#help-0

1 messages · Page 3 of 1

analog basalt
#

What is "the problem"?

rough orbit
#

Is the scanned doc

analog basalt
#

Yes, but what are you asked to do?

rough orbit
#

Find D

#

Using a construction

analog basalt
#

Oh

rough orbit
#

I wasnt paying attention in class so if you could do the porblem while explaining that would be help ful 😅

analog basalt
#

I'm rusty on geometry, I don't think I can solve this right away

rough orbit
#

Its all good just please @ me when somebody solves this

tacit arch
#

Ask a more specific question

lone heartBOT
#

@rough orbit Has your question been resolved?

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terse oak
#

n(n+1)/k^n

lone heartBOT
terse oak
#

how to

#

<@&286206848099549185>

wary stream
lone heartBOT
# terse oak <@&286206848099549185>

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@terse oak Has your question been resolved?

lone heartBOT
#

@terse oak Has your question been resolved?

real gazelle
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indigo heart
#

What's the formula for summation of even numbers

indigo heart
#

I couldn't find anything on Google

worn fox
#

double whatever the summation is if you halved everything

indigo heart
#

1+2+3+4+5+6

6*(6+1)/2

but how do i get 2+4+6

worn fox
#

2(1+2+3)

indigo heart
#

so i take the result of 6*(6+1)/2 and double it?

#

or should i like half N at the start

#

i am confused

keen pasture
#

1+2+3+...+n = n(n+1)/2

indigo heart
#

that's true, but i want it to be the even numbers only

keen pasture
#

2+4+6+..+2n = 2(1+2+3+...n) = 2n(n+1)/2 = n(n+1)

indigo heart
#

for 6, it'd be 2+4+6 = 12
n(n+1)
6(6+1)=42

sorry if i am misunderstanding

keen pasture
#

2+4+6 = 2(1+2+3)

indigo heart
#

i am coding, so
if a user inputs 6,
i'd half it, then take the summation of that
then multiply it by two?

example:
6
6/2=3
summation of 3 = 1+2+3
*2
= 12

keen pasture
#

Take the half of the end number 2n in your case 6

indigo heart
#

Yes

keen pasture
#

And multiply it by n+1

#

6/2 = 3. 3+1 = 4. 3*4 = 12

indigo heart
#

yup got it to work

#

thanks a ton

real gazelle
#

you can also find an explicit formula for it (it is an arithmetic series)

#

but tobias's way is also nice and simple :)

keen pasture
real gazelle
#

ah yeah

#

missed that sorry

indigo heart
#

yeah i basically just did that

#

and if a user entered an odd number, i'd remove 1 from it

keen pasture
#

Sorry, I've no idea about coding

indigo heart
#

well it's basically the same but i don't know exactly what n will be

#

how do i close the help channel?

keen pasture
indigo heart
#

.close

lone heartBOT
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narrow cape
#

Probability;
Roll a 20 sided die, if it's not a 20 reroll it once.
How do I get the Probability for the final being 20 or not-20?

prime badge
#

you add up 2 cases you want to add up

narrow cape
#

Follow up would be scaling;
Roll a 20 sided die, if it's not 18 or higher, reroll it up to 3 total times.

prime badge
#

you have two ways to get that 20, immediately, or after a fail

#

you're really just looking for the chance to fail three times in that case

#

scaling complete

ocean sealBOT
#

Result:

2.0354162426216e-4
narrow cape
#

So for first, is it
5% 20
95% reroll, then 5% 20
So total 20 is 5%+(5%×95%)?

prime badge
#

yes, that's correct

#

,calc 0.05 + 0.95(0.05)

ocean sealBOT
#

Result:

0.0975
prime badge
#

,calc 1 - 0.95^2

ocean sealBOT
#

Result:

0.0975
prime badge
#

,calc 1-(17/20)(17/20)(17/20)

ocean sealBOT
#

Result:

0.385875
prime badge
#

fail three times is the only way to not roll 18+

narrow cape
#

Ok so for 2nd
15% 18+
85%reroll, then 15% 18+
85%of 85% to reroll again
So 15% for 18+ after 1 roll (3/20)
27.75% for 18+ after reroll (15%+(85×15)
38.58% for 18+ after 2 rerolls(27.75+(85%×85%×15%)

prime badge
#

right

narrow cape
#

Is there a better way than just doing each equation one by one?

prime badge
#

that's what i showed tho

#

you skip to 38.58

narrow cape
#

I mean I could make a spreadsheet and turn that into a graph for each variable

prime badge
#

yeah

narrow cape
#

No I mean the 38.58 is one equation

prime badge
#

1 − chance^max_attempt

#

chance to fail that is

narrow cape
#

What about
Roll d20, if not 20 reroll, then if not 19 or more (20-1) reroll, then if not 18 or more reroll.... then if not 2 or more reroll

prime badge
#

that's bad yeah

narrow cape
#

That's just 1/20×2/20×3/20....x19/20

prime badge
#

yeah that makes sense

narrow cape
#

Ok cool thanks :)

#

Oh wait

prime badge
#

one minus

narrow cape
#

Is it 1- all that

#

Ok nice

#

.close

lone heartBOT
#
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narrow cape
#

:)

lone heartBOT
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honest cliff
#

I have a really simple question that I'm too dumb to figure out, if I have a 0.06% of getting something everyday, How likely is it I get it after for example 30 days or 365 days?

prime badge
#

,calc 1 - (1 - 0.06)^365

ocean sealBOT
#

Result:

0.99999999984452
prime badge
#

,calc 1 - (1 - 0.0006)^365

ocean sealBOT
#

Result:

0.19673107946895
prime badge
#

20%

lone heartBOT
#

@honest cliff Has your question been resolved?

