help-0

[short veldt]

down

[last ether]

Yeah so if it's looking down, it's vertex is the maximum

[short veldt]

ty

[last ether]

This is basically calculus, like why it's -b/2a

Don't worry about that yet

[short veldt]

yea why is it -b/2a

[last ether]

Alright well calculus moment

[hallow vessel]

u can find without calculus

how would u solve the roots of a quadratic

[last ether]

Ig you can complete the square

Calculus is easier to show

[hallow vessel]

yea ahhaha

but without calc still doable

[short veldt]

just to double check, is it (6, 98)

[last ether]

For quadratic $f(x) = ax^2 + bx + c$, the maximum is when $f'(x) = 0$.

$$f'(x) = 2ax + b = 0$$
$$x = \frac{-b}{2a}$$

[ocean seal]

Umbraleviathan

[hallow vessel]

x = 6

yea

[last ether]

,graph -2x^2 + 24x + 26

[hallow vessel]

what yr lvl r u in?

[last ether]

Dumbass bot

,plot -2x^2 + 24x + 26

[short veldt]

grade?

[hallow vessel]

yes

[last ether]

,w graph -2x^2 + 24x + 26

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Umbraleviathan#3607

[last ether]

Yeah seems about right

[short veldt]

gr8 but I have a lot of empty holes in my knowledge :l

[last ether]

,w Calc max(-2x^2 + 24x + 26)

[short veldt]

ty

[last ether]

(6, 98)

[hallow vessel]

no bro calc comes way later

[short veldt]

there is no minima right

[hallow vessel]

well, in 4 years earliest

[last ether]

No minima for an infinite domain

[hallow vessel]

do no worry

[short veldt]

yea I'm trying to do advanced functions rn

[hallow vessel]

calc is not advanced functions ahaha

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Umbraleviathan#3607

[short veldt]

this was one of the questions and I'm not sure if I should graph or not

[hallow vessel]

i think its important to understand

[last ether]

It plots it too lol this is funky

[hallow vessel]

that with a quadratic, it will always go to infinity

on either one side or both

[short veldt]

alright, makes sense

[hallow vessel]

wait

i think only 1 side

wait it can be both

im dumb

[last ether]

Wdym both

[short veldt]

negative infinity on the other side?

[last ether]

The left and right side?

[hallow vessel]

like, both are going opposite ways

[last ether]

For a quadratic?

[hallow vessel]

ye

[last ether]

It's either concave down or concave up

[short veldt]

is there a general way to find min max values though

[last ether]

For a quadratic, the thing I showed you

[hallow vessel]

can u not have a stationary point of inflection

[last ether]

For other stuff

Well

[hallow vessel]

u learn it later

if u have numbers u can factorise and find the roots

[last ether]

Quadratics don't have a point of inflection

[hallow vessel]

then the max or min will be in between

[hallow vessel]

oh wait brah i forgot LMAO

[last ether]

Gamer moment

[short veldt]

inflection?

[last ether]

[hallow vessel]

holy canoli im stupid

[last ether]

Don't worry

Unless you really wanna know

[hallow vessel]

dont worry not important

[short veldt]

yea sure

[last ether]

Walk into an algebra class and be like "yo teacher I heard about this fuckin thing called an inflection point tell me about it"

[last ether]

A point where a graph changes concavity

[hallow vessel]

its basically does the function make a U shape, or upside down U shape

at different parts

[last ether]

Basically changes from opening up/down to opening down/up

[hallow vessel]

@last ether what level of maths r u upto?

[last ether]

Uh I'm doing Calc 3 rn

[short veldt]

math class for me is still talking about equality signs

[last ether]

So like vector calculus and Multivariable stuff

[short veldt]

so increasing and decreasing intervals?

[last ether]

Lmao

[last ether]

No

Like if I were to draw it out

Like for example

Look at

Uh

,w graph x^3 - x

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Umbraleviathan#3607

[hallow vessel]

is that first year uni?

[last ether]

The red is concave down (opening down), the blue is concave up (opening up)

[last ether]

I'm in high school rn

Probably is a uni class considering it's a double enrollment

[hallow vessel]

oh nice

[last ether]

And basically at x = 0, the function goes from opening down to opening up

[short veldt]

so inflection point is the point at which it changes?

[short veldt]

how does that work lol

[last ether]

I signed and paid a fucking 300-dollar contract that's how

[hallow vessel]

so ur doing multivariate calc, vector functions, odes?

