#help-0
1 messages · Page 67 of 1
this is exciting
We start with 116.14 friends
After one year it's 113.2 etc
yea
Alright that's great
There are a lot of infos in your problem but if you take your time to sum it up it becomes clear
last thing is the r^2=.58 im still kinda confused
Well you see
The statistician did his graph
point by point
And he has something that's not a line right?
The points are not perfectly aligned
That would be too lucky, in reality it doesn't happen
But he needs a line so what does he do?
He draw a line passing through the maximum number of points
r²=0.58 is about how much points the line passes through
The line passes through 58% of the points
The line described by friends=(-2.94)*age+116.14 (or f=-2.94x+116.14)
For example, here the point represents reality (the data he collected) and the line is an approximation of what's going on, r² is about whether the approximation/line is close to reality
If you have r²=1 the points were perfectly aligned
if r²=0 the points are everywhere and we can't really draw a good line
yea
im actually understanding it
you're an amazing teacher dude
Thx 
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hi can someone help me with this question
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help w rational root theorem

you check the factors of a0 and the factors of a3
and the rational roots will all be of the form +-(factors of a0)/(factors of a3)
lol ofc
hm
otherwise factors of a0 doesnt really make sense
n factors means pos n neg?
no i wrote a +- so
o
you only need positive factors
but like
if you include both +-
then you get the +- anyway
well
it always works given a rational root exists?
all RRT says is all rational roots must be of the form +-(factors of a0)/(factors of a3)
and nothing about whether any of them are actually roots
fails
wait all?
and none of those are roots
and thats it
well yes
RRT says if you are a rational root, you are of the form +-(factors of a0)/(factors of a3)
ok i thought it was one
so rrt also works
on some eq
if we can * some k such tht they r all ints
btw why must the a1,a2 b ints
because number theory
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wtf LOL
💕



on my road to becoming immortal
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my teacher has lost touch with reality and I need help on this problem
..
FORTNITEEE
ur teacher
no way LOL
LOL
yea
It looks like those math sums on newspapers
inb4 swiss shows his true power
or just decor
what is it? I know the bricks equal 9
1 brick and 2 pinatas = 17 einsteins
maybe its 27^spikes /3
Wtf is that
no I think the einstein is just decoration
its not worth doing these problems
27/3=9
17-9=8
8/2=4
4-2=2
2+4+9=15
lol
1 iron + 1 brick + 1 pinata = ?? fortnite skin
thats what im trying to figure out
decor
It's 14 lol
breh wat
No it's only 1 steel in the final equation
oh
in my country u could actually solve these random problems on newspapers and submit it to the publishing house, you can win a cruise trip lol
But seriously yo teacher's gone mad
yea
17 einsteins lmfao
,w b + b + b = 27, b + p + p = 17, p - 2j = 2
:0
amazing

another question by the same insane teacher
LOL
yea, he not a real fortnite player
dude that looks like a google reviews comment thing

He's lost his marbles and his screws
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good night
Depends how much money he has.
If he is allowed to cancel and buy again.
If he is allowed to buy from a friend for cheeper.
or just 3
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answer was 3
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Stumble Guys
There should be more fortnite questions. Like the probability to get certain items in a row. Size and position of the circle area etc, and whether a bullet hits the target etc.
I HAVE BEEN SUMMONED
eh
wait there’s no question here
Imagine using Fortnite for your Physics test
😆 image Fortnite is the Topic of your final Math Exam
I remember we once got a Physics test on projectile motion. 2 questions. One was The Hunger Games themed and the other one had Selena Gomez crashing her car.
I am not kidding.
Selena Gomez
Granted this was 9th grade
crashing her car? oh my gosh
Yeah like driving her car off a bridge into a fairly large drop
Fortunately the only one that died was the car
She was just fine.
Until you did the problem and realized she decided to commit insurance fraud.
I will not elaborate further.
so it was like a braking distance question?
Yes, actually
i first read "unfortunately" the only one who died... so like you wanted Selena Gomez to ... xd
The question was to find out whether she had actually used her brakes or not.
nice to hear Selena is fine 🙂
No she's in jail for insurance fraud
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I am in Calc 2 and learning about Sequences and Series, anyone able to help?
someone probably can, what questions do you have?
Just one homework question
I can send pictures
Parts a and b
I have part a down, just need help understanding what part b is asking
<@&286206848099549185>
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Hi
I’m a bit lost
With this
Oops <AF= y, so would that be the overall 360?
So 5x-15=360,x=75?
half the revolution bruh
yeah that's the problem
??
it should be = 180
I lied, y=3x+6 so I doubled it and CLT w the rest and added all up to 360


I solved it
Are they not all opposite angles? 2 of each given angle add to 360?
No
Well
how did u even aplly clt lol
CLT?
3x+6 x 2 = 6x+12, then the others
LOL

