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y=-x²+6x-16
@lime tartan Has your question been resolved?
@lime tartan Has your question been resolved?
<@&286206848099549185>
What's your question?
@lime tartan Has your question been resolved?
Written up how do I make it into vertex form
And get the max/min function on graph
How do you make what into vertex form?
It would help if we could see the top of the table
hello
@lime tartan Has your question been resolved?
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Why is (-2)^6 diff than -2^6
-2^6 = -(2^6)
Pls explain I still no understand
Hello
Oh wait
if you see 3-4², then you read it as 3-(4²)
Ohhh
they are one unit
yeah
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so here are 5 questions i didn’t get in my review for a test i have tomorrow based on the material (complex numbers, operations w/ complex numbers, matrix operations: add, sub, mult by a scalar, and vectors operations)
for #7, I’ve been taught that matrixes must have the same dimensions, or else they’re undefined if they cannot be added/ subtracted; i chose undefined as my answer but didn’t get it right and would like an explanation to the correct answer and why
for #11, i didn’t understand how to find the value of b and at first went by finding the vector of the given line (<a, b>) and then using the pythagorean theorem (square root a^2 + b^2) but that didn’t work as my final answer was none of the choices given
for #17, i tried finding the magnitude of l, m, and n and substitute the answers with the equation given but my answer again, was none of the ones given
for #22, i have a feeling it’s solved by distributing but don’t know how to approach it or where to start
and for #24, don’t understand where i was incorrect on half of my work
(pictures provided below in order if dc doesn’t mess up)
in question 7, the matrices are being multiplied
for question 11, not sure what you mean by using the pythagorean theorem
it was asking for a vector, not the magnitude
for 17, it is not true in general that | l + n - m | = |l| + |n| - |m|
not sure what question 22 is asking, haven't seen an actual question there
as for question 24, I don't see any work you've shown
,w (-3 - 4i)^2
for 24, i think the partial credit came from answer 2 (+) but here’s the work i did for it using the foil method (still confused as how the answer is -7 + 24i)
for the vector, our teacher taught us to use rise/run to find the vector (so what i got was <-7, 6>) but the answer wasn’t there
in this case, how should i approach the equation then?? i originally got these answers, subbed them in but didn’t get any of the answers shown
22 is based on this section of my notes
and i need an elaboration on 7 (don’t understand how they are multiplied)
it is 9 + 12i + 12i - 16, not sure how you got whatever you wrote there
-2b is the vector drawn, and it is [-7, 6], but you were asked for b
l, m, and n are not equal to that
there is a difference between m and |m|
so it's asking you to combine terms and stuff?
the notation AB means that A and B are multiplied
@mystic parrot Has your question been resolved?
basically but idk how to or where to start—and i have to make sure it’s something along x - y since my teacher included the minus sign already, indication it’s supposed to be a subtraction answer
figured out what i did wrong on 24—forgot the i in the second 12 and forgot to make it i^2 on the 16
and figured out 17
anyways i’ll close this now—ty for the help
.close
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Is there any integer such that x + x = 1?
In this problem, the domain is the set of all integers. Which statements are true? If an existential statement is true, give an example. If a universal statement is false, give a counterexample.
(a) ∃x (x + x = 1) ```
confused because I can't think of a single integer where this would be true
but the question is worded in a way that implies it is true and my task is to prove it
nope
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Yo this is an arrow diagram. I wanted to ask if it’s a function or not. The book says it’s a function but I believe otherwise
@fickle nacelle Has your question been resolved?
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Let h(x) = f(x)g(x).
if f(x) = -4x^2 + 5x -2, g(2)= 3, g'(2) = -2
What is h'(2)?
you can use the product rule to write h'(2) in terms of f(2), f'(2), g(2), and g'(2)
I apologize I am not that familiar with the product rule. Could you explain that for me? If not I'll try to watch a video. First time here, sorry!
oh, have you ever seen it before?
I'm trying to learn up on calculus in order to get better at it. I've sorta seen it but never really understood the idea of it.
it gives you a recipe to compute the derivative of a product of functions
it might be better to watch a video or something
Okay no worries I'll do that. Thank you. One second
sure thing
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Hello
@lunar girder Has your question been resolved?
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wheres the question start
oops at the top
ye looks good to me
easy problem since you the L[y] cancels
All the way to the end looks correct to you?
yes
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<@&286206848099549185> can someone help me with something please
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@vestal crag Has your question been resolved?
