

[sly mantle]

@warm gale pls dont ask for help in other users channels

[mossy laurel]

You have it's original acceleration

[river kite]

Bruh you didn't need to tag mods for that

[sly mantle]

you can ping us for that

[desert zephyr]

He is standing still when it happens

[river kite]

But anyways, no. You'll also need to know for how long that force was acting and how that force was changing with time

[wanton nova]

yes

[desert zephyr]

I assumed that's what they're here for? RootJooter also confirms it?

[wanton nova]

i don't think you can

[desert zephyr]

Hmmm since he jumps from standstill does not make the time it was acting on the person just equal to when his feet leave the ground?

[river kite]

you'll need to know that tho

[desert zephyr]

Oh okiii I will check more into it. Thanks!

.close

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[warm gale]

my sincere apologies

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[gritty sorrel]

how can i find this>?

[wanton nova]

well

the numbers seem to be decreasing by 3

[gritty sorrel]

yes

[wanton nova]

so

all the terms will be multiples of 3

[gritty sorrel]

42?

cause its divisble by 3

?

[wanton nova]

yes

no

yes

[gritty sorrel]

it can also be 75

wait

no

no

[wanton nova]

haha

[gritty sorrel]

yea 42

your confusing me

[wanton nova]

that's what i did too

🤣

[prime badge]

yes it's 42

[wanton nova]

we thought the exact same thing

lmao

[gritty sorrel]

-42

[wanton nova]

yes

[gritty sorrel]

thx lol

.close

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[fallen citrus]

can someone help plz

[ornate condor]

sus

nvm thats fine

oh

lol

here to

the 2 wasnt ^5 before

[fallen citrus]

ohhh ty!

[ornate condor]

np

[fallen citrus]

also hows the lim evaluate to 1 i thought it's 0

since the last part u get ln(1) = 0 so its |x/3| * 0

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[leaden aspen]

Did I do this properly ?

Hey already had this channel

[serene junco]

The first one is right, but you may have to restrict the domain

y=1/x is defined for all real x except x=0

But that domain does not work for the parametric function

@leaden aspen

[leaden aspen]

Ahh so I should define I when I write solution? got it

[serene junco]

Yes, do you see what the new domain would have to be?

[leaden aspen]

all reals not equal to 0 ?

[serene junco]

No, I mean, that would be the usual domain for 1/x

But it is not the domain of your parametric function

So I'm saying you need to restrict the domain in order for it to be equivalent to the parametric function

[leaden aspen]

Ok so when sin(t) = 0 ? like pi and 2pi?

[serene junco]

Oh, not exactly

Like, y=1/x would include the point (2, 1/2)

But your function can't include that point because x=sin(t) cannot equal 2

sin(t) can only output values between -1 and 1

[leaden aspen]

Ahhh I see now - I'm sorry my professor legit spent 45 minutes describing all of this stuff for parametric EQs the whole class is lost in the forest on it me included. That makes sense thank you! is my second one ok since no trig EQs involved?

err I mean that domain should be all reals

[serene junco]

In the second one you just made a small mistake

you said y^2 - 1 = t

It should be y^2 + 1 = t

[leaden aspen]

wow I'm shot out - good catch thanks again. so x= sqrt(y^2 + 2) - is it ok to leave it in terms of x or should I solve for y?

[serene junco]

It's fine solved for x

It's actually nicer this way

If you solved for y you'd have to do the +/- thing

[leaden aspen]

ahh yeah it would be a bit messier the other way right on

Thank you much for checking those out!

[serene junco]

Sure, no problem 👍

[leaden aspen]

.close

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[karmic folio]

Hello i had a question about finding when tan functions are 0

[karmic folio]

in my book they show functions like tan(x/2) and those i can solve

but i dont get the right answer when i try and solve something more like 4tan(pi*x/2)+4

[snow furnace]

are you using a calculator?

[karmic folio]

for these types i set x/2 = n*pi

and then solve for x

then try to get values that are inside my domain

[karmic folio]

yeah kinda

[snow furnace]

is it in radians or degrees

[karmic folio]

radians

[snow furnace]

what are you confused about

finding the domain?

because with the tangent graph, there is going to be spots where it is undefined

[karmic folio]

i cant seem to solve when the tan function is x= 0(zero points). when there is something infront of the tan like 4tan(blah blah)

[snow furnace]

all the 4 in front does is streach it vertically

[serene junco]

You want to find where it's equal to 0, right? So set it equal to 0

And isolate the tan(pi*x/2) part

[snow furnace]

^

so when you divide both sides by 4, you can ignore it

[karmic folio]

my book explains this stuff badly, it just puts whats inside = n*pi and they dont show examples where there is more than just the function

[snow furnace]

as your solving for 0

what is tan(0)?

