#help-0
1 messages · Page 10 of 1
OH
ah okay yes
so from here im not exactly sure how to show thats its not a perfect square
you showed that a+b is 2 times an odd number
show that no perfect square can be 2 times an odd number
perhaps by showing that all even perfect squares are necessarily divisible by 4, and two times an odd number never is
HellO
hmm ill try this
wait so im proving something inside my proof?
like proving a general statement inside my proof
i think the proof of the general statement would best go BEFORE your proof proper
so like
Lemma: Let n be an odd number. Then 2n is not a perfect square.
Proof.
[proof of lemma goes here]
-----------
Claim: The sum of two odd perfect squares is never a perfect square.
Proof.
[your work thus far]
By the Lemma proved above, [...], being 2 times an odd number, is not a perfect square.
QED.
alright
one sec
Lemma: Let n be an odd number. Then 2n is not a perfect square.\
n = 2k + 1, k $\in \bZ$ (by definition of odd numbers)\
2n = 2(2k + 1) = 4k + 2 (by basic algebra)\
Let a, b be odd perfect squares
Then, a = $(2m + 1)^2$ and b = $(2k + 1)^2$, m, k $\in \bN$ (by T1)
a + b = $4m^2 + 4m + 1+ 4k^2 + 4k + 1 = 2(2m^2 + 2k^2 +2m +2k +1)$ (by basic algebra)
a + b = $2(2(m^2 + k^2 +m +k) +1)$
HellO
okay Im actually not sure how to prove that something is/is not a perfect square.. my idea is that if the value of 2n was odd or something I could show that 2n cant be a perfecr square but now its even so im kinda lost
Can 4k+2 be a perfect square ? That's all you need to answer
The rest is already done
Suppose it is
Then we can write 4k+2 = p^2, and we know p is even
Can you finish ?
p^2 = (2q)^2 = 4q^2
wait idk if im missing the picture but i still dont see why that proves a contradiction
OH
wait so to prove contradiction
we first assume something wrong
then try to show that the result doesnt make sens
If P if the property we want to prove, we can show that (not P) => false, then by contraposition, true => P, therefore P
ahhh i see
Wait
Did you just not understand how to prove by contradiction but understood a formal logic proof ?
That's kind of funny
oh i knew how to prove by contradiction but i generally did it by proving something thats "related"
like um
If it can't be wrong it has to be true. That's basically the idea
the 4k+2 is a multiple of 4 doesnt really link to the perfect square stuff and i didnt know we could do taht
ahh yes sir
me understand
lemme try to write out the full proof
But the contradiction can be anything
but what gave u the idea of going towards this
When you have no idea you give yourself a starting point. (not P) is a starting point
That way you see if it leads to some nonsense
What proof works best depends on the property. Look at what you need to prove with that method and ask "does that look easy" and pick the best option
And if it proves hard, try something else
Any contradiction works btw, that's what makes it "strong". A lot of proofs for the irrationallity of π construct a sequence of nonzero integers that goes to zero, which is impossible. That is very distant from what it proves
Lemma: Let n be an odd number. Then 2n is not a perfect square.\
n = 2k + 1, k $\in \bZ$ (by definition of odd numbers)\
2n = 2(2k + 1) = 4k + 2 (by basic algebra)\
Assume 4k + 2 is a perfect square.\
By definition, 4k + 2 = $(2q)^2$ (by T1)\
$(2q)^2 = 4q^2$\
$4q^2$ is divisible by 4, but 4k + 2 isnt. Contradiction.\
Hence, 2n must not be a perfect square.
Let a, b be odd perfect squares\
Then, a = $(2m + 1)^2$ and b = $(2k + 1)^2$, m, k $\in \bN$ (by T1)\
a + b = $4m^2 + 4m + 1+ 4k^2 + 4k + 1 = 2(2m^2 + 2k^2 +2m +2k +1)$ (by basic algebra)\
a + b = $2(2(m^2 + k^2 +m +k) +1)$
ah okay i see
so i should always try to use contradiction
instead of direct proofs
No
HellO
Direct works well sometimes too
For proving equalities for instance
Direct is still the usual method
But if the result is obscure, contradiction can be nice because it gives you a starting point
ahh i see
okie dokie
Lemma: Let n be an odd number. Then 2n is not a perfect square.\
n = 2k + 1, k $\in \bZ$ (by definition of odd numbers)\
2n = 2(2k + 1) = 4k + 2 (by basic algebra)\
Assume 4k + 2 is a perfect square.\
By definition, 4k + 2 = $(2q)^2$ (by T1)\
$(2q)^2 = 4q^2$\
$4q^2$ is divisible by 4, but 4k + 2 isnt. Contradiction.\
Hence, 2n must not be a perfect square.
