help-0

[alpine siren]

+12

[tribal oxide]

no -12 only

[alpine siren]

Sorry -, yes

[runic trench]

Factor left side of eqn

[alpine sable]

i dont get it

[runic trench]

Factor -1 out of the whole thing

[alpine sable]

-12 and 1

ok i get

$-(x^{2}+11x-12)$

[ocean seal]

BabaEagle

[alpine sable]

?

[runic trench]

And =0 behind

Then factor from here

[alpine sable]

idk how to factor still

[runic trench]

Use ac method

[alpine sable]

a times c?

[runic trench]

Remember what form this is

ax^2+bx+c

[alpine sable]

idk what =12 and makes 11

[runic trench]

^ this

[alpine sable]

oh ok ty

ty for helping guys

.close

[lone heart]

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[alpine sable]

y’all I have a math assignment due tomorrow and I have no time tomorrow to do it and I’m so stressed. It’s markups/markdowns/percentages.

[alpine sable]

One question im struggling with is;

A medical insurance policy requires Ana to pu the first $100 of her hospital expense. The insurance company will pay 70% of the remaining expense. Ana is expecting a short surgical stay in the hospital for what she estimates the total bill to be about $4,300. How much, in $, of the total bill will Ana owe?

[runic trench]

Hello.

Find the outstanding payment left after her initial payment of 100

Since the qn stated " The insurance company will pay 70% of the remaining expense. " , how much percentage will ana have to pay ?

[fiery storm]

30% of 4.2k

[runic trench]

^basically this but 30% of 4.3k
and the addition of the initial 100$

Done

[fiery storm]

isnt it 30% of 4.2k then add 100

[wind yoke]

no

[alpine sable]

i will have to see if this helps in a bit as I am now incredibly sick on top of the 3 assignments I have to do before I can sleep

[wind yoke]

its 30 percent of 4.3k

oh wait

u have to subtract

the total bill by 100

So in total anna have to pay [100 + 30 percent of remaining

[lone heart]

@alpine sable Has your question been resolved?

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[karmic cedar]

Find the surface area of a sphere whose volume is 97440mm³.

[karmic cedar]

I ne3d help on this.

[chilly condor]

Do you know the formula for volume of a sphere?

[karmic cedar]

Yeah

[chilly condor]

So you should be able to plug in your known volume to solve for the radius

Then once you have the radius, you should be able to solve for surface area

[karmic cedar]

Must I convert the mm to cm or I should leave it be? @chilly condor

Sorry for ping 😅

[chilly condor]

I'd think leaving it in mm would be more appropriate

[karmic cedar]

May I ask you one more question? @chilly condor

[chilly condor]

Sure thing

[karmic cedar]

Find the volume of a cone if it's height is 7m and the perimeter of its base is 11m.

[chilly condor]

The base of a cone would be a circle, right?

[karmic cedar]

It is a circle

[chilly condor]

It is 🙂 So it's a similar problem as the last one

If you know the formula for the perimeter (circumference) or a circle, you can put in your known value then solve for the radius

Then once you have the radius, you can use it to calculate the volume of the cone

[karmic cedar]

I see

I'll try it 🙂

Ohhh I get it now

Tysmmm

But I have 1 last question

This is the final question I promise 😅

The circumference of a solid circular cylinder is 24cm, and its length is 44cm. Find its volume.

Is this question similar to the previous questions I had asked? @chilly condor

Sorry for ping again 😅😅

[chilly condor]

Hehe all good. Yep 🙂 Same thing

[karmic cedar]

Tysmm

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[rapid vapor]

how do u solve root a + b * root a - b

[royal pagoda]

yo boys
I wanna ask
my discussions right now is circles and I did not really pay attention to class recently
and I wanna know when to use the formula
(x - h) ^2 + (y - k)^2 = r^2

[gray isle]

$a + b\sqrt{a} - b$?

[ocean seal]

ℝamonov

[gray isle]

wdym by "solve"

[royal pagoda]

this is the equation of a circle
and if you are wondering what subject this is it is pre calculus

[vale wigeon]

@royal pagoda you're gonna need to open your own channel sorry

[rapid vapor]

how did he get root 25 + 144

[royal pagoda]

alr

[rapid vapor]

it by the formula (a + b ) ^2

[royal pagoda]

oh damn mv I thought u can ask help on these channels

[rapid vapor]

choose a channel in the available section mate

[royal pagoda]

alr ty

[rapid vapor]

np

yo help me someone

pls explain how did root 5 + 12i x root 5 - 12i became root ( 5+ 12i ) ( root 5 - 12i)

<@&286206848099549185>

[lone heart]

@rapid vapor Has your question been resolved?