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how would I isolate n where n > the rest of the terms
yeah
does it make a difference if I know that n > 1? which means the denominator would always be negative
is there more context to this
I'm trying to do a proof for limit of a sequence
and I need to isolate n, where n > M which would be the rest of the terms
if the denominator is negative then the thing inside | is also negative
so u can translate this to -24/(5(3-5n^2))<H
do the absolute value signs need to be there
yes without the absolute u could get a different answer
wait so |-24/ 5(3-5n^2) | < H?
yeah
5n^2>5
so 3-5n^2 this bit is negative
5 times that bit is negative
24 by that bit is negative
so in the absolute u are just taking away the negative which is the same thing as multplying the -1
oh
like |-1|=-(-1)=1
so it would end up as just 24/5(3-5n^2)
aren't i taking away the negative because of the absolute value
do you know $|x|=-x$ if $x<=0$
does calc even end(cat gang)
in this case $\frac{24}{5(3-5n^2)}<0$
does calc even end(cat gang)
yeah
so $|\frac{24}{5(3-5n^2)}|=-\frac{24}{5(3-5n^2)}$
does calc even end(cat gang)
thats what i am saying
yeah because when n>1 the denominator has to be negative
yes
oh
now u are left with $\frac{24}{5(5n^2-3)}<H$[bring the - to the denominator and multply it out]
does calc even end(cat gang)
what
ignore @alpine sable he is shitposting probably
ok
this implies $5(5n^2-3)>\frac{24}{H}$
does calc even end(cat gang)
omg
do u understand my last step
this one
yeah
ok now if i distribute the 5 then $25n^2-15>\frac{24}{H}$
does calc even end(cat gang)
i hope u can do it from here
yeah
got it
thanks @alpine sable
i need to work on my absolute value skills 💀
.close
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what did u try
i think there is only one square root of 225 and 15
no
what do you by understand by square root lemme ask first
the opposite of square is square root
correct
it tells u what number/numbers when u square it gives the desired value
and what do you understand by $\sqrt{x}$
does calc even end(cat gang)
for x>=0
ok
? that does not answer my question
that x is being square rooted
ok
$\sqrt{225}=15$
does calc even end(cat gang)
but isnt $(-15)^2=225$
does calc even end(cat gang)
but the principal square root only gives the non negative solution
however the square root gives both
ye
No square root of a non negative number only means the non negative value lol.
Sqrt(4) is 2 always.
Bruh
no
coz $\sqrt{x}$ is not the square root
does calc even end(cat gang)
its the principle square root

.close
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Good call.
Nope.
lol
then dont argue pointlessly lol
sqrt is square root, the square root is always meant for the positive value.
we cannot argue whats defined as what if we dont use another source except telling each other as this is defined as that
so here i have for u
a source

this is your source, it says sqrt(x) is positive, we use a negative in front to denote the negative version of it
correct
and also its written
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hi which formula should i use to determine the n for blue and red balls? (separately)
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Let 𝑡 be a parameter. For which values of 𝑡 does the system of equations have a) exactly one solution, b) no solution or c) infinitely many solutions?
thats what i have done so far, but i have no clue how to start with b) (no solution) or c) (infinitely many). Can anyone explain how I can start/complete this or know a good video that explain similar problem?
<@&286206848099549185>
basically all values of t such that t / 1 = 10/(t+3) fall into either (b) or (c), because you can imagine that both of the x and y cancel out
so you just get some number = some other number
and if it's true, then you get infinitely many solutions (the values of x and y don't matter)
and if it's false, then no value of x and y is going to satisfy that
so if t/1 = 10/(t+3) = 8/2t, then you have infinitely many solutions
otherwise if just t/1 = 10/(t+3), you have no solution
if you want to see it in matrix form, reduce to rref and look for what makes the left matrix have a row with all zeroes
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So i want to ask a simple question

So (sinx)^2+(cosx)^2 = 1 right?
indeed
Does that mean 1/(secx)^2+1/(cscx)^2 = 1?
yes
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why is this true?
hint : cos(x)=-cos(π-x)
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who circled that?
one would think it's C...
"which of the following must be false"
there exist functions with a VA at x=1 for which C is true
1 + 1/(x-1) for example
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Is (2.5/5) considered a rational number?
yes
My professor told me it’s not rational and it’s not irrational
Because of the decimal
your professor is wrong
are you sure those were his exact words?
I have to double check with him but I’m certain he said the decimal makes it different
if your number can be expressed in the form p/q where p and q are integers,
then it's rational
2.5 is an integer
is he implying that 2.5 is an irrational number?