[serene junco]

I don't think they want x=0

[snow furnace]

are you solving for where x=0 or y=0

[serene junco]

4tan(pi*x/2)+4 = 0
Can you get the tan() part by itself? @karmic folio

[serene junco]

y=0. They're looking for where the function is equal to 0

[karmic folio]

i am trying to find this, sorry if i didnt explain well

[snow furnace]

ah

just solve with y=0

what is the inverse of tanx?

[karmic folio]

dont know 💀

this thing tan'(x)

do i just put the function = 0

[snow furnace]

yeah

and if you take arctan of both sides, you can get rid of the tan

[serene junco]

Yes. Because your goal is to find when that is true. When the function is equal to 0

[snow furnace]

as arctan is the inverse of tan

you just have to isolate the tan(pix/2

[karmic folio]

hmm, I am a bit confiused about this part now, the book puts n*pi = the inside of tan(x)

the book gets the whole n*pi from sin=0 i think

if that helps

[snow furnace]

like tan(n*pi)?

[sour dove]

here's another hint. Consider that $tan(a) = \frac{sin(a)}{cos(a)}$. Then where $tan(a) = 0 \implies \frac{sin(a)}{cos(a)} = 0$. Then the only places where $\frac{sin(a)}{cos(a)} = 0$ is where $sin(a) = 0$. For any value of $a$ this fact will still hold true.

[ocean seal]

MellowDramaLlama

[sour dove]

aka tan(a) will equal 0 where sin(a) = 0

[sour dove]

,rotate

[karmic folio]

a function like this: tan (x/2)

then they do this

set the inside of the tan = n*pi

then solve for x

then put -1 and 0 instead of n to get values that are within the domain

(-2pi,2pi)

i think i kinda got it, by the example i should first solve the whole function for x and find the angle, the set the angle i got + n*pi

then solve for x and lastly change n with numbers like 1 or 0 to match the domain

ill try it now

.close

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[alpine violet]

help

I have to use the sum of the first n squares formula

[glacial crest]

Remember that you can split the summation up by taking the summation of the first term and subtracting the summation of the second term

[alpine violet]

ohh

like distribubbting

im still lost tho

[glacial crest]

The original sum is equal to $$\sum_{i=1}^{n}\frac{24i^2}{n^3} - \sum_{i=1}^{n}\frac{2}{n}$$

[ocean seal]

Saul

[alpine violet]

Yes

[glacial crest]

And you can factor out anything that does not involve your summation index

Because the summation will only deal with anything has to do with i

[alpine violet]

uhh okay

how do I get rid of n

[glacial crest]

well n you just factor out

it's a constant with respect to i

[glacial crest]

You could even pull that 24 out

[alpine violet]

https://cdn.discordapp.com/attachments/490557019623915520/1036408229640548393/unknown.png

ok

Done

[glacial crest]

yep

But when I say factor out I mean like $$\frac{24}{n^3}\sum_{i=1}^{n} i^2$$

[ocean seal]

Saul

[alpine violet]

ahh

and the summation formula is = to

and I can just multiply the 24/n^3 back in?

valid or no

[glacial crest]

Yep

[alpine violet]

summation of the constant

is n multiplied by the constant?

what do I do for the -2/n part

[glacial crest]

again, anything that is constant with respect to i you can just pull outside the summation and multiply back in after evaluating

[alpine violet]

but there is no i !

[glacial crest]

Exactly, so everything would be a constant in this case

[alpine violet]

hmm

so =0

[glacial crest]

Not quite

[alpine violet]

uh oh

im lost

[glacial crest]

Sorry, i think I may have complicated things a bit

Essentially you use this identity

which you mentioned

[alpine violet]

so 2

since the n's cancel

[glacial crest]

yep

[alpine violet]

Got it

Thank you sm Saul

have a good night/morning/day :)

.close

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[quasi cliff]

How does one approach b

[astral pond]

yo i need help with my math qeustion

[ornate condor]

#❓how-to-get-help

[uncut goblet]

Can someone help

[quasi cliff]

4x +x + 2x+5 = 180

[uncut goblet]

Oh shit u right

Thank you

[sour dove]

consider the example where a = 4, b = 3, m = 6, and n = 4. Then ab = 12 and mn = 24. 12 | 24 is certainly true, but is it true that a | m --> 4 | 6 or b | n --> 3 | 4? Seems false to me 🙂

[quasi cliff]

is there a way to prove this without an example?

