#help-0

1 messages · Page 10 of 1

vale wigeon
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and \bZ for integers

stable night
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OH

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ah okay yes

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so from here im not exactly sure how to show thats its not a perfect square

vale wigeon
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you showed that a+b is 2 times an odd number

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show that no perfect square can be 2 times an odd number

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perhaps by showing that all even perfect squares are necessarily divisible by 4, and two times an odd number never is

ocean sealBOT
stable night
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wait so im proving something inside my proof?

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like proving a general statement inside my proof

vale wigeon
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i think the proof of the general statement would best go BEFORE your proof proper

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so like

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Lemma: Let n be an odd number. Then 2n is not a perfect square.
Proof.
[proof of lemma goes here]
-----------
Claim: The sum of two odd perfect squares is never a perfect square.
Proof.
[your work thus far]
By the Lemma proved above, [...], being 2 times an odd number, is not a perfect square.
QED.
stable night
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alright

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one sec

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Lemma: Let n be an odd number. Then 2n is not a perfect square.\
n = 2k + 1, k $\in \bZ$ (by definition of odd numbers)\
2n = 2(2k + 1) = 4k + 2 (by basic algebra)\

Let a, b be odd perfect squares
Then, a = $(2m + 1)^2$ and b = $(2k + 1)^2$, m, k $\in \bN$ (by T1)
a + b = $4m^2 + 4m + 1+ 4k^2 + 4k + 1 = 2(2m^2 + 2k^2 +2m +2k +1)$ (by basic algebra)
a + b = $2(2(m^2 + k^2 +m +k) +1)$

ocean sealBOT
stable night
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okay Im actually not sure how to prove that something is/is not a perfect square.. my idea is that if the value of 2n was odd or something I could show that 2n cant be a perfecr square but now its even so im kinda lost

marsh rapids
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Can 4k+2 be a perfect square ? That's all you need to answer

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The rest is already done

stable night
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i dont have proper reasoning to say its not tho..

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like i cant think of it

marsh rapids
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Suppose it is

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Then we can write 4k+2 = p^2, and we know p is even

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Can you finish ?

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p^2 = (2q)^2 = 4q^2

stable night
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wait idk if im missing the picture but i still dont see why that proves a contradiction

marsh rapids
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Therefore 4k+2 is a multiple of 4

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But it can't

stable night
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OH

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wait so to prove contradiction

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we first assume something wrong

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then try to show that the result doesnt make sens

marsh rapids
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If P if the property we want to prove, we can show that (not P) => false, then by contraposition, true => P, therefore P

stable night
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ahhh i see

marsh rapids
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Wait

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Did you just not understand how to prove by contradiction but understood a formal logic proof ?

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That's kind of funny

stable night
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oh i knew how to prove by contradiction but i generally did it by proving something thats "related"

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like um

marsh rapids
stable night
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the 4k+2 is a multiple of 4 doesnt really link to the perfect square stuff and i didnt know we could do taht

stable night
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me understand

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lemme try to write out the full proof

marsh rapids
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But the contradiction can be anything

stable night
marsh rapids
stable night
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ahh i see

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then how do u know when to use contradiction/contraposition etc

marsh rapids
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That way you see if it leads to some nonsense

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What proof works best depends on the property. Look at what you need to prove with that method and ask "does that look easy" and pick the best option

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And if it proves hard, try something else

stable night
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ah okay i see

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thank u

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lemme summarize the proof

marsh rapids
stable night
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Lemma: Let n be an odd number. Then 2n is not a perfect square.\
n = 2k + 1, k $\in \bZ$ (by definition of odd numbers)\
2n = 2(2k + 1) = 4k + 2 (by basic algebra)\
Assume 4k + 2 is a perfect square.\
By definition, 4k + 2 = $(2q)^2$ (by T1)\
$(2q)^2 = 4q^2$\
$4q^2$ is divisible by 4, but 4k + 2 isnt. Contradiction.\
Hence, 2n must not be a perfect square.

Let a, b be odd perfect squares\
Then, a = $(2m + 1)^2$ and b = $(2k + 1)^2$, m, k $\in \bN$ (by T1)\
a + b = $4m^2 + 4m + 1+ 4k^2 + 4k + 1 = 2(2m^2 + 2k^2 +2m +2k +1)$ (by basic algebra)\
a + b = $2(2(m^2 + k^2 +m +k) +1)$

stable night
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so i should always try to use contradiction

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instead of direct proofs

marsh rapids
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No

ocean sealBOT
marsh rapids
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Direct works well sometimes too

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For proving equalities for instance

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Direct is still the usual method

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But if the result is obscure, contradiction can be nice because it gives you a starting point

stable night
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ahh i see

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okie dokie

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Lemma: Let n be an odd number. Then 2n is not a perfect square.\
n = 2k + 1, k $\in \bZ$ (by definition of odd numbers)\
2n = 2(2k + 1) = 4k + 2 (by basic algebra)\
Assume 4k + 2 is a perfect square.\
By definition, 4k + 2 = $(2q)^2$ (by T1)\
$(2q)^2 = 4q^2$\
$4q^2$ is divisible by 4, but 4k + 2 isnt. Contradiction.\
Hence, 2n must not be a perfect square.

