help-0

[alpine sable]

what happened?

dont worry the 2 can help me

[languid haven]

the confusion

[alpine sable]

which one you solved?

[languid haven]

ah wait

shi

[alpine sable]

what happened?

I got like

400 something

and my friend got 391.60m

I was asking for the oct

but if you solved the hex its ok

[alpine sable]

DUDE

[exotic viper]

Anybody help ?

[languid haven]

i got

392

[alpine sable]

how?

[languid haven]

its for the 8 sides

[alpine sable]

yeah

[languid haven]

so

[alpine sable]

ok wait

[languid haven]

imagine this

[alpine sable]

A = N x S x A over 2

yeah?

[languid haven]

nono ill make it easy for ya

[alpine sable]

ok ok

tell me

[languid haven]

so then octagon is composed of 8 isoceles triagnle

man i cant spell

[alpine sable]

ok

[languid haven]

clear till that much?

[alpine sable]

yeah

[languid haven]

so

the value were

22 cm across and

10 m base yeah?

[alpine sable]

yeah

[languid haven]

ok

then

22/2 is 11

[alpine sable]

wait we need to divide by 2?

ooooh

ye ye

Im getting it

[languid haven]

now from this we have two options

[alpine sable]

yeah?

[languid haven]

first is directly finding the area of an isoceles trisngle

[alpine sable]

ok

or?

[languid haven]

or the right angled way

[alpine sable]

I dont think I know that because im on seventh grade but ill try

[languid haven]

oh

wait

then nvm

[alpine sable]

?

ok ok

[languid haven]

ill just give you the octagon formula

[alpine sable]

I need to do like pyhtagoras

[languid haven]

what did your teacher give ya

[languid haven]

ignore it then

[alpine sable]

ok

[languid haven]

man you have to do the pythagorus man

sorry dude

[alpine sable]

so I was doing like c= 11 a= ? b=5

[languid haven]

the h is obtained from this

[languid haven]

b = a

[alpine sable]

oh ok

then I got 146

and I need to get the square root

so its

12.08

and then I need A = 8 x 5 x 12.08 over 2

im confused here

could you help on this part?

hello?

omg dude why this always happens

[languid haven]

ok so

we have

A = 8 /2 ah

right?

we have a as 10 right?

SO a = 10

that means

A=(8/2) * 10 *h

@alpine sable now whats left is to find h

[alpine sable]

ok

[alpine sable]

ok it is good

but wait

arent we finding the apothem or other thing?

because on all shapes my teacher told me just to find area and perimeter, the formula for area was A = N x S x A over 2 and for perimeter was P = N x S

[languid haven]

hmmm

[languid haven]

thats correct

but

[alpine sable]

?

[languid haven]

what you need to do is find the area of one triangle

octagon is just that triangle multiplied by 8

it goes for all the gon shapes

[alpine sable]

wait

isnt like this

[languid haven]

?

[alpine sable]

like

[languid haven]

nono its an isoceles triangle a triangle with two equal sides

lol

a is also 11

wait no

you did a right angles triangle

solve it

a = 13

[alpine sable]

like this

let me send you like procedure

[alpine sable]

this is easy

look

[languid haven]

okok

[alpine sable]

its example

I did it

[languid haven]

thats for a 7 heptagon(7 sided)

odd numbers are a pain

[alpine sable]

ok let me send you what I was doing

[languid haven]

sure

[alpine sable]

ok wiat

that far is how I im going

hello?

[languid haven]

ye just ping me lol

[languid haven]

a = 11 not 5

and b = 5

[alpine sable]

ok

but is it correct'

[languid haven]

no

the bottom part

[alpine sable]

no way

[languid haven]

the procedure is tho

[alpine sable]

ok wait

[languid haven]

@alpine sable

[alpine sable]

no way thank you so much I FOUND IT

I GOT 391.60

m

than u so much

so so so so much

I need to go tho

but thank you so much bye

if you have time can we solve the other just if you have time

just in case you respond me give me 5 minutes becausei m helping my mom

I will be back

[lone heart]

@alpine sable Has your question been resolved?

Channel closed

Closed by @nova orbit

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[viscid wren]

can i get help with 54?

[lone heart]

@viscid wren Has your question been resolved?

[keen plinth]

f can be thought of as the distance from (1, 0)

and R is the upper half of a disc centred on the origin

if you draw a diagram it should be clear where the maxima/minima are

[lone heart]

@viscid wren Has your question been resolved?

[lunar bolt]

If you partially differentiate the equation inside the square root of f(x,y) with respect to x, you'll get 2x - 2. Then set this equal to zero, then you'll get x=1.