[lone heart]

@quasi cliff Has your question been resolved?

[lone heart]

@quasi cliff Has your question been resolved?

[lone heart]

@quasi cliff Has your question been resolved?

[lone heart]

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[lone heart]

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[left citrus]

How does this step work?

[naive crystal]

Cos45sinx+sin45cosx

[left citrus]

Got it

[naive crystal]

Now remember: sin(x+y) = sinxcosy+sinycosx

Ok

[left citrus]

Yep compound angles

Thank you!

.close

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[clear hatch]

2S(A')+(B)=6 S(B')+2S(A)=36 S(E)=?

[surreal meadow]

what is E? is s a function? what are A, B, A' and B'

[clear hatch]

hello

[clear hatch]

math set

@surreal meadow

[surreal meadow]

what

E is a set?

[clear hatch]

one minutew

universal set @surreal meadow

[surreal meadow]

is s(E) the cardinality of E?

[clear hatch]

i dont know cardinality

[surreal meadow]

size of E?

the number of elements

[clear hatch]

yes

[surreal meadow]

add the second equation to the top equation

[clear hatch]

how can i do that

[surreal meadow]

2s(A') + s(B) + s(B') + 2s(A) = 6 + 36

[clear hatch]

are you sure?

[surreal meadow]

yes

notice that s(B) + s(B') = s(E), same with s(A) + s(A') = s(E)

[clear hatch]

i understand thank you

but

[clear hatch]

there have 2.s

[surreal meadow]

yes

[clear hatch]

it can change answer?

[surreal meadow]

2s(A) + 2s(A') = 2(s(A)+s(A'))

=2s(E)

[clear hatch]

now answer is 2s(E) yes?

[surreal meadow]

that's not the answer

[clear hatch]

then answer is 42 yes?

s(E)=42

yeap?

[clear hatch]

if teacher ask that i will write that yes? i understand?

[surreal meadow]

no

2s(A')+s(B)+s(B')+2s(A)=42
2s(E)+s(E)=42
3s(E)=42

what is s(E)?

[clear hatch]

very complicated

[clear hatch]

i cant understand im sorry finally whats the answer?

[surreal meadow]

what don't you understand

[clear hatch]

Im a bit of an idiot

[surreal meadow]

don't say that

just what is it that you don't understand

[clear hatch]

finally answer

[surreal meadow]

we have 3 * s(E) = 42

do you know how to solve for s(E)?

[clear hatch]

no

42*3?

[surreal meadow]

42 / 3

we divide by 3 on both sides

so s(E) = 42/3 = 14

[clear hatch]

ha

i understand

thank you

@surreal meadow

[surreal meadow]

yes

[clear hatch]

2s is multiplication

[surreal meadow]

yes

[clear hatch]

no 2.s is multiplication

s is symbol math set

[surreal meadow]

we have 2s(E) + s(E) = 3s(E)

2s(E) = s(E) + s(E)

[clear hatch]

not plus s s

s is just symbol

[surreal meadow]

i'm confused by your question

[clear hatch]

i cant explein that

thanks for everything

[lone heart]

@clear hatch Has your question been resolved?

[lone heart]

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[surreal meadow]

using log_10(2) = .3
im going to cry

ok so

can you write 40 as a product of 2 numbers?

[wicked badger]

20?

[surreal meadow]

and

[wicked badger]

20

[surreal meadow]

20 * 20 =/= 40

[wicked badger]

Oh wait 20 and 2

[surreal meadow]

yes

so we can write it as $\log_{10}(2\cdot 20)$

[ocean seal]

maximo

[surreal meadow]

do you remember log rules?

[wicked badger]

I'm actually still getting used to them, but I have some from a previous homework

[surreal meadow]

we want to use log(ab) = log(a) + log(b)

[wicked badger]

This?

[surreal meadow]

yes

so we have log(xy) = log(x) + log(y)

[wicked badger]

Okay so we'd use Rule 1 for my first problem?

[surreal meadow]

yes

[wicked badger]

Ok. Why is that?