[last ether]

Odes, probably not

I'm not sure if we go into that

Uh

For fun there's 4D shit for no reason

[short veldt]

also is there a way to draw the quadratic

without graphing tools

[last ether]

Uh

Plot points

Lol

[hallow vessel]

4d doesnt even make sense

im doing the calc 3 equiv rn

i think

[short veldt]

oh

[last ether]

But like plotting points is lame and stupid and dumb

[short veldt]

yep

[hallow vessel]

u get pretty good with like 3 points normally

[short veldt]

the interval(s) where the graph of y increases is increasing intervals right

[hallow vessel]

the roots and like the vertex

[last ether]

Yes

[short veldt]

ty

[last ether]

When y increases with x, it's increasing

When y decreases as x increases, it's decreasing

[short veldt]

ok

also what grade is this supposed to be

[last ether]

Usually 10th grade stuff

Sometimes 11

[short veldt]

aight thanks

.close

[lone heart]

Channel closed

Closed by @short veldt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cerulean musk]

how would I find when the second derivative = 0

[lone heart]

@cerulean musk Has your question been resolved?

[carmine reef]

😨

factor a y³ out of the numerator

factor out a 1/(1-3xy) as well

[lone heart]

@cerulean musk Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lilac nest]

.close

[lone heart]

Channel closed

Closed by @lilac nest

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[swift sky]

Can anyone help me find a bijection between Z+ x R= R, I have gotten many tips and hints but I just can't wrap my head around it. I really need a step by step help.

[lone heart]

@swift sky Has your question been resolved?

[lone heart]

@swift sky Has your question been resolved?

[lone heart]

@swift sky Has your question been resolved?

[vale wigeon]

.close

[lone heart]

Channel closed

Closed by @vale wigeon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[oak flame]

pretty confused on question 6

[tacit arch]

don't upload files, just screenshot and upload images

[oak flame]

ok lemme do that

[tacit arch]

,rccw

[tacit arch]

which part

[oak flame]

a b and c

drew the graph but other than that i dont understand the problems

[tacit arch]

do you know when an inverse function exists?

[oak flame]

yeah its like a reflection over y=x from the original function

[tacit arch]

try drawing an $f(x)$ such that the reflection doesn't satisfy the vertical line test

[ocean seal]

riemann

[oak flame]

something like that?

[lone heart]

@oak flame Has your question been resolved?

[oak flame]

is that for question a?

[tacit arch]

right.

[oak flame]

still a bit confused on how that makes a false

[tacit arch]

do you know what the vertical line test is used for

[oak flame]

oh it tests if it is a function

i see

its like 1 am where i am my brain isnt functioning lol

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tacit arch]

[tacit arch]

and read this @elder lava

[lone heart]

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rustic mortar]

What's wrong here?

[tacit arch]

Look in #old-network for chem or physics server

[lone heart]

@rustic mortar Has your question been resolved?

[rustic mortar]

How to join?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[desert zephyr]

Does the notation N_n with n \in \N mean anything?

[desert zephyr]

I have this sum for my homework and it is from k=0

to N_n

But no clue what that is

$N_n$ with $n \in \mathbb{N}$

If that helps

[ocean seal]

Yeetus

[ornate condor]

um

i think N should have been defined elsewhere as well?

[desert zephyr]

Nope not in the question

[ornate condor]

whats the Q

[desert zephyr]

It has to do with differential equations if that helps

This is given

And I am suppose to give an explicit expression for N_n

[mortal trellis]

usually this means something along the lines "for all n there exists some N_n depending on n so that this is true"

[desert zephyr]

Ahh I see

What useless then 😂

Thanks!

.close

[lone heart]

Channel closed

Closed by @desert zephyr

Use .reopen if this was a mistake.

[mortal trellis]

it would help to give us the full question

maybe it means something else

[desert zephyr]

.reopen

[lone heart]

✅

[desert zephyr]

Sure thing

It is homework though so I am not looking for answers. Just trying to understand the question

Given the ODE $y'=2ty^2$ with $y(0)=1$ the nth picard iteration $y_n(t)$ is given by the sum above where $c_{k,n} \geq 0$ is dependent on the indexes k and n. Give an explicit expression for $N_n$

[ocean seal]

Yeetus

[desert zephyr]

There ya go

[mortal trellis]

have you done a few steps of the picard iteration?

you will get a sum containing a certain number of terms

and that number will depend on n (which is hopefully not a surprise)

and they want you to figure out the number of terms given n

[desert zephyr]

Well the question before this was to calculate $y_1(t)$ and $y_2(t)$. I got $t^2$ and $1+\frac{1}{2}t^4$

[ocean seal]

Yeetus

[desert zephyr]

Not sure if thats correct though

[mortal trellis]

well doesn't look obviously wrong at least

fits the pattern of the sigma notation

[desert zephyr]

c_{n,k} can be zero though so sometimes the terms are 0

[mortal trellis]

oh yeah sorry. not number of terms, should be degree of highest term

or rather half of that

[desert zephyr]

I kinda got it I suppose. The degree of the highest term is at most 2k is it not?