[chilly condor]

where?

oh nevermind, I see now

Looks like the same thing. They just got combined into 1 sqrt sign

[lone heart]

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[timid kettle]

Van someone solve this ?

I cant my brain is dead

[wanton nova]

,rotate

[lone heart]

@timid kettle Has your question been resolved?

[timid kettle]

Someone ?

[lone heart]

@timid kettle Has your question been resolved?

[lone heart]

@timid kettle Has your question been resolved?

[lone heart]

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[undone lantern]

Hi !

[languid bolt]

hi too

[undone lantern]

i need help for an exercise

i need to prove that

$S_n = \sum_{k=1}^{n} \dfrac{e^{i\sqrt{k}}}{\sqrt{k}}$

[keen plinth]

bot?

[languid bolt]

dont add a space after $

[keen plinth]

is \bigsum a thing

just do \sum

\sum_

[ocean seal]

じさつ しょうねん

[keen plinth]

there we go

[undone lantern]

Thanks !!

I need to show that S_n diverges

Using the fact that

Sn is not a Cauchy sequence

Using def of « not cauchy »

<@&286206848099549185>

Anyone ???

[lone heart]

@undone lantern Has your question been resolved?

[keen plinth]

https://math.stackexchange.com/questions/4035842/convergence-of-sum-frac-cos-sqrt-n-sqrt-n

[lone heart]

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[broken blaze]

I can't get the same result after solving the equation

[undone lantern]

My question has not been solved …

[trim wagon]

Open new help channel then

[keen plinth]

[broken blaze]

.close

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[dense sleet]

Point 𝑀 on side 𝐵𝐶 and point 𝑁 on side 𝐴𝐵 of triangle 𝐴𝐵𝐶 are chosen so that
holds <𝐵𝐴𝑀 = <𝑀𝐴𝐶 = <𝑁𝐶𝐵. Prove that

[dense sleet]

<@&286206848099549185>

[lone heart]

@dense sleet Has your question been resolved?

[lone heart]

@dense sleet Has your question been resolved?

[lone heart]

@dense sleet Has your question been resolved?

[lone heart]

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[iron inlet]

Have I done something wrong here?

Bc it says x-2 is a factor but when I substitute it for factorisation, it doesn't equal 0

[viral falcon]

Then you most likely have gotten a or b wrong, that would be my guess at least. Perhaps try solving it again? I’d also solve it, but can’t atm, unfortunately. But anyways, if x-2 is a factor without a remainder, f(2) must equal 0.

so if it doesn’t equal 0, you probably have done something incorrectly along the way

[iron inlet]

Yeah thanks. I'll try it again.

[viral falcon]

Alright, np!

Ah

I see what you got wrong

It was a tiny mistake…

a is meant to be +2, not -2…

so it was a tiny mistake at the very end, that’s sad…

@iron inlet

[iron inlet]

Ohhh thank you!!

[viral falcon]

at least you got everything else right

You’re welcome!

[iron inlet]

Yeah, the main thing is that I get the process.
Never done factor theorum before.

[viral falcon]

Oh, yeah, absolutely.

but nice job if you’ve never done it before

[iron inlet]

Thanks
Once I get maths I get it.
I've never forgotten the quadratic formula or sohcahtoa etc.

My brain just likes maths hah

[viral falcon]

Hah, excellent

[viral falcon]

Same

[iron inlet]

.close

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[alpine sable]

I'm confused

[gray isle]

which part?

[alpine sable]

like I just forgot how to do this cause summer passed

what does it mean by finding intercepts

[gray isle]

finding two points will be sufficient when graphing a straight line,
they want you to find and use the x and y intercepts

[alpine sable]

Okay so how do I do that

like for a)

[gray isle]

do you know what x and y intercepts are?

[alpine sable]

well yes

I'm just confused on how to find them idk

like what does the number 3 stand for

[gray isle]

3 is 3

3 stand for 3

[alpine sable]

I just don't understand how they got this

thats the answer key

I just don't get it

how do I solve it to get to that

[gray isle]

do you know what x and y intercepts are?
well yes
explain in your own words

[alpine sable]

ummm

like the point on the line

y interecept?

like the point on the line

IDK

[gray isle]

yes, that would be the y-intercept

[alpine sable]

exactly so how do I find it then cause thats the answer key

[alpine sable]

if its just this

x + y = 3

[gray isle]

do you know the equation of the y axis?