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craggy summit
#

I'm trying to understand how the second-order formula
[
\forall P Py \land (\forall a \forall b Pb \land Parent(a, b) \rightarrow Pa) \rightarrow Px
]
expresses that $x$ is an ancestor of $y$. It's not very clear to me.

What is the scope of the first $\forall$? Is it
[
\begin{array}{l}
\forall P (Py) \land \boldsymbol(\forall a \forall b Pb \land Parent(a, b) \rightarrow Pa\boldsymbol) \rightarrow Px, \
\forall P \boldsymbol(Py \land (\forall a \forall b Pb \land Parent(a, b) \rightarrow Pa)\boldsymbol) \rightarrow Px, \text{or} \
\forall P \boldsymbol(Py \land (\forall a \forall b Pb \land Parent(a, b) \rightarrow Pa) \rightarrow Px\boldsymbol)
\end{array}
]
What about the scopes of the $\forall$'s in $\forall a \forall b Pb \land Parent(a, b) \rightarrow Pa$?

Also, can we switch $b$ and $a$ and say $\forall a \forall b Pa \land Parent(a, b) \rightarrow Pb$ to say that the set is closed under the parent relation?

ocean sealBOT
lone heartBOT
#

@craggy summit Has your question been resolved?

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#

@craggy summit Has your question been resolved?

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lone heartBOT
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uneven cosmos
lone heartBOT
vernal thunder
# uneven cosmos

First of all, you need to draw triangles with respective side lengths

#

Make sure it’s in the appropriate quadrants

real gazelle
#

do you know the sum formulas

uneven cosmos
#

yeah

real gazelle
#

aight

#

are you struggling with figuring out cos x, cos y?

#

or do you know how

vernal thunder
uneven cosmos
#

havent done one like it before

real gazelle
#

ah okay

#

so do you know how to figure out what cos x is

uneven cosmos
real gazelle
#

cool

vernal thunder
real gazelle
#

so what is cos x?

uneven cosmos
#

hang on

#

yeah its -rt(51)

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sorry had to go fix something

real gazelle
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how did you get -rt(51)?

uneven cosmos
#

that the adj

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-rt(51)/26 is the cos

real gazelle
#

what did you calculate in order to get the 51

uneven cosmos
real gazelle
#

like what did you plug into the calculator to give you 51?

#

oh okay

#

26^2 - 24^2 is 100

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so I'm not sure where the 51 came from

uneven cosmos
#

my calculator must be wrong idk

#

or I typed it wrong

real gazelle
#

maybe a typo yea

#

but yeah take the square root and then you get -10/26 as the cosine of x

#

that's right 👍

#

what about cos y?

uneven cosmos
#

58^2=-42^2+x^2

real gazelle
#

yep

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don't forget the parentheses, (-42)^2

uneven cosmos
#

40

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40/58 is cos

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20/29

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cos(100+ 20/29)

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or what?

real gazelle
#

cos(x+y) = cos(x)cos(y) - sin(x)sin(y) right

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just plug the values you have into this equation and you are good

real gazelle
#

if it's QIII

uneven cosmos
#

neg

real gazelle
#

yup

uneven cosmos
#

let me check my work

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all im getting is cos(2920/29

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and i cant use trig equations for my answer

gray isle
#

show your work

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cos(100+ 20/29)
you shouldn't be doing anything resembling that

uneven cosmos
#

thats what you said right

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cos(x)cos(y) - sin(x)sin(y)

gray isle
#

what eric said

uneven cosmos
#

oh

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so (100 (-20/29)) - (24/26 (-42/58))

#

thats easier than I thought

real gazelle
#

where did you get the 100

#

should be -10/26 like we said earlier, no?

#

otherwise it looks good

#

remember that cosine and sine are always between -1 and 1

lone heartBOT
#

@uneven cosmos Has your question been resolved?

#
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lone heartBOT
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sharp moth
#

What is the highlighted portion referring to

sharp moth
#

Is that like a coordinate plane

fluid basin
#

not really, no, it's a subregion of the domain over which the function is defined

#

for a function defined over the real numbers, it'll be some interval of the real number line

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like 0 < x < 2, often written as (0,2)

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that's what is meant by an "interval"

sharp moth
#

Ah okay that kind of bridges the gap between what I'm writing and what it means

fluid basin
#

any further questions i can help with?

lone heartBOT
#

@sharp moth Has your question been resolved?

sharp moth
#

What two functions are they referring to

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Why is the comparison valuable

last ether
#

Well it's for any function

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Usually continuous, preferably continuous within the interval I

#

They're basically saying that if f(a) is the lowest output within a certain set of inputs, then f(a) is the absolute minimum.

On the other hand, if f(a) is the largest output within a certain set of inputs, then f(a) is the absolute maximum.

sharp moth
#

This says that a is any value within the interval, right?

last ether
#

Yup

#

Well

#

a is an element of set "I"

#

Which means that a could be any number within the set "I"

lone heartBOT
#

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#
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sharp moth
lone heartBOT
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sharp moth
#

What does f(c) refer to?

lone heartBOT
gilded citrus
#

the value of the function at x = c

karmic rapids
#

where I presume c is any value in the domain

remote heron
#

helo caarson

sharp moth
#

Hello!

sharp moth
#

If x = c then wouldn't it be c = c

#

How could x = c when x has to be x

gilded citrus
#

if f(x) is x^2 + 2x + 1, the expression "the value of the function at x = c" is f(c) = c^2 + 2c + 1

lone heartBOT
#

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sharp moth
#

Thank you

lone heartBOT
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lapis night
lone heartBOT
lapis night
#

would really appreciate some help

strange hound
#

Do you have the triangle DEF plotted?