[viscid wren]

thats only one of the extrema

i need the absolute max and mins

prof told us to solve the bounded region for y and then plug that into the original function but

[lunar bolt]

Similarly, you can also differentiate wrt y to get 2y, if you equate that to 0, you get y=0

[viscid wren]

yyup

[keen plinth]

rewrite the inside of the sqrt as

[lunar bolt]

Therefore, the point (1,0) is a point where there is either a minima or maxima

[keen plinth]

you can see that its minimised when x=1 and y=0

and that its maximised when its furthest away from (1, 0) in the half-disc

[viscid wren]

heres the work, sorry for the mess

[keen plinth]

quadratics dont require taking derivatives to maximise/minimise

[viscid wren]

well this was the method we were taught to find the abs max and mins so I don't really know what to say

I used this exact same method for question 51 and had 0 issues

[keen plinth]

you can plug in the boundary directly to find the maximum

51 can likewise be done without differentiating

[viscid wren]

I 100% get that but we have to work it out like this for whatever reason.

like I asked if I could just plug in the boundary points and he said no lol

anyways I'm gonna go ahead and go to bed.

.close

[lone heart]

Channel closed

Closed by @viscid wren

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lone heart]

Please don't occupy multiple help channels.

[limpid moat]

.close

[lone heart]

Channel closed

Closed by @limpid moat

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wooden mantle]

Is this correct?

also the calculator says ln(x)^2 is 2ln(x)/x

But isnt is 2/x?

like the derivative of it

[tacit arch]

chain rule

[wooden mantle]

Oh right

So then we get 0/0

and can use lhopitals again

[tall topaz]

Yes

[wooden mantle]

Aight gotcha

thanks

.close

[lone heart]

Channel closed

Closed by @wooden mantle

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wooden mantle]

How should I go about solving it?

Since I still got 2 constants in the equation

[vale wigeon]

well you've used the initial condition y(0) = 0

now use the other one

[wooden mantle]

Oh do we get a systems of equation out of it?

[vale wigeon]

yes

i believe i told you about that before

[wooden mantle]

Cant remember that on one go

Especially when Im trying to practise all the other stuff in my calculus course at the same time

Bound to forget some things here and there

Anyways I reckon I can take it from here

thanks

.close

[lone heart]

Channel closed

Closed by @wooden mantle

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rigid tundra]

Need help trying to rearrange a fraction in order to compute a limit

[rigid tundra]

Tried

Multiplying by congugate

For both expressions

[lone heart]

@rigid tundra Has your question been resolved?

[gray isle]

show work

[rigid tundra]

Ok

[gray isle]

don't unnecessarily expand stuff

[rigid tundra]

I rearrange, but this new form still has same problem

I see ,so something can cancel when I multiply conjugate

[gray isle]

i would prefer that you don't, if you have questions make a channel

consider conjugates of the numerator as well

[rigid tundra]

Yh I tried aswell separately

Could u do them at the same time

Or will one succeed in cancelling

Somewhere

If u don't expand

[gray isle]

only do the multiplications involving the difference of two squares

and you should end up with a relatively easily identifiable common factor in the numerator and denominator

[rigid tundra]

Ahh I see thanks

I'll try now

I saw the cancel ,thanksm

How did u understand to multiply by both conjugates

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[gray isle]

standard idea for these types of problems

[rigid tundra]

I see thanks ,I have it in my tool kit 🙂

[gray isle]

builds on the same principle of why you'd do the first conjugate

[rigid tundra]

Yh true

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[woeful wind]

Please can I have some help with 9i)

[lone heart]

@woeful wind Has your question been resolved?

[lone heart]

@woeful wind Has your question been resolved?

[woeful wind]

<@&286206848099549185>

[lone heart]

@woeful wind Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[surreal sky]

write in polar form:

my try:
(1 − i)^3 ( √ 3 + i) / 4i ⇔
(1-3i-3+i)(√3 + i) / 4i ⇔
(-2-2i)(√3 + i) / 4i ⇔
2(-1-i)(√3 + i) / 4i ⇔
(-1-i)(√3 + i) / 2i ⇔
(-√3-i-√3 x i+1) / 2i ⇔
(-√3-i-√3 x i+1) x -2i / (2i x -2i)⇔
(2i√3 - 2 - 2√3+-2i) / 4 ⇔
(- 2 - 2√3)/4 + (2i√3-2i) / 4 ⇔
-(1+√3)/2 + (√3-1)i / 2

Polär form:
r =√( (-(1+√3)/2)2 +((√3-1) / 2)2) = √2
tanv = (√3-1) / -(1+√3) ⇔ v = arctan(√3-2) <-- this i cant do by hand , is their a better way of going about it?

[runic trench]

multiply the fraction by the conjugate of 4i

[surreal sky]

from the start yea?

[runic trench]

yeah then combine and simplify

[surreal sky]

ill give it a try

thx 😄

.close

[lone heart]

Channel closed

Closed by @surreal sky

Use .reopen if this was a mistake.