[mortal trellis]

the degree of the highest term is 2N_n

k runs from 0 to N_n

[desert zephyr]

Oh yes sorry hahaha

Obviously N_n indeed

[rose olive]

Yeet!

[desert zephyr]

Could you not? I am trying to understand some maths here lol

[lone heart]

@desert zephyr Has your question been resolved?

Channel closed

Closed by @desert zephyr

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[languid bolt]

random question, is pre calc necessary for calc?

[languid bolt]

i dont think i've seen matrices used in calculus

[vale wigeon]

"precalc" in america can mean like a dozen different things

[languid bolt]

ok let me just rephrase the question

are matrices, combinatorics and probability, series, limits and continuity, conic sections, and vectors needed in calculus?

limits is probably needed

[mortal trellis]

series probably yes. the rest probably no. you'll run into matrices and vectors again in linear algebra and multivariable calculus

[lone heart]

@languid bolt Has your question been resolved?

[languid bolt]

ok

[lone heart]

Channel closed

Closed by @languid bolt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[distant cove]

Hey guys

[distant cove]

i want to ask a question about bounds of integral

where

is there any theorem that states that -
b must be greater then a

[vale wigeon]

no

in fact it is often convenient to allow b to be less than a, or even equal

[distant cove]

so in that integral

what are the solutions for a?

[vale wigeon]

,w int(x+3)/sqrt(x^2+6x) dx

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Ann#0413

[distant cove]

i got
-3+3sqrt(5)

-3-3sqrt(5)

but in my quiz, i canceled out -3-3sqrt5

[alpine sable]

Uhh solve the integral and put the limits Ig

[vale wigeon]

$\sqrt{a(a+6)} - \sqrt{2 \cdot 8} = 2$, i suppose. whichever numbers solve this equation.

[ocean seal]

Ann

[distant cove]

but -3-3sqrt5
doesn't give 2

when integrating with it

[vale wigeon]

,w sqrt(a(a+6)) - 4 = 2

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Ann#0413

[vale wigeon]

,w int[2, -3-3sqrt(5)] (x+3)/sqrt(x^2+6x) dx

[distant cove]

it's a correct answer for the rational equation,
but not for the integral

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Ann#0413

[vale wigeon]

ah well there you have it. the function under the integral is undefined on [-6, 0].

that is why integrating from -3-3sqrt(5) to 2, or the other way around, is nonsensical.

[distant cove]

in my test i cancled out the minus

-3-3sqrt(5)

is it ok?

[vale wigeon]

correct decision for the wrong reason

[distant cove]

so i should've left it there?

[vale wigeon]

.........

[distant cove]

because it fits the rational equation?

[vale wigeon]

you made the correct decision, but for the wrong reason.

[distant cove]

irrational

[vale wigeon]

you made the correct decision (leaving out a=-3-3sqrt(5) was correct) but for the wrong reason (it being less than 2 was not by itself illegal)

[distant cove]

wait i'll show you the original question

Its the second one

Translated:

Find a that satisfies

[tall topaz]

Think about the domain of your function

[vale wigeon]

the image contained no new information

you conveyed the question earlier just fine

and i already told you

discarding the solution a=-3-3sqrt(5) was correct, but the reason for doing that is not because -3 - 3sqrt(5) < 2.

[distant cove]

but i know that
the upper bound must be greater than the lower bound.

and
-3 - 3sqrt(5) < 2
so i have to cancel it out

[vale wigeon]

..........

did you even read what i just said

[distant cove]

yes i did

[vale wigeon]

and yet you spit in my face

i just told you, again, that -3 - 3sqrt(5) being less than 2 is NOT illegal by itself.

for example it would be perfectly okay to consider $a = 1.9$ (even though this $a$ doesn't solve our equation)

[ocean seal]

Ann

[distant cove]

so -
"the upper bound must be greater than the lower bound" - this sentence is incorrect.
right?

[tall topaz]

Yeah that’s not true

[distant cove]

alright that's what im asking

can you show me any proof please?
i don't know the name of it

maybe you know

[tall topaz]

I don’t know if any theorem like that

But do you understand why you discard -3-3sqrt5?

[distant cove]

yes
because the domain of f(x)

[tall topaz]

Okay that’s good then.

[distant cove]

@tall topaz

it does in the domain (?)

[tall topaz]

But it’s not defined between -6 and 0

You can’t find the area in that region

So integral from -3-5sqrt3 to 2 doesn’t make sense

[distant cove]

that's what you mean

[tall topaz]

I guess

[distant cove]

alright

[vale wigeon]

.