Let a, b be odd perfect squares\
Then, a = $(2m + 1)^2$ and b = $(2k + 1)^2$, m, k $\in \bN$ (by T1)\
a + b = $4m^2 + 4m + 1+ 4k^2 + 4k + 1 = 2(2m^2 + 2k^2 +2m +2k +1)$ (by basic algebra)\
a + b = $2(2(m^2 + k^2 +m +k) +1)$ \
By the lemma proven above, a + b is not a perfect square.

ocean sealBOT
stable night
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is this okay?

marsh rapids
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It works

stable night
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ah okay i see

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tysm sir

marsh rapids
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It's far more detailed than I'd make it, but it depends on the expectations

stable night
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i wanna rpactice being formal hah

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also any advice for self learning maths xD

marsh rapids
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What level are you at ?

stable night
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im turning 15

marsh rapids
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That's quite young to know that much logic

stable night
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idk my mom sends me for extra math classes lol

marsh rapids
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Cause for HS level stuff, there's Khan academy, but it won't help you for proof based math

stable night
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oh i wanna self learn like discrete maths and linear algebra kind

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some people said its good to learn these early on

halcyon niche
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definitely

marsh rapids
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Proofs are done by practicing, finding new techniques, getting experience and intuition for things. That kinda of stuff

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Are you French?

stable night
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nop

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oh so ill just practice more

marsh rapids
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That's a weird "about me" lol

stable night
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XD

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okay tysm

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i shall go back to doing work

marsh rapids
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Don't really have any non-french resources for proofs unfortunately

stable night
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aww

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how about youtube

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ive seen some nice videos on graph theory but not much on proofs

marsh rapids
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Try to find an online pdf on your topic, maybe some teacher's website or some academic resource

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That explores a topic and includes proofs for everything

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Don't have any of that in English though

stable night
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hmm ill try my best to find some

marsh rapids
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And exercises to practice it yourself

stable night
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yessir

marsh rapids
stable night
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should i also try studying calculus if i have time

marsh rapids
stable night
marsh rapids
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Calc is very important

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It's usually studied partially in high school, while a lot of the proof based stuff only comes after it

stable night
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oh i did study abit on calc

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its taught like

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next year for me

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i think

marsh rapids
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Not very surprising

stable night
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im rly bad at it blobcry

marsh rapids
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Calc 1 is just memorisation

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There's no actual thinking

stable night
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woooot

marsh rapids
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Calc 2 is where thinking is required and it can get tough if you don't have the right ideas

marsh rapids
# stable night woooot

It's just knowing elementary derivatives, differentiation rules, basic properties and theorems. Limits can be more involved, but basic calc 1 limits are hardly a problem, though they are more like calc 2 for the approach

stable night
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i see

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so ill try finding resources online

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and read thru and practice some qns

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lemme try finishing discrete maths first xD

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okay tysm sir

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ive learnt alot

marsh rapids
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Calc is doable on Khan academy btw

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Since it's not proof based

stable night
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OH

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okay

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me will check it out catthumbsup

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thank u

lone heartBOT
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@stable night Has your question been resolved?

lone heartBOT
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alpine sable
lone heartBOT
marsh rapids
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The line above is what we want, but we don't do any computations with it here. We start from P(k) and add k+1 to get the LHS, and then we transform the RHS into what we want

alpine sable
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when/where do they add the k term, which we say to be equal to k(k+1)/2

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oh i see, its added to the right below my red line

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so then we add our k+1 term..

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so where does the (k+1)(k+2)/2 = k+1 come back in

marsh rapids
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That last message makes no sense. This equality doesn't even hold

alpine sable
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k+1 = what i wrote above

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that you said makes "no sense"

marsh rapids
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The sum is equal to the product. Not k+1 alone

alpine sable
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ok the k+1 version of the P(n) expression

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P(k)

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can you just help me i don't understand

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every time i come to this server people talk down to me without helping at all

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.close

lone heartBOT
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lone heartBOT
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misty notch
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i need to calculate the area of that triangle

misty notch
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abit confused but i think angle BCA is 90

vale wigeon
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that is indeed true given the equations you've written

misty notch
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yeh i figured cuz of the slopes

vale wigeon
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it also appears that your triangle has a height of 4 and a base of 21 - 1/5

misty notch
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so just 1/2 x 4 x 20.8

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if i considered AC to be the base

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i would get the same answer right?

lone heartBOT
#

@misty notch Has your question been resolved?

lone heartBOT
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distant cove
lone heartBOT
distant cove
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what can i mark as T=...?
in order to solve this one

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original equation:

keen socket
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why cant u just take natural logs on both sides

distant cove
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we can't use logs yet unfortunately

keen socket
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oh

distant cove
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we aren't allowed to, to be exact

alpine sable
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You want to solve for x?

distant cove
alpine sable
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You wrote T for some reason

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Okay

distant cove
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no

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i mean t for any substitue

keen socket
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to reduce to a linear expression

distant cove
alpine sable
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maybe (3/2)^x

keen socket
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wat

alpine sable
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or (3/2)^(x/2), shouldn't matter much.

distant cove
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how

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refer to the original equation, maybe i did something wrong

distant cove
alpine sable
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You get something like 4t^2 - 9 = 5t.

distant cove
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let me try

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t=(3/2)^(x/2)?

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yep

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turns out good and correct

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thank you!

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@alpine sable

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.close

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.close

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tough tangle
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i need help understanding this

lone heartBOT
tough tangle
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if probability of smallR shooting the target is 1/2, and proability of shooting the target for Zanoes is 1/2, then how is the probability of SmallR winning 2/3

alpine sable
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SmallR goes first, so in order for Zanoes to be able to have n atempts, SmallR must get N+1 atempts

(SmallR has to miss for Zanoes to get a chance, Zanoes has to miss for SmallR to get a chance)

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That diagram was wrong

tough tangle
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P(SmallR doesnt hit, Zanoes hits) == 1/4
P(SmallR hits on first try) == 1/2
P(SmallR hits, Zanoes doesnt hit) == 1/4

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right?

alpine sable
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Not quite

SmallR has a 1/2 to hit on first try
SmallR miss, Zanoes hits 1/4
SmallR miss, Zanoes miss, SmallR, hits, 1/8

And so on

tough tangle
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those get added?