8x-9=360

x=46 1/8
im so lost rn
,w 5x-15=180
Oh-

Oh bye I just realized..
Thx- odnfdmsmsms
Oh right im not sure about this 1
10.25=x
Uhm
Crickets
<@&286206848099549185> Im rlly lost sry for ping
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Hey guys, could you please help me solve this? The question asks to calculate the integral over D
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(x2-x1) + (y2-y1)
what do u mean?
subtract initial from final
why did you multiply by 6.8 twice?
wdym?
shouldn't 4 be multiplied by 6.2?
where exactly
ebic
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Help me please
When they said consider three different cases what they mean by that?
i believe it's related to the value of the discriminant
do you have 2 real roots, 1 repeated real rool or 2 complex conjugate roots
not sure
Maybe just consider cases b=0, c is not 0, c=0, b is not 0, both not zero
2 is just power rule, for 1 and 3 u need trig subs
How do I apply it to my question
Let’s just say
I completed the square
How do I proceed?
<@&286206848099549185>
You can write it as (x+(b/2))^2 + sqrt[(c-(b^2)/4)]^2, so you just have something of the form X^2 + A^2
assuming c-(b^2/4) is positive
I also suggest you to substitute something for c-b^2/4 just for the sake of making it cleaner so you dont accidentally leave a minus sign somewhere and trip yourself
Okay if u see the hint earlier, does that mean c-(b^2/4) can be considered as positive negative and 0?
Yes
Why did square root c-b^2/4?
Oh wait nvm
Wait what else to do from there
Assuming c-b^2/4 is positive I just take tan as a substitution
Yeah
So x+b/2 = tan theta?
Uh
First let x+(b/2) = X, c-b^2/4 = A^2
You get 1/(X^2 + A^2)
then use the substitution X=Atan(theta)
And that will be 1/atantheta^2 + a^2
Could u verify if I have to integrate this and substitute back the theta and a?
@shell widget
1/[A^2(tan^2 (theta) + 1)]
then use tan^2(theta) + 1 = sec^2 (theta)
and since ur now integration wrt theta, you need replace dx as well
Why +1?
factored out A^2
You forgot to multiply by the derivative of x
Yes
Can you please help me simplify this one and show me the process?
@alpine sable open a help channel
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How do you answer question 3c
Isn't this like physics
I see
,rccw
Couldn't find an attached image in the last 10 messages.
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interesting
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Can anyone tell me why the highlighted is 1/2e^(y/2) and the last one
#calculation problem
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Thats just $$\dfrac{de^{y/2}}{dy}$$
jimmy1234
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Hey could I get help with Question 5 please? I’m particularly stuck on F and C
I don’t know what Part F is asking with the question mark box
seems like a typo, ig treat it like a variable called '?'
So is it asking me to put any input?
yes, a variable can be thought of as an arbitrary input
So when is says f of x, do I put that in all of the x’s like for example
It says f(-x)
x (-x)/x(-x)^2 + 1?
yes, everywhere you see an x, put -x instead
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Hi, I'm currently learning Loci and I'm confused on why the correct area shaded on is this, and how they got that.
I tried substituting points in each area, and I ticked where the equation was correct at that co-ordinate.
But the marking scheme had a much smaller area shaded
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hello there
It's when 2 or more lines meet.
the corners of the triangle lol
Bruh
bruh
Like how the ends of each meet each other
ok
so what would the answer to this be
and could you explain
how you got there
add them together lol
ah-
i forgot abt this lol...like i did this years ago 💀 lemme try
yh im in yr8
and boy this is some tricky stuff
specially when the literal entirety of year 7 you literally fapped in class
noo
like 12-13 age
grade 7 for u guys
i think
yes grade 7
ah- ew imagine being 13
sorry lemme help
last one
@craggy flax sorry im in grade 10 and doing polynomials...so i forgot most of this shit. wtf am i supposed to do
oof
bruh help him lol
teach him bruh
well ive guessed them now so the numbers have changed :/
because sparx is an absolute shithole of a software to be using for homework
yh no i give up how tf am i gon do my gcsc's bruh
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someone help 17.b)
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How did it get factored?
i did but there is a part i don’t understand
Which
$(\theta +
\cot {\theta}) \times (-\csc{\theta}\cot{\theta})$
Pure
$=(\csc{\theta}\cot{\theta})\times (\theta +
\cot {\theta})$
That’s just cot^2
oh
But that’s not relevant here
Then how do i multiply it here
Pure
This is the same thing just without the negative sign
Ah yeah I forgot the negative sign
$=-(\csc{\theta}\cot{\theta})\times (\theta +
\cot {\theta})$
Pure
We have this
yes
$=-(\csc{\theta}) \times (\cot{\theta})\times (\theta +
\cot {\theta})$
Pure
$=-(\csc{\theta}) \times (\cot{\theta}(\theta +
\cot {\theta}))$
Pure
okay so we just put it inside a bracket cuz its already all multiplied
$=-(\csc{\theta}) \times (\theta \cot{\theta} +
\cot ^2{\theta})$
Pure
okay i got this now the last part is csc * cot
we shouldnt do ot and just take common factor right?
Yes