[alpine sable]

how on earth do I know x is 3 and y is 3 too

[alpine sable]

uh

isnt it y = mx+b

[gray isle]

no

[alpine sable]

sooo

[gray isle]

that's the slope intercept form of a non-vertical line

[alpine sable]

righttt

ok

so like how do i solve this

what r the steps

x + y = 3

[gray isle]

do you know the equation of the y axis?

[alpine sable]

um

no?

maybe i forgot?

not sure probably forgot

[gray isle]

try not to overthink

[alpine sable]

x = 0

HELP

[gray isle]

yes

[alpine sable]

wait so thats just a basic equation of the y axis

ok

[gray isle]

to find the y-intercept, find the intersection point of
x=0 nd x+y=3

[alpine sable]

ook then ok

but then

how do I do b)

5x -3y = 15

so

[gray isle]

same idea

[alpine sable]

x = 0

[gray isle]

and similarly, the equation of the x-axis is y=0, so use that for finding the x-intercept

[alpine sable]

can u like show me by texting me the step LOL

[gray isle]

also why did you jump ahead to b) before even finishing a)

[alpine sable]

5(0)-3(0) = 15 ???

[gray isle]

no

[alpine sable]

I THOUGHT WE WERE DONE HELP

[gray isle]

no

we were just getting started

[alpine sable]

oh.

[gray isle]

or at least you haven't shown me that you were able to find the x and y intercepts algebraically here

[alpine sable]

ok

[gray isle]

to find the y-intercept, find the intersection point of
x=0 nd x+y=3

[alpine sable]

ya so

0 + y = 3

y = 3

[gray isle]

yes

[alpine sable]

so then like how would i get x

[gray isle]

your y intercept will be 3, giving the point (0,3)

[alpine sable]

yes

so what abt x

i found that y is 3

[gray isle]

and similarly, the equation of the x-axis is y=0, so use that for finding the x-intercept

[alpine sable]

ok

oh

so same thing but change a letter

x + 0 = 3

x = 3

ok got it

so can we do b) now

5x — 3y = 15

do i do same thing

wait let me try this

5(0) - 3y = 15

yes??

[gray isle]

yes, so far that's ok

[alpine sable]

oh

[gray isle]

continue

[alpine sable]

0 - 3y = 15

-3y / 3 = 15/ 3

[gray isle]

no

[alpine sable]

-y = 5

UGH

WHYY

[gray isle]

0-3y isn't 3y

[alpine sable]

oh

right

its nnegative

-3y

[gray isle]

so y = ?

[alpine sable]

uhuhhhh

does the y have to be positive

[gray isle]

what you want is for your equation to explicitly tell you what y is equal to

[alpine sable]

yes sooo

[alpine sable]

this?

-y = 5?

[gray isle]

-y = 5
tells you what -y is, not y

[alpine sable]

yes

so now i solve for x??

[tough jasper]

🤣

[gray isle]

it's like you didn't read what I said

[alpine sable]

STOP

I LTERLALY DONT GET THIS.

[gray isle]

don't overthink

[alpine sable]

I HAD BREAKDOWNS YESTERDAY

[tough jasper]

No y doesnt have to be positive

[alpine sable]

I UNDERSTAND BETTER WITH EXAMPLES / VISUAL STEPS

[gray isle]

-y = 5
means
y = ?

[alpine sable]

i literally dont know

y = -5?

bye

[tough jasper]

Yes

[gray isle]

yes. y = -5

[alpine sable]

oh OH

I GET IT HELP

[gray isle]

don't overthink

[alpine sable]

omg

ok

[gray isle]

same idea for the x-intercept

[alpine sable]

5x — 3(0) = 15

5x - 0 = 15

5x = 15

5x/5 = 15/5

WUIHAJ

[gray isle]

oh, edited

[alpine sable]

x = 3

YEAHHHH

YAEYAYAYA

[gray isle]

very good

[alpine sable]

yay thank u

:)

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[alpine sable]

hello can someone help me

[near saffron]

can you put your question

[alpine sable]

okay so this

I solved it like this

3x3x3x3

= 81

• 1

[gray isle]

is there a better image

[alpine sable]

= 80

ohhh

okay ill crop

[near saffron]

Do you know the formula for the sum of a finite geometric series

[alpine sable]

this

yeah its this one

[near saffron]

What's your confusion

[alpine sable]

so I solved mine like this

3x3x3x3

= 81

-1

=80

[near saffron]

Do you think the sum is 80?