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and honestly there is no bound to this problem so isnt this an infinite sum

alpine sable
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It could be thought of like that

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But the numbers very small very fast (1/(2^n)), so anything over 10 throws would never happen in reality

lone heartBOT
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@tough tangle Has your question been resolved?

alpine sable
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Throw 1, 3, 5... is made by SmallR
So id assume the sum of the probability of all odd throws are 2/3

alpine sable
tough tangle
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so is that just the sum of P(SmallR hits)^(odd numbers)?

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i am doing a problem where this probability changes so

alpine sable
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Yes, asuming a different probability change it acordingly
(1000 should be infinity, but desmos isnt good at that)

The total sum of all the probabilites is 1, someone will hit some time

tough tangle
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i see

alpine sable
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If someone has 0.3 odds one time and 0.2 odds another time, their total odds of winning is 0.3+0.2 = 0.5

tough tangle
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ohh

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if its just P(smallr hits)^odd

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then why was zanoe's probability given @alpine sable

alpine sable
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Problems are not meant for you to walk right into the solution, in that case you would have had an easier time and learned less

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Also this assumes SmallE and Zanoes has the same probability of winning, which may be a simplification

lone heartBOT
#

@tough tangle Has your question been resolved?

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lone lotus
#

Question: "Write down the steps and process you follow to determine the total number of manhole covers in the county." This county would be San Joaquin County in California. Do I start by getting the population of the county? I'm not even sure how to start going about this. Thank you all in advance!

alpine sable
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are you trying to do a fermi estimate?

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or are you actually trying to get an accurate number

lone lotus
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The questions says “total” so I’m guessing they do want an accurate number but it may be hard to do as a lot of estimation is gonna need to be done @alpine sable

alpine sable
#

google maps seems to have your county fully mapped, shouldnt take more than a few days ¯_(ツ)_/¯

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perhaps something more reasonable is to get an average manhole count per street/intersection and then count the number of streets

tacit arch
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sounds like a fermi problem for a job interview

lone lotus
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That's exactly what it is lol

tacit arch
lone lotus
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I wasnt told it was a fermi question but by the looks if it I think it is, I appreciate your help!

tacit arch
lone lotus
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@tacit arch Yea im reading through this rn and it seems like its just testing my ability to guesstimate and the method im using to do it. So I could safely get the average amount of manholes off lets say 10 streets and then times that by number of streets in county and Ill have a very rough answer right? Its kind of insane how interview processes have changed for me going from blue collar jobs to higher level corporate ones. Like wtf is this question lol.

worn fox
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they're not really bothered how close you get to the answer unless you're doing stupid estimates of things

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they're just trying to see how you're thinking about the problem

lone heartBOT
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@lone lotus Has your question been resolved?

lone lotus
#

So i'm sure if I just type out my reasoning as to how id go about and give my answer I should be fine.

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Thank you everybody i know this turned out to be pretty unrelated to actual math but I appreciate it all the same.

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Good day all.

lone heartBOT
#
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lapis ingot
#

are parametric equations and vector valued functions the same

mortal trellis
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no. equations and functions are different things

lapis ingot
mortal trellis
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well I guess you can use them to define a function

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so in that sense, I guess

lapis ingot
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like you define them in terms of t

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but then what's the difference between parametric equations and vector valued functions

mortal trellis
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well on one hand you have eg two equations $x=\cos t, y=\sin t$

ocean sealBOT
#

Denascite

mortal trellis
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and on the other hand you have a function $f(t)=(\cos t, \sin t)$

ocean sealBOT
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Denascite

lapis ingot
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but isn't that just the same thing

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both of them describe the same circle

mortal trellis
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ok maybe the distinction I want to make is too nitpicky

lapis ingot
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so basically

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they are pretty much the same

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except

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that the parametric equation

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isn't really a function?

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because it's given as equations

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?

mortal trellis
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yeah you can say it like that

lapis ingot
#

aight thanks bro

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👍

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.close

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calm swift
#

hi is anyone free to help?

lone heartBOT
fierce prairie
calm swift
#

The diagram shows a triangle with coordinates A(–2, –1), B(6, –1) and C(3, 4)

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im stuck on part c

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im not sure how to find CX

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this is where im stuck

alpine sable
#

It just so happens that the x and y coordinates of A and C both have a difference of 5, so you can skip the distance formula and avoid messy numbers

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otherwise, you need to find the point on AC that is 4.24264 units away from A by considering the formula of the line AC (or any parametrisation of it)

alpine sable
#

since AC is a straight line, the ratio 3:2 can be taken componentwise

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ie find the x coordinate of X first by looking at the x coordinates of A and C. Then do it for y

calm swift
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so ill basically finding the coordinates for point X?

alpine sable
#

yes

calm swift
#

ah i see

#

thanks so much!

alpine sable
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yw :)

calm swift
alpine sable
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I get (-2+3,-1+3)=(1,2)

calm swift
#

oh okay i understand thanks

#

.close

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alpine sable
#

Hi I just want to know if what I did is right

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integral calc

tacit arch
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,w integral e^(x/2) / (1+e^x) dx

tacit arch
#

thinkies might be?

alpine sable
#

yup i tried wolram alpha but its different from mine

tacit arch
#

try differentiating your answer to get the integrand

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some inverse trig and inverse hyperbolic trig functions relate to each other

alpine sable
tacit arch
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u sub looks good

alpine sable
tacit arch
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,w integral 1/(x * sqrt(x-1)) dx

alpine sable
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the form i know is arcsec

tacit arch
#

,w derivative arcsec(x)

alpine sable
#

i memorized that

tacit arch
#

yea looks the same

alpine sable
#

so its correct?

