#help-0

1 messages · Page 31 of 1

robust copper
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i will try

wide raven
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if you are not able to do it

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i think the only way we would be to show you how to do it

fleet mist
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hmmm @wide raven excuse me, i was in this channel someone tried to help me. But since i'm a helpless cause i didn't find my answer

wide raven
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@fleet mist i don't mind you pinging, but others might

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and about your question

fleet mist
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oh sry

wide raven
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you can ask it again, on a different channel

fleet mist
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ok thank u!

wide raven
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someone would help ya

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maybe even i can if i can solve that problem

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just ask it

lone heartBOT
#

@robust copper Has your question been resolved?

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alpine sable
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can someone help ?

lone heartBOT
alpine sable
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<@&286206848099549185>

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someone please help

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i been stuck for 1 hour

lone heartBOT
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@alpine sable Has your question been resolved?

long axle
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which one are u stuck on

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number 16?

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@alpine sable

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@alpine sable Has your question been resolved?

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turbid stratus
#

Hello , what’s the formula for Gradient ?

rose sigil
languid bolt
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$m = \frac{x_2 - x_1}{y_2 - y_1}$

ocean sealBOT
lone heartBOT
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@turbid stratus Has your question been resolved?

keen plinth
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even if they did mean gradient of a line

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its usually given the other way round

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$m = \frac {y_2 - y_1} {x_2 - x_1}$

ocean sealBOT
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夢雪

rose sigil
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and there is no mention of what, m, y_1, y_2, x_1, and x_2 are

languid bolt
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i forgot

lone heartBOT
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severe sequoia
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could someone help me figure out how to approach this ODE problem? I am trying to verify the implicit solution on the left side.

severe sequoia
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I think what I need to do is get the 1st and 2nd derivative of the left side? and then if I tried to isolated y'' I could then verify if it matches the left? or is there a simpler approach?

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this is what I have so far, but honestly I don't know if it's right... if it is, then I have no clue how to isolate y'' sad

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#

@severe sequoia Has your question been resolved?

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@severe sequoia Has your question been resolved?

lone heartBOT
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edgy sand
lone heartBOT
edgy sand
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hey guys I have a, b ,c and d values for this one and get that I can graph the function by putting into desmos but what does the x> -b/2a mean?

worn fox
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only plot x values bigger than -b/2a

edgy sand
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ah gotcha thanks

#

.close

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edgy sand
lone heartBOT
edgy sand
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hey guys I have a, b ,c and d values for this one

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how do i know what the point coordinates will be?

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i get the c would just be the c value itself

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would f(c) be the function with c value plugged in for x?

paper ridge
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pretty much

edgy sand
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ok ty

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.close

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neat frost
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Hi, I'm working on Herstein 2.3.14 and I don't really understand the answer. Suppose a finite set G is closed under an associative product and that both cancellation laws hold in G. Prove that G must be group

neat frost
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The solution makes no sense since it just shows that you can solve both ax = b and ya = b and stuff online talks about bijections, but I don't really see how this PROVES that an identity elemetn exists and therefore, each element in G has an inverse in G

ionic trail
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If you can solve ax = b, for any a,b then there exists an inverse for every a, since you can solve ax = e, no?

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(e = neutral element)

neat frost
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yea, this is where I get stuck, i feel like it's really simple so I don't know why I don't get it. So if I can ax = b, x = ba^{-1} = e?

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I just don't see why that necessiates a natural element

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unless that above is the explanation?

ionic trail
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Being able to solve ax=b for any a,b is way stronger than having an inverse for every element. Because in particular, you can solve ax = e for any a (just be replacing b with e).

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If ax = e for some a, then x is the inverse of a by definition.

neat frost
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OHHH I SEE

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thanks so much I've literally been reading the same few passages and not making this connection for some reason

ionic trail
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Alright😅 yw

lone heartBOT
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@neat frost Has your question been resolved?

lone heartBOT
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granite dirge
lone heartBOT
granite dirge
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Idk how to do 14

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I got DNE as my answer but that’s not right

vale wigeon
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multiply by the conjugate

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or more precisely

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multiply numerator and denominator by (sqrt(x)+2)

granite dirge
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Oh ok I will try that now

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Thanks

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x-4/sqrtx - 8?

vale wigeon
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no, doing what i described will not give $x - \frac{4}{\sqrt{x}} - 8$.

ocean sealBOT
vale wigeon
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it won't give $\frac{x-4}{\sqrt{x} - 8}$ either, but you should've been more careful with parentheses to write that.

ocean sealBOT
granite dirge
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1/sqrtx + 2 is what I have so far

vale wigeon
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no, you don't have $\frac{1}{\sqrt{x}} + 2$.

ocean sealBOT
granite dirge
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you know what I mean

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lol

vale wigeon
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no, i do not.