I think so
2.5 is not an integer
What is 2.5?
its a rational, too because it can be written as 5/2
2.5 is the same as 5/2?
Hmmm I will have to think about that
Interesting
Is that the case for all decimal numbers?
I didn’t realize that before
So what do we call (2.5/5)?
Rational?
if your number can be expressed in the form p/q where p and q are integers,
then it's rational
a rational divided by a rational is always a rational
also ^
What is it called when decimal is divided by integer?
depends on the decimal
if your number can be expressed in the form p/q where p and q are integers,
then it's rational
So it’s not rational?
i said can be
But it’s also not irrational either?
integers are a subset of the rationals, so you still could interpret "decimal divided by integer" as "rational divided by rational"
any integer is also a rational, but not all rationals are integers
just because you don't originally have an integer divided by an integer doesn't make what you have irrational
OK but on it’s own (2.5/5) without any conversion what would you call it?
Not rational
But also not irrational?
if your number can be expressed in the form
it doesn't matter what you're starting with
Oh so to say (2.5/5) is not rational is incorrect
yes. that can be expressed as 1/2 which is rational (and would satisfy the definition of a rational number)
At the end of the day it can be converted in 5/10 and 1/2 so therefor it is rational. It just isn’t obvious from the very beginning with decimal but it can be expressed in this form so therefor it is rational
OK I think I understand now.. I think what the instructor was trying to demonstrate is that 2.5/5 is not it’s final form to be rational but he didn’t explain it very well
Thank you for the clarification
and also
a rational divided by a rational is always a rational
(if you aren't dividing by 0)
Right the denom can never be 0
also note that repeating decimals are also rational
Oh sorry
They are rational.. I misread this
Why would repeating decimals be rational?
Because there is an end to it?
The pattern
With pi there is no known end
And infinity too
Why would repeating decimals be rational?
look up converting repeating decimals to fractions
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how to know the orientation of a parabola with the points of a parabola without graphing?
like if we have 3 points in a parabola how do i know its y or x ?
from the points alone?
you don't
Do you have a question to work
unless two of them just happen to align horizontally or vertically, i guess...
Right as Ann said
so you graph it ?
Look at (1,2) and (3,2)
They align vertically right?
Meaning for same value of y there are 2 different values of x
ohnvm
h and c being?
Ah we are finding for the equation here
so i just need the c and the h
(x-h)^2=4c(y-k)
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so for I've done (4/52) * 12 + (12/52) * 1
Please don't occupy multiple help channels.
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is that the vieta jumping question?
well you could just google "imo 1988 q6 without vieta"
google immediately gives you a stackexchange post
in general it's a famous enough question that you can probably find lots of solutions on the net
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in my textbook (about limits) they went through this step:
tan(pix + pi/2) = -1 / tan(pix)
what formula did they use?
thanks
tan(t+pi/2) = sin(t + pi/2)/cos(t + pi/2) = cos(t)/(-sin(t))
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how can we find that
lim(x->0-) t / tan(pi×t) = 1/pi
knowing that
lim(x->0) tan(x) / x = 1
?
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The dots of the plane have been colored in 2015 different colours. We say that triangle ABC is colored if its three vertices, A, B, and C are the same colour. Prove that there are an infinite number of triangles, all of the same color and the same area.
@oak perch
Old competition problem I see
it seems easy tho
I think I got it
pretty sure this is not a easy problem
yea same, idt its easy
Choose 2016 parallel lines in the plane
never seen a problem from this guy thats easy tho takes me atleast a hour to solve
Then two of them must contain an infinite number of points of a common color C
im tripping my solution is simple enough but is very poorly constructed i thinki its wrong
idt i even understand the problem lol
id t?
Choose two points of color C from one of the lines, and construct an infinite number of triangles by choosing points of color C from the 3rd line
Brilliant
why tho
if one line has the first half of colors
every line must contain an infinite number of points of at least one color
Well that's why I started with 2016 parallel lines
Pigeon hole
So even if every line has infinitely many points from only 1 color you can still find 2 where it's the same
oh clever
Cool problem
This
ya thats what i thought too lol
this is kinda easy
like assuming cart coordinates, there are color on each point?
can anyone check if mine is correct?
Sure
He is answering this question
probably
oh yeah
if i draw a reg 4031-gon, i will get at least one triangle of a certain area and color, if i keep doing this, it will have to repeat
wait
cuz idk the exact amount i need
Ooh sick
how do u prove same area?