Let a, b be odd perfect squares\
Then, a = $(2m + 1)^2$ and b = $(2k + 1)^2$, m, k $\in \bN$ (by T1)\
a + b = $4m^2 + 4m + 1+ 4k^2 + 4k + 1 = 2(2m^2 + 2k^2 +2m +2k +1)$ (by basic algebra)\
a + b = $2(2(m^2 + k^2 +m +k) +1)$ \
By the lemma proven above, a + b is not a perfect square.
HellO
is this okay?
It works
It's far more detailed than I'd make it, but it depends on the expectations
What level are you at ?
im turning 15
That's quite young to know that much logic
idk my mom sends me for extra math classes lol
Cause for HS level stuff, there's Khan academy, but it won't help you for proof based math
oh i wanna self learn like discrete maths and linear algebra kind
some people said its good to learn these early on
definitely
Proofs are done by practicing, finding new techniques, getting experience and intuition for things. That kinda of stuff
Are you French?
That's a weird "about me" lol
Don't really have any non-french resources for proofs unfortunately
aww
how about youtube
ive seen some nice videos on graph theory but not much on proofs
Try to find an online pdf on your topic, maybe some teacher's website or some academic resource
That explores a topic and includes proofs for everything
Don't have any of that in English though
hmm ill try my best to find some
And exercises to practice it yourself
yessir
See #resources maybe
should i also try studying calculus if i have time
Or #books-old

Calc is very important
It's usually studied partially in high school, while a lot of the proof based stuff only comes after it
Not very surprising
im rly bad at it 
woooot
Calc 2 is where thinking is required and it can get tough if you don't have the right ideas
It's just knowing elementary derivatives, differentiation rules, basic properties and theorems. Limits can be more involved, but basic calc 1 limits are hardly a problem, though they are more like calc 2 for the approach
i see
so ill try finding resources online
and read thru and practice some qns
lemme try finishing discrete maths first xD
okay tysm sir
ive learnt alot
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The line above is what we want, but we don't do any computations with it here. We start from P(k) and add k+1 to get the LHS, and then we transform the RHS into what we want
when/where do they add the k term, which we say to be equal to k(k+1)/2
oh i see, its added to the right below my red line
so then we add our k+1 term..
so where does the (k+1)(k+2)/2 = k+1 come back in
That last message makes no sense. This equality doesn't even hold
The sum is equal to the product. Not k+1 alone
ok the k+1 version of the P(n) expression
P(k)
can you just help me i don't understand
every time i come to this server people talk down to me without helping at all
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i need to calculate the area of that triangle
abit confused but i think angle BCA is 90
that is indeed true given the equations you've written
yeh i figured cuz of the slopes
it also appears that your triangle has a height of 4 and a base of 21 - 1/5
so just 1/2 x 4 x 20.8
if i considered AC to be the base
i would get the same answer right?
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why cant u just take natural logs on both sides
we can't use logs yet unfortunately
oh
we aren't allowed to, to be exact
You want to solve for x?
Yes
he want a T substitution
to reduce to a linear expression
yea
maybe (3/2)^x
wat
or (3/2)^(x/2), shouldn't matter much.
this is the original
Just look at this, (3/2)^(x/2) should work nicely.
You get something like 4t^2 - 9 = 5t.
let me try
t=(3/2)^(x/2)?
yep
turns out good and correct
thank you!
@alpine sable
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i need help understanding this
if probability of smallR shooting the target is 1/2, and proability of shooting the target for Zanoes is 1/2, then how is the probability of SmallR winning 2/3
SmallR goes first, so in order for Zanoes to be able to have n atempts, SmallR must get N+1 atempts
(SmallR has to miss for Zanoes to get a chance, Zanoes has to miss for SmallR to get a chance)
That diagram was wrong
P(SmallR doesnt hit, Zanoes hits) == 1/4
P(SmallR hits on first try) == 1/2
P(SmallR hits, Zanoes doesnt hit) == 1/4
right?