tacit arch
#

no wait i lie

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$\frac{1}{x^2\sqrt{1-1/x^2}} = \frac{1}{x\sqrt{x^2 - 1}}$

ocean sealBOT
#

riemann

tacit arch
#

not quite your integrand

alpine sable
#

side thought, integration by parts is easier than substitution

alpine sable
#

my bad

tacit arch
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tough find

alpine sable
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yup

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hey someone can you please help me with this integral

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$\frac{1}{x\sqrt{x - 1}}$

ocean sealBOT
#

plumbe_r

alpine sable
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I know wolfram alpha can give me the answer but i just want to know how i can do it on my own

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using u-sub i simplified it to $\frac{1}{\sqrt{x^3} -\sqrt{x}}$

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help with integral of the above

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$\int{\frac{1}{\sqrt{x^3} -\sqrt{x}}}dx$

ocean ravine
#

.

alpine sable
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<@&286206848099549185> i need help please

ocean ravine
alpine sable
#

you have to ping helpers

ocean ravine
ocean sealBOT
#

plumbe_r

alpine sable
ocean ravine
alpine sable
#

why they have the helper ping then?

ocean ravine
#

who doesnt want their name in green text

alpine sable
#

haha people are helpful

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though

lone heartBOT
#
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tired echo
lone heartBOT
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alpine sable
lone heartBOT
#

Please don't occupy multiple help channels.

alpine sable
#

oh sorry i thought it was closed

lilac nest
#

.close

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alpine sable
lone heartBOT
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nimble bane
#

How would I use my calculator to get this answer

tacit arch
#

thinkies newton rhapson method?

nimble bane
#

whats that

tacit arch
#

it finds roots of functions. in your case, $f(x) = 6(x^{15} - 1)/(x-1) - 29$.

ocean sealBOT
#

riemann

tacit arch
tacit arch
nimble bane
#

oh

nimble bane
#

I dont think our teacher is gonna teach us this method in class and

#

For me its a bit too complicated lol

tacit arch
#

then your calculator probably has a solver that you'll have to google how to use

lone heartBOT
#

@nimble bane Has your question been resolved?

nimble bane
#

Thanks ig

lone heartBOT
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empty plover
#

show than un and vn are adjacent and that they both tend to the thing on the right
ive tried to show something but i cant. Cant find out which sequence is increasing and which is decreasing, and cant think of anyway they might relate to trigonometry

empty plover
#

a and b are real numbers

ripe jasper
empty plover
#

prepa

ripe jasper
#

Cute

#

ok lets do this

empty plover
#

thanks xD

ripe jasper
#

so you want to prove they are adjacent?

empty plover
#

yeah

ripe jasper
#

aight so did you that u_n is increasing and v_n decreasing?

#

Aight first of all show that u_n and v_n are positive -i think you can just say it since its kinda obvious-

empty plover
#

its kinda obvious

ripe jasper
empty plover
#

they're positive

ripe jasper
empty plover
#

first terms are positive and recurrence directe

ripe jasper
#

then show this u_n < v_n

empty plover
#

yeah i ve been trying

#

un-vn

#

but i am not getting anything i can know the sign of

ripe jasper
#

ok check my "proof"

#

base case n=0 $u_0 < v_0$ "trivial"

ocean sealBOT
#

Hellboy

ripe jasper
#

assume $u_n < v_n$

ocean sealBOT
#

Hellboy

empty plover
#

Ah fuck didnt think of induction this always slips me :p

ripe jasper
#

$v_{n+1} - u_{n+1} = \sqrt{\frac{u_n v_n + v_n ^2}{2}} - \frac{u_n + v_n }{2}$

ocean sealBOT
#

Hellboy

empty plover
#

yes

#

ill try to see where this lead

ripe jasper
empty plover
#

ok easy

#

yeah it work

#

s

#

simply replace vn by un and we'll have that its bigger than 0

marsh rapids
#

btw on appelle leur limite commune la moyenne arithmético-géometrique de a et b

empty plover
#

c'est racine(un+1*vn)

#

pas racine (un*vn)

#

i think its different

marsh rapids
#

Oh exact

empty plover
#

t'as des idess comment proceder?

marsh rapids
empty plover
#

Non ca va ca marche j ai juste remplace vn par un

#

Apres ca on montre que un et vn sont respectivement croissant et decroissante resp. n est ce pas?

marsh rapids
#

Donc un_n croit c'est clair aussi ?

ripe jasper
empty plover
#

No the limit

#

how to find the limit

ripe jasper
#

you dont need to find limit now

#

you need to show that lim u_n - v_n = 0

marsh rapids
#

C'est un peu la 2e partie de la question quoi

ripe jasper
#

this is after showing u_n and v_n are resp. increasing/decreasing

empty plover
#

Un is obvious

marsh rapids
#

v_n décrois t'a la démo ou pas encore

empty plover
#

si

#

ca va

#

je travaille sur un-vn

#

we have that un+1/vn+1<1/2 true?

marsh rapids
#

Faux car leur limite est commune

#

un -> l, vn-> l donc un/vn -> l/l = 1

empty plover
#

Okay nevermind lol

#

XD

#

ok j ia eu que c'est plus petit que 0 alors egal a 0 ca va?

#

I found its smaller than 0 so its 0 right?

#

un-vn

marsh rapids
#

vn > un !=> vn = un

empty plover
#

what?