lapis night
#

i do not

#

this is all i was given

strange hound
#

Do you have graph paper?

lapis night
#

no

strange hound
#

Ok. Draw an xy coordinate plane on paper.

lapis night
#

just a second

#

ok

strange hound
#

Like this, right?

lapis night
#

yes

strange hound
#

Draw the point D

lapis night
#

ok

strange hound
#

Just curious? What is the x value of your point D?

lapis night
#

6

strange hound
#

Groovy. Do points E then F and draw the triangle.

lapis night
#

done

strange hound
#

That was question A. B says reflect over x = 2. Do you know reflections?

lapis night
#

a little not so sure

strange hound
#

Imagine a mirror at x=2. This is for every y. Draw a light line from x=2 all the way up and all the way down.

lapis night
#

this is where i am at. does that look right for now?

strange hound
#

Yep. Label your points though.

#

Just think about D. If x=2 was a mirror, where would the reflection look to be?

lapis night
#

(-6,2)?

strange hound
#

Close. The distance of D from the "mirror" is 4. (6-2)
The distance of the reflection will be the same. 2-4

lapis night
#

hm so would it be (-2,-2)

strange hound
#

Yes.

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Is that enough for you to find the reflected triangle DEF prime?

lapis night
#

wait

#

yes

#

thank you!!!!!

#

just one question

#

does that look right

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cause the shapes look a little different

strange hound
#

The points aren't labeled. So I can't tell you which one is incorrect.

lapis night
#

just a second

strange hound
#

I'll tell you the problem, you can tell me the answer, and good job on noticing the shapes weren't the same.

#

E is 6 away from x=2. E' is -6 away from x=0.

lapis night
#

ohh

#

so it would be at 4 instead of x

#

6**

strange hound
#

(-)4

lapis night
#

like this?

strange hound
#

Bingo

lapis night
#

ah thank you very much

strange hound
#

I'll double check your last triangle, if you like.

lapis night
#

that would be great ill try to do it

#

how does this look?

strange hound
#

Oops. You reflected (correctly) DEF. Question C asked to reflect D'E'F.

lapis night
#

im confused

strange hound
#

Point E' has x=-4. If you reflect E' over x=-4, E' doesn't move and becomes E''.

lapis night
#

still confused

strange hound
#

First triangle: DEF, pronounced Dee Eee Eff was reflected to become a new triangle, a second triangle: D'E'F', Dee prime, Eee prime, Eff prime.

#

Question C want the reflection of D'E'F', the second triangle, to become D''E''F''.

lapis night
#

so they want me to reflect D"E"F" from D'E'F'?

strange hound
#

yup.

lapis night
#

So i just need to change question c>

strange hound
#

That's right. Erase the apostrophes from question c and your answer is correct.

lapis night
#

like this?

#

im back to confused

strange hound
#

I'll do the x part of D.
b) Reflect D over x=2.
D = 6
Distance = 4
D' = 2 - 4
D' = -2
c) Reflect D' over x=-4
D' = -2
Distance = 2
D'' = -4 -2
D'' = -6

lapis night
#

so do i need to change both answers?

strange hound
#

B is correct. In C you reflected the wrong triangle.

#

Triangle 1, DEF. Triangle 2, D'E'F'. Triangle 3, D''E''F''.
In question C they want the reflection of D'E'F'.

lapis night
#

im going to try

#

something like this?

strange hound
#

That's it. Well done.

lapis night
#

wow

#

thank you!

#

i really appreciate your time

strange hound
#

No worries. Use the names of the points, make an effort out loud and in your head to call it Dee... then Dee prime... then Dee double prime.

#

From Dee we reflected over x equals 2 to find Dee prime. Then we reflected Dee prime over x = -4 to find Dee double prime. The ex coordinate of Dee double prime is negative six.

#

I use this math all the time when I design video games.

lone heartBOT
#

@lapis night Has your question been resolved?

lone heartBOT
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jolly notch
#

What ratio do i divide the line into? 1:2 for A right?

jolly notch
#

I know the formula is (mx2 + nx1)/m+n and vice versa for y

#

But im unclear about the ratio to use here

alpine sable
#

for the x cord divide it by three and multiply it by 2

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for the y cord same things

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use similar triangles

#

easier to visualize

jolly notch
alpine sable
#

yes

#

but in this case

#

no need to add x2

jolly notch
alpine sable
#

yes

jolly notch
#

.close

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indigo cedar
#

how do you do 3 + 3 (1+1)?

lone heartBOT
karmic rapids
#

,, 3 + 3 \cdot (1 + 1)

ocean sealBOT
#

illuminator3

karmic rapids
#

first do parenthesis

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then products

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then additions

indigo cedar
#

woah, ok, but after i do parenthesis and get the answer, what do i do with the answer??

karmic rapids
#

what's 1+1

indigo cedar
#

2

karmic rapids
#

so you now have

#

,,3 + 3 \cdot 2

ocean sealBOT
#

illuminator3

karmic rapids
#

what's $3 \cdot 2$

ocean sealBOT
#

illuminator3

indigo cedar
#

6

karmic rapids
#

,, 3 + 6

ocean sealBOT
#

illuminator3

indigo cedar
#

9

karmic rapids
#

,, = 9

ocean sealBOT
#

illuminator3

karmic rapids
#

so all in all $$ 3 + 3 \cdot (1 + 1) = 9 $$

ocean sealBOT
#

illuminator3

indigo cedar
#

ok so like 10+11 (2+5)

#

that would be

#

21 * 7?