Not quite
SmallR has a 1/2 to hit on first try
SmallR miss, Zanoes hits 1/4
SmallR miss, Zanoes miss, SmallR, hits, 1/8
And so on
those get added?
and honestly there is no bound to this problem so isnt this an infinite sum
It could be thought of like that
But the numbers very small very fast (1/(2^n)), so anything over 10 throws would never happen in reality
@tough tangle Has your question been resolved?
Throw 1, 3, 5... is made by SmallR
So id assume the sum of the probability of all odd throws are 2/3
Here is a sketchy desmos sum
-1+2n makes it evaluated for throw 1,3,5,7...
so is that just the sum of P(SmallR hits)^(odd numbers)?
i am doing a problem where this probability changes so
Yes, asuming a different probability change it acordingly
(1000 should be infinity, but desmos isnt good at that)
The total sum of all the probabilites is 1, someone will hit some time
i see
If someone has 0.3 odds one time and 0.2 odds another time, their total odds of winning is 0.3+0.2 = 0.5
ohh
if its just P(smallr hits)^odd
then why was zanoe's probability given @alpine sable
Problems are not meant for you to walk right into the solution, in that case you would have had an easier time and learned less
Also this assumes SmallE and Zanoes has the same probability of winning, which may be a simplification
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Question: "Write down the steps and process you follow to determine the total number of manhole covers in the county." This county would be San Joaquin County in California. Do I start by getting the population of the county? I'm not even sure how to start going about this. Thank you all in advance!
are you trying to do a fermi estimate?
or are you actually trying to get an accurate number
The questions says “total” so I’m guessing they do want an accurate number but it may be hard to do as a lot of estimation is gonna need to be done @alpine sable
google maps seems to have your county fully mapped, shouldnt take more than a few days ¯_(ツ)_/¯
perhaps something more reasonable is to get an average manhole count per street/intersection and then count the number of streets
sounds like a fermi problem for a job interview
That's exactly what it is lol
here's a couple general outlines
https://scioly.org/wiki/index.php/Fermi_Questions
I wasnt told it was a fermi question but by the looks if it I think it is, I appreciate your help!
It's deliberately open ended and the answer that will get you the offer will be dependent on your ability to impress the team which isn't really a math problem. Soooo good luck
@tacit arch Yea im reading through this rn and it seems like its just testing my ability to guesstimate and the method im using to do it. So I could safely get the average amount of manholes off lets say 10 streets and then times that by number of streets in county and Ill have a very rough answer right? Its kind of insane how interview processes have changed for me going from blue collar jobs to higher level corporate ones. Like wtf is this question lol.
they're not really bothered how close you get to the answer unless you're doing stupid estimates of things
they're just trying to see how you're thinking about the problem
@lone lotus Has your question been resolved?
So i'm sure if I just type out my reasoning as to how id go about and give my answer I should be fine.
Thank you everybody i know this turned out to be pretty unrelated to actual math but I appreciate it all the same.
Good day all.
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are parametric equations and vector valued functions the same
no. equations and functions are different things
aren't parametric equations technically functions of a variable though
like you define them in terms of t
but then what's the difference between parametric equations and vector valued functions
well on one hand you have eg two equations $x=\cos t, y=\sin t$
Denascite
and on the other hand you have a function $f(t)=(\cos t, \sin t)$
Denascite
ok maybe the distinction I want to make is too nitpicky
so basically
they are pretty much the same
except
that the parametric equation
isn't really a function?
because it's given as equations
?
yeah you can say it like that
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hi is anyone free to help?

The diagram shows a triangle with coordinates A(–2, –1), B(6, –1) and C(3, 4)
im stuck on part c
im not sure how to find CX
this is where im stuck
It just so happens that the x and y coordinates of A and C both have a difference of 5, so you can skip the distance formula and avoid messy numbers
otherwise, you need to find the point on AC that is 4.24264 units away from A by considering the formula of the line AC (or any parametrisation of it)
how would i continue with this?
since AC is a straight line, the ratio 3:2 can be taken componentwise
ie find the x coordinate of X first by looking at the x coordinates of A and C. Then do it for y
so ill basically finding the coordinates for point X?
yes
yw :)
hey just to check would X be (1,1)?
I get (-2+3,-1+3)=(1,2)
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,w integral e^(x/2) / (1+e^x) dx
might be?
yup i tried wolram alpha but its different from mine
try differentiating your answer to get the integrand
some inverse trig and inverse hyperbolic trig functions relate to each other
gotcha, but can you please check if my substitution are correct
u sub looks good
we dont learn hyperbolic functions, can i self learn it?