[surreal sky]

.reopen

[lone heart]

✅

[surreal sky]

well i gave it a try and got the same problem

(1 − i)^3 ( √ 3 + i) / 4i ⇔
(1 − i)^3 ( √ 3 + i) x -4i / 16 ⇔
(1-3i-3+i)(√3 + i) x -4i / 16 ⇔
(-2-2i)(√3 + i) x -4i / 16 ⇔
(-1-i)(√3 + i) x -4i / 8 ⇔
(4i - 4)(√3 + i)/8 ⇔
(i-1)(√3 + i)/2 ⇔
(√3 x i-1-√3-i)/2 ⇔
-(√3+1)/2 + (√3 - 1)i / 2

Polar form:
r =√( (-(1+√3)/2)2 +((√3-1) / 2)2) = √2
tanv = (√3-1) / -(1+√3)

[rigid smelt]

what is the problem?

[surreal sky]

i cant do tanv = (√3-1) / -(1+√3) by hand

[rigid smelt]

what do you mean exactly?

you cant find the exact value?

[surreal sky]

pretty much

[rigid smelt]

that's because you cant, the exact value of arctan(that) is just itself

it's not very nice, but you would have to deal with it

however though, arctan(...) is not your argument

so be careful about that

[surreal sky]

what do you mean by that?

[rigid smelt]

finding v by taking arctangent on both sides will not give you the argument of your complex number

refer back to principal argument definition

[surreal sky]

thx for the clarifications 👍

.close

[lone heart]

Channel closed

Closed by @surreal sky

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lavish bane]

how do i do this?

i got -8.873 x 10^8
i multiplied 8.2 and -7.9
which was -64. something
then i did
-3-5
which was -8
then i divided -64.78 by 7.3
which was 8.873
then i did -8+16
which was 8
so it was 8.873 x 10^8

[tacit bobcat]

,calc 8.210^-3 * -7.910^5/(7.3*10^16)

[ocean seal]

Result:

-8.8739726027397e-14

[tacit bobcat]

you are mixing up positive and negative parts

[lone heart]

@lavish bane Has your question been resolved?

[lavish bane]

oh ok

thank you

[lone heart]

Channel closed

Closed by @lavish bane

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[patent bluff]

Ah sht wait how do u rotate

Forgot how to rotate but basically i need help with number 2.

Where my physics bois at?

[sonic drum]

bro

discord.gg/physics 😑

[patent bluff]

.close

[lone heart]

Channel closed

Closed by @patent bluff

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[craggy basin]

hey good eve can someone give me a easy run down piecewise three sub-functions over a specific interval??

[craggy basin]

i just want to make a situated problem and answer it myself also

(i can't plagiarize)

something like this

[mortal trellis]

should that function have any requirements?

continuous? differentiable?

$f(x) = \begin{cases} x^2+4x+7 & x\leq -3 \ 5 \cos(x) & -3<x\leq 4 \ -7x & x > 4 \end{cases}$

[ocean seal]

Denascite

[craggy basin]

i only have to provide two questions to evaluate the constructed piecewise function and show a detailed solution based on the formulated problem

and create three sub-functions over a specific interval.

thats all

[worn hedge]

i need help

its so hard

[alpine sable]

serious questions only, you are occupying a channel that someone else could use.

[worn hedge]

i am serious

[lone heart]

@craggy basin Has your question been resolved?

[lone heart]

@craggy basin Has your question been resolved?

[lone heart]

@craggy basin Has your question been resolved?

[alpine sable]

<@&268886789983436800>

[lone heart]

@craggy basin Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[earnest cradle]

quick question. Why the anwer is infinity? shouldn't it be 0?

[carmine reef]

why 0?

limit is infinity because the function gets arbitrarily large when x is close to 1

[earnest cradle]

it seems more resonable to me 3/0 should be 0

maybe the + next to 0 changes smh

[warped light]

whats 3/(0.00001)

plug it into your calculator

[earnest cradle]

ahhhhhh now i understand

thanks

[lone heart]

@earnest cradle Has your question been resolved?

[pearl dragon]

Quadratic equations using the Quadratic formula

Iam confused nkw

[lone heart]

Channel closed

Closed by @earnest cradle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jade imp]

In order to differentiate this, I know I need to use product rule

but

Can I treat this function as (6x^2sinx) (tanx)

or are all three pieces independent

[tall topaz]

You can but then you’ll have to use product rule again anyway

[jade imp]

Yea i understand that but Its better to do one than two

[tall topaz]

You’ll see that $$\frac{d}{dx} f(x)g(x)h(x) = f’(x)g(x)h(x) + f(x)g’(x)h(x) +f(x)g(x)h’(x)$$

[ocean seal]

Pure

[jade imp]

okay

Let me work it out and then Ill let you know my answer

[rustic cypress]

good luck

[jade imp]

12xsinstanx+6x^2cosxtanx + 6x^2sinxsec^2x

Can that be simplified any more?

[tall topaz]

I guess you could factor out some stuff

[jade imp]

Can you? The only thing I can see you factoring out is a 6

[tall topaz]

tanx = sinx/cosx

[jade imp]

oh okay. I guess sec^2(x) = 1/cos^2(x) too right

[tall topaz]

Yes

[jade imp]

Okay. Ill factor later but this answer should suffice

Thanks man

have a good one

.close

[lone heart]

Channel closed

Closed by @jade imp

Use .reopen if this was a mistake.