#

i didnt say that

marsh rapids
#

Sois plus précis alors

empty plover
#

vn-un dsl

#

vn-un is positive and smaller or equal than 0

#

(when i say smaller it includes equality, when i dont want to include i say strictly smaller)

ripe jasper
#

meh look gros pq tu veux v_n - u_n?

marsh rapids
#

We already know that u_n <= v_n. You said it earlier

marsh rapids
empty plover
ripe jasper
#

ah ok j vois

#

look

empty plover
marsh rapids
#

jsp détaille rigoureusement et regarde

ocean sealBOT
#

Hellboy

empty plover
#

right

ripe jasper
#

oh also

#

you can do something more direct

#

you have u_n < v_n

#

thus

#

v_n - u_n > 0

ripe jasper
ocean sealBOT
#

Hellboy

ripe jasper
#

since u_0 < u_n then -u_n < -u_0

ocean sealBOT
#

Hellboy

marsh rapids
#

On sais mais faut mq que la lim vaut 0

ripe jasper
empty plover
#

everything is clear until now and i am looking forward to how this will lead to it going to 0

ripe jasper
#

then this shows lim v_n - u_n = 0

empty plover
#

right

ripe jasper
empty plover
#

i am thinking hold on

#

just a few seconds more

empty plover
#

no ive got nothing go ahead

ripe jasper
empty plover
#

okay

ripe jasper
#

meh

empty plover
#

Hahaha

ripe jasper
#

just let e = v_0 - u_0

#

e = b-a > 0

empty plover
#

okay i did do that

#

now what?

ripe jasper
#

ok great gg

#

you proved lim v_n - u_n = 0

empty plover
#

yeah how?

ripe jasper
#

you have $|v_n - u_n| < e$ what you waiting for?

ocean sealBOT
#

Hellboy

empty plover
#

it should be for all e>0 :p

marsh rapids
#

That's for one epsilon and only 1

empty plover
#

lol

ripe jasper
#

lol

empty plover
#

a could be infinitely big for all we now

#

and so is b

ripe jasper
#

no problem

#

you still find the epsilon

empty plover
#

we have no control over a or b

marsh rapids
#

So if I fix epsilon, for what n do we have v_n - u_n < epsilon

ripe jasper
#

for n > N

#

lol

marsh rapids
#

You're very unhelpful right now

#

And you know it. Or you're drunk

ripe jasper
#

idc im just talkin

ripe jasper
#

pick e = (b-a)/n maybe?

marsh rapids
#

You fix a and b. Then you fix epsilon. Then you find n

#

Not any other way round

lone heartBOT
#

@empty plover Has your question been resolved?

ripe jasper
#

meh

#

just look if u dont want to do it this way

#

then maybe use logic , assume its not converging to 0 , find contradiction

ocean sealBOT
#

Hellboy

ripe jasper
#

@empty plover

#

so if u assume its not goin to 0 as n->infty :

empty plover
#

yes

ocean sealBOT
#

Hellboy

ripe jasper
#

@empty plover you see this?

empty plover
#

Yeah i see it

#

but i dont think thats the correct contraposition to the limit of a sequence

ripe jasper
#

Why

marsh rapids
#

Very weirdly formulated. More like wrong

empty plover
#

there exists an epsilon there exists an n for which n>N and un-l>e

ripe jasper
empty plover
marsh rapids
#

There exists epsilon > 0 st for all N, there exists n >= N st |v_n - u_n| > epsilon

#

Know your fundamentals guys

marsh rapids
marsh rapids
ripe jasper
empty plover
#

Its fine i read the correction to this exerciseee during this time it's all good, tho thanks a lot for the help so far @ripe jasper

marsh rapids
empty plover
#

and mateo ofc

ripe jasper
marsh rapids
# ripe jasper wut?

For all these limit things, pretty much every inequality can be taken strict or large without consequences

marsh rapids
ripe jasper
marsh rapids
#

By forgetting to be formal you forgot to be correct. That's bad

lone heartBOT
#
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ripe jasper
#

also what i was doin wasn't tryin to do a proof so its just an idea, idk why ur skeptic asf ptn

real gazelle
#

okay the channel is closed let's move on

marsh rapids
#

Who it's directed to doesn't change what it says

real gazelle
#

y'all can settle this in DMs

lone heartBOT
#
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ripe jasper
#

bruh this guy got skeptical rq but meh

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#
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lone heartBOT
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versed widget
lone heartBOT
versed widget
#

I need help finding the equation of this graph

#

I know it’s a cosine graph but I don’t know how to find the rest of the numbers

lone heartBOT
#

@versed widget Has your question been resolved?

lone heartBOT
#

@versed widget Has your question been resolved?

versed widget
jade bloom
versed widget
#

Alright thank you

#

Is the max 5 and the min -3?

jade bloom
#

Yes but make sure to watch your signs so a = 4 and also c is the x coordinate of the max

versed widget
#

How is a=4?

jade bloom
#

[5-(-3)]/2

versed widget
#

Oh okay

jade bloom
#

a is the amplitude of the graph

versed widget
#

For the period how is it found.

jade bloom
#

the period is the length of one cyvle of the graph so for you graph its 3 and you can subract the two max point to find your period

versed widget
#

Oh okay, I’ll do that thank you

jade bloom
#

Yeah youre welcome

versed widget
#

I got y=4cos(3x-5)+1

#

Is that right?

#

Nvm, I did it wrong I think

jade bloom
#

your k and c are wrong and you need to included the paranthesis

versed widget
#

I forgot to divide the 2pi/3

jade bloom
#

your max coordinate is at 0 and 3 so you could choose one of those for your c

versed widget
#

Alright I got y = 4cos(2pi/3(x+3))+1

jade bloom
#

close but its a subtraction between x and 3

#

(x-c) --> (x-3)

versed widget
#

Oh okay, i saw the 3 which was positive. If it was negative 3 it would have x +3?

jade bloom
#

Yes

versed widget
#

Thank you 🙏

#

.close

lone heartBOT
#
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cobalt ridge
#

What is y = mx + b google is too complex for my brain to comprehend

abstract fractal
#

It's the equation of a line

cobalt ridge
#

Wat

#

What is slope again, Ik rise over run, but I coding and the problem is every x must have a y and somehow that is related to y = mx + b

abstract fractal
#

The m represents the slope and the b represents the y intercept

cobalt ridge
#

Ok but what is the meaning of every x must have a y

elfin snow
#

slope is how quickly you ascend or descend

#

like the slope of a mountain

cobalt ridge
#

Yea I know that much

#

Rise over run or something like that

elfin snow
#

yeah

abstract fractal
cobalt ridge
#

Ok so I am plotting a MatPlot

Assume we have a List called Weeks: [1,2,3,4,5,6,7,8] (X axis)

And a List called Profit/Dollars: [1000, 2567, 5678, 8907, 13476, 11993] (Y axis)

We plot that in the MatPlot and we should have no problem or i am wrong? In normal math grid or whatever

wary stream
#

I don't think you have enough values

cobalt ridge
#

Ohhhhhhhhh

wary stream
#

For the y

#

You have 8 for x, and you need 8 for y

cobalt ridge
#

Wait u have to have the same amount of values for both?