,w integral 1/(x * sqrt(x-1)) dx
the form i know is arcsec
,w derivative arcsec(x)
i memorized that
yea looks the same
so its correct?
riemann
not quite your integrand
side thought, integration by parts is easier than substitution
tough find
yup
hey someone can you please help me with this integral
$\frac{1}{x\sqrt{x - 1}}$
plumbe_r
I know wolfram alpha can give me the answer but i just want to know how i can do it on my own
using u-sub i simplified it to $\frac{1}{\sqrt{x^3} -\sqrt{x}}$
help with integral of the above
$\int{\frac{1}{\sqrt{x^3} -\sqrt{x}}}dx$
.
<@&286206848099549185> i need help please
i wouldnt count on it
usually people get mad when you ping them
plumbe_r
oh
i dunno tho
why they have the helper ping then?
.
who doesnt want their name in green text
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which u sub did you use ?
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i didnt i just want to know which technique i should use
Please don't occupy multiple help channels.
oh sorry i thought it was closed
.close
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How would I use my calculator to get this answer
newton rhapson method?
whats that
it finds roots of functions. in your case, $f(x) = 6(x^{15} - 1)/(x-1) - 29$.
riemann
i guess it depends on your calculator. newton rhapson is just the method. how it gets implemented on calculators is up to the manufacturers
oh
is there any other method?
I dont think our teacher is gonna teach us this method in class and
For me its a bit too complicated lol
then your calculator probably has a solver that you'll have to google how to use
@nimble bane Has your question been resolved?
Thanks ig
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show than un and vn are adjacent and that they both tend to the thing on the right
ive tried to show something but i cant. Cant find out which sequence is increasing and which is decreasing, and cant think of anyway they might relate to trigonometry
prepa? bac?
prepa
thanks xD
so you want to prove they are adjacent?
yeah
aight so did you that u_n is increasing and v_n decreasing?
Aight first of all show that u_n and v_n are positive -i think you can just say it since its kinda obvious-
its kinda obvious
what is obvious?
they're positive
Ok great
first terms are positive and recurrence directe
then show this u_n < v_n
use induction
ok check my "proof"
base case n=0 $u_0 < v_0$ "trivial"
Hellboy
assume $u_n < v_n$
Hellboy
Ah fuck didnt think of induction this always slips me :p
$v_{n+1} - u_{n+1} = \sqrt{\frac{u_n v_n + v_n ^2}{2}} - \frac{u_n + v_n }{2}$
Hellboy
you can start from your induction hypothesis tho
ok easy
yeah it work
s
simply replace vn by un and we'll have that its bigger than 0
btw on appelle leur limite commune la moyenne arithmético-géometrique de a et b
non c'est une suite differente
c'est racine(un+1*vn)
pas racine (un*vn)
i think its different
Oh exact
t'as des idess comment proceder?
Pour montrer que ceci est positif ?
Non ca va ca marche j ai juste remplace vn par un
Apres ca on montre que un et vn sont respectivement croissant et decroissante resp. n est ce pas?
Donc un_n croit c'est clair aussi ?
for proving adjencency?
C'est un peu la 2e partie de la question quoi
this is after showing u_n and v_n are resp. increasing/decreasing
Un is obvious
v_n décrois t'a la démo ou pas encore
Okay nevermind lol
XD
ok j ia eu que c'est plus petit que 0 alors egal a 0 ca va?
I found its smaller than 0 so its 0 right?
un-vn
vn > un !=> vn = un
Sois plus précis alors
vn-un dsl
vn-un is positive and smaller or equal than 0
(when i say smaller it includes equality, when i dont want to include i say strictly smaller)
meh look gros pq tu veux v_n - u_n?
We already know that u_n <= v_n. You said it earlier
Pour mq que ça tend vers 0 non ?
because if i replace un by vn it's 0 and its smaller than that
is this correct reasoning it feels false
jsp détaille rigoureusement et regarde
Hellboy
right
oh also
you can do something more direct
you have u_n < v_n
thus
v_n - u_n > 0
or to make a clear picture
Hellboy
since u_0 < u_n then -u_n < -u_0
Hellboy
On sais mais faut mq que la lim vaut 0
oui oui tkt on arrive
everything is clear until now and i am looking forward to how this will lead to it going to 0
so if i show |v_n - u_n| < e , e > 0
then this shows lim v_n - u_n = 0
right
can you figure it out from this ? or should i spoil?
no ive got nothing go ahead
no think more
okay
meh
Hahaha
yeah how?
you have $|v_n - u_n| < e$ what you waiting for?