[tall topaz]

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[night dagger]

We will determine a linear mapping 𝑓(𝑥,𝑦)=𝐀⋅(𝑥 / 𝑦) with 𝐀∈ℝ2×2 which "turns the coordinate system around the origin" by 30 degrees anti-clockwise.
The task should be to determine the matrix 𝐀
a) A turn of 30 degrees counter-clockwise transfers the vector (𝑥𝑦)=(10)
to 𝐀⋅(10)=(((√3)/2)/(1/2)). Where is the second coordinate direction mapped to, i.e. what is the image of (0/1) under the mapping f? (x and y direction, write √3 as sqrt(3) if you need to.)

b) Based on information from part task a), it is now possible to determine matrix 𝐀

[night dagger]

Task descrpition:
We will determine a linear mapping 𝑓(𝑥,𝑦)=𝐀⋅(𝑥 / 𝑦) with 𝐀∈ℝ2×2 which "turns the coordinate system around the origin" by 30 degrees anti-clockwise.

The final goal is to determine the matrix 𝐀

Task:
a) A turn of 30 degrees counter-clockwise transfers the vector (𝑥/𝑦)=(1/0)
to 𝐀⋅(1/0)=(((√3)/2)/(1/2)). Where is the second coordinate direction mapped to, i.e. what is the image of (0/1) under the mapping f? (x and y direction, write √3 as sqrt(3) if you need to.)

b) Based on information from part task a), it is now possible to determine matrix 𝐀

Cant figure out how to do task B, does anyone know how I can do this?

[lone heart]

@night dagger Has your question been resolved?

[night dagger]

.close

[lone heart]

Channel closed

Closed by @night dagger

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hollow zephyr]

hello, I'm trying to calculate linear approximation of this data

that's the formulas I'm using

but the result is simply wrong

[lone heart]

@hollow zephyr Has your question been resolved?

[lone heart]

@hollow zephyr Has your question been resolved?

Channel closed

Closed by @hollow zephyr

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quasi moth]

Help

[quasi moth]

-x-3+2x

[dim oasis]

What are you trying to do?

[quasi moth]

Simplify

[dim oasis]

$-x - 3 + 2x$

[ocean seal]

lexitorius

[dim oasis]

What are your like terms in this equation?

[quasi moth]

X

?

[dim oasis]

Yup the ones that have an x

So -x and 2x

[quasi moth]

1x

[dim oasis]

Bingo

Which can also just be written x

Are there any like terms for the -3?

[quasi moth]

Nah

[dim oasis]

$x - 3$

[ocean seal]

lexitorius

[dim oasis]

There you are

[quasi moth]

Thank you

[dim oasis]

👍

[quasi moth]

For teaching me how to do this

Byeee

.close

[lone heart]

Channel closed

Closed by @quasi moth

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pseudo fjord]

hi

[pseudo fjord]

hi?

i have a question

how do u solve this

[plain flame]

just ask the question

[pseudo fjord]

3.9=(radical)2delta y over -9.8

??

anyone?

[lone heart]

@pseudo fjord Has your question been resolved?

[lone heart]

@pseudo fjord Has your question been resolved?

Channel closed

Closed by @pseudo fjord

Use .reopen if this was a mistake.

[pseudo fjord]

, reopen

reopen

.reopen

[lone heart]

✅

[pseudo fjord]

is vertical shift and vertical translation the same thing

[jagged cobalt]

yeah

[pseudo fjord]

oh lol thanks

just wanted to make sure

[jagged cobalt]

.close

[lone heart]

Channel closed

Closed by @jagged cobalt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[haughty tiger]

I m kind of lost on what steps to take on the first problem I can find the derivative of x= 121/6 after that I tried plugging it into the original function to find C and got 20959.91667 as the number but it aint right..

[lone heart]

@haughty tiger Has your question been resolved?

[haughty tiger]

<@&286206848099549185>

.close

[lone heart]

Channel closed

Closed by @haughty tiger

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gray heart]

Is molar mass and formula mass asking for the same thing?

[lone heart]

@gray heart Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vital fog]

pls help im stuck

<@&286206848099549185>

[abstract fractal]

!15m

[lone heart]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[vital fog]

oh sorry

.close

[lone heart]

Channel closed

Closed by @vital fog

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gloomy spruce]

problem: secx*cotx - sinx

[naive crystal]

You gotta simplify??

[gloomy spruce]

yep

[naive crystal]

So secx is the reciprocal of cosx

[gloomy spruce]

yep[

[naive crystal]

So secx is equal to??

[gloomy spruce]

1/cosx

[naive crystal]

Yes

[gloomy spruce]

and 1/cosx*cosx/sinx

[naive crystal]

Yes

Then cancel out

[gloomy spruce]

cancels to 1/sinx

which is cscx?

[naive crystal]

Yes

Ye but

[gloomy spruce]

1/sinx-sinx

[naive crystal]

Don't do that

Ye

Then take lcm

So it becomes??