vale wigeon
#

no

karmic rapids
#

no

indigo cedar
#

bruh

vale wigeon
#

your bad spacing is what is making you confused

karmic rapids
#

parenthesis, then products, then additions

vale wigeon
#

it would have been better if you had written it as 10 + 11(2+5)

indigo cedar
#

idk what products are

vale wigeon
#

that way it would be clearer that the multiplication is to be done first

karmic rapids
#

,, 10 + 11 \cdot (2 + 5)

indigo cedar
#

legit same thing

ocean sealBOT
#

illuminator3

karmic rapids
#

,, \cdot

ocean sealBOT
#

illuminator3

indigo cedar
#

Theres no multiplication thooo

#

in that equation

vale wigeon
#

yes there is

indigo cedar
#

WHERE

karmic rapids
#

there is

vale wigeon
#

the 11 is being multiplied by the parenthetical

#

10 + 11*(2+5)

#

to write it out more explicitly

indigo cedar
#

im soooo confuseddd

karmic rapids
#

$$a(b) = ab = a \cdot b$$

ocean sealBOT
#

illuminator3

vale wigeon
#

when we put two things next to each other in algebra, it means multiplication

indigo cedar
#

thats stupid

karmic rapids
#

no?

vale wigeon
#

how old are you

indigo cedar
#

14!!!!!!

#

bro this too complex omg

vale wigeon
#

,w (((((14!)!)!)!)!)!

ocean sealBOT
#

An unknown error occurred querying the WolframAlpha API!
ERROR: 1010 Computation error

vale wigeon
#

LMFAO

indigo cedar
#

bruh

vale wigeon
#

ok no

#

i was going to make a factorial joke

#

but nevermind that

indigo cedar
#

lmaoo

karmic rapids
#

didn't you run out of puns for today already

vale wigeon
#

you are fourteen years old. that is plenty old enough to know what multiplication is and how it is written

indigo cedar
#

ok ok

#

lets do this

#

1+1(1+1)

#

what is this

vale wigeon
#

do you have paper

indigo cedar
#

no

vale wigeon
#

then go get some

indigo cedar
#

no

vale wigeon
#

and work it out step by step

indigo cedar
#

i got a pc

#

i can write it

#

type*

#

look ok

#

this is what i know

#

u do the () first

#

ok

#

u solve it

#

get the answer

#

but MY question is

#

WHERE do u put the answer of the ()

karmic rapids
#

in place of the ()

vale wigeon
#

wherever the () were in the expression...

indigo cedar
#

oh damnn

vale wigeon
#

just like with any other operation

indigo cedar
#

and then

karmic rapids
#

lol nice about me

indigo cedar
#

i do like

#

then i solve

#

the original one right

#

then like

#

it becomes

#

2 +2?

karmic rapids
#

weird, horny, smart

indigo cedar
#

2 * 2

#

right?

vale wigeon
#

no

indigo cedar
#

BIRIG{OSDIkg]kepr[wshklohp

#

WTF BRO

vale wigeon
#

calm down

indigo cedar
#

this makes 0 sense bro

vale wigeon
#

ok so you are trying to calculate 1 + 1*(1+1), yes?

indigo cedar
#

1 +1 (1+1)

vale wigeon
#

yes, that's what i wrote.

indigo cedar
#

no

#

u wrote *

vale wigeon
#
  • stands for multiplication.
indigo cedar
#

yeah i know

#

which i didnt type

#

u did

#

so

vale wigeon
#

1(1+1) also means 1 multiplied by (1+1)

ember lava
#

💀 💀

indigo cedar
#

why

vale wigeon
#

that is how mathematical notation works

indigo cedar
#

1(1+1) isin't even valid]

vale wigeon
#

sure is.

indigo cedar
#

NO

languid bolt
#

it is

indigo cedar
#

NOIOOO

#

its like grammar

#

its not correct

vale wigeon
#

and the grammar of mathematical notation does permit such a thing...

indigo cedar
#

wow

vale wigeon
#

no matter how much you want to deny it

indigo cedar
#

OK SO

#

1+1(1+1)

#

whats the answer

#

how do u do it

vale wigeon
#

1 + 1*(1+1)

#

do the thing inside the parentheses first

#

1+1 = 2

indigo cedar
#

yes

#

ok

#

what now

vale wigeon
#

so your expression becomes 1 + 1*2

#

once you replace the stuff in the parentheses with the value you worked it out to be

indigo cedar
#

4

vale wigeon
#

no

indigo cedar
#

bro what

vale wigeon
#

remember your order of operations

#

multiplication comes first

indigo cedar
#

waaat

karmic rapids
#

ong

indigo cedar
#

so 3

vale wigeon
#

you are fourteen, you are plenty old enough to know the order of operations from school

indigo cedar
#

i dont listen to school

vale wigeon
#

ah.

gilded citrus
#

troll detector is off the charts

indigo cedar
#

IS IT 3?

vale wigeon
#

WHY ARE YOU YELLING

indigo cedar
#

UR NOT ANSWERING ME

vale wigeon
#

SURE, IT IS 3, BUT THERE'S NO NEED TO ALLCAPS

indigo cedar
#

OK

#

COOL

#

lets do another

#

2+2(2+2)