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and i will insist that you parenthesize fractions properly.

granite dirge
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the 2 is under

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ok ok

vale wigeon
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ok, then write 1/(sqrt(x) + 2).

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not 1/sqrt(x) + 2.

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unless you're one of those people who likes not being understood.

granite dirge
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😂😂

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thanks for the help

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.close

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limpid garnet
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|P(A ×B)|

lone heartBOT
limpid garnet
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Suppose that |A| = m and |B| = n. Find the following cardinalities.

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would the cardinalities be 2^(m+n)

vale wigeon
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no

limpid garnet
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sorry i am confused

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what would (A x B) look like?

vale wigeon
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A x B is the Cartesian product of A and B

limpid garnet
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so (A,B) right?

vale wigeon
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...no?

mortal trellis
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${(a,b): a\in A, b\in B}$

ocean sealBOT
#

Denascite

limpid garnet
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pls

vale wigeon
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|P(A x B)| = 2^|A x B| = 2^(|A| * |B|)

limpid garnet
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so 2^(m*n) is the answer

limpid garnet
lone heartBOT
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@limpid garnet Has your question been resolved?

mortal trellis
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yes

lone heartBOT
#

@limpid garnet Has your question been resolved?

lone heartBOT
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alpine sable
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can i get help

lone heartBOT
alpine sable
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its with business calculus

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does anybody understand excel up in here !!!

keen pasture
alpine sable
molten pivot
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Just ask

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I can probably help

alpine sable
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okay

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alright so

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HOW IN THE WORLD

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i know the answer is right there but lord

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can we go on call or something??

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like i literally do understand how to evalute that function

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for it to turn into whatever the hell they got

molten pivot
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Alright

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The first one is:
$2 × (2^2+1)^3$

ocean sealBOT
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Mr. Gamer

molten pivot
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The second one is

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$(2^2+1)^{2×3}$

ocean sealBOT
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Mr. Gamer

molten pivot
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Does that make sense?

alpine sable
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no .

molten pivot
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The exponent would normally just apply to the next term, if you want to raise something to the power of a longer expression then you have to group it together

alpine sable
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how do u get there

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okay wait

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so is it just where u put the similar things together

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in the equation

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hol on

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im abt to drop this class cuz wtf

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mr gamer help!

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i havent taken a math since sophmore year

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i am a sophmore in college

molten pivot
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There is an order in which we evaluate operations

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We start with parantheses

alpine sable
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PEMDAS

molten pivot
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Yes

alpine sable
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f(2)= (2^2 + 1) ^ 3*2

molten pivot
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Look at the first problem

alpine sable
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okay so how do u do tht here?

molten pivot
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Evaluate whats inside the parantheses first

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What is 2² + 1?

alpine sable
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um . 5.

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right?

molten pivot
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Yes

alpine sable
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OHHHH i SEE

molten pivot
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So then we have:

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5³ × 2

alpine sable
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ok so ur doing the paranthese

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hold on

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WAIT.

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(5) 3^2

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so do we do the expontnet ?

molten pivot
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Not quite

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It's 5³ × 2

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Or 5^3 * 2

alpine sable
molten pivot
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Now we do the exponent

alpine sable
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OH

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but why did u leave the 2 by itself?

molten pivot
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I thought we were looking at the first one, weren't we?

alpine sable
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yea

molten pivot
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The 2 is not inside the parantheses there

alpine sable
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which 2 are u talking abt

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bc im refering to the 3*2

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bc we already solved what was inside the parantheses

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now we have

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^ (3*2) left

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5 ^3*2

molten pivot
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Ok lets be clear which problem we are referring to then

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Which one?

alpine sable
molten pivot
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Ok

alpine sable
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the first

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and the question is asking

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which one of those equations correctly evaluates whatever the hell this is

molten pivot
alpine sable
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right

molten pivot
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So that turns into 5^(3×2)

alpine sable
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right

molten pivot
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Then we evaluate what's inside the parantheses

alpine sable
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so it would beeeee

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6 right

molten pivot
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Yes

alpine sable
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OM

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GG

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mr gamer. i am so sorry if im making u frustrated but BARE WITH ME.