[gloomy spruce]

sinx

1/sinx-sinx^2/sinx

[naive crystal]

On Simplifying the fraction you get??

[gloomy spruce]

1-sinx^2/sinx

and that is cosx^2/sinx

right

[naive crystal]

Yes

[gloomy spruce]

is that it

[naive crystal]

No

[gloomy spruce]

cosx/sinx *cosx

[naive crystal]

Cosx/sinx * cosx

[gloomy spruce]

so thats cotx*cosx

AND THEN THATS IT

[naive crystal]

Yes

Yep

[gloomy spruce]

alr thanks

have a great day

[naive crystal]

K

You too

[gloomy spruce]

.close

[lone heart]

Channel closed

Closed by @gloomy spruce

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[urban pendant]

help

[urban pendant]

how do I solve this? I am not sure what the T between the vectors means

[buoyant kayak]

the T stands for transpose, which means switching the rows and columns of the matrix

once you do that, it's just matrix multiplication

[urban pendant]

ah ok thanks

[urban pendant]

the first two are basically the same exact operation and are basically like finding a dot product, -10
i am not sure what the bottom two matrix answers are asking for though

[lone heart]

@urban pendant Has your question been resolved?

[lone heart]

@urban pendant Has your question been resolved?

[urban orchid]

think about how matrix multiplication works. Yes, if you multiply a row vector by a column vector, you'll get a single number. What happens if you multiply a column vector by a row vector?

[urban pendant]

Oh hmm

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[undone agate]

Why can we use SAS here?

It doesnt look like DCA is included angle on the bottom triangle

[carmine reef]

you're right, that looks improper

[lone heart]

@undone agate Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ashen portal]

https://cdn.discordapp.com/attachments/814945818217152623/1032137200571260969/unknown.png

I have no clue what the end behavior is for this graph

[pulsar aspen]

What function is that?

[ashen portal]

Its a polynomial

Finding the end behavior of the function

Gimme a min to paste it

[pulsar aspen]

Cubic?

[ashen portal]

https://gyazo.com/08819492c90ce3a8ca1210ead7a4afbd

its a polynomial function

[pulsar aspen]

By "end behavior", do you mean the limit of the function as it goes to infinity?

[ashen portal]

ye

[pulsar aspen]

It will diverge to $\infty$

[ocean seal]

BlokirKominfo

[ashen portal]

mhm

[pulsar aspen]

Just look at the leading coefficient.

[ashen portal]

Actually i figured it out got stuck for like 20 minutes

Thanks for the help

[lone heart]

@ashen portal Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jade canyon]

Set A={ ( [-1,0] ∩ Q ) ∪ [0, 1] }, what is the unordered sum on A? ( ∑x, x∈A )

[jade canyon]

is it +∞ or its undefined?

I know the sum on [-1, 1] is undefined, but…

[lone heart]

@jade canyon Has your question been resolved?

[jade canyon]

<@&286206848099549185>

[rose sigil]

I'm not sure how much convention there is on what it means to sum over an uncountable set

[jade canyon]

I only know that the uncountable sum of a non-negative set is the supremum of the sum over its finite subsets.

dont know when it have negative numbers

[rose sigil]

I don't know if there is any convention for that, but there might also not be any useful way to define it anyway

[jade canyon]

because its ∞-∞?

[rose sigil]

if you take this

wouldn't the negative numbers not affect the sum?

[jade canyon]

If it is a finite number of negative numbers, it has nothing to do with the order. If there are infinitely many negative numbers then the order will matter.

[rose sigil]

but the sup won't change

[rose sigil]

ok actually I'll ask why do you ask this?

[jade canyon]

ok I was thinking that the cardinality of R is much more than Q, might this affects the result to be positive infinity?

[rose sigil]

well... let $$A= [-1,0]\cup ((0,1)\cap\bQ).$$ Then $$\sup\left{\sum_{x\in F}x:F\subseteq A, F \text{ is finite}\right}=\infty$$

actually let me rewrite that

[ocean seal]

layla💜

[jade canyon]

How to prove that this formula holds even with negative numbers?

All books/articles only show that it holds only if it contains only non-negative numbers

[rose sigil]

the negative numbers don't affect the sup lol

[rose sigil]

nono

they just don't define it for the case where there are non-negative numbers

[rose sigil]

there are infinitely many rational numbers greater than 1/2

what is still what?

[jade canyon]

ok for only non-negative number, its sup; but for only negative number, its inf

[rose sigil]

sure

[jade canyon]

while both non-negative and negative numbers are included, I didn't find any definition of summation

[rose sigil]

yea, that's what I meant with no convention lol

[jade canyon]

ok but for this, If the answer for any order of summation is positive infinity, then does it not exist or is positive infinity?

[rose sigil]

not sure what you're asking

[keen plinth]

finite sums from A can range anywhere from -infinity to +infinity

it just sorta doesnt make sense

[jade canyon]

uhm intuitively, this disordered sum should be positive infinity since the R <-> P(Q)…

idk

its no convention

like the uncountable sum on negative integers union positive real numbers

[rose sigil]

my intuition says there are more worthwhile things to think about than this 🥴

[jade canyon]

lol

[lone heart]

@jade canyon Has your question been resolved?