Hellboy
it should be for all e>0 :p
That's for one epsilon and only 1
lol
i mean you can pick any a,b , you find the epsilon
lol
we have no control over a or b
So if I fix epsilon, for what n do we have v_n - u_n < epsilon
idc im just talkin
tbh for any n ig
pick e = (b-a)/n maybe?
@empty plover Has your question been resolved?
meh
just look if u dont want to do it this way
then maybe use logic , assume its not converging to 0 , find contradiction
Hellboy
yes
Hellboy
@empty plover you see this?
Yeah i see it
but i dont think thats the correct contraposition to the limit of a sequence
Why
Very weirdly formulated. More like wrong
there exists an epsilon there exists an n for which n>N and un-l>e
negation
why wrong
sprry fixed it
There exists epsilon > 0 st for all N, there exists n >= N st |v_n - u_n| > epsilon
Know your fundamentals guys
literally what i wrote
also its >=
The existence of n is pretty much nonsense
Actually irrelevant
?
wut?
Its fine i read the correction to this exerciseee during this time it's all good, tho thanks a lot for the help so far @ripe jasper
You can't define N if n doesn't already exist.
and mateo ofc
i mean we assumed n is there alrdy so idk what u get to say
For all these limit things, pretty much every inequality can be taken strict or large without consequences
Where did you define n in that statement ? Nowhere so it doesn't exist to me
i mean it was directed to him, not you "cuz i wasnt tryin to be any formal tbh"
By forgetting to be formal you forgot to be correct. That's bad
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send me correction tho
why do u think that was directed to u?
also what i was doin wasn't tryin to do a proof so its just an idea, idk why ur skeptic asf ptn
okay the channel is closed let's move on
Who it's directed to doesn't change what it says
y'all can settle this in DMs
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bruh this guy got skeptical rq but meh
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I need help finding the equation of this graph
I know it’s a cosine graph but I don’t know how to find the rest of the numbers
@versed widget Has your question been resolved?
@versed widget Has your question been resolved?
<@&286206848099549185>
Yes but make sure to watch your signs so a = 4 and also c is the x coordinate of the max
How is a=4?
[5-(-3)]/2
Oh okay
a is the amplitude of the graph
For the period how is it found.
the period is the length of one cyvle of the graph so for you graph its 3 and you can subract the two max point to find your period
Oh okay, I’ll do that thank you
Yeah youre welcome
your k and c are wrong and you need to included the paranthesis
I forgot to divide the 2pi/3
your max coordinate is at 0 and 3 so you could choose one of those for your c
Alright I got y = 4cos(2pi/3(x+3))+1
Oh okay, i saw the 3 which was positive. If it was negative 3 it would have x +3?
Yes
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What is y = mx + b google is too complex for my brain to comprehend
It's the equation of a line
Wat
What is slope again, Ik rise over run, but I coding and the problem is every x must have a y and somehow that is related to y = mx + b
The m represents the slope and the b represents the y intercept
Ok but what is the meaning of every x must have a y
yeah
If you plug in something for x, you'll never get "undefined" or sumn
Ok so I am plotting a MatPlot
Assume we have a List called Weeks: [1,2,3,4,5,6,7,8] (X axis)
And a List called Profit/Dollars: [1000, 2567, 5678, 8907, 13476, 11993] (Y axis)
We plot that in the MatPlot and we should have no problem or i am wrong? In normal math grid or whatever
I don't think you have enough values
Ohhhhhhhhh
How else would you define f(8). If the y values line up with the x values from left to right, then the x values 7 and 8 don't have a y value, because there's not enough y values
Yea but in my mind u could still technically plot it no?
Waht
You need an equal amount of x values to y values
Why
To plot it
What's the corresponding y value to x = 7, if you can plot it?