There's only so many distinct possible areas
bro same area T.T
hol on the question says same color and area
Yeah
the aree will also have to repeat
Every point (x,y) gets a color
i dont think the monikanicity solution told about the area part
"it"
will have to repeat
all the triangles have the same base and height in mine
base is on the line with 2 points, height is the distance between the lines
oh yeah the base
wait i dont think i get why height is same either
u put 3 points
one on each line
i think
height is same
nah
base idk
I chose 2 constant points from one line
ohhhh
They form the base of the triangle
yeah
oh i dont think then its obvious that such a combination will exist always
where one line has 2 same colors
That's what the first part of the argument was for
Every line must have an infinite number of points of at least 1 color
So I choose 2016 parallel lines
oh nvm i am just dumb lol ur right
That way, 2 are guaranteed to have infinite amounts of the same color
based
I chose 2 constant points from one line
and then made an infinite number of triangles by choices of the third point on the other line
yes
with same color
but i am asking about the same area part
Yeah
i didnt even understand that
Choose an infinite number of disjoint regular 4031-gons
Smallest number that guarantees 3 points of at least 1 color
Finitely many colors. Finitely many areas, have to repeat infinitely many times, for one color one area
If there were 4030 vertices, you could have 2 points of every color
Regular 4031-gon yeah
Regular 4031-gon
Or doesn’t have ti be regular, just infinitely many copies of 4031-gons of the same shape
ye how do u say its existence
any 4031 point structure without 3 collinear points really
Yeah, better
mainly just imagining putting a bunch side by side
infinitely many
take circles with radius 1 centered at (3n,0) for every integer n
and inscribe the polygons in the circles
no i mean
if u find 4031 gons of same shape
n inf of it
it doesnt work as the color might be of the same shape
as u arent finding regular 4031 gons
well there's only a finite number of ways to choose 3 points for a triangle
and showing if u can fond regular 4031 gons on a grid is also hard
so eventually it'll have to repeat if you have infinitely many
i mean
that isnt rly an explaination
o well
the same area 1 is gd enough for me
ty
np
@agile condor Has your question been resolved?
thnx guys
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Hi
context
Why 21?
I think because 9+10=21
smh dumb teacher must've thought it was 19 or something
but really the correct answer is on there
you can write out all the different combinations and count how many there are
nvm
Ok so 11
I can order it 5 different ways
then why 11 if it's 5
Are you solving this with combinations or a tree
how would i solve this if the order is relevant but you can also say nothing about an ingredient🤔
Order doesn't matter so you use combinations
You have 4 possible toppings
You can use all 4, 4C4
You can use 3 out of the 4, 4C3
You can use 2 out of the 4, 4C2
You can use 1 out of the 4, 4C1
And finally you can just add no toppings if you have a boring personality, 4C0
(correct me if I am wrong I suck at the perm. and comb.)
No clue what jacks and clubs are
Me neither
lol
a deck has 52 cards
there are 4 jacks and 4 clubs in it
this is the explanation of why we find the possible toppings using
2x2x2x2
following each path gives you 1 possible combination of topings
in total there are 16 paths you can take
and the tree doesnt count with different orders
k: ketchup
y: mayo
r: redish
m: mustard
with and without indicated by the red dash
Being in a test and not explaining this would be messed up
very true i had to look it up online
@humble scroll Has your question been resolved?
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So 1/52
what are all the desired draws?
there are 13 clubs, but one of them is a jack
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hello
i have a question about a certain problem
what formula would you use for this problem?
i'm not quite sure how to approach this
you know arc length, radius
er
you know arc length, and the angle of the arc
you want to find radius
do you know the formula that relates those 3 values
isn't it like s=rO
O is angle?
ye the theta symbol
Yeah
Btw does this work or am I dumb
$\frac{207}{360}2πr=50$
ahmed349
it would work yeah
Yes
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Did I do this correctly or is it (√6)⁶
this
OK
$x^{n + m} = x^n * x^m$
$x^{nm}= (x^n)^m$
Sorry?
i meant about this message
(the one the bot sent)
does it make sense now @dawn quail
I think so, but what about negative exponents?
trololol !
this is when you multiply and when you add exponents
yes
This is correct too?
yes
yes
yes
Thank you
Just to drive it home
You go in order inside to outside? Or doesn’t matter
it doesn't matter, because multiplication is commutative
Division too
division isnt commutative
Oh
Right, there is no division here
I mistook the fraction as division
½
Addition and multiplication are the only commutatives in math?
yes
Good to know.. in theory can every equation be forced to use commutatives?