[vale wigeon]

.

but when i say it, it goes ignored.

[distant cove]

it's the attitude 😉

[vale wigeon]

what attitude?

[distant cove]

thank you both for helping me.
i appreciate that alot.

@vale wigeon @tall topaz

.close

[lone heart]

Channel closed

Closed by @distant cove

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fathom field]

I dont understand what this is asking for

how can a topology contain another?

[vale wigeon]

topologies are collections of sets

[fathom field]

so i need to give two topologies on the same set that have at least one element the other one doesnt have

[vale wigeon]

indeed

[fathom field]

could i just give two sierpinski topologies

[vale wigeon]

or in the language of topology, you need to give two topologies on the same set s.t. there exists a set that's open in one and not the other, and vice versa.

that might work.

[fathom field]

{O}{a}{ab} and {O}{b}{ab}

for the set {a,b}

[lone heart]

@fathom field Has your question been resolved?

Channel closed

Closed by @fathom field

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[proven cloud]

I’m struggling with 20.6 does anyone know how to do it

[gray isle]

,rotate

[autumn pasture]

have you found the inverse?

[proven cloud]

Wait you have to find the inverse

What does the -1 do next to the f

[gray isle]

f^-1 denotes the inverse function of f

(something the book should have)

[proven cloud]

So I find the inverse of x-4

[autumn pasture]

yes

[proven cloud]

It’s x+4 right

and then I just change x to 2

[autumn pasture]

yea seems right

[autumn pasture]

yes

[proven cloud]

ok thx guys

[autumn pasture]

no prob!

[proven cloud]

.close

[lone heart]

Channel closed

Closed by @proven cloud

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rose olive]

In order for an object to remain above ground without falling due to gravity, it has to have a force vector with same magnitude and opposite direction as force of gravity pulling the object down

[rose olive]

So force of gravity, and force pulling the object up, both sum up to zero net force

Is this correct?

And in order for the object to move up, it has to have a force vector greater than force of gravity

==========

Any work problem i come across,
Just does Work= mgh

mg= gives us force equal to force of gravity on our object

If we are pushing our object up with same force as gravity is pulling us down then how is it even moving?

[lone heart]

@rose olive Has your question been resolved?

[rose olive]

HEY YOU! HELP ME! I SEE YOU!

[silver marsh]

The force vector’s upward component must have a value greater than gravity yes

[rose olive]

Then why do all the work problems just only take in value for mass * gravity

[silver marsh]

It can still have velocity, it’ll just have zero acceleration. But if it starts with zero velocity, it won’t move true.
What’s your question?

[alpine sable]

Whats 2+2

[silver marsh]

Do not troll on help channels.

[silver marsh]

This is the force of gravity

[rose olive]

Look at 1st question

[rose olive]

Ohh yea i know that

This question's answer only takes into account the work done vertically

And force the man was applying as mass*gravity

[silver marsh]

Well because he’s not floating

[rose olive]

If he is not floating, and the normal force cancels the force of gravity

Then

[silver marsh]

Well the issue is you have to assume constant force (for simplicity)

[rose olive]

Why is it mgh, why it isn't just F of man * vertical distance

[silver marsh]

And if you have to do this, then you have to assume this force is equal to gravity

Which is a better approximation to real life than assuming it’s greater than gravity

[rose olive]

But doesn't the normal force cancel the gravity?

I calculated the force of man and it came out to be 19.6 newtons

19.6N * vertical dist covered = work done by man?

[silver marsh]

Yeah

[rose olive]

Is the statement i made that "normal force cancels gravity" correct?

[silver marsh]

No

[rose olive]

Explain

[silver marsh]

Ignore that sorry

[rose olive]

Yea thats didn't make sense anyways

[silver marsh]

Yes you’re right, the force he’s exerting is the normal force, so yes

Well like it’s equal to the normal force

He’s exerting force on the stair, the stair is then exerting force on him (which is the normal force) so you’re right, sorry

[rose olive]

Wait, so normal force is there so the man doesn't go into the ground which is equal to gravity, plus more force the man exerts go move upwards but we just assume that increased force isn't really there

[rose olive]

Does this sound right?

[silver marsh]

Well the only force upward is the normal force, but yes you’re it’s equal to gravity because you’re assuming his velocity is constant

[rose olive]

Would velocity being constant or not matter if he was on a horizontal ground

[silver marsh]

Wdym

[rose olive]

I don't understand the constant velocity part

[silver marsh]

If he’s not going up, then his vertical velocity is 0 (and therefore constant)

[rose olive]

Ohh nvm

[toxic ingot]

Hey

[silver marsh]

Oh you just assume constant velocity because it didn’t say anything about him accelerating.