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ok so 5^6

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okay so now this one

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there is no parathenses

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soo would it be the same process?

molten pivot
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Yes, do whats inside the parantheses first

alpine sable
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ok soo 5

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5 ^3*2

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then u would do exponent first

molten pivot
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Yes

alpine sable
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so 5^3

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umm i dont have my caclulator

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one sec

molten pivot
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Yeah

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Thats 125

alpine sable
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ok boom !

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thenn

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its 125 * 2

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right?

molten pivot
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Yep

alpine sable
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OK

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so i am assuming

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the right answer is

alpine sable
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cuz it gave us 5^6

molten pivot
#

Yes

alpine sable
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WHEW

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can i add u ?

molten pivot
#

Sure, but I don't use discord too much

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Try using these help channels if anything else comes up

alpine sable
#

what if i need help

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ok !

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imma wish u the best in life everyday

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we need more people like u

molten pivot
#

👍

lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
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potent yacht
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hello

lone heartBOT
potent yacht
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what does this symbol mean?

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like the one in the middle

uneven maple
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exponent

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9^(-12)

potent yacht
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im confused

uneven maple
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oh uh

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did you learn negative exponents

potent yacht
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as in like

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-1

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-2

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?

uneven maple
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like 3^-2

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is 1/9

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do you know how that's done

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do you know powers

potent yacht
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yes i do

uneven maple
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okay

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so it's 9 to the power of negative 12

potent yacht
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ohhh

uneven maple
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you just have to know the trick for negative exponents

potent yacht
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which is? lol sorry i just started school again and my brain is still in summer mode lol

uneven maple
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it's just

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1/(9^12)

potent yacht
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bro

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tysm

uneven maple
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cool yeah

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any other questions?

potent yacht
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nope

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ty!!!

uneven maple
#

np

lone heartBOT
#

@potent yacht Has your question been resolved?

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scarlet shale
lone heartBOT
scarlet shale
#

i dont really know if the line L is a positive or negative gradient, and im not quite sure what does it mean by 30^o with the positive direction of x-axis

strong compass
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Between the line l and the X axis is 30 degrees, I feel like it is most obvious for it to have a positive gradient imo

scarlet shale
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but then if it has a positive gradient then how is the line perpendicular to L passing through (0,-4)?

strong compass
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Like that, the red line is l and blue perpendicular

scarlet shale
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ohhhhh i seee

strong compass
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Make sense?

scarlet shale
#

yep

strong compass
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Cool do you know how to do it from here

scarlet shale
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not quite since i have not found out the coords yet

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wait no i have to coords

strong compass
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What coords?

scarlet shale
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(0,-4) and (0,0)

strong compass
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Right

scarlet shale
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then i can find the gradient of line L

strong compass
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No

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L doesn't go through 0,-4 the perpendicular line does

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You need another point that lies on L to find it's gradient

scarlet shale
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is it an equation or something?

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cuz i got no clue

strong compass
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Let's say y=4x

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Do you know what the gradient of the line perpendicular to it would be?

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That's parallel

scarlet shale
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sorry wrong thing

strong compass
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It's all good

scarlet shale
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-1/4

strong compass
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Yes cool

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So you know that l makes 30 degrees a the X axis, so I suggest we find the function that makes l first

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Then we can find the equation of the perpendicular

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Does this diagram remind you of something, ignoring the y axis?

scarlet shale
#

a pencil tip? 🤣 i dont really remember anything apart from that sorry

strong compass
#

Do you see the triangle?

scarlet shale
#

?

strong compass
scarlet shale
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ohh ok

strong compass
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So if the base of the triangle is 1, what is the height

scarlet shale
#

root3/3 units

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is it?

strong compass
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Yeh

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Do you see how you just found another coordinate

scarlet shale
#

ohhhhhh (1, 0.6)

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or do it with the frraction

strong compass
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I would keep as root3/3

scarlet shale
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ok

strong compass
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Now find the gradient of l

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L goes from (0,0) to (1,tan(30))

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I put tan 30 cause easier to type lol

scarlet shale
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that's fine

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so m = tan30/1

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so basically tan30

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perpendicular gradient = -root3?

strong compass
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Yeh

scarlet shale
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so that's question done

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y-b=m(x-a)

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sub in (0,-4) and -root3

strong compass
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Yeh that's the last step making the equation

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Yeh

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Tbh

scarlet shale
#

thank you soooo much

strong compass
#

You don't even need to do that it's just y=-root 3 -4

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Because -4 is the yintercept when X is 0

scarlet shale
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yeah but it's homework so i gotta show everything

strong compass
#

Fair enough

scarlet shale
#

thank you for your help again

#

life saver

strong compass
#

No worries 👍

scarlet shale
#

have a nice day!!

strong compass
#

You too

scarlet shale
#

.close

lone heartBOT
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past wave
#

This right?

lone heartBOT
past wave
#

Ah shit

#

-9/2 not -5/2 💀

#

I'm dumb

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@past wave Has your question been resolved?