#

ok so

#

4

#

right

karmic rapids
languid bolt
#

ITS NOT 4

indigo cedar
#

2+2*4

#

10

#

its 10 right

karmic rapids
#

how in the world did you get 4

indigo cedar
#

no

#

no

languid bolt
#

YES ITS 10

indigo cedar
#

not 4 as in the answer

indigo cedar
vale wigeon
indigo cedar
#

im smart again

vale wigeon
#

shit happens

vale wigeon
#

sometimes you get teenage contrarians

indigo cedar
#

xd

karmic rapids
#

what is a contrarian

vale wigeon
#

who don't like clear communication and think it is cringe

indigo cedar
#

im just tryna be fast ok

karmic rapids
#

slay girly

indigo cedar
#

anyway

vale wigeon
indigo cedar
#

thank u

#

for da

#

help

vale wigeon
indigo cedar
#

very helpful

#

and appriciated

indigo cedar
vale wigeon
#

please don't call me bro.

indigo cedar
#

ok dude

karmic rapids
#

LMAO

vale wigeon
#

please don't call me that either.

indigo cedar
#

ok mABOi

#

XD

vale wigeon
#

i'm not a boy you dipshit

indigo cedar
#

Ok girly

vale wigeon
#

...

indigo cedar
#

knaii

#

lmaoooooooooo

#

ok thank

#

s

#

.close

lone heartBOT
#
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karmic pond
#

I need someone to check my work for a calculus worksheet, Im unsure whether it is correct or not. I tried sending a image but it wont let me

karmic rapids
#

lol

#

send it again

karmic pond
#

okay

karmic rapids
#

that's not an image

karmic pond
#

fianlly it worked

karmic rapids
#

send it as png or jpg

karmic pond
#

oh no wonder sorry ill screenshot it

#

This is all i have gotten so far, do you see any mistakes?

#

i believe its wrong

#

@karmic rapids are you still there lol

karmic rapids
#

yes but you asked a bad question

karmic pond
#

oh my apologizes

karmic rapids
#

well the question isn't bad of itself

#

but the way you asked it

karmic rapids
#

it just reduces your chances of getting help

karmic pond
#

oh my apologizes im new to this

karmic rapids
#

ask a clear and concise question

#

preferably in text with tex if needed

karmic pond
#

How may I find F(0) for question 1?

karmic rapids
#

you're being given the function equation for each line part

#

use the linearity of the integral operator and do piecewise integration

#

ohh

#

you mean f(0) or F(0)

#

@karmic pond ?

karmic pond
#

f(0)

karmic rapids
#

what's $$\int \limits_a^a f(x)dx$$

#

hint: it's a constant

ocean sealBOT
#

illuminator3

karmic pond
#

its the integral of 0 to 0

#

if we are using f(0)

karmic rapids
#

like without even knowing what f(x) is

karmic pond
#

0?

karmic rapids
#

no

karmic rapids
ocean sealBOT
#

illuminator3

karmic rapids
#

and you have the integral you're trying to solve

#

so what's $$\int \limits_0^0 g(t)dt$$

ocean sealBOT
#

illuminator3

karmic pond
#

0

karmic rapids
#

yes

karmic pond
#

ohhh

#

tyty @karmic rapids

#

I underestimated this question and assumed there was no answer for it. ty for clearing that up

#

Did i find all the critical points or am I missing any for question 2?

karmic rapids
#

yes but idk what critical points are lol

karmic pond
#

lmao its fine

karmic rapids
#

you gotta wait for someone else

karmic pond
#

.close

lone heartBOT
#
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lone heartBOT
#
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covert cairn
lone heartBOT
analog basalt
# covert cairn

What do you know of $[\sqrt{x}]$ if (a) $1 \leq x < 4$ or (b) $25 \leq x < 36$?

covert cairn
#

Can u pls elaborate??

analog basalt
#

Woops I forgot a thing, let me rewrite it

ocean sealBOT
analog basalt
#

Just to give an example: what is $[\sqrt{3}]$?

ocean sealBOT
covert cairn
#

√3 = 1.73

#

If we get gif of that it will return 1

analog basalt
#

Exactly

#

You actually don't even need to calculate the value for this, just because we know that $[\sqrt{1}] = [1] = 1$ and $[\sqrt{4}] = [2] = 2$, we know that $[\sqrt{x}] = 1$ if $1 \leq x < 4$ because in that case $1 \leq \sqrt{x} < 2$

ocean sealBOT
covert cairn
#

Smth like this??

analog basalt
#

Yes great!

#

Now we only need to find out exactly how many we have of each term, and then we can calculate the sum

analog basalt
#

So we now know that every for $x$ with $n^2 \leq x < (n+1)^2$ it holds that $[\sqrt{x}] = n$

ocean sealBOT
covert cairn
#

Yeah

analog basalt
#

And because $x$ is an integer, we know that there for every $n$ there are exactly $(n+1)^2 - n^2$ of those

ocean sealBOT
analog basalt
#

For example there will be $3$ numbers giving $1$, $5$ numbers giving $2$, etc.

ocean sealBOT
covert cairn
analog basalt
#

You are actually computing the sum $$\sum_{n=1}^{44} \left( (n+1)^2 - n^2 \right) n$$

ocean sealBOT
analog basalt
# covert cairn This is true but how did u get that?

We just "count" how many numbers are greater or equal to $n^2$ but smaller then $(n+1)^2$, and this is just the same as subtracting the lower bound from the upper bound, and thus $(n+1)^2 - n^2$ (this can actually be simplified to $(2n+1)$)

ocean sealBOT
analog basalt
#

This means that our answer will be $$\sum_{n=1}^{44} n(2n+1) = \sum_{n=1}^{44} 2n^2 + n$$, there exist formulae to calculate such sums or you can use a calculator

ocean sealBOT
covert cairn
#

Sir I am getting confused

lone heartBOT
#

@covert cairn Has your question been resolved?

covert cairn
#

<@&286206848099549185>

alpine sable
#

is this rounding

#

or floor

analog basalt
alpine sable
#

firstly there are 2n+1 numbers x such that $n^2 <= x < (n+1)^2$ ([x] = n)

ocean sealBOT
#

Jester

alpine sable
#

since 2025 = 45^2

#

we count how many numbers between the squares and multiply them by their floors

#

1->2 would be 1 * (2 * 1 + 1)

covert cairn
#

I have proceeded

#

Now how will I solve the rest??

alpine sable
covert cairn
alpine sable
covert cairn
#

How did u get n^2+n

alpine sable
lone heartBOT
#

@covert cairn Has your question been resolved?