#

Ohhhhhhhhh

abstract fractal
#

How else would you define f(8). If the y values line up with the x values from left to right, then the x values 7 and 8 don't have a y value, because there's not enough y values

cobalt ridge
#

Yea but in my mind u could still technically plot it no?

wary stream
#

No

#

Because you don't have enough y values

cobalt ridge
#

Waht

wary stream
#

You need an equal amount of x values to y values

cobalt ridge
#

Why

wary stream
#

To plot it

abstract fractal
#

What's the corresponding y value to x = 7, if you can plot it?

wary stream
#

You can either get rid of the extra x values or add more y values, but every x should have a y value

abstract fractal
#

The matplot code (maybe idk I haven't looked at it) assumes the x and y values are the same length

cobalt ridge
#

Ohhhhhh I get it now

#

Thx

#

!close

#

/close

#

;close

#

Goofy what

abstract fractal
#

".close"

cobalt ridge
#

Ohhhhh

#

Diff prefix

#

.close

lone heartBOT
#
Channel closed

Closed by @cobalt ridge

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#
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Ask your math question in a clear, concise manner.
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After 15 minutes, feel free to ping <@&286206848099549185>.
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minor osprey
lone heartBOT
minor osprey
#

i dont get how to do this

alpine sable
#

Bro is this physics lol? @minor osprey

minor osprey
#

no

#

applied maths

#

using integration

#

and stuff

alpine sable
#

Oh I don’t know this one can’t help sorry

minor osprey
#

ok

alpine sable
#

Never did this one before

#

Sorry just wait for someone up

#

I can defenitrly try helping if you’d like

worn fox
#

I'm assuming you're gonna want to show that dE/dt=0

minor osprey
#

tbh im a little confused

#

because i think e is a constant

#

at least thats what they say in the notes

worn fox
#

Right that's what this question is making you show

#

If its derivative is zero, it must be constant

minor osprey
#

so how would i do that

worn fox
#

What's the equation for energy

minor osprey
#

e= mv^2/2 + v(x)

#

the farthest i got is to get rid of m as it is a unit mass particle

worn fox
#

Okay now you need to differentiate

#

Remember that F=ma

#

And also that F=-dU/dx

minor osprey
#

im confused as to why i would need to differentiate f(x)

#

and what the derivative of the kinetic energy is

worn fox
#

You just gave me the equation for energy

#

We want to show that energy is constant during motion

minor osprey
#

i get that part

#

but i dont know why i would need to differentiate the force

worn fox
#

Why do you think you need to?

minor osprey
#

as the derivative reprents the change

#

and if the change is 0 then the energy is constant

worn fox
#

Yes but where have we said anything about differentiating force

minor osprey
#

i misunderstood this part

#

i dont get this part

worn fox
#

That's just a general fact you should know if you're doing physics

minor osprey
#

im not

worn fox
#

"Force is the negative derivative of the potential"

minor osprey
#

okay so what do i after this part

worn fox
#

Well what do you have so far

minor osprey
#

v^2/2 + -dv/dx=E

worn fox
#

Eh huh

worn fox
minor osprey
#

okay

worn fox
#

Sorry what I was calling U, you were calling v

#

Wait youre using v twice

minor osprey
#

v for potential or veloctiy?

worn fox
#

v for velocity

#

Big V for potential if you want to use V still

worn fox
minor osprey
#

the problem is i dont know how to differentiate the right side

#

is it just (dv/dx)/2 + dV/dx

worn fox
#

We can set m to 1 to make our life easy

#

youre gonna need to use the chain rule on the first term

#

Youre close

minor osprey
#

so v*dv/dx?

worn fox
#

Ish

#

Yeah!

minor osprey
#

im still a bit stuck on what to do after

worn fox
#

Yikes sorry we should be differentiating with respect to time!

#

Everything is basically the same

minor osprey
#

sorry so is x just t

worn fox
#

dE/dt = v*dv/dt + d/dt(V(x(t)))

#

Happy so far?

minor osprey
#

does d/dt just mean the derivative of what is after

worn fox
#

Yeah

#

Sorry I should latex it but I'm on mobile

minor osprey
#

okay

worn fox
#

d/dt(stuff)

minor osprey
#

im with you so far

worn fox
#

Now chain rule the second term

#

On the RHS

minor osprey
#

dV/dx(t)?

worn fox
#

Its going to be dV/dx * something

#

Wait

minor osprey
#

i didnt get how there could be v(x(t)))

#

im not sure what this means

worn fox
#

V is your potential

#

It's a function of position V(x)

minor osprey
#

yes

#

okay

worn fox
#

But position is a function of time x(t)

minor osprey
#

ah okay

worn fox
#

So V(x(t))

minor osprey
#

yep i get that

#

so how do i find the derivative of a function within a function

worn fox
#

Chain rule!

minor osprey
#

so dV/dx*dx/dt?

worn fox
#

Yes!