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twin jolt
#

tan(x)=-sqrt3

lone heartBOT
twin jolt
#

work out for x

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@twin jolt Has your question been resolved?

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tawdry temple
#

.open

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@tawdry temple Has your question been resolved?

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@tawdry temple Has your question been resolved?

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edgy flare
lone heartBOT
edgy flare
#

I have this so far:

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Not sure if my reasoning is correct. Any advice is appreciated.

rose sigil
#

not sure exactly what you are doing there but it does not look right

edgy flare
#

I think I am mis-remembering the rules of nth roots

oak perch
#

5^2=25=1 mod 8 therefore 5^2n=1^2n=1 mod 8

rose sigil
#

why are you taking any roots at all?

edgy flare
#

to get rid of the n power on the (5^2) term

#

and taking the nth root of 1 is = 1

rose sigil
#

so are you saying... nthroot((5^2)^n - 1) = (5^2) - 1 for any n?

edgy flare
#

Then stat that 5^2 ^ n = 25 ^n

#

25 = 1 mod 8

#

1 ^ 2n = 1 for all n s.t. n is a natural number

#

thus 1 - 1 =0 mod 8

oak perch
#

No

edgy flare
#

as needed?

oak perch
#

Literally what I typed is sufficient

slow hound
#

@edgy flare are you aware of how mod rules work?

edgy flare
#

Yes.

slow hound
#

usually when proving something you dont start with the conclusion

edgy flare
#

I have an extremely picky professor for intermediate analysis, and she will count off if it is not explained well enough. So I am very cautious on how in depth I need to state before using something.

real gazelle
#

It is the job of an analysis professor to be picky

#

Because usually the students taking the class don't know how to write proofs

#

Lol

#

what cogwheels of the mind said is good though

edgy flare
#

Okay. I just suck at proofs, so I need as many points on every assignment to counter balance if I do poorly on quizs/tests

#

Thanks @oak perch

#

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alpine sable
#

what is -9/9 💀

lone heartBOT
wary stream
alpine sable
#

1

wary stream
#

And -9/9 is the same as -1 * 9/9

alpine sable
#

so -1

wary stream
#

Yes

alpine sable
#

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alpine sable
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.reopen

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alpine sable
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lament cloak
#

How do i graph this function to find the limit

lament cloak
fathom kite
#

since its continuous at w = 3.3, you can just find the value of f(w) at x = 3.3

#

that will be the limit

lament cloak
#

yea i did that

#

and got 0.86

#

but it still tells me im wrong

#

i mean i got 0.938

fathom kite
#

i think its just a problem of the logic

lament cloak
#

oh im stupid

fathom kite
#

since 3.3 is .34(first ounce) + .26(second ounce) + .26(third ounce) + .26(fourth ounce)

lament cloak
#

i read the problem wrong

#

yea ur right

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uneven cove
#

Help

lone heartBOT
uneven cove
#

Pls,,., i have been here for 4 hours

solar granite
#

Is it solving for x?

#

^

uneven cove
#

Ih my god

#

I love u

#

i love u so much

#

i love u

#

ily

#

ur tbe best

#

i was crying

#

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vivid pond
lone heartBOT
vivid pond
#

so I know that the conjugate is another zero

#

-3i

#

but I'm not exactly sure how to find the last zero

ocean sealBOT
gray isle
#

once you know 2 of the roots, finding the last could be achieved from vietas formula

slow hound
#

oh shit thats brain

gray isle
#

more convenient would be using the sum

#

also not quite

slow hound
#

right right

#

divide by 2

vivid pond
#

so x^2-9

slow hound
#

dont do it my way

vivid pond
#

and then divide how

next thorn
#

.reopen

ocean sealBOT
gray isle
#

prod would be -d/a = -45/2

vivid pond
#

err

#

confused sorry 💀

#

shouldn't it be 3

#

from x^2-9=0

#

it'd become x=3?

#

oh it's -5/2

#

thanks

#

I'm actually not sure about this one

lone heartBOT
#

@vivid pond Has your question been resolved?

serene junco
#

@vivid pond You still here?