Channel closed

Closed by @jade canyon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

could anyone help me with a linear equation?

[alpine sable]

i gotta find the y-int

3x - y/2 - 5 = 0

[jade canyon]

set x=0

solve for y

which is -y/2 - 5 =0

-y/2 = 5

-y = 10

y = -10

[alpine sable]

what happened to the 3

[jade canyon]

set x = 0

[alpine sable]

wait so

if its 3x

it just goes to 0

[jade canyon]

3 time 0 is 0

yeah

[alpine sable]

oohhh

ok thanks

i was a little confused

/close

.close

[lone heart]

Channel closed

Closed by @limpid snow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

how would u find y-int for 7y = 5 - 2x

[alpine sable]

just repeat the same thing

set x to 0 then solve for y

[ornate moon]

I think u need to make x = 0 or something like that?

[alpine sable]

i did solving for y and got 0.7

[ornate moon]

Can someone please help me with coordinate geometry? It makes me want to die

[eternal lantern]

Hey could anyone please help me answer C and D

[alpine sable]

did i do something wrong

[alpine sable]

yes correct

but

on my sheet

wait no

don’t write 0.7

7/10?

just write y = 5/7

on my sheet

there is an answer list

[jade canyon]

set x=0

[alpine sable]

use #help-15

[jade canyon]

7y = 5

[alpine sable]

and 0.7 isn't a part of the asnwers

yeah

[jade canyon]

so y = 5/7

[alpine sable]

5/7 = approximately 0.7

but it’s better to just write

5/7

there's no 5/7 either

then, what’s the answer?

idk

[cobalt raptor]

omg i have my best friend's discord is also mooncakee woahh

[alpine sable]

it’s probably 5/7

maybe there's a mistake on the sheet then

[jade canyon]

try 0.71

[cobalt raptor]

😱😱😱😱

[alpine sable]

haha

is their mooncake from final space?

cuz mine is

[cobalt raptor]

not sure lemme as her

ask*

[alpine sable]

,w 7y = 5 - 0

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by miky#7649

[alpine sable]

probably

huh

that

on my calculator

i did 0.7

then clicked the S D button

and i got 7/10

yes

because

[jade canyon]

because

[alpine sable]

5/7 isn’t 0.7

it’s approximately 0.7

oh

would 7/10 be a valid answer?

nope

wait whattt

,w 5/7

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by miky#7649

[alpine sable]

the calc lied to me!

,w 7/10

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by miky#7649

[alpine sable]

7/10 is 0.7 while 5/7 is that

so that means

7/10 is also an answer?

[jade canyon]

try it

[alpine sable]

i can't really do that rn

no, but if the teacher accepts it I’ll be surprised

i'm not at school

i got a sheet

oh okay

and i'm at home trying to do it

if you write something like

≈ 7/10

maybe the teacher will accept it

maybe

[jade canyon]

actually…

i dont think they will accept this

[alpine sable]

how come

yeah, that’s why I said maybe
but if this was me I would honestly just write 5/7

oh wait

so i redid the calculator

and i wrote every decimal point

and i did S D

and got 5/7

yeah it’s 5/7

alr thanks for the help guys

np

:)

.close

[lone heart]

Channel closed

Closed by @limpid snow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[signal sable]

So I'm doing a maths paper that is measuring the correlation between core affinity (how many cpu cores are being used) and CPU temp

[signal sable]

as well as

GPU temp and CPU temp

so 2 different correlations

both GPU temp AND core affinity impact CPU temp

as they both increase it, is there a way i can model their combined impacts onto a 3d graph of sorts?

basically

there will be a positive correlation between GPU temp and CPU temp, as well as core affinity and cpu temp

from this correlation, i can derive 2 trendlines, and 2 functions

then i wanna run a video game, and using those two functions, try to estimate CPU temperature using both gpu temperature AND core affinity

[lone heart]

@signal sable Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[grave juniper]

i really need help with this question i am so clueless on how to do it

[analog falcon]

I actually solved it uh one sec lemme find the solution

https://media.discordapp.net/attachments/903463353417072641/1031514027635003402/912969666295627787.png
Message link: #help-17 message

Correction: Let $\angle AQP=x$

[ocean seal]

n11

[analog falcon]

in the first line

@grave juniper ^

[grave juniper]

OMG TYSM ILL HAVE A LOOK

[analog falcon]

npp! :)

Oh so actually we don't need to join AP really, so you can skip that part

[grave juniper]

i see

[grave juniper]

but how does the exterior angle property work

[analog falcon]

let me unleash my artistry

[grave juniper]

lmao

[analog falcon]

So basically the exterior angle is equal to sum of interior opposite angles

both are 180 minus the third angle

[grave juniper]

i see

OHHHH

OMG

THIS IS SO SMART

THANK YOU SO MUCH

btw are you good in geometry?

i have some more questions

that i am struggling

[analog falcon]

np!