[rose olive]

Right, now if velocity was not constant, would it effect the normal force, and in what way

[silver marsh]

Well if the acceleration were negative, the normal force would be less than mg, and if it were positive, the normal force would be greater than mg

[rose olive]

When you say normal force, do you mean the force that that keeps you from going into the ground, or do you mean (force to keep you from going into earth + the more force you exert to go up)

I mean when i say normal force is the force keeping you from going into the ground not the added force of you climbing

[silver marsh]

The normal force is just any force that the “ground” exerts on you

[rose olive]

So you mean the second one

[silver marsh]

Well that’s not really what the normal force is

[rose olive]

Yea, i am new to physics

Sorry

[silver marsh]

It’s all good

I haven’t done this stuff in a while anyway so I’m quite rusty sorry

[rose olive]

Atleast your helping

So let me summarize what i understood so far

When accelerating vertically up, the normal force is greator than gravity.
But when we have constant velocity, it means that there is no accelaration, and since f=ma, there is no upward force, thus normal force is equal to gravity.
@silver marsh

.close

[lone heart]

Channel closed

Closed by @rose olive

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[soft rapids]

hey

[soft rapids]

help.

The graph of a linear function g is a line that is parallel to the primary axis and the line passes through the point P = (0;5)

a. Determine the prescription g(x)

The graph of the linear function f intersects the second axis at point Q = (0;2). The graphs of f(x) and g(x) intersect at a point where x = 6

b. Calculate the coordinates of the point of intersection
c. Set up a function specification f(x)
d. Calculate the values of the independent variable at the locations where the vertical distance between the graphs of f and g is 3

[soft rapids]

Tylerr not here.

Zyb not here.

[violet canopy]

Bruh

30 seconds late

Cmon

Less

[soft rapids]

Not here.

The graph of a linear function g is a line that is parallel to the primary axis and the line passes through the point P = (0;5)

a. Determine the prescription g(x)

The graph of the linear function f intersects the second axis at point Q = (0;2). The graphs of f(x) and g(x) intersect at a point where x = 6

b. Calculate the coordinates of the point of intersection
c. Set up a function specification f(x)
d. Calculate the values of the independent variable at the locations where the vertical distance between the graphs of f and g is 3

@minor needle

[autumn pasture]

what is a primary axis?

[soft rapids]

dm

soooo

''It is parallel to the first axis''

[autumn pasture]

what is first axis?

[soft rapids]

You dont know what the ''first axis' is?

[autumn pasture]

are you talking about x axis?

because I’ve never heard of first axis haha

[soft rapids]

We dont know what about x or y axis.

But

[soft rapids]

It may well be

[autumn pasture]

if we take it x-axis

that means g(x) has gradient 0

[soft rapids]

yea

[autumn pasture]

so it’s just y=5

[soft rapids]

yes

So g(x) = 5

[autumn pasture]

oh so primary axis does mean x-axis?

[soft rapids]

I dont know

but it must give = 5 as I know

[autumn pasture]

okay

so for whatever x-coordinate on g(x)

it’ll be (x, 5)

y-coordinate is always 5

[soft rapids]

yes

yea

[autumn pasture]

so if f(x) intersects g(x) when x=6

f(x) would have what y-coordinate

[soft rapids]

yea

sooo

f(x) = 6x - 5

[autumn pasture]

no

6 isn’t the gradient

[soft rapids]

6/5

[autumn pasture]

how?

[soft rapids]

nvm

[autumn pasture]

how’d you get 6/5

[soft rapids]

ok so we know what x and y are?

[autumn pasture]

did you use the formula?

[soft rapids]

nvm aha

[autumn pasture]

at x=6

[autumn pasture]

what is y coordinate of g(x)

[soft rapids]

how

[soft rapids]

5?

[autumn pasture]

oh it’s in your question

[autumn pasture]

yea

no matter what x-coordinate, y coordinate of g(x) always 5

now for f(x)

[soft rapids]

We have to do task a)

[autumn pasture]

it intersects g(x) at the same point

[autumn pasture]

isn’t it done?

[soft rapids]

The graph of a linear function g is a line that is parallel to the primary axis and the line passes through the point P = (0;5)

a. Determine the prescription g(x)

[autumn pasture]

what’s prescription?

what do they mean

by prescription g(x)

is it equation?

the words they use

[soft rapids]

I think we have to make an equation f(x)

[autumn pasture]

are a little weird I think

[autumn pasture]

but they asked g(x)

wait did you translate this

[soft rapids]

yea

sorry haha

[autumn pasture]

oh okay I see

HAHA it makes more sense now

[soft rapids]

HAHA

[autumn pasture]

so I’m guessing

they want equation of g(x)

you already said it just now remember

[soft rapids]

Yes

[autumn pasture]

okay

so part 1 done

[soft rapids]

x y
P = (0;5)

[autumn pasture]

so what’s equation of g(x)?