[surreal meadow]

because it let

's us get to

log(2) + log(20)

log(2) we know since it was given to us

and we can do a similar thing with 20

[surreal meadow]

the why is something that you get more with experience

[wicked badger]

Okay

[surreal meadow]

it just makes sense to use it here

so

how can we write 20 as a product of 2 numbers

[wicked badger]

10 and 2

[surreal meadow]

great

so we get log(2) + log(2*10)

notice anything we can do?

[wicked badger]

Cancel the 2s?

[surreal meadow]

not quite

we have log(xy) again

so we can split it once more

[wicked badger]

Ohh okay

[surreal meadow]

so what would the expression be now

[wicked badger]

log(5*2) ?

[surreal meadow]

not quite

we have log(2) + log(2*10) right?

[wicked badger]

Yep

[surreal meadow]

log(2*10) we can split into what

[wicked badger]

Not sure

[surreal meadow]

remember log(xy) = log(x) + log(y)

what's our x and y here

[wicked badger]

2 and 10?

[surreal meadow]

yes

so log(2*10) = log(2) + log(10)

make sense?

[wicked badger]

Yep

[surreal meadow]

ok great

so we get

log(2) + log(2) + log(10)

what is log(2)?

[wicked badger]

Is that something i can plug in the calculator or should I just know it?

[surreal meadow]

it's given in the question

[wicked badger]

Ohhh

.3

[surreal meadow]

yes

so we have .3 + .3 + log(10)

now what is $log_{10}(10)$?

[ocean seal]

maximo

[wicked badger]

1?

[surreal meadow]

yes

so what is the answer to the first question

[wicked badger]

1?

[surreal meadow]

.

.3 + .3 + 1

[wicked badger]

Ohhh

1.6?

[surreal meadow]

yes

[wicked badger]

Okay cool. So what's the easiest way to show my work for this? I'm trying to get used to what I have to write out to show what's happening to get that answer

This is very new to me because I'm used to simple logs like log2 8 = 3

[surreal meadow]

exactly what we talked about

$\log_{10}(40)=\log_{10}(2\cdot 20)=\log_{10}(2)+\log_{10}(20)=...$

[ocean seal]

maximo

[wicked badger]

Ohh thank you 🙏

I'm starting to understand these. I'm just so new to it. Could I share some more with you?

[surreal meadow]

sure

[wicked badger]

Thank you

I'm going to write this one out on paper real quick

[wicked badger]

Okay what about #2? Pretty similar?

@surreal meadow Or would it be a different rule to use?

[surreal meadow]

express 1/4 as a power of 2

then use another logarithm rule

nono

so we want to write

2^x = 1/4

[wicked badger]

Oh

So we don't put the first line of work in a log like before?

[surreal meadow]

wdym

[wicked badger]

I'm just comparing it to how I wrote out the first problem. How I showed my work

[surreal meadow]

well we can start with log(1/4) = something

we just need to figure out what that something is

so

do you know how to write 4 as a power of 2?

[wicked badger]

Ok

2*2

[surreal meadow]

yes, so 2^2

now

do you know what 2^-1 is?

[wicked badger]

.5

[surreal meadow]

yes

in general, $a^{-b} = \frac{1}{a^b}$

[ocean seal]

maximo

[surreal meadow]

so how can we write 1/4 as a power of 2?

(notice 1/4 = 1/(2*2))

[wicked badger]

Hmm, I'm not sure

[surreal meadow]

we want 2^-2

so log(1/4) = log(2^-2)

now check your log rules to see if any apply that might help us

[wicked badger]

i'm trying to figure out which rule

[wicked badger]

Would it be rule 5?

[surreal meadow]

rule 3 is more fitting

we could also use rule 5 but let's go with 3

we have $\log(\frac{1}{4})=\log(2^{-2})=-2\log(2)$

[ocean seal]

maximo

[surreal meadow]

and like before, we know what log(2) is

[wicked badger]

Yes, .3

[surreal meadow]

so log(1/4) = -2 * .3 = -.6

[wicked badger]

Okay, so what would the full work consecutively look like? I'm going to write it out for reference

[wicked badger]

@surreal meadow Like for the work, would I just write this? But at the end add log(1/4) = -2 * .3 = -.6 ?

[lone heart]

@wicked badger Has your question been resolved?

[lone heart]

@wicked badger Has your question been resolved?