#
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sonic prism
lone heartBOT
sonic prism
#

uh i got one of the solutions which is -1 <= x <= 5

#

how do i obtain the other solution

#

nvm

#

.close

lone heartBOT
#
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zealous wraith
#

Really easy question but i cant remember how to do this

zealous wraith
raven dagger
#

Write √x as x^1/2
Then see what rules of indices you can apply

zealous wraith
#

ive got x^1/2(1/3x^2)

raven dagger
#

What happens to input of exponents when the outputs are dividing?

zealous wraith
#

power of -1?

#

idk

lone heartBOT
#

@zealous wraith Has your question been resolved?

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sonic egret
#

What is the definition of a group $G$ generated by a set $S$ \ $G = \langle S \rangle$ \ ?

ocean sealBOT
#

Mr.Brawler

pliant dune
#

there are equivalent definitions but one way to think of it is that it's the smallest group containing S

sonic egret
#

let's take |S|=2

#

What is $\langle 2, 7 \rangle \leq \mathbb{Z}?

pliant dune
#

if you want to calculate the subgroup a set generates then it's the set of all finite products of that set S

#

in this case all finite additions might be better wording

sonic egret
#

ok cool

#

and what about a generated ideal?

#

what is the definition?

pliant dune
#

like ideals in rings?

sonic egret
#

yes

pliant dune
#

it's similar in that it's the smallest ideal that contains S, but now for S a subset of a ring R, then <S> is the set of all finite sums of products between elements of S and R

#

that last bit is kind of a soup of words

sonic egret
#

ok cool

#

got it

#

basically

#

$(a,b) = {a,a^2,...,b,b^2,...ab,ab^2,ababa^2..., ab+b^2+a^{192}+ab^4a}$

pliant dune
ocean sealBOT
#

Mr.Brawler

sonic egret
#

correct?

#

@pliant dune

pliant dune
#

might be missing some elements and depending on the ring there might be repeats but all of those should be in the ideal

sonic egret
#

cool

#

thanks

#

.close

lone heartBOT
#
Channel closed

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sonic egret
#

$ \langle S \rangle = {r_1s_1 + r_2s_2 + ... + r_ns_n | n \in \mathbb{N}, r_i \in R, s_i \in S}$

#

just checking

pliant dune
#

idk why the bot doesn't like it

sonic egret
#

ok nice

lone heartBOT
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sonic egret
lone heartBOT
pliant dune
#

Yes

sonic egret
#

and does s_i s_j belong to the set?

#

in a case of a group it does?

pliant dune
#

like is s_i * s_j in <S> ?

sonic egret
#

yes

pliant dune
#

yes, you can get it from this definition since S is a subset of R

#

so r_i can be from S

sonic egret
#

ok cool

#

thanks

#

.close

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#
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quiet sinew
#

how do i find the arithmetic sequence of 2-6+10-14+18....
i tried using the basic formula a+(n-1)b, which obviously didn't work. i also tried using the an²+bn+c formula but it also didnt work.

languid bolt
#

isnt this a geometric sequence?

quiet sinew
#

i dont even know

languid bolt
#

do you know what a geometric sequence is?

quiet sinew
#

uhhh a sequence

#

sooo can u use the a r^n-1 formula?

languid bolt
#

wait...

quiet sinew
#

i dont think it will work

languid bolt
#

hmm

quiet sinew
#

hmm i just realized somethint

languid bolt
#

difference is 4 if it's all positive

wanton turtle
#

Two different APs?

quiet sinew
#

yes but the question is different

wanton turtle
#

Separate the positive and negative terms and you get two separate APs ye?

quiet sinew
#

ohhh lemme try

languid bolt
#

i think i found the answer

#

ok

quiet sinew
#

tbh i dont need the direct answer, i need the step

#

sooooo
2 + 10 + 18.....
-6 - 14 -22
what should i do with this?

#

whats ap

#

sorry

languid bolt
#

arithemetic progression

quiet sinew
#

english is my 2nd lang

ocean sealBOT
quiet sinew
#

the first one is
2+(n-1)8
the second is
-6 +(n-1)-8

#

is that correct

#

oh sn

#

i thought ap formula is a+(n-1)b

#

oh

ocean sealBOT
quiet sinew
#

ahhh i see

#

n/2(2a+(n-1)b)

#

i need the ap formula

#

or as i call it un

#

but i need for it to be 2-6+10-14...

#

yes

#

yep

#

uhmmm no

#

but

#

uhhh i have no idea

#

OH I GET IT

#

(-1)^n

#

i see

#

-sin(n-1/2)π

#

thanks for the help

#

.close

lone heartBOT
#
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plucky geyser
#

the derivative of sx and this comes from triangle similarity rule

plucky geyser
#

@tawny merlin

#

I think it's correct

#

derivative of sx with respect to t

#

I found sx from triangle similarty

#

I found the relationship between s and x to find the rate of s

#

isn't clear

#

the entire problem

#

yeah

#

am I correct

#

thank you Keb 🫂

#

.close

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eager jackal
#

how do i find the phase shift of the function y=sin6(x-30)+1

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#

@eager jackal Has your question been resolved?