🥲
Cya and thanks you so much for helping me i can’t find anything thing to explain to me
couldnt*
Np
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I got the first step, but idk what to do afterwards. im trying to prove bec = dea
@glacial trail Has your question been resolved?
consider the definition of bisection and what step 1 tells you about certain lengths,
applying that thoroughly will lead to the required congruence proof
wdym
bisecting is just 2 lines meeting at the middle right
so what does that tell you about the lengths of certain segments
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It asks to simplify in terms of the second expression
This is what I’ve got so far
Am I on the right path or close?
nah, I gave up like halfway cause my brain is burnt out rn
the sinx is what it wants the simplified answer in terms of
the answer is 1/sinx, I'm just not sure how to get there, or if the work I currently have is on the right path
yeah, I tried that app earlier, it seems to kinda give up with most trig identities lol
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how do i state the domain and range of each relation and how do i determine whether each relation is a function. if it is a function, determine if it is onto, both, or neither.
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Domain is an interval from the lowest X-value to the highest, Range is that for the Y-values
A relation is not a function if any x-value has 2 different y-values
for example, if you had the set { (0, 1), (0,2), (1,2 }, this would not be a function because 0 is paired with 2 different Y-values (1 and 2)
ahh
im not sure what that means
can i get more like a
idk
EASIER EXPLANATION i dont know english that wlel
bu why
but*
A function basically takes a number and spits out a new one. If you have the function y=2x, and you give it the number 2, it's the same as saying 2x2, so it'd be 4. A function can't give more than 1 answer for any given number.
You can also think of this with the "vertical line test". If you graphed the points that a problem gives you, would you be able to draw a single vertical line and touch more than one of them? If so, it's not a function, and if not, then it is a function.
What does onto mean
in this case first question
would not be a function
because of the
0.5
if im correct
or well there’s a 0
correct, but because of the 0.4, not the 0.5
i just don’t know how to determine wether it’s a onto or both or neither
oh why
oh yeah
0.4, and 0?
0.4 appears more than once, and because it's the first number in a pair (making it the x-coordinate), it violates the rule that an x-value can't have more than 1 y-value
If 1 number in the X spot of (X,Y) appears more than once, it's not a function
oHH
The 0 doesn't matter here
i understand it now tysm
ohh
so its only if it
repeats
its not a function
yes, if an x-value repeats, it's not a function
does the same go with y-value?
no, only x
ohh
how do i know which one is the x and y value in the first problem
is like
the first two
sets
y values
and the last 2
x?
Notice how the problems gives you sets of numbers in parentheses? Those are called ordered pairs, The first number in any ordered pair is the x-value, and the 2nd is the y-value
so for the first problem, you have the points (0.5 , 3) , (0.4, 2) , (3.1,1) , and (0.4, 0)
0.5 is x and 3 is y
yes!
exactly!
now if it's a function how do i know it's onto both or neither
I honestly have no idea what “onto” means there
i don't either 😭
i tried searching it up
and it says
'If A and B are the two sets, if for every element of B, there is at least one or more element matching with set A'
but i still dont know
im not sure if the x is a and b is y
do u know what would mean as for both or neither?
A continuous function can be theoretically drawn forever without lifting your pencil
both of those functions are continuous
I won’t explain exactly how to draw each of those graphs, but I’ll say that y=x^2-1 will look almost like the letter U, and y=3x+2 will be a diagonal line going up and to the right
For problems 7 and 8, simply replace the “x” in the given functions, with the the value in the parenthese
So for 7, you’ll turn -2x+4 into -2(12)+4 and solve it
ohh
For 8 you’ll replace “x” with “7c” and expand it, since it can’t be fully solved unless they tell you what c equals
where did the 12 come from
f(12)
OH
ooh i get it now for that one
i understand 7 and 8 but for 5 and 6 how do i graph
Do you know what the graphs X^2 and X look like?
A graph is essentially a visual representation of the all the possible solutions of a function
This is the graph of y=x
This is the graph of y=2x
ooo
how do i know if its a function
also i suppose its continous because its a straight line right?
A function is continuous if it has no end, and discrete if it only shows specific values
y=x is continuous because you can put any number for x and get an answer back
The vertical line test, if you draw a vertical line thru a graph and it hits more than once, it’s not a function
I is a vertical line, _ is a horizontal line