#

What have you tried for this one?

vivid pond
#

oh sorry forgot to close it

#

deadline was 15 mins ago

#

thanks though 🫡

serene junco
#

no worries

vivid pond
#

.close

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gilded kiln
lone heartBOT
gilded kiln
#

how is this wrong

vale wigeon
#
Five independent trials of a binomial experiment with probability of success p=0.6 and probability of failure q=0.4 are performed. Find the probability of the following event rounded to five decimal places:

At least 4 successes
#

(transcribing the problem here so as not to have to squint)

#

your answer is 0.02016. how did you calculate this?

gilded kiln
#

no worires

#

i figured it out lmao

#

sorry to waste ur time

#

i multipled % of winning 4 and % of winning 5 instead of adding

#

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wise jewel
lone heartBOT
wise jewel
#

how r they getting these numbers?

tacit arch
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dapper tide
#

what does epsilon denote in the context of sequences?

vale wigeon
#

are you looking at the epsilon-N definition of limits?

dapper tide
#

idk

#

my professor defined it as

#

the scale of small limits

#

and just went on

tacit arch
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grizzled cliff
#

Hello guys! I need help with this question me and my classmates have been stuck on.

tribal oxide
grizzled cliff
#

Nevermind we found the answer thank you. It was (-1)^i(2+i).

#

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dull leaf
#

This is a previous exam, and the professor did not include a solution , can someone please check my answer for part 1

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@dull leaf Has your question been resolved?

dull leaf
#

awesome thanks @naive valley catlove

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safe pewter
#

So i am confused where to ^2 comes from that is applied to 1?

worn fox
#

What is 1²?

safe pewter
#

just 1

worn fox
#

So it doesn't matter which we write

#

They've done it to make you spot a factorisation technique as the next step

safe pewter
#

Ah okay so its a logic trick to factorise

#

thanks you very much! ^^

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modern pollen
lone heartBOT
modern pollen
#

Hi, I have this permutations and combinations question

#

usually for these questions, they only ask if C is to the right of 1 O instead of 3, because then you can simply divide the total number of arrangements by 2

#

however this question has multiple o's so I am somewhat confused as to what to do

#

oh i should clarify I am talking about b) and c), a) is quite straightforward

#

so I tried a case study with b) however I can't quite get it to work

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modern pollen
#

.reopen

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frigid lintel
#

Hey. I am wondering if anyone could help me understand this example question in my exercise book.

It says that the average return is calculated by P(winning) * value of win.

The example has three prizes, $1000 for first place, and $100 for second and third place.

But the example says P(1st) * 1000 + P(2nd) * 100 + P(3rd) * 1000

I don't understand why P(3rd) is multiplied by 1000. Shouldn't it be 100 since that is the value winning of 3rd place?

Here is the example question from the book.

Any help is appreciated. Thanks.

grave island
#

,rotate

ocean sealBOT
frigid lintel
grave island
#

yea

#

its a typo

#

see how they did 1/318*100 in the next line

frigid lintel
#

Ah, I didn't even notice that. Thank you! I am blind

grave island
#

all g lmao

frigid lintel
#

I have one more question about it also. I am confused about the probably of losing * value of losing. Why is it multiplied by 0? Is the value of losing not the $5 to play? How do you determine the value of losing?

grave island
#

bc u get nothing if u loose

#

lose

#

then they say all that is ur average return 3.75 right

frigid lintel
#

Okay so the price of playing is not the same as the value of losing even though in a sense you have lost the $5?

#

Sure

grave island
frigid lintel
#

Can you think of any example where the value of losing isnt 0?

#

Just to help clarify

grave island
#

$1

#

no matter what u draw

frigid lintel
#

Okay. Thanks for the help dude, appreciate it

#

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#
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viscid wren
#

The only context I can give is this is vector calculus, I have no idea what to do though

vale wigeon
#

,rccw

ocean sealBOT
vale wigeon
#

what are u and v?

viscid wren
#

I’m assuming one is a vector u and the other is vector v

#

It wants to create a vector uv maybe? I’m not sure

vale wigeon
#

no that is not what i'm asking

#

did you get this problem from a textbook?

viscid wren
#

Yes I copied this problem straight out of my textbook

#

Like word for word

vale wigeon
#

show the textbook itself

#

if so then there should be an instruction nearby that tells you the values of u and v

#

they are vectors and that much is clear from context

#

but we do not know what vectors they are

viscid wren
vale wigeon
#

see, ok

#

you have it right there

viscid wren
#

Oh my god

vale wigeon
#

they say u = <1, 1> and v = <-1, 1>

viscid wren
#

I’m such an idiot

#

It’s too late for this

vale wigeon
#

does this now enable you to do the problem?

viscid wren
#

Actually never mind I’m still a bit confused

vale wigeon
#

you need to find scalars $c_1, c_2$ such that $c_1 \ang{1, 1} + c_2 \ang{-1, 1} = \ang{4, -8}$.

ocean sealBOT
viscid wren
#

Oooh I see

#

So I’m setting both u+v=<4,-8>?

vale wigeon
#

...