[lone heart]

@wicked badger Has your question been resolved?

[pine helm]

1. log_10(40) = log_10(20 * 2)

= log_10(20) + log_10(2)
= log_10(10) + log_10(2) + log_10(2)
= 1 + 0.3 + 0.3
= 1.6

2. log_10(1/4) = log_10(2^-2)

= 1/2 log_10(2)
= 1/2 * 0.3
= 0.15

3. log_10(16) = log_10(2^4)

= 4 log_10(2)
= 4 * 0.3
= 1.2

[lone heart]

@wicked badger Has your question been resolved?

[wicked badger]

@pine helm Thank you. What about #3 ?

[pine helm]

number 3 is 1.2

i shouldve clarified th enumbers

[lone heart]

@wicked badger Has your question been resolved?

[past steppe]

how do you get your own channel

[static flume]

There are open channels

Above the occupied section

[past steppe]

ohhh thank you

[static flume]

hears a picture

just send a question

and it will become your channel

until you close it with .close

more info is in #❓how-to-get-help

[past steppe]

ohhh ok thanks

[lone heart]

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[graceful quail]

Law of sines just need clarification if I'm going in the Right direction

[lone heart]

@graceful quail Has your question been resolved?

[lone heart]

@graceful quail Has your question been resolved?

[lone heart]

@graceful quail Has your question been resolved?

[lone heart]

@graceful quail Has your question been resolved?

[meager phoenix]

my response is a bit late, but you seem to be going on the right track

[lone heart]

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[cyan rapids]

Sorry for all the differentiating questions, I just keep running into issues with them, although I think I'm getting somewhat better. I don't know what's wrong with my answer here

[cyan rapids]

This solution also is wrong

[tacit arch]

you didn't multiply by the correct exponent

[small panther]

You got the right answer on your paper

[tacit arch]

$\frac{d}{dx} (x^n) = nx^{n-1}$

[ocean seal]

riemann

[small panther]

If i read it correctly

[cyan rapids]

Oh

Oh wait yeah I did type that correctly

Forgot to put /3 under the 7

Sure enough typing it in correctly did the trick

Thanks

.close

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[cosmic prairie]

how do you go from ak to ak-1

[minor needle]

plug k-1 instead of k

that's it

[cosmic prairie]

ty

.close

[lone heart]

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[alpine sable]

bruh

[lone heart]

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[rustic lily]

For this particular question 4 all I do is set both EQTNS equal to each other and which will result in a Quadratic so that I can use the discriminant on?

<@&286206848099549185>

[last ether]

!15m

[lone heart]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[crimson monolith]

yes exactly

and you have solutions if discrim is bigger than or equal to 0

[rustic lily]

Could you explain why I set them equal to each other

[crimson monolith]

okay imagine you are diving in a quadratic shape

and the pool floor is given by the line

we want to know if these two things intercept

where your position in the pool is p

this metaphor is getting away from me

but one equation is the trajectory of your dive, the second is the line of the pool floor

[rustic lily]

Haha so basically we set them equal to each other so we have the point of intersection (when solved) and to see the intersection point is even there or not we shove it into discriminant

[crimson monolith]

yes exactly

[rustic lily]

Okay thanks man

[crimson monolith]

if you get a graph plotter and plot both lines

it might help

[rustic lily]

Yes thanks a tonne my friend

.close

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[split tide]

question, if i have 2 equation but i dont know what the Y is can i solve it?

[final ember]

yes

[slate jolt]

wdym?

can you give an example?

[split tide]

so this is my 2 equations

Y=66x+0

Y=99x+0

[slate jolt]

if both have to be true at the same time

yeah you can find out

for example you can sub in one expression of Y in the other equation

[split tide]

bc i just have to make a solution using elimination, substitution and graphing

[final ember]

u can solveee by substitution

[slate jolt]

ok so lets start with substitution

[final ember]

which is probably the easiest

[split tide]

info i have

sorry for flooding

[final ember]

You know how to solve by substitution right?

[split tide]

if i'm being honest i'm not really good at it so not really

all i know is you plug in what Y='s

[final ember]

Y=66x+0
Y=99x+0 both equal y

so we can set them equal to each othjerr

so 66x=99x

x= 0

now you can find y by subing in x for 0

[split tide]

wait what?

[final ember]

for any equation

[split tide]

how did u get 66x=99x?