[analog falcon]

I can give them a try!

[grave juniper]

should we do it here or dms?

i have to sleep right now because i have been working on the worksheet for the past 3 hours

[analog falcon]

here should be okay?

[grave juniper]

alright ill just send the rest of the question

but thank you so much tho

[analog falcon]

np!

[grave juniper]

just 2 more with 2 sub questions

[ocean seal]

n11

[analog falcon]

And now since they're similar, the second part can easily be proven.

↑ This is for question 5 btw ↑

[grave juniper]

btw i dont think i understand (angle subtended by a chord to the centre of a circle is double the angle subtended by it on any other point of the cirlcle than the chord)

[grave juniper]

tysm

[ocean seal]

n11
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[analog falcon]

oop

ignores the warning

[analog falcon]

Its a theorem. Let me see where I can find it

https://byjus.com/maths/angle-subtended-by-an-arc-of-a-circle/

Ah its an arc actually not chord lmao

[grave juniper]

ohhh okay i understand now

anyways thank you

btw out of curiousity what year are you in?

[limpid spade]

First

[grave juniper]

?

wait is n11 your alt or smth?

[limpid spade]

No

I answered your question

[grave juniper]

um how does that work???

[limpid spade]

?

How answering a question works?

[grave juniper]

that wasnt my math question lmao

i was asking n11 because he was so good at explaining

and he seems good at math

[limpid spade]

What a lad

[grave juniper]

but anyways ig i should close this channel now

.close

[lone heart]

Channel closed

Closed by @grave juniper

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[robust oak]

how did we get here

[mortal trellis]

wdym

[golden canyon]

you just entered a really good approximation of the golden ratio

[robust oak]

its (-1 sqrt5) /2

[golden canyon]

maybe even the approximation the calculator used

[robust oak]

how is that the reciprocal of phi

[mortal trellis]

the golden ratio is a root of x^2-x-1=0

by vieta then the second root is -1/phi

but you can also calculate that the other root is (1-sqrt 5)/2

[robust oak]

huh

-1/phi?

[mortal trellis]

$\frac{1-\sqrt 5}{2} = -\frac{1}{\varphi}$, so $\frac{1}{\varphi} = -\frac{1-\sqrt 5}{2} = \frac{\sqrt 5-1}{2}$

[ocean seal]

Denascite

[robust oak]

wouldnt x1 be (-1+sqrt5)/2

wait

whay

phi is (1+sqrt 5)/2 right

[mortal trellis]

the two roots of $x^2-x-1=0$ are $x_1=\frac{1+\sqrt 5}{2} =\varphi$ and $x_2 = \frac{1-\sqrt 5}{2}$

[ocean seal]

Denascite

[robust oak]

o yeah

[mortal trellis]

by vieta $x_1x_2=-1$, so $\varphi x_2 = -1$

[ocean seal]

Denascite

[mortal trellis]

or $x_2 = \frac{-1}{\varphi}$

[ocean seal]

Denascite

[mortal trellis]

and then this

[robust oak]

is x2 -1/phi

ye

but um

why is(sqrt 5 - 1)/2 the reciprocal of phi

[mortal trellis]

$\frac{\sqrt 5-1}{2} = -x_2 = -\frac{-1}{\varphi} = \frac{1}{\varphi}$

[ocean seal]

Denascite

[robust oak]

maybe im just dumb

is it just in the rules or smth

or my brain is just fried

[tall topaz]

Simplify
$\frac{1}{\frac{1+\sqrt{5}}{2}}$

[ocean seal]

Pure

[robust oak]

thats 1/phi right

[tall topaz]

Yes simplify that

[robust oak]

huh

isnt it just 2/(1+sqrt5)

[tall topaz]

Yes then multiply top and bottom by the conjugate

So $1-\sqrt 5$

[ocean seal]

Pure

[robust oak]

what conjugate

[tall topaz]

Conjugate of $1+\sqrt 5$

[ocean seal]

Pure

[tall topaz]

You want to rationalise the fraction

[mortal trellis]

or as a third method, if you know that $\varphi$ is the root of $x^2-x=1$, dividing by $x$ gives $x-1=\frac 1 x$, which is exactly what we want. $\varphi-1 = \frac 1 \varphi$

[ocean seal]

Denascite

[robust oak]

hmm

my brain is not braining

um

i dont

understand

😅

[robust oak]

do we multiply this by 1 - sqrt5 or smth

we conjugate 1+sqrt5

how

[tall topaz]

$\frac{2}{1+\sqrt{5}} = \frac{2}{1+\sqrt{5}} \times \frac{1-\sqrt 5}{1-\sqrt 5}$

[ocean seal]

Pure

[robust oak]

so

[tall topaz]

https://youtu.be/gY5TvlHg4Vk

[robust oak]

1-5

2(1-sqrt5)

wait

2(1-sqrt5)/-4

so

minus?

ooohhhh

oohhhhhhhhhhhhhhhh

conjugate

making the denominator not have sqrts

oh

my first language is not english so

thank you

[tall topaz]

[robust oak]

i am no longer smal brain anymore

do we close this channel

[tall topaz]

Sure

.close

[lone heart]

Channel closed

Closed by @tall topaz

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

Really having time with finding rates change

[gray isle]

try plotting the one in the bottom right

[lone heart]

@alpine sable Has your question been resolved?