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alpine sable
#

.

#

How would you prove (a * b)^n =a^n * b^n if a * b=b * a

alpine sable
#

a^n is defined as a * a * a ..... a n times

pliant dune
#

(a*b)^n = (ab)(ab)...(ab) [n times]
= abababab...ab [with n a's and n b's]
then since ab=ba we can move all the a's to the left and all the b's to the right to get
= aaa....a * bbb...b
= a^n * b^n

alpine sable
#

it may be true that u can do that

pliant dune
#

basically whenever you see an 'a' to the right of a 'b' replace the 'ba' you see with 'ab' and repeat until you don't see an 'a' to the right of a 'b'

wheat zenith
#

maybe nicer to do it with induction

alpine sable
#

ohhh

wheat zenith
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bc the base case is trivial and each step u just gotta switch the last two

alpine sable
#

then the number of a's and b's stay consistent after each operation

pliant dune
alpine sable
#

and there will not be ba

#

induction also works

alpine sable
wheat zenith
#

what tom said is good intuition tho at least; ab=ba just means a and b commute so you can rearrange them and (ab)^n just gives you a string of n as and n bs

wheat zenith
alpine sable
#

yeah but that doesnt mean it ends

wheat zenith
#

well if u want to do it rigorously you need induction

alpine sable
#

i guess

#

ok thanks

#

.close

lone heartBOT
#
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empty plover
#

help

lone heartBOT
marsh rapids
#

find an equivalent ?

#

what's the question ?

empty plover
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nature of the series

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if it converges or diverges

marsh rapids
#

do you know how to find an equivalent to S(n) ?

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cause that's useful in general

empty plover
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is it possible tho we don't know n

empty plover
marsh rapids
#

TCSI

empty plover
#

seems like something magical tbh

empty plover
marsh rapids
#

then you sum over all p

empty plover
#

youre talking about integral series comparaison?

marsh rapids
#

Théorème de comparaison entre séries et intégrales oui

empty plover
#

ok alors je fais quoi ici exactement?

#

je trouve un equivalent de S(n) pout tout n?

marsh rapids
#

ça donne un encadrement de S(n) et t'en déduis un équivalent

#

en fonction de n

marsh rapids
#

vaut mieux trouver un équivalent alors oui

empty plover
#

look at what they did

#

mais n importe je vais essayer ta methode

marsh rapids
#

ça à l'air bien

empty plover
#

mais je comprends rien

marsh rapids
#

"what I did" mais c'est pas toi ?

empty plover
#

meme ca n a pas meme l air juste. pour alpha =-100 la serie converge aussi :l

empty plover
marsh rapids
marsh rapids
empty plover
#

C'est maths france

marsh rapids
#

je sais pas lire, je lu I au lieu de they

empty plover
#

hahaha

marsh rapids
empty plover
#

le web est devenu payee mais j ai toujours tous les pdf gratuits sur mon ordi

marsh rapids
#

pas grave. Les profs donnent déjà bien assez d'exos comme ça

empty plover
marsh rapids
#

type transition entre sup et spé ?

empty plover
#

Oui je commence spe en quelques semaines

marsh rapids
#

où ça ?

empty plover
#

En Liban, il y a un parcourt de concours international a polytechnique

#

t'es en uni?

marsh rapids
#

prépa. J'entre en MP* l'année prochaine

empty plover
#

Ah pareil

empty plover
marsh rapids
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ok

empty plover
#

quelle grande ecole tu aimeras integrer?

marsh rapids
#

...

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lol

#

faudra que je regarde un de ces 4

#

les formations les plus intéressantes

empty plover
#

quelle 4?

marsh rapids
#

un de ces quatres <=> un moment ou un autre. Expression française

empty plover
#

Hahaha

#

d accord

empty plover
marsh rapids
#

tant que j'y pense

empty plover
#

Waaw je le trouve ou?

empty plover
marsh rapids
#

il y a une différence entre "passer" et "passer à"

#

l'un oui, l'autre non

empty plover
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Hahha oui c'est logique

marsh rapids
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mais peut-être que j'obtient Ulm, qui sait

empty plover
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Ok

#

Est ce que tu travailles cet ete

marsh rapids
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pour un salaire non, pour les maths et la physique oui

empty plover
#

quelle est ton banque d 'exercices si c'est pas maths france, et est ce qu il ya des youtube channels sur les maths que tu aimes?

marsh rapids
#

du coup voilà le site de mon prof de maths de l'année dernière

empty plover
#

Ok genial

marsh rapids
empty plover
#

Les cours et les exercices de maths france sont complets si tu veus un chapitre dit le moi

marsh rapids
empty plover
#

c'est bizarre que t'as jamais entendu de maths france j ai cru que c'etait une source universelle

empty plover
marsh rapids
#

maintenant il y aussi le site de la prof de maths de spé, mais celui là jsp si je peux publier le lien comme ça

empty plover
#

et est ce que tu regardes des chaines youtubes ou pas necessairement?

marsh rapids
empty plover
#

mes profs sont nuls alors les chaines youtube m'aide a comprendre les notions beacoup plus profondement

marsh rapids
#

maintenant plus trop vu que les cours sont bien. Avant j'étais au lycée donc rien de bien utile pour la spé

marsh rapids
empty plover
#

est ce que je peus te parler d un temps a un autre si j ai besoin de mieux comprendre une notion?

marsh rapids
#

vu que je suis pas vraiment en avance sur toi je pense que ç'est mieux pour toi de demander sur le serveur quant t'a besoin. Je dis pas non mais je garantis rien

empty plover
#

soit honnete mdr est ce que ca va si je te demande des quest ou non, si l idee te derange c'est pas grave