#

no?

#

that's not what i said at all.

viscid wren
#

Haven’t done any sort of math in 3 months you’re gonna have to give me a break. Am I creating a system of equations for this or what

vale wigeon
#

you could do some algebra to the left-hand side to write it as one vector, then equate the x-components and the y-components on both sides amd yes, you would get a system of equations from that

viscid wren
#

I’m good to distribute the c1 and c2 to both the u and c right?

vale wigeon
#
  1. your angle brackets don't have much angle to them. that's something you need to fix.
#
  1. c_2 <-1, 1> = <-c2**,** c2**>**
#

that comma just up and disappeared and it looked like you were writing <0>

viscid wren
#

Ya lol just a sleep deprived I put the +

vale wigeon
#

why are you doing math when sleep-deprived??????

#

are you on a deadline?

viscid wren
#

Some personal stuff came up and I have to finish this textbook hw another one and a quiz before 8 am Thursday

#

But ya I am I guess

#

That’s my final answer. Not sure if I did my system wrong it’s been a few years since I’ve done these.

vale wigeon
#

seems ok

viscid wren
#

Alright well thank you.

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#

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boreal stag
lone heartBOT
boreal stag
#

Qbi,bii

keen pasture
#

What have you tried?

lone heartBOT
#

@boreal stag Has your question been resolved?

boreal stag
#

Cant get it

keen pasture
#

We say we throw a dice. It does not matter what the result of the 1st throw is. There can't be the same number again. So how many different numbers are possible for the 2nd dice?

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#
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boreal stag
#

.reopen

lone heartBOT
#

alpine sable
#

and so the third 4/6

boreal stag
#

What about bii

raw fractal
boreal stag
#

oh

#

.close

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boreal stag
lone heartBOT
boreal stag
#

Need help with ai and aii

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#

@boreal stag Has your question been resolved?

alpine sable
boreal stag
#

But the photo i seen was clear

#

.rotate

#

Is this ok?

#

@alpine sable

junior phoenix
#

how do u do question 6 😅😅

boreal stag
#

???

alpine sable
boreal stag
alpine sable
#

No, not really sorry

lone heartBOT
#

@boreal stag Has your question been resolved?

potent bane
#

1out of 6

#

There are 2 possibilities that the arrow goes down or to x

#

1 out of 2 chance

#

The dice is 1 out of 3

#

1 out of 3 × 1 out of 2 = 1 out of six

#

This is my guess

#

A i

#

A ii is uhhh

#

1 out of 4 chance of getting y

#

1 out of 4 × 1 out of 3 = 1 out of 12

#

Chance

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wanton hearth
#

for what n $(\sqrt(3) + i)^n$ is a purely imaginary? purely real?

ocean sealBOT
wanton hearth
#

idk how to resolve this

#

i know that if we want a purely real then Im(z) = 0 and a purely imaginary then Re(z) = 0

half epoch
#

Write the inside of the exponent in the polar form

rose gate
#

also recall that arg(z^n) = n arg(z)

half epoch
#

Or if you are familiar with it the exponential form due to eulers formula can also make it obvious

wanton hearth
#

Ok I'll test that

lone heartBOT
#

@wanton hearth Has your question been resolved?

wanton hearth
#

i found $(2e^{\frac{\pi}{6}})^n$

#

so $2^n e^{\frac{n\pi}{6}}$

ocean sealBOT
wanton hearth
#

i repass it to the algebric form

#

$2^n cos(n\frac{\pi}{6}) + i (2^n sin(n\frac{\pi}{6})$

ocean sealBOT
wanton hearth
#

but now idk how to resolve Re(z) = 0 and Im(z) = 0 cause i still have some power n

half epoch
#

Notice in this form the real part and the imaginary part are split

#

$Re(z) = 2^n \cos{(\frac{\pi}{6}n)}$

ocean sealBOT
#

Learath2

half epoch
#

But $2^{n} \neq 0\ \forall n \in \mathbb{N}$

ocean sealBOT
#

Learath2

wanton hearth
#

did i make a mistake somewhere?