What I mean is fraction is division, but 2 ÷ 3 can also be written as ⅔ almost like it’s a single term.
2 - 3 is subtraction but it can also be written as 2 + (-3)
i mean, you can write $a - b$ as $a + (-b)$, making it commutative
same for multiplication : $a \div \frac{x}{y} = a \times \frac{y}{x}$
trololol !
for exponentiation it is a bit harder, though
in fact, i dont think it is possible to write it in a commutative way
And in theory you can move those values anywhere if they belong on LHS or RHS of the equation? It won’t affect the outcome if they are written as commutative?
what does lhs and rhs mean
left-hand-side and right-hand-side ?
if yes, then yes, it won't affect the outcome - this is the very definition of being commutative - the order of the operations doesnt matter
but remember to not mix addition with multiplication - you can only move the terms within the same "addition chain", and the same "multiplication chain"
u cant say that $a + b \times x = a \times x + b$
trololol !
This is because BEDMAS only works for multiplication/division and addition/subtraction in order from left to right, correct?
what is BEDMAS ?
Brackets Exponents Division Multiplication Addition Subtraction
Order of operations
For DM/MD it should be treated left to right whatever order they come in
Same for AS/SA left to right whatever order they come in
But with the commutative property that makes me think I can rearrange DM or AS if I really want to
But not when they are combined.. I think that’s what you are saying here
So commutative only works if LHS or RHS is DM/MD exclusively or AS/SA exclusively. It can not be both DM/MD+AS/SA on LHS or RHS for commutative to work
I hope someone can confirm this for me? I don’t know if I explained that correctly?
exactly
And this doesn’t account for brackets or exponents either. I think those could change things too
it is commutative only with operations of the same "type"
brackets can be changed, added/removed however you like, too
this is called associativity
and multiplication and addition are also associative
exponentiation is neither
Are exponents considered included as part of MD/DA?
then what is distributive?
no
$x(a+b) = xa + xb$
trololol !
this is distributive
OK, so exponents are kept on their own.. √ and ² are like saying a new family such as DM and SA
yes, to a certain degree
mhh we profesional englesh speakerre call ita foil
root is not the only opposite of exponentiation - there are also logarithms
but this is another topic
Foil would be two binomials no? This is distributive
so for now, you can say that root and exponentiation are of the same family
FOIL!
This is FOIL or Distributive?
Idk all i heard is engleshmen never use distributive
they say
FOIIIIIIIIIIIIIIIIIIIIIIIIIL
Engleshmen?
yes
lets not talk about engleshh men please
I need real mathematical help
I am dealing with one trignometric qn
*Trollonometry
You think im trolling?
Yes
i just want answer
To what?
trignometry
Start a new thread
It’s easy and free to do so, you are just confusing people by stating something is FOIL when it’s distributive
Which has nothing to do with trigonometry
when it comes to cross multiplying it does
Can someone confirm?
Is FOIL algebra, trigonometry, or both?
First Outside Inside Last
I am curious now
AFAIK it’s a convention for remembering to do all the operations when multiplying binomials
help pramad please in pramad help channel
anyways, if your question has been answered, remember to close the thread, @dawn quail
@dawn quail Has your question been resolved?
Not yet I’m looking for clarification on @wind yoke’s point
Is FOIL algebra, trigonometry, or both?
@dawn quail Has your question been resolved?
multiplying out brackets is algebra
and FOIL is a common trick to remember how to do that
was that your question?
@dawn quail Has your question been resolved?
No the question is whether FOIL is a common trick for algebra only
Or if it can also be used for trigonometric questions too
But perhaps this is where algebra and trig blend together so FOIL perhaps can be used for both? It’s not so black and white one or the other?
If someone can give me an example where FOIL is used for a trigonometric question that would be greatly appreciated
This will also finally answer @wind yoke ‘s question here too…
well FOIL is used whenever we multiply out brackets
if you wanna multiply out (sin(x)+cos(x))(tan(x)+sec(x)) or something and call that trig, sure FOIL is used for that
multiplying out brackets is something that happens often in a lot of contexts in math
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i know this is a lot to digest here so i'll dissect it
i'm evaluating the integral of sqrt cos x
which is a non elementary
so i did it with taylor series
i just got the taylor series for sqrt x and plugged in the cosine
since the cosine has a power i just used the beta function right away to calculate the integral, shown in upper right corner
i then developed the calculation a little and then changed the gamma's to their product definition
and got that product below
and just plugged it into the taylor series
that's it
the small sum in the center, ignore it, i was tryna simplify the thing more but didnt know how to so called it
so i plug both the integral and the sum in desmos
i get a result around 2.39 for the integral, and one of the order of 1e-169, for the sum
pretty darn close to 0
so what went wrong
if there's any clarification to do, ping me
thanks in advance
@serene flame Has your question been resolved?