#

le serveur marche mais c est pas efficace j aimerai avoir des personnes que je peus analyser avec les notions

marsh rapids
#

pourquoi pas, si tu veux

marsh rapids
empty plover
#

j etais entrain de voir le site que tu m as envoye

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supposons n=2

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ok non en fait c'est clair oui

marsh rapids
#

parce que exponentielle >> polynomes

#

en gros

lone heartBOT
#

@empty plover Has your question been resolved?

lone heartBOT
#
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Ask your math question in a clear, concise manner.
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alpine sable
#

anywhere to get help with the mathematics associated with algorithms? like reading pseudocode and converting into mathematical notation?

marsh rapids
#

and also probably ask in some CS / python / more programming oriented discord server as well if you want to

alpine sable
marsh rapids
#

so what's your question ?

alpine sable
#

how one would read the pseudocode and convert it to the mathematical notation. i think i could do it if someone walks me through it

marsh rapids
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wdym convert it to math notation ? It's not like an algorithm is a sort of mathematical sentence or a logical statement (think theorems, properties etc)
If you could give an example of what you're looking for it'd be helpful

half epoch
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I’m guessing he is wondering how to go from the algorithm to the time complexity

gilded citrus
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do you mean going from the code to the expression for the runtime

marsh rapids
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just count the number of iterations of loops

alpine sable
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thats not mathematical enough

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i have to be able to write the equations

marsh rapids
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you got 2 for loops and each iteration ends up with an theta(1) operation

#

and for chained loops the number of iterations is the sum over all the outer loop iterations, of what's done inside 1 iteration, which here is the length of the inner loop

half epoch
# alpine sable

Focus on the outer loop. We go from i = 1 to i = n - 1 and for each iteration we do n - i times the inner loop

#

Another way to put it is that the inside has a time complexity of n-i, for iteration i. Thus we need to sum up n-i for the amount of times we run the outer loop to get the total time

alpine sable
#

yeah i'm not seeing it. the algorithm makes sense but i don't understand which part gives rise to which expression or why in the second expression it becomes equal to n(n-1) - summation(i)from i=1 through n-1

#

i see where the n^2 - n comes from, they expanded the n(n-1) in the previous expression

half epoch
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That’s just a math trick, summation can be split in two

alpine sable
#

so that must mean that the second summation we see gave rise to the n^2 - n / 2 expression?

half epoch
#

$\sum_{i = 1}^{n -1} (n - i) = \sum_{i = 1}^{n - 1} n - \sum_{i = 1}^{n - 1} i$

ocean sealBOT
#

Learath2

alpine sable
#

is the entire running time given by:

half epoch
alpine sable
#

thanks im going to write that down. but how would you interpret it? why is there only a single summation when we have multiple loops

half epoch
alpine sable
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why does it get converted into n(n-1) in the first step

half epoch
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They split the summation as I pointed out, then you use the sum rule for sum of consecutive numbers

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$\sum_{i=1}^{n} i = \frac{n(n-1)}{2}$

ocean sealBOT
#

Learath2

alpine sable
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i don't understand why multiplication comes in at all i thought summations were simply adding up a bunch of expressions

half epoch
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1/2 is a constant factor. O(n/2) = O(n)

#

So the factor is discarded

alpine sable
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why does it become n*(n-1)

half epoch
alpine sable
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i get you said its breaking apart the expression but i don't understand the multiplicative aspect

half epoch
half epoch
alpine sable
#

this summation is in a different format its going to confuse me. i'll watch

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the variables being in different spots is difficult for me

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its a brilliant proof

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ok so how do i use that info in the context of the algorithm

half epoch
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Oh, I misread that, sorry. You don’t even need the summation thing there 😦

#

It’s just the summation of a constant, my bad

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$\sum_{i=1}^{n - 1} n$ notice there is no $i$ in the sum, thus it’s just $(n-1)*n$

ocean sealBOT
#

Learath2

alpine sable
#

lets just analyze this piece:

half epoch
#

The second part is where you use the theorem, the sum with the i in it

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Okay, that’s just the sum rule, you split the sum in 2 because it’s linear

alpine sable
#

wait wait

#

first off

#

why is it n - i

half epoch
#

Look at the inside of the outer loop. For each iteration, we do “something constant” n - i times

alpine sable
#

i can see why it's n-1..

half epoch
#

In other words inner loop happens n - i times

#

I guess the fact that they discard constant times from the very start is what is confusing you

#

Doing it without that “optimization” will give you the 2 summations you expect, would you like to try it like that?

alpine sable
#

sure whatever will help me understand

half epoch
#

Okay, so let’s give each operation a time of 1. Just 1, we aren’t concerned about units

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Now let’s calculate the runtime of the inside portion of the outer loop, from line 2 to 9

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It’s $1 + \text{ inner loop } + 1$

ocean sealBOT
#

Learath2

half epoch
#

Do we agree on that?

alpine sable
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yes

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wait the first loop should be n not 1

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or i

half epoch
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We are just calculating the inner portion now

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Not looping yet

alpine sable
#

ok

half epoch
#

This is how much time each iteration of the outer loop will take

#

Now we need to add together the time taken by each iteration. So we use a summation

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$\sum_{i=1}^{n - 1} (1 + \text{inner loop} + 1)$

ocean sealBOT
#

Learath2

half epoch
#

Do we agree with this one?

alpine sable
#

! = statements seem to be at odds

half epoch
#

min = i, is 1. The swap is 1

alpine sable
#

ok i see whats going on

half epoch
#

It’s the assignment + the inner loop + the swap

alpine sable
#

ok ok

half epoch
#

Now let’s look at that inner loop