#help-0
1 messages · Page 31 of 1
if you are not able to do it
i think the only way we would be to show you how to do it
hmmm @wide raven excuse me, i was in this channel someone tried to help me. But since i'm a helpless cause i didn't find my answer
oh sry
you can ask it again, on a different channel
ok thank u!
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can someone help ?
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Hello , what’s the formula for Gradient ?
gradient of what? a line?
$m = \frac{x_2 - x_1}{y_2 - y_1}$
help
@turbid stratus Has your question been resolved?
bruh what
even if they did mean gradient of a line
its usually given the other way round
$m = \frac {y_2 - y_1} {x_2 - x_1}$
夢雪
and there is no mention of what, m, y_1, y_2, x_1, and x_2 are
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could someone help me figure out how to approach this ODE problem? I am trying to verify the implicit solution on the left side.
I think what I need to do is get the 1st and 2nd derivative of the left side? and then if I tried to isolated y'' I could then verify if it matches the left? or is there a simpler approach?
this is what I have so far, but honestly I don't know if it's right... if it is, then I have no clue how to isolate y'' 
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hey guys I have a, b ,c and d values for this one and get that I can graph the function by putting into desmos but what does the x> -b/2a mean?
only plot x values bigger than -b/2a
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hey guys I have a, b ,c and d values for this one
how do i know what the point coordinates will be?
i get the c would just be the c value itself
would f(c) be the function with c value plugged in for x?
pretty much
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Hi, I'm working on Herstein 2.3.14 and I don't really understand the answer. Suppose a finite set G is closed under an associative product and that both cancellation laws hold in G. Prove that G must be group
The solution makes no sense since it just shows that you can solve both ax = b and ya = b and stuff online talks about bijections, but I don't really see how this PROVES that an identity elemetn exists and therefore, each element in G has an inverse in G
If you can solve ax = b, for any a,b then there exists an inverse for every a, since you can solve ax = e, no?
(e = neutral element)
yea, this is where I get stuck, i feel like it's really simple so I don't know why I don't get it. So if I can ax = b, x = ba^{-1} = e?
I just don't see why that necessiates a natural element
unless that above is the explanation?
Being able to solve ax=b for any a,b is way stronger than having an inverse for every element. Because in particular, you can solve ax = e for any a (just be replacing b with e).
If ax = e for some a, then x is the inverse of a by definition.
OHHH I SEE
thanks so much I've literally been reading the same few passages and not making this connection for some reason
Alright😅 yw
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multiply by the conjugate
or more precisely
multiply numerator and denominator by (sqrt(x)+2)
no, doing what i described will not give $x - \frac{4}{\sqrt{x}} - 8$.
Ann
it won't give $\frac{x-4}{\sqrt{x} - 8}$ either, but you should've been more careful with parentheses to write that.
Ann
1/sqrtx + 2 is what I have so far
no, you don't have $\frac{1}{\sqrt{x}} + 2$.
Ann
ok, then write 1/(sqrt(x) + 2).
not 1/sqrt(x) + 2.
unless you're one of those people who likes not being understood.
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|P(A ×B)|
Suppose that |A| = m and |B| = n. Find the following cardinalities.
would the cardinalities be 2^(m+n)
no
A x B is the Cartesian product of A and B
so (A,B) right?
...no?
${(a,b): a\in A, b\in B}$
Denascite
|P(A x B)| = 2^|A x B| = 2^(|A| * |B|)
so 2^(m*n) is the answer
^ i think that is the answer?
@limpid garnet Has your question been resolved?
yes
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can i get help

tobias!
okay
alright so
HOW IN THE WORLD
i know the answer is right there but lord
can we go on call or something??
like i literally do understand how to evalute that function
for it to turn into whatever the hell they got
Mr. Gamer
Mr. Gamer
Does that make sense?
no .
The exponent would normally just apply to the next term, if you want to raise something to the power of a longer expression then you have to group it together
how do u get there
okay wait
so is it just where u put the similar things together
in the equation
hol on
im abt to drop this class cuz wtf
mr gamer help!
i havent taken a math since sophmore year
i am a sophmore in college
PEMDAS
Yes
f(2)= (2^2 + 1) ^ 3*2
Look at the first problem
okay so how do u do tht here?
Yes
OHHHH i SEE
ok so ur doing the paranthese
hold on
WAIT.
(5) 3^2
so do we do the expontnet ?
Now we do the exponent
I thought we were looking at the first one, weren't we?
yea
The 2 is not inside the parantheses there
which 2 are u talking abt
bc im refering to the 3*2
bc we already solved what was inside the parantheses
now we have
^ (3*2) left
5 ^3*2
this
Ok
the first
and the question is asking
which one of those equations correctly evaluates whatever the hell this is
Here the 3*2 is inside the parantheses
right
So that turns into 5^(3×2)
right
Then we evaluate what's inside the parantheses
Yes
OM
GG
mr gamer. i am so sorry if im making u frustrated but BARE WITH ME.
ok so 5^6
okay so now this one
there is no parathenses
soo would it be the same process?
Yes, do whats inside the parantheses first
Yes
Yep
Yes
Sure, but I don't use discord too much
Try using these help channels if anything else comes up
what if i need help
ok !
imma wish u the best in life everyday
we need more people like u
👍
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hello
im confused
yes i do
ohhh
you just have to know the trick for negative exponents
which is? lol sorry i just started school again and my brain is still in summer mode lol
np
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i dont really know if the line L is a positive or negative gradient, and im not quite sure what does it mean by 30^o with the positive direction of x-axis
Between the line l and the X axis is 30 degrees, I feel like it is most obvious for it to have a positive gradient imo
but then if it has a positive gradient then how is the line perpendicular to L passing through (0,-4)?
ohhhhh i seee
Make sense?
yep
Cool do you know how to do it from here
What coords?
(0,-4) and (0,0)
Right
then i can find the gradient of line L
No
L doesn't go through 0,-4 the perpendicular line does
You need another point that lies on L to find it's gradient
Let's say y=4x
Do you know what the gradient of the line perpendicular to it would be?
That's parallel
sorry wrong thing
It's all good
-1/4
Yes cool
So you know that l makes 30 degrees a the X axis, so I suggest we find the function that makes l first
Then we can find the equation of the perpendicular
Does this diagram remind you of something, ignoring the y axis?
a pencil tip? 🤣 i dont really remember anything apart from that sorry
Do you see the triangle?
?
ohh ok
I would keep as root3/3
ok
Now find the gradient of l
L goes from (0,0) to (1,tan(30))
I put tan 30 cause easier to type lol
that's fine
so m = tan30/1
so basically tan30
perpendicular gradient = -root3?
Yeh
thank you soooo much
You don't even need to do that it's just y=-root 3 -4
Because -4 is the yintercept when X is 0
yeah but it's homework so i gotta show everything
Fair enough
No worries 👍
have a nice day!!
You too
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This right?
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tan(x)=-sqrt3
work out for x
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.open
@tawdry temple Has your question been resolved?
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I have this so far:
Not sure if my reasoning is correct. Any advice is appreciated.
not sure exactly what you are doing there but it does not look right
I think I am mis-remembering the rules of nth roots
5^2=25=1 mod 8 therefore 5^2n=1^2n=1 mod 8
why are you taking any roots at all?
so are you saying... nthroot((5^2)^n - 1) = (5^2) - 1 for any n?
Would I first need to state that "suppose 5^2n - 1 is divisible by 8, then 5^2n - 1 = 0 mod 8 . . . "
Then stat that 5^2 ^ n = 25 ^n
25 = 1 mod 8
1 ^ 2n = 1 for all n s.t. n is a natural number
thus 1 - 1 =0 mod 8
No
as needed?
Literally what I typed is sufficient
@edgy flare are you aware of how mod rules work?
Yes.
you can just start here
usually when proving something you dont start with the conclusion
I have an extremely picky professor for intermediate analysis, and she will count off if it is not explained well enough. So I am very cautious on how in depth I need to state before using something.
It is the job of an analysis professor to be picky
Because usually the students taking the class don't know how to write proofs
Lol
what cogwheels of the mind said is good though
Okay. I just suck at proofs, so I need as many points on every assignment to counter balance if I do poorly on quizs/tests
Thanks @oak perch
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what is -9/9 💀
What's 9/9?
1
And -9/9 is the same as -1 * 9/9
so -1
Yes
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✅
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How do i graph this function to find the limit
since its continuous at w = 3.3, you can just find the value of f(w) at x = 3.3
that will be the limit
i think its just a problem of the logic
oh im stupid
since 3.3 is .34(first ounce) + .26(second ounce) + .26(third ounce) + .26(fourth ounce)
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Help
Ih my god
I love u
i love u so much
i love u
ily
ur tbe best
i was crying
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so I know that the conjugate is another zero
-3i
but I'm not exactly sure how to find the last zero
once you know 2 of the roots, finding the last could be achieved from vietas formula
oh shit thats brain
so x^2-9
dont do it my way
and then divide how
.reopen
prod would be -d/a = -45/2
err
confused sorry 💀
shouldn't it be 3
from x^2-9=0
it'd become x=3?
oh it's -5/2
thanks
I'm actually not sure about this one
@vivid pond Has your question been resolved?
no worries
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\
how is this wrong
Five independent trials of a binomial experiment with probability of success p=0.6 and probability of failure q=0.4 are performed. Find the probability of the following event rounded to five decimal places:
At least 4 successes
(transcribing the problem here so as not to have to squint)
your answer is 0.02016. how did you calculate this?
no worires
i figured it out lmao
sorry to waste ur time
i multipled % of winning 4 and % of winning 5 instead of adding
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how r they getting these numbers?
Binomial distribution formula
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what does epsilon denote in the context of sequences?
are you looking at the epsilon-N definition of limits?
Do you have specific notes you're trying to understand?
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Hello guys! I need help with this question me and my classmates have been stuck on.
||It looks like the odd place terms and the even place terms are in an ap||
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This is a previous exam, and the professor did not include a solution , can someone please check my answer for part 1
@dull leaf Has your question been resolved?
yes, it's correct
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So i am confused where to ^2 comes from that is applied to 1?
What is 1²?
just 1
So it doesn't matter which we write
They've done it to make you spot a factorisation technique as the next step
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Hi, I have this permutations and combinations question
usually for these questions, they only ask if C is to the right of 1 O instead of 3, because then you can simply divide the total number of arrangements by 2
however this question has multiple o's so I am somewhat confused as to what to do
oh i should clarify I am talking about b) and c), a) is quite straightforward
so I tried a case study with b) however I can't quite get it to work
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Hey. I am wondering if anyone could help me understand this example question in my exercise book.
It says that the average return is calculated by P(winning) * value of win.
The example has three prizes, $1000 for first place, and $100 for second and third place.
But the example says P(1st) * 1000 + P(2nd) * 100 + P(3rd) * 1000
I don't understand why P(3rd) is multiplied by 1000. Shouldn't it be 100 since that is the value winning of 3rd place?
Here is the example question from the book.
Any help is appreciated. Thanks.
,rotate
Ty
Ah, I didn't even notice that. Thank you! I am blind
all g lmao
I have one more question about it also. I am confused about the probably of losing * value of losing. Why is it multiplied by 0? Is the value of losing not the $5 to play? How do you determine the value of losing?
bc u get nothing if u loose
lose
then they say all that is ur average return 3.75 right
Okay so the price of playing is not the same as the value of losing even though in a sense you have lost the $5?
Sure
but u pay 5 dollars for that 3.75
yea
basically
Can you think of any example where the value of losing isnt 0?
Just to help clarify
uh probably if there is a garuntee that u will at least win 1
$1
no matter what u draw
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The only context I can give is this is vector calculus, I have no idea what to do though
,rccw
what are u and v?
I’m assuming one is a vector u and the other is vector v
It wants to create a vector uv maybe? I’m not sure
show the textbook itself
if so then there should be an instruction nearby that tells you the values of u and v
they are vectors and that much is clear from context
but we do not know what vectors they are
72
Oh my god
they say u = <1, 1> and v = <-1, 1>
does this now enable you to do the problem?
Actually never mind I’m still a bit confused
you need to find scalars $c_1, c_2$ such that $c_1 \ang{1, 1} + c_2 \ang{-1, 1} = \ang{4, -8}$.
Ann
Haven’t done any sort of math in 3 months you’re gonna have to give me a break. Am I creating a system of equations for this or what
well i said what you need to do right here in what i thought was plain and simple language.
you could do some algebra to the left-hand side to write it as one vector, then equate the x-components and the y-components on both sides amd yes, you would get a system of equations from that
- your angle brackets don't have much angle to them. that's something you need to fix.
- c_2 <-1, 1> = <-c2**,** c2**>**
that comma just up and disappeared and it looked like you were writing <0>
Ya lol just a sleep deprived I put the +
Some personal stuff came up and I have to finish this textbook hw another one and a quiz before 8 am Thursday
But ya I am I guess
That’s my final answer. Not sure if I did my system wrong it’s been a few years since I’ve done these.
seems ok
Alright well thank you.
@viscid wren Has your question been resolved?
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Qbi,bii
What have you tried?
@boreal stag Has your question been resolved?
We say we throw a dice. It does not matter what the result of the 1st throw is. There can't be the same number again. So how many different numbers are possible for the 2nd dice?
So its wihout replacement?
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✅
5/6
and so the third 4/6
What about bii
"at least two dice show the same number" is simply the complement of "all the dice show different numbers".
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Need help with ai and aii
@boreal stag Has your question been resolved?
it's not really clear
???
yeah better
U know how do?
No, not really sorry
@boreal stag Has your question been resolved?
1out of 6
There are 2 possibilities that the arrow goes down or to x
1 out of 2 chance
The dice is 1 out of 3
1 out of 3 × 1 out of 2 = 1 out of six
This is my guess
A i
A ii is uhhh
1 out of 4 chance of getting y
1 out of 4 × 1 out of 3 = 1 out of 12
Chance
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for what n $(\sqrt(3) + i)^n$ is a purely imaginary? purely real?
idk how to resolve this
i know that if we want a purely real then Im(z) = 0 and a purely imaginary then Re(z) = 0
Write the inside of the exponent in the polar form
also recall that arg(z^n) = n arg(z)
Or if you are familiar with it the exponential form due to eulers formula can also make it obvious
Ok I'll test that
@wanton hearth Has your question been resolved?
i repass it to the algebric form
$2^n cos(n\frac{\pi}{6}) + i (2^n sin(n\frac{\pi}{6})$
but now idk how to resolve Re(z) = 0 and Im(z) = 0 cause i still have some power n
Notice in this form the real part and the imaginary part are split
$Re(z) = 2^n \cos{(\frac{\pi}{6}n)}$
Learath2
But $2^{n} \neq 0\ \forall n \in \mathbb{N}$
Learath2
did i make a mistake somewhere?
No, you just stopped there for whatever reason
I just went on and split it into Re and Im, and set them equal to 0
ok i found n = 3 + 6k (with k€Z) <=> purely imaginary
and n = 6k <=> purely real
Looks good to me 
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Yo
Why the hell did you pin that
the first post you make should be your question, asked in a clear concise manner
the bot auto pins that to make it easier for people to find the original question you are stuck on
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Anyone know whats the idea here?
tg=tan ctg=cot, different notation in my country
And theres a missing parenthesis at the end of ctgx
Write numerator completely in terms of tan x
And use log properties, then substitute t=tan x, so dt=sec²x dx
So the whole integral reduces to..
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Hi
Show your work
So i found out the values from my book of sin and cos
I feel like i Did something wrong
It's actually right
I don't suggest checking values from book
Get to know of basic trig. identities
Yeah i have to work on that. In my quiz test I only have these options so i think my answer is wrong
It says mark the answer to the expression
Haha Yeah not the first time..
But my answer is correct right?
Yes
Ty!
F(x)=4+1/x has No x and y with horizontal tangent right?
Well, F'(x)=-1/x²
Equating it to zero just gives infinity
The graph will be asymptotic to y-axis
Oh
So, there's no horizontal tangent for this function.
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X
Here is what I did:
Questions:
- Is my work above incomplete? Do I have to show that if x and y are both rational, then 3x+5y can't be irrational?
- Would it have been faster if I proved the contrapositive?
Think proof by contradiction is easiest
I did do a contradiction here, but see question 1)
You've proved that if x is rational and y is irrational or vice versa then 3x+5y is irrational
That's not what you want to show
You’d only have the case where both are rational
For conjecture to be true:
case 1: x is rational, y is irrational, 3x+5y is irrational
case 2: x is irrational, y is rational, 3x+5y is irrational
case 3: x is rational, y is rational, 3x+5y can't be irrational
I have the intuition for this too, but why exactly?
I can't put it into words
But I agree with you
You're given that 5x+3y is irrational
and moreover, why do I not have to consider the case where x is irrational and y is irrational? (This case was weird to me because consider x = sqrt(2)/3, y = - sqrt(2)/5) but i guess at least one doesn't necessarily mean "both" has to be true
right
3x+5y
I assumed the negation is true and found a contradiction
I missed this text but yes, 1 is the contrapositive
ohhh
contrapositive here is "x is rational, y is rational, so 3x+5y can't be irrational" ?
I don't understand this concept very well, (even though I have googled it) please bear with me
Yes
Oh
"A contrapositive statement occurs when you switch the hypothesis and the conclusion in a statement, and negate both statements."
So hypothesis: x is irrational or y is irrational.
Conclusion: 3x+5y is irrational.
contrapositive:
Negated hypothesis: x is rational or y is rational.
Negated conclusion: 3x+5y is rational.
$A\implies B \iff \lnot A \impliedby \lnot B$
giannis_money
Got it
So I have to switch the order of A and B/
I have to go from 3x+5y is rational -> x is ratiojnal or y is rational?
If P then Q | if not q then not p
No
is that not switching A and B ?
.
B is necessary for A so if B is false A can't be true. That's what the contrapositive means
Tim O’Brien
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reaction for more information.
(You may edit your message to recompile.)
B and A should be switched at the beginning
That is a bit confusing
Read the qn
if A = X or Y
then (not A) = (not X) AND (not Y)
so your second line here is wrong
Oh
Oh right we learned that
Alright thanks a lot, I will show the contrapositive now
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i need help with some
linear problems
that has connections to pythoagoras
tangent lines to circles
midpoint, distance formula
perpendicular lines
distance from line to a point
i have some example questions
i think i can do them i just need someone to like
explain to me how it works
i hate my life
@formal hornet Has your question been resolved?
FK
the easy way to start this is to draw the figures
lets do 1 then
no the points given in the question
so b and c are unknown points
yea
but we know ABC is. a triangle
yep
and we know that M is the mid point of
BC and so we can
work out where B and C is
well no we need B first
we can find b by
finding the perpendicular of N?
no
fk
start with the first part of the question
okay
it will give the clue to finding where B is
A (7, 8) N (3, 4)
so find the slope
8-4 over 7-3
4 / 4
or slope is 1
y = x + c
plug a values
8 = 7 + c
c = 1
so a) y = x + 1
right
yep
yes
what they're saying is
there's a line going through M
that is perpendicular to BC
and hits N?
but not perpendicular to AB
exactly
how tf
so what is the next step
draw the line between M and N
yes but B can be anywhere on y=x+1
wait lemme get my
drawing thing
this what we know so far right
oh i am stupid
find equation of NM
I have this for where we're at
yep
yep
2 = -8 + c
c = 10
y = -2x + 10
now set
y = x + 1 = y = -2x + 10
x + 1 = -2x + 10
3x + 1 = 10
no
now you're just finding N again
bruh
this line
fck
is perpendicular
to BC
so what should you do first
y = -2x + 10
negative recipricals
so BC is
y = 1/2x + c
right
2 = 1/2(4) + c
yes
good