[soft rapids]

ehh

The graph of a linear function g is a line that is parallel to the primary axis and the line passes through the point P = (0;5)

a. Determine the prescription g(x)

0 = x

[autumn pasture]

what’s your answer for a

[soft rapids]

dont know

[autumn pasture]

do you know the equation of a line

[soft rapids]

yes

[autumn pasture]

$y = mx+c$

[ocean seal]

duckiescute!

[autumn pasture]

is this familiar

[soft rapids]

what’s your answer for a

how

[autumn pasture]

i want to lead you to the answer

[soft rapids]

I know a little bit

but

[autumn pasture]

^

[soft rapids]

''little bit''

[autumn pasture]

okay

what do you know about it

what’s the little bit you know

[soft rapids]

I have only heard it

[autumn pasture]

do you know the m stands for

and the c

[soft rapids]

no

<@&286206848099549185>

The graph of a linear function g is a line that is parallel to the primary axis and the line passes through the point P = (0;5)

a. Determine the prescription g(x)

(0,5)
x y.

y2 - y1 = 0 - 5

P = 0 - 5 = 5

@autumn pasture

[autumn pasture]

hi sorry

was helping someone

[autumn pasture]

what is this?

[autumn pasture]

okay

[soft rapids]

Thie line of the task

[autumn pasture]

do you know what

gradient means

[soft rapids]

you se what i mean?

see

[autumn pasture]

no

what did you graph?

[soft rapids]

(0,5)
x y.
y2 - y1 = 0 - 5
P = 0 - 5 = 5

[autumn pasture]

you don’t need to use formula

because they say it’s parallel to x-axis

[soft rapids]

It is the line of (0.5)

[soft rapids]

YES!

[autumn pasture]

do you know what it means

if it’s parallel

to the x axis

[soft rapids]

no

[autumn pasture]

what does it mean for gradient@

oh okay

do you know what gradient means

[soft rapids]

No

[autumn pasture]

or slope

[soft rapids]

nope

o.o

[autumn pasture]

uhhh

wait I’m confused why your teacher gave you this as homework

wait did your teacher go through the y=mx + c

or y-y1 = m(x-x1)

[soft rapids]

I dont know...

but g(x)

[autumn pasture]

hmm

I’ll send you a video

https://youtu.be/LTb2-LE7StE

[soft rapids]

how we find this

[autumn pasture]

^

watch this video

it’ll help to build a foundation I think

[soft rapids]

Y = 0x + 5?

[autumn pasture]

yes

[soft rapids]

p = (0,5)

soo

[autumn pasture]

^

[modern topaz]

https://tenor.com/view/steinsgate-thumbs-up-nice-sweet-cool-gif-10332382

[soft rapids]

Y = 5

[autumn pasture]

https://youtu.be/Ft2_QtXAnh8

this one too

[autumn pasture]

yea

[soft rapids]

Y = 5
Y = 0x + 5?

[modern topaz]

But he’s a chemistry teacher😅

[autumn pasture]

but that’s a math video

[soft rapids]

Go pleasse.

[modern topaz]

[autumn pasture]

and yea he has chemistry stuff too

@soft rapids

I think

you should watch the video

I sent on top

it’ll help you understand better

[soft rapids]

but

hmm

[autumn pasture]

then you can follow easier

[soft rapids]

b) is essay

[autumn pasture]

essay?

[soft rapids]

i meant easily

[autumn pasture]

oh okay

yea it is

but for beginners not really

[soft rapids]

wiat

wait

Y = 5

[autumn pasture]

yea why

[soft rapids]

Y = 0,5x + 2

5 + 3 = 8

[autumn pasture]

no

there’s no x

because they said parallel to x axis

m=0

https://youtu.be/LTb2-LE7StE

https://youtu.be/Ft2_QtXAnh8

it can really help :)

[soft rapids]

We do not need to do more out of task a

[autumn pasture]

yes we do

i think foundation is not really there

because you don’t know meaning of gradient/slope

[soft rapids]

my friend say this i correct

[autumn pasture]

so it’ll be hard to do more questions

[autumn pasture]

y=x+8??

[soft rapids]

huh?