You can either get rid of the extra x values or add more y values, but every x should have a y value
The matplot code (maybe idk I haven't looked at it) assumes the x and y values are the same length
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i dont get how to do this
Bro is this physics lol? @minor osprey
Oh I don’t know this one can’t help sorry
ok
Never did this one before
Sorry just wait for someone up
I can defenitrly try helping if you’d like
I'm assuming you're gonna want to show that dE/dt=0
tbh im a little confused
because i think e is a constant
at least thats what they say in the notes
Right that's what this question is making you show
If its derivative is zero, it must be constant
so how would i do that
What's the equation for energy
e= mv^2/2 + v(x)
the farthest i got is to get rid of m as it is a unit mass particle
im confused as to why i would need to differentiate f(x)
and what the derivative of the kinetic energy is
You just gave me the equation for energy
We want to show that energy is constant during motion
Why do you think you need to?
as the derivative reprents the change
and if the change is 0 then the energy is constant
Yes but where have we said anything about differentiating force
oh sorry
i misunderstood this part
i dont get this part
That's just a general fact you should know if you're doing physics
im not
"Force is the negative derivative of the potential"
okay so what do i after this part
Well what do you have so far
v^2/2 + -dv/dx=E
Eh huh
Start with this
okay
v for potential or veloctiy?
Okay start with this, and differentiate both sides, carefully
the problem is i dont know how to differentiate the right side
is it just (dv/dx)/2 + dV/dx
We can set m to 1 to make our life easy
youre gonna need to use the chain rule on the first term
Youre close
so v*dv/dx?
im still a bit stuck on what to do after
Yikes sorry we should be differentiating with respect to time!
Everything is basically the same
sorry so is x just t
does d/dt just mean the derivative of what is after
okay
d/dt(stuff)
im with you so far
dV/dx(t)?
But position is a function of time x(t)
ah okay
So V(x(t))
Chain rule!
so dV/dx*dx/dt?
is that dV/dt?
Yes, by the chain rule
Oh hang on
We just showed that this
Is this by the chain rule
i thought that you could just get rid of the dx
as there was one on the bottom and one on the top
You can, but we don't want to
0?
Nice
thanks dude this made a lot of sense
No worries!
btw is it okay if i privately dm you? dont know if its allowed in this server
I have dms turned off for this server sorry
ah
so theres no chance of asking for you to look over answers ive written down for questions?
i would pay
You'd get quicker and more consistent replies posting them here in this discord with thousands of people my friend
i tried earlier but i couldnt get anyone to answer an applied maths quesiton
Alright friend me and you can DM me stuff but can't guarantee replies, not right now anyway its 3AM I'm about to sleep
Sweet, have a nice sleep when you do!
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I was wondering, should you index using the set of real numbers or should you avoid that on all costs. Are there limitations of what set of numbers to use while indexing things?
I'm not an expert on indexing, my creative mind randomly decides using the set of reals for indexing a collection of sets. Here is an image (v) The big question is, is this valid to do?
you can index a collection of sets with the real numbers but I'm not sure what your example is
I was trying to make a class A_i, whose sets share a common arbitrary property. I think this is called a class. My question was, is it valid to use any "set of numbers" for indexing.
or does it depend on the situation.
umm your notation, at the very least, could have some problems
and maybe other things
but yes, you can use any set of numbers for indexing (if you express it clearly)
Are the brackets and the random "|" the main issue, (pointing out my notation?)?
I don't understand either of those
uh...
or the i in R with what comes after it
i should space it
actually
$ \begin{array}{l}
\ i\ \in \ R\ \ \ \
\
A_{i} \ =\ {A_{1} ,A_{2} ,A_{3} ,A_{3} ,A_{3} ...........A_{i}}
\end{array}$
nesymerp1
Oh i get it now, yeah mb i thought you knew set theory. But, it doesn't matter I think? Since you knew indexing...
ye ye, ts fine
what is this supposed to mean?
So, basically.
i in R means that i is any real number (Or: i is a member of the set of reals)
And what I'm doing is indexing using "i". To classify that A_i is a set containing other sets indexed by i.
why does A_i reference itself in its definition?
I feel like it is used to explain what the "class" is made of in terms of indexing
but maybe its the wrong notation? im new to all of that still
ignoring that for now, can you tell me what the set A_{1/2} is?
or A_{pi}
or A_{-10}
Well I said the entire class contains sets that share a 'arbritrary property', like all the sets in the class contain elements that for example: Reals,Rational.
or class as you want to call it
i also could refer it as a family of sets.
the notation is still meaningless to me. You are trying to, for each real number i, define a collection of sets A_i, right?
yeah
this is why im asking if it was recommended to index like this
then no, I'm not sure what you are trying to define, but the notation is meaningless right now
I don't know specifically, it could be any collection of numbers that share a common property with let's say A_{pi}
but it may be because it's very ill defined and such, which causes you to not understand it well
but what is A_{pi}
same answer, any collection of numbers that share a common property/properties with any set A_[i]
are you familiar with any examples of classes?
no sadly not
im new to all of this and im trying to build my set builder comprehension by examples and such
then you might want to try to understand some. This doesn't look like any way to construct a class to me
Yeah I came here to ask if it was valid
to build a class like this, honestly.
but maybe like someone who knows set theory well could answer it to me, which would be an additional great help.