#

Put everything together so far and you're basically there

minor osprey
#

is that dV/dt?

worn fox
#

Yes, by the chain rule

minor osprey
#

okay so i think i might have missed something

#

but i have v*dv/dt + dV/dt = dE/dt

worn fox
#

Oh hang on

worn fox
worn fox
minor osprey
#

i thought that you could just get rid of the dx

#

as there was one on the bottom and one on the top

worn fox
#

You can, but we don't want to

minor osprey
#

okay

#

v*dv/dt + (dV/dx)(dx/dt) = dE/dt

worn fox
#

dv/dt has a better name

#

So does dx/dt

minor osprey
#

v?

#

and accerlation?

#

i mean flipped

worn fox
#

Yes

#

And the last piece is using F = -dV/dx

#

And F=ma=a (m=1)

minor osprey
#

ahhhhhhhhhh

#

i got it now

worn fox
#

0?

minor osprey
#

that makes sense

#

ye

worn fox
#

Nice

minor osprey
#

thanks dude this made a lot of sense

worn fox
#

No worries!

minor osprey
#

btw is it okay if i privately dm you? dont know if its allowed in this server

worn fox
#

I have dms turned off for this server sorry

minor osprey
#

ah

#

so theres no chance of asking for you to look over answers ive written down for questions?

#

i would pay

worn fox
#

You'd get quicker and more consistent replies posting them here in this discord with thousands of people my friend

minor osprey
#

i tried earlier but i couldnt get anyone to answer an applied maths quesiton

worn fox
#

Alright friend me and you can DM me stuff but can't guarantee replies, not right now anyway its 3AM I'm about to sleep

minor osprey
#

ye its 3am where i am aswell

#

its fine im also not expecting guaranteed replies

worn fox
#

Sweet, have a nice sleep when you do!

minor osprey
#

.close

lone heartBOT
#
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inland vessel
#

I was wondering, should you index using the set of real numbers or should you avoid that on all costs. Are there limitations of what set of numbers to use while indexing things?

I'm not an expert on indexing, my creative mind randomly decides using the set of reals for indexing a collection of sets. Here is an image (v) The big question is, is this valid to do?

rose sigil
#

you can index a collection of sets with the real numbers but I'm not sure what your example is

inland vessel
#

or does it depend on the situation.

rose sigil
#

umm your notation, at the very least, could have some problems

#

and maybe other things

inland vessel
#

(I was trying to condense it lolol)

#

to save space

rose sigil
#

but yes, you can use any set of numbers for indexing (if you express it clearly)

inland vessel
#

Are the brackets and the random "|" the main issue, (pointing out my notation?)?

rose sigil
#

I don't understand either of those

inland vessel
#

uh...

rose sigil
#

or the i in R with what comes after it

inland vessel
#

i should space it

#

actually

#

$ \begin{array}{l}
\ i\ \in \ R\ \ \ \
\
A_{i} \ =\ {A_{1} ,A_{2} ,A_{3} ,A_{3} ,A_{3} ...........A_{i}}
\end{array}$

ocean sealBOT
#

nesymerp1

inland vessel
#

Oh i get it now, yeah mb i thought you knew set theory. But, it doesn't matter I think? Since you knew indexing...

inland vessel
rose sigil
inland vessel
#

So, basically.

i in R means that i is any real number (Or: i is a member of the set of reals)

#

And what I'm doing is indexing using "i". To classify that A_i is a set containing other sets indexed by i.

rose sigil
#

why does A_i reference itself in its definition?

inland vessel
#

I feel like it is used to explain what the "class" is made of in terms of indexing

#

but maybe its the wrong notation? im new to all of that still

rose sigil
#

ignoring that for now, can you tell me what the set A_{1/2} is?

#

or A_{pi}

#

or A_{-10}

inland vessel
#

Well I said the entire class contains sets that share a 'arbritrary property', like all the sets in the class contain elements that for example: Reals,Rational.

rose sigil
#

or class as you want to call it

inland vessel
#

i also could refer it as a family of sets.

rose sigil
#

the notation is still meaningless to me. You are trying to, for each real number i, define a collection of sets A_i, right?

inland vessel
#

this is why im asking if it was recommended to index like this

rose sigil
#

then no, I'm not sure what you are trying to define, but the notation is meaningless right now

inland vessel
# rose sigil so..?

I don't know specifically, it could be any collection of numbers that share a common property with let's say A_{pi}

#

but it may be because it's very ill defined and such, which causes you to not understand it well

rose sigil
#

but what is A_{pi}

inland vessel
#

same answer, any collection of numbers that share a common property/properties with any set A_[i]

rose sigil
#

are you familiar with any examples of classes?

inland vessel
#

no sadly not

#

im new to all of this and im trying to build my set builder comprehension by examples and such

rose sigil
#

then you might want to try to understand some. This doesn't look like any way to construct a class to me

inland vessel
#

Yeah I came here to ask if it was valid

#

to build a class like this, honestly.

#

but maybe like someone who knows set theory well could answer it to me, which would be an additional great help.

inland vessel
rose sigil
#

yes

inland vessel
#

How much?

#

is it like, a lot or are you just like me?

rose sigil
#

I've taken one grad level class in axiomatic set theory and used it in some other places

inland vessel
#

just, making sure im no dumbo

rose sigil
#

not sure what to say to that, some things you said were intuitively fine but you seem to have some misconceptions on what a class is

inland vessel
#

as all beginners do sometimes yeah...

inland vessel
rose sigil
#

no problem, good night 😁

lone heartBOT
#

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frank nacelle
lone heartBOT
frank nacelle
#

The only a i got was 2

#

what does 115 have to do with this problem?

naive valley
#

does 115 refer to the previous problem? presumably 1.1.5?