[alpine sable]

my problem is

nope

its 1 -3

its suppposed to be -2 right?

[near saffron]

1-3 is -2

[alpine sable]

but I did mine positive 2

and I still got 400

so 3x3x3x3

-1

I divided it by 2

[near saffron]

yes you're right

[alpine sable]

and then multiplied by 10

[near saffron]

(a-b)/(c-d) = (b-a)/(d-c)

[alpine sable]

ohhhh thanks

[near saffron]

If you multiply top and bottom by -1 you get that

It can be useful when manipulating an algebraic expression

[alpine sable]

Ohhhh thank you very much

.close

[lone heart]

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Use .reopen if this was a mistake.

[alpine sable]

.reopen

[lone heart]

✅

[alpine sable]

sorry for closing while u typing

.close

[lone heart]

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[alpine sable]

Rework problems 13 and 14 from section 2.4 of your textbook (page 81) about the bucket containing orange tennis balls and yellow tennis balls from which 5 balls are selected at random, but assume that the bucket contains 6 orange balls and 9 yellow balls.
(1) What is the probability that, of the 5 balls selected at random, at least two are orange and at least two are yellow?

[alpine sable]

.close

[lone heart]

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[burnt root]

hello, I need to verify if $\int_0^{\pi/2} \frac{f(\sin{x})}{f(\sin{x}) + f(\cos{x})}dx = \pi / 4$, and I am hinted that I should use the substitution $t = \pi /2 - x$, with which I got that the previous integral is equal to $-\int_0^{\pi/2} \frac{f(\cos{x})}{f(\sin{x}) + f(\cos{x})}dx$, but I'm not really sure what to do with that now

[ocean seal]

Spiwocoal

[slow hound]

add the two integrals and you get 1

[burnt root]

oh, right, I can see that

[slow hound]

oh man

[slow hound]

$\bigbreak 2$

tragic but you get the point

[burnt root]

yeah I get it :)

latex's hard lol

thank you <3

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[lone heart]

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[woven jackal]

is this correct?

[fathom mantle]

show work

[woven jackal]

wdym

don't get asked for working

[limpid elm]

your first one is wrong

[woven jackal]

oh its -1

is it correct now?

[limpid elm]

yes, but you should hopefully understand how to know if you are correct by doing the proper techniques

[woven jackal]

yeah, its just that its 6:40am and I havent slept

so I'm making sure

thanks you @limpid elm

.close

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[marble oxide]

oop

[fluid zealot]

Oops my bad sorry

[marble oxide]

lol its ok

The Social Security Administration increased the taxable wage base from $137,700 to $142,800. The 6.2% tax rate is unchanged. Joe Burns earned over $131,900 each of the past two years.

What is the percent increase in the base?

I got 1440 for this but i think its wrong

[lone heart]

Channel closed

Closed due to the original message being deleted

[marble oxide]

.reopen

. reopen

.reopen

[last ether]

You can't reopen it

Go to a diff vacant channel

[marble oxide]

kk ty

[lone heart]

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[proper lake]

How do I do this? I tried plugging in but didnt work.

[lone heart]

@proper lake Has your question been resolved?

[proper lake]

<@&286206848099549185>

[lone heart]

@proper lake Has your question been resolved?

[lone heart]

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[worthy solstice]

Yo did I find the derivative for this absolute value correctly?

[lone heart]

@worthy solstice Has your question been resolved?

[lone heart]

@worthy solstice Has your question been resolved?

[worthy solstice]

<@&286206848099549185> quick question above ^^

[small fog]

yeah

[worthy solstice]

.close

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[fiery storm]

i told you man

[fiery storm]

.close

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[crude holly]

how to solve this?

[crude holly]

6*12 = 72
9^2-6^2=45
root(45) * 12

(whats the symbol for root on a keyboard like power -> ^, would i just do ^1/2 ?)