[final ember]

pretend y = 6

[split tide]

ok

[final ember]

that means 6 = 66x and 6 ==99x

[split tide]

ok

[final ember]

so that means both 66x and 99x equal 6

we can set them equal to each other

[split tide]

ohh

[final ember]

66x = 99x

[split tide]

i think my teacher would want to do it in steps

[final ember]

i think that is one step

[split tide]

so i can do 1Y = 66x and 1Y = 99x

[final ember]

y is assumeed to be 1y so u can just leave it like that

but if ur teacher wants it go with that

[split tide]

so i turned y=66x+0 -> Y=66x

and the same for the other one

[final ember]

yea

[split tide]

so what now?

[final ember]

set them equal to each other

66x=99x

[split tide]

ok

What I’ve done

[final ember]

ok good

now solve for x

[split tide]

but how?

so it would be Y=99(66) + 0?

[final ember]

no

solve 66x=99x

[split tide]

so divide?

[final ember]

no subtract 66x from both sides

[split tide]

oh

[final ember]

so 0=33x

u will get 0

[split tide]

okay

so for my solution it's (0,?)

[final ember]

yes

[split tide]

but then how would i find why?

but in the context it doesnt make sense

[final ember]

now plug in 0 to any of the original equations

[split tide]

so like Y=66(0) +0?

[final ember]

yea

[split tide]

so y=0

[final ember]

hmm

[split tide]

how can the rate of change be 0?

[final ember]

well lets read the context

so ur slope is monthly gas cost

which is then 66

I think u have the wrong y int

[split tide]

but when we did it it's 0?

[final ember]

so wrong equation

starting point doesn;t make sense

[split tide]

so i did the graph wrong

[final ember]

for ur second one, ur staring point i believe is the value of the car when bought

thats b or the y intercept

i think you need to redo it with the correct equations

[split tide]

so i'll just get more paper and restart it

[final ember]

yea

but u can still use the process we went through

Substitution should still work

[split tide]

got rid of all the paper

i'll just restart

so does it matter how i start

so since the hybrid's initial price is 40k would i put Y=66x+40000?

and then for the gas i'll do Y=99x+30000

[final ember]

yes

[split tide]

then how would i find my Y?

[final ember]

ok do the samething

99x+30000=66x+40000

find x and then find y

[split tide]

i think i should have it from now, thank you anyways

.close

[lone heart]

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[noble imp]

How to solve this?

[lone heart]

@noble imp Has your question been resolved?

[lone heart]

@noble imp Has your question been resolved?

[lone heart]

@noble imp Has your question been resolved?

[tacit arch]

Do the matrix multiplication

[lone heart]

@noble imp Has your question been resolved?

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[worldly bolt]

Website is refusing my answer. Followed this video exactly:

https://www.youtube.com/watch?v=jadCHUZ0-xU

[alpine sable]

you're allowed to use your calculator?

[worldly bolt]

Yes

[alpine sable]

csc is 1/cos right?

[worldly bolt]

Pretty sure you have to?

[alpine sable]

well yes but i mean if ur allowed to use like arccos or cos^-1

[worldly bolt]

Yes, but this video is also saying hyp/opp or r/y

[alpine sable]

and then 1/cosu = -12.82
cosu =1/-12.82 then just use arcos

because cosine is opp/hyp

oh shit mb

csc is 1/sin

woops

[worldly bolt]

.close

[lone heart]

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[echo plaza]

wouldnt this be 16 and not -16 like the answer key says?

[jagged imp]

please dont post over someone else's question

[jagged imp]

Answer is correct, it would be -16

[echo plaza]

how come?

[jagged imp]

sqrt(-8)*sqrt(32)=sqrt(8)i*sqrt(32)i=i^2*sqrt(8*32)=-16

[echo plaza]

?

[jagged imp]

What about what I said is question mark worthy

[echo plaza]

what does sqrt mean?

[jagged imp]

square root

[echo plaza]

oh

It's kind of written weird lol

[shut pewter]

No

That's actually correct

[jagged imp]

Pretty standard notation, but I can write it more neatly: $$\sqrt{-8}\sqrt{-32}=\sqrt{8}i\sqrt{32}i=i^2*\sqrt{8*32}=-16$$

[shut pewter]

Ok he already did it

[echo plaza]

this makes more sense

[shut pewter]

There's a typo

[ocean seal]

Sneaky

[jagged imp]

fixed

As for why it isn't 16, sqrt(ab)=sqrt(a)*sqrt(b) doesnt always hold when a or b are less than 0

[echo plaza]

I think I get it now

.close

[lone heart]

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[thorny parcel]

use a calculator

[pseudo dew]

owo

[tacit arch]

Is this a troll?