Channel closed

Closed by @fallen plinth

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pseudo shuttle]

Can someone please explain to me how to represent irrational numbers on a number line (Class 9 Math)

[vale wigeon]

depends on what kind of irrational

if it's made from integers or rational numbers by means of square roots then you can construct it exactly with some pythagoras bullshit

otherwise youll have to make do with a decimal approximation

[pseudo shuttle]

roots yeah

but how to take the units

[vale wigeon]

wdym by "take the units"?

...can you just send the entire question

will be easier this way

[pseudo shuttle]

represent root 2, 3 and 5 on a number line

[prime badge]

maybe you're not required to draw the triangles?

[gray isle]

yeh, use right triangles and pythagoras as ann mentioned

[prime badge]

just put it approximately betwee 1 and 1.5

[pseudo shuttle]

yeaa

and what else about the √3 and √5?
what measure should i take

?

[gray isle]

if you just want an approximation, just use a ruler and calculator

[prime badge]

because you don't draw circle arcs to represent 0.5 do you

[pseudo shuttle]

but tomorrow's my exam

lmao

[pseudo shuttle]

nah just right angled triangles

[gray isle]

,calc sqrt(3)

[ocean seal]

Result:

1.7320508075689

[gray isle]

,calc sqrt(5)

[ocean seal]

Result:

2.2360679774998

[pseudo shuttle]

this is the mesaure i shoul take

[gray isle]

if you just want an approximation, just use a ruler and calculator

[pseudo shuttle]

but i can't

use a calculator

[gray isle]

if you want something as close to the desired value as humanly possible with the tools available, draw triangles and use compass

[pseudo shuttle]

ohk

and what do i do if i have to represent a decimal

eg √9.3

[gray isle]

then its gonna be painful

like it really depends what you're being required to do

[pseudo shuttle]

represent this on a number line
with using a ruler and a compass

[gray isle]

doubt you'd be required to plot sqrt(9.3)

[pseudo shuttle]

but it really comes in a lot of our book questions

[vale wigeon]

,w a^2 + b^2 = 930 integer solutions

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Ann#0413

[vale wigeon]

,w a^2 + b^2 = 929 integer solutions

[pseudo shuttle]

lmao

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Ann#0413

[pseudo shuttle]

but this is not my problem

aa

[vale wigeon]

well there you have it ig. you can plot sqrt(929) using a 20 by 23 right triangle, then plot sqrt(930) using a 1 by sqrt(929) right triangle, then divide that into 10 equal parts and have one of them be sqrt(930/100) a.k.a. sqrt(9.3)

[pseudo shuttle]

oh what the hell

[vale wigeon]

it's hacky but it works ¯_(ツ)_/¯

[pseudo shuttle]

nah this not the method we used to do

[vale wigeon]

OH SORRY YOU DIDNT SPECIFY A METHOD TO ADHERE TO

[gray isle]

you already had a method outlined for you?

[pseudo shuttle]

using a ruler and a compass

representing √9.3 on a number line

[pseudo shuttle]

yea ig it works

[gray isle]

what method were they using

[pseudo shuttle]

take a measure as 9.3 cm

draw an arc

[gray isle]

and then?

[pseudo shuttle]

you have √9.3

[gray isle]

no?

[pseudo shuttle]

but i don't understand that HOW!?

[gray isle]

because you don't get sqrt(9.3) from what you described in two lines?

can you show exactly what the book is saying?

[empty cedar]

Hu???

by that logic sqrt of 9cm is 9 cm

[pseudo shuttle]

WAIT I'LL SHOW THE SS

by this method ig

[gray isle]

yeh.. that's pythagoras

as Ann described

there's no nice way to apply that for sqrt(9.3)

[pseudo shuttle]

yea

but on a decimal?

will Pythagoras work?

[gray isle]

there's no nice way to do it

[pseudo shuttle]

:(

[gray isle]

hence why Ann had to go through all those hoops

well there you have it ig. you can plot sqrt(929) using a 20 by 23 right triangle, then plot sqrt(930) using a 1 by sqrt(929) right triangle, then divide that into 10 equal parts and have one of them be sqrt(930/100) a.k.a. sqrt(9.3)

[pseudo shuttle]

ayo wat de fok is this sheit

[gray isle]

and dividing into 10 is also a pain depending on how much precision is expected

[pseudo shuttle]

@gray isle

the solution?

.close

[lone heart]

Channel closed

Closed by @pseudo shuttle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gray isle]

1 sec

[gray isle]

double checking whether that actually works

[pseudo shuttle]

ohh