half epoch
#

No, you just stopped there for whatever reason

#

I just went on and split it into Re and Im, and set them equal to 0

wanton hearth
#

ok i found n = 3 + 6k (with k€Z) <=> purely imaginary
and n = 6k <=> purely real

half epoch
#

Looks good to me Celebrate

wanton hearth
#

ok thx

#

.close

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alpine sable
#

Yo

lone heartBOT
alpine sable
#

Why the hell did you pin that

gray isle
#

the first post you make should be your question, asked in a clear concise manner
the bot auto pins that to make it easier for people to find the original question you are stuck on

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fleet thistle
#

Anyone know whats the idea here?

lone heartBOT
fleet thistle
#

tg=tan ctg=cot, different notation in my country

#

And theres a missing parenthesis at the end of ctgx

kindred anchor
#

Write numerator completely in terms of tan x

#

And use log properties, then substitute t=tan x, so dt=sec²x dx

#

So the whole integral reduces to..

fleet thistle
#

Thanks!

#

.close

lone heartBOT
#
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kindred anchor
lone heartBOT
#
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mellow skiff
lone heartBOT
kindred anchor
#

Show your work

mellow skiff
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So i found out the values from my book of sin and cos

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I feel like i Did something wrong

kindred anchor
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It's actually right

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I don't suggest checking values from book

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Get to know of basic trig. identities

mellow skiff
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Yeah i have to work on that. In my quiz test I only have these options so i think my answer is wrong

kindred anchor
#

It has got very bad notation

mellow skiff
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It says mark the answer to the expression

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Haha Yeah not the first time..

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But my answer is correct right?

kindred anchor
mellow skiff
mellow skiff
kindred anchor
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No x and y with horizontal tangent?

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Wdym?

mellow skiff
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Does F(x)=4+1/x have points with horizontal tangent ?

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It’s a another question

kindred anchor
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Well, F'(x)=-1/x²

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Equating it to zero just gives infinity

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The graph will be asymptotic to y-axis

mellow skiff
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Oh

kindred anchor
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So, there's no horizontal tangent for this function.

mellow skiff
#

Yeah I figured thanks!

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Sorry forgot to close

#

.close

lone heartBOT
#
Channel closed

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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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fringe yoke
#

X

lone heartBOT
fringe yoke
#

Here is what I did:

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Questions:

  1. Is my work above incomplete? Do I have to show that if x and y are both rational, then 3x+5y can't be irrational?
  2. Would it have been faster if I proved the contrapositive?
brittle hedge
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Think proof by contradiction is easiest

fringe yoke
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I did do a contradiction here, but see question 1)

weary wyvern
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You've proved that if x is rational and y is irrational or vice versa then 3x+5y is irrational

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That's not what you want to show

fringe yoke
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?

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Really?

brittle hedge
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You’d only have the case where both are rational

fringe yoke
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For conjecture to be true:
case 1: x is rational, y is irrational, 3x+5y is irrational
case 2: x is irrational, y is rational, 3x+5y is irrational
case 3: x is rational, y is rational, 3x+5y can't be irrational

fringe yoke
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I can't put it into words

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But I agree with you

weary wyvern
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You're given that 5x+3y is irrational

fringe yoke
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and moreover, why do I not have to consider the case where x is irrational and y is irrational? (This case was weird to me because consider x = sqrt(2)/3, y = - sqrt(2)/5) but i guess at least one doesn't necessarily mean "both" has to be true

fringe yoke
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3x+5y

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I assumed the negation is true and found a contradiction

weary wyvern
fringe yoke
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ohhh

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contrapositive here is "x is rational, y is rational, so 3x+5y can't be irrational" ?

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I don't understand this concept very well, (even though I have googled it) please bear with me

fringe yoke
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Oh

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"A contrapositive statement occurs when you switch the hypothesis and the conclusion in a statement, and negate both statements."

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So hypothesis: x is irrational or y is irrational.
Conclusion: 3x+5y is irrational.

contrapositive:
Negated hypothesis: x is rational or y is rational.
Negated conclusion: 3x+5y is rational.

weary wyvern
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$A\implies B \iff \lnot A \impliedby \lnot B$

ocean sealBOT
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giannis_money

fringe yoke
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Got it

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So I have to switch the order of A and B/

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I have to go from 3x+5y is rational -> x is ratiojnal or y is rational?

brittle hedge
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If P then Q | if not q then not p

fringe yoke
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why can't I just go the other way around

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^

fringe yoke
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is that not switching A and B ?

weary wyvern
ocean sealBOT
#

Tim O’Brien
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

weary wyvern
#

B and A should be switched at the beginning

fringe yoke
#

That is a bit confusing

weary wyvern
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Read the qn

fringe yoke
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qn?