<@&286206848099549185> i'm sorry for pinging, is anyone down to help here
@serene flame Has your question been resolved?
@serene flame Has your question been resolved?
@serene flame 👋 You may want to check the early university and advanced sections of the server since this is quite advanced, there you don't have to also confirm to the bot that you are actually there and it may be nicer if you want to do other things in the meanwhile
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Hi
Can someone help me with this
@humble scroll Has your question been resolved?
<@&286206848099549185>
So I think i can help you with number 22
Have you seen something like this before?
Basically what this is
is it shows all the possible outcomes of rolling 2 dice
Can you see how the dice outcomes correlate to the numbers on the inside?
basically you just add together the numbers in the right row and column
so if you rolled a 4 on Dice B and a 4 on Dice A, you would see what box is in Column 4 Row 4
and there is your answer
Basically the reason I am showing you this is because if you count all of the middle boxes, there are 36
which means there are 36 possible solutions to rolling 2 dice
Or just rolling a dice twice
How this can be used is
since it is asking you the probability of rolling a 10, you would count how many boxes have a "10" in them
so how many is that?
A hint to help you is that the same numbers are diagonal to each other
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limit as x approaches 0 of (1-cos^2(x))/x^2
plz help i am begging and will fail my life if i dont get this
L hop it
If you dont know what that is then lim as x approaches a of g(x)/h(x)=lim as x approaches a of g'(x)/h'(x)
@rain scaffold Has your question been resolved?
@rain scaffold
find the derivative of numerator and denominator separately and post here
what is a derivative
we were never taught that
@old sinew i have a question
how can i simplify 1 - cos^2 x?
can it be (1+cos x)(1- cos x)
$\lim_{x \to 0} \frac{1-\cos^2 x}{x^2}$
CapitalW
try dividing both numerator and denominator with x^2
so essentially we will not change anything, as we are multiplying by 1
infy will pop up
i dont understand how i can simplify the top part
would difference of squares work
essentially we need to get rid off x^2 in the denominator
else applying limit will go to infy
okay
do you know lim x to 0 sin x/x = 1?
yes
great
i also know lim x to 0 (1-cos x)/x = 0
whats tripping me up in the problem is the square on the cos
i dont understand how to rid of that
let's try this way
$\lim_{x \to 0} \frac{1-\cos^2 x}{x^2}= \lim_{x \to 0} \frac{\sin^2 x}{x^2}$
CapitalW
$\lim{x \to 0} \left(\frac{\sin x}{x}\right)^2$
wait
you can do that????
i understand that 1-cos squared equuals sin squared
but how are you removing the squared
CapitalW
OHHHHHH
$\sin^2 x = (\sin x )^2 = \sin x * \sin x$
OK THAT MAKES SO MUCH MORE SENSE NOW
CapitalW
keep this in mind
that does make sense, but there shouldn't be an equals
in the end?
not after lim x to 0
okay i took it off
@rain scaffold btw, your answer to 16 is wrong
you are asked to find the limit not f(0)
16's limit exists
i wrote IND next to it
that's how our teacher taught us
when u plug in 0 (first step)
u have to see whether it is indeterminate
look ill send my full work
0/0 is not my answer
2 is
okay, then you shouldn't put =0 in first
just hear me
he wants us to write it the way he wants it
Have you learned L'Hopitals?
no
If not, you can use difference of squares then
ya i used difference of squares
Which is what you did
you found lim x to 0 is 2 not 0/0
so you should only write f(0)=0/0
Nah their work is fine
not lim x to 0 f(x)=0
ALTHOUGH
dw thats just how the teacher wants it
You DO NOT put an = 0/0
not precise to what the definition of limits are
It would be $\rightarrow \frac{0}{0} (\text{IND})$
Umbraleviathan
that will work
he wants us to write f(0) is 0/0 (IND) but lets us skip the f(0) part
f(0)=0/0 but lim x to 0 is not 0/0
which is what whole question is about
that's the key distinction you need to understand
any ideas on how to approach it?
@rain scaffold Has your question been resolved?
i got it