#

otherwise i have no idea, 115 is obviously not a solution

tight locust
#

Rationalize denominators

#

Multiply by the conjugate

elfin snow
#

there are 115 hints

lone heartBOT
#

@frank nacelle Has your question been resolved?

frank nacelle
#

@naive valley No clue tbh

#

None of the answers above really relate to 115

lone heartBOT
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last ether
#

115 v bucks

lone heartBOT
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safe mural
#

hi can someone please help me with part 3 of this question

safe mural
#

so i've got this for k hat

#

and i think that i can follow something similar to this from stackexchange, but i'm confused on how to make it work

lone heartBOT
#

@safe mural Has your question been resolved?

safe mural
#

<@&286206848099549185>

lone heartBOT
#

@safe mural Has your question been resolved?

lone heartBOT
#

@safe mural Has your question been resolved?

lone heartBOT
#

@safe mural Has your question been resolved?

lone heartBOT
#

@safe mural Has your question been resolved?

safe mural
#

.close

lone heartBOT
#
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astral portal
lone heartBOT
marsh rapids
#

Try to find information on the coefficients of P, then draw some conclusions

astral portal
marsh rapids
#

You can tell a lot about P just from the fact its roots are imaginary

#

A lot more than delta <= 0

astral portal
#

the graph does not touch the axis

astral portal
marsh rapids
#

Is 0 purely imaginary ?

astral portal
marsh rapids
#

Ok

astral portal
#

all i am gonna say the answer will be either c or d

#

according to my calculation

#

as p(x) has to be imaginary

marsh rapids
#

Why not a ?

astral portal
#

to make p(p(x))=0

astral portal
marsh rapids
#

Yes but why ?

astral portal
#

idk

marsh rapids
#

Especially since the roots are complex conjugates of each other

astral portal
#

x = +- ai

#

then only p(x) can be 0

mellow tusk
marsh rapids
#

ai is weird because then you can't write ax^2 + bx + c though

astral portal
marsh rapids
astral portal
#

yea

mellow tusk
marsh rapids
#

So you know it's complex and need to disprove it's purely imaginary

astral portal
#

-ak^2+bki +c = 0
-ak^2 - bki + c = 0
bki = 0 => b = 0

marsh rapids
#

Yes

#

And c = ak^2 which doesn't hurt

astral portal
#

ak^2 = c
k = sqrt(c/a)

#

ye

marsh rapids
#

But b=0 is the useful one

astral portal
#

p(x) = ax^2 + c = 0 x = +- sqrt(-c/a)

#

so c/a is negative

marsh rapids
astral portal
#

p(p(x)) = a(ax^2+c)^2 + c = 0
ax^2 + c = +-sqrt(-c/a)

#

hence answer d as c and a are real
while sqrt c/a is imaginary
hoping c not equal to 0

#

am i missing smth

#

or this is it

marsh rapids
frail lantern
#

@marsh rapids Can I learn along and ask questions?

marsh rapids
#

Not starting from 0 on the complex numbers but if there's a step you didn't understand feel free to ask

#

But I just finished the solution

frail lantern
#

c would never be equal to 0 because product of 2 purely imaginary numbers would never be 0, am I correct in assuming this?

marsh rapids
#

Yes c != 0 or 0 would be the root

#

And 0 isn't purely imaginary

frail lantern
#

! ?

#

Yes, I just didnt understand the ! notation

marsh rapids
#

!= means not equal

astral portal
#

!-> not

#

yea

frail lantern
#

okay thanks a ton

astral portal
#

i think i understood

#

thanks

marsh rapids
astral portal
#

i amma close it now

frail lantern
#

yes i remmeber my coding days now xd

#

alright

astral portal
#

.close

lone heartBOT
#
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lone heartBOT
#
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empty plover
#

show that this is bijective and calculate for any given n (x,y)

empty plover
#

just want the steps ill do the calculations alone

#

seems super difficult

lone heartBOT
#

@empty plover Has your question been resolved?

mortal trellis
#

note that the second part is a triangular number

#

show that you can write each natural number uniquely as a triangular number plus a certain rest

alpine sable
#

y=n, x=-n?

#

for any n, n=f(-n, n)

mortal trellis
#

-n is not a natural number

alpine sable
#

ah damn

lone heartBOT
#
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lone heartBOT
#
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keen furnace
lone heartBOT
keen furnace
#

qu 11

#

This is what I came to conclusion so far

#

I have no idea what’s my next step

vestal locust
#

Rather than horrible calculations, maybe show that both sides have the same derivate

#

which proves that left_side = right_side + constant

#

and then show that constant=0

#

That may be better

#

maybe not

#

You also have $\sin^2 \cos^2 = (\sin (2x))^2$

ocean sealBOT
#

Guilhem

vestal locust
#

...

keen furnace
#

I haven’t seen that one

#

yea I am kinda ignoring the other side too much

#

.close

lone heartBOT
#
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shrewd whale
lone heartBOT
shrewd whale
#

I have no clue

#

I got it down to

languid bolt
#

is that the whole question?

shrewd whale
#

r = -2pih +- (sqrt(4(pi^2)(h^2)+8piA))/4pi

#

yes

#

thats it

#

the whole thing

#

solve for r

gray isle
#

missing ()

#

also missing the r=

shrewd whale
#

yeah sry

gray isle
#

still missing ()

last ether
#

$\frac{-2πh \pm 2πh}{4π}$

#

Save the pain

gray isle
#

$$r = \frac{-2\pi h \pm \sqrt{4\pi^2h^2 + 8\pi A}}{4\pi}$$

ocean sealBOT
#

ℝamonov

shrewd whale
#

yes

last ether
#

Oh I forgor the A

#

Uh

gray isle
#

you can factor sqrt(4)=2 out of the sqrt

shrewd whale
#

ok

gray isle
#

cancel the common factor in both the numerator and denominator
and then there isn't really much to do after that

shrewd whale
#

what would it be?