OHH
understood!!
so in that case for exp y = x^2 - 1 which it's shaped as a u it's not a function and its discrete
no
it’s shaped like a U, but it can be drawn forever in either direction, and it’s impossible to hit it more than once with a vertical line
(I’m still currently making a visual example for what “hitting it more than once” means)
continous*
ahh okay tysm!!
This would be a function, because it’s impossible to draw a vertical line that crosses it more than once
This would not be a function, because it can be crossed more than once with 1 vertical line
Although y=x^2 can get steep, it’s also impossible to cross more than once with a single vertical line
OHH
Neither of them are discrete
wait so what type of graph is discrete
A discrete function’s graph would look more like a set of dots, or a line split into multiple pieces, instead of one line that can be drawn forever
ohhh
Here’s a good example
OOO THATS REALLY HELPFUL
Oh, and to further explain the Domain and Range : intervals are basically a convenient way to show the maximum and minimum values of a function
Ahhh
So we’ll go back to this
Yes
What’s the smallest X-value here?
0.4
and what’s the largest?
3.1
Alright, so since an interval shows the largest and smallest values, those are the only numbers we’re concerned with.
Since those are X-values, we use them to write the domain
and that would be written as [0.4, 3.1]
Yes, those would be the horizontal position on a graph, but this problem doesn’t need to be graphed
Now, what are the smallest and largest Y-values?
Yep, so what would the range be?
intervals are always written from smallest to largest
Yep! And the type of bracket you use does actually matter
[0,3] means the interval includes 0 and 3, while (0,3) would not include 0 and 3
Ohh
So for these sets you’d be using [], because there’s nothing going on that would cause the numbers to be excluded
@alpine sable Has your question been resolved?
can someone help me?
by using rules for differentiation
I don't know how to solve using chain rule
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32x^{\frac{3}{2}}x-1=0
how to simplify this further
well, what else can you do here? You can't take a power to both sides yet because you have a constant on the LHS
well there ya go, so how do we get x by itself now?
i can do tha root thing
lol. Well what I would say is "raise both sides by 2/5" Make sense?
good!
x = (1/32)^2/5
but then i am conufsed
oh
wait
i am smart
i got it
1^2/5 = 1
and
32 ^ 2/5 becomes 4
bingo! 🙂
darn tootin you are!
tootin means ?
it means "emphasis"
but it's more slang than it is an actual word
no worries, that's how you find out!
are you a pro at math
coool
yeah sure, sounds fun lol
i ask my friends this trick math question
what is 1/0
if you get is correct that you didnt fall for it
well it's undefined. We say that's an illegal operation in math
can't stump me 😉
well we do PEMDAS from left to right. So it would be 1/6
lol daaaarn
looool
so like 01/02/0003 ? Like 3 years AD ? 😮
lol well also! it depends on who you ask!
you gotta be supar smart to get that
i think
let me guess what grade you are
and you guess what grade im in
my turn first
ok
so
lol okay
6th grade
even colder
Lmao
ok then you are 10th grader
getting warmer, but still pretty cold
13th grade
lol is that a freshman in college?
that is colleg thought right
if so then you're getting warmer
ok 15th grade
well we don't really have "grades" in college
same thingg
PFFFT
well I won't disclose that, but I"m a senior in college
I graduate this semester
and I'm 31
31 years old
ohh
but yes 16th grade techincally
you are old
awww thanks
warm
9th
less warm
6th
gotem
NICE
are you in the US or elsewhere?
6th grade, how old is that supposed to be?
I think I was 10 when I was in 6th grade
Lol.
lol my birthday was on the 2nd
yep fair enough
thansk
good job on the work!
😄
.close out
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Can I have an explanation on why I have to rewrite this x^2 + 2x-x-2?
It’s so u can clearly see how the terms are about to be grouped
the x^2 + 2x becomes x(x+2)
And the -x-2 becomes -1(x+2)
Because it was grouped in that manner, we can combine the two of them to make
(x-1)(x+2)
See what happened?
Closed by @orchid chasm
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"In general, for a real-valued system of linear equations we obtain either
no, exactly one, or infinitely many solutions. Linear regression (Chapter 9)
solves a version of Example 2.1 when we cannot solve the system of linear
equations."
Does cannot solve mean a system with no solution?
@smoky dagger Has your question been resolved?
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hello, how can I get the area of this polygon?
I think
k lemme see
Yeah
here have the formula
yes I know the formula but I dont know how to solve it
ok ok
yeah
then you find the rest
wait
A = N x S x A over 2
thats more complex
?
first do the hexagon
ok ok
xd
wait chief
i mean wait ill try to solve ti
got it
A = N x S x A over 2 A= 8 x 5 x 12.08 and then im stucl
stuck
You got it?
😄
Wait
ye