The graph of the linear function f intersects the second axis at point Q = (0;2). The graphs of f(x) and g(x) intersect at a point where x = 6

b. Calculate the coordinates of the point of intersection

[autumn pasture]

what was your answer for a

[soft rapids]

WE already know about the linear function f that goes through the point (0,5) which is parallel to the x-axis. By calculating the function specification: x y P = (0;5) Y = 5

what I have written

[autumn pasture]

what language do you speak?

maybe I can try to translate something

[soft rapids]

danish

[autumn pasture]

hældning

what does that stay

say

[soft rapids]

what you mean

[autumn pasture]

does that say slope

[soft rapids]

ohhh

I know slop

slope

[autumn pasture]

yes

okay

phew

[soft rapids]

slope = hældning

[autumn pasture]

yes yes

[soft rapids]

aaaaa

aha

[autumn pasture]

so if parallel to x-axis

it means hældning=0

[alpine sable]

yes

[autumn pasture]

that’s why g(x) = 5

[soft rapids]

yes

Y = 5

[autumn pasture]

hi are you danish?

[autumn pasture]

yes

[soft rapids]

soo task b)

[alpine sable]

no haha

[autumn pasture]

oh hahaha

this is g(x)

[soft rapids]

es

yes

[autumn pasture]

okay

now f(x) cuts g(x) at one point right

x=6

at that point

f(x) and g(x) will have same coordinate

[soft rapids]

task b right?

[autumn pasture]

yes

[soft rapids]

okay

soo

X = 6

[autumn pasture]

yes

[soft rapids]

Y = 5

[autumn pasture]

yes

that’s part b

(6, 5)

[soft rapids]

The point of intersection = (6,5)

yea

[autumn pasture]

what’s part c question

[soft rapids]

hmm

2 sec

[autumn pasture]

okay

take your time

[soft rapids]

Soo

Task c

Set up a function specification f(x)

[autumn pasture]

does that mean

equation

f(x)?

[soft rapids]

Ye

f(x)

[autumn pasture]

The graph of a linear function g is a line that is parallel to the primary axis and the line passes through the point P = (0;5)

a. Determine the prescription g(x)

The graph of the linear function f intersects the second axis at point Q = (0;2). The graphs of f(x) and g(x) intersect at a point where x = 6

b. Calculate the coordinates of the point of intersection
c. Set up a function specification f(x)
d. Calculate the values of the independent variable at the locations where the vertical distance between the graphs of f and g is 3

okay

[soft rapids]

We must set up the function

[autumn pasture]

they say f(x) go through (0,2)

what other point f(x) go through

[soft rapids]

Q = (0,2)

[autumn pasture]

got another point right

f(x)

remember part b

the point

of intersection

[soft rapids]

(6,5)

Part b

Soo

[autumn pasture]

yes

so f(x)

(6,5)

(0,2)

[soft rapids]

f(x) = 6x - 5

?

Example

[autumn pasture]

uhh I never calculate

oh example

let me see

no that’s not f(x)

[soft rapids]

Ohh

[autumn pasture]

use formula

hældning formula

[soft rapids]

ax + b

Right?

Oh nooo

Noni

Y2 - y1

[autumn pasture]

yes equation look like f(x)= ax+ b

[soft rapids]

X2 - x1

[autumn pasture]

yes

that is formula

formel

[soft rapids]

Soo

5 - 2 / 6 - 0

[autumn pasture]

yes

[soft rapids]

= 4,666666667

[autumn pasture]

no

[soft rapids]

hm

[autumn pasture]

don’t type like that

use bracket

(5-2)

(6-0)

$(5-2) \div{(6-0)}$

[soft rapids]

18

[ocean seal]

duckiescute!

[autumn pasture]

no

[soft rapids]

0,5

[autumn pasture]

yes

[soft rapids]

UHH

[autumn pasture]

that is a

[soft rapids]

A???? WHAT

we don't do task c

Now part d?

[autumn pasture]

Nono

not part a

[soft rapids]

Okay

[autumn pasture]

you say f(x) = ax + b

0.5 is a

[soft rapids]

Soo what is 0,5??

Ohhh

[autumn pasture]

so now $f(x) = 0.5x + b$

[ocean seal]

duckiescute!

[autumn pasture]

how to find b?

[soft rapids]

ehh

[autumn pasture]

use one

(5,6)

or

(0,2)

choose 1

anything is okay

[soft rapids]

I use (5,6)

So

What now

[autumn pasture]

okay

put inside f(x)

to find b

wait it’s (6,5

not (5,6)

[soft rapids]

Opsss

I meant 5,6

[autumn pasture]

6,5

sorry I type wrongly just now

it’s (6,5)

[soft rapids]

6,5

[autumn pasture]

yes

[soft rapids]

Yeywd

So what now

[autumn pasture]

put inside f(x)

[soft rapids]

We take 6,5

[autumn pasture]

what you get for b?

[autumn pasture]

^

[soft rapids]

F(6,5)?

[autumn pasture]

f(6)

[soft rapids]

Ohh

[autumn pasture]

so put (6,5) inside f(x)

[soft rapids]

f(6) = 0,5 x + b

[autumn pasture]

no

$5 = 0.5(6) + b$

[ocean seal]

duckiescute!