Do you have any background in set theory by any chance?
yes
I've taken one grad level class in axiomatic set theory and used it in some other places
Oh I see, well did I say anything incorrect about uh, classes? As in like, the explenation of them.
just, making sure im no dumbo
not sure what to say to that, some things you said were intuitively fine but you seem to have some misconceptions on what a class is
as all beginners do sometimes yeah...
Rightly... Well thanks for giving me a reality check about it. Now I'll be heading off to sleep, since its 4:00AM
no problem, good night 😁
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does 115 refer to the previous problem? presumably 1.1.5?
otherwise i have no idea, 115 is obviously not a solution
there are 115 hints
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115 v bucks
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hi can someone please help me with part 3 of this question
so i've got this for k hat
and i think that i can follow something similar to this from stackexchange, but i'm confused on how to make it work
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Try to find information on the coefficients of P, then draw some conclusions
well discriminant of p(x) is less than 0
You can tell a lot about P just from the fact its roots are imaginary
A lot more than delta <= 0
the graph does not touch the axis
not equal* coz if equal it will be touching x axis
Is 0 purely imaginary ?
no
Ok
all i am gonna say the answer will be either c or d
according to my calculation
as p(x) has to be imaginary
Why not a ?
to make p(p(x))=0
the answer is d
Yes but why ?
idk
Really investigate this. You can tell more than you think
Especially since the roots are complex conjugates of each other
pp(x)=0 would have solutions [ if possible ] at x=p(x) right?
ai is weird because then you can't write ax^2 + bx + c though
yea so p(x) has to be imaginary to make it possible
It's a solution iff p(x) = +- ki, where ki is the root
yea
and x=p(x) can have either 2,1 or 0 real solutions
So you know it's complex and need to disprove it's purely imaginary
-ak^2+bki +c = 0
-ak^2 - bki + c = 0
bki = 0 => b = 0
But b=0 is the useful one
Think about that and the fact b = 0
p(p(x)) = a(ax^2+c)^2 + c = 0
ax^2 + c = +-sqrt(-c/a)
hence answer d as c and a are real
while sqrt c/a is imaginary
hoping c not equal to 0
am i missing smth
or this is it
We know x can't be real. If x = hi for some h in R and p(x) = +- ki, then -ah^2 + c = +- ki, impossible
@marsh rapids Can I learn along and ask questions?
Not starting from 0 on the complex numbers but if there's a step you didn't understand feel free to ask
But I just finished the solution
c would never be equal to 0 because product of 2 purely imaginary numbers would never be 0, am I correct in assuming this?
!= means not equal
okay thanks a ton
You have that in a lot of programming languages
i amma close it now
.close
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show that this is bijective and calculate for any given n (x,y)
@empty plover Has your question been resolved?
note that the second part is a triangular number
show that you can write each natural number uniquely as a triangular number plus a certain rest
-n is not a natural number
ah damn
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qu 11
This is what I came to conclusion so far
I have no idea what’s my next step
Rather than horrible calculations, maybe show that both sides have the same derivate
which proves that left_side = right_side + constant
and then show that constant=0
That may be better
maybe not
You also have $\sin^2 \cos^2 = (\sin (2x))^2$
Guilhem
...
oh is that another trigo identity?
I haven’t seen that one
yea I am kinda ignoring the other side too much
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is that the whole question?
r = -2pih +- (sqrt(4(pi^2)(h^2)+8piA))/4pi
yes
thats it
the whole thing
solve for r
yeah sry
still missing ()
$$r = \frac{-2\pi h \pm \sqrt{4\pi^2h^2 + 8\pi A}}{4\pi}$$
ℝamonov
yes
you can factor sqrt(4)=2 out of the sqrt
ok
cancel the common factor in both the numerator and denominator
and then there isn't really much to do after that
what would it be?