[lone heart]

@dusk hearth Has your question been resolved?

[shut pewter]

I mean are you trying to find a way to square a number without a calculator?

Nah I think my method was wrong, let me try to find my source

Separate 6 and 9
Add 9 into 69 = 78
78 X 6 = 468 x 10 = 4680
4680+9^2=4761

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[cold bluff]

hey i was just wondering if anybody could help me with that?

nevermind i think i figured it out

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[drowsy sedge]

now idk if I should of done the exact trig values or left it as is

but yeah

sorry for the messy work but I basically pretended this was a test question and they always give you like seemingly the exact amount of time to do the question down to the minute so I just threw down everything I knew

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[final summit]

Having a hard time seeing what my professor did between step 3 and 4

[thorny parcel]

He used trig identities

[final summit]

I know cos(2v) = cos^2(v)-sin^2(v), and sin(2v) = 2sin(v)cos(v), so I got that step to (cos^2(v)-sin^(v))cos(v) - 2sin(v)cos(v)

Oh there's multiple identities for double angles

[west lion]

do you mean the part where it starts 2cos^3(v)... ?

[final summit]

Yeah was wondering where the -1 came from

I see it now, didn't know there were multiple identities

[west lion]

yeah, hard to remember sometimes lol

[final summit]

Here's to hoping I get an identity sheet for my exam lol

Anyways ty

.close

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[stiff root]

Hi, I have a question? What do you say, length of an airplane on average.

1. 10m
2. 20m
   3.50m
3. 150m

Thanks for the help-

[thorny parcel]

Add them all together and then divide them by 4

[pearl dagger]

Ye

[prime badge]

unless those are just choices

[pearl dagger]

Hope not

[stiff root]

Thank you !

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[dull phoenix]

Hello, can someone help me with this equation? 4x^4 + 4x^3 + x^2 = 0

[thorny parcel]

Factor x^2

[small panther]

Factor

[dull phoenix]

Where do I begin…?

[thorny parcel]

You see that all terms have x^2 ?

So you can factor it

x^2 * (4x^2 + 4 x + 1)

[dull phoenix]

Alright nice

Is there any simpler way?

[thorny parcel]

yeah

If u see that (4x^2 + 4x + 1) = (2x+1)^2

[dull phoenix]

Alright, thank you

.close

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[sleek tartan]

How do I find vector v here? I know the vectors AB and BC. Would a cross product work in that case?

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[paper mango]

given all value pairs (X|Y) from a function, how does one check whether it's part of a logarithmic function e.g. f(x) = ln(x)?

[paper mango]

For exponential functions it seems easy since one can check f(x)/f(x-1) = constant

[jolly hare]

Can someone help

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[vapid steppe]

would the degree of this be 6

[small panther]

Its at least 2

[vapid steppe]

yea but quadratics can’t have that shape

[small panther]

My guess is also 6 but there is no justification

I don't see any math proof

[vapid steppe]

i said to like translate it one unit down and then look at the zeros

[small panther]

Yes

[vapid steppe]

the zero at x=0 has multiplicity 3

[small panther]

That makes sense to me

No w8

If you translate it one unit down, there will be 3 answers for 0 and only 1 answer to the left

The current right hand zero will be removed

[vapid steppe]

oh yea

[small panther]

So with this translation, we can say that the degree is at least 4

[vapid steppe]

can degree 4 polynomials have that shape?

[small panther]

Maybe idk

You should have a lesson on this kind of questions

[vapid steppe]

ye ima ask teacher today

[small panther]

Ok

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[dark trail]

i need

[dark trail]

serious elp

when i expand

do i set x = 2x

for the formula

well when i check wolfram the answers up to x^3 r

but my answer is like this

1-4x+24x^2-288x^3

where i set x = 2x and expand that 2x by squaring it and cubing it

then multiplying as follows

n(N-1)x2!(ax)^2

where a = 2

and n = -2

and x = 2x

[lone belfry]

you have to divide by 2! the term in x^2, by 3! the one in x^3 and so on

[dark trail]

i thought you could move the factorial to the right

no the left

multiplyig it by the descending or ascending numbers as the powers increase @lone belfry