[autumn pasture]

remember

(6,5)

y=5

x=6

[soft rapids]

Ohh

3?

[autumn pasture]

what 3?

[autumn pasture]

$b+3=5$

[ocean seal]

duckiescute!

[autumn pasture]

what b?

[soft rapids]

5?

[autumn pasture]

no

solve

[soft rapids]

B is b?

[autumn pasture]

if b+3 = 5

what is b

[soft rapids]

2

?

[autumn pasture]

yes

[soft rapids]

OHHJJ

[autumn pasture]

so what is f(x)

[soft rapids]

Q (0,2)

You take 2

ohh

Omg

haha

[autumn pasture]

HAHA no

the 2 not from Q

[soft rapids]

Oh

[autumn pasture]

oh wait

[soft rapids]

Soo

[autumn pasture]

yaya

sorry

read wrongly

[soft rapids]

ahahha

[autumn pasture]

it’s from Q

so what is f(x)

[soft rapids]

f(6) = 0,5x + 2

[autumn pasture]

just f(x)

$f(x) = 0.5x +2$

[ocean seal]

duckiescute!

[soft rapids]

Ohh

f(x) = 0.5x + 2?

[autumn pasture]

yes

nice

yay

godt arbejde

[soft rapids]

Tak = thanks you

Part d

Thats right?

[autumn pasture]

yes

[soft rapids]

Okay

[autumn pasture]

what is part d question

[soft rapids]

Part d and we done

[autumn pasture]

okay

what is

part d question

[soft rapids]

d) Calculate the values of the independent variable at the locations where the vertical distance between the graphs of f and g is 3

But i you sure is f(x) = 0.5x + 2

(5-2) is 3?

You know about this

[autumn pasture]

it’s 2

you can try with (0,2) also

will give same answer

[autumn pasture]

uhhh I don’t get this

what is it asking for?

[soft rapids]

I send the danish version so you can transtelse this

''d) Beregn værdierne af den uafhængige variable de steder, hvor den lodrette afstand mellem graferne for f og g er 3 ''

[autumn pasture]

it says same thing

[soft rapids]

Ehh

[autumn pasture]

uhhh

it doesn’t quite make sense to me

[soft rapids]

We need to find the independent and the dependent variable

[soft rapids]

.

Now

We know y

5 + 3

and

[autumn pasture]

so they want the coordinate of f(x)

[soft rapids]

5 - 2

yea

[autumn pasture]

where vertical distance is 3?

ohhh okay

so yes

[autumn pasture]

this is correct

[soft rapids]

f(x) = 1/2x + 2

[autumn pasture]

yes

good

[soft rapids]

yea

[autumn pasture]

so you know (x, 8)

how to find x

put 8 inside f(x)

løse for x

[soft rapids]

yes

Yesyes

[autumn pasture]

yes

so what is x

[soft rapids]

ehh

8 = 1/2x+2

16 = x + 4

-x = 4 - 16

-x = -12

x= 12

soo x is 12?

@autumn pasture

[autumn pasture]

yes

good job

:D

so coordinates

is

(12,8)

[soft rapids]

Is -12 or 12?

[autumn pasture]

12

[soft rapids]

Yes but we must find independent variable

x = 0 and × = 12

Because

2 = 1/2 x + 2

Same with 2

[autumn pasture]

oh I thought you said coordinates

[soft rapids]

Done

[autumn pasture]

5-2=2?

[soft rapids]

Yeah?

8 and 2

8 = 1/2 x + 2

[autumn pasture]

5-2 is not 2

[soft rapids]

2 = 1/2 x + 2

[soft rapids]

Oppss

5 - 3

= 2

[autumn pasture]

ohh okay haha

[soft rapids]

Im done

What do you think?

[autumn pasture]

yea okay

good job! You

wooo

[soft rapids]

Thanks for all the help you gave me🙏

[autumn pasture]

no prob!

bye bye 👋

[soft rapids]

Bye

[lone heart]

@soft rapids Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[short void]

How do I approach this question?

[short void]

Do I just find the inverse with k? Then, how do I go about it..?

[plain flame]

if you prove that there exists k such that the colums of A are linearly independant youre good

[alpine sable]

do you know determinants?

[lone heart]

@short void Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fickle musk]

im lacking rn so how is this alpha please helmp

[sand ermine]

ooh

the angle b/vv mgcos alpha and ma is (90 - alpha)

[fickle musk]

ohhh

[sand ermine]

and the angle b/vv macos alpha and ma is (90 - (90 - alpha))

yea

[fickle musk]

.close

[sand ermine]

yea

[fickle musk]

.close