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question

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ok

finite spindle
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if A = X or Y
then (not A) = (not X) AND (not Y)

finite spindle
fringe yoke
#

Oh

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Oh right we learned that

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Alright thanks a lot, I will show the contrapositive now

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.close

lone heartBOT
#
Channel closed

Closed by @fringe yoke

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#
Available help channel!

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Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

formal hornet
#

i need help with some

lone heartBOT
formal hornet
#

linear problems

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that has connections to pythoagoras

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tangent lines to circles

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midpoint, distance formula

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perpendicular lines

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distance from line to a point

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i have some example questions

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i think i can do them i just need someone to like

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explain to me how it works

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i hate my life

lone heartBOT
#

@formal hornet Has your question been resolved?

formal hornet
#

FK

tawdry saffron
formal hornet
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lets do 1 then

tawdry saffron
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and do you know how to calculate a function from 2 given points?

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@formal hornet

formal hornet
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well

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wait let me draw it out ok

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and ill send an image

tawdry saffron
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I have an image

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if you want it

formal hornet
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oh sure ty

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of the triangle right

tawdry saffron
tawdry saffron
formal hornet
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so b and c are unknown points

tawdry saffron
#

yea

formal hornet
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but we know ABC is. a triangle

tawdry saffron
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yep

formal hornet
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and we know that M is the mid point of

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BC and so we can

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work out where B and C is

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well no we need B first

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we can find b by

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finding the perpendicular of N?

tawdry saffron
#

no

formal hornet
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fk

tawdry saffron
#

start with the first part of the question

formal hornet
#

okay

tawdry saffron
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it will give the clue to finding where B is

formal hornet
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A (7, 8) N (3, 4)

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so find the slope

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8-4 over 7-3

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4 / 4

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or slope is 1

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y = x + c

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plug a values

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8 = 7 + c

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c = 1

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so a) y = x + 1

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right

tawdry saffron
#

yep

formal hornet
#

k now

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we can find b by

tawdry saffron
#

yes

formal hornet
#

uhhh

tawdry saffron
#

what they're saying is

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there's a line going through M

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that is perpendicular to BC

formal hornet
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and hits N?

tawdry saffron
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and that line goes through N

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yea

formal hornet
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but not perpendicular to AB

tawdry saffron
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exactly

formal hornet
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how tf

tawdry saffron
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so what is the next step

formal hornet
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do i do this shit

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i need to find B

tawdry saffron
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draw the line between M and N

formal hornet
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y = x + 1 is the formula for

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AB

tawdry saffron
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yes but B can be anywhere on y=x+1

formal hornet
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wait lemme get my

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drawing thing

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this what we know so far right

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oh i am stupid

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find equation of NM

tawdry saffron
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I have this for where we're at

tawdry saffron
formal hornet
#

4-2/4-3 =

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2/1

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or 2

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so y = 2x + c

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i nean

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y = -2x + c

tawdry saffron
#

yep

formal hornet
#

2 = -8 + c

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c = 10

#

y = -2x + 10

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now set

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y = x + 1 = y = -2x + 10

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x + 1 = -2x + 10

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3x + 1 = 10

tawdry saffron
#

no

formal hornet
#

3x = 9

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x = 3

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shit

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what did i do wrong

tawdry saffron
#

now you're just finding N again

formal hornet
#

bruh

tawdry saffron
#

this line

formal hornet
#

fck

tawdry saffron
#

is perpendicular

formal hornet
#

ohhhh

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wait

tawdry saffron
#

to BC

formal hornet
#

waut

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wait

tawdry saffron
#

so what should you do first

formal hornet
#

y = -2x + 10

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negative recipricals

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so BC is

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y = 1/2x + c

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right

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2 = 1/2(4) + c

tawdry saffron
#

yes

formal hornet
#

2 = 2 + c

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c = 0

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how

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now

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1/2x = x + 1

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x = 2x + 2

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x - 2 = 2x

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-2 = x

tawdry saffron
#

good

formal hornet
#

y = 1/2(-2)

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y = -1

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B (-2, -1)

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right

tawdry saffron
#

one sec

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yea

formal hornet
#

k now

tawdry saffron
#

first find C

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should be easy