[grave island]

put it in latex

[crude holly]

wym? (i think i may have sold thios just a sec)

[grave island]

$9^2-6^2=45$

[ocean seal]

Mothy

[grave island]

dollar signs

[crude holly]

how would u do sqr root

[grave island]

$\sqrt{2}$

[ocean seal]

Mothy

[grave island]

\sqrt and curly braces

[crude holly]

oh ok ty

[crude holly]

yep im still a bit unsure

[grave island]

$1^\frac{1}{2}$

[ocean seal]

Mothy

[grave island]

fractions is \frac {}{}

[crude holly]

oh ok

[grave island]

yea idk how to as well

but u can find the height of QOC

[crude holly]

can i ping support or something

[grave island]

PDA is the issue

[crude holly]

where is qoc

[grave island]

wait 15 mins

[crude holly]

oh qdc

[grave island]

like triangle constructed from those points

[crude holly]

maybe pd is 6

o its a pyramid so pd is 9 no?

[grave island]

u cant assume that?

[crude holly]

r those red lines the same?

<@&286206848099549185> im not sure how to answer to this question, i keep getting the answer wrong

would the red lines be equal to each other?

[grave island]

no u cannot assume that

it does not say that anywhere in the question

[crude holly]

its a pyramid

[grave island]

The height would be the same

but the height is not the same as the slant height

[crude holly]

which is the slant height, these??

[grave island]

slant height is the ones drawn here

[crude holly]

oh i see

hmm

[grave island]

in an equilateral pyramid that would be true

but we dont know that

[crude holly]

<@&286206848099549185>

how do u get this answer?

unsure how to do this question too, i found slanted side dqc, then got the rectangle length in to centre thingy to be 7 coz 14/2 then i used Pythagoras, slanted side ^ 2 - 49 then square root that result and got 15.9

[elder furnace]

can you see how to find the red heights?

consider the right triangles

[crude holly]

oh sorry i misunderstood which question u were doing, i thought u were doing q1 mb

[elder furnace]

yes - since it is a net of pyramyde

the first one - but I took the second pic

i think

[crude holly]

oh, but yh now q1 makes sense ty

can u find the slanted hight then u times that to AD and divide by 2 to find area of PDA?

[elder furnace]

yep

[crude holly]

ok ty

[crude holly]

anyone got any idea how to do this question to find the height of the pyramid

[elder furnace]

can you find the diagonal of ABCD?

[crude holly]

oh then u half it?

[elder furnace]

yep

[crude holly]

ah thats where i went wrong

ty

quick question

.close

[lone heart]

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[soft seal]

What’s 9 +10

[alpine sable]

Can anyone help me find the indeterminate form in the highlighted question? Any help is appreciated.

[last ether]

Go to a vacant channel for a sec, some guy is trolling in this one

.close

[lone heart]

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[prime sluice]

We are not qualified to answer advanced topics such as these, please consult your teacher/professor for guidance and leave us alone

[soft seal]

Ok

[lone heart]

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[clever tapir]

Wondering how to do question 5 on this sheet

[tough jasper]

Is there some extra info at the end not in the picture?

Oh wait nvm

Basically its symmetrical about the y axis

Due to not having a linear component

[lone heart]

@clever tapir Has your question been resolved?

[lone heart]

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[fast shell]

how to solve the last 2?

ping me when someone figures it out

[rustic coral]

You can claim your own channel (see #❓how-to-get-help, people claim the help channels for themselves, not for them to be used by others)

[rustic coral]

3. multiply numerator and denominator by the conjugate of the numberator in 2

4. set h=0 prolly

[fast shell]

wont 4) become 0/0?

wait let me try

i know its wrong

but it will become -2/0

[rustic coral]

ummm x shouldn't just disappear like that

only h=0

not x

[fast shell]

i know

try to plug in h=0

[fast shell]

it will become this

[rustic coral]

you should get $-\frac{2}{\sqrt{-2x+1}+\sqrt{-2x+1}}=-\frac{1}{\sqrt{-2x+1}}$, right?

lemme check that cause I don't trust my mental math lol

[fast shell]

lol tyt

[ocean seal]

enclave wangedrocht

[rustic coral]

should work

[fast shell]

oh it did work

how did you get that tho

[wary stream]

No it would not because you're plugging in h = 0 into the 3rd expression

Not whatever expression that gave you -2/0

[fast shell]

i did understand that part

[fast shell]

but i dont get how did he do the algebra here tbh

OH

nvm i got it

Thank you both so much

.

.close

[lone heart]

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[clever tapir]

H

[clever tapir]

I was wondering how I would do this

Question 5

[slender gull]

Do you know what x intercepts mean?

[clever tapir]

yes

[slender gull]

What?

[clever tapir]

when the line crosses the x axis

[slender gull]

Yes

[clever tapir]

the 6,0 is a guess cuz I was utterly clueless

[slender gull]

So you have a quadratic, hence you are given 2 intercepts.

[clever tapir]

ye

[slender gull]

Sub the value of those intercepts, one at a time.

You should get 2 equations and 2 variables (a and q)

[gray isle]

consider sum of roots

[lone heart]

@clever tapir Has your question been resolved?

[lone heart]

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[light bronze]

Hi

[light bronze]

So i'm trying to figure out weather this is a function or not and the domain and range

for weather it's a function i have a feeling that weather or not in crosses the x axis has something to do with it but im not sure

also i'm trying to figure out how to see if its a function based off the eqaution alone

[last ether]

Do a vertical line test

[light bronze]

i did

it's not a fucntion based off that

but how would i know from the equation

*it is a function i mean

[last ether]

I mean you just kinda know

[light bronze]

facts

[last ether]

It stems from the parent function x^2

[light bronze]

if it's raised to an exponent its a function?

[last ether]

Not necessarily

You just gotta recognize it's a function

Typically if only positive y can be isolated by itself, it's a function

But it's just a "just know" kinda thing

[light bronze]

ok

[steep vector]

Domain and range on those are also simple

[light bronze]

what about the D and R?

[last ether]

Domain well

[light bronze]

how would i solve it

would it just be -3

[last ether]

There's nothing that would make it go wrong

[light bronze]

for X

[steep vector]

For those.. domain would always be (-infinity,+infinity) if it goes on forever.

[last ether]

^

All polynomials have a domain of $x\in\bR$

[ocean seal]

Umbraleviathan

[last ether]

Which is -infinity to infinity

[light bronze]

isn't xEr just the domain

and the range is yEr

[last ether]

No because look at the vertex

What's the y value of the vertex

[light bronze]

-3

[last ether]

Is the quadratic opening up or down

[light bronze]

up

[last ether]

Then the range is $y \geq -3$

[ocean seal]

Umbraleviathan

[light bronze]

and domain is Xer

since infinite

[last ether]

Pretty much yeah

[light bronze]

ok thanks

[last ether]

Just make sure your R is boldfaced

[light bronze]

ok

[last ether]

If you're done, close the channel

[light bronze]

!close

[last ether]

.close

[lone heart]

Channel closed

Closed by @last ether

Use .reopen if this was a mistake.

[light bronze]

.close

[last ether]

I got it for you

[light bronze]

ok

[lone heart]

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[vapid steppe]

help

[vapid steppe]

.close

[lone heart]

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[raven aspen]

$(I-S)(I-S^{-1}S^{-1})(I+S)$

[ocean seal]

Maxerature

[raven aspen]

Where do I go from here? Simplifying down to the Identity matrix? S is skew-hermitian

I think if I'm doing this right, I can simplify to

$-(S^{-1})^{2}-S^{2}$

[ocean seal]

Maxerature

[raven aspen]

But I'm not sure how to get from here to the identity matrix

[lone heart]

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[raven aspen]

...

it's not available tho...

[alpine sable]

?

[raven aspen]

I had an open question then the bot randomly reopened the channel

How do I get from

$-(S^{-1})^{2}-S^{2}$

[ocean seal]

Maxerature

[raven aspen]

To the identity matrix

[alpine sable]

The bot closes when inactive

[raven aspen]

I posted less than a minute before it reopened it

opened it at 10:08, my last post was 10:07

regardless

[alpine sable]

I dont know whats that

[raven aspen]

:/

<@&286206848099549185>

Here's the original equation I'm trying to simplify btw

$[(I-S)^{-1}(I+S)]^{*}[(I-S)^{-1}(I+S)]$

[ocean seal]

Maxerature

[raven aspen]

<@&286206848099549185>

[lone heart]

@raven aspen Has your question been resolved?

[lone heart]

@raven aspen Has your question been resolved?

[lone heart]

@raven aspen Has your question been resolved?

[void niche]

post the entire question

what is S

what is the goal

[lone heart]

@raven aspen Has your question been resolved?

[lone heart]

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[past goblet]

how to tell when you have to reduce an improper fraction?

[ornate condor]

when the question asks u to

[past goblet]

What if it isn't indicated?

[ornate condor]

i dont think u have to

[past goblet]

what about factoring

how do you tell when you have to factor

[ornate condor]

when they ask u to i guess

or if it helps with solving the question

[past goblet]

oh alright

thanks

[ornate condor]

np

[past goblet]

.close

[lone heart]

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[dark trail]

I need help with understanding this probability question

[dark trail]

Im going to send it here

how do i answer 6ii?

How do I complete the q6

Or what topic can I revise to solve the q

[ornate condor]

idk try

drawing out the probably thing

n label what means what

[dark trail]

Uhhh

I’ve done something similar

[ornate condor]

venn diagram i think its called

[dark trail]

I don’t think that is required for this q

Can I get someone who knows what to do to help?

No offence

[ornate condor]

well u kinda just said for understanding

so a venn diagram is best for that

[dark trail]

It’s the notation I’m confused about

Like what’s the U

[ornate condor]

oh..

[dark trail]

What does that mean

[ornate condor]

U is union

[dark trail]

Ok so instance where a and b are equal or something

[ornate condor]

the big n is intersection

draw it on the venn diagram

[dark trail]

Wait what’s the diff between two?

Ight nvm

still struglling with the q

i dont know whether to multiply the two or add them

the two probabilities

[ornate condor]

so

what have u gotten so far

have u drawn a venn diagram

[dark trail]

yes

a is 0.6

b is 0.5

i wrote those numbers in a venn diagram

[ornate condor]

can u

send that venn diagram

[dark trail]

k

[ornate condor]

ok um

venn diagrams should also be enclosed with a

[dark trail]

oh ok ill do tht

[ornate condor]

rectangle to indicate that is all probabilities

[dark trail]

with universal symbol in corner of box

[ornate condor]

next, how would u indicate the other value u know on the diagram

P(A and B)

[dark trail]

ummm

maybe multiply the two

but that wont give 0.4

lemme try calculate

[ornate condor]

no its

literally given

so u just fill that into the diagram

[dark trail]

ohh ok

just did tht and out it into

the intersecyion

[ornate condor]

out it?

[dark trail]

put*

[ornate condor]

ok so

[dark trail]

how do i find the U

[ornate condor]

so

when u take

P(A) and P(B) on the diagram

[dark trail]

yes

[ornate condor]

ull notice what u get is

that part u have drawn

but the center part is counted twice right

so how will u account for that

[dark trail]

well a and b is 0.3

right

[ornate condor]

what

[dark trail]

the center part is the little pocket between a and b

[ornate condor]

how did u

[dark trail]

if u multiply and b the value is0.3

[ornate condor]

thats considering a and b are independent

but they are not

[dark trail]

ohhhh

how did u know

[ornate condor]

they said

P(A and B) = 0.4

and being another way of saying intersection

[dark trail]

so intersections are always dependen

[ornate condor]

no

it

depends on the Q

in this case they told u the probability of the intersection

[dark trail]

okok

so now the issue is what?

accounting for whats outside the circles

[ornate condor]

so

u want to find

A U B

so

if u take the probability of A + the probability of B

[dark trail]

which is known as the union?

[ornate condor]

u get this

[ornate condor]

yes

[dark trail]

okokok

[ornate condor]

u get this, a and b bit, but with the centre bit counted twice

so how would u account for this center bit being counted twice

[dark trail]

maybe minus either a or b

from the center bit value

or divide

[ornate condor]

um

u know the notation right can u write it with that

[ornate condor]

and maybe isnt rly

[ornate condor]

u kinda gave 2 answers

[dark trail]

yeah im confused i dont know which one to use

or if they are even correct

[ornate condor]

so this is P(A)

u get that?

[dark trail]

yes

hmmm

so p(A)-P(B)?

or vice versa

[ornate condor]

this is P(B)

this is P(A and B)

u want to find P(A or B)

'or' being the same as union

[dark trail]

so i can minus the P(A) and P(b) from total union

[ornate condor]

yea

but its more like

P(A) + P(B)

but yea

[dark trail]

huhhh

so i do P(A)+P(B)

then negative P(A) and P(B)which earlier i said was 0.3 for independent events but 0.4 for this case

[ornate condor]

.. i cant really

read that rn

can u write it like

[dark trail]

oh ok

[ornate condor]

P(A)

or like this

P(A or B)

[dark trail]

bruh now im confused

so 0.6+0.5=1.1

-0.4

= 0.7

so the union is 0.7?

[ornate condor]

yep

[dark trail]

thanks bro

[ornate condor]

np

[dark trail]

so is 6ii

P(A) given B occurs

.close

[lone heart]

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• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dark trail]

how do i do 6ii

[dark trail]

i know the notation is B given A right?

[dark trail]

ok 0.4/0.5

i realsied its B/A

[ornate condor]

yea

[ornate condor]

to this

and btw its

|

not /

[dark trail]

so intersection 'over A

[ornate condor]

yes

[dark trail]

so 6ii is 0.4/0.4?

[ornate condor]

no its

P(A and B)/ P(A)

which is

.4/.6

[dark trail]

oh my bad i meant to say 6iii

i got that for 6ii

but the remaining prob of B is 0.5

so it'll be union a and b divided by 0.4 which is A?

no im wrong

i think i have to redo the union of a and b as union of a and counter b

0.6+0.5=1.1-0.4

but that gives same value

[ornate condor]

yes

[ornate condor]

idk im lazy to calculate i hate those

[dark trail]

yeah but b is 0.5

so counter b is 0.5

so its the same total right

[ornate condor]

um

idt so

the

B with a thing on top is essentially

~B

or not B right

[dark trail]

yes

[ornate condor]

so P(~B|A)

P(~B and A) is not P(B and A)

[keen plinth]

should just draw the table

[ornate condor]

bru i alr drew

4 tables

[ornate condor]

so done

[keen plinth]

where table

gimme

[ornate condor]

with drawing

i drew venn diagrams

just draw the diagram and find the region of P(~B) and then repeat for P(A) and see where they interesct

[keen plinth]

  |  A  |  A' |
--+-----+-----+----
B | 0.4 |  ?  | 0.5
--+-----+-----+----
B'|  ?  |  ?  |  ? 
--+-----+-----+----
  | 0.6 |  ?  |  ?

this table

makes life so much easier

[ornate condor]

lol

ive

never draw that in my life

:O

[dark trail]

sooo

b' is 0.6

thanks snow

ahhhh

[keen plinth]

wait

im

pepega

[ornate condor]

its ok

we r all

[dark trail]

whats pepega

[keen plinth]

  |  A  |  A' |
--+-----+-----+----
B | 0.4 | 0.1 | 0.5
--+-----+-----+----
B'| 0.2 | 0.3 | 0.5
--+-----+-----+----
  | 0.6 | 0.4 |  1

B' is 0.5

last column second row

[dark trail]

tyty

gonna be back in 30mins pls dont close the channel

[ornate condor]

LOL

itll auto close

dont worry

[keen plinth]

that depends on the will of the bot

LOL

how is that dont worry

[ornate condor]

GODS HAND

well

u cant do anything about it

no point worrying

[keen plinth]

pretty sure if you have bot perms you can keep it open

[lone heart]

@dark trail Has your question been resolved?

[keen plinth]

@ornate condor look

its gods hand

[ornate condor]

OH GOD

WE ARE FAITHFUL

[keen plinth]

HAHA

[ornate condor]

SHOW MERCY ON THY

[dark trail]

Clutched

15 more mins

[keen plinth]

oooooo

[trim wagon]

It automatically closes if there is no activity in channel

[keen plinth]

theres also an increasing timeout

kinda hard to predict sometimes

[trim wagon]

Well so far from what I’ve seen is 1st it asks in 15 mins then 30 mins, 1hr, 2hrs

[keen plinth]

hmmm 🤔

ill keep that in mind

[trim wagon]

Also the amount of time it waits after it asks Has your question been resolved? keeps on increasing

[lone heart]

@dark trail Has your question been resolved?

[keen plinth]

gods hand is back

[dark trail]

Back

I calculated 6iii as .83333

So for 6iv it’s the union of A and alternate b

Which is .5

@keen plinth @trim wagon

[keen plinth]

.

P(B' | A), P(A n B')

[dark trail]

?

[keen plinth]

just to get the questions

[dark trail]

Multiply the two

[keen plinth]

cuz its

way up there

[dark trail]

Ahhh okok

[keen plinth]

but

P(B' | A) is not 5/6

and P(A n B') is not 0.5

[dark trail]

Oh

So

I got that b’ was equal to .5

As b is .5 so the alternate must be the other half

[keen plinth]

yes

[dark trail]

Ok so the formula for A|B’ is

[keen plinth]

other way

P(B' | A)

[dark trail]

Ohhh

All Over P(A)

I meant P(B’nA)/P(A)?

Which is .4/.5?

[keen plinth]

whats P(A)

[dark trail]

My bad .6

[keen plinth]

https://cdn.discordapp.com/attachments/490557019623915520/1018806477537951784/IMG_3011.png

yeah

so

[dark trail]

.4/.6

[keen plinth]

i just realised your username isnt "it" "shim"

its probably